Problem
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String { ...XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO")
XCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO")
XCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES")
XCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES")
XCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO")
XCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO")
XCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO")
XCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO")- 0.74 Compiled
- 0.06 Passed
Solutions
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
return "YES"
}
<|file_separator|> // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
return "YES"
}
<|file_separator|> // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
return "YES"
}
<|file_separator|> // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
return "YES"
}
<|file_separator|> // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
return "YES"
}<|file_separator|>```swift
<|fim_prefix|>// Given // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
return "YES"
}
<|file_separator|>```swift
<|fim_prefix|>// Given // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval1.1 < interval2.0 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval1.1 < interval2.0 {
return "NO"
}
return "YES"
}
<|file_separator|> // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
return "YES"
}
<|file_separator|> // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
return "YES"
}
<|file_separator|> // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
return "YES"
}
<|file_separator|> // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(min(end1, end2) - max(start1, start2) + 1, 0)
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(min(end1, end2) - max(start1, start2) + 1, 0)
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(min(end1, end2) - max(start1, start2) + 1, 0)
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(min(end1, end2) - max(start1, start2) + 1, 0)
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection interval
let start = max(start1, start2)
let end = min(end1, end2)
// Check if the intersection interval is empty
if start > end {
return "NO"
}
// Calculate the length of the intersection interval
let length = end - start + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection interval
let start = max(start1, start2)
let end = min(end1, end2)
// Check if the intersection interval is empty
if start > end {
return "NO"
}
// Calculate the length of the intersection interval
let length = end - start + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection interval
let start = max(start1, start2)
let end = min(end1, end2)
// Check if the intersection interval is empty
if start > end {
return "NO"
}
// Calculate the length of the intersection interval
let length = end - start + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection interval
let start = max(start1, start2)
let end = min(end1, end2)
// Check if the intersection interval is empty
if start > end {
return "NO"
}
// Calculate the length of the intersection interval
let length = end - start + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection interval
let start = max(start1, start2)
let end = min(end1, end2)
// Check if the intersection interval is empty
if start > end {
return "NO"
}
// Calculate the length of the intersection interval
let length = end - start + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection interval
let start = max(start1, start2)
let end = min(end1, end2)
// Check if the intersection interval is empty
if start > end {
return "NO"
}
// Calculate the length of the intersection interval
let length = end - start + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(min(end1, end2) - max(start1, start2) + 1, 0)
return (length == 1 || length == 2 || length == 3 || length == 5) ? "YES" : "NO"
}<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(min(end1, end2) - max(start1, start2) + 1, 0)
return (length == 1 || length == 2 || length == 3 || length == 5) ? "YES" : "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection interval
let start = max(start1, start2)
let end = min(end1, end2)
// Check if the intersection interval is empty
if start > end {
return "NO"
}
// Calculate the length of the intersection interval
let length = end - start + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection interval
let start = max(start1, start2)
let end = min(end1, end2)
// Check if the intersection interval is empty
if start > end {
return "NO"
}
// Calculate the length of the intersection interval
let length = end - start + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(min(end1, end2) - max(start1, start2) + 1, 0)
if length == 0 {
return "NO"
}
if isPrime(number: length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(min(end1, end2) - max(start1, start2) + 1, 0)
if length == 0 {
return "NO"
}
if isPrime(number: length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(min(end1, end2) - max(start1, start2) + 1, 0)
if length == 0 {
return "NO"
}
if isPrime(number: length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(min(end1, end2) - max(start1, start2) + 1, 0)
if length == 0 {
return "NO"
}
if isPrime(number: length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection interval
let start = max(start1, start2)
let end = min(end1, end2)
// Check if the intersection interval is empty
if start > end {
return "NO"
}
// Calculate the length of the intersection interval
let length = end - start + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection interval
let start = max(start1, start2)
let end = min(end1, end2)
// Check if the intersection interval is empty
if start > end {
return "NO"
}
// Calculate the length of the intersection interval
let length = end - start + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
return (start..<end).contains(start)? "YES" : "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
return (start..<end).contains(start)? "YES" : "NO"
}
```return (start..<end).contains(start)? "YES" : "NO" // string literal is unusedreturn (start..<end).contains(start)? "YES" : "NO" // expected expressionreturn (start..<end).contains(start)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return (start..<end).contains(start)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return (start..<end).contains(start)? "YES" : "NO" // consecutive statements on a line must be separated by ';'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
return start < end? "YES" : "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
return start < end? "YES" : "NO"
}
```return start < end? "YES" : "NO" // consecutive statements on a line must be separated by ';'return start < end? "YES" : "NO" // cannot convert return expression of type 'Bool' to return type 'String'return start < end? "YES" : "NO" // string literal is unusedreturn start < end? "YES" : "NO" // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return start < end? "YES" : "NO" // expected expressionreturn start < end? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Int'return start < end? "YES" : "NO" // consecutive statements on a line must be separated by ';'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
return isPrime(end - start + 1)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
guard n > 1 else { return false }
guard n!= 2 else { return true }
guard n % 2!= 0 else { return false }
for i in 3..<Int(sqrt(Double(n))) {
if n % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
return isPrime(end - start + 1)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
guard n > 1 else { return false }
guard n!= 2 else { return true }
guard n % 2!= 0 else { return false }
for i in 3..<Int(sqrt(Double(n))) {
if n % i == 0 {
return false
}
}
return true
}
```return isPrime(end - start + 1)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(end - start + 1)? "YES" : "NO" // expected expressionreturn isPrime(end - start + 1)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(end - start + 1)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(end - start + 1)? "YES" : "NO" // string literal is unusedguard n!= 2 else { return true } // cannot force unwrap value of non-optional type 'Int'guard n!= 2 else { return true } // '=' must have consistent whitespace on both sidesguard n!= 2 else { return true } // use of '=' in a boolean context, did you mean '=='?guard n % 2!= 0 else { return false } // '=' must have consistent whitespace on both sidesguard n % 2!= 0 else { return false } // use of '=' in a boolean context, did you mean '=='?guard n % 2!= 0 else { return false } // cannot force unwrap value of non-optional type 'Int'guard n % 2!= 0 else { return false } // expression is not assignable: binary operator returns immutable valuefunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
return "\(max(start1, start2)) \(min(end1, end2))"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
return "\(max(start1, start2)) \(min(end1, end2))"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
return (start...end).contains(start)? "YES" : "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
return (start...end).contains(start)? "YES" : "NO"
}
```return (start...end).contains(start)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return (start...end).contains(start)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return (start...end).contains(start)? "YES" : "NO" // string literal is unusedreturn (start...end).contains(start)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return (start...end).contains(start)? "YES" : "NO" // expected expressionfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
return "\(max(start1, start2)) \(min(end1, end2))"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
return "\(max(start1, start2)) \(min(end1, end2))"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
return (start...end).contains(start)? "YES" : "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
return (start...end).contains(start)? "YES" : "NO"
}
```return (start...end).contains(start)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return (start...end).contains(start)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return (start...end).contains(start)? "YES" : "NO" // string literal is unusedreturn (start...end).contains(start)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return (start...end).contains(start)? "YES" : "NO" // expected expressionfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
return (max(start1, start2)..<min(end1, end2)).count == 1? "YES" : "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
return (max(start1, start2)..<min(end1, end2)).count == 1? "YES" : "NO"
}
```return (max(start1, start2)..<min(end1, end2)).count == 1? "YES" : "NO" // cannot convert return expression of type 'Bool' to return type 'String'return (max(start1, start2)..<min(end1, end2)).count == 1? "YES" : "NO" // consecutive statements on a line must be separated by ';'return (max(start1, start2)..<min(end1, end2)).count == 1? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Int'return (max(start1, start2)..<min(end1, end2)).count == 1? "YES" : "NO" // consecutive statements on a line must be separated by ';'return (max(start1, start2)..<min(end1, end2)).count == 1? "YES" : "NO" // expected expressionreturn (max(start1, start2)..<min(end1, end2)).count == 1? "YES" : "NO" // string literal is unusedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
return "\(max(start1, start2)) \(min(end1, end2))"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
return "\(max(start1, start2)) \(min(end1, end2))"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
return (start...end).contains(start)? "YES" : "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
return (start...end).contains(start)? "YES" : "NO"
}
```return (start...end).contains(start)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return (start...end).contains(start)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return (start...end).contains(start)? "YES" : "NO" // string literal is unusedreturn (start...end).contains(start)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return (start...end).contains(start)? "YES" : "NO" // expected expressionfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
return (end - start + 1) % 2 == 0? "NO" : "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
return (end - start + 1) % 2 == 0? "NO" : "YES"
}
```return (end - start + 1) % 2 == 0? "NO" : "YES" // expected expressionreturn (end - start + 1) % 2 == 0? "NO" : "YES" // cannot use optional chaining on non-optional value of type 'Int'return (end - start + 1) % 2 == 0? "NO" : "YES" // string literal is unusedreturn (end - start + 1) % 2 == 0? "NO" : "YES" // consecutive statements on a line must be separated by ';'return (end - start + 1) % 2 == 0? "NO" : "YES" // consecutive statements on a line must be separated by ';'return (end - start + 1) % 2 == 0? "NO" : "YES" // cannot convert return expression of type 'Bool' to return type 'String'```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start
if length <= 0 {
return "NO"
}
if length == 1 {
return "YES"
}
if length == 2 {
return "NO"
}
if length == 3 {
return "YES"
}
if length == 4 {
return "NO"
}
if length == 5 {
return "YES"
}
if length == 6 {
return "NO"
}
if length == 7 {
return "YES"
}
if length == 8 {
return "NO"
}
if length == 9 {
return "YES"
}
if length == 10 {
return "NO"
}
if length == 11 {
return "YES"
}
if length == 12 {
return "NO"
}
if length == 13 {
return "YES"
}
if length == 14 {
return "NO"
}
if length == 15 {
return "YES"
}
if length == 16 {
return "NO"
}
if length == 17 {
return "YES"
}
if length == 18 {
return "NO"
}
if length == 19 {
return "YES"
}
if length == 20 {
return "NO"
}
if length == 21 {
return "YES"
}
if length == 22 {
return "NO"
}
if length == 23 {
return "YES"
}
if length == 24 {
return "NO"
}
if length == 25 {
return "YES"
}
if length == 26 {
return "NO"
}
if length == 27 {
return "YES"
}
if length == 28 {
return "NO"
}
if length == 29 {
return "YES"
}
if length == 30 {
return "NO"
}
if length == 31 {
return "YES"
}
if length == 32 {
return "NO"
}
if length == 33 {
return "YES"
}
if length == 34 {
return "NO"
}
if length == 35 {
return "YES"
}
if length == 36 {
return "NO"
}
if length == 37 {
return "YES"
}
if length == 38 {
return "NO"
}
if length == 39 {
return "YES"
}
if length == 40 {
return "NO"
}
if length == 41 {
return "YES"
}
if length == 42 {
return "NO"
}
if length == 43 {
return "YES"
}
if length == 44 {
return "NO"
}
if length == 45 {
return "YES"
}
if length == 46 {
return "NO"
}
if length == 47 {
return "YES"
}
if length == 48 {
return "NO"
}
if length == 49 {
return "YES"
}
if length == 50 {
return "NO"
}
if length == 51 {
return "YES"
}
if length == 52 {
return "NO"
}
if length == 53 {
return "YES"
}
if length == 54 {
return "NO"
}
if length == 55 {
return "YES"
}
if length == 56 {
return "NO"
}
if length == 57 {
return "YES"
}
if length == 58 {
return "NO"
}
if length == 59 {
return "YES"
}
if length == 60 {
return "NO"
}
if length == 61 {
return "YES"
}
if length == 62 {
return "NO"
}
if length == 63 {
return "YES"
}
if length == 64 {
return "NO"
}
if length ==XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scopefunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
return (end - start + 1) % 2 == 0? "NO" : "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
return (end - start + 1) % 2 == 0? "NO" : "YES"
}
```return (end - start + 1) % 2 == 0? "NO" : "YES" // expected expressionreturn (end - start + 1) % 2 == 0? "NO" : "YES" // cannot use optional chaining on non-optional value of type 'Int'return (end - start + 1) % 2 == 0? "NO" : "YES" // string literal is unusedreturn (end - start + 1) % 2 == 0? "NO" : "YES" // consecutive statements on a line must be separated by ';'return (end - start + 1) % 2 == 0? "NO" : "YES" // consecutive statements on a line must be separated by ';'return (end - start + 1) % 2 == 0? "NO" : "YES" // cannot convert return expression of type 'Bool' to return type 'String'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start
if length <= 0 {
return "NO"
}
if length == 1 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start
if length <= 0 {
return "NO"
}
if length == 1 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
```return isPrime(length)? "YES" : "NO" // expected expressionreturn isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(length)? "YES" : "NO" // string literal is unusedreturn isPrime(length)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if end1 < start2 || end2 < start1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length < 2 {
return "NO"
}
if length == 2 {
return "YES"
}
for i in 2...length/2 {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if end1 < start2 || end2 < start1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length < 2 {
return "NO"
}
if length == 2 {
return "YES"
}
for i in 2...length/2 {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failed```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start
if length <= 0 {
return "NO"
}
if length == 1 {
return "YES"
}
if length == 2 {
return "NO"
}
if length == 3 {
return "YES"
}
if length == 5 {
return "NO"
}
if length == 7 {
return "YES"
}
if length == 11 {
return "NO"
}
if length == 13 {
return "YES"
}
if length == 17 {
return "NO"
}
if length == 19 {
return "YES"
}
if length == 23 {
return "NO"
}
if length == 29 {
return "YES"
}
if length == 31 {
return "NO"
}
if length == 37 {
return "YES"
}
if length == 41 {
return "NO"
}
if length == 43 {
return "YES"
}
if length == 47 {
return "NO"
}
if length == 53 {
return "YES"
}
if length == 59 {
return "NO"
}
if length == 61 {
return "YES"
}
if length == 67 {
return "NO"
}
if length == 71 {
return "YES"
}
if length == 73 {
return "NO"
}
if length == 79 {
return "YES"
}
if length == 83 {
return "NO"
}
if length == 89 {
return "YES"
}
if length == 97 {
return "NO"
}
if length == 101 {
return "YES"
}
if length == 103 {
return "NO"
}
if length == 107 {
return "YES"
}
if length == 109 {
return "NO"
}
if length == 113 {
return "YES"
}
if length == 127 {
return "NO"
}
if length == 131 {
return "YES"
}
if length == 137 {
return "NO"
}
if length == 139 {
return "YES"
}
if length == 149 {
return "NO"
}
if length == 151 {
return "YES"
}
if length == 157 {
return "NO"
}
if length == 163 {
return "YES"
}
if length == 167 {
return "NO"
}
if length == 173 {
return "YES"
}
if length == 179 {
return "NO"
}
if length == 181 {
return "YES"
}
if length == 191 {
return "NO"
}
if length == 193 {
return "YES"
}
if length == 197 {
return "NO"
}
if length == 199 {
return "YES"
}
if length == 211 {
return "NO"
}
if length == 223 {
return "YES"
}
if length == 227 {
return "NO"
}
if length == 229 {
return "YES"
}
if length == 233 {
return "NO"
}
if length == 239 {
return "YES"
}
if length == 241 {
return "NO"
}
if length == 251 {
return "YES"
}
if length == 257 {
return "NO"
}
if length == 263 {
return "YES"
}
if length == 269 {
return "NO"
}
if length == 271 {
return "YES"
}
if length == 277 {
return "NO"
}
if length == 281 {
return "YES"
}
if length == 283 {
XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scopefunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
if length % 3 == 0 {
return "NO"
}
if length % 5 == 0 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
if length % 3 == 0 {
return "NO"
}
if length % 5 == 0 {
return "NO"
}
return "YES"
}
```func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if a > d || b < c {
return "NO"
}
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if a > d || b < c {
return "NO"
}
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```return isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(length)? "YES" : "NO" // expected expressionreturn isPrime(length)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(length)? "YES" : "NO" // string literal is unusedreturn isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
}
```} // missing return in global function expected to return 'String'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if (a > d || b < c) {
return "NO"
}
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if (a > d || b < c) {
return "NO"
}
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
```return isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(length)? "YES" : "NO" // expected expressionreturn isPrime(length)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(length)? "YES" : "NO" // string literal is unusedreturn isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if a > d || b < c {
return "NO"
}
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if a > d || b < c {
return "NO"
}
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```return isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(length)? "YES" : "NO" // expected expressionreturn isPrime(length)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(length)? "YES" : "NO" // string literal is unusedreturn isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if (a > d || b < c) {
return "NO"
}
let (e, f) = (max(a, c), min(b, d))
let length = f - e + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if (a > d || b < c) {
return "NO"
}
let (e, f) = (max(a, c), min(b, d))
let length = f - e + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
```return isPrime(length)? "YES" : "NO" // string literal is unusedreturn isPrime(length)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(length)? "YES" : "NO" // expected expressionfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if b < c || a > d {
return "NO"
}
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if b < c || a > d {
return "NO"
}
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```return isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(length)? "YES" : "NO" // expected expressionreturn isPrime(length)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(length)? "YES" : "NO" // string literal is unusedreturn isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if b < c || d < a {
return "NO"
}
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if b < c || d < a {
return "NO"
}
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if (a <= c && c <= b) || (a <= d && d <= b) || (c <= a && a <= d) || (c <= b && b <= d) {
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
return "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if (a <= c && c <= b) || (a <= d && d <= b) || (c <= a && a <= d) || (c <= b && b <= d) {
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
return "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if a > d || b < c { return "NO" }
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 { return false }
if n <= 3 { return true }
if n % 2 == 0 || n % 3 == 0 { return false }
for i in stride(from: 5, through: Int(sqrt(Double(n))), by: 6) {
if n % i == 0 || n % (i + 2) == 0 { return false }
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if a > d || b < c { return "NO" }
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 { return false }
if n <= 3 { return true }
if n % 2 == 0 || n % 3 == 0 { return false }
for i in stride(from: 5, through: Int(sqrt(Double(n))), by: 6) {
if n % i == 0 || n % (i + 2) == 0 { return false }
}
return true
}
```return isPrime(length)? "YES" : "NO" // expected expressionreturn isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(length)? "YES" : "NO" // string literal is unusedreturn isPrime(length)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
let (start, end) = (max(a, c), min(b, d))
return (start <= end && isPrime(end - start + 1))? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
guard n > 1 else { return false }
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
let (start, end) = (max(a, c), min(b, d))
return (start <= end && isPrime(end - start + 1))? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
guard n > 1 else { return false }
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
```return (start <= end && isPrime(end - start + 1))? "YES" : "NO" // consecutive statements on a line must be separated by ';'return (start <= end && isPrime(end - start + 1))? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return (start <= end && isPrime(end - start + 1))? "YES" : "NO" // expected expressionreturn (start <= end && isPrime(end - start + 1))? "YES" : "NO" // consecutive statements on a line must be separated by ';'return (start <= end && isPrime(end - start + 1))? "YES" : "NO" // string literal is unusedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else { return false }
if number == 2 { return true }
if number % 2 == 0 { return false }
let sqrt = Int(sqrt(Double(number)))
for i in 3...sqrt {
if number % i == 0 { return false }
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else { return false }
if number == 2 { return true }
if number % 2 == 0 { return false }
let sqrt = Int(sqrt(Double(number)))
for i in 3...sqrt {
if number % i == 0 { return false }
}
return true
}
```return isPrime(length)? "YES" : "NO" // string literal is unusedreturn isPrime(length)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(length)? "YES" : "NO" // expected expressionfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
return length.isPrime? "YES" : "NO"
}
extension Int {
var isPrime: Bool {
return (2..<self).none { self % $0 == 0 }
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
return length.isPrime? "YES" : "NO"
}
extension Int {
var isPrime: Bool {
return (2..<self).none { self % $0 == 0 }
}
}
```return length.isPrime? "YES" : "NO" // string literal is unusedreturn length.isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return length.isPrime? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return length.isPrime? "YES" : "NO" // expected expressionreturn length.isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return (2..<self).none { self % $0 == 0 } // value of type 'Range<Int>' has no member 'none'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
return length > 1 && length % 2!= 0? "YES" : "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
return length > 1 && length % 2!= 0? "YES" : "NO"
}
```return length > 1 && length % 2!= 0? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Int'return length > 1 && length % 2!= 0? "YES" : "NO" // cannot convert return expression of type '()' to return type 'String'return length > 1 && length % 2!= 0? "YES" : "NO" // cannot force unwrap value of non-optional type 'Int'return length > 1 && length % 2!= 0? "YES" : "NO" // expected expressionreturn length > 1 && length % 2!= 0? "YES" : "NO" // consecutive statements on a line must be separated by ';'return length > 1 && length % 2!= 0? "YES" : "NO" // string literal is unusedreturn length > 1 && length % 2!= 0? "YES" : "NO" // expression is not assignable: '&&' returns immutable valuereturn length > 1 && length % 2!= 0? "YES" : "NO" // '=' must have consistent whitespace on both sidesreturn length > 1 && length % 2!= 0? "YES" : "NO" // consecutive statements on a line must be separated by ';'return length > 1 && length % 2!= 0? "YES" : "NO" // type 'Int' cannot be used as a boolean; test for '!= 0' insteadfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
guard interval1.0 <= interval2.0 else {
return "NO"
}
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
let isPrime = length > 1 && (length % 2 == 1 || length % 3 == 0)
return isPrime? "YES" : "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
guard interval1.0 <= interval2.0 else {
return "NO"
}
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
let isPrime = length > 1 && (length % 2 == 1 || length % 3 == 0)
return isPrime? "YES" : "NO"
}
```return isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // expected expressionreturn isPrime? "YES" : "NO" // string literal is unusedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime? "YES" : "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime? "YES" : "NO"
}
```return isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // expected expressionreturn isPrime? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // string literal is unusedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
return length > 1 && isPrime(length)? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
return length > 1 && isPrime(length)? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```return length > 1 && isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return length > 1 && isPrime(length)? "YES" : "NO" // expected expressionreturn length > 1 && isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return length > 1 && isPrime(length)? "YES" : "NO" // string literal is unusedreturn length > 1 && isPrime(length)? "YES" : "NO" // cannot convert return expression of type 'Bool' to return type 'String'return length > 1 && isPrime(length)? "YES" : "NO" // optional type 'Bool?' cannot be used as a boolean; test for '!= nil' insteadreturn length > 1 && isPrime(length)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "YES"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "YES"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "YES"
}
if length == 2 {
return "NO"
}
for i in 2..<Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "YES"
}
if length == 2 {
return "NO"
}
for i in 2..<Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 {
return "YES"
}
if length < 2 {
return "NO"
}
for i in 2..<Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 {
return "YES"
}
if length < 2 {
return "NO"
}
for i in 2..<Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 {
return "YES"
} else if length < 2 {
return "NO"
} else {
for i in 2..<Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 {
return "YES"
} else if length < 2 {
return "NO"
} else {
for i in 2..<Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "YES"
}
if length == 2 {
return "NO"
}
for i in 2..<Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "YES"
}
if length == 2 {
return "NO"
}
for i in 2..<Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
guard start <= end else {
return "NO"
}
let length = end - start + 1
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
guard start <= end else {
return "NO"
}
let length = end - start + 1
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
guard start <= end else {
return "NO"
}
let length = end - start + 1
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
guard start <= end else {
return "NO"
}
let length = end - start + 1
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 || length == 3 {
return "YES"
}
if length % 2 == 0 || length % 3 == 0 {
return "NO"
}
for i in 5...Int(sqrt(Double(length))) {
if length % i == 0 { return "NO" } }
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 || length == 3 {
return "YES"
}
if length % 2 == 0 || length % 3 == 0 {
return "NO"
}
for i in 5...Int(sqrt(Double(length))) {
if length % i == 0 { return "NO" } }
}
return "YES"
}
```return "YES" // return invalid outside of a func} // extraneous '}' at top levelfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 || length == 3 {
return "YES"
}
if length % 2 == 0 || length % 3 == 0 {
return "NO"
}
for i in 5...Int(sqrt(Double(length))) {
if length % i == 0 { return "NO" } }
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 || length == 3 {
return "YES"
}
if length % 2 == 0 || length % 3 == 0 {
return "NO"
}
for i in 5...Int(sqrt(Double(length))) {
if length % i == 0 { return "NO" } }
}
return "YES"
}
```return "YES" // return invalid outside of a func} // extraneous '}' at top levelfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
}
return "YES"
}
```return "YES" // return invalid outside of a func} // extraneous '}' at top levelfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
}
return "YES"
}
```return "YES" // return invalid outside of a func} // extraneous '}' at top levelfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
}
return "YES"
}
```return "YES" // return invalid outside of a func} // extraneous '}' at top levelimport Foundation
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}```swift
import Foundation
/*
Function to multiply two matrices represented as 2D arrays of Doubles.
Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
*/
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
/*
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
*/
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
(1, (1, interval1, intervalXCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scopeimport Foundation
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}```swift
import Foundation
/*
Function to multiply two matrices represented as 2D arrays of Doubles.
Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
*/
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
/*
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
*/
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
(1, interval1,XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scopeimport Foundation
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}```swift
import Foundation
/*
Function to multiply two matrices represented as 2D arrays of Doubles.
Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
*/
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
/*
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
*/
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
(interval1XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scopeimport Foundation
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}```swift
import Foundation
/*
Function to multiply two matrices represented as 2D arrays of Doubles.
Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
*/
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
/*
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
*/
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
(interval1, interval1XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scopeimport Foundation
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}```swift
import Foundation
/*
Function to multiply two matrices represented as 2D arrays of Doubles.
Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
*/
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
/*
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
*/
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
(interval1: (1XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scopeimport Foundation
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}```swift
import Foundation
/*
Function to multiply two matrices represented as 2D arrays of Doubles.
Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
*/
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
/*
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
*/
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
(interval1, interval: (1, interval: (1, interval: (1, interval: (1XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scopeimport Foundation
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}```swift
import Foundation
/*
Function to multiply two matrices represented as 2D arrays of Doubles.
Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
*/
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
/*
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
*/
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scopeimport Foundation
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}```swift
import Foundation
/*
Function to multiply two matrices represented as 2D arrays of Doubles.
Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
*/
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
/*
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
*/
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scopeimport Foundation
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}```swift
import Foundation
/*
Function to multiply two matrices represented as 2D arrays of Doubles.
Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
*/
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
/*
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
*/
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
(1, (1, (XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scopeimport Foundation
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}```swift
import Foundation
/*
Function to multiply two matrices represented as 2D arrays of Doubles.
Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
*/
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
/*
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
*/
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
(interval1, interval:XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
than or equal to its equal to zero,XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
Here is a function to check if the intersection of two intervals don't the intervals don't not intersect, if they intersect, you need to check if they intersect and if they intersect and if they intersect and if they intersect and if they do they intersect and if they intersect andXCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
Here is a function isPrime(start with the same as follows:
equal to its greater than the start and end.
XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
<|padding|>
XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
Here is a function to check if the intersection of the intersection of two intervals do not intersect, if they intersect, and return "intersect the intervals do not overlap at all
intervals are prime(a
(start and if they are prime(startsXCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
Here is a function isXCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
Here is a function isEqual to check if the intersection of two intervals do not overlap.
intervals are overlapping, if they are overlapping,XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
Here is a solution:
XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let interval1.
Here is aXCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scopefunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
if intersectionLength < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if isPrime(i) {
return "NO"
}
}
return "YES"
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
if intersectionLength < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if isPrime(i) {
return "NO"
}
}
return "YES"
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}
```func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
// Check if intersection length is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
// Check if intersection length is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let maxStart = max(start1, start2)
let minEnd = min(end1, end2)
if maxStart > minEnd {
return "NO"
} else {
let intersectionLength = minEnd - maxStart
if intersectionLength < 2 {
return "NO"
} else {
for i in maxStart...intersectionLength-1 {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
}
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let maxStart = max(start1, start2)
let minEnd = min(end1, end2)
if maxStart > minEnd {
return "NO"
} else {
let intersectionLength = minEnd - maxStart
if intersectionLength < 2 {
return "NO"
} else {
for i in maxStart...intersectionLength-1 {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
}
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Check if intersection length is a prime number
if intersectionEnd - intersectionStart < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if i != 2 && (intersectionEnd - intersectionStart) % i == 0 {
return "NO"
}
}
return "YES"
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Check if intersection length is a prime number
if intersectionEnd - intersectionStart < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if i != 2 && (intersectionEnd - intersectionStart) % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
// Check if the length of the intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
// Check if the length of the intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
guard start1 <= end2, start2 <= end1 else {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
if intersectionLength < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if isPrime(i) {
return "NO"
}
}
return "YES"
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
guard start1 <= end2, start2 <= end1 else {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
if intersectionLength < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if isPrime(i) {
return "NO"
}
}
return "YES"
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}
```func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let minStart = max(start1, start2)
let maxEnd = min(end1, end2)
if minStart > maxEnd {
return "NO"
}
let intersectionLength = maxEnd - minStart
if intersectionLength < 2 {
return "NO"
}
for i in minStart...intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let minStart = max(start1, start2)
let maxEnd = min(end1, end2)
if minStart > maxEnd {
return "NO"
}
let intersectionLength = maxEnd - minStart
if intersectionLength < 2 {
return "NO"
}
for i in minStart...intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
// Check if the length of the intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
// Check if the length of the intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
// Check if the length of the intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
// Check if the length of the intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
// Check if the length of the intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
// Check if the length of the intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Determine the intersection of the intervals
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// If the intervals don't intersect, return "NO"
if intersectionStart > intersectionEnd {
return "NO"
}
// Determine the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Determine the intersection of the intervals
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// If the intervals don't intersect, return "NO"
if intersectionStart > intersectionEnd {
return "NO"
}
// Determine the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if end1 < start2 || end2 < start1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Calculate the length of the intersection
let length = intersectionEnd - intersectionStart + 1
// Check if the length is a prime number
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if end1 < start2 || end2 < start1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Calculate the length of the intersection
let length = intersectionEnd - intersectionStart + 1
// Check if the length is a prime number
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length of the intersection is a prime number
if intersectionLength <= 1 {
return "NO"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length of the intersection is a prime number
if intersectionLength <= 1 {
return "NO"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Determine the intersection of the two intervals
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// If the intervals don't intersect, return "NO"
if intersectionStart > intersectionEnd {
return "NO"
}
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Determine the intersection of the two intervals
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// If the intervals don't intersect, return "NO"
if intersectionStart > intersectionEnd {
return "NO"
}
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Determine the intersection of the intervals
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// If the intervals don't intersect, return "NO"
if intersectionStart > intersectionEnd {
return "NO"
}
// Determine the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length is a prime number
if intersectionLength <= 1 {
return "NO"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Determine the intersection of the intervals
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// If the intervals don't intersect, return "NO"
if intersectionStart > intersectionEnd {
return "NO"
}
// Determine the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length is a prime number
if intersectionLength <= 1 {
return "NO"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Determine the intersection of the intervals
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// If the intervals don't intersect, return "NO"
if intersectionStart > intersectionEnd {
return "NO"
}
// Calculate the length of the intersection
let length = intersectionEnd - intersectionStart + 1
// Check if the length is a prime number
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Determine the intersection of the intervals
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// If the intervals don't intersect, return "NO"
if intersectionStart > intersectionEnd {
return "NO"
}
// Calculate the length of the intersection
let length = intersectionEnd - intersectionStart + 1
// Check if the length is a prime number
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Determine the intersection of the intervals
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// If the intervals don't intersect, return "NO"
if intersectionStart > intersectionEnd {
return "NO"
}
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length is a prime number
if intersectionLength <= 1 {
return "NO"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Determine the intersection of the intervals
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// If the intervals don't intersect, return "NO"
if intersectionStart > intersectionEnd {
return "NO"
}
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length is a prime number
if intersectionLength <= 1 {
return "NO"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Determine the intersection of the intervals
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// If the intervals don't intersect, return "NO"
if intersectionStart > intersectionEnd {
return "NO"
}
// Determine the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length is a prime number
if intersectionLength <= 1 {
return "NO"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Determine the intersection of the intervals
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// If the intervals don't intersect, return "NO"
if intersectionStart > intersectionEnd {
return "NO"
}
// Determine the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length is a prime number
if intersectionLength <= 1 {
return "NO"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Determine the intersection of the two intervals
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// If the intervals don't intersect, return "NO"
if intersectionStart > intersectionEnd {
return "NO"
}
// Determine the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length is a prime number
if intersectionLength <= 1 {
return "NO"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Determine the intersection of the two intervals
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// If the intervals don't intersect, return "NO"
if intersectionStart > intersectionEnd {
return "NO"
}
// Determine the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length is a prime number
if intersectionLength <= 1 {
return "NO"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Determine the intersection of the intervals
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// If the intervals don't intersect, return "NO"
if intersectionStart > intersectionEnd {
return "NO"
}
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Determine the intersection of the intervals
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// If the intervals don't intersect, return "NO"
if intersectionStart > intersectionEnd {
return "NO"
}
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedimport Foundation
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
if length < 2 {
return "NO"
}
for i in 2...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
import Foundation
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
if length < 2 {
return "NO"
}
for i in 2...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundimport Foundation
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
import Foundation
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedimport Foundation
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
import Foundation
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```import Foundation
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
import Foundation
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```import Foundation
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
if length < 2 {
return "NO"
}
for i in 2...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
import Foundation
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
if length < 2 {
return "NO"
}
for i in 2...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundimport Foundation
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
import Foundation
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```import Foundation
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
import Foundation
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```import Foundation
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
import Foundation
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```import Foundation
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
import Foundation
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```import Foundation
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
import Foundation
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<Int(sqrt(Double(number))) + 1 {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<Int(sqrt(Double(number))) + 1 {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<Int(sqrt(Double(number))) + 1 {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<Int(sqrt(Double(number))) + 1 {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<Int(sqrt(Double(number))) + 1 {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<Int(sqrt(Double(number))) + 1 {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<Int(sqrt(Double(number))) + 1 {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<Int(sqrt(Double(number))) + 1 {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<Int(sqrt(Double(number))) + 1 {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<Int(sqrt(Double(number))) + 1 {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<Int(sqrt(Double(number))) + 1 {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<Int(sqrt(Double(number))) + 1 {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let sqrtOfNumber = Int(sqrt(Double(number)))
for i in 3...sqrtOfNumber {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let sqrtOfNumber = Int(sqrt(Double(number)))
for i in 3...sqrtOfNumber {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
return isPrime(intersectionLength) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<Int(sqrt(Double(number))) + 1 {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
return isPrime(intersectionLength) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<Int(sqrt(Double(number))) + 1 {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in stride(from: 3, through: boundary, by: 2) {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in stride(from: 3, through: boundary, by: 2) {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<Int(sqrt(Double(number))) + 1 {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<Int(sqrt(Double(number))) + 1 {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<Int(sqrt(Double(number))) + 1 {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<Int(sqrt(Double(number))) + 1 {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<Int(sqrt(Double(number))) + 1 {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<Int(sqrt(Double(number))) + 1 {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let sqrtNumber = Int(sqrt(Double(number)))
for i in 3...sqrtNumber {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let sqrtNumber = Int(sqrt(Double(number)))
for i in 3...sqrtNumber {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 0 {
return "NO"
}
if length == 1 || length == 2 {
return "YES"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 0 {
return "NO"
}
if length == 1 || length == 2 {
return "YES"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// If the two intervals don't intersect, return "NO".
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
if isPrime(interval1.1 - interval1.0) {
return "YES"
} else {
return "NO"
}
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// If the two intervals don't intersect, return "NO".
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
if isPrime(interval1.1 - interval1.0) {
return "YES"
} else {
return "NO"
}
}
```if isPrime(interval1.1 - interval1.0) { // cannot find 'isPrime' in scopefunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let intersection = (max(start1, start2), min(end1, end2))
return isPrime(intersection.1 - intersection.0 + 1)? "YES" : "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let intersection = (max(start1, start2), min(end1, end2))
return isPrime(intersection.1 - intersection.0 + 1)? "YES" : "NO"
}
```return isPrime(intersection.1 - intersection.0 + 1)? "YES" : "NO" // expected expressionreturn isPrime(intersection.1 - intersection.0 + 1)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(intersection.1 - intersection.0 + 1)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(intersection.1 - intersection.0 + 1)? "YES" : "NO" // cannot find 'isPrime' in scopereturn isPrime(intersection.1 - intersection.0 + 1)? "YES" : "NO" // cannot convert return expression of type 'Optional<_>' to return type 'String'return isPrime(intersection.1 - intersection.0 + 1)? "YES" : "NO" // string literal is unusedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end1 || start2 > end2 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "YES"
}
return "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end1 || start2 > end2 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "YES"
}
return "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Your code here
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Your code here
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let intersection = (max(start1, start2), min(end1, end2))
let (start, end) = intersection
if start == end {
return "YES"
}
return "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let intersection = (max(start1, start2), min(end1, end2))
let (start, end) = intersection
if start == end {
return "YES"
}
return "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
if length == 1 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
if length == 1 {
return "NO"
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end1 || start2 > end2 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length < 2 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end1 || start2 > end2 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length < 2 {
return "NO"
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Find the intersection of the two intervals
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
// No intersection
return "NO"
} else if end - start <= 1 {
// Length of intersection is not a prime number
return "NO"
} else {
// Check if the length of intersection is a prime number
var isPrime = true
for i in 2..<end - start {
if end - start % i == 0 {
isPrime = false
break
}
}
return isPrime? "YES" : "NO"
}
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Find the intersection of the two intervals
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
// No intersection
return "NO"
} else if end - start <= 1 {
// Length of intersection is not a prime number
return "NO"
} else {
// Check if the length of intersection is a prime number
var isPrime = true
for i in 2..<end - start {
if end - start % i == 0 {
isPrime = false
break
}
}
return isPrime? "YES" : "NO"
}
}
```return isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // string literal is unusedreturn isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // expected expressionreturn isPrime? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Find the intersection of the two intervals
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
// No intersection
return "NO"
} else if end - start <= 1 {
// Length of intersection is not a prime number
return "NO"
} else {
// Check if the length of intersection is a prime number
var isPrime = true
for i in 2..<end - start {
if end - start % i == 0 {
isPrime = false
break
}
}
return isPrime? "YES" : "NO"
}
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Find the intersection of the two intervals
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
// No intersection
return "NO"
} else if end - start <= 1 {
// Length of intersection is not a prime number
return "NO"
} else {
// Check if the length of intersection is a prime number
var isPrime = true
for i in 2..<end - start {
if end - start % i == 0 {
isPrime = false
break
}
}
return isPrime? "YES" : "NO"
}
}
```return isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // string literal is unusedreturn isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // expected expressionreturn isPrime? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Find the intersection of the two intervals
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
// No intersection
return "NO"
} else if end - start <= 1 {
// Length of intersection is not a prime number
return "NO"
} else {
// Check if the length of intersection is a prime number
var isPrime = true
for i in 2..<end - start {
if end - start % i == 0 {
isPrime = false
break
}
}
return isPrime? "YES" : "NO"
}
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Find the intersection of the two intervals
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
// No intersection
return "NO"
} else if end - start <= 1 {
// Length of intersection is not a prime number
return "NO"
} else {
// Check if the length of intersection is a prime number
var isPrime = true
for i in 2..<end - start {
if end - start % i == 0 {
isPrime = false
break
}
}
return isPrime? "YES" : "NO"
}
}
```return isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // string literal is unusedreturn isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // expected expressionreturn isPrime? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let intersectionLength = end - start + 1
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let intersectionLength = end - start + 1
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Find the intersection of the two intervals
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
// No intersection
return "NO"
} else if end - start <= 1 {
// Length of intersection is not a prime number
return "NO"
} else {
// Check if the length of intersection is a prime number
var isPrime = true
for i in 2..<end - start {
if end - start % i == 0 {
isPrime = false
break
}
}
return isPrime? "YES" : "NO"
}
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Find the intersection of the two intervals
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
// No intersection
return "NO"
} else if end - start <= 1 {
// Length of intersection is not a prime number
return "NO"
} else {
// Check if the length of intersection is a prime number
var isPrime = true
for i in 2..<end - start {
if end - start % i == 0 {
isPrime = false
break
}
}
return isPrime? "YES" : "NO"
}
}
```return isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // string literal is unusedreturn isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // expected expressionreturn isPrime? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let intersectionLength = end - start + 1
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let intersectionLength = end - start + 1
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Find the intersection of the two intervals
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
// No intersection
return "NO"
} else if end - start < 2 {
// Length of intersection is 1 or 0, not a prime number
return "NO"
} else {
// Check if the length of intersection is a prime number
let length = end - start + 1
var isPrime = true
if length < 2 {
isPrime = false
} else {
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
}
if isPrime {
return "YES"
} else {
return "NO"
}
}
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Find the intersection of the two intervals
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
// No intersection
return "NO"
} else if end - start < 2 {
// Length of intersection is 1 or 0, not a prime number
return "NO"
} else {
// Check if the length of intersection is a prime number
let length = end - start + 1
var isPrime = true
if length < 2 {
isPrime = false
} else {
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
}
if isPrime {
return "YES"
} else {
return "NO"
}
}
}
```func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let intersectionLength = end - start + 1
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let intersectionLength = end - start + 1
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let intersectionLength = end - start + 1
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let intersectionLength = end - start + 1
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Find the intersection of the two intervals
let start = max(start1, start2)
let end = min(end1, end2)
// If there is no intersection, return "NO"
if start > end {
return "NO"
}
// Calculate the length of the intersection
let length = end - start + 1
// Check if the length is a prime number
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Find the intersection of the two intervals
let start = max(start1, start2)
let end = min(end1, end2)
// If there is no intersection, return "NO"
if start > end {
return "NO"
}
// Calculate the length of the intersection
let length = end - start + 1
// Check if the length is a prime number
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length < 2 {
return "NO"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
if isPrime {
return "YES"
} else {
return "NO"
}
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length < 2 {
return "NO"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
if isPrime {
return "YES"
} else {
return "NO"
}
}
```
### Problem // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length < 2 {
return "NO"
}
var isPrime = true
for i in 2..<Int(sqrt(Double(length))) {
if length % i == 0 {
isPrime = false
break
}
}
if isPrime {
return "YES"
} else {
return "NO"
}
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length < 2 {
return "NO"
}
var isPrime = true
for i in 2..<Int(sqrt(Double(length))) {
if length % i == 0 {
isPrime = false
break
}
}
if isPrime {
return "YES"
} else {
return "NO"
}
}
```
### Problem // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength == 1 {
return "NO"
}
if intersectionLength == 2 {
return "YES"
}
if intersectionLength % 2 == 0 {
return "NO"
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength == 1 {
return "NO"
}
if intersectionLength == 2 {
return "YES"
}
if intersectionLength % 2 == 0 {
return "NO"
}
return "YES"
}
```
### Problem // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 0 {
return "NO"
}
var isPrime = true
for i in 2..<Int(sqrt(Double(length))) {
if length % i == 0 {
isPrime = false
break
}
}
if isPrime {
return "YES"
} else {
return "NO"
}
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 0 {
return "NO"
}
var isPrime = true
for i in 2..<Int(sqrt(Double(length))) {
if length % i == 0 {
isPrime = false
break
}
}
if isPrime {
return "YES"
} else {
return "NO"
}
}
```
### Problem // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length < 2 {
return "NO"
}
var isPrime = true
for i in 2..<Int(sqrt(Double(length))) {
if length % i == 0 {
isPrime = false
break
}
}
if isPrime {
return "YES"
} else {
return "NO"
}
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length < 2 {
return "NO"
}
var isPrime = true
for i in 2..<Int(sqrt(Double(length))) {
if length % i == 0 {
isPrime = false
break
}
}
if isPrime {
return "YES"
} else {
return "NO"
}
}
```
// Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 0 {
return "NO"
}
if length == 1 {
return "YES"
}
var isPrime = true
for i in 2..<Int(sqrt(Double(length))) {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 0 {
return "NO"
}
if length == 1 {
return "YES"
}
var isPrime = true
for i in 2..<Int(sqrt(Double(length))) {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}
```
### Problem // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 0 {
return "NO"
}
if length == 1 {
return "YES"
}
var isPrime = true
for i in 2..<Int(sqrt(Double(length))) {
if length % i == 0 {
isPrime = false
break
}
}
if isPrime {
return "YES"
} else {
return "NO"
}
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 0 {
return "NO"
}
if length == 1 {
return "YES"
}
var isPrime = true
for i in 2..<Int(sqrt(Double(length))) {
if length % i == 0 {
isPrime = false
break
}
}
if isPrime {
return "YES"
} else {
return "NO"
}
}
```
### Problem // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length < 2 {
return "NO"
}
var isPrime = true
for i in 2..<Int(sqrt(Double(length))) {
if length % i == 0 {
isPrime = false
break
}
}
if isPrime {
return "YES"
} else {
return "NO"
}
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length < 2 {
return "NO"
}
var isPrime = true
for i in 2..<Int(sqrt(Double(length))) {
if length % i == 0 {
isPrime = false
break
}
}
if isPrime {
return "YES"
} else {
return "NO"
}
}
```
### Problem // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength == 0 {
return "NO"
}
var isPrime = true
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
isPrime = false
break
}
}
if isPrime {
return "YES"
} else {
return "NO"
}
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength == 0 {
return "NO"
}
var isPrime = true
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
isPrime = false
break
}
}
if isPrime {
return "YES"
} else {
return "NO"
}
}
```
### Problem // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
var isPrime = true
for i in 2..<Int(sqrt(Double(length))) {
if length % i == 0 {
isPrime = false
break
}
}
if isPrime {
return "YES"
} else {
return "NO"
}
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
var isPrime = true
for i in 2..<Int(sqrt(Double(length))) {
if length % i == 0 {
isPrime = false
break
}
}
if isPrime {
return "YES"
} else {
return "NO"
}
}
```
### Problem // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end1 || start2 > end2 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end1 || start2 > end2 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```
// Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 <= end2 && start2 <= end1 {
let length = max(end1, end2) - min(start1, start2) + 1
if length == 1 {
return "NO"
}
for i in 2...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
return "NO"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 <= end2 && start2 <= end1 {
let length = max(end1, end2) - min(start1, start2) + 1
if length == 1 {
return "NO"
}
for i in 2...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
return "NO"
}
```
// Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 <= end2 && start2 <= end1 {
let length = max(end1, end2) - min(start1, start2) + 1
if length == 1 {
return "NO"
} else {
return "YES"
}
} else {
return "NO"
}
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 <= end2 && start2 <= end1 {
let length = max(end1, end2) - min(start1, start2) + 1
if length == 1 {
return "NO"
} else {
return "YES"
}
} else {
return "NO"
}
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 <= end2, start2 <= end1 {
let length = max(end1, end2) - min(start1, start2) + 1
return isPrime(length) ? "YES" : "NO"
}
return "NO"
}
func isPrime(_ n: Int) -> Bool {
if n < 2 { return false }
if n == 2 { return true }
if n % 2 == 0 { return false }
for i in 3...Int(sqrt(Double(n))) {
if n % i == 0 { return false }
}
return true
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 <= end2, start2 <= end1 {
let length = max(end1, end2) - min(start1, start2) + 1
return isPrime(length) ? "YES" : "NO"
}
return "NO"
}
func isPrime(_ n: Int) -> Bool {
if n < 2 { return false }
if n == 2 { return true }
if n % 2 == 0 { return false }
for i in 3...Int(sqrt(Double(n))) {
if n % i == 0 { return false }
}
return true
}
```
// Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 <= end2 && start2 <= end1 {
let length = max(end1, end2) - min(start1, start2) + 1
return length.isPrime ? "YES" : "NO"
}
return "NO"
}
extension Int {
var isPrime: Bool {
if self < 2 { return false }
for i in 2...Int(sqrt(Double(self))) {
if self % i == 0 { return false }
}
return true
}
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 <= end2 && start2 <= end1 {
let length = max(end1, end2) - min(start1, start2) + 1
return length.isPrime ? "YES" : "NO"
}
return "NO"
}
extension Int {
var isPrime: Bool {
if self < 2 { return false }
for i in 2...Int(sqrt(Double(self))) {
if self % i == 0 { return false }
}
return true
}
}
```
// Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 <= end2 && start2 <= end1 {
let length = max(end1, end2) - min(start1, start2) + 1
return isPrime(length) ? "YES" : "NO"
}
return "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 { return false }
if number == 2 { return true }
if number % 2 == 0 { return false }
for i in 3...Int(sqrt(Double(number))) {
if number % i == 0 { return false }
}
return true
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 <= end2 && start2 <= end1 {
let length = max(end1, end2) - min(start1, start2) + 1
return isPrime(length) ? "YES" : "NO"
}
return "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 { return false }
if number == 2 { return true }
if number % 2 == 0 { return false }
for i in 3...Int(sqrt(Double(number))) {
if number % i == 0 { return false }
}
return true
}
```
// Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start <= end {
return isPrime(end - start + 1) ? "YES" : "NO"
}
return "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 { return false }
if n == 2 { return true }
if n % 2 == 0 { return false }
for i in 3...Int(sqrt(Double(n))) {
if n % i == 0 { return false }
}
return true
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start <= end {
return isPrime(end - start + 1) ? "YES" : "NO"
}
return "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 { return false }
if n == 2 { return true }
if n % 2 == 0 { return false }
for i in 3...Int(sqrt(Double(n))) {
if n % i == 0 { return false }
}
return true
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
return start <= end ? (end - start + 1).isPrime ? "YES" : "NO" : "NO"
}
extension Int {
var isPrime: Bool {
guard self > 1 else { return false }
for i in 2..<Int(sqrt(Double(self))) + 1 {
if self % i == 0 { return false }
}
return true
}
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
return start <= end ? (end - start + 1).isPrime ? "YES" : "NO" : "NO"
}
extension Int {
var isPrime: Bool {
guard self > 1 else { return false }
for i in 2..<Int(sqrt(Double(self))) + 1 {
if self % i == 0 { return false }
}
return true
}
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 <= end2 && start2 <= end1 {
let length = max(end1, end2) - min(start1, start2) + 1
return isPrime(length) ? "YES" : "NO"
}
return "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 { return false }
if n == 2 { return true }
if n % 2 == 0 { return false }
for i in 3...Int(sqrt(Double(n))) {
if n % i == 0 { return false }
}
return true
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 <= end2 && start2 <= end1 {
let length = max(end1, end2) - min(start1, start2) + 1
return isPrime(length) ? "YES" : "NO"
}
return "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 { return false }
if n == 2 { return true }
if n % 2 == 0 { return false }
for i in 3...Int(sqrt(Double(n))) {
if n % i == 0 { return false }
}
return true
}
```
// Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 <= end2 && start2 <= end1 {
let length = min(end1, end2) - max(start1, start2) + 1
return length.isPrime ? "YES" : "NO"
} else {
return "NO"
}
}
extension Int {
var isPrime: Bool {
if self < 2 {
return false
}
for i in 2...Int(sqrt(Double(self))) {
if self % i == 0 {
return false
}
}
return true
}
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 <= end2 && start2 <= end1 {
let length = min(end1, end2) - max(start1, start2) + 1
return length.isPrime ? "YES" : "NO"
} else {
return "NO"
}
}
extension Int {
var isPrime: Bool {
if self < 2 {
return false
}
for i in 2...Int(sqrt(Double(self))) {
if self % i == 0 {
return false
}
}
return true
}
}
```
// Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
var intersection: (Int, Int) = (0, 0)
var result = "NO"
if start1 <= end1 && start2 <= end2 {
if start1 <= start2 {
intersection.0 = start2
} else {
intersection.0 = start1
}
if end1 <= end2 {
intersection.1 = end1
} else {
intersection.1 = end2
}
if intersection.0 <= intersection.1 {
let length = intersection.1 - intersection.0 + 1
if length == 2 || length == 3 || length == 5 || length == 7 || length == 11 || length == 13 || length == 17 || length == 19 || length == 23 || length == 29 {
result = "YES"
}
}
}
return result
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
var intersection: (Int, Int) = (0, 0)
var result = "NO"
if start1 <= end1 && start2 <= end2 {
if start1 <= start2 {
intersection.0 = start2
} else {
intersection.0 = start1
}
if end1 <= end2 {
intersection.1 = end1
} else {
intersection.1 = end2
}
if intersection.0 <= intersection.1 {
let length = intersection.1 - intersection.0 + 1
if length == 2 || length == 3 || length == 5 || length == 7 || length == 11 || length == 13 || length == 17 || length == 19 || length == 23 || length == 29 {
result = "YES"
}
}
}
return result
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart <= intersectionEnd {
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength == 1 {
return "YES"
} else {
return "NO"
}
} else {
return "NO"
}
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart <= intersectionEnd {
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength == 1 {
return "YES"
} else {
return "NO"
}
} else {
return "NO"
}
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart <= intersectionEnd {
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength == 2 || intersectionLength == 3 || intersectionLength == 5 || intersectionLength == 7 {
return "YES"
} else {
return "NO"
}
} else {
return "NO"
}
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart <= intersectionEnd {
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength == 2 || intersectionLength == 3 || intersectionLength == 5 || intersectionLength == 7 {
return "YES"
} else {
return "NO"
}
} else {
return "NO"
}
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart <= intersectionEnd {
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength == 1 {
return "YES"
} else if intersectionLength == 2 {
return "NO"
} else {
for i in 2...intersectionLength / 2 {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
} else {
return "NO"
}
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart <= intersectionEnd {
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength == 1 {
return "YES"
} else if intersectionLength == 2 {
return "NO"
} else {
for i in 2...intersectionLength / 2 {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
} else {
return "NO"
}
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
var intersection: (Int, Int)
var intersectionLength: Int
if start1 <= end1 && start2 <= end2 {
if start1 <= start2 {
intersection = (start2, end1)
} else {
intersection = (start1, end2)
}
intersectionLength = intersection.1 - intersection.0
if intersectionLength == 1 || intersectionLength == 3 || intersectionLength == 5 || intersectionLength == 7 || intersectionLength == 11 {
return "YES"
} else {
return "NO"
}
} else {
return "NO"
}
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
var intersection: (Int, Int)
var intersectionLength: Int
if start1 <= end1 && start2 <= end2 {
if start1 <= start2 {
intersection = (start2, end1)
} else {
intersection = (start1, end2)
}
intersectionLength = intersection.1 - intersection.0
if intersectionLength == 1 || intersectionLength == 3 || intersectionLength == 5 || intersectionLength == 7 || intersectionLength == 11 {
return "YES"
} else {
return "NO"
}
} else {
return "NO"
}
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let intersection = max(interval1.0, interval2.0)...min(interval1.1, interval2.1)
return (intersection.count > 0 && intersection.count < 3) ? "YES" : "NO"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let intersection = max(interval1.0, interval2.0)...min(interval1.1, interval2.1)
return (intersection.count > 0 && intersection.count < 3) ? "YES" : "NO"
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
if intersectionLength > 0 {
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
if intersectionLength > 0 {
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersection = max(start1, start2)...min(end1, end2)
let intersectionLength = intersection.count
if intersectionLength == 1 {
return "YES"
} else {
return "NO"
}
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersection = max(start1, start2)...min(end1, end2)
let intersectionLength = intersection.count
if intersectionLength == 1 {
return "YES"
} else {
return "NO"
}
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
var intersection: (Int, Int)
var intersectionLength: Int
if start1 <= end1 && start2 <= end2 {
intersection = (max(start1, start2), min(end1, end2))
intersectionLength = intersection.1 - intersection.0 + 1
if intersectionLength > 1 {
return "NO"
} else {
if intersectionLength == 1 {
return "YES"
} else {
return "NO"
}
}
} else {
return "NO"
}
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
var intersection: (Int, Int)
var intersectionLength: Int
if start1 <= end1 && start2 <= end2 {
intersection = (max(start1, start2), min(end1, end2))
intersectionLength = intersection.1 - intersection.0 + 1
if intersectionLength > 1 {
return "NO"
} else {
if intersectionLength == 1 {
return "YES"
} else {
return "NO"
}
}
} else {
return "NO"
}
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 <= start2 && end1 >= start2 {
if end1 - start2 == 1 {
return "YES"
} else {
return "NO"
}
} else if start2 <= start1 && end2 >= start1 {
if end2 - start1 == 1 {
return "YES"
} else {
return "NO"
}
} else {
return "NO"
}
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 <= start2 && end1 >= start2 {
if end1 - start2 == 1 {
return "YES"
} else {
return "NO"
}
} else if start2 <= start1 && end2 >= start1 {
if end2 - start1 == 1 {
return "YES"
} else {
return "NO"
}
} else {
return "NO"
}
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
}
```} // missing return in global function expected to return 'String'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
}
```} // missing return in global function expected to return 'String'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
}
```} // missing return in global function expected to return 'String'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
}
```} // missing return in global function expected to return 'String'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
}
```} // missing return in global function expected to return 'String'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
return "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
return "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
}
```} // missing return in global function expected to return 'String'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
}
```} // missing return in global function expected to return 'String'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
}
```} // missing return in global function expected to return 'String'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
}
```} // missing return in global function expected to return 'String'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
if interval1.0 <= interval2.0 && interval1.1 >= interval2.1 {
return "YES"
}
if interval2.0 <= interval1.0 && interval2.1 >= interval1.1 {
return "YES"
}
return "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
if interval1.0 <= interval2.0 && interval1.1 >= interval2.1 {
return "YES"
}
if interval2.0 <= interval1.0 && interval2.1 >= interval1.1 {
return "YES"
}
return "NO"
}
<|file_separator|> // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
if start == end {
return "YES"
}
if end - start == 1 {
return "YES"
}
if isPrime(end - start) {
return "YES"
}
return "NO"
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
if start == end {
return "YES"
}
if end - start == 1 {
return "YES"
}
if isPrime(end - start) {
return "YES"
}
return "NO"
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
<|file_separator|> // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval1.1 < interval2.0 {
return "NO"
}
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if end - start == 1 {
return "YES"
}
return "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval1.1 < interval2.0 {
return "NO"
}
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if end - start == 1 {
return "YES"
}
return "NO"
}
<|file_separator|> // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
if start1 <= start2 && end1 >= end2 {
return "YES"
}
if start2 <= start1 && end2 >= end1 {
return "YES"
}
if start1 <= start2 && end1 >= start2 {
return "YES"
}
if start2 <= start1 && end2 >= start1 {
return "YES"
}
return "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
if start1 <= start2 && end1 >= end2 {
return "YES"
}
if start2 <= start1 && end2 >= end1 {
return "YES"
}
if start1 <= start2 && end1 >= start2 {
return "YES"
}
if start2 <= start1 && end2 >= start1 {
return "YES"
}
return "NO"
}
<|file_separator|> // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Write your code here
if interval1.0 > interval2.1 || interval1.1 < interval2.0 {
return "NO"
} else {
return "YES"
}
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Write your code here
if interval1.0 > interval2.1 || interval1.1 < interval2.0 {
return "NO"
} else {
return "YES"
}
}
<|file_separator|> // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end1 || start2 > end2 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
if end < start {
return "NO"
}
if end - start == 1 {
return "YES"
}
var isPrime = true
for i in start...end {
if i == 1 {
continue
}
if i == 2 {
continue
}
if i % 2 == 0 {
isPrime = false
break
}
for j in 3...i {
if i % j == 0 {
if j == i {
continue
}
isPrime = false
break
}
}
}
if isPrime {
return "YES"
}
return "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end1 || start2 > end2 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
if end < start {
return "NO"
}
if end - start == 1 {
return "YES"
}
var isPrime = true
for i in start...end {
if i == 1 {
continue
}
if i == 2 {
continue
}
if i % 2 == 0 {
isPrime = false
break
}
for j in 3...i {
if i % j == 0 {
if j == i {
continue
}
isPrime = false
break
}
}
}
if isPrime {
return "YES"
}
return "NO"
}
<|file_separator|> // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
return "YES"
}
<|file_separator|>``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval1.1 < interval2.0 {
return "NO"
}
let length = interval1.1 - interval1.0
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
if length % 2 == 1 {
return "NO"
}
let middle = length / 2
if middle % 2 == 0 {
return "YES"
}
return "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval1.1 < interval2.0 {
return "NO"
}
let length = interval1.1 - interval1.0
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
if length % 2 == 1 {
return "NO"
}
let middle = length / 2
if middle % 2 == 0 {
return "YES"
}
return "NO"
}
<|file_separator|>``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end1 || start2 > end2 {
return "NO"
}
if start2 >= start1 && start2 <= end1 {
return "YES"
}
if start1 >= start2 && start1 <= end2 {
return "YES"
}
return "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end1 || start2 > end2 {
return "NO"
}
if start2 >= start1 && start2 <= end1 {
return "YES"
}
if start1 >= start2 && start1 <= end2 {
return "YES"
}
return "NO"
}<|file_separator|>``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval1.1 < interval2.0 {
return "NO"
}
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length == 1 {
return "NO"
}
if length % 2 == 0 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval1.1 < interval2.0 {
return "NO"
}
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length == 1 {
return "NO"
}
if length % 2 == 0 {
return "NO"
}
return "YES"
}
<|file_separator|>``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval1.1 < interval2.0 {
return "NO"
}
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length == 1 {
return "NO"
}
if length % 2 == 0 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval1.1 < interval2.0 {
return "NO"
}
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length == 1 {
return "NO"
}
if length % 2 == 0 {
return "NO"
}
return "YES"
}
<|file_separator|> // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
return "YES"
}
<|file_separator|>``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
if interval1.0 <= interval2.0 && interval1.1 >= interval2.1 {
return "YES"
}
return "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
if interval1.0 <= interval2.0 && interval1.1 >= interval2.1 {
return "YES"
}
return "NO"
}
<|file_separator|> // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval1.1 < interval2.0 {
return "NO"
}
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if end - start == 1 {
return "YES"
}
return "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval1.1 < interval2.0 {
return "NO"
}
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if end - start == 1 {
return "YES"
}
return "NO"
}
<|file_separator|> // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Write your code here
if interval1.0 > interval2.1 || interval1.1 < interval2.0 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Write your code here
if interval1.0 > interval2.1 || interval1.1 < interval2.0 {
return "NO"
}
return "YES"
}
<|file_separator|>``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval1.1 < interval2.0 {
return "NO"
}
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if end - start == 1 {
return "YES"
}
return "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval1.1 < interval2.0 {
return "NO"
}
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if end - start == 1 {
return "YES"
}
return "NO"
}<|file_separator|>``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval1.1 < interval2.0 {
return "NO"
}
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if end - start == 1 {
return "YES"
}
return "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval1.1 < interval2.0 {
return "NO"
}
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if end - start == 1 {
return "YES"
}
return "NO"
}<|file_separator|>``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end1 || start2 > end2 {
return "NO"
}
if start1 > start2 {
return "NO"
}
if end1 < start2 {
return "NO"
}
if end1 == start2 {
return "YES"
}
if end1 > start2 {
return "YES"
}
return "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end1 || start2 > end2 {
return "NO"
}
if start1 > start2 {
return "NO"
}
if end1 < start2 {
return "NO"
}
if end1 == start2 {
return "YES"
}
if end1 > start2 {
return "YES"
}
return "NO"
}
<|file_separator|> // XCTAssertTrue failed```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end1 || start2 > end2 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
if end < start {
return "NO"
}
if end - start == 1 {
return "NO"
}
if end - start == 2 {
return "YES"
}
if end - start == 3 {
return "NO"
}
if end - start == 4 {
return "YES"
}
if end - start == 5 {
return "NO"
}
if end - start == 6 {
return "YES"
}
if end - start == 7 {
return "NO"
}
if end - start == 8 {
return "YES"
}
if end - start == 9 {
return "NO"
}
if end - start == 10 {
return "YES"
}
if end - start == 11 {
return "NO"
}
if end - start == 12 {
return "YES"
}
if end - start == 13 {
return "NO"
}
if end - start == 14 {
return "YES"
}
if end - start == 15 {
return "NO"
}
if end - start == 16 {
return "YES"
}
if end - start == 17 {
return "NO"
}
if end - start == 18 {
return "YES"
}
if end - start == 19 {
return "NO"
}
if end - start == 20 {
return "YES"
}
if end - start == 21 {
return "NO"
}
if end - start == 22 {
return "YES"
}
if end - start == 23 {
return "NO"
}
if end - start == 24 {
return "YES"
}
if end - start == 25 {
return "NO"
}
if end - start == 26 {
return "YES"
}
if end - start == 27 {
return "NO"
}
if end - start == 28 {
return "YES"
}
if end - start == 29 {
return "NO"
}
if end - start == 30 {
return "YES"
}
if end - start == 31 {
return "NO"
}
if end - start == 32 {
return "YES"
}
if end - start == 33 {
return "NO"
}
if end - start == 34 {
return "YES"
}
if end - start == 35 {
return "NO"
}
if end - start == 36 {
return "YES"
}
if end - start == 37 {
return "NO"
}
if end - start == 38 {
return "YES"
}
if end - start == 39 {
return "NO"
}
if end - start == 40 {
return "YES"
}
if end - start == 41 {
return "NO"
}
if end - start == 42 {
return "YES"
}
if end - start == 43 {
return "NO"
}
if end - start == 44 {
return "YES"
}
if end - start == 45 {
return "NO"
}
if end - start == 46 {
return "YES"
}
if end - start == 47 {
return "NO"
}
XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scopefunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// write your code here
if interval1.0 > interval2.1 || interval1.1 < interval2.0 {
return "NO"
}
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if end - start == 1 {
return "YES"
}
if end - start == 2 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// write your code here
if interval1.0 > interval2.1 || interval1.1 < interval2.0 {
return "NO"
}
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if end - start == 1 {
return "YES"
}
if end - start == 2 {
return "NO"
}
return "YES"
}
<|file_separator|>``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let (start, end) = (max(start1, start2), min(end1, end2))
let length = end - start
return length > 0 ? (length > 1 && (2...(length/2)).allSatisfy({ length % $0 != 0 }) ? "YES" : "NO") : "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let (start, end) = (max(start1, start2), min(end1, end2))
let length = end - start
return length > 0 ? (length > 1 && (2...(length/2)).allSatisfy({ length % $0 != 0 }) ? "YES" : "NO") : "NO"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let (minStart, maxEnd) = (max(start1, start2), min(end1, end2))
if minStart > maxEnd {
return "NO"
}
let length = maxEnd - minStart + 1
return length > 1 && isPrime(length) ? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n < 2 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let (minStart, maxEnd) = (max(start1, start2), min(end1, end2))
if minStart > maxEnd {
return "NO"
}
let length = maxEnd - minStart + 1
return length > 1 && isPrime(length) ? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n < 2 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if (start1 > end2 || start2 > end1) {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
if (start == end) {
return "NO"
}
let length = end - start
for i in 2...length {
if (length % i == 0) {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if (start1 > end2 || start2 > end1) {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
if (start == end) {
return "NO"
}
let length = end - start
for i in 2...length {
if (length % i == 0) {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if (start1 >= end2) || (start2 >= end1) {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start
if length < 2 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if (start1 >= end2) || (start2 >= end1) {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start
if length < 2 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let (minStart, maxEnd) = (max(start1, start2), min(end1, end2))
let (minEnd, maxStart) = (min(end1, end2), max(start1, start2))
if minEnd > maxStart {
return "NO"
}
let length = maxEnd - minStart
return length > 1 && isPrime(num: length) ? "YES" : "NO"
}
func isPrime(num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let (minStart, maxEnd) = (max(start1, start2), min(end1, end2))
let (minEnd, maxStart) = (min(end1, end2), max(start1, start2))
if minEnd > maxStart {
return "NO"
}
let length = maxEnd - minStart
return length > 1 && isPrime(num: length) ? "YES" : "NO"
}
func isPrime(num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let (start, end) = (max(start1, start2), min(end1, end2))
if start > end {
return "NO"
}
let length = end - start
guard length > 1 else {
return "NO"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let (start, end) = (max(start1, start2), min(end1, end2))
if start > end {
return "NO"
}
let length = end - start
guard length > 1 else {
return "NO"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}
```func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let (start, end) = (max(start1, start2), min(end1, end2))
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(number: length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
guard number > 1 else {
return false
}
var isPrime = true
for i in 2..<number {
if number % i == 0 {
isPrime = false
break
}
}
return isPrime
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let (start, end) = (max(start1, start2), min(end1, end2))
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(number: length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
guard number > 1 else {
return false
}
var isPrime = true
for i in 2..<number {
if number % i == 0 {
isPrime = false
break
}
}
return isPrime
}
``` // XCTAssertTrue failed```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
if length == 2 {
return "NO"
}
if length == 3 {
return "NO"
}
if length == 5 {
return "NO"
}
if length == 7 {
return "NO"
}
if length == 11 {
return "NO"
}
if length == 13 {
return "NO"
}
if length == 17 {
return "NO"
}
if length == 19 {
return "NO"
}
if length == 23 {
return "NO"
}
if length == 29 {
return "NO"
}
if length == 31 {
return "NO"
}
if length == 37 {
return "NO"
}
if length == 41 {
return "NO"
}
if length == 43 {
return "NO"
}
if length == 47 {
return "NO"
}
if length == 53 {
return "NO"
}
if length == 59 {
return "NO"
}
if length == 61 {
return "NO"
}
if length == 67 {
return "NO"
}
if length == 71 {
return "NO"
}
if length == 73 {
return "NO"
}
if length == 79 {
return "NO"
}
if length == 83 {
return "NO"
}
if length == 89 {
return "NO"
}
if length == 97 {
return "NO"
}
if length == 101 {
return "NO"
}
if length == 103 {
return "NO"
}
if length == 107 {
return "NO"
}
if length == 109 {
return "NO"
}
if length == 113 {
return "NO"
}
if length == 127 {
return "NO"
}
if length == 131 {
return "NO"
}
if length == 137 {
return "NO"
}
if length == 139 {
return "NO"
}
if length == 149 {
return "NO"
}
if length == 151 {
return "NO"
}
if length == 157 {
return "NO"
}
if length == 163 {
return "NO"
}
if length == 167 {
return "NO"
}
if length == 173 {
return "NO"
}
if length == 179 {
return "NO"
}
if length == 181 {
return "NO"
}
if length == 191 {
return "NO"
}
if length == 193 {
return "NO"
}
if length == 197 {
return "NO"
}
if length == 199 {
return "NO"
}
if length == 211 {
return "NO"
}
if length == 223 {
return "NO"
}
if length == 227 {
return "NO"
}
if length == 229 {
return "NO"
}
if length == 2XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scopefunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if (start1 >= end2) || (start2 >= end1) {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if (length > 1) && (2...length).allSatisfy({ length % $0 != 0}) {
return "YES"
}
return "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if (start1 >= end2) || (start2 >= end1) {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if (length > 1) && (2...length).allSatisfy({ length % $0 != 0}) {
return "YES"
}
return "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let (start, end) = (max(start1, start2), min(end1, end2))
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 || length == 2 {
return "NO"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let (start, end) = (max(start1, start2), min(end1, end2))
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 || length == 2 {
return "NO"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}
```func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0;
let end1 = interval1.1;
let start2 = interval2.0;
let end2 = interval2.1;
let intersectionStart = max(start1, start2);
let intersectionEnd = min(end1, end2);
let intersectionLength = max(intersectionEnd - intersectionStart, 0);
if intersectionLength == 0 {
return "NO";
} else {
let intersection = (intersectionStart, intersectionEnd);
let intersectionLength = intersectionEnd - intersectionStart;
let isPrime = isPrime(intersectionLength);
if isPrime {
return "YES";
} else {
return "NO";
}
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false;
}
let limit = Int.squareRoot(n);
for i in 2..limit {
if n % i == 0 {
return false;
}
}
return true;
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0;
let end1 = interval1.1;
let start2 = interval2.0;
let end2 = interval2.1;
let intersectionStart = max(start1, start2);
let intersectionEnd = min(end1, end2);
let intersectionLength = max(intersectionEnd - intersectionStart, 0);
if intersectionLength == 0 {
return "NO";
} else {
let intersection = (intersectionStart, intersectionEnd);
let intersectionLength = intersectionEnd - intersectionStart;
let isPrime = isPrime(intersectionLength);
if isPrime {
return "YES";
} else {
return "NO";
}
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false;
}
let limit = Int.squareRoot(n);
for i in 2..limit {
if n % i == 0 {
return false;
}
}
return true;
}
```let isPrime = isPrime(intersectionLength); // missing argument label 'n:' in calllet limit = Int.squareRoot(n); // type 'Int' has no member 'squareRoot'for i in 2..limit { // cannot find operator '..' in scope; did you mean '...'?func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let intersection = interval1.0.max(interval2.0).min(interval1.1.min(interval2.1))
if intersection == interval1.1 || intersection == interval2.1 {
return "NO"
} else if intersection == interval1.0 || intersection == interval2.0 {
return "YES"
} else {
return "NO"
}
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let intersection = interval1.0.max(interval2.0).min(interval1.1.min(interval2.1))
if intersection == interval1.1 || intersection == interval2.1 {
return "NO"
} else if intersection == interval1.0 || intersection == interval2.0 {
return "YES"
} else {
return "NO"
}
}
// Test cases
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
```let intersection = interval1.0.max(interval2.0).min(interval1.1.min(interval2.1)) // static member 'max' cannot be used on instance of type 'Int'let intersection = interval1.0.max(interval2.0).min(interval1.1.min(interval2.1)) // static member 'min' cannot be used on instance of type 'Int'let intersection = interval1.0.max(interval2.0).min(interval1.1.min(interval2.1)) // cannot call value of non-function type 'Int'let intersection = interval1.0.max(interval2.0).min(interval1.1.min(interval2.1)) // cannot call value of non-function type 'Int'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1;
let (start2, end2) = interval2;
if start1 > end2 || start2 > end1 {
return "NO";
}
let intersectionStart = max(start1, start2);
let intersectionEnd = min(end1, end2);
if intersectionStart <= intersectionEnd {
let intersectionLength = intersectionEnd - intersectionStart + 1;
if isPrime(intersectionLength) {
return "YES";
}
}
return "NO";
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false;
}
let sqrtN = sqrt(n);
for i in 2..sqrtN {
if n % i == 0 {
return false;
}
}
return true;
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1;
let (start2, end2) = interval2;
if start1 > end2 || start2 > end1 {
return "NO";
}
let intersectionStart = max(start1, start2);
let intersectionEnd = min(end1, end2);
if intersectionStart <= intersectionEnd {
let intersectionLength = intersectionEnd - intersectionStart + 1;
if isPrime(intersectionLength) {
return "YES";
}
}
return "NO";
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false;
}
let sqrtN = sqrt(n);
for i in 2..sqrtN {
if n % i == 0 {
return false;
}
}
return true;
}
// Test cases
let result1 = intersection(interval1: (1, 2), interval2: (2, 3));
let result2 = intersection(interval1: (-1, 1), interval2: (0, 4));
let result3 = intersection(interval1: (-3, -1), interval2: (-5, 5));
print(result1); // Output: "NO"
print(result2); // Output: "NO"
print(result3); // Output: "YES"
```if isPrime(intersectionLength) { // missing argument label 'n:' in calllet sqrtN = sqrt(n); // cannot convert value of type 'Int' to expected argument type 'Double'for i in 2..sqrtN { // cannot find operator '..' in scope; did you mean '...'?func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1;
let (start2, end2) = interval2;
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO";
}
// Calculate the length of the intersection
let intersectionLength = max(0, min(end1, end2) - max(start1, start2) + 1);
// Check if the intersection length is a prime number
let isPrime = true;
for i in 2..intersectionLength {
if intersectionLength % i == 0 {
isPrime = false;
break;
}
}
if isPrime {
return "YES";
} else {
return "NO";
}
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1;
let (start2, end2) = interval2;
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO";
}
// Calculate the length of the intersection
let intersectionLength = max(0, min(end1, end2) - max(start1, start2) + 1);
// Check if the intersection length is a prime number
let isPrime = true;
for i in 2..intersectionLength {
if intersectionLength % i == 0 {
isPrime = false;
break;
}
}
if isPrime {
return "YES";
} else {
return "NO";
}
}
// Test cases
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
```for i in 2..intersectionLength { // cannot find operator '..' in scope; did you mean '...'?func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1;
let (start2, end2) = interval2;
if start1 > end2 || start2 > end1 {
return "NO";
}
let intersectionStart = max(start1, start2);
let intersectionEnd = min(end1, end2);
if intersectionStart > intersectionEnd {
return "NO";
}
let intersectionLength = intersectionEnd - intersectionStart + 1;
if intersectionLength == 1 {
return "NO";
}
let isPrime = true;
for i in 2..intersectionLength {
if intersectionLength % i == 0 {
isPrime = false;
break;
}
}
if isPrime {
return "YES";
} else {
return "NO";
}
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1;
let (start2, end2) = interval2;
if start1 > end2 || start2 > end1 {
return "NO";
}
let intersectionStart = max(start1, start2);
let intersectionEnd = min(end1, end2);
if intersectionStart > intersectionEnd {
return "NO";
}
let intersectionLength = intersectionEnd - intersectionStart + 1;
if intersectionLength == 1 {
return "NO";
}
let isPrime = true;
for i in 2..intersectionLength {
if intersectionLength % i == 0 {
isPrime = false;
break;
}
}
if isPrime {
return "YES";
} else {
return "NO";
}
}
```for i in 2..intersectionLength { // cannot find operator '..' in scope; did you mean '...'?func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0;
let end1 = interval1.1;
let start2 = interval2.0;
let end2 = interval2.1;
let intersection = (max(start1, start2), min(end1, end2));
if intersection.0 > intersection.1 {
return "NO";
} else {
let length = intersection.1 - intersection.0 + 1;
if length == 1 {
return "NO";
} else {
let prime = isPrime(length);
if prime {
return "YES";
} else {
return "NO";
}
}
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false;
}
for i in 2 ..< sqrt(n) {
if n % i == 0 {
return false;
}
}
return true;
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0;
let end1 = interval1.1;
let start2 = interval2.0;
let end2 = interval2.1;
let intersection = (max(start1, start2), min(end1, end2));
if intersection.0 > intersection.1 {
return "NO";
} else {
let length = intersection.1 - intersection.0 + 1;
if length == 1 {
return "NO";
} else {
let prime = isPrime(length);
if prime {
return "YES";
} else {
return "NO";
}
}
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false;
}
for i in 2 ..< sqrt(n) {
if n % i == 0 {
return false;
}
}
return true;
}
```let prime = isPrime(length); // missing argument label 'n:' in callfor i in 2 ..< sqrt(n) { // global function 'sqrt' requires that 'Int' conform to 'FloatingPoint'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let intersection = interval1.0 ..= interval1.1
let intersection2 = interval2.0 ..= interval2.1
if intersection.isEmpty || intersection2.isEmpty {
return "NO"
}
let intersectionLength = intersection.count
if intersectionLength.isOdd {
return "YES"
}
return "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let intersection = interval1.0 ..= interval1.1
let intersection2 = interval2.0 ..= interval2.1
if intersection.isEmpty || intersection2.isEmpty {
return "NO"
}
let intersectionLength = intersection.count
if intersectionLength.isOdd {
return "YES"
}
return "NO"
}
```let intersection = interval1.0 ..= interval1.1 // cannot find operator '..=' in scopelet intersection2 = interval2.0 ..= interval2.1 // cannot find operator '..=' in scopefunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1;
let (start2, end2) = interval2;
if start1 > end2 || start2 > end1 {
return "NO";
}
let intersectionStart = max(start1, start2);
let intersectionEnd = min(end1, end2);
if intersectionStart > intersectionEnd {
return "NO";
}
let intersectionLength = intersectionEnd - intersectionStart + 1;
if intersectionLength == 1 {
return "NO";
}
return "YES";
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1;
let (start2, end2) = interval2;
if start1 > end2 || start2 > end1 {
return "NO";
}
let intersectionStart = max(start1, start2);
let intersectionEnd = min(end1, end2);
if intersectionStart > intersectionEnd {
return "NO";
}
let intersectionLength = intersectionEnd - intersectionStart + 1;
if intersectionLength == 1 {
return "NO";
}
return "YES";
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0;
let end1 = interval1.1;
let start2 = interval2.0;
let end2 = interval2.1;
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO";
}
// Calculate the intersection length
let intersectionLength = max(0, min(end1, end2) - max(start1, start2) + 1);
// Check if the intersection length is a prime number
let intersectionPrime = isPrime(intersectionLength);
if intersectionPrime {
return "YES";
} else {
return "NO";
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false;
}
let limit = Int(sqrt(n));
for i in 2..limit {
if n % i == 0 {
return false;
}
}
return true;
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0;
let end1 = interval1.1;
let start2 = interval2.0;
let end2 = interval2.1;
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO";
}
// Calculate the intersection length
let intersectionLength = max(0, min(end1, end2) - max(start1, start2) + 1);
// Check if the intersection length is a prime number
let intersectionPrime = isPrime(intersectionLength);
if intersectionPrime {
return "YES";
} else {
return "NO";
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false;
}
let limit = Int(sqrt(n));
for i in 2..limit {
if n % i == 0 {
return false;
}
}
return true;
}
// Test the function
let interval1 = (1, 2);
let interval2 = (2, 3);
let result = intersection(interval1, interval2);
print(result); // Output: "NO"
let interval1 = (-1, 1);
let interval2 = (0, 4);
let result = intersection(interval1, interval2);
print(result); // Output: "NO"
let interval1 = (-3, -1);
let interval2 = (-5, 5);
let result = intersection(interval1, interval2);
print(result); // Output: "YES"
```let intersectionPrime = isPrime(intersectionLength); // missing argument label 'n:' in calllet limit = Int(sqrt(n)); // no exact matches in call to global function 'sqrt'for i in 2..limit { // cannot find operator '..' in scope; did you mean '...'?func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0;
let end1 = interval1.1;
let start2 = interval2.0;
let end2 = interval2.1;
if start2 > end1 || end2 < start1 {
return "NO";
}
let intersectionLength = min(end1, end2) - max(start1, start2) + 1;
if intersectionLength == 1 {
return "NO";
}
let isPrime = false;
for i in 2..intersectionLength {
if intersectionLength % i == 0 {
isPrime = false;
break;
}
isPrime = true;
}
if isPrime {
return "YES";
} else {
return "NO";
}
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0;
let end1 = interval1.1;
let start2 = interval2.0;
let end2 = interval2.1;
if start2 > end1 || end2 < start1 {
return "NO";
}
let intersectionLength = min(end1, end2) - max(start1, start2) + 1;
if intersectionLength == 1 {
return "NO";
}
let isPrime = false;
for i in 2..intersectionLength {
if intersectionLength % i == 0 {
isPrime = false;
break;
}
isPrime = true;
}
if isPrime {
return "YES";
} else {
return "NO";
}
}
```for i in 2..intersectionLength { // cannot find operator '..' in scope; did you mean '...'?func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection interval
let start = max(start1, start2)
let end = min(end1, end2)
// Check if the intersection interval has a length of 1
if end - start == 0 {
return "NO"
}
// Check if the length of the intersection interval is a prime number
var i = 2
while i <= sqrt(Double(end - start)) {
if (end - start) % i == 0 {
return "NO"
}
i += 1
}
return "YES"
}<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection interval
let start = max(start1, start2)
let end = min(end1, end2)
// Check if the intersection interval has a length of 1
if end - start == 0 {
return "NO"
}
// Check if the length of the intersection interval is a prime number
var i = 2
while i <= sqrt(Double(end - start)) {
if (end - start) % i == 0 {
return "NO"
}
i += 1
}
return "YES"
}
```while i <= sqrt(Double(end - start)) { // cannot convert value of type 'Double' to expected argument type 'Int'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(min(end1, end2) - max(start1, start2) + 1, 0)
if length == 0 {
return "NO"
} else if length == 1 {
return "YES"
}
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
} else if number <= 3 {
return true
} else if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(min(end1, end2) - max(start1, start2) + 1, 0)
if length == 0 {
return "NO"
} else if length == 1 {
return "YES"
}
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
} else if number <= 3 {
return true
} else if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength > 1 && isPrime(number: intersectionLength) {
return "YES"
}
return "NO"
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength > 1 && isPrime(number: intersectionLength) {
return "YES"
}
return "NO"
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the length of the intersection
let length = max(0, min(end1, end2) - max(start1, start2) + 1)
// Check if the length is a prime number
if length == 1 {
return "NO"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
if isPrime {
return "YES"
} else {
return "NO"
}
}<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the length of the intersection
let length = max(0, min(end1, end2) - max(start1, start2) + 1)
// Check if the length is a prime number
if length == 1 {
return "NO"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
if isPrime {
return "YES"
} else {
return "NO"
}
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(0, min(end1, end2) - max(start1, start2) + 1)
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<Int(sqrt(Double(number))) + 1 {
if number % i == 0 {
return false
}
}
return true
}<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(0, min(end1, end2) - max(start1, start2) + 1)
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<Int(sqrt(Double(number))) + 1 {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the two intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection interval
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Check if the intersection interval is empty
if intersectionStart > intersectionEnd {
return "NO"
}
// Calculate the length of the intersection interval
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the intersection length is a prime number
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the two intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection interval
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Check if the intersection interval is empty
if intersectionStart > intersectionEnd {
return "NO"
}
// Calculate the length of the intersection interval
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the intersection length is a prime number
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the two intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection interval
let start = max(start1, start2)
let end = min(end1, end2)
// Check if the intersection interval has a length of 1
if end - start == 0 {
return "NO"
}
// Check if the length of the intersection interval is a prime number
var i = 2
while i <= Int(sqrt(Double(end - start))) {
if (end - start) % i == 0 {
return "NO"
}
i += 1
}
return "YES"
}<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the two intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection interval
let start = max(start1, start2)
let end = min(end1, end2)
// Check if the intersection interval has a length of 1
if end - start == 0 {
return "NO"
}
// Check if the length of the intersection interval is a prime number
var i = 2
while i <= Int(sqrt(Double(end - start))) {
if (end - start) % i == 0 {
return "NO"
}
i += 1
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength == 1 {
return "NO"
}
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength == 1 {
return "NO"
}
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the two intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection interval
let start = max(start1, start2)
let end = min(end1, end2)
// Check if the intersection interval has a positive length
if start <= end {
// Check if the length of the intersection interval is a prime number
if isPrime(length: end - start + 1) {
return "YES"
}
}
return "NO"
}
func isPrime(length: Int) -> Bool {
if length <= 1 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the two intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection interval
let start = max(start1, start2)
let end = min(end1, end2)
// Check if the intersection interval has a positive length
if start <= end {
// Check if the length of the intersection interval is a prime number
if isPrime(length: end - start + 1) {
return "YES"
}
}
return "NO"
}
// Function to check if a number is prime
func isPrime(length: Int) -> Bool {
if length <= 1 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the two intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the length of the intersection
let length = min(end1, end2) - max(start1, start2) + 1
// Check if the length is a prime number
if length > 1 {
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
}
return "YES"
}<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the two intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the length of the intersection
let length = min(end1, end2) - max(start1, start2) + 1
// Check if the length is a prime number
if length > 1 {
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(0, min(end1, end2) - max(start1, start2) + 1)
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(0, min(end1, end2) - max(start1, start2) + 1)
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(min(end1, end2) - max(start1, start2) + 1, 0)
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(min(end1, end2) - max(start1, start2) + 1, 0)
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(min(end1, end2) - max(start1, start2) + 1, 0)
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(min(end1, end2) - max(start1, start2) + 1, 0)
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(min(end1, end2) - max(start1, start2) + 1, 0)
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(min(end1, end2) - max(start1, start2) + 1, 0)
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(min(end1, end2) - max(start1, start2) + 1, 0)
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(min(end1, end2) - max(start1, start2) + 1, 0)
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(0, min(end1, end2) - max(start1, start2) + 1)
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(0, min(end1, end2) - max(start1, start2) + 1)
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(min(end1, end2) - max(start1, start2) + 1, 0)
if isPrime(number: length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(min(end1, end2) - max(start1, start2) + 1, 0)
if isPrime(number: length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(0, min(end1, end2) - max(start1, start2) + 1)
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(0, min(end1, end2) - max(start1, start2) + 1)
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(0, min(end1, end2) - max(start1, start2) + 1)
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(0, min(end1, end2) - max(start1, start2) + 1)
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(0, min(end1, end2) - max(start1, start2) + 1)
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<end_of_turn>
<start_of_turn>model
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = max(0, min(end1, end2) - max(start1, start2) + 1)
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
if length.isPrime {
return "YES"
}
return "NO"
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
if length.isPrime {
return "YES"
}
return "NO"
}
```if length.isPrime { // value of type 'Int' has no member 'isPrime'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 0 {
return "NO"
}
if length == 1 {
return "YES"
}
if length > 1 && length % 2 == 1 {
return "YES"
}
return "NO"
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 0 {
return "NO"
}
if length == 1 {
return "YES"
}
if length > 1 && length % 2 == 1 {
return "YES"
}
return "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength == 1 {
return "NO"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength == 1 {
return "NO"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 <= end2 && start2 <= end1 {
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the intersection length is a prime number
if intersectionLength.isPrime {
return "YES"
} else {
return "NO"
}
} else {
return "NO"
}
}
extension Int {
var isPrime: Bool {
guard self > 1 else { return false }
for i in 2..<self {
if self % i == 0 {
return false
}
}
return true
}
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 <= end2 && start2 <= end1 {
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the intersection length is a prime number
if intersectionLength.isPrime {
return "YES"
} else {
return "NO"
}
} else {
return "NO"
}
}
extension Int {
var isPrime: Bool {
guard self > 1 else { return false }
for i in 2..<self {
if self % i == 0 {
return false
}
}
return true
}
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Check if the intervals intersect
if interval1.1 < interval2.0 || interval1.0 > interval2.1 {
return "NO"
}
// Calculate the length of the intersection
let length = min(interval1.1, interval2.1) - max(interval1.0, interval2.0) + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(n: Int) -> Bool {
// Check if n is a prime number
if n <= 1 {
return false
} else if n == 2 {
return true
} else {
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Check if the intervals intersect
if interval1.1 < interval2.0 || interval1.0 > interval2.1 {
return "NO"
}
// Calculate the length of the intersection
let length = min(interval1.1, interval2.1) - max(interval1.0, interval2.0) + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(n: Int) -> Bool {
// Check if n is a prime number
if n <= 1 {
return false
} else if n == 2 {
return true
} else {
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
}
```if isPrime(length) { // missing argument label 'n:' in callfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end1 || start2 > end2 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end1 || start2 > end2 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Check if the intervals intersect
if interval1.1 < interval2.0 || interval2.1 < interval1.0 {
return "NO"
}
// Find the intersection of the intervals
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
// Check if the length of the intersection is a prime number
let length = end - start + 1
if length == 1 {
return "NO"
} else if length == 2 {
return "YES"
} else {
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Check if the intervals intersect
if interval1.1 < interval2.0 || interval2.1 < interval1.0 {
return "NO"
}
// Find the intersection of the intervals
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
// Check if the length of the intersection is a prime number
let length = end - start + 1
if length == 1 {
return "NO"
} else if length == 2 {
return "YES"
} else {
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Check if the intervals intersect
if interval1.1 < interval2.0 || interval2.1 < interval1.0 {
return "NO"
}
// Find the intersection of the intervals
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
// Check if the length of the intersection is a prime number
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ n: Int) -> Bool {
// Check if n is a prime number
if n <= 1 {
return false
}
// Check if n is divisible by any number between 2 and sqrt(n)
for i in 2...Int(sqrt(Double(n))) {
if n % i == 0 {
return false
}
}
return true
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Check if the intervals intersect
if interval1.1 < interval2.0 || interval2.1 < interval1.0 {
return "NO"
}
// Find the intersection of the intervals
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
// Check if the length of the intersection is a prime number
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ n: Int) -> Bool {
// Check if n is a prime number
if n <= 1 {
return false
}
// Check if n is divisible by any number between 2 and sqrt(n)
for i in 2...Int(sqrt(Double(n))) {
if n % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end1 || start2 > end2 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end1 || start2 > end2 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end1 || start2 > end2 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2...Int(sqrt(Double(n))) {
if n % i == 0 {
return false
}
}
return true
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end1 || start2 > end2 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2...Int(sqrt(Double(n))) {
if n % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end1 || start2 > end2 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end1 || start2 > end2 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Check if the intervals intersect
if interval1.1 < interval2.0 || interval2.1 < interval1.0 {
return "NO"
}
// Find the intersection of the intervals
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
// Check if the length of the intersection is a prime number
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ n: Int) -> Bool {
// Check if n is a prime number
if n <= 1 {
return false
} else if n == 2 {
return true
} else if n % 2 == 0 {
return false
}
// Check if n is divisible by any number in the range [3, sqrt(n)]
for i in 3...Int(sqrt(Double(n))) {
if n % i == 0 {
return false
}
}
return true
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Check if the intervals intersect
if interval1.1 < interval2.0 || interval2.1 < interval1.0 {
return "NO"
}
// Find the intersection of the intervals
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
// Check if the length of the intersection is a prime number
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ n: Int) -> Bool {
// Check if n is a prime number
if n <= 1 {
return false
} else if n == 2 {
return true
} else if n % 2 == 0 {
return false
}
// Check if n is divisible by any number in the range [3, sqrt(n)]
for i in 3...Int(sqrt(Double(n))) {
if n % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Check if the intervals intersect
if interval1.1 < interval2.0 || interval2.1 < interval1.0 {
return "NO"
}
// Find the intersection of the intervals
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
// Check if the length of the intersection is a prime number
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ n: Int) -> Bool {
// Check if n is a prime number
if n <= 1 {
return false
} else if n == 2 {
return true
} else {
for i in 2...Int(sqrt(Double(n))) {
if n % i == 0 {
return false
}
}
return true
}
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Check if the intervals intersect
if interval1.1 < interval2.0 || interval2.1 < interval1.0 {
return "NO"
}
// Find the intersection of the intervals
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
// Check if the length of the intersection is a prime number
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ n: Int) -> Bool {
// Check if n is a prime number
if n <= 1 {
return false
} else if n == 2 {
return true
} else {
for i in 2...Int(sqrt(Double(n))) {
if n % i == 0 {
return false
}
}
return true
}
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end1 || start2 > end2 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2...Int(sqrt(Double(n))) {
if n % i == 0 {
return false
}
}
return true
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end1 || start2 > end2 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2...Int(sqrt(Double(n))) {
if n % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let intersectionStart = max(interval1.start, interval2.start)
let intersectionEnd = min(interval1.end, interval2.end)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let intersectionStart = max(interval1.start, interval2.start)
let intersectionEnd = min(interval1.end, interval2.end)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}
```let intersectionStart = max(interval1.start, interval2.start) // value of tuple type '(Int, Int)' has no member 'start'let intersectionStart = max(interval1.start, interval2.start) // value of tuple type '(Int, Int)' has no member 'start'let intersectionEnd = min(interval1.end, interval2.end) // value of tuple type '(Int, Int)' has no member 'end'let intersectionEnd = min(interval1.end, interval2.end) // value of tuple type '(Int, Int)' has no member 'end'let intersectionLength = intersectionEnd - intersectionStart + 1 // binary operator '+' cannot be applied to operands of type 'Duration' and 'Int'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let intersection = (max(interval1.0, interval2.0), min(interval1.1, interval2.1))
if intersection.0 <= intersection.1 {
let length = intersection.1 - intersection.0 + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let intersection = (max(interval1.0, interval2.0), min(interval1.1, interval2.1))
if intersection.0 <= intersection.1 {
let length = intersection.1 - intersection.0 + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let intersection = (max(interval1.0, interval2.0), min(interval1.1, interval2.1))
if intersection.0 <= intersection.1 {
let length = intersection.1 - intersection.0 + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
} else {
return "NO"
}
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2...Int(sqrt(Double(n))) {
if n % i == 0 {
return false
}
}
return true
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let intersection = (max(interval1.0, interval2.0), min(interval1.1, interval2.1))
if intersection.0 <= intersection.1 {
let length = intersection.1 - intersection.0 + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
} else {
return "NO"
}
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2...Int(sqrt(Double(n))) {
if n % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end1 || start2 > end2 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...number / 2 {
if number % i == 0 {
return false
}
}
return true
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end1 || start2 > end2 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...number / 2 {
if number % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let intersection = (max(interval1.start, interval2.start), min(interval1.end, interval2.end))
if intersection.start <= intersection.end {
let length = intersection.end - intersection.start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let intersection = (max(interval1.start, interval2.start), min(interval1.end, interval2.end))
if intersection.start <= intersection.end {
let length = intersection.end - intersection.start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```let intersection = (max(interval1.start, interval2.start), min(interval1.end, interval2.end)) // value of tuple type '(Int, Int)' has no member 'start'let intersection = (max(interval1.start, interval2.start), min(interval1.end, interval2.end)) // value of tuple type '(Int, Int)' has no member 'start'let intersection = (max(interval1.start, interval2.start), min(interval1.end, interval2.end)) // value of tuple type '(Int, Int)' has no member 'end'let intersection = (max(interval1.start, interval2.start), min(interval1.end, interval2.end)) // value of tuple type '(Int, Int)' has no member 'end'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let intersection = (max(interval1.0, interval2.0), min(interval1.1, interval2.1))
if intersection.0 <= intersection.1 {
let length = intersection.1 - intersection.0 + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let intersection = (max(interval1.0, interval2.0), min(interval1.1, interval2.1))
if intersection.0 <= intersection.1 {
let length = intersection.1 - intersection.0 + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end1 || start2 > end2 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...number / 2 {
if number % i == 0 {
return false
}
}
return true
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end1 || start2 > end2 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...number / 2 {
if number % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end1 || start2 > end2 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...number / 2 {
if number % i == 0 {
return false
}
}
return true
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end1 || start2 > end2 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...number / 2 {
if number % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let intersectionStart = max(interval1.start, interval2.start)
let intersectionEnd = min(interval1.end, interval2.end)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let intersectionStart = max(interval1.start, interval2.start)
let intersectionEnd = min(interval1.end, interval2.end)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```let intersectionStart = max(interval1.start, interval2.start) // value of tuple type '(Int, Int)' has no member 'start'let intersectionStart = max(interval1.start, interval2.start) // value of tuple type '(Int, Int)' has no member 'start'let intersectionEnd = min(interval1.end, interval2.end) // value of tuple type '(Int, Int)' has no member 'end'let intersectionEnd = min(interval1.end, interval2.end) // value of tuple type '(Int, Int)' has no member 'end'let intersectionLength = intersectionEnd - intersectionStart + 1 // binary operator '+' cannot be applied to operands of type 'Duration' and 'Int'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let intersection = (max(interval1.0, interval2.0), min(interval1.1, interval2.1))
if intersection.0 <= intersection.1 {
let length = intersection.1 - intersection.0 + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES" [/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let intersection = (max(interval1.0, interval2.0), min(interval1.1, interval2.1))
if intersection.0 <= intersection.1 {
let length = intersection.1 - intersection.0 + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length <= 1 {
return "NO"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime? "YES" : "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length <= 1 {
return "NO"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime? "YES" : "NO"
}
```return isPrime? "YES" : "NO" // expected expressionreturn isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime? "YES" : "NO" // string literal is unusedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
guard interval1.0 <= interval2.0 else {
return "NO"
}
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
guard interval1.0 <= interval2.0 else {
return "NO"
}
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```return isPrime(length)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(length)? "YES" : "NO" // string literal is unusedreturn isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(length)? "YES" : "NO" // expected expressionfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end1 || start2 > end2 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime? "YES" : "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end1 || start2 > end2 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime? "YES" : "NO"
}
```return isPrime? "YES" : "NO" // expected expressionreturn isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime? "YES" : "NO" // string literal is unusedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime? "YES" : "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime? "YES" : "NO"
}
```return isPrime? "YES" : "NO" // expected expressionreturn isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime? "YES" : "NO" // string literal is unusedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
guard interval1.0 <= interval2.0 else {
return "NO"
}
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
guard interval1.0 <= interval2.0 else {
return "NO"
}
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
guard interval1.0 <= interval2.0 else { return "NO" }
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
guard interval1.0 <= interval2.0 else { return "NO" }
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```return isPrime(length)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(length)? "YES" : "NO" // expected expressionreturn isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(length)? "YES" : "NO" // string literal is unusedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
guard interval1.0 <= interval2.0 else { return "NO" }
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 { return "NO" }
for i in 2..<length {
if length % i == 0 { return "NO" }
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
guard interval1.0 <= interval2.0 else { return "NO" }
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 { return "NO" }
for i in 2..<length {
if length % i == 0 { return "NO" }
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime? "YES" : "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime? "YES" : "NO"
}
```return isPrime? "YES" : "NO" // expected expressionreturn isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime? "YES" : "NO" // string literal is unusedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength <= 1 {
return "NO"
}
let isPrime = (2..<intersectionLength).allSatisfy { intersectionLength % $0!= 0 }
return isPrime? "YES" : "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength <= 1 {
return "NO"
}
let isPrime = (2..<intersectionLength).allSatisfy { intersectionLength % $0!= 0 }
return isPrime? "YES" : "NO"
}
```let isPrime = (2..<intersectionLength).allSatisfy { intersectionLength % $0!= 0 } // cannot force unwrap value of non-optional type 'Int'let isPrime = (2..<intersectionLength).allSatisfy { intersectionLength % $0!= 0 } // '=' must have consistent whitespace on both sideslet isPrime = (2..<intersectionLength).allSatisfy { intersectionLength % $0!= 0 } // expression is not assignable: binary operator returns immutable valuereturn isPrime? "YES" : "NO" // cannot convert return expression of type 'Optional<_>' to return type 'String'return isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // string literal is unusedreturn isPrime? "YES" : "NO" // expected expressionreturn isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength == 1 {
return "NO"
}
let primeNumbers = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97]
return primeNumbers.contains(intersectionLength)? "YES" : "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength == 1 {
return "NO"
}
let primeNumbers = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97]
return primeNumbers.contains(intersectionLength)? "YES" : "NO"
}
```return primeNumbers.contains(intersectionLength)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return primeNumbers.contains(intersectionLength)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return primeNumbers.contains(intersectionLength)? "YES" : "NO" // expected expressionreturn primeNumbers.contains(intersectionLength)? "YES" : "NO" // string literal is unusedreturn primeNumbers.contains(intersectionLength)? "YES" : "NO" // consecutive statements on a line must be separated by ';'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength == 1 {
return "NO"
}
if intersectionLength == 2 {
return "YES"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength == 1 {
return "NO"
}
if intersectionLength == 2 {
return "YES"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let length = intersectionEnd - intersectionStart + 1
if length == 1 {
return "NO"
}
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97]
return primes.contains(length)? "YES" : "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let length = intersectionEnd - intersectionStart + 1
if length == 1 {
return "NO"
}
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97]
return primes.contains(length)? "YES" : "NO"
}
```return primes.contains(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return primes.contains(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return primes.contains(length)? "YES" : "NO" // expected expressionreturn primes.contains(length)? "YES" : "NO" // string literal is unusedreturn primes.contains(length)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let length = intersectionEnd - intersectionStart + 1
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let length = intersectionEnd - intersectionStart + 1
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength == 1 {
return "NO"
}
if intersectionLength == 2 {
return "YES"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength == 1 {
return "NO"
}
if intersectionLength == 2 {
return "YES"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength == 1 {
return "NO"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength == 1 {
return "NO"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
for i in 3..<Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
for i in 3..<Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
for i in 2..<Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
for i in 2..<Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// If intervals don't intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Calculate length of intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if length is prime
if intersectionLength < 2 {
return "NO"
}
var isPrime = true
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// If intervals don't intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Calculate length of intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if length is prime
if intersectionLength < 2 {
return "NO"
}
var isPrime = true
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the start and end of the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length of the intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
var isPrime = true
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the start and end of the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length of the intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
var isPrime = true
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Determine the intersection of the intervals
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// If the intervals don't intersect, return "NO"
if intersectionStart > intersectionEnd {
return "NO"
}
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length is a prime number
if intersectionLength < 2 {
return "NO"
}
var isPrime = true
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Determine the intersection of the intervals
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// If the intervals don't intersect, return "NO"
if intersectionStart > intersectionEnd {
return "NO"
}
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length is a prime number
if intersectionLength < 2 {
return "NO"
}
var isPrime = true
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the start and end of the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length of the intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the start and end of the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length of the intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length of the intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
var isPrime = true
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length of the intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
var isPrime = true
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Determine the intersection of the intervals
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// If the intervals don't intersect, return "NO"
if intersectionStart > intersectionEnd {
return "NO"
}
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Determine the intersection of the intervals
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// If the intervals don't intersect, return "NO"
if intersectionStart > intersectionEnd {
return "NO"
}
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length of the intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
var isPrime = true
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length of the intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
var isPrime = true
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length of the intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
var isPrime = true
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length of the intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
var isPrime = true
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length of the intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
var isPrime = true
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length of the intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
var isPrime = true
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length of the intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
var isPrime = true
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length of the intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
var isPrime = true
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals do not intersect
if start2 > end1 || start1 > end2 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
// Check if the length of the intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if i != 2 && intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals do not intersect
if start2 > end1 || start1 > end2 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
// Check if the length of the intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if i != 2 && intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Check if intersection length is a prime number
if intersectionEnd - intersectionStart < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if i != 2 && intersectionEnd % i == 0 {
return "NO"
}
}
return "YES"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Check if intersection length is a prime number
if intersectionEnd - intersectionStart < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if i != 2 && intersectionEnd % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Check if intersection length is a prime number
if intersectionEnd - intersectionStart < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if i > 1 && (intersectionEnd - intersectionStart) % i == 0 {
return "NO"
}
}
return "YES"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Check if intersection length is a prime number
if intersectionEnd - intersectionStart < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if i > 1 && (intersectionEnd - intersectionStart) % i == 0 {
return "NO"
}
}
return "YES"
}
```func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Find intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Check if intersection length is a prime number
if intersectionEnd - intersectionStart < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if i > 1 && (intersectionEnd - intersectionStart) % i == 0 {
return "NO"
}
}
return "YES"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Find intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Check if intersection length is a prime number
if intersectionEnd - intersectionStart < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if i > 1 && (intersectionEnd - intersectionStart) % i == 0 {
return "NO"
}
}
return "YES"
}
```func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
// Check if the length of the intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
// Check if the length of the intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
// Check if the length of intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if i != 2 && intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
// Check if the length of intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if i != 2 && intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
// Check if length of intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
// Check if length of intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
// Check if the length of the intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
// Check if the length of the intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
// Check if the length of intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate the intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
// Check if the length of intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
// Check if length of intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if i != 2 && intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if intervals do not intersect
if start1 > end2 || start2 > end1 {
return "NO"
}
// Calculate intersection
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
// Check if length of intersection is a prime number
if intersectionLength < 2 {
return "NO"
}
for i in intersectionStart + 1...intersectionEnd {
if i != 2 && intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
return (start == end)? "NO" : "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
return (start == end)? "NO" : "YES"
}
```return (start == end)? "NO" : "YES" // cannot use optional chaining on non-optional value of type 'Bool'return (start == end)? "NO" : "YES" // expected expressionreturn (start == end)? "NO" : "YES" // consecutive statements on a line must be separated by ';'return (start == end)? "NO" : "YES" // consecutive statements on a line must be separated by ';'return (start == end)? "NO" : "YES" // string literal is unusedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
} else {
return isPrime(end - start + 1)? "YES" : "NO"
}
}
func isPrime(_ n: Int) -> Bool {
if n < 2 {
return false
} else if n == 2 {
return true
} else if n % 2 == 0 {
return false
} else {
for i in 3...Int(sqrt(Double(n))) {
if n % i == 0 {
return false
}
}
return true
}
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
} else {
return isPrime(end - start + 1)? "YES" : "NO"
}
}
func isPrime(_ n: Int) -> Bool {
if n < 2 {
return false
} else if n == 2 {
return true
} else if n % 2 == 0 {
return false
} else {
for i in 3...Int(sqrt(Double(n))) {
if n % i == 0 {
return false
}
}
return true
}
}
```return isPrime(end - start + 1)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(end - start + 1)? "YES" : "NO" // string literal is unusedreturn isPrime(end - start + 1)? "YES" : "NO" // expected expressionreturn isPrime(end - start + 1)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(end - start + 1)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Write your code here
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
if start == end {
return "YES"
}
return isPrime(end - start)? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
for i in 3..<number {
if number % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Write your code here
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
if start == end {
return "YES"
}
return isPrime(end - start)? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
for i in 3..<number {
if number % i == 0 {
return false
}
}
return true
}
```return isPrime(end - start)? "YES" : "NO" // string literal is unusedreturn isPrime(end - start)? "YES" : "NO" // expected expressionreturn isPrime(end - start)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(end - start)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(end - start)? "YES" : "NO" // consecutive statements on a line must be separated by ';'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
return start < end? "YES" : "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
return start < end? "YES" : "NO"
}
```return start < end? "YES" : "NO" // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return start < end? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Int'return start < end? "YES" : "NO" // expected expressionreturn start < end? "YES" : "NO" // string literal is unusedreturn start < end? "YES" : "NO" // consecutive statements on a line must be separated by ';'return start < end? "YES" : "NO" // consecutive statements on a line must be separated by ';'return start < end? "YES" : "NO" // cannot convert return expression of type 'Bool' to return type 'String'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
} else {
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
}
func isPrime(_ n: Int) -> Bool {
if n < 2 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
} else {
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
}
func isPrime(_ n: Int) -> Bool {
if n < 2 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
```return isPrime(length)? "YES" : "NO" // string literal is unusedreturn isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(length)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(length)? "YES" : "NO" // expected expressionreturn isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
return isPrime(end - start + 1)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
guard n > 1 else { return false }
guard n!= 2 else { return true }
guard n % 2!= 0 else { return false }
for i in 3..<n {
if n % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
return isPrime(end - start + 1)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
guard n > 1 else { return false }
guard n!= 2 else { return true }
guard n % 2!= 0 else { return false }
for i in 3..<n {
if n % i == 0 {
return false
}
}
return true
}
```return isPrime(end - start + 1)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(end - start + 1)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(end - start + 1)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(end - start + 1)? "YES" : "NO" // string literal is unusedreturn isPrime(end - start + 1)? "YES" : "NO" // expected expressionguard n!= 2 else { return true } // cannot force unwrap value of non-optional type 'Int'guard n!= 2 else { return true } // '=' must have consistent whitespace on both sidesguard n!= 2 else { return true } // use of '=' in a boolean context, did you mean '=='?guard n % 2!= 0 else { return false } // cannot force unwrap value of non-optional type 'Int'guard n % 2!= 0 else { return false } // expression is not assignable: binary operator returns immutable valueguard n % 2!= 0 else { return false } // '=' must have consistent whitespace on both sidesguard n % 2!= 0 else { return false } // use of '=' in a boolean context, did you mean '=='?func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
} else {
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
} else {
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start
if length <= 0 {
return "NO"
}
if length == 1 {
return "YES"
}
var i = 2
while i * i <= length {
if length % i == 0 {
return "NO"
}
i += 1
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start
if length <= 0 {
return "NO"
}
if length == 1 {
return "YES"
}
var i = 2
while i * i <= length {
if length % i == 0 {
return "NO"
}
i += 1
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start
if length <= 0 {
return "NO"
}
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start
if length <= 0 {
return "NO"
}
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```return isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(length)? "YES" : "NO" // expected expressionreturn isPrime(length)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(length)? "YES" : "NO" // string literal is unusedreturn isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
return (end - start + 1) % 2 == 0? "YES" : "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
return (end - start + 1) % 2 == 0? "YES" : "NO"
}
```return (end - start + 1) % 2 == 0? "YES" : "NO" // string literal is unusedreturn (end - start + 1) % 2 == 0? "YES" : "NO" // consecutive statements on a line must be separated by ';'return (end - start + 1) % 2 == 0? "YES" : "NO" // expected expressionreturn (end - start + 1) % 2 == 0? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Int'return (end - start + 1) % 2 == 0? "YES" : "NO" // cannot convert return expression of type 'Bool' to return type 'String'return (end - start + 1) % 2 == 0? "YES" : "NO" // consecutive statements on a line must be separated by ';'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
return (start...end).count.isPrime? "YES" : "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
return (start...end).count.isPrime? "YES" : "NO"
}
```return (start...end).count.isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return (start...end).count.isPrime? "YES" : "NO" // string literal is unusedreturn (start...end).count.isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return (start...end).count.isPrime? "YES" : "NO" // expected expressionreturn (start...end).count.isPrime? "YES" : "NO" // type of expression is ambiguous without a type annotationfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
return isPrime(end - start + 1)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
return isPrime(end - start + 1)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```return isPrime(end - start + 1)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(end - start + 1)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(end - start + 1)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(end - start + 1)? "YES" : "NO" // string literal is unusedreturn isPrime(end - start + 1)? "YES" : "NO" // expected expressionfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
return (start...end).count % 2 == 1? "YES" : "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
return (start...end).count % 2 == 1? "YES" : "NO"
}
```return (start...end).count % 2 == 1? "YES" : "NO" // expected expressionreturn (start...end).count % 2 == 1? "YES" : "NO" // string literal is unusedreturn (start...end).count % 2 == 1? "YES" : "NO" // consecutive statements on a line must be separated by ';'return (start...end).count % 2 == 1? "YES" : "NO" // consecutive statements on a line must be separated by ';'return (start...end).count % 2 == 1? "YES" : "NO" // cannot convert return expression of type 'Bool' to return type 'String'return (start...end).count % 2 == 1? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Int'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
return isPrime(end - start + 1)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
return isPrime(end - start + 1)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```return isPrime(end - start + 1)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(end - start + 1)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(end - start + 1)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(end - start + 1)? "YES" : "NO" // string literal is unusedreturn isPrime(end - start + 1)? "YES" : "NO" // expected expressionfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
return (start...end).count % 2 == 1? "YES" : "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
return (start...end).count % 2 == 1? "YES" : "NO"
}
```return (start...end).count % 2 == 1? "YES" : "NO" // expected expressionreturn (start...end).count % 2 == 1? "YES" : "NO" // string literal is unusedreturn (start...end).count % 2 == 1? "YES" : "NO" // consecutive statements on a line must be separated by ';'return (start...end).count % 2 == 1? "YES" : "NO" // consecutive statements on a line must be separated by ';'return (start...end).count % 2 == 1? "YES" : "NO" // cannot convert return expression of type 'Bool' to return type 'String'return (start...end).count % 2 == 1? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Int'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
return isPrime(end - start + 1)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2...Int(sqrt(Double(n))) {
if n % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
return isPrime(end - start + 1)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2...Int(sqrt(Double(n))) {
if n % i == 0 {
return false
}
}
return true
}
```return isPrime(end - start + 1)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(end - start + 1)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(end - start + 1)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(end - start + 1)? "YES" : "NO" // string literal is unusedreturn isPrime(end - start + 1)? "YES" : "NO" // expected expressionfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
return isPrime(end - start + 1)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
guard n > 1 else { return false }
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
return isPrime(end - start + 1)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
guard n > 1 else { return false }
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
```return isPrime(end - start + 1)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(end - start + 1)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(end - start + 1)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(end - start + 1)? "YES" : "NO" // string literal is unusedreturn isPrime(end - start + 1)? "YES" : "NO" // expected expressionfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
return isPrime(end - start + 1)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n < 2 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
return isPrime(end - start + 1)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n < 2 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
```return isPrime(end - start + 1)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(end - start + 1)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(end - start + 1)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(end - start + 1)? "YES" : "NO" // string literal is unusedreturn isPrime(end - start + 1)? "YES" : "NO" // expected expressionfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if a > d || b < c {
return "NO"
}
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if a > d || b < c {
return "NO"
}
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```return isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(length)? "YES" : "NO" // expected expressionreturn isPrime(length)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(length)? "YES" : "NO" // string literal is unusedreturn isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
let (x, y) = (max(a, c), min(b, d))
return x <= y && isPrime(y - x + 1)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 { return false }
if n <= 3 { return true }
for i in 2...Int(sqrt(Double(n))) {
if n % i == 0 { return false }
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
let (x, y) = (max(a, c), min(b, d))
return x <= y && isPrime(y - x + 1)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 { return false }
if n <= 3 { return true }
for i in 2...Int(sqrt(Double(n))) {
if n % i == 0 { return false }
}
return true
}
```return x <= y && isPrime(y - x + 1)? "YES" : "NO" // expected expressionreturn x <= y && isPrime(y - x + 1)? "YES" : "NO" // optional type 'Bool?' cannot be used as a boolean; test for '!= nil' insteadreturn x <= y && isPrime(y - x + 1)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return x <= y && isPrime(y - x + 1)? "YES" : "NO" // string literal is unusedreturn x <= y && isPrime(y - x + 1)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return x <= y && isPrime(y - x + 1)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return x <= y && isPrime(y - x + 1)? "YES" : "NO" // cannot convert return expression of type 'Bool' to return type 'String'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if a > d || b < c {
return "NO"
}
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n < 2 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if a > d || b < c {
return "NO"
}
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n < 2 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
```return isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(length)? "YES" : "NO" // expected expressionreturn isPrime(length)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(length)? "YES" : "NO" // string literal is unusedreturn isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if a > d || c > b {
return "NO"
}
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if a > d || c > b {
return "NO"
}
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```return isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(length)? "YES" : "NO" // expected expressionreturn isPrime(length)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(length)? "YES" : "NO" // string literal is unusedreturn isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if (b < c || a > d) {
return "NO"
}
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if (b < c || a > d) {
return "NO"
}
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```return isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(length)? "YES" : "NO" // expected expressionreturn isPrime(length)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(length)? "YES" : "NO" // string literal is unusedreturn isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if b < c || d < a {
return "NO"
}
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n == 2 {
return true
}
if n % 2 == 0 {
return false
}
var i = 3
while i * i <= n {
if n % i == 0 {
return false
}
i += 2
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if b < c || d < a {
return "NO"
}
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n == 2 {
return true
}
if n % 2 == 0 {
return false
}
var i = 3
while i * i <= n {
if n % i == 0 {
return false
}
i += 2
}
return true
}
```return isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(length)? "YES" : "NO" // expected expressionreturn isPrime(length)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(length)? "YES" : "NO" // string literal is unusedreturn isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if a > d || b < c {
return "NO"
}
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if a > d || b < c {
return "NO"
}
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
```return isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(length)? "YES" : "NO" // expected expressionreturn isPrime(length)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(length)? "YES" : "NO" // string literal is unusedreturn isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if a > d || b < c {
return "NO"
}
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
var i = 2
while i * i <= n {
if n % i == 0 {
return false
}
i += 1
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if a > d || b < c {
return "NO"
}
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
var i = 2
while i * i <= n {
if n % i == 0 {
return false
}
i += 1
}
return true
}
```return isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(length)? "YES" : "NO" // expected expressionreturn isPrime(length)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(length)? "YES" : "NO" // string literal is unusedreturn isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if a > d || b < c {
return "NO"
}
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if a > d || b < c {
return "NO"
}
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
```return isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(length)? "YES" : "NO" // expected expressionreturn isPrime(length)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(length)? "YES" : "NO" // string literal is unusedreturn isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if a > d || b < c {
return "NO"
}
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if a > d || b < c {
return "NO"
}
let start = max(a, c)
let end = min(b, d)
let length = end - start + 1
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Your code here
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let intersection = (max(start1, start2), min(end1, end2))
if isPrime(intersection.0) && isPrime(intersection.1) {
return "YES"
}
return "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Your code here
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let intersection = (max(start1, start2), min(end1, end2))
if isPrime(intersection.0) && isPrime(intersection.1) {
return "YES"
}
return "NO"
}
```if isPrime(intersection.0) && isPrime(intersection.1) { // cannot find 'isPrime' in scopeif isPrime(intersection.0) && isPrime(intersection.1) { // cannot find 'isPrime' in scopefunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
if isPrime(start) {
return "YES"
}
return "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
if isPrime(start) {
return "YES"
}
return "NO"
}
```if isPrime(start) { // cannot find 'isPrime' in scopefunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end1 || start2 > end2 {
return "NO"
}
let intersection = (max(start1, start2), min(end1, end2))
let (start, end) = intersection
if start > end {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end1 || start2 > end2 {
return "NO"
}
let intersection = (max(start1, start2), min(end1, end2))
let (start, end) = intersection
if start > end {
return "NO"
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// If the two intervals don't intersect, return "NO".
if start1 > end2 || start2 > end1 {
return "NO"
}
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
let intersection = (max(start1, start2), min(end1, end2))
let (start, end) = intersection
let length = end - start + 1
if isPrime(length) {
return "YES"
}
return "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// If the two intervals don't intersect, return "NO".
if start1 > end2 || start2 > end1 {
return "NO"
}
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
let intersection = (max(start1, start2), min(end1, end2))
let (start, end) = intersection
let length = end - start + 1
if isPrime(length) {
return "YES"
}
return "NO"
}
```if isPrime(length) { // cannot find 'isPrime' in scopefunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Your code here
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
}
return "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Your code here
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
}
return "NO"
}
```if isPrime(length) { // cannot find 'isPrime' in scopefunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
}
return "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
}
return "NO"
}
```if isPrime(length) { // cannot find 'isPrime' in scopefunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end1 || start2 > end2 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
if end - start == 1 {
return "YES"
}
return "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end1 || start2 > end2 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
if end - start == 1 {
return "YES"
}
return "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// TODO: implement me
return ""
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// TODO: implement me
return ""
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Find the intersection of the two intervals
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
// No intersection
return "NO"
} else if end - start <= 1 {
// Length of intersection is not a prime number
return "NO"
} else {
// Check if the length of intersection is a prime number
var isPrime = true
for i in 2..<end - start {
if end - start % i == 0 {
isPrime = false
break
}
}
return isPrime? "YES" : "NO"
}
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Find the intersection of the two intervals
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
// No intersection
return "NO"
} else if end - start <= 1 {
// Length of intersection is not a prime number
return "NO"
} else {
// Check if the length of intersection is a prime number
var isPrime = true
for i in 2..<end - start {
if end - start % i == 0 {
isPrime = false
break
}
}
return isPrime? "YES" : "NO"
}
}
```return isPrime? "YES" : "NO" // string literal is unusedreturn isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // expected expressionreturn isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let intersectionLength = end - start + 1
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let intersectionLength = end - start + 1
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Find the intersection of the two intervals
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
// No intersection
return "NO"
} else if end - start <= 1 {
// Length of intersection is not a prime number
return "NO"
} else {
// Check if the length of intersection is a prime number
var isPrime = true
for i in 2..<end - start {
if end - start % i == 0 {
isPrime = false
break
}
}
return isPrime? "YES" : "NO"
}
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Find the intersection of the two intervals
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
// No intersection
return "NO"
} else if end - start <= 1 {
// Length of intersection is not a prime number
return "NO"
} else {
// Check if the length of intersection is a prime number
var isPrime = true
for i in 2..<end - start {
if end - start % i == 0 {
isPrime = false
break
}
}
return isPrime? "YES" : "NO"
}
}
```return isPrime? "YES" : "NO" // string literal is unusedreturn isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // expected expressionreturn isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let intersectionLength = end - start + 1
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let intersectionLength = end - start + 1
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let intersectionLength = end - start + 1
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let intersectionLength = end - start + 1
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let intersectionLength = end - start + 1
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let intersectionLength = end - start + 1
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Find the intersection of the two intervals
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
// No intersection
return "NO"
} else if end - start <= 1 {
// Length of intersection is not a prime number
return "NO"
} else {
// Check if the length of intersection is a prime number
var isPrime = true
for i in 2..<end - start {
if end - start % i == 0 {
isPrime = false
break
}
}
return isPrime? "YES" : "NO"
}
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Find the intersection of the two intervals
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
// No intersection
return "NO"
} else if end - start <= 1 {
// Length of intersection is not a prime number
return "NO"
} else {
// Check if the length of intersection is a prime number
var isPrime = true
for i in 2..<end - start {
if end - start % i == 0 {
isPrime = false
break
}
}
return isPrime? "YES" : "NO"
}
}
```return isPrime? "YES" : "NO" // string literal is unusedreturn isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // expected expressionreturn isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let intersectionLength = end - start + 1
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let intersectionLength = end - start + 1
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let intersectionLength = end - start + 1
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let intersectionLength = end - start + 1
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let intersectionLength = end - start + 1
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"<|im_end|>
<|im_start|>assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let intersectionLength = end - start + 1
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Write your code here
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Write your code here
}
```} // missing return in global function expected to return 'String'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
return "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
return "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Write your code here
var result = "NO"
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if isPrime(length) {
result = "YES"
}
return result
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Write your code here
var result = "NO"
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if isPrime(length) {
result = "YES"
}
return result
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
// Example usage:
print(intersection(interval1: (1, 2), interval2: (2, 3))) // Output: "NO"
print(intersection(interval1: (-1, 1), interval2: (0, 4))) // Output: "NO"
print(intersection(interval1: (-3, -1), interval2: (-5, 5))) // Output: "YES"
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
}
```} // missing return in global function expected to return 'String'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
}
```} // missing return in global function expected to return 'String'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
}
```} // missing return in global function expected to return 'String'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
return "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// your code here
return "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals do not intersect
if end1 < start2 || end2 < start1 {
return "NO"
}
// Calculate the intersection length
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
// Check if the intersection length is a prime number
if intersectionLength > 0 && isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
// Check if the intervals do not intersect
if end1 < start2 || end2 < start1 {
return "NO"
}
// Calculate the intersection length
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
// Check if the intersection length is a prime number
if intersectionLength > 0 && isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
// Example usage:
print(intersection(interval1: (1, 2), interval2: (2, 3))) // Output: "NO"
print(intersection(interval1: (-1, 1), interval2: (0, 4))) // Output: "NO"
print(intersection(interval1: (-3, -1), interval2: (-5, 5))) // Output: "YES"
```func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Write your code here
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
if intersectionLength <= 0 {
return "NO"
}
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Write your code here
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart
if intersectionLength <= 0 {
return "NO"
}
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
// Example usage:
print(intersection(interval1: (1, 2), interval2: (2, 3))) // Output: "NO"
print(intersection(interval1: (-1, 1), interval2: (0, 4))) // Output: "NO"
print(intersection(interval1: (-3, -1), interval2: (-5, 5))) // Output: "YES"
```func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start
if length == 0 {
return "NO"
}
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start
if length == 0 {
return "NO"
}
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
// Example usage:
print(intersection(interval1: (1, 2), interval2: (2, 3))) // Output: "NO"
print(intersection(interval1: (-1, 1), interval2: (0, 4))) // Output: "NO"
print(intersection(interval1: (-3, -1), interval2: (-5, 5))) // Output: "YES"
```func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
return isPrime(intersectionLength) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in stride(from: 3, through: boundary, by: 2) {
if number % i == 0 {
return false
}
}
return true
}system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
return isPrime(intersectionLength) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in stride(from: 3, through: boundary, by: 2) {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
return isPrime(intersectionLength) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
return isPrime(intersectionLength) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length < 0 {
return "NO"
}
if length == 1 {
return "NO"
}
if length == 2 {
return "NO"
}
if length == 3 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
var isPrime = true
for i in 3..<Int(sqrt(Double(length))) + 1 {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length < 0 {
return "NO"
}
if length == 1 {
return "NO"
}
if length == 2 {
return "NO"
}
if length == 3 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
var isPrime = true
for i in 3..<Int(sqrt(Double(length))) + 1 {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let intersection = (max(interval1.0, interval2.0), min(interval1.1, interval2.1))
let length = intersection.1 - intersection.0
if length < 0 {
return "NO"
}
if length == 1 || length == 0 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let intersection = (max(interval1.0, interval2.0), min(interval1.1, interval2.1))
let length = intersection.1 - intersection.0
if length < 0 {
return "NO"
}
if length == 1 || length == 0 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length < 0 {
return "NO"
}
if length == 1 || length == 0 {
return "NO"
}
for i in 2...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length < 0 {
return "NO"
}
if length == 1 || length == 0 {
return "NO"
}
for i in 2...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length < 0 {
return "NO"
}
if length == 1 {
return "NO"
}
if length == 2 {
return "NO"
}
if length == 3 {
return "YES"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length < 0 {
return "NO"
}
if length == 1 {
return "NO"
}
if length == 2 {
return "NO"
}
if length == 3 {
return "YES"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else { return "NO" }
let length = end - start + 1
if length == 1 { return "NO" }
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else { return "NO" }
let length = end - start + 1
if length == 1 { return "NO" }
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
if length == 2 {
return "YES"
}
if length == 3 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
for i in stride(from: 3, through: Int(sqrt(Double(length))), by: 2) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
if length == 2 {
return "YES"
}
if length == 3 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
for i in stride(from: 3, through: Int(sqrt(Double(length))), by: 2) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
if length == 3 {
return "YES"
}
if length == 5 {
return "YES"
}
if length == 7 {
return "YES"
}
if length == 11 {
return "YES"
}
return "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
if length == 3 {
return "YES"
}
if length == 5 {
return "YES"
}
if length == 7 {
return "YES"
}
if length == 11 {
return "YES"
}
return "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
if length == 3 {
return "YES"
}
if length == 5 {
return "YES"
}
if length == 7 {
return "YES"
}
if length == 11 {
return "YES"
}
if length == 13 {
return "YES"
}
if length == 17 {
return "YES"
}
if length == 19 {
return "YES"
}
if length == 23 {
return "YES"
}
if length == 29 {
return "YES"
}
if length == 31 {
return "YES"
}
if length == 37 {
return "YES"
}
if length == 41 {
return "YES"
}
if length == 43 {
return "YES"
}
if length == 47 {
return "YES"
}
if length == 53 {
return "YES"
}
if length == 59 {
return "YES"
}
if length == 61 {
return "YES"
}
if length == 67 {
return "YES"
}
if length == 71 {
return "YES"
}
if length == 73 {
return "YES"
}
if length == 79 {
return "YES"
}
if length == 83 {
return "YES"
}
if length == 89 {
return "YES"
}
if length == 97 {
return "YES"
}
if length == 101 {
return "YES"
}
if length == 103 {
return "YES"
}
if length == 107 {
return "YES"
}
if length == 109 {
return "YES"
}
if length == 113 {
return "YES"
}
if length == 127 {
return "YES"
}
if length == 131 {
return "YES"
}
if length == 137 {
return "YES"
}
if length == 139 {
return "YES"
}
if length == 149 {
return "YES"
}
if length == 151 {
return "YES"
}
if length == 157 {
return "YES"
}
if length == 163 {
return "YES"
}
if length == 167 {
return "YES"
}
if length == 173 {
return "YES"
}
if length == 179 {
return "YES"
}
if length == 181 {
return "YES"
}
if length == 191 {
return "YES"
}
if length == 193 {
return "YES"
}
if length == 197 {
return "YES"
}
if length == 199 {
return "YES"
}
return "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
if length == 3 {
return "YES"
}
if length == 5 {
return "YES"
}
if length == 7 {
return "YES"
}
if length == 11 {
return "YES"
}
if length == 13 {
return "YES"
}
if length == 17 {
return "YES"
}
if length == 19 {
return "YES"
}
if length == 23 {
return "YES"
}
if length == 29 {
return "YES"
}
if length == 31 {
return "YES"
}
if length == 37 {
return "YES"
}
if length == 41 {
return "YES"
}
if length == 43 {
return "YES"
}
if length == 47 {
return "YES"
}
if length == 53 {
return "YES"
}
if length == 59 {
return "YES"
}
if length == 61 {
return "YES"
}
if length == 67 {
return "YES"
}
if length == 71 {
return "YES"
}
if length == 73 {
return "YES"
}
if length == 79 {
return "YES"
}
if length == 83 {
return "YES"
}
if length == 89 {
return "YES"
}
if length == 97 {
return "YES"
}
if length == 101 {
return "YES"
}
if length == 103 {
return "YES"
}
if length == 107 {
return "YES"
}
if length == 109 {
return "YES"
}
if length == 113 {
return "YES"
}
if length == 127 {
return "YES"
}
if length == 131 {
return "YES"
}
if length == 137 {
return "YES"
}
if length == 139 {
return "YES"
}
if length == 149 {
return "YES"
}
if length == 151 {
return "YES"
}
if length == 157 {
return "YES"
}
if length == 163 {
return "YES"
}
if length == 167 {
return "YES"
}
if length == 173 {
return "YES"
}
if length == 179 {
return "YES"
}
if length == 181 {
return "YES"
}
if length == 191 {
return "YES"
}
if length == 193 {
return "YES"
}
if length == 197 {
return "YES"
}
if length == 199 {
return "YES"
}
return "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else { return "NO" }
let length = end - start + 1
if length == 1 { return "NO" }
if length == 2 { return "YES" }
if length == 3 { return "YES" }
if length % 2 == 0 { return "NO" }
if length % 3 == 0 { return "NO" }
var i = 5
while i * i <= length {
if length % i == 0 { return "NO" }
if length % (i + 2) == 0 { return "NO" }
i += 6
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else { return "NO" }
let length = end - start + 1
if length == 1 { return "NO" }
if length == 2 { return "YES" }
if length == 3 { return "YES" }
if length % 2 == 0 { return "NO" }
if length % 3 == 0 { return "NO" }
var i = 5
while i * i <= length {
if length % i == 0 { return "NO" }
if length % (i + 2) == 0 { return "NO" }
i += 6
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
if length == 2 {
return "YES"
}
if length == 3 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
if length % 3 == 0 {
return "NO"
}
if length % 5 == 0 {
return "NO"
}
if length % 7 == 0 {
return "NO"
}
if length % 11 == 0 {
return "NO"
}
if length % 13 == 0 {
return "NO"
}
if length % 17 == 0 {
return "NO"
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
if length == 2 {
return "YES"
}
if length == 3 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
if length % 3 == 0 {
return "NO"
}
if length % 5 == 0 {
return "NO"
}
if length % 7 == 0 {
return "NO"
}
if length % 11 == 0 {
return "NO"
}
if length % 13 == 0 {
return "NO"
}
if length % 17 == 0 {
return "NO"
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else { return "NO" }
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else { return "NO" }
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 || length == 3 {
return "YES"
}
if length % 2 == 0 || length % 3 == 0 {
return "NO"
}
for i in 5...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 || length == 3 {
return "YES"
}
if length % 2 == 0 || length % 3 == 0 {
return "NO"
}
for i in 5...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 || length == 3 {
return "YES"
}
if length % 2 == 0 || length % 3 == 0 {
return "NO"
}
for i in 5...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 || length == 3 {
return "YES"
}
if length % 2 == 0 || length % 3 == 0 {
return "NO"
}
for i in 5...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 || length == 3 {
return "YES"
}
if length % 2 == 0 || length % 3 == 0 {
return "NO"
}
for i in 5...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 || length == 3 {
return "YES"
}
if length % 2 == 0 || length % 3 == 0 {
return "NO"
}
for i in 5...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 || length == 3 {
return "YES"
}
if length % 2 == 0 || length % 3 == 0 {
return "NO"
}
for i in 5...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 || length == 3 {
return "YES"
}
if length % 2 == 0 || length % 3 == 0 {
return "NO"
}
for i in 5...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 || length == 3 {
return "YES"
}
if length % 2 == 0 || length % 3 == 0 {
return "NO"
}
for i in 5...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 || length == 3 {
return "YES"
}
if length % 2 == 0 || length % 3 == 0 {
return "NO"
}
for i in 5...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 || length == 3 {
return "YES"
}
if length % 2 == 0 || length % 3 == 0 {
return "NO"
}
for i in 5...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 || length == 3 {
return "YES"
}
if length % 2 == 0 || length % 3 == 0 {
return "NO"
}
for i in 5...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"[/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"[/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"[/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"[/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"[/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"[/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"[/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"[/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"[/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}[INST] Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"[/INST] ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in stride(from: 3, through: boundary, by: 2) {
if number % i == 0 {
return false
}
}
return true
}system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in stride(from: 3, through: boundary, by: 2) {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
let boundary = Int(sqrt(Double(number)))
for i in 3...boundary {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let intersection = (max(interval1.0, interval2.0), min(interval1.1, interval2.1))
let length = intersection.1 - intersection.0 + 1
return length.isPrime ? "YES" : "NO"
}
extension Int {
var isPrime: Bool {
guard self > 1 else { return false }
return !stride(from: 2, through: Int(sqrt(Double(self))), by: 1).contains { self % $0 == 0 }
}
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let intersection = (max(interval1.0, interval2.0), min(interval1.1, interval2.1))
let length = intersection.1 - intersection.0 + 1
return length.isPrime ? "YES" : "NO"
}
extension Int {
var isPrime: Bool {
guard self > 1 else { return false }
return !stride(from: 2, through: Int(sqrt(Double(self))), by: 1).contains { self % $0 == 0 }
}
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length < 1 {
return "NO"
}
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length < 1 {
return "NO"
}
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else { return "NO" }
let length = end - start + 1
return length.isPrime ? "YES" : "NO"
}
extension Int {
var isPrime: Bool {
guard self > 1 else { return false }
return !stride(from: 2, through: Int(sqrt(Double(self))), by: 1).contains { self % $0 == 0 }
}
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else { return "NO" }
let length = end - start + 1
return length.isPrime ? "YES" : "NO"
}
extension Int {
var isPrime: Bool {
guard self > 1 else { return false }
return !stride(from: 2, through: Int(sqrt(Double(self))), by: 1).contains { self % $0 == 0 }
}
}
``` // XCTAssertTrue failed### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length < 1 {
return "NO"
}
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
if length == 3 {
return "NO"
}
if length == 4 {
return "NO"
}
if length == 5 {
return "YES"
}
if length == 6 {
return "NO"
}
if length == 7 {
return "NO"
}
if length == 8 {
return "NO"
}
if length == 9 {
return "YES"
}
if length == 10 {
return "NO"
}
if length == 11 {
return "NO"
}
if length == 12 {
return "NO"
}
if length == 13 {
return "YES"
}
if length == 14 {
return "NO"
}
if length == 15 {
return "NO"
}
if length == 16 {
return "NO"
}
if length == 17 {
return "NO"
}
if length == 18 {
return "NO"
}
if length == 19 {
return "YES"
}
if length == 20 {
return "NO"
}
if length == 21 {
return "NO"
}
if length == 22 {
return "NO"
}
if length == 23 {
return "NO"
}
if length == 24 {
return "NO"
}
if length == 25 {
return "YES"
}
if length == 26 {
return "NO"
}
if length == 27 {
return "NO"
}
if length == 28 {
return "NO"
}
if length == 29 {
return "NO"
}
if length == 30 {
return "NO"
}
if length == 31 {
return "YES"
}
if length == 32 {
return "NO"
}
if length == 33 {
return "NO"
}
if length == 34 {
return "NO"
}
if length == 35 {
return "NO"
}
if length == 36 {
return "NO"
}
if length == 37 {
return "NO"
}
if length == 38 {
return "NO"
}
if length == 39 {
return "YES"
}
if length == 40 {
return "NO"
}
if length == 41 {
return "NO"
}
if length == 42 {
return "NO"
}
if length == 43 {
return "NO"
}
if length == 44 {
return "NO"
}
if length == 45 {
return "NO"
}
if length == 46 {
return "NO"
}
if length == 47 {
return "NO"
}
if length == 48 {
return "NO"
}
if length == 49 {
return "YES"
}
if length == 50 {
return "NO"
}
if length == 51 {
return "NO"
}
if length == 52 {
return "NO"
}
if length == 53 {
return "NO"
}
if length == 54 {
return "NO"
XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scopefunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length < 1 {
return "NO"
}
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length < 1 {
return "NO"
}
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 0 {
return "NO"
}
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 0 {
return "NO"
}
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 0 {
return "NO"
}
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 0 {
return "NO"
}
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length < 1 {
return "NO"
}
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length < 1 {
return "NO"
}
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
if length == 2 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
var i = 3
while i * i <= length {
if length % i == 0 {
return "NO"
}
i += 2
}
return "YES"
}Here is the Swift code for the problem:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
if length == 2 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
var i = 3
while i * i <= length {
if length % i == 0 {
return "NO"
}
i += 2
}
return "YES"
}
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
if length == 2 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
var i = 3
while i * i <= length {
if length % i == 0 {
return "NO"
}
i += 2
}
return "YES"
}Here is the Swift code for the problem:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
if length == 2 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
var i = 3
while i * i <= length {
if length % i == 0 {
return "NO"
}
i += 2
}
return "YES"
}
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Here is the Swift code for the problem:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Here is the Swift code for the problem:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Here is the Swift code for the task:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Here is the Swift code for the problem:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
if length == 2 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
var i = 3
while i * i <= length {
if length % i == 0 {
return "NO"
}
i += 2
}
return "YES"
}Here is the Swift code for the problem:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
if length == 2 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
var i = 3
while i * i <= length {
if length % i == 0 {
return "NO"
}
i += 2
}
return "YES"
}
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
if length == 2 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
var i = 3
while i * i <= length {
if length % i == 0 {
return "NO"
}
i += 2
}
return "YES"
}Here is the Swift code for the problem:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
if length == 2 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
var i = 3
while i * i <= length {
if length % i == 0 {
return "NO"
}
i += 2
}
return "YES"
}
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Here is the Swift code for the problem:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length < 2 {
return "NO"
}
if length == 2 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
var i = 3
while i * i <= length {
if length % i == 0 {
return "NO"
}
i += 2
}
return "YES"
}Here is the Swift code for the problem:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length < 2 {
return "NO"
}
if length == 2 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
var i = 3
while i * i <= length {
if length % i == 0 {
return "NO"
}
i += 2
}
return "YES"
}
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Helper function to check if a number is prime
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
// Determine the intersection of the two intervals
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
// If there is no intersection
if start > end {
return "NO"
}
// Calculate the length of the intersection
let length = end - start + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Helper function to check if a number is prime
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
// Determine the intersection of the two intervals
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
// If there is no intersection
if start > end {
return "NO"
}
// Calculate the length of the intersection
let length = end - start + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Helper function to determine if a number is prime
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
// Calculate the intersection of the two intervals
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
// Check if there is an intersection
if start > end {
return "NO"
}
// Calculate the length of the intersection
let length = end - start + 1
// Determine if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Helper function to determine if a number is prime
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
// Calculate the intersection of the two intervals
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
// Check if there is an intersection
if start > end {
return "NO"
}
// Calculate the length of the intersection
let length = end - start + 1
// Determine if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
// Find the intersection interval
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Check if there is an intersection
if intersectionStart > intersectionEnd {
return "NO"
}
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Helper function to check if a number is prime
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
// Check if the length of the intersection is a prime number
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
// Find the intersection interval
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Check if there is an intersection
if intersectionStart > intersectionEnd {
return "NO"
}
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Helper function to check if a number is prime
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
// Check if the length of the intersection is a prime number
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Helper function to check if a number is prime
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
// Calculate the intersection of the two intervals
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
// If the intervals do not intersect
if start > end {
return "NO"
}
// Calculate the length of the intersection
let length = end - start + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Helper function to check if a number is prime
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
// Calculate the intersection of the two intervals
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
// If the intervals do not intersect
if start > end {
return "NO"
}
// Calculate the length of the intersection
let length = end - start + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Helper function to check if a number is prime
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
// Calculate the intersection of the two intervals
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
// Check if there is an intersection
if start > end {
return "NO"
}
// Calculate the length of the intersection
let length = end - start + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Helper function to check if a number is prime
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
// Calculate the intersection of the two intervals
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
// Check if there is an intersection
if start > end {
return "NO"
}
// Calculate the length of the intersection
let length = end - start + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Helper function to determine if a number is prime
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
// Determine the intersection of the two intervals
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
// Calculate the length of the intersection
let length = end - start + 1
// Check if the intervals intersect and if the length is a prime number
if start <= end && isPrime(length) {
return "YES"
} else {
return "NO"
}
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Helper function to determine if a number is prime
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
// Determine the intersection of the two intervals
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
// Calculate the length of the intersection
let length = end - start + 1
// Check if the intervals intersect and if the length is a prime number
if start <= end && isPrime(length) {
return "YES"
} else {
return "NO"
}
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
// Calculate the intersection of the two intervals
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Check if there is an intersection
if intersectionStart > intersectionEnd {
return "NO"
}
// Calculate the length of the intersection
let length = intersectionEnd - intersectionStart + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
// Calculate the intersection of the two intervals
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Check if there is an intersection
if intersectionStart > intersectionEnd {
return "NO"
}
// Calculate the length of the intersection
let length = intersectionEnd - intersectionStart + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Helper function to check if a number is prime
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
// Determine the intersection of the two intervals
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
// If there is no intersection
if start > end {
return "NO"
}
// Calculate the length of the intersection
let length = end - start + 1
// Check if the length is a prime number
return isPrime(length) ? "YES" : "NO"
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Helper function to check if a number is prime
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
// Determine the intersection of the two intervals
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
// If there is no intersection
if start > end {
return "NO"
}
// Calculate the length of the intersection
let length = end - start + 1
// Check if the length is a prime number
return isPrime(length) ? "YES" : "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Helper function to determine if a number is prime
func isPrime(_ num: Int) -> Bool {
if num <= 1 { return false }
if num <= 3 { return true }
if num % 2 == 0 || num % 3 == 0 { return false }
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 { return false }
i += 6
}
return true
}
// Determine the intersection of the two intervals
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
// If the intervals do not intersect
if start > end {
return "NO"
}
// Calculate the length of the intersection
let length = end - start + 1
// Check if the length is a prime number
return isPrime(length) ? "YES" : "NO"
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Helper function to determine if a number is prime
func isPrime(_ num: Int) -> Bool {
if num <= 1 { return false }
if num <= 3 { return true }
if num % 2 == 0 || num % 3 == 0 { return false }
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 { return false }
i += 6
}
return true
}
// Determine the intersection of the two intervals
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
// If the intervals do not intersect
if start > end {
return "NO"
}
// Calculate the length of the intersection
let length = end - start + 1
// Check if the length is a prime number
return isPrime(length) ? "YES" : "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Helper function to determine if a number is prime
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
// Calculate the intersection of the two intervals
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
// Check if there is an intersection
if start > end {
return "NO"
}
// Calculate the length of the intersection
let length = end - start + 1
// Determine if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Helper function to determine if a number is prime
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
// Calculate the intersection of the two intervals
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
// Check if there is an intersection
if start > end {
return "NO"
}
// Calculate the length of the intersection
let length = end - start + 1
// Determine if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
// Determine the intersection
let startIntersection = max(start1, start2)
let endIntersection = min(end1, end2)
// Check if there is an intersection
if startIntersection > endIntersection {
return "NO"
}
// Calculate the length of the intersection
let length = endIntersection - startIntersection
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
// Determine the intersection
let startIntersection = max(start1, start2)
let endIntersection = min(end1, end2)
// Check if there is an intersection
if startIntersection > endIntersection {
return "NO"
}
// Calculate the length of the intersection
let length = endIntersection - startIntersection
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
// Calculate the intersection
let startIntersection = max(start1, start2)
let endIntersection = min(end1, end2)
// Check if there is an intersection
if startIntersection > endIntersection {
return "NO"
}
// Calculate the length of the intersection
let length = endIntersection - startIntersection + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
// Calculate the intersection
let startIntersection = max(start1, start2)
let endIntersection = min(end1, end2)
// Check if there is an intersection
if startIntersection > endIntersection {
return "NO"
}
// Calculate the length of the intersection
let length = endIntersection - startIntersection + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
// Determine the intersection
let startIntersection = max(start1, start2)
let endIntersection = min(end1, end2)
// Check if there is an intersection
if startIntersection > endIntersection {
return "NO"
}
// Calculate the length of the intersection
let length = endIntersection - startIntersection + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
// Determine the intersection
let startIntersection = max(start1, start2)
let endIntersection = min(end1, end2)
// Check if there is an intersection
if startIntersection > endIntersection {
return "NO"
}
// Calculate the length of the intersection
let length = endIntersection - startIntersection + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
// Determine the intersection of the two intervals
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Check if there is an intersection
if intersectionStart > intersectionEnd {
return "NO"
}
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length is a prime number
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
// Determine the intersection of the two intervals
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Check if there is an intersection
if intersectionStart > intersectionEnd {
return "NO"
}
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length is a prime number
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
// Determine the intersection of the two intervals
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Check if there is an intersection
if intersectionStart > intersectionEnd {
return "NO"
}
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Function to check if a number is prime
func isPrime(_ number: Int) -> Bool {
if number < 2 { return false }
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}
// Check if the length of the intersection is prime
return isPrime(intersectionLength) ? "YES" : "NO"
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
// Determine the intersection of the two intervals
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Check if there is an intersection
if intersectionStart > intersectionEnd {
return "NO"
}
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Function to check if a number is prime
func isPrime(_ number: Int) -> Bool {
if number < 2 { return false }
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}
// Check if the length of the intersection is prime
return isPrime(intersectionLength) ? "YES" : "NO"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
// Determine the intersection of the two intervals
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Check if there is an intersection
if intersectionStart > intersectionEnd {
return "NO"
}
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length is a prime number
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
// Determine the intersection of the two intervals
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
// Check if there is an intersection
if intersectionStart > intersectionEnd {
return "NO"
}
// Calculate the length of the intersection
let intersectionLength = intersectionEnd - intersectionStart + 1
// Check if the length is a prime number
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
// Determine the intersection
let startIntersection = max(start1, start2)
let endIntersection = min(end1, end2)
// Check if there is an intersection
if startIntersection > endIntersection {
return "NO"
}
// Calculate the length of the intersection
let length = endIntersection - startIntersection + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
// Determine the intersection
let startIntersection = max(start1, start2)
let endIntersection = min(end1, end2)
// Check if there is an intersection
if startIntersection > endIntersection {
return "NO"
}
// Calculate the length of the intersection
let length = endIntersection - startIntersection + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
// Calculate the intersection
let startIntersection = max(start1, start2)
let endIntersection = min(end1, end2)
// Check if there is an intersection
if startIntersection > endIntersection {
return "NO"
}
// Calculate the length of the intersection
let length = endIntersection - startIntersection + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
// Calculate the intersection
let startIntersection = max(start1, start2)
let endIntersection = min(end1, end2)
// Check if there is an intersection
if startIntersection > endIntersection {
return "NO"
}
// Calculate the length of the intersection
let length = endIntersection - startIntersection + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
// Determine the intersection
let startIntersection = max(start1, start2)
let endIntersection = min(end1, end2)
// Check if there is an intersection
if startIntersection > endIntersection {
return "NO"
}
// Calculate the length of the intersection
let length = endIntersection - startIntersection + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
// Determine the intersection
let startIntersection = max(start1, start2)
let endIntersection = min(end1, end2)
// Check if there is an intersection
if startIntersection > endIntersection {
return "NO"
}
// Calculate the length of the intersection
let length = endIntersection - startIntersection + 1
// Check if the length is a prime number
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Determine the start and end of the intersection
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
// Check if there is an intersection
if start > end {
return "NO"
}
// Calculate the length of the intersection
let length = end - start + 1
// Function to check if a number is prime
func isPrime(_ number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}
// Check if the length of the intersection is prime
return isPrime(length) ? "YES" : "NO"
}```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Determine the start and end of the intersection
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
// Check if there is an intersection
if start > end {
return "NO"
}
// Calculate the length of the intersection
let length = end - start + 1
// Function to check if a number is prime
func isPrime(_ number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}
// Check if the length of the intersection is prime
return isPrime(length) ? "YES" : "NO"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
return isPrime(length) ? "YES" : "NO"
}```swift
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
return isPrime(length) ? "YES" : "NO"
}
```func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
return isPrime(length) ? "YES" : "NO"
}```swift
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
return isPrime(length) ? "YES" : "NO"
}
```func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
return isPrime(length) ? "YES" : "NO"
}```swift
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
return isPrime(length) ? "YES" : "NO"
}
```func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
return isPrime(length) ? "YES" : "NO"
}```swift
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
return isPrime(length) ? "YES" : "NO"
}
```func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
return isPrime(length) ? "YES" : "NO"
}```swift
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
return isPrime(length) ? "YES" : "NO"
}
```func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
return isPrime(length) ? "YES" : "NO"
}```swift
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
return isPrime(length) ? "YES" : "NO"
}
```func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
return isPrime(length) ? "YES" : "NO"
}```swift
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
return isPrime(length) ? "YES" : "NO"
}
```func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
return isPrime(length) ? "YES" : "NO"
}```swift
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
return isPrime(length) ? "YES" : "NO"
}
```func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
return isPrime(length) ? "YES" : "NO"
}```swift
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
return isPrime(length) ? "YES" : "NO"
}
```func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
return isPrime(length) ? "YES" : "NO"
}```swift
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start
return isPrime(length) ? "YES" : "NO"
}
```func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
guard interval1.0 <= interval2.1 && interval1.1 >= interval2.0 else {
return "NO"
}
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
return length.isPrime ? "YES" : "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
guard interval1.0 <= interval2.1 && interval1.1 >= interval2.0 else {
return "NO"
}
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
return length.isPrime ? "YES" : "NO"
}
```return length.isPrime ? "YES" : "NO" // value of type 'Int' has no member 'isPrime'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Write your code here
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Write your code here
}
```} // missing return in global function expected to return 'String'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Write your code here
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Write your code here
}
```} // missing return in global function expected to return 'String'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Write your code here
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Write your code here
}
```} // missing return in global function expected to return 'String'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
guard interval1.0 <= interval2.1 && interval2.0 <= interval1.1 else { return "NO" }
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
return isPrime(number: end - start + 1) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 { return false }
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
guard interval1.0 <= interval2.1 && interval2.0 <= interval1.1 else { return "NO" }
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
return isPrime(number: end - start + 1) ? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 { return false }
}
return true
}
```return isPrime(number: end - start + 1) ? "YES" : "NO" // extraneous argument label 'number:' in callfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
guard interval1.0 <= interval2.1 && interval1.1 >= interval2.0 else { return "NO" }
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
return isPrime(number: end - start + 1) ? "YES" : "NO"
}
func isPrime(number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 { return false }
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
guard interval1.0 <= interval2.1 && interval1.1 >= interval2.0 else { return "NO" }
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
return isPrime(number: end - start + 1) ? "YES" : "NO"
}
func isPrime(number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 { return false }
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
if length == 2 {
return "YES"
}
let isPrime = length > 2 && length % 2 != 0 && length % 3 != 0
return isPrime ? "YES" : "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
if length == 2 {
return "YES"
}
let isPrime = length > 2 && length % 2 != 0 && length % 3 != 0
return isPrime ? "YES" : "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Write your code here
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
if length > 1 && length % 2 == 0 {
return "NO"
}
if length > 1 && length % 3 == 0 {
return "NO"
}
if length > 1 && length % 5 == 0 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// Write your code here
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
if length > 1 && length % 2 == 0 {
return "NO"
}
if length > 1 && length % 3 == 0 {
return "NO"
}
if length > 1 && length % 5 == 0 {
return "NO"
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
if length == 2 {
return "YES"
}
var prime = true
for i in 2...Int(sqrt(Double(length))) {
if length % i == 0 {
prime = false
break
}
}
return prime ? "YES" : "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
if length == 2 {
return "YES"
}
var prime = true
for i in 2...Int(sqrt(Double(length))) {
if length % i == 0 {
prime = false
break
}
}
return prime ? "YES" : "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
return isPrime(number: end - start + 1) ? "YES" : "NO"
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
var i = 3
while i * i <= number {
if number % i == 0 {
return false
}
i += 2
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
return isPrime(number: end - start + 1) ? "YES" : "NO"
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
var i = 3
while i * i <= number {
if number % i == 0 {
return false
}
i += 2
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
guard start1 <= end1, start2 <= end2 else {
return "NO"
}
guard start1 <= end2, start2 <= end1 else {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
guard start <= end else {
return "NO"
}
let length = end - start + 1
guard isPrime(length) else {
return "NO"
}
return "YES"
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else {
return false
}
var isPrime = true
for i in 2..<number {
if number % i == 0 {
isPrime = false
break
}
}
return isPrime
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
guard start1 <= end1, start2 <= end2 else {
return "NO"
}
guard start1 <= end2, start2 <= end1 else {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
guard start <= end else {
return "NO"
}
let length = end - start + 1
guard isPrime(length) else {
return "NO"
}
return "YES"
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else {
return false
}
var isPrime = true
for i in 2..<number {
if number % i == 0 {
isPrime = false
break
}
}
return isPrime
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval1.1 || interval2.0 > interval2.1 {
return "NO"
}
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
let isPrime = (2...Int(sqrt(Double(length)))).reduce(true) { $0 && length % $1 != 0 }
return isPrime ? "YES" : "NO"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval1.1 || interval2.0 > interval2.1 {
return "NO"
}
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
let isPrime = (2...Int(sqrt(Double(length)))).reduce(true) { $0 && length % $1 != 0 }
return isPrime ? "YES" : "NO"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
let isPrime = (2...Int(sqrt(Double(length)))).reduce(true) { $0 && length % $1 != 0 }
return isPrime ? "YES" : "NO"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
let isPrime = (2...Int(sqrt(Double(length)))).reduce(true) { $0 && length % $1 != 0 }
return isPrime ? "YES" : "NO"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a1, b1) = interval1
let (a2, b2) = interval2
let min = max(a1, a2)
let max = min(b1, b2)
if min > max {
return "NO"
}
let length = max - min + 1
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
if length.isPrime {
return "YES"
}
return "NO"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a1, b1) = interval1
let (a2, b2) = interval2
let min = max(a1, a2)
let max = min(b1, b2)
if min > max {
return "NO"
}
let length = max - min + 1
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
if length.isPrime {
return "YES"
}
return "NO"
}
```let max = min(b1, b2) // cannot call value of non-function type 'Int'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = max(0, intersectionEnd - intersectionStart)
if intersectionLength == 0 {
return "NO"
}
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = max(0, intersectionEnd - intersectionStart)
if intersectionLength == 0 {
return "NO"
}
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end1 || start2 > end2 {
return "NO"
}
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
if isPrime(end - start + 1) {
return "YES"
}
return "NO"
}
func isPrime(_ number: Int) -> Bool {
if number == 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end1 || start2 > end2 {
return "NO"
}
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
if isPrime(end - start + 1) {
return "YES"
}
return "NO"
}
func isPrime(_ number: Int) -> Bool {
if number == 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = max(0, end - start + 1)
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
guard n > 1 else { return false }
guard n > 2 else { return true }
guard n % 2 != 0 else { return false }
for i in 3..<Int(sqrt(Double(n))) {
if n % i == 0 {
return false
}
}
return true
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = max(0, end - start + 1)
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
guard n > 1 else { return false }
guard n > 2 else { return true }
guard n % 2 != 0 else { return false }
for i in 3..<Int(sqrt(Double(n))) {
if n % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end1 || start2 > end2 {
return "NO"
}
let minStart = max(start1, start2)
let maxEnd = min(end1, end2)
if minStart > maxEnd {
return "NO"
}
let length = maxEnd - minStart + 1
if length == 1 {
return "NO"
}
if isPrime(length) {
return "YES"
}
return "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i = i + 6
}
return true
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end1 || start2 > end2 {
return "NO"
}
let minStart = max(start1, start2)
let maxEnd = min(end1, end2)
if minStart > maxEnd {
return "NO"
}
let length = maxEnd - minStart + 1
if length == 1 {
return "NO"
}
if isPrime(length) {
return "YES"
}
return "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i = i + 6
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = max(0, intersectionEnd - intersectionStart)
if intersectionLength == 0 {
return "NO"
}
if isPrime(intersectionLength) {
return "YES"
}
return "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
for i in 5...Int(sqrt(Double(number))) {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
}
return true
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = max(0, intersectionEnd - intersectionStart)
if intersectionLength == 0 {
return "NO"
}
if isPrime(intersectionLength) {
return "YES"
}
return "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
for i in 5...Int(sqrt(Double(number))) {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
}
return true
}
```func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
var prime = true
for i in 2...Int(sqrt(Double(length))) {
if length % i == 0 {
prime = false
break
}
}
return prime ? "YES" : "NO"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
var prime = true
for i in 2...Int(sqrt(Double(length))) {
if length % i == 0 {
prime = false
break
}
}
return prime ? "YES" : "NO"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// write your code here
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// write your code here
}
} // missing return in global function expected to return 'String'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// write your code here
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// write your code here
}
} // missing return in global function expected to return 'String'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// write your code here
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// write your code here
}
} // missing return in global function expected to return 'String'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
}
```
##} // missing return in global function expected to return 'String'### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = intervalXCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scopefunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// write your code here
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// write your code here
}
} // missing return in global function expected to return 'String'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// write your code here
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// write your code here
}
} // missing return in global function expected to return 'String'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// write your code here
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// write your code here
}
} // missing return in global function expected to return 'String'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// write your code here
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// write your code here
}
} // missing return in global function expected to return 'String'### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = intervalXCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) =XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) =XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) =XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) =XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) =XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) =XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) =XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) =XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) =XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) =XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) =XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) =XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.1 < interval2.XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) =XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) =XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) =XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) =XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if b < c || d < a {
return "NO"
}
let l = max(a, c)
let r = min(b, d)
if l > r {
return "NO"
}
let len = r - l + 1
if len == 1 {
return "NO"
}
if len == 2 {
return "YES"
}
if len == 3 {
return "NO"
}
ifXCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scopefunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "YES"
}
if length == 2 {
return "NO"
}
if length % 2 == 0 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "YES"
}
if length == 2 {
return "NO"
}
if length % 2 == 0 {
return "NO"
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let length = min(end1, end2) - max(start1, start2)
if length <= 0 {
return "NO"
}
if length % 2 == 0 && length != 0 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let length = min(end1, end2) - max(start1, start2)
if length <= 0 {
return "NO"
}
if length % 2 == 0 && length != 0 {
return "NO"
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
let l = min(b, d) - max(a, c) + 1
if l < 0 {
return "NO"
}
if l == 0 {
return "NO"
}
if l % 2 == 0 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
let l = min(b, d) - max(a, c) + 1
if l < 0 {
return "NO"
}
if l == 0 {
return "NO"
}
if l % 2 == 0 {
return "NO"
}
return "YES"
}
``` // XCTAssertTrue failed```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let length = end1 - start1
let length2 = end2 - start2
let minLength = min(length, length2)
if minLength == 0 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start
if length % minLength != 0 {
return "NO"
}
if length == minLength {
return "YESXCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scopefunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let length = end1 - start1
let length2 = end2 - start2
let start = min(start1, start2)
let end = max(end1, end2)
let length3 = end - start
if length3 == 0 {
return "NO"
}
if length3 % 2 == 0 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let length = end1 - start1
let length2 = end2 - start2
let start = min(start1, start2)
let end = max(end1, end2)
let length3 = end - start
if length3 == 0 {
return "NO"
}
if length3 % 2 == 0 {
return "NO"
}
return "YES"
}
```let length = end1 - start1 // initialization of immutable value 'length' was never used; consider replacing with assignment to '_' or removing itlet length2 = end2 - start2 // initialization of immutable value 'length2' was never used; consider replacing with assignment to '_' or removing it // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let length = min(end1, end2) - max(start1, start2) + 1
if length < 0 {
return "NO"
}
if length == 0 {
return "NO"
}
if length == 1 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let length = min(end1, end2) - max(start1, start2) + 1
if length < 0 {
return "NO"
}
if length == 0 {
return "NO"
}
if length == 1 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
return "YES"
}
``` // XCTAssertTrue failed```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let length = end1 - start1
let length2 = end2 - start2
let lengthIntersection = min(end1, end2) - max(start1, start2)
if lengthIntersection <= 0 {
return "NO"
}
if lengthIntersection == length || lengthIntersection == length2 {
return "YES"
}
if lengthIntersection == 1 {
return "NO"
}
if lengthIntersection % 2 == XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scopefunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
for iif isPrime(length) { // cannot find 'isPrime' in scopefunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "YES"
}
if length == 0 {
return "NO"
}
if length % 2 == 0 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "YES"
}
if length == 0 {
return "NO"
}
if length % 2 == 0 {
return "NO"
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 0 {
return "NO"
}
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 0 {
return "NO"
}
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}
``````
```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 0 {
return "NO"
}
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 0 {
return "NO"
}
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 0 {
return "NO"
}
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}
``````
```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 0 {
return "NO"
}
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``````swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// determine the intersection of the two intervals
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let intersection = (start, end)
// check if the length of the intersection is a prime number
if intersection.0 > intersection.1 {
return "NO"
}
let length = intersection.1 - intersection.0 + 1
if length <= 1 {
return "NO"
}
if length <= 3 {
return "YES"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
// determine the intersection of the two intervals
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let intersection = (start, end)
// check if the length of the intersection is a prime number
if intersection.0 > intersection.1 {
return "NO"
}
let length = intersection.1 - intersection.0 + 1
if length <= 1 {
return "NO"
}
if length <= 3 {
return "YES"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}
``````python
def intersection(interval1: (int, int), interval2: (int, int)) -> str:
# determine the intersection of the two intervals
start = max(interval1[0], interval2[0])
end = min(interval1[1], interval2[1])
intersection = (start, end)
# check if the length of the intersection is a prime number
if intersection[0] > intersection[1]:
return "NO"
length = intersection[1] - intersection[0] + 1
if length <= 1:
return "NO"
if length <= 3:
return "YES"
is_prime = True
for i in range(2, length):
if length % i == 0:
is_prime = False
break
return "YES" if is_prime else "NO"
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``````swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``````swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``````swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``````swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``````swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``````swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let length = end1 - start1
if length == 0 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start
if length == 0 {
return "NO"
}
if length % 2 == 0 {
let mid = start + length / 2
let midInt = mid / 2
let midInt2 = midInt + 1
let midInt3 = midInt - 1
if midInt2.isPrime && midInt3.isPrime {
return "YES"
}
}
return "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let length = end1 - start1
if length == 0 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start
if length == 0 {
return "NO"
}
if length % 2 == 0 {
let mid = start + length / 2
let midInt = mid / 2
let midInt2 = midInt + 1
let midInt3 = midInt - 1
if midInt2.isPrime && midInt3.isPrime {
return "YES"
}
}
return "NO"
}
```let length = end - start // invalid redeclaration of 'length'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = min(end1, end2) - max(start1, start2) + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ num: Int) -> Bool {
if num == 1 {
return false
}
for i in 2...Int(sqrt(Double(num))) {
if num % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = min(end1, end2) - max(start1, start2) + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ num: Int) -> Bool {
if num == 1 {
return false
}
for i in 2...Int(sqrt(Double(num))) {
if num % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let length = end1 - start1
if length == 0 {
return "NO"
}
let length2 = end2 - start2
if length2 == 0 {
return "NO"
}
let length3 = min(end1, end2) - max(start1, start2)
if length3 < 0 {
return "NO"
}
let length4 = length3 % length
if length4 == 0 {
return "YES"
}
return "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let length = end1 - start1
if length == 0 {
return "NO"
}
let length2 = end2 - start2
if length2 == 0 {
return "NO"
}
let length3 = min(end1, end2) - max(start1, start2)
if length3 < 0 {
return "NO"
}
let length4 = length3 % length
if length4 == 0 {
return "YES"
}
return "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 0 {
return "NO"
}
if length == 1 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 0 {
return "NO"
}
if length == 1 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let length = end1 - start1
let length2 = end2 - start2
if length <= 0 || length2 <= 0 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start
if length <= 0 {
return "NO"
}
if length == 1 {
return "YES"
}
if length == 2 {
return "NO"
}
if length == 3 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let length = end1 - start1
let length2 = end2 - start2
if length <= 0 || length2 <= 0 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start
if length <= 0 {
return "NO"
}
if length == 1 {
return "YES"
}
if length == 2 {
return "NO"
}
if length == 3 {
return "YES"
}
if length % 2 == 0 {
return "NO"
}
return "YES"
}
```let length = end - start // invalid redeclaration of 'length'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ n: Int) -> Bool {
if n == 1 {
return false
}
for i in 2...Int(sqrt(Double(n))) {
if n % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ n: Int) -> Bool {
if n == 1 {
return false
}
for i in 2...Int(sqrt(Double(n))) {
if n % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = min(end1, end2) - max(start1, start2) + 1
if length % 2 == 0 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = min(end1, end2) - max(start1, start2) + 1
if length % 2 == 0 {
return "NO"
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let length = end1 - start1
let length2 = end2 - start2
let start = min(start1, start2)
let end = max(end1, end2)
let length3 = end - start
if length3 < 0 {
return "NO"
}
if length3 == 0 {
return "NO"
}
if length3 == 1 {
return "NO"
}
if length3 % 2 == 0 {
return "NO"
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let length = end1 - start1
let length2 = end2 - start2
let start = min(start1, start2)
let end = max(end1, end2)
let length3 = end - start
if length3 < 0 {
return "NO"
}
if length3 == 0 {
return "NO"
}
if length3 == 1 {
return "NO"
}
if length3 % 2 == 0 {
return "NO"
}
return "YES"
}
```let length = end1 - start1 // initialization of immutable value 'length' was never used; consider replacing with assignment to '_' or removing itlet length2 = end2 - start2 // initialization of immutable value 'length2' was never used; consider replacing with assignment to '_' or removing it // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 0 {
return "NO"
}
if length == 1 {
return "YES"
}
if isPrime(length) {
return "YES"
}
return "NO"
}
func isPrime(_ n: Int) -> Bool {
if n == 1 {
return false
}
for i in 2...Int(sqrt(Double(n))) {
if n % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 0 {
return "NO"
}
if length == 1 {
return "YES"
}
if isPrime(length) {
return "YES"
}
return "NO"
}
func isPrime(_ n: Int) -> Bool {
if n == 1 {
return false
}
for i in 2...Int(sqrt(Double(n))) {
if n % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ n: Int) -> Bool {
if n == 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ n: Int) -> Bool {
if n == 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length1 = end1 - start1 + 1
let length2 = end2 - start2 + 1
let length = max(length1, length2)
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
if length == 3 {
return "YES"
}
let isPrime = isPrime(length)
return isPrime? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length1 = end1 - start1 + 1
let length2 = end2 - start2 + 1
let length = max(length1, length2)
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
if length == 3 {
return "YES"
}
let isPrime = isPrime(length)
return isPrime? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}
print(intersection(interval1: (1, 2), interval2: (2, 3))) // NO
print(intersection(interval1: (-1, 1), interval2: (0, 4))) // NO
print(intersection(interval1: (-3, -1), interval2: (-5, 5))) // YESreturn isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // expected expressionreturn isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // string literal is unusedreturn isPrime? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length1 = end1 - start1 + 1
let length2 = end2 - start2 + 1
if length1 > length2 {
return intersection(interval1: interval2, interval2: interval1)
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
return isPrime(number: length)? "YES" : "NO"
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length1 = end1 - start1 + 1
let length2 = end2 - start2 + 1
if length1 > length2 {
return intersection(interval1: interval2, interval2: interval1)
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
return isPrime(number: length)? "YES" : "NO"
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}
print(intersection(interval1: (1, 2), interval2: (2, 3))) // NO
print(intersection(interval1: (-1, 1), interval2: (0, 4))) // NO
print(intersection(interval1: (-3, -1), interval2: (-5, 5))) // YESreturn isPrime(number: length)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(number: length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(number: length)? "YES" : "NO" // expected expressionreturn isPrime(number: length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(number: length)? "YES" : "NO" // string literal is unusedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length1 = end1 - start1 + 1
let length2 = end2 - start2 + 1
if length1 > length2 {
return isPrime(length1)? "YES" : "NO"
} else {
return isPrime(length2)? "YES" : "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length1 = end1 - start1 + 1
let length2 = end2 - start2 + 1
if length1 > length2 {
return isPrime(length1)? "YES" : "NO"
} else {
return isPrime(length2)? "YES" : "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}
print(intersection(interval1: (1, 2), interval2: (2, 3))) // NO
print(intersection(interval1: (-1, 1), interval2: (0, 4))) // NO
print(intersection(interval1: (-3, -1), interval2: (-5, 5))) // YESreturn isPrime(length1)? "YES" : "NO" // expected expressionreturn isPrime(length1)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(length1)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(length1)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(length1)? "YES" : "NO" // string literal is unusedreturn isPrime(length2)? "YES" : "NO" // string literal is unusedreturn isPrime(length2)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(length2)? "YES" : "NO" // expected expressionreturn isPrime(length2)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(length2)? "YES" : "NO" // consecutive statements on a line must be separated by ';'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = end1 - start1 + end2 - start2
if length <= 1 {
return "NO"
}
if isPrime(length) {
return "YES"
}
return "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = end1 - start1 + end2 - start2
if length <= 1 {
return "NO"
}
if isPrime(length) {
return "YES"
}
return "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}
//print(intersection(interval1: (1, 2), interval2: (2, 3)))
//print(intersection(interval1: (-1, 1), interval2: (0, 4)))
print(intersection(interval1: (-3, -1), interval2: (-5, 5))) // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start2 > end1 || start1 > end2 {
return "NO"
}
let length = end1 - start1 + 1
if length == 0 {
return "NO"
}
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start2 > end1 || start1 > end2 {
return "NO"
}
let length = end1 - start1 + 1
if length == 0 {
return "NO"
}
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}
//print(intersection(interval1: (1, 2), interval2: (2, 3)))
//print(intersection(interval1: (-1, 1), interval2: (0, 4)))
print(intersection(interval1: (-3, -1), interval2: (-5, 5))) // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = end1 - start1 + end2 - start2
if length <= 1 {
return "NO"
}
if isPrime(length) {
return "YES"
}
return "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = end1 - start1 + end2 - start2
if length <= 1 {
return "NO"
}
if isPrime(length) {
return "YES"
}
return "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}
// Test
print(intersection(interval1: (1, 2), interval2: (2, 3))) // NO
print(intersection(interval1: (-1, 1), interval2: (0, 4))) // NO
print(intersection(interval1: (-3, -1), interval2: (-5, 5))) // YES // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start2 > end1 || start1 > end2 {
return "NO"
}
let length = end1 - start1 + 1
if length == 0 {
return "NO"
}
if isPrime(length) {
return "YES"
}
return "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start2 > end1 || start1 > end2 {
return "NO"
}
let length = end1 - start1 + 1
if length == 0 {
return "NO"
}
if isPrime(length) {
return "YES"
}
return "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
//print(intersection(interval1: (1, 2), interval2: (2, 3)))
//print(intersection(interval1: (-1, 1), interval2: (0, 4)))
print(intersection(interval1: (-3, -1), interval2: (-5, 5))) // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = end1 - start1 + end2 - start2
if length <= 1 {
return "NO"
}
if isPrime(length) {
return "YES"
}
return "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = end1 - start1 + end2 - start2
if length <= 1 {
return "NO"
}
if isPrime(length) {
return "YES"
}
return "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
print(intersection(interval1: (1, 2), interval2: (2, 3)))
print(intersection(interval1: (-1, 1), interval2: (0, 4)))
print(intersection(interval1: (-3, -1), interval2: (-5, 5)))
``` // XCTAssertTrue failed```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length1 = end1 - start1 + 1
let length2 = end2 - start2 + 1
let length = max(length1, length2)
if length == 1 {
return "NO"
}
if length == 2 {
return "YES"
}
if length == 3 {
return "YES"
}
if length == 4 {
return "YES"
}
if length == 5 {
return "YES"
}
if length == 6 {
return "YES"
}
if length == 7 {
return "YES"
}
if length == 8 {
return "YES"
}
if length == 9 {
return "YES"
}
if length == 10 {
return "YES"
}
if length == 11 {
return "YES"
}
if length == 12 {
return "YES"
}
if length == 13 {
return "YES"
}
if length == 14 {
return "YES"
}
if length == 15 {
return "YES"
}
if length == 16 {
return "YES"
}
if length == 17 {
return "YES"
}
if length == 18 {
return "YES"
}
if length == 19 {
return "YES"
}
if length == 20 {
return "YES"
}
if length == 21 {
return "YES"
}
if length == 22 {
return "YES"
}
if length == 23 {
return "YES"
}
if length == 24 {
return "YES"
}
if length == 25 {
return "YES"
}
if length == 26 {
return "YES"
}
if length == 27 {
return "YES"
}
if length == 28 {
return "YES"
}
if length == 29 {
return "YES"
}
if length == 30 {
return "YES"
}
if length == 31 {
return "YES"
}
if length == 32 {
return "YES"
}
if length == 33 {
return "YES"
}
if length == 34 {
return "YES"
}
if length == 35 {
return "YES"
}
if length == 36 {
return "YES"
}
if length == 37 {
return "YES"
}
if length == 38 {
return "YES"
}
if length == 39 {
return "YES"
}
if length == 40 {
return "YES"
}
if length == 41 {
return "YES"
}
if length == 42 {
return "YES"
}
if length == 43 {
return "YES"
}
if length == 44 {
return "YES"
}
if length == 45 {
return "YES"
}
if length == 46 {
return "YES"
}
if length == 47 {
return "YES"
}
if length == 48 {
return "YES"
}
if length == 49 {
return "YES"
}
if length == 50 {
return "YES"
}
if length == 51 {
return "YES"
}
if length == 52 {
return "YES"
}
if length == 53 {
return "YES"
}
if length == 54 {
return "YES"
}
if length == 55 {
return "YES"
}
if length == 56 {
return "YES"
}
if length == 57 {
return "YES"
}
if length == 58 {
return "YES"
}
if length == 59 {
return "YES"
}
if length == 60 {
return "YES"
}
if length == 61 {
return "YES"
}
if length == 62 {
return "YES"
}
if length == 63 {
return "YES"
}
if length == XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scopefunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = end1 - start1 + end2 - start2
if length <= 1 {
return "NO"
}
if isPrime(length) {
return "YES"
}
return "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let length = end1 - start1 + end2 - start2
if length <= 1 {
return "NO"
}
if isPrime(length) {
return "YES"
}
return "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...Int(sqrt(Double(number))) {
if number % i == 0 {
return false
}
}
return true
}
print(intersection(interval1: (1, 2), interval2: (2, 3)))
print(intersection(interval1: (-1, 1), interval2: (0, 4)))
print(intersection(interval1: (-3, -1), interval2: (-5, 5)))
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
let intersectionLength = max(interval1.1, interval2.1) - min(interval1.0, interval2.0)
if intersectionLength > 0 && isPrime(intersectionLength) {
return "YES"
}
return "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...(number / 2) {
if number % i == 0 {
return false
}
}
return true
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
let intersectionLength = max(interval1.1, interval2.1) - min(interval1.0, interval2.0)
if intersectionLength > 0 && isPrime(intersectionLength) {
return "YES"
}
return "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...(number / 2) {
if number % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if a > d || b < c {
return "NO"
}
let length = max(b - a, d - c)
if length > 0 {
if length > 1 {
return "NO"
} else {
return "YES"
}
}
return "NO"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
if a > d || b < c {
return "NO"
}
let length = max(b - a, d - c)
if length > 0 {
if length > 1 {
return "NO"
} else {
return "YES"
}
}
return "NO"
}
```
### Time Complexity:
O(1)
### Space Complexity:
O(1)
### Notes:
* The length of the intersection of two intervals is the maximum of the difference between their end points.
* If the length of the intersection is greater than 1, it means that the two intervals do not intersect and the function returns "NO".
* If the two intervals intersect and the length of the intersection is 1, it means that the two intervals are touching and the function returns "YES".
* If the two intervals do not intersect, the function returns "NO".
* The function uses the max() function to find the length of the intersection.
* The function does not use any additional data structures. // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end1 || start2 > end2 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength > 1 {
if intersectionLength == 2 {
return "YES"
}
var isPrime = true
for i in 2...intersectionLength-1 {
if intersectionLength % i == 0 {
isPrime = false
break
}
}
if isPrime {
return "YES"
}
}
return "NO"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end1 || start2 > end2 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength > 1 {
if intersectionLength == 2 {
return "YES"
}
var isPrime = true
for i in 2...intersectionLength-1 {
if intersectionLength % i == 0 {
isPrime = false
break
}
}
if isPrime {
return "YES"
}
}
return "NO"
}
```
### Time Complexity:
O(1)
### Space Complexity:
O(1) // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
let intersectionLength = max(interval1.1, interval2.1) - min(interval1.0, interval2.0)
if intersectionLength > 0 && isPrime(intersectionLength) {
return "YES"
}
return "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...(number / 2) {
if number % i == 0 {
return false
}
}
return true
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.0 > interval2.1 || interval2.0 > interval1.1 {
return "NO"
}
let intersectionLength = max(interval1.1, interval2.1) - min(interval1.0, interval2.0)
if intersectionLength > 0 && isPrime(intersectionLength) {
return "YES"
}
return "NO"
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2...(number / 2) {
if number % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end1 || start2 > end2 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength > 1 {
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
for i in 2...(number / 2) {
if number % i == 0 {
return false
}
}
return true
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end1 || start2 > end2 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength > 1 {
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
} else {
return "NO"
}
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
for i in 2...(number / 2) {
if number % i == 0 {
return false
}
}
return true
}
```
### Time Complexity:
O(1)
### Space Complexity:
O(1) // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.1 < interval2.0 || interval2.1 < interval1.0 {
return "NO"
}
let intersectionLength = max(interval1.1, interval2.1) - min(interval1.0, interval2.0)
if intersectionLength == 0 {
return "NO"
}
if intersectionLength > 1 {
return "NO"
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.1 < interval2.0 || interval2.1 < interval1.0 {
return "NO"
}
let intersectionLength = max(interval1.1, interval2.1) - min(interval1.0, interval2.0)
if intersectionLength == 0 {
return "NO"
}
if intersectionLength > 1 {
return "NO"
}
return "YES"
}
```
### Time Complexity:
O(1)
### Space Complexity:
O(1) // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end1 || start2 > end2 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart == intersectionEnd {
return "YES"
}
var count = 0
for i in intersectionStart..<intersectionEnd {
if i.isPrime() {
count += 1
}
}
if count > 0 {
return "YES"
}
return "NO"
}
extension Int {
func isPrime() -> Bool {
if self <= 1 {
return false
}
for i in 2...sqrt(Double(self)) {
if self % Double(i) == 0.0 {
return false
}
}
return true
}
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end1 || start2 > end2 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart == intersectionEnd {
return "YES"
}
var count = 0
for i in intersectionStart..<intersectionEnd {
if i.isPrime() {
count += 1
}
}
if count > 0 {
return "YES"
}
return "NO"
}
extension Int {
func isPrime() -> Bool {
if self <= 1 {
return false
}
for i in 2...sqrt(Double(self)) {
if self % Double(i) == 0.0 {
return false
}
}
return true
}
}
```
### Time Complexity:
O(n) where n is the length of the intersection
### Space Complexity:
O(1)for i in 2...sqrt(Double(self)) { // cannot convert value of type 'Double?' to expected argument type 'Int'for i in 2...sqrt(Double(self)) { // no exact matches in call to initializerfor i in 2...sqrt(Double(self)) { // global function 'sqrt' requires that 'Double?' conform to 'FloatingPoint'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.1 < interval2.0 || interval2.1 < interval1.0 {
return "NO"
}
let intersectionLength = max(interval1.1, interval2.1) - min(interval1.0, interval2.0)
if intersectionLength > 0 && isPrime(intersectionLength) {
return "YES"
}
return "NO"
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
for i in 2...(number / 2) {
if number % i == 0 {
return false
}
}
return true
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.1 < interval2.0 || interval2.1 < interval1.0 {
return "NO"
}
let intersectionLength = max(interval1.1, interval2.1) - min(interval1.0, interval2.0)
if intersectionLength > 0 && isPrime(intersectionLength) {
return "YES"
}
return "NO"
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
for i in 2...(number / 2) {
if number % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end1 || start2 > end2 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength > 1 {
if isPrime(intersectionLength) {
return "YES"
}
}
return "NO"
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
for i in 2...<number {
if number % i == 0 {
return false
}
}
return true
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end1 || start2 > end2 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength > 1 {
if isPrime(intersectionLength) {
return "YES"
}
}
return "NO"
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
for i in 2...<number {
if number % i == 0 {
return false
}
}
return true
}
```for i in 2...<number { // cannot find operator '...<' in scope; did you mean '..<'?func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.1 < interval2.0 || interval2.1 < interval1.0 {
return "NO"
}
let intersectionLength = max(interval1.1, interval2.1) - min(interval1.0, interval2.0)
if intersectionLength == 0 {
return "NO"
}
if intersectionLength > 1 {
return "NO"
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
if interval1.1 < interval2.0 || interval2.1 < interval1.0 {
return "NO"
}
let intersectionLength = max(interval1.1, interval2.1) - min(interval1.0, interval2.0)
if intersectionLength == 0 {
return "NO"
}
if intersectionLength > 1 {
return "NO"
}
return "YES"
}
```
### Time Complexity:
O(1)
### Space Complexity:
O(1) // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
let min = max(a, c)
let max = min(b, d)
if min > max {
return "NO"
}
let len = max - min
if len == 0 {
return "NO"
}
for i in 2...len {
if len % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
let min = max(a, c)
let max = min(b, d)
if min > max {
return "NO"
}
let len = max - min
if len == 0 {
return "NO"
}
for i in 2...len {
if len % i == 0 {
return "NO"
}
}
return "YES"
}
// -----------------------------------------------------------------------------
// Task description
// -----------------------------------------------------------------------------
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two .
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
let min = max(a, c)
let max = min(b, d)
if min > max {
return "NO"
}
let len = max - min
if len == 0 {
return "NO"
}
for i in 2...len {
if len % i == 0 {
return "NO"
}
}
return "YES"
}<|endoftext|>// -----------------------------------------------------------------------------
// Task description
// -----------------------------------------------------------------------------
// You are given a string of words. You need to find the word "Nemo",
// and return a string like this: "I found Nemo at [the order of the word you find nemo]!".
// If you can't find Nemo, return "I can't find Nemo :(".
// Example
// findNemo("I am finding Nemo !") should return "I found Nemo at 4!".
// findNemo("Nemo is me") should return "I found Nemo at 1!".
// findNemo("I Nemo am") should return "I found Nemo at 2!".
// findNemo("") should return "I can't find Nemo :(".
// findNemo("I am finding Nemo !") should return "I found Nemo at 4!".
// findNemo("Nemo is me") should return "I found Nemo at 1!".
// findNemo("I Nemo am") should return "I found Nemo at 2!".
// findNemo("") should return "I can't find Nemo :(".
// findNemo("I am finding Nemo !") should return "I found Nemo at 4!".
// findNemo("Nemo is me") should return "I found Nemo at 1!".
// findNlet max = min(b, d) // cannot call value of non-function type 'Int'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a1, b1) = interval1
let (a2, b2) = interval2
let a = max(a1, a2)
let b = min(b1, b2)
if a > b {
return "NO"
}
let len = b - a
if len < 0 {
return "NO"
}
let isPrime = true
for i in 2...len {
if len % i == 0 {
isPrime = false
break
}
}
if isPrime {
return "YES"
}
return "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a1, b1) = interval1
let (a2, b2) = interval2
let a = max(a1, a2)
let b = min(b1, b2)
if a > b {
return "NO"
}
let len = b - a
if len < 0 {
return "NO"
}
let isPrime = true
for i in 2...len {
if len % i == 0 {
isPrime = false
break
}
}
if isPrime {
return "YES"
}
return "NO"
}
// -----------------------------------------------------------------------------
// 1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.isPrime = false // cannot assign to value: 'isPrime' is a 'let' constantfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start
if length <= 0 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
func isPalindrome(s: String) -> Bool {
return s == String(s.reversed())
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start
if length <= 0 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
// -----------------------------------------------------------------------------
// [task description]
// -----------------------------------------------------------------------------
// You are given a string s.
// Your task is to check if the string is palindrome or not.
// A string is said to be palindrome if it is equal to itself when reversed.
// Example:
// s = "abba"
// The string is a palindrome.
// s = "abc"
// The string is not a palindrome.
// [input/output] samples:
// isPalindrome("abba") == true
// isPalindrome("abc") == false
func isPalindrome(s: String) -> Bool {
return s == String(s.reversed())
}
// -----------------------------------------------------------------------------
// [task description]
// -----------------------------------------------------------------------------
// You are given a string s.
// Your task is to check if the string is palindrome or not.
// A string is said to be palindrome if it is equal to itself when reversed.
// Example:
// s = "abba"
// The string is a palindrome.
// s = "abc"
// The string is not a palindrome.
// [input/output] samples:
// isPalindrome("abba") == true
// isPalindrome("abc") == false
func isPalindrome(s: String) -> Bool {
return s == String(s.reversed())
}
// -----------------------------------------------------------------------------
// [task description]
// -----------------------------------------------------------------------------
// You are given a string s.
// Your task is to check if the string is palindrome or not.
// A string is said to be palindrome if it is equal to itself when reversed.
// Example:
// s = "abba"
// The string is a palindrome.
// s = "abc"
// The string is not a palindrome.
// [input/output] samples:
// isPalindrome("abba") == true
// isPalindrome("abc") == false
func isPalindrome(s: String) -> Bool {
return s == String(s.reversed())
}
// -----------------------------------------------------------------------------
// [task description]
// -----------------------------------------------------------------------------
// You are given a string s.
// Your task is to check if the string is palindrome or not.
// A string is said to be palindrome if it is equal to itself when reversed.
// Example:
// s = "abba"
// The string is a palindrome.
// s = "abc"
// The string is not a palindrome.
// [input/output] samples:
// isPalindrome("abba") == true
// isPalindrome("abc") == false
func isPalindrome(s: String) -> Bool {
return s == String(s.reversed())
}
// -----------------------------------------------------------------------------
// [task description]
// ------ // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start
if length < 0 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start
if length < 0 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
// -----------------------------------------------------------------------------
// Task description
// -----------------------------------------------------------------------------
//
// You are given a string of words. You need to find the word "Nemo",
// and return a string like this: "I found Nemo at [the order of the word he appears]!".
// If you can't find Nemo, return "I can't find Nemo :(".
//
// Example
//
// findNemo("I am finding Nemo !") should return "I found Nemo at 4!".
// findNemo("I am findNemo !") should return "I found Nemo at 1!".
// findNemo("I am FindNemo !") should return "I found Nemo at 1!".
// findNemo("I am FindNemo !") should return "I found Nemo at 1!".
// findNemo("I am findNemo !") should return "I found Nemo at 1!".
// findNemo("I am find nemo !") should return "I found Nemo at 1!".
// findNemo("I am Find nemo !") should return "I found Nemo at 1!".
// findNemo("I am Find nemo !") should return "I found Nemo at 1!".
// findNemo("I am Find nemo !") should return "I found Nemo at 1!".
// findNemo("I am Find nemo !") should return "I found Nemo at 1!".
// findNemo("I am Find nemo !") should return "I found Nemo at 1!".
// findNemo("I am Find nemo !") should return "I found Nemo at 1!".
// findNemo("I am Find nemo !") should return "I found Nemo at 1!".
// findNemo("I am Find nemo !") should return "I found Nemo at 1!".
// findNemo("I am Find nemo !") should return "I found Nemo at 1!".
// findNemo("I am Find nemo !") should return "I found Nemo at 1!".
// findNemo("I am Find nemo !") should return "I found Nemo at 1!".
// findNemo("I am Find nemo !") should return "I found Nemo at 1!".
// findNemo("I am Find nemo !") should return "I found Nemo at 1!".
// findNemo("I am Find nemo !") should return "I found Nemo at 1!".
// findNemo("I am Find nemo !") should return "I found Nemo at 1!".
// findNemo("I am Find nemo !") should return "I found Nemo at 1!".
// findNemo("I am Find nemo !") should return "I found Nemo at 1!".
// findNemo("I am Find nemo !") should return "I found Nemo at 1!".
// findNemo("I am Find nemo !") should return "I found Nemo at 1!".
// findNemo("I am Find nemo !") should return "I found // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start
if length <= 0 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start
if length <= 0 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
// -----------------------------------------------------------------------------
// Task description
// -----------------------------------------------------------------------------
// You are given a string.
// Your task is to check if the string is palindrome or not.
// A string is said to be a palindrome if it is same after reverse.
// Example
// For inputString = "abcdba", the output should be
// isPalindrome(inputString) = true;
// For inputString = "abcbade", the output should be
// isPalindrome(inputString) = false.
// Input/Output
// [input] string inputString
// A string consisting of lowercase latin letters.
// Guaranteed constraints:
// 3 ≤ inputString.length ≤ 10.
// [output] boolean
// true if inputString is a palindrome, false otherwise.
// -----------------------------------------------------------------------------
// Solution
// -----------------------------------------------------------------------------
// You can use the built-in function `reverse` to reverse a string.
// -----------------------------------------------------------------------------
// [input] string inputString
// A string consisting of lowercase latin letters.
// Guaranteed constraints:
// 3 ≤ inputString.length ≤ 10.
// [output] boolean
// true if inputString is a palindrome, false otherwise.
// -----------------------------------------------------------------------------
// [input] string inputString
// A string consisting of lowercase latin letters.
// Guaranteed constraints:
// 3 ≤ inputString.length ≤ 10.
// [output] boolean
// true if inputString is a palindrome, false otherwise.
// -----------------------------------------------------------------------------
// [input] string inputString
// A string consisting of lowercase latin letters.
// Guaranteed constraints:
// 3 ≤ inputString.length ≤ 10.
// [output] boolean
// true if inputString is a palindrome, false otherwise.
// -----------------------------------------------------------------------------
// [input] string inputString
// A string consisting of lowercase latin letters.
// Guaranteed constraints:
// 3 ≤ inputString.length ≤ 10.
// [output] boolean
// true if inputString is a palindrome, false otherwise.
// -----------------------------------------------------------------------------
// [input] string inputString
// A string consisting of lowercase latin letters.
// Guaranteed constraints:
// 3 ≤ inputString.length ≤ 10.
// [output] boolean
// true if inputString is a palindrome, false otherwise.
// -----------------------------------------------------------------------------
// [input] string inputString
// A string consisting of lowercase latin letters.
// Guaranteed constraints:
// 3 ≤ inputString.length ≤ 10.
// [output] boolean
// true if inputString is a palindrome, false otherwise.
// -----------------------------------------------------------------------------
// [input] string inputString
// Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
func reverseString(s: String) -> String {
return String(s.reversed())
}
func capitalizeEven(s: String) -> String {
var result = ""
for i in 0..<s.length {
let c = s[i]
if i % 2 == 0 {
result += c.uppercaseString
} else {
result += c.lowercaseString
}
}
return result
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
// -----------------------------------------------------------------------------
// 10. Write a function that takes a string as input and returns the string reversed.
// Example:
// Given s = "hello", return "olleh".
// [input/output] samples:
// reverseString("hello") == "olleh"
// reverseString("") == ""
// reverseString("h") == "h"
// reverseString("a") == "a"
// reverseString("ab") == "ba"
// reverseString("abc") == "cba"
// reverseString("abcd") == "dcba"
// reverseString("abcde") == "edcba"
// reverseString("abcdefg") == "gfedcba"
// reverseString("abcdefghijklmnopqrstuvwxyz") == "zyxwvutsrqponmlkjihgfedcba"
func reverseString(s: String) -> String {
return String(s.reversed())
}
// -----------------------------------------------------------------------------
// 11. Write a function that takes a string as input and returns the string with
// all the even characters capitalized and all the odd characters small.
// Example:
// Given s = "abcdefg", return "abCedg".
// [input/output] samples:
// capitalizeEven("abcdefg") == "abCedg"
// capitalizeEven("") == ""
// capitalizeEven("a") == "a"
// capitalizeEven("ab") == "Ab"
// capitalizeEven("abc") == "AbC"
// capitalizeEven("abcd") == "AbCd"
// capitalizeEven("abcde") == "AbCdE"
// capitalizeEven("abcdefg") == "AbCedg"
// capitalizeEven("abcdefghijklmnopqrstuvwxyz") == "AbCedgHijklmnopqrstuvwxyz"
func capitalizeEven(s: String) -> String {
var result = ""
for i in 0..<s.length {
let c = s[i]
if i % 2 == 0 {
result += c.uppercaseString
} else {
result += c.lowercaseString
}
}
return result
}
// -----------------------------------------------------------------------------
// 12. Write a function that takes a string as input and returns the string with
// all the even characters capitalized and all the odd characters small.
// Example:
// Given s = "abcdefg", return "abCedg".
// [input/output] samples:
// capitalizeEven("abcdefg") == "abCedg"
// capitalizeEven("") == ""
// capitalizeEven("a") == "a"
// capitalizeEven("ab") == "Ab"
// capitalizeEven("abc") == "AbC"
// capitalizeEven("abcd") == "AbCd"
// capitalizeEven("abcde") == "AbCdE"
// capitalizeEven("abcdefg") == "AbCedg"
// capitalizeEven("abcdefghijklmnopqrstuvwxyz") == "AbCedgHijklmnopqrstuvwxyz"
func capitalizeEven(s: String) -> String {
var result = ""
for i in 0..for i in 0..<s.length { // value of type 'String' has no member 'length'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
let min = max(a, c)
let max = min(b, d)
let length = max - min
if length <= 0 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a, b) = interval1
let (c, d) = interval2
let min = max(a, c)
let max = min(b, d)
let length = max - min
if length <= 0 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
// -----------------------------------------------------------------------------
// 10. Write a function that takes a string as input and returns the string reversed.
// Example:
// Given s = "hello", return "olleh".
// [input/output] samples:
// reverseString("hello") == "olleh"
// reverseString("12345") == "54321"
// reverseString("") == ""
// reverseString("h") == "h"
// reverseString("ha") == "ah"
// reverseString("hello world") == "dlrow olleh"
// reverseString("123456789") == "987654321"
// reverseString("1234567890") == "0987654321"
// reverseString("12345678901") == "10987654321"
// reverseString("123456789012") == "210987654321"
// reverseString("1234567890123") == "3210987654321"
// reverseString("12345678901234") == "43210987654321"
// reverseString("123456789012345") == "543210987654321"
// reverseString("1234567890123456") == "6543210987654321"
// reverseString("12345678901234567")
// reverseString("123456789012345678")
// reverseString("1234567890123456789")
// reverseString("12345678901234567890")
// reverseString("123456789012345678901")
// reverseString("1234567890123456789012")
// reverseString("12345678901234567890123")
// reverseString("123456789012345678901234")
// reverseString("1234567890123456789012345")
// reverseString("12345678901234567890123456")
// reverseString("123456789012345678901234567")
// reverseString("1234567890123456789012345678")
// reverseString("12345678901234567890123456789")
// reverseString("123456789012345678901234567890")
// reverseString("1234567let max = min(b, d) // cannot call value of non-function type 'Int'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start
if length <= 0 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
func reverseString(s: String) -> String {
return String(s.reversed())
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start
if length <= 0 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
// -----------------------------------------------------------------------------
// 10. Write a function that takes a string as input and returns the string reversed.
// Example:
// Given s = "hello", return "olleh".
// [input/output] samples:
// reverseString("hello") == "olleh"
// reverseString("") == ""
// reverseString("h") == "h"
// reverseString("a") == "a"
// reverseString("a b c") == "c b a"
// reverseString("a b c d e f g h i j k l m n o p q r s t u v w x y z") == "z y x w v u t s r q p o n m l k j i h g f e d c b a"
func reverseString(s: String) -> String {
return String(s.reversed())
}
// -----------------------------------------------------------------------------
// 11. Write a function that takes an integer as input, and returns the number of bits that are equal to one in the binary representation of that number.
// Example:
// The binary representation of 5 is 101 (in base-10), so the return value should be 2.
// Note:
// Note that in some languages such as Java, there is no unsigned integer type.
// In this case, the input will be given as a signed integer type.
// It should not affect your implementation, as the integer's internal binary representation is the same, whether it is signed or unsigned.
// [input/output] samples:
// countBits(5) == 2
// countBits(0) == 0
// countBits(1) == 1
// countBits(2) == 1
// countBits(3) == 2
// countBits(4) == 1
// countBits(5) == 2
// countBits(6) == 2
// countBits(7) == 3
// countBits(8) == 1
// countBits(9) == 2
// countBits(10) == 2
// countBits(11) == 3
// countBits(12) == 2
// countBits(13) == 3
// countBits(14) == 3
// countBits(15) == 4
// countBits(16) == 1
// countBits(17) == 2
// countBits(18) == 2
// countBits(19) == 3
// countBits(20) == 2
// countBits(21) == 3
// countBits(22) == 3
// countBits(23) == 4
// countBits(24) == 1
// countBits(25) == 2
// countBits(26) == 2
// countBits(27) == 3
// countBits(28) == 3
// countBits(29) == 4
// countBits(30) == 1
// countBits(31) == 2
// countBits(32) == 1
// countBits(33) == 2
// countBits(34) == 2
// countBits(35) == 3
// countBits(36) == 2
// countBits(37) == 3
// countBits(38) == 3
// countBits(39) == 4
// countBits(40) == 1
// countBits(41) == 2
// countBits(42) == 2
// countBits(43) == 3
// countBits(44) == // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a1, b1) = interval1
let (a2, b2) = interval2
let a = max(a1, a2)
let b = min(b1, b2)
if a > b {
return "NO"
}
let len = b - a
if len < 0 {
return "NO"
}
var isPrime = true
for i in 2...len {
if len % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (a1, b1) = interval1
let (a2, b2) = interval2
let a = max(a1, a2)
let b = min(b1, b2)
if a > b {
return "NO"
}
let len = b - a
if len < 0 {
return "NO"
}
var isPrime = true
for i in 2...len {
if len % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}
// -----------------------------------------------------------------------------
// -----------------------------------------------------------------------------
// -----------------------------------------------------------------------------
// -----------------------------------------------------------------------------
// -----------------------------------------------------------------------------
// -----------------------------------------------------------------------------
// -----------------------------------------------------------------------------
// -----------------------------------------------------------------------------
// -----------------------------------------------------------------------------
// -----------------------------------------------------------------------------
// -----------------------------------------------------------------------------
// -----------------------------------------------------------------------------
// -----------------------------------------------------------------------------
// -----------------------------------------------------------------------------
// -----------------------------------------------------------------------------
// -----------------------------------------------------------------------------
// -----------------------------------------------------------------------------
// -----------------------------------------------------------------------------
// -----------------------------------------------------------------------------
// -----------------------------------------------------------------------------
// -----------------------------------------------------------------------------
// -----------------------------------------------------------------------------
// -----------------------------------------------------------------------------
// -----------------------------------------------------------------------------
// -----------------------------------------------------------------------------
// -----------------------------------------------------------------------------
// -----------------------------------------------------------------------------
// -----------------------------------------------------------------------------
// -----------------------------------------------------------------------------
// --------------------------------------------------------------------- // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start
if length <= 0 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start
if length <= 0 {
return "NO"
}
for i in 2...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
// -----------------------------------------------------------------------------
// 1.2.1.3.1.2.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1.1. // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in length...2 {
if length % i == 0 {
return "NO"
}
}
return "YES"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in length...2 {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in stride(from: 2, through: length, by: 1) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in stride(from: 2, through: length, by: 1) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in length...2 {
if length % i == 0 {
return "NO"
}
}
return "YES"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in length...2 {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in length - 1...2 {
if length % i == 0 {
return "NO"
}
}
return "YES"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in length - 1...2 {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in length - 1...2 {
if length % i == 0 {
return "NO"
}
}
return "YES"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in length - 1...2 {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in stride(from: 2, through: length, by: 1) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in stride(from: 2, through: length, by: 1) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in length - 1...2 {
if length % i == 0 {
return "NO"
}
}
return "YES"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in length - 1...2 {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime ? "YES" : "NO"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in start...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in start...length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Division by zero in remainder operationfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else { return "NO" }
let length = end - start + 1
if length < 2 { return "NO" }
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else { return "NO" }
let length = end - start + 1
if length < 2 { return "NO" }
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else { return "NO" }
let length = end - start + 1
if length < 2 { return "NO" }
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else { return "NO" }
let length = end - start + 1
if length < 2 { return "NO" }
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let intersectionLength = end - start + 1
if intersectionLength <= 0 {
return "NO"
}
if isPrime(number: intersectionLength) {
return "YES"
}
return "NO"
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let intersectionLength = end - start + 1
if intersectionLength <= 0 {
return "NO"
}
if isPrime(number: intersectionLength) {
return "YES"
}
return "NO"
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failed```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length <= 0 {
return "NO"
}
if length == 1 {
return "NO"
}
if length == 2 {
return "NO"
}
if length == 3 {
return "NO"
}
if length == 4 {
return "NO"
}
if length == 5 {
return "NO"
}
if length == 6 {
return "NO"
}
if length == 7 {
return "NO"
}
if length == 8 {
return "NO"
}
if length == 9 {
return "NO"
}
if length == 10 {
return "NO"
}
if length == 11 {
return "NO"
}
if length == 12 {
return "NO"
}
if length == 13 {
return "NO"
}
if length == 14 {
return "NO"
}
if length == 15 {
return "NO"
}
if length == 16 {
return "NO"
}
if length == 17 {
return "NO"
}
if length == 18 {
return "NO"
}
if length == 19 {
return "NO"
}
if length == 20 {
return "NO"
}
if length == 21 {
return "NO"
}
if length == 22 {
return "NO"
}
if length == 23 {
return "NO"
}
if length == 24 {
return "NO"
}
if length == 25 {
return "NO"
}
if length == 26 {
return "NO"
}
if length == 27 {
return "NO"
}
if length == 28 {
return "NO"
}
if length == 29 {
return "NO"
}
if length == 30 {
return "NO"
}
if length == 31 {
return "NO"
}
if length == 32 {
return "NO"
}
if length == 33 {
return "NO"
}
if length == 34 {
return "NO"
}
if length == 35 {
return "NO"
}
if length == 36 {
return "NO"
}
if length == 37 {
return "NO"
}
if length == 38 {
return "NO"
}
if length == 39 {
return "NO"
}
if length == 40 {
return "NO"
}
if length == 41 {
return "NO"
}
if length == 42 {
return "NO"
}
if length == 43 {
return "NO"
}
if length == 44 {
return "NO"
}
if length == 45 {
return "NO"
}
if length == 46 {
return "NO"
}
if length == 47 {
return "NO"
}
if length == 48 {
return "NO"
}
if length == 49 {
return "NO"
}
if length == 50 {
return "NO"
}
if length == 51 {
return "NO"
}
if length == 52 {
return "NO"
}
if length == 53 {
return "NO"
}
if length == 54 {
return "NO"
}
if length == 55 {
return "NO"
}
if length == 56 {
return "NO"
}
if length == 57 {
return "NO"
}
if length == 58 {
return "NO"
}
if length == 59 {
return "NO"
}
if length == 60 {
return "NO"
}
if length == 61 {
return "NO"
}
if length == 62 {
return "NO"
}
if length == 63 {
return "NO"
}
if length == 64 {
return "NO"
}
if length == 65 {
return "NO"
}
if length == XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length <= 0 {
return "NO"
}
if length == 1 {
return "YES"
}
if length == 2 {
return "YES"
}
if length == 3 {
return "YES"
}
if length == 4 {
return "YES"
}
if length == 5 {
return "YES"
}
if length == 6 {
return "YES"
}
if length == 7 {
return "YES"
}
if length == 8 {
return "YES"
}
if length == 9 {
return "YES"
}
if length == 10 {
return "YES"
}
if length == 11 {
return "YES"
}
if length == 12 {
return "YES"
}
if length == 13 {
return "YES"
}
if length == 14 {
return "YES"
}
if length == 15 {
return "YES"
}
if length == 16 {
return "YES"
}
if length == 17 {
return "YES"
}
if length == 18 {
return "YES"
}
if length == 19 {
return "YES"
}
if length == 20 {
return "YES"
}
if length == 21 {
return "YES"
}
if length == 22 {
return "YES"
}
if length == 23 {
return "YES"
}
if length == 24 {
return "YES"
}
if length == 25 {
return "YES"
}
if length == 26 {
return "YES"
}
if length == 27 {
return "YES"
}
if length == 28 {
return "YES"
}
if length == 29 {
return "YES"
}
if length == 30 {
return "YES"
}
if length == 31 {
return "YES"
}
if length == 32 {
return "YES"
}
if length == 33 {
return "YES"
}
if length == 34 {
return "YES"
}
if length == 35 {
return "YES"
}
if length == 36 {
return "YES"
}
if length == 37 {
return "YES"
}
if length == 38 {
return "YES"
}
if length == 39 {
return "YES"
}
if length == 40 {
return "YES"
}
if length == 41 {
return "YES"
}
if length == 42 {
return "YES"
}
if length == 43 {
return "YES"
}
if length == 44 {
return "YES"
}
if length == 45 {
return "YES"
}
if length == 46 {
return "YES"
}
if length == 47 {
return "YES"
}
if length == 48 {
return "YES"
}
if length == 49 {
return "YES"
}
if length == 50 {
return "YES"
}
if length == 51 {
return "YES"
}
if length == 52 {
return "YES"
}
if length == 53 {
return "YES"
}
if length == 54 {
return "YES"
}
if length == 55 {
return "YES"
}
if length == 56 {
return "YES"
}
if length == 57 {
return "YES"
}
if length == 58 {
return "YES"
}
if length == 59 {
return "YES"
}
if length == 60 {
return "YES"
}
if length == 61 {
return "YES"
}
if length == 62 {
return "YES"
}
if length == 63 {
return "YES"
}
if length == 64 {
return "YES"
}
if length == 65 {
return "YES"
}
if length == XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length <= 0 {
return "NO"
}
if length == 1 {
return "NO"
}
if length == 2 {
return "NO"
}
if length == 3 {
return "NO"
}
if length == 4 {
return "NO"
}
if length == 5 {
return "NO"
}
if length == 6 {
return "NO"
}
if length == 7 {
return "NO"
}
if length == 8 {
return "NO"
}
if length == 9 {
return "NO"
}
if length == 10 {
return "NO"
}
if length == 11 {
return "NO"
}
if length == 12 {
return "NO"
}
if length == 13 {
return "NO"
}
if length == 14 {
return "NO"
}
if length == 15 {
return "NO"
}
if length == 16 {
return "NO"
}
if length == 17 {
return "NO"
}
if length == 18 {
return "NO"
}
if length == 19 {
return "NO"
}
if length == 20 {
return "NO"
}
if length == 21 {
return "NO"
}
if length == 22 {
return "NO"
}
if length == 23 {
return "NO"
}
if length == 24 {
return "NO"
}
if length == 25 {
return "NO"
}
if length == 26 {
return "NO"
}
if length == 27 {
return "NO"
}
if length == 28 {
return "NO"
}
if length == 29 {
return "NO"
}
if length == 30 {
return "NO"
}
if length == 31 {
return "NO"
}
if length == 32 {
return "NO"
}
if length == 33 {
return "NO"
}
if length == 34 {
return "NO"
}
if length == 35 {
return "NO"
}
if length == 36 {
return "NO"
}
if length == 37 {
return "NO"
}
if length == 38 {
return "NO"
}
if length == 39 {
return "NO"
}
if length == 40 {
return "NO"
}
if length == 41 {
return "NO"
}
if length == 42 {
return "NO"
}
if length == 43 {
return "NO"
}
if length == 44 {
return "NO"
}
if length == 45 {
return "NO"
}
if length == 46 {
return "NO"
}
if length == 47 {
return "NO"
}
if length == 48 {
return "NO"
}
if length == 49 {
return "NO"
}
if length == 50 {
return "NO"
}
if length == 51 {
return "NO"
}
if length == 52 {
return "NO"
}
if length == 53 {
return "NO"
}
if length == 54 {
return "NO"
}
if length == 55 {
return "NO"
}
if length == 56 {
return "NO"
}
if length == 57 {
return "NO"
}
if length == 58 {
return "NO"
}
if length == 59 {
return "NO"
}
if length == 60 {
return "NO"
}
if length == 61 {
return "NO"
}
if length == 62 {
return "NO"
}
if length == 63 {
return "NO"
}
if length == 64 {
return "NO"
}
if length == 65 {
return "NO"
}
if length == XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length <= 0 {
return "NO"
}
if length == 1 {
return "NO"
}
if length == 2 {
return "NO"
}
if length == 3 {
return "NO"
}
if length == 4 {
return "NO"
}
if length == 5 {
return "NO"
}
if length == 6 {
return "NO"
}
if length == 7 {
return "NO"
}
if length == 8 {
return "NO"
}
if length == 9 {
return "NO"
}
if length == 10 {
return "NO"
}
if length == 11 {
return "NO"
}
if length == 12 {
return "NO"
}
if length == 13 {
return "NO"
}
if length == 14 {
return "NO"
}
if length == 15 {
return "NO"
}
if length == 16 {
return "NO"
}
if length == 17 {
return "NO"
}
if length == 18 {
return "NO"
}
if length == 19 {
return "NO"
}
if length == 20 {
return "NO"
}
if length == 21 {
return "NO"
}
if length == 22 {
return "NO"
}
if length == 23 {
return "NO"
}
if length == 24 {
return "NO"
}
if length == 25 {
return "NO"
}
if length == 26 {
return "NO"
}
if length == 27 {
return "NO"
}
if length == 28 {
return "NO"
}
if length == 29 {
return "NO"
}
if length == 30 {
return "NO"
}
if length == 31 {
return "NO"
}
if length == 32 {
return "NO"
}
if length == 33 {
return "NO"
}
if length == 34 {
return "NO"
}
if length == 35 {
return "NO"
}
if length == 36 {
return "NO"
}
if length == 37 {
return "NO"
}
if length == 38 {
return "NO"
}
if length == 39 {
return "NO"
}
if length == 40 {
return "NO"
}
if length == 41 {
return "NO"
}
if length == 42 {
return "NO"
}
if length == 43 {
return "NO"
}
if length == 44 {
return "NO"
}
if length == 45 {
return "NO"
}
if length == 46 {
return "NO"
}
if length == 47 {
return "NO"
}
if length == 48 {
return "NO"
}
if length == 49 {
return "NO"
}
if length == 50 {
return "NO"
}
if length == 51 {
return "NO"
}
if length == 52 {
return "NO"
}
if length == 53 {
return "NO"
}
if length == 54 {
return "NO"
}
if length == 55 {
return "NO"
}
if length == 56 {
return "NO"
}
if length == 57 {
return "NO"
}
if length == 58 {
return "NO"
}
if length == 59 {
return "NO"
}
if length == 60 {
return "NO"
}
if length == 61 {
return "NO"
}
if length == 62 {
return "NO"
}
if length == 63 {
return "NO"
}
if length == 64 {
return "NO"
}
if length == 65 {
return "NO"
}
if length == XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length <= 0 {
return "NO"
}
if length == 1 {
return "NO"
}
if length == 2 {
return "NO"
}
if length == 3 {
return "NO"
}
if length == 4 {
return "NO"
}
if length == 5 {
return "NO"
}
if length == 6 {
return "NO"
}
if length == 7 {
return "NO"
}
if length == 8 {
return "NO"
}
if length == 9 {
return "NO"
}
if length == 10 {
return "NO"
}
if length == 11 {
return "NO"
}
if length == 12 {
return "NO"
}
if length == 13 {
return "NO"
}
if length == 14 {
return "NO"
}
if length == 15 {
return "NO"
}
if length == 16 {
return "NO"
}
if length == 17 {
return "NO"
}
if length == 18 {
return "NO"
}
if length == 19 {
return "NO"
}
if length == 20 {
return "NO"
}
if length == 21 {
return "NO"
}
if length == 22 {
return "NO"
}
if length == 23 {
return "NO"
}
if length == 24 {
return "NO"
}
if length == 25 {
return "NO"
}
if length == 26 {
return "NO"
}
if length == 27 {
return "NO"
}
if length == 28 {
return "NO"
}
if length == 29 {
return "NO"
}
if length == 30 {
return "NO"
}
if length == 31 {
return "NO"
}
if length == 32 {
return "NO"
}
if length == 33 {
return "NO"
}
if length == 34 {
return "NO"
}
if length == 35 {
return "NO"
}
if length == 36 {
return "NO"
}
if length == 37 {
return "NO"
}
if length == 38 {
return "NO"
}
if length == 39 {
return "NO"
}
if length == 40 {
return "NO"
}
if length == 41 {
return "NO"
}
if length == 42 {
return "NO"
}
if length == 43 {
return "NO"
}
if length == 44 {
return "NO"
}
if length == 45 {
return "NO"
}
if length == 46 {
return "NO"
}
if length == 47 {
return "NO"
}
if length == 48 {
return "NO"
}
if length == 49 {
return "NO"
}
if length == 50 {
return "NO"
}
if length == 51 {
return "NO"
}
if length == 52 {
return "NO"
}
if length == 53 {
return "NO"
}
if length == 54 {
return "NO"
}
if length == 55 {
return "NO"
}
if length == 56 {
return "NO"
}
if length == 57 {
return "NO"
}
if length == 58 {
return "NO"
}
if length == 59 {
return "NO"
}
if length == 60 {
return "NO"
}
if length == 61 {
return "NO"
}
if length == 62 {
return "NO"
}
if length == 63 {
return "NO"
}
if length == 64 {
return "NO"
}
if length == 65 {
return "NO"
}
if length == XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let intersectionLength = end - start
if intersectionLength <= 0 {
return "NO"
}
if intersectionLength == 1 {
return "NO"
}
if intersectionLength == 2 {
return "NO"
}
if intersectionLength == 3 {
return "NO"
}
if intersectionLength == 4 {
return "NO"
}
if intersectionLength == 5 {
return "NO"
}
if intersectionLength == 6 {
return "NO"
}
if intersectionLength == 7 {
return "NO"
}
if intersectionLength == 8 {
return "NO"
}
if intersectionLength == 9 {
return "NO"
}
if intersectionLength == 10 {
return "NO"
}
if intersectionLength == 11 {
return "NO"
}
if intersectionLength == 12 {
return "NO"
}
if intersectionLength == 13 {
return "NO"
}
if intersectionLength == 14 {
return "NO"
}
if intersectionLength == 15 {
return "NO"
}
if intersectionLength == 16 {
return "NO"
}
if intersectionLength == 17 {
return "NO"
}
if intersectionLength == 18 {
return "NO"
}
if intersectionLength == 19 {
return "NO"
}
if intersectionLength == 20 {
return "NO"
}
if intersectionLength == 21 {
return "NO"
}
if intersectionLength == 22 {
return "NO"
}
if intersectionLength == 23 {
return "NO"
}
if intersectionLength == 24 {
return "NO"
}
if intersectionLength == 25 {
return "NO"
}
if intersectionLength == 26 {
return "NO"
}
if intersectionLength == 27 {
return "NO"
}
if intersectionLength == 28 {
return "NO"
}
if intersectionLength == 29 {
return "NO"
}
if intersectionLength == 30 {
return "NO"
}
if intersectionLength == 31 {
return "NO"
}
if intersectionLength == 32 {
return "NO"
}
if intersectionLength == 33 {
return "NO"
}
if intersectionLength == 34 {
return "NO"
}
if intersectionLength == 35 {
return "NO"
}
if intersectionLength == 36 {
return "NO"
}
if intersectionLength == 37 {
return "NO"
}
if intersectionLength == 38 {
return "NO"
}
if intersectionLength == 39 {
return "NO"
}
if intersectionLength == 40 {
return "NO"
}
if intersectionLength == 41 {
return "NO"
}
if intersectionLength == 42 {
return "NO"
}
if intersectionLength == 43 {
return "NO"
}
if intersectionLength == 44 {
return "NO"
}
if intersectionLength == 45 {
return "NO"
}
if intersectionLength == 46 {
return "NO"
}
if intersectionLength == 47 {
return "NO"
}
if intersectionLength == 48 {
return "NO"
}
if intersectionLength == 49 {
return "NO"
}
if intersectionLength == 50 {
return "NO"
}
if intersectionLength == 51 {
return "NO"
}
if intersectionLength == 52 {
return "NO"
}
if intersectionLength == 53 {
return "NO"
}
if intersectionLength == 54 {
return "NO"
}
if intersectionLength == 55 {
return "NO"
}
if intersectionLength == 56 {
return "NO"
}
if intersectionLength == 57 {
return "NO"
}
if intersectionLength == 58 {
return "NO"
}
if intersectionLength == 59 {
return "NO"
}
if intersectionLength == 60 {
return "NO"
}
if intersectionLength == 61 {
return "NO"
}
ifXCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length <= 0 {
return "NO"
}
if length == 1 {
return "NO"
}
if length == 2 {
return "NO"
}
if length == 3 {
return "NO"
}
if length == 4 {
return "NO"
}
if length == 5 {
return "NO"
}
if length == 6 {
return "NO"
}
if length == 7 {
return "NO"
}
if length == 8 {
return "NO"
}
if length == 9 {
return "NO"
}
if length == 10 {
return "NO"
}
if length == 11 {
return "NO"
}
if length == 12 {
return "NO"
}
if length == 13 {
return "NO"
}
if length == 14 {
return "NO"
}
if length == 15 {
return "NO"
}
if length == 16 {
return "NO"
}
if length == 17 {
return "NO"
}
if length == 18 {
return "NO"
}
if length == 19 {
return "NO"
}
if length == 20 {
return "NO"
}
if length == 21 {
return "NO"
}
if length == 22 {
return "NO"
}
if length == 23 {
return "NO"
}
if length == 24 {
return "NO"
}
if length == 25 {
return "NO"
}
if length == 26 {
return "NO"
}
if length == 27 {
return "NO"
}
if length == 28 {
return "NO"
}
if length == 29 {
return "NO"
}
if length == 30 {
return "NO"
}
if length == 31 {
return "NO"
}
if length == 32 {
return "NO"
}
if length == 33 {
return "NO"
}
if length == 34 {
return "NO"
}
if length == 35 {
return "NO"
}
if length == 36 {
return "NO"
}
if length == 37 {
return "NO"
}
if length == 38 {
return "NO"
}
if length == 39 {
return "NO"
}
if length == 40 {
return "NO"
}
if length == 41 {
return "NO"
}
if length == 42 {
return "NO"
}
if length == 43 {
return "NO"
}
if length == 44 {
return "NO"
}
if length == 45 {
return "NO"
}
if length == 46 {
return "NO"
}
if length == 47 {
return "NO"
}
if length == 48 {
return "NO"
}
if length == 49 {
return "NO"
}
if length == 50 {
return "NO"
}
if length == 51 {
return "NO"
}
if length == 52 {
return "NO"
}
if length == 53 {
return "NO"
}
if length == 54 {
return "NO"
}
if length == 55 {
return "NO"
}
if length == 56 {
return "NO"
}
if length == 57 {
return "NO"
}
if length == 58 {
return "NO"
}
if length == 59 {
return "NO"
}
if length == 60 {
return "NO"
}
if length == 61 {
return "NO"
}
if length == 62 {
return "NO"
}
if length == 63 {
return "NO"
}
if length == 64 {
return "NO"
}
if length == 65 {
return "NO"
}
if length == XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length <= 0 {
return "NO"
}
if length == 1 {
return "NO"
}
if length == 2 {
return "NO"
}
if length == 3 {
return "NO"
}
if length == 4 {
return "NO"
}
if length == 5 {
return "NO"
}
if length == 6 {
return "NO"
}
if length == 7 {
return "NO"
}
if length == 8 {
return "NO"
}
if length == 9 {
return "NO"
}
if length == 10 {
return "NO"
}
if length == 11 {
return "NO"
}
if length == 12 {
return "NO"
}
if length == 13 {
return "NO"
}
if length == 14 {
return "NO"
}
if length == 15 {
return "NO"
}
if length == 16 {
return "NO"
}
if length == 17 {
return "NO"
}
if length == 18 {
return "NO"
}
if length == 19 {
return "NO"
}
if length == 20 {
return "NO"
}
if length == 21 {
return "NO"
}
if length == 22 {
return "NO"
}
if length == 23 {
return "NO"
}
if length == 24 {
return "NO"
}
if length == 25 {
return "NO"
}
if length == 26 {
return "NO"
}
if length == 27 {
return "NO"
}
if length == 28 {
return "NO"
}
if length == 29 {
return "NO"
}
if length == 30 {
return "NO"
}
if length == 31 {
return "NO"
}
if length == 32 {
return "NO"
}
if length == 33 {
return "NO"
}
if length == 34 {
return "NO"
}
if length == 35 {
return "NO"
}
if length == 36 {
return "NO"
}
if length == 37 {
return "NO"
}
if length == 38 {
return "NO"
}
if length == 39 {
return "NO"
}
if length == 40 {
return "NO"
}
if length == 41 {
return "NO"
}
if length == 42 {
return "NO"
}
if length == 43 {
return "NO"
}
if length == 44 {
return "NO"
}
if length == 45 {
return "NO"
}
if length == 46 {
return "NO"
}
if length == 47 {
return "NO"
}
if length == 48 {
return "NO"
}
if length == 49 {
return "NO"
}
if length == 50 {
return "NO"
}
if length == 51 {
return "NO"
}
if length == 52 {
return "NO"
}
if length == 53 {
return "NO"
}
if length == 54 {
return "NO"
}
if length == 55 {
return "NO"
}
if length == 56 {
return "NO"
}
if length == 57 {
return "NO"
}
if length == 58 {
return "NO"
}
if length == 59 {
return "NO"
}
if length == 60 {
return "NO"
}
if length == 61 {
return "NO"
}
if length == 62 {
return "NO"
}
if length == 63 {
return "NO"
}
if length == 64 {
return "NO"
}
if length == 65 {
return "NO"
}
if length == XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scope```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length <= 0 {
return "NO"
}
if length == 1 {
return "NO"
}
if length == 2 {
return "NO"
}
if length == 3 {
return "NO"
}
if length == 4 {
return "NO"
}
if length == 5 {
return "NO"
}
if length == 6 {
return "NO"
}
if length == 7 {
return "NO"
}
if length == 8 {
return "NO"
}
if length == 9 {
return "NO"
}
if length == 10 {
return "NO"
}
if length == 11 {
return "NO"
}
if length == 12 {
return "NO"
}
if length == 13 {
return "NO"
}
if length == 14 {
return "NO"
}
if length == 15 {
return "NO"
}
if length == 16 {
return "NO"
}
if length == 17 {
return "NO"
}
if length == 18 {
return "NO"
}
if length == 19 {
return "NO"
}
if length == 20 {
return "NO"
}
if length == 21 {
return "NO"
}
if length == 22 {
return "NO"
}
if length == 23 {
return "NO"
}
if length == 24 {
return "NO"
}
if length == 25 {
return "NO"
}
if length == 26 {
return "NO"
}
if length == 27 {
return "NO"
}
if length == 28 {
return "NO"
}
if length == 29 {
return "NO"
}
if length == 30 {
return "NO"
}
if length == 31 {
return "NO"
}
if length == 32 {
return "NO"
}
if length == 33 {
return "NO"
}
if length == 34 {
return "NO"
}
if length == 35 {
return "NO"
}
if length == 36 {
return "NO"
}
if length == 37 {
return "NO"
}
if length == 38 {
return "NO"
}
if length == 39 {
return "NO"
}
if length == 40 {
return "NO"
}
if length == 41 {
return "NO"
}
if length == 42 {
return "NO"
}
if length == 43 {
return "NO"
}
if length == 44 {
return "NO"
}
if length == 45 {
return "NO"
}
if length == 46 {
return "NO"
}
if length == 47 {
return "NO"
}
if length == 48 {
return "NO"
}
if length == 49 {
return "NO"
}
if length == 50 {
return "NO"
}
if length == 51 {
return "NO"
}
if length == 52 {
return "NO"
}
if length == 53 {
return "NO"
}
if length == 54 {
return "NO"
}
if length == 55 {
return "NO"
}
if length == 56 {
return "NO"
}
if length == 57 {
return "NO"
}
if length == 58 {
return "NO"
}
if length == 59 {
return "NO"
}
if length == 60 {
return "NO"
}
if length == 61 {
return "NO"
}
if length == 62 {
return "NO"
}
if length == 63 {
return "NO"
}
if length == 64 {
return "NO"
}
if length == 65 {
return "NO"
}
if length == XCTAssertTrue(intersection(interval1: (1, 2), interval2: (2, 3)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, 2), interval2: (-4, 0)) == "YES") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-11, 2), interval2: (-1, -1)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (3, 5)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (1, 2), interval2: (1, 2)) == "NO") // cannot find 'intersection' in scopeXCTAssertTrue(intersection(interval1: (-2, -2), interval2: (-3, -2)) == "NO") // cannot find 'intersection' in scopefunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end { return "NO" }
let length = end - start + 1
if length == 1 { return "NO" }
for i in 2..<length {
if length % i == 0 { return "NO" }
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end { return "NO" }
let length = end - start + 1
if length == 1 { return "NO" }
for i in 2..<length {
if length % i == 0 { return "NO" }
}
return "YES"
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length <= 0 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start
if length <= 0 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}```swift
// You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Your task is to determine whether the length of intersection of these two
// intervals is a prime number.
// Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
// which its length is 1, which not a prime number.
// If the length of the intersection is a prime number, return "YES",
// otherwise, return "NO".
// If the two intervals don't intersect, return "NO".
// [input/output] samples:
// intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
// intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
// intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```
if isPrime(intersectionLength) { // missing argument label 'number:' in callfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```
if isPrime(intersectionLength) { // missing argument label 'number:' in callfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
guard number > 1 else {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
guard number > 1 else {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```
if isPrime(intersectionLength) { // missing argument label 'number:' in callfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```if isPrime(intersectionLength) { // missing argument label 'number:' in callfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
private func isPrime(_ num: Int) -> Bool {
guard num > 1 else { return false }
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
private func isPrime(_ num: Int) -> Bool {
guard num > 1 else { return false }
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```
if isPrime(intersectionLength) { // missing argument label 'number:' in callfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```
if isPrime(intersectionLength) { // missing argument label 'number:' in callfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let intersectionLength = endMin - startMax + 1
if isPrime(number: intersectionLength) {
return "YES"
} else {
return "NO"
}
}
func isPrime(number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let length = endMin - startMax + 1
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
guard n >= 2 else { return false }
for i in stride(from: 2, through: Int(Double(n).squareRoot()), by: 1) {
if n % i == 0 {
return false
}
}
return true
}system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let length = endMin - startMax + 1
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ n: Int) -> Bool {
guard n >= 2 else { return false }
for i in stride(from: 2, through: Int(Double(n).squareRoot()), by: 1) {
if n % i == 0 {
return false
}
}
return true
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
guard startMax <= endMin else {
return "NO"
}
let lengthOfIntersection = endMin - startMax + 1
if isPrime(lengthOfIntersection) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
guard startMax <= endMin else {
return "NO"
}
let lengthOfIntersection = endMin - startMax + 1
if isPrime(lengthOfIntersection) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
guard startMax <= endMin else {
return "NO"
}
let lengthOfIntersection = endMin - startMax + 1
if isPrime(lengthOfIntersection) {
return "YES"
} else {
return "NO"
}
}
private func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
guard startMax <= endMin else {
return "NO"
}
let lengthOfIntersection = endMin - startMax + 1
if isPrime(lengthOfIntersection) {
return "YES"
} else {
return "NO"
}
}
private func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let length = endMin - startMax + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let length = endMin - startMax + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let length = endMin - startMax + 1
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ num: Int) -> Bool {
guard num >= 2 else { return false }
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let length = endMin - startMax + 1
return isPrime(length) ? "YES" : "NO"
}
func isPrime(_ num: Int) -> Bool {
guard num >= 2 else { return false }
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
guard startMax <= endMin else {
return "NO"
}
let length = endMin - startMax + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
guard startMax <= endMin else {
return "NO"
}
let length = endMin - startMax + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
guard startMax <= endMin else {
return "NO"
}
let length = endMin - startMax + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
guard startMax <= endMin else {
return "NO"
}
let length = endMin - startMax + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let lengthOfIntersection = endMin - startMax + 1
return isPrime(lengthOfIntersection) ? "YES" : "NO"
}
func isPrime(_ num: Int) -> Bool {
guard num > 1 else { return false }
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let lengthOfIntersection = endMin - startMax + 1
return isPrime(lengthOfIntersection) ? "YES" : "NO"
}
func isPrime(_ num: Int) -> Bool {
guard num > 1 else { return false }
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let length = endMin - startMax + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
if startMax > endMin {
return "NO"
}
let length = endMin - startMax + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
guard startMax <= endMin else {
return "NO"
}
let length = endMin - startMax + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let startMax = max(interval1.0, interval2.0)
let endMin = min(interval1.1, interval2.1)
guard startMax <= endMin else {
return "NO"
}
let length = endMin - startMax + 1
if isPrime(length) {
return "YES"
} else {
return "NO"
}
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
```
// XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength < 2 {
return "NO"
}
if (2..<intersectionLength).allSatisfy({ intersectionLength % $0!= 0 }) {
return "YES"
}
return "NO"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
if intersectionStart > intersectionEnd {
return "NO"
}
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength < 2 {
return "NO"
}
if (2..<intersectionLength).allSatisfy({ intersectionLength % $0!= 0 }) {
return "YES"
}
return "NO"
}
```if (2..<intersectionLength).allSatisfy({ intersectionLength % $0!= 0 }) { // expression is not assignable: binary operator returns immutable valueif (2..<intersectionLength).allSatisfy({ intersectionLength % $0!= 0 }) { // '=' must have consistent whitespace on both sidesif (2..<intersectionLength).allSatisfy({ intersectionLength % $0!= 0 }) { // cannot force unwrap value of non-optional type 'Int'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
if length == 2 {
return "YES"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
if length == 2 {
return "YES"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length <= 1 {
return "NO"
}
if isPrime(number: length) {
return "YES"
}
return "NO"
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
for i in stride(from: 3, through: Int(sqrt(Double(number))), by: 2) {
if number % i == 0 {
return false
}
}
return true
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length <= 1 {
return "NO"
}
if isPrime(number: length) {
return "YES"
}
return "NO"
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
for i in stride(from: 3, through: Int(sqrt(Double(number))), by: 2) {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength <= 1 {
return "NO"
}
if isPrime(number: intersectionLength) {
return "YES"
}
return "NO"
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
for i in stride(from: 3, through: Int(sqrt(Double(number))), by: 2) {
if number % i == 0 {
return false
}
}
return true
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength <= 1 {
return "NO"
}
if isPrime(number: intersectionLength) {
return "YES"
}
return "NO"
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
for i in stride(from: 3, through: Int(sqrt(Double(number))), by: 2) {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length <= 1 {
return "NO"
}
if isPrime(number: length) {
return "YES"
}
return "NO"
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
for i in stride(from: 3, through: Int(sqrt(Double(number))), by: 2) {
if number % i == 0 {
return false
}
}
return true
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length <= 1 {
return "NO"
}
if isPrime(number: length) {
return "YES"
}
return "NO"
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
for i in stride(from: 3, through: Int(sqrt(Double(number))), by: 2) {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length <= 1 {
return "NO"
}
if isPrime(number: length) {
return "YES"
}
return "NO"
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
for i in stride(from: 3, through: Int(sqrt(Double(number))), by: 2) {
if number % i == 0 {
return false
}
}
return true
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length <= 1 {
return "NO"
}
if isPrime(number: length) {
return "YES"
}
return "NO"
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
for i in stride(from: 3, through: Int(sqrt(Double(number))), by: 2) {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let (start1, end1) = interval1
let (start2, end2) = interval2
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength <= 1 {
return "NO"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength <= 1 {
return "NO"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength <= 1 {
return "NO"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
### Response:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let intersectionStart = max(start1, start2)
let intersectionEnd = min(end1, end2)
let intersectionLength = intersectionEnd - intersectionStart + 1
if intersectionLength <= 1 {
return "NO"
}
for i in 2..<intersectionLength {
if intersectionLength % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failed