func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i + 1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i + 1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```
### Challenge

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i + 1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i + 1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```
### H

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i + 1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i + 1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```
### H

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i + 1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i + 1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```
### H

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i + 1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i + 1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```
### H

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i + 1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i + 1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```
### H

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i + 1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i + 1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```
### Challenge

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i + 1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i + 1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```
### H

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```
### H

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i + 1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count - 1 {
        for j in i + 1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```
### Challenge

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var currentGroup = ""
    var isOpen = false
    for char in parenString {
        if char == "(" {
            isOpen = true
            currentGroup += char
        } else if char == ")" {
            isOpen = false
            currentGroup += char
        } else if isOpen {
            currentGroup += char
        }
        if char == ")" && !isOpen {
            result.append(currentGroup)
            currentGroup = ""
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var currentGroup = ""
    var isOpen = false
    for char in parenString {
        if char == "(" {
            isOpen = true
            currentGroup += char
        } else if char == ")" {
            isOpen = false
            currentGroup += char
        } else if isOpen {
            currentGroup += char
        }
        if char == ")" && !isOpen {
            result.append(currentGroup)
            currentGroup = ""
        }
    }
    return result
}
```
### Ex

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup: String = ""
    var openParens: Int = 0
    for char in parenString {
        if char == "(" {
            openParens += 1
            currentGroup += char
        } else if char == ")" {
            openParens -= 1
            currentGroup += char
            if openParens == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        } else {
            currentGroup += char
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup: String = ""
    var openParens: Int = 0
    for char in parenString {
        if char == "(" {
            openParens += 1
            currentGroup += char
        } else if char == ")" {
            openParens -= 1
            currentGroup += char
            if openParens == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        } else {
            currentGroup += char
        }
    }
    return result
}
```
### Challenge

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup: String = ""
    var openParens: Int = 0
    for char in parenString {
        switch char {
        case "(":
            openParens += 1
            currentGroup += char
        case ")":
            openParens -= 1
            currentGroup += char
        default:
            break
        }
        if openParens == 0 {
            result.append(currentGroup)
            currentGroup = ""
            openParens = 0
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup: String = ""
    var openParens: Int = 0
    for char in parenString {
        switch char {
        case "(":
            openParens += 1
            currentGroup += char
        case ")":
            openParens -= 1
            currentGroup += char
        default:
            break
        }
        if openParens == 0 {
            result.append(currentGroup)
            currentGroup = ""
            openParens = 0
        }
    }
    return result
}
```
### Ex

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var currentGroup = ""
    var stack = [Int]()
    for char in parenString {
        switch char {
        case "(":
            stack.append(currentGroup.count)
            currentGroup.append(char)
        case ")":
            currentGroup.append(char)
            if let lastIndex = stack.popLast() {
                let group = currentGroup[lastIndex..<currentGroup.count]
                result.append(String(group))
                currentGroup = String(currentGroup[..<lastIndex])
            }
        default:
            currentGroup.append(char)
        }
    }
    if !stack.isEmpty {
        fatalError("Unbalanced parentheses")
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var currentGroup = ""
    var stack = [Int]()
    for char in parenString {
        switch char {
        case "(":
            stack.append(currentGroup.count)
            currentGroup.append(char)
        case ")":
            currentGroup.append(char)
            if let lastIndex = stack.popLast() {
                let group = currentGroup[lastIndex..<currentGroup.count]
                result.append(String(group))
                currentGroup = String(currentGroup[..<lastIndex])
            }
        default:
            currentGroup.append(char)
        }
    }
    if !stack.isEmpty {
        fatalError("Unbalanced parentheses")
    }
    return result
}
```
### Test

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup: String = ""
    var stack: [String] = []
    for char in parenString {
        switch char {
        case "(":
            stack.append(char)
        case ")":
            if let last = stack.popLast() {
                if last == "(" {
                    currentGroup.append(char)
                } else {
                    stack.append(char)
                }
            }
        default:
            currentGroup.append(char)
        }
    }
    for group in stack {
        currentGroup.append(group)
    }
    result.append(currentGroup)
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup: String = ""
    var stack: [String] = []
    for char in parenString {
        switch char {
        case "(":
            stack.append(char)
        case ")":
            if let last = stack.popLast() {
                if last == "(" {
                    currentGroup.append(char)
                } else {
                    stack.append(char)
                }
            }
        default:
            currentGroup.append(char)
        }
    }
    for group in stack {
        currentGroup.append(group)
    }
    result.append(currentGroup)
    return result
}
```
### Challenge

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var currentGroup = ""
    var isInGroup = false
    for char in parenString {
        if char == "(" {
            if !isInGroup {
                currentGroup = ""
                isInGroup = true
            }
            currentGroup.append(char)
        } else if char == ")" {
            if isInGroup {
                currentGroup.append(char)
                result.append(currentGroup)
                isInGroup = false
            }
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var currentGroup = ""
    var isInGroup = false
    for char in parenString {
        if char == "(" {
            if !isInGroup {
                currentGroup = ""
                isInGroup = true
            }
            currentGroup.append(char)
        } else if char == ")" {
            if isInGroup {
                currentGroup.append(char)
                result.append(currentGroup)
                isInGroup = false
            }
        }
    }
    return result
}
```
### Challenge

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var currentGroup = ""
    var openCount = 0
    for char in parenString {
        switch char {
        case "(":
            openCount += 1
            currentGroup.append(char)
        case ")":
            openCount -= 1
            currentGroup.append(char)
            if openCount == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        default:
            break
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var currentGroup = ""
    var openCount = 0
    for char in parenString {
        switch char {
        case "(":
            openCount += 1
            currentGroup.append(char)
        case ")":
            openCount -= 1
            currentGroup.append(char)
            if openCount == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        default:
            break
        }
    }
    return result
}
```
### Challenge

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup: String = ""
    for char in parenString {
        switch char {
        case "(":
            currentGroup.append(char)
        case ")":
            currentGroup.append(char)
            result.append(currentGroup)
            currentGroup = ""
        default:
            break
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup: String = ""
    for char in parenString {
        switch char {
        case "(":
            currentGroup.append(char)
        case ")":
            currentGroup.append(char)
            result.append(currentGroup)
            currentGroup = ""
        default:
            break
        }
    }
    return result
}
```
### Challenge

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var currentGroup = ""
    var isInsideGroup = false
    for char in parenString {
        if char == "(" {
            isInsideGroup = true
            currentGroup += char
        } else if char == ")" {
            isInsideGroup = false
            currentGroup += char
        } else if isInsideGroup {
            currentGroup += char
        }
        if !isInsideGroup && currentGroup.count > 0 {
            result.append(currentGroup)
            currentGroup = ""
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var currentGroup = ""
    var isInsideGroup = false
    for char in parenString {
        if char == "(" {
            isInsideGroup = true
            currentGroup += char
        } else if char == ")" {
            isInsideGroup = false
            currentGroup += char
        } else if isInsideGroup {
            currentGroup += char
        }
        if !isInsideGroup && currentGroup.count > 0 {
            result.append(currentGroup)
            currentGroup = ""
        }
    }
    return result
}
```
### Challenge

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [String]()
    var currentGroup = ""
    for char in parenString {
        if char == "(" {
            stack.append(currentGroup)
            currentGroup = ""
        } else if char == ")" {
            if let lastGroup = stack.popLast() {
                currentGroup = lastGroup + ")" + currentGroup
            }
        } else {
            currentGroup.append(char)
        }
    }
    if !currentGroup.isEmpty {
        result.append(currentGroup)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [String]()
    var currentGroup = ""
    for char in parenString {
        if char == "(" {
            stack.append(currentGroup)
            currentGroup = ""
        } else if char == ")" {
            if let lastGroup = stack.popLast() {
                currentGroup = lastGroup + ")" + currentGroup
            }
        } else {
            currentGroup.append(char)
        }
    }
    if !currentGroup.isEmpty {
        result.append(currentGroup)
    }
    return result
}
```
### Ex

func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}
```
### Ex

func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}
```
### Ex

func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}
```
### Problem

func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}
```
### Problem

func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}
```
### Ex

func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}
```
### Ex

func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}
```
### Ex

func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}
```
### Ex

func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}
```
### Ex

func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}
```
### Ex

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        if operation < 0 {
            return true
        }
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        if operation < 0 {
            return true
        }
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```
### Inst

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```
### Ex

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```
### Problem

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```
### Ex

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```
### Problem

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        if operation < 0 {
            return true
        }
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        if operation < 0 {
            return true
        }
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```
### Inst

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```
### Challenge

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```
### Ex

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        if operation < 0 {
            return true
        }
        balance += operation
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        if operation < 0 {
            return true
        }
        balance += operation
    }
    return false
}
```
### Problem

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```
### Problem

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.reduce(0) {
        abs($1 - mean) + $0
    } / Double(numbers.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.reduce(0) {
        abs($1 - mean) + $0
    } / Double(numbers.count)
}
```
### Challenge

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.map({ abs($0 - mean) }).reduce(0, +) / Double(numbers.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.map({ abs($0 - mean) }).reduce(0, +) / Double(numbers.count)
}
```
### Challenge

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.reduce(0) {
        abs($1 - mean) + $0
    } / Double(numbers.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.reduce(0) {
        abs($1 - mean) + $0
    } / Double(numbers.count)
}
```
### Challenge

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.reduce(0) {
        abs($0 - mean) + $1
    } / Double(numbers.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.reduce(0) {
        abs($0 - mean) + $1
    } / Double(numbers.count)
}
```
### Ex

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.map({ abs($0 - mean) }).reduce(0, +) / Double(numbers.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.map({ abs($0 - mean) }).reduce(0, +) / Double(numbers.count)
}
```
### Challenge

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.map({ abs($0 - mean) }).reduce(0, +) / Double(numbers.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.map({ abs($0 - mean) }).reduce(0, +) / Double(numbers.count)
}
```
### Challenge

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.map({ abs($0 - mean) }).reduce(0, +) / Double(numbers.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.map({ abs($0 - mean) }).reduce(0, +) / Double(numbers.count)
}
```
### Challenge

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.map({ abs($0 - mean) }).reduce(0, +) / Double(numbers.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.map({ abs($0 - mean) }).reduce(0, +) / Double(numbers.count)
}
```
### Challenge

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.map({ abs($0 - mean) }).reduce(0, +) / Double(numbers.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.map({ abs($0 - mean) }).reduce(0, +) / Double(numbers.count)
}
```
### Challenge

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.map({ abs($0 - mean) }).reduce(0, +) / Double(numbers.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.map({ abs($0 - mean) }).reduce(0, +) / Double(numbers.count)
}
```
### Challenge

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        if index > 0 {
            result.append(delimeter)
        }
        result.append(number)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        if index > 0 {
            result.append(delimeter)
        }
        result.append(number)
    }
    return result
}
```
### Challenge

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        if index > 0 {
            result.append(delimeter)
        }
        result.append(number)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        if index > 0 {
            result.append(delimeter)
        }
        result.append(number)
    }
    return result
}
```
### Problem

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        if index > 0 {
            result.append(delimeter)
        }
        result.append(number)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        if index > 0 {
            result.append(delimeter)
        }
        result.append(number)
    }
    return result
}
```
### H

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    return numbers.reduce([Int](), { $0 + [$1, delimeter] })
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    return numbers.reduce([Int](), { $0 + [$1, delimeter] })
}
```
### Challenge

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        if index > 0 {
            result.append(delimeter)
        }
        result.append(number)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        if index > 0 {
            result.append(delimeter)
        }
        result.append(number)
    }
    return result
}
```
### H

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    return numbers.flatMap { [$0, delimeter] }.dropLast(1)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    return numbers.flatMap { [$0, delimeter] }.dropLast(1)
}
```
### Challenge

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for i in 0..<numbers.count {
        result.append(numbers[i])
        if i < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for i in 0..<numbers.count {
        result.append(numbers[i])
        if i < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```
### Problem

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        if index > 0 {
            result.append(delimeter)
        }
        result.append(number)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        if index > 0 {
            result.append(delimeter)
        }
        result.append(number)
    }
    return result
}
```
### Challenge

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        if index > 0 {
            result.append(delimeter)
        }
        result.append(number)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        if index > 0 {
            result.append(delimeter)
        }
        result.append(number)
    }
    return result
}
```
### Problem

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        if index > 0 {
            result.append(delimeter)
        }
        result.append(number)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        if index > 0 {
            result.append(delimeter)
        }
        result.append(number)
    }
    return result
}
```
### Challenge

func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var currentLevel = 0
    var currentGroup = ""
    for char in parenString {
        if char == "(" {
            currentLevel += 1
            currentGroup += char
        } else if char == ")" {
            currentLevel -= 1
            currentGroup += char
            if currentLevel == 0 {
                result.append(currentGroup.count)
                currentGroup = ""
            }
        } else {
            currentGroup += char
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var currentLevel = 0
    var currentGroup = ""
    for char in parenString {
        if char == "(" {
            currentLevel += 1
            currentGroup += char
        } else if char == ")" {
            currentLevel -= 1
            currentGroup += char
            if currentLevel == 0 {
                result.append(currentGroup.count)
                currentGroup = ""
            }
        } else {
            currentGroup += char
        }
    }
    return result
}
```
### Challenge

func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var currentLevel = 0
    var currentGroup = ""
    for char in parenString {
        if char == "(" {
            currentLevel += 1
            currentGroup += char
        } else if char == ")" {
            currentLevel -= 1
            currentGroup += char
            if currentLevel < 0 {
                return []
            }
            if currentLevel > result.last ?? 0 {
                result.append(currentLevel)
            }
        } else {
            currentGroup += char
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var currentLevel = 0
    var currentGroup = ""
    for char in parenString {
        if char == "(" {
            currentLevel += 1
            currentGroup += char
        } else if char == ")" {
            currentLevel -= 1
            currentGroup += char
            if currentLevel < 0 {
                return []
            }
            if currentLevel > result.last ?? 0 {
                result.append(currentLevel)
            }
        } else {
            currentGroup += char
        }
    }
    return result
}
```
### Challenge

func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var level = 0
    for char in parenString {
        switch char {
        case "(":
            level += 1
        case ")":
            level -= 1
        default:
            break
        }
        if level > result.max() ?? 0 {
            result.append(level)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var level = 0
    for char in parenString {
        switch char {
        case "(":
            level += 1
        case ")":
            level -= 1
        default:
            break
        }
        if level > result.max() ?? 0 {
            result.append(level)
        }
    }
    return result
}
```
### Challenge

func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var currentLevel = 0
    var parenStack = [Int]()
    for char in parenString {
        switch char {
        case "(":
            parenStack.append(currentLevel)
            currentLevel += 1
        case ")":
            currentLevel = parenStack.popLast()!
        default:
            break
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var currentLevel = 0
    var parenStack = [Int]()
    for char in parenString {
        switch char {
        case "(":
            parenStack.append(currentLevel)
            currentLevel += 1
        case ")":
            currentLevel = parenStack.popLast()!
        default:
            break
        }
    }
    return result
}
```
### Challenge

func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var currentLevel = 0
    for char in parenString {
        if char == "(" {
            currentLevel += 1
        } else if char == ")" {
            currentLevel -= 1
        }
        if currentLevel > result.last ?? 0 {
            result.append(currentLevel)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var currentLevel = 0
    for char in parenString {
        if char == "(" {
            currentLevel += 1
        } else if char == ")" {
            currentLevel -= 1
        }
        if currentLevel > result.last ?? 0 {
            result.append(currentLevel)
        }
    }
    return result
}
```
### Challenge

func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var currentLevel = 0
    for char in parenString {
        switch char {
        case "(":
            currentLevel += 1
        case ")":
            currentLevel -= 1
        default:
            break
        }
        if currentLevel > result.last ?? 0 {
            result.append(currentLevel)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var currentLevel = 0
    for char in parenString {
        switch char {
        case "(":
            currentLevel += 1
        case ")":
            currentLevel -= 1
        default:
            break
        }
        if currentLevel > result.last ?? 0 {
            result.append(currentLevel)
        }
    }
    return result
}
```
### Challenge

func parseNestedParens(parenString: String) -> [Int] {
    var nestingLevel = 0
    var maxNestingLevel = 0
    var result = [Int]()
    for char in parenString {
        switch char {
        case "(":
            nestingLevel += 1
            if nestingLevel > maxNestingLevel {
                maxNestingLevel = nestingLevel
            }
        case ")":
            nestingLevel -= 1
        default:
            break
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var nestingLevel = 0
    var maxNestingLevel = 0
    var result = [Int]()
    for char in parenString {
        switch char {
        case "(":
            nestingLevel += 1
            if nestingLevel > maxNestingLevel {
                maxNestingLevel = nestingLevel
            }
        case ")":
            nestingLevel -= 1
        default:
            break
        }
    }
    return result
}
```
### Challenge

func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var currentLevel = 0
    var parenStack = [Int]()
    for char in parenString {
        switch char {
        case "(":
            parenStack.append(currentLevel)
            currentLevel += 1
        case ")":
            let lastLevel = parenStack.removeLast()
            currentLevel = lastLevel
        default:
            break
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var currentLevel = 0
    var parenStack = [Int]()
    for char in parenString {
        switch char {
        case "(":
            parenStack.append(currentLevel)
            currentLevel += 1
        case ")":
            let lastLevel = parenStack.removeLast()
            currentLevel = lastLevel
        default:
            break
        }
    }
    return result
}
```
### Challenge

func parseNestedParens(parenString: String) -> [Int] {
    var nestingLevels = [Int]()
    var currentNestingLevel = 0
    for char in parenString {
        if char == "(" {
            currentNestingLevel += 1
        } else if char == ")" {
            currentNestingLevel -= 1
        }
        if currentNestingLevel > nestingLevels.last ?? 0 {
            nestingLevels.append(currentNestingLevel)
        }
    }
    return nestingLevels
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var nestingLevels = [Int]()
    var currentNestingLevel = 0
    for char in parenString {
        if char == "(" {
            currentNestingLevel += 1
        } else if char == ")" {
            currentNestingLevel -= 1
        }
        if currentNestingLevel > nestingLevels.last ?? 0 {
            nestingLevels.append(currentNestingLevel)
        }
    }
    return nestingLevels
}
```
### Challenge

func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var currentLevel = 0
    var previousChar: Character?
    for char in parenString {
        if char == "(" {
            currentLevel += 1
        } else if char == ")" {
            currentLevel -= 1
        }
        if currentLevel > result.last ?? 0 {
            result.append(currentLevel)
        }
        previousChar = char
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var currentLevel = 0
    var previousChar: Character?
    for char in parenString {
        if char == "(" {
            currentLevel += 1
        } else if char == ")" {
            currentLevel -= 1
        }
        if currentLevel > result.last ?? 0 {
            result.append(currentLevel)
        }
        previousChar = char
    }
    return result
}
```
### Challenge

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```
### Challenge

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```
### Challenge

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```
### Challenge

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```
### Challenge

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```
### Challenge

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```
### Solution

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```
### Challenge

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```
### Challenge

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```
### Challenge

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```
### Challenge

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```
### Challenge

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```
### Challenge

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```
### Challenge

func sumProduct(numbers: [Int]) -> (Int, Int) {
    let sum = numbers.reduce(0, +)
    let product = numbers.reduce(1, *)
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    let sum = numbers.reduce(0, +)
    let product = numbers.reduce(1, *)
    return (sum, product)
}
```
### Challenge

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```
### Challenge

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```
### Challenge

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = Int.min
    for num in numbers {
        if num > max {
            max = num
        }
        result.append(max)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = Int.min
    for num in numbers {
        if num > max {
            max = num
        }
        result.append(max)
    }
    return result
}
```
### Challenge

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = 0
    for number in numbers {
        if number > max {
            max = number
        }
        result.append(max)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = 0
    for number in numbers {
        if number > max {
            max = number
        }
        result.append(max)
    }
    return result
}
```
### Challenge

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = Int.min
    for number in numbers {
        max = max > number ? max : number
        result.append(max)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = Int.min
    for number in numbers {
        max = max > number ? max : number
        result.append(max)
    }
    return result
}
```
### Challenge

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = 0
    for num in numbers {
        if num > max {
            max = num
        }
        result.append(max)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = 0
    for num in numbers {
        if num > max {
            max = num
        }
        result.append(max)
    }
    return result
}
```
### Challenge

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = 0
    for number in numbers {
        if number > max {
            max = number
        }
        result.append(max)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = 0
    for number in numbers {
        if number > max {
            max = number
        }
        result.append(max)
    }
    return result
}
```
### Challenge

func rollingMax(numbers: [Int]) -> [Int] {
    var max = 0
    var result = [Int]()
    for num in numbers {
        if num > max {
            max = num
        }
        result.append(max)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var max = 0
    var result = [Int]()
    for num in numbers {
        if num > max {
            max = num
        }
        result.append(max)
    }
    return result
}
```
### Challenge

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = Int.min
    for number in numbers {
        if number > max {
            max = number
        }
        result.append(max)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = Int.min
    for number in numbers {
        if number > max {
            max = number
        }
        result.append(max)
    }
    return result
}
```
### Challenge

func rollingMax(numbers: [Int]) -> [Int] {
    var max = 0
    var result = [Int]()
    for number in numbers {
        if number > max {
            max = number
        }
        result.append(max)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var max = 0
    var result = [Int]()
    for number in numbers {
        if number > max {
            max = number
        }
        result.append(max)
    }
    return result
}
```
### Challenge

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = Int.min
    for number in numbers {
        max = max > number ? max : number
        result.append(max)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = Int.min
    for number in numbers {
        max = max > number ? max : number
        result.append(max)
    }
    return result
}
```
### Challenge

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = Int.min
    for number in numbers {
        max = max > number ? max : number
        result.append(max)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = Int.min
    for number in numbers {
        max = max > number ? max : number
        result.append(max)
    }
    return result
}
```
### Challenge

func makePalindrome(string: String) -> String {
    let palindrome = string + string
    return palindrome.reversed()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    let palindrome = string + string
    return palindrome.reversed()
}
```
### Version

func makePalindrome(string: String) -> String {
    var palindrome = ""
    var prefix = ""
    var suffix = ""
    var reversedSuffix = ""
    var length = string.count
    var i = 0
    while i < length {
        let character = string[string.index(string.startIndex, offsetBy: i)]
        if character == string[string.index(string.startIndex, offsetBy: length - i - 1)] {
            palindrome += character
            prefix += character
            suffix += character
        } else {
            break
        }
        i += 1
    }
    reversedSuffix = String(suffix.reversed())
    return palindrome + prefix + reversedSuffix
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    var palindrome = ""
    var prefix = ""
    var suffix = ""
    var reversedSuffix = ""
    var length = string.count
    var i = 0
    while i < length {
        let character = string[string.index(string.startIndex, offsetBy: i)]
        if character == string[string.index(string.startIndex, offsetBy: length - i - 1)] {
            palindrome += character
            prefix += character
            suffix += character
        } else {
            break
        }
        i += 1
    }
    reversedSuffix = String(suffix.reversed())
    return palindrome + prefix + reversedSuffix
}
```
### Challenge

func makePalindrome(string: String) -> String {
    let palindrome = string + string.reversed()
    let prefix = palindrome.prefix { $0 == string }
    return String(prefix) + prefix.reversed()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    let palindrome = string + string.reversed()
    let prefix = palindrome.prefix { $0 == string }
    return String(prefix) + prefix.reversed()
}
```
### Version

func makePalindrome(string: String) -> String {
    let palindrome = string + string.reversed()
    let prefix = palindrome.prefix { $0 == string.last }
    return String(prefix) + prefix.reversed()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    let palindrome = string + string.reversed()
    let prefix = palindrome.prefix { $0 == string.last }
    return String(prefix) + prefix.reversed()
}
```
### Challenge

func makePalindrome(string: String) -> String {
    var palindrome = ""
    var suffix = ""
    var prefix = ""
    for i in 0..<string.count {
        suffix = string.suffix(i)
        if suffix == suffix.reversed() {
            palindrome = string + suffix.reversed()
            break
        }
    }
    return palindrome
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    var palindrome = ""
    var suffix = ""
    var prefix = ""
    for i in 0..<string.count {
        suffix = string.suffix(i)
        if suffix == suffix.reversed() {
            palindrome = string + suffix.reversed()
            break
        }
    }
    return palindrome
}
```
### Challenge

func makePalindrome(string: String) -> String {
    let palindrome = string + string.reversed()
    let prefix = palindrome.prefix { $0 == string.last }
    return string + prefix.reversed()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    let palindrome = string + string.reversed()
    let prefix = palindrome.prefix { $0 == string.last }
    return string + prefix.reversed()
}
```
### Version

func makePalindrome(string: String) -> String {
    let palindrome = string + string.reversed()
    let longestPalindrome = palindrome.longestCommonPrefix(with: palindrome)
    return string + longestPalindrome.reversed()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    let palindrome = string + string.reversed()
    let longestPalindrome = palindrome.longestCommonPrefix(with: palindrome)
    return string + longestPalindrome.reversed()
}
```
### Challenge

func makePalindrome(string: String) -> String {
    let palindrome = string + string.reversed()
    let prefix = palindrome.prefix { $0 == string }
    return String(prefix) + String(prefix.reversed())
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    let palindrome = string + string.reversed()
    let prefix = palindrome.prefix { $0 == string }
    return String(prefix) + String(prefix.reversed())
}
```
### Challenge

func makePalindrome(string: String) -> String {
    let palindrome = string + string.reversed()
    let prefix = palindrome.prefix(while: { $0 == string.last })
    return String(string.reversed()) + String(prefix)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    let palindrome = string + string.reversed()
    let prefix = palindrome.prefix(while: { $0 == string.last })
    return String(string.reversed()) + String(prefix)
}
```
### Version

func makePalindrome(string: String) -> String {
    let palindrome = string + string.reversed()
    let prefix = palindrome.prefix { $0 == string.last }
    return String(prefix) + String(prefix.reversed())
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    let palindrome = string + string.reversed()
    let prefix = palindrome.prefix { $0 == string.last }
    return String(prefix) + String(prefix.reversed())
}
```
### Challenge

func stringXor(a: String, b: String) -> String {
    var result = ""
    for (index, char) in a.enumerated() {
        if char == "1" {
            if b[index] == "1" {
                result += "0"
            } else {
                result += "1"
            }
        } else {
            result += "0"
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for (index, char) in a.enumerated() {
        if char == "1" {
            if b[index] == "1" {
                result += "0"
            } else {
                result += "1"
            }
        } else {
            result += "0"
        }
    }
    return result
}
```
### Challenge

func stringXor(a: String, b: String) -> String {
    var result = ""
    for (index, char) in a.enumerated() {
        if char == "1" {
            result.append(b[index] == "1" ? "0" : "1")
        } else {
            result.append(b[index] == "1" ? "1" : "0")
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for (index, char) in a.enumerated() {
        if char == "1" {
            result.append(b[index] == "1" ? "0" : "1")
        } else {
            result.append(b[index] == "1" ? "1" : "0")
        }
    }
    return result
}
```
### Problem

func stringXor(a: String, b: String) -> String {
    var result = ""
    for (index, char) in a.enumerated() {
        if char == "1" {
            result += b[index] == "1" ? "0" : "1"
        } else {
            result += b[index] == "0" ? "1" : "0"
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for (index, char) in a.enumerated() {
        if char == "1" {
            result += b[index] == "1" ? "0" : "1"
        } else {
            result += b[index] == "0" ? "1" : "0"
        }
    }
    return result
}
```
### Challenge

func stringXor(a: String, b: String) -> String {
    var result = ""
    for i in 0..<a.count {
        if a[i] == "1" && b[i] == "1" {
            result += "0"
        } else {
            result += "1"
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for i in 0..<a.count {
        if a[i] == "1" && b[i] == "1" {
            result += "0"
        } else {
            result += "1"
        }
    }
    return result
}
```
### Problem

func stringXor(a: String, b: String) -> String {
    var result = ""
    for (index, char) in a.enumerated() {
        if char == "1" {
            result += b[index]
        } else {
            result += a[index]
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for (index, char) in a.enumerated() {
        if char == "1" {
            result += b[index]
        } else {
            result += a[index]
        }
    }
    return result
}
```
### Challenge

func stringXor(a: String, b: String) -> String {
    var result = ""
    for (index, char) in a.enumerated() {
        if char == "1" {
            result += b[index]
        } else {
            result += a[index]
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for (index, char) in a.enumerated() {
        if char == "1" {
            result += b[index]
        } else {
            result += a[index]
        }
    }
    return result
}
```
### Problem

func stringXor(a: String, b: String) -> String {
    var result = ""
    for i in 0..<a.count {
        if a[i] == b[i] {
            result += "0"
        } else {
            result += "1"
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for i in 0..<a.count {
        if a[i] == b[i] {
            result += "0"
        } else {
            result += "1"
        }
    }
    return result
}
```
### Problem

func stringXor(a: String, b: String) -> String {
    var result = ""
    for (index, char) in a.enumerated() {
        if char == "1" {
            result += b[index]
        } else {
            result += a[index]
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for (index, char) in a.enumerated() {
        if char == "1" {
            result += b[index]
        } else {
            result += a[index]
        }
    }
    return result
}
```
### Problem

func stringXor(a: String, b: String) -> String {
    var result = ""
    for (index, char) in a.enumerated() {
        if char == "1" {
            result.append(b[index] == "1" ? "0" : "1")
        } else {
            result.append(b[index] == "1" ? "1" : "0")
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for (index, char) in a.enumerated() {
        if char == "1" {
            result.append(b[index] == "1" ? "0" : "1")
        } else {
            result.append(b[index] == "1" ? "1" : "0")
        }
    }
    return result
}
```
### Challenge

func stringXor(a: String, b: String) -> String {
    var result = ""
    for i in 0..<a.count {
        let charA = a[a.index(a.startIndex, offsetBy: i)]
        let charB = b[b.index(b.startIndex, offsetBy: i)]
        if charA == "1" && charB == "1" {
            result += "0"
        } else if charA == "0" && charB == "0" {
            result += "1"
        } else {
            result += "0"
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for i in 0..<a.count {
        let charA = a[a.index(a.startIndex, offsetBy: i)]
        let charB = b[b.index(b.startIndex, offsetBy: i)]
        if charA == "1" && charB == "1" {
            result += "0"
        } else if charA == "0" && charB == "0" {
            result += "1"
        } else {
            result += "0"
        }
    }
    return result
}
```
### Challenge

func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    return strings.sorted(by: { $0.count > $1.count }).first
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    return strings.sorted(by: { $0.count > $1.count }).first
}
```
### Ex

func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    return strings.sorted(by: { $0.count > $1.count }).first
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    return strings.sorted(by: { $0.count > $1.count }).first
}
```
### Ex

func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    return strings.sorted(by: { $0.count > $1.count }).first
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    return strings.sorted(by: { $0.count > $1.count }).first
}
```
### Version

func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    return strings.sorted(by: { $0.count > $1.count }).first
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    return strings.sorted(by: { $0.count > $1.count }).first
}
```
### Ex

func longest(strings: [String]) -> String? {
    if strings.isEmpty {
        return nil
    }
    return strings.max { $0.count < $1.count }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    if strings.isEmpty {
        return nil
    }
    return strings.max { $0.count < $1.count }
}
```
### Version

func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    return strings.sorted(by: { $0.count > $1.count }).first
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    return strings.sorted(by: { $0.count > $1.count }).first
}
```
### Version

func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    return strings.sorted(by: { $0.count > $1.count }).first
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    return strings.sorted(by: { $0.count > $1.count }).first
}
```
### Ex

func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    return strings.sorted(by: { $0.count > $1.count }).first
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    return strings.sorted(by: { $0.count > $1.count }).first
}
```
### Ex

func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else {
        return nil
    }
    return strings.sorted(by: { $0.count > $1.count }).first
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else {
        return nil
    }
    return strings.sorted(by: { $0.count > $1.count }).first
}
```
### Ex

func longest(strings: [String]) -> String? {
    if strings.isEmpty {
        return nil
    }
    return strings.max { $0.count < $1.count }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    if strings.isEmpty {
        return nil
    }
    return strings.max { $0.count < $1.count }
}
```
### Ex

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while a != 0 {
        let temp = a
        a = b % a
        b = temp
    }
    return b
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while a != 0 {
        let temp = a
        a = b % a
        b = temp
    }
    return b
}
```
### Ex

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while a != 0 {
        a = b % a
        b = a
    }
    return b
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while a != 0 {
        a = b % a
        b = a
    }
    return b
}
```
### Ex

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while a != 0 {
        a = b % a
        b = a
    }
    return b
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while a != 0 {
        a = b % a
        b = a
    }
    return b
}
```
### Problem

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while a != 0 {
        a = b % a
        b = a
    }
    return b
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while a != 0 {
        a = b % a
        b = a
    }
    return b
}
```
### Ex

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while a != 0 {
        a = b % a
        b = a
    }
    return b
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while a != 0 {
        a = b % a
        b = a
    }
    return b
}
```
### Problem

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while a != 0 {
        (a, b) = (b % a, a)
    }
    return b
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while a != 0 {
        (a, b) = (b % a, a)
    }
    return b
}
```
### Ex

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while a != 0 {
        (a, b) = (b % a, a)
    }
    return b
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while a != 0 {
        (a, b) = (b % a, a)
    }
    return b
}
```
### Problem

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while a != 0 {
        let temp = a
        a = b % a
        b = temp
    }
    return b
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while a != 0 {
        let temp = a
        a = b % a
        b = temp
    }
    return b
}
```
### Problem

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while a != 0 {
        let temp = a
        a = b % a
        b = temp
    }
    return b
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while a != 0 {
        let temp = a
        a = b % a
        b = temp
    }
    return b
}
```
### Problem

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while a != 0 {
        let temp = a
        a = b % a
        b = temp
    }
    return b
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while a != 0 {
        let temp = a
        a = b % a
        b = temp
    }
    return b
}
```
### Problem

func allPrefixes(string: String) -> [String] {
    var result = [String]()
    for i in 0..<string.count {
        result.append(string[..<string.index(string.startIndex, offsetBy: i)])
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    var result = [String]()
    for i in 0..<string.count {
        result.append(string[..<string.index(string.startIndex, offsetBy: i)])
    }
    return result
}
```
### Problem

func allPrefixes(string: String) -> [String] {
    return string.map { [$0] } + allPrefixes(string: String(string.dropFirst()))
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    return string.map { [$0] } + allPrefixes(string: String(string.dropFirst()))
}
```
### Version

func allPrefixes(string: String) -> [String] {
    return (0..<string.count).map { string.prefix(upTo: $0) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    return (0..<string.count).map { string.prefix(upTo: $0) }
}
```
### Version

func allPrefixes(string: String) -> [String] {
    return (0..<string.count).map { string.prefix(upTo: string.index(string.startIndex, offsetBy: $0)) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    return (0..<string.count).map { string.prefix(upTo: string.index(string.startIndex, offsetBy: $0)) }
}
```
### Version

func allPrefixes(string: String) -> [String] {
    var result = [String]()
    for i in 0..<string.count {
        result.append(string[..<i])
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    var result = [String]()
    for i in 0..<string.count {
        result.append(string[..<i])
    }
    return result
}
```
### Problem

func allPrefixes(string: String) -> [String] {
    return (0...string.count).map { string.prefix(upTo: $0) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    return (0...string.count).map { string.prefix(upTo: $0) }
}
```
### Challenge

func allPrefixes(string: String) -> [String] {
    var result = [String]()
    for i in 0..<string.count {
        result.append(String(string.prefix(i)))
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    var result = [String]()
    for i in 0..<string.count {
        result.append(String(string.prefix(i)))
    }
    return result
}
```
### Challenge

func allPrefixes(string: String) -> [String] {
    var result = [String]()
    for i in 0..<string.count {
        result.append(String(string.prefix(i)))
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    var result = [String]()
    for i in 0..<string.count {
        result.append(String(string.prefix(i)))
    }
    return result
}
```
### Challenge

func allPrefixes(string: String) -> [String] {
    var result = [String]()
    for i in 0..<string.count {
        result.append(String(string.prefix(i)))
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    var result = [String]()
    for i in 0..<string.count {
        result.append(String(string.prefix(i)))
    }
    return result
}
```
### Challenge

func allPrefixes(string: String) -> [String] {
    return string.map { [$0] } + allPrefixes(string: String(string.dropFirst()))
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    return string.map { [$0] } + allPrefixes(string: String(string.dropFirst()))
}
```
### Ex

func stringSequence(n: Int) -> String {
    return (0...n).map { String($0) }.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    return (0...n).map { String($0) }.joined(separator: " ")
}
```
### Reference

func stringSequence(n: Int) -> String {
    return (0...n).map(String.init).joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    return (0...n).map(String.init).joined(separator: " ")
}
```
### Challenge

func stringSequence(n: Int) -> String {
    return (0...n).map(String.init).joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    return (0...n).map(String.init).joined(separator: " ")
}
```
### Ex

func stringSequence(n: Int) -> String {
    return (0...n).map(String.init).joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    return (0...n).map(String.init).joined(separator: " ")
}
```
### Version

func stringSequence(n: Int) -> String {
    return (0...n).map(String.init).joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    return (0...n).map(String.init).joined(separator: " ")
}
```
### Reference

func stringSequence(n: Int) -> String {
    return (0...n).map(String.init).joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    return (0...n).map(String.init).joined(separator: " ")
}
```
### Version

func stringSequence(n: Int) -> String {
    return (0...n).map { String($0) }.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    return (0...n).map { String($0) }.joined(separator: " ")
}
```
### Version

func stringSequence(n: Int) -> String {
    return (0...n).map(String.init).joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    return (0...n).map(String.init).joined(separator: " ")
}
```
### Challenge

func stringSequence(n: Int) -> String {
    return (0...n).map { String($0) }.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    return (0...n).map { String($0) }.joined(separator: " ")
}
```
### Version

func stringSequence(n: Int) -> String {
    return (0...n).map { String($0) }.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    return (0...n).map { String($0) }.joined(separator: " ")
}
```
### Reference

func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}
```
### Problem

func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}
```
### Challenge

func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}
```
### Ex

func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters = Set<Character>()
    for character in string.lowercased() {
        distinctCharacters.insert(character)
    }
    return distinctCharacters.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters = Set<Character>()
    for character in string.lowercased() {
        distinctCharacters.insert(character)
    }
    return distinctCharacters.count
}
```
### Challenge

func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}
```
### Challenge

func countDistinctCharacters(string: String) -> Int {
    var result = 0
    for char in string.lowercased() {
        if !string.lowercased().contains(char) {
            result += 1
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    var result = 0
    for char in string.lowercased() {
        if !string.lowercased().contains(char) {
            result += 1
        }
    }
    return result
}
```
### Challenge

func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters = Set<Character>()
    for character in string.lowercased() {
        distinctCharacters.insert(character)
    }
    return distinctCharacters.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters = Set<Character>()
    for character in string.lowercased() {
        distinctCharacters.insert(character)
    }
    return distinctCharacters.count
}
```
### Challenge

func countDistinctCharacters(string: String) -> Int {
    return Array(Set(string.lowercased())).count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    return Array(Set(string.lowercased())).count
}
```
### Challenge

func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}
```
### Ex

func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}
```
### Version

func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentBeat = 0
    for char in musicString {
        switch char {
        case "o":
            currentBeat += 4
        case "o|":
            currentBeat += 2
        case ".|":
            currentBeat += 1
        default:
            break
        }
        beats.append(currentBeat)
    }
    return beats
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentBeat = 0
    for char in musicString {
        switch char {
        case "o":
            currentBeat += 4
        case "o|":
            currentBeat += 2
        case ".|":
            currentBeat += 1
        default:
            break
        }
        beats.append(currentBeat)
    }
    return beats
}
```
### Challenge

func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    for char in musicString {
        switch char {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    for char in musicString {
        switch char {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}
```
### Challenge

func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentBeat = 0
    for char in musicString {
        switch char {
        case "o":
            currentBeat += 4
        case "o|":
            currentBeat += 2
        case ".|":
            currentBeat += 1
        default:
            break
        }
        beats.append(currentBeat)
    }
    return beats
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentBeat = 0
    for char in musicString {
        switch char {
        case "o":
            currentBeat += 4
        case "o|":
            currentBeat += 2
        case ".|":
            currentBeat += 1
        default:
            break
        }
        beats.append(currentBeat)
    }
    return beats
}
```
### Challenge

func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentBeat = 0
    for char in musicString {
        switch char {
        case "o":
            beats.append(4)
            currentBeat += 4
        case "o|":
            beats.append(2)
            currentBeat += 2
        case ".|":
            beats.append(1)
            currentBeat += 1
        default:
            break
        }
    }
    return beats
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentBeat = 0
    for char in musicString {
        switch char {
        case "o":
            beats.append(4)
            currentBeat += 4
        case "o|":
            beats.append(2)
            currentBeat += 2
        case ".|":
            beats.append(1)
            currentBeat += 1
        default:
            break
        }
    }
    return beats
}
```
### Challenge

func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    for char in musicString {
        switch char {
        case "o":
            beats.append(4)
        case "|":
            beats.append(2)
        case ".":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    for char in musicString {
        switch char {
        case "o":
            beats.append(4)
        case "|":
            beats.append(2)
        case ".":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}
```
### Challenge

func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentBeat = 0
    for char in musicString {
        switch char {
        case "o":
            currentBeat += 4
        case "|":
            currentBeat += 2
        case ".":
            currentBeat += 1
        default:
            break
        }
        beats.append(currentBeat)
    }
    return beats
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentBeat = 0
    for char in musicString {
        switch char {
        case "o":
            currentBeat += 4
        case "|":
            currentBeat += 2
        case ".":
            currentBeat += 1
        default:
            break
        }
        beats.append(currentBeat)
    }
    return beats
}
```
### Challenge

func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    for char in musicString {
        switch char {
        case "o":
            beats.append(4)
        case "|":
            beats.append(2)
        case ".":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    for char in musicString {
        switch char {
        case "o":
            beats.append(4)
        case "|":
            beats.append(2)
        case ".":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}
```
### Challenge

func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentBeat = 0
    for char in musicString {
        switch char {
        case "o":
            currentBeat += 4
        case "|":
            currentBeat += 2
        case ".":
            currentBeat += 1
        default:
            break
        }
        beats.append(currentBeat)
    }
    return beats
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentBeat = 0
    for char in musicString {
        switch char {
        case "o":
            currentBeat += 4
        case "|":
            currentBeat += 2
        case ".":
            currentBeat += 1
        default:
            break
        }
        beats.append(currentBeat)
    }
    return beats
}
```
### Challenge

func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentBeat = 0
    for char in musicString {
        switch char {
        case "o":
            currentBeat += 4
        case "|":
            currentBeat += 2
        case ".":
            currentBeat += 1
        default:
            break
        }
        beats.append(currentBeat)
    }
    return beats
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentBeat = 0
    for char in musicString {
        switch char {
        case "o":
            currentBeat += 4
        case "|":
            currentBeat += 2
        case ".":
            currentBeat += 1
        default:
            break
        }
        beats.append(currentBeat)
    }
    return beats
}
```
### Challenge

func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentBeat = 0
    for char in musicString {
        switch char {
        case "o":
            beats.append(currentBeat + 4)
            currentBeat += 4
        case "o|":
            beats.append(currentBeat + 2)
            currentBeat += 2
        case ".|":
            beats.append(currentBeat + 1)
            currentBeat += 1
        default:
            break
        }
    }
    return beats
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentBeat = 0
    for char in musicString {
        switch char {
        case "o":
            beats.append(currentBeat + 4)
            currentBeat += 4
        case "o|":
            beats.append(currentBeat + 2)
            currentBeat += 2
        case ".|":
            beats.append(currentBeat + 1)
            currentBeat += 1
        default:
            break
        }
    }
    return beats
}
```
### Challenge

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var start = string.startIndex
    while start < string.endIndex {
        if let range = string.rangeOfString(substring, options: [], range: start..<string.endIndex) {
            count += 1
            start = range.endIndex
        } else {
            break
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var start = string.startIndex
    while start < string.endIndex {
        if let range = string.rangeOfString(substring, options: [], range: start..<string.endIndex) {
            count += 1
            start = range.endIndex
        } else {
            break
        }
    }
    return count
}
```
### Challenge

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var lastIndex = -substring.count
    while let range = string.range(of: substring, range: lastIndex..<string.count) {
        count += 1
        lastIndex = range.upperBound
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var lastIndex = -substring.count
    while let range = string.range(of: substring, range: lastIndex..<string.count) {
        count += 1
        lastIndex = range.upperBound
    }
    return count
}
```
### Challenge

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var startIndex = string.startIndex
    while startIndex < string.endIndex {
        if let range = string.range(of: substring, range: startIndex..<string.endIndex) {
            count += 1
            startIndex = range.upperBound
        } else {
            startIndex = string.index(after: startIndex)
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var startIndex = string.startIndex
    while startIndex < string.endIndex {
        if let range = string.range(of: substring, range: startIndex..<string.endIndex) {
            count += 1
            startIndex = range.upperBound
        } else {
            startIndex = string.index(after: startIndex)
        }
    }
    return count
}
```
### Challenge

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var startIndex = string.startIndex
    while startIndex < string.endIndex {
        if let range = string.range(of: substring, range: startIndex..<string.endIndex) {
            count += 1
            startIndex = range.upperBound
        } else {
            break
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var startIndex = string.startIndex
    while startIndex < string.endIndex {
        if let range = string.range(of: substring, range: startIndex..<string.endIndex) {
            count += 1
            startIndex = range.upperBound
        } else {
            break
        }
    }
    return count
}
```
### Challenge

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var i = 0
    while i < string.count {
        if string[i..<i+substring.count] == substring {
            count += 1
        }
        i += 1
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var i = 0
    while i < string.count {
        if string[i..<i+substring.count] == substring {
            count += 1
        }
        i += 1
    }
    return count
}
```
### Challenge

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var i = 0
    while i < string.count {
        if string[i] == substring[0] && string.hasPrefix(substring, at: i) {
            count += 1
            i += substring.count
        } else {
            i += 1
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var i = 0
    while i < string.count {
        if string[i] == substring[0] && string.hasPrefix(substring, at: i) {
            count += 1
            i += substring.count
        } else {
            i += 1
        }
    }
    return count
}
```
### Challenge

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var start = string.startIndex
    while start < string.endIndex {
        if let range = string.range(of: substring, range: start..<string.endIndex) {
            count += 1
            start = range.upperBound
        } else {
            break
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var start = string.startIndex
    while start < string.endIndex {
        if let range = string.range(of: substring, range: start..<string.endIndex) {
            count += 1
            start = range.upperBound
        } else {
            break
        }
    }
    return count
}
```
### Ex

func howManyTimes(string: String, substring: String) -> Int {
    var counter = 0
    var startIndex = string.startIndex
    while startIndex < string.endIndex {
        if let range = string.range(of: substring, range: startIndex..<string.endIndex) {
            counter += 1
            startIndex = range.upperBound
        } else {
            break
        }
    }
    return counter
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var counter = 0
    var startIndex = string.startIndex
    while startIndex < string.endIndex {
        if let range = string.range(of: substring, range: startIndex..<string.endIndex) {
            counter += 1
            startIndex = range.upperBound
        } else {
            break
        }
    }
    return counter
}
```
### Challenge

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var start = string.startIndex
    while start < string.endIndex {
        if let range = string.range(of: substring, range: start..<string.endIndex) {
            count += 1
            start = range.upperBound
        } else {
            break
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var start = string.startIndex
    while start < string.endIndex {
        if let range = string.range(of: substring, range: start..<string.endIndex) {
            count += 1
            start = range.upperBound
        } else {
            break
        }
    }
    return count
}
```
### Challenge

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var lastIndex = string.startIndex
    while let range = string.range(of: substring, range: lastIndex..<string.endIndex) {
        count += 1
        lastIndex = range.upperBound
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var lastIndex = string.startIndex
    while let range = string.range(of: substring, range: lastIndex..<string.endIndex) {
        count += 1
        lastIndex = range.upperBound
    }
    return count
}
```
### Challenge

func sortNumbers(numbers: String) -> String {
    let sorted = numbers.components(separatedBy: " ").sorted(by: <)
    return sorted.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    let sorted = numbers.components(separatedBy: " ").sorted(by: <)
    return sorted.joined(separator: " ")
}
```
### Challenge

func sortNumbers(numbers: String) -> String {
    let sorted = numbers.split(separator: " ").sorted()
    return sorted.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    let sorted = numbers.split(separator: " ").sorted()
    return sorted.joined(separator: " ")
}
```
### Challenge

func sortNumbers(numbers: String) -> String {
    let nums = numbers.components(separatedBy: " ")
    let sortedNums = nums.sorted(by: <)
    return sortedNums.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    let nums = numbers.components(separatedBy: " ")
    let sortedNums = nums.sorted(by: <)
    return sortedNums.joined(separator: " ")
}
```
### Challenge

func sortNumbers(numbers: String) -> String {
    return numbers.components(separatedBy: " ").sorted(by: <).joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    return numbers.components(separatedBy: " ").sorted(by: <).joined(separator: " ")
}
```
### Challenge

func sortNumbers(numbers: String) -> String {
    var sortedNumbers = [Int]()
    for number in numbers.split(separator: " ") {
        sortedNumbers.append(Int(number)!)
    }
    sortedNumbers.sort()
    return sortedNumbers.map { String($0) }.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    var sortedNumbers = [Int]()
    for number in numbers.split(separator: " ") {
        sortedNumbers.append(Int(number)!)
    }
    sortedNumbers.sort()
    return sortedNumbers.map { String($0) }.joined(separator: " ")
}
```
### Challenge

func sortNumbers(numbers: String) -> String {
    let sorted = numbers.components(separatedBy: " ").sorted(by: <)
    return sorted.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    let sorted = numbers.components(separatedBy: " ").sorted(by: <)
    return sorted.joined(separator: " ")
}
```
### Challenge

func sortNumbers(numbers: String) -> String {
    var sorted = [Int]()
    for number in numbers.components(separatedBy: " ") {
        sorted.append(Int(number)!)
    }
    sorted.sort()
    return sorted.map { String($0) }.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    var sorted = [Int]()
    for number in numbers.components(separatedBy: " ") {
        sorted.append(Int(number)!)
    }
    sorted.sort()
    return sorted.map { String($0) }.joined(separator: " ")
}
```
### Challenge

func sortNumbers(numbers: String) -> String {
    return numbers.components(separatedBy: " ").sorted(by: <).joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    return numbers.components(separatedBy: " ").sorted(by: <).joined(separator: " ")
}
```
### Challenge

func sortNumbers(numbers: String) -> String {
    let sorted = numbers.split(separator: " ").sorted()
    return sorted.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    let sorted = numbers.split(separator: " ").sorted()
    return sorted.joined(separator: " ")
}
```
### Challenge

func sortNumbers(numbers: String) -> String {
    let nums = numbers.components(separatedBy: " ")
    let sortedNums = nums.sorted(by: <)
    return sortedNums.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    let nums = numbers.components(separatedBy: " ")
    let sortedNums = nums.sorted(by: <)
    return sortedNums.joined(separator: " ")
}
```
### Challenge

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closest = (0.0, 0.0)
    for i in 0..<numbers.count-1 {
        let diff = abs(numbers[i] - numbers[i+1])
        if diff < closest.0 {
            closest = (diff, numbers[i])
        }
    }
    return (closest.1, numbers[closest.0])
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closest = (0.0, 0.0)
    for i in 0..<numbers.count-1 {
        let diff = abs(numbers[i] - numbers[i+1])
        if diff < closest.0 {
            closest = (diff, numbers[i])
        }
    }
    return (closest.1, numbers[closest.0])
}
```
### Challenge

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    let sorted = numbers.sorted()
    let first = sorted.first!
    let last = sorted.last!
    return (first, last)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    let sorted = numbers.sorted()
    let first = sorted.first!
    let last = sorted.last!
    return (first, last)
}
```
### Challenge

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    let sorted = numbers.sorted()
    let first = sorted[0]
    let last = sorted[sorted.count - 1]
    return (first, last)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    let sorted = numbers.sorted()
    let first = sorted[0]
    let last = sorted[sorted.count - 1]
    return (first, last)
}
```
### Challenge

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closestPairs: [(Double, Double)] = []
    for i in 0..<numbers.count-1 {
        let diff = abs(numbers[i] - numbers[i+1])
        if closestPairs.isEmpty || diff < closestPairs.last!.0 {
            closestPairs.append((diff, numbers[i], numbers[i+1]))
        }
    }
    return (closestPairs.first!.1, closestPairs.first!.2)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closestPairs: [(Double, Double)] = []
    for i in 0..<numbers.count-1 {
        let diff = abs(numbers[i] - numbers[i+1])
        if closestPairs.isEmpty || diff < closestPairs.last!.0 {
            closestPairs.append((diff, numbers[i], numbers[i+1]))
        }
    }
    return (closestPairs.first!.1, closestPairs.first!.2)
}
```
### Challenge

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    let sorted = numbers.sorted()
    let first = sorted.first!
    let last = sorted.last!
    return (first, last)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    let sorted = numbers.sorted()
    let first = sorted.first!
    let last = sorted.last!
    return (first, last)
}
```
### Challenge

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    let sorted = numbers.sorted()
    let first = sorted[0]
    let last = sorted[sorted.count - 1]
    return (first, last)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    let sorted = numbers.sorted()
    let first = sorted[0]
    let last = sorted[sorted.count - 1]
    return (first, last)
}
```
### Challenge

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    let sortedNumbers = numbers.sorted()
    let first = sortedNumbers[0]
    let last = sortedNumbers[sortedNumbers.count - 1]
    return (first, last)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    let sortedNumbers = numbers.sorted()
    let first = sortedNumbers[0]
    let last = sortedNumbers[sortedNumbers.count - 1]
    return (first, last)
}
```
### Challenge

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    let sorted = numbers.sorted()
    let first = sorted[0]
    let last = sorted[sorted.count - 1]
    return (first, last)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    let sorted = numbers.sorted()
    let first = sorted[0]
    let last = sorted[sorted.count - 1]
    return (first, last)
}
```
### Challenge

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closest = (0.0, 0.0)
    for i in 0..<numbers.count-1 {
        let diff = abs(numbers[i] - numbers[i+1])
        if diff < closest.0 {
            closest = (diff, numbers[i])
        }
    }
    return (closest.1, numbers[closest.0])
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closest = (0.0, 0.0)
    for i in 0..<numbers.count-1 {
        let diff = abs(numbers[i] - numbers[i+1])
        if diff < closest.0 {
            closest = (diff, numbers[i])
        }
    }
    return (closest.1, numbers[closest.0])
}
```
### Challenge

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    let sorted = numbers.sorted()
    let first = sorted[0]
    let last = sorted[sorted.count - 1]
    return (first, last)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    let sorted = numbers.sorted()
    let first = sorted[0]
    let last = sorted[sorted.count - 1]
    return (first, last)
}
```
### Challenge

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { (number) -> Double in
        (number - min) / range
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { (number) -> Double in
        (number - min) / range
    }
}
```
### Inst

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { (number) -> Double in
        (number - min) / range
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { (number) -> Double in
        (number - min) / range
    }
}
```
### Inst

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { (number) -> Double in
        return (number - min) / range
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { (number) -> Double in
        return (number - min) / range
    }
}
```
### Problem

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { (number) -> Double in
        return (number - min) / range
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { (number) -> Double in
        return (number - min) / range
    }
}
```
### Inst

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { (number) -> Double in
        return (number - min) / range
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { (number) -> Double in
        return (number - min) / range
    }
}
```
### Inst

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { (number) -> Double in
        (number - min) / range
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { (number) -> Double in
        (number - min) / range
    }
}
```
### Inst

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { (value) -> Double in
        return (value - min) / range
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { (value) -> Double in
        return (value - min) / range
    }
}
```
### Inst

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { (number) -> Double in
        return (number - min) / range
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { (number) -> Double in
        return (number - min) / range
    }
}
```
### Inst

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { (number) -> Double in
        return (number - min) / range
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { (number) -> Double in
        return (number - min) / range
    }
}
```
### Inst

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { (number) -> Double in
        return (number - min) / range
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { (number) -> Double in
        return (number - min) / range
    }
}
```
### Challenge

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int }.map { $0 as! Int }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int }.map { $0 as! Int }
}
```
### Inst

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int }.map { $0 as! Int }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int }.map { $0 as! Int }
}
```
### Ex

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int }.map { $0 as! Int }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int }.map { $0 as! Int }
}
```
### Ex

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int }.map { $0 as! Int }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int }.map { $0 as! Int }
}
```
### Ex

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int }.map { $0 as! Int }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int }.map { $0 as! Int }
}
```
### Inst

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int }.map { $0 as! Int }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int }.map { $0 as! Int }
}
```
### Inst

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int }.map { $0 as! Int }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int }.map { $0 as! Int }
}
```
### Inst

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int }.map { $0 as! Int }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int }.map { $0 as! Int }
}
```
### Ex

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int }.map { $0 as! Int }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int }.map { $0 as! Int }
}
```
### Ex

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int }.map { $0 as! Int }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int }.map { $0 as! Int }
}
```
### Inst

func strlen(string: String) -> Int {
    return string.characters.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.characters.count
}
```
### Ex

func strlen(string: String) -> Int {
    return string.characters.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.characters.count
}
```
### Challenge

func strlen(string: String) -> Int {
    return string.characters.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.characters.count
}
```
### Challenge

func strlen(string: String) -> Int {
    return string.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```
### Ex

func strlen(string: String) -> Int {
    return string.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```
### H

func strlen(string: String) -> Int {
    return string.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```
### Challenge

func strlen(string: String) -> Int {
    return string.characters.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.characters.count
}
```
### Ex

func strlen(string: String) -> Int {
    return string.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```
### Challenge

func strlen(string: String) -> Int {
    return string.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```
### H

func strlen(string: String) -> Int {
    return string.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```
### Ex

func largestDivisor(n: Int) -> Int {
    var divisor = 0
    for i in 1...n {
        if n % i == 0 {
            divisor = i
        }
    }
    return divisor
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = 0
    for i in 1...n {
        if n % i == 0 {
            divisor = i
        }
    }
    return divisor
}
```
### Challenge

func largestDivisor(n: Int) -> Int {
    var divisor = 0
    for i in 1..<n {
        if n % i == 0 {
            divisor = i
        }
    }
    return divisor
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = 0
    for i in 1..<n {
        if n % i == 0 {
            divisor = i
        }
    }
    return divisor
}
```
### Problem

func largestDivisor(n: Int) -> Int {
    var divisor = 0
    for i in 1..<n {
        if n % i == 0 {
            divisor = i
            break
        }
    }
    return divisor
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = 0
    for i in 1..<n {
        if n % i == 0 {
            divisor = i
            break
        }
    }
    return divisor
}
```
### Challenge

func largestDivisor(n: Int) -> Int {
    var divisor = 0
    for i in 1...n {
        if n % i == 0 {
            divisor = i
        }
    }
    return divisor
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = 0
    for i in 1...n {
        if n % i == 0 {
            divisor = i
        }
    }
    return divisor
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = 0
    for i in 1..<n {
        if n % i == 0 {
            divisor = i
        }
    }
    return divisor
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = 0
    for i in 1..<n {
        if n % i == 0 {
            divisor = i
        }
    }
    return divisor
}
```
### Challenge

func largestDivisor(n: Int) -> Int {
    var divisor = 1
    while divisor < n {
        if n % divisor == 0 {
            return divisor
        }
        divisor += 1
    }
    return 1
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = 1
    while divisor < n {
        if n % divisor == 0 {
            return divisor
        }
        divisor += 1
    }
    return 1
}
```
### Challenge

func largestDivisor(n: Int) -> Int {
    var divisor = 0
    for i in 1..<n {
        if n % i == 0 {
            divisor = i
        }
    }
    return divisor
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = 0
    for i in 1..<n {
        if n % i == 0 {
            divisor = i
        }
    }
    return divisor
}
```
### Problem

func largestDivisor(n: Int) -> Int {
    var divisor = 0
    for i in 1..<n {
        if n % i == 0 {
            divisor = i
        }
    }
    return divisor
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = 0
    for i in 1..<n {
        if n % i == 0 {
            divisor = i
        }
    }
    return divisor
}
```
### Challenge

func largestDivisor(n: Int) -> Int {
    var i = n / 2
    while i > 0 {
        if n % i == 0 {
            return i
        }
        i -= 1
    }
    return 0
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    var i = n / 2
    while i > 0 {
        if n % i == 0 {
            return i
        }
        i -= 1
    }
    return 0
}
```
### Challenge

func largestDivisor(n: Int) -> Int {
    var divisor = 0
    for i in 1...n {
        if n % i == 0 {
            divisor = i
        }
    }
    return divisor
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = 0
    for i in 1...n {
        if n % i == 0 {
            divisor = i
        }
    }
    return divisor
}
```
### Problem

func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var i = 2
    while i * i <= n {
        while n % i == 0 {
            factors.append(i)
            n /= i
        }
        i += 1
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var i = 2
    while i * i <= n {
        while n % i == 0 {
            factors.append(i)
            n /= i
        }
        i += 1
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}
```
### Challenge

func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var i = 2
    while i * i <= n {
        while n % i == 0 {
            factors.append(i)
            n /= i
        }
        i += 1
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var i = 2
    while i * i <= n {
        while n % i == 0 {
            factors.append(i)
            n /= i
        }
        i += 1
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}
```
### Challenge

func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var i = 2
    while i * i <= n {
        while n % i == 0 {
            factors.append(i)
            n /= i
        }
        i += 1
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var i = 2
    while i * i <= n {
        while n % i == 0 {
            factors.append(i)
            n /= i
        }
        i += 1
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}
```
### Challenge

func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            factors.append(i)
            n /= i
        } else {
            i += 1
        }
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            factors.append(i)
            n /= i
        } else {
            i += 1
        }
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}
```
### Challenge

func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var i = 2
    while i * i <= n {
        while n % i == 0 {
            factors.append(i)
            n /= i
        }
        i += 1
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var i = 2
    while i * i <= n {
        while n % i == 0 {
            factors.append(i)
            n /= i
        }
        i += 1
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}
```
### Challenge

func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            factors.append(i)
            n /= i
        } else {
            i += 1
        }
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            factors.append(i)
            n /= i
        } else {
            i += 1
        }
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}
```
### Challenge

func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var i = 2
    while i * i <= n {
        while n % i == 0 {
            factors.append(i)
            n /= i
        }
        i += 1
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var i = 2
    while i * i <= n {
        while n % i == 0 {
            factors.append(i)
            n /= i
        }
        i += 1
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}
```
### Challenge

func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var i = 2
    while i * i <= n {
        while n % i == 0 {
            factors.append(i)
            n /= i
        }
        i += 1
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var i = 2
    while i * i <= n {
        while n % i == 0 {
            factors.append(i)
            n /= i
        }
        i += 1
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}
```
### Challenge

func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            factors.append(i)
            n /= i
        } else {
            i += 1
        }
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            factors.append(i)
            n /= i
        } else {
            i += 1
        }
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}
```
### Challenge

func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            factors.append(i)
            n /= i
        } else {
            i += 1
        }
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            factors.append(i)
            n /= i
        } else {
            i += 1
        }
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}
```
### Challenge

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    for number in numbers {
        if !result.contains(number) {
            result.append(number)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    for number in numbers {
        if !result.contains(number) {
            result.append(number)
        }
    }
    return result
}
```
### Challenge

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    for number in numbers {
        if !result.contains(number) {
            result.append(number)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    for number in numbers {
        if !result.contains(number) {
            result.append(number)
        }
    }
    return result
}
```
### Challenge

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    for number in numbers {
        if !result.contains(number) {
            result.append(number)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    for number in numbers {
        if !result.contains(number) {
            result.append(number)
        }
    }
    return result
}
```
### Challenge

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    for number in numbers {
        if !result.contains(number) {
            result.append(number)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    for number in numbers {
        if !result.contains(number) {
            result.append(number)
        }
    }
    return result
}
```
### Challenge

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    for number in numbers {
        if !result.contains(number) {
            result.append(number)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    for number in numbers {
        if !result.contains(number) {
            result.append(number)
        }
    }
    return result
}
```
### Challenge

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    for number in numbers {
        if !result.contains(number) {
            result.append(number)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    for number in numbers {
        if !result.contains(number) {
            result.append(number)
        }
    }
    return result
}
```
### Challenge

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    for number in numbers {
        if !result.contains(number) {
            result.append(number)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    for number in numbers {
        if !result.contains(number) {
            result.append(number)
        }
    }
    return result
}
```
### Inst

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    for num in numbers {
        if !result.contains(num) {
            result.append(num)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    for num in numbers {
        if !result.contains(num) {
            result.append(num)
        }
    }
    return result
}
```
### Challenge

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    for num in numbers {
        if !result.contains(num) {
            result.append(num)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    for num in numbers {
        if !result.contains(num) {
            result.append(num)
        }
    }
    return result
}
```
### Challenge

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    for number in numbers {
        if !result.contains(number) {
            result.append(number)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    for number in numbers {
        if !result.contains(number) {
            result.append(number)
        }
    }
    return result
}
```
### Challenge

func flipCase(string: String) -> String {
    var newString = ""
    for char in string {
        if char.isLowercase {
            newString.append(char.uppercased())
        } else {
            newString.append(char.lowercased())
        }
    }
    return newString
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    var newString = ""
    for char in string {
        if char.isLowercase {
            newString.append(char.uppercased())
        } else {
            newString.append(char.lowercased())
        }
    }
    return newString
}
```
### Challenge

func flipCase(string: String) -> String {
    var newString = ""
    for char in string {
        if char.isLowercase {
            newString.append(char.uppercased())
        } else {
            newString.append(char.lowercased())
        }
    }
    return newString
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    var newString = ""
    for char in string {
        if char.isLowercase {
            newString.append(char.uppercased())
        } else {
            newString.append(char.lowercased())
        }
    }
    return newString
}
```
### Challenge

func flipCase(string: String) -> String {
    var result = ""
    for char in string {
        if char.isLowercase {
            result.append(char.uppercased())
        } else if char.isUppercase {
            result.append(char.lowercased())
        } else {
            result.append(char)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    var result = ""
    for char in string {
        if char.isLowercase {
            result.append(char.uppercased())
        } else if char.isUppercase {
            result.append(char.lowercased())
        } else {
            result.append(char)
        }
    }
    return result
}
```
### Challenge

func flipCase(string: String) -> String {
    var result = ""
    for char in string {
        if char.isLowercase {
            result.append(char.uppercased())
        } else if char.isUppercase {
            result.append(char.lowercased())
        } else {
            result.append(char)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    var result = ""
    for char in string {
        if char.isLowercase {
            result.append(char.uppercased())
        } else if char.isUppercase {
            result.append(char.lowercased())
        } else {
            result.append(char)
        }
    }
    return result
}
```
### Challenge

func flipCase(string: String) -> String {
    var newString = ""
    for char in string {
        if char.isLowercase {
            newString.append(char.uppercased())
        } else if char.isUppercase {
            newString.append(char.lowercased())
        } else {
            newString.append(char)
        }
    }
    return newString
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    var newString = ""
    for char in string {
        if char.isLowercase {
            newString.append(char.uppercased())
        } else if char.isUppercase {
            newString.append(char.lowercased())
        } else {
            newString.append(char)
        }
    }
    return newString
}
```
### Challenge

func flipCase(string: String) -> String {
    var newString = ""
    for char in string {
        if char.isLowercase {
            newString.append(char.uppercased())
        } else if char.isUppercase {
            newString.append(char.lowercased())
        } else {
            newString.append(char)
        }
    }
    return newString
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    var newString = ""
    for char in string {
        if char.isLowercase {
            newString.append(char.uppercased())
        } else if char.isUppercase {
            newString.append(char.lowercased())
        } else {
            newString.append(char)
        }
    }
    return newString
}
```
### Challenge

func flipCase(string: String) -> String {
    var result = ""
    for char in string {
        if char.isLowercase {
            result.append(char.uppercased())
        } else if char.isUppercase {
            result.append(char.lowercased())
        } else {
            result.append(char)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    var result = ""
    for char in string {
        if char.isLowercase {
            result.append(char.uppercased())
        } else if char.isUppercase {
            result.append(char.lowercased())
        } else {
            result.append(char)
        }
    }
    return result
}
```
### Challenge

func flipCase(string: String) -> String {
    var result = ""
    for char in string {
        if char.isLowercase {
            result.append(char.uppercased())
        } else {
            result.append(char.lowercased())
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    var result = ""
    for char in string {
        if char.isLowercase {
            result.append(char.uppercased())
        } else {
            result.append(char.lowercased())
        }
    }
    return result
}
```
### Challenge

func flipCase(string: String) -> String {
    var newString = ""
    for char in string {
        if char.isLowercase {
            newString.append(char.uppercased())
        } else if char.isUppercase {
            newString.append(char.lowercased())
        } else {
            newString.append(char)
        }
    }
    return newString
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    var newString = ""
    for char in string {
        if char.isLowercase {
            newString.append(char.uppercased())
        } else if char.isUppercase {
            newString.append(char.lowercased())
        } else {
            newString.append(char)
        }
    }
    return newString
}
```
### Challenge

func flipCase(string: String) -> String {
    var newString = ""
    for char in string {
        if char.isLowercase {
            newString.append(char.uppercased())
        } else {
            newString.append(char.lowercased())
        }
    }
    return newString
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    var newString = ""
    for char in string {
        if char.isLowercase {
            newString.append(char.uppercased())
        } else {
            newString.append(char.lowercased())
        }
    }
    return newString
}
```
### Challenge

func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}
```

func concatenate(strings: [String]) -> String {
  return strings.joined(separator: "")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
  return strings.joined(separator: "")
}
```
### Challenge

func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}
```
### Challenge

func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}
```
### Challenge

func concatenate(strings: [String]) -> String {
  return strings.joined(separator: "")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
  return strings.joined(separator: "")
}
```
### Challenge

func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}
```
### Challenge

func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}
```
### Challenge

func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}
```

func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}
```

func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}
```
### Challenge

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```
### Challenge

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```
### Challenge

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```
### Ex

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```
### Challenge

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```
### Challenge

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```
### Challenge

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```
### Problem

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```
### Challenge

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```
### H

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```
### Challenge

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```
### Challenge

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```
### Challenge

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```
### Inst

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```
### H

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```
### Challenge

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```
### Challenge

func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2..<Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2..<Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2..<Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2..<Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```
### Ex

func isPrime(n: Int) -> Bool {
    if n == 1 {
        return false
    }
    for i in 2...Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n == 1 {
        return false
    }
    for i in 2...Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```
### Ex

func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2..<Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2..<Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```
### Ex

func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2..<Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2..<Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```
### Ex

func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2...Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2...Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2..<Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2..<Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2..<Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2..<Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```
### Ex

func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2..<Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2..<Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```
### Ex

func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2..<Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2..<Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```
### Challenge

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 3 == 0 {
            l.sort()
        }
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 3 == 0 {
            l.sort()
        }
    }
    return l
}
```
### Problem

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 3 == 0 {
            l.sort()
        }
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 3 == 0 {
            l.sort()
        }
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 3 == 0 {
            l.sort()
        }
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 3 == 0 {
            l.sort()
        }
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 3 == 0 {
            l.sort()
        }
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 3 == 0 {
            l.sort()
        }
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 3 == 0 {
            l.sort()
        }
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 3 == 0 {
            l.sort()
        }
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 3 == 0 {
            l.sort()
        }
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 3 == 0 {
            l.sort()
        }
    }
    return l
}
```
### Problem

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 3 == 0 {
            l.sort()
        }
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 3 == 0 {
            l.sort()
        }
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 3 == 0 {
            l.sort()
        }
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 3 == 0 {
            l.sort()
        }
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 3 == 0 {
            l.sort()
        }
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 3 == 0 {
            l.sort()
        }
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 3 == 0 {
            l.sort(by: <)
        }
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 3 == 0 {
            l.sort(by: <)
        }
    }
    return l
}
```

func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    for i in l {
        if !result.contains(i) {
            result.append(i)
        }
    }
    return result.sorted()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    for i in l {
        if !result.contains(i) {
            result.append(i)
        }
    }
    return result.sorted()
}
```
### Inst

func unique(l: [Int]) -> [Int] {
    return Array(Set(l)).sorted()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    return Array(Set(l)).sorted()
}
```
### Inst

func unique(l: [Int]) -> [Int] {
    return Array(Set(l)).sorted()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    return Array(Set(l)).sorted()
}
```
### Inst

func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    for i in l {
        if !result.contains(i) {
            result.append(i)
        }
    }
    return result.sorted()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    for i in l {
        if !result.contains(i) {
            result.append(i)
        }
    }
    return result.sorted()
}
```
### Inst

func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    for i in l {
        if !result.contains(i) {
            result.append(i)
        }
    }
    return result.sorted()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    for i in l {
        if !result.contains(i) {
            result.append(i)
        }
    }
    return result.sorted()
}
```
### Inst

func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    for i in l {
        if !result.contains(i) {
            result.append(i)
        }
    }
    return result.sorted()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    for i in l {
        if !result.contains(i) {
            result.append(i)
        }
    }
    return result.sorted()
}
```
### Inst

func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    for i in l {
        if !result.contains(i) {
            result.append(i)
        }
    }
    return result.sorted()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    for i in l {
        if !result.contains(i) {
            result.append(i)
        }
    }
    return result.sorted()
}
```
### Inst

func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    for i in l {
        if !result.contains(i) {
            result.append(i)
        }
    }
    return result.sorted()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    for i in l {
        if !result.contains(i) {
            result.append(i)
        }
    }
    return result.sorted()
}
```
### Inst

func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    for i in l {
        if !result.contains(i) {
            result.append(i)
        }
    }
    return result.sorted()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    for i in l {
        if !result.contains(i) {
            result.append(i)
        }
    }
    return result.sorted()
}
```
### Inst

func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    for i in l {
        if !result.contains(i) {
            result.append(i)
        }
    }
    return result.sorted()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    for i in l {
        if !result.contains(i) {
            result.append(i)
        }
    }
    return result.sorted()
}
```
### Inst

func maxElement(l: [Int]) -> Int {
    return l.maxElement()!
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    return l.maxElement()!
}
```
### [

func maxElement(l: [Int]) -> Int {
    return l.maxElement()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    return l.maxElement()
}
```
### Challenge

func maxElement(l: [Int]) -> Int {
    return l.maxElement()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    return l.maxElement()
}
```
### [

func maxElement(l: [Int]) -> Int {
    return l.max()!
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max()!
}
```
### Problem

func maxElement(l: [Int]) -> Int {
    return l.max()!
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max()!
}
```
### [

func maxElement(l: [Int]) -> Int {
    return l.max()!
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max()!
}
```
### Problem

func maxElement(l: [Int]) -> Int {
    return l.maxElement()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    return l.maxElement()
}
```
### [

func maxElement(l: [Int]) -> Int {
    return l.max()!
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max()!
}
```
### Challenge

func maxElement(l: [Int]) -> Int {
    return l.max()!
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max()!
}
```
### [

func maxElement(l: [Int]) -> Int {
    return l.maxElement()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    return l.maxElement()
}
```
### [

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            count += 1
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            count += 1
        }
    }
    return count
}
```
### Version

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            count += 1
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            count += 1
        }
    }
    return count
}
```
### Ex

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            count += 1
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            count += 1
        }
    }
    return count
}
```
### Version

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            count += 1
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            count += 1
        }
    }
    return count
}
```
### Version

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            count += 1
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            count += 1
        }
    }
    return count
}
```
### Version

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            count += 1
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            count += 1
        }
    }
    return count
}
```
### Version

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            count += 1
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            count += 1
        }
    }
    return count
}
```
### Version

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            count += 1
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            count += 1
        }
    }
    return count
}
```
### Version

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            count += 1
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            count += 1
        }
    }
    return count
}
```
### Version

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            count += 1
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            count += 1
        }
    }
    return count
}
```
### Ex

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        l[i] = l[i].sorted().first!
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        l[i] = l[i].sorted().first!
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 2 == 0 {
            l[i] = l[i].sorted()
        }
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 2 == 0 {
            l[i] = l[i].sorted()
        }
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        l[i] = l[i].sorted()
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        l[i] = l[i].sorted()
    }
    return l
}
```
### Challenge

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 2 == 0 {
            l[i] = l[i].sorted()
        }
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 2 == 0 {
            l[i] = l[i].sorted()
        }
    }
    return l
}
```
### Question

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count where i % 2 == 0 {
        l[i] = l[i]
        l[i] = l[i].sorted()
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count where i % 2 == 0 {
        l[i] = l[i]
        l[i] = l[i].sorted()
    }
    return l
}
```
### Ex

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 2 == 0 {
            l[i] = l[i].sorted()
        }
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 2 == 0 {
            l[i] = l[i].sorted()
        }
    }
    return l
}
```
### Problem

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        l[i] = l[i].sorted()
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        l[i] = l[i].sorted()
    }
    return l
}
```
### Problem

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        l[i] = l[i].sorted()
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        l[i] = l[i].sorted()
    }
    return l
}
```
### Problem

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 2 == 0 {
            l[i] = l[i].sorted().first
        }
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 2 == 0 {
            l[i] = l[i].sorted().first
        }
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count where i % 2 == 0 {
        l[i] = l[i].sorted().first!
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count where i % 2 == 0 {
        l[i] = l[i].sorted().first!
    }
    return l
}
```
### Problem

func primeFib(n: Int) -> Int {
    var fib = 0
    var prime = 0
    for i in 1...n {
        fib = fib + prime
        if isPrime(fib) {
            prime = fib
        }
    }
    return prime
}

func isPrime(n: Int) -> Bool {
    if n == 1 {
        return false
    }
    for i in 2...Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var fib = 0
    var prime = 0
    for i in 1...n {
        fib = fib + prime
        if isPrime(fib) {
            prime = fib
        }
    }
    return prime
}

func isPrime(n: Int) -> Bool {
    if n == 1 {
        return false
    }
    for i in 2...Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```
### Problem

func primeFib(n: Int) -> Int {
    var fib = [1, 1]
    var prime = [2]
    for i in 2..<n {
        fib.append(fib[i-1] + fib[i-2])
        if isPrime(fib[i]) {
            prime.append(fib[i])
        }
    }
    return prime[n-1]
}

func isPrime(_ n: Int) -> Bool {
    if n == 1 {
        return false
    }
    for i in 2..<Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var fib = [1, 1]
    var prime = [2]
    for i in 2..<n {
        fib.append(fib[i-1] + fib[i-2])
        if isPrime(fib[i]) {
            prime.append(fib[i])
        }
    }
    return prime[n-1]
}

func isPrime(_ n: Int) -> Bool {
    if n == 1 {
        return false
    }
    for i in 2..<Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```
### Problem

func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var fib = 0
    var isPrime = false
    for i in 1...n {
        fib = a + b
        a = b
        b = fib
        if fib > 1000000 {
            break
        }
        isPrime = true
        for j in 2...Int(sqrt(Double(fib))) {
            if fib % j == 0 {
                isPrime = false
                break
            }
        }
        if isPrime {
            return fib
        }
    }
    return 0
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var fib = 0
    var isPrime = false
    for i in 1...n {
        fib = a + b
        a = b
        b = fib
        if fib > 1000000 {
            break
        }
        isPrime = true
        for j in 2...Int(sqrt(Double(fib))) {
            if fib % j == 0 {
                isPrime = false
                break
            }
        }
        if isPrime {
            return fib
        }
    }
    return 0
}
```
### Problem

func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var fib = 1
    var i = 0
    while i < n {
        fib = a + b
        a = b
        b = fib
        i += 1
    }
    return fib
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var fib = 1
    var i = 0
    while i < n {
        fib = a + b
        a = b
        b = fib
        i += 1
    }
    return fib
}
```
### Challenge

func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var fib = 0
    var isPrime = false
    for _ in 1...n {
        fib = a + b
        a = b
        b = fib
        if isPrime(fib) {
            isPrime = true
        } else {
            isPrime = false
        }
    }
    return fib
}

func isPrime(n: Int) -> Bool {
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            return false
        }
        i += 1
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var fib = 0
    var isPrime = false
    for _ in 1...n {
        fib = a + b
        a = b
        b = fib
        if isPrime(fib) {
            isPrime = true
        } else {
            isPrime = false
        }
    }
    return fib
}

func isPrime(n: Int) -> Bool {
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            return false
        }
        i += 1
    }
    return true
}
```
### Problem

func primeFib(n: Int) -> Int {
    var fib = 0
    var prime = 0
    for i in 0...n {
        fib = fibonacci(n: i)
        if isPrime(n: fib) {
            prime = fib
        }
    }
    return prime
}

func fibonacci(n: Int) -> Int {
    if n == 0 {
        return 0
    } else if n == 1 {
        return 1
    } else {
        return fibonacci(n: n-1) + fibonacci(n: n-2)
    }
}

func isPrime(n: Int) -> Bool {
    if n == 1 {
        return false
    } else {
        for i in 2...Int(sqrt(Double(n))) {
            if n % i == 0 {
                return false
            }
        }
        return true
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var fib = 0
    var prime = 0
    for i in 0...n {
        fib = fibonacci(n: i)
        if isPrime(n: fib) {
            prime = fib
        }
    }
    return prime
}

func fibonacci(n: Int) -> Int {
    if n == 0 {
        return 0
    } else if n == 1 {
        return 1
    } else {
        return fibonacci(n: n-1) + fibonacci(n: n-2)
    }
}

func isPrime(n: Int) -> Bool {
    if n == 1 {
        return false
    } else {
        for i in 2...Int(sqrt(Double(n))) {
            if n % i == 0 {
                return false
            }
        }
        return true
    }
}
```
### Problem

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var c = a + b
    var d = 0
    var e = 0
    var f = 0
    var g = 0
    var h = 0
    var i = 0
    var j = 0
    var k = 0
    var l = 0
    var m = 0
    var n = 0
    var o = 0
    var p = 0
    var q = 0
    var r = 0
    var s = 0
    var t = 0
    var u = 0
    var v = 0
    var w = 0
    var x = 0
    var y = 0
    var z = 0
    var zz = 0
    var zzz = 0
    var zzzz = 0
    var zzzzz = 0
    var zzzzzz = 0
    var zzzzzzz = 0
    var zzzzzzzz = 0
    var zzzzzzzzz = 0
    var zzzzzzzzzz = 0
    var zzzzzzzzzzz = 0
    var zzzzzzzzzzzz = 0
    var zzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz = 0
    var zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz

func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var fib = 0
    for _ in 1...n {
        fib = a + b
        a = b
        b = fib
        if fib % 2 == 0 && fib % 3 == 0 {
            return fib
        }
    }
    return fib
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var fib = 0
    for _ in 1...n {
        fib = a + b
        a = b
        b = fib
        if fib % 2 == 0 && fib % 3 == 0 {
            return fib
        }
    }
    return fib
}
```
### Problem

func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var fib = 1
    var isPrime = false
    for _ in 1...n {
        a = b
        b = fib
        fib = a + b
        if fib % 2 == 0 {
            isPrime = true
        } else {
            isPrime = false
        }
    }
    return fib
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var fib = 1
    var isPrime = false
    for _ in 1...n {
        a = b
        b = fib
        fib = a + b
        if fib % 2 == 0 {
            isPrime = true
        } else {
            isPrime = false
        }
    }
    return fib
}
```
### Problem

func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var c = a + b
    for _ in 1...n {
        a = b
        b = c
        c = a + b
    }
    return c
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var c = a + b
    for _ in 1...n {
        a = b
        b = c
        c = a + b
    }
    return c
}
```
### Ex

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count-1 {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count-1 {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```
### Ex

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count-1 {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count-1 {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```
### Ex

func triplesSumToZero(l: [Int]) -> Bool {
    var seen = Set<Int>()
    for i in l {
        for j in l {
            if i + j == 0 && !seen.contains(i) && !seen.contains(j) {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    var seen = Set<Int>()
    for i in l {
        for j in l {
            if i + j == 0 && !seen.contains(i) && !seen.contains(j) {
                return true
            }
        }
    }
    return false
}
```
### Problem

func triplesSumToZero(l: [Int]) -> Bool {
    var seen = Set<Int>()
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 && !seen.contains(l[i]) && !seen.contains(l[j]) && !seen.contains(l[k]) {
                    return true
                }
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    var seen = Set<Int>()
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 && !seen.contains(l[i]) && !seen.contains(l[j]) && !seen.contains(l[k]) {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count-1 {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count-1 {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```
### Problem

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count-1 {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count-1 {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count-1 {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count-1 {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```
### Ex

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count-1 {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count-1 {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```
### Problem

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count-1 {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count-1 {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```
### Ex

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count-1 {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count-1 {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```
### Ex

func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}
```
### Ex

func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}
```

func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}
```

func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}
```

func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}
```

func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}
```

func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}
```

func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}
```

func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}
```
### Ex

func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}
```
### Ex

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```
### [

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```
### [

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```
### [

func incrList(l: [Int]) -> [Int] {
    return l.map({$0 + 1})
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map({$0 + 1})
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```
### Challenge

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```
### Challenge

func incrList(l: [Int]) -> [Int] {
    return l.map({$0 + 1})
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map({$0 + 1})
}
```
### Problem

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```
### Challenge

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```
### Problem

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```
### Problem

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var seen = Set<Int>()
    for i in l {
        if seen.contains(-i) {
            return true
        }
        seen.insert(i)
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var seen = Set<Int>()
    for i in l {
        if seen.contains(-i) {
            return true
        }
        seen.insert(i)
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```
### Problem

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```
### Question

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    while x > 0 {
        result = String(x % base) + result
        x /= base
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    while x > 0 {
        result = String(x % base) + result
        x /= base
    }
    return result
}
```
### Challenge

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    while x > 0 {
        result = String(x % base) + result
        x /= base
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    while x > 0 {
        result = String(x % base) + result
        x /= base
    }
    return result
}
```
### Challenge

func changeBase(x: Int, base: Int) -> String {
    return String(x, radix: base)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    return String(x, radix: base)
}
```
### Problem

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    while x > 0 {
        result = String(x % base) + result
        x /= base
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    while x > 0 {
        result = String(x % base) + result
        x /= base
    }
    return result
}
```
### Ex

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var remainder = x
    while remainder > 0 {
        result = String(remainder % base) + result
        remainder = remainder / base
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var remainder = x
    while remainder > 0 {
        result = String(remainder % base) + result
        remainder = remainder / base
    }
    return result
}
```
### Problem

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    while x > 0 {
        result = String(x % base) + result
        x /= base
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    while x > 0 {
        result = String(x % base) + result
        x /= base
    }
    return result
}
```
### Challenge

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var remainder = x
    while remainder > 0 {
        result = String(remainder % base) + result
        remainder /= base
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var remainder = x
    while remainder > 0 {
        result = String(remainder % base) + result
        remainder /= base
    }
    return result
}
```
### Challenge

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    while x > 0 {
        result = String(x % base) + result
        x /= base
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    while x > 0 {
        result = String(x % base) + result
        x /= base
    }
    return result
}
```
### Challenge

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var remainder = x
    while remainder > 0 {
        result = String(remainder % base) + result
        remainder = remainder / base
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var remainder = x
    while remainder > 0 {
        result = String(remainder % base) + result
        remainder = remainder / base
    }
    return result
}
```
### Problem

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var remainder = x
    while remainder > 0 {
        result = String(remainder % base) + result
        remainder /= base
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var remainder = x
    while remainder > 0 {
        result = String(remainder % base) + result
        remainder /= base
    }
    return result
}
```
### Challenge

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```
### Challenge

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```
### Challenge

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```
### Challenge

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2.0
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2.0
}
```
### Challenge

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2.0
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2.0
}
```
### Challenge

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2.0
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2.0
}
```
### Challenge

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```
### Challenge

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2.0
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2.0
}
```
### Challenge

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```
### Challenge

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2.0
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2.0
}
```
### Challenge

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    switch n {
    case 0:
        return a
    case 1:
        return b
    case 2:
        return c
    case 3:
        return d
    default:
        break
    }
    for i in 4...n {
        a = b
        b = c
        c = d
        d = a + b + c + d
    }
    return d
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    switch n {
    case 0:
        return a
    case 1:
        return b
    case 2:
        return c
    case 3:
        return d
    default:
        break
    }
    for i in 4...n {
        a = b
        b = c
        c = d
        d = a + b + c + d
    }
    return d
}
```
### Inst

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    switch n {
    case 0:
        return a
    case 1:
        return b
    case 2:
        return c
    case 3:
        return d
    default:
        for i in 0..<n {
            let temp = a + b + c + d
            a = b
            b = c
            c = d
            d = temp
        }
        return d
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    switch n {
    case 0:
        return a
    case 1:
        return b
    case 2:
        return c
    case 3:
        return d
    default:
        for i in 0..<n {
            let temp = a + b + c + d
            a = b
            b = c
            c = d
            d = temp
        }
        return d
    }
}
```
### Challenge

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    switch n {
    case 0:
        return a
    case 1:
        return b
    case 2:
        return c
    case 3:
        return d
    default:
        break
    }
    for i in 0..<n {
        let temp = a + b + c + d
        a = b
        b = c
        c = d
        d = temp
    }
    return d
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    switch n {
    case 0:
        return a
    case 1:
        return b
    case 2:
        return c
    case 3:
        return d
    default:
        break
    }
    for i in 0..<n {
        let temp = a + b + c + d
        a = b
        b = c
        c = d
        d = temp
    }
    return d
}
```
### Challenge

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    switch n {
    case 0:
        return a
    case 1:
        return b
    case 2:
        return c
    case 3:
        return d
    default:
        break
    }
    for i in 4...n {
        a = b
        b = c
        c = d
        d = a + b + c + d
    }
    return d
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    switch n {
    case 0:
        return a
    case 1:
        return b
    case 2:
        return c
    case 3:
        return d
    default:
        break
    }
    for i in 4...n {
        a = b
        b = c
        c = d
        d = a + b + c + d
    }
    return d
}
```
### Inst

func fib4(n: Int) -> Int {
    var a = 0, b = 0, c = 0, d = 0
    switch n {
    case 0: return a
    case 1: return b
    case 2: return c
    case 3: return d
    default:
        for i in 0..<n {
            let t = a + b + c + d
            a = b
            b = c
            c = d
            d = t
        }
        return d
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var a = 0, b = 0, c = 0, d = 0
    switch n {
    case 0: return a
    case 1: return b
    case 2: return c
    case 3: return d
    default:
        for i in 0..<n {
            let t = a + b + c + d
            a = b
            b = c
            c = d
            d = t
        }
        return d
    }
}
```
### Inst

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    switch n {
    case 0:
        return a
    case 1:
        return b
    case 2:
        return c
    case 3:
        return d
    default:
        for i in 4...n {
            a = b
            b = c
            c = d
            d = a + b + c + d
        }
        return d
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    switch n {
    case 0:
        return a
    case 1:
        return b
    case 2:
        return c
    case 3:
        return d
    default:
        for i in 4...n {
            a = b
            b = c
            c = d
            d = a + b + c + d
        }
        return d
    }
}
```
### Inst

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    switch n {
    case 0:
        return a
    case 1:
        return b
    case 2:
        return c
    case 3:
        return d
    default:
        break
    }
    for i in 4...n {
        a = b
        b = c
        c = d
        d = a + b + c + d
    }
    return d
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    switch n {
    case 0:
        return a
    case 1:
        return b
    case 2:
        return c
    case 3:
        return d
    default:
        break
    }
    for i in 4...n {
        a = b
        b = c
        c = d
        d = a + b + c + d
    }
    return d
}
```
### Inst

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    switch n {
    case 0:
        return a
    case 1:
        return b
    case 2:
        return c
    case 3:
        return d
    default:
        break
    }
    for i in 0..<n {
        let temp = a + b + c + d
        a = b
        b = c
        c = d
        d = temp
    }
    return d
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    switch n {
    case 0:
        return a
    case 1:
        return b
    case 2:
        return c
    case 3:
        return d
    default:
        break
    }
    for i in 0..<n {
        let temp = a + b + c + d
        a = b
        b = c
        c = d
        d = temp
    }
    return d
}
```
### Inst

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    switch n {
    case 0:
        return a
    case 1:
        return b
    case 2:
        return c
    case 3:
        return d
    default:
        for i in 0..<n {
            let temp = a + b + c + d
            a = b
            b = c
            c = d
            d = temp
        }
        return d
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    switch n {
    case 0:
        return a
    case 1:
        return b
    case 2:
        return c
    case 3:
        return d
    default:
        for i in 0..<n {
            let temp = a + b + c + d
            a = b
            b = c
            c = d
            d = temp
        }
        return d
    }
}
```
### Inst

func fib4(n: Int) -> Int {
    var a = 0, b = 0, c = 0, d = 0
    switch n {
    case 0: return a
    case 1: return b
    case 2: return c
    case 3: return d
    default:
        for _ in 0..<n {
            (a, b, c, d) = (b, c, d, a + b + c + d)
        }
        return d
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var a = 0, b = 0, c = 0, d = 0
    switch n {
    case 0: return a
    case 1: return b
    case 2: return c
    case 3: return d
    default:
        for _ in 0..<n {
            (a, b, c, d) = (b, c, d, a + b + c + d)
        }
        return d
    }
}
```
### Ex

func median(l: [Int]) -> Double {
    let n = Double(l.count)
    let sorted = l.sorted()
    if n % 2 == 0 {
        return Double(sorted[Int(n / 2)] + sorted[Int(n / 2) - 1]) / 2
    } else {
        return Double(sorted[Int(n / 2)])
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let n = Double(l.count)
    let sorted = l.sorted()
    if n % 2 == 0 {
        return Double(sorted[Int(n / 2)] + sorted[Int(n / 2) - 1]) / 2
    } else {
        return Double(sorted[Int(n / 2)])
    }
}
```
### Ex

func median(l: [Int]) -> Double {
    let l = l.sorted()
    let n = l.count
    if n % 2 == 0 {
        return Double(l[n / 2 - 1] + l[n / 2]) / 2
    } else {
        return Double(l[n / 2])
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let l = l.sorted()
    let n = l.count
    if n % 2 == 0 {
        return Double(l[n / 2 - 1] + l[n / 2]) / 2
    } else {
        return Double(l[n / 2])
    }
}
```
### Ex

func median(l: [Int]) -> Double {
    let l = l.sorted()
    let n = Double(l.count)
    if n % 2 == 0 {
        return Double(l[Int(n / 2)] + l[Int(n / 2) - 1]) / 2
    } else {
        return Double(l[Int(n / 2)])
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let l = l.sorted()
    let n = Double(l.count)
    if n % 2 == 0 {
        return Double(l[Int(n / 2)] + l[Int(n / 2) - 1]) / 2
    } else {
        return Double(l[Int(n / 2)])
    }
}
```
### Ex

func median(l: [Int]) -> Double {
    let l = l.sorted()
    let n = l.count
    if n % 2 == 0 {
        return Double(l[n / 2] + l[n / 2 - 1]) / 2
    } else {
        return Double(l[n / 2])
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let l = l.sorted()
    let n = l.count
    if n % 2 == 0 {
        return Double(l[n / 2] + l[n / 2 - 1]) / 2
    } else {
        return Double(l[n / 2])
    }
}
```
### Ex

func median(l: [Int]) -> Double {
    let l = l.sorted()
    let n = l.count
    if n % 2 == 0 {
        return Double(l[n/2] + l[n/2 - 1]) / 2
    } else {
        return Double(l[n/2])
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let l = l.sorted()
    let n = l.count
    if n % 2 == 0 {
        return Double(l[n/2] + l[n/2 - 1]) / 2
    } else {
        return Double(l[n/2])
    }
}
```
### Ex

func median(l: [Int]) -> Double {
    let l = l.sorted()
    let n = Double(l.count)
    let m = l[Int(n/2)]
    return m
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let l = l.sorted()
    let n = Double(l.count)
    let m = l[Int(n/2)]
    return m
}
```
### Challenge

func median(l: [Int]) -> Double {
    let l = l.sorted()
    let n = l.count
    if n % 2 == 0 {
        return Double(l[n / 2] + l[n / 2 - 1]) / 2
    } else {
        return Double(l[n / 2])
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let l = l.sorted()
    let n = l.count
    if n % 2 == 0 {
        return Double(l[n / 2] + l[n / 2 - 1]) / 2
    } else {
        return Double(l[n / 2])
    }
}
```
### Challenge

func median(l: [Int]) -> Double {
    let n = l.count
    let sorted = l.sorted()
    if n % 2 == 0 {
        return Double(sorted[n / 2 - 1] + sorted[n / 2]) / 2
    } else {
        return Double(sorted[n / 2])
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let n = l.count
    let sorted = l.sorted()
    if n % 2 == 0 {
        return Double(sorted[n / 2 - 1] + sorted[n / 2]) / 2
    } else {
        return Double(sorted[n / 2])
    }
}
```
### Ex

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let n = Double(l.count)
    if n % 2 == 0 {
        return Double(sorted[Int(n / 2) - 1] + sorted[Int(n / 2)]) / 2
    } else {
        return Double(sorted[Int(n / 2)])
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let n = Double(l.count)
    if n % 2 == 0 {
        return Double(sorted[Int(n / 2) - 1] + sorted[Int(n / 2)]) / 2
    } else {
        return Double(sorted[Int(n / 2)])
    }
}
```
### Challenge

func median(l: [Int]) -> Double {
    let l = l.sorted()
    let n = l.count
    if n % 2 == 0 {
        return Double(l[n/2] + l[n/2 - 1]) / 2
    } else {
        return Double(l[n/2])
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let l = l.sorted()
    let n = l.count
    if n % 2 == 0 {
        return Double(l[n/2] + l[n/2 - 1]) / 2
    } else {
        return Double(l[n/2])
    }
}
```
### Challenge

func isPalindrome(text: String) -> Bool {
    let text = text.lowercased()
    let reversed = String(text.reversed())
    return text == reversed
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    let text = text.lowercased()
    let reversed = String(text.reversed())
    return text == reversed
}
```

func isPalindrome(text: String) -> Bool {
    let text = text.lowercased()
    let reversed = String(text.reversed())
    return text == reversed
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    let text = text.lowercased()
    let reversed = String(text.reversed())
    return text == reversed
}
```
### Ex

func isPalindrome(text: String) -> Bool {
    let text = text.lowercased()
    let reversedText = String(text.reversed())
    return text == reversedText
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    let text = text.lowercased()
    let reversedText = String(text.reversed())
    return text == reversedText
}
```

func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}
```

func isPalindrome(text: String) -> Bool {
    let text = text.lowercased()
    let reversed = String(text.reversed())
    return text == reversed
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    let text = text.lowercased()
    let reversed = String(text.reversed())
    return text == reversed
}
```

func isPalindrome(text: String) -> Bool {
    let text = text.lowercased()
    let reversed = String(text.reversed())
    return text == reversed
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    let text = text.lowercased()
    let reversed = String(text.reversed())
    return text == reversed
}
```
### Ex

func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}
```
### Ex

func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}
```

func isPalindrome(text: String) -> Bool {
    let text = text.lowercased()
    let reversed = String(text.reversed())
    return text == reversed
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    let text = text.lowercased()
    let reversed = String(text.reversed())
    return text == reversed
}
```

func isPalindrome(text: String) -> Bool {
    let text = text.lowercased()
    let reversed = String(text.reversed())
    return text == reversed
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    let text = text.lowercased()
    let reversed = String(text.reversed())
    return text == reversed
}
```

func modp(n: Int, p: Int) -> Int {
    return n % p
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
### Response:
```swift
func modp(n: Int, p: Int) -> Int {
    return n % p
}
```
### Problem

func modp(n: Int, p: Int) -> Int {
    return n % p
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
### Response:
```swift
func modp(n: Int, p: Int) -> Int {
    return n % p
}
```

func modp(n: Int, p: Int) -> Int {
    return n % p
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
### Response:
```swift
func modp(n: Int, p: Int) -> Int {
    return n % p
}
```
### Challenge

func modp(n: Int, p: Int) -> Int {
    return n % p
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
### Response:
```swift
func modp(n: Int, p: Int) -> Int {
    return n % p
}
```

func modp(n: Int, p: Int) -> Int {
    return n % p
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
### Response:
```swift
func modp(n: Int, p: Int) -> Int {
    return n % p
}
```

func modp(n: Int, p: Int) -> Int {
    return n % p
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
### Response:
```swift
func modp(n: Int, p: Int) -> Int {
    return n % p
}
```