func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}
<|file_separator|>

func solution(lst: [Int]) -> Int {
    var result = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            result += value
        }
    }
    return result
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var result = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            result += value
        }
    }
    return result
}
<|file_separator|>

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}
<|file_separator|>

func solution(lst: [Int]) -> Int {
  var result = 0
  for (index, value) in lst.enumerated() {
    if index % 2 == 0 {
      if value % 2 == 1 {
        result += value
      }
    }
  }
  return result
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
  var result = 0
  for (index, value) in lst.enumerated() {
    if index % 2 == 0 {
      if value % 2 == 1 {
        result += value
      }
    }
  }
  return result
}
<|file_separator|>

func solution(lst: [Int]) -> Int {
  var sum = 0
  for i in 0..<lst.count {
    if i % 2 == 0 {
      sum += lst[i]
    }
  }
  return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
  var sum = 0
  for i in 0..<lst.count {
    if i % 2 == 0 {
      sum += lst[i]
    }
  }
  return sum
}
<|file_separator|>

func solution(lst: [Int]) -> Int {
    return lst.filter { $0 % 2 == 1 }.reduce(0, +)
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.filter { $0 % 2 == 1 }.reduce(0, +)
}
<|file_separator|>

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}
<|file_separator|>

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}
<|file_separator|>

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            if value % 2 != 0 {
                sum += value
            }
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            if value % 2 != 0 {
                sum += value
            }
        }
    }
    return sum
}
<|file_separator|>

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}
<|file_separator|>

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().reduce(0) { (result, element) in
        if element.offset % 2 == 0 {
            return result
        }
        return result + element.element
    }
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.enumerated().reduce(0) { (result, element) in
        if element.offset % 2 == 0 {
            return result
        }
        return result + element.element
    }
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().reduce(0) {
        $1.offset % 2 == 1? $0 + $1.element : $0
    }
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.enumerated().reduce(0) {
        $1.offset % 2 == 1? $0 + $1.element : $0
    }
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().reduce(0) {
        $0 + ($1.offset % 2 == 1? $1.element : 0)
    }
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.enumerated().reduce(0) {
        $0 + ($1.offset % 2 == 1? $1.element : 0)
    }
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().reduce(0) {
        $0 + ($1.offset % 2 == 1? $1.element : 0)
    }
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.enumerated().reduce(0) {
        $0 + ($1.offset % 2 == 1? $1.element : 0)
    }
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().reduce(0) {
        $0 + ($1.offset % 2 == 1? $1.element : 0)
    }
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.enumerated().reduce(0) {
        $0 + ($1.offset % 2 == 1? $1.element : 0)
    }
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().reduce(0) {
        $0 + ($1.offset % 2 == 1? $1.element : 0)
    }
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.enumerated().reduce(0) {
        $0 + ($1.offset % 2 == 1? $1.element : 0)
    }
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().reduce(0) { (result, element) in
        return result + (element.offset % 2!= 0 && element.element % 2!= 0? element.element : 0)
    }
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.enumerated().reduce(0) { (result, element) in
        return result + (element.offset % 2!= 0 && element.element % 2!= 0? element.element : 0)
    }
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().reduce(0) {
        $0 + ($1.offset % 2 == 0 && $1.element.isOdd? $1.element : 0)
    }
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.enumerated().reduce(0) {
        $0 + ($1.offset % 2 == 0 && $1.element.isOdd? $1.element : 0)
    }
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().reduce(0) {
        $0 + ($1.offset % 2 == 0 && $1.element.isOdd? $1.element : 0)
    }
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.enumerated().reduce(0) {
        $0 + ($1.offset % 2 == 0 && $1.element.isOdd? $1.element : 0)
    }
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }.reduce(0, +)
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }.reduce(0, +)
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 1 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 1 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 1 && element % 2 == 1 {
            sum += element
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 1 && element % 2 == 1 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 1 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 1 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 1 && element % 2 == 1 {
            sum += element
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 1 && element % 2 == 1 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 1 && element % 2 == 1 {
            sum += element
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 1 && element % 2 == 1 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 1 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 1 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 1 && element % 2 == 1 {
            sum += element
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 1 && element % 2 == 1 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if value % 2 == 1 && index % 2 == 0 {
            sum += value
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if value % 2 == 1 && index % 2 == 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if value % 2 == 1 && index % 2 == 0 {
            sum += value
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if value % 2 == 1 && index % 2 == 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if value % 2 == 1 && index % 2 == 0 {
            sum += value
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if value % 2 == 1 && index % 2 == 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}
```

import Foundation

func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
    guard lhs[0].count == rhs.count else { 
        return nil 
    }
    
    var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
    for i in 0..<lhs.count {
        for j in 0..<rhs[0].count {
            for k in 0..<rhs.count {
                result[i][j] += lhs[i][k] * rhs[k][j]
            }
        }
    }
    
    return result
}

```swift
import Foundation

/* 
 Function to multiply two matrices represented as 2D arrays of Doubles.
 Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
 */
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
    guard lhs[0].count == rhs.count else { 
        return nil 
    }
    
    var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
    for i in 0..<lhs.count {
        for j in 0..<rhs[0].count {
            for k in 0..<rhs.count {
                result[i][j] += lhs[i][k] * rhs[k][j]
            }
        }
    }
    
    return result
}

/*
 Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
 Examples
 solution(lst: [5, 8, 7, 1]) == 12
 solution(lst: [3, 3, 3, 3, 3]) == 9
 solution(lst: [30, 13, 24, 321]) == 0
 */
func solution(lst: [Int]) -> Int {
    
    
    
    

import Foundation

func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
    guard lhs[0].count == rhs.count else { 
        return nil 
    }
    
    var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
    for i in 0..<lhs.count {
        for j in 0..<rhs[0].count {
            for k in 0..<rhs.count {
                result[i][j] += lhs[i][k] * rhs[k][j]
            }
        }
    }
    
    return result
}

```swift
import Foundation

/* 
 Function to multiply two matrices represented as 2D arrays of Doubles.
 Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
 */
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
    guard lhs[0].count == rhs.count else { 
        return nil 
    }
    
    var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
    for i in 0..<lhs.count {
        for j in 0..<rhs[0].count {
            for k in 0..<rhs.count {
                result[i][j] += lhs[i][k] * rhs[k][j]
            }
        }
    }
    
    return result
}

/*
 Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
 Examples
 solution(lst: [5, 8, 7, 1]) == 12
 solution(lst: [3, 3, 3, 3, 3]) == 9
 solution(lst: [30, 13, 24, 321]) == 0
 */
func solution(lst: [Int]) -> Int {
    
    
    
    
    var result = 0

import Foundation

func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
    guard lhs[0].count == rhs.count else { 
        return nil 
    }
    
    var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
    for i in 0..<lhs.count {
        for j in 0..<rhs[0].count {
            for k in 0..<rhs.count {
                result[i][j] += lhs[i][k] * rhs[k][j]
            }
        }
    }
    
    return result
}

```swift
import Foundation

/* 
 Function to multiply two matrices represented as 2D arrays of Doubles.
 Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
 */
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
    guard lhs[0].count == rhs.count else { 
        return nil 
    }
    
    var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
    for i in 0..<lhs.count {
        for j in 0..<rhs[0].count {
            for k in 0..<rhs.count {
                result[i][j] += lhs[i][k] * rhs[k][j]
            }
        }
    }
    
    return result
}

/*
 Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
 Examples
 solution(lst: [5, 8, 7, 1]) == 12
 solution(lst: [3, 3, 3, 3, 3]) == 9
 solution(lst: [30, 13, 24, 321]) == 0
 */
func solution(lst: [Int]) -> Int {
    
    

import Foundation

func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
    guard lhs[0].count == rhs.count else { 
        return nil 
    }
    
    var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
    for i in 0..<lhs.count {
        for j in 0..<rhs[0].count {
            for k in 0..<rhs.count {
                result[i][j] += lhs[i][k] * rhs[k][j]
            }
        }
    }
    
    return result
}

```swift
import Foundation

/* 
 Function to multiply two matrices represented as 2D arrays of Doubles.
 Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
 */
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
    guard lhs[0].count == rhs.count else { 
        return nil 
    }
    
    var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
    for i in 0..<lhs.count {
        for j in 0..<rhs[0].count {
            for k in 0..<rhs.count {
                result[i][j] += lhs[i][k] * rhs[k][j]
            }
        }
    }
    
    return result
}

/*
 Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
 Examples
 solution(lst: [5, 8, 7, 1]) == 12
 solution(lst: [3, 3, 3, 3, 3]) == 9
 solution(lst: [30, 13, 24, 321]) == 0
 */
func solution(lst: [Int]) -> Int {
    
    
    
    var result = [[Double](repeekt =

import Foundation

func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
    guard lhs[0].count == rhs.count else { 
        return nil 
    }
    
    var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
    for i in 0..<lhs.count {
        for j in 0..<rhs[0].count {
            for k in 0..<rhs.count {
                result[i][j] += lhs[i][k] * rhs[k][j]
            }
        }
    }
    
    return result
}

```swift
import Foundation

/* 
 Function to multiply two matrices represented as 2D arrays of Doubles.
 Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
 */
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
    guard lhs[0].count == rhs.count else { 
        return nil 
    }
    
    var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
    for i in 0..<lhs.count {
        for j in 0..<rhs[0].count {
            for k in 0..<rhs.count {
                result[i][j] += lhs[i][k] * rhs[k][j]
            }
        }
    }
    
    return result
}

/*
 Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
 Examples
 solution(lst: [5, 8, 7, 1]) == 12
 solution(lst: [3, 3, 3, 3, 3]) == 9
 solution(lst: [30, 13, 24, 321]) == 0
 */
func solution(lst: [Int]) -> Int {
    
    
    
    
    var sum = 0
    

import Foundation

func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
    guard lhs[0].count == rhs.count else { 
        return nil 
    }
    
    var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
    for i in 0..<lhs.count {
        for j in 0..<rhs[0].count {
            for k in 0..<rhs.count {
                result[i][j] += lhs[i][k] * rhs[k][j]
            }
        }
    }
    
    return result
}

```swift
import Foundation

/* 
 Function to multiply two matrices represented as 2D arrays of Doubles.
 Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
 */
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
    guard lhs[0].count == rhs.count else { 
        return nil 
    }
    
    var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
    for i in 0..<lhs.count {
        for j in 0..<rhs[0].count {
            for k in 0..<rhs.count {
                result[i][j] += lhs[i][k] * rhs[k][j]
            }
        }
    }
    
    return result
}

/*
 Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
 Examples
 solution(lst: [5, 8, 7, 1]) == 12
 solution(lst: [3, 3, 3, 3, 3]) == 9
 solution(lst: [30, 13, 24, 321]) == 0
 */
func solution(lst: [Int]) -> Int {
    
    
    

import Foundation

func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
    guard lhs[0].count == rhs.count else { 
        return nil 
    }
    
    var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
    for i in 0..<lhs.count {
        for j in 0..<rhs[0].count {
            for k in 0..<rhs.count {
                result[i][j] += lhs[i][k] * rhs[k][j]
            }
        }
    }
    
    return result
}

```swift
import Foundation

/* 
 Function to multiply two matrices represented as 2D arrays of Doubles.
 Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
 */
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
    guard lhs[0].count == rhs.count else { 
        return nil 
    }
    
    var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
    for i in 0..<lhs.count {
        for j in 0..<rhs[0].count {
            for k in 0..<rhs.count {
                result[i][j] += lhs[i][k] * rhs[k][j]
            }
        }
    }
    
    return result
}

/*
 Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
 Examples
 solution(lst: [5, 8, 7, 1]) == 12
 solution(lst: [3, 3, 3, 3, 3]) == 9
 solution(lst: [30, 13, 24, 321]) == 0
 */
func solution(lst: [Int]) -> Int {
    
    
    
    var result = 0
    for

import Foundation

func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
    guard lhs[0].count == rhs.count else { 
        return nil 
    }
    
    var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
    for i in 0..<lhs.count {
        for j in 0..<rhs[0].count {
            for k in 0..<rhs.count {
                result[i][j] += lhs[i][k] * rhs[k][j]
            }
        }
    }
    
    return result
}

```swift
import Foundation

/* 
 Function to multiply two matrices represented as 2D arrays of Doubles.
 Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
 */
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
    guard lhs[0].count == rhs.count else { 
        return nil 
    }
    
    var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
    for i in 0..<lhs.count {
        for j in 0..<rhs[0].count {
            for k in 0..<rhs.count {
                result[i][j] += lhs[i][k] * rhs[k][j]
            }
        }
    }
    
    return result
}

/*
 Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
 Examples
 solution(lst: [5, 8, 7, 1]) == 12
 solution(lst: [3, 3, 3, 3, 3]) == 9
 solution(lst: [30, 13, 24, 321]) == 0
 */
func solution(lst: [Int]) -> Int {
    

import Foundation

func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
    guard lhs[0].count == rhs.count else { 
        return nil 
    }
    
    var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
    for i in 0..<lhs.count {
        for j in 0..<rhs[0].count {
            for k in 0..<rhs.count {
                result[i][j] += lhs[i][k] * rhs[k][j]
            }
        }
    }
    
    return result
}

```swift
import Foundation

/* 
 Function to multiply two matrices represented as 2D arrays of Doubles.
 Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
 */
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
    guard lhs[0].count == rhs.count else { 
        return nil 
    }
    
    var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
    for i in 0..<lhs.count {
        for j in 0..<rhs[0].count {
            for k in 0..<rhs.count {
                result[i][j] += lhs[i][k] * rhs[k][j]
            }
        }
    }
    
    return result
}

/*
 Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
 Examples
 solution(lst: [5, 8, 7, 1]) == 12
 solution(lst: [3, 3, 3, 3, 3]) == 9
 solution(lst: [30, 13, 24, 321]) == 0
 */
func solution(lst: [Int]) -> Int {
    
    
    
    var result = 0
    
    for i

import Foundation

func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
    guard lhs[0].count == rhs.count else { 
        return nil 
    }
    
    var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
    for i in 0..<lhs.count {
        for j in 0..<rhs[0].count {
            for k in 0..<rhs.count {
                result[i][j] += lhs[i][k] * rhs[k][j]
            }
        }
    }
    
    return result
}

```swift
import Foundation

/* 
 Function to multiply two matrices represented as 2D arrays of Doubles.
 Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
 */
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
    guard lhs[0].count == rhs.count else { 
        return nil 
    }
    
    var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
    for i in 0..<lhs.count {
        for j in 0..<rhs[0].count {
            for k in 0..<rhs.count {
                result[i][j] += lhs[i][k] * rhs[k][j]
            }
        }
    }
    
    return result
}

/*
 Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
 Examples
 solution(lst: [5, 8, 7, 1]) == 12
 solution(lst: [3, 3, 3, 3, 3]) == 9
 solution(lst: [30, 13, 24, 321]) == 0
 */
func solution(lst: [Int]) -> Int {
    

func solution(lst: [Int]) -> Int {
    return lst.filter(lst.enumerics.enumerating(1 % 2...).filter({ $0, where $0 == 1 % 2, { $0 % 2 == 0}.reduce( { $0).reduce(0).filter { $0).reduce(+$0).reduce(0)
        ).reduce(0)
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    return lst.filter(lst.enumerics.enumerating(1 % 2...).filter({ $0, where $0 == 1 % 2, { $0 % 2 == 0}.reduce( { $0).reduce(0).filter { $0).reduce(+$0).reduce(0)
        ).reduce(0)
}
}
}
}
}
}
}
}
}
}
}
}
}
```

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index = 0
    for (index, count in stride(0, max(where index in lst in l

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in
    if lst.indices.enumerating from 0..< lst.count {
        if lst.indices.contains(where(index % 2 % 2 == 0 {
            if lst.stride(

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    // Filter odd numbers in even positions

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index = 0
    for (index, count in lst = 0
    index % 2
    if index

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index = 0
    for (index, index in lst in lst.enumerator index in lst

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    return lst.filter({(lst.indices.filter({$

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    return lst.filter({(lst.indices(where: {$0 % 2...1 % 2 == 0}).reduce(in
        return ($0

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    return lst.filter({$0
       .filter({$0
            return $0
           .filter({$0 % 2 == 0 //

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    // Filter odd numbers in even index numbers, sum of odd numbers at even positions and then add up
    // If the array is 0-1, so

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    return lst.indices.filter { (index) -> Bool in
        (index % 2 == 0 && lst[index] % 2 != 0)
    }.reduce(0, +)
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    return lst.indices.filter { (index) -> Bool in
        (index % 2 == 0 && lst[index] % 2 != 0)
    }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.indices.filter { (index) -> Bool in
        index % 2 == 0 && lst[index] % 2 != 0
    }.reduce(0, +)
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    return lst.indices.filter { (index) -> Bool in
        index % 2 == 0 && lst[index] % 2 != 0
    }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.indices.filter { (index) -> Bool in
        index % 2 == 0 && lst[index] % 2 != 0
    }.reduce(0, +)
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    return lst.indices.filter { (index) -> Bool in
        index % 2 == 0 && lst[index] % 2 != 0
    }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.indices.filter { $0 % 2 == 0 && lst[$0] % 2 != 0 }.reduce(0, +)
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    return lst.indices.filter { $0 % 2 == 0 && lst[$0] % 2 != 0 }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.indices.filter { (index) -> Bool in
        index % 2 == 0 && lst[index] % 2 != 0
    }.reduce(0, +)
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    return lst.indices.filter { (index) -> Bool in
        index % 2 == 0 && lst[index] % 2 != 0
    }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    return lst.indices.filter { $0 % 2 == 0 && lst[$0] % 2 != 0 }.reduce(0, +)
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    return lst.indices.filter { $0 % 2 == 0 && lst[$0] % 2 != 0 }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    return lst.indices.filter { $0 % 2 == 0 && lst[$0] % 2 != 0 }.reduce(0, +)
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    return lst.indices.filter { $0 % 2 == 0 && lst[$0] % 2 != 0 }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<｜begin▁of▁sentence｜>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

import Foundation

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
import Foundation

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

import Foundation

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
import Foundation

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

import Foundation

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
import Foundation

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

import Foundation

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
import Foundation

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

import Foundation

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
import Foundation

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

import Foundation

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
import Foundation

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

import Foundation

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
import Foundation

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

import Foundation

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
import Foundation

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

import Foundation

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
import Foundation

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

import Foundation

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
import Foundation

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() where index % 2 == 0 && value % 2 != 0 {
        sum += value
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() where index % 2 == 0 && value % 2 != 0 {
        sum += value
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    return lst.filter { $0 % 2 == 0 }.reduce(0, +)
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.filter { $0 % 2 == 0 }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    var result = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            result += value
        }
    }
    return result
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var result = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            result += value
        }
    }
    return result
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    return lst.filter { $0 % 2 == 0 }.reduce(0, +)
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.filter { $0 % 2 == 0 }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerate() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerate() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerate() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerate() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2!= 0 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2!= 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 {
            if lst[i] % 2!= 0 {
                sum += lst[i]
            }
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 {
            if lst[i] % 2!= 0 {
                sum += lst[i]
            }
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2!= 0 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2!= 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2!= 0 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2!= 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2!= 0 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2!= 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2!= 0 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2!= 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2!= 0 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2!= 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2!= 0 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2!= 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2!= 0 }.reduce(0, +)
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2!= 0 }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2!= 0 }.reduce(0, +)
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2!= 0 }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2!= 0 }.reduce(0, +)
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2!= 0 }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2!= 0 }.reduce(0, +)
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2!= 0 }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2!= 0 }.reduce(0, +)
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2!= 0 }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2!= 0 }.reduce(0, +)
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2!= 0 }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2!= 0 }.reduce(0, +)
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2!= 0 }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2!= 0 }.reduce(0, +)
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2!= 0 }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2!= 0 }.reduce(0, +)
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2!= 0 }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2!= 0 }.reduce(0, +)
}

<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<|im_end|>
<|im_start|>assistant
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2!= 0 }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.filter { $0 % 2 == 0 && $0.isMultiple(of: 2) }.reduce(0, +)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    return lst.filter { $0 % 2 == 0 && $0.isMultiple(of: 2) }.reduce(0, +)
}
```
### Ex

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count where lst[i] % 2 != 0 {
        sum += lst[i]
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count where lst[i] % 2 != 0 {
        sum += lst[i]
    }
    return sum
}
```
### Inst

func solution(lst: [Int]) -> Int {
    return lst.filter { $0 % 2 == 0 && $0 > 0 }.reduce(0, +)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    return lst.filter { $0 % 2 == 0 && $0 > 0 }.reduce(0, +)
}
```
### Ex

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count where lst[i] % 2 != 0 {
        sum += lst[i]
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count where lst[i] % 2 != 0 {
        sum += lst[i]
    }
    return sum
}
```
### Challenge

func solution(lst: [Int]) -> Int {
    return lst.filter { $0 % 2 == 0 && $0.isMultiple(of: 2) }.reduce(0, +)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    return lst.filter { $0 % 2 == 0 && $0.isMultiple(of: 2) }.reduce(0, +)
}
```
### Challenge

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count where lst[i] % 2 != 0 && i % 2 == 0 {
        sum += lst[i]
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count where lst[i] % 2 != 0 && i % 2 == 0 {
        sum += lst[i]
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    return lst.filter { $0 % 2 != 0 && $0 % 2 == 0 }.reduce(0, +)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    return lst.filter { $0 % 2 != 0 && $0 % 2 == 0 }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.filter { $0 % 2 == 0 && $0 > 0 }.reduce(0, +)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    return lst.filter { $0 % 2 == 0 && $0 > 0 }.reduce(0, +)
}
```
### Ex

func solution(lst: [Int]) -> Int {
    return lst.filter { $0 % 2 == 0 }.reduce(0, +)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    return lst.filter { $0 % 2 == 0 }.reduce(0, +)
}
```
### Challenge

func solution(lst: [Int]) -> Int {
    return lst.filter { $0 % 2 == 0 }.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }.reduce(0, +)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    return lst.filter { $0 % 2 == 0 }.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }.reduce(0, +)
}
```
### Challenge

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if value % 2 != 0 && index % 2 == 0 {
            sum += value
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if value % 2 != 0 && index % 2 == 0 {
            sum += value
        }
    }
    return sum
}
```
### Test

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}
```
### Link

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if value % 2 != 0 && index % 2 == 0 {
            sum += value
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if value % 2 != 0 && index % 2 == 0 {
            sum += value
        }
    }
    return sum
}
```
### Test

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if value % 2 != 0 && index % 2 == 0 {
            sum += value
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if value % 2 != 0 && index % 2 == 0 {
            sum += value
        }
    }
    return sum
}
```
### Test

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if lst[i] % 2 != 0 && i % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if lst[i] % 2 != 0 && i % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if value % 2 != 0 && index % 2 == 0 {
            sum += value
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if value % 2 != 0 && index % 2 == 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if value % 2 != 0 && index % 2 == 0 {
            sum += value
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if value % 2 != 0 && index % 2 == 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if value % 2 != 0 && index % 2 == 0 {
            sum += value
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if value % 2 != 0 && index % 2 == 0 {
            sum += value
        }
    }
    return sum
}
```
### Test

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}
```
### Test

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    // Your code here
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    // Your code here
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

// Example usage:
print(solution(lst: [5, 8, 7, 1])) // Output: 12
print(solution(lst: [3, 3, 3, 3, 3])) // Output: 9
print(solution(lst: [30, 13, 24, 321])) // Output: 0
```

func solution(lst: [Int]) -> Int {
    // Initialize a variable to store the sum of odd elements in even positions
    var sum = 0
    
    // Iterate over the array, considering only elements at even indices (0, 2, 4, ...)
    for (index, value) in lst.enumerated() where index % 2 == 0 {
        // Check if the element is odd
        if value % 2 != 0 {
            // Add the odd element to the sum
            sum += value
        }
    }
    
    // Return the calculated sum
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    // Initialize a variable to store the sum of odd elements in even positions
    var sum = 0
    
    // Iterate over the array, considering only elements at even indices (0, 2, 4, ...)
    for (index, value) in lst.enumerated() where index % 2 == 0 {
        // Check if the element is odd
        if value % 2 != 0 {
            // Add the odd element to the sum
            sum += value
        }
    }
    
    // Return the calculated sum
    return sum
}

// Example usage:
print(solution(lst: [5, 8, 7, 1]))  // Output: 12
print(solution(lst: [3, 3, 3, 3, 3]))  // Output: 9
print(solution(lst: [30, 13, 24, 321]))  // Output: 0
```

This function iterates over the given array, checks if the element is odd and if it's at an even index, it adds it to the sum. It then returns the total sum of such elements.

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

// Example usage:
print(solution(lst: [5, 8, 7, 1]))  // Output: 12
print(solution(lst: [3, 3, 3, 3, 3]))  // Output: 9
print(solution(lst: [30, 13, 24, 321]))  // Output: 0
```

This function iterates over the given array, checking the position and parity of each element. If the element is odd and at an even index, it is added to the sum. The function returns the total sum of such elements.

func solution(lst: [Int]) -> Int {
    // Your code here
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 == 1 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    // Your code here
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 == 1 {
            sum += lst[i]
        }
    }
    return sum
}

// Example usage:
print(solution(lst: [5, 8, 7, 1]))  // Output: 12
print(solution(lst: [3, 3, 3, 3, 3]))  // Output: 9
print(solution(lst: [30, 13, 24, 321]))  // Output: 0
```

This function takes an array of integers and returns the sum of all the odd elements that are in even positions. The position is determined by zero-based indexing, where even positions are 0, 2, 4, etc. The function iterates over the array and accumulates the sum of odd elements at even indices.

func solution(lst: [Int]) -> Int {
    // Initialize a variable to store the sum of odd elements at even positions
    var sumOfOddElements = 0
    
    // Iterate over the array with index
    for (index, element) in lst.enumerated() {
        // Check if the element is odd AND the index is even
        if element % 2 != 0 && index % 2 == 0 {
            // Add the element to the sum
            sumOfOddElements += element
        }
    }
    
    // Return the sum of odd elements at even positions
    return sumOfOddElements
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    // Initialize a variable to store the sum of odd elements at even positions
    var sumOfOddElements = 0
    
    // Iterate over the array with index
    for (index, element) in lst.enumerated() {
        // Check if the element is odd AND the index is even
        if element % 2 != 0 && index % 2 == 0 {
            // Add the element to the sum
            sumOfOddElements += element
        }
    }
    
    // Return the sum of odd elements at even positions
    return sumOfOddElements
}

// Example usage:
print(solution(lst: [5, 8, 7, 1]))  // Output: 12
print(solution(lst: [3, 3, 3, 3, 3]))  // Output: 9
print(solution(lst: [30, 13, 24, 321]))  // Output: 0
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 == 1 {
            sum += element
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 == 1 {
            sum += element
        }
    }
    return sum
}

// Example usage:
print(solution(lst: [5, 8, 7, 1]))  // Output: 12
print(solution(lst: [3, 3, 3, 3, 3]))  // Output: 9
print(solution(lst: [30, 13, 24, 321]))  // Output: 0
```

This function iterates over the list, checking the position and parity of each element. If the element is odd and at an even index, it is added to the sum. The function returns the total sum of such elements.

func solution(lst: [Int]) -> Int {
    // Your code here
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 == 1 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    // Your code here
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 == 1 {
            sum += lst[i]
        }
    }
    return sum
}

// Example usage:
print(solution(lst: [5, 8, 7, 1])) // Output: 12
print(solution(lst: [3, 3, 3, 3, 3])) // Output: 9
print(solution(lst: [30, 13, 24, 321])) // Output: 0
```

This Swift function takes an array of integers and returns the sum of all the odd elements that are in even positions. The function uses a for loop to iterate over the elements at even indices and checks if they are odd. If they are, it adds them to the sum.

The function then returns the sum of the odd elements at even indices.

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

// Example usage:
print(solution(lst: [5, 8, 7, 1]))  // Output: 12
print(solution(lst: [3, 3, 3, 3, 3]))  // Output: 9
print(solution(lst: [30, 13, 24, 321]))  // Output: 0
```

This function iterates over the array, checking if the index is even and the element is odd. If both conditions are met, it adds the element to the sum.

func solution(lst: [Int]) -> Int {
    // Your code here
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 == 1 {
            sum += element
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    // Your code here
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 == 1 {
            sum += element
        }
    }
    return sum
}

// Example usage:
print(solution(lst: [5, 8, 7, 1]))  // Output: 12
print(solution(lst: [3, 3, 3, 3, 3]))  // Output: 9
print(solution(lst: [30, 13, 24, 321]))  // Output: 0
```

func solution(lst: [Int]) -> Int {
    // Your code here
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    // Your code here
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

// Example usage:
print(solution(lst: [5, 8, 7, 1]))  // Output: 12
print(solution(lst: [3, 3, 3, 3, 3]))  // Output: 9
print(solution(lst: [30, 13, 24, 321]))  // Output: 0
```

This Swift code defines a function `solution` that takes an array of integers `lst` and returns the sum of all the odd elements that are in even positions. The position is determined by zero-based indexing, where even indices are considered even positions (0, 2, 4, ...).

The function iterates over the array using `stride` to get elements at even indices and checks if they are odd. If they are, the element is added to the sum.

The function returns the computed sum.

The example usage shows how to call the function with different arrays and print the results.

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 1 && lst[i] % 2 == 1 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 1 && lst[i] % 2 == 1 {
            sum += lst[i]
        }
    }
    return sum
}
<|file_separator|>```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 1 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 1 {
            sum += value
        }
    }
    return sum
}
<|file_separator|>

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 1 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 1 {
            sum += value
        }
    }
    return sum
}
<|file_separator|>

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}
<|file_separator|>

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 1 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 1 {
            sum += lst[i]
        }
    }
    return sum
}
<|file_separator|>

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}
<|file_separator|>```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 1 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 1 {
            sum += lst[i]
        }
    }
    return sum
}
<|file_separator|>

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}
<|file_separator|>

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 1 && lst[i] % 2 == 1 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 1 && lst[i] % 2 == 1 {
            sum += lst[i]
        }
    }
    return sum
}
<|file_separator|>

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 1 && value % 2 == 1 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 1 && value % 2 == 1 {
            sum += value
        }
    }
    return sum
}
<|file_separator|>

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}
<|file_separator|>

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 1 && value % 2 == 1 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 1 && value % 2 == 1 {
            sum += value
        }
    }
    return sum
}
<|file_separator|>

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 1 && value % 2 == 1 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 1 && value % 2 == 1 {
            sum += value
        }
    }
    return sum
}
<|file_separator|>

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 1 && value % 2 == 1 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 1 && value % 2 == 1 {
            sum += value
        }
    }
    return sum
}
<|file_separator|>

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 1 && value % 2 == 1 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 1 && value % 2 == 1 {
            sum += value
        }
    }
    return sum
}
<|file_separator|>

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 1 && value % 2 == 1 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 1 && value % 2 == 1 {
            sum += value
        }
    }
    return sum
}
<|file_separator|>

func solution(lst: [Int]) -> Int {
  var sum = 0
  for i in 0..<lst.count {
    if i % 2 == 1 {
      sum += lst[i]
    }
  }
  return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
  var sum = 0
  for i in 0..<lst.count {
    if i % 2 == 1 {
      sum += lst[i]
    }
  }
  return sum
}
<|file_separator|>

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}
<|file_separator|>```

func solution(lst: [Int]) -> Int {
  var sum = 0
  for i in 0..<lst.count {
    if i % 2 == 0 {
      sum += lst[i]
    }
  }
  return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
  var sum = 0
  for i in 0..<lst.count {
    if i % 2 == 0 {
      sum += lst[i]
    }
  }
  return sum
}
<|file_separator|>

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}
<|file_separator|>

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }.filter { $0 % 2 != 0 }.reduce(0, +)
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }.filter { $0 % 2 != 0 }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (i, value) in lst.enumerated() {
        if i % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (i, value) in lst.enumerated() {
        if i % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    return lst.filter { $0 % 2 == 0 }.reduce(0, +)
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.filter { $0 % 2 == 0 }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (i, n) in lst.enumerated() {
        if i % 2 == 0 && n % 2 != 0 {
            sum += n
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (i, n) in lst.enumerated() {
        if i % 2 == 0 && n % 2 != 0 {
            sum += n
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    return lst.filter { $0 % 2 == 1 }.reduce(0, +)
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.filter { $0 % 2 == 1 }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (i, num) in lst.enumerated() {
        if i % 2 == 0 && num % 2 != 0 {
            sum += num
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (i, num) in lst.enumerated() {
        if i % 2 == 0 && num % 2 != 0 {
            sum += num
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter({$0.offset % 2 == 0}).filter({$0.element % 2 == 1}).reduce(0, { $0 + $1.element })
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter({$0.offset % 2 == 0}).filter({$0.element % 2 == 1}).reduce(0, { $0 + $1.element })
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }.filter { $0 % 2 == 1 }.reduce(0, +)
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }.filter { $0 % 2 == 1 }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter({$0.offset % 2 == 0 }).map({$0.element}).filter({$0 % 2 == 1}).reduce(0, +)
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter({$0.offset % 2 == 0 }).map({$0.element}).filter({$0 % 2 == 1}).reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if lst[i] % 2 == 0 && i % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if lst[i] % 2 == 0 && i % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum: Int = 0
    for i in 0..<lst.count {
        if lst[i] % 2 == 0 && i % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum: Int = 0
    for i in 0..<lst.count {
        if lst[i] % 2 == 0 && i % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum: Int = 0
    for i in 0..<lst.count {
        if lst[i] % 2 == 0 && i % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum: Int = 0
    for i in 0..<lst.count {
        if lst[i] % 2 == 0 && i % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum: Int = 0
    for i in 0..<lst.count {
        if lst[i] % 2 == 0 && i % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum: Int = 0
    for i in 0..<lst.count {
        if lst[i] % 2 == 0 && i % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum: Int = 0
    for i in 0..<lst.count {
        if lst[i] % 2 == 0 && i % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum: Int = 0
    for i in 0..<lst.count {
        if lst[i] % 2 == 0 && i % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum: Int = 0
    for i in 0..<lst.count {
        if lst[i] % 2 == 0 && i % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst:

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if lst[i] % 2 == 0 && i % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if lst[i] % 2 == 0 && i % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum: Int = 0
    for i in 0..<lst.count {
        if lst[i] % 2 == 0 && i % 2 == 1 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum: Int = 0
    for i in 0..<lst.count {
        if lst[i] % 2 == 0 && i % 2 == 1 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum: Int = 0
    for i in 0..<lst.count {
        if lst[i] % 2 == 0 && i % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum: Int = 0
    for i in 0..<lst.count {
        if lst[i] % 2 == 0 && i % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum: Int = 0
    for i in 0..<lst.count {
        if lst[i] % 2 == 0 && i % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum: Int = 0
    for i in 0..<lst.count {
        if lst[i] % 2 == 0 && i % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 == 1 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 == 1 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
  return lst.enumerated()
    .filter { $0.offset % 2 == 0 && $0.element % 2 != 0 }
    .map { $0.element }
    .reduce(0, +)
}

<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
  return lst.enumerated()
    .filter { $0.offset % 2 == 0 && $0.element % 2 != 0 }
    .map { $0.element }
    .reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
  var sum = 0
  for i in stride(from: 0, to: lst.count, by: 2) {
    if lst[i] % 2 != 0 {
      sum += lst[i]
    }
  }
  return sum
}

<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
  var sum = 0
  for i in stride(from: 0, to: lst.count, by: 2) {
    if lst[i] % 2 != 0 {
      sum += lst[i]
    }
  }
  return sum
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 != 0 }.map { $0.element }.reduce(0, +)
}

<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 != 0 }.map { $0.element }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    var result = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            result += element
        }
    }
    return result
}

<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
    var result = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            result += element
        }
    }
    return result
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.element % 2 != 0 && $0.offset % 2 == 0 }.map { $0.element }.reduce(0, +)
}

<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.element % 2 != 0 && $0.offset % 2 == 0 }.map { $0.element }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
  var result = 0
  for (index, value) in lst.enumerated() {
    if index % 2 == 0 && value % 2 != 0 {
      result += value
    }
  }
  return result
}

<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
  var result = 0
  for (index, value) in lst.enumerated() {
    if index % 2 == 0 && value % 2 != 0 {
      result += value
    }
  }
  return result
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 != 0 }.map { $0.element }.reduce(0, +)
}

<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 != 0 }.map { $0.element }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
  return lst.enumerated()
    .filter { $0.offset % 2 == 0 && $0.element % 2 != 0 }
    .map { $0.element }
    .reduce(0, +)
}

<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
  return lst.enumerated()
    .filter { $0.offset % 2 == 0 && $0.element % 2 != 0 }
    .map { $0.element }
    .reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated()
        .filter { $0.element % 2 == 1 && $0.offset % 2 == 0 }
        .map { $0.element }
        .reduce(0, +)
}

<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated()
        .filter { $0.element % 2 == 1 && $0.offset % 2 == 0 }
        .map { $0.element }
        .reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.index % 2 == 0 && $0.element % 2 != 0 }.map { $0.element }.reduce(0, +)
}

<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.index % 2 == 0 && $0.element % 2 != 0 }.map { $0.element }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated()
        .filter { $0.offset % 2 == 0 && $0.element % 2 != 0 }
        .map { $0.element }
        .reduce(0, +)
}

<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated()
        .filter { $0.offset % 2 == 0 && $0.element % 2 != 0 }
        .map { $0.element }
        .reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated()
        .filter { $0.offset % 2 == 0 && $0.element % 2 != 0 }
        .map { $0.element }
        .reduce(0, +)
}

<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated()
        .filter { $0.offset % 2 == 0 && $0.element % 2 != 0 }
        .map { $0.element }
        .reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated()
        .filter { $0.offset % 2 == 0 && $0.element % 2 != 0 }
        .map { $0.element }
        .reduce(0, +)
}

<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated()
        .filter { $0.offset % 2 == 0 && $0.element % 2 != 0 }
        .map { $0.element }
        .reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated()
        .filter { $0.element % 2 != 0 && $0.offset % 2 == 0 }
        .map { $0.element }
        .reduce(0, +)
}

<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated()
        .filter { $0.element % 2 != 0 && $0.offset % 2 == 0 }
        .map { $0.element }
        .reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated()
        .filter { $0.element % 2 != 0 && $0.offset % 2 == 0 }
        .map { $0.element }
        .reduce(0, +)
}

<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated()
        .filter { $0.element % 2 != 0 && $0.offset % 2 == 0 }
        .map { $0.element }
        .reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated()
        .filter { $0.element % 2 != 0 && $0.offset % 2 == 0 }
        .map { $0.element }
        .reduce(0, +)
}

<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0<end_of_turn>
<start_of_turn>model
```swift
func solution(lst: [Int]) -> Int {
    return lst.enumerated()
        .filter { $0.element % 2 != 0 && $0.offset % 2 == 0 }
        .map { $0.element }
        .reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count where lst[i] % 2 == 1 && i % 2 == 0 {
        sum += lst[i]
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count where lst[i] % 2 == 1 && i % 2 == 0 {
        sum += lst[i]
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count where lst[i] % 2 == 1 && i % 2 == 0 {
        sum += lst[i]
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count where lst[i] % 2 == 1 && i % 2 == 0 {
        sum += lst[i]
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count where lst[i] % 2 == 1 && i % 2 == 0 {
        sum += lst[i]
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count where lst[i] % 2 == 1 && i % 2 == 0 {
        sum += lst[i]
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count where lst[i] % 2 == 1 && i % 2 == 0 {
        sum += lst[i]
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count where lst[i] % 2 == 1 && i % 2 == 0 {
        sum += lst[i]
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count where lst[i] % 2 == 1 && i % 2 == 0 {
        sum += lst[i]
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count where lst[i] % 2 == 1 && i % 2 == 0 {
        sum += lst[i]
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count where lst[i] % 2 == 1 && i % 2 == 0 {
        sum += lst[i]
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count where lst[i] % 2 == 1 && i % 2 == 0 {
        sum += lst[i]
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count where lst[i] % 2 == 1 && i % 2 == 0 {
        sum += lst[i]
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count where lst[i] % 2 == 1 && i % 2 == 0 {
        sum += lst[i]
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count where lst[i] % 2 == 1 && i % 2 == 0 {
        sum += lst[i]
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count where lst[i] % 2 == 1 && i % 2 == 0 {
        sum += lst[i]
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count where lst[i] % 2 == 1 && i % 2 == 0 {
        sum += lst[i]
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count where lst[i] % 2 == 1 && i % 2 == 0 {
        sum += lst[i]
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count where lst[i] % 2 == 1 && i % 2 == 0 {
        sum += lst[i]
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count where lst[i] % 2 == 1 && i % 2 == 0 {
        sum += lst[i]
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if element % 2 == 1 && index % 2 == 0 {
            sum += element
        }
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if element % 2 == 1 && index % 2 == 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if element % 2 == 1 && index % 2 == 0 {
            sum += element
        }
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if element % 2 == 1 && index % 2 == 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if element % 2 == 1 && index % 2 == 0 {
            sum += element
        }
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if element % 2 == 1 && index % 2 == 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if element % 2 == 1 && index % 2 == 0 {
            sum += element
        }
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if element % 2 == 1 && index % 2 == 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (i, element) in lst.enumerated() {
        if element % 2 == 1 && i % 2 == 0 {
            sum += element
        }
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (i, element) in lst.enumerated() {
        if element % 2 == 1 && i % 2 == 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (i, element) in lst.enumerated() {
        if element % 2 == 1 && i % 2 == 0 {
            sum += element
        }
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (i, element) in lst.enumerated() {
        if element % 2 == 1 && i % 2 == 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if element % 2 == 1 && index % 2 == 0 {
            sum += element
        }
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if element % 2 == 1 && index % 2 == 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if element % 2 == 1 && index % 2 == 0 {
            sum += element
        }
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if element % 2 == 1 && index % 2 == 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if element % 2 == 1 && index % 2 == 0 {
            sum += element
        }
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if element % 2 == 1 && index % 2 == 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if element % 2 == 1 && index % 2 == 0 {
            sum += element
        }
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if element % 2 == 1 && index % 2 == 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 == 1 {
            sum += element
        }
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 == 1 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (i, element) in lst.enumerated() {
        if i % 2 == 0 && element % 2 == 1 {
            sum += element
        }
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (i, element) in lst.enumerated() {
        if i % 2 == 0 && element % 2 == 1 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (i, element) in lst.enumerated() {
        if i % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (i, element) in lst.enumerated() {
        if i % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (i, element) in lst.enumerated() {
        if i % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (i, element) in lst.enumerated() {
        if i % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (i, element) in lst.enumerated() {
        if i % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (i, element) in lst.enumerated() {
        if i % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (i, element) in lst.enumerated() {
        if i % 2 == 0 && element % 2 == 1 {
            sum += element
        }
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (i, element) in lst.enumerated() {
        if i % 2 == 0 && element % 2 == 1 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 == 1 {
            sum += element
        }
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 == 1 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 == 1 {
            sum += element
        }
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 == 1 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (i, element) in lst.enumerated() {
        if i % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}

[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0 [/INST] ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (i, element) in lst.enumerated() {
        if i % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, num) in lst.enumerated() {
        if index % 2 == 0 && num % 2!= 0 {
            sum += num
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, num) in lst.enumerated() {
        if index % 2 == 0 && num % 2!= 0 {
            sum += num
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 1 && element % 2 == 1 {
            sum += element
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 1 && element % 2 == 1 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2!= 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0

Answer:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    return lst.indices.filter { lst[$0] % 2 != 0 && $0 % 2 == 0 }.reduce(0, +)
}

You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    return lst.indices.filter { lst[$0] % 2 != 0 && $0 % 2 == 0 }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    return lst.indices.filter { lst[$0] % 2 != 0 && $0 % 2 == 0 }.reduce(0, +)
}

You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    return lst.indices.filter { lst[$0] % 2 != 0 && $0 % 2 == 0 }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        let number = lst[i]
        if number % 2 != 0 {
            sum += number
        }
    }
    return sum
}

You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        let number = lst[i]
        if number % 2 != 0 {
            sum += number
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}

You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 0, to: lst.count, by: 2) {
        if lst[i] % 2 != 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}

You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    return lst.indices.filter { $0 % 2 == 0 && lst[$0] % 2 != 0 }.reduce(0, +)
}

You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    return lst.indices.filter { $0 % 2 == 0 && lst[$0] % 2 != 0 }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.indices.filter { $0 % 2 == 0 && lst[$0] % 2 != 0 }.reduce(0, +)
}

You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    return lst.indices.filter { $0 % 2 == 0 && lst[$0] % 2 != 0 }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}

You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    return lst.indices.filter { (index) -> Bool in
        index % 2 == 0 && lst[index] % 2 != 0
    }.reduce(0, +)
}

You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    return lst.indices.filter { (index) -> Bool in
        index % 2 == 0 && lst[index] % 2 != 0
    }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}

You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}

You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2 != 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    return lst.indices.filter { $0 % 2 == 0 && lst[$0] % 2 != 0 }.reduce(0, +)
}

You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    return lst.indices.filter { $0 % 2 == 0 && lst[$0] % 2 != 0 }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.indices.filter { $0 % 2 == 0 && lst[$0] % 2 != 0 }.reduce(0, +)
}

You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    return lst.indices.filter { $0 % 2 == 0 && lst[$0] % 2 != 0 }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.indices.filter { $0 % 2 == 0 && lst[$0] % 2 != 0 }.reduce(0, +)
}

You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
### Response:
```swift
func solution(lst: [Int]) -> Int {
    return lst.indices.filter { $0 % 2 == 0 && lst[$0] % 2 != 0 }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2!= 0 }.reduce(0, { $0 + $1.element })
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2!= 0 }.reduce(0, { $0 + $1.element })
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2!= 0 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2!= 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2!= 0 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2!= 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.reduce(0) { $0 + $1.element }
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.reduce(0) { $0 + $1.element }
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2!= 0 }.reduce(0, { $0 + $1.element })
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2!= 0 }.reduce(0, { $0 + $1.element })
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2!= 0 }.reduce(0) { $0 + $1.element }
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2!= 0 }.reduce(0) { $0 + $1.element }
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2!= 0 }.reduce(0, { $0 + $1.element })
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2!= 0 }.reduce(0, { $0 + $1.element })
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }.reduce(0, +)
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }.reduce(0, +)
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }.reduce(0, +)
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }.reduce(0, +)
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }.reduce(0, +)
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    return lst.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }.reduce(0, +)
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerated() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2!= 0 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2!= 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerate() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerate() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2!= 0 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2!= 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerate() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerate() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerate() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerate() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerate() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, value) in lst.enumerate() {
        if index % 2 == 0 && value % 2!= 0 {
            sum += value
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 {
            if lst[i] % 2!= 0 {
                sum += lst[i]
            }
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 {
            if lst[i] % 2!= 0 {
                sum += lst[i]
            }
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 {
            if lst[i] % 2!= 0 {
                sum += lst[i]
            }
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 {
            if lst[i] % 2!= 0 {
                sum += lst[i]
            }
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2!= 0 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2!= 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2!= 0 {
            sum += lst[i]
        }
    }
    return sum
}

```swift
// Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// solution(lst: [5, 8, 7, 1]) == 12
// solution(lst: [3, 3, 3, 3, 3]) == 9
// solution(lst: [30, 13, 24, 321]) == 0
func solution(lst: [Int]) -> Int {
    var sum = 0
    for i in 0..<lst.count {
        if i % 2 == 0 && lst[i] % 2!= 0 {
            sum += lst[i]
        }
    }
    return sum
}
```