func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i + 1..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i + 1..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i + 1..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i + 1..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i + 1..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i + 1..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentString: String = ""
    var openParens: Int = 0
    for char in parenString {
        if char == "(" {
            openParens += 1
            currentString += "("
        } else if char == ")" {
            openParens -= 1
            currentString += ")"
            if openParens == 0 {
                result.append(currentString)
                currentString = ""
            }
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentString: String = ""
    var openParens: Int = 0
    for char in parenString {
        if char == "(" {
            openParens += 1
            currentString += "("
        } else if char == ")" {
            openParens -= 1
            currentString += ")"
            if openParens == 0 {
                result.append(currentString)
                currentString = ""
            }
        }
    }
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup: String = ""
    var openParens: Int = 0
    for char in parenString {
        if char == "(" {
            openParens += 1
        } else if char == ")" {
            openParens -= 1
        }
        currentGroup.append(char)
        if openParens == 0 {
            result.append(currentGroup)
            currentGroup = ""
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup: String = ""
    var openParens: Int = 0
    for char in parenString {
        if char == "(" {
            openParens += 1
        } else if char == ")" {
            openParens -= 1
        }
        currentGroup.append(char)
        if openParens == 0 {
            result.append(currentGroup)
            currentGroup = ""
        }
    }
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentString: String = ""
    var openCount: Int = 0
    
    for char in parenString {
        if char == "(" {
            openCount += 1
            currentString += String(char)
        } else if char == ")" {
            openCount -= 1
            currentString += String(char)
        }
        
        if openCount == 0 && currentString != "" {
            result.append(currentString)
            currentString = ""
        }
    }
    
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentString: String = ""
    var openCount: Int = 0
    
    for char in parenString {
        if char == "(" {
            openCount += 1
            currentString += String(char)
        } else if char == ")" {
            openCount -= 1
            currentString += String(char)
        }
        
        if openCount == 0 && currentString != "" {
            result.append(currentString)
            currentString = ""
        }
    }
    
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup: String = ""
    var openParens: Int = 0
    for char in parenString {
        if char == "(" {
            openParens += 1
            currentGroup += String(char)
        } else if char == ")" {
            openParens -= 1
            currentGroup += String(char)
        }
        if openParens == 0 && currentGroup != "" {
            result.append(currentGroup)
            currentGroup = ""
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup: String = ""
    var openParens: Int = 0
    for char in parenString {
        if char == "(" {
            openParens += 1
            currentGroup += String(char)
        } else if char == ")" {
            openParens -= 1
            currentGroup += String(char)
        }
        if openParens == 0 && currentGroup != "" {
            result.append(currentGroup)
            currentGroup = ""
        }
    }
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var current = ""
    var count = 0
    for char in parenString {
        if char == "(" {
            count += 1
            current.append(char)
        } else if char == ")" {
            count -= 1
            current.append(char)
            if count == 0 {
                result.append(current)
                current = ""
            }
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var current = ""
    var count = 0
    for char in parenString {
        if char == "(" {
            count += 1
            current.append(char)
        } else if char == ")" {
            count -= 1
            current.append(char)
            if count == 0 {
                result.append(current)
                current = ""
            }
        }
    }
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup: String = ""
    var openParens: Int = 0
    
    for char in parenString {
        if char == "(" {
            openParens += 1
            currentGroup += String(char)
        } else if char == ")" {
            openParens -= 1
            currentGroup += String(char)
        }
        
        if openParens == 0 && currentGroup != "" {
            result.append(currentGroup)
            currentGroup = ""
        }
    }
    
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup: String = ""
    var openParens: Int = 0
    
    for char in parenString {
        if char == "(" {
            openParens += 1
            currentGroup += String(char)
        } else if char == ")" {
            openParens -= 1
            currentGroup += String(char)
        }
        
        if openParens == 0 && currentGroup != "" {
            result.append(currentGroup)
            currentGroup = ""
        }
    }
    
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var currentGroup = ""
    var openParens = 0
    for char in parenString {
        if char == "(" {
            openParens += 1
            currentGroup += "("
        } else if char == ")" {
            openParens -= 1
            currentGroup += ")"
            if openParens == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var currentGroup = ""
    var openParens = 0
    for char in parenString {
        if char == "(" {
            openParens += 1
            currentGroup += "("
        } else if char == ")" {
            openParens -= 1
            currentGroup += ")"
            if openParens == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var currentGroup = ""
    var openParens = 0
    for char in parenString {
        if char == "(" {
            openParens += 1
        } else if char == ")" {
            openParens -= 1
        }
        if openParens == 0 {
            result.append(currentGroup)
            currentGroup = ""
        } else {
            currentGroup.append(char)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var currentGroup = ""
    var openParens = 0
    for char in parenString {
        if char == "(" {
            openParens += 1
        } else if char == ")" {
            openParens -= 1
        }
        if openParens == 0 {
            result.append(currentGroup)
            currentGroup = ""
        } else {
            currentGroup.append(char)
        }
    }
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var current: String = ""
    var count: Int = 0
    for char in parenString {
        if char == "(" {
            count += 1
            current.append(char)
        } else if char == ")" {
            count -= 1
            current.append(char)
        }
        if count == 0, !current.isEmpty {
            result.append(current)
            current = ""
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var current: String = ""
    var count: Int = 0
    for char in parenString {
        if char == "(" {
            count += 1
            current.append(char)
        } else if char == ")" {
            count -= 1
            current.append(char)
        }
        if count == 0, !current.isEmpty {
            result.append(current)
            current = ""
        }
    }
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup: String = ""
    var openParenCount: Int = 0

    for char in parenString {
        if char == "(" {
            openParenCount += 1
            currentGroup += String(char)
        } else if char == ")" {
            openParenCount -= 1
            currentGroup += String(char)
        }

        if openParenCount == 0 && currentGroup != "" {
            result.append(currentGroup)
            currentGroup = ""
        }
    }

    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup: String = ""
    var openParenCount: Int = 0

    for char in parenString {
        if char == "(" {
            openParenCount += 1
            currentGroup += String(char)
        } else if char == ")" {
            openParenCount -= 1
            currentGroup += String(char)
        }

        if openParenCount == 0 && currentGroup != "" {
            result.append(currentGroup)
            currentGroup = ""
        }
    }

    return result
}
```

func truncateNumber(number: Double) -> Double {
    let intPart = Int(number)
    let decPart = number - Double(intPart)
    return decPart
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    let intPart = Int(number)
    let decPart = number - Double(intPart)
    return decPart
}
```

func truncateNumber(number: Double) -> Double {
    let intPart = Int(number)
    let decPart = number - Double(intPart)
    return decPart
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    let intPart = Int(number)
    let decPart = number - Double(intPart)
    return decPart
}
```

func truncateNumber(number: Double) -> Double {
    let intPart = Int(number)
    let decimals = number - Double(intPart)
    return decimals
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    let intPart = Int(number)
    let decimals = number - Double(intPart)
    return decimals
}
```

func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}
```

func truncateNumber(number: Double) -> Double {
    let intPart = Int(number)
    let decPart = number - Double(intPart)
    return decPart
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    let intPart = Int(number)
    let decPart = number - Double(intPart)
    return decPart
}
```

func truncateNumber(number: Double) -> Double {
    let intPart = Int(number)
    let decimals = number - Double(intPart)
    return decimals
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    let intPart = Int(number)
    let decimals = number - Double(intPart)
    return decimals
}
```

func truncateNumber(number: Double) -> Double {
    let intPart = Int(number)
    let decPart = number - Double(intPart)
    return decPart
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    let intPart = Int(number)
    let decPart = number - Double(intPart)
    return decPart
}
```

func truncateNumber(number: Double) -> Double {
    let intPart = Int(number)
    let decPart = number - Double(intPart)
    return decPart
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    let intPart = Int(number)
    let decPart = number - Double(intPart)
    return decPart
}
```

func truncateNumber(number: Double) -> Double {
    let intPart = Int(number)
    let decPart = number - Double(intPart)
    return decPart
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    let intPart = Int(number)
    let decPart = number - Double(intPart)
    return decPart
}
```

func truncateNumber(number: Double) -> Double {
    let intPart = Int(number)
    let decPart = number - Double(intPart)
    return decPart
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    let intPart = Int(number)
    let decPart = number - Double(intPart)
    return decPart
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.reduce(0) { $0 + abs($1 - mean) } / Double(numbers.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.reduce(0) { $0 + abs($1 - mean) } / Double(numbers.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let distances = numbers.map { abs($0 - mean) }
    return distances.reduce(0, +) / Double(distances.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let distances = numbers.map { abs($0 - mean) }
    return distances.reduce(0, +) / Double(distances.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.map { abs($0 - mean) }.reduce(0, +) / Double(numbers.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.map { abs($0 - mean) }.reduce(0, +) / Double(numbers.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDeviations = numbers.map { abs($0 - mean) }
    return absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDeviations = numbers.map { abs($0 - mean) }
    return absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDeviations = numbers.map { abs($0 - mean) }
    return absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDeviations = numbers.map { abs($0 - mean) }
    return absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDeviations = numbers.map { abs($0 - mean) }
    return absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDeviations = numbers.map { abs($0 - mean) }
    return absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.reduce(0, { abs($1 - mean) + $0 }) / Double(numbers.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.reduce(0, { abs($1 - mean) + $0 }) / Double(numbers.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDeviations = numbers.map { abs($0 - mean) }
    return absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDeviations = numbers.map { abs($0 - mean) }
    return absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.map { abs($0 - mean) }.reduce(0, +) / Double(numbers.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.map { abs($0 - mean) }.reduce(0, +) / Double(numbers.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.reduce(0) { $0 + abs($1 - mean) } / Double(numbers.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.reduce(0) { $0 + abs($1 - mean) } / Double(numbers.count)
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for i in 0..<numbers.count {
        result.append(numbers[i])
        if i != numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for i in 0..<numbers.count {
        result.append(numbers[i])
        if i != numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for i in 0..<numbers.count {
        result.append(numbers[i])
        if i != numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for i in 0..<numbers.count {
        result.append(numbers[i])
        if i != numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for i in 0..<numbers.count {
        result.append(numbers[i])
        if i < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for i in 0..<numbers.count {
        result.append(numbers[i])
        if i < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for i in 0..<numbers.count {
        result.append(numbers[i])
        if i != numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for i in 0..<numbers.count {
        result.append(numbers[i])
        if i != numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for i in 0..<numbers.count {
        result.append(numbers[i])
        if i != numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for i in 0..<numbers.count {
        result.append(numbers[i])
        if i != numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index != numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index != numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var maxLevels: [Int] = []
    var currentLevel = 0
    var maxLevel = 0
    var isOpen = false
    
    for char in parenString {
        if char == "(" {
            currentLevel += 1
            maxLevel = max(currentLevel, maxLevel)
            isOpen = true
        } else if char == ")" {
            currentLevel -= 1
            isOpen = false
        } else if char == " " {
            if isOpen {
                maxLevels.append(maxLevel)
            } else {
                maxLevels.append(currentLevel)
            }
            currentLevel = 0
            maxLevel = 0
        }
    }
    
    if isOpen {
        maxLevels.append(maxLevel)
    } else {
        maxLevels.append(currentLevel)
    }
    
    return maxLevels
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var maxLevels: [Int] = []
    var currentLevel = 0
    var maxLevel = 0
    var isOpen = false
    
    for char in parenString {
        if char == "(" {
            currentLevel += 1
            maxLevel = max(currentLevel, maxLevel)
            isOpen = true
        } else if char == ")" {
            currentLevel -= 1
            isOpen = false
        } else if char == " " {
            if isOpen {
                maxLevels.append(maxLevel)
            } else {
                maxLevels.append(currentLevel)
            }
            currentLevel = 0
            maxLevel = 0
        }
    }
    
    if isOpen {
        maxLevels.append(maxLevel)
    } else {
        maxLevels.append(currentLevel)
    }
    
    return maxLevels
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var result: [Int] = []
    var maxLevel: Int = 0
    var currentLevel: Int = 0
    var isOpen: Bool = false
    for char in parenString {
        switch char {
        case "(":
            if !isOpen {
                maxLevel = 0
                currentLevel = 0
                isOpen = true
            }
            currentLevel += 1
            maxLevel = max(currentLevel, maxLevel)
        case ")":
            if isOpen {
                isOpen = false
                result.append(maxLevel)
            }
        default:
            break
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result: [Int] = []
    var maxLevel: Int = 0
    var currentLevel: Int = 0
    var isOpen: Bool = false
    for char in parenString {
        switch char {
        case "(":
            if !isOpen {
                maxLevel = 0
                currentLevel = 0
                isOpen = true
            }
            currentLevel += 1
            maxLevel = max(currentLevel, maxLevel)
        case ")":
            if isOpen {
                isOpen = false
                result.append(maxLevel)
            }
        default:
            break
        }
    }
    return result
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var maxLevels = [Int]()
    var currentLevel = 0
    var currentMaxLevel = 0
    var isOpenParen = false

    for char in parenString {
        if char == "(" {
            currentLevel += 1
            isOpenParen = true
        } else if char == ")" {
            currentLevel -= 1
            if isOpenParen {
                if currentMaxLevel < currentLevel {
                    currentMaxLevel = currentLevel
                }
                isOpenParen = false
            }
        } else if char == " " {
            if isOpenParen {
                currentMaxLevel = currentLevel
            }
            maxLevels.append(currentMaxLevel)
            currentLevel = 0
            currentMaxLevel = 0
            isOpenParen = false
        }
    }

    if isOpenParen {
        currentMaxLevel = currentLevel
    }
    maxLevels.append(currentMaxLevel)
    return maxLevels
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var maxLevels = [Int]()
    var currentLevel = 0
    var currentMaxLevel = 0
    var isOpenParen = false

    for char in parenString {
        if char == "(" {
            currentLevel += 1
            isOpenParen = true
        } else if char == ")" {
            currentLevel -= 1
            if isOpenParen {
                if currentMaxLevel < currentLevel {
                    currentMaxLevel = currentLevel
                }
                isOpenParen = false
            }
        } else if char == " " {
            if isOpenParen {
                currentMaxLevel = currentLevel
            }
            maxLevels.append(currentMaxLevel)
            currentLevel = 0
            currentMaxLevel = 0
            isOpenParen = false
        }
    }

    if isOpenParen {
        currentMaxLevel = currentLevel
    }
    maxLevels.append(currentMaxLevel)
    return maxLevels
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var result: [Int] = []
    var maxLevel: Int = 0
    var currentLevel: Int = 0
    var isOpen: Bool = false
    for char in parenString {
        if char == "(" {
            isOpen = true
            currentLevel += 1
            maxLevel = max(maxLevel, currentLevel)
        } else if char == ")" {
            isOpen = false
            currentLevel -= 1
        } else if char == " " {
            result.append(maxLevel)
            maxLevel = 0
            currentLevel = 0
            isOpen = false
        }
    }
    if isOpen {
        result.append(currentLevel)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result: [Int] = []
    var maxLevel: Int = 0
    var currentLevel: Int = 0
    var isOpen: Bool = false
    for char in parenString {
        if char == "(" {
            isOpen = true
            currentLevel += 1
            maxLevel = max(maxLevel, currentLevel)
        } else if char == ")" {
            isOpen = false
            currentLevel -= 1
        } else if char == " " {
            result.append(maxLevel)
            maxLevel = 0
            currentLevel = 0
            isOpen = false
        }
    }
    if isOpen {
        result.append(currentLevel)
    }
    return result
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var maxLevels: [Int] = []
    var currentLevel = 0
    var maxLevel = 0
    var isOpen = false
    for char in parenString {
        if char == "(" {
            currentLevel += 1
            if currentLevel > maxLevel {
                maxLevel = currentLevel
            }
            isOpen = true
        } else if char == ")" {
            currentLevel -= 1
            if isOpen {
                maxLevels.append(maxLevel)
                maxLevel = 0
            }
            isOpen = false
        } else if char == " " {
            if isOpen {
                maxLevels.append(maxLevel)
                maxLevel = 0
            }
            currentLevel = 0
            isOpen = false
        }
    }
    return maxLevels
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var maxLevels: [Int] = []
    var currentLevel = 0
    var maxLevel = 0
    var isOpen = false
    for char in parenString {
        if char == "(" {
            currentLevel += 1
            if currentLevel > maxLevel {
                maxLevel = currentLevel
            }
            isOpen = true
        } else if char == ")" {
            currentLevel -= 1
            if isOpen {
                maxLevels.append(maxLevel)
                maxLevel = 0
            }
            isOpen = false
        } else if char == " " {
            if isOpen {
                maxLevels.append(maxLevel)
                maxLevel = 0
            }
            currentLevel = 0
            isOpen = false
        }
    }
    return maxLevels
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var maxLevels = [Int]()
    var currentLevel = 0
    var currentMaxLevel = 0
    for char in parenString {
        if char == "(" {
            currentLevel += 1
            if currentLevel > currentMaxLevel {
                currentMaxLevel = currentLevel
            }
        } else if char == ")" {
            currentLevel -= 1
        }
        if char == " " && currentLevel == 0 {
            maxLevels.append(currentMaxLevel)
            currentMaxLevel = 0
        }
    }
    return maxLevels
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var maxLevels = [Int]()
    var currentLevel = 0
    var currentMaxLevel = 0
    for char in parenString {
        if char == "(" {
            currentLevel += 1
            if currentLevel > currentMaxLevel {
                currentMaxLevel = currentLevel
            }
        } else if char == ")" {
            currentLevel -= 1
        }
        if char == " " && currentLevel == 0 {
            maxLevels.append(currentMaxLevel)
            currentMaxLevel = 0
        }
    }
    return maxLevels
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var maxNesting = [Int]()
    var currentNesting = 0
    var maxNestingInCurrentGroup = 0
    var isInsideGroup = false
    var isOpenParen = false

    for char in parenString {
        if char == "(" {
            if isInsideGroup {
                currentNesting += 1
            } else {
                isInsideGroup = true
                currentNesting = 1
            }
            isOpenParen = true
        } else if char == ")" {
            if isOpenParen {
                maxNestingInCurrentGroup = max(maxNestingInCurrentGroup, currentNesting)
                currentNesting -= 1
                if currentNesting == 0 {
                    maxNesting.append(maxNestingInCurrentGroup)
                    maxNestingInCurrentGroup = 0
                    isInsideGroup = false
                }
            } else {
                currentNesting += 1
            }
            isOpenParen = false
        }
    }
    return maxNesting
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var maxNesting = [Int]()
    var currentNesting = 0
    var maxNestingInCurrentGroup = 0
    var isInsideGroup = false
    var isOpenParen = false

    for char in parenString {
        if char == "(" {
            if isInsideGroup {
                currentNesting += 1
            } else {
                isInsideGroup = true
                currentNesting = 1
            }
            isOpenParen = true
        } else if char == ")" {
            if isOpenParen {
                maxNestingInCurrentGroup = max(maxNestingInCurrentGroup, currentNesting)
                currentNesting -= 1
                if currentNesting == 0 {
                    maxNesting.append(maxNestingInCurrentGroup)
                    maxNestingInCurrentGroup = 0
                    isInsideGroup = false
                }
            } else {
                currentNesting += 1
            }
            isOpenParen = false
        }
    }
    return maxNesting
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var parenStack: [Int] = []
    var maxLevel = 0
    var result: [Int] = []
    for char in parenString {
        if char == "(" {
            parenStack.append(maxLevel)
            maxLevel = max(maxLevel, parenStack.count)
        } else if char == ")" {
            parenStack.removeLast()
        }
    }
    return parenStack
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var parenStack: [Int] = []
    var maxLevel = 0
    var result: [Int] = []
    for char in parenString {
        if char == "(" {
            parenStack.append(maxLevel)
            maxLevel = max(maxLevel, parenStack.count)
        } else if char == ")" {
            parenStack.removeLast()
        }
    }
    return parenStack
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var currentLevel = 0
    var maxLevel = 0
    for char in parenString {
        if char == "(" {
            currentLevel += 1
            if currentLevel > maxLevel {
                maxLevel = currentLevel
            }
        } else if char == ")" {
            currentLevel -= 1
        }
        if char == " " && currentLevel == 0 {
            result.append(maxLevel)
            maxLevel = 0
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var currentLevel = 0
    var maxLevel = 0
    for char in parenString {
        if char == "(" {
            currentLevel += 1
            if currentLevel > maxLevel {
                maxLevel = currentLevel
            }
        } else if char == ")" {
            currentLevel -= 1
        }
        if char == " " && currentLevel == 0 {
            result.append(maxLevel)
            maxLevel = 0
        }
    }
    return result
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var parenString = parenString
    var maxLevels = [Int]()
    var currentLevel = 0

    while !parenString.isEmpty {
        var openParens = 0
        var closeParens = 0

        for char in parenString {
            if char == "(" {
                openParens += 1
            } else if char == ")" {
                closeParens += 1
            }
        }

        if openParens == closeParens {
            maxLevels.append(openParens)
            parenString = String(parenString.dropFirst(openParens * 2))
            currentLevel = 0
        } else {
            currentLevel += 1
            maxLevels.append(currentLevel)
            parenString = String(parenString.dropFirst())
        }
    }

    return maxLevels
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var parenString = parenString
    var maxLevels = [Int]()
    var currentLevel = 0

    while !parenString.isEmpty {
        var openParens = 0
        var closeParens = 0

        for char in parenString {
            if char == "(" {
                openParens += 1
            } else if char == ")" {
                closeParens += 1
            }
        }

        if openParens == closeParens {
            maxLevels.append(openParens)
            parenString = String(parenString.dropFirst(openParens * 2))
            currentLevel = 0
        } else {
            currentLevel += 1
            maxLevels.append(currentLevel)
            parenString = String(parenString.dropFirst())
        }
    }

    return maxLevels
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    let sum = numbers.reduce(0, +)
    let product = numbers.reduce(1, *)
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    let sum = numbers.reduce(0, +)
    let product = numbers.reduce(1, *)
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    let sum = numbers.reduce(0, +)
    let product = numbers.reduce(1, *)
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    let sum = numbers.reduce(0, +)
    let product = numbers.reduce(1, *)
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var max: Int = 0
    for number in numbers {
        if number > max {
            max = number
        }
        result.append(max)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var max: Int = 0
    for number in numbers {
        if number > max {
            max = number
        }
        result.append(max)
    }
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var max: Int = 0
    for i in 0..<numbers.count {
        if numbers[i] > max {
            max = numbers[i]
        }
        result.append(max)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var max: Int = 0
    for i in 0..<numbers.count {
        if numbers[i] > max {
            max = numbers[i]
        }
        result.append(max)
    }
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = 0
    for num in numbers {
        if num > max {
            max = num
        }
        result.append(max)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = 0
    for num in numbers {
        if num > max {
            max = num
        }
        result.append(max)
    }
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var max: Int = 0
    for number in numbers {
        if number > max {
            max = number
        }
        result.append(max)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var max: Int = 0
    for number in numbers {
        if number > max {
            max = number
        }
        result.append(max)
    }
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = 0
    for num in numbers {
        if num > max {
            max = num
        }
        result.append(max)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = 0
    for num in numbers {
        if num > max {
            max = num
        }
        result.append(max)
    }
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = 0
    for num in numbers {
        if num > max {
            max = num
        }
        result.append(max)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = 0
    for num in numbers {
        if num > max {
            max = num
        }
        result.append(max)
    }
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = 0
    for num in numbers {
        if num > max {
            max = num
        }
        result.append(max)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = 0
    for num in numbers {
        if num > max {
            max = num
        }
        result.append(max)
    }
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = 0
    for num in numbers {
        if num > max {
            max = num
        }
        result.append(max)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = 0
    for num in numbers {
        if num > max {
            max = num
        }
        result.append(max)
    }
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var max: Int = 0
    for number in numbers {
        if number > max {
            max = number
        }
        result.append(max)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var max: Int = 0
    for number in numbers {
        if number > max {
            max = number
        }
        result.append(max)
    }
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = 0
    for num in numbers {
        if num > max {
            max = num
        }
        result.append(max)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = 0
    for num in numbers {
        if num > max {
            max = num
        }
        result.append(max)
    }
    return result
}
```

func makePalindrome(string: String) -> String {
    let reversedString = String(string.reversed())
    var suffix = string
    var prefix = ""
    while !suffix.isEmpty {
        if suffix == String(suffix.reversed()) {
            break
        }
        prefix = String(suffix.last!) + prefix
        suffix = String(suffix.dropLast())
    }
    return string + reversedString.prefix(reversedString.count - prefix.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    let reversedString = String(string.reversed())
    var suffix = string
    var prefix = ""
    while !suffix.isEmpty {
        if suffix == String(suffix.reversed()) {
            break
        }
        prefix = String(suffix.last!) + prefix
        suffix = String(suffix.dropLast())
    }
    return string + reversedString.prefix(reversedString.count - prefix.count)
}
```

func makePalindrome(string: String) -> String {
    let reversedString = String(string.reversed())
    var suffix = ""
    var prefix = ""
    for i in 0..<string.count {
        if string[i] == reversedString[i] {
            suffix += String(string[i])
        } else {
            prefix = String(string[i..<string.count])
            break
        }
    }
    return string + String(prefix.reversed())
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    let reversedString = String(string.reversed())
    var suffix = ""
    var prefix = ""
    for i in 0..<string.count {
        if string[i] == reversedString[i] {
            suffix += String(string[i])
        } else {
            prefix = String(string[i..<string.count])
            break
        }
    }
    return string + String(prefix.reversed())
}
```

func makePalindrome(string: String) -> String {
    let reversedString = String(string.reversed())
    var longestPalindrome = ""
    for i in 0..<string.count {
        let suffix = string[string.index(string.startIndex, offsetBy: i)...]
        if suffix == String(suffix.reversed()) {
            longestPalindrome = String(suffix)
        }
    }
    return string + reversedString[reversedString.index(reversedString.startIndex, offsetBy: longestPalindrome.count)...]
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    let reversedString = String(string.reversed())
    var longestPalindrome = ""
    for i in 0..<string.count {
        let suffix = string[string.index(string.startIndex, offsetBy: i)...]
        if suffix == String(suffix.reversed()) {
            longestPalindrome = String(suffix)
        }
    }
    return string + reversedString[reversedString.index(reversedString.startIndex, offsetBy: longestPalindrome.count)...]
}
```

func makePalindrome(string: String) -> String {
    let reversedString = String(string.reversed())
    var suffix = ""
    var prefix = ""
    var isPalindrome = false
    for i in 0..<string.count {
        suffix = String(string.suffix(i))
        prefix = String(string.prefix(i))
        if suffix == reversedString {
            isPalindrome = true
            break
        }
    }
    if isPalindrome {
        return string + String(prefix.reversed())
    } else {
        return string
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    let reversedString = String(string.reversed())
    var suffix = ""
    var prefix = ""
    var isPalindrome = false
    for i in 0..<string.count {
        suffix = String(string.suffix(i))
        prefix = String(string.prefix(i))
        if suffix == reversedString {
            isPalindrome = true
            break
        }
    }
    if isPalindrome {
        return string + String(prefix.reversed())
    } else {
        return string
    }
}
```

func makePalindrome(string: String) -> String {
    let reversedString = String(string.reversed())
    var longestPalindrome = ""
    for i in 0..<string.count {
        let palindrome = String(string.suffix(i))
        if palindrome == String(palindrome.reversed()) {
            longestPalindrome = palindrome
        }
    }
    return string + reversedString.dropFirst(longestPalindrome.count).reversed()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    let reversedString = String(string.reversed())
    var longestPalindrome = ""
    for i in 0..<string.count {
        let palindrome = String(string.suffix(i))
        if palindrome == String(palindrome.reversed()) {
            longestPalindrome = palindrome
        }
    }
    return string + reversedString.dropFirst(longestPalindrome.count).reversed()
}
```

func makePalindrome(string: String) -> String {
    let reversedString = String(string.reversed())
    var longestPalindrome = ""
    var palindromeStartIndex = string.startIndex
    var palindromeEndIndex = string.startIndex

    for i in 0..<string.count {
        let startIndex = string.index(string.startIndex, offsetBy: i)
        let endIndex = string.index(string.startIndex, offsetBy: string.count - i - 1)
        let substring = string[startIndex...endIndex]

        if substring == String(substring.reversed()) {
            longestPalindrome = String(substring)
            palindromeStartIndex = startIndex
            palindromeEndIndex = endIndex
        }
    }

    let prefix = string[..<palindromeStartIndex]
    let suffix = string[palindromeEndIndex...]

    return String(suffix) + String(prefix.reversed())
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    let reversedString = String(string.reversed())
    var longestPalindrome = ""
    var palindromeStartIndex = string.startIndex
    var palindromeEndIndex = string.startIndex

    for i in 0..<string.count {
        let startIndex = string.index(string.startIndex, offsetBy: i)
        let endIndex = string.index(string.startIndex, offsetBy: string.count - i - 1)
        let substring = string[startIndex...endIndex]

        if substring == String(substring.reversed()) {
            longestPalindrome = String(substring)
            palindromeStartIndex = startIndex
            palindromeEndIndex = endIndex
        }
    }

    let prefix = string[..<palindromeStartIndex]
    let suffix = string[palindromeEndIndex...]

    return String(suffix) + String(prefix.reversed())
}
```

func makePalindrome(string: String) -> String {
    let reversedString = String(string.reversed())
    let longestPalindrome = longestCommonSubstring(string: string, reversedString)
    return string + String(reversedString.prefix(reversedString.count - longestPalindrome.count))
}

func longestCommonSubstring(string: String, _ reversedString: String) -> String {
    var longestCommonSubstring = ""
    for i in 0..<string.count {
        let palindrome = String(string.suffix(string.count - i))
        if palindrome == String(reversedString.prefix(palindrome.count)) {
            longestCommonSubstring = palindrome
        }
    }
    return longestCommonSubstring
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    let reversedString = String(string.reversed())
    let longestPalindrome = longestCommonSubstring(string: string, reversedString)
    return string + String(reversedString.prefix(reversedString.count - longestPalindrome.count))
}

func longestCommonSubstring(string: String, _ reversedString: String) -> String {
    var longestCommonSubstring = ""
    for i in 0..<string.count {
        let palindrome = String(string.suffix(string.count - i))
        if palindrome == String(reversedString.prefix(palindrome.count)) {
            longestCommonSubstring = palindrome
        }
    }
    return longestCommonSubstring
}
```

func makePalindrome(string: String) -> String {
    let reversedString = String(string.reversed())
    let suffixLength = string.commonPrefix(with: reversedString).count
    return string + String(reversedString.dropFirst(suffixLength))
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    let reversedString = String(string.reversed())
    let suffixLength = string.commonPrefix(with: reversedString).count
    return string + String(reversedString.dropFirst(suffixLength))
}
```

func makePalindrome(string: String) -> String {
    let reversedString = String(string.reversed())
    let longestPalindrome = longestPalindromicSubstring(string: string)
    let prefix = string.prefix(string.count - longestPalindrome.count)
    return string + String(prefix.reversed())
}

func longestPalindromicSubstring(string: String) -> String {
    var longestPalindrome = ""
    for index in string.indices {
        let palindrome = String(string.suffix(from: index))
        if palindrome == String(palindrome.reversed()) {
            longestPalindrome = palindrome
        }
    }
    return longestPalindrome
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    let reversedString = String(string.reversed())
    let longestPalindrome = longestPalindromicSubstring(string: string)
    let prefix = string.prefix(string.count - longestPalindrome.count)
    return string + String(prefix.reversed())
}

func longestPalindromicSubstring(string: String) -> String {
    var longestPalindrome = ""
    for index in string.indices {
        let palindrome = String(string.suffix(from: index))
        if palindrome == String(palindrome.reversed()) {
            longestPalindrome = palindrome
        }
    }
    return longestPalindrome
}
```

func makePalindrome(string: String) -> String {
    let reversedString = String(string.reversed())
    let longestPalindrome = longestCommonSubstring(string, reversedString)
    let prefix = string.prefix(string.count - longestPalindrome.count)
    return string + String(prefix.reversed())
}

func longestCommonSubstring(_ string1: String, _ string2: String) -> String {
    var longestCommonSubstring = ""
    for i in 0..<string1.count {
        for j in 0..<string2.count {
            var currentSubstring = ""
            var k = i
            var l = j
            while k < string1.count && l < string2.count && string1[k] == string2[l] {
                currentSubstring.append(string1[k])
                k += 1
                l += 1
            }
            if currentSubstring.count > longestCommonSubstring.count {
                longestCommonSubstring = currentSubstring
            }
        }
    }
    return longestCommonSubstring
}

extension StringProtocol {
    subscript(_ offset: Int) -> Element { self[index(startIndex, offsetBy: offset)] }
    subscript(_ range: Range<Int>) -> SubSequence { prefix(range.lowerBound+range.count).suffix(range.count) }
    subscript(_ range: ClosedRange<Int>) -> SubSequence { prefix(range.lowerBound+range.count).suffix(range.count) }
    subscript(_ range: PartialRangeThrough<Int>) -> SubSequence { prefix(range.upperBound.advanced(by: 1)) }
    subscript(_ range: PartialRangeUpTo<Int>) -> SubSequence { prefix(range.upperBound) }
    subscript(_ range: PartialRangeFrom<Int>) -> SubSequence { suffix(Swift.max(0, count-range.lowerBound)) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    let reversedString = String(string.reversed())
    let longestPalindrome = longestCommonSubstring(string, reversedString)
    let prefix = string.prefix(string.count - longestPalindrome.count)
    return string + String(prefix.reversed())
}

func longestCommonSubstring(_ string1: String, _ string2: String) -> String {
    var longestCommonSubstring = ""
    for i in 0..<string1.count {
        for j in 0..<string2.count {
            var currentSubstring = ""
            var k = i
            var l = j
            while k < string1.count && l < string2.count && string1[k] == string2[l] {
                currentSubstring.append(string1[k])
                k += 1
                l += 1
            }
            if currentSubstring.count > longestCommonSubstring.count {
                longestCommonSubstring = currentSubstring
            }
        }
    }
    return longestCommonSubstring
}

extension StringProtocol {
    subscript(_ offset: Int) -> Element { self[index(startIndex, offsetBy: offset)] }
    subscript(_ range: Range<Int>) -> SubSequence { prefix(range.lowerBound+range.count).suffix(range.count) }
    subscript(_ range: ClosedRange<Int>) -> SubSequence { prefix(range.lowerBound+range.count).suffix(range.count) }
    subscript(_ range: PartialRangeThrough<Int>) -> SubSequence { prefix(range.upperBound.advanced(by: 1)) }
    subscript(_ range: PartialRangeUpTo<Int>) -> SubSequence { prefix(range.upperBound) }
    subscript(_ range: PartialRangeFrom<Int>) -> SubSequence { suffix(Swift.max(0, count-range.lowerBound)) }
}
```

func stringXor(a: String, b: String) -> String {
    let a = Array(a)
    let b = Array(b)
    let result = zip(a, b).map { $0 != $1 ? "1" : "0" }
    return String(result)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    let a = Array(a)
    let b = Array(b)
    let result = zip(a, b).map { $0 != $1 ? "1" : "0" }
    return String(result)
}
```

func stringXor(a: String, b: String) -> String {
    var result = ""
    for (i, j) in zip(a, b) {
        result.append(i == j ? "0" : "1")
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for (i, j) in zip(a, b) {
        result.append(i == j ? "0" : "1")
    }
    return result
}
```

func stringXor(a: String, b: String) -> String {
    var result = ""
    for (i, j) in zip(a, b) {
        result.append(i == j ? "0" : "1")
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for (i, j) in zip(a, b) {
        result.append(i == j ? "0" : "1")
    }
    return result
}
```

func stringXor(a: String, b: String) -> String {
    let a = a.map { $0 == "1" }
    let b = b.map { $0 == "1" }
    let result = zip(a, b).map { $0 != $1 }
    return result.map { $0 ? "1" : "0" }.joined()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    let a = a.map { $0 == "1" }
    let b = b.map { $0 == "1" }
    let result = zip(a, b).map { $0 != $1 }
    return result.map { $0 ? "1" : "0" }.joined()
}
```

func stringXor(a: String, b: String) -> String {
    var result = ""
    for (i, j) in zip(a, b) {
        if i == j {
            result += "0"
        } else {
            result += "1"
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for (i, j) in zip(a, b) {
        if i == j {
            result += "0"
        } else {
            result += "1"
        }
    }
    return result
}
```

func stringXor(a: String, b: String) -> String {
    var result = ""
    for (i, j) in zip(a, b) {
        if i == j {
            result += "0"
        } else {
            result += "1"
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for (i, j) in zip(a, b) {
        if i == j {
            result += "0"
        } else {
            result += "1"
        }
    }
    return result
}
```

func stringXor(a: String, b: String) -> String {
    let a = Array(a)
    let b = Array(b)
    var result = ""
    for i in 0..<a.count {
        result += a[i] == b[i] ? "0" : "1"
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    let a = Array(a)
    let b = Array(b)
    var result = ""
    for i in 0..<a.count {
        result += a[i] == b[i] ? "0" : "1"
    }
    return result
}
```

func stringXor(a: String, b: String) -> String {
    let a = Array(a)
    let b = Array(b)
    let result = zip(a, b).map { $0 == $1 ? "0" : "1" }
    return result.joined()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    let a = Array(a)
    let b = Array(b)
    let result = zip(a, b).map { $0 == $1 ? "0" : "1" }
    return result.joined()
}
```

func stringXor(a: String, b: String) -> String {
    var result = ""
    for (i, j) in zip(a, b) {
        result += i == j ? "0" : "1"
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for (i, j) in zip(a, b) {
        result += i == j ? "0" : "1"
    }
    return result
}
```

func stringXor(a: String, b: String) -> String {
    let a = Array(a)
    let b = Array(b)
    let result = a.enumerated().map { (i, char) -> String in
        return char == b[i] ? "0" : "1"
    }
    return result.joined()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    let a = Array(a)
    let b = Array(b)
    let result = a.enumerated().map { (i, char) -> String in
        return char == b[i] ? "0" : "1"
    }
    return result.joined()
}
```

func longest(strings: [String]) -> String? {
    guard let max = strings.max(by: { $0.count < $1.count }) else {
        return nil
    }
    return max
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    guard let max = strings.max(by: { $0.count < $1.count }) else {
        return nil
    }
    return max
}
```

func longest(strings: [String]) -> String? {
    guard let max = strings.max(by: { $0.count < $1.count }) else { return nil }
    return max
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    guard let max = strings.max(by: { $0.count < $1.count }) else { return nil }
    return max
}
```

func longest(strings: [String]) -> String? {
    guard let max = strings.max(by: { $0.count < $1.count }) else { return nil }
    return max
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    guard let max = strings.max(by: { $0.count < $1.count }) else { return nil }
    return max
}
```

func longest(strings: [String]) -> String? {
    guard let firstString = strings.first else { return nil }
    var longestString = firstString
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }
    return longestString
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    guard let firstString = strings.first else { return nil }
    var longestString = firstString
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }
    return longestString
}
```

func longest(strings: [String]) -> String? {
    guard let maxString = strings.max(by: { $0.count < $1.count }) else { return nil }
    return maxString
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    guard let maxString = strings.max(by: { $0.count < $1.count }) else { return nil }
    return maxString
}
```

func longest(strings: [String]) -> String? {
    guard let firstString = strings.first else { return nil }
    var longestString = firstString
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }
    return longestString
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    guard let firstString = strings.first else { return nil }
    var longestString = firstString
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }
    return longestString
}
```

func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    return strings.max { $0.count < $1.count }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    return strings.max { $0.count < $1.count }
}
```

func longest(strings: [String]) -> String? {
    guard let max = strings.max(by: { $0.count < $1.count }) else { return nil }
    return max
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    guard let max = strings.max(by: { $0.count < $1.count }) else { return nil }
    return max
}
```

func longest(strings: [String]) -> String? {
    guard let max = strings.max(by: { $0.count < $1.count }) else { return nil }
    return max
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    guard let max = strings.max(by: { $0.count < $1.count }) else { return nil }
    return max
}
```

func longest(strings: [String]) -> String? {
    guard let max = strings.max(by: {$0.count < $1.count}) else { return nil }
    return max
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    guard let max = strings.max(by: {$0.count < $1.count}) else { return nil }
    return max
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var x = 0
    var y = max(a, b)
    var z = min(a, b)
    while z != 0 {
        x = y
        y = z
        z = x % y
    }
    return y
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var x = 0
    var y = max(a, b)
    var z = min(a, b)
    while z != 0 {
        x = y
        y = z
        z = x % y
    }
    return y
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var x = 0
    var y = max(a, b)
    var z = min(a, b)
    while z != 0 {
        x = y
        y = z
        z = x % y
    }
    return y
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var x = 0
    var y = max(a, b)
    var z = min(a, b)
    while z != 0 {
        x = y
        y = z
        z = x % y
    }
    return y
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let tmp = b
        b = a % b
        a = tmp
    }
    return a
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let tmp = b
        b = a % b
        a = tmp
    }
    return a
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let tmp = b
        b = a % b
        a = tmp
    }
    return a
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let tmp = b
        b = a % b
        a = tmp
    }
    return a
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        let index = string.index(string.startIndex, offsetBy: i)
        prefixes.append(String(string[..<index]))
    }
    return prefixes
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        let index = string.index(string.startIndex, offsetBy: i)
        prefixes.append(String(string[..<index]))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 1...string.count {
        prefixes.append(String(string.prefix(i)))
    }
    return prefixes
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 1...string.count {
        prefixes.append(String(string.prefix(i)))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 0...string.count {
        prefixes.append(String(string.prefix(i)))
    }
    return prefixes
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 0...string.count {
        prefixes.append(String(string.prefix(i)))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 1...string.count {
        prefixes.append(String(string.prefix(i)))
    }
    return prefixes
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 1...string.count {
        prefixes.append(String(string.prefix(i)))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 1...string.count {
        prefixes.append(String(string.prefix(i)))
    }
    return prefixes
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 1...string.count {
        prefixes.append(String(string.prefix(i)))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}
```

func stringSequence(n: Int) -> String {
    return (0...n).map { String($0) }.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    return (0...n).map { String($0) }.joined(separator: " ")
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in: .whitespaces)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in: .whitespaces)
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result
}
```

func stringSequence(n: Int) -> String {
    return (0...n).map { String($0) }.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    return (0...n).map { String($0) }.joined(separator: " ")
}
```

func stringSequence(n: Int) -> String {
    return (0...n).map { String($0) }.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    return (0...n).map { String($0) }.joined(separator: " ")
}
```

func stringSequence(n: Int) -> String {
    return (0...n).map { String($0) }.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    return (0...n).map { String($0) }.joined(separator: " ")
}
```

func stringSequence(n: Int) -> String {
    return (0...n).map { String($0) }.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    return (0...n).map { String($0) }.joined(separator: " ")
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result
}
```

func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}
```

func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}
```

func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    var distinctChars: Set<Character> = []
    for char in lowercaseString {
        distinctChars.insert(char)
    }
    return distinctChars.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    var distinctChars: Set<Character> = []
    for char in lowercaseString {
        distinctChars.insert(char)
    }
    return distinctChars.count
}
```

func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}
```

func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}
```

func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}
```

func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}
```

func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}
```

func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}
```

func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}
```

func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.components(separatedBy: " ")
    var beats = [Int]()
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.components(separatedBy: " ")
    var beats = [Int]()
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var result: [Int] = []
    for char in musicString {
        switch char {
        case "o":
            result.append(4)
        case "|":
            result.append(2)
        case ".":
            result.append(1)
        default:
            break
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    var result: [Int] = []
    for char in musicString {
        switch char {
        case "o":
            result.append(4)
        case "|":
            result.append(2)
        case ".":
            result.append(1)
        default:
            break
        }
    }
    return result
}
```

func parseMusic(musicString: String) -> [Int] {
    var result: [Int] = []
    for char in musicString {
        switch char {
        case "o":
            result.append(4)
        case "|":
            result.append(2)
        case ".":
            result.append(1)
        default:
            break
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    var result: [Int] = []
    for char in musicString {
        switch char {
        case "o":
            result.append(4)
        case "|":
            result.append(2)
        case ".":
            result.append(1)
        default:
            break
        }
    }
    return result
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats: [Int] = []
    for char in musicString {
        switch char {
        case "o":
            beats.append(4)
        case "|":
            beats.append(2)
        case ".":
            beats.append(1)
        default:
            continue
        }
    }
    return beats
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats: [Int] = []
    for char in musicString {
        switch char {
        case "o":
            beats.append(4)
        case "|":
            beats.append(2)
        case ".":
            beats.append(1)
        default:
            continue
        }
    }
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var notes = [Int]()
    for char in musicString {
        switch char {
        case "o":
            notes.append(4)
        case "|":
            notes.append(2)
        case ".":
            notes.append(1)
        default:
            break
        }
    }
    return notes
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    var notes = [Int]()
    for char in musicString {
        switch char {
        case "o":
            notes.append(4)
        case "|":
            notes.append(2)
        case ".":
            notes.append(1)
        default:
            break
        }
    }
    return notes
}
```

func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats: [Int] = []
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats: [Int] = []
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var result: [Int] = []
    for char in musicString {
        switch char {
        case "o":
            result.append(4)
        case "|":
            result.append(2)
        case ".":
            result.append(1)
        default:
            break
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    var result: [Int] = []
    for char in musicString {
        switch char {
        case "o":
            result.append(4)
        case "|":
            result.append(2)
        case ".":
            result.append(1)
        default:
            break
        }
    }
    return result
}
```

func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats = [Int]()
    for note in notes {
        if note == "o" {
            beats.append(4)
        } else if note == "o|" {
            beats.append(2)
        } else if note == ".|" {
            beats.append(1)
        }
    }
    return beats
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats = [Int]()
    for note in notes {
        if note == "o" {
            beats.append(4)
        } else if note == "o|" {
            beats.append(2)
        } else if note == ".|" {
            beats.append(1)
        }
    }
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var result: [Int] = []
    for char in musicString {
        switch char {
        case "o":
            result.append(4)
        case "|":
            result.append(2)
        case ".":
            result.append(1)
        default:
            break
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    var result: [Int] = []
    for char in musicString {
        switch char {
        case "o":
            result.append(4)
        case "|":
            result.append(2)
        case ".":
            result.append(1)
        default:
            break
        }
    }
    return result
}
```

func parseMusic(musicString: String) -> [Int] {
    var result: [Int] = []
    var string = musicString
    while !string.isEmpty {
        if string.hasPrefix("o") {
            result.append(4)
            string.removeFirst()
        } else if string.hasPrefix("o|") {
            result.append(2)
            string.removeFirst(2)
        } else if string.hasPrefix(".|") {
            result.append(1)
            string.removeFirst(2)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    var result: [Int] = []
    var string = musicString
    while !string.isEmpty {
        if string.hasPrefix("o") {
            result.append(4)
            string.removeFirst()
        } else if string.hasPrefix("o|") {
            result.append(2)
            string.removeFirst(2)
        } else if string.hasPrefix(".|") {
            result.append(1)
            string.removeFirst(2)
        }
    }
    return result
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var i = string.startIndex
    while i < string.endIndex {
        if string[i...].starts(with: substring) {
            count += 1
            i = string.index(i, offsetBy: substring.count)
        } else {
            i = string.index(after: i)
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var i = string.startIndex
    while i < string.endIndex {
        if string[i...].starts(with: substring) {
            count += 1
            i = string.index(i, offsetBy: substring.count)
        } else {
            i = string.index(after: i)
        }
    }
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var i = string.startIndex
    while i < string.endIndex {
        if string[i...].hasPrefix(substring) {
            count += 1
            i = string.index(i, offsetBy: substring.count)
        } else {
            i = string.index(after: i)
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var i = string.startIndex
    while i < string.endIndex {
        if string[i...].hasPrefix(substring) {
            count += 1
            i = string.index(i, offsetBy: substring.count)
        } else {
            i = string.index(after: i)
        }
    }
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var i = string.startIndex
    while i < string.endIndex {
        if string[i...].starts(with: substring) {
            count += 1
            i = string.index(i, offsetBy: substring.count - 1)
        }
        i = string.index(after: i)
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var i = string.startIndex
    while i < string.endIndex {
        if string[i...].starts(with: substring) {
            count += 1
            i = string.index(i, offsetBy: substring.count - 1)
        }
        i = string.index(after: i)
    }
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var start = string.startIndex
    while start < string.endIndex,
          let range = string[start...].range(of: substring),
          !range.isEmpty {
        count += 1
        start = range.upperBound
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var start = string.startIndex
    while start < string.endIndex,
          let range = string[start...].range(of: substring),
          !range.isEmpty {
        count += 1
        start = range.upperBound
    }
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var i = string.startIndex
    while i < string.endIndex {
        if string[i...].hasPrefix(substring) {
            count += 1
            i = string.index(i, offsetBy: substring.count)
        } else {
            i = string.index(after: i)
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var i = string.startIndex
    while i < string.endIndex {
        if string[i...].hasPrefix(substring) {
            count += 1
            i = string.index(i, offsetBy: substring.count)
        } else {
            i = string.index(after: i)
        }
    }
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var i = string.startIndex
    while i < string.endIndex {
        if string[i...].starts(with: substring) {
            count += 1
            i = string.index(i, offsetBy: substring.count)
        } else {
            i = string.index(after: i)
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var i = string.startIndex
    while i < string.endIndex {
        if string[i...].starts(with: substring) {
            count += 1
            i = string.index(i, offsetBy: substring.count)
        } else {
            i = string.index(after: i)
        }
    }
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    while index != string.endIndex {
        if string[index...].starts(with: substring) {
            count += 1
            index = string.index(index, offsetBy: substring.count)
        } else {
            index = string.index(after: index)
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    while index != string.endIndex {
        if string[index...].starts(with: substring) {
            count += 1
            index = string.index(index, offsetBy: substring.count)
        } else {
            index = string.index(after: index)
        }
    }
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var i = string.startIndex
    while i < string.endIndex {
        if string[i...].hasPrefix(substring) {
            count += 1
            i = string.index(i, offsetBy: substring.count)
        } else {
            i = string.index(after: i)
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var i = string.startIndex
    while i < string.endIndex {
        if string[i...].hasPrefix(substring) {
            count += 1
            i = string.index(i, offsetBy: substring.count)
        } else {
            i = string.index(after: i)
        }
    }
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    while index != string.endIndex {
        if string[index] == substring.first {
            var i = index
            var j = substring.startIndex
            var found = true
            while j != substring.endIndex {
                if i == string.endIndex {
                    found = false
                    break
                }
                if string[i] != substring[j] {
                    found = false
                    break
                }
                i = string.index(after: i)
                j = substring.index(after: j)
            }
            if found {
                count += 1
            }
        }
        index = string.index(after: index)
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    while index != string.endIndex {
        if string[index] == substring.first {
            var i = index
            var j = substring.startIndex
            var found = true
            while j != substring.endIndex {
                if i == string.endIndex {
                    found = false
                    break
                }
                if string[i] != substring[j] {
                    found = false
                    break
                }
                i = string.index(after: i)
                j = substring.index(after: j)
            }
            if found {
                count += 1
            }
        }
        index = string.index(after: index)
    }
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var startIndex = string.startIndex
    while startIndex < string.endIndex,
          let range = string[startIndex...].range(of: substring),
          !range.isEmpty {
        count += 1
        startIndex = range.upperBound
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var startIndex = string.startIndex
    while startIndex < string.endIndex,
          let range = string[startIndex...].range(of: substring),
          !range.isEmpty {
        count += 1
        startIndex = range.upperBound
    }
    return count
}
```

func sortNumbers(numbers: String) -> String {
    let numberArray = numbers.components(separatedBy: " ")
    let sortedArray = numberArray.sorted { $0 < $1 }
    let sortedString = sortedArray.joined(separator: " ")
    return sortedString
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    let numberArray = numbers.components(separatedBy: " ")
    let sortedArray = numberArray.sorted { $0 < $1 }
    let sortedString = sortedArray.joined(separator: " ")
    return sortedString
}
```

func sortNumbers(numbers: String) -> String {
    let numberals = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
    let numbersArray = numbers.components(separatedBy: " ")
    let sortedNumbers = numbersArray.sorted { numberals.firstIndex(of: $0)! < numberals.firstIndex(of: $1)! }
    return sortedNumbers.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    let numberals = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
    let numbersArray = numbers.components(separatedBy: " ")
    let sortedNumbers = numbersArray.sorted { numberals.firstIndex(of: $0)! < numberals.firstIndex(of: $1)! }
    return sortedNumbers.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numberals = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
    let numbersArray = numbers.components(separatedBy: " ")
    let sortedNumbersArray = numbersArray.sorted { numberals.firstIndex(of: $0)! < numberals.firstIndex(of: $1)! }
    return sortedNumbersArray.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    let numberals = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
    let numbersArray = numbers.components(separatedBy: " ")
    let sortedNumbersArray = numbersArray.sorted { numberals.firstIndex(of: $0)! < numberals.firstIndex(of: $1)! }
    return sortedNumbersArray.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numbersArray = numbers.components(separatedBy: " ")
    let sortedNumbersArray = numbersArray.sorted()
    let sortedNumbersString = sortedNumbersArray.joined(separator: " ")
    return sortedNumbersString
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    let numbersArray = numbers.components(separatedBy: " ")
    let sortedNumbersArray = numbersArray.sorted()
    let sortedNumbersString = sortedNumbersArray.joined(separator: " ")
    return sortedNumbersString
}
```

func sortNumbers(numbers: String) -> String {
    let nums = numbers.components(separatedBy: " ")
    let sortedNums = nums.sorted { (num1, num2) -> Bool in
        return num1 < num2
    }
    return sortedNums.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    let nums = numbers.components(separatedBy: " ")
    let sortedNums = nums.sorted { (num1, num2) -> Bool in
        return num1 < num2
    }
    return sortedNums.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let sortedNumberals = numberals.sorted()
    return sortedNumberals.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let sortedNumberals = numberals.sorted()
    return sortedNumberals.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let sorted = numberals.sorted()
    return sorted.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let sorted = numberals.sorted()
    return sorted.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numberArray = numbers.components(separatedBy: " ")
    let sortedArray = numberArray.sorted { (first, second) -> Bool in
        return first < second
    }
    return sortedArray.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    let numberArray = numbers.components(separatedBy: " ")
    let sortedArray = numberArray.sorted { (first, second) -> Bool in
        return first < second
    }
    return sortedArray.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let sortedNumberals = numberals.sorted()
    let sortedNumbers = sortedNumberals.joined(separator: " ")
    return sortedNumbers
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let sortedNumberals = numberals.sorted()
    let sortedNumbers = sortedNumberals.joined(separator: " ")
    return sortedNumbers
}
```

func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let sortedNumberals = numberals.sorted()
    let sortedNumbers = sortedNumberals.joined(separator: " ")
    return sortedNumbers
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let sortedNumberals = numberals.sorted()
    let sortedNumbers = sortedNumberals.joined(separator: " ")
    return sortedNumbers
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closestElements: (Double, Double) = (0.0, 0.0)
    var closestDistance: Double = 0.0
    for i in 0..<numbers.count - 1 {
        let distance = numbers[i + 1] - numbers[i]
        if closestDistance == 0.0 || distance < closestDistance {
            closestDistance = distance
            closestElements = (numbers[i], numbers[i + 1])
        }
    }
    return closestElements
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closestElements: (Double, Double) = (0.0, 0.0)
    var closestDistance: Double = 0.0
    for i in 0..<numbers.count - 1 {
        let distance = numbers[i + 1] - numbers[i]
        if closestDistance == 0.0 || distance < closestDistance {
            closestDistance = distance
            closestElements = (numbers[i], numbers[i + 1])
        }
    }
    return closestElements
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closestElements: (Double, Double) = (0, 0)
    var closestDistance: Double = 0
    for i in 0..<numbers.count - 1 {
        let distance = numbers[i + 1] - numbers[i]
        if closestDistance == 0 || distance < closestDistance {
            closestDistance = distance
            closestElements = (numbers[i], numbers[i + 1])
        }
    }
    return closestElements
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closestElements: (Double, Double) = (0, 0)
    var closestDistance: Double = 0
    for i in 0..<numbers.count - 1 {
        let distance = numbers[i + 1] - numbers[i]
        if closestDistance == 0 || distance < closestDistance {
            closestDistance = distance
            closestElements = (numbers[i], numbers[i + 1])
        }
    }
    return closestElements
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closest: (Double, Double) = (0.0, 0.0)
    var closestDiff: Double = 0.0
    for i in 0..<numbers.count - 1 {
        for j in i+1..<numbers.count {
            let diff = numbers[j] - numbers[i]
            if closestDiff == 0.0 || diff <= closestDiff {
                closestDiff = diff
                closest = (numbers[i], numbers[j])
            }
        }
    }
    return closest
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closest: (Double, Double) = (0.0, 0.0)
    var closestDiff: Double = 0.0
    for i in 0..<numbers.count - 1 {
        for j in i+1..<numbers.count {
            let diff = numbers[j] - numbers[i]
            if closestDiff == 0.0 || diff <= closestDiff {
                closestDiff = diff
                closest = (numbers[i], numbers[j])
            }
        }
    }
    return closest
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closest: (Double, Double) = (0, 0)
    var minDiff: Double = 0
    for i in 0..<numbers.count - 1 {
        for j in i+1..<numbers.count {
            let diff = numbers[j] - numbers[i]
            if (minDiff == 0) || (diff < minDiff) {
                minDiff = diff
                closest = (numbers[i], numbers[j])
            }
        }
    }
    return closest
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closest: (Double, Double) = (0, 0)
    var minDiff: Double = 0
    for i in 0..<numbers.count - 1 {
        for j in i+1..<numbers.count {
            let diff = numbers[j] - numbers[i]
            if (minDiff == 0) || (diff < minDiff) {
                minDiff = diff
                closest = (numbers[i], numbers[j])
            }
        }
    }
    return closest
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closestElements: (Double, Double) = (0, 0)
    var closestDistance: Double = 0
    for (index, element) in numbers.enumerated() {
        for (index2, element2) in numbers.enumerated() {
            if index != index2 {
                let distance = abs(element - element2)
                if closestDistance == 0 || distance < closestDistance {
                    closestDistance = distance
                    closestElements = (element, element2)
                }
            }
        }
    }
    return closestElements
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closestElements: (Double, Double) = (0, 0)
    var closestDistance: Double = 0
    for (index, element) in numbers.enumerated() {
        for (index2, element2) in numbers.enumerated() {
            if index != index2 {
                let distance = abs(element - element2)
                if closestDistance == 0 || distance < closestDistance {
                    closestDistance = distance
                    closestElements = (element, element2)
                }
            }
        }
    }
    return closestElements
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closestElements: (Double, Double) = (0, 0)
    var closestDifference: Double = 0

    for i in 0..<numbers.count - 1 {
        let difference = numbers[i + 1] - numbers[i]

        if i == 0 || difference < closestDifference {
            closestDifference = difference
            closestElements = (numbers[i], numbers[i + 1])
        }
    }

    return closestElements
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closestElements: (Double, Double) = (0, 0)
    var closestDifference: Double = 0

    for i in 0..<numbers.count - 1 {
        let difference = numbers[i + 1] - numbers[i]

        if i == 0 || difference < closestDifference {
            closestDifference = difference
            closestElements = (numbers[i], numbers[i + 1])
        }
    }

    return closestElements
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closestElements: (Double, Double) = (0, 0)
    var closestDistance: Double = 0
    for (index, element) in numbers.enumerated() {
        for (index2, element2) in numbers.enumerated() {
            if index != index2 {
                let distance = abs(element - element2)
                if closestDistance == 0 {
                    closestDistance = distance
                    closestElements = (element, element2)
                } else if distance < closestDistance {
                    closestDistance = distance
                    closestElements = (element, element2)
                }
            }
        }
    }
    return closestElements
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closestElements: (Double, Double) = (0, 0)
    var closestDistance: Double = 0
    for (index, element) in numbers.enumerated() {
        for (index2, element2) in numbers.enumerated() {
            if index != index2 {
                let distance = abs(element - element2)
                if closestDistance == 0 {
                    closestDistance = distance
                    closestElements = (element, element2)
                } else if distance < closestDistance {
                    closestDistance = distance
                    closestElements = (element, element2)
                }
            }
        }
    }
    return closestElements
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closestElements: (Double, Double) = (0, 0)
    var closestDistance: Double = 0
    for (index, number) in numbers.enumerated() {
        for (index2, number2) in numbers.enumerated() {
            if index != index2 {
                let distance = abs(number - number2)
                if closestDistance == 0 || distance < closestDistance {
                    closestDistance = distance
                    closestElements = (number, number2)
                }
            }
        }
    }
    return closestElements
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closestElements: (Double, Double) = (0, 0)
    var closestDistance: Double = 0
    for (index, number) in numbers.enumerated() {
        for (index2, number2) in numbers.enumerated() {
            if index != index2 {
                let distance = abs(number - number2)
                if closestDistance == 0 || distance < closestDistance {
                    closestDistance = distance
                    closestElements = (number, number2)
                }
            }
        }
    }
    return closestElements
}
```

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closestElements: (Double, Double) = (0.0, 0.0)
    var closestDistance: Double = 100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closestElements: (Double, Double) = (0.0, 0.0)
    var closestDistance: Double = 100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min() ?? 0
    let max = numbers.max() ?? 0
    let range = max - min
    return numbers.map { (($0 - min) / range) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min() ?? 0
    let max = numbers.max() ?? 0
    let range = max - min
    return numbers.map { (($0 - min) / range) }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min() ?? 0
    let max = numbers.max() ?? 0
    return numbers.map { ($0 - min) / (max - min) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min() ?? 0
    let max = numbers.max() ?? 0
    return numbers.map { ($0 - min) / (max - min) }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min() ?? 0
    let max = numbers.max() ?? 0
    let range = max - min
    return numbers.map { (($0 - min) / range) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min() ?? 0
    let max = numbers.max() ?? 0
    let range = max - min
    return numbers.map { (($0 - min) / range) }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min() ?? 0
    let max = numbers.max() ?? 0
    return numbers.map { ($0 - min) / (max - min) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min() ?? 0
    let max = numbers.max() ?? 0
    return numbers.map { ($0 - min) / (max - min) }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min() ?? 0
    let max = numbers.max() ?? 0
    let range = max - min
    return numbers.map { ($0 - min) / range }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min() ?? 0
    let max = numbers.max() ?? 0
    let range = max - min
    return numbers.map { ($0 - min) / range }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min() ?? 0
    let max = numbers.max() ?? 0
    return numbers.map { ($0 - min) / (max - min) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min() ?? 0
    let max = numbers.max() ?? 0
    return numbers.map { ($0 - min) / (max - min) }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min() ?? 0
    let max = numbers.max() ?? 0
    let range = max - min
    return numbers.map { (($0 - min) / range) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min() ?? 0
    let max = numbers.max() ?? 0
    let range = max - min
    return numbers.map { (($0 - min) / range) }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min() ?? 0
    let max = numbers.max() ?? 0
    let range = max - min
    return numbers.map { (($0 - min) / range) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min() ?? 0
    let max = numbers.max() ?? 0
    let range = max - min
    return numbers.map { (($0 - min) / range) }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min() ?? 0
    let max = numbers.max() ?? 1
    return numbers.map { (($0 - min) / (max - min)) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min() ?? 0
    let max = numbers.max() ?? 1
    return numbers.map { (($0 - min) / (max - min)) }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min() ?? 0
    let max = numbers.max() ?? 0
    let range = max - min
    return numbers.map { (($0 - min) / range) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min() ?? 0
    let max = numbers.max() ?? 0
    let range = max - min
    return numbers.map { (($0 - min) / range) }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    var result: [Int] = []
    for value in values {
        if let intValue = value as? Int {
            result.append(intValue)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    var result: [Int] = []
    for value in values {
        if let intValue = value as? Int {
            result.append(intValue)
        }
    }
    return result
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    var result: [Int] = []
    for value in values {
        if let intValue = value as? Int {
            result.append(intValue)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    var result: [Int] = []
    for value in values {
        if let intValue = value as? Int {
            result.append(intValue)
        }
    }
    return result
}
```

func strlen(string: String) -> Int {
    return string.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = 1
    for i in 2...n {
        if n % i == 0 {
            divisor = i
        }
    }
    return divisor
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = 1
    for i in 2...n {
        if n % i == 0 {
            divisor = i
        }
    }
    return divisor
}
```

func largestDivisor(n: Int) -> Int {
    for i in stride(from: n, through: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return 1
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    for i in stride(from: n, through: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = 1
    for i in 2...n {
        if n % i == 0 {
            divisor = i
        }
    }
    return divisor
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = 1
    for i in 2...n {
        if n % i == 0 {
            divisor = i
        }
    }
    return divisor
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = 1
    for i in 2...n/2 {
        if n % i == 0 {
            divisor = i
        }
    }
    return divisor
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = 1
    for i in 2...n/2 {
        if n % i == 0 {
            divisor = i
        }
    }
    return divisor
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = 1
    for i in 2...n/2 {
        if n % i == 0 {
            divisor = i
        }
    }
    return divisor
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = 1
    for i in 2...n/2 {
        if n % i == 0 {
            divisor = i
        }
    }
    return divisor
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        if n % divisor == 0 {
            break
        }
        divisor -= 1
    }
    return divisor
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        if n % divisor == 0 {
            break
        }
        divisor -= 1
    }
    return divisor
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = 1
    for i in 2...n/2 {
        if n % i == 0 {
            divisor = i
        }
    }
    return divisor
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = 1
    for i in 2...n/2 {
        if n % i == 0 {
            divisor = i
        }
    }
    return divisor
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        if n % divisor == 0 {
            break
        }
        divisor -= 1
    }
    return divisor
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        if n % divisor == 0 {
            break
        }
        divisor -= 1
    }
    return divisor
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = 1
    for i in 2...n {
        if n % i == 0 {
            divisor = i
        }
    }
    return divisor
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = 1
    for i in 2...n {
        if n % i == 0 {
            divisor = i
        }
    }
    return divisor
}
```

func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var divisor = 2
    while n > 1 {
        if n % divisor == 0 {
            factors.append(divisor)
            n /= divisor
        } else {
            divisor += 1
        }
    }
    return factors
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var divisor = 2
    while n > 1 {
        if n % divisor == 0 {
            factors.append(divisor)
            n /= divisor
        } else {
            divisor += 1
        }
    }
    return factors
}
```

func factorize(n: Int) -> [Int] {
    var result: [Int] = []
    var n = n
    for i in 2...n {
        while n % i == 0 {
            result.append(i)
            n /= i
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var result: [Int] = []
    var n = n
    for i in 2...n {
        while n % i == 0 {
            result.append(i)
            n /= i
        }
    }
    return result
}
```

func factorize(n: Int) -> [Int] {
    var result: [Int] = []
    var n = n
    for i in 2...n {
        while n % i == 0 {
            result.append(i)
            n /= i
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var result: [Int] = []
    var n = n
    for i in 2...n {
        while n % i == 0 {
            result.append(i)
            n /= i
        }
    }
    return result
}
```

func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var num = n
    for i in 2...num {
        while num % i == 0 {
            factors.append(i)
            num /= i
        }
    }
    return factors
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var num = n
    for i in 2...num {
        while num % i == 0 {
            factors.append(i)
            num /= i
        }
    }
    return factors
}
```

func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var n = n
    for i in 2...Int(sqrt(Double(n))) {
        while n % i == 0 {
            factors.append(i)
            n /= i
        }
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var n = n
    for i in 2...Int(sqrt(Double(n))) {
        while n % i == 0 {
            factors.append(i)
            n /= i
        }
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}
```

func factorize(n: Int) -> [Int] {
    var result: [Int] = []
    var n = n
    for i in 2...n {
        while n % i == 0 {
            result.append(i)
            n /= i
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var result: [Int] = []
    var n = n
    for i in 2...n {
        while n % i == 0 {
            result.append(i)
            n /= i
        }
    }
    return result
}
```

func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var num = n
    for i in 2...num {
        while num % i == 0 {
            factors.append(i)
            num /= i
        }
    }
    return factors
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var num = n
    for i in 2...num {
        while num % i == 0 {
            factors.append(i)
            num /= i
        }
    }
    return factors
}
```

func factorize(n: Int) -> [Int] {
    var result: [Int] = []
    var num = n
    for i in 2...num {
        while num % i == 0 {
            result.append(i)
            num /= i
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var result: [Int] = []
    var num = n
    for i in 2...num {
        while num % i == 0 {
            result.append(i)
            num /= i
        }
    }
    return result
}
```

func factorize(n: Int) -> [Int] {
    var result: [Int] = []
    var n = n
    for i in 2...n {
        while n % i == 0 {
            result.append(i)
            n /= i
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var result: [Int] = []
    var n = n
    for i in 2...n {
        while n % i == 0 {
            result.append(i)
            n /= i
        }
    }
    return result
}
```

func factorize(n: Int) -> [Int] {
    var result: [Int] = []
    var number = n
    var i = 2
    while i <= number {
        if number % i == 0 {
            result.append(i)
            number /= i
        } else {
            i += 1
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var result: [Int] = []
    var number = n
    var i = 2
    while i <= number {
        if number % i == 0 {
            result.append(i)
            number /= i
        } else {
            i += 1
        }
    }
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    for number in numbers {
        if result.contains(number) == false {
            result.append(number)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    for number in numbers {
        if result.contains(number) == false {
            result.append(number)
        }
    }
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    for num in numbers {
        if !result.contains(num) {
            result.append(num)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    for num in numbers {
        if !result.contains(num) {
            result.append(num)
        }
    }
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    for number in numbers {
        if !result.contains(number) {
            result.append(number)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    for number in numbers {
        if !result.contains(number) {
            result.append(number)
        }
    }
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    for num in numbers {
        if !result.contains(num) {
            result.append(num)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    for num in numbers {
        if !result.contains(num) {
            result.append(num)
        }
    }
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    for number in numbers {
        if !result.contains(number) {
            result.append(number)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    for number in numbers {
        if !result.contains(number) {
            result.append(number)
        }
    }
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    for num in numbers {
        if !result.contains(num) {
            result.append(num)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    for num in numbers {
        if !result.contains(num) {
            result.append(num)
        }
    }
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    for number in numbers {
        if !result.contains(number) {
            result.append(number)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    for number in numbers {
        if !result.contains(number) {
            result.append(number)
        }
    }
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    for number in numbers {
        if !result.contains(number) {
            result.append(number)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    for number in numbers {
        if !result.contains(number) {
            result.append(number)
        }
    }
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    for num in numbers {
        if !result.contains(num) {
            result.append(num)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    for num in numbers {
        if !result.contains(num) {
            result.append(num)
        }
    }
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    for number in numbers {
        if !result.contains(number) {
            result.append(number)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    for number in numbers {
        if !result.contains(number) {
            result.append(number)
        }
    }
    return result
}
```

func flipCase(string: String) -> String {
    return string.map {
        let s = String($0)
        return s.lowercased() == s ? s.uppercased() : s.lowercased()
    }.joined()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    return string.map {
        let s = String($0)
        return s.lowercased() == s ? s.uppercased() : s.lowercased()
    }.joined()
}
```

func flipCase(string: String) -> String {
    return string.map {
        $0.isUppercase ? String($0).lowercased() : String($0).uppercased()
    }.joined()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    return string.map {
        $0.isUppercase ? String($0).lowercased() : String($0).uppercased()
    }.joined()
}
```

func flipCase(string: String) -> String {
    return string.map {
        let s = String($0)
        return s.lowercased() == s ? s.uppercased() : s.lowercased()
    }.joined()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    return string.map {
        let s = String($0)
        return s.lowercased() == s ? s.uppercased() : s.lowercased()
    }.joined()
}
```

func flipCase(string: String) -> String {
    return string.map {
        let s = String($0)
        return s.lowercased() == s
            ? s.uppercased()
            : s.lowercased()
    }.joined()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    return string.map {
        let s = String($0)
        return s.lowercased() == s
            ? s.uppercased()
            : s.lowercased()
    }.joined()
}
```

func flipCase(string: String) -> String {
    return string.map {
        let s = String($0)
        return s.lowercased() == s
            ? s.uppercased()
            : s.lowercased()
    }.joined()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    return string.map {
        let s = String($0)
        return s.lowercased() == s
            ? s.uppercased()
            : s.lowercased()
    }.joined()
}
```

func flipCase(string: String) -> String {
    return string.map {
        let s = String($0)
        return s.lowercased() == s ? s.uppercased() : s.lowercased()
    }.joined()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    return string.map {
        let s = String($0)
        return s.lowercased() == s ? s.uppercased() : s.lowercased()
    }.joined()
}
```

func flipCase(string: String) -> String {
    return string.map {
        let s = String($0)
        return s.lowercased() == s ? s.uppercased() : s.lowercased()
    }.joined()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    return string.map {
        let s = String($0)
        return s.lowercased() == s ? s.uppercased() : s.lowercased()
    }.joined()
}
```

func flipCase(string: String) -> String {
    return string.map {
        let s = String($0)
        return s.lowercased() == s
            ? s.uppercased()
            : s.lowercased()
    }.joined()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    return string.map {
        let s = String($0)
        return s.lowercased() == s
            ? s.uppercased()
            : s.lowercased()
    }.joined()
}
```

func flipCase(string: String) -> String {
    return string.unicodeScalars.map {
        Character(UnicodeScalar(
            $0.value ^ (32 * ($0.value >= 65 && $0.value <= 90 ? 1 : 0))
        ))
    }.reduce("", +)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    return string.unicodeScalars.map {
        Character(UnicodeScalar(
            $0.value ^ (32 * ($0.value >= 65 && $0.value <= 90 ? 1 : 0))
        ))
    }.reduce("", +)
}
```

func flipCase(string: String) -> String {
    return string.map {
        let s = String($0)
        return s.lowercased() == s ? s.uppercased() : s.lowercased()
    }.joined()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    return string.map {
        let s = String($0)
        return s.lowercased() == s ? s.uppercased() : s.lowercased()
    }.joined()
}
```

func concatenate(strings: [String]) -> String {
    return strings.joined()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined()
}
```

func concatenate(strings: [String]) -> String {
    return strings.joined()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined()
}
```

func concatenate(strings: [String]) -> String {
    return strings.joined()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined()
}
```

func concatenate(strings: [String]) -> String {
    return strings.joined()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined()
}
```

func concatenate(strings: [String]) -> String {
    return strings.joined()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined()
}
```

func concatenate(strings: [String]) -> String {
    return strings.joined()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined()
}
```

func concatenate(strings: [String]) -> String {
    return strings.joined()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined()
}
```

func concatenate(strings: [String]) -> String {
    return strings.joined()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined()
}
```

func concatenate(strings: [String]) -> String {
    return strings.joined()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined()
}
```

func concatenate(strings: [String]) -> String {
    return strings.joined()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined()
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    for i in 2...Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    for i in 2...Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            return false
        }
        i += 1
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            return false
        }
        i += 1
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func sortThird(l: [Int]) -> [Int] {
    let third = l.enumerated().filter { $0.offset % 3 == 0 }.map { $0.element }.sorted()
    var result = l
    for (i, v) in third.enumerated() {
        result[3 * i] = v
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    let third = l.enumerated().filter { $0.offset % 3 == 0 }.map { $0.element }.sorted()
    var result = l
    for (i, v) in third.enumerated() {
        result[3 * i] = v
    }
    return result
}
```

func sortThird(l: [Int]) -> [Int] {
    var sortedArray = l.sorted()
    var resultArray = [Int]()
    for i in 0..<l.count {
        if i % 3 != 0 {
            resultArray.append(sortedArray[i])
        } else {
            resultArray.append(l[i])
        }
    }
    return resultArray
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    var sortedArray = l.sorted()
    var resultArray = [Int]()
    for i in 0..<l.count {
        if i % 3 != 0 {
            resultArray.append(sortedArray[i])
        } else {
            resultArray.append(l[i])
        }
    }
    return resultArray
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    let third = l.enumerated().filter { $0.offset % 3 == 0 }.map { $0.element }.sorted()
    for (i, v) in third.enumerated() {
        l[3 * i] = v
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    let third = l.enumerated().filter { $0.offset % 3 == 0 }.map { $0.element }.sorted()
    for (i, v) in third.enumerated() {
        l[3 * i] = v
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    let thirdIndicies = l.indices.filter { $0 % 3 == 0 }
    let sortedThirdIndicies = thirdIndicies.sorted { l[$0] < l[$1] }
    for i in 0..<thirdIndicies.count {
        l[sortedThirdIndicies[i]] = l[thirdIndicies[i]]
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    let thirdIndicies = l.indices.filter { $0 % 3 == 0 }
    let sortedThirdIndicies = thirdIndicies.sorted { l[$0] < l[$1] }
    for i in 0..<thirdIndicies.count {
        l[sortedThirdIndicies[i]] = l[thirdIndicies[i]]
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    let sorted = l.enumerated().filter { $0.offset % 3 == 0 }.sorted { $0.element < $1.element }.map { $0.element }
    for (i, element) in sorted.enumerated() {
        l[i * 3] = element
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    let sorted = l.enumerated().filter { $0.offset % 3 == 0 }.sorted { $0.element < $1.element }.map { $0.element }
    for (i, element) in sorted.enumerated() {
        l[i * 3] = element
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var sorted = l.sorted()
    var result = [Int]()
    for (i, v) in l.enumerated() {
        if i % 3 != 0 {
            result.append(v)
        } else {
            result.append(sorted[i])
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    var sorted = l.sorted()
    var result = [Int]()
    for (i, v) in l.enumerated() {
        if i % 3 != 0 {
            result.append(v)
        } else {
            result.append(sorted[i])
        }
    }
    return result
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    let thirdIndicies = l.indices.filter { $0 % 3 == 0 }
    let sortedThirdIndicies = thirdIndicies.sorted { l[$0] < l[$1] }
    for i in 0..<thirdIndicies.count {
        l[sortedThirdIndicies[i]] = l[thirdIndicies[i]]
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    let thirdIndicies = l.indices.filter { $0 % 3 == 0 }
    let sortedThirdIndicies = thirdIndicies.sorted { l[$0] < l[$1] }
    for i in 0..<thirdIndicies.count {
        l[sortedThirdIndicies[i]] = l[thirdIndicies[i]]
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    let thirdIndicies = l.enumerated().filter { $0.offset % 3 == 0 }.map { $0.element }
    let sortedThirdIndicies = thirdIndicies.sorted()
    for (i, element) in thirdIndicies.enumerated() {
        l[sortedThirdIndicies[i]] = element
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    let thirdIndicies = l.enumerated().filter { $0.offset % 3 == 0 }.map { $0.element }
    let sortedThirdIndicies = thirdIndicies.sorted()
    for (i, element) in thirdIndicies.enumerated() {
        l[sortedThirdIndicies[i]] = element
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    let third = l.enumerated().filter { $0.offset % 3 == 0 }.map { $0.element }.sorted()
    var result = l
    for (i, v) in third.enumerated() {
        result[3 * i] = v
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    let third = l.enumerated().filter { $0.offset % 3 == 0 }.map { $0.element }.sorted()
    var result = l
    for (i, v) in third.enumerated() {
        result[3 * i] = v
    }
    return result
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    let sorted = l.enumerated().filter { $0.offset % 3 == 0 }.sorted { $0.element < $1.element }.map { $0.element }
    for (i, v) in sorted.enumerated() {
        l[3 * i] = v
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    let sorted = l.enumerated().filter { $0.offset % 3 == 0 }.sorted { $0.element < $1.element }.map { $0.element }
    for (i, v) in sorted.enumerated() {
        l[3 * i] = v
    }
    return l
}
```

func unique(l: [Int]) -> [Int] {
    var result: [Int] = []
    for i in l {
        if !result.contains(i) {
            result.append(i)
        }
    }
    return result.sorted()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    var result: [Int] = []
    for i in l {
        if !result.contains(i) {
            result.append(i)
        }
    }
    return result.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var result: [Int] = []
    for element in l {
        if !result.contains(element) {
            result.append(element)
        }
    }
    return result.sorted()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    var result: [Int] = []
    for element in l {
        if !result.contains(element) {
            result.append(element)
        }
    }
    return result.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    return Array(Set(l))
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    return Array(Set(l))
}
```

func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    for i in l {
        if !result.contains(i) {
            result.append(i)
        }
    }
    return result.sorted()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    for i in l {
        if !result.contains(i) {
            result.append(i)
        }
    }
    return result.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var result: [Int] = []
    for element in l {
        if !result.contains(element) {
            result.append(element)
        }
    }
    return result.sorted()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    var result: [Int] = []
    for element in l {
        if !result.contains(element) {
            result.append(element)
        }
    }
    return result.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    for element in l {
        if !result.contains(element) {
            result.append(element)
        }
    }
    return result.sorted()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    for element in l {
        if !result.contains(element) {
            result.append(element)
        }
    }
    return result.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var result: [Int] = []
    for i in l {
        if !result.contains(i) {
            result.append(i)
        }
    }
    return result.sorted()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    var result: [Int] = []
    for i in l {
        if !result.contains(i) {
            result.append(i)
        }
    }
    return result.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var result: [Int] = []
    for element in l {
        if !result.contains(element) {
            result.append(element)
        }
    }
    return result.sorted()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    var result: [Int] = []
    for element in l {
        if !result.contains(element) {
            result.append(element)
        }
    }
    return result.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var result: [Int] = []
    for i in l {
        if !result.contains(i) {
            result.append(i)
        }
    }
    return result.sorted()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    var result: [Int] = []
    for i in l {
        if !result.contains(i) {
            result.append(i)
        }
    }
    return result.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    for i in l {
        if !result.contains(i) {
            result.append(i)
        }
    }
    return result.sorted()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    for i in l {
        if !result.contains(i) {
            result.append(i)
        }
    }
    return result.sorted()
}
```

func maxElement(l: [Int]) -> Int {
    return l.max() ?? 0
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max() ?? 0
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    return l.max()!
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max()!
}
```

func maxElement(l: [Int]) -> Int {
    return l.max() ?? 0
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max() ?? 0
}
```

func maxElement(l: [Int]) -> Int {
    return l.max() ?? 0
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max() ?? 0
}
```

func maxElement(l: [Int]) -> Int {
    return l.max() ?? 0
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max() ?? 0
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in l {
        if i > max {
            max = i
        }
    }
    return max
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in l {
        if i > max {
            max = i
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    return l.max() ?? 0
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max() ?? 0
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            for char in str {
                if char == "7" {
                    count += 1
                }
            }
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            for char in str {
                if char == "7" {
                    count += 1
                }
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count: Int = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            for char in str {
                if char == "7" {
                    count += 1
                    break
                }
            }
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count: Int = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            for char in str {
                if char == "7" {
                    count += 1
                    break
                }
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            for char in str {
                if char == "7" {
                    count += 1
                }
            }
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            for char in str {
                if char == "7" {
                    count += 1
                }
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            for char in str {
                if char == "7" {
                    count += 1
                }
            }
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            for char in str {
                if char == "7" {
                    count += 1
                }
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            for char in str {
                if char == "7" {
                    count += 1
                    break
                }
            }
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            for char in str {
                if char == "7" {
                    count += 1
                    break
                }
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            for char in str {
                if char == "7" {
                    count += 1
                }
            }
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            for char in str {
                if char == "7" {
                    count += 1
                }
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count: Int = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            for char in str {
                if char == "7" {
                    count += 1
                }
            }
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count: Int = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            for char in str {
                if char == "7" {
                    count += 1
                }
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count: Int = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            if str.contains("7") {
                count += 1
            }
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count: Int = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            if str.contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let string = String(i)
            for char in string {
                if char == "7" {
                    count += 1
                }
            }
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let string = String(i)
            for char in string {
                if char == "7" {
                    count += 1
                }
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count: Int = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            for char in str {
                if char == "7" {
                    count += 1
                    break
                }
            }
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count: Int = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            for char in str {
                if char == "7" {
                    count += 1
                    break
                }
            }
        }
    }
    return count
}
```

func sortEven(l: [Int]) -> [Int] {
    var sortedEven = l.filter { $0 % 2 == 0 }.sorted()
    var result = [Int]()
    for (index, value) in l.enumerated() {
        if index % 2 == 0 {
            result.append(value)
        } else {
            result.append(sortedEven.removeFirst())
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
    var sortedEven = l.filter { $0 % 2 == 0 }.sorted()
    var result = [Int]()
    for (index, value) in l.enumerated() {
        if index % 2 == 0 {
            result.append(value)
        } else {
            result.append(sortedEven.removeFirst())
        }
    }
    return result
}
```

func sortEven(l: [Int]) -> [Int] {
    var result = l
    let evenIndicies = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.offset }
    let evenValues = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }.sorted()
    for (i, index) in evenIndicies.enumerated() {
        result[index] = evenValues[i]
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
    var result = l
    let evenIndicies = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.offset }
    let evenValues = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }.sorted()
    for (i, index) in evenIndicies.enumerated() {
        result[index] = evenValues[i]
    }
    return result
}
```

func sortEven(l: [Int]) -> [Int] {
  var result = l
  let sortedEven = l.enumerated().filter { $0.offset % 2 == 0 }.sorted { $0.element < $1.element }.map { $0.element }
  for (i, v) in sortedEven.enumerated() {
    result[i * 2] = v
  }
  return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
  var result = l
  let sortedEven = l.enumerated().filter { $0.offset % 2 == 0 }.sorted { $0.element < $1.element }.map { $0.element }
  for (i, v) in sortedEven.enumerated() {
    result[i * 2] = v
  }
  return result
}
```

func sortEven(l: [Int]) -> [Int] {
    var result = l
    for i in stride(from: 0, to: l.count, by: 2) {
        result[i] = l[i]
    }
    result.sort(by: <)
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
    var result = l
    for i in stride(from: 0, to: l.count, by: 2) {
        result[i] = l[i]
    }
    result.sort(by: <)
    return result
}
```

func sortEven(l: [Int]) -> [Int] {
    var result = l
    let evenIndicies = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    result.removeAll(where: { evenIndicies.contains($0) })
    result.insert(contentsOf: evenIndicies.sorted(), at: 0)
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
    var result = l
    let evenIndicies = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    result.removeAll(where: { evenIndicies.contains($0) })
    result.insert(contentsOf: evenIndicies.sorted(), at: 0)
    return result
}
```

func sortEven(l: [Int]) -> [Int] {
  var l = l
  let sortedEven = l.enumerated().filter { $0.offset % 2 == 0 }.sorted { $0.element < $1.element }.map { $0.element }
  for i in 0..<sortedEven.count {
    l[i * 2] = sortedEven[i]
  }
  return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
  var l = l
  let sortedEven = l.enumerated().filter { $0.offset % 2 == 0 }.sorted { $0.element < $1.element }.map { $0.element }
  for i in 0..<sortedEven.count {
    l[i * 2] = sortedEven[i]
  }
  return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var sortedEven = l.filter { $0 % 2 == 0 }.sorted()
    var odd = l.filter { $0 % 2 != 0 }
    var result = [Int]()
    for i in 0..<l.count {
        if i % 2 == 0 {
            result.append(sortedEven.removeFirst())
        } else {
            result.append(odd.removeFirst())
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
    var sortedEven = l.filter { $0 % 2 == 0 }.sorted()
    var odd = l.filter { $0 % 2 != 0 }
    var result = [Int]()
    for i in 0..<l.count {
        if i % 2 == 0 {
            result.append(sortedEven.removeFirst())
        } else {
            result.append(odd.removeFirst())
        }
    }
    return result
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    var even = l.enumerated().filter { $0.offset % 2 == 0 }.sorted { $0.element < $1.element }.map { $0.element }
    var i = 0
    while i < even.count {
        l[i * 2] = even[i]
        i += 1
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    var even = l.enumerated().filter { $0.offset % 2 == 0 }.sorted { $0.element < $1.element }.map { $0.element }
    var i = 0
    while i < even.count {
        l[i * 2] = even[i]
        i += 1
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    let even = l.enumerated().filter { $0.offset % 2 == 0 }.sorted { $0.element < $1.element }
    for (i, v) in even {
        l[i] = v
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    let even = l.enumerated().filter { $0.offset % 2 == 0 }.sorted { $0.element < $1.element }
    for (i, v) in even {
        l[i] = v
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var result = l
    let evenIndicies = stride(from: 0, to: l.count, by: 2)
    let evenValues = evenIndicies.map { l[$0] }
    let sortedEvenValues = evenValues.sorted()
    for (index, value) in zip(evenIndicies, sortedEvenValues) {
        result[index] = value
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
    var result = l
    let evenIndicies = stride(from: 0, to: l.count, by: 2)
    let evenValues = evenIndicies.map { l[$0] }
    let sortedEvenValues = evenValues.sorted()
    for (index, value) in zip(evenIndicies, sortedEvenValues) {
        result[index] = value
    }
    return result
}
```

func primeFib(n: Int) -> Int {
    var fib = [0, 1]
    var i = 2
    while true {
        let next = fib[i - 1] + fib[i - 2]
        if next > fib[i - 1] {
            fib.append(next)
            i += 1
        }
        if isPrime(fib[i - 1]) {
            if n == 1 {
                return fib[i - 1]
            } else {
                n -= 1
            }
        }
    }
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 { return false }
    if n <= 3 { return true }
    var i = 2
    while i * i <= n {
        if n % i == 0 { return false }
        i += 1
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var fib = [0, 1]
    var i = 2
    while true {
        let next = fib[i - 1] + fib[i - 2]
        if next > fib[i - 1] {
            fib.append(next)
            i += 1
        }
        if isPrime(fib[i - 1]) {
            if n == 1 {
                return fib[i - 1]
            } else {
                n -= 1
            }
        }
    }
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 { return false }
    if n <= 3 { return true }
    var i = 2
    while i * i <= n {
        if n % i == 0 { return false }
        i += 1
    }
    return true
}
```

func primeFib(n: Int) -> Int {
    var fib = [1, 2]
    var i = 2
    while fib.count < n {
        let next = fib[i] + fib[i - 1]
        if isPrime(next) {
            fib.append(next)
        }
        i += 1
    }
    return fib.last!
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            return false
        }
        i += 1
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var fib = [1, 2]
    var i = 2
    while fib.count < n {
        let next = fib[i] + fib[i - 1]
        if isPrime(next) {
            fib.append(next)
        }
        i += 1
    }
    return fib.last!
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            return false
        }
        i += 1
    }
    return true
}
```

func primeFib(n: Int) -> Int {
    var fib = [0, 1]
    var i = 2
    while fib.count < n {
        let next = fib[i - 1] + fib[i - 2]
        if isPrime(next) {
            fib.append(next)
        }
        i += 1
    }
    return fib[n - 1]
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            return false
        }
        i += 1
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var fib = [0, 1]
    var i = 2
    while fib.count < n {
        let next = fib[i - 1] + fib[i - 2]
        if isPrime(next) {
            fib.append(next)
        }
        i += 1
    }
    return fib[n - 1]
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            return false
        }
        i += 1
    }
    return true
}
```

func primeFib(n: Int) -> Int {
    var fib = [1, 1]
    var index = 2
    while fib.count <= n {
        fib.append(fib[index - 1] + fib[index - 2])
        index += 1
    }
    return fib[n]
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var fib = [1, 1]
    var index = 2
    while fib.count <= n {
        fib.append(fib[index - 1] + fib[index - 2])
        index += 1
    }
    return fib[n]
}
```

func primeFib(n: Int) -> Int {
    var fib = [0, 1]
    var i = 2
    while fib.count < n {
        fib.append(fib[i-1] + fib[i-2])
        i += 1
    }
    return fib.last!
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var fib = [0, 1]
    var i = 2
    while fib.count < n {
        fib.append(fib[i-1] + fib[i-2])
        i += 1
    }
    return fib.last!
}
```

func primeFib(n: Int) -> Int {
    var fib = [2, 3]
    var i = 3
    while fib.count < n {
        let f = fib[i - 1] + fib[i - 2]
        if f > 1 && f.isPrime() {
            fib.append(f)
        }
        i += 1
    }
    return fib[n - 1]
}

extension Int {
    func isPrime() -> Bool {
        if self <= 1 { return false }
        if self <= 3 { return true }
        for i in 2...Int(sqrtf(Float(self))) {
            if self % i == 0 { return false }
        }
        return true
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var fib = [2, 3]
    var i = 3
    while fib.count < n {
        let f = fib[i - 1] + fib[i - 2]
        if f > 1 && f.isPrime() {
            fib.append(f)
        }
        i += 1
    }
    return fib[n - 1]
}

extension Int {
    func isPrime() -> Bool {
        if self <= 1 { return false }
        if self <= 3 { return true }
        for i in 2...Int(sqrtf(Float(self))) {
            if self % i == 0 { return false }
        }
        return true
    }
}
```

func primeFib(n: Int) -> Int {
    var fib = [0, 1]
    var i = 2
    while fib.count < n {
        let new = fib[i - 1] + fib[i - 2]
        if new > 1 {
            fib.append(new)
        }
        i += 1
    }
    return fib[n - 1]
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var fib = [0, 1]
    var i = 2
    while fib.count < n {
        let new = fib[i - 1] + fib[i - 2]
        if new > 1 {
            fib.append(new)
        }
        i += 1
    }
    return fib[n - 1]
}
```

func primeFib(n: Int) -> Int {
    var fib = [0, 1]
    var i = 2
    while fib.count < n {
        let f = fib[i-1] + fib[i-2]
        if f > 1 && f.isPrime() {
            fib.append(f)
        }
        i += 1
    }
    return fib.last!
}

extension Int {
    func isPrime() -> Bool {
        if self < 2 {
            return false
        }
        for i in 2..<self {
            if self % i == 0 {
                return false
            }
        }
        return true
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var fib = [0, 1]
    var i = 2
    while fib.count < n {
        let f = fib[i-1] + fib[i-2]
        if f > 1 && f.isPrime() {
            fib.append(f)
        }
        i += 1
    }
    return fib.last!
}

extension Int {
    func isPrime() -> Bool {
        if self < 2 {
            return false
        }
        for i in 2..<self {
            if self % i == 0 {
                return false
            }
        }
        return true
    }
}
```

func primeFib(n: Int) -> Int {
    var fib1 = 1
    var fib2 = 1
    var count = 1
    var prime = 2
    while count < n {
        (fib1, fib2) = (fib2, fib1 + fib2)
        while prime <= fib2 {
            if fib2 % prime == 0 {
                break
            }
            prime += 1
        }
        if prime == fib2 {
            count += 1
        }
    }
    return fib2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var fib1 = 1
    var fib2 = 1
    var count = 1
    var prime = 2
    while count < n {
        (fib1, fib2) = (fib2, fib1 + fib2)
        while prime <= fib2 {
            if fib2 % prime == 0 {
                break
            }
            prime += 1
        }
        if prime == fib2 {
            count += 1
        }
    }
    return fib2
}
```

func primeFib(n: Int) -> Int {
    var fib = [0, 1]
    var i = 2
    while true {
        let next = fib[i-1] + fib[i-2]
        if next >= fib[i-1] {
            fib.append(next)
            i += 1
        }
        if isPrime(fib[i-1]) {
            if n == i {
                return fib[i-1]
            }
        }
    }
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 { return false }
    if n <= 3 { return true }
    if n % 2 == 0 || n % 3 == 0 { return false }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 { return false }
        i += 6
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var fib = [0, 1]
    var i = 2
    while true {
        let next = fib[i-1] + fib[i-2]
        if next >= fib[i-1] {
            fib.append(next)
            i += 1
        }
        if isPrime(fib[i-1]) {
            if n == i {
                return fib[i-1]
            }
        }
    }
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 { return false }
    if n <= 3 { return true }
    if n % 2 == 0 || n % 3 == 0 { return false }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 { return false }
        i += 6
    }
    return true
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func carRaceCollision(n: Int) -> Int {
    return n / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    return n / 2
}
```

func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}
```

func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}
```

func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}
```

func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}
```

func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}
```

func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}
```

func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}
```

func carRaceCollision(n: Int) -> Int {
    var collisions = 0
    var leftToRight = 0
    var rightToLeft = n - 1
    while leftToRight < rightToLeft {
        if leftToRight < rightToLeft {
            leftToRight += 1
        }
        if leftToRight < rightToLeft {
            rightToLeft -= 1
        }
        collisions += 1
    }
    return collisions
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    var collisions = 0
    var leftToRight = 0
    var rightToLeft = n - 1
    while leftToRight < rightToLeft {
        if leftToRight < rightToLeft {
            leftToRight += 1
        }
        if leftToRight < rightToLeft {
            rightToLeft -= 1
        }
        collisions += 1
    }
    return collisions
}
```

func carRaceCollision(n: Int) -> Int {
    var collisions = 0
    var leftToRight = 0
    var rightToLeft = n - 1
    while leftToRight < rightToLeft {
        leftToRight += 1
        rightToLeft -= 1
        collisions += 1
    }
    return collisions
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    var collisions = 0
    var leftToRight = 0
    var rightToLeft = n - 1
    while leftToRight < rightToLeft {
        leftToRight += 1
        rightToLeft -= 1
        collisions += 1
    }
    return collisions
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    var result: [Int] = []
    for i in l {
        result.append(i + 1)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    var result: [Int] = []
    for i in l {
        result.append(i + 1)
    }
    return result
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    var result = [Int]()
    for i in l {
        result.append(i+1)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    var result = [Int]()
    for i in l {
        result.append(i+1)
    }
    return result
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for element in l {
        if set.contains(element) {
            return true
        } else {
            set.insert(-element)
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for element in l {
        if set.contains(element) {
            return true
        } else {
            set.insert(-element)
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var hash: [Int: Bool] = [:]
    for i in l {
        if hash[i] == true {
            return true
        }
        hash[i] = true
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var hash: [Int: Bool] = [:]
    for i in l {
        if hash[i] == true {
            return true
        }
        hash[i] = true
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for element in l {
        if set.contains(-element) {
            return true
        }
        set.insert(element)
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for element in l {
        if set.contains(-element) {
            return true
        }
        set.insert(element)
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for element in l {
        if set.contains(-element) {
            return true
        }
        set.insert(element)
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for element in l {
        if set.contains(-element) {
            return true
        }
        set.insert(element)
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var hash = [Int: Bool]()
    for i in l {
        if hash[i] == true {
            return true
        } else {
            hash[i] = true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var hash = [Int: Bool]()
    for i in l {
        if hash[i] == true {
            return true
        } else {
            hash[i] = true
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var hash = [Int: Bool]()
    for element in l {
        if hash[element] == true {
            return true
        } else {
            hash[element] = true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var hash = [Int: Bool]()
    for element in l {
        if hash[element] == true {
            return true
        } else {
            hash[element] = true
        }
    }
    return false
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        result = "\(num % base)" + result
        num /= base
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        result = "\(num % base)" + result
        num /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        result = "\(num % base)" + result
        num /= base
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        result = "\(num % base)" + result
        num /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        result = "\(num % base)" + result
        num /= base
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        result = "\(num % base)" + result
        num /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        result = "\(num % base)" + result
        num /= base
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        result = "\(num % base)" + result
        num /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        result = "\(num % base)" + result
        num /= base
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        result = "\(num % base)" + result
        num /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        result = "\(num % base)" + result
        num /= base
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        result = "\(num % base)" + result
        num /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        result = "\(num % base)" + result
        num /= base
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        result = "\(num % base)" + result
        num /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        result = "\(num % base)" + result
        num /= base
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        result = "\(num % base)" + result
        num /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        result = "\(num % base)" + result
        num /= base
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        result = "\(num % base)" + result
        num /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        result = "\(num % base)" + result
        num /= base
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        result = "\(num % base)" + result
        num /= base
    }
    return result
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var result = 0
    var i = 2
    while i < n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
        i += 1
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var result = 0
    var i = 2
    while i < n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
        i += 1
    }
    return result
}
```

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var e = 0
    var result = 0
    for _ in 0..<n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = e
        e = result
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var e = 0
    var result = 0
    for _ in 0..<n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = e
        e = result
    }
    return result
}
```

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var e = 0
    var result = 0
    var i = 1
    while i < n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = e
        e = result
        i += 1
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var e = 0
    var result = 0
    var i = 1
    while i < n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = e
        e = result
        i += 1
    }
    return result
}
```

func fib4(n: Int) -> Int {
    var fib4Array: [Int] = [0, 0, 2, 0]
    for i in 4...n {
        fib4Array.append(fib4Array[i-1] + fib4Array[i-2] + fib4Array[i-3] + fib4Array[i-4])
    }
    return fib4Array[n]
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var fib4Array: [Int] = [0, 0, 2, 0]
    for i in 4...n {
        fib4Array.append(fib4Array[i-1] + fib4Array[i-2] + fib4Array[i-3] + fib4Array[i-4])
    }
    return fib4Array[n]
}
```

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var e = 0
    var f = 0
    var g = 0
    var h = 0
    var i = 0
    var j = 0
    var k = 0
    var l = 0
    var m = 0
    var n = 0
    var o = 0
    var p = 0
    var q = 0
    var r = 0
    var s = 0
    var t = 0
    var u = 0
    var v = 0
    var w = 0
    var x = 0
    var y = 0
    var z = 0
    var aa = 0
    var bb = 0
    var cc = 0
    var dd = 0
    var ee = 0
    var ff = 0
    var gg = 0
    var hh = 0
    var ii = 0
    var jj = 0
    var kk = 0
    var ll = 0
    var mm = 0
    var nn = 0
    var oo = 0
    var pp = 0
    var qq = 0
    var rr = 0
    var ss = 0
    var tt = 0
    var uu = 0
    var vv = 0
    var ww = 0
    var xx = 0
    var yy = 0
    var zz = 0
    var aaa = 0
    var bbb = 0
    var ccc = 0
    var ddd = 0
    var eee = 0
    var fff = 0
    var ggg = 0
    var hhh = 0
    var iii = 0
    var jjj = 0
    var kkk = 0
    var lll = 0
    var mmm = 0
    var nnn = 0
    var ooo = 0
    var ppp = 0
    var qqq = 0
    var rrr = 0
    var sss = 0
    var ttt = 0
    var uuu = 0
    var vvv = 0
    var www = 0
    var xxx = 0
    var yyy = 0
    var zzz = 0
    var aaaa = 0
    var bbbb = 0
    var cccc = 0
    var dddd = 0
    var eeee = 0
    var ffff = 0
    var gggg = 0
    var hhhh = 0
    var iiii = 0
    var jjjj = 0
    var kkkk = 0
    var llll = 0
    var mmmm = 0
    var nnnn = 0
    var oooo = 0
    var pppp = 0
    var qqqq = 0
    var rrrr = 0
    var ssss = 0
    var tttt = 0
    var uuuu = 0
    var vvvv = 0
    var www = 0
    var xxxx = 0
    var yyyy = 0
    var zzzz = 0
    var aaaaa = 0
    var bbbbb = 0
    var ccccc = 0
    var ddddd = 0
    var eeeee = 0
    var fffff = 0
    var ggggg = 0
    var hhhhh = 0
    var iiiii = 0
    var jjjjj = 0
    var kkkkk = 0
    var lllll = 0
    var mmmmm = 0
    var nnnnn = 0
    var ooooo = 0
    var ppppp = 0
    var qqqqq = 0
    var rrrrr = 0
    var sssss = 0
    var ttttt = 0
    var uuuuu = 0
    var vvvvv = 0
    var

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var result = 0
    var i = 3
    while i <= n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
        i += 1
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var result = 0
    var i = 3
    while i <= n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
        i += 1
    }
    return result
}
```

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var e = 0
    var f = 0
    var g = 0
    var h = 0
    var i = 0
    var j = 0
    var k = 0
    var l = 0
    var m = 0
    var n = 0
    var o = 0
    var p = 0
    var q = 0
    var r = 0
    var s = 0
    var t = 0
    var u = 0
    var v = 0
    var w = 0
    var x = 0
    var y = 0
    var z = 0
    var aa = 0
    var bb = 0
    var cc = 0
    var dd = 0
    var ee = 0
    var ff = 0
    var gg = 0
    var hh = 0
    var ii = 0
    var jj = 0
    var kk = 0
    var ll = 0
    var mm = 0
    var nn = 0
    var oo = 0
    var pp = 0
    var qq = 0
    var rr = 0
    var ss = 0
    var tt = 0
    var uu = 0
    var vv = 0
    var ww = 0
    var xx = 0
    var yy = 0
    var zz = 0
    var aaa = 0
    var bbb = 0
    var ccc = 0
    var ddd = 0
    var eee = 0
    var fff = 0
    var ggg = 0
    var hhh = 0
    var iii = 0
    var jjj = 0
    var kkk = 0
    var lll = 0
    var mmm = 0
    var nnn = 0
    var ooo = 0
    var ppp = 0
    var qqq = 0
    var rrr = 0
    var sss = 0
    var ttt = 0
    var uuu = 0
    var vvv = 0
    var www = 0
    var xxx = 0
    var yyy = 0
    var zzz = 0
    var aaaa = 0
    var bbbb = 0
    var cccc = 0
    var dddd = 0
    var eeee = 0
    var ffff = 0
    var gggg = 0
    var hhhh = 0
    var iiii = 0
    var jjjj = 0
    var kkkk = 0
    var llll = 0
    var mmmm = 0
    var nnnn = 0
    var oooo = 0
    var pppp = 0
    var qqqq = 0
    var rrrr = 0
    var ssss = 0
    var tttt = 0
    var uuuu = 0
    var vvvv = 0
    var www = 0
    var xxxx = 0
    var yyyy = 0
    var zzzz = 0
    var aaaaa = 0
    var bbbbb = 0
    var ccccc = 0
    var ddddd = 0
    var eeeee = 0
    var fffff = 0
    var ggggg = 0
    var hhhhh = 0
    var iiiii = 0
    var jjjjj = 0
    var kkkkk = 0
    var lllll = 0
    var mmmmm = 0
    var nnnnn = 0
    var ooooo = 0
    var ppppp = 0
    var qqqqq = 0
    var rrrrr = 0
    var sssss = 0
    var ttttt = 0
    var uuuuu = 0
    var vvvvv = 0
    var

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var e = 0
    var result = 0
    var i = 0
    while i < n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = e
        e = result
        i += 1
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var e = 0
    var result = 0
    var i = 0
    while i < n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = e
        e = result
        i += 1
    }
    return result
}
```

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var e = 0
    var result = 0
    for _ in 0..<n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = e
        e = result
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var e = 0
    var result = 0
    for _ in 0..<n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = e
        e = result
    }
    return result
}
```

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var result = 0
    var i = 2
    while i < n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
        i += 1
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var result = 0
    var i = 2
    while i < n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
        i += 1
    }
    return result
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = l.count / 2
    let isEven = l.count % 2 == 0
    return isEven ? Double(sorted[middle - 1] + sorted[middle]) / 2 : Double(sorted[middle])
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = l.count / 2
    let isEven = l.count % 2 == 0
    return isEven ? Double(sorted[middle - 1] + sorted[middle]) / 2 : Double(sorted[middle])
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = l.count / 2
    return l.count % 2 == 0 ? Double(sorted[middle - 1] + sorted[middle]) / 2 : Double(sorted[middle])
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = l.count / 2
    return l.count % 2 == 0 ? Double(sorted[middle - 1] + sorted[middle]) / 2 : Double(sorted[middle])
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = l.count / 2
    if l.count % 2 == 0 {
        return Double(sorted[middle - 1] + sorted[middle]) / 2
    } else {
        return Double(sorted[middle])
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = l.count / 2
    if l.count % 2 == 0 {
        return Double(sorted[middle - 1] + sorted[middle]) / 2
    } else {
        return Double(sorted[middle])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = l.count / 2
    if l.count % 2 == 0 {
        return Double(sorted[middle - 1] + sorted[middle]) / 2
    } else {
        return Double(sorted[middle])
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = l.count / 2
    if l.count % 2 == 0 {
        return Double(sorted[middle - 1] + sorted[middle]) / 2
    } else {
        return Double(sorted[middle])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = l.count / 2
    if l.count % 2 == 0 {
        return Double(sorted[middle - 1] + sorted[middle]) / 2
    } else {
        return Double(sorted[middle])
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = l.count / 2
    if l.count % 2 == 0 {
        return Double(sorted[middle - 1] + sorted[middle]) / 2
    } else {
        return Double(sorted[middle])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    if l.count % 2 == 0 {
        return Double(sorted[l.count / 2] + sorted[l.count / 2 - 1]) / 2
    } else {
        return Double(sorted[l.count / 2])
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    if l.count % 2 == 0 {
        return Double(sorted[l.count / 2] + sorted[l.count / 2 - 1]) / 2
    } else {
        return Double(sorted[l.count / 2])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    if l.count % 2 == 0 {
        return Double(sorted[l.count / 2] + sorted[l.count / 2 - 1]) / 2.0
    } else {
        return Double(sorted[l.count / 2])
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    if l.count % 2 == 0 {
        return Double(sorted[l.count / 2] + sorted[l.count / 2 - 1]) / 2.0
    } else {
        return Double(sorted[l.count / 2])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    if l.count % 2 == 0 {
        return Double(sorted[l.count / 2] + sorted[l.count / 2 - 1]) / 2
    } else {
        return Double(sorted[l.count / 2])
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    if l.count % 2 == 0 {
        return Double(sorted[l.count / 2] + sorted[l.count / 2 - 1]) / 2
    } else {
        return Double(sorted[l.count / 2])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = l.count / 2
    if l.count % 2 == 0 {
        return Double(sorted[middle - 1] + sorted[middle]) / 2
    } else {
        return Double(sorted[middle])
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = l.count / 2
    if l.count % 2 == 0 {
        return Double(sorted[middle - 1] + sorted[middle]) / 2
    } else {
        return Double(sorted[middle])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    if l.count % 2 == 0 {
        return Double(sorted[l.count / 2] + sorted[l.count / 2 - 1]) / 2
    } else {
        return Double(sorted[l.count / 2])
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    if l.count % 2 == 0 {
        return Double(sorted[l.count / 2] + sorted[l.count / 2 - 1]) / 2
    } else {
        return Double(sorted[l.count / 2])
    }
}
```

func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}
```

func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}
```

func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}
```

func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}
```

func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}
```

func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}
```

func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}
```

func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}
```

func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}
```

func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}
```

func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(n), Double(p)))
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
### Response:
```swift
func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(n), Double(p)))
}
```

func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(n), Double(p)))
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
### Response:
```swift
func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(n), Double(p)))
}
```

func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(n), Double(p)))
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
### Response:
```swift
func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(n), Double(p)))
}
```

func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(n), Double(p)))
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
### Response:
```swift
func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(n), Double(p)))
}
```

func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(n), Double(p))) % p
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
### Response:
```swift
func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(n), Double(p))) % p
}
```

func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(n), Double(p))) % p
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
### Response:
```swift
func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(n), Double(p))) % p
}
```

func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(n), Double(p))) % p
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
### Response:
```swift
func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(n), Double(p))) % p
}
```

func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(n), Double(p)))
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
### Response:
```swift
func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(n), Double(p)))
}
```

func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(n), Double(p)))
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
### Response:
```swift
func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(n), Double(p)))
}
```

func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(n), Double(p)))
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
### Response:
```swift
func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(n), Double(p)))
}
```

func removeVowels(text: String) -> String {
    let vowels: [Character] = ["a", "e", "i", "o", "u"]
    return String(text.filter { !vowels.contains($0) })
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
### Response:
```swift
func removeVowels(text: String) -> String {
    let vowels: [Character] = ["a", "e", "i", "o", "u"]
    return String(text.filter { !vowels.contains($0) })
}
```

func removeVowels(text: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
    return String(text.filter { !vowels.contains($0) })
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
### Response:
```swift
func removeVowels(text: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
    return String(text.filter { !vowels.contains($0) })
}
```

func removeVowels(text: String) -> String {
    let vowels: [Character] = ["a", "e", "i", "o", "u"]
    return String(text.filter { !vowels.contains($0) })
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
### Response:
```swift
func removeVowels(text: String) -> String {
    let vowels: [Character] = ["a", "e", "i", "o", "u"]
    return String(text.filter { !vowels.contains($0) })
}
```

func removeVowels(text: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
    return String(text.filter { !vowels.contains($0) })
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
### Response:
```swift
func removeVowels(text: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
    return String(text.filter { !vowels.contains($0) })
}
```

func removeVowels(text: String) -> String {
    let vowels: [Character] = ["a", "e", "i", "o", "u"]
    return String(text.filter { !vowels.contains($0) })
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
### Response:
```swift
func removeVowels(text: String) -> String {
    let vowels: [Character] = ["a", "e", "i", "o", "u"]
    return String(text.filter { !vowels.contains($0) })
}
```

func removeVowels(text: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
    return String(text.filter { !vowels.contains($0) })
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
### Response:
```swift
func removeVowels(text: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
    return String(text.filter { !vowels.contains($0) })
}
```

func removeVowels(text: String) -> String {
    let vowels: [Character] = ["a", "e", "i", "o", "u"]
    return String(text.filter { !vowels.contains($0) })
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
### Response:
```swift
func removeVowels(text: String) -> String {
    let vowels: [Character] = ["a", "e", "i", "o", "u"]
    return String(text.filter { !vowels.contains($0) })
}
```