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temp 0.2
top_p 0.95
max_new_tokens 1024
n_completions 10

Solutions

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i+1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true[/INST]  ```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i+1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true[/INST]  ```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i+1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true[/INST]  ```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i+1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i+1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true[/INST]  ```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i+1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    let sortedNumbers = numbers.sorted()

    for i in 0..<sortedNumbers.count - 1 {
        if sortedNumbers[i + 1] - sortedNumbers[i] < threshold {
            return true
        }
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true[/INST]  ```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    let sortedNumbers = numbers.sorted()

    for i in 0..<sortedNumbers.count - 1 {
        if sortedNumbers[i + 1] - sortedNumbers[i] < threshold {
            return true
        }
    }

    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true[/INST]  ```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i+1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true[/INST]  ```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i+1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i+1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true[/INST]  ```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i+1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i+1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true[/INST]  ```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i+1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true[/INST]  ```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var temp = ""

    for char in parenString {
        if char == " " {
            continue
        }

        if char == "(" {
            if !stack.isEmpty {
                temp.append(char)
            }
            stack.append(char)
        } else if char == ")" {
            if !stack.isEmpty {
                temp.append(char)
                stack.removeLast()
                if stack.isEmpty {
                    result.append(temp)
                    temp = ""
                }
            }
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"][/INST]  ```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var temp = ""

    for char in parenString {
        if char == " " {
            continue
        }

        if char == "(" {
            if !stack.isEmpty {
                temp.append(char)
            }
            stack.append(char)
        } else if char == ")" {
            if !stack.isEmpty {
                temp.append(char)
                stack.removeLast()
                if stack.isEmpty {
                    result.append(temp)
                    temp = ""
                }
            }
        }
    }

    return result
}
```
 // XCTAssertTrue failed

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var temp = ""

    for char in parenString {
        if char == " " {
            continue
        }

        if char == "(" {
            if !stack.isEmpty {
                temp.append(char)
            }
            stack.append(char)
        } else if char == ")" {
            stack.removeLast()
            temp.append(char)
            if stack.isEmpty {
                result.append(temp)
                temp = ""
            }
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"][/INST]  ```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var temp = ""

    for char in parenString {
        if char == " " {
            continue
        }

        if char == "(" {
            if !stack.isEmpty {
                temp.append(char)
            }
            stack.append(char)
        } else if char == ")" {
            stack.removeLast()
            temp.append(char)
            if stack.isEmpty {
                result.append(temp)
                temp = ""
            }
        }
    }

    return result
}
```
 // XCTAssertTrue failed

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var temp = ""

    for char in parenString {
        if char == " " {
            continue
        }

        if char == "(" {
            if !stack.isEmpty {
                temp.append(char)
            }
            stack.append(char)
        } else if char == ")" {
            if !stack.isEmpty {
                stack.removeLast()
                temp.append(char)
            }

            if stack.isEmpty {
                result.append(temp)
                temp = ""
            }
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"][/INST]  ```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var temp = ""

    for char in parenString {
        if char == " " {
            continue
        }

        if char == "(" {
            if !stack.isEmpty {
                temp.append(char)
            }
            stack.append(char)
        } else if char == ")" {
            if !stack.isEmpty {
                stack.removeLast()
                temp.append(char)
            }

            if stack.isEmpty {
                result.append(temp)
                temp = ""
            }
        }
    }

    return result
}
```
 // XCTAssertTrue failed

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var temp = ""

    for char in parenString {
        if char == " " {
            continue
        }

        if char == "(" {
            if !stack.isEmpty {
                temp.append(char)
            }
            stack.append(char)
        } else if char == ")" {
            if !stack.isEmpty {
                temp.append(char)
                stack.removeLast()
            }
            if stack.isEmpty {
                result.append(temp)
                temp = ""
            }
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"][/INST]  ```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var temp = ""

    for char in parenString {
        if char == " " {
            continue
        }

        if char == "(" {
            if !stack.isEmpty {
                temp.append(char)
            }
            stack.append(char)
        } else if char == ")" {
            if !stack.isEmpty {
                temp.append(char)
                stack.removeLast()
            }
            if stack.isEmpty {
                result.append(temp)
                temp = ""
            }
        }
    }

    return result
}
```
 // XCTAssertTrue failed

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var temp = ""

    for char in parenString {
        if char == " " {
            continue
        }

        if char == "(" {
            if !stack.isEmpty {
                temp += String(char)
            }
            stack.append(char)
        } else if char == ")" {
            if !stack.isEmpty {
                stack.removeLast()
                temp += String(char)
            }

            if stack.isEmpty {
                result.append(temp)
                temp = ""
            }
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"][/INST]  ```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var temp = ""

    for char in parenString {
        if char == " " {
            continue
        }

        if char == "(" {
            if !stack.isEmpty {
                temp += String(char)
            }
            stack.append(char)
        } else if char == ")" {
            if !stack.isEmpty {
                stack.removeLast()
                temp += String(char)
            }

            if stack.isEmpty {
                result.append(temp)
                temp = ""
            }
        }
    }

    return result
}
```
 // XCTAssertTrue failed

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var temp = ""

    for char in parenString {
        if char == " " {
            continue
        }

        if char == "(" {
            if !stack.isEmpty {
                temp.append(char)
            }
            stack.append(char)
        } else if char == ")" {
            if !stack.isEmpty {
                temp.append(char)
                stack.removeLast()
            }

            if stack.isEmpty {
                result.append(temp)
                temp = ""
            }
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"][/INST]  ```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var temp = ""

    for char in parenString {
        if char == " " {
            continue
        }

        if char == "(" {
            if !stack.isEmpty {
                temp.append(char)
            }
            stack.append(char)
        } else if char == ")" {
            if !stack.isEmpty {
                temp.append(char)
                stack.removeLast()
            }

            if stack.isEmpty {
                result.append(temp)
                temp = ""
            }
        }
    }

    return result
}
```
 // XCTAssertTrue failed

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var currentGroup = ""

    for char in parenString {
        if char == " " {
            continue
        }

        if char == "(" {
            if !stack.isEmpty {
                currentGroup.append(char)
            }
            stack.append(char)
        } else if char == ")" {
            if !stack.isEmpty {
                currentGroup.append(char)
                stack.removeLast()
                if stack.isEmpty {
                    result.append(currentGroup)
                    currentGroup = ""
                }
            }
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"][/INST]  ```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var currentGroup = ""

    for char in parenString {
        if char == " " {
            continue
        }

        if char == "(" {
            if !stack.isEmpty {
                currentGroup.append(char)
            }
            stack.append(char)
        } else if char == ")" {
            if !stack.isEmpty {
                currentGroup.append(char)
                stack.removeLast()
                if stack.isEmpty {
                    result.append(currentGroup)
                    currentGroup = ""
                }
            }
        }
    }

    return result
}
```
 // XCTAssertTrue failed

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var currentGroup = ""

    for char in parenString {
        if char == "(" {
            if !stack.isEmpty {
                currentGroup.append(char)
            }
            stack.append(char)
        } else if char == ")" {
            if !stack.isEmpty {
                currentGroup.append(char)
                stack.removeLast()
                if stack.isEmpty {
                    result.append(currentGroup)
                    currentGroup = ""
                }
            }
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"][/INST]  ```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var currentGroup = ""

    for char in parenString {
        if char == "(" {
            if !stack.isEmpty {
                currentGroup.append(char)
            }
            stack.append(char)
        } else if char == ")" {
            if !stack.isEmpty {
                currentGroup.append(char)
                stack.removeLast()
                if stack.isEmpty {
                    result.append(currentGroup)
                    currentGroup = ""
                }
            }
        }
    }

    return result
}
```
 // XCTAssertTrue failed

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var temp = ""

    for char in parenString {
        if char == "(" {
            if !stack.isEmpty {
                temp.append(char)
            }
            stack.append(char)
        } else if char == ")" {
            if !stack.isEmpty {
                temp.append(char)
                stack.removeLast()
                if stack.isEmpty {
                    result.append(temp)
                    temp = ""
                }
            }
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"][/INST]  ```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var temp = ""

    for char in parenString {
        if char == "(" {
            if !stack.isEmpty {
                temp.append(char)
            }
            stack.append(char)
        } else if char == ")" {
            if !stack.isEmpty {
                temp.append(char)
                stack.removeLast()
                if stack.isEmpty {
                    result.append(temp)
                    temp = ""
                }
            }
        }
    }

    return result
}
```
 // XCTAssertTrue failed

func separateParenGroups(parenString: String) -> [String] {
    var groups = [String]()
    var currentGroup = ""
    var openCount = 0

    for char in parenString {
        if char == "(" {
            openCount += 1
        } else if char == ")" {
            openCount -= 1
        }

        currentGroup.append(char)

        if openCount == 0 {
            groups.append(currentGroup)
            currentGroup = ""
        }
    }

    return groups
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"][/INST]  ```swift
func separateParenGroups(parenString: String) -> [String] {
    var groups = [String]()
    var currentGroup = ""
    var openCount = 0

    for char in parenString {
        if char == "(" {
            openCount += 1
        } else if char == ")" {
            openCount -= 1
        }

        currentGroup.append(char)

        if openCount == 0 {
            groups.append(currentGroup)
            currentGroup = ""
        }
    }

    return groups
}
```
 // XCTAssertTrue failed

func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5[/INST]  ```swift
func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}
```

func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5[/INST]  ```swift
func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5[/INST]  ```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5[/INST]  ```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5[/INST]  ```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5[/INST]  ```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5[/INST]  ```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5[/INST]  ```swift
func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}
```

func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5[/INST]  ```swift
func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}
```

func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5[/INST]  ```swift
func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true[/INST]  ```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true[/INST]  ```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true[/INST]  ```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true[/INST]  ```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true[/INST]  ```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true[/INST]  ```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true[/INST]  ```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true[/INST]  ```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true[/INST]  ```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true[/INST]  ```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let sumOfAbsoluteDifferences = numbers.map { abs($0 - mean) }.reduce(0, +)
    return sumOfAbsoluteDifferences / Double(numbers.count)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0[/INST]  ```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let sumOfAbsoluteDifferences = numbers.map { abs($0 - mean) }.reduce(0, +)
    return sumOfAbsoluteDifferences / Double(numbers.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDifferences = numbers.map { abs($0 - mean) }
    let mad = absoluteDifferences.reduce(0, +) / Double(numbers.count)
    return mad
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0[/INST]  ```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDifferences = numbers.map { abs($0 - mean) }
    let mad = absoluteDifferences.reduce(0, +) / Double(numbers.count)
    return mad
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let sumOfAbsoluteDifferences = numbers.map { abs($0 - mean) }.reduce(0, +)
    return sumOfAbsoluteDifferences / Double(numbers.count)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0[/INST]  ```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let sumOfAbsoluteDifferences = numbers.map { abs($0 - mean) }.reduce(0, +)
    return sumOfAbsoluteDifferences / Double(numbers.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let sumOfAbsoluteDifferences = numbers.map { abs($0 - mean) }.reduce(0, +)
    return sumOfAbsoluteDifferences / Double(numbers.count)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0[/INST]  ```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let sumOfAbsoluteDifferences = numbers.map { abs($0 - mean) }.reduce(0, +)
    return sumOfAbsoluteDifferences / Double(numbers.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let sumOfAbsoluteDifferences = numbers.map { abs($0 - mean) }.reduce(0, +)
    return sumOfAbsoluteDifferences / Double(numbers.count)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0[/INST]  ```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let sumOfAbsoluteDifferences = numbers.map { abs($0 - mean) }.reduce(0, +)
    return sumOfAbsoluteDifferences / Double(numbers.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let sumOfAbsoluteDifferences = numbers.map { abs($0 - mean) }.reduce(0, +)
    return sumOfAbsoluteDifferences / Double(numbers.count)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0[/INST]  ```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let sumOfAbsoluteDifferences = numbers.map { abs($0 - mean) }.reduce(0, +)
    return sumOfAbsoluteDifferences / Double(numbers.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDifferences = numbers.map { abs($0 - mean) }
    let mad = absoluteDifferences.reduce(0, +) / Double(numbers.count)
    return mad
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0[/INST]  ```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDifferences = numbers.map { abs($0 - mean) }
    let mad = absoluteDifferences.reduce(0, +) / Double(numbers.count)
    return mad
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDifferences = numbers.map { abs($0 - mean) }
    let mad = absoluteDifferences.reduce(0, +) / Double(numbers.count)
    return mad
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0[/INST]  ```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDifferences = numbers.map { abs($0 - mean) }
    let mad = absoluteDifferences.reduce(0, +) / Double(numbers.count)
    return mad
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDifferences = numbers.map { abs($0 - mean) }
    let mad = absoluteDifferences.reduce(0, +) / Double(numbers.count)
    return mad
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0[/INST]  ```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDifferences = numbers.map { abs($0 - mean) }
    let mad = absoluteDifferences.reduce(0, +) / Double(numbers.count)
    return mad
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let count = Double(numbers.count)
    let mean = numbers.reduce(0, +) / count
    let sumOfAbsoluteDifferences = numbers.map { abs($0 - mean) }.reduce(0, +)
    return sumOfAbsoluteDifferences / count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0[/INST]  ```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let count = Double(numbers.count)
    let mean = numbers.reduce(0, +) / count
    let sumOfAbsoluteDifferences = numbers.map { abs($0 - mean) }.reduce(0, +)
    return sumOfAbsoluteDifferences / count
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3][/INST]  ```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3][/INST]  ```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index != numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3][/INST]  ```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index != numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3][/INST]  ```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index != numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3][/INST]  ```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index != numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3][/INST]  ```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3][/INST]  ```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3][/INST]  ```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3][/INST]  ```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3][/INST]  ```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var maxDepths: [Int] = []
    var currentDepth = 0
    var maxDepth = 0

    for char in parenString {
        if char == "(" {
            currentDepth += 1
            maxDepth = max(maxDepth, currentDepth)
        } else if char == ")" {
            currentDepth -= 1
        } else if char == " " && currentDepth > 0 {
            maxDepths.append(maxDepth)
            maxDepth = 0
            currentDepth = 0
        }
    }

    if currentDepth > 0 {
        maxDepths.append(maxDepth)
    }

    return maxDepths
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3][/INST]  ```swift
func parseNestedParens(parenString: String) -> [Int] {
    var maxDepths: [Int] = []
    var currentDepth = 0
    var maxDepth = 0

    for char in parenString {
        if char == "(" {
            currentDepth += 1
            maxDepth = max(maxDepth, currentDepth)
        } else if char == ")" {
            currentDepth -= 1
        } else if char == " " && currentDepth > 0 {
            maxDepths.append(maxDepth)
            maxDepth = 0
            currentDepth = 0
        }
    }

    if currentDepth > 0 {
        maxDepths.append(maxDepth)
    }

    return maxDepths
}
```
 // XCTAssertTrue failed

func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var stack = [Int]()
    var maxDepth = 0

    for char in parenString {
        if char == "(" {
            stack.append(1)
            maxDepth = max(maxDepth, stack.count)
        } else if char == ")" {
            stack.removeLast()
            if stack.isEmpty {
                result.append(maxDepth)
                maxDepth = 0
            }
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3][/INST]  ```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var stack = [Int]()
    var maxDepth = 0

    for char in parenString {
        if char == "(" {
            stack.append(1)
            maxDepth = max(maxDepth, stack.count)
        } else if char == ")" {
            stack.removeLast()
            if stack.isEmpty {
                result.append(maxDepth)
                maxDepth = 0
            }
        }
    }

    return result
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var stack = [Int]()
    var maxDepth = 0

    for char in parenString {
        if char == "(" {
            stack.append(stack.count)
            maxDepth = max(maxDepth, stack.count)
        } else if char == ")" {
            stack.removeLast()
            if stack.isEmpty {
                result.append(maxDepth)
                maxDepth = 0
            }
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3][/INST]  ```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var stack = [Int]()
    var maxDepth = 0

    for char in parenString {
        if char == "(" {
            stack.append(stack.count)
            maxDepth = max(maxDepth, stack.count)
        } else if char == ")" {
            stack.removeLast()
            if stack.isEmpty {
                result.append(maxDepth)
                maxDepth = 0
            }
        }
    }

    return result
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var maxDepths: [Int] = []
    var currentDepth = 0
    var maxDepth = 0

    for char in parenString {
        if char == "(" {
            currentDepth += 1
            maxDepth = max(maxDepth, currentDepth)
        } else if char == ")" {
            currentDepth -= 1
        } else if char == " " && currentDepth > 0 {
            maxDepths.append(maxDepth)
            maxDepth = 0
            currentDepth = 0
        }
    }

    if currentDepth > 0 {
        maxDepths.append(maxDepth)
    }

    return maxDepths
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3][/INST]  ```swift
func parseNestedParens(parenString: String) -> [Int] {
    var maxDepths: [Int] = []
    var currentDepth = 0
    var maxDepth = 0

    for char in parenString {
        if char == "(" {
            currentDepth += 1
            maxDepth = max(maxDepth, currentDepth)
        } else if char == ")" {
            currentDepth -= 1
        } else if char == " " && currentDepth > 0 {
            maxDepths.append(maxDepth)
            maxDepth = 0
            currentDepth = 0
        }
    }

    if currentDepth > 0 {
        maxDepths.append(maxDepth)
    }

    return maxDepths
}
```
 // XCTAssertTrue failed

func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var stack = [Int]()
    var maxDepth = 0

    for char in parenString {
        if char == "(" {
            stack.append(stack.count)
            maxDepth = max(maxDepth, stack.count)
        } else if char == ")" {
            stack.removeLast()
        } else if char == " " && !stack.isEmpty {
            result.append(maxDepth)
            stack.removeAll()
            maxDepth = 0
        }
    }

    if !stack.isEmpty {
        result.append(maxDepth)
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3][/INST]  ```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var stack = [Int]()
    var maxDepth = 0

    for char in parenString {
        if char == "(" {
            stack.append(stack.count)
            maxDepth = max(maxDepth, stack.count)
        } else if char == ")" {
            stack.removeLast()
        } else if char == " " && !stack.isEmpty {
            result.append(maxDepth)
            stack.removeAll()
            maxDepth = 0
        }
    }

    if !stack.isEmpty {
        result.append(maxDepth)
    }

    return result
}
```
 // XCTAssertTrue failed

func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var stack = [Int]()
    var maxDepth = 0

    for char in parenString {
        if char == "(" {
            stack.append(1)
            maxDepth = max(maxDepth, stack.count)
        } else if char == ")" {
            stack.removeLast()
            if stack.isEmpty {
                result.append(maxDepth)
                maxDepth = 0
            }
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3][/INST]  ```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var stack = [Int]()
    var maxDepth = 0

    for char in parenString {
        if char == "(" {
            stack.append(1)
            maxDepth = max(maxDepth, stack.count)
        } else if char == ")" {
            stack.removeLast()
            if stack.isEmpty {
                result.append(maxDepth)
                maxDepth = 0
            }
        }
    }

    return result
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var maxDepths: [Int] = []
    var currentDepth = 0
    var maxDepth = 0

    for char in parenString {
        if char == "(" {
            currentDepth += 1
            maxDepth = max(maxDepth, currentDepth)
        } else if char == ")" {
            currentDepth -= 1
        } else if char == " " {
            maxDepths.append(maxDepth)
            maxDepth = 0
            currentDepth = 0
        }
    }

    maxDepths.append(maxDepth)

    return maxDepths
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3][/INST]  ```swift
func parseNestedParens(parenString: String) -> [Int] {
    var maxDepths: [Int] = []
    var currentDepth = 0
    var maxDepth = 0

    for char in parenString {
        if char == "(" {
            currentDepth += 1
            maxDepth = max(maxDepth, currentDepth)
        } else if char == ")" {
            currentDepth -= 1
        } else if char == " " {
            maxDepths.append(maxDepth)
            maxDepth = 0
            currentDepth = 0
        }
    }

    maxDepths.append(maxDepth)

    return maxDepths
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var stack = [Int]()
    var maxDepth = 0

    for char in parenString {
        if char == "(" {
            stack.append(stack.count)
            maxDepth = max(maxDepth, stack.count)
        } else if char == ")" {
            stack.removeLast()
        } else if char == " " && !stack.isEmpty {
            result.append(maxDepth)
            stack.removeAll()
            maxDepth = 0
        }
    }

    if !stack.isEmpty {
        result.append(maxDepth)
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3][/INST]  ```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var stack = [Int]()
    var maxDepth = 0

    for char in parenString {
        if char == "(" {
            stack.append(stack.count)
            maxDepth = max(maxDepth, stack.count)
        } else if char == ")" {
            stack.removeLast()
        } else if char == " " && !stack.isEmpty {
            result.append(maxDepth)
            stack.removeAll()
            maxDepth = 0
        }
    }

    if !stack.isEmpty {
        result.append(maxDepth)
    }

    return result
}
```
 // XCTAssertTrue failed

func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var stack = [Int]()
    var maxDepth = 0

    for char in parenString {
        if char == "(" {
            stack.append(1)
            maxDepth = max(maxDepth, stack.count)
        } else if char == ")" {
            stack.removeLast()
        } else if char == " " && !stack.isEmpty {
            result.append(maxDepth)
            stack.removeAll()
            maxDepth = 0
        }
    }

    if !stack.isEmpty {
        result.append(maxDepth)
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3][/INST]  ```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var stack = [Int]()
    var maxDepth = 0

    for char in parenString {
        if char == "(" {
            stack.append(1)
            maxDepth = max(maxDepth, stack.count)
        } else if char == ")" {
            stack.removeLast()
        } else if char == " " && !stack.isEmpty {
            result.append(maxDepth)
            stack.removeAll()
            maxDepth = 0
        }
    }

    if !stack.isEmpty {
        result.append(maxDepth)
    }

    return result
}
```
 // XCTAssertTrue failed

func parseNestedParens(parenString: String) -> [Int] {
    var maxDepths: [Int] = []
    var currentDepth = 0
    var maxDepth = 0

    for char in parenString {
        if char == "(" {
            currentDepth += 1
            maxDepth = max(maxDepth, currentDepth)
        } else if char == ")" {
            currentDepth -= 1
        } else if char == " " && currentDepth > 0 {
            maxDepths.append(maxDepth)
            maxDepth = 0
            currentDepth = 0
        }
    }

    if currentDepth > 0 {
        maxDepths.append(maxDepth)
    }

    return maxDepths
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3][/INST]  ```swift
func parseNestedParens(parenString: String) -> [Int] {
    var maxDepths: [Int] = []
    var currentDepth = 0
    var maxDepth = 0

    for char in parenString {
        if char == "(" {
            currentDepth += 1
            maxDepth = max(maxDepth, currentDepth)
        } else if char == ")" {
            currentDepth -= 1
        } else if char == " " && currentDepth > 0 {
            maxDepths.append(maxDepth)
            maxDepth = 0
            currentDepth = 0
        }
    }

    if currentDepth > 0 {
        maxDepths.append(maxDepth)
    }

    return maxDepths
}
```
 // XCTAssertTrue failed

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"][/INST]  ```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"][/INST]  ```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"][/INST]  ```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"][/INST]  ```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"][/INST]  ```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"][/INST]  ```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"][/INST]  ```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"][/INST]  ```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"][/INST]  ```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"][/INST]  ```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1

    for number in numbers {
        sum += number
        product *= number
    }

    return (sum, product)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)[/INST]  ```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1

    for number in numbers {
        sum += number
        product *= number
    }

    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)[/INST]  ```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1

    for number in numbers {
        sum += number
        product *= number
    }

    return (sum, product)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)[/INST]  ```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1

    for number in numbers {
        sum += number
        product *= number
    }

    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1

    for number in numbers {
        sum += number
        product *= number
    }

    return (sum, product)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)[/INST]  ```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1

    for number in numbers {
        sum += number
        product *= number
    }

    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1

    for number in numbers {
        sum += number
        product *= number
    }

    return (sum, product)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)[/INST]  ```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1

    for number in numbers {
        sum += number
        product *= number
    }

    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)[/INST]  ```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1

    for number in numbers {
        sum += number
        product *= number
    }

    return (sum, product)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)[/INST]  ```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1

    for number in numbers {
        sum += number
        product *= number
    }

    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1

    for number in numbers {
        sum += number
        product *= number
    }

    return (sum, product)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)[/INST]  ```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1

    for number in numbers {
        sum += number
        product *= number
    }

    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)[/INST]  ```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1

    for number in numbers {
        sum += number
        product *= number
    }

    return (sum, product)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)[/INST]  ```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1

    for number in numbers {
        sum += number
        product *= number
    }

    return (sum, product)
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var maxNumbers: [Int] = []
    var currentMax = Int.min

    for number in numbers {
        if number > currentMax {
            currentMax = number
        }
        maxNumbers.append(currentMax)
    }

    return maxNumbers
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4][/INST]  ```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var maxNumbers: [Int] = []
    var currentMax = Int.min

    for number in numbers {
        if number > currentMax {
            currentMax = number
        }
        maxNumbers.append(currentMax)
    }

    return maxNumbers
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var maxSoFar = Int.min

    for number in numbers {
        maxSoFar = max(maxSoFar, number)
        result.append(maxSoFar)
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4][/INST]  ```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var maxSoFar = Int.min

    for number in numbers {
        maxSoFar = max(maxSoFar, number)
        result.append(maxSoFar)
    }

    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var maxSoFar = Int.min
    var result = [Int]()

    for number in numbers {
        maxSoFar = max(maxSoFar, number)
        result.append(maxSoFar)
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4][/INST]  ```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var maxSoFar = Int.min
    var result = [Int]()

    for number in numbers {
        maxSoFar = max(maxSoFar, number)
        result.append(maxSoFar)
    }

    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var maxArray = [Int]()
    var currentMax = Int.min

    for number in numbers {
        if number > currentMax {
            currentMax = number
        }
        maxArray.append(currentMax)
    }

    return maxArray
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4][/INST]  ```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var maxArray = [Int]()
    var currentMax = Int.min

    for number in numbers {
        if number > currentMax {
            currentMax = number
        }
        maxArray.append(currentMax)
    }

    return maxArray
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var maxArray = [Int]()
    var currentMax = Int.min

    for number in numbers {
        if number > currentMax {
            currentMax = number
        }
        maxArray.append(currentMax)
    }

    return maxArray
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4][/INST]  ```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var maxArray = [Int]()
    var currentMax = Int.min

    for number in numbers {
        if number > currentMax {
            currentMax = number
        }
        maxArray.append(currentMax)
    }

    return maxArray
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var maxNumbers = [Int]()
    var currentMax = Int.min

    for number in numbers {
        if number > currentMax {
            currentMax = number
        }
        maxNumbers.append(currentMax)
    }

    return maxNumbers
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4][/INST]  ```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var maxNumbers = [Int]()
    var currentMax = Int.min

    for number in numbers {
        if number > currentMax {
            currentMax = number
        }
        maxNumbers.append(currentMax)
    }

    return maxNumbers
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var maxNumbers = [Int]()
    var currentMax = Int.min

    for number in numbers {
        if number > currentMax {
            currentMax = number
        }
        maxNumbers.append(currentMax)
    }

    return maxNumbers
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4][/INST]  ```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var maxNumbers = [Int]()
    var currentMax = Int.min

    for number in numbers {
        if number > currentMax {
            currentMax = number
        }
        maxNumbers.append(currentMax)
    }

    return maxNumbers
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var maxArray = [Int]()
    var currentMax = Int.min

    for number in numbers {
        currentMax = max(currentMax, number)
        maxArray.append(currentMax)
    }

    return maxArray
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4][/INST]  ```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var maxArray = [Int]()
    var currentMax = Int.min

    for number in numbers {
        currentMax = max(currentMax, number)
        maxArray.append(currentMax)
    }

    return maxArray
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var maxArray = [Int]()
    var currentMax = Int.min

    for number in numbers {
        currentMax = max(currentMax, number)
        maxArray.append(currentMax)
    }

    return maxArray
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4][/INST]  ```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var maxArray = [Int]()
    var currentMax = Int.min

    for number in numbers {
        currentMax = max(currentMax, number)
        maxArray.append(currentMax)
    }

    return maxArray
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var maxNumbers = [Int]()
    var currentMax = Int.min

    for number in numbers {
        if number > currentMax {
            currentMax = number
        }
        maxNumbers.append(currentMax)
    }

    return maxNumbers
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4][/INST]  ```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var maxNumbers = [Int]()
    var currentMax = Int.min

    for number in numbers {
        if number > currentMax {
            currentMax = number
        }
        maxNumbers.append(currentMax)
    }

    return maxNumbers
}
```

func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    var i = string.count

    while i > 0 {
        if string.hasPrefix(reversed.suffix(from: reversed.index(reversed.startIndex, offsetBy: string.count - i))) {
            break
        }
        i -= 1
    }

    let prefix = string.prefix(upTo: string.index(string.startIndex, offsetBy: i))
    let suffix = string.suffix(from: string.index(string.startIndex, offsetBy: i))
    let middle = String(prefix.reversed())

    return string + middle + suffix
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"[/INST]  ```swift
func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    var i = string.count

    while i > 0 {
        if string.hasPrefix(reversed.suffix(from: reversed.index(reversed.startIndex, offsetBy: string.count - i))) {
            break
        }
        i -= 1
    }

    let prefix = string.prefix(upTo: string.index(string.startIndex, offsetBy: i))
    let suffix = string.suffix(from: string.index(string.startIndex, offsetBy: i))
    let middle = String(prefix.reversed())

    return string + middle + suffix
}
```
 // XCTAssertTrue failed

func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    for i in 0..<string.count {
        let prefix = String(string.prefix(i))
        if prefix == String(reversed.prefix(i)) {
            return string + String(reversed.dropFirst(i))
        }
    }
    return string
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"[/INST]  ```swift
func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    for i in 0..<string.count {
        let prefix = String(string.prefix(i))
        if prefix == String(reversed.prefix(i)) {
            return string + String(reversed.dropFirst(i))
        }
    }
    return string
}
```
 // XCTAssertTrue failed

func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    for i in 0...string.count {
        let prefix = String(string.prefix(i))
        let suffix = String(reversed.prefix(i))
        if prefix == suffix {
            let remaining = String(string.dropFirst(i))
            return string + String(remaining.reversed())
        }
    }
    return string
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"[/INST]  ```swift
func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    for i in 0...string.count {
        let prefix = String(string.prefix(i))
        let suffix = String(reversed.prefix(i))
        if prefix == suffix {
            let remaining = String(string.dropFirst(i))
            return string + String(remaining.reversed())
        }
    }
    return string
}
```
 // XCTAssertTrue failed

func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    var i = 0
    while i < string.count && string[string.startIndex..<string.index(string.startIndex, offsetBy: i + 1)] != reversed[reversed.startIndex..<reversed.index(reversed.startIndex, offsetBy: i + 1)] {
        i += 1
    }
    let prefix = String(string[string.index(string.startIndex, offsetBy: i)...])
    let suffix = String(string[..<string.index(string.startIndex, offsetBy: i)])
    return string + String(suffix.reversed())
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"[/INST]  ```swift
func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    var i = 0
    while i < string.count && string[string.startIndex..<string.index(string.startIndex, offsetBy: i + 1)] != reversed[reversed.startIndex..<reversed.index(reversed.startIndex, offsetBy: i + 1)] {
        i += 1
    }
    let prefix = String(string[string.index(string.startIndex, offsetBy: i)...])
    let suffix = String(string[..<string.index(string.startIndex, offsetBy: i)])
    return string + String(suffix.reversed())
}
```
let prefix = String(string[string.index(string.startIndex, offsetBy: i)...]) // initialization of immutable value 'prefix' was never used; consider replacing with assignment to '_' or removing it
 // XCTAssertTrue failed

func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    var i = 0
    while i < string.count && string[string.startIndex..<string.index(string.startIndex, offsetBy: i + 1)] != reversed[reversed.startIndex..<reversed.index(reversed.startIndex, offsetBy: i + 1)] {
        i += 1
    }
    let prefix = String(string[string.index(string.startIndex, offsetBy: i)...])
    let suffix = String(string[..<string.index(string.startIndex, offsetBy: i)])
    return string + String(suffix.reversed())
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"[/INST]  ```swift
func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    var i = 0
    while i < string.count && string[string.startIndex..<string.index(string.startIndex, offsetBy: i + 1)] != reversed[reversed.startIndex..<reversed.index(reversed.startIndex, offsetBy: i + 1)] {
        i += 1
    }
    let prefix = String(string[string.index(string.startIndex, offsetBy: i)...])
    let suffix = String(string[..<string.index(string.startIndex, offsetBy: i)])
    return string + String(suffix.reversed())
}
```
let prefix = String(string[string.index(string.startIndex, offsetBy: i)...]) // initialization of immutable value 'prefix' was never used; consider replacing with assignment to '_' or removing it
 // XCTAssertTrue failed

func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    var i = 0
    while i < string.count && string[string.startIndex..<string.index(string.startIndex, offsetBy: i + 1)] != reversed[reversed.startIndex..<reversed.index(reversed.startIndex, offsetBy: i + 1)] {
        i += 1
    }
    let prefix = String(string[string.index(string.startIndex, offsetBy: i)...])
    let suffix = String(string[..<string.index(string.startIndex, offsetBy: i)])
    return string + String(suffix.reversed())
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"[/INST]  ```swift
func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    var i = 0
    while i < string.count && string[string.startIndex..<string.index(string.startIndex, offsetBy: i + 1)] != reversed[reversed.startIndex..<reversed.index(reversed.startIndex, offsetBy: i + 1)] {
        i += 1
    }
    let prefix = String(string[string.index(string.startIndex, offsetBy: i)...])
    let suffix = String(string[..<string.index(string.startIndex, offsetBy: i)])
    return string + String(suffix.reversed())
}
```
let prefix = String(string[string.index(string.startIndex, offsetBy: i)...]) // initialization of immutable value 'prefix' was never used; consider replacing with assignment to '_' or removing it
 // XCTAssertTrue failed

func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    var i = string.count

    while i > 0 {
        if string.hasPrefix(reversed.suffix(from: reversed.index(reversed.startIndex, offsetBy: string.count - i))) {
            break
        }
        i -= 1
    }

    let prefix = String(string.prefix(i))
    let suffix = String(string.dropFirst(i))
    let reversedPrefix = String(prefix.reversed())

    return string + reversedPrefix + suffix
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"[/INST]  ```swift
func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    var i = string.count

    while i > 0 {
        if string.hasPrefix(reversed.suffix(from: reversed.index(reversed.startIndex, offsetBy: string.count - i))) {
            break
        }
        i -= 1
    }

    let prefix = String(string.prefix(i))
    let suffix = String(string.dropFirst(i))
    let reversedPrefix = String(prefix.reversed())

    return string + reversedPrefix + suffix
}
```
 // XCTAssertTrue failed

func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    var i = 0
    while i < string.count && string[string.startIndex..<string.index(string.startIndex, offsetBy: i + 1)] != reversed[reversed.startIndex..<reversed.index(reversed.startIndex, offsetBy: i + 1)] {
        i += 1
    }
    let prefix = String(string[string.index(string.startIndex, offsetBy: i)...])
    let suffix = String(string[..<string.index(string.startIndex, offsetBy: i)])
    return string + String(suffix.reversed())
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"[/INST]  ```swift
func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    var i = 0
    while i < string.count && string[string.startIndex..<string.index(string.startIndex, offsetBy: i + 1)] != reversed[reversed.startIndex..<reversed.index(reversed.startIndex, offsetBy: i + 1)] {
        i += 1
    }
    let prefix = String(string[string.index(string.startIndex, offsetBy: i)...])
    let suffix = String(string[..<string.index(string.startIndex, offsetBy: i)])
    return string + String(suffix.reversed())
}
```
let prefix = String(string[string.index(string.startIndex, offsetBy: i)...]) // initialization of immutable value 'prefix' was never used; consider replacing with assignment to '_' or removing it
 // XCTAssertTrue failed

func makePalindrome(string: String) -> String {
    let characters = Array(string)
    var longestPalindromeLength = 0

    for i in 0..<characters.count {
        if isPalindrome(characters[i...]) {
            longestPalindromeLength = characters.count - i
            break
        }
    }

    let prefix = String(characters[0..<characters.count - longestPalindromeLength])
    let reversedPrefix = String(prefix.reversed())

    return string + reversedPrefix
}

func isPalindrome(_ characters: ArraySlice<Character>) -> Bool {
    let reversedCharacters = characters.reversed()
    return Array(characters) == Array(reversedCharacters)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"[/INST]  ```swift
func makePalindrome(string: String) -> String {
    let characters = Array(string)
    var longestPalindromeLength = 0

    for i in 0..<characters.count {
        if isPalindrome(characters[i...]) {
            longestPalindromeLength = characters.count - i
            break
        }
    }

    let prefix = String(characters[0..<characters.count - longestPalindromeLength])
    let reversedPrefix = String(prefix.reversed())

    return string + reversedPrefix
}

func isPalindrome(_ characters: ArraySlice<Character>) -> Bool {
    let reversedCharacters = characters.reversed()
    return Array(characters) == Array(reversedCharacters)
}
```

func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    var i = string.count

    while i > 0 {
        if string.hasPrefix(reversed.suffix(i)) {
            break
        }
        i -= 1
    }

    let prefix = String(string.dropLast(i))
    let palindrome = string + String(prefix.reversed())

    return palindrome
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"[/INST]  ```swift
func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    var i = string.count

    while i > 0 {
        if string.hasPrefix(reversed.suffix(i)) {
            break
        }
        i -= 1
    }

    let prefix = String(string.dropLast(i))
    let palindrome = string + String(prefix.reversed())

    return palindrome
}
```

func stringXor(a: String, b: String) -> String {
    var result = ""
    for (charA, charB) in zip(a, b) {
        if charA == charB {
            result.append("0")
        } else {
            result.append("1")
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"[/INST]  ```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for (charA, charB) in zip(a, b) {
        if charA == charB {
            result.append("0")
        } else {
            result.append("1")
        }
    }
    return result
}
```

func stringXor(a: String, b: String) -> String {
    var result = ""
    for (charA, charB) in zip(a, b) {
        if charA != charB {
            result += "1"
        } else {
            result += "0"
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"[/INST]  ```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for (charA, charB) in zip(a, b) {
        if charA != charB {
            result += "1"
        } else {
            result += "0"
        }
    }
    return result
}
```

func stringXor(a: String, b: String) -> String {
    var result = ""
    for (charA, charB) in zip(a, b) {
        if charA == charB {
            result.append("0")
        } else {
            result.append("1")
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"[/INST]  ```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for (charA, charB) in zip(a, b) {
        if charA == charB {
            result.append("0")
        } else {
            result.append("1")
        }
    }
    return result
}
```

func stringXor(a: String, b: String) -> String {
    var result = ""
    for (charA, charB) in zip(a, b) {
        if charA == charB {
            result.append("0")
        } else {
            result.append("1")
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"[/INST]  ```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for (charA, charB) in zip(a, b) {
        if charA == charB {
            result.append("0")
        } else {
            result.append("1")
        }
    }
    return result
}
```

func stringXor(a: String, b: String) -> String {
    var result = ""
    for (charA, charB) in zip(a, b) {
        if charA == charB {
            result.append("0")
        } else {
            result.append("1")
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"[/INST]  ```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for (charA, charB) in zip(a, b) {
        if charA == charB {
            result.append("0")
        } else {
            result.append("1")
        }
    }
    return result
}
```

func stringXor(a: String, b: String) -> String {
    var result = ""
    for (charA, charB) in zip(a, b) {
        if charA == charB {
            result += "0"
        } else {
            result += "1"
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"[/INST]  ```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for (charA, charB) in zip(a, b) {
        if charA == charB {
            result += "0"
        } else {
            result += "1"
        }
    }
    return result
}
```

func stringXor(a: String, b: String) -> String {
    var result = ""
    for (charA, charB) in zip(a, b) {
        if charA == charB {
            result.append("0")
        } else {
            result.append("1")
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"[/INST]  ```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for (charA, charB) in zip(a, b) {
        if charA == charB {
            result.append("0")
        } else {
            result.append("1")
        }
    }
    return result
}
```

func stringXor(a: String, b: String) -> String {
    var result = ""
    for (charA, charB) in zip(a, b) {
        if charA == charB {
            result.append("0")
        } else {
            result.append("1")
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"[/INST]  ```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for (charA, charB) in zip(a, b) {
        if charA == charB {
            result.append("0")
        } else {
            result.append("1")
        }
    }
    return result
}
```

func stringXor(a: String, b: String) -> String {
    var result = ""
    for (charA, charB) in zip(a, b) {
        if charA == charB {
            result.append("0")
        } else {
            result.append("1")
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"[/INST]  ```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for (charA, charB) in zip(a, b) {
        if charA == charB {
            result.append("0")
        } else {
            result.append("1")
        }
    }
    return result
}
```

func stringXor(a: String, b: String) -> String {
    var result = ""
    for (charA, charB) in zip(a, b) {
        if charA == charB {
            result.append("0")
        } else {
            result.append("1")
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"[/INST]  ```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for (charA, charB) in zip(a, b) {
        if charA == charB {
            result.append("0")
        } else {
            result.append("1")
        }
    }
    return result
}
```

func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else {
        return nil
    }

    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }

    return longestString
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"[/INST]  ```swift
func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else {
        return nil
    }

    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }

    return longestString
}
```

func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else {
        return nil
    }

    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }

    return longestString
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"[/INST]  ```swift
func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else {
        return nil
    }

    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }

    return longestString
}
```

func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else {
        return nil
    }

    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }

    return longestString
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"[/INST]  ```swift
func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else {
        return nil
    }

    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }

    return longestString
}
```

func longest(strings: [String]) -> String? {
    if strings.isEmpty {
        return nil
    }

    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }

    return longestString
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"[/INST]  ```swift
func longest(strings: [String]) -> String? {
    if strings.isEmpty {
        return nil
    }

    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }

    return longestString
}
```

func longest(strings: [String]) -> String? {
    if strings.isEmpty {
        return nil
    }

    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }

    return longestString
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"[/INST]  ```swift
func longest(strings: [String]) -> String? {
    if strings.isEmpty {
        return nil
    }

    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }

    return longestString
}
```

func longest(strings: [String]) -> String? {
    if strings.isEmpty {
        return nil
    }

    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }

    return longestString
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"[/INST]  ```swift
func longest(strings: [String]) -> String? {
    if strings.isEmpty {
        return nil
    }

    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }

    return longestString
}
```

func longest(strings: [String]) -> String? {
    if strings.isEmpty {
        return nil
    }

    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }

    return longestString
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"[/INST]  ```swift
func longest(strings: [String]) -> String? {
    if strings.isEmpty {
        return nil
    }

    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }

    return longestString
}
```

func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else {
        return nil
    }

    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }

    return longestString
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"[/INST]  ```swift
func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else {
        return nil
    }

    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }

    return longestString
}
```

func longest(strings: [String]) -> String? {
    if strings.isEmpty {
        return nil
    }

    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }

    return longestString
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"[/INST]  ```swift
func longest(strings: [String]) -> String? {
    if strings.isEmpty {
        return nil
    }

    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }

    return longestString
}
```

func longest(strings: [String]) -> String? {
    if strings.isEmpty {
        return nil
    }

    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }

    return longestString
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"[/INST]  ```swift
func longest(strings: [String]) -> String? {
    if strings.isEmpty {
        return nil
    }

    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }

    return longestString
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var num1 = a
    var num2 = b

    while num2 != 0 {
        let temp = num2
        num2 = num1 % num2
        num1 = temp
    }

    return num1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5[/INST]  ```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var num1 = a
    var num2 = b

    while num2 != 0 {
        let temp = num2
        num2 = num1 % num2
        num1 = temp
    }

    return num1
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5[/INST]  ```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5[/INST]  ```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var num1 = a
    var num2 = b
    while num2 != 0 {
        let temp = num2
        num2 = num1 % num2
        num1 = temp
    }
    return num1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5[/INST]  ```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var num1 = a
    var num2 = b
    while num2 != 0 {
        let temp = num2
        num2 = num1 % num2
        num1 = temp
    }
    return num1
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var num1 = a
    var num2 = b

    while num2 != 0 {
        let temp = num2
        num2 = num1 % num2
        num1 = temp
    }

    return num1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5[/INST]  ```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var num1 = a
    var num2 = b

    while num2 != 0 {
        let temp = num2
        num2 = num1 % num2
        num1 = temp
    }

    return num1
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var num1 = a
    var num2 = b
    while num2 != 0 {
        let temp = num2
        num2 = num1 % num2
        num1 = temp
    }
    return num1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5[/INST]  ```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var num1 = a
    var num2 = b
    while num2 != 0 {
        let temp = num2
        num2 = num1 % num2
        num1 = temp
    }
    return num1
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var num1 = a
    var num2 = b
    while num2 != 0 {
        let temp = num2
        num2 = num1 % num2
        num1 = temp
    }
    return num1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5[/INST]  ```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var num1 = a
    var num2 = b
    while num2 != 0 {
        let temp = num2
        num2 = num1 % num2
        num1 = temp
    }
    return num1
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var num1 = a
    var num2 = b

    while num2 != 0 {
        let temp = num2
        num2 = num1 % num2
        num1 = temp
    }

    return num1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5[/INST]  ```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var num1 = a
    var num2 = b

    while num2 != 0 {
        let temp = num2
        num2 = num1 % num2
        num1 = temp
    }

    return num1
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var num1 = a
    var num2 = b
    while num2 != 0 {
        let temp = num2
        num2 = num1 % num2
        num1 = temp
    }
    return num1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5[/INST]  ```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var num1 = a
    var num2 = b
    while num2 != 0 {
        let temp = num2
        num2 = num1 % num2
        num1 = temp
    }
    return num1
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5[/INST]  ```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for endIndex in string.indices {
        prefixes.append(String(string[string.startIndex...endIndex]))
    }
    return prefixes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"][/INST]  ```swift
func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for endIndex in string.indices {
        prefixes.append(String(string[string.startIndex...endIndex]))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for endIndex in string.indices {
        prefixes.append(String(string[string.startIndex...endIndex]))
    }
    return prefixes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"][/INST]  ```swift
func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for endIndex in string.indices {
        prefixes.append(String(string[string.startIndex...endIndex]))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for endIndex in string.indices {
        prefixes.append(String(string[string.startIndex...endIndex]))
    }
    return prefixes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"][/INST]  ```swift
func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for endIndex in string.indices {
        prefixes.append(String(string[string.startIndex...endIndex]))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for endIndex in string.indices {
        prefixes.append(String(string[string.startIndex...endIndex]))
    }
    return prefixes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"][/INST]  ```swift
func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for endIndex in string.indices {
        prefixes.append(String(string[string.startIndex...endIndex]))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for endIndex in string.indices {
        prefixes.append(String(string[..<endIndex]))
    }
    return prefixes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"][/INST]  ```swift
func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for endIndex in string.indices {
        prefixes.append(String(string[..<endIndex]))
    }
    return prefixes
}
```
 // XCTAssertTrue failed

func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    var currentPrefix = ""

    for char in string {
        currentPrefix.append(char)
        prefixes.append(currentPrefix)
    }

    return prefixes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"][/INST]  ```swift
func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    var currentPrefix = ""

    for char in string {
        currentPrefix.append(char)
        prefixes.append(currentPrefix)
    }

    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for endIndex in string.indices {
        prefixes.append(String(string[..<endIndex]))
    }
    return prefixes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"][/INST]  ```swift
func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for endIndex in string.indices {
        prefixes.append(String(string[..<endIndex]))
    }
    return prefixes
}
```
 // XCTAssertTrue failed

func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for endIndex in string.indices {
        prefixes.append(String(string[..<endIndex]))
    }
    return prefixes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"][/INST]  ```swift
func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for endIndex in string.indices {
        prefixes.append(String(string[..<endIndex]))
    }
    return prefixes
}
```
 // XCTAssertTrue failed

func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for endIndex in string.indices {
        prefixes.append(String(string[string.startIndex...endIndex]))
    }
    return prefixes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"][/INST]  ```swift
func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for endIndex in string.indices {
        prefixes.append(String(string[string.startIndex...endIndex]))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    var currentPrefix = ""
    for char in string {
        currentPrefix.append(char)
        prefixes.append(currentPrefix)
    }
    return prefixes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"][/INST]  ```swift
func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    var currentPrefix = ""
    for char in string {
        currentPrefix.append(char)
        prefixes.append(currentPrefix)
    }
    return prefixes
}
```

func stringSequence(n: Int) -> String {
    var sequence = ""
    for i in 0...n {
        sequence += "\(i) "
    }
    return sequence.trimmingCharacters(in: .whitespaces)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"[/INST]  ```swift
func stringSequence(n: Int) -> String {
    var sequence = ""
    for i in 0...n {
        sequence += "\(i) "
    }
    return sequence.trimmingCharacters(in: .whitespaces)
}
```

func stringSequence(n: Int) -> String {
    var sequence = ""
    for i in 0...n {
        sequence += "\(i) "
    }
    return sequence.trimmingCharacters(in: .whitespaces)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"[/INST]  ```swift
func stringSequence(n: Int) -> String {
    var sequence = ""
    for i in 0...n {
        sequence += "\(i) "
    }
    return sequence.trimmingCharacters(in: .whitespaces)
}
```

func stringSequence(n: Int) -> String {
    var sequence = ""
    for i in 0...n {
        sequence += "\(i) "
    }
    return sequence.trimmingCharacters(in: .whitespaces)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"[/INST]  ```swift
func stringSequence(n: Int) -> String {
    var sequence = ""
    for i in 0...n {
        sequence += "\(i) "
    }
    return sequence.trimmingCharacters(in: .whitespaces)
}
```

func stringSequence(n: Int) -> String {
    var sequence = [String]()
    for i in 0...n {
        sequence.append(String(i))
    }
    return sequence.joined(separator: " ")
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"[/INST]  ```swift
func stringSequence(n: Int) -> String {
    var sequence = [String]()
    for i in 0...n {
        sequence.append(String(i))
    }
    return sequence.joined(separator: " ")
}
```

func stringSequence(n: Int) -> String {
    var sequence = ""
    for i in 0...n {
        sequence += "\(i) "
    }
    return sequence.trimmingCharacters(in: .whitespaces)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"[/INST]  ```swift
func stringSequence(n: Int) -> String {
    var sequence = ""
    for i in 0...n {
        sequence += "\(i) "
    }
    return sequence.trimmingCharacters(in: .whitespaces)
}
```

func stringSequence(n: Int) -> String {
    var sequence = ""
    for i in 0...n {
        sequence += "\(i) "
    }
    return sequence.trimmingCharacters(in: .whitespaces)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"[/INST]  ```swift
func stringSequence(n: Int) -> String {
    var sequence = ""
    for i in 0...n {
        sequence += "\(i) "
    }
    return sequence.trimmingCharacters(in: .whitespaces)
}
```

func stringSequence(n: Int) -> String {
    var sequence = ""
    for i in 0...n {
        sequence += "\(i) "
    }
    return sequence.trimmingCharacters(in: .whitespaces)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"[/INST]  ```swift
func stringSequence(n: Int) -> String {
    var sequence = ""
    for i in 0...n {
        sequence += "\(i) "
    }
    return sequence.trimmingCharacters(in: .whitespaces)
}
```

func stringSequence(n: Int) -> String {
    var sequence = ""
    for i in 0...n {
        sequence += "\(i) "
    }
    return sequence.trimmingCharacters(in: .whitespaces)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"[/INST]  ```swift
func stringSequence(n: Int) -> String {
    var sequence = ""
    for i in 0...n {
        sequence += "\(i) "
    }
    return sequence.trimmingCharacters(in: .whitespaces)
}
```

func stringSequence(n: Int) -> String {
    var sequence = ""
    for i in 0...n {
        sequence += "\(i) "
    }
    return sequence.trimmingCharacters(in: .whitespaces)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"[/INST]  ```swift
func stringSequence(n: Int) -> String {
    var sequence = ""
    for i in 0...n {
        sequence += "\(i) "
    }
    return sequence.trimmingCharacters(in: .whitespaces)
}
```

func stringSequence(n: Int) -> String {
    var sequence = [String]()
    for i in 0...n {
        sequence.append(String(i))
    }
    return sequence.joined(separator: " ")
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"[/INST]  ```swift
func stringSequence(n: Int) -> String {
    var sequence = [String]()
    for i in 0...n {
        sequence.append(String(i))
    }
    return sequence.joined(separator: " ")
}
```

func countDistinctCharacters(string: String) -> Int {
    let lowercasedString = string.lowercased()
    let distinctCharacters = Set(lowercasedString)
    return distinctCharacters.count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4[/INST]  ```swift
func countDistinctCharacters(string: String) -> Int {
    let lowercasedString = string.lowercased()
    let distinctCharacters = Set(lowercasedString)
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let lowercasedString = string.lowercased()
    let distinctCharacters = Set(lowercasedString)
    return distinctCharacters.count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4[/INST]  ```swift
func countDistinctCharacters(string: String) -> Int {
    let lowercasedString = string.lowercased()
    let distinctCharacters = Set(lowercasedString)
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let distinctCharacters = Set(string.lowercased())
    return distinctCharacters.count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4[/INST]  ```swift
func countDistinctCharacters(string: String) -> Int {
    let distinctCharacters = Set(string.lowercased())
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let distinctCharacters = Set(string.lowercased())
    return distinctCharacters.count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4[/INST]  ```swift
func countDistinctCharacters(string: String) -> Int {
    let distinctCharacters = Set(string.lowercased())
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let distinctCharacters = Set(string.lowercased())
    return distinctCharacters.count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4[/INST]  ```swift
func countDistinctCharacters(string: String) -> Int {
    let distinctCharacters = Set(string.lowercased())
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let lowercasedString = string.lowercased()
    let distinctCharacters = Set(lowercasedString)
    return distinctCharacters.count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4[/INST]  ```swift
func countDistinctCharacters(string: String) -> Int {
    let lowercasedString = string.lowercased()
    let distinctCharacters = Set(lowercasedString)
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let distinctCharacters = Set(string.lowercased())
    return distinctCharacters.count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4[/INST]  ```swift
func countDistinctCharacters(string: String) -> Int {
    let distinctCharacters = Set(string.lowercased())
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let distinctCharacters = Set(string.lowercased())
    return distinctCharacters.count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4[/INST]  ```swift
func countDistinctCharacters(string: String) -> Int {
    let distinctCharacters = Set(string.lowercased())
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let distinctCharacters = Set(string.lowercased())
    return distinctCharacters.count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4[/INST]  ```swift
func countDistinctCharacters(string: String) -> Int {
    let distinctCharacters = Set(string.lowercased())
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let distinctCharacters = Set(string.lowercased())
    return distinctCharacters.count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4[/INST]  ```swift
func countDistinctCharacters(string: String) -> Int {
    let distinctCharacters = Set(string.lowercased())
    return distinctCharacters.count
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    let notes = musicString.split(separator: " ")

    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }

    return beats
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4][/INST]  ```swift
func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    let notes = musicString.split(separator: " ")

    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }

    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentBeat = 0

    for char in musicString {
        switch char {
        case "o":
            currentBeat = 4
        case "|":
            beats.append(currentBeat)
            currentBeat = 0
        case ".":
            currentBeat = 1
        case " ":
            if currentBeat > 0 {
                beats.append(currentBeat)
                currentBeat = 0
            }
        default:
            break
        }
    }

    if currentBeat > 0 {
        beats.append(currentBeat)
    }

    return beats
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4][/INST]  ```swift
func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentBeat = 0

    for char in musicString {
        switch char {
        case "o":
            currentBeat = 4
        case "|":
            beats.append(currentBeat)
            currentBeat = 0
        case ".":
            currentBeat = 1
        case " ":
            if currentBeat > 0 {
                beats.append(currentBeat)
                currentBeat = 0
            }
        default:
            break
        }
    }

    if currentBeat > 0 {
        beats.append(currentBeat)
    }

    return beats
}
```
 // XCTAssertTrue failed

func parseMusic(musicString: String) -> [Int] {
    var beats: [Int] = []
    let notes = musicString.split(separator: " ")

    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }

    return beats
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4][/INST]  ```swift
func parseMusic(musicString: String) -> [Int] {
    var beats: [Int] = []
    let notes = musicString.split(separator: " ")

    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }

    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentNote = ""

    for char in musicString {
        if char == " " && !currentNote.isEmpty {
            switch currentNote {
            case "o":
                beats.append(4)
            case "o|":
                beats.append(2)
            case ".|":
                beats.append(1)
            default:
                break
            }
            currentNote = ""
        } else {
            currentNote.append(char)
        }
    }

    // Append the last note
    if !currentNote.isEmpty {
        switch currentNote {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }

    return beats
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4][/INST]  ```swift
func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentNote = ""

    for char in musicString {
        if char == " " && !currentNote.isEmpty {
            switch currentNote {
            case "o":
                beats.append(4)
            case "o|":
                beats.append(2)
            case ".|":
                beats.append(1)
            default:
                break
            }
            currentNote = ""
        } else {
            currentNote.append(char)
        }
    }

    // Append the last note
    if !currentNote.isEmpty {
        switch currentNote {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }

    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    let notes = musicString.split(separator: " ")

    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }

    return beats
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4][/INST]  ```swift
func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    let notes = musicString.split(separator: " ")

    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }

    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentNote = ""

    for char in musicString {
        if char == " " && !currentNote.isEmpty {
            switch currentNote {
            case "o":
                beats.append(4)
            case "o|":
                beats.append(2)
            case ".|":
                beats.append(1)
            default:
                break
            }
            currentNote = ""
        } else {
            currentNote.append(char)
        }
    }

    if !currentNote.isEmpty {
        switch currentNote {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }

    return beats
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4][/INST]  ```swift
func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentNote = ""

    for char in musicString {
        if char == " " && !currentNote.isEmpty {
            switch currentNote {
            case "o":
                beats.append(4)
            case "o|":
                beats.append(2)
            case ".|":
                beats.append(1)
            default:
                break
            }
            currentNote = ""
        } else {
            currentNote.append(char)
        }
    }

    if !currentNote.isEmpty {
        switch currentNote {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }

    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats: [Int] = []
    let notes = musicString.split(separator: " ")

    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }

    return beats
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4][/INST]  ```swift
func parseMusic(musicString: String) -> [Int] {
    var beats: [Int] = []
    let notes = musicString.split(separator: " ")

    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }

    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    let notes = musicString.split(separator: " ")

    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }

    return beats
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4][/INST]  ```swift
func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    let notes = musicString.split(separator: " ")

    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }

    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats: [Int] = []
    let notes = musicString.split(separator: " ")

    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }

    return beats
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4][/INST]  ```swift
func parseMusic(musicString: String) -> [Int] {
    var beats: [Int] = []
    let notes = musicString.split(separator: " ")

    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }

    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    let notes = musicString.split(separator: " ")

    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }

    return beats
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4][/INST]  ```swift
func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    let notes = musicString.split(separator: " ")

    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }

    return beats
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var searchStartIndex = string.startIndex

    while searchStartIndex < string.endIndex {
        if let foundRange = string[searchStartIndex...].range(of: substring) {
            count += 1
            searchStartIndex = foundRange.upperBound
        } else {
            break
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3[/INST]  ```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var searchStartIndex = string.startIndex

    while searchStartIndex < string.endIndex {
        if let foundRange = string[searchStartIndex...].range(of: substring) {
            count += 1
            searchStartIndex = foundRange.upperBound
        } else {
            break
        }
    }

    return count
}
```
 // XCTAssertTrue failed

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var startIndex = string.startIndex

    while startIndex < string.endIndex {
        if let range = string[startIndex...].range(of: substring) {
            count += 1
            startIndex = range.upperBound
        } else {
            break
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3[/INST]  ```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var startIndex = string.startIndex

    while startIndex < string.endIndex {
        if let range = string[startIndex...].range(of: substring) {
            count += 1
            startIndex = range.upperBound
        } else {
            break
        }
    }

    return count
}
```
 // XCTAssertTrue failed

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var startIndex = string.startIndex

    while startIndex < string.endIndex {
        if let range = string[startIndex...].range(of: substring) {
            count += 1
            startIndex = range.upperBound
        } else {
            break
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3[/INST]  ```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var startIndex = string.startIndex

    while startIndex < string.endIndex {
        if let range = string[startIndex...].range(of: substring) {
            count += 1
            startIndex = range.upperBound
        } else {
            break
        }
    }

    return count
}
```
 // XCTAssertTrue failed

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var startIndex = string.startIndex

    while startIndex < string.endIndex {
        if let range = string[startIndex...].range(of: substring) {
            count += 1
            startIndex = range.upperBound
        } else {
            break
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3[/INST]  ```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var startIndex = string.startIndex

    while startIndex < string.endIndex {
        if let range = string[startIndex...].range(of: substring) {
            count += 1
            startIndex = range.upperBound
        } else {
            break
        }
    }

    return count
}
```
 // XCTAssertTrue failed

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var startIndex = string.startIndex

    while startIndex < string.endIndex {
        if let range = string[startIndex...].range(of: substring) {
            count += 1
            startIndex = range.upperBound
        } else {
            break
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3[/INST]  ```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var startIndex = string.startIndex

    while startIndex < string.endIndex {
        if let range = string[startIndex...].range(of: substring) {
            count += 1
            startIndex = range.upperBound
        } else {
            break
        }
    }

    return count
}
```
 // XCTAssertTrue failed

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var startIndex = string.startIndex

    while startIndex < string.endIndex {
        if let range = string[startIndex...].range(of: substring) {
            count += 1
            startIndex = range.upperBound
        } else {
            break
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3[/INST]  ```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var startIndex = string.startIndex

    while startIndex < string.endIndex {
        if let range = string[startIndex...].range(of: substring) {
            count += 1
            startIndex = range.upperBound
        } else {
            break
        }
    }

    return count
}
```
 // XCTAssertTrue failed

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var startIndex = string.startIndex

    while startIndex < string.endIndex {
        if let range = string[startIndex...].range(of: substring) {
            count += 1
            startIndex = range.upperBound
        } else {
            break
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3[/INST]  ```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var startIndex = string.startIndex

    while startIndex < string.endIndex {
        if let range = string[startIndex...].range(of: substring) {
            count += 1
            startIndex = range.upperBound
        } else {
            break
        }
    }

    return count
}
```
 // XCTAssertTrue failed

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var startIndex = string.startIndex

    while startIndex < string.endIndex {
        if let range = string[startIndex...].range(of: substring) {
            count += 1
            startIndex = range.upperBound
        } else {
            break
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3[/INST]  ```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var startIndex = string.startIndex

    while startIndex < string.endIndex {
        if let range = string[startIndex...].range(of: substring) {
            count += 1
            startIndex = range.upperBound
        } else {
            break
        }
    }

    return count
}
```
 // XCTAssertTrue failed

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var startIndex = string.startIndex

    while startIndex < string.endIndex {
        if let range = string[startIndex...].range(of: substring) {
            count += 1
            startIndex = range.upperBound
        } else {
            break
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3[/INST]  ```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var startIndex = string.startIndex

    while startIndex < string.endIndex {
        if let range = string[startIndex...].range(of: substring) {
            count += 1
            startIndex = range.upperBound
        } else {
            break
        }
    }

    return count
}
```
 // XCTAssertTrue failed

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var startIndex = string.startIndex

    while startIndex < string.endIndex {
        if let range = string[startIndex...].range(of: substring) {
            count += 1
            startIndex = range.upperBound
        } else {
            break
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3[/INST]  ```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var startIndex = string.startIndex

    while startIndex < string.endIndex {
        if let range = string[startIndex...].range(of: substring) {
            count += 1
            startIndex = range.upperBound
        } else {
            break
        }
    }

    return count
}
```
 // XCTAssertTrue failed

func sortNumbers(numbers: String) -> String {
    let numberWords = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
    let numberValues = numbers.split(separator: " ").map { numberWords.firstIndex(of: String($0))! }
    let sortedValues = numberValues.sorted()
    let sortedNumbers = sortedValues.map { numberWords[$0] }.joined(separator: " ")
    return sortedNumbers
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"[/INST]  ```swift
func sortNumbers(numbers: String) -> String {
    let numberWords = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
    let numberValues = numbers.split(separator: " ").map { numberWords.firstIndex(of: String($0))! }
    let sortedValues = numberValues.sorted()
    let sortedNumbers = sortedValues.map { numberWords[$0] }.joined(separator: " ")
    return sortedNumbers
}
```

func sortNumbers(numbers: String) -> String {
    let numberWords = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
    let numberValues = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]

    let words = numbers.split(separator: " ").map { String($0) }
    let sortedWords = words.sorted { numberValues[$0]! < numberValues[$1]! }

    return sortedWords.joined(separator: " ")
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"[/INST]  ```swift
func sortNumbers(numbers: String) -> String {
    let numberWords = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
    let numberValues = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]

    let words = numbers.split(separator: " ").map { String($0) }
    let sortedWords = words.sorted { numberValues[$0]! < numberValues[$1]! }

    return sortedWords.joined(separator: " ")
}
```
let numberWords = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"] // initialization of immutable value 'numberWords' was never used; consider replacing with assignment to '_' or removing it

func sortNumbers(numbers: String) -> String {
    let numberMap: [String: Int] = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
    let numberWords = numbers.split(separator: " ").map { String($0) }
    let sortedNumbers = numberWords.sorted { numberMap[$0] ?? 0 < numberMap[$1] ?? 0 }
    return sortedNumbers.joined(separator: " ")
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"[/INST]  ```swift
func sortNumbers(numbers: String) -> String {
    let numberMap: [String: Int] = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
    let numberWords = numbers.split(separator: " ").map { String($0) }
    let sortedNumbers = numberWords.sorted { numberMap[$0] ?? 0 < numberMap[$1] ?? 0 }
    return sortedNumbers.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numberWords = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
    let numberValues = numbers.split(separator: " ").map { numberWords.firstIndex(of: String($0))! }
    let sortedNumberValues = numberValues.sorted()
    let sortedNumbers = sortedNumberValues.map { numberWords[$0] }.joined(separator: " ")
    return sortedNumbers
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"[/INST]  ```swift
func sortNumbers(numbers: String) -> String {
    let numberWords = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
    let numberValues = numbers.split(separator: " ").map { numberWords.firstIndex(of: String($0))! }
    let sortedNumberValues = numberValues.sorted()
    let sortedNumbers = sortedNumberValues.map { numberWords[$0] }.joined(separator: " ")
    return sortedNumbers
}
```

func sortNumbers(numbers: String) -> String {
    let numberWords = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
    let numberValues = numbers.split(separator: " ").map { numberWords.firstIndex(of: String($0))! }
    let sortedValues = numberValues.sorted()
    let sortedNumbers = sortedValues.map { numberWords[$0] }.joined(separator: " ")
    return sortedNumbers
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"[/INST]  ```swift
func sortNumbers(numbers: String) -> String {
    let numberWords = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
    let numberValues = numbers.split(separator: " ").map { numberWords.firstIndex(of: String($0))! }
    let sortedValues = numberValues.sorted()
    let sortedNumbers = sortedValues.map { numberWords[$0] }.joined(separator: " ")
    return sortedNumbers
}
```

func sortNumbers(numbers: String) -> String {
    let numberWords = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
    let numberValues = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]

    let words = numbers.split(separator: " ").map { String($0) }
    let sortedWords = words.sorted { numberValues[$0]! < numberValues[$1]! }

    return sortedWords.joined(separator: " ")
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"[/INST]  ```swift
func sortNumbers(numbers: String) -> String {
    let numberWords = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
    let numberValues = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]

    let words = numbers.split(separator: " ").map { String($0) }
    let sortedWords = words.sorted { numberValues[$0]! < numberValues[$1]! }

    return sortedWords.joined(separator: " ")
}
```
let numberWords = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"] // initialization of immutable value 'numberWords' was never used; consider replacing with assignment to '_' or removing it

func sortNumbers(numbers: String) -> String {
    let numberWords = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
    let numberValues = numbers.split(separator: " ").map { numberWords.firstIndex(of: String($0))! }
    let sortedValues = numberValues.sorted()
    let sortedNumbers = sortedValues.map { numberWords[$0] }.joined(separator: " ")
    return sortedNumbers
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"[/INST]  ```swift
func sortNumbers(numbers: String) -> String {
    let numberWords = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
    let numberValues = numbers.split(separator: " ").map { numberWords.firstIndex(of: String($0))! }
    let sortedValues = numberValues.sorted()
    let sortedNumbers = sortedValues.map { numberWords[$0] }.joined(separator: " ")
    return sortedNumbers
}
```

func sortNumbers(numbers: String) -> String {
    let numberWords = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
    let numberValues = ["0", "1", "2", "3", "4", "5", "6", "7", "8", "9"]

    var numberArray = numbers.split(separator: " ").map { String($0) }

    numberArray.sort {
        if let index1 = numberWords.firstIndex(of: $0),
           let index2 = numberWords.firstIndex(of: $1) {
            return index1 < index2
        }
        return false
    }

    for (index, number) in numberArray.enumerated() {
        if let valueIndex = numberWords.firstIndex(of: number) {
            numberArray[index] = numberValues[valueIndex]
        }
    }

    numberArray.sort {
        if let value1 = Int($0),
           let value2 = Int($1) {
            return value1 < value2
        }
        return false
    }

    for (index, number) in numberArray.enumerated() {
        if let wordIndex = numberValues.firstIndex(of: number) {
            numberArray[index] = numberWords[wordIndex]
        }
    }

    return numberArray.joined(separator: " ")
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"[/INST]  ```swift
func sortNumbers(numbers: String) -> String {
    let numberWords = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
    let numberValues = ["0", "1", "2", "3", "4", "5", "6", "7", "8", "9"]

    var numberArray = numbers.split(separator: " ").map { String($0) }

    numberArray.sort {
        if let index1 = numberWords.firstIndex(of: $0),
           let index2 = numberWords.firstIndex(of: $1) {
            return index1 < index2
        }
        return false
    }

    for (index, number) in numberArray.enumerated() {
        if let valueIndex = numberWords.firstIndex(of: number) {
            numberArray[index] = numberValues[valueIndex]
        }
    }

    numberArray.sort {
        if let value1 = Int($0),
           let value2 = Int($1) {
            return value1 < value2
        }
        return false
    }

    for (index, number) in numberArray.enumerated() {
        if let wordIndex = numberValues.firstIndex(of: number) {
            numberArray[index] = numberWords[wordIndex]
        }
    }

    return numberArray.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numberMap: [String: Int] = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
    let numberStrings = numbers.split(separator: " ").map { String($0) }
    let sortedNumbers = numberStrings.sorted { numberMap[$0] ?? 0 < numberMap[$1] ?? 0 }
    return sortedNumbers.joined(separator: " ")
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"[/INST]  ```swift
func sortNumbers(numbers: String) -> String {
    let numberMap: [String: Int] = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
    let numberStrings = numbers.split(separator: " ").map { String($0) }
    let sortedNumbers = numberStrings.sorted { numberMap[$0] ?? 0 < numberMap[$1] ?? 0 }
    return sortedNumbers.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numberWords = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
    let numberValues = numbers.split(separator: " ").map { numberWords.firstIndex(of: String($0))! }
    let sortedValues = numberValues.sorted()
    let sortedNumbers = sortedValues.map { numberWords[$0] }.joined(separator: " ")
    return sortedNumbers
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"[/INST]  ```swift
func sortNumbers(numbers: String) -> String {
    let numberWords = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
    let numberValues = numbers.split(separator: " ").map { numberWords.firstIndex(of: String($0))! }
    let sortedValues = numberValues.sorted()
    let sortedNumbers = sortedValues.map { numberWords[$0] }.joined(separator: " ")
    return sortedNumbers
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var sortedNumbers = numbers.sorted()
    var minDiff = Double.greatestFiniteMagnitude
    var result = (sortedNumbers[0], sortedNumbers[1])

    for i in 0..<sortedNumbers.count - 1 {
        let diff = sortedNumbers[i+1] - sortedNumbers[i]
        if diff < minDiff {
            minDiff = diff
            result = (sortedNumbers[i], sortedNumbers[i+1])
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)[/INST]  ```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var sortedNumbers = numbers.sorted()
    var minDiff = Double.greatestFiniteMagnitude
    var result = (sortedNumbers[0], sortedNumbers[1])

    for i in 0..<sortedNumbers.count - 1 {
        let diff = sortedNumbers[i+1] - sortedNumbers[i]
        if diff < minDiff {
            minDiff = diff
            result = (sortedNumbers[i], sortedNumbers[i+1])
        }
    }

    return result
}
```
var sortedNumbers = numbers.sorted() // variable 'sortedNumbers' was never mutated; consider changing to 'let' constant

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var sortedNumbers = numbers.sorted()
    var minDiff = Double.greatestFiniteMagnitude
    var result = (sortedNumbers[0], sortedNumbers[1])

    for i in 0..<sortedNumbers.count - 1 {
        let diff = sortedNumbers[i + 1] - sortedNumbers[i]
        if diff < minDiff {
            minDiff = diff
            result = (sortedNumbers[i], sortedNumbers[i + 1])
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)[/INST]  ```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var sortedNumbers = numbers.sorted()
    var minDiff = Double.greatestFiniteMagnitude
    var result = (sortedNumbers[0], sortedNumbers[1])

    for i in 0..<sortedNumbers.count - 1 {
        let diff = sortedNumbers[i + 1] - sortedNumbers[i]
        if diff < minDiff {
            minDiff = diff
            result = (sortedNumbers[i], sortedNumbers[i + 1])
        }
    }

    return result
}
```
var sortedNumbers = numbers.sorted() // variable 'sortedNumbers' was never mutated; consider changing to 'let' constant

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var sortedNumbers = numbers.sorted()
    var minDifference = Double.greatestFiniteMagnitude
    var closestPair = (sortedNumbers[0], sortedNumbers[1])

    for i in 0..<sortedNumbers.count - 1 {
        let difference = sortedNumbers[i + 1] - sortedNumbers[i]
        if difference < minDifference {
            minDifference = difference
            closestPair = (sortedNumbers[i], sortedNumbers[i + 1])
        }
    }

    return closestPair
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)[/INST]  ```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var sortedNumbers = numbers.sorted()
    var minDifference = Double.greatestFiniteMagnitude
    var closestPair = (sortedNumbers[0], sortedNumbers[1])

    for i in 0..<sortedNumbers.count - 1 {
        let difference = sortedNumbers[i + 1] - sortedNumbers[i]
        if difference < minDifference {
            minDifference = difference
            closestPair = (sortedNumbers[i], sortedNumbers[i + 1])
        }
    }

    return closestPair
}
```
var sortedNumbers = numbers.sorted() // variable 'sortedNumbers' was never mutated; consider changing to 'let' constant

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var sortedNumbers = numbers.sorted()
    var minDiff = Double.greatestFiniteMagnitude
    var result = (sortedNumbers[0], sortedNumbers[1])

    for i in 0..<sortedNumbers.count - 1 {
        let diff = sortedNumbers[i+1] - sortedNumbers[i]
        if diff < minDiff {
            minDiff = diff
            result = (sortedNumbers[i], sortedNumbers[i+1])
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)[/INST]  ```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var sortedNumbers = numbers.sorted()
    var minDiff = Double.greatestFiniteMagnitude
    var result = (sortedNumbers[0], sortedNumbers[1])

    for i in 0..<sortedNumbers.count - 1 {
        let diff = sortedNumbers[i+1] - sortedNumbers[i]
        if diff < minDiff {
            minDiff = diff
            result = (sortedNumbers[i], sortedNumbers[i+1])
        }
    }

    return result
}
```
var sortedNumbers = numbers.sorted() // variable 'sortedNumbers' was never mutated; consider changing to 'let' constant

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var sortedNumbers = numbers.sorted()
    var minDiff = Double.greatestFiniteMagnitude
    var result = (sortedNumbers[0], sortedNumbers[1])

    for i in 0..<sortedNumbers.count - 1 {
        let diff = sortedNumbers[i+1] - sortedNumbers[i]
        if diff < minDiff {
            minDiff = diff
            result = (sortedNumbers[i], sortedNumbers[i+1])
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)[/INST]  ```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var sortedNumbers = numbers.sorted()
    var minDiff = Double.greatestFiniteMagnitude
    var result = (sortedNumbers[0], sortedNumbers[1])

    for i in 0..<sortedNumbers.count - 1 {
        let diff = sortedNumbers[i+1] - sortedNumbers[i]
        if diff < minDiff {
            minDiff = diff
            result = (sortedNumbers[i], sortedNumbers[i+1])
        }
    }

    return result
}
```
var sortedNumbers = numbers.sorted() // variable 'sortedNumbers' was never mutated; consider changing to 'let' constant

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var sortedNumbers = numbers.sorted()
    var minDiff = Double.greatestFiniteMagnitude
    var result = (sortedNumbers[0], sortedNumbers[1])

    for i in 0..<sortedNumbers.count - 1 {
        let diff = sortedNumbers[i + 1] - sortedNumbers[i]
        if diff < minDiff {
            minDiff = diff
            result = (sortedNumbers[i], sortedNumbers[i + 1])
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)[/INST]  ```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var sortedNumbers = numbers.sorted()
    var minDiff = Double.greatestFiniteMagnitude
    var result = (sortedNumbers[0], sortedNumbers[1])

    for i in 0..<sortedNumbers.count - 1 {
        let diff = sortedNumbers[i + 1] - sortedNumbers[i]
        if diff < minDiff {
            minDiff = diff
            result = (sortedNumbers[i], sortedNumbers[i + 1])
        }
    }

    return result
}
```
var sortedNumbers = numbers.sorted() // variable 'sortedNumbers' was never mutated; consider changing to 'let' constant

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var sortedNumbers = numbers.sorted()
    var minDiff = Double.greatestFiniteMagnitude
    var result = (sortedNumbers[0], sortedNumbers[1])

    for i in 0..<sortedNumbers.count - 1 {
        let diff = sortedNumbers[i + 1] - sortedNumbers[i]
        if diff < minDiff {
            minDiff = diff
            result = (sortedNumbers[i], sortedNumbers[i + 1])
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)[/INST]  ```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var sortedNumbers = numbers.sorted()
    var minDiff = Double.greatestFiniteMagnitude
    var result = (sortedNumbers[0], sortedNumbers[1])

    for i in 0..<sortedNumbers.count - 1 {
        let diff = sortedNumbers[i + 1] - sortedNumbers[i]
        if diff < minDiff {
            minDiff = diff
            result = (sortedNumbers[i], sortedNumbers[i + 1])
        }
    }

    return result
}
```
var sortedNumbers = numbers.sorted() // variable 'sortedNumbers' was never mutated; consider changing to 'let' constant

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var sortedNumbers = numbers.sorted()
    var minDiff = Double.greatestFiniteMagnitude
    var result = (sortedNumbers[0], sortedNumbers[1])

    for i in 0..<sortedNumbers.count - 1 {
        let diff = sortedNumbers[i + 1] - sortedNumbers[i]
        if diff < minDiff {
            minDiff = diff
            result = (sortedNumbers[i], sortedNumbers[i + 1])
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)[/INST]  ```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var sortedNumbers = numbers.sorted()
    var minDiff = Double.greatestFiniteMagnitude
    var result = (sortedNumbers[0], sortedNumbers[1])

    for i in 0..<sortedNumbers.count - 1 {
        let diff = sortedNumbers[i + 1] - sortedNumbers[i]
        if diff < minDiff {
            minDiff = diff
            result = (sortedNumbers[i], sortedNumbers[i + 1])
        }
    }

    return result
}
```
var sortedNumbers = numbers.sorted() // variable 'sortedNumbers' was never mutated; consider changing to 'let' constant

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var sortedNumbers = numbers.sorted()
    var minDifference = Double.greatestFiniteMagnitude
    var result = (sortedNumbers[0], sortedNumbers[1])

    for i in 0..<sortedNumbers.count - 1 {
        let difference = sortedNumbers[i + 1] - sortedNumbers[i]
        if difference < minDifference {
            minDifference = difference
            result = (sortedNumbers[i], sortedNumbers[i + 1])
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)[/INST]  ```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var sortedNumbers = numbers.sorted()
    var minDifference = Double.greatestFiniteMagnitude
    var result = (sortedNumbers[0], sortedNumbers[1])

    for i in 0..<sortedNumbers.count - 1 {
        let difference = sortedNumbers[i + 1] - sortedNumbers[i]
        if difference < minDifference {
            minDifference = difference
            result = (sortedNumbers[i], sortedNumbers[i + 1])
        }
    }

    return result
}
```
var sortedNumbers = numbers.sorted() // variable 'sortedNumbers' was never mutated; consider changing to 'let' constant

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var sortedNumbers = numbers.sorted()
    var minDiff = Double.greatestFiniteMagnitude
    var result = (sortedNumbers[0], sortedNumbers[1])

    for i in 0..<sortedNumbers.count - 1 {
        let diff = sortedNumbers[i + 1] - sortedNumbers[i]
        if diff < minDiff {
            minDiff = diff
            result = (sortedNumbers[i], sortedNumbers[i + 1])
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)[/INST]  ```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var sortedNumbers = numbers.sorted()
    var minDiff = Double.greatestFiniteMagnitude
    var result = (sortedNumbers[0], sortedNumbers[1])

    for i in 0..<sortedNumbers.count - 1 {
        let diff = sortedNumbers[i + 1] - sortedNumbers[i]
        if diff < minDiff {
            minDiff = diff
            result = (sortedNumbers[i], sortedNumbers[i + 1])
        }
    }

    return result
}
```
var sortedNumbers = numbers.sorted() // variable 'sortedNumbers' was never mutated; consider changing to 'let' constant

func rescaleToUnit(numbers: [Double]) -> [Double] {
    if let min = numbers.min(), let max = numbers.max() {
        let diff = max - min
        return numbers.map { ($0 - min) / diff }
    }
    return []
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0][/INST]  ```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    if let min = numbers.min(), let max = numbers.max() {
        let diff = max - min
        return numbers.map { ($0 - min) / diff }
    }
    return []
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    if let min = numbers.min(), let max = numbers.max(), min != max {
        return numbers.map { ($0 - min) / (max - min) }
    } else {
        return numbers.map { _ in 0.0 }
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0][/INST]  ```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    if let min = numbers.min(), let max = numbers.max(), min != max {
        return numbers.map { ($0 - min) / (max - min) }
    } else {
        return numbers.map { _ in 0.0 }
    }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    if let min = numbers.min(), let max = numbers.max() {
        let range = max - min
        return numbers.map { ($0 - min) / range }
    }
    return []
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0][/INST]  ```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    if let min = numbers.min(), let max = numbers.max() {
        let range = max - min
        return numbers.map { ($0 - min) / range }
    }
    return []
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    if let min = numbers.min(), let max = numbers.max() {
        let diff = max - min
        return numbers.map { ($0 - min) / diff }
    }
    return []
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0][/INST]  ```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    if let min = numbers.min(), let max = numbers.max() {
        let diff = max - min
        return numbers.map { ($0 - min) / diff }
    }
    return []
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    if let min = numbers.min(), let max = numbers.max() {
        let diff = max - min
        return numbers.map { ($0 - min) / diff }
    }
    return []
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0][/INST]  ```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    if let min = numbers.min(), let max = numbers.max() {
        let diff = max - min
        return numbers.map { ($0 - min) / diff }
    }
    return []
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    if let min = numbers.min(), let max = numbers.max(), min != max {
        return numbers.map { ($0 - min) / (max - min) }
    } else {
        return numbers.map { _ in 0.0 }
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0][/INST]  ```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    if let min = numbers.min(), let max = numbers.max(), min != max {
        return numbers.map { ($0 - min) / (max - min) }
    } else {
        return numbers.map { _ in 0.0 }
    }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    if let min = numbers.min(), let max = numbers.max() {
        let diff = max - min
        return numbers.map { ($0 - min) / diff }
    }
    return []
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0][/INST]  ```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    if let min = numbers.min(), let max = numbers.max() {
        let diff = max - min
        return numbers.map { ($0 - min) / diff }
    }
    return []
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    if let min = numbers.min(), let max = numbers.max() {
        let diff = max - min
        return numbers.map { ($0 - min) / diff }
    }
    return []
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0][/INST]  ```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    if let min = numbers.min(), let max = numbers.max() {
        let diff = max - min
        return numbers.map { ($0 - min) / diff }
    }
    return []
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    if let min = numbers.min(), let max = numbers.max() {
        let range = max - min
        return numbers.map { ($0 - min) / range }
    }
    return []
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0][/INST]  ```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    if let min = numbers.min(), let max = numbers.max() {
        let range = max - min
        return numbers.map { ($0 - min) / range }
    }
    return []
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    if let min = numbers.min(), let max = numbers.max() {
        let range = max - min
        return numbers.map { ($0 - min) / range }
    }
    return []
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0][/INST]  ```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    if let min = numbers.min(), let max = numbers.max() {
        let range = max - min
        return numbers.map { ($0 - min) / range }
    }
    return []
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3][/INST]  ```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3][/INST]  ```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3][/INST]  ```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3][/INST]  ```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3][/INST]  ```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3][/INST]  ```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3][/INST]  ```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3][/INST]  ```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3][/INST]  ```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3][/INST]  ```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func strlen(string: String) -> Int {
    return string.count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3[/INST]  ```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3[/INST]  ```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3[/INST]  ```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3[/INST]  ```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3[/INST]  ```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3[/INST]  ```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3[/INST]  ```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3[/INST]  ```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3[/INST]  ```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3[/INST]  ```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func largestDivisor(n: Int) -> Int {
    for i in stride(from: n - 1, through: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return -1 // This line will never be executed for n > 1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5[/INST]  ```swift
func largestDivisor(n: Int) -> Int {
    for i in stride(from: n - 1, through: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return -1 // This line will never be executed for n > 1
}
```

func largestDivisor(n: Int) -> Int {
    for i in stride(from: n - 1, through: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return -1 // If no divisor is found, return -1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5[/INST]  ```swift
func largestDivisor(n: Int) -> Int {
    for i in stride(from: n - 1, through: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return -1 // If no divisor is found, return -1
}
```

func largestDivisor(n: Int) -> Int {
    for i in stride(from: n - 1, through: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return -1 // In case there is no divisor smaller than n
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5[/INST]  ```swift
func largestDivisor(n: Int) -> Int {
    for i in stride(from: n - 1, through: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return -1 // In case there is no divisor smaller than n
}
```

func largestDivisor(n: Int) -> Int {
    for i in stride(from: n - 1, through: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return -1 // In case there is no divisor smaller than n
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5[/INST]  ```swift
func largestDivisor(n: Int) -> Int {
    for i in stride(from: n - 1, through: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return -1 // In case there is no divisor smaller than n
}
```

func largestDivisor(n: Int) -> Int {
    for i in stride(from: n - 1, through: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return -1 // In case no divisor is found, return -1 or handle it as per your requirement
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5[/INST]  ```swift
func largestDivisor(n: Int) -> Int {
    for i in stride(from: n - 1, through: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return -1 // In case no divisor is found, return -1 or handle it as per your requirement
}
```

func largestDivisor(n: Int) -> Int {
    for i in stride(from: n - 1, through: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return -1 // This line will never be reached for positive integers
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5[/INST]  ```swift
func largestDivisor(n: Int) -> Int {
    for i in stride(from: n - 1, through: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return -1 // This line will never be reached for positive integers
}
```

func largestDivisor(n: Int) -> Int {
    for i in stride(from: n - 1, through: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return -1 // This line will never be reached for n > 1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5[/INST]  ```swift
func largestDivisor(n: Int) -> Int {
    for i in stride(from: n - 1, through: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return -1 // This line will never be reached for n > 1
}
```

func largestDivisor(n: Int) -> Int {
    for i in stride(from: n - 1, through: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return -1 // In case no divisor is found, return -1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5[/INST]  ```swift
func largestDivisor(n: Int) -> Int {
    for i in stride(from: n - 1, through: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return -1 // In case no divisor is found, return -1
}
```

func largestDivisor(n: Int) -> Int {
    for i in stride(from: n - 1, through: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return -1 // In case there is no divisor smaller than n
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5[/INST]  ```swift
func largestDivisor(n: Int) -> Int {
    for i in stride(from: n - 1, through: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return -1 // In case there is no divisor smaller than n
}
```

func largestDivisor(n: Int) -> Int {
    for i in stride(from: n - 1, through: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return -1 // This line will never be reached for n > 1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5[/INST]  ```swift
func largestDivisor(n: Int) -> Int {
    for i in stride(from: n - 1, through: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return -1 // This line will never be reached for n > 1
}
```

func factorize(n: Int) -> [Int] {
    var number = n
    var factors = [Int]()
    var divisor = 2

    while divisor * divisor <= number {
        if number % divisor == 0 {
            factors.append(divisor)
            number /= divisor
        } else {
            divisor += 1
        }
    }

    if number > 1 {
        factors.append(number)
    }

    return factors
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7][/INST]  ```swift
func factorize(n: Int) -> [Int] {
    var number = n
    var factors = [Int]()
    var divisor = 2

    while divisor * divisor <= number {
        if number % divisor == 0 {
            factors.append(divisor)
            number /= divisor
        } else {
            divisor += 1
        }
    }

    if number > 1 {
        factors.append(number)
    }

    return factors
}
```

func factorize(n: Int) -> [Int] {
    var number = n
    var factors = [Int]()
    var divisor = 2

    while divisor * divisor <= number {
        if number % divisor == 0 {
            factors.append(divisor)
            number /= divisor
        } else {
            divisor += 1
        }
    }

    if number > 1 {
        factors.append(number)
    }

    return factors
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7][/INST]  ```swift
func factorize(n: Int) -> [Int] {
    var number = n
    var factors = [Int]()
    var divisor = 2

    while divisor * divisor <= number {
        if number % divisor == 0 {
            factors.append(divisor)
            number /= divisor
        } else {
            divisor += 1
        }
    }

    if number > 1 {
        factors.append(number)
    }

    return factors
}
```

func factorize(n: Int) -> [Int] {
    var number = n
    var factors = [Int]()
    var divisor = 2

    while divisor * divisor <= number {
        if number % divisor == 0 {
            factors.append(divisor)
            number /= divisor
        } else {
            divisor += 1
        }
    }

    if number > 1 {
        factors.append(number)
    }

    return factors
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7][/INST]  ```swift
func factorize(n: Int) -> [Int] {
    var number = n
    var factors = [Int]()
    var divisor = 2

    while divisor * divisor <= number {
        if number % divisor == 0 {
            factors.append(divisor)
            number /= divisor
        } else {
            divisor += 1
        }
    }

    if number > 1 {
        factors.append(number)
    }

    return factors
}
```

func factorize(n: Int) -> [Int] {
    var number = n
    var factors = [Int]()
    var divisor = 2

    while divisor * divisor <= number {
        if number % divisor == 0 {
            factors.append(divisor)
            number /= divisor
        } else {
            divisor += 1
        }
    }

    if number > 1 {
        factors.append(number)
    }

    return factors
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7][/INST]  ```swift
func factorize(n: Int) -> [Int] {
    var number = n
    var factors = [Int]()
    var divisor = 2

    while divisor * divisor <= number {
        if number % divisor == 0 {
            factors.append(divisor)
            number /= divisor
        } else {
            divisor += 1
        }
    }

    if number > 1 {
        factors.append(number)
    }

    return factors
}
```

func factorize(n: Int) -> [Int] {
    var number = n
    var factors = [Int]()
    var divisor = 2

    while divisor * divisor <= number {
        if number % divisor == 0 {
            factors.append(divisor)
            number /= divisor
        } else {
            divisor += 1
        }
    }

    if number > 1 {
        factors.append(number)
    }

    return factors
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7][/INST]  ```swift
func factorize(n: Int) -> [Int] {
    var number = n
    var factors = [Int]()
    var divisor = 2

    while divisor * divisor <= number {
        if number % divisor == 0 {
            factors.append(divisor)
            number /= divisor
        } else {
            divisor += 1
        }
    }

    if number > 1 {
        factors.append(number)
    }

    return factors
}
```

func factorize(n: Int) -> [Int] {
    var number = n
    var factors = [Int]()
    var divisor = 2

    while divisor * divisor <= number {
        if number % divisor == 0 {
            factors.append(divisor)
            number /= divisor
        } else {
            divisor += 1
        }
    }

    if number > 1 {
        factors.append(number)
    }

    return factors
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7][/INST]  ```swift
func factorize(n: Int) -> [Int] {
    var number = n
    var factors = [Int]()
    var divisor = 2

    while divisor * divisor <= number {
        if number % divisor == 0 {
            factors.append(divisor)
            number /= divisor
        } else {
            divisor += 1
        }
    }

    if number > 1 {
        factors.append(number)
    }

    return factors
}
```

func factorize(n: Int) -> [Int] {
    var number = n
    var factors = [Int]()
    var divisor = 2

    while divisor * divisor <= number {
        if number % divisor == 0 {
            factors.append(divisor)
            number /= divisor
        } else {
            divisor += 1
        }
    }

    if number > 1 {
        factors.append(number)
    }

    return factors
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7][/INST]  ```swift
func factorize(n: Int) -> [Int] {
    var number = n
    var factors = [Int]()
    var divisor = 2

    while divisor * divisor <= number {
        if number % divisor == 0 {
            factors.append(divisor)
            number /= divisor
        } else {
            divisor += 1
        }
    }

    if number > 1 {
        factors.append(number)
    }

    return factors
}
```

func factorize(n: Int) -> [Int] {
    var number = n
    var factors = [Int]()
    var divisor = 2

    while divisor * divisor <= number {
        if number % divisor == 0 {
            factors.append(divisor)
            number /= divisor
        } else {
            divisor += 1
        }
    }

    if number > 1 {
        factors.append(number)
    }

    return factors
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7][/INST]  ```swift
func factorize(n: Int) -> [Int] {
    var number = n
    var factors = [Int]()
    var divisor = 2

    while divisor * divisor <= number {
        if number % divisor == 0 {
            factors.append(divisor)
            number /= divisor
        } else {
            divisor += 1
        }
    }

    if number > 1 {
        factors.append(number)
    }

    return factors
}
```

func factorize(n: Int) -> [Int] {
    var number = n
    var factors = [Int]()
    var divisor = 2

    while divisor * divisor <= number {
        if number % divisor == 0 {
            factors.append(divisor)
            number /= divisor
        } else {
            divisor += 1
        }
    }

    if number > 1 {
        factors.append(number)
    }

    return factors
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7][/INST]  ```swift
func factorize(n: Int) -> [Int] {
    var number = n
    var factors = [Int]()
    var divisor = 2

    while divisor * divisor <= number {
        if number % divisor == 0 {
            factors.append(divisor)
            number /= divisor
        } else {
            divisor += 1
        }
    }

    if number > 1 {
        factors.append(number)
    }

    return factors
}
```

func factorize(n: Int) -> [Int] {
    var number = n
    var factors = [Int]()
    var divisor = 2

    while divisor * divisor <= number {
        if number % divisor == 0 {
            factors.append(divisor)
            number /= divisor
        } else {
            divisor += 1
        }
    }

    if number > 1 {
        factors.append(number)
    }

    return factors
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7][/INST]  ```swift
func factorize(n: Int) -> [Int] {
    var number = n
    var factors = [Int]()
    var divisor = 2

    while divisor * divisor <= number {
        if number % divisor == 0 {
            factors.append(divisor)
            number /= divisor
        } else {
            divisor += 1
        }
    }

    if number > 1 {
        factors.append(number)
    }

    return factors
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var countDict = [Int: Int]()

    for number in numbers {
        if let count = countDict[number] {
            countDict[number] = count + 1
        } else {
            countDict[number] = 1
        }
    }

    for number in numbers {
        if countDict[number] == 1 {
            result.append(number)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4][/INST]  ```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var countDict = [Int: Int]()

    for number in numbers {
        if let count = countDict[number] {
            countDict[number] = count + 1
        } else {
            countDict[number] = 1
        }
    }

    for number in numbers {
        if countDict[number] == 1 {
            result.append(number)
        }
    }

    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var counts: [Int: Int] = [:]
    for number in numbers {
        counts[number, default: 0] += 1
    }
    return numbers.filter { counts[$0] == 1 }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4][/INST]  ```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var counts: [Int: Int] = [:]
    for number in numbers {
        counts[number, default: 0] += 1
    }
    return numbers.filter { counts[$0] == 1 }
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var counts = [Int: Int]()
    for number in numbers {
        counts[number, default: 0] += 1
    }
    return numbers.filter { counts[$0] == 1 }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4][/INST]  ```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var counts = [Int: Int]()
    for number in numbers {
        counts[number, default: 0] += 1
    }
    return numbers.filter { counts[$0] == 1 }
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var counts: [Int: Int] = [:]
    for number in numbers {
        counts[number, default: 0] += 1
    }
    return numbers.filter { counts[$0] == 1 }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4][/INST]  ```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var counts: [Int: Int] = [:]
    for number in numbers {
        counts[number, default: 0] += 1
    }
    return numbers.filter { counts[$0] == 1 }
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var counts: [Int: Int] = [:]
    for number in numbers {
        counts[number, default: 0] += 1
    }

    var result: [Int] = []
    for number in numbers {
        if counts[number] == 1 {
            result.append(number)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4][/INST]  ```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var counts: [Int: Int] = [:]
    for number in numbers {
        counts[number, default: 0] += 1
    }

    var result: [Int] = []
    for number in numbers {
        if counts[number] == 1 {
            result.append(number)
        }
    }

    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var countDict = [Int: Int]()

    for number in numbers {
        countDict[number, default: 0] += 1
    }

    for number in numbers {
        if countDict[number] == 1 {
            result.append(number)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4][/INST]  ```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var countDict = [Int: Int]()

    for number in numbers {
        countDict[number, default: 0] += 1
    }

    for number in numbers {
        if countDict[number] == 1 {
            result.append(number)
        }
    }

    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var counts: [Int: Int] = [:]
    for number in numbers {
        counts[number, default: 0] += 1
    }
    return numbers.filter { counts[$0] == 1 }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4][/INST]  ```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var counts: [Int: Int] = [:]
    for number in numbers {
        counts[number, default: 0] += 1
    }
    return numbers.filter { counts[$0] == 1 }
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var counts: [Int: Int] = [:]
    for number in numbers {
        counts[number, default: 0] += 1
    }

    var result: [Int] = []
    for number in numbers {
        if counts[number] == 1 {
            result.append(number)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4][/INST]  ```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var counts: [Int: Int] = [:]
    for number in numbers {
        counts[number, default: 0] += 1
    }

    var result: [Int] = []
    for number in numbers {
        if counts[number] == 1 {
            result.append(number)
        }
    }

    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var countDict = [Int: Int]()

    for number in numbers {
        countDict[number, default: 0] += 1
    }

    for number in numbers {
        if countDict[number] == 1 {
            result.append(number)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4][/INST]  ```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var countDict = [Int: Int]()

    for number in numbers {
        countDict[number, default: 0] += 1
    }

    for number in numbers {
        if countDict[number] == 1 {
            result.append(number)
        }
    }

    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var counts = [Int: Int]()

    for number in numbers {
        counts[number, default: 0] += 1
    }

    for number in numbers {
        if counts[number] == 1 {
            result.append(number)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4][/INST]  ```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var counts = [Int: Int]()

    for number in numbers {
        counts[number, default: 0] += 1
    }

    for number in numbers {
        if counts[number] == 1 {
            result.append(number)
        }
    }

    return result
}
```

func flipCase(string: String) -> String {
    return String(string.map { $0.isLowercase ? $0.uppercased() : $0.lowercased() })
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"[/INST]  ```swift
func flipCase(string: String) -> String {
    return String(string.map { $0.isLowercase ? $0.uppercased() : $0.lowercased() })
}
```
return String(string.map { $0.isLowercase ? $0.uppercased() : $0.lowercased() }) // no exact matches in call to initializer

func flipCase(string: String) -> String {
    return String(string.map { $0.isLowercase ? $0.uppercased() : $0.lowercased() })
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"[/INST]  ```swift
func flipCase(string: String) -> String {
    return String(string.map { $0.isLowercase ? $0.uppercased() : $0.lowercased() })
}
```
return String(string.map { $0.isLowercase ? $0.uppercased() : $0.lowercased() }) // no exact matches in call to initializer

func flipCase(string: String) -> String {
    return String(string.map { $0.isLowercase ? $0.uppercased() : $0.lowercased() })
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"[/INST]  ```swift
func flipCase(string: String) -> String {
    return String(string.map { $0.isLowercase ? $0.uppercased() : $0.lowercased() })
}
```
return String(string.map { $0.isLowercase ? $0.uppercased() : $0.lowercased() }) // no exact matches in call to initializer

func flipCase(string: String) -> String {
    return String(string.map { $0.isLowercase ? $0.uppercased() : $0.lowercased() })
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"[/INST]  ```swift
func flipCase(string: String) -> String {
    return String(string.map { $0.isLowercase ? $0.uppercased() : $0.lowercased() })
}
```
return String(string.map { $0.isLowercase ? $0.uppercased() : $0.lowercased() }) // no exact matches in call to initializer

func flipCase(string: String) -> String {
    return String(string.map { $0.isLowercase ? $0.uppercased() : $0.lowercased() })
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"[/INST]  ```swift
func flipCase(string: String) -> String {
    return String(string.map { $0.isLowercase ? $0.uppercased() : $0.lowercased() })
}
```
return String(string.map { $0.isLowercase ? $0.uppercased() : $0.lowercased() }) // no exact matches in call to initializer

func flipCase(string: String) -> String {
    return String(string.map { $0.isLowercase ? $0.uppercased() : $0.lowercased() })
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"[/INST]  ```swift
func flipCase(string: String) -> String {
    return String(string.map { $0.isLowercase ? $0.uppercased() : $0.lowercased() })
}
```
return String(string.map { $0.isLowercase ? $0.uppercased() : $0.lowercased() }) // no exact matches in call to initializer

func flipCase(string: String) -> String {
    return string.map { char in
        if char.isLowercase {
            return char.uppercased()
        } else if char.isUppercase {
            return char.lowercased()
        } else {
            return String(char)
        }
    }.joined()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"[/INST]  ```swift
func flipCase(string: String) -> String {
    return string.map { char in
        if char.isLowercase {
            return char.uppercased()
        } else if char.isUppercase {
            return char.lowercased()
        } else {
            return String(char)
        }
    }.joined()
}
```

func flipCase(string: String) -> String {
    return String(string.map { $0.isLowercase ? $0.uppercased() : $0.lowercased() })
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"[/INST]  ```swift
func flipCase(string: String) -> String {
    return String(string.map { $0.isLowercase ? $0.uppercased() : $0.lowercased() })
}
```
return String(string.map { $0.isLowercase ? $0.uppercased() : $0.lowercased() }) // no exact matches in call to initializer

func flipCase(string: String) -> String {
    return String(string.map { $0.isLowercase ? $0.uppercased() : $0.lowercased() })
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"[/INST]  ```swift
func flipCase(string: String) -> String {
    return String(string.map { $0.isLowercase ? $0.uppercased() : $0.lowercased() })
}
```
return String(string.map { $0.isLowercase ? $0.uppercased() : $0.lowercased() }) // no exact matches in call to initializer

func flipCase(string: String) -> String {
    return string.map {
        if $0.isLowercase {
            return $0.uppercased()
        } else if $0.isUppercase {
            return $0.lowercased()
        } else {
            return String($0)
        }
    }.joined()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"[/INST]  ```swift
func flipCase(string: String) -> String {
    return string.map {
        if $0.isLowercase {
            return $0.uppercased()
        } else if $0.isUppercase {
            return $0.lowercased()
        } else {
            return String($0)
        }
    }.joined()
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"[/INST]  ```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
```

func concatenate(strings: [String]) -> String {
    return strings.joined()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"[/INST]  ```swift
func concatenate(strings: [String]) -> String {
    return strings.joined()
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"[/INST]  ```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"[/INST]  ```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"[/INST]  ```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"[/INST]  ```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"[/INST]  ```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"[/INST]  ```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"[/INST]  ```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"[/INST]  ```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"][/INST]  ```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"][/INST]  ```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"][/INST]  ```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"][/INST]  ```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"][/INST]  ```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"][/INST]  ```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"][/INST]  ```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"][/INST]  ```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"][/INST]  ```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"][/INST]  ```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1][/INST]  ```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1][/INST]  ```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1][/INST]  ```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1][/INST]  ```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1][/INST]  ```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1][/INST]  ```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1][/INST]  ```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1][/INST]  ```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1][/INST]  ```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1][/INST]  ```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false[/INST]  ```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false[/INST]  ```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false[/INST]  ```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false[/INST]  ```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false[/INST]  ```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false[/INST]  ```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false[/INST]  ```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false[/INST]  ```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false[/INST]  ```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false[/INST]  ```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func sortThird(l: [Int]) -> [Int] {
    var thirdElements = l.enumerated().filter { $0.offset % 3 == 2 }.map { $0.element }
    thirdElements.sort()
    return l.enumerated().map { $0.offset % 3 == 2 ? thirdElements.removeFirst() : $0.element }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5][/INST]  ```swift
func sortThird(l: [Int]) -> [Int] {
    var thirdElements = l.enumerated().filter { $0.offset % 3 == 2 }.map { $0.element }
    thirdElements.sort()
    return l.enumerated().map { $0.offset % 3 == 2 ? thirdElements.removeFirst() : $0.element }
}
```
 // XCTAssertTrue failed

func sortThird(l: [Int]) -> [Int] {
    var sortedArray = l
    var thirdElements = sortedArray.enumerated().filter { $0.offset % 3 == 2 }.map { $0.element }
    thirdElements.sort()
    for (index, element) in thirdElements.enumerated() {
        sortedArray[index * 3 + 2] = element
    }
    return sortedArray
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5][/INST]  ```swift
func sortThird(l: [Int]) -> [Int] {
    var sortedArray = l
    var thirdElements = sortedArray.enumerated().filter { $0.offset % 3 == 2 }.map { $0.element }
    thirdElements.sort()
    for (index, element) in thirdElements.enumerated() {
        sortedArray[index * 3 + 2] = element
    }
    return sortedArray
}
```
 // XCTAssertTrue failed

func sortThird(l: [Int]) -> [Int] {
    var lPrime = l
    var thirdElements = l.enumerated().filter { $0.offset % 3 == 2 }.map { $0.element }
    thirdElements.sort()
    for (index, element) in thirdElements.enumerated() {
        lPrime[index * 3 + 2] = element
    }
    return lPrime
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5][/INST]  ```swift
func sortThird(l: [Int]) -> [Int] {
    var lPrime = l
    var thirdElements = l.enumerated().filter { $0.offset % 3 == 2 }.map { $0.element }
    thirdElements.sort()
    for (index, element) in thirdElements.enumerated() {
        lPrime[index * 3 + 2] = element
    }
    return lPrime
}
```
 // XCTAssertTrue failed

func sortThird(l: [Int]) -> [Int] {
    var sortedArray = l
    var thirdElements = sortedArray.enumerated().filter { $0.offset % 3 == 2 }.map { $0.element }
    thirdElements.sort()
    for (index, element) in thirdElements.enumerated() {
        sortedArray[index * 3 + 2] = element
    }
    return sortedArray
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5][/INST]  ```swift
func sortThird(l: [Int]) -> [Int] {
    var sortedArray = l
    var thirdElements = sortedArray.enumerated().filter { $0.offset % 3 == 2 }.map { $0.element }
    thirdElements.sort()
    for (index, element) in thirdElements.enumerated() {
        sortedArray[index * 3 + 2] = element
    }
    return sortedArray
}
```
 // XCTAssertTrue failed

func sortThird(l: [Int]) -> [Int] {
    var sortedArray = l
    var thirdElements = sortedArray.enumerated().filter { $0.offset % 3 == 2 }.map { $0.element }
    thirdElements.sort()
    for (index, element) in thirdElements.enumerated() {
        sortedArray[index * 3 + 2] = element
    }
    return sortedArray
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5][/INST]  ```swift
func sortThird(l: [Int]) -> [Int] {
    var sortedArray = l
    var thirdElements = sortedArray.enumerated().filter { $0.offset % 3 == 2 }.map { $0.element }
    thirdElements.sort()
    for (index, element) in thirdElements.enumerated() {
        sortedArray[index * 3 + 2] = element
    }
    return sortedArray
}
```
 // XCTAssertTrue failed

func sortThird(l: [Int]) -> [Int] {
    var newArray = l
    var thirdElements = newArray.enumerated().filter { $0.offset % 3 == 2 }.map { $0.element }
    thirdElements.sort()
    for (index, element) in thirdElements.enumerated() {
        newArray[index * 3 + 2] = element
    }
    return newArray
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5][/INST]  ```swift
func sortThird(l: [Int]) -> [Int] {
    var newArray = l
    var thirdElements = newArray.enumerated().filter { $0.offset % 3 == 2 }.map { $0.element }
    thirdElements.sort()
    for (index, element) in thirdElements.enumerated() {
        newArray[index * 3 + 2] = element
    }
    return newArray
}
```
 // XCTAssertTrue failed

func sortThird(l: [Int]) -> [Int] {
    var sortedArray = l
    var thirdElements = sortedArray.enumerated().filter { $0.offset % 3 == 2 }.map { $0.element }
    thirdElements.sort()
    for (index, element) in thirdElements.enumerated() {
        sortedArray[index * 3 + 2] = element
    }
    return sortedArray
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5][/INST]  ```swift
func sortThird(l: [Int]) -> [Int] {
    var sortedArray = l
    var thirdElements = sortedArray.enumerated().filter { $0.offset % 3 == 2 }.map { $0.element }
    thirdElements.sort()
    for (index, element) in thirdElements.enumerated() {
        sortedArray[index * 3 + 2] = element
    }
    return sortedArray
}
```
 // XCTAssertTrue failed

func sortThird(l: [Int]) -> [Int] {
    var lPrime = l
    var divisibleByThreeElements = l.enumerated().filter { $0.offset % 3 == 2 }.map { $0.element }
    divisibleByThreeElements.sort()
    for (index, element) in divisibleByThreeElements.enumerated() {
        lPrime[index * 3 + 2] = element
    }
    return lPrime
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5][/INST]  ```swift
func sortThird(l: [Int]) -> [Int] {
    var lPrime = l
    var divisibleByThreeElements = l.enumerated().filter { $0.offset % 3 == 2 }.map { $0.element }
    divisibleByThreeElements.sort()
    for (index, element) in divisibleByThreeElements.enumerated() {
        lPrime[index * 3 + 2] = element
    }
    return lPrime
}
```
 // XCTAssertTrue failed

func sortThird(l: [Int]) -> [Int] {
    var sortedArray = l
    var thirdElements = sortedArray.enumerated().filter { $0.offset % 3 == 2 }.map { $0.element }
    thirdElements.sort()
    for (index, element) in thirdElements.enumerated() {
        sortedArray[index * 3 + 2] = element
    }
    return sortedArray
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5][/INST]  ```swift
func sortThird(l: [Int]) -> [Int] {
    var sortedArray = l
    var thirdElements = sortedArray.enumerated().filter { $0.offset % 3 == 2 }.map { $0.element }
    thirdElements.sort()
    for (index, element) in thirdElements.enumerated() {
        sortedArray[index * 3 + 2] = element
    }
    return sortedArray
}
```
 // XCTAssertTrue failed

func sortThird(l: [Int]) -> [Int] {
    var sortedArray = l
    var thirdElements = sortedArray.enumerated().filter { $0.offset % 3 == 2 }.map { $0.element }
    thirdElements.sort()
    for (index, element) in thirdElements.enumerated() {
        sortedArray[index * 3 + 2] = element
    }
    return sortedArray
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5][/INST]  ```swift
func sortThird(l: [Int]) -> [Int] {
    var sortedArray = l
    var thirdElements = sortedArray.enumerated().filter { $0.offset % 3 == 2 }.map { $0.element }
    thirdElements.sort()
    for (index, element) in thirdElements.enumerated() {
        sortedArray[index * 3 + 2] = element
    }
    return sortedArray
}
```
 // XCTAssertTrue failed

func unique(l: [Int]) -> [Int] {
    let uniqueElements = Array(Set(l))
    return uniqueElements.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123][/INST]  ```swift
func unique(l: [Int]) -> [Int] {
    let uniqueElements = Array(Set(l))
    return uniqueElements.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    let uniqueElements = Array(Set(l))
    return uniqueElements.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123][/INST]  ```swift
func unique(l: [Int]) -> [Int] {
    let uniqueElements = Array(Set(l))
    return uniqueElements.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    let uniqueSet = Set(l)
    return uniqueSet.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123][/INST]  ```swift
func unique(l: [Int]) -> [Int] {
    let uniqueSet = Set(l)
    return uniqueSet.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    let uniqueSet = Set(l)
    let uniqueArray = Array(uniqueSet)
    return uniqueArray.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123][/INST]  ```swift
func unique(l: [Int]) -> [Int] {
    let uniqueSet = Set(l)
    let uniqueArray = Array(uniqueSet)
    return uniqueArray.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    let uniqueElements = Array(Set(l)).sorted()
    return uniqueElements
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123][/INST]  ```swift
func unique(l: [Int]) -> [Int] {
    let uniqueElements = Array(Set(l)).sorted()
    return uniqueElements
}
```

func unique(l: [Int]) -> [Int] {
    let uniqueArray = Array(Set(l)).sorted()
    return uniqueArray
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123][/INST]  ```swift
func unique(l: [Int]) -> [Int] {
    let uniqueArray = Array(Set(l)).sorted()
    return uniqueArray
}
```

func unique(l: [Int]) -> [Int] {
    let uniqueSet = Set(l)
    let uniqueArray = Array(uniqueSet).sorted()
    return uniqueArray
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123][/INST]  ```swift
func unique(l: [Int]) -> [Int] {
    let uniqueSet = Set(l)
    let uniqueArray = Array(uniqueSet).sorted()
    return uniqueArray
}
```

func unique(l: [Int]) -> [Int] {
    let uniqueArray = Array(Set(l)).sorted()
    return uniqueArray
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123][/INST]  ```swift
func unique(l: [Int]) -> [Int] {
    let uniqueArray = Array(Set(l)).sorted()
    return uniqueArray
}
```

func unique(l: [Int]) -> [Int] {
    let uniqueElements = Array(Set(l))
    return uniqueElements.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123][/INST]  ```swift
func unique(l: [Int]) -> [Int] {
    let uniqueElements = Array(Set(l))
    return uniqueElements.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    let uniqueElements = Array(Set(l))
    return uniqueElements.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123][/INST]  ```swift
func unique(l: [Int]) -> [Int] {
    let uniqueElements = Array(Set(l))
    return uniqueElements.sorted()
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for num in l {
        if num > max {
            max = num
        }
    }
    return max
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123[/INST]  ```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for num in l {
        if num > max {
            max = num
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for num in l {
        if num > max {
            max = num
        }
    }
    return max
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123[/INST]  ```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for num in l {
        if num > max {
            max = num
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for element in l {
        if element > max {
            max = element
        }
    }
    return max
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123[/INST]  ```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for element in l {
        if element > max {
            max = element
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for element in l {
        if element > max {
            max = element
        }
    }
    return max
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123[/INST]  ```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for element in l {
        if element > max {
            max = element
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in l {
        if i > max {
            max = i
        }
    }
    return max
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123[/INST]  ```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in l {
        if i > max {
            max = i
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for num in l {
        if num > max {
            max = num
        }
    }
    return max
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123[/INST]  ```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for num in l {
        if num > max {
            max = num
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in l {
        if i > max {
            max = i
        }
    }
    return max
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123[/INST]  ```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in l {
        if i > max {
            max = i
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for num in l {
        if num > max {
            max = num
        }
    }
    return max
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123[/INST]  ```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for num in l {
        if num > max {
            max = num
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for element in l {
        if element > max {
            max = element
        }
    }
    return max
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123[/INST]  ```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for element in l {
        if element > max {
            max = element
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in l {
        if i > max {
            max = i
        }
    }
    return max
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123[/INST]  ```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in l {
        if i > max {
            max = i
        }
    }
    return max
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            for char in str {
                if char == "7" {
                    count += 1
                }
            }
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3[/INST]  ```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            for char in str {
                if char == "7" {
                    count += 1
                }
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            for char in str {
                if char == "7" {
                    count += 1
                }
            }
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3[/INST]  ```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            for char in str {
                if char == "7" {
                    count += 1
                }
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let digits = String(i).map { Int(String($0))! }
            count += digits.filter { $0 == 7 }.count
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3[/INST]  ```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let digits = String(i).map { Int(String($0))! }
            count += digits.filter { $0 == 7 }.count
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let digits = String(i).map { Int(String($0))! }
            count += digits.filter { $0 == 7 }.count
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3[/INST]  ```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let digits = String(i).map { Int(String($0))! }
            count += digits.filter { $0 == 7 }.count
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let digits = String(i).map { Int(String($0))! }
            count += digits.filter { $0 == 7 }.count
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3[/INST]  ```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let digits = String(i).map { Int(String($0))! }
            count += digits.filter { $0 == 7 }.count
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let digits = String(i).map { Int(String($0))! }
            count += digits.filter { $0 == 7 }.count
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3[/INST]  ```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let digits = String(i).map { Int(String($0))! }
            count += digits.filter { $0 == 7 }.count
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let digits = String(i).map { Int(String($0))! }
            count += digits.filter { $0 == 7 }.count
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3[/INST]  ```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let digits = String(i).map { Int(String($0))! }
            count += digits.filter { $0 == 7 }.count
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let digits = String(i).map { Int(String($0))! }
            count += digits.filter { $0 == 7 }.count
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3[/INST]  ```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let digits = String(i).map { Int(String($0))! }
            count += digits.filter { $0 == 7 }.count
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            for char in str {
                if char == "7" {
                    count += 1
                }
            }
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3[/INST]  ```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            for char in str {
                if char == "7" {
                    count += 1
                }
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let digits = String(i).map { Int(String($0))! }
            count += digits.filter { $0 == 7 }.count
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3[/INST]  ```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let digits = String(i).map { Int(String($0))! }
            count += digits.filter { $0 == 7 }.count
        }
    }
    return count
}
```

func sortEven(l: [Int]) -> [Int] {
    var evenNumbers = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    evenNumbers.sort()

    var result = [Int]()
    var evenIndex = 0

    for i in 0..<l.count {
        if i % 2 == 0 {
            result.append(evenNumbers[evenIndex])
            evenIndex += 1
        } else {
            result.append(l[i])
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4][/INST]  ```swift
func sortEven(l: [Int]) -> [Int] {
    var evenNumbers = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    evenNumbers.sort()

    var result = [Int]()
    var evenIndex = 0

    for i in 0..<l.count {
        if i % 2 == 0 {
            result.append(evenNumbers[evenIndex])
            evenIndex += 1
        } else {
            result.append(l[i])
        }
    }

    return result
}
```

func sortEven(l: [Int]) -> [Int] {
    var evenNumbers = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    evenNumbers.sort()

    var result = l
    for (index, value) in evenNumbers.enumerated() {
        result[index * 2] = value
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4][/INST]  ```swift
func sortEven(l: [Int]) -> [Int] {
    var evenNumbers = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    evenNumbers.sort()

    var result = l
    for (index, value) in evenNumbers.enumerated() {
        result[index * 2] = value
    }

    return result
}
```

func sortEven(l: [Int]) -> [Int] {
    var evenNumbers = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    evenNumbers.sort()

    var result = l
    for (index, value) in evenNumbers.enumerated() {
        result[index * 2] = value
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4][/INST]  ```swift
func sortEven(l: [Int]) -> [Int] {
    var evenNumbers = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    evenNumbers.sort()

    var result = l
    for (index, value) in evenNumbers.enumerated() {
        result[index * 2] = value
    }

    return result
}
```

func sortEven(l: [Int]) -> [Int] {
    var evenNumbers = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    evenNumbers.sort()
    var result = l
    for (index, value) in evenNumbers.enumerated() {
        result[index * 2] = value
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4][/INST]  ```swift
func sortEven(l: [Int]) -> [Int] {
    var evenNumbers = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    evenNumbers.sort()
    var result = l
    for (index, value) in evenNumbers.enumerated() {
        result[index * 2] = value
    }
    return result
}
```

func sortEven(l: [Int]) -> [Int] {
    var evenNumbers = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    evenNumbers.sort()

    var result = [Int]()
    var evenIndex = 0

    for i in 0..<l.count {
        if i % 2 == 0 {
            result.append(evenNumbers[evenIndex])
            evenIndex += 1
        } else {
            result.append(l[i])
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4][/INST]  ```swift
func sortEven(l: [Int]) -> [Int] {
    var evenNumbers = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    evenNumbers.sort()

    var result = [Int]()
    var evenIndex = 0

    for i in 0..<l.count {
        if i % 2 == 0 {
            result.append(evenNumbers[evenIndex])
            evenIndex += 1
        } else {
            result.append(l[i])
        }
    }

    return result
}
```

func sortEven(l: [Int]) -> [Int] {
    var evenNumbers = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    evenNumbers.sort()

    var result = [Int]()
    var evenIndex = 0

    for i in 0..<l.count {
        if i % 2 == 0 {
            result.append(evenNumbers[evenIndex])
            evenIndex += 1
        } else {
            result.append(l[i])
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4][/INST]  ```swift
func sortEven(l: [Int]) -> [Int] {
    var evenNumbers = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    evenNumbers.sort()

    var result = [Int]()
    var evenIndex = 0

    for i in 0..<l.count {
        if i % 2 == 0 {
            result.append(evenNumbers[evenIndex])
            evenIndex += 1
        } else {
            result.append(l[i])
        }
    }

    return result
}
```

func sortEven(l: [Int]) -> [Int] {
    var evenNumbers = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    evenNumbers.sort()

    var result = [Int]()
    for (index, number) in l.enumerated() {
        if index % 2 == 0 {
            result.append(evenNumbers.removeFirst())
        } else {
            result.append(number)
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4][/INST]  ```swift
func sortEven(l: [Int]) -> [Int] {
    var evenNumbers = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    evenNumbers.sort()

    var result = [Int]()
    for (index, number) in l.enumerated() {
        if index % 2 == 0 {
            result.append(evenNumbers.removeFirst())
        } else {
            result.append(number)
        }
    }
    return result
}
```

func sortEven(l: [Int]) -> [Int] {
    var evenNumbers = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    evenNumbers.sort()

    var result = [Int]()
    var evenIndex = 0

    for (index, number) in l.enumerated() {
        if index % 2 == 0 {
            result.append(evenNumbers[evenIndex])
            evenIndex += 1
        } else {
            result.append(number)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4][/INST]  ```swift
func sortEven(l: [Int]) -> [Int] {
    var evenNumbers = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    evenNumbers.sort()

    var result = [Int]()
    var evenIndex = 0

    for (index, number) in l.enumerated() {
        if index % 2 == 0 {
            result.append(evenNumbers[evenIndex])
            evenIndex += 1
        } else {
            result.append(number)
        }
    }

    return result
}
```

func sortEven(l: [Int]) -> [Int] {
    var evenNumbers = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    evenNumbers.sort()

    var result = [Int]()
    var evenIndex = 0

    for i in 0..<l.count {
        if i % 2 == 0 {
            result.append(evenNumbers[evenIndex])
            evenIndex += 1
        } else {
            result.append(l[i])
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4][/INST]  ```swift
func sortEven(l: [Int]) -> [Int] {
    var evenNumbers = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    evenNumbers.sort()

    var result = [Int]()
    var evenIndex = 0

    for i in 0..<l.count {
        if i % 2 == 0 {
            result.append(evenNumbers[evenIndex])
            evenIndex += 1
        } else {
            result.append(l[i])
        }
    }

    return result
}
```

func sortEven(l: [Int]) -> [Int] {
    var evenNumbers = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    evenNumbers.sort()
    var result = l
    for (index, value) in evenNumbers.enumerated() {
        result[index * 2] = value
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4][/INST]  ```swift
func sortEven(l: [Int]) -> [Int] {
    var evenNumbers = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    evenNumbers.sort()
    var result = l
    for (index, value) in evenNumbers.enumerated() {
        result[index * 2] = value
    }
    return result
}
```

func primeFib(n: Int) -> Int {
    var count = 0
    var fib = [0, 1]
    var i = 2

    while count < n {
        let nextFib = fib[i - 1] + fib[i - 2]
        fib.append(nextFib)

        if isPrime(nextFib) {
            count += 1
        }

        i += 1
    }

    return fib[i - 1]
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }

    if number <= 3 {
        return true
    }

    var i = 2
    while i * i <= number {
        if number % i == 0 {
            return false
        }
        i += 1
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89[/INST]  ```swift
func primeFib(n: Int) -> Int {
    var count = 0
    var fib = [0, 1]
    var i = 2

    while count < n {
        let nextFib = fib[i - 1] + fib[i - 2]
        fib.append(nextFib)

        if isPrime(nextFib) {
            count += 1
        }

        i += 1
    }

    return fib[i - 1]
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }

    if number <= 3 {
        return true
    }

    var i = 2
    while i * i <= number {
        if number % i == 0 {
            return false
        }
        i += 1
    }

    return true
}
```

func primeFib(n: Int) -> Int {
    var count = 0
    var fib = [0, 1]
    var i = 2

    while count < n {
        let nextFib = fib[i - 1] + fib[i - 2]
        fib.append(nextFib)

        if isPrime(nextFib) {
            count += 1
        }

        i += 1
    }

    return fib[i - 1]
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }

    if number <= 3 {
        return true
    }

    if number % 2 == 0 || number % 3 == 0 {
        return false
    }

    var i = 5
    while i * i <= number {
        if number % i == 0 || number % (i + 2) == 0 {
            return false
        }
        i += 6
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89[/INST]  ```swift
func primeFib(n: Int) -> Int {
    var count = 0
    var fib = [0, 1]
    var i = 2

    while count < n {
        let nextFib = fib[i - 1] + fib[i - 2]
        fib.append(nextFib)

        if isPrime(nextFib) {
            count += 1
        }

        i += 1
    }

    return fib[i - 1]
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }

    if number <= 3 {
        return true
    }

    if number % 2 == 0 || number % 3 == 0 {
        return false
    }

    var i = 5
    while i * i <= number {
        if number % i == 0 || number % (i + 2) == 0 {
            return false
        }
        i += 6
    }

    return true
}
```

func primeFib(n: Int) -> Int {
    var count = 0
    var fib = [0, 1]
    var i = 2

    while count < n {
        let nextFib = fib[i - 1] + fib[i - 2]
        fib.append(nextFib)

        if isPrime(number: nextFib) {
            count += 1
        }

        i += 1
    }

    return fib[i - 1]
}

func isPrime(number: Int) -> Bool {
    if number <= 1 {
        return false
    }

    if number <= 3 {
        return true
    }

    var i = 2
    while i * i <= number {
        if number % i == 0 {
            return false
        }
        i = i + 1
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89[/INST]  ```swift
func primeFib(n: Int) -> Int {
    var count = 0
    var fib = [0, 1]
    var i = 2

    while count < n {
        let nextFib = fib[i - 1] + fib[i - 2]
        fib.append(nextFib)

        if isPrime(number: nextFib) {
            count += 1
        }

        i += 1
    }

    return fib[i - 1]
}

func isPrime(number: Int) -> Bool {
    if number <= 1 {
        return false
    }

    if number <= 3 {
        return true
    }

    var i = 2
    while i * i <= number {
        if number % i == 0 {
            return false
        }
        i = i + 1
    }

    return true
}
```

func primeFib(n: Int) -> Int {
    var count = 0
    var fib = [0, 1]
    var i = 2

    while count < n {
        let nextFib = fib[i-1] + fib[i-2]
        fib.append(nextFib)

        if isPrime(nextFib) {
            count += 1
        }

        i += 1
    }

    return fib[i-1]
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }

    if number <= 3 {
        return true
    }

    var i = 2
    while i * i <= number {
        if number % i == 0 {
            return false
        }
        i = i + 1
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89[/INST]  ```swift
func primeFib(n: Int) -> Int {
    var count = 0
    var fib = [0, 1]
    var i = 2

    while count < n {
        let nextFib = fib[i-1] + fib[i-2]
        fib.append(nextFib)

        if isPrime(nextFib) {
            count += 1
        }

        i += 1
    }

    return fib[i-1]
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }

    if number <= 3 {
        return true
    }

    var i = 2
    while i * i <= number {
        if number % i == 0 {
            return false
        }
        i = i + 1
    }

    return true
}
```

func primeFib(n: Int) -> Int {
    var count = 0
    var fibNum = 0
    var prevNum = 0
    var currentNum = 1

    func isPrime(_ num: Int) -> Bool {
        if num <= 1 {
            return false
        }
        if num <= 3 {
            return true
        }
        var i = 2
        while i * i <= num {
            if num % i == 0 {
                return false
            }
            i = i + 1
        }
        return true
    }

    while count < n {
        fibNum = prevNum + currentNum
        prevNum = currentNum
        currentNum = fibNum
        if isPrime(fibNum) {
            count += 1
        }
    }
    return fibNum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89[/INST]  ```swift
func primeFib(n: Int) -> Int {
    var count = 0
    var fibNum = 0
    var prevNum = 0
    var currentNum = 1

    func isPrime(_ num: Int) -> Bool {
        if num <= 1 {
            return false
        }
        if num <= 3 {
            return true
        }
        var i = 2
        while i * i <= num {
            if num % i == 0 {
                return false
            }
            i = i + 1
        }
        return true
    }

    while count < n {
        fibNum = prevNum + currentNum
        prevNum = currentNum
        currentNum = fibNum
        if isPrime(fibNum) {
            count += 1
        }
    }
    return fibNum
}
```

func primeFib(n: Int) -> Int {
    var count = 0
    var fib = [0, 1]
    var i = 2

    while count < n {
        let nextFib = fib[i - 1] + fib[i - 2]
        fib.append(nextFib)

        if isPrime(nextFib) {
            count += 1
        }

        i += 1
    }

    return fib[i - 1]
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }

    if number <= 3 {
        return true
    }

    var i = 2
    while i * i <= number {
        if number % i == 0 {
            return false
        }
        i = i + 1
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89[/INST]  ```swift
func primeFib(n: Int) -> Int {
    var count = 0
    var fib = [0, 1]
    var i = 2

    while count < n {
        let nextFib = fib[i - 1] + fib[i - 2]
        fib.append(nextFib)

        if isPrime(nextFib) {
            count += 1
        }

        i += 1
    }

    return fib[i - 1]
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }

    if number <= 3 {
        return true
    }

    var i = 2
    while i * i <= number {
        if number % i == 0 {
            return false
        }
        i = i + 1
    }

    return true
}
```

func primeFib(n: Int) -> Int {
    var count = 0
    var fib = [0, 1]
    var i = 2

    while count < n {
        let nextFib = fib[i - 1] + fib[i - 2]
        fib.append(nextFib)

        if isPrime(nextFib) {
            count += 1
        }

        i += 1
    }

    return fib[i - 1]
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }

    if number <= 3 {
        return true
    }

    var i = 2
    while i * i <= number {
        if number % i == 0 {
            return false
        }
        i = i + 1
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89[/INST]  ```swift
func primeFib(n: Int) -> Int {
    var count = 0
    var fib = [0, 1]
    var i = 2

    while count < n {
        let nextFib = fib[i - 1] + fib[i - 2]
        fib.append(nextFib)

        if isPrime(nextFib) {
            count += 1
        }

        i += 1
    }

    return fib[i - 1]
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }

    if number <= 3 {
        return true
    }

    var i = 2
    while i * i <= number {
        if number % i == 0 {
            return false
        }
        i = i + 1
    }

    return true
}
```

func primeFib(n: Int) -> Int {
    var count = 0
    var fib = [0, 1]
    var i = 2

    while count < n {
        let nextFib = fib[i-1] + fib[i-2]
        fib.append(nextFib)

        if isPrime(nextFib) {
            count += 1
        }

        i += 1
    }

    return fib[i-1]
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }

    if number <= 3 {
        return true
    }

    if number % 2 == 0 || number % 3 == 0 {
        return false
    }

    var i = 5
    while i * i <= number {
        if number % i == 0 || number % (i + 2) == 0 {
            return false
        }
        i += 6
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89[/INST]  ```swift
func primeFib(n: Int) -> Int {
    var count = 0
    var fib = [0, 1]
    var i = 2

    while count < n {
        let nextFib = fib[i-1] + fib[i-2]
        fib.append(nextFib)

        if isPrime(nextFib) {
            count += 1
        }

        i += 1
    }

    return fib[i-1]
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }

    if number <= 3 {
        return true
    }

    if number % 2 == 0 || number % 3 == 0 {
        return false
    }

    var i = 5
    while i * i <= number {
        if number % i == 0 || number % (i + 2) == 0 {
            return false
        }
        i += 6
    }

    return true
}
```

func primeFib(n: Int) -> Int {
    var count = 0
    var fib = [0, 1]
    var i = 2

    while count < n {
        let nextFib = fib[i-1] + fib[i-2]
        fib.append(nextFib)

        if isPrime(nextFib) {
            count += 1
        }

        i += 1
    }

    return fib[i-1]
}

func isPrime(_ num: Int) -> Bool {
    if num <= 1 {
        return false
    }

    if num <= 3 {
        return true
    }

    if num % 2 == 0 || num % 3 == 0 {
        return false
    }

    var i = 5
    while i * i <= num {
        if num % i == 0 || num % (i + 2) == 0 {
            return false
        }
        i += 6
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89[/INST]  ```swift
func primeFib(n: Int) -> Int {
    var count = 0
    var fib = [0, 1]
    var i = 2

    while count < n {
        let nextFib = fib[i-1] + fib[i-2]
        fib.append(nextFib)

        if isPrime(nextFib) {
            count += 1
        }

        i += 1
    }

    return fib[i-1]
}

func isPrime(_ num: Int) -> Bool {
    if num <= 1 {
        return false
    }

    if num <= 3 {
        return true
    }

    if num % 2 == 0 || num % 3 == 0 {
        return false
    }

    var i = 5
    while i * i <= num {
        if num % i == 0 || num % (i + 2) == 0 {
            return false
        }
        i += 6
    }

    return true
}
```

func primeFib(n: Int) -> Int {
    var count = 0
    var fib = [0, 1]
    var i = 2

    while count < n {
        let nextFib = fib[i - 1] + fib[i - 2]
        fib.append(nextFib)

        if isPrime(nextFib) {
            count += 1
        }

        i += 1
    }

    return fib[i - 1]
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }

    if number <= 3 {
        return true
    }

    if number % 2 == 0 || number % 3 == 0 {
        return false
    }

    var i = 5
    while i * i <= number {
        if number % i == 0 || number % (i + 2) == 0 {
            return false
        }
        i += 6
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89[/INST]  ```swift
func primeFib(n: Int) -> Int {
    var count = 0
    var fib = [0, 1]
    var i = 2

    while count < n {
        let nextFib = fib[i - 1] + fib[i - 2]
        fib.append(nextFib)

        if isPrime(nextFib) {
            count += 1
        }

        i += 1
    }

    return fib[i - 1]
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }

    if number <= 3 {
        return true
    }

    if number % 2 == 0 || number % 3 == 0 {
        return false
    }

    var i = 5
    while i * i <= number {
        if number % i == 0 || number % (i + 2) == 0 {
            return false
        }
        i += 6
    }

    return true
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    let sortedArray = l.sorted()
    for i in 0..<sortedArray.count - 2 {
        if i > 0 && sortedArray[i] == sortedArray[i - 1] {
            continue
        }
        var left = i + 1
        var right = sortedArray.count - 1
        while left < right {
            let sum = sortedArray[i] + sortedArray[left] + sortedArray[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false[/INST]  ```swift
func triplesSumToZero(l: [Int]) -> Bool {
    let sortedArray = l.sorted()
    for i in 0..<sortedArray.count - 2 {
        if i > 0 && sortedArray[i] == sortedArray[i - 1] {
            continue
        }
        var left = i + 1
        var right = sortedArray.count - 1
        while left < right {
            let sum = sortedArray[i] + sortedArray[left] + sortedArray[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}
```
 // Fatal error: Range requires lowerBound <= upperBound

func triplesSumToZero(l: [Int]) -> Bool {
    let sortedArray = l.sorted()
    for i in 0..<sortedArray.count - 2 {
        if i > 0 && sortedArray[i] == sortedArray[i - 1] {
            continue
        }
        var left = i + 1
        var right = sortedArray.count - 1
        while left < right {
            let sum = sortedArray[i] + sortedArray[left] + sortedArray[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false[/INST]  ```swift
func triplesSumToZero(l: [Int]) -> Bool {
    let sortedArray = l.sorted()
    for i in 0..<sortedArray.count - 2 {
        if i > 0 && sortedArray[i] == sortedArray[i - 1] {
            continue
        }
        var left = i + 1
        var right = sortedArray.count - 1
        while left < right {
            let sum = sortedArray[i] + sortedArray[left] + sortedArray[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}
```
 // Fatal error: Range requires lowerBound <= upperBound

func triplesSumToZero(l: [Int]) -> Bool {
    let sortedArray = l.sorted()
    for i in 0..<sortedArray.count - 2 {
        if i > 0 && sortedArray[i] == sortedArray[i - 1] {
            continue
        }
        var left = i + 1
        var right = sortedArray.count - 1
        while left < right {
            let sum = sortedArray[i] + sortedArray[left] + sortedArray[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false[/INST]  ```swift
func triplesSumToZero(l: [Int]) -> Bool {
    let sortedArray = l.sorted()
    for i in 0..<sortedArray.count - 2 {
        if i > 0 && sortedArray[i] == sortedArray[i - 1] {
            continue
        }
        var left = i + 1
        var right = sortedArray.count - 1
        while left < right {
            let sum = sortedArray[i] + sortedArray[left] + sortedArray[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}
```
 // Fatal error: Range requires lowerBound <= upperBound

func triplesSumToZero(l: [Int]) -> Bool {
    let sortedArray = l.sorted()
    for i in 0..<sortedArray.count - 2 {
        if i > 0 && sortedArray[i] == sortedArray[i - 1] {
            continue
        }
        var left = i + 1
        var right = sortedArray.count - 1
        while left < right {
            let sum = sortedArray[i] + sortedArray[left] + sortedArray[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false[/INST]  ```swift
func triplesSumToZero(l: [Int]) -> Bool {
    let sortedArray = l.sorted()
    for i in 0..<sortedArray.count - 2 {
        if i > 0 && sortedArray[i] == sortedArray[i - 1] {
            continue
        }
        var left = i + 1
        var right = sortedArray.count - 1
        while left < right {
            let sum = sortedArray[i] + sortedArray[left] + sortedArray[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}
```
 // Fatal error: Range requires lowerBound <= upperBound

func triplesSumToZero(l: [Int]) -> Bool {
    let sortedArray = l.sorted()
    for i in 0..<sortedArray.count-2 {
        if i > 0 && sortedArray[i] == sortedArray[i-1] {
            continue
        }
        var left = i + 1
        var right = sortedArray.count - 1
        while left < right {
            let sum = sortedArray[i] + sortedArray[left] + sortedArray[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false[/INST]  ```swift
func triplesSumToZero(l: [Int]) -> Bool {
    let sortedArray = l.sorted()
    for i in 0..<sortedArray.count-2 {
        if i > 0 && sortedArray[i] == sortedArray[i-1] {
            continue
        }
        var left = i + 1
        var right = sortedArray.count - 1
        while left < right {
            let sum = sortedArray[i] + sortedArray[left] + sortedArray[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}
```
 // Fatal error: Range requires lowerBound <= upperBound

func triplesSumToZero(l: [Int]) -> Bool {
    let sortedArray = l.sorted()
    for i in 0..<sortedArray.count-2 {
        if i > 0 && sortedArray[i] == sortedArray[i-1] {
            continue
        }
        var left = i + 1
        var right = sortedArray.count - 1
        while left < right {
            let sum = sortedArray[i] + sortedArray[left] + sortedArray[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false[/INST]  ```swift
func triplesSumToZero(l: [Int]) -> Bool {
    let sortedArray = l.sorted()
    for i in 0..<sortedArray.count-2 {
        if i > 0 && sortedArray[i] == sortedArray[i-1] {
            continue
        }
        var left = i + 1
        var right = sortedArray.count - 1
        while left < right {
            let sum = sortedArray[i] + sortedArray[left] + sortedArray[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}
```
 // Fatal error: Range requires lowerBound <= upperBound

func triplesSumToZero(l: [Int]) -> Bool {
    let sortedArray = l.sorted()
    for i in 0..<sortedArray.count-2 {
        if i > 0 && sortedArray[i] == sortedArray[i-1] {
            continue
        }
        var left = i + 1
        var right = sortedArray.count - 1
        while left < right {
            let sum = sortedArray[i] + sortedArray[left] + sortedArray[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false[/INST]  ```swift
func triplesSumToZero(l: [Int]) -> Bool {
    let sortedArray = l.sorted()
    for i in 0..<sortedArray.count-2 {
        if i > 0 && sortedArray[i] == sortedArray[i-1] {
            continue
        }
        var left = i + 1
        var right = sortedArray.count - 1
        while left < right {
            let sum = sortedArray[i] + sortedArray[left] + sortedArray[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}
```
 // Fatal error: Range requires lowerBound <= upperBound

func triplesSumToZero(l: [Int]) -> Bool {
    let sortedArray = l.sorted()
    for i in 0..<sortedArray.count-2 {
        if i > 0 && sortedArray[i] == sortedArray[i-1] {
            continue
        }
        var left = i + 1
        var right = sortedArray.count - 1
        while left < right {
            let sum = sortedArray[i] + sortedArray[left] + sortedArray[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false[/INST]  ```swift
func triplesSumToZero(l: [Int]) -> Bool {
    let sortedArray = l.sorted()
    for i in 0..<sortedArray.count-2 {
        if i > 0 && sortedArray[i] == sortedArray[i-1] {
            continue
        }
        var left = i + 1
        var right = sortedArray.count - 1
        while left < right {
            let sum = sortedArray[i] + sortedArray[left] + sortedArray[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}
```
 // Fatal error: Range requires lowerBound <= upperBound

func triplesSumToZero(l: [Int]) -> Bool {
    let sortedArray = l.sorted()
    for i in 0..<sortedArray.count - 2 {
        if i > 0 && sortedArray[i] == sortedArray[i - 1] {
            continue
        }
        var left = i + 1
        var right = sortedArray.count - 1
        while left < right {
            let sum = sortedArray[i] + sortedArray[left] + sortedArray[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false[/INST]  ```swift
func triplesSumToZero(l: [Int]) -> Bool {
    let sortedArray = l.sorted()
    for i in 0..<sortedArray.count - 2 {
        if i > 0 && sortedArray[i] == sortedArray[i - 1] {
            continue
        }
        var left = i + 1
        var right = sortedArray.count - 1
        while left < right {
            let sum = sortedArray[i] + sortedArray[left] + sortedArray[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}
```
 // Fatal error: Range requires lowerBound <= upperBound

func triplesSumToZero(l: [Int]) -> Bool {
    let sortedArray = l.sorted()
    for i in 0..<sortedArray.count-2 {
        if i > 0 && sortedArray[i] == sortedArray[i-1] {
            continue
        }
        var left = i + 1
        var right = sortedArray.count - 1
        while left < right {
            let sum = sortedArray[i] + sortedArray[left] + sortedArray[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false[/INST]  ```swift
func triplesSumToZero(l: [Int]) -> Bool {
    let sortedArray = l.sorted()
    for i in 0..<sortedArray.count-2 {
        if i > 0 && sortedArray[i] == sortedArray[i-1] {
            continue
        }
        var left = i + 1
        var right = sortedArray.count - 1
        while left < right {
            let sum = sortedArray[i] + sortedArray[left] + sortedArray[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}
```
 // Fatal error: Range requires lowerBound <= upperBound

func carRaceCollision(n: Int) -> Int {
    // Since all cars move in the same speed and they collide when they meet,
    // it means that every pair of cars will collide.
    // So, the number of collisions is equal to the number of cars.
    return n
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
[/INST]  ```swift
func carRaceCollision(n: Int) -> Int {
    // Since all cars move in the same speed and they collide when they meet,
    // it means that every pair of cars will collide.
    // So, the number of collisions is equal to the number of cars.
    return n
}
```
 // XCTAssertTrue failed

func carRaceCollision(n: Int) -> Int {
    // Since all cars move at the same speed and the road is infinitely long,
    // each car will collide with a car coming from the opposite direction.
    // Since there are n cars moving in each direction, there will be n collisions.
    return n
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
[/INST]  ```swift
func carRaceCollision(n: Int) -> Int {
    // Since all cars move at the same speed and the road is infinitely long,
    // each car will collide with a car coming from the opposite direction.
    // Since there are n cars moving in each direction, there will be n collisions.
    return n
}
```
 // XCTAssertTrue failed

func carRaceCollision(n: Int) -> Int {
    // Since all cars move at the same speed and the road is infinitely long,
    // every pair of cars will collide once.
    // So, the total number of collisions is equal to the number of cars (n).
    return n
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
[/INST]  ```swift
func carRaceCollision(n: Int) -> Int {
    // Since all cars move at the same speed and the road is infinitely long,
    // every pair of cars will collide once.
    // So, the total number of collisions is equal to the number of cars (n).
    return n
}
```
 // XCTAssertTrue failed

func carRaceCollision(n: Int) -> Int {
    // Since all cars move at the same speed and the road is infinitely long,
    // each car will collide with exactly one car.
    // So, the total number of collisions is equal to the number of cars (n).
    return n
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
[/INST]  ```swift
func carRaceCollision(n: Int) -> Int {
    // Since all cars move at the same speed and the road is infinitely long,
    // each car will collide with exactly one car.
    // So, the total number of collisions is equal to the number of cars (n).
    return n
}
```
 // XCTAssertTrue failed

func carRaceCollision(n: Int) -> Int {
    // Since all cars move at the same speed and the road is infinitely long,
    // every pair of cars (one moving left and one moving right) will collide.
    // So, the number of collisions is equal to the number of cars.
    return n
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
[/INST]  ```swift
func carRaceCollision(n: Int) -> Int {
    // Since all cars move at the same speed and the road is infinitely long,
    // every pair of cars (one moving left and one moving right) will collide.
    // So, the number of collisions is equal to the number of cars.
    return n
}
```
 // XCTAssertTrue failed

func carRaceCollision(n: Int) -> Int {
    // Since all cars move at the same speed and the road is infinitely long,
    // each car will collide with a car coming from the opposite direction.
    // Therefore, the number of collisions is equal to the number of cars.
    return n
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
[/INST]  ```swift
func carRaceCollision(n: Int) -> Int {
    // Since all cars move at the same speed and the road is infinitely long,
    // each car will collide with a car coming from the opposite direction.
    // Therefore, the number of collisions is equal to the number of cars.
    return n
}
```
 // XCTAssertTrue failed

func carRaceCollision(n: Int) -> Int {
    // Since all cars move at the same speed and the road is infinitely long,
    // every pair of cars will collide exactly once.
    // So, the total number of collisions is equal to the number of cars (n).
    return n
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
[/INST]  ```swift
func carRaceCollision(n: Int) -> Int {
    // Since all cars move at the same speed and the road is infinitely long,
    // every pair of cars will collide exactly once.
    // So, the total number of collisions is equal to the number of cars (n).
    return n
}
```
 // XCTAssertTrue failed

func carRaceCollision(n: Int) -> Int {
    // Since all cars move at the same speed and the road is infinitely long,
    // each car will collide with exactly one car.
    // Therefore, the total number of collisions is equal to the number of cars.
    return n
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
[/INST]  ```swift
func carRaceCollision(n: Int) -> Int {
    // Since all cars move at the same speed and the road is infinitely long,
    // each car will collide with exactly one car.
    // Therefore, the total number of collisions is equal to the number of cars.
    return n
}
```
 // XCTAssertTrue failed

func carRaceCollision(n: Int) -> Int {
    // Since all cars move at the same speed and the road is infinitely long,
    // each car will collide with a car coming from the opposite direction.
    // Since there are n cars moving left to right and n cars moving right to left,
    // there will be n collisions.
    return n
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
[/INST]  ```swift
func carRaceCollision(n: Int) -> Int {
    // Since all cars move at the same speed and the road is infinitely long,
    // each car will collide with a car coming from the opposite direction.
    // Since there are n cars moving left to right and n cars moving right to left,
    // there will be n collisions.
    return n
}
```
 // XCTAssertTrue failed

func carRaceCollision(n: Int) -> Int {
    // Since all cars move at the same speed and the road is infinitely long,
    // each car will collide with a car coming from the opposite direction.
    // Therefore, the number of collisions is equal to the number of cars.
    return n
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
[/INST]  ```swift
func carRaceCollision(n: Int) -> Int {
    // Since all cars move at the same speed and the road is infinitely long,
    // each car will collide with a car coming from the opposite direction.
    // Therefore, the number of collisions is equal to the number of cars.
    return n
}
```
 // XCTAssertTrue failed

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124][/INST]  ```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124][/INST]  ```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124][/INST]  ```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124][/INST]  ```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124][/INST]  ```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124][/INST]  ```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124][/INST]  ```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124][/INST]  ```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124][/INST]  ```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124][/INST]  ```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false[/INST]  ```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()

    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false[/INST]  ```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()

    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }

    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false[/INST]  ```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false[/INST]  ```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()

    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false[/INST]  ```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()

    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }

    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()

    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false[/INST]  ```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()

    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }

    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()

    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false[/INST]  ```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()

    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }

    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()

    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false[/INST]  ```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()

    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }

    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()

    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false[/INST]  ```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()

    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }

    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()

    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false[/INST]  ```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()

    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }

    return false
}
```

func changeBase(x: Int, base: Int) -> String {
    var number = x
    var result = ""

    while number > 0 {
        result = String(number % base) + result
        number /= base
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"[/INST]  ```swift
func changeBase(x: Int, base: Int) -> String {
    var number = x
    var result = ""

    while number > 0 {
        result = String(number % base) + result
        number /= base
    }

    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var number = x
    var result = ""

    while number > 0 {
        result = String(number % base) + result
        number /= base
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"[/INST]  ```swift
func changeBase(x: Int, base: Int) -> String {
    var number = x
    var result = ""

    while number > 0 {
        result = String(number % base) + result
        number /= base
    }

    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var number = x
    var result = ""
    while number > 0 {
        result = String(number % base) + result
        number /= base
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"[/INST]  ```swift
func changeBase(x: Int, base: Int) -> String {
    var number = x
    var result = ""
    while number > 0 {
        result = String(number % base) + result
        number /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var number = x
    var result = ""
    while number > 0 {
        result = String(number % base) + result
        number /= base
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"[/INST]  ```swift
func changeBase(x: Int, base: Int) -> String {
    var number = x
    var result = ""
    while number > 0 {
        result = String(number % base) + result
        number /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var number = x
    var result = ""

    while number > 0 {
        let remainder = number % base
        number /= base
        result = String(remainder) + result
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"[/INST]  ```swift
func changeBase(x: Int, base: Int) -> String {
    var number = x
    var result = ""

    while number > 0 {
        let remainder = number % base
        number /= base
        result = String(remainder) + result
    }

    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var number = x
    var result = ""

    while number > 0 {
        result = String(number % base) + result
        number /= base
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"[/INST]  ```swift
func changeBase(x: Int, base: Int) -> String {
    var number = x
    var result = ""

    while number > 0 {
        result = String(number % base) + result
        number /= base
    }

    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var number = x
    var result = ""

    while number > 0 {
        result = String(number % base) + result
        number /= base
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"[/INST]  ```swift
func changeBase(x: Int, base: Int) -> String {
    var number = x
    var result = ""

    while number > 0 {
        result = String(number % base) + result
        number /= base
    }

    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var number = x
    var result = ""

    while number > 0 {
        result = String(number % base) + result
        number /= base
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"[/INST]  ```swift
func changeBase(x: Int, base: Int) -> String {
    var number = x
    var result = ""

    while number > 0 {
        result = String(number % base) + result
        number /= base
    }

    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var number = x
    var result = ""
    while number > 0 {
        result = String(number % base) + result
        number /= base
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"[/INST]  ```swift
func changeBase(x: Int, base: Int) -> String {
    var number = x
    var result = ""
    while number > 0 {
        result = String(number % base) + result
        number /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var number = x
    var result = ""

    while number > 0 {
        result = String(number % base) + result
        number /= base
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"[/INST]  ```swift
func changeBase(x: Int, base: Int) -> String {
    var number = x
    var result = ""

    while number > 0 {
        result = String(number % base) + result
        number /= base
    }

    return result
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5[/INST]  ```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5[/INST]  ```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2.0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5[/INST]  ```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2.0
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5[/INST]  ```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5[/INST]  ```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5[/INST]  ```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5[/INST]  ```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5[/INST]  ```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2.0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5[/INST]  ```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2.0
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2.0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5[/INST]  ```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2.0
}
```

func fib4(n: Int) -> Int {
    if n < 0 {
        return 0
    } else if n == 0 {
        return 0
    } else if n == 1 {
        return 0
    } else if n == 2 {
        return 2
    } else if n == 3 {
        return 0
    }

    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var result = 0

    for _ in 4...n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14[/INST]  ```swift
func fib4(n: Int) -> Int {
    if n < 0 {
        return 0
    } else if n == 0 {
        return 0
    } else if n == 1 {
        return 0
    } else if n == 2 {
        return 2
    } else if n == 3 {
        return 0
    }

    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var result = 0

    for _ in 4...n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
    }

    return result
}
```

func fib4(n: Int) -> Int {
    if n < 0 {
        return 0
    } else if n == 0 {
        return 0
    } else if n == 1 {
        return 0
    } else if n == 2 {
        return 2
    } else if n == 3 {
        return 0
    }

    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var result = 0

    for _ in 4...n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14[/INST]  ```swift
func fib4(n: Int) -> Int {
    if n < 0 {
        return 0
    } else if n == 0 {
        return 0
    } else if n == 1 {
        return 0
    } else if n == 2 {
        return 2
    } else if n == 3 {
        return 0
    }

    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var result = 0

    for _ in 4...n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
    }

    return result
}
```

func fib4(n: Int) -> Int {
    if n < 0 {
        return 0
    } else if n == 0 {
        return 0
    } else if n == 1 {
        return 0
    } else if n == 2 {
        return 2
    } else if n == 3 {
        return 0
    }

    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var result = 0

    for _ in 4...n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14[/INST]  ```swift
func fib4(n: Int) -> Int {
    if n < 0 {
        return 0
    } else if n == 0 {
        return 0
    } else if n == 1 {
        return 0
    } else if n == 2 {
        return 2
    } else if n == 3 {
        return 0
    }

    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var result = 0

    for _ in 4...n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
    }

    return result
}
```

func fib4(n: Int) -> Int {
    if n < 0 {
        return 0
    } else if n == 0 {
        return 0
    } else if n == 1 {
        return 0
    } else if n == 2 {
        return 2
    } else if n == 3 {
        return 0
    }

    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var result = 0

    for _ in 4...n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14[/INST]  ```swift
func fib4(n: Int) -> Int {
    if n < 0 {
        return 0
    } else if n == 0 {
        return 0
    } else if n == 1 {
        return 0
    } else if n == 2 {
        return 2
    } else if n == 3 {
        return 0
    }

    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var result = 0

    for _ in 4...n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
    }

    return result
}
```

func fib4(n: Int) -> Int {
    if n < 0 {
        return 0
    } else if n == 0 {
        return 0
    } else if n == 1 {
        return 0
    } else if n == 2 {
        return 2
    } else if n == 3 {
        return 0
    }

    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var result = 0

    for _ in 4...n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14[/INST]  ```swift
func fib4(n: Int) -> Int {
    if n < 0 {
        return 0
    } else if n == 0 {
        return 0
    } else if n == 1 {
        return 0
    } else if n == 2 {
        return 2
    } else if n == 3 {
        return 0
    }

    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var result = 0

    for _ in 4...n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
    }

    return result
}
```

func fib4(n: Int) -> Int {
    if n < 0 {
        return 0
    } else if n == 0 {
        return 0
    } else if n == 1 {
        return 0
    } else if n == 2 {
        return 2
    } else if n == 3 {
        return 0
    }

    var a = 0
    var b = 0
    var c = 2
    var d = 0

    for _ in 4...n {
        let temp = a + b + c + d
        a = b
        b = c
        c = d
        d = temp
    }

    return d
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14[/INST]  ```swift
func fib4(n: Int) -> Int {
    if n < 0 {
        return 0
    } else if n == 0 {
        return 0
    } else if n == 1 {
        return 0
    } else if n == 2 {
        return 2
    } else if n == 3 {
        return 0
    }

    var a = 0
    var b = 0
    var c = 2
    var d = 0

    for _ in 4...n {
        let temp = a + b + c + d
        a = b
        b = c
        c = d
        d = temp
    }

    return d
}
```

func fib4(n: Int) -> Int {
    if n < 0 {
        return 0
    } else if n == 0 {
        return 0
    } else if n == 1 {
        return 0
    } else if n == 2 {
        return 2
    } else if n == 3 {
        return 0
    }

    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var result = 0

    for _ in 4...n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14[/INST]  ```swift
func fib4(n: Int) -> Int {
    if n < 0 {
        return 0
    } else if n == 0 {
        return 0
    } else if n == 1 {
        return 0
    } else if n == 2 {
        return 2
    } else if n == 3 {
        return 0
    }

    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var result = 0

    for _ in 4...n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
    }

    return result
}
```

func fib4(n: Int) -> Int {
    if n < 0 {
        return 0
    } else if n == 0 {
        return 0
    } else if n == 1 {
        return 0
    } else if n == 2 {
        return 2
    } else if n == 3 {
        return 0
    }

    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var result = 0

    for _ in 4...n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14[/INST]  ```swift
func fib4(n: Int) -> Int {
    if n < 0 {
        return 0
    } else if n == 0 {
        return 0
    } else if n == 1 {
        return 0
    } else if n == 2 {
        return 2
    } else if n == 3 {
        return 0
    }

    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var result = 0

    for _ in 4...n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
    }

    return result
}
```

func fib4(n: Int) -> Int {
    if n < 0 {
        return 0
    } else if n == 0 {
        return 0
    } else if n == 1 {
        return 0
    } else if n == 2 {
        return 2
    } else if n == 3 {
        return 0
    }

    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var result = 0

    for _ in 4...n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14[/INST]  ```swift
func fib4(n: Int) -> Int {
    if n < 0 {
        return 0
    } else if n == 0 {
        return 0
    } else if n == 1 {
        return 0
    } else if n == 2 {
        return 2
    } else if n == 3 {
        return 0
    }

    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var result = 0

    for _ in 4...n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
    }

    return result
}
```

func fib4(n: Int) -> Int {
    if n < 0 {
        return 0
    } else if n == 0 {
        return 0
    } else if n == 1 {
        return 0
    } else if n == 2 {
        return 2
    } else if n == 3 {
        return 0
    }

    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var result = 0

    for _ in 4...n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14[/INST]  ```swift
func fib4(n: Int) -> Int {
    if n < 0 {
        return 0
    } else if n == 0 {
        return 0
    } else if n == 1 {
        return 0
    } else if n == 2 {
        return 2
    } else if n == 3 {
        return 0
    }

    var a = 0
    var b = 0
    var c = 2
    var d = 0
    var result = 0

    for _ in 4...n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
    }

    return result
}
```

func median(l: [Int]) -> Double {
    let sortedArray = l.sorted()
    let count = sortedArray.count

    if count % 2 == 0 {
        let midIndex = count / 2
        return Double(sortedArray[midIndex - 1] + sortedArray[midIndex]) / 2.0
    } else {
        let midIndex = count / 2
        return Double(sortedArray[midIndex])
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0[/INST]  ```swift
func median(l: [Int]) -> Double {
    let sortedArray = l.sorted()
    let count = sortedArray.count

    if count % 2 == 0 {
        let midIndex = count / 2
        return Double(sortedArray[midIndex - 1] + sortedArray[midIndex]) / 2.0
    } else {
        let midIndex = count / 2
        return Double(sortedArray[midIndex])
    }
}
```

func median(l: [Int]) -> Double {
    let sortedArray = l.sorted()
    let count = sortedArray.count

    if count % 2 == 0 {
        return Double(sortedArray[count / 2] + sortedArray[count / 2 - 1]) / 2.0
    } else {
        return Double(sortedArray[count / 2])
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0[/INST]  ```swift
func median(l: [Int]) -> Double {
    let sortedArray = l.sorted()
    let count = sortedArray.count

    if count % 2 == 0 {
        return Double(sortedArray[count / 2] + sortedArray[count / 2 - 1]) / 2.0
    } else {
        return Double(sortedArray[count / 2])
    }
}
```

func median(l: [Int]) -> Double {
    let sortedArray = l.sorted()
    let count = sortedArray.count
    let mid = count / 2

    if count % 2 == 0 {
        return Double(sortedArray[mid] + sortedArray[mid - 1]) / 2.0
    } else {
        return Double(sortedArray[mid])
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0[/INST]  ```swift
func median(l: [Int]) -> Double {
    let sortedArray = l.sorted()
    let count = sortedArray.count
    let mid = count / 2

    if count % 2 == 0 {
        return Double(sortedArray[mid] + sortedArray[mid - 1]) / 2.0
    } else {
        return Double(sortedArray[mid])
    }
}
```

func median(l: [Int]) -> Double {
    let sortedArray = l.sorted()
    let count = sortedArray.count

    if count % 2 == 0 {
        let midIndex = count / 2
        return Double(sortedArray[midIndex - 1] + sortedArray[midIndex]) / 2.0
    } else {
        let midIndex = count / 2
        return Double(sortedArray[midIndex])
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0[/INST]  ```swift
func median(l: [Int]) -> Double {
    let sortedArray = l.sorted()
    let count = sortedArray.count

    if count % 2 == 0 {
        let midIndex = count / 2
        return Double(sortedArray[midIndex - 1] + sortedArray[midIndex]) / 2.0
    } else {
        let midIndex = count / 2
        return Double(sortedArray[midIndex])
    }
}
```

func median(l: [Int]) -> Double {
    let sortedArray = l.sorted()
    let count = sortedArray.count

    if count % 2 == 0 {
        let midIndex = count / 2
        return Double(sortedArray[midIndex - 1] + sortedArray[midIndex]) / 2.0
    } else {
        let midIndex = count / 2
        return Double(sortedArray[midIndex])
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0[/INST]  ```swift
func median(l: [Int]) -> Double {
    let sortedArray = l.sorted()
    let count = sortedArray.count

    if count % 2 == 0 {
        let midIndex = count / 2
        return Double(sortedArray[midIndex - 1] + sortedArray[midIndex]) / 2.0
    } else {
        let midIndex = count / 2
        return Double(sortedArray[midIndex])
    }
}
```

func median(l: [Int]) -> Double {
    let sortedArray = l.sorted()
    let count = sortedArray.count
    let mid = count / 2

    if count % 2 == 0 {
        return Double(sortedArray[mid] + sortedArray[mid - 1]) / 2.0
    } else {
        return Double(sortedArray[mid])
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0[/INST]  ```swift
func median(l: [Int]) -> Double {
    let sortedArray = l.sorted()
    let count = sortedArray.count
    let mid = count / 2

    if count % 2 == 0 {
        return Double(sortedArray[mid] + sortedArray[mid - 1]) / 2.0
    } else {
        return Double(sortedArray[mid])
    }
}
```

func median(l: [Int]) -> Double {
    let sortedArray = l.sorted()
    let count = sortedArray.count
    if count % 2 == 0 {
        return Double(sortedArray[count / 2 - 1] + sortedArray[count / 2]) / 2.0
    } else {
        return Double(sortedArray[count / 2])
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0[/INST]  ```swift
func median(l: [Int]) -> Double {
    let sortedArray = l.sorted()
    let count = sortedArray.count
    if count % 2 == 0 {
        return Double(sortedArray[count / 2 - 1] + sortedArray[count / 2]) / 2.0
    } else {
        return Double(sortedArray[count / 2])
    }
}
```

func median(l: [Int]) -> Double {
    let sortedList = l.sorted()
    let count = sortedList.count
    let mid = count / 2

    if count % 2 == 0 {
        return Double(sortedList[mid] + sortedList[mid - 1]) / 2.0
    } else {
        return Double(sortedList[mid])
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0[/INST]  ```swift
func median(l: [Int]) -> Double {
    let sortedList = l.sorted()
    let count = sortedList.count
    let mid = count / 2

    if count % 2 == 0 {
        return Double(sortedList[mid] + sortedList[mid - 1]) / 2.0
    } else {
        return Double(sortedList[mid])
    }
}
```

func median(l: [Int]) -> Double {
    let sortedArray = l.sorted()
    let count = sortedArray.count

    if count % 2 == 0 {
        return Double(sortedArray[count / 2] + sortedArray[count / 2 - 1]) / 2.0
    } else {
        return Double(sortedArray[count / 2])
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0[/INST]  ```swift
func median(l: [Int]) -> Double {
    let sortedArray = l.sorted()
    let count = sortedArray.count

    if count % 2 == 0 {
        return Double(sortedArray[count / 2] + sortedArray[count / 2 - 1]) / 2.0
    } else {
        return Double(sortedArray[count / 2])
    }
}
```

func median(l: [Int]) -> Double {
    let sortedArray = l.sorted()
    let count = sortedArray.count
    if count % 2 == 0 {
        return Double(sortedArray[count / 2] + sortedArray[count / 2 - 1]) / 2.0
    } else {
        return Double(sortedArray[count / 2])
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0[/INST]  ```swift
func median(l: [Int]) -> Double {
    let sortedArray = l.sorted()
    let count = sortedArray.count
    if count % 2 == 0 {
        return Double(sortedArray[count / 2] + sortedArray[count / 2 - 1]) / 2.0
    } else {
        return Double(sortedArray[count / 2])
    }
}
```

func isPalindrome(text: String) -> Bool {
    let reversedText = String(text.reversed())
    return text == reversedText
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false[/INST]  ```swift
func isPalindrome(text: String) -> Bool {
    let reversedText = String(text.reversed())
    return text == reversedText
}
```

func isPalindrome(text: String) -> Bool {
    let reversedText = String(text.reversed())
    return text == reversedText
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false[/INST]  ```swift
func isPalindrome(text: String) -> Bool {
    let reversedText = String(text.reversed())
    return text == reversedText
}
```

func isPalindrome(text: String) -> Bool {
    let reversedText = String(text.reversed())
    return text == reversedText
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false[/INST]  ```swift
func isPalindrome(text: String) -> Bool {
    let reversedText = String(text.reversed())
    return text == reversedText
}
```

func isPalindrome(text: String) -> Bool {
    let reversedText = String(text.reversed())
    return text == reversedText
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false[/INST]  ```swift
func isPalindrome(text: String) -> Bool {
    let reversedText = String(text.reversed())
    return text == reversedText
}
```

func isPalindrome(text: String) -> Bool {
    let reversedText = String(text.reversed())
    return text == reversedText
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false[/INST]  ```swift
func isPalindrome(text: String) -> Bool {
    let reversedText = String(text.reversed())
    return text == reversedText
}
```

func isPalindrome(text: String) -> Bool {
    let reversedText = String(text.reversed())
    return text == reversedText
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false[/INST]  ```swift
func isPalindrome(text: String) -> Bool {
    let reversedText = String(text.reversed())
    return text == reversedText
}
```

func isPalindrome(text: String) -> Bool {
    let reversedText = String(text.reversed())
    return text == reversedText
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false[/INST]  ```swift
func isPalindrome(text: String) -> Bool {
    let reversedText = String(text.reversed())
    return text == reversedText
}
```

func isPalindrome(text: String) -> Bool {
    let reversedText = String(text.reversed())
    return text == reversedText
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false[/INST]  ```swift
func isPalindrome(text: String) -> Bool {
    let reversedText = String(text.reversed())
    return text == reversedText
}
```

func isPalindrome(text: String) -> Bool {
    let reversedText = String(text.reversed())
    return text == reversedText
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false[/INST]  ```swift
func isPalindrome(text: String) -> Bool {
    let reversedText = String(text.reversed())
    return text == reversedText
}
```

func isPalindrome(text: String) -> Bool {
    let reversedText = String(text.reversed())
    return text == reversedText
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false[/INST]  ```swift
func isPalindrome(text: String) -> Bool {
    let reversedText = String(text.reversed())
    return text == reversedText
}
```

func modp(n: Int, p: Int) -> Int {
    if n == 0 {
        return 1
    } else if n == 1 {
        return 2 % p
    } else if n % 2 == 0 {
        let half = modp(n: n / 2, p: p)
        return (half * half) % p
    } else {
        let half = modp(n: n / 2, p: p)
        return ((half * half) % p * 2) % p
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1[/INST]  ```swift
func modp(n: Int, p: Int) -> Int {
    if n == 0 {
        return 1
    } else if n == 1 {
        return 2 % p
    } else if n % 2 == 0 {
        let half = modp(n: n / 2, p: p)
        return (half * half) % p
    } else {
        let half = modp(n: n / 2, p: p)
        return ((half * half) % p * 2) % p
    }
}
```

func modp(n: Int, p: Int) -> Int {
    if p == 1 {
        return 1
    }
    var result = 1
    var base = 2
    var exponent = n
    while exponent > 0 {
        if exponent % 2 == 1 {
            result = (result * base) % p
        }
        base = (base * base) % p
        exponent /= 2
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1[/INST]  ```swift
func modp(n: Int, p: Int) -> Int {
    if p == 1 {
        return 1
    }
    var result = 1
    var base = 2
    var exponent = n
    while exponent > 0 {
        if exponent % 2 == 1 {
            result = (result * base) % p
        }
        base = (base * base) % p
        exponent /= 2
    }
    return result
}
```

func modp(n: Int, p: Int) -> Int {
    if p == 1 {
        return 1
    }
    var result = 1
    var base = 2
    var exponent = n
    while exponent > 0 {
        if exponent % 2 == 1 {
            result = (result * base) % p
        }
        base = (base * base) % p
        exponent /= 2
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1[/INST]  ```swift
func modp(n: Int, p: Int) -> Int {
    if p == 1 {
        return 1
    }
    var result = 1
    var base = 2
    var exponent = n
    while exponent > 0 {
        if exponent % 2 == 1 {
            result = (result * base) % p
        }
        base = (base * base) % p
        exponent /= 2
    }
    return result
}
```

func modp(n: Int, p: Int) -> Int {
    if n == 0 {
        return 1
    }
    var result = 1
    var base = 2
    var exponent = n
    while exponent > 0 {
        if exponent % 2 == 1 {
            result = (result * base) % p
        }
        base = (base * base) % p
        exponent /= 2
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1[/INST]  ```swift
func modp(n: Int, p: Int) -> Int {
    if n == 0 {
        return 1
    }
    var result = 1
    var base = 2
    var exponent = n
    while exponent > 0 {
        if exponent % 2 == 1 {
            result = (result * base) % p
        }
        base = (base * base) % p
        exponent /= 2
    }
    return result
}
```

func modp(n: Int, p: Int) -> Int {
    if n == 0 {
        return 1
    }
    var result = 1
    var base = 2
    var exponent = n
    while exponent > 0 {
        if exponent % 2 == 1 {
            result = (result * base) % p
        }
        base = (base * base) % p
        exponent /= 2
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1[/INST]  ```swift
func modp(n: Int, p: Int) -> Int {
    if n == 0 {
        return 1
    }
    var result = 1
    var base = 2
    var exponent = n
    while exponent > 0 {
        if exponent % 2 == 1 {
            result = (result * base) % p
        }
        base = (base * base) % p
        exponent /= 2
    }
    return result
}
```

func modp(n: Int, p: Int) -> Int {
    if n == 0 {
        return 1
    }
    var result = 1
    var base = 2
    var exponent = n
    while exponent > 0 {
        if exponent % 2 == 1 {
            result = (result * base) % p
        }
        base = (base * base) % p
        exponent /= 2
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1[/INST]  ```swift
func modp(n: Int, p: Int) -> Int {
    if n == 0 {
        return 1
    }
    var result = 1
    var base = 2
    var exponent = n
    while exponent > 0 {
        if exponent % 2 == 1 {
            result = (result * base) % p
        }
        base = (base * base) % p
        exponent /= 2
    }
    return result
}
```

func modp(n: Int, p: Int) -> Int {
    if n == 0 {
        return 1
    } else if n == 1 {
        return 2 % p
    } else {
        var result = 2
        for _ in 1..<n {
            result = (result * 2) % p
        }
        return result
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1[/INST]  ```swift
func modp(n: Int, p: Int) -> Int {
    if n == 0 {
        return 1
    } else if n == 1 {
        return 2 % p
    } else {
        var result = 2
        for _ in 1..<n {
            result = (result * 2) % p
        }
        return result
    }
}
```

func modp(n: Int, p: Int) -> Int {
    if n == 0 {
        return 1
    }
    var result = 1
    var base = 2
    var exponent = n
    while exponent > 0 {
        if exponent % 2 == 1 {
            result = (result * base) % p
        }
        base = (base * base) % p
        exponent /= 2
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1[/INST]  ```swift
func modp(n: Int, p: Int) -> Int {
    if n == 0 {
        return 1
    }
    var result = 1
    var base = 2
    var exponent = n
    while exponent > 0 {
        if exponent % 2 == 1 {
            result = (result * base) % p
        }
        base = (base * base) % p
        exponent /= 2
    }
    return result
}
```

func modp(n: Int, p: Int) -> Int {
    if n == 0 {
        return 1
    } else if n == 1 {
        return 2 % p
    } else if n % 2 == 0 {
        let half = modp(n: n / 2, p: p)
        return (half * half) % p
    } else {
        let half = modp(n: n / 2, p: p)
        return ((half * half) % p * 2) % p
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1[/INST]  ```swift
func modp(n: Int, p: Int) -> Int {
    if n == 0 {
        return 1
    } else if n == 1 {
        return 2 % p
    } else if n % 2 == 0 {
        let half = modp(n: n / 2, p: p)
        return (half * half) % p
    } else {
        let half = modp(n: n / 2, p: p)
        return ((half * half) % p * 2) % p
    }
}
```

func modp(n: Int, p: Int) -> Int {
    if n == 0 {
        return 1
    }
    var result = 1
    var base = 2
    var exponent = n
    while exponent > 0 {
        if exponent % 2 == 1 {
            result = (result * base) % p
        }
        base = (base * base) % p
        exponent /= 2
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1[/INST]  ```swift
func modp(n: Int, p: Int) -> Int {
    if n == 0 {
        return 1
    }
    var result = 1
    var base = 2
    var exponent = n
    while exponent > 0 {
        if exponent % 2 == 1 {
            result = (result * base) % p
        }
        base = (base * base) % p
        exponent /= 2
    }
    return result
}
```

func removeVowels(text: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    return String(text.filter { !vowels.contains($0) })
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"[/INST]  ```swift
func removeVowels(text: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    return String(text.filter { !vowels.contains($0) })
}
```

func removeVowels(text: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    return String(text.filter { !vowels.contains($0) })
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"[/INST]  ```swift
func removeVowels(text: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    return String(text.filter { !vowels.contains($0) })
}
```

func removeVowels(text: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    return String(text.filter { !vowels.contains($0) })
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"[/INST]  ```swift
func removeVowels(text: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    return String(text.filter { !vowels.contains($0) })
}
```

func removeVowels(text: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    return String(text.filter { !vowels.contains($0) })
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"[/INST]  ```swift
func removeVowels(text: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    return String(text.filter { !vowels.contains($0) })
}
```

func removeVowels(text: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    return String(text.filter { !vowels.contains($0) })
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"[/INST]  ```swift
func removeVowels(text: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    return String(text.filter { !vowels.contains($0) })
}
```

func removeVowels(text: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    return String(text.filter { !vowels.contains($0) })
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"[/INST]  ```swift
func removeVowels(text: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    return String(text.filter { !vowels.contains($0) })
}
```

func removeVowels(text: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    return String(text.filter { !vowels.contains($0) })
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"[/INST]  ```swift
func removeVowels(text: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    return String(text.filter { !vowels.contains($0) })
}
```

func removeVowels(text: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    return String(text.filter { !vowels.contains($0) })
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"[/INST]  ```swift
func removeVowels(text: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    return String(text.filter { !vowels.contains($0) })
}
```

func removeVowels(text: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    return String(text.filter { !vowels.contains($0) })
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"[/INST]  ```swift
func removeVowels(text: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    return String(text.filter { !vowels.contains($0) })
}
```

func removeVowels(text: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    return String(text.filter { !vowels.contains($0) })
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"[/INST]  ```swift
func removeVowels(text: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    return String(text.filter { !vowels.contains($0) })
}
```

func belowThreshold(l: [Int], t: Int) -> Bool {
    return l.allSatisfy { $0 < t }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false[/INST]  ```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
    return l.allSatisfy { $0 < t }
}
```

func belowThreshold(l: [Int], t: Int) -> Bool {
    for num in l {
        if num >= t {
            return false
        }
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false[/INST]  ```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
    for num in l {
        if num >= t {
            return false
        }
    }
    return true
}
```

func belowThreshold(l: [Int], t: Int) -> Bool {
    for number in l {
        if number >= t {
            return false
        }
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false[/INST]  ```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
    for number in l {
        if number >= t {
            return false
        }
    }
    return true
}
```

func belowThreshold(l: [Int], t: Int) -> Bool {
    return l.allSatisfy { $0 < t }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false[/INST]  ```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
    return l.allSatisfy { $0 < t }
}
```

func belowThreshold(l: [Int], t: Int) -> Bool {
    return l.allSatisfy { $0 < t }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false[/INST]  ```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
    return l.allSatisfy { $0 < t }
}
```

func belowThreshold(l: [Int], t: Int) -> Bool {
    return l.allSatisfy { $0 < t }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false[/INST]  ```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
    return l.allSatisfy { $0 < t }
}
```

func belowThreshold(l: [Int], t: Int) -> Bool {
    return l.allSatisfy { $0 < t }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false[/INST]  ```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
    return l.allSatisfy { $0 < t }
}
```

func belowThreshold(l: [Int], t: Int) -> Bool {
    return l.allSatisfy { $0 < t }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false[/INST]  ```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
    return l.allSatisfy { $0 < t }
}
```

func belowThreshold(l: [Int], t: Int) -> Bool {
    for num in l {
        if num >= t {
            return false
        }
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false[/INST]  ```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
    for num in l {
        if num >= t {
            return false
        }
    }
    return true
}
```

func belowThreshold(l: [Int], t: Int) -> Bool {
    return l.allSatisfy { $0 < t }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false[/INST]  ```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
    return l.allSatisfy { $0 < t }
}
```

func add(x: Int, y: Int) -> Int {
    return x + y
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12[/INST]  ```swift
func add(x: Int, y: Int) -> Int {
    return x + y
}
```

func add(x: Int, y: Int) -> Int {
    return x + y
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12[/INST]  ```swift
func add(x: Int, y: Int) -> Int {
    return x + y
}
```

func add(x: Int, y: Int) -> Int {
    return x + y
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12[/INST]  ```swift
func add(x: Int, y: Int) -> Int {
    return x + y
}
```

func add(x: Int, y: Int) -> Int {
    return x + y
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12[/INST]  ```swift
func add(x: Int, y: Int) -> Int {
    return x + y
}
```

func add(x: Int, y: Int) -> Int {
    return x + y
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12[/INST]  ```swift
func add(x: Int, y: Int) -> Int {
    return x + y
}
```

func add(x: Int, y: Int) -> Int {
    return x + y
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12[/INST]  ```swift
func add(x: Int, y: Int) -> Int {
    return x + y
}
```

func add(x: Int, y: Int) -> Int {
    return x + y
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12[/INST]  ```swift
func add(x: Int, y: Int) -> Int {
    return x + y
}
```

func add(x: Int, y: Int) -> Int {
    return x + y
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12[/INST]  ```swift
func add(x: Int, y: Int) -> Int {
    return x + y
}
```

func add(x: Int, y: Int) -> Int {
    return x + y
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12[/INST]  ```swift
func add(x: Int, y: Int) -> Int {
    return x + y
}
```

func add(x: Int, y: Int) -> Int {
    return x + y
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12[/INST]  ```swift
func add(x: Int, y: Int) -> Int {
    return x + y
}
```

func sameChars(s0: String, s1: String) -> Bool {
    let set0 = Set(s0)
    let set1 = Set(s1)
    return set0 == set1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false[/INST]  ```swift
func sameChars(s0: String, s1: String) -> Bool {
    let set0 = Set(s0)
    let set1 = Set(s1)
    return set0 == set1
}
```

func sameChars(s0: String, s1: String) -> Bool {
    let set0 = Set(s0)
    let set1 = Set(s1)
    return set0 == set1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false[/INST]  ```swift
func sameChars(s0: String, s1: String) -> Bool {
    let set0 = Set(s0)
    let set1 = Set(s1)
    return set0 == set1
}
```

func sameChars(s0: String, s1: String) -> Bool {
    let set0 = Set(s0)
    let set1 = Set(s1)
    return set0 == set1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false[/INST]  ```swift
func sameChars(s0: String, s1: String) -> Bool {
    let set0 = Set(s0)
    let set1 = Set(s1)
    return set0 == set1
}
```

func sameChars(s0: String, s1: String) -> Bool {
    let set0 = Set(s0)
    let set1 = Set(s1)
    return set0 == set1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false[/INST]  ```swift
func sameChars(s0: String, s1: String) -> Bool {
    let set0 = Set(s0)
    let set1 = Set(s1)
    return set0 == set1
}
```

func sameChars(s0: String, s1: String) -> Bool {
    let set0 = Set(s0)
    let set1 = Set(s1)
    return set0 == set1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false[/INST]  ```swift
func sameChars(s0: String, s1: String) -> Bool {
    let set0 = Set(s0)
    let set1 = Set(s1)
    return set0 == set1
}
```

func sameChars(s0: String, s1: String) -> Bool {
    return s0.sorted() == s1.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false[/INST]  ```swift
func sameChars(s0: String, s1: String) -> Bool {
    return s0.sorted() == s1.sorted()
}
```
 // XCTAssertTrue failed

func sameChars(s0: String, s1: String) -> Bool {
    let set0 = Set(s0)
    let set1 = Set(s1)
    return set0 == set1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false[/INST]  ```swift
func sameChars(s0: String, s1: String) -> Bool {
    let set0 = Set(s0)
    let set1 = Set(s1)
    return set0 == set1
}
```

func sameChars(s0: String, s1: String) -> Bool {
    let set0 = Set(s0)
    let set1 = Set(s1)
    return set0 == set1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false[/INST]  ```swift
func sameChars(s0: String, s1: String) -> Bool {
    let set0 = Set(s0)
    let set1 = Set(s1)
    return set0 == set1
}
```

func sameChars(s0: String, s1: String) -> Bool {
    let set0 = Set(s0)
    let set1 = Set(s1)
    return set0 == set1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false[/INST]  ```swift
func sameChars(s0: String, s1: String) -> Bool {
    let set0 = Set(s0)
    let set1 = Set(s1)
    return set0 == set1
}
```

func sameChars(s0: String, s1: String) -> Bool {
    let set0 = Set(s0)
    let set1 = Set(s1)
    return set0 == set1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false[/INST]  ```swift
func sameChars(s0: String, s1: String) -> Bool {
    let set0 = Set(s0)
    let set1 = Set(s1)
    return set0 == set1
}
```

func fib(n: Int) -> Int {
    if n <= 1 {
        return n
    }
    var a = 0
    var b = 1
    for _ in 2...n {
        let temp = a
        a = b
        b = temp + b
    }
    return b
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21[/INST]  ```swift
func fib(n: Int) -> Int {
    if n <= 1 {
        return n
    }
    var a = 0
    var b = 1
    for _ in 2...n {
        let temp = a
        a = b
        b = temp + b
    }
    return b
}
```

func fib(n: Int) -> Int {
    if n <= 1 {
        return n
    }
    var fibNumbers = [0, 1]
    for i in 2...n {
        fibNumbers.append(fibNumbers[i-1] + fibNumbers[i-2])
    }
    return fibNumbers[n]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21[/INST]  ```swift
func fib(n: Int) -> Int {
    if n <= 1 {
        return n
    }
    var fibNumbers = [0, 1]
    for i in 2...n {
        fibNumbers.append(fibNumbers[i-1] + fibNumbers[i-2])
    }
    return fibNumbers[n]
}
```

func fib(n: Int) -> Int {
    if n <= 1 {
        return n
    }
    var fibNumbers = [0, 1]
    for i in 2...n {
        fibNumbers.append(fibNumbers[i-1] + fibNumbers[i-2])
    }
    return fibNumbers[n]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21[/INST]  ```swift
func fib(n: Int) -> Int {
    if n <= 1 {
        return n
    }
    var fibNumbers = [0, 1]
    for i in 2...n {
        fibNumbers.append(fibNumbers[i-1] + fibNumbers[i-2])
    }
    return fibNumbers[n]
}
```

func fib(n: Int) -> Int {
    if n <= 1 {
        return n
    }
    var a = 0
    var b = 1
    for _ in 2...n {
        let temp = a
        a = b
        b = temp + b
    }
    return b
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21[/INST]  ```swift
func fib(n: Int) -> Int {
    if n <= 1 {
        return n
    }
    var a = 0
    var b = 1
    for _ in 2...n {
        let temp = a
        a = b
        b = temp + b
    }
    return b
}
```

func fib(n: Int) -> Int {
    if n <= 1 {
        return n
    }
    var a = 0
    var b = 1
    for _ in 2...n {
        let temp = a
        a = b
        b = temp + b
    }
    return b
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21[/INST]  ```swift
func fib(n: Int) -> Int {
    if n <= 1 {
        return n
    }
    var a = 0
    var b = 1
    for _ in 2...n {
        let temp = a
        a = b
        b = temp + b
    }
    return b
}
```

func fib(n: Int) -> Int {
    if n <= 1 {
        return n
    }
    var a = 0
    var b = 1
    for _ in 2...n {
        let temp = a
        a = b
        b = temp + b
    }
    return b
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21[/INST]  ```swift
func fib(n: Int) -> Int {
    if n <= 1 {
        return n
    }
    var a = 0
    var b = 1
    for _ in 2...n {
        let temp = a
        a = b
        b = temp + b
    }
    return b
}
```

func fib(n: Int) -> Int {
    if n <= 1 {
        return n
    }
    var fibNumbers = [0, 1]
    for i in 2...n {
        fibNumbers.append(fibNumbers[i-1] + fibNumbers[i-2])
    }
    return fibNumbers[n]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21[/INST]  ```swift
func fib(n: Int) -> Int {
    if n <= 1 {
        return n
    }
    var fibNumbers = [0, 1]
    for i in 2...n {
        fibNumbers.append(fibNumbers[i-1] + fibNumbers[i-2])
    }
    return fibNumbers[n]
}
```

func fib(n: Int) -> Int {
    if n <= 1 {
        return n
    }
    var a = 0
    var b = 1
    for _ in 2...n {
        let temp = a
        a = b
        b = temp + b
    }
    return b
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21[/INST]  ```swift
func fib(n: Int) -> Int {
    if n <= 1 {
        return n
    }
    var a = 0
    var b = 1
    for _ in 2...n {
        let temp = a
        a = b
        b = temp + b
    }
    return b
}
```

func fib(n: Int) -> Int {
    if n <= 1 {
        return n
    }
    var a = 0
    var b = 1
    for _ in 2...n {
        let temp = a
        a = b
        b = temp + b
    }
    return b
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21[/INST]  ```swift
func fib(n: Int) -> Int {
    if n <= 1 {
        return n
    }
    var a = 0
    var b = 1
    for _ in 2...n {
        let temp = a
        a = b
        b = temp + b
    }
    return b
}
```

func fib(n: Int) -> Int {
    if n <= 1 {
        return n
    }
    var fibNumbers = [0, 1]
    for i in 2...n {
        fibNumbers.append(fibNumbers[i-1] + fibNumbers[i-2])
    }
    return fibNumbers[n]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21[/INST]  ```swift
func fib(n: Int) -> Int {
    if n <= 1 {
        return n
    }
    var fibNumbers = [0, 1]
    for i in 2...n {
        fibNumbers.append(fibNumbers[i-1] + fibNumbers[i-2])
    }
    return fibNumbers[n]
}
```

func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "<" {
            count += 1
        } else if bracket == ">" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false[/INST]  ```swift
func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "<" {
            count += 1
        } else if bracket == ">" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
```

func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "<" {
            count += 1
        } else if bracket == ">" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false[/INST]  ```swift
func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "<" {
            count += 1
        } else if bracket == ">" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
```

func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "<" {
            count += 1
        } else if bracket == ">" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false[/INST]  ```swift
func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "<" {
            count += 1
        } else if bracket == ">" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
```

func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "<" {
            count += 1
        } else if bracket == ">" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false[/INST]  ```swift
func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "<" {
            count += 1
        } else if bracket == ">" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
```

func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "<" {
            count += 1
        } else if bracket == ">" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false[/INST]  ```swift
func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "<" {
            count += 1
        } else if bracket == ">" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
```

func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "<" {
            count += 1
        } else if bracket == ">" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false[/INST]  ```swift
func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "<" {
            count += 1
        } else if bracket == ">" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
```

func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "<" {
            count += 1
        } else if bracket == ">" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false[/INST]  ```swift
func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "<" {
            count += 1
        } else if bracket == ">" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
```

func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "<" {
            count += 1
        } else if bracket == ">" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false[/INST]  ```swift
func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "<" {
            count += 1
        } else if bracket == ">" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
```

func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "<" {
            count += 1
        } else if bracket == ">" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false[/INST]  ```swift
func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "<" {
            count += 1
        } else if bracket == ">" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
```

func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "<" {
            count += 1
        } else if bracket == ">" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false[/INST]  ```swift
func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "<" {
            count += 1
        } else if bracket == ">" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
```

func monotonic(l: [Int]) -> Bool {
    if l.count < 3 {
        return true
    }

    let isIncreasing = l[0] < l[1]

    for i in 1..<l.count - 1 {
        if isIncreasing && l[i] > l[i + 1] {
            return false
        } else if !isIncreasing && l[i] < l[i + 1] {
            return false
        }
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true[/INST]  ```swift
func monotonic(l: [Int]) -> Bool {
    if l.count < 3 {
        return true
    }

    let isIncreasing = l[0] < l[1]

    for i in 1..<l.count - 1 {
        if isIncreasing && l[i] > l[i + 1] {
            return false
        } else if !isIncreasing && l[i] < l[i + 1] {
            return false
        }
    }

    return true
}
```

func monotonic(l: [Int]) -> Bool {
    if l.count <= 2 {
        return true
    }
    var isIncreasing = l[1] > l[0]
    for i in 2..<l.count {
        if isIncreasing && l[i] < l[i - 1] {
            return false
        } else if !isIncreasing && l[i] > l[i - 1] {
            return false
        }
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true[/INST]  ```swift
func monotonic(l: [Int]) -> Bool {
    if l.count <= 2 {
        return true
    }
    var isIncreasing = l[1] > l[0]
    for i in 2..<l.count {
        if isIncreasing && l[i] < l[i - 1] {
            return false
        } else if !isIncreasing && l[i] > l[i - 1] {
            return false
        }
    }
    return true
}
```
var isIncreasing = l[1] > l[0] // variable 'isIncreasing' was never mutated; consider changing to 'let' constant

func monotonic(l: [Int]) -> Bool {
    if l.count < 3 {
        return true
    }

    let isIncreasing = l[0] < l[1]

    for i in 1..<l.count - 1 {
        if isIncreasing && l[i] > l[i + 1] {
            return false
        } else if !isIncreasing && l[i] < l[i + 1] {
            return false
        }
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true[/INST]  ```swift
func monotonic(l: [Int]) -> Bool {
    if l.count < 3 {
        return true
    }

    let isIncreasing = l[0] < l[1]

    for i in 1..<l.count - 1 {
        if isIncreasing && l[i] > l[i + 1] {
            return false
        } else if !isIncreasing && l[i] < l[i + 1] {
            return false
        }
    }

    return true
}
```

func monotonic(l: [Int]) -> Bool {
    if l.count < 3 {
        return true
    }

    let isIncreasing = l[0] < l[1]

    for i in 1..<l.count - 1 {
        if isIncreasing && l[i] > l[i + 1] {
            return false
        } else if !isIncreasing && l[i] < l[i + 1] {
            return false
        }
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true[/INST]  ```swift
func monotonic(l: [Int]) -> Bool {
    if l.count < 3 {
        return true
    }

    let isIncreasing = l[0] < l[1]

    for i in 1..<l.count - 1 {
        if isIncreasing && l[i] > l[i + 1] {
            return false
        } else if !isIncreasing && l[i] < l[i + 1] {
            return false
        }
    }

    return true
}
```

func monotonic(l: [Int]) -> Bool {
    if l.count < 2 {
        return true
    }

    let isIncreasing = l[0] < l[1]

    for i in 1..<l.count - 1 {
        if isIncreasing && l[i] > l[i + 1] {
            return false
        } else if !isIncreasing && l[i] < l[i + 1] {
            return false
        }
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true[/INST]  ```swift
func monotonic(l: [Int]) -> Bool {
    if l.count < 2 {
        return true
    }

    let isIncreasing = l[0] < l[1]

    for i in 1..<l.count - 1 {
        if isIncreasing && l[i] > l[i + 1] {
            return false
        } else if !isIncreasing && l[i] < l[i + 1] {
            return false
        }
    }

    return true
}
```

func monotonic(l: [Int]) -> Bool {
    if l.count < 3 {
        return true
    }

    let isIncreasing = l[0] < l[1]

    for i in 1..<l.count - 1 {
        if isIncreasing && l[i] > l[i + 1] {
            return false
        } else if !isIncreasing && l[i] < l[i + 1] {
            return false
        }
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true[/INST]  ```swift
func monotonic(l: [Int]) -> Bool {
    if l.count < 3 {
        return true
    }

    let isIncreasing = l[0] < l[1]

    for i in 1..<l.count - 1 {
        if isIncreasing && l[i] > l[i + 1] {
            return false
        } else if !isIncreasing && l[i] < l[i + 1] {
            return false
        }
    }

    return true
}
```

func monotonic(l: [Int]) -> Bool {
    if l.count < 2 {
        return true
    }

    let isIncreasing = l[1] > l[0]

    for i in 1..<l.count {
        if isIncreasing && l[i] < l[i - 1] {
            return false
        } else if !isIncreasing && l[i] > l[i - 1] {
            return false
        }
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true[/INST]  ```swift
func monotonic(l: [Int]) -> Bool {
    if l.count < 2 {
        return true
    }

    let isIncreasing = l[1] > l[0]

    for i in 1..<l.count {
        if isIncreasing && l[i] < l[i - 1] {
            return false
        } else if !isIncreasing && l[i] > l[i - 1] {
            return false
        }
    }

    return true
}
```

func monotonic(l: [Int]) -> Bool {
    if l.count <= 2 {
        return true
    }

    var isIncreasing = l[1] > l[0]
    for i in 2..<l.count {
        if isIncreasing && l[i] < l[i - 1] {
            return false
        } else if !isIncreasing && l[i] > l[i - 1] {
            return false
        }
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true[/INST]  ```swift
func monotonic(l: [Int]) -> Bool {
    if l.count <= 2 {
        return true
    }

    var isIncreasing = l[1] > l[0]
    for i in 2..<l.count {
        if isIncreasing && l[i] < l[i - 1] {
            return false
        } else if !isIncreasing && l[i] > l[i - 1] {
            return false
        }
    }
    return true
}
```
var isIncreasing = l[1] > l[0] // variable 'isIncreasing' was never mutated; consider changing to 'let' constant

func monotonic(l: [Int]) -> Bool {
    if l.count <= 2 {
        return true
    }

    var isIncreasing = l[1] > l[0]
    for i in 2..<l.count {
        if isIncreasing && l[i] < l[i - 1] {
            return false
        } else if !isIncreasing && l[i] > l[i - 1] {
            return false
        }
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true[/INST]  ```swift
func monotonic(l: [Int]) -> Bool {
    if l.count <= 2 {
        return true
    }

    var isIncreasing = l[1] > l[0]
    for i in 2..<l.count {
        if isIncreasing && l[i] < l[i - 1] {
            return false
        } else if !isIncreasing && l[i] > l[i - 1] {
            return false
        }
    }

    return true
}
```
var isIncreasing = l[1] > l[0] // variable 'isIncreasing' was never mutated; consider changing to 'let' constant

func monotonic(l: [Int]) -> Bool {
    if l.count < 3 {
        return true
    }

    let isIncreasing = l[0] < l[1]

    for i in 1..<l.count - 1 {
        if isIncreasing && l[i] > l[i + 1] {
            return false
        } else if !isIncreasing && l[i] < l[i + 1] {
            return false
        }
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true[/INST]  ```swift
func monotonic(l: [Int]) -> Bool {
    if l.count < 3 {
        return true
    }

    let isIncreasing = l[0] < l[1]

    for i in 1..<l.count - 1 {
        if isIncreasing && l[i] > l[i + 1] {
            return false
        } else if !isIncreasing && l[i] < l[i + 1] {
            return false
        }
    }

    return true
}
```

func common(l1: [Int], l2: [Int]) -> [Int] {
    let set1 = Set(l1)
    let set2 = Set(l2)
    let commonSet = set1.intersection(set2)
    return commonSet.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3][/INST]  ```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
    let set1 = Set(l1)
    let set2 = Set(l2)
    let commonSet = set1.intersection(set2)
    return commonSet.sorted()
}
```

func common(l1: [Int], l2: [Int]) -> [Int] {
    let set1 = Set(l1)
    let set2 = Set(l2)
    let commonSet = set1.intersection(set2)
    return commonSet.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3][/INST]  ```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
    let set1 = Set(l1)
    let set2 = Set(l2)
    let commonSet = set1.intersection(set2)
    return commonSet.sorted()
}
```

func common(l1: [Int], l2: [Int]) -> [Int] {
    let set1 = Set(l1)
    let set2 = Set(l2)
    let commonSet = set1.intersection(set2)
    return commonSet.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3][/INST]  ```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
    let set1 = Set(l1)
    let set2 = Set(l2)
    let commonSet = set1.intersection(set2)
    return commonSet.sorted()
}
```

func common(l1: [Int], l2: [Int]) -> [Int] {
    let set1 = Set(l1)
    let set2 = Set(l2)
    let commonSet = set1.intersection(set2)
    return commonSet.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3][/INST]  ```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
    let set1 = Set(l1)
    let set2 = Set(l2)
    let commonSet = set1.intersection(set2)
    return commonSet.sorted()
}
```

func common(l1: [Int], l2: [Int]) -> [Int] {
    let set1 = Set(l1)
    let set2 = Set(l2)
    let commonSet = set1.intersection(set2)
    return commonSet.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3][/INST]  ```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
    let set1 = Set(l1)
    let set2 = Set(l2)
    let commonSet = set1.intersection(set2)
    return commonSet.sorted()
}
```

func common(l1: [Int], l2: [Int]) -> [Int] {
    let set1 = Set(l1)
    let set2 = Set(l2)
    let commonSet = set1.intersection(set2)
    return commonSet.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3][/INST]  ```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
    let set1 = Set(l1)
    let set2 = Set(l2)
    let commonSet = set1.intersection(set2)
    return commonSet.sorted()
}
```

func common(l1: [Int], l2: [Int]) -> [Int] {
    let set1 = Set(l1)
    let set2 = Set(l2)
    let commonSet = set1.intersection(set2)
    return commonSet.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3][/INST]  ```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
    let set1 = Set(l1)
    let set2 = Set(l2)
    let commonSet = set1.intersection(set2)
    return commonSet.sorted()
}
```

func common(l1: [Int], l2: [Int]) -> [Int] {
    let set1 = Set(l1)
    let set2 = Set(l2)
    let commonSet = set1.intersection(set2)
    return commonSet.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3][/INST]  ```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
    let set1 = Set(l1)
    let set2 = Set(l2)
    let commonSet = set1.intersection(set2)
    return commonSet.sorted()
}
```

func common(l1: [Int], l2: [Int]) -> [Int] {
    let set1 = Set(l1)
    let set2 = Set(l2)
    let commonSet = set1.intersection(set2)
    return Array(commonSet).sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3][/INST]  ```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
    let set1 = Set(l1)
    let set2 = Set(l2)
    let commonSet = set1.intersection(set2)
    return Array(commonSet).sorted()
}
```

func common(l1: [Int], l2: [Int]) -> [Int] {
    let set1 = Set(l1)
    let set2 = Set(l2)
    let commonSet = set1.intersection(set2)
    return commonSet.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3][/INST]  ```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
    let set1 = Set(l1)
    let set2 = Set(l2)
    let commonSet = set1.intersection(set2)
    return commonSet.sorted()
}
```

func largestPrimeFactor(n: Int) -> Int {
    var number = n
    var i = 2

    while i * i <= number {
        if number % i == 0 {
            number = number / i
        } else {
            i += 1
        }
    }

    return number
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2[/INST]  ```swift
func largestPrimeFactor(n: Int) -> Int {
    var number = n
    var i = 2

    while i * i <= number {
        if number % i == 0 {
            number = number / i
        } else {
            i += 1
        }
    }

    return number
}
```

func largestPrimeFactor(n: Int) -> Int {
    var number = n
    var i = 2

    while i * i <= number {
        if number % i == 0 {
            number /= i
        } else {
            i += 1
        }
    }

    return number
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2[/INST]  ```swift
func largestPrimeFactor(n: Int) -> Int {
    var number = n
    var i = 2

    while i * i <= number {
        if number % i == 0 {
            number /= i
        } else {
            i += 1
        }
    }

    return number
}
```

func largestPrimeFactor(n: Int) -> Int {
    var number = n
    var i = 2

    while i * i <= number {
        if number % i == 0 {
            number = number / i
        } else {
            i += 1
        }
    }

    return number
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2[/INST]  ```swift
func largestPrimeFactor(n: Int) -> Int {
    var number = n
    var i = 2

    while i * i <= number {
        if number % i == 0 {
            number = number / i
        } else {
            i += 1
        }
    }

    return number
}
```

func largestPrimeFactor(n: Int) -> Int {
    var number = n
    var i = 2

    while i * i <= number {
        if number % i == 0 {
            number = number / i
        } else {
            i += 1
        }
    }

    return number
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2[/INST]  ```swift
func largestPrimeFactor(n: Int) -> Int {
    var number = n
    var i = 2

    while i * i <= number {
        if number % i == 0 {
            number = number / i
        } else {
            i += 1
        }
    }

    return number
}
```

func largestPrimeFactor(n: Int) -> Int {
    var number = n
    var i = 2

    while i * i <= number {
        if number % i == 0 {
            number = number / i
        } else {
            i += 1
        }
    }

    return number
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2[/INST]  ```swift
func largestPrimeFactor(n: Int) -> Int {
    var number = n
    var i = 2

    while i * i <= number {
        if number % i == 0 {
            number = number / i
        } else {
            i += 1
        }
    }

    return number
}
```

func largestPrimeFactor(n: Int) -> Int {
    var number = n
    var i = 2

    while i * i <= number {
        if number % i == 0 {
            number = number / i
        } else {
            i += 1
        }
    }

    return number
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2[/INST]  ```swift
func largestPrimeFactor(n: Int) -> Int {
    var number = n
    var i = 2

    while i * i <= number {
        if number % i == 0 {
            number = number / i
        } else {
            i += 1
        }
    }

    return number
}
```

func largestPrimeFactor(n: Int) -> Int {
    var number = n
    var i = 2

    while i * i <= number {
        if number % i == 0 {
            number /= i
        } else {
            i += 1
        }
    }

    return number
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2[/INST]  ```swift
func largestPrimeFactor(n: Int) -> Int {
    var number = n
    var i = 2

    while i * i <= number {
        if number % i == 0 {
            number /= i
        } else {
            i += 1
        }
    }

    return number
}
```

func largestPrimeFactor(n: Int) -> Int {
    var number = n
    var i = 2

    while i * i <= number {
        if number % i == 0 {
            number = number / i
        } else {
            i += 1
        }
    }

    return number
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2[/INST]  ```swift
func largestPrimeFactor(n: Int) -> Int {
    var number = n
    var i = 2

    while i * i <= number {
        if number % i == 0 {
            number = number / i
        } else {
            i += 1
        }
    }

    return number
}
```

func largestPrimeFactor(n: Int) -> Int {
    var number = n
    var i = 2

    while i * i <= number {
        if number % i == 0 {
            number = number / i
        } else {
            i += 1
        }
    }

    return number
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2[/INST]  ```swift
func largestPrimeFactor(n: Int) -> Int {
    var number = n
    var i = 2

    while i * i <= number {
        if number % i == 0 {
            number = number / i
        } else {
            i += 1
        }
    }

    return number
}
```

func largestPrimeFactor(n: Int) -> Int {
    var number = n
    var i = 2

    while i * i <= number {
        if number % i == 0 {
            number = number / i
        } else {
            i += 1
        }
    }

    return number
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2[/INST]  ```swift
func largestPrimeFactor(n: Int) -> Int {
    var number = n
    var i = 2

    while i * i <= number {
        if number % i == 0 {
            number = number / i
        } else {
            i += 1
        }
    }

    return number
}
```

func sumToN(n: Int) -> Int {
    return (n * (n + 1)) / 2
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1[/INST]  ```swift
func sumToN(n: Int) -> Int {
    return (n * (n + 1)) / 2
}
```

func sumToN(n: Int) -> Int {
    return (n * (n + 1)) / 2
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1[/INST]  ```swift
func sumToN(n: Int) -> Int {
    return (n * (n + 1)) / 2
}
```

func sumToN(n: Int) -> Int {
    return (1...n).reduce(0, +)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1[/INST]  ```swift
func sumToN(n: Int) -> Int {
    return (1...n).reduce(0, +)
}
```

func sumToN(n: Int) -> Int {
    return (n * (n + 1)) / 2
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1[/INST]  ```swift
func sumToN(n: Int) -> Int {
    return (n * (n + 1)) / 2
}
```

func sumToN(n: Int) -> Int {
    return (n * (n + 1)) / 2
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1[/INST]  ```swift
func sumToN(n: Int) -> Int {
    return (n * (n + 1)) / 2
}
```

func sumToN(n: Int) -> Int {
    return (n * (n + 1)) / 2
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1[/INST]  ```swift
func sumToN(n: Int) -> Int {
    return (n * (n + 1)) / 2
}
```

func sumToN(n: Int) -> Int {
    return (n * (n + 1)) / 2
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1[/INST]  ```swift
func sumToN(n: Int) -> Int {
    return (n * (n + 1)) / 2
}
```

func sumToN(n: Int) -> Int {
    return (n * (n + 1)) / 2
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1[/INST]  ```swift
func sumToN(n: Int) -> Int {
    return (n * (n + 1)) / 2
}
```

func sumToN(n: Int) -> Int {
    return (n * (n + 1)) / 2
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1[/INST]  ```swift
func sumToN(n: Int) -> Int {
    return (n * (n + 1)) / 2
}
```

func sumToN(n: Int) -> Int {
    return (n * (n + 1)) / 2
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1[/INST]  ```swift
func sumToN(n: Int) -> Int {
    return (n * (n + 1)) / 2
}
```

func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "(" {
            count += 1
        } else if bracket == ")" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false[/INST]  ```swift
func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "(" {
            count += 1
        } else if bracket == ")" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
```

func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "(" {
            count += 1
        } else if bracket == ")" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false[/INST]  ```swift
func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "(" {
            count += 1
        } else if bracket == ")" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
```

func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "(" {
            count += 1
        } else if bracket == ")" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false[/INST]  ```swift
func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "(" {
            count += 1
        } else if bracket == ")" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
```

func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "(" {
            count += 1
        } else if bracket == ")" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false[/INST]  ```swift
func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "(" {
            count += 1
        } else if bracket == ")" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
```

func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "(" {
            count += 1
        } else if bracket == ")" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false[/INST]  ```swift
func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "(" {
            count += 1
        } else if bracket == ")" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
```

func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "(" {
            count += 1
        } else if bracket == ")" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false[/INST]  ```swift
func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "(" {
            count += 1
        } else if bracket == ")" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
```

func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "(" {
            count += 1
        } else if bracket == ")" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false[/INST]  ```swift
func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "(" {
            count += 1
        } else if bracket == ")" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
```

func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "(" {
            count += 1
        } else if bracket == ")" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false[/INST]  ```swift
func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "(" {
            count += 1
        } else if bracket == ")" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
```

func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "(" {
            count += 1
        } else if bracket == ")" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false[/INST]  ```swift
func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "(" {
            count += 1
        } else if bracket == ")" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
```

func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "(" {
            count += 1
        } else if bracket == ")" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false[/INST]  ```swift
func correctBracketing(brackets: String) -> Bool {
    var count = 0
    for bracket in brackets {
        if bracket == "(" {
            count += 1
        } else if bracket == ")" {
            count -= 1
            if count < 0 {
                return false
            }
        }
    }
    return count == 0
}
```

func derivative(xs: [Int]) -> [Int] {
    var derivativeCoefficients = [Int]()
    for i in 1..<xs.count {
        derivativeCoefficients.append(i * xs[i])
    }
    return derivativeCoefficients
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 + ....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6][/INST]  ```swift
func derivative(xs: [Int]) -> [Int] {
    var derivativeCoefficients = [Int]()
    for i in 1..<xs.count {
        derivativeCoefficients.append(i * xs[i])
    }
    return derivativeCoefficients
}
```

func derivative(xs: [Int]) -> [Int] {
    var result = [Int]()
    for i in 1..<xs.count {
        result.append(i * xs[i])
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 + ....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6][/INST]  ```swift
func derivative(xs: [Int]) -> [Int] {
    var result = [Int]()
    for i in 1..<xs.count {
        result.append(i * xs[i])
    }
    return result
}
```

func derivative(xs: [Int]) -> [Int] {
    var result = [Int]()
    for i in 1..<xs.count {
        result.append(i * xs[i])
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 + ....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6][/INST]  ```swift
func derivative(xs: [Int]) -> [Int] {
    var result = [Int]()
    for i in 1..<xs.count {
        result.append(i * xs[i])
    }
    return result
}
```

func derivative(xs: [Int]) -> [Int] {
    var result = [Int]()
    for i in 1..<xs.count {
        result.append(i * xs[i])
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 + ....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6][/INST]  ```swift
func derivative(xs: [Int]) -> [Int] {
    var result = [Int]()
    for i in 1..<xs.count {
        result.append(i * xs[i])
    }
    return result
}
```

func derivative(xs: [Int]) -> [Int] {
    var result: [Int] = []
    for i in 1..<xs.count {
        result.append(i * xs[i])
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 + ....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6][/INST]  ```swift
func derivative(xs: [Int]) -> [Int] {
    var result: [Int] = []
    for i in 1..<xs.count {
        result.append(i * xs[i])
    }
    return result
}
```

func derivative(xs: [Int]) -> [Int] {
    var result: [Int] = []
    for i in 1..<xs.count {
        result.append(i * xs[i])
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 + ....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6][/INST]  ```swift
func derivative(xs: [Int]) -> [Int] {
    var result: [Int] = []
    for i in 1..<xs.count {
        result.append(i * xs[i])
    }
    return result
}
```

func derivative(xs: [Int]) -> [Int] {
    var result = [Int]()
    for i in 1..<xs.count {
        result.append(i * xs[i])
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 + ....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6][/INST]  ```swift
func derivative(xs: [Int]) -> [Int] {
    var result = [Int]()
    for i in 1..<xs.count {
        result.append(i * xs[i])
    }
    return result
}
```

func derivative(xs: [Int]) -> [Int] {
    var derivativeCoefficients = [Int]()
    for i in 1..<xs.count {
        derivativeCoefficients.append(i * xs[i])
    }
    return derivativeCoefficients
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 + ....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6][/INST]  ```swift
func derivative(xs: [Int]) -> [Int] {
    var derivativeCoefficients = [Int]()
    for i in 1..<xs.count {
        derivativeCoefficients.append(i * xs[i])
    }
    return derivativeCoefficients
}
```

func derivative(xs: [Int]) -> [Int] {
    var result = [Int]()
    for i in 1..<xs.count {
        result.append(i * xs[i])
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 + ....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6][/INST]  ```swift
func derivative(xs: [Int]) -> [Int] {
    var result = [Int]()
    for i in 1..<xs.count {
        result.append(i * xs[i])
    }
    return result
}
```

func derivative(xs: [Int]) -> [Int] {
    var result = [Int]()
    for i in 1..<xs.count {
        result.append(i * xs[i])
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 + ....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6][/INST]  ```swift
func derivative(xs: [Int]) -> [Int] {
    var result = [Int]()
    for i in 1..<xs.count {
        result.append(i * xs[i])
    }
    return result
}
```

func fibfib(n: Int) -> Int {
    if n == 0 {
        return 0
    } else if n == 1 || n == 2 {
        return 0
    } else if n == 3 {
        return 1
    }

    var fibfibNumbers = [0, 0, 1]
    for i in 4...n {
        let nextNumber = fibfibNumbers[i-1] + fibfibNumbers[i-2] + fibfibNumbers[i-3]
        fibfibNumbers.append(nextNumber)
    }

    return fibfibNumbers[n]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24[/INST]  ```swift
func fibfib(n: Int) -> Int {
    if n == 0 {
        return 0
    } else if n == 1 || n == 2 {
        return 0
    } else if n == 3 {
        return 1
    }

    var fibfibNumbers = [0, 0, 1]
    for i in 4...n {
        let nextNumber = fibfibNumbers[i-1] + fibfibNumbers[i-2] + fibfibNumbers[i-3]
        fibfibNumbers.append(nextNumber)
    }

    return fibfibNumbers[n]
}
```
 // XCTAssertTrue failed

func fibfib(n: Int) -> Int {
    if n == 0 || n == 1 {
        return 0
    } else if n == 2 {
        return 1
    }

    var fibfibNumbers = [0, 0, 1]

    for i in 3...n {
        let nextNumber = fibfibNumbers[i-1] + fibfibNumbers[i-2] + fibfibNumbers[i-3]
        fibfibNumbers.append(nextNumber)
    }

    return fibfibNumbers[n]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24[/INST]  ```swift
func fibfib(n: Int) -> Int {
    if n == 0 || n == 1 {
        return 0
    } else if n == 2 {
        return 1
    }

    var fibfibNumbers = [0, 0, 1]

    for i in 3...n {
        let nextNumber = fibfibNumbers[i-1] + fibfibNumbers[i-2] + fibfibNumbers[i-3]
        fibfibNumbers.append(nextNumber)
    }

    return fibfibNumbers[n]
}
```

func fibfib(n: Int) -> Int {
    if n == 0 || n == 1 {
        return 0
    } else if n == 2 {
        return 1
    }

    var fibValues = [0, 0, 1]

    for i in 3...n {
        let nextFib = fibValues[i-1] + fibValues[i-2] + fibValues[i-3]
        fibValues.append(nextFib)
    }

    return fibValues[n]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24[/INST]  ```swift
func fibfib(n: Int) -> Int {
    if n == 0 || n == 1 {
        return 0
    } else if n == 2 {
        return 1
    }

    var fibValues = [0, 0, 1]

    for i in 3...n {
        let nextFib = fibValues[i-1] + fibValues[i-2] + fibValues[i-3]
        fibValues.append(nextFib)
    }

    return fibValues[n]
}
```

func fibfib(n: Int) -> Int {
    if n < 3 {
        return 0
    } else if n == 3 {
        return 1
    }

    var fibValues = [0, 0, 1]

    for i in 4...n {
        let nextValue = fibValues[i-1] + fibValues[i-2] + fibValues[i-3]
        fibValues.append(nextValue)
    }

    return fibValues[n]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24[/INST]  ```swift
func fibfib(n: Int) -> Int {
    if n < 3 {
        return 0
    } else if n == 3 {
        return 1
    }

    var fibValues = [0, 0, 1]

    for i in 4...n {
        let nextValue = fibValues[i-1] + fibValues[i-2] + fibValues[i-3]
        fibValues.append(nextValue)
    }

    return fibValues[n]
}
```
 // XCTAssertTrue failed

func fibfib(n: Int) -> Int {
    if n == 0 {
        return 0
    } else if n == 1 || n == 2 {
        return 0
    } else if n == 3 {
        return 1
    }

    var fibfibNumbers = [0, 0, 1]
    for i in 4...n {
        let nextNumber = fibfibNumbers[i-1] + fibfibNumbers[i-2] + fibfibNumbers[i-3]
        fibfibNumbers.append(nextNumber)
    }

    return fibfibNumbers[n]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24[/INST]  ```swift
func fibfib(n: Int) -> Int {
    if n == 0 {
        return 0
    } else if n == 1 || n == 2 {
        return 0
    } else if n == 3 {
        return 1
    }

    var fibfibNumbers = [0, 0, 1]
    for i in 4...n {
        let nextNumber = fibfibNumbers[i-1] + fibfibNumbers[i-2] + fibfibNumbers[i-3]
        fibfibNumbers.append(nextNumber)
    }

    return fibfibNumbers[n]
}
```
 // XCTAssertTrue failed

func fibfib(n: Int) -> Int {
    if n == 0 || n == 1 {
        return 0
    } else if n == 2 {
        return 1
    }

    var fibfibNumbers = [0, 0, 1]
    for i in 3...n {
        let nextNumber = fibfibNumbers[i-1] + fibfibNumbers[i-2] + fibfibNumbers[i-3]
        fibfibNumbers.append(nextNumber)
    }

    return fibfibNumbers[n]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24[/INST]  ```swift
func fibfib(n: Int) -> Int {
    if n == 0 || n == 1 {
        return 0
    } else if n == 2 {
        return 1
    }

    var fibfibNumbers = [0, 0, 1]
    for i in 3...n {
        let nextNumber = fibfibNumbers[i-1] + fibfibNumbers[i-2] + fibfibNumbers[i-3]
        fibfibNumbers.append(nextNumber)
    }

    return fibfibNumbers[n]
}
```

func fibfib(n: Int) -> Int {
    if n == 0 {
        return 0
    } else if n == 1 || n == 2 {
        return 0
    } else if n == 3 {
        return 1
    }

    var fibfibNumbers = [0, 0, 1]
    for i in 4...n {
        let nextNumber = fibfibNumbers[i-1] + fibfibNumbers[i-2] + fibfibNumbers[i-3]
        fibfibNumbers.append(nextNumber)
    }

    return fibfibNumbers[n]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24[/INST]  ```swift
func fibfib(n: Int) -> Int {
    if n == 0 {
        return 0
    } else if n == 1 || n == 2 {
        return 0
    } else if n == 3 {
        return 1
    }

    var fibfibNumbers = [0, 0, 1]
    for i in 4...n {
        let nextNumber = fibfibNumbers[i-1] + fibfibNumbers[i-2] + fibfibNumbers[i-3]
        fibfibNumbers.append(nextNumber)
    }

    return fibfibNumbers[n]
}
```
 // XCTAssertTrue failed

func fibfib(n: Int) -> Int {
    if n == 0 || n == 1 {
        return 0
    } else if n == 2 {
        return 1
    }

    var fibfibNumbers = [0, 0, 1]
    for i in 3...n {
        let nextFibfibNumber = fibfibNumbers[i-1] + fibfibNumbers[i-2] + fibfibNumbers[i-3]
        fibfibNumbers.append(nextFibfibNumber)
    }

    return fibfibNumbers[n]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24[/INST]  ```swift
func fibfib(n: Int) -> Int {
    if n == 0 || n == 1 {
        return 0
    } else if n == 2 {
        return 1
    }

    var fibfibNumbers = [0, 0, 1]
    for i in 3...n {
        let nextFibfibNumber = fibfibNumbers[i-1] + fibfibNumbers[i-2] + fibfibNumbers[i-3]
        fibfibNumbers.append(nextFibfibNumber)
    }

    return fibfibNumbers[n]
}
```

func fibfib(n: Int) -> Int {
    if n == 0 {
        return 0
    } else if n == 1 || n == 2 {
        return 0
    } else if n == 3 {
        return 1
    }

    var fibfibNumbers = [0, 0, 1]

    for i in 4...n {
        let nextNumber = fibfibNumbers[i-1] + fibfibNumbers[i-2] + fibfibNumbers[i-3]
        fibfibNumbers.append(nextNumber)
    }

    return fibfibNumbers[n]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24[/INST]  ```swift
func fibfib(n: Int) -> Int {
    if n == 0 {
        return 0
    } else if n == 1 || n == 2 {
        return 0
    } else if n == 3 {
        return 1
    }

    var fibfibNumbers = [0, 0, 1]

    for i in 4...n {
        let nextNumber = fibfibNumbers[i-1] + fibfibNumbers[i-2] + fibfibNumbers[i-3]
        fibfibNumbers.append(nextNumber)
    }

    return fibfibNumbers[n]
}
```
 // XCTAssertTrue failed

func fibfib(n: Int) -> Int {
    if n == 0 {
        return 0
    } else if n == 1 || n == 2 {
        return 0
    } else if n == 3 {
        return 1
    }

    var fibfibNumbers = [0, 0, 1]

    for i in 4...n {
        let nextNumber = fibfibNumbers[i-1] + fibfibNumbers[i-2] + fibfibNumbers[i-3]
        fibfibNumbers.append(nextNumber)
    }

    return fibfibNumbers[n]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24[/INST]  ```swift
func fibfib(n: Int) -> Int {
    if n == 0 {
        return 0
    } else if n == 1 || n == 2 {
        return 0
    } else if n == 3 {
        return 1
    }

    var fibfibNumbers = [0, 0, 1]

    for i in 4...n {
        let nextNumber = fibfibNumbers[i-1] + fibfibNumbers[i-2] + fibfibNumbers[i-3]
        fibfibNumbers.append(nextNumber)
    }

    return fibfibNumbers[n]
}
```
 // XCTAssertTrue failed

func vowelsCount(s: String) -> Int {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
    let lowercasedString = s.lowercased()
    var count = 0

    for (index, char) in lowercasedString.enumerated() {
        if vowels.contains(char) {
            count += 1
        }
        if char == "y" && index == lowercasedString.count - 1 {
            count += 1
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3[/INST]  ```swift
func vowelsCount(s: String) -> Int {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
    let lowercasedString = s.lowercased()
    var count = 0

    for (index, char) in lowercasedString.enumerated() {
        if vowels.contains(char) {
            count += 1
        }
        if char == "y" && index == lowercasedString.count - 1 {
            count += 1
        }
    }

    return count
}
```

func vowelsCount(s: String) -> Int {
    let lowercasedString = s.lowercased()
    var count = 0
    for char in lowercasedString {
        switch char {
        case "a", "e", "i", "o", "u":
            count += 1
        case "y":
            if lowercasedString.last == "y" {
                count += 1
            }
        default:
            break
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3[/INST]  ```swift
func vowelsCount(s: String) -> Int {
    let lowercasedString = s.lowercased()
    var count = 0
    for char in lowercasedString {
        switch char {
        case "a", "e", "i", "o", "u":
            count += 1
        case "y":
            if lowercasedString.last == "y" {
                count += 1
            }
        default:
            break
        }
    }
    return count
}
```

func vowelsCount(s: String) -> Int {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
    let lowercasedString = s.lowercased()
    var count = 0

    for (index, char) in lowercasedString.enumerated() {
        if vowels.contains(char) {
            count += 1
        }
        if char == "y" && index == lowercasedString.count - 1 {
            count += 1
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3[/INST]  ```swift
func vowelsCount(s: String) -> Int {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
    let lowercasedString = s.lowercased()
    var count = 0

    for (index, char) in lowercasedString.enumerated() {
        if vowels.contains(char) {
            count += 1
        }
        if char == "y" && index == lowercasedString.count - 1 {
            count += 1
        }
    }

    return count
}
```

func vowelsCount(s: String) -> Int {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
    let lowercasedString = s.lowercased()
    var count = 0

    for (index, char) in lowercasedString.enumerated() {
        if vowels.contains(char) {
            count += 1
        }
        if char == "y" && index == lowercasedString.count - 1 {
            count += 1
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3[/INST]  ```swift
func vowelsCount(s: String) -> Int {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
    let lowercasedString = s.lowercased()
    var count = 0

    for (index, char) in lowercasedString.enumerated() {
        if vowels.contains(char) {
            count += 1
        }
        if char == "y" && index == lowercasedString.count - 1 {
            count += 1
        }
    }

    return count
}
```

func vowelsCount(s: String) -> Int {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
    let lowercasedString = s.lowercased()
    var count = 0

    for (index, char) in lowercasedString.enumerated() {
        if vowels.contains(char) {
            count += 1
        }
        if char == "y" && index == lowercasedString.count - 1 {
            count += 1
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3[/INST]  ```swift
func vowelsCount(s: String) -> Int {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
    let lowercasedString = s.lowercased()
    var count = 0

    for (index, char) in lowercasedString.enumerated() {
        if vowels.contains(char) {
            count += 1
        }
        if char == "y" && index == lowercasedString.count - 1 {
            count += 1
        }
    }

    return count
}
```

func vowelsCount(s: String) -> Int {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
    var count = 0
    let lowercasedString = s.lowercased()

    for (index, char) in lowercasedString.enumerated() {
        if vowels.contains(char) {
            count += 1
        }
        if char == "y" && index == lowercasedString.count - 1 {
            count += 1
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3[/INST]  ```swift
func vowelsCount(s: String) -> Int {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
    var count = 0
    let lowercasedString = s.lowercased()

    for (index, char) in lowercasedString.enumerated() {
        if vowels.contains(char) {
            count += 1
        }
        if char == "y" && index == lowercasedString.count - 1 {
            count += 1
        }
    }
    return count
}
```

func vowelsCount(s: String) -> Int {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
    let lowercasedString = s.lowercased()
    var count = 0

    for (index, char) in lowercasedString.enumerated() {
        if vowels.contains(char) {
            count += 1
        } else if char == "y" && index == lowercasedString.count - 1 {
            count += 1
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3[/INST]  ```swift
func vowelsCount(s: String) -> Int {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
    let lowercasedString = s.lowercased()
    var count = 0

    for (index, char) in lowercasedString.enumerated() {
        if vowels.contains(char) {
            count += 1
        } else if char == "y" && index == lowercasedString.count - 1 {
            count += 1
        }
    }

    return count
}
```

func vowelsCount(s: String) -> Int {
    let lowercasedString = s.lowercased()
    var count = 0
    let vowels: Set<Character> = ["a", "e", "i", "o", "u"]

    for (index, char) in lowercasedString.enumerated() {
        if vowels.contains(char) {
            count += 1
        } else if char == "y" && index == lowercasedString.count - 1 {
            count += 1
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3[/INST]  ```swift
func vowelsCount(s: String) -> Int {
    let lowercasedString = s.lowercased()
    var count = 0
    let vowels: Set<Character> = ["a", "e", "i", "o", "u"]

    for (index, char) in lowercasedString.enumerated() {
        if vowels.contains(char) {
            count += 1
        } else if char == "y" && index == lowercasedString.count - 1 {
            count += 1
        }
    }

    return count
}
```

func vowelsCount(s: String) -> Int {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
    var count = 0
    let lowercasedString = s.lowercased()

    for (index, char) in lowercasedString.enumerated() {
        if vowels.contains(char) {
            count += 1
        }
        if char == "y" && index == lowercasedString.count - 1 {
            count += 1
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3[/INST]  ```swift
func vowelsCount(s: String) -> Int {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
    var count = 0
    let lowercasedString = s.lowercased()

    for (index, char) in lowercasedString.enumerated() {
        if vowels.contains(char) {
            count += 1
        }
        if char == "y" && index == lowercasedString.count - 1 {
            count += 1
        }
    }

    return count
}
```

func vowelsCount(s: String) -> Int {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
    let lowercasedString = s.lowercased()
    var count = 0

    for (index, char) in lowercasedString.enumerated() {
        if vowels.contains(char) {
            count += 1
        }
        if char == "y" && index == lowercasedString.count - 1 {
            count += 1
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3[/INST]  ```swift
func vowelsCount(s: String) -> Int {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
    let lowercasedString = s.lowercased()
    var count = 0

    for (index, char) in lowercasedString.enumerated() {
        if vowels.contains(char) {
            count += 1
        }
        if char == "y" && index == lowercasedString.count - 1 {
            count += 1
        }
    }

    return count
}
```

func circularShift(x: Int, shift: Int) -> String {
    let digits = Array(String(x))
    let shift = shift % digits.count
    let shiftedDigits = Array(digits.suffix(shift) + digits.dropLast(shift))
    return String(shiftedDigits)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"[/INST]  ```swift
func circularShift(x: Int, shift: Int) -> String {
    let digits = Array(String(x))
    let shift = shift % digits.count
    let shiftedDigits = Array(digits.suffix(shift) + digits.dropLast(shift))
    return String(shiftedDigits)
}
```
 // XCTAssertTrue failed

func circularShift(x: Int, shift: Int) -> String {
    let digits = Array(String(x))
    let shift = shift % digits.count
    let shiftedDigits = Array(digits.suffix(shift) + digits.dropLast(shift))
    return String(shiftedDigits)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"[/INST]  ```swift
func circularShift(x: Int, shift: Int) -> String {
    let digits = Array(String(x))
    let shift = shift % digits.count
    let shiftedDigits = Array(digits.suffix(shift) + digits.dropLast(shift))
    return String(shiftedDigits)
}
```
 // XCTAssertTrue failed

func circularShift(x: Int, shift: Int) -> String {
    let digits = Array(String(x))
    let shift = shift % digits.count
    let shiftedDigits = Array(digits.suffix(shift) + digits.dropLast(shift))
    return String(shiftedDigits)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"[/INST]  ```swift
func circularShift(x: Int, shift: Int) -> String {
    let digits = Array(String(x))
    let shift = shift % digits.count
    let shiftedDigits = Array(digits.suffix(shift) + digits.dropLast(shift))
    return String(shiftedDigits)
}
```
 // XCTAssertTrue failed

func circularShift(x: Int, shift: Int) -> String {
    let digits = Array(String(x))
    let shift = shift % digits.count
    let shiftedDigits = Array(digits.suffix(shift) + digits.dropLast(shift))
    return String(shiftedDigits)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"[/INST]  ```swift
func circularShift(x: Int, shift: Int) -> String {
    let digits = Array(String(x))
    let shift = shift % digits.count
    let shiftedDigits = Array(digits.suffix(shift) + digits.dropLast(shift))
    return String(shiftedDigits)
}
```
 // XCTAssertTrue failed

func circularShift(x: Int, shift: Int) -> String {
    let digits = Array(String(x))
    let shift = shift % digits.count
    let shiftedDigits = Array(digits.suffix(shift) + digits.dropLast(shift))
    return String(shiftedDigits)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"[/INST]  ```swift
func circularShift(x: Int, shift: Int) -> String {
    let digits = Array(String(x))
    let shift = shift % digits.count
    let shiftedDigits = Array(digits.suffix(shift) + digits.dropLast(shift))
    return String(shiftedDigits)
}
```
 // XCTAssertTrue failed

func circularShift(x: Int, shift: Int) -> String {
    let digits = Array(String(x))
    let shift = shift % digits.count
    let shiftedDigits = Array(digits.suffix(shift) + digits.dropLast(shift))
    return String(shiftedDigits)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"[/INST]  ```swift
func circularShift(x: Int, shift: Int) -> String {
    let digits = Array(String(x))
    let shift = shift % digits.count
    let shiftedDigits = Array(digits.suffix(shift) + digits.dropLast(shift))
    return String(shiftedDigits)
}
```
 // XCTAssertTrue failed

func circularShift(x: Int, shift: Int) -> String {
    let digits = Array(String(x))
    let shift = shift % digits.count
    let shiftedDigits = Array(digits.suffix(shift) + digits.dropLast(shift))
    return String(shiftedDigits)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"[/INST]  ```swift
func circularShift(x: Int, shift: Int) -> String {
    let digits = Array(String(x))
    let shift = shift % digits.count
    let shiftedDigits = Array(digits.suffix(shift) + digits.dropLast(shift))
    return String(shiftedDigits)
}
```
 // XCTAssertTrue failed

func circularShift(x: Int, shift: Int) -> String {
    let digits = Array(String(x))
    let shift = shift % digits.count
    let shiftedDigits = Array(digits.suffix(shift) + digits.dropLast(shift))
    return String(shiftedDigits)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"[/INST]  ```swift
func circularShift(x: Int, shift: Int) -> String {
    let digits = Array(String(x))
    let shift = shift % digits.count
    let shiftedDigits = Array(digits.suffix(shift) + digits.dropLast(shift))
    return String(shiftedDigits)
}
```
 // XCTAssertTrue failed

func circularShift(x: Int, shift: Int) -> String {
    let digits = Array(String(x))
    let shift = shift % digits.count
    let shiftedDigits = Array(digits.suffix(shift) + digits.dropLast(shift))
    return String(shiftedDigits)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"[/INST]  ```swift
func circularShift(x: Int, shift: Int) -> String {
    let digits = Array(String(x))
    let shift = shift % digits.count
    let shiftedDigits = Array(digits.suffix(shift) + digits.dropLast(shift))
    return String(shiftedDigits)
}
```
 // XCTAssertTrue failed

func circularShift(x: Int, shift: Int) -> String {
    let digits = Array(String(x))
    let n = digits.count
    let shift = shift % n
    let shiftedDigits = Array(digits[(n - shift)...]) + Array(digits[..<(n - shift)])
    return String(shiftedDigits)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"[/INST]  ```swift
func circularShift(x: Int, shift: Int) -> String {
    let digits = Array(String(x))
    let n = digits.count
    let shift = shift % n
    let shiftedDigits = Array(digits[(n - shift)...]) + Array(digits[..<(n - shift)])
    return String(shiftedDigits)
}
```
 // XCTAssertTrue failed

func digitSum(s: String) -> Int {
    var sum = 0
    for char in s {
        if let ascii = char.asciiValue, ascii >= 65, ascii <= 90 {
            sum += Int(ascii)
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153[/INST]  ```swift
func digitSum(s: String) -> Int {
    var sum = 0
    for char in s {
        if let ascii = char.asciiValue, ascii >= 65, ascii <= 90 {
            sum += Int(ascii)
        }
    }
    return sum
}
```

func digitSum(s: String) -> Int {
    var sum = 0
    for char in s {
        if let ascii = char.asciiValue, ascii >= 65, ascii <= 90 {
            sum += Int(ascii)
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153[/INST]  ```swift
func digitSum(s: String) -> Int {
    var sum = 0
    for char in s {
        if let ascii = char.asciiValue, ascii >= 65, ascii <= 90 {
            sum += Int(ascii)
        }
    }
    return sum
}
```

func digitSum(s: String) -> Int {
    var sum = 0
    for char in s {
        if let asciiValue = char.asciiValue, asciiValue >= 65, asciiValue <= 90 {
            sum += Int(asciiValue)
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153[/INST]  ```swift
func digitSum(s: String) -> Int {
    var sum = 0
    for char in s {
        if let asciiValue = char.asciiValue, asciiValue >= 65, asciiValue <= 90 {
            sum += Int(asciiValue)
        }
    }
    return sum
}
```

func digitSum(s: String) -> Int {
    var sum = 0
    for char in s {
        if let asciiValue = char.asciiValue, asciiValue >= 65, asciiValue <= 90 {
            sum += Int(asciiValue)
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153[/INST]  ```swift
func digitSum(s: String) -> Int {
    var sum = 0
    for char in s {
        if let asciiValue = char.asciiValue, asciiValue >= 65, asciiValue <= 90 {
            sum += Int(asciiValue)
        }
    }
    return sum
}
```

func digitSum(s: String) -> Int {
    var sum = 0
    for char in s {
        if let asciiValue = char.asciiValue, asciiValue >= 65, asciiValue <= 90 {
            sum += Int(asciiValue)
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153[/INST]  ```swift
func digitSum(s: String) -> Int {
    var sum = 0
    for char in s {
        if let asciiValue = char.asciiValue, asciiValue >= 65, asciiValue <= 90 {
            sum += Int(asciiValue)
        }
    }
    return sum
}
```

func digitSum(s: String) -> Int {
    var sum = 0
    for char in s {
        if let asciiValue = char.asciiValue, asciiValue >= 65, asciiValue <= 90 {
            sum += Int(asciiValue)
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153[/INST]  ```swift
func digitSum(s: String) -> Int {
    var sum = 0
    for char in s {
        if let asciiValue = char.asciiValue, asciiValue >= 65, asciiValue <= 90 {
            sum += Int(asciiValue)
        }
    }
    return sum
}
```

func digitSum(s: String) -> Int {
    var sum = 0
    for char in s {
        if let asciiValue = char.asciiValue, asciiValue >= 65, asciiValue <= 90 {
            sum += Int(asciiValue)
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153[/INST]  ```swift
func digitSum(s: String) -> Int {
    var sum = 0
    for char in s {
        if let asciiValue = char.asciiValue, asciiValue >= 65, asciiValue <= 90 {
            sum += Int(asciiValue)
        }
    }
    return sum
}
```

func digitSum(s: String) -> Int {
    var sum = 0
    for char in s {
        if let asciiValue = char.asciiValue, asciiValue >= 65, asciiValue <= 90 {
            sum += Int(asciiValue)
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153[/INST]  ```swift
func digitSum(s: String) -> Int {
    var sum = 0
    for char in s {
        if let asciiValue = char.asciiValue, asciiValue >= 65, asciiValue <= 90 {
            sum += Int(asciiValue)
        }
    }
    return sum
}
```

func digitSum(s: String) -> Int {
    var sum = 0
    for char in s {
        if let asciiValue = char.asciiValue, asciiValue >= 65, asciiValue <= 90 {
            sum += Int(asciiValue)
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153[/INST]  ```swift
func digitSum(s: String) -> Int {
    var sum = 0
    for char in s {
        if let asciiValue = char.asciiValue, asciiValue >= 65, asciiValue <= 90 {
            sum += Int(asciiValue)
        }
    }
    return sum
}
```

func digitSum(s: String) -> Int {
    var sum = 0
    for char in s {
        if let asciiValue = char.asciiValue, asciiValue >= 65, asciiValue <= 90 {
            sum += Int(asciiValue)
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153[/INST]  ```swift
func digitSum(s: String) -> Int {
    var sum = 0
    for char in s {
        if let asciiValue = char.asciiValue, asciiValue >= 65, asciiValue <= 90 {
            sum += Int(asciiValue)
        }
    }
    return sum
}
```

func fruitDistribution(s: String, n: Int) -> Int {
    let components = s.components(separatedBy: " ")
    let apples = Int(components[0]) ?? 0
    let oranges = Int(components[3]) ?? 0
    let totalFruits = apples + oranges
    return n - totalFruits
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges 
that are distributed in a basket of fruit this basket contains 
apples, oranges, and mango fruits. Given the string that represents the total number of 
the oranges and apples and an integer that represent the total number of the fruits 
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19[/INST]  ```swift
func fruitDistribution(s: String, n: Int) -> Int {
    let components = s.components(separatedBy: " ")
    let apples = Int(components[0]) ?? 0
    let oranges = Int(components[3]) ?? 0
    let totalFruits = apples + oranges
    return n - totalFruits
}
```

func fruitDistribution(s: String, n: Int) -> Int {
    let components = s.components(separatedBy: " ")
    let apples = Int(components[0]) ?? 0
    let oranges = Int(components[3]) ?? 0
    let totalFruits = apples + oranges
    return n - totalFruits
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges 
that are distributed in a basket of fruit this basket contains 
apples, oranges, and mango fruits. Given the string that represents the total number of 
the oranges and apples and an integer that represent the total number of the fruits 
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19[/INST]  ```swift
func fruitDistribution(s: String, n: Int) -> Int {
    let components = s.components(separatedBy: " ")
    let apples = Int(components[0]) ?? 0
    let oranges = Int(components[3]) ?? 0
    let totalFruits = apples + oranges
    return n - totalFruits
}
```

func fruitDistribution(s: String, n: Int) -> Int {
    let components = s.components(separatedBy: " ")
    let apples = Int(components[0]) ?? 0
    let oranges = Int(components[3]) ?? 0
    return n - apples - oranges
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges 
that are distributed in a basket of fruit this basket contains 
apples, oranges, and mango fruits. Given the string that represents the total number of 
the oranges and apples and an integer that represent the total number of the fruits 
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19[/INST]  ```swift
func fruitDistribution(s: String, n: Int) -> Int {
    let components = s.components(separatedBy: " ")
    let apples = Int(components[0]) ?? 0
    let oranges = Int(components[3]) ?? 0
    return n - apples - oranges
}
```

func fruitDistribution(s: String, n: Int) -> Int {
    let components = s.components(separatedBy: " ")
    let apples = Int(components[0]) ?? 0
    let oranges = Int(components[3]) ?? 0
    let totalFruits = apples + oranges
    return n - totalFruits
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges 
that are distributed in a basket of fruit this basket contains 
apples, oranges, and mango fruits. Given the string that represents the total number of 
the oranges and apples and an integer that represent the total number of the fruits 
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19[/INST]  ```swift
func fruitDistribution(s: String, n: Int) -> Int {
    let components = s.components(separatedBy: " ")
    let apples = Int(components[0]) ?? 0
    let oranges = Int(components[3]) ?? 0
    let totalFruits = apples + oranges
    return n - totalFruits
}
```

func fruitDistribution(s: String, n: Int) -> Int {
    let components = s.components(separatedBy: " ")
    let apples = Int(components[0]) ?? 0
    let oranges = Int(components[3]) ?? 0
    let totalFruits = apples + oranges
    return n - totalFruits
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges 
that are distributed in a basket of fruit this basket contains 
apples, oranges, and mango fruits. Given the string that represents the total number of 
the oranges and apples and an integer that represent the total number of the fruits 
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19[/INST]  ```swift
func fruitDistribution(s: String, n: Int) -> Int {
    let components = s.components(separatedBy: " ")
    let apples = Int(components[0]) ?? 0
    let oranges = Int(components[3]) ?? 0
    let totalFruits = apples + oranges
    return n - totalFruits
}
```

func fruitDistribution(s: String, n: Int) -> Int {
    let components = s.components(separatedBy: " ")
    let apples = Int(components[0]) ?? 0
    let oranges = Int(components[3]) ?? 0
    let totalFruits = apples + oranges
    return n - totalFruits
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges 
that are distributed in a basket of fruit this basket contains 
apples, oranges, and mango fruits. Given the string that represents the total number of 
the oranges and apples and an integer that represent the total number of the fruits 
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19[/INST]  ```swift
func fruitDistribution(s: String, n: Int) -> Int {
    let components = s.components(separatedBy: " ")
    let apples = Int(components[0]) ?? 0
    let oranges = Int(components[3]) ?? 0
    let totalFruits = apples + oranges
    return n - totalFruits
}
```

func fruitDistribution(s: String, n: Int) -> Int {
    let components = s.components(separatedBy: " ")
    let apples = Int(components[0]) ?? 0
    let oranges = Int(components[3]) ?? 0
    let totalFruits = apples + oranges
    return n - totalFruits
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges 
that are distributed in a basket of fruit this basket contains 
apples, oranges, and mango fruits. Given the string that represents the total number of 
the oranges and apples and an integer that represent the total number of the fruits 
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19[/INST]  ```swift
func fruitDistribution(s: String, n: Int) -> Int {
    let components = s.components(separatedBy: " ")
    let apples = Int(components[0]) ?? 0
    let oranges = Int(components[3]) ?? 0
    let totalFruits = apples + oranges
    return n - totalFruits
}
```

func fruitDistribution(s: String, n: Int) -> Int {
    let components = s.components(separatedBy: " ")
    let apples = Int(components[0]) ?? 0
    let oranges = Int(components[3]) ?? 0
    return n - apples - oranges
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges 
that are distributed in a basket of fruit this basket contains 
apples, oranges, and mango fruits. Given the string that represents the total number of 
the oranges and apples and an integer that represent the total number of the fruits 
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19[/INST]  ```swift
func fruitDistribution(s: String, n: Int) -> Int {
    let components = s.components(separatedBy: " ")
    let apples = Int(components[0]) ?? 0
    let oranges = Int(components[3]) ?? 0
    return n - apples - oranges
}
```

func fruitDistribution(s: String, n: Int) -> Int {
    let components = s.components(separatedBy: " ")
    let apples = Int(components[0]) ?? 0
    let oranges = Int(components[3]) ?? 0
    return n - apples - oranges
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges 
that are distributed in a basket of fruit this basket contains 
apples, oranges, and mango fruits. Given the string that represents the total number of 
the oranges and apples and an integer that represent the total number of the fruits 
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19[/INST]  ```swift
func fruitDistribution(s: String, n: Int) -> Int {
    let components = s.components(separatedBy: " ")
    let apples = Int(components[0]) ?? 0
    let oranges = Int(components[3]) ?? 0
    return n - apples - oranges
}
```

func fruitDistribution(s: String, n: Int) -> Int {
    let components = s.components(separatedBy: " ")
    let apples = Int(components[0]) ?? 0
    let oranges = Int(components[3]) ?? 0
    let totalFruits = apples + oranges
    return n - totalFruits
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges 
that are distributed in a basket of fruit this basket contains 
apples, oranges, and mango fruits. Given the string that represents the total number of 
the oranges and apples and an integer that represent the total number of the fruits 
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19[/INST]  ```swift
func fruitDistribution(s: String, n: Int) -> Int {
    let components = s.components(separatedBy: " ")
    let apples = Int(components[0]) ?? 0
    let oranges = Int(components[3]) ?? 0
    let totalFruits = apples + oranges
    return n - totalFruits
}
```

func pluck(arr: [Int]) -> [Int] {
    var smallestEven = Int.max
    var smallestIndex = -1

    for (index, value) in arr.enumerated() {
        if value % 2 == 0 && value < smallestEven {
            smallestEven = value
            smallestIndex = index
        }
    }

    if smallestIndex != -1 {
        return [smallestEven, smallestIndex]
    } else {
        return []
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but  there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1][/INST]  ```swift
func pluck(arr: [Int]) -> [Int] {
    var smallestEven = Int.max
    var smallestIndex = -1

    for (index, value) in arr.enumerated() {
        if value % 2 == 0 && value < smallestEven {
            smallestEven = value
            smallestIndex = index
        }
    }

    if smallestIndex != -1 {
        return [smallestEven, smallestIndex]
    } else {
        return []
    }
}
```

func pluck(arr: [Int]) -> [Int] {
    var smallestEven = Int.max
    var smallestIndex = -1

    for (index, value) in arr.enumerated() {
        if value % 2 == 0 && value < smallestEven {
            smallestEven = value
            smallestIndex = index
        }
    }

    if smallestIndex != -1 {
        return [smallestEven, smallestIndex]
    } else {
        return []
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but  there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1][/INST]  ```swift
func pluck(arr: [Int]) -> [Int] {
    var smallestEven = Int.max
    var smallestIndex = -1

    for (index, value) in arr.enumerated() {
        if value % 2 == 0 && value < smallestEven {
            smallestEven = value
            smallestIndex = index
        }
    }

    if smallestIndex != -1 {
        return [smallestEven, smallestIndex]
    } else {
        return []
    }
}
```

func pluck(arr: [Int]) -> [Int] {
    var smallestEven = Int.max
    var smallestIndex = -1

    for (index, value) in arr.enumerated() {
        if value % 2 == 0 && value < smallestEven {
            smallestEven = value
            smallestIndex = index
        }
    }

    if smallestIndex == -1 {
        return []
    } else {
        return [smallestEven, smallestIndex]
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but  there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1][/INST]  ```swift
func pluck(arr: [Int]) -> [Int] {
    var smallestEven = Int.max
    var smallestIndex = -1

    for (index, value) in arr.enumerated() {
        if value % 2 == 0 && value < smallestEven {
            smallestEven = value
            smallestIndex = index
        }
    }

    if smallestIndex == -1 {
        return []
    } else {
        return [smallestEven, smallestIndex]
    }
}
```

func pluck(arr: [Int]) -> [Int] {
    var smallestEven = Int.max
    var smallestIndex = -1

    for (index, value) in arr.enumerated() {
        if value % 2 == 0 && value < smallestEven {
            smallestEven = value
            smallestIndex = index
        }
    }

    if smallestIndex == -1 {
        return []
    } else {
        return [smallestEven, smallestIndex]
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but  there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1][/INST]  ```swift
func pluck(arr: [Int]) -> [Int] {
    var smallestEven = Int.max
    var smallestIndex = -1

    for (index, value) in arr.enumerated() {
        if value % 2 == 0 && value < smallestEven {
            smallestEven = value
            smallestIndex = index
        }
    }

    if smallestIndex == -1 {
        return []
    } else {
        return [smallestEven, smallestIndex]
    }
}
```

func pluck(arr: [Int]) -> [Int] {
    var smallestEven = Int.max
    var smallestIndex = -1

    for (index, value) in arr.enumerated() {
        if value % 2 == 0 && value < smallestEven {
            smallestEven = value
            smallestIndex = index
        }
    }

    if smallestIndex == -1 {
        return []
    } else {
        return [smallestEven, smallestIndex]
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but  there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1][/INST]  ```swift
func pluck(arr: [Int]) -> [Int] {
    var smallestEven = Int.max
    var smallestIndex = -1

    for (index, value) in arr.enumerated() {
        if value % 2 == 0 && value < smallestEven {
            smallestEven = value
            smallestIndex = index
        }
    }

    if smallestIndex == -1 {
        return []
    } else {
        return [smallestEven, smallestIndex]
    }
}
```

func pluck(arr: [Int]) -> [Int] {
    var smallestEven = Int.max
    var smallestIndex = -1

    for (index, value) in arr.enumerated() {
        if value % 2 == 0 && value < smallestEven {
            smallestEven = value
            smallestIndex = index
        }
    }

    if smallestIndex == -1 {
        return []
    } else {
        return [smallestEven, smallestIndex]
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but  there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1][/INST]  ```swift
func pluck(arr: [Int]) -> [Int] {
    var smallestEven = Int.max
    var smallestIndex = -1

    for (index, value) in arr.enumerated() {
        if value % 2 == 0 && value < smallestEven {
            smallestEven = value
            smallestIndex = index
        }
    }

    if smallestIndex == -1 {
        return []
    } else {
        return [smallestEven, smallestIndex]
    }
}
```

func pluck(arr: [Int]) -> [Int] {
    var smallestEven = Int.max
    var smallestIndex = -1

    for (index, value) in arr.enumerated() {
        if value % 2 == 0 && value < smallestEven {
            smallestEven = value
            smallestIndex = index
        }
    }

    if smallestIndex == -1 {
        return []
    } else {
        return [smallestEven, smallestIndex]
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but  there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1][/INST]  ```swift
func pluck(arr: [Int]) -> [Int] {
    var smallestEven = Int.max
    var smallestIndex = -1

    for (index, value) in arr.enumerated() {
        if value % 2 == 0 && value < smallestEven {
            smallestEven = value
            smallestIndex = index
        }
    }

    if smallestIndex == -1 {
        return []
    } else {
        return [smallestEven, smallestIndex]
    }
}
```

func pluck(arr: [Int]) -> [Int] {
    var smallestEven = Int.max
    var smallestIndex = -1

    for (index, value) in arr.enumerated() {
        if value % 2 == 0 && value < smallestEven {
            smallestEven = value
            smallestIndex = index
        }
    }

    if smallestIndex == -1 {
        return []
    } else {
        return [smallestEven, smallestIndex]
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but  there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1][/INST]  ```swift
func pluck(arr: [Int]) -> [Int] {
    var smallestEven = Int.max
    var smallestIndex = -1

    for (index, value) in arr.enumerated() {
        if value % 2 == 0 && value < smallestEven {
            smallestEven = value
            smallestIndex = index
        }
    }

    if smallestIndex == -1 {
        return []
    } else {
        return [smallestEven, smallestIndex]
    }
}
```

func pluck(arr: [Int]) -> [Int] {
    var smallestEven = Int.max
    var smallestIndex = -1

    for (index, value) in arr.enumerated() {
        if value % 2 == 0 && value < smallestEven {
            smallestEven = value
            smallestIndex = index
        }
    }

    if smallestIndex != -1 {
        return [smallestEven, smallestIndex]
    } else {
        return []
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but  there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1][/INST]  ```swift
func pluck(arr: [Int]) -> [Int] {
    var smallestEven = Int.max
    var smallestIndex = -1

    for (index, value) in arr.enumerated() {
        if value % 2 == 0 && value < smallestEven {
            smallestEven = value
            smallestIndex = index
        }
    }

    if smallestIndex != -1 {
        return [smallestEven, smallestIndex]
    } else {
        return []
    }
}
```

func pluck(arr: [Int]) -> [Int] {
    var smallestEven = Int.max
    var smallestIndex = -1

    for (index, value) in arr.enumerated() {
        if value % 2 == 0 && value < smallestEven {
            smallestEven = value
            smallestIndex = index
        }
    }

    if smallestIndex == -1 {
        return []
    } else {
        return [smallestEven, smallestIndex]
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but  there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1][/INST]  ```swift
func pluck(arr: [Int]) -> [Int] {
    var smallestEven = Int.max
    var smallestIndex = -1

    for (index, value) in arr.enumerated() {
        if value % 2 == 0 && value < smallestEven {
            smallestEven = value
            smallestIndex = index
        }
    }

    if smallestIndex == -1 {
        return []
    } else {
        return [smallestEven, smallestIndex]
    }
}
```

func search(lst: [Int]) -> Int {
    var frequency = [Int: Int]()

    for num in lst {
        frequency[num, default: 0] += 1
    }

    for num in stride(from: lst.max()!, through: 1, by: -1) {
        if frequency[num] ?? 0 >= num {
            return num
        }
    }

    return -1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than 
zero, and has a frequency greater than or equal to the value of the integer itself. 
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1[/INST]  ```swift
func search(lst: [Int]) -> Int {
    var frequency = [Int: Int]()

    for num in lst {
        frequency[num, default: 0] += 1
    }

    for num in stride(from: lst.max()!, through: 1, by: -1) {
        if frequency[num] ?? 0 >= num {
            return num
        }
    }

    return -1
}
```

func search(lst: [Int]) -> Int {
    var frequency = [Int: Int]()

    for num in lst {
        frequency[num, default: 0] += 1
    }

    for num in stride(from: lst.max()!, through: 1, by: -1) {
        if let count = frequency[num], count >= num {
            return num
        }
    }

    return -1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than 
zero, and has a frequency greater than or equal to the value of the integer itself. 
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1[/INST]  ```swift
func search(lst: [Int]) -> Int {
    var frequency = [Int: Int]()

    for num in lst {
        frequency[num, default: 0] += 1
    }

    for num in stride(from: lst.max()!, through: 1, by: -1) {
        if let count = frequency[num], count >= num {
            return num
        }
    }

    return -1
}
```

func search(lst: [Int]) -> Int {
    var countDict = [Int: Int]()

    for num in lst {
        countDict[num, default: 0] += 1
    }

    for num in lst.sorted(by: >) where countDict[num]! >= num {
        return num
    }

    return -1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than 
zero, and has a frequency greater than or equal to the value of the integer itself. 
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1[/INST]  ```swift
func search(lst: [Int]) -> Int {
    var countDict = [Int: Int]()

    for num in lst {
        countDict[num, default: 0] += 1
    }

    for num in lst.sorted(by: >) where countDict[num]! >= num {
        return num
    }

    return -1
}
```

func search(lst: [Int]) -> Int {
    var count = Array(repeating: 0, count: 1001)
    for num in lst {
        count[num] += 1
    }
    for i in stride(from: 1000, through: 1, by: -1) {
        if count[i] >= i {
            return i
        }
    }
    return -1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than 
zero, and has a frequency greater than or equal to the value of the integer itself. 
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1[/INST]  ```swift
func search(lst: [Int]) -> Int {
    var count = Array(repeating: 0, count: 1001)
    for num in lst {
        count[num] += 1
    }
    for i in stride(from: 1000, through: 1, by: -1) {
        if count[i] >= i {
            return i
        }
    }
    return -1
}
```

func search(lst: [Int]) -> Int {
    var frequency = [Int: Int]()
    for num in lst {
        frequency[num, default: 0] += 1
    }
    for num in stride(from: lst.max()!, through: 1, by: -1) {
        if frequency[num] != nil && frequency[num]! >= num {
            return num
        }
    }
    return -1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than 
zero, and has a frequency greater than or equal to the value of the integer itself. 
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1[/INST]  ```swift
func search(lst: [Int]) -> Int {
    var frequency = [Int: Int]()
    for num in lst {
        frequency[num, default: 0] += 1
    }
    for num in stride(from: lst.max()!, through: 1, by: -1) {
        if frequency[num] != nil && frequency[num]! >= num {
            return num
        }
    }
    return -1
}
```

func search(lst: [Int]) -> Int {
    var frequency = [Int: Int]()
    for num in lst {
        frequency[num, default: 0] += 1
    }
    for num in stride(from: lst.max()!, through: 1, by: -1) {
        if frequency[num] ?? 0 >= num {
            return num
        }
    }
    return -1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than 
zero, and has a frequency greater than or equal to the value of the integer itself. 
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1[/INST]  ```swift
func search(lst: [Int]) -> Int {
    var frequency = [Int: Int]()
    for num in lst {
        frequency[num, default: 0] += 1
    }
    for num in stride(from: lst.max()!, through: 1, by: -1) {
        if frequency[num] ?? 0 >= num {
            return num
        }
    }
    return -1
}
```

func search(lst: [Int]) -> Int {
    var frequency = [Int: Int]()
    for num in lst {
        frequency[num, default: 0] += 1
    }
    for num in stride(from: lst.max()!, through: 1, by: -1) {
        if frequency[num] ?? 0 >= num {
            return num
        }
    }
    return -1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than 
zero, and has a frequency greater than or equal to the value of the integer itself. 
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1[/INST]  ```swift
func search(lst: [Int]) -> Int {
    var frequency = [Int: Int]()
    for num in lst {
        frequency[num, default: 0] += 1
    }
    for num in stride(from: lst.max()!, through: 1, by: -1) {
        if frequency[num] ?? 0 >= num {
            return num
        }
    }
    return -1
}
```

func search(lst: [Int]) -> Int {
    var count = [Int: Int]()
    for num in lst {
        count[num, default: 0] += 1
    }
    for num in lst.sorted(by: >) where count[num]! >= num {
        return num
    }
    return -1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than 
zero, and has a frequency greater than or equal to the value of the integer itself. 
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1[/INST]  ```swift
func search(lst: [Int]) -> Int {
    var count = [Int: Int]()
    for num in lst {
        count[num, default: 0] += 1
    }
    for num in lst.sorted(by: >) where count[num]! >= num {
        return num
    }
    return -1
}
```

func search(lst: [Int]) -> Int {
    var frequency = [Int: Int]()

    for num in lst {
        frequency[num, default: 0] += 1
    }

    for num in lst.sorted(by: >) {
        if frequency[num]! >= num {
            return num
        }
    }

    return -1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than 
zero, and has a frequency greater than or equal to the value of the integer itself. 
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1[/INST]  ```swift
func search(lst: [Int]) -> Int {
    var frequency = [Int: Int]()

    for num in lst {
        frequency[num, default: 0] += 1
    }

    for num in lst.sorted(by: >) {
        if frequency[num]! >= num {
            return num
        }
    }

    return -1
}
```

func search(lst: [Int]) -> Int {
    var frequency = [Int: Int]()
    for num in lst {
        frequency[num, default: 0] += 1
    }
    for num in stride(from: lst.max()!, through: 1, by: -1) {
        if frequency[num] != nil && frequency[num]! >= num {
            return num
        }
    }
    return -1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than 
zero, and has a frequency greater than or equal to the value of the integer itself. 
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1[/INST]  ```swift
func search(lst: [Int]) -> Int {
    var frequency = [Int: Int]()
    for num in lst {
        frequency[num, default: 0] += 1
    }
    for num in stride(from: lst.max()!, through: 1, by: -1) {
        if frequency[num] != nil && frequency[num]! >= num {
            return num
        }
    }
    return -1
}
```

func strangeSortList(lst: [Int]) -> [Int] {
    guard !lst.isEmpty else {
        return []
    }

    var sortedList = lst.sorted()
    var result: [Int] = []

    while !sortedList.isEmpty {
        result.append(sortedList.removeFirst())

        if !sortedList.isEmpty {
            result.append(sortedList.removeLast())
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int][/INST]  ```swift
func strangeSortList(lst: [Int]) -> [Int] {
    guard !lst.isEmpty else {
        return []
    }

    var sortedList = lst.sorted()
    var result: [Int] = []

    while !sortedList.isEmpty {
        result.append(sortedList.removeFirst())

        if !sortedList.isEmpty {
            result.append(sortedList.removeLast())
        }
    }

    return result
}
```

func strangeSortList(lst: [Int]) -> [Int] {
    var sortedList = lst.sorted()
    var resultList = [Int]()
    var left = 0
    var right = sortedList.count - 1

    while left <= right {
        resultList.append(sortedList[left])
        if left < right {
            resultList.append(sortedList[right])
        }
        left += 1
        right -= 1
    }

    return resultList
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int][/INST]  ```swift
func strangeSortList(lst: [Int]) -> [Int] {
    var sortedList = lst.sorted()
    var resultList = [Int]()
    var left = 0
    var right = sortedList.count - 1

    while left <= right {
        resultList.append(sortedList[left])
        if left < right {
            resultList.append(sortedList[right])
        }
        left += 1
        right -= 1
    }

    return resultList
}
```
var sortedList = lst.sorted() // variable 'sortedList' was never mutated; consider changing to 'let' constant

func strangeSortList(lst: [Int]) -> [Int] {
    var sortedList = lst.sorted()
    var result: [Int] = []
    var left = 0
    var right = sortedList.count - 1

    while left <= right {
        result.append(sortedList[left])
        if left < right {
            result.append(sortedList[right])
        }
        left += 1
        right -= 1
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int][/INST]  ```swift
func strangeSortList(lst: [Int]) -> [Int] {
    var sortedList = lst.sorted()
    var result: [Int] = []
    var left = 0
    var right = sortedList.count - 1

    while left <= right {
        result.append(sortedList[left])
        if left < right {
            result.append(sortedList[right])
        }
        left += 1
        right -= 1
    }

    return result
}
```
var sortedList = lst.sorted() // variable 'sortedList' was never mutated; consider changing to 'let' constant

func strangeSortList(lst: [Int]) -> [Int] {
    guard !lst.isEmpty else {
        return []
    }

    var sortedList = lst.sorted()
    var result: [Int] = []

    while !sortedList.isEmpty {
        result.append(sortedList.removeFirst())

        if !sortedList.isEmpty {
            result.append(sortedList.removeLast())
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int][/INST]  ```swift
func strangeSortList(lst: [Int]) -> [Int] {
    guard !lst.isEmpty else {
        return []
    }

    var sortedList = lst.sorted()
    var result: [Int] = []

    while !sortedList.isEmpty {
        result.append(sortedList.removeFirst())

        if !sortedList.isEmpty {
            result.append(sortedList.removeLast())
        }
    }

    return result
}
```

func strangeSortList(lst: [Int]) -> [Int] {
    var sortedList = lst.sorted()
    var resultList = [Int]()
    var left = 0
    var right = sortedList.count - 1

    while left <= right {
        resultList.append(sortedList[left])
        if left < right {
            resultList.append(sortedList[right])
        }
        left += 1
        right -= 1
    }

    return resultList
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int][/INST]  ```swift
func strangeSortList(lst: [Int]) -> [Int] {
    var sortedList = lst.sorted()
    var resultList = [Int]()
    var left = 0
    var right = sortedList.count - 1

    while left <= right {
        resultList.append(sortedList[left])
        if left < right {
            resultList.append(sortedList[right])
        }
        left += 1
        right -= 1
    }

    return resultList
}
```
var sortedList = lst.sorted() // variable 'sortedList' was never mutated; consider changing to 'let' constant

func strangeSortList(lst: [Int]) -> [Int] {
    var sortedList = lst.sorted()
    var resultList = [Int]()
    var left = 0
    var right = sortedList.count - 1

    while left <= right {
        if left == right {
            resultList.append(sortedList[left])
            break
        }

        resultList.append(sortedList[left])
        resultList.append(sortedList[right])

        left += 1
        right -= 1
    }

    return resultList
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int][/INST]  ```swift
func strangeSortList(lst: [Int]) -> [Int] {
    var sortedList = lst.sorted()
    var resultList = [Int]()
    var left = 0
    var right = sortedList.count - 1

    while left <= right {
        if left == right {
            resultList.append(sortedList[left])
            break
        }

        resultList.append(sortedList[left])
        resultList.append(sortedList[right])

        left += 1
        right -= 1
    }

    return resultList
}
```
var sortedList = lst.sorted() // variable 'sortedList' was never mutated; consider changing to 'let' constant

func strangeSortList(lst: [Int]) -> [Int] {
    guard !lst.isEmpty else { return [] }
    var sortedList = lst.sorted()
    var result = [Int]()
    var left = 0
    var right = sortedList.count - 1
    while left <= right {
        result.append(sortedList[left])
        if left < right {
            result.append(sortedList[right])
        }
        left += 1
        right -= 1
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int][/INST]  ```swift
func strangeSortList(lst: [Int]) -> [Int] {
    guard !lst.isEmpty else { return [] }
    var sortedList = lst.sorted()
    var result = [Int]()
    var left = 0
    var right = sortedList.count - 1
    while left <= right {
        result.append(sortedList[left])
        if left < right {
            result.append(sortedList[right])
        }
        left += 1
        right -= 1
    }
    return result
}
```
var sortedList = lst.sorted() // variable 'sortedList' was never mutated; consider changing to 'let' constant

func strangeSortList(lst: [Int]) -> [Int] {
    guard !lst.isEmpty else { return [] }
    var sortedList = lst.sorted()
    var result: [Int] = []
    var left = 0
    var right = sortedList.count - 1
    while left <= right {
        result.append(sortedList[left])
        if left < right {
            result.append(sortedList[right])
        }
        left += 1
        right -= 1
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int][/INST]  ```swift
func strangeSortList(lst: [Int]) -> [Int] {
    guard !lst.isEmpty else { return [] }
    var sortedList = lst.sorted()
    var result: [Int] = []
    var left = 0
    var right = sortedList.count - 1
    while left <= right {
        result.append(sortedList[left])
        if left < right {
            result.append(sortedList[right])
        }
        left += 1
        right -= 1
    }
    return result
}
```
var sortedList = lst.sorted() // variable 'sortedList' was never mutated; consider changing to 'let' constant

func strangeSortList(lst: [Int]) -> [Int] {
    guard !lst.isEmpty else { return [] }
    let sortedList = lst.sorted()
    var result: [Int] = []
    var left = 0
    var right = sortedList.count - 1
    while left <= right {
        result.append(sortedList[left])
        if left < right {
            result.append(sortedList[right])
        }
        left += 1
        right -= 1
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int][/INST]  ```swift
func strangeSortList(lst: [Int]) -> [Int] {
    guard !lst.isEmpty else { return [] }
    let sortedList = lst.sorted()
    var result: [Int] = []
    var left = 0
    var right = sortedList.count - 1
    while left <= right {
        result.append(sortedList[left])
        if left < right {
            result.append(sortedList[right])
        }
        left += 1
        right -= 1
    }
    return result
}
```

func strangeSortList(lst: [Int]) -> [Int] {
    var sortedArray = lst.sorted()
    var resultArray = [Int]()
    var left = 0
    var right = sortedArray.count - 1

    while left <= right {
        if left == right {
            resultArray.append(sortedArray[left])
            break
        }
        resultArray.append(sortedArray[left])
        resultArray.append(sortedArray[right])
        left += 1
        right -= 1
    }
    return resultArray
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int][/INST]  ```swift
func strangeSortList(lst: [Int]) -> [Int] {
    var sortedArray = lst.sorted()
    var resultArray = [Int]()
    var left = 0
    var right = sortedArray.count - 1

    while left <= right {
        if left == right {
            resultArray.append(sortedArray[left])
            break
        }
        resultArray.append(sortedArray[left])
        resultArray.append(sortedArray[right])
        left += 1
        right -= 1
    }
    return resultArray
}
```
var sortedArray = lst.sorted() // variable 'sortedArray' was never mutated; consider changing to 'let' constant

func triangleArea(a: Int, b: Int, c: Int) -> Double {
    if a + b > c && a + c > b && b + c > a {
        let s = Double(a + b + c) / 2.0
        let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
        return round(area * 100) / 100
    } else {
        return -1
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle. 
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater 
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1[/INST]  ```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
    if a + b > c && a + c > b && b + c > a {
        let s = Double(a + b + c) / 2.0
        let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
        return round(area * 100) / 100
    } else {
        return -1
    }
}
```

func triangleArea(a: Int, b: Int, c: Int) -> Double {
    if a + b > c && a + c > b && b + c > a {
        let s = Double(a + b + c) / 2.0
        let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
        return Double(round(area * 100) / 100)
    } else {
        return -1
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle. 
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater 
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1[/INST]  ```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
    if a + b > c && a + c > b && b + c > a {
        let s = Double(a + b + c) / 2.0
        let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
        return Double(round(area * 100) / 100)
    } else {
        return -1
    }
}
```

func triangleArea(a: Int, b: Int, c: Int) -> Double {
    if a + b > c && a + c > b && b + c > a {
        let s = Double(a + b + c) / 2.0
        let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
        return Double(round(area * 100) / 100)
    } else {
        return -1
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle. 
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater 
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1[/INST]  ```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
    if a + b > c && a + c > b && b + c > a {
        let s = Double(a + b + c) / 2.0
        let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
        return Double(round(area * 100) / 100)
    } else {
        return -1
    }
}
```

func triangleArea(a: Int, b: Int, c: Int) -> Double {
    if a + b > c && a + c > b && b + c > a {
        let s = Double(a + b + c) / 2.0
        let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
        return Double(round(area * 100) / 100)
    } else {
        return -1
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle. 
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater 
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1[/INST]  ```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
    if a + b > c && a + c > b && b + c > a {
        let s = Double(a + b + c) / 2.0
        let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
        return Double(round(area * 100) / 100)
    } else {
        return -1
    }
}
```

func triangleArea(a: Int, b: Int, c: Int) -> Double {
    if a + b > c && a + c > b && b + c > a {
        let s = Double(a + b + c) / 2.0
        let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
        return Double(round(area * 100) / 100)
    } else {
        return -1
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle. 
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater 
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1[/INST]  ```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
    if a + b > c && a + c > b && b + c > a {
        let s = Double(a + b + c) / 2.0
        let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
        return Double(round(area * 100) / 100)
    } else {
        return -1
    }
}
```

func triangleArea(a: Int, b: Int, c: Int) -> Double {
    if a + b > c && a + c > b && b + c > a {
        let s = Double(a + b + c) / 2
        let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
        return Double(round(100 * area) / 100)
    } else {
        return -1
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle. 
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater 
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1[/INST]  ```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
    if a + b > c && a + c > b && b + c > a {
        let s = Double(a + b + c) / 2
        let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
        return Double(round(100 * area) / 100)
    } else {
        return -1
    }
}
```

func triangleArea(a: Int, b: Int, c: Int) -> Double {
    if a + b > c && a + c > b && b + c > a {
        let s = Double(a + b + c) / 2.0
        let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
        return Double(round(area * 100) / 100)
    } else {
        return -1
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle. 
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater 
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1[/INST]  ```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
    if a + b > c && a + c > b && b + c > a {
        let s = Double(a + b + c) / 2.0
        let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
        return Double(round(area * 100) / 100)
    } else {
        return -1
    }
}
```

func triangleArea(a: Int, b: Int, c: Int) -> Double {
    if a + b > c && a + c > b && b + c > a {
        let s = Double(a + b + c) / 2.0
        let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
        return Double(round(area * 100) / 100)
    } else {
        return -1
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle. 
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater 
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1[/INST]  ```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
    if a + b > c && a + c > b && b + c > a {
        let s = Double(a + b + c) / 2.0
        let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
        return Double(round(area * 100) / 100)
    } else {
        return -1
    }
}
```

func triangleArea(a: Int, b: Int, c: Int) -> Double {
    if a + b > c && a + c > b && b + c > a {
        let s = Double(a + b + c) / 2.0
        let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
        return Double(round(area * 100) / 100)
    } else {
        return -1
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle. 
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater 
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1[/INST]  ```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
    if a + b > c && a + c > b && b + c > a {
        let s = Double(a + b + c) / 2.0
        let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
        return Double(round(area * 100) / 100)
    } else {
        return -1
    }
}
```

func triangleArea(a: Int, b: Int, c: Int) -> Double {
    if a + b > c && a + c > b && b + c > a {
        let s = Double(a + b + c) / 2.0
        let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
        return Double(round(100 * area) / 100)
    } else {
        return -1
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle. 
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater 
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1[/INST]  ```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
    if a + b > c && a + c > b && b + c > a {
        let s = Double(a + b + c) / 2.0
        let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
        return Double(round(100 * area) / 100)
    } else {
        return -1
    }
}
```

func willItFly(q: [Int], w: Int) -> Bool {
    func isPalindrome(_ arr: [Int]) -> Bool {
        return arr == arr.reversed()
    }

    let sum = q.reduce(0, +)
    return sum <= w && isPalindrome(q)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true[/INST]  ```swift
func willItFly(q: [Int], w: Int) -> Bool {
    func isPalindrome(_ arr: [Int]) -> Bool {
        return arr == arr.reversed()
    }

    let sum = q.reduce(0, +)
    return sum <= w && isPalindrome(q)
}
```

func willItFly(q: [Int], w: Int) -> Bool {
    func isPalindromic(arr: [Int]) -> Bool {
        return arr == arr.reversed()
    }

    let sum = q.reduce(0, +)
    return isPalindromic(arr: q) && sum <= w
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true[/INST]  ```swift
func willItFly(q: [Int], w: Int) -> Bool {
    func isPalindromic(arr: [Int]) -> Bool {
        return arr == arr.reversed()
    }

    let sum = q.reduce(0, +)
    return isPalindromic(arr: q) && sum <= w
}
```

func willItFly(q: [Int], w: Int) -> Bool {
    func isPalindrome(_ arr: [Int]) -> Bool {
        return arr == arr.reversed()
    }

    let sum = q.reduce(0, +)
    return isPalindrome(q) && sum <= w
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true[/INST]  ```swift
func willItFly(q: [Int], w: Int) -> Bool {
    func isPalindrome(_ arr: [Int]) -> Bool {
        return arr == arr.reversed()
    }

    let sum = q.reduce(0, +)
    return isPalindrome(q) && sum <= w
}
```

func willItFly(q: [Int], w: Int) -> Bool {
    // Check if the array is balanced (palindromic)
    let isBalanced = q == q.reversed()

    // Calculate the sum of the elements in the array
    let sum = q.reduce(0, +)

    // Check if the sum is less than or equal to the maximum possible weight
    let isLightEnough = sum <= w

    // Return true if the object is balanced and light enough, false otherwise
    return isBalanced && isLightEnough
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true[/INST]  ```swift
func willItFly(q: [Int], w: Int) -> Bool {
    // Check if the array is balanced (palindromic)
    let isBalanced = q == q.reversed()

    // Calculate the sum of the elements in the array
    let sum = q.reduce(0, +)

    // Check if the sum is less than or equal to the maximum possible weight
    let isLightEnough = sum <= w

    // Return true if the object is balanced and light enough, false otherwise
    return isBalanced && isLightEnough
}
```

func willItFly(q: [Int], w: Int) -> Bool {
    func isPalindromic(_ arr: [Int]) -> Bool {
        return arr == arr.reversed()
    }

    let sum = q.reduce(0, +)
    return isPalindromic(q) && sum <= w
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true[/INST]  ```swift
func willItFly(q: [Int], w: Int) -> Bool {
    func isPalindromic(_ arr: [Int]) -> Bool {
        return arr == arr.reversed()
    }

    let sum = q.reduce(0, +)
    return isPalindromic(q) && sum <= w
}
```

func willItFly(q: [Int], w: Int) -> Bool {
    // Check if the array is balanced (palindromic)
    let isBalanced = q == q.reversed()

    // Calculate the sum of the elements in the array
    let sum = q.reduce(0, +)

    // Check if the sum is less than or equal to the maximum possible weight
    let isLightEnough = sum <= w

    // Return true if the object is balanced and light enough, false otherwise
    return isBalanced && isLightEnough
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true[/INST]  ```swift
func willItFly(q: [Int], w: Int) -> Bool {
    // Check if the array is balanced (palindromic)
    let isBalanced = q == q.reversed()

    // Calculate the sum of the elements in the array
    let sum = q.reduce(0, +)

    // Check if the sum is less than or equal to the maximum possible weight
    let isLightEnough = sum <= w

    // Return true if the object is balanced and light enough, false otherwise
    return isBalanced && isLightEnough
}
```

func willItFly(q: [Int], w: Int) -> Bool {
    // Check if the array is balanced (palindromic)
    let isBalanced = q == q.reversed()

    // Calculate the sum of the elements in the array
    let sum = q.reduce(0, +)

    // Check if the sum is less than or equal to the maximum possible weight
    let isLightEnough = sum <= w

    // Return true if the object is balanced and light enough, false otherwise
    return isBalanced && isLightEnough
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true[/INST]  ```swift
func willItFly(q: [Int], w: Int) -> Bool {
    // Check if the array is balanced (palindromic)
    let isBalanced = q == q.reversed()

    // Calculate the sum of the elements in the array
    let sum = q.reduce(0, +)

    // Check if the sum is less than or equal to the maximum possible weight
    let isLightEnough = sum <= w

    // Return true if the object is balanced and light enough, false otherwise
    return isBalanced && isLightEnough
}
```

func willItFly(q: [Int], w: Int) -> Bool {
    func isPalindrome(_ arr: [Int]) -> Bool {
        return arr == arr.reversed()
    }

    let sum = q.reduce(0, +)
    return isPalindrome(q) && sum <= w
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true[/INST]  ```swift
func willItFly(q: [Int], w: Int) -> Bool {
    func isPalindrome(_ arr: [Int]) -> Bool {
        return arr == arr.reversed()
    }

    let sum = q.reduce(0, +)
    return isPalindrome(q) && sum <= w
}
```

func willItFly(q: [Int], w: Int) -> Bool {
    let sum = q.reduce(0, +)
    let isBalanced = q == q.reversed()
    return sum <= w && isBalanced
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true[/INST]  ```swift
func willItFly(q: [Int], w: Int) -> Bool {
    let sum = q.reduce(0, +)
    let isBalanced = q == q.reversed()
    return sum <= w && isBalanced
}
```

func willItFly(q: [Int], w: Int) -> Bool {
    func isPalindromic(arr: [Int]) -> Bool {
        return arr == arr.reversed()
    }

    let sum = q.reduce(0, +)
    return isPalindromic(arr: q) && sum <= w
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true[/INST]  ```swift
func willItFly(q: [Int], w: Int) -> Bool {
    func isPalindromic(arr: [Int]) -> Bool {
        return arr == arr.reversed()
    }

    let sum = q.reduce(0, +)
    return isPalindromic(arr: q) && sum <= w
}
```

func smallestChange(arr: [Int]) -> Int {
    var changes = 0
    var left = 0
    var right = arr.count - 1

    while left < right {
        if arr[left] != arr[right] {
            changes += 1
        }
        left += 1
        right -= 1
    }

    return changes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0[/INST]  ```swift
func smallestChange(arr: [Int]) -> Int {
    var changes = 0
    var left = 0
    var right = arr.count - 1

    while left < right {
        if arr[left] != arr[right] {
            changes += 1
        }
        left += 1
        right -= 1
    }

    return changes
}
```

func smallestChange(arr: [Int]) -> Int {
    var changes = 0
    var left = 0
    var right = arr.count - 1

    while left < right {
        if arr[left] != arr[right] {
            changes += 1
        }
        left += 1
        right -= 1
    }

    return changes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0[/INST]  ```swift
func smallestChange(arr: [Int]) -> Int {
    var changes = 0
    var left = 0
    var right = arr.count - 1

    while left < right {
        if arr[left] != arr[right] {
            changes += 1
        }
        left += 1
        right -= 1
    }

    return changes
}
```

func smallestChange(arr: [Int]) -> Int {
    var changes = 0
    var left = 0
    var right = arr.count - 1

    while left < right {
        if arr[left] != arr[right] {
            changes += 1
        }
        left += 1
        right -= 1
    }

    return changes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0[/INST]  ```swift
func smallestChange(arr: [Int]) -> Int {
    var changes = 0
    var left = 0
    var right = arr.count - 1

    while left < right {
        if arr[left] != arr[right] {
            changes += 1
        }
        left += 1
        right -= 1
    }

    return changes
}
```

func smallestChange(arr: [Int]) -> Int {
    var changes = 0
    var left = 0
    var right = arr.count - 1

    while left < right {
        if arr[left] != arr[right] {
            changes += 1
        }
        left += 1
        right -= 1
    }

    return changes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0[/INST]  ```swift
func smallestChange(arr: [Int]) -> Int {
    var changes = 0
    var left = 0
    var right = arr.count - 1

    while left < right {
        if arr[left] != arr[right] {
            changes += 1
        }
        left += 1
        right -= 1
    }

    return changes
}
```

func smallestChange(arr: [Int]) -> Int {
    var changes = 0
    var left = 0
    var right = arr.count - 1

    while left < right {
        if arr[left] != arr[right] {
            changes += 1
        }
        left += 1
        right -= 1
    }

    return changes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0[/INST]  ```swift
func smallestChange(arr: [Int]) -> Int {
    var changes = 0
    var left = 0
    var right = arr.count - 1

    while left < right {
        if arr[left] != arr[right] {
            changes += 1
        }
        left += 1
        right -= 1
    }

    return changes
}
```

func smallestChange(arr: [Int]) -> Int {
    var changes = 0
    var left = 0
    var right = arr.count - 1

    while left < right {
        if arr[left] != arr[right] {
            changes += 1
        }
        left += 1
        right -= 1
    }

    return changes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0[/INST]  ```swift
func smallestChange(arr: [Int]) -> Int {
    var changes = 0
    var left = 0
    var right = arr.count - 1

    while left < right {
        if arr[left] != arr[right] {
            changes += 1
        }
        left += 1
        right -= 1
    }

    return changes
}
```

func smallestChange(arr: [Int]) -> Int {
    var changes = 0
    var left = 0
    var right = arr.count - 1

    while left < right {
        if arr[left] != arr[right] {
            changes += 1
        }
        left += 1
        right -= 1
    }

    return changes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0[/INST]  ```swift
func smallestChange(arr: [Int]) -> Int {
    var changes = 0
    var left = 0
    var right = arr.count - 1

    while left < right {
        if arr[left] != arr[right] {
            changes += 1
        }
        left += 1
        right -= 1
    }

    return changes
}
```

func smallestChange(arr: [Int]) -> Int {
    var changes = 0
    var left = 0
    var right = arr.count - 1

    while left < right {
        if arr[left] != arr[right] {
            changes += 1
        }
        left += 1
        right -= 1
    }

    return changes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0[/INST]  ```swift
func smallestChange(arr: [Int]) -> Int {
    var changes = 0
    var left = 0
    var right = arr.count - 1

    while left < right {
        if arr[left] != arr[right] {
            changes += 1
        }
        left += 1
        right -= 1
    }

    return changes
}
```

func smallestChange(arr: [Int]) -> Int {
    var changes = 0
    var left = 0
    var right = arr.count - 1

    while left < right {
        if arr[left] != arr[right] {
            changes += 1
        }
        left += 1
        right -= 1
    }

    return changes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0[/INST]  ```swift
func smallestChange(arr: [Int]) -> Int {
    var changes = 0
    var left = 0
    var right = arr.count - 1

    while left < right {
        if arr[left] != arr[right] {
            changes += 1
        }
        left += 1
        right -= 1
    }

    return changes
}
```

func smallestChange(arr: [Int]) -> Int {
    var changes = 0
    var left = 0
    var right = arr.count - 1

    while left < right {
        if arr[left] != arr[right] {
            changes += 1
        }
        left += 1
        right -= 1
    }

    return changes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0[/INST]  ```swift
func smallestChange(arr: [Int]) -> Int {
    var changes = 0
    var left = 0
    var right = arr.count - 1

    while left < right {
        if arr[left] != arr[right] {
            changes += 1
        }
        left += 1
        right -= 1
    }

    return changes
}
```

func totalMatch(lst1: [String], lst2: [String]) -> [String] {
    let totalCharsLst1 = lst1.reduce(0, { $0 + $1.count })
    let totalCharsLst2 = lst2.reduce(0, { $0 + $1.count })

    if totalCharsLst1 <= totalCharsLst2 {
        return lst1
    } else {
        return lst2
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has 
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"][/INST]  ```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
    let totalCharsLst1 = lst1.reduce(0, { $0 + $1.count })
    let totalCharsLst2 = lst2.reduce(0, { $0 + $1.count })

    if totalCharsLst1 <= totalCharsLst2 {
        return lst1
    } else {
        return lst2
    }
}
```

func totalMatch(lst1: [String], lst2: [String]) -> [String] {
    let sum1 = lst1.reduce(0, { $0 + $1.count })
    let sum2 = lst2.reduce(0, { $0 + $1.count })
    return sum1 <= sum2 ? lst1 : lst2
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has 
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"][/INST]  ```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
    let sum1 = lst1.reduce(0, { $0 + $1.count })
    let sum2 = lst2.reduce(0, { $0 + $1.count })
    return sum1 <= sum2 ? lst1 : lst2
}
```

func totalMatch(lst1: [String], lst2: [String]) -> [String] {
    let totalCharsLst1 = lst1.reduce(0, { $0 + $1.count })
    let totalCharsLst2 = lst2.reduce(0, { $0 + $1.count })

    if totalCharsLst1 <= totalCharsLst2 {
        return lst1
    } else {
        return lst2
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has 
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"][/INST]  ```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
    let totalCharsLst1 = lst1.reduce(0, { $0 + $1.count })
    let totalCharsLst2 = lst2.reduce(0, { $0 + $1.count })

    if totalCharsLst1 <= totalCharsLst2 {
        return lst1
    } else {
        return lst2
    }
}
```

func totalMatch(lst1: [String], lst2: [String]) -> [String] {
    let sum1 = lst1.reduce(0, { $0 + $1.count })
    let sum2 = lst2.reduce(0, { $0 + $1.count })

    if sum1 <= sum2 {
        return lst1
    } else {
        return lst2
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has 
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"][/INST]  ```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
    let sum1 = lst1.reduce(0, { $0 + $1.count })
    let sum2 = lst2.reduce(0, { $0 + $1.count })

    if sum1 <= sum2 {
        return lst1
    } else {
        return lst2
    }
}
```

func totalMatch(lst1: [String], lst2: [String]) -> [String] {
    let sum1 = lst1.reduce(0, { $0 + $1.count })
    let sum2 = lst2.reduce(0, { $0 + $1.count })

    if sum1 <= sum2 {
        return lst1
    } else {
        return lst2
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has 
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"][/INST]  ```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
    let sum1 = lst1.reduce(0, { $0 + $1.count })
    let sum2 = lst2.reduce(0, { $0 + $1.count })

    if sum1 <= sum2 {
        return lst1
    } else {
        return lst2
    }
}
```

func totalMatch(lst1: [String], lst2: [String]) -> [String] {
    let lst1Chars = lst1.reduce(0, { $0 + $1.count })
    let lst2Chars = lst2.reduce(0, { $0 + $1.count })

    return lst1Chars < lst2Chars ? lst1 : lst2
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has 
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"][/INST]  ```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
    let lst1Chars = lst1.reduce(0, { $0 + $1.count })
    let lst2Chars = lst2.reduce(0, { $0 + $1.count })

    return lst1Chars < lst2Chars ? lst1 : lst2
}
```
 // XCTAssertTrue failed

func totalMatch(lst1: [String], lst2: [String]) -> [String] {
    let totalCharsLst1 = lst1.reduce(0, { $0 + $1.count })
    let totalCharsLst2 = lst2.reduce(0, { $0 + $1.count })

    if totalCharsLst1 <= totalCharsLst2 {
        return lst1
    } else {
        return lst2
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has 
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"][/INST]  ```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
    let totalCharsLst1 = lst1.reduce(0, { $0 + $1.count })
    let totalCharsLst2 = lst2.reduce(0, { $0 + $1.count })

    if totalCharsLst1 <= totalCharsLst2 {
        return lst1
    } else {
        return lst2
    }
}
```

func totalMatch(lst1: [String], lst2: [String]) -> [String] {
    let sum1 = lst1.reduce(0, { $0 + $1.count })
    let sum2 = lst2.reduce(0, { $0 + $1.count })

    if sum1 <= sum2 {
        return lst1
    } else {
        return lst2
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has 
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"][/INST]  ```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
    let sum1 = lst1.reduce(0, { $0 + $1.count })
    let sum2 = lst2.reduce(0, { $0 + $1.count })

    if sum1 <= sum2 {
        return lst1
    } else {
        return lst2
    }
}
```

func totalMatch(lst1: [String], lst2: [String]) -> [String] {
    let sum1 = lst1.reduce(0, { $0 + $1.count })
    let sum2 = lst2.reduce(0, { $0 + $1.count })

    if sum1 <= sum2 {
        return lst1
    } else {
        return lst2
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has 
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"][/INST]  ```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
    let sum1 = lst1.reduce(0, { $0 + $1.count })
    let sum2 = lst2.reduce(0, { $0 + $1.count })

    if sum1 <= sum2 {
        return lst1
    } else {
        return lst2
    }
}
```

func totalMatch(lst1: [String], lst2: [String]) -> [String] {
    let sum1 = lst1.reduce(0, { $0 + $1.count })
    let sum2 = lst2.reduce(0, { $0 + $1.count })

    if sum1 <= sum2 {
        return lst1
    } else {
        return lst2
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has 
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"][/INST]  ```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
    let sum1 = lst1.reduce(0, { $0 + $1.count })
    let sum2 = lst2.reduce(0, { $0 + $1.count })

    if sum1 <= sum2 {
        return lst1
    } else {
        return lst2
    }
}
```

func isMultiplyPrime(a: Int) -> Bool {
    var number = a
    var count = 0
    var i = 2

    while i * i <= number {
        if number % i == 0 {
            number = number / i
            count += 1
        } else {
            i += 1
        }
    }

    if number > 1 {
        count += 1
    }

    return count == 3
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100. 
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true[/INST]  ```swift
func isMultiplyPrime(a: Int) -> Bool {
    var number = a
    var count = 0
    var i = 2

    while i * i <= number {
        if number % i == 0 {
            number = number / i
            count += 1
        } else {
            i += 1
        }
    }

    if number > 1 {
        count += 1
    }

    return count == 3
}
```

func isMultiplyPrime(a: Int) -> Bool {
    var number = a
    var primeFactors = [Int]()

    for i in 2...number {
        while number % i == 0 {
            primeFactors.append(i)
            number /= i
        }
    }

    return primeFactors.count == 3
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100. 
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true[/INST]  ```swift
func isMultiplyPrime(a: Int) -> Bool {
    var number = a
    var primeFactors = [Int]()

    for i in 2...number {
        while number % i == 0 {
            primeFactors.append(i)
            number /= i
        }
    }

    return primeFactors.count == 3
}
```

func isMultiplyPrime(a: Int) -> Bool {
    var number = a
    var primeFactors = [Int]()

    for i in 2...number {
        while number % i == 0 {
            primeFactors.append(i)
            number /= i
        }
    }

    return primeFactors.count == 3 && Set(primeFactors).count == 3
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100. 
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true[/INST]  ```swift
func isMultiplyPrime(a: Int) -> Bool {
    var number = a
    var primeFactors = [Int]()

    for i in 2...number {
        while number % i == 0 {
            primeFactors.append(i)
            number /= i
        }
    }

    return primeFactors.count == 3 && Set(primeFactors).count == 3
}
```
 // XCTAssertTrue failed

func isMultiplyPrime(a: Int) -> Bool {
    var number = a
    var primeFactors = [Int]()

    for i in 2...number {
        while number % i == 0 {
            primeFactors.append(i)
            number /= i
        }
    }

    return primeFactors.count == 3
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100. 
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true[/INST]  ```swift
func isMultiplyPrime(a: Int) -> Bool {
    var number = a
    var primeFactors = [Int]()

    for i in 2...number {
        while number % i == 0 {
            primeFactors.append(i)
            number /= i
        }
    }

    return primeFactors.count == 3
}
```

func isMultiplyPrime(a: Int) -> Bool {
    var number = a
    var count = 0
    var i = 2

    while i * i <= number {
        if number % i == 0 {
            number = number / i
            count += 1
        } else {
            i += 1
        }
    }

    if number > 1 {
        count += 1
    }

    return count == 3
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100. 
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true[/INST]  ```swift
func isMultiplyPrime(a: Int) -> Bool {
    var number = a
    var count = 0
    var i = 2

    while i * i <= number {
        if number % i == 0 {
            number = number / i
            count += 1
        } else {
            i += 1
        }
    }

    if number > 1 {
        count += 1
    }

    return count == 3
}
```

func isMultiplyPrime(a: Int) -> Bool {
    var number = a
    var count = 0

    for i in 2...number {
        while number % i == 0 {
            number /= i
            count += 1
        }

        if count > 3 {
            return false
        }
    }

    return count == 3
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100. 
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true[/INST]  ```swift
func isMultiplyPrime(a: Int) -> Bool {
    var number = a
    var count = 0

    for i in 2...number {
        while number % i == 0 {
            number /= i
            count += 1
        }

        if count > 3 {
            return false
        }
    }

    return count == 3
}
```

func isMultiplyPrime(a: Int) -> Bool {
    var number = a
    var primeFactors = [Int]()

    for i in 2...number {
        while number % i == 0 {
            primeFactors.append(i)
            number /= i
        }
    }

    return primeFactors.count == 3
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100. 
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true[/INST]  ```swift
func isMultiplyPrime(a: Int) -> Bool {
    var number = a
    var primeFactors = [Int]()

    for i in 2...number {
        while number % i == 0 {
            primeFactors.append(i)
            number /= i
        }
    }

    return primeFactors.count == 3
}
```

func isMultiplyPrime(a: Int) -> Bool {
    var number = a
    var primeFactors = [Int]()

    for i in 2...number {
        while number % i == 0 {
            primeFactors.append(i)
            number /= i
        }
    }

    return primeFactors.count == 3
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100. 
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true[/INST]  ```swift
func isMultiplyPrime(a: Int) -> Bool {
    var number = a
    var primeFactors = [Int]()

    for i in 2...number {
        while number % i == 0 {
            primeFactors.append(i)
            number /= i
        }
    }

    return primeFactors.count == 3
}
```

func isMultiplyPrime(a: Int) -> Bool {
    var number = a
    var primeFactors = [Int]()

    while number % 2 == 0 {
        primeFactors.append(2)
        number /= 2
    }

    var i = 3
    while i * i <= number {
        while number % i == 0 {
            primeFactors.append(i)
            number /= i
        }
        i += 2
    }

    if number > 2 {
        primeFactors.append(number)
    }

    return primeFactors.count == 3
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100. 
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true[/INST]  ```swift
func isMultiplyPrime(a: Int) -> Bool {
    var number = a
    var primeFactors = [Int]()

    while number % 2 == 0 {
        primeFactors.append(2)
        number /= 2
    }

    var i = 3
    while i * i <= number {
        while number % i == 0 {
            primeFactors.append(i)
            number /= i
        }
        i += 2
    }

    if number > 2 {
        primeFactors.append(number)
    }

    return primeFactors.count == 3
}
```

func isMultiplyPrime(a: Int) -> Bool {
    var number = a
    var primeFactors = [Int]()

    for i in 2...number {
        while number % i == 0 {
            primeFactors.append(i)
            number /= i
        }
    }

    return primeFactors.count == 3
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100. 
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true[/INST]  ```swift
func isMultiplyPrime(a: Int) -> Bool {
    var number = a
    var primeFactors = [Int]()

    for i in 2...number {
        while number % i == 0 {
            primeFactors.append(i)
            number /= i
        }
    }

    return primeFactors.count == 3
}
```

func isSimplePower(x: Int, n: Int) -> Bool {
    if x == 1 {
        return true
    }
    if n == 1 {
        return false
    }
    var power = n
    while power <= x {
        if power == x {
            return true
        }
        power *= n
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false[/INST]  ```swift
func isSimplePower(x: Int, n: Int) -> Bool {
    if x == 1 {
        return true
    }
    if n == 1 {
        return false
    }
    var power = n
    while power <= x {
        if power == x {
            return true
        }
        power *= n
    }
    return false
}
```

func isSimplePower(x: Int, n: Int) -> Bool {
    if x == 1 {
        return n == 1
    }
    var temp = n
    while temp < x {
        temp *= n
    }
    return temp == x
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false[/INST]  ```swift
func isSimplePower(x: Int, n: Int) -> Bool {
    if x == 1 {
        return n == 1
    }
    var temp = n
    while temp < x {
        temp *= n
    }
    return temp == x
}
```
 // XCTAssertTrue failed

func isSimplePower(x: Int, n: Int) -> Bool {
    if x == 1 {
        return n == 1
    }
    var power = n
    while power <= x {
        if power == x {
            return true
        }
        power *= n
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false[/INST]  ```swift
func isSimplePower(x: Int, n: Int) -> Bool {
    if x == 1 {
        return n == 1
    }
    var power = n
    while power <= x {
        if power == x {
            return true
        }
        power *= n
    }
    return false
}
```
 // XCTAssertTrue failed

func isSimplePower(x: Int, n: Int) -> Bool {
    if x == 1 {
        return n == 1
    }
    var power = n
    while power <= x {
        if power == x {
            return true
        }
        power *= n
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false[/INST]  ```swift
func isSimplePower(x: Int, n: Int) -> Bool {
    if x == 1 {
        return n == 1
    }
    var power = n
    while power <= x {
        if power == x {
            return true
        }
        power *= n
    }
    return false
}
```
 // XCTAssertTrue failed

func isSimplePower(x: Int, n: Int) -> Bool {
    if x == 1 {
        return n == 1
    }
    var power = n
    while power <= x {
        if power == x {
            return true
        }
        power *= n
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false[/INST]  ```swift
func isSimplePower(x: Int, n: Int) -> Bool {
    if x == 1 {
        return n == 1
    }
    var power = n
    while power <= x {
        if power == x {
            return true
        }
        power *= n
    }
    return false
}
```
 // XCTAssertTrue failed

func isSimplePower(x: Int, n: Int) -> Bool {
    if x == 1 {
        return n == 1
    }
    if n == 1 {
        return x == 1
    }
    var power = n
    while power <= x {
        if power == x {
            return true
        }
        power *= n
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false[/INST]  ```swift
func isSimplePower(x: Int, n: Int) -> Bool {
    if x == 1 {
        return n == 1
    }
    if n == 1 {
        return x == 1
    }
    var power = n
    while power <= x {
        if power == x {
            return true
        }
        power *= n
    }
    return false
}
```
 // XCTAssertTrue failed

func isSimplePower(x: Int, n: Int) -> Bool {
    if x == 1 {
        return n == 1
    }

    var power = n
    while power <= x {
        if power == x {
            return true
        }
        power *= n
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false[/INST]  ```swift
func isSimplePower(x: Int, n: Int) -> Bool {
    if x == 1 {
        return n == 1
    }

    var power = n
    while power <= x {
        if power == x {
            return true
        }
        power *= n
    }

    return false
}
```
 // XCTAssertTrue failed

func isSimplePower(x: Int, n: Int) -> Bool {
    if x == 1 {
        return n == 1
    }
    var power = n
    while power <= x {
        if power == x {
            return true
        }
        power *= n
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false[/INST]  ```swift
func isSimplePower(x: Int, n: Int) -> Bool {
    if x == 1 {
        return n == 1
    }
    var power = n
    while power <= x {
        if power == x {
            return true
        }
        power *= n
    }
    return false
}
```
 // XCTAssertTrue failed

func isSimplePower(x: Int, n: Int) -> Bool {
    if x == 1 {
        return n == 1
    }
    var power = 1
    while power < x {
        power *= n
    }
    return power == x
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false[/INST]  ```swift
func isSimplePower(x: Int, n: Int) -> Bool {
    if x == 1 {
        return n == 1
    }
    var power = 1
    while power < x {
        power *= n
    }
    return power == x
}
```
 // XCTAssertTrue failed

func isSimplePower(x: Int, n: Int) -> Bool {
    if x == 1 {
        return n == 1
    }
    var temp = n
    while temp < x {
        temp *= n
    }
    return temp == x
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false[/INST]  ```swift
func isSimplePower(x: Int, n: Int) -> Bool {
    if x == 1 {
        return n == 1
    }
    var temp = n
    while temp < x {
        temp *= n
    }
    return temp == x
}
```
 // XCTAssertTrue failed

func iscube(a: Int) -> Bool {
    let cubeRoot = Int(round(Double(abs(a)).cbrt))
    return cubeRoot * cubeRoot * cubeRoot == abs(a)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true 
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false[/INST]  ```swift
func iscube(a: Int) -> Bool {
    let cubeRoot = Int(round(Double(abs(a)).cbrt))
    return cubeRoot * cubeRoot * cubeRoot == abs(a)
}
```
let cubeRoot = Int(round(Double(abs(a)).cbrt)) // value of type 'Double' has no member 'cbrt'

func iscube(a: Int) -> Bool {
    let cubeRoot = Int(round(Double(abs(a)).cbrt))
    return cubeRoot * cubeRoot * cubeRoot == abs(a)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true 
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false[/INST]  ```swift
func iscube(a: Int) -> Bool {
    let cubeRoot = Int(round(Double(abs(a)).cbrt))
    return cubeRoot * cubeRoot * cubeRoot == abs(a)
}
```
let cubeRoot = Int(round(Double(abs(a)).cbrt)) // value of type 'Double' has no member 'cbrt'

func iscube(a: Int) -> Bool {
    let cubeRoot = Int(round(Double(abs(a)).cbrt))
    return cubeRoot * cubeRoot * cubeRoot == abs(a)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true 
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false[/INST]  ```swift
func iscube(a: Int) -> Bool {
    let cubeRoot = Int(round(Double(abs(a)).cbrt))
    return cubeRoot * cubeRoot * cubeRoot == abs(a)
}
```
let cubeRoot = Int(round(Double(abs(a)).cbrt)) // value of type 'Double' has no member 'cbrt'

func iscube(a: Int) -> Bool {
    let cubeRoot = Int(round(Double(abs(a)).cbrt))
    return cubeRoot * cubeRoot * cubeRoot == abs(a)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true 
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false[/INST]  ```swift
func iscube(a: Int) -> Bool {
    let cubeRoot = Int(round(Double(abs(a)).cbrt))
    return cubeRoot * cubeRoot * cubeRoot == abs(a)
}
```
let cubeRoot = Int(round(Double(abs(a)).cbrt)) // value of type 'Double' has no member 'cbrt'

func iscube(a: Int) -> Bool {
    let cubeRoot = Int(round(Double(abs(a)).cbrt))
    return cubeRoot * cubeRoot * cubeRoot == abs(a)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true 
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false[/INST]  ```swift
func iscube(a: Int) -> Bool {
    let cubeRoot = Int(round(Double(abs(a)).cbrt))
    return cubeRoot * cubeRoot * cubeRoot == abs(a)
}
```
let cubeRoot = Int(round(Double(abs(a)).cbrt)) // value of type 'Double' has no member 'cbrt'

func iscube(a: Int) -> Bool {
    let cubeRoot = Int(round(Double(abs(a)).cbrt))
    return cubeRoot * cubeRoot * cubeRoot == abs(a)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true 
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false[/INST]  ```swift
func iscube(a: Int) -> Bool {
    let cubeRoot = Int(round(Double(abs(a)).cbrt))
    return cubeRoot * cubeRoot * cubeRoot == abs(a)
}
```
let cubeRoot = Int(round(Double(abs(a)).cbrt)) // value of type 'Double' has no member 'cbrt'

func iscube(a: Int) -> Bool {
    let cubeRoot = Int(round(Double(abs(a)).cbrt))
    return cubeRoot * cubeRoot * cubeRoot == abs(a)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true 
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false[/INST]  ```swift
func iscube(a: Int) -> Bool {
    let cubeRoot = Int(round(Double(abs(a)).cbrt))
    return cubeRoot * cubeRoot * cubeRoot == abs(a)
}
```
let cubeRoot = Int(round(Double(abs(a)).cbrt)) // value of type 'Double' has no member 'cbrt'

func iscube(a: Int) -> Bool {
    let cubeRoot = Int(round(Double(abs(a)).cbrt))
    return cubeRoot * cubeRoot * cubeRoot == abs(a)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true 
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false[/INST]  ```swift
func iscube(a: Int) -> Bool {
    let cubeRoot = Int(round(Double(abs(a)).cbrt))
    return cubeRoot * cubeRoot * cubeRoot == abs(a)
}
```
let cubeRoot = Int(round(Double(abs(a)).cbrt)) // value of type 'Double' has no member 'cbrt'

func iscube(a: Int) -> Bool {
    let cubeRoot = Int(round(Double(abs(a)).cbrt))
    return cubeRoot * cubeRoot * cubeRoot == abs(a)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true 
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false[/INST]  ```swift
func iscube(a: Int) -> Bool {
    let cubeRoot = Int(round(Double(abs(a)).cbrt))
    return cubeRoot * cubeRoot * cubeRoot == abs(a)
}
```
let cubeRoot = Int(round(Double(abs(a)).cbrt)) // value of type 'Double' has no member 'cbrt'

func iscube(a: Int) -> Bool {
    let cubeRoot = Int(round(Double(abs(a)).cbrt))
    return cubeRoot * cubeRoot * cubeRoot == abs(a)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true 
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false[/INST]  ```swift
func iscube(a: Int) -> Bool {
    let cubeRoot = Int(round(Double(abs(a)).cbrt))
    return cubeRoot * cubeRoot * cubeRoot == abs(a)
}
```
let cubeRoot = Int(round(Double(abs(a)).cbrt)) // value of type 'Double' has no member 'cbrt'

func hexKey(num: String) -> Int {
    let primeHexDigits: Set<Character> = ["2", "3", "5", "7", "B", "D"]
    var count = 0
    for char in num {
        if primeHexDigits.contains(char) {
            count += 1
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives 
a hexadecimal number as a string and counts the number of hexadecimal 
digits that are primes (prime number, or a prime, is a natural number 
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7, 
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string, 
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2[/INST]  ```swift
func hexKey(num: String) -> Int {
    let primeHexDigits: Set<Character> = ["2", "3", "5", "7", "B", "D"]
    var count = 0
    for char in num {
        if primeHexDigits.contains(char) {
            count += 1
        }
    }
    return count
}
```

func hexKey(num: String) -> Int {
    let primeHexDigits: Set<Character> = ["2", "3", "5", "7", "B", "D"]
    var count = 0

    for char in num {
        if primeHexDigits.contains(char) {
            count += 1
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives 
a hexadecimal number as a string and counts the number of hexadecimal 
digits that are primes (prime number, or a prime, is a natural number 
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7, 
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string, 
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2[/INST]  ```swift
func hexKey(num: String) -> Int {
    let primeHexDigits: Set<Character> = ["2", "3", "5", "7", "B", "D"]
    var count = 0

    for char in num {
        if primeHexDigits.contains(char) {
            count += 1
        }
    }

    return count
}
```

func hexKey(num: String) -> Int {
    let primes: Set<Character> = ["2", "3", "5", "7", "B", "D"]
    var count = 0
    for char in num {
        if primes.contains(char) {
            count += 1
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives 
a hexadecimal number as a string and counts the number of hexadecimal 
digits that are primes (prime number, or a prime, is a natural number 
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7, 
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string, 
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2[/INST]  ```swift
func hexKey(num: String) -> Int {
    let primes: Set<Character> = ["2", "3", "5", "7", "B", "D"]
    var count = 0
    for char in num {
        if primes.contains(char) {
            count += 1
        }
    }
    return count
}
```

func hexKey(num: String) -> Int {
    let primeHexDigits: Set<Character> = ["2", "3", "5", "7", "B", "D"]
    var count = 0

    for digit in num {
        if primeHexDigits.contains(digit) {
            count += 1
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives 
a hexadecimal number as a string and counts the number of hexadecimal 
digits that are primes (prime number, or a prime, is a natural number 
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7, 
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string, 
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2[/INST]  ```swift
func hexKey(num: String) -> Int {
    let primeHexDigits: Set<Character> = ["2", "3", "5", "7", "B", "D"]
    var count = 0

    for digit in num {
        if primeHexDigits.contains(digit) {
            count += 1
        }
    }

    return count
}
```

func hexKey(num: String) -> Int {
    let primeHexDigits: Set<Character> = ["2", "3", "5", "7", "B", "D"]
    var count = 0

    for char in num {
        if primeHexDigits.contains(char) {
            count += 1
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives 
a hexadecimal number as a string and counts the number of hexadecimal 
digits that are primes (prime number, or a prime, is a natural number 
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7, 
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string, 
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2[/INST]  ```swift
func hexKey(num: String) -> Int {
    let primeHexDigits: Set<Character> = ["2", "3", "5", "7", "B", "D"]
    var count = 0

    for char in num {
        if primeHexDigits.contains(char) {
            count += 1
        }
    }

    return count
}
```

func hexKey(num: String) -> Int {
    let primeHexDigits: Set<Character> = ["2", "3", "5", "7", "B", "D"]
    var count = 0

    for char in num {
        if primeHexDigits.contains(char) {
            count += 1
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives 
a hexadecimal number as a string and counts the number of hexadecimal 
digits that are primes (prime number, or a prime, is a natural number 
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7, 
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string, 
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2[/INST]  ```swift
func hexKey(num: String) -> Int {
    let primeHexDigits: Set<Character> = ["2", "3", "5", "7", "B", "D"]
    var count = 0

    for char in num {
        if primeHexDigits.contains(char) {
            count += 1
        }
    }

    return count
}
```

func hexKey(num: String) -> Int {
    let primes: Set<Character> = ["2", "3", "5", "7", "B", "D"]
    var count = 0

    for char in num {
        if primes.contains(char) {
            count += 1
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives 
a hexadecimal number as a string and counts the number of hexadecimal 
digits that are primes (prime number, or a prime, is a natural number 
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7, 
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string, 
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2[/INST]  ```swift
func hexKey(num: String) -> Int {
    let primes: Set<Character> = ["2", "3", "5", "7", "B", "D"]
    var count = 0

    for char in num {
        if primes.contains(char) {
            count += 1
        }
    }

    return count
}
```

func hexKey(num: String) -> Int {
    let primeHexDigits: Set<Character> = ["2", "3", "5", "7", "B", "D"]
    var count = 0

    for digit in num {
        if primeHexDigits.contains(digit) {
            count += 1
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives 
a hexadecimal number as a string and counts the number of hexadecimal 
digits that are primes (prime number, or a prime, is a natural number 
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7, 
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string, 
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2[/INST]  ```swift
func hexKey(num: String) -> Int {
    let primeHexDigits: Set<Character> = ["2", "3", "5", "7", "B", "D"]
    var count = 0

    for digit in num {
        if primeHexDigits.contains(digit) {
            count += 1
        }
    }

    return count
}
```

func hexKey(num: String) -> Int {
    let primeHexDigits: Set<Character> = ["2", "3", "5", "7", "B", "D"]
    var count = 0

    for char in num {
        if primeHexDigits.contains(char) {
            count += 1
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives 
a hexadecimal number as a string and counts the number of hexadecimal 
digits that are primes (prime number, or a prime, is a natural number 
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7, 
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string, 
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2[/INST]  ```swift
func hexKey(num: String) -> Int {
    let primeHexDigits: Set<Character> = ["2", "3", "5", "7", "B", "D"]
    var count = 0

    for char in num {
        if primeHexDigits.contains(char) {
            count += 1
        }
    }

    return count
}
```

func hexKey(num: String) -> Int {
    let primeHexDigits: Set<Character> = ["2", "3", "5", "7", "B", "D"]
    var count = 0

    for digit in num {
        if primeHexDigits.contains(digit) {
            count += 1
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives 
a hexadecimal number as a string and counts the number of hexadecimal 
digits that are primes (prime number, or a prime, is a natural number 
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7, 
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string, 
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2[/INST]  ```swift
func hexKey(num: String) -> Int {
    let primeHexDigits: Set<Character> = ["2", "3", "5", "7", "B", "D"]
    var count = 0

    for digit in num {
        if primeHexDigits.contains(digit) {
            count += 1
        }
    }

    return count
}
```

func decimalToBinary(decimal: Int) -> String {
    let binary = String(decimal, radix: 2)
    return "db" + binary + "db"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"[/INST]  ```swift
func decimalToBinary(decimal: Int) -> String {
    let binary = String(decimal, radix: 2)
    return "db" + binary + "db"
}
```

func decimalToBinary(decimal: Int) -> String {
    let binary = String(decimal, radix: 2)
    return "db" + binary + "db"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"[/INST]  ```swift
func decimalToBinary(decimal: Int) -> String {
    let binary = String(decimal, radix: 2)
    return "db" + binary + "db"
}
```

func decimalToBinary(decimal: Int) -> String {
    let binaryString = String(decimal, radix: 2)
    return "db" + binaryString + "db"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"[/INST]  ```swift
func decimalToBinary(decimal: Int) -> String {
    let binaryString = String(decimal, radix: 2)
    return "db" + binaryString + "db"
}
```

func decimalToBinary(decimal: Int) -> String {
    let binary = String(decimal, radix: 2)
    return "db" + binary + "db"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"[/INST]  ```swift
func decimalToBinary(decimal: Int) -> String {
    let binary = String(decimal, radix: 2)
    return "db" + binary + "db"
}
```

func decimalToBinary(decimal: Int) -> String {
    let binary = String(decimal, radix: 2)
    return "db" + binary + "db"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"[/INST]  ```swift
func decimalToBinary(decimal: Int) -> String {
    let binary = String(decimal, radix: 2)
    return "db" + binary + "db"
}
```

func decimalToBinary(decimal: Int) -> String {
    let binary = String(decimal, radix: 2)
    return "db" + binary + "db"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"[/INST]  ```swift
func decimalToBinary(decimal: Int) -> String {
    let binary = String(decimal, radix: 2)
    return "db" + binary + "db"
}
```

func decimalToBinary(decimal: Int) -> String {
    let binaryString = String(decimal, radix: 2)
    return "db" + binaryString + "db"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"[/INST]  ```swift
func decimalToBinary(decimal: Int) -> String {
    let binaryString = String(decimal, radix: 2)
    return "db" + binaryString + "db"
}
```

func decimalToBinary(decimal: Int) -> String {
    let binary = String(decimal, radix: 2)
    return "db" + binary + "db"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"[/INST]  ```swift
func decimalToBinary(decimal: Int) -> String {
    let binary = String(decimal, radix: 2)
    return "db" + binary + "db"
}
```

func decimalToBinary(decimal: Int) -> String {
    let binary = String(decimal, radix: 2)
    return "db" + binary + "db"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"[/INST]  ```swift
func decimalToBinary(decimal: Int) -> String {
    let binary = String(decimal, radix: 2)
    return "db" + binary + "db"
}
```

func decimalToBinary(decimal: Int) -> String {
    let binaryString = String(decimal, radix: 2)
    return "db" + binaryString + "db"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"[/INST]  ```swift
func decimalToBinary(decimal: Int) -> String {
    let binaryString = String(decimal, radix: 2)
    return "db" + binaryString + "db"
}
```

func isHappy(s: String) -> Bool {
    guard s.count >= 3 else {
        return false
    }

    let characters = Array(s)
    for i in 0...characters.count - 3 {
        let subArray = characters[i..<i+3]
        if subArray[0] == subArray[1] || subArray[0] == subArray[2] || subArray[1] == subArray[2] {
            return false
        }
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false[/INST]  ```swift
func isHappy(s: String) -> Bool {
    guard s.count >= 3 else {
        return false
    }

    let characters = Array(s)
    for i in 0...characters.count - 3 {
        let subArray = characters[i..<i+3]
        if subArray[0] == subArray[1] || subArray[0] == subArray[2] || subArray[1] == subArray[2] {
            return false
        }
    }

    return true
}
```
 // Fatal error: Index out of bounds

func isHappy(s: String) -> Bool {
    guard s.count >= 3 else {
        return false
    }

    let characters = Array(s)
    for i in 0...characters.count - 3 {
        let subArray = Array(characters[i..<i+3])
        if subArray[0] == subArray[1] || subArray[0] == subArray[2] || subArray[1] == subArray[2] {
            return false
        }
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false[/INST]  ```swift
func isHappy(s: String) -> Bool {
    guard s.count >= 3 else {
        return false
    }

    let characters = Array(s)
    for i in 0...characters.count - 3 {
        let subArray = Array(characters[i..<i+3])
        if subArray[0] == subArray[1] || subArray[0] == subArray[2] || subArray[1] == subArray[2] {
            return false
        }
    }

    return true
}
```

func isHappy(s: String) -> Bool {
    guard s.count >= 3 else {
        return false
    }

    var characters = Array(s)
    for i in 2..<characters.count {
        if characters[i] == characters[i-1] || characters[i] == characters[i-2] || characters[i-1] == characters[i-2] {
            return false
        }
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false[/INST]  ```swift
func isHappy(s: String) -> Bool {
    guard s.count >= 3 else {
        return false
    }

    var characters = Array(s)
    for i in 2..<characters.count {
        if characters[i] == characters[i-1] || characters[i] == characters[i-2] || characters[i-1] == characters[i-2] {
            return false
        }
    }

    return true
}
```
var characters = Array(s) // variable 'characters' was never mutated; consider changing to 'let' constant

func isHappy(s: String) -> Bool {
    guard s.count >= 3 else {
        return false
    }

    var characters = Array(s)

    for i in 2..<characters.count {
        if characters[i] == characters[i-1] || characters[i] == characters[i-2] || characters[i-1] == characters[i-2] {
            return false
        }
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false[/INST]  ```swift
func isHappy(s: String) -> Bool {
    guard s.count >= 3 else {
        return false
    }

    var characters = Array(s)

    for i in 2..<characters.count {
        if characters[i] == characters[i-1] || characters[i] == characters[i-2] || characters[i-1] == characters[i-2] {
            return false
        }
    }

    return true
}
```
var characters = Array(s) // variable 'characters' was never mutated; consider changing to 'let' constant

func isHappy(s: String) -> Bool {
    guard s.count >= 3 else {
        return false
    }

    var characters = Array(s)

    for i in 2..<characters.count {
        if characters[i] == characters[i - 1] || characters[i] == characters[i - 2] || characters[i - 1] == characters[i - 2] {
            return false
        }
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false[/INST]  ```swift
func isHappy(s: String) -> Bool {
    guard s.count >= 3 else {
        return false
    }

    var characters = Array(s)

    for i in 2..<characters.count {
        if characters[i] == characters[i - 1] || characters[i] == characters[i - 2] || characters[i - 1] == characters[i - 2] {
            return false
        }
    }

    return true
}
```
var characters = Array(s) // variable 'characters' was never mutated; consider changing to 'let' constant

func isHappy(s: String) -> Bool {
    guard s.count >= 3 else {
        return false
    }

    let characters = Array(s)
    for i in 0...characters.count - 3 {
        let subArray = characters[i..<i+3]
        if subArray[0] == subArray[1] || subArray[0] == subArray[2] || subArray[1] == subArray[2] {
            return false
        }
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false[/INST]  ```swift
func isHappy(s: String) -> Bool {
    guard s.count >= 3 else {
        return false
    }

    let characters = Array(s)
    for i in 0...characters.count - 3 {
        let subArray = characters[i..<i+3]
        if subArray[0] == subArray[1] || subArray[0] == subArray[2] || subArray[1] == subArray[2] {
            return false
        }
    }

    return true
}
```
 // Fatal error: Index out of bounds

func isHappy(s: String) -> Bool {
    guard s.count >= 3 else {
        return false
    }

    var characters = Array(s)

    for i in 2..<characters.count {
        if characters[i] == characters[i-1] || characters[i] == characters[i-2] || characters[i-1] == characters[i-2] {
            return false
        }
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false[/INST]  ```swift
func isHappy(s: String) -> Bool {
    guard s.count >= 3 else {
        return false
    }

    var characters = Array(s)

    for i in 2..<characters.count {
        if characters[i] == characters[i-1] || characters[i] == characters[i-2] || characters[i-1] == characters[i-2] {
            return false
        }
    }

    return true
}
```
var characters = Array(s) // variable 'characters' was never mutated; consider changing to 'let' constant

func isHappy(s: String) -> Bool {
    guard s.count >= 3 else {
        return false
    }

    let characters = Array(s)
    for i in 0..<characters.count - 2 {
        if characters[i] == characters[i+1] || characters[i] == characters[i+2] || characters[i+1] == characters[i+2] {
            return false
        }
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false[/INST]  ```swift
func isHappy(s: String) -> Bool {
    guard s.count >= 3 else {
        return false
    }

    let characters = Array(s)
    for i in 0..<characters.count - 2 {
        if characters[i] == characters[i+1] || characters[i] == characters[i+2] || characters[i+1] == characters[i+2] {
            return false
        }
    }

    return true
}
```

func isHappy(s: String) -> Bool {
    guard s.count >= 3 else {
        return false
    }

    var characters = Array(s)

    for i in 2..<characters.count {
        if characters[i] == characters[i - 1] || characters[i] == characters[i - 2] || characters[i - 1] == characters[i - 2] {
            return false
        }
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false[/INST]  ```swift
func isHappy(s: String) -> Bool {
    guard s.count >= 3 else {
        return false
    }

    var characters = Array(s)

    for i in 2..<characters.count {
        if characters[i] == characters[i - 1] || characters[i] == characters[i - 2] || characters[i - 1] == characters[i - 2] {
            return false
        }
    }

    return true
}
```
var characters = Array(s) // variable 'characters' was never mutated; consider changing to 'let' constant

func isHappy(s: String) -> Bool {
    guard s.count >= 3 else {
        return false
    }

    var characters = Array(s)

    for i in stride(from: 0, to: characters.count - 2, by: 1) {
        if characters[i] == characters[i + 1] || characters[i] == characters[i + 2] || characters[i + 1] == characters[i + 2] {
            return false
        }
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false[/INST]  ```swift
func isHappy(s: String) -> Bool {
    guard s.count >= 3 else {
        return false
    }

    var characters = Array(s)

    for i in stride(from: 0, to: characters.count - 2, by: 1) {
        if characters[i] == characters[i + 1] || characters[i] == characters[i + 2] || characters[i + 1] == characters[i + 2] {
            return false
        }
    }

    return true
}
```
var characters = Array(s) // variable 'characters' was never mutated; consider changing to 'let' constant

func numericalLetterGrade(grades: [Double]) -> [String] {
    var letterGrades: [String] = []

    for grade in grades {
        switch grade {
        case 4.0:
            letterGrades.append("A+")
        case 3.7..<4.0:
            letterGrades.append("A")
        case 3.3..<3.7:
            letterGrades.append("A-")
        case 3.0..<3.3:
            letterGrades.append("B+")
        case 2.7..<3.0:
            letterGrades.append("B")
        case 2.3..<2.7:
            letterGrades.append("B-")
        case 2.0..<2.3:
            letterGrades.append("C+")
        case 1.7..<2.0:
            letterGrades.append("C")
        case 1.3..<1.7:
            letterGrades.append("C-")
        case 1.0..<1.3:
            letterGrades.append("D+")
        case 0.7..<1.0:
            letterGrades.append("D")
        case 0.0..<0.7:
            letterGrades.append("D-")
        case 0.0:
            letterGrades.append("E")
        default:
            letterGrades.append("Invalid Grade")
        }
    }

    return letterGrades
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write 
a function that can output an array of letter grades using the following table:
GPA       |    Letter grade
4.0                A+
> 3.7                A 
> 3.3                A- 
> 3.0                B+
> 2.7                B 
> 2.3                B-
> 2.0                C+
> 1.7                C
> 1.3                C-
> 1.0                D+ 
> 0.7                D 
> 0.0                D-
0.0                E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"][/INST]  ```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
    var letterGrades: [String] = []

    for grade in grades {
        switch grade {
        case 4.0:
            letterGrades.append("A+")
        case 3.7..<4.0:
            letterGrades.append("A")
        case 3.3..<3.7:
            letterGrades.append("A-")
        case 3.0..<3.3:
            letterGrades.append("B+")
        case 2.7..<3.0:
            letterGrades.append("B")
        case 2.3..<2.7:
            letterGrades.append("B-")
        case 2.0..<2.3:
            letterGrades.append("C+")
        case 1.7..<2.0:
            letterGrades.append("C")
        case 1.3..<1.7:
            letterGrades.append("C-")
        case 1.0..<1.3:
            letterGrades.append("D+")
        case 0.7..<1.0:
            letterGrades.append("D")
        case 0.0..<0.7:
            letterGrades.append("D-")
        case 0.0:
            letterGrades.append("E")
        default:
            letterGrades.append("Invalid Grade")
        }
    }

    return letterGrades
}
```
 // XCTAssertTrue failed

func numericalLetterGrade(grades: [Double]) -> [String] {
    var letterGrades: [String] = []

    for grade in grades {
        switch grade {
        case 4.0:
            letterGrades.append("A+")
        case 3.7..<4.0:
            letterGrades.append("A")
        case 3.3..<3.7:
            letterGrades.append("A-")
        case 3.0..<3.3:
            letterGrades.append("B+")
        case 2.7..<3.0:
            letterGrades.append("B")
        case 2.3..<2.7:
            letterGrades.append("B-")
        case 2.0..<2.3:
            letterGrades.append("C+")
        case 1.7..<2.0:
            letterGrades.append("C")
        case 1.3..<1.7:
            letterGrades.append("C-")
        case 1.0..<1.3:
            letterGrades.append("D+")
        case 0.7..<1.0:
            letterGrades.append("D")
        case 0.0..<0.7:
            letterGrades.append("D-")
        case 0.0:
            letterGrades.append("E")
        default:
            letterGrades.append("Invalid Grade")
        }
    }

    return letterGrades
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write 
a function that can output an array of letter grades using the following table:
GPA       |    Letter grade
4.0                A+
> 3.7                A 
> 3.3                A- 
> 3.0                B+
> 2.7                B 
> 2.3                B-
> 2.0                C+
> 1.7                C
> 1.3                C-
> 1.0                D+ 
> 0.7                D 
> 0.0                D-
0.0                E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"][/INST]  ```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
    var letterGrades: [String] = []

    for grade in grades {
        switch grade {
        case 4.0:
            letterGrades.append("A+")
        case 3.7..<4.0:
            letterGrades.append("A")
        case 3.3..<3.7:
            letterGrades.append("A-")
        case 3.0..<3.3:
            letterGrades.append("B+")
        case 2.7..<3.0:
            letterGrades.append("B")
        case 2.3..<2.7:
            letterGrades.append("B-")
        case 2.0..<2.3:
            letterGrades.append("C+")
        case 1.7..<2.0:
            letterGrades.append("C")
        case 1.3..<1.7:
            letterGrades.append("C-")
        case 1.0..<1.3:
            letterGrades.append("D+")
        case 0.7..<1.0:
            letterGrades.append("D")
        case 0.0..<0.7:
            letterGrades.append("D-")
        case 0.0:
            letterGrades.append("E")
        default:
            letterGrades.append("Invalid Grade")
        }
    }

    return letterGrades
}
```
 // XCTAssertTrue failed

func numericalLetterGrade(grades: [Double]) -> [String] {
    var letterGrades: [String] = []
    for grade in grades {
        switch grade {
        case 4.0:
            letterGrades.append("A+")
        case 3.7..<4.0:
            letterGrades.append("A")
        case 3.3..<3.7:
            letterGrades.append("A-")
        case 3.0..<3.3:
            letterGrades.append("B+")
        case 2.7..<3.0:
            letterGrades.append("B")
        case 2.3..<2.7:
            letterGrades.append("B-")
        case 2.0..<2.3:
            letterGrades.append("C+")
        case 1.7..<2.0:
            letterGrades.append("C")
        case 1.3..<1.7:
            letterGrades.append("C-")
        case 1.0..<1.3:
            letterGrades.append("D+")
        case 0.7..<1.0:
            letterGrades.append("D")
        case 0.0..<0.7:
            letterGrades.append("D-")
        default:
            letterGrades.append("E")
        }
    }
    return letterGrades
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write 
a function that can output an array of letter grades using the following table:
GPA       |    Letter grade
4.0                A+
> 3.7                A 
> 3.3                A- 
> 3.0                B+
> 2.7                B 
> 2.3                B-
> 2.0                C+
> 1.7                C
> 1.3                C-
> 1.0                D+ 
> 0.7                D 
> 0.0                D-
0.0                E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"][/INST]  ```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
    var letterGrades: [String] = []
    for grade in grades {
        switch grade {
        case 4.0:
            letterGrades.append("A+")
        case 3.7..<4.0:
            letterGrades.append("A")
        case 3.3..<3.7:
            letterGrades.append("A-")
        case 3.0..<3.3:
            letterGrades.append("B+")
        case 2.7..<3.0:
            letterGrades.append("B")
        case 2.3..<2.7:
            letterGrades.append("B-")
        case 2.0..<2.3:
            letterGrades.append("C+")
        case 1.7..<2.0:
            letterGrades.append("C")
        case 1.3..<1.7:
            letterGrades.append("C-")
        case 1.0..<1.3:
            letterGrades.append("D+")
        case 0.7..<1.0:
            letterGrades.append("D")
        case 0.0..<0.7:
            letterGrades.append("D-")
        default:
            letterGrades.append("E")
        }
    }
    return letterGrades
}
```
 // XCTAssertTrue failed

func numericalLetterGrade(grades: [Double]) -> [String] {
    var letterGrades: [String] = []
    for grade in grades {
        switch grade {
        case 4.0:
            letterGrades.append("A+")
        case 3.7..<4.0:
            letterGrades.append("A")
        case 3.3..<3.7:
            letterGrades.append("A-")
        case 3.0..<3.3:
            letterGrades.append("B+")
        case 2.7..<3.0:
            letterGrades.append("B")
        case 2.3..<2.7:
            letterGrades.append("B-")
        case 2.0..<2.3:
            letterGrades.append("C+")
        case 1.7..<2.0:
            letterGrades.append("C")
        case 1.3..<1.7:
            letterGrades.append("C-")
        case 1.0..<1.3:
            letterGrades.append("D+")
        case 0.7..<1.0:
            letterGrades.append("D")
        case 0.0..<0.7:
            letterGrades.append("D-")
        default:
            letterGrades.append("E")
        }
    }
    return letterGrades
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write 
a function that can output an array of letter grades using the following table:
GPA       |    Letter grade
4.0                A+
> 3.7                A 
> 3.3                A- 
> 3.0                B+
> 2.7                B 
> 2.3                B-
> 2.0                C+
> 1.7                C
> 1.3                C-
> 1.0                D+ 
> 0.7                D 
> 0.0                D-
0.0                E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"][/INST]  ```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
    var letterGrades: [String] = []
    for grade in grades {
        switch grade {
        case 4.0:
            letterGrades.append("A+")
        case 3.7..<4.0:
            letterGrades.append("A")
        case 3.3..<3.7:
            letterGrades.append("A-")
        case 3.0..<3.3:
            letterGrades.append("B+")
        case 2.7..<3.0:
            letterGrades.append("B")
        case 2.3..<2.7:
            letterGrades.append("B-")
        case 2.0..<2.3:
            letterGrades.append("C+")
        case 1.7..<2.0:
            letterGrades.append("C")
        case 1.3..<1.7:
            letterGrades.append("C-")
        case 1.0..<1.3:
            letterGrades.append("D+")
        case 0.7..<1.0:
            letterGrades.append("D")
        case 0.0..<0.7:
            letterGrades.append("D-")
        default:
            letterGrades.append("E")
        }
    }
    return letterGrades
}
```
 // XCTAssertTrue failed

func numericalLetterGrade(grades: [Double]) -> [String] {
    var letterGrades: [String] = []

    for grade in grades {
        switch grade {
        case 4.0:
            letterGrades.append("A+")
        case 3.7..<4.0:
            letterGrades.append("A")
        case 3.3..<3.7:
            letterGrades.append("A-")
        case 3.0..<3.3:
            letterGrades.append("B+")
        case 2.7..<3.0:
            letterGrades.append("B")
        case 2.3..<2.7:
            letterGrades.append("B-")
        case 2.0..<2.3:
            letterGrades.append("C+")
        case 1.7..<2.0:
            letterGrades.append("C")
        case 1.3..<1.7:
            letterGrades.append("C-")
        case 1.0..<1.3:
            letterGrades.append("D+")
        case 0.7..<1.0:
            letterGrades.append("D")
        case 0.0..<0.7:
            letterGrades.append("D-")
        case 0.0:
            letterGrades.append("E")
        default:
            letterGrades.append("Invalid Grade")
        }
    }

    return letterGrades
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write 
a function that can output an array of letter grades using the following table:
GPA       |    Letter grade
4.0                A+
> 3.7                A 
> 3.3                A- 
> 3.0                B+
> 2.7                B 
> 2.3                B-
> 2.0                C+
> 1.7                C
> 1.3                C-
> 1.0                D+ 
> 0.7                D 
> 0.0                D-
0.0                E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"][/INST]  ```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
    var letterGrades: [String] = []

    for grade in grades {
        switch grade {
        case 4.0:
            letterGrades.append("A+")
        case 3.7..<4.0:
            letterGrades.append("A")
        case 3.3..<3.7:
            letterGrades.append("A-")
        case 3.0..<3.3:
            letterGrades.append("B+")
        case 2.7..<3.0:
            letterGrades.append("B")
        case 2.3..<2.7:
            letterGrades.append("B-")
        case 2.0..<2.3:
            letterGrades.append("C+")
        case 1.7..<2.0:
            letterGrades.append("C")
        case 1.3..<1.7:
            letterGrades.append("C-")
        case 1.0..<1.3:
            letterGrades.append("D+")
        case 0.7..<1.0:
            letterGrades.append("D")
        case 0.0..<0.7:
            letterGrades.append("D-")
        case 0.0:
            letterGrades.append("E")
        default:
            letterGrades.append("Invalid Grade")
        }
    }

    return letterGrades
}
```
 // XCTAssertTrue failed

func numericalLetterGrade(grades: [Double]) -> [String] {
    var letterGrades: [String] = []
    for grade in grades {
        switch grade {
        case 4.0:
            letterGrades.append("A+")
        case 3.7..<4.0:
            letterGrades.append("A")
        case 3.3..<3.7:
            letterGrades.append("A-")
        case 3.0..<3.3:
            letterGrades.append("B+")
        case 2.7..<3.0:
            letterGrades.append("B")
        case 2.3..<2.7:
            letterGrades.append("B-")
        case 2.0..<2.3:
            letterGrades.append("C+")
        case 1.7..<2.0:
            letterGrades.append("C")
        case 1.3..<1.7:
            letterGrades.append("C-")
        case 1.0..<1.3:
            letterGrades.append("D+")
        case 0.7..<1.0:
            letterGrades.append("D")
        case 0.0..<0.7:
            letterGrades.append("D-")
        default:
            letterGrades.append("E")
        }
    }
    return letterGrades
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write 
a function that can output an array of letter grades using the following table:
GPA       |    Letter grade
4.0                A+
> 3.7                A 
> 3.3                A- 
> 3.0                B+
> 2.7                B 
> 2.3                B-
> 2.0                C+
> 1.7                C
> 1.3                C-
> 1.0                D+ 
> 0.7                D 
> 0.0                D-
0.0                E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"][/INST]  ```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
    var letterGrades: [String] = []
    for grade in grades {
        switch grade {
        case 4.0:
            letterGrades.append("A+")
        case 3.7..<4.0:
            letterGrades.append("A")
        case 3.3..<3.7:
            letterGrades.append("A-")
        case 3.0..<3.3:
            letterGrades.append("B+")
        case 2.7..<3.0:
            letterGrades.append("B")
        case 2.3..<2.7:
            letterGrades.append("B-")
        case 2.0..<2.3:
            letterGrades.append("C+")
        case 1.7..<2.0:
            letterGrades.append("C")
        case 1.3..<1.7:
            letterGrades.append("C-")
        case 1.0..<1.3:
            letterGrades.append("D+")
        case 0.7..<1.0:
            letterGrades.append("D")
        case 0.0..<0.7:
            letterGrades.append("D-")
        default:
            letterGrades.append("E")
        }
    }
    return letterGrades
}
```
 // XCTAssertTrue failed

func numericalLetterGrade(grades: [Double]) -> [String] {
    var letterGrades: [String] = []

    for grade in grades {
        switch grade {
        case 4.0:
            letterGrades.append("A+")
        case 3.7..<4.0:
            letterGrades.append("A")
        case 3.3..<3.7:
            letterGrades.append("A-")
        case 3.0..<3.3:
            letterGrades.append("B+")
        case 2.7..<3.0:
            letterGrades.append("B")
        case 2.3..<2.7:
            letterGrades.append("B-")
        case 2.0..<2.3:
            letterGrades.append("C+")
        case 1.7..<2.0:
            letterGrades.append("C")
        case 1.3..<1.7:
            letterGrades.append("C-")
        case 1.0..<1.3:
            letterGrades.append("D+")
        case 0.7..<1.0:
            letterGrades.append("D")
        case 0.0..<0.7:
            letterGrades.append("D-")
        case 0.0:
            letterGrades.append("E")
        default:
            letterGrades.append("Invalid Grade")
        }
    }

    return letterGrades
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write 
a function that can output an array of letter grades using the following table:
GPA       |    Letter grade
4.0                A+
> 3.7                A 
> 3.3                A- 
> 3.0                B+
> 2.7                B 
> 2.3                B-
> 2.0                C+
> 1.7                C
> 1.3                C-
> 1.0                D+ 
> 0.7                D 
> 0.0                D-
0.0                E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"][/INST]  ```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
    var letterGrades: [String] = []

    for grade in grades {
        switch grade {
        case 4.0:
            letterGrades.append("A+")
        case 3.7..<4.0:
            letterGrades.append("A")
        case 3.3..<3.7:
            letterGrades.append("A-")
        case 3.0..<3.3:
            letterGrades.append("B+")
        case 2.7..<3.0:
            letterGrades.append("B")
        case 2.3..<2.7:
            letterGrades.append("B-")
        case 2.0..<2.3:
            letterGrades.append("C+")
        case 1.7..<2.0:
            letterGrades.append("C")
        case 1.3..<1.7:
            letterGrades.append("C-")
        case 1.0..<1.3:
            letterGrades.append("D+")
        case 0.7..<1.0:
            letterGrades.append("D")
        case 0.0..<0.7:
            letterGrades.append("D-")
        case 0.0:
            letterGrades.append("E")
        default:
            letterGrades.append("Invalid Grade")
        }
    }

    return letterGrades
}
```
 // XCTAssertTrue failed

func numericalLetterGrade(grades: [Double]) -> [String] {
    var letterGrades: [String] = []
    for grade in grades {
        switch grade {
        case 4.0:
            letterGrades.append("A+")
        case 3.7..<4.0:
            letterGrades.append("A")
        case 3.3..<3.7:
            letterGrades.append("A-")
        case 3.0..<3.3:
            letterGrades.append("B+")
        case 2.7..<3.0:
            letterGrades.append("B")
        case 2.3..<2.7:
            letterGrades.append("B-")
        case 2.0..<2.3:
            letterGrades.append("C+")
        case 1.7..<2.0:
            letterGrades.append("C")
        case 1.3..<1.7:
            letterGrades.append("C-")
        case 1.0..<1.3:
            letterGrades.append("D+")
        case 0.7..<1.0:
            letterGrades.append("D")
        case 0.0..<0.7:
            letterGrades.append("D-")
        default:
            letterGrades.append("E")
        }
    }
    return letterGrades
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write 
a function that can output an array of letter grades using the following table:
GPA       |    Letter grade
4.0                A+
> 3.7                A 
> 3.3                A- 
> 3.0                B+
> 2.7                B 
> 2.3                B-
> 2.0                C+
> 1.7                C
> 1.3                C-
> 1.0                D+ 
> 0.7                D 
> 0.0                D-
0.0                E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"][/INST]  ```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
    var letterGrades: [String] = []
    for grade in grades {
        switch grade {
        case 4.0:
            letterGrades.append("A+")
        case 3.7..<4.0:
            letterGrades.append("A")
        case 3.3..<3.7:
            letterGrades.append("A-")
        case 3.0..<3.3:
            letterGrades.append("B+")
        case 2.7..<3.0:
            letterGrades.append("B")
        case 2.3..<2.7:
            letterGrades.append("B-")
        case 2.0..<2.3:
            letterGrades.append("C+")
        case 1.7..<2.0:
            letterGrades.append("C")
        case 1.3..<1.7:
            letterGrades.append("C-")
        case 1.0..<1.3:
            letterGrades.append("D+")
        case 0.7..<1.0:
            letterGrades.append("D")
        case 0.0..<0.7:
            letterGrades.append("D-")
        default:
            letterGrades.append("E")
        }
    }
    return letterGrades
}
```
 // XCTAssertTrue failed

func numericalLetterGrade(grades: [Double]) -> [String] {
    var letterGrades: [String] = []

    for grade in grades {
        switch grade {
        case 4.0:
            letterGrades.append("A+")
        case 3.7..<4.0:
            letterGrades.append("A")
        case 3.3..<3.7:
            letterGrades.append("A-")
        case 3.0..<3.3:
            letterGrades.append("B+")
        case 2.7..<3.0:
            letterGrades.append("B")
        case 2.3..<2.7:
            letterGrades.append("B-")
        case 2.0..<2.3:
            letterGrades.append("C+")
        case 1.7..<2.0:
            letterGrades.append("C")
        case 1.3..<1.7:
            letterGrades.append("C-")
        case 1.0..<1.3:
            letterGrades.append("D+")
        case 0.7..<1.0:
            letterGrades.append("D")
        case 0.0..<0.7:
            letterGrades.append("D-")
        case 0.0:
            letterGrades.append("E")
        default:
            letterGrades.append("Invalid Grade")
        }
    }

    return letterGrades
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write 
a function that can output an array of letter grades using the following table:
GPA       |    Letter grade
4.0                A+
> 3.7                A 
> 3.3                A- 
> 3.0                B+
> 2.7                B 
> 2.3                B-
> 2.0                C+
> 1.7                C
> 1.3                C-
> 1.0                D+ 
> 0.7                D 
> 0.0                D-
0.0                E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"][/INST]  ```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
    var letterGrades: [String] = []

    for grade in grades {
        switch grade {
        case 4.0:
            letterGrades.append("A+")
        case 3.7..<4.0:
            letterGrades.append("A")
        case 3.3..<3.7:
            letterGrades.append("A-")
        case 3.0..<3.3:
            letterGrades.append("B+")
        case 2.7..<3.0:
            letterGrades.append("B")
        case 2.3..<2.7:
            letterGrades.append("B-")
        case 2.0..<2.3:
            letterGrades.append("C+")
        case 1.7..<2.0:
            letterGrades.append("C")
        case 1.3..<1.7:
            letterGrades.append("C-")
        case 1.0..<1.3:
            letterGrades.append("D+")
        case 0.7..<1.0:
            letterGrades.append("D")
        case 0.0..<0.7:
            letterGrades.append("D-")
        case 0.0:
            letterGrades.append("E")
        default:
            letterGrades.append("Invalid Grade")
        }
    }

    return letterGrades
}
```
 // XCTAssertTrue failed

func numericalLetterGrade(grades: [Double]) -> [String] {
    var letterGrades: [String] = []

    for grade in grades {
        switch grade {
        case 4.0:
            letterGrades.append("A+")
        case 3.7..<4.0:
            letterGrades.append("A")
        case 3.3..<3.7:
            letterGrades.append("A-")
        case 3.0..<3.3:
            letterGrades.append("B+")
        case 2.7..<3.0:
            letterGrades.append("B")
        case 2.3..<2.7:
            letterGrades.append("B-")
        case 2.0..<2.3:
            letterGrades.append("C+")
        case 1.7..<2.0:
            letterGrades.append("C")
        case 1.3..<1.7:
            letterGrades.append("C-")
        case 1.0..<1.3:
            letterGrades.append("D+")
        case 0.7..<1.0:
            letterGrades.append("D")
        case 0.0..<0.7:
            letterGrades.append("D-")
        case 0.0:
            letterGrades.append("E")
        default:
            letterGrades.append("Invalid Grade")
        }
    }

    return letterGrades
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write 
a function that can output an array of letter grades using the following table:
GPA       |    Letter grade
4.0                A+
> 3.7                A 
> 3.3                A- 
> 3.0                B+
> 2.7                B 
> 2.3                B-
> 2.0                C+
> 1.7                C
> 1.3                C-
> 1.0                D+ 
> 0.7                D 
> 0.0                D-
0.0                E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"][/INST]  ```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
    var letterGrades: [String] = []

    for grade in grades {
        switch grade {
        case 4.0:
            letterGrades.append("A+")
        case 3.7..<4.0:
            letterGrades.append("A")
        case 3.3..<3.7:
            letterGrades.append("A-")
        case 3.0..<3.3:
            letterGrades.append("B+")
        case 2.7..<3.0:
            letterGrades.append("B")
        case 2.3..<2.7:
            letterGrades.append("B-")
        case 2.0..<2.3:
            letterGrades.append("C+")
        case 1.7..<2.0:
            letterGrades.append("C")
        case 1.3..<1.7:
            letterGrades.append("C-")
        case 1.0..<1.3:
            letterGrades.append("D+")
        case 0.7..<1.0:
            letterGrades.append("D")
        case 0.0..<0.7:
            letterGrades.append("D-")
        case 0.0:
            letterGrades.append("E")
        default:
            letterGrades.append("Invalid Grade")
        }
    }

    return letterGrades
}
```
 // XCTAssertTrue failed

func primeLength(string: String) -> Bool {
    let length = string.count
    if length < 2 {
        return false
    }
    for i in 2..<length {
        if length % i == 0 {
            return false
        }
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false[/INST]  ```swift
func primeLength(string: String) -> Bool {
    let length = string.count
    if length < 2 {
        return false
    }
    for i in 2..<length {
        if length % i == 0 {
            return false
        }
    }
    return true
}
```

func primeLength(string: String) -> Bool {
    let length = string.count
    if length <= 1 {
        return false
    }
    if length <= 3 {
        return true
    }
    if length % 2 == 0 || length % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= length {
        if length % i == 0 || length % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false[/INST]  ```swift
func primeLength(string: String) -> Bool {
    let length = string.count
    if length <= 1 {
        return false
    }
    if length <= 3 {
        return true
    }
    if length % 2 == 0 || length % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= length {
        if length % i == 0 || length % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func primeLength(string: String) -> Bool {
    let length = string.count
    if length <= 1 {
        return false
    }
    if length <= 3 {
        return true
    }
    if length % 2 == 0 || length % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= length {
        if length % i == 0 || length % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false[/INST]  ```swift
func primeLength(string: String) -> Bool {
    let length = string.count
    if length <= 1 {
        return false
    }
    if length <= 3 {
        return true
    }
    if length % 2 == 0 || length % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= length {
        if length % i == 0 || length % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func primeLength(string: String) -> Bool {
    let length = string.count
    if length <= 1 {
        return false
    }
    if length <= 3 {
        return true
    }
    if length % 2 == 0 || length % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= length {
        if length % i == 0 || length % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false[/INST]  ```swift
func primeLength(string: String) -> Bool {
    let length = string.count
    if length <= 1 {
        return false
    }
    if length <= 3 {
        return true
    }
    if length % 2 == 0 || length % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= length {
        if length % i == 0 || length % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func primeLength(string: String) -> Bool {
    let length = string.count
    if length <= 1 {
        return false
    }
    if length <= 3 {
        return true
    }
    if length % 2 == 0 || length % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= length {
        if length % i == 0 || length % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false[/INST]  ```swift
func primeLength(string: String) -> Bool {
    let length = string.count
    if length <= 1 {
        return false
    }
    if length <= 3 {
        return true
    }
    if length % 2 == 0 || length % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= length {
        if length % i == 0 || length % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func primeLength(string: String) -> Bool {
    let length = string.count
    if length < 2 {
        return false
    }
    for i in 2..<length {
        if length % i == 0 {
            return false
        }
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false[/INST]  ```swift
func primeLength(string: String) -> Bool {
    let length = string.count
    if length < 2 {
        return false
    }
    for i in 2..<length {
        if length % i == 0 {
            return false
        }
    }
    return true
}
```

func primeLength(string: String) -> Bool {
    let length = string.count
    if length < 2 {
        return false
    }
    for i in 2..<length {
        if length % i == 0 {
            return false
        }
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false[/INST]  ```swift
func primeLength(string: String) -> Bool {
    let length = string.count
    if length < 2 {
        return false
    }
    for i in 2..<length {
        if length % i == 0 {
            return false
        }
    }
    return true
}
```

func primeLength(string: String) -> Bool {
    let length = string.count
    if length < 2 {
        return false
    }
    for i in 2..<length {
        if length % i == 0 {
            return false
        }
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false[/INST]  ```swift
func primeLength(string: String) -> Bool {
    let length = string.count
    if length < 2 {
        return false
    }
    for i in 2..<length {
        if length % i == 0 {
            return false
        }
    }
    return true
}
```

func primeLength(string: String) -> Bool {
    let length = string.count
    if length <= 1 {
        return false
    }
    if length <= 3 {
        return true
    }
    if length % 2 == 0 || length % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= length {
        if length % i == 0 || length % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false[/INST]  ```swift
func primeLength(string: String) -> Bool {
    let length = string.count
    if length <= 1 {
        return false
    }
    if length <= 3 {
        return true
    }
    if length % 2 == 0 || length % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= length {
        if length % i == 0 || length % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func primeLength(string: String) -> Bool {
    let length = string.count
    if length <= 1 {
        return false
    }
    if length <= 3 {
        return true
    }
    if length % 2 == 0 || length % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= length {
        if length % i == 0 || length % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false[/INST]  ```swift
func primeLength(string: String) -> Bool {
    let length = string.count
    if length <= 1 {
        return false
    }
    if length <= 3 {
        return true
    }
    if length % 2 == 0 || length % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= length {
        if length % i == 0 || length % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func startsOneEnds(n: Int) -> Int {
    if n == 1 {
        return 1
    }

    var dp = Array(repeating: Array(repeating: 0, count: 2), count: n + 1)
    dp[1][0] = 1
    dp[1][1] = 1

    for i in 2...n {
        dp[i][0] = dp[i - 1][0] * 9 + dp[i - 1][1]
        dp[i][1] = dp[i - 1][0] + dp[i - 1][1] * 9
    }

    return dp[n][0] + dp[n][1]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
[/INST]  ```swift
func startsOneEnds(n: Int) -> Int {
    if n == 1 {
        return 1
    }

    var dp = Array(repeating: Array(repeating: 0, count: 2), count: n + 1)
    dp[1][0] = 1
    dp[1][1] = 1

    for i in 2...n {
        dp[i][0] = dp[i - 1][0] * 9 + dp[i - 1][1]
        dp[i][1] = dp[i - 1][0] + dp[i - 1][1] * 9
    }

    return dp[n][0] + dp[n][1]
}
```
 // XCTAssertTrue failed

func startsOneEnds(n: Int) -> Int {
    if n == 1 {
        return 1
    }

    var dp = Array(repeating: Array(repeating: 0, count: 2), count: n + 1)
    dp[1][0] = 1
    dp[1][1] = 1

    for i in 2...n {
        dp[i][0] = dp[i - 1][0] * 9 + dp[i - 1][1]
        dp[i][1] = dp[i - 1][0] + dp[i - 1][1] * 9
    }

    return dp[n][0] + dp[n][1]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
[/INST]  ```swift
func startsOneEnds(n: Int) -> Int {
    if n == 1 {
        return 1
    }

    var dp = Array(repeating: Array(repeating: 0, count: 2), count: n + 1)
    dp[1][0] = 1
    dp[1][1] = 1

    for i in 2...n {
        dp[i][0] = dp[i - 1][0] * 9 + dp[i - 1][1]
        dp[i][1] = dp[i - 1][0] + dp[i - 1][1] * 9
    }

    return dp[n][0] + dp[n][1]
}
```
 // XCTAssertTrue failed

func startsOneEnds(n: Int) -> Int {
    if n == 1 {
        return 1
    }

    var dp = Array(repeating: Array(repeating: 0, count: 2), count: n + 1)
    dp[1][0] = 1
    dp[1][1] = 1

    for i in 2...n {
        dp[i][0] = dp[i - 1][0] * 9 + dp[i - 1][1]
        dp[i][1] = dp[i - 1][0] + dp[i - 1][1] * 9
    }

    return dp[n][0] + dp[n][1]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
[/INST]  ```swift
func startsOneEnds(n: Int) -> Int {
    if n == 1 {
        return 1
    }

    var dp = Array(repeating: Array(repeating: 0, count: 2), count: n + 1)
    dp[1][0] = 1
    dp[1][1] = 1

    for i in 2...n {
        dp[i][0] = dp[i - 1][0] * 9 + dp[i - 1][1]
        dp[i][1] = dp[i - 1][0] + dp[i - 1][1] * 9
    }

    return dp[n][0] + dp[n][1]
}
```
 // XCTAssertTrue failed

func startsOneEnds(n: Int) -> Int {
    if n == 1 {
        return 1
    }

    var dp = Array(repeating: Array(repeating: 0, count: 2), count: n+1)
    dp[1][0] = 1
    dp[1][1] = 1

    for i in 2...n {
        dp[i][0] = dp[i-1][0] + dp[i-1][1]
        dp[i][1] = dp[i-1][0]
    }

    return dp[n][0] + dp[n][1]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
[/INST]  ```swift
func startsOneEnds(n: Int) -> Int {
    if n == 1 {
        return 1
    }

    var dp = Array(repeating: Array(repeating: 0, count: 2), count: n+1)
    dp[1][0] = 1
    dp[1][1] = 1

    for i in 2...n {
        dp[i][0] = dp[i-1][0] + dp[i-1][1]
        dp[i][1] = dp[i-1][0]
    }

    return dp[n][0] + dp[n][1]
}
```
 // XCTAssertTrue failed

func startsOneEnds(n: Int) -> Int {
    if n == 1 {
        return 1
    }
    if n == 2 {
        return 18
    }
    var count = 18
    var a = 9, b = 9
    for _ in 3...n {
        let temp = a
        a = 9 * a + b
        b = temp
    }
    count += 2 * a
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
[/INST]  ```swift
func startsOneEnds(n: Int) -> Int {
    if n == 1 {
        return 1
    }
    if n == 2 {
        return 18
    }
    var count = 18
    var a = 9, b = 9
    for _ in 3...n {
        let temp = a
        a = 9 * a + b
        b = temp
    }
    count += 2 * a
    return count
}
```
 // XCTAssertTrue failed

func startsOneEnds(n: Int) -> Int {
    if n == 1 {
        return 1
    }

    var dp = Array(repeating: Array(repeating: 0, count: 2), count: n + 1)
    dp[1][0] = 1
    dp[1][1] = 1

    for i in 2...n {
        dp[i][0] = dp[i - 1][0] * 9 + dp[i - 1][1]
        dp[i][1] = dp[i - 1][0] + dp[i - 1][1] * 9
    }

    return dp[n][0] + dp[n][1]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
[/INST]  ```swift
func startsOneEnds(n: Int) -> Int {
    if n == 1 {
        return 1
    }

    var dp = Array(repeating: Array(repeating: 0, count: 2), count: n + 1)
    dp[1][0] = 1
    dp[1][1] = 1

    for i in 2...n {
        dp[i][0] = dp[i - 1][0] * 9 + dp[i - 1][1]
        dp[i][1] = dp[i - 1][0] + dp[i - 1][1] * 9
    }

    return dp[n][0] + dp[n][1]
}
```
 // XCTAssertTrue failed

func startsOneEnds(n: Int) -> Int {
    if n == 1 {
        return 1
    }
    if n == 2 {
        return 18
    }
    var count = 18
    var a = 1, b = 8, c = 9
    for _ in 3...n {
        let temp = (a + b) * 2
        a = b
        b = c
        c = temp
    }
    count += c
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
[/INST]  ```swift
func startsOneEnds(n: Int) -> Int {
    if n == 1 {
        return 1
    }
    if n == 2 {
        return 18
    }
    var count = 18
    var a = 1, b = 8, c = 9
    for _ in 3...n {
        let temp = (a + b) * 2
        a = b
        b = c
        c = temp
    }
    count += c
    return count
}
  ```
 // XCTAssertTrue failed

func startsOneEnds(n: Int) -> Int {
    if n == 1 {
        return 1
    }

    var dp = Array(repeating: Array(repeating: 0, count: 2), count: n + 1)
    dp[1][0] = 1
    dp[1][1] = 1

    for len in 2...n {
        dp[len][0] = dp[len - 1][0] * 9 + dp[len - 1][1]
        dp[len][1] = dp[len - 1][0] + dp[len - 1][1] * 9
    }

    return dp[n][0] + dp[n][1]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
[/INST]  ```swift
func startsOneEnds(n: Int) -> Int {
    if n == 1 {
        return 1
    }

    var dp = Array(repeating: Array(repeating: 0, count: 2), count: n + 1)
    dp[1][0] = 1
    dp[1][1] = 1

    for len in 2...n {
        dp[len][0] = dp[len - 1][0] * 9 + dp[len - 1][1]
        dp[len][1] = dp[len - 1][0] + dp[len - 1][1] * 9
    }

    return dp[n][0] + dp[n][1]
}
```
 // XCTAssertTrue failed

func startsOneEnds(n: Int) -> Int {
    if n == 1 {
        return 1
    }

    var dp = Array(repeating: Array(repeating: 0, count: 2), count: n + 1)
    dp[1][0] = 1
    dp[1][1] = 1

    for i in 2...n {
        dp[i][0] = dp[i - 1][0] * 9 + dp[i - 1][1]
        dp[i][1] = dp[i - 1][0] + dp[i - 1][1] * 9
    }

    return dp[n][0] + dp[n][1] - 9
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
[/INST]  ```swift
func startsOneEnds(n: Int) -> Int {
    if n == 1 {
        return 1
    }

    var dp = Array(repeating: Array(repeating: 0, count: 2), count: n + 1)
    dp[1][0] = 1
    dp[1][1] = 1

    for i in 2...n {
        dp[i][0] = dp[i - 1][0] * 9 + dp[i - 1][1]
        dp[i][1] = dp[i - 1][0] + dp[i - 1][1] * 9
    }

    return dp[n][0] + dp[n][1] - 9
}
  ```
 // XCTAssertTrue failed

func startsOneEnds(n: Int) -> Int {
    if n == 1 {
        return 1
    }

    var dp = Array(repeating: Array(repeating: 0, count: 2), count: n + 1)
    dp[1][0] = 1
    dp[1][1] = 1

    for i in 2...n {
        dp[i][0] = dp[i - 1][0] * 9 + dp[i - 1][1]
        dp[i][1] = dp[i - 1][0] + dp[i - 1][1] * 9
    }

    return dp[n][0] + dp[n][1] - 9
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
[/INST]  ```swift
func startsOneEnds(n: Int) -> Int {
    if n == 1 {
        return 1
    }

    var dp = Array(repeating: Array(repeating: 0, count: 2), count: n + 1)
    dp[1][0] = 1
    dp[1][1] = 1

    for i in 2...n {
        dp[i][0] = dp[i - 1][0] * 9 + dp[i - 1][1]
        dp[i][1] = dp[i - 1][0] + dp[i - 1][1] * 9
    }

    return dp[n][0] + dp[n][1] - 9
}
```
 // XCTAssertTrue failed

@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"[/INST]  ```swift
func solve(N: Int) -> String {
    let binary = String(N, radix: 2)
    var sum = 0
    for digit in binary {
        if let num = Int(String(digit)) {
            sum += num
        }
    }
    return String(sum, radix: 2)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"[/INST]  ```swift
func solve(N: Int) -> String {
    let binary = String(N, radix: 2)
    var sum = 0
    for digit in binary {
        if let num = Int(String(digit)) {
            sum += num
        }
    }
    return String(sum, radix: 2)
}
```
@N integer // cannot find type 'integer' in scope
@N integer // unknown attribute 'N'
Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'
Constraints: 0 ≤ N ≤ 10000. // expected expression
Constraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'
Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scope

@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"[/INST]  ```swift
func solve(N: Int) -> String {
    let binary = String(N, radix: 2)
    var sum = 0
    for digit in binary {
        if let num = Int(String(digit)) {
            sum += num
        }
    }
    return String(sum, radix: 2)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"[/INST]  ```swift
func solve(N: Int) -> String {
    let binary = String(N, radix: 2)
    var sum = 0
    for digit in binary {
        if let num = Int(String(digit)) {
            sum += num
        }
    }
    return String(sum, radix: 2)
}
```
@N integer // cannot find type 'integer' in scope
@N integer // unknown attribute 'N'
Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'
Constraints: 0 ≤ N ≤ 10000. // expected expression
Constraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'
Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scope

@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"[/INST]  ```swift
func solve(N: Int) -> String {
    let binary = String(N, radix: 2)
    var sum = 0
    for digit in binary {
        if let num = Int(String(digit)) {
            sum += num
        }
    }
    return String(sum, radix: 2)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"[/INST]  ```swift
func solve(N: Int) -> String {
    let binary = String(N, radix: 2)
    var sum = 0
    for digit in binary {
        if let num = Int(String(digit)) {
            sum += num
        }
    }
    return String(sum, radix: 2)
}
```
@N integer // cannot find type 'integer' in scope
@N integer // unknown attribute 'N'
Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'
Constraints: 0 ≤ N ≤ 10000. // expected expression
Constraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'
Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scope

@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"[/INST]  ```swift
func solve(N: Int) -> String {
    let binary = String(N, radix: 2)
    var sum = 0
    for digit in binary {
        if let num = Int(String(digit)) {
            sum += num
        }
    }
    return String(sum, radix: 2)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"[/INST]  ```swift
func solve(N: Int) -> String {
    let binary = String(N, radix: 2)
    var sum = 0
    for digit in binary {
        if let num = Int(String(digit)) {
            sum += num
        }
    }
    return String(sum, radix: 2)
}
```
@N integer // cannot find type 'integer' in scope
@N integer // unknown attribute 'N'
Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'
Constraints: 0 ≤ N ≤ 10000. // expected expression
Constraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'
Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scope

@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"[/INST]  ```swift
func solve(N: Int) -> String {
    var num = N
    var binarySum = 0

    while num > 0 {
        binarySum += num % 2
        num /= 2
    }

    return String(binarySum, radix: 2)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"[/INST]  ```swift
func solve(N: Int) -> String {
    var num = N
    var binarySum = 0

    while num > 0 {
        binarySum += num % 2
        num /= 2
    }

    return String(binarySum, radix: 2)
}
```
@N integer // cannot find type 'integer' in scope
@N integer // unknown attribute 'N'
Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'
Constraints: 0 ≤ N ≤ 10000. // expected expression
Constraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'
Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scope

@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"[/INST]  ```swift
func solve(N: Int) -> String {
    let binary = String(N, radix: 2)
    var sum = 0
    for digit in binary {
        if let num = Int(String(digit)) {
            sum += num
        }
    }
    return String(sum, radix: 2)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"[/INST]  ```swift
func solve(N: Int) -> String {
    let binary = String(N, radix: 2)
    var sum = 0
    for digit in binary {
        if let num = Int(String(digit)) {
            sum += num
        }
    }
    return String(sum, radix: 2)
}
```
@N integer // cannot find type 'integer' in scope
@N integer // unknown attribute 'N'
Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'
Constraints: 0 ≤ N ≤ 10000. // expected expression
Constraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'
Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scope

@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"[/INST]  ```swift
func solve(N: Int) -> String {
    let binary = String(N, radix: 2)
    var sum = 0
    for digit in binary {
        if let num = Int(String(digit)) {
            sum += num
        }
    }
    return String(sum, radix: 2)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"[/INST]  ```swift
func solve(N: Int) -> String {
    let binary = String(N, radix: 2)
    var sum = 0
    for digit in binary {
        if let num = Int(String(digit)) {
            sum += num
        }
    }
    return String(sum, radix: 2)
}
```
@N integer // cannot find type 'integer' in scope
@N integer // unknown attribute 'N'
Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'
Constraints: 0 ≤ N ≤ 10000. // expected expression
Constraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'
Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scope

@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"[/INST]  ```swift
func solve(N: Int) -> String {
    let binary = String(N, radix: 2)
    var sum = 0
    for digit in binary {
        if let num = Int(String(digit)) {
            sum += num
        }
    }
    return String(sum, radix: 2)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"[/INST]  ```swift
func solve(N: Int) -> String {
    let binary = String(N, radix: 2)
    var sum = 0
    for digit in binary {
        if let num = Int(String(digit)) {
            sum += num
        }
    }
    return String(sum, radix: 2)
}
```
@N integer // cannot find type 'integer' in scope
@N integer // unknown attribute 'N'
Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'
Constraints: 0 ≤ N ≤ 10000. // expected expression
Constraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'
Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scope

@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"[/INST]  ```swift
func solve(N: Int) -> String {
    let binary = String(N, radix: 2)
    var sum = 0
    for digit in binary {
        if let num = Int(String(digit)) {
            sum += num
        }
    }
    return String(sum, radix: 2)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"[/INST]  ```swift
func solve(N: Int) -> String {
    let binary = String(N, radix: 2)
    var sum = 0
    for digit in binary {
        if let num = Int(String(digit)) {
            sum += num
        }
    }
    return String(sum, radix: 2)
}
```
@N integer // cannot find type 'integer' in scope
@N integer // unknown attribute 'N'
Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'
Constraints: 0 ≤ N ≤ 10000. // expected expression
Constraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'
Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scope

@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"[/INST]  ```swift
func solve(N: Int) -> String {
    let binary = String(N, radix: 2)
    var sum = 0
    for digit in binary {
        if let num = Int(String(digit)) {
            sum += num
        }
    }
    return String(sum, radix: 2)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"[/INST]  ```swift
func solve(N: Int) -> String {
    let binary = String(N, radix: 2)
    var sum = 0
    for digit in binary {
        if let num = Int(String(digit)) {
            sum += num
        }
    }
    return String(sum, radix: 2)
}
```
@N integer // cannot find type 'integer' in scope
@N integer // unknown attribute 'N'
Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'
Constraints: 0 ≤ N ≤ 10000. // expected expression
Constraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'
Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scope

func add(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 1, to: lst.count, by: 2) {
        if lst[i] % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2[/INST]  ```swift
func add(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 1, to: lst.count, by: 2) {
        if lst[i] % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func add(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 1, to: lst.count, by: 2) {
        if lst[i] % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2[/INST]  ```swift
func add(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 1, to: lst.count, by: 2) {
        if lst[i] % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func add(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 1, to: lst.count, by: 2) {
        if lst[i] % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2[/INST]  ```swift
func add(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 1, to: lst.count, by: 2) {
        if lst[i] % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func add(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 1, to: lst.count, by: 2) {
        if lst[i] % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2[/INST]  ```swift
func add(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 1, to: lst.count, by: 2) {
        if lst[i] % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func add(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 1, to: lst.count, by: 2) {
        if lst[i] % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2[/INST]  ```swift
func add(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 1, to: lst.count, by: 2) {
        if lst[i] % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func add(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 1, to: lst.count, by: 2) {
        if lst[i] % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2[/INST]  ```swift
func add(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 1, to: lst.count, by: 2) {
        if lst[i] % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func add(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 1, to: lst.count, by: 2) {
        if lst[i] % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2[/INST]  ```swift
func add(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 1, to: lst.count, by: 2) {
        if lst[i] % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func add(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 1, to: lst.count, by: 2) {
        if lst[i] % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2[/INST]  ```swift
func add(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 1, to: lst.count, by: 2) {
        if lst[i] % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func add(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 1, to: lst.count, by: 2) {
        if lst[i] % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2[/INST]  ```swift
func add(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 1, to: lst.count, by: 2) {
        if lst[i] % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func add(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 1, to: lst.count, by: 2) {
        if lst[i] % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2[/INST]  ```swift
func add(lst: [Int]) -> Int {
    var sum = 0
    for i in stride(from: 1, to: lst.count, by: 2) {
        if lst[i] % 2 == 0 {
            sum += lst[i]
        }
    }
    return sum
}
```

func antiShuffle(s: String) -> String {
    let words = s.split(separator: " ")
    var result = [String]()

    for word in words {
        let sortedChars = word.sorted()
        result.append(String(sortedChars))
    }

    return result.joined(separator: " ")
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello !!!Wdlor"[/INST]  ```swift
func antiShuffle(s: String) -> String {
    let words = s.split(separator: " ")
    var result = [String]()

    for word in words {
        let sortedChars = word.sorted()
        result.append(String(sortedChars))
    }

    return result.joined(separator: " ")
}
```

func antiShuffle(s: String) -> String {
    let words = s.components(separatedBy: " ")
    var orderedWords: [String] = []

    for word in words {
        let orderedWord = String(word.sorted(by: <))
        orderedWords.append(orderedWord)
    }

    return orderedWords.joined(separator: " ")
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello !!!Wdlor"[/INST]  ```swift
func antiShuffle(s: String) -> String {
    let words = s.components(separatedBy: " ")
    var orderedWords: [String] = []

    for word in words {
        let orderedWord = String(word.sorted(by: <))
        orderedWords.append(orderedWord)
    }

    return orderedWords.joined(separator: " ")
}
```

func antiShuffle(s: String) -> String {
    let words = s.components(separatedBy: " ")
    var orderedWords: [String] = []

    for word in words {
        let characters = word.map { String($0) }.sorted()
        let orderedWord = characters.joined()
        orderedWords.append(orderedWord)
    }

    return orderedWords.joined(separator: " ")
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello !!!Wdlor"[/INST]  ```swift
func antiShuffle(s: String) -> String {
    let words = s.components(separatedBy: " ")
    var orderedWords: [String] = []

    for word in words {
        let characters = word.map { String($0) }.sorted()
        let orderedWord = characters.joined()
        orderedWords.append(orderedWord)
    }

    return orderedWords.joined(separator: " ")
}
```

func antiShuffle(s: String) -> String {
    let words = s.components(separatedBy: " ")
    var orderedWords: [String] = []

    for word in words {
        let orderedWord = String(word.sorted())
        orderedWords.append(orderedWord)
    }

    return orderedWords.joined(separator: " ")
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello !!!Wdlor"[/INST]  ```swift
func antiShuffle(s: String) -> String {
    let words = s.components(separatedBy: " ")
    var orderedWords: [String] = []

    for word in words {
        let orderedWord = String(word.sorted())
        orderedWords.append(orderedWord)
    }

    return orderedWords.joined(separator: " ")
}
```

func antiShuffle(s: String) -> String {
    let words = s.split(separator: " ")
    var result = [String]()

    for word in words {
        var chars = Array(word)
        chars.sort()
        result.append(String(chars))
    }

    return result.joined(separator: " ")
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello !!!Wdlor"[/INST]  ```swift
func antiShuffle(s: String) -> String {
    let words = s.split(separator: " ")
    var result = [String]()

    for word in words {
        var chars = Array(word)
        chars.sort()
        result.append(String(chars))
    }

    return result.joined(separator: " ")
}
```

func antiShuffle(s: String) -> String {
    let words = s.components(separatedBy: " ")
    var orderedWords: [String] = []

    for word in words {
        let orderedWord = String(word.sorted(by: <))
        orderedWords.append(orderedWord)
    }

    return orderedWords.joined(separator: " ")
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello !!!Wdlor"[/INST]  ```swift
func antiShuffle(s: String) -> String {
    let words = s.components(separatedBy: " ")
    var orderedWords: [String] = []

    for word in words {
        let orderedWord = String(word.sorted(by: <))
        orderedWords.append(orderedWord)
    }

    return orderedWords.joined(separator: " ")
}
```

func antiShuffle(s: String) -> String {
    return s.components(separatedBy: " ").map { String($0.sorted()) }.joined(separator: " ")
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello !!!Wdlor"[/INST]  ```swift
func antiShuffle(s: String) -> String {
    return s.components(separatedBy: " ").map { String($0.sorted()) }.joined(separator: " ")
}
```

func antiShuffle(s: String) -> String {
    let words = s.components(separatedBy: " ")
    var orderedWords: [String] = []

    for word in words {
        let orderedWord = String(word.sorted(by: <))
        orderedWords.append(orderedWord)
    }

    return orderedWords.joined(separator: " ")
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello !!!Wdlor"[/INST]  ```swift
func antiShuffle(s: String) -> String {
    let words = s.components(separatedBy: " ")
    var orderedWords: [String] = []

    for word in words {
        let orderedWord = String(word.sorted(by: <))
        orderedWords.append(orderedWord)
    }

    return orderedWords.joined(separator: " ")
}
```

func antiShuffle(s: String) -> String {
    let words = s.components(separatedBy: " ")
    var orderedWords: [String] = []

    for word in words {
        let orderedWord = String(word.sorted())
        orderedWords.append(orderedWord)
    }

    return orderedWords.joined(separator: " ")
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello !!!Wdlor"[/INST]  ```swift
func antiShuffle(s: String) -> String {
    let words = s.components(separatedBy: " ")
    var orderedWords: [String] = []

    for word in words {
        let orderedWord = String(word.sorted())
        orderedWords.append(orderedWord)
    }

    return orderedWords.joined(separator: " ")
}
```

func antiShuffle(s: String) -> String {
    let words = s.components(separatedBy: " ")
    var orderedWords = [String]()

    for word in words {
        let sortedChars = word.sorted()
        let orderedWord = String(sortedChars)
        orderedWords.append(orderedWord)
    }

    return orderedWords.joined(separator: " ")
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello !!!Wdlor"[/INST]  ```swift
func antiShuffle(s: String) -> String {
    let words = s.components(separatedBy: " ")
    var orderedWords = [String]()

    for word in words {
        let sortedChars = word.sorted()
        let orderedWord = String(sortedChars)
        orderedWords.append(orderedWord)
    }

    return orderedWords.joined(separator: " ")
}
```

func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
    var coordinates: [(Int, Int)] = []

    for (rowIndex, row) in lst.enumerated() {
        for (colIndex, col) in row.enumerated() {
            if col == x {
                coordinates.append((rowIndex, colIndex))
            }
        }
    }

    coordinates.sort {
        if $0.0 == $1.0 {
            return $0.1 > $1.1
        } else {
            return $0.0 < $1.0
        }
    }

    return coordinates
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)][/INST]  ```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
    var coordinates: [(Int, Int)] = []

    for (rowIndex, row) in lst.enumerated() {
        for (colIndex, col) in row.enumerated() {
            if col == x {
                coordinates.append((rowIndex, colIndex))
            }
        }
    }

    coordinates.sort {
        if $0.0 == $1.0 {
            return $0.1 > $1.1
        } else {
            return $0.0 < $1.0
        }
    }

    return coordinates
}
```

func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
    var coordinates: [(Int, Int)] = []

    for (rowIndex, row) in lst.enumerated() {
        for (colIndex, col) in row.enumerated() {
            if col == x {
                coordinates.append((rowIndex, colIndex))
            }
        }
    }

    coordinates.sort {
        if $0.0 == $1.0 {
            return $0.1 > $1.1
        } else {
            return $0.0 < $1.0
        }
    }

    return coordinates
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)][/INST]  ```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
    var coordinates: [(Int, Int)] = []

    for (rowIndex, row) in lst.enumerated() {
        for (colIndex, col) in row.enumerated() {
            if col == x {
                coordinates.append((rowIndex, colIndex))
            }
        }
    }

    coordinates.sort {
        if $0.0 == $1.0 {
            return $0.1 > $1.1
        } else {
            return $0.0 < $1.0
        }
    }

    return coordinates
}
```

func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
    var coordinates: [(Int, Int)] = []

    for (rowIndex, row) in lst.enumerated() {
        for (colIndex, col) in row.enumerated() {
            if col == x {
                coordinates.append((rowIndex, colIndex))
            }
        }
    }

    coordinates.sort {
        if $0.0 == $1.0 {
            return $0.1 > $1.1
        } else {
            return $0.0 < $1.0
        }
    }

    return coordinates
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)][/INST]  ```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
    var coordinates: [(Int, Int)] = []

    for (rowIndex, row) in lst.enumerated() {
        for (colIndex, col) in row.enumerated() {
            if col == x {
                coordinates.append((rowIndex, colIndex))
            }
        }
    }

    coordinates.sort {
        if $0.0 == $1.0 {
            return $0.1 > $1.1
        } else {
            return $0.0 < $1.0
        }
    }

    return coordinates
}
```

func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
    var result: [(Int, Int)] = []

    for (rowIndex, row) in lst.enumerated() {
        for (colIndex, col) in row.enumerated() {
            if col == x {
                result.append((rowIndex, colIndex))
            }
        }
    }

    result.sort {
        if $0.0 == $1.0 {
            return $0.1 > $1.1
        } else {
            return $0.0 < $1.0
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)][/INST]  ```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
    var result: [(Int, Int)] = []

    for (rowIndex, row) in lst.enumerated() {
        for (colIndex, col) in row.enumerated() {
            if col == x {
                result.append((rowIndex, colIndex))
            }
        }
    }

    result.sort {
        if $0.0 == $1.0 {
            return $0.1 > $1.1
        } else {
            return $0.0 < $1.0
        }
    }

    return result
}
```

func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
    var result: [(Int, Int)] = []

    for (rowIndex, row) in lst.enumerated() {
        for (colIndex, col) in row.enumerated() {
            if col == x {
                result.append((rowIndex, colIndex))
            }
        }
    }

    result.sort {
        if $0.0 == $1.0 {
            return $0.1 > $1.1
        } else {
            return $0.0 < $1.0
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)][/INST]  ```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
    var result: [(Int, Int)] = []

    for (rowIndex, row) in lst.enumerated() {
        for (colIndex, col) in row.enumerated() {
            if col == x {
                result.append((rowIndex, colIndex))
            }
        }
    }

    result.sort {
        if $0.0 == $1.0 {
            return $0.1 > $1.1
        } else {
            return $0.0 < $1.0
        }
    }

    return result
}
```

func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
    var coordinates: [(Int, Int)] = []

    for (rowIndex, row) in lst.enumerated() {
        for (colIndex, col) in row.enumerated() {
            if col == x {
                coordinates.append((rowIndex, colIndex))
            }
        }
    }

    coordinates.sort {
        if $0.0 == $1.0 {
            return $0.1 > $1.1
        } else {
            return $0.0 < $1.0
        }
    }

    return coordinates
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)][/INST]  ```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
    var coordinates: [(Int, Int)] = []

    for (rowIndex, row) in lst.enumerated() {
        for (colIndex, col) in row.enumerated() {
            if col == x {
                coordinates.append((rowIndex, colIndex))
            }
        }
    }

    coordinates.sort {
        if $0.0 == $1.0 {
            return $0.1 > $1.1
        } else {
            return $0.0 < $1.0
        }
    }

    return coordinates
}
```

func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
    var result: [(Int, Int)] = []
    for (i, row) in lst.enumerated() {
        for (j, num) in row.enumerated() {
            if num == x {
                result.append((i, j))
            }
        }
    }
    result.sort {
        if $0.0 == $1.0 {
            return $0.1 > $1.1
        } else {
            return $0.0 < $1.0
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)][/INST]  ```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
    var result: [(Int, Int)] = []
    for (i, row) in lst.enumerated() {
        for (j, num) in row.enumerated() {
            if num == x {
                result.append((i, j))
            }
        }
    }
    result.sort {
        if $0.0 == $1.0 {
            return $0.1 > $1.1
        } else {
            return $0.0 < $1.0
        }
    }
    return result
}
```

func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
    var result: [(Int, Int)] = []
    for (rowIndex, row) in lst.enumerated() {
        for (colIndex, col) in row.enumerated() {
            if col == x {
                result.append((rowIndex, colIndex))
            }
        }
    }
    result.sort {
        if $0.0 == $1.0 {
            return $0.1 > $1.1
        } else {
            return $0.0 < $1.0
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)][/INST]  ```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
    var result: [(Int, Int)] = []
    for (rowIndex, row) in lst.enumerated() {
        for (colIndex, col) in row.enumerated() {
            if col == x {
                result.append((rowIndex, colIndex))
            }
        }
    }
    result.sort {
        if $0.0 == $1.0 {
            return $0.1 > $1.1
        } else {
            return $0.0 < $1.0
        }
    }
    return result
}
```

func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
    var result: [(Int, Int)] = []
    for (i, row) in lst.enumerated() {
        for (j, num) in row.enumerated() {
            if num == x {
                result.append((i, j))
            }
        }
    }
    result.sort {
        if $0.0 == $1.0 {
            return $0.1 > $1.1
        } else {
            return $0.0 < $1.0
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)][/INST]  ```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
    var result: [(Int, Int)] = []
    for (i, row) in lst.enumerated() {
        for (j, num) in row.enumerated() {
            if num == x {
                result.append((i, j))
            }
        }
    }
    result.sort {
        if $0.0 == $1.0 {
            return $0.1 > $1.1
        } else {
            return $0.0 < $1.0
        }
    }
    return result
}
```

func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
    var result: [(Int, Int)] = []

    for (rowIndex, row) in lst.enumerated() {
        for (colIndex, col) in row.enumerated() {
            if col == x {
                result.append((rowIndex, colIndex))
            }
        }
    }

    return result.sorted {
        if $0.0 == $1.0 {
            return $0.1 > $1.1
        } else {
            return $0.0 < $1.0
        }
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)][/INST]  ```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
    var result: [(Int, Int)] = []

    for (rowIndex, row) in lst.enumerated() {
        for (colIndex, col) in row.enumerated() {
            if col == x {
                result.append((rowIndex, colIndex))
            }
        }
    }

    return result.sorted {
        if $0.0 == $1.0 {
            return $0.1 > $1.1
        } else {
            return $0.0 < $1.0
        }
    }
}
```

func sortArray(array: [Int]) -> [Int] {
    guard !array.isEmpty else { return [] }

    let sum = array.first! + array.last!
    let sortedArray = array.sorted(by: sum % 2 == 0 ? > : <)

    return sortedArray
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0][/INST]  ```swift
func sortArray(array: [Int]) -> [Int] {
    guard !array.isEmpty else { return [] }

    let sum = array.first! + array.last!
    let sortedArray = array.sorted(by: sum % 2 == 0 ? > : <)

    return sortedArray
}
```
let sum = array.first! + array.last! // initialization of immutable value 'sum' was never used; consider replacing with assignment to '_' or removing it
let sortedArray = array.sorted(by: sum % 2 == 0 ? > : <) // expected expression after '?' in ternary expression
let sortedArray = array.sorted(by: sum % 2 == 0 ? > : <) // unary operator cannot be separated from its operand

func sortArray(array: [Int]) -> [Int] {
    guard !array.isEmpty else {
        return []
    }

    let sum = array.first! + array.last!
    let sortedArray = array.sorted()

    if sum % 2 == 0 {
        return sortedArray.reversed()
    } else {
        return sortedArray
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0][/INST]  ```swift
func sortArray(array: [Int]) -> [Int] {
    guard !array.isEmpty else {
        return []
    }

    let sum = array.first! + array.last!
    let sortedArray = array.sorted()

    if sum % 2 == 0 {
        return sortedArray.reversed()
    } else {
        return sortedArray
    }
}
```

func sortArray(array: [Int]) -> [Int] {
    guard !array.isEmpty else {
        return []
    }

    let first = array.first!
    let last = array.last!

    if (first + last) % 2 == 0 {
        return array.sorted(by: >)
    } else {
        return array.sorted(by: <)
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0][/INST]  ```swift
func sortArray(array: [Int]) -> [Int] {
    guard !array.isEmpty else {
        return []
    }

    let first = array.first!
    let last = array.last!

    if (first + last) % 2 == 0 {
        return array.sorted(by: >)
    } else {
        return array.sorted(by: <)
    }
}
```

func sortArray(array: [Int]) -> [Int] {
    guard !array.isEmpty else {
        return []
    }

    let firstElement = array.first!
    let lastElement = array.last!

    if (firstElement + lastElement) % 2 == 0 {
        return array.sorted(by: >)
    } else {
        return array.sorted(by: <)
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0][/INST]  ```swift
func sortArray(array: [Int]) -> [Int] {
    guard !array.isEmpty else {
        return []
    }

    let firstElement = array.first!
    let lastElement = array.last!

    if (firstElement + lastElement) % 2 == 0 {
        return array.sorted(by: >)
    } else {
        return array.sorted(by: <)
    }
}
```

func sortArray(array: [Int]) -> [Int] {
    guard !array.isEmpty else {
        return []
    }

    let first = array.first!
    let last = array.last!

    if (first + last) % 2 == 0 {
        return array.sorted(by: >)
    } else {
        return array.sorted(by: <)
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0][/INST]  ```swift
func sortArray(array: [Int]) -> [Int] {
    guard !array.isEmpty else {
        return []
    }

    let first = array.first!
    let last = array.last!

    if (first + last) % 2 == 0 {
        return array.sorted(by: >)
    } else {
        return array.sorted(by: <)
    }
}
```

func sortArray(array: [Int]) -> [Int] {
    guard !array.isEmpty else {
        return []
    }

    let first = array.first!
    let last = array.last!
    let sum = first + last

    if sum % 2 == 0 {
        return array.sorted(by: >)
    } else {
        return array.sorted(by: <)
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0][/INST]  ```swift
func sortArray(array: [Int]) -> [Int] {
    guard !array.isEmpty else {
        return []
    }

    let first = array.first!
    let last = array.last!
    let sum = first + last

    if sum % 2 == 0 {
        return array.sorted(by: >)
    } else {
        return array.sorted(by: <)
    }
}
```

func sortArray(array: [Int]) -> [Int] {
    guard !array.isEmpty else {
        return []
    }

    let firstElement = array.first!
    let lastElement = array.last!
    let sum = firstElement + lastElement

    if sum % 2 == 0 {
        return array.sorted(by: >)
    } else {
        return array.sorted(by: <)
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0][/INST]  ```swift
func sortArray(array: [Int]) -> [Int] {
    guard !array.isEmpty else {
        return []
    }

    let firstElement = array.first!
    let lastElement = array.last!
    let sum = firstElement + lastElement

    if sum % 2 == 0 {
        return array.sorted(by: >)
    } else {
        return array.sorted(by: <)
    }
}
```

func sortArray(array: [Int]) -> [Int] {
    guard !array.isEmpty else {
        return []
    }

    let first = array.first!
    let last = array.last!

    if (first + last) % 2 == 0 {
        return array.sorted(by: >)
    } else {
        return array.sorted(by: <)
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0][/INST]  ```swift
func sortArray(array: [Int]) -> [Int] {
    guard !array.isEmpty else {
        return []
    }

    let first = array.first!
    let last = array.last!

    if (first + last) % 2 == 0 {
        return array.sorted(by: >)
    } else {
        return array.sorted(by: <)
    }
}
```

func sortArray(array: [Int]) -> [Int] {
    guard !array.isEmpty else {
        return []
    }

    let first = array.first!
    let last = array.last!

    if (first + last) % 2 == 0 {
        return array.sorted(by: >)
    } else {
        return array.sorted(by: <)
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0][/INST]  ```swift
func sortArray(array: [Int]) -> [Int] {
    guard !array.isEmpty else {
        return []
    }

    let first = array.first!
    let last = array.last!

    if (first + last) % 2 == 0 {
        return array.sorted(by: >)
    } else {
        return array.sorted(by: <)
    }
}
```

func sortArray(array: [Int]) -> [Int] {
    guard !array.isEmpty else {
        return []
    }

    let first = array.first!
    let last = array.last!
    let sum = first + last

    if sum % 2 == 0 {
        return array.sorted(by: >)
    } else {
        return array.sorted(by: <)
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0][/INST]  ```swift
func sortArray(array: [Int]) -> [Int] {
    guard !array.isEmpty else {
        return []
    }

    let first = array.first!
    let last = array.last!
    let sum = first + last

    if sum % 2 == 0 {
        return array.sorted(by: >)
    } else {
        return array.sorted(by: <)
    }
}
```

func encrypt(s: String) -> String {
    let alphabet = Array("abcdefghijklmnopqrstuvwxyz")
    var encryptedString = ""

    for char in s {
        if let index = alphabet.firstIndex(of: Character(char.lowercased())) {
            let newIndex = (index + 2 * 2) % alphabet.count
            let newChar = alphabet[newIndex]
            encryptedString.append(char.isUppercase ? Character(newChar.uppercased()) : newChar)
        } else {
            encryptedString.append(char)
        }
    }

    return encryptedString
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated. 
The alphabet should be rotated in a manner such that the letters 
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"[/INST]  ```swift
func encrypt(s: String) -> String {
    let alphabet = Array("abcdefghijklmnopqrstuvwxyz")
    var encryptedString = ""

    for char in s {
        if let index = alphabet.firstIndex(of: Character(char.lowercased())) {
            let newIndex = (index + 2 * 2) % alphabet.count
            let newChar = alphabet[newIndex]
            encryptedString.append(char.isUppercase ? Character(newChar.uppercased()) : newChar)
        } else {
            encryptedString.append(char)
        }
    }

    return encryptedString
}
```

func encrypt(s: String) -> String {
    let lowercaseAlphabet = Array("abcdefghijklmnopqrstuvwxyz")
    let uppercaseAlphabet = Array("ABCDEFGHIJKLMNOPQRSTUVWXYZ")

    var encryptedString = ""

    for char in s {
        if let index = lowercaseAlphabet.firstIndex(of: char) {
            let newIndex = (index + 2 * 2) % lowercaseAlphabet.count
            encryptedString.append(lowercaseAlphabet[newIndex])
        } else if let index = uppercaseAlphabet.firstIndex(of: char) {
            let newIndex = (index + 2 * 2) % uppercaseAlphabet.count
            encryptedString.append(uppercaseAlphabet[newIndex])
        } else {
            encryptedString.append(char)
        }
    }

    return encryptedString
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated. 
The alphabet should be rotated in a manner such that the letters 
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"[/INST]  ```swift
func encrypt(s: String) -> String {
    let lowercaseAlphabet = Array("abcdefghijklmnopqrstuvwxyz")
    let uppercaseAlphabet = Array("ABCDEFGHIJKLMNOPQRSTUVWXYZ")

    var encryptedString = ""

    for char in s {
        if let index = lowercaseAlphabet.firstIndex(of: char) {
            let newIndex = (index + 2 * 2) % lowercaseAlphabet.count
            encryptedString.append(lowercaseAlphabet[newIndex])
        } else if let index = uppercaseAlphabet.firstIndex(of: char) {
            let newIndex = (index + 2 * 2) % uppercaseAlphabet.count
            encryptedString.append(uppercaseAlphabet[newIndex])
        } else {
            encryptedString.append(char)
        }
    }

    return encryptedString
}
```

func encrypt(s: String) -> String {
    let alphabet = Array("abcdefghijklmnopqrstuvwxyz")
    var encryptedString = ""

    for char in s {
        if let index = alphabet.firstIndex(of: Character(char.lowercased())) {
            let newIndex = (index + 2 * 2) % alphabet.count
            let newChar = alphabet[newIndex]
            encryptedString.append(char.isUppercase ? Character(newChar.uppercased()) : newChar)
        } else {
            encryptedString.append(char)
        }
    }

    return encryptedString
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated. 
The alphabet should be rotated in a manner such that the letters 
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"[/INST]  ```swift
func encrypt(s: String) -> String {
    let alphabet = Array("abcdefghijklmnopqrstuvwxyz")
    var encryptedString = ""

    for char in s {
        if let index = alphabet.firstIndex(of: Character(char.lowercased())) {
            let newIndex = (index + 2 * 2) % alphabet.count
            let newChar = alphabet[newIndex]
            encryptedString.append(char.isUppercase ? Character(newChar.uppercased()) : newChar)
        } else {
            encryptedString.append(char)
        }
    }

    return encryptedString
}
```

func encrypt(s: String) -> String {
    let alphabet = Array("abcdefghijklmnopqrstuvwxyz")
    var encryptedString = ""

    for char in s {
        if let index = alphabet.firstIndex(of: Character(char.lowercased())) {
            let newIndex = (index + 2 * 2) % alphabet.count
            let newChar = alphabet[newIndex]
            encryptedString.append(char.isUppercase ? Character(newChar.uppercased()) : newChar)
        } else {
            encryptedString.append(char)
        }
    }

    return encryptedString
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated. 
The alphabet should be rotated in a manner such that the letters 
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"[/INST]  ```swift
func encrypt(s: String) -> String {
    let alphabet = Array("abcdefghijklmnopqrstuvwxyz")
    var encryptedString = ""

    for char in s {
        if let index = alphabet.firstIndex(of: Character(char.lowercased())) {
            let newIndex = (index + 2 * 2) % alphabet.count
            let newChar = alphabet[newIndex]
            encryptedString.append(char.isUppercase ? Character(newChar.uppercased()) : newChar)
        } else {
            encryptedString.append(char)
        }
    }

    return encryptedString
}
```

func encrypt(s: String) -> String {
    let alphabet = Array("abcdefghijklmnopqrstuvwxyz")
    var encryptedString = ""

    for char in s.lowercased() {
        if let index = alphabet.firstIndex(of: char) {
            let newIndex = (index + 2 * 2) % alphabet.count
            encryptedString.append(alphabet[newIndex])
        } else {
            encryptedString.append(char)
        }
    }

    return encryptedString
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated. 
The alphabet should be rotated in a manner such that the letters 
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"[/INST]  ```swift
func encrypt(s: String) -> String {
    let alphabet = Array("abcdefghijklmnopqrstuvwxyz")
    var encryptedString = ""

    for char in s.lowercased() {
        if let index = alphabet.firstIndex(of: char) {
            let newIndex = (index + 2 * 2) % alphabet.count
            encryptedString.append(alphabet[newIndex])
        } else {
            encryptedString.append(char)
        }
    }

    return encryptedString
}
```

func encrypt(s: String) -> String {
    let alphabet = Array("abcdefghijklmnopqrstuvwxyz")
    let upperAlphabet = Array("ABCDEFGHIJKLMNOPQRSTUVWXYZ")
    var encryptedString = ""

    for char in s {
        if let index = alphabet.firstIndex(of: char) {
            let newIndex = (index + 2 * 2) % alphabet.count
            encryptedString.append(alphabet[newIndex])
        } else if let index = upperAlphabet.firstIndex(of: char) {
            let newIndex = (index + 2 * 2) % upperAlphabet.count
            encryptedString.append(upperAlphabet[newIndex])
        } else {
            encryptedString.append(char)
        }
    }

    return encryptedString
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated. 
The alphabet should be rotated in a manner such that the letters 
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"[/INST]  ```swift
func encrypt(s: String) -> String {
    let alphabet = Array("abcdefghijklmnopqrstuvwxyz")
    let upperAlphabet = Array("ABCDEFGHIJKLMNOPQRSTUVWXYZ")
    var encryptedString = ""

    for char in s {
        if let index = alphabet.firstIndex(of: char) {
            let newIndex = (index + 2 * 2) % alphabet.count
            encryptedString.append(alphabet[newIndex])
        } else if let index = upperAlphabet.firstIndex(of: char) {
            let newIndex = (index + 2 * 2) % upperAlphabet.count
            encryptedString.append(upperAlphabet[newIndex])
        } else {
            encryptedString.append(char)
        }
    }

    return encryptedString
}
```

func encrypt(s: String) -> String {
    let alphabet = Array("abcdefghijklmnopqrstuvwxyz")
    let shiftedAlphabet = Array(alphabet[2..<26] + alphabet[0..<2])

    var encryptedString = ""
    for char in s.lowercased() {
        if let index = alphabet.firstIndex(of: char) {
            encryptedString.append(shiftedAlphabet[index])
        } else {
            encryptedString.append(char)
        }
    }

    return encryptedString
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated. 
The alphabet should be rotated in a manner such that the letters 
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"[/INST]  ```swift
func encrypt(s: String) -> String {
    let alphabet = Array("abcdefghijklmnopqrstuvwxyz")
    let shiftedAlphabet = Array(alphabet[2..<26] + alphabet[0..<2])

    var encryptedString = ""
    for char in s.lowercased() {
        if let index = alphabet.firstIndex(of: char) {
            encryptedString.append(shiftedAlphabet[index])
        } else {
            encryptedString.append(char)
        }
    }

    return encryptedString
}
```
 // XCTAssertTrue failed

func encrypt(s: String) -> String {
    let alphabet = Array("abcdefghijklmnopqrstuvwxyz")
    var encryptedString = ""

    for char in s {
        if let index = alphabet.firstIndex(of: Character(char.lowercased())) {
            let newIndex = (index + 2 * 2) % alphabet.count
            let newChar = alphabet[newIndex]
            encryptedString.append(char.isUppercase ? Character(newChar.uppercased()) : newChar)
        } else {
            encryptedString.append(char)
        }
    }

    return encryptedString
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated. 
The alphabet should be rotated in a manner such that the letters 
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"[/INST]  ```swift
func encrypt(s: String) -> String {
    let alphabet = Array("abcdefghijklmnopqrstuvwxyz")
    var encryptedString = ""

    for char in s {
        if let index = alphabet.firstIndex(of: Character(char.lowercased())) {
            let newIndex = (index + 2 * 2) % alphabet.count
            let newChar = alphabet[newIndex]
            encryptedString.append(char.isUppercase ? Character(newChar.uppercased()) : newChar)
        } else {
            encryptedString.append(char)
        }
    }

    return encryptedString
}
```

func encrypt(s: String) -> String {
    let alphabet = Array("abcdefghijklmnopqrstuvwxyz")
    let upperAlphabet = Array("ABCDEFGHIJKLMNOPQRSTUVWXYZ")
    var encryptedString = ""

    for char in s {
        if let index = alphabet.firstIndex(of: char) {
            let newIndex = (index + 2 * 2) % alphabet.count
            encryptedString.append(alphabet[newIndex])
        } else if let index = upperAlphabet.firstIndex(of: char) {
            let newIndex = (index + 2 * 2) % upperAlphabet.count
            encryptedString.append(upperAlphabet[newIndex])
        } else {
            encryptedString.append(char)
        }
    }

    return encryptedString
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated. 
The alphabet should be rotated in a manner such that the letters 
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"[/INST]  ```swift
func encrypt(s: String) -> String {
    let alphabet = Array("abcdefghijklmnopqrstuvwxyz")
    let upperAlphabet = Array("ABCDEFGHIJKLMNOPQRSTUVWXYZ")
    var encryptedString = ""

    for char in s {
        if let index = alphabet.firstIndex(of: char) {
            let newIndex = (index + 2 * 2) % alphabet.count
            encryptedString.append(alphabet[newIndex])
        } else if let index = upperAlphabet.firstIndex(of: char) {
            let newIndex = (index + 2 * 2) % upperAlphabet.count
            encryptedString.append(upperAlphabet[newIndex])
        } else {
            encryptedString.append(char)
        }
    }

    return encryptedString
}
```

func encrypt(s: String) -> String {
    let alphabet = Array("abcdefghijklmnopqrstuvwxyz")
    var encryptedString = ""

    for char in s {
        if let index = alphabet.firstIndex(of: Character(char.lowercased())) {
            let newIndex = (index + 2 * 2) % alphabet.count
            let newChar = alphabet[newIndex]
            encryptedString.append(char.isUppercase ? Character(newChar.uppercased()) : newChar)
        } else {
            encryptedString.append(char)
        }
    }

    return encryptedString
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated. 
The alphabet should be rotated in a manner such that the letters 
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"[/INST]  ```swift
func encrypt(s: String) -> String {
    let alphabet = Array("abcdefghijklmnopqrstuvwxyz")
    var encryptedString = ""

    for char in s {
        if let index = alphabet.firstIndex(of: Character(char.lowercased())) {
            let newIndex = (index + 2 * 2) % alphabet.count
            let newChar = alphabet[newIndex]
            encryptedString.append(char.isUppercase ? Character(newChar.uppercased()) : newChar)
        } else {
            encryptedString.append(char)
        }
    }

    return encryptedString
}
```

func nextSmallest(lst: [Int]) -> Int? {
    if lst.count < 2 {
        return nil
    }

    var smallest = Int.max
    var secondSmallest = Int.max

    for num in lst {
        if num < smallest {
            secondSmallest = smallest
            smallest = num
        } else if num < secondSmallest && num != smallest {
            secondSmallest = num
        }
    }

    return secondSmallest == Int.max ? nil : secondSmallest
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil[/INST]  ```swift
func nextSmallest(lst: [Int]) -> Int? {
    if lst.count < 2 {
        return nil
    }

    var smallest = Int.max
    var secondSmallest = Int.max

    for num in lst {
        if num < smallest {
            secondSmallest = smallest
            smallest = num
        } else if num < secondSmallest && num != smallest {
            secondSmallest = num
        }
    }

    return secondSmallest == Int.max ? nil : secondSmallest
}
```

func nextSmallest(lst: [Int]) -> Int? {
    var smallest = Int.max
    var secondSmallest = Int.max

    for num in lst {
        if num < smallest {
            secondSmallest = smallest
            smallest = num
        } else if num < secondSmallest && num != smallest {
            secondSmallest = num
        }
    }

    return secondSmallest == Int.max ? nil : secondSmallest
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil[/INST]  ```swift
func nextSmallest(lst: [Int]) -> Int? {
    var smallest = Int.max
    var secondSmallest = Int.max

    for num in lst {
        if num < smallest {
            secondSmallest = smallest
            smallest = num
        } else if num < secondSmallest && num != smallest {
            secondSmallest = num
        }
    }

    return secondSmallest == Int.max ? nil : secondSmallest
}
```

func nextSmallest(lst: [Int]) -> Int? {
    if lst.count < 2 {
        return nil
    }

    var smallest = Int.max
    var secondSmallest = Int.max

    for num in lst {
        if num < smallest {
            secondSmallest = smallest
            smallest = num
        } else if num < secondSmallest && num != smallest {
            secondSmallest = num
        }
    }

    return secondSmallest == Int.max ? nil : secondSmallest
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil[/INST]  ```swift
func nextSmallest(lst: [Int]) -> Int? {
    if lst.count < 2 {
        return nil
    }

    var smallest = Int.max
    var secondSmallest = Int.max

    for num in lst {
        if num < smallest {
            secondSmallest = smallest
            smallest = num
        } else if num < secondSmallest && num != smallest {
            secondSmallest = num
        }
    }

    return secondSmallest == Int.max ? nil : secondSmallest
}
```

func nextSmallest(lst: [Int]) -> Int? {
    if lst.count < 2 {
        return nil
    }

    var smallest = Int.max
    var secondSmallest = Int.max

    for num in lst {
        if num < smallest {
            secondSmallest = smallest
            smallest = num
        } else if num < secondSmallest && num != smallest {
            secondSmallest = num
        }
    }

    return secondSmallest == Int.max ? nil : secondSmallest
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil[/INST]  ```swift
func nextSmallest(lst: [Int]) -> Int? {
    if lst.count < 2 {
        return nil
    }

    var smallest = Int.max
    var secondSmallest = Int.max

    for num in lst {
        if num < smallest {
            secondSmallest = smallest
            smallest = num
        } else if num < secondSmallest && num != smallest {
            secondSmallest = num
        }
    }

    return secondSmallest == Int.max ? nil : secondSmallest
}
```

func nextSmallest(lst: [Int]) -> Int? {
    var smallest = Int.max
    var secondSmallest = Int.max

    for num in lst {
        if num < smallest {
            secondSmallest = smallest
            smallest = num
        } else if num < secondSmallest && num != smallest {
            secondSmallest = num
        }
    }

    return secondSmallest != Int.max ? secondSmallest : nil
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil[/INST]  ```swift
func nextSmallest(lst: [Int]) -> Int? {
    var smallest = Int.max
    var secondSmallest = Int.max

    for num in lst {
        if num < smallest {
            secondSmallest = smallest
            smallest = num
        } else if num < secondSmallest && num != smallest {
            secondSmallest = num
        }
    }

    return secondSmallest != Int.max ? secondSmallest : nil
}
```

func nextSmallest(lst: [Int]) -> Int? {
    var smallest = Int.max
    var secondSmallest = Int.max

    for num in lst {
        if num < smallest {
            secondSmallest = smallest
            smallest = num
        } else if num < secondSmallest && num != smallest {
            secondSmallest = num
        }
    }

    return secondSmallest != Int.max ? secondSmallest : nil
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil[/INST]  ```swift
func nextSmallest(lst: [Int]) -> Int? {
    var smallest = Int.max
    var secondSmallest = Int.max

    for num in lst {
        if num < smallest {
            secondSmallest = smallest
            smallest = num
        } else if num < secondSmallest && num != smallest {
            secondSmallest = num
        }
    }

    return secondSmallest != Int.max ? secondSmallest : nil
}
```

func nextSmallest(lst: [Int]) -> Int? {
    if lst.count < 2 {
        return nil
    }

    var smallest = Int.max
    var secondSmallest = Int.max

    for num in lst {
        if num < smallest {
            secondSmallest = smallest
            smallest = num
        } else if num < secondSmallest && num != smallest {
            secondSmallest = num
        }
    }

    return secondSmallest != Int.max ? secondSmallest : nil
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil[/INST]  ```swift
func nextSmallest(lst: [Int]) -> Int? {
    if lst.count < 2 {
        return nil
    }

    var smallest = Int.max
    var secondSmallest = Int.max

    for num in lst {
        if num < smallest {
            secondSmallest = smallest
            smallest = num
        } else if num < secondSmallest && num != smallest {
            secondSmallest = num
        }
    }

    return secondSmallest != Int.max ? secondSmallest : nil
}
```

func nextSmallest(lst: [Int]) -> Int? {
    var smallest = Int.max
    var secondSmallest = Int.max

    for num in lst {
        if num < smallest {
            secondSmallest = smallest
            smallest = num
        } else if num < secondSmallest && num != smallest {
            secondSmallest = num
        }
    }

    return secondSmallest == Int.max ? nil : secondSmallest
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil[/INST]  ```swift
func nextSmallest(lst: [Int]) -> Int? {
    var smallest = Int.max
    var secondSmallest = Int.max

    for num in lst {
        if num < smallest {
            secondSmallest = smallest
            smallest = num
        } else if num < secondSmallest && num != smallest {
            secondSmallest = num
        }
    }

    return secondSmallest == Int.max ? nil : secondSmallest
}
```

func nextSmallest(lst: [Int]) -> Int? {
    var smallest = Int.max
    var secondSmallest = Int.max

    for num in lst {
        if num < smallest {
            secondSmallest = smallest
            smallest = num
        } else if num < secondSmallest && num != smallest {
            secondSmallest = num
        }
    }

    return secondSmallest == Int.max ? nil : secondSmallest
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil[/INST]  ```swift
func nextSmallest(lst: [Int]) -> Int? {
    var smallest = Int.max
    var secondSmallest = Int.max

    for num in lst {
        if num < smallest {
            secondSmallest = smallest
            smallest = num
        } else if num < secondSmallest && num != smallest {
            secondSmallest = num
        }
    }

    return secondSmallest == Int.max ? nil : secondSmallest
}
```

func nextSmallest(lst: [Int]) -> Int? {
    var smallest = Int.max
    var secondSmallest = Int.max

    for num in lst {
        if num < smallest {
            secondSmallest = smallest
            smallest = num
        } else if num < secondSmallest && num != smallest {
            secondSmallest = num
        }
    }

    return secondSmallest != Int.max ? secondSmallest : nil
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil[/INST]  ```swift
func nextSmallest(lst: [Int]) -> Int? {
    var smallest = Int.max
    var secondSmallest = Int.max

    for num in lst {
        if num < smallest {
            secondSmallest = smallest
            smallest = num
        } else if num < secondSmallest && num != smallest {
            secondSmallest = num
        }
    }

    return secondSmallest != Int.max ? secondSmallest : nil
}
```

func isBored(S: String) -> Int {
    let sentences = S.split(whereSeparator: { $0 == "." || $0 == "?" || $0 == "!" })
    var boredomCount = 0

    for sentence in sentences {
        let trimmedSentence = sentence.trimmingCharacters(in: .whitespaces)
        if trimmedSentence.hasPrefix("I") {
            boredomCount += 1
        }
    }

    return boredomCount
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1[/INST]  ```swift
func isBored(S: String) -> Int {
    let sentences = S.split(whereSeparator: { $0 == "." || $0 == "?" || $0 == "!" })
    var boredomCount = 0

    for sentence in sentences {
        let trimmedSentence = sentence.trimmingCharacters(in: .whitespaces)
        if trimmedSentence.hasPrefix("I") {
            boredomCount += 1
        }
    }

    return boredomCount
}
```
 // XCTAssertTrue failed

func isBored(S: String) -> Int {
    let sentences = S.split(whereSeparator: { $0 == "." || $0 == "?" || $0 == "!" })
    var boredomCount = 0

    for sentence in sentences {
        let trimmedSentence = sentence.trimmingCharacters(in: .whitespaces)
        if trimmedSentence.hasPrefix("I") {
            boredomCount += 1
        }
    }

    return boredomCount
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1[/INST]  ```swift
func isBored(S: String) -> Int {
    let sentences = S.split(whereSeparator: { $0 == "." || $0 == "?" || $0 == "!" })
    var boredomCount = 0

    for sentence in sentences {
        let trimmedSentence = sentence.trimmingCharacters(in: .whitespaces)
        if trimmedSentence.hasPrefix("I") {
            boredomCount += 1
        }
    }

    return boredomCount
}
```
 // XCTAssertTrue failed

func isBored(S: String) -> Int {
    let sentences = S.split(whereSeparator: { $0 == "." || $0 == "?" || $0 == "!" })
    var boredomCount = 0
    for sentence in sentences {
        let trimmedSentence = sentence.trimmingCharacters(in: .whitespaces)
        if trimmedSentence.hasPrefix("I") {
            boredomCount += 1
        }
    }
    return boredomCount
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1[/INST]  ```swift
func isBored(S: String) -> Int {
    let sentences = S.split(whereSeparator: { $0 == "." || $0 == "?" || $0 == "!" })
    var boredomCount = 0
    for sentence in sentences {
        let trimmedSentence = sentence.trimmingCharacters(in: .whitespaces)
        if trimmedSentence.hasPrefix("I") {
            boredomCount += 1
        }
    }
    return boredomCount
}
```
 // XCTAssertTrue failed

func isBored(S: String) -> Int {
    let sentences = S.split(whereSeparator: { $0 == "." || $0 == "?" || $0 == "!" })
    var boredomCount = 0
    for sentence in sentences {
        let trimmedSentence = sentence.trimmingCharacters(in: .whitespaces)
        if trimmedSentence.hasPrefix("I") {
            boredomCount += 1
        }
    }
    return boredomCount
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1[/INST]  ```swift
func isBored(S: String) -> Int {
    let sentences = S.split(whereSeparator: { $0 == "." || $0 == "?" || $0 == "!" })
    var boredomCount = 0
    for sentence in sentences {
        let trimmedSentence = sentence.trimmingCharacters(in: .whitespaces)
        if trimmedSentence.hasPrefix("I") {
            boredomCount += 1
        }
    }
    return boredomCount
}
```
 // XCTAssertTrue failed

func isBored(S: String) -> Int {
    let sentences = S.split(whereSeparator: { $0 == "." || $0 == "?" || $0 == "!" })
    var boredomCount = 0

    for sentence in sentences {
        let trimmedSentence = sentence.trimmingCharacters(in: .whitespaces)
        if trimmedSentence.hasPrefix("I") {
            boredomCount += 1
        }
    }

    return boredomCount
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1[/INST]  ```swift
func isBored(S: String) -> Int {
    let sentences = S.split(whereSeparator: { $0 == "." || $0 == "?" || $0 == "!" })
    var boredomCount = 0

    for sentence in sentences {
        let trimmedSentence = sentence.trimmingCharacters(in: .whitespaces)
        if trimmedSentence.hasPrefix("I") {
            boredomCount += 1
        }
    }

    return boredomCount
}
```
 // XCTAssertTrue failed

func isBored(S: String) -> Int {
    let sentences = S.split(whereSeparator: { $0 == "." || $0 == "?" || $0 == "!" })
    var boredomCount = 0

    for sentence in sentences {
        let trimmedSentence = sentence.trimmingCharacters(in: .whitespaces)
        if trimmedSentence.hasPrefix("I") {
            boredomCount += 1
        }
    }

    return boredomCount
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1[/INST]  ```swift
func isBored(S: String) -> Int {
    let sentences = S.split(whereSeparator: { $0 == "." || $0 == "?" || $0 == "!" })
    var boredomCount = 0

    for sentence in sentences {
        let trimmedSentence = sentence.trimmingCharacters(in: .whitespaces)
        if trimmedSentence.hasPrefix("I") {
            boredomCount += 1
        }
    }

    return boredomCount
}
```
 // XCTAssertTrue failed

func isBored(S: String) -> Int {
    let sentences = S.split(whereSeparator: { $0 == "." || $0 == "?" || $0 == "!" })
    var boredomCount = 0

    for sentence in sentences {
        let trimmedSentence = sentence.trimmingCharacters(in: .whitespaces)
        if trimmedSentence.hasPrefix("I") {
            boredomCount += 1
        }
    }

    return boredomCount
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1[/INST]  ```swift
func isBored(S: String) -> Int {
    let sentences = S.split(whereSeparator: { $0 == "." || $0 == "?" || $0 == "!" })
    var boredomCount = 0

    for sentence in sentences {
        let trimmedSentence = sentence.trimmingCharacters(in: .whitespaces)
        if trimmedSentence.hasPrefix("I") {
            boredomCount += 1
        }
    }

    return boredomCount
}
```
 // XCTAssertTrue failed

func isBored(S: String) -> Int {
    let sentences = S.split(whereSeparator: { $0 == "." || $0 == "?" || $0 == "!" })
    var boredomCount = 0

    for sentence in sentences {
        let trimmedSentence = sentence.trimmingCharacters(in: .whitespaces)
        if trimmedSentence.hasPrefix("I") {
            boredomCount += 1
        }
    }

    return boredomCount
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1[/INST]  ```swift
func isBored(S: String) -> Int {
    let sentences = S.split(whereSeparator: { $0 == "." || $0 == "?" || $0 == "!" })
    var boredomCount = 0

    for sentence in sentences {
        let trimmedSentence = sentence.trimmingCharacters(in: .whitespaces)
        if trimmedSentence.hasPrefix("I") {
            boredomCount += 1
        }
    }

    return boredomCount
}
```
 // XCTAssertTrue failed

func isBored(S: String) -> Int {
    let sentences = S.split(whereSeparator: { $0 == "." || $0 == "?" || $0 == "!" })
    var boredomCount = 0

    for sentence in sentences {
        let trimmedSentence = sentence.trimmingCharacters(in: .whitespaces)
        if trimmedSentence.hasPrefix("I") {
            boredomCount += 1
        }
    }

    return boredomCount
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1[/INST]  ```swift
func isBored(S: String) -> Int {
    let sentences = S.split(whereSeparator: { $0 == "." || $0 == "?" || $0 == "!" })
    var boredomCount = 0

    for sentence in sentences {
        let trimmedSentence = sentence.trimmingCharacters(in: .whitespaces)
        if trimmedSentence.hasPrefix("I") {
            boredomCount += 1
        }
    }

    return boredomCount
}
```
 // XCTAssertTrue failed

func isBored(S: String) -> Int {
    let sentences = S.split(whereSeparator: { $0 == "." || $0 == "?" || $0 == "!" })
    var boredomCount = 0

    for sentence in sentences {
        let trimmedSentence = sentence.trimmingCharacters(in: .whitespaces)
        if trimmedSentence.hasPrefix("I") {
            boredomCount += 1
        }
    }

    return boredomCount
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1[/INST]  ```swift
func isBored(S: String) -> Int {
    let sentences = S.split(whereSeparator: { $0 == "." || $0 == "?" || $0 == "!" })
    var boredomCount = 0

    for sentence in sentences {
        let trimmedSentence = sentence.trimmingCharacters(in: .whitespaces)
        if trimmedSentence.hasPrefix("I") {
            boredomCount += 1
        }
    }

    return boredomCount
}
```
 // XCTAssertTrue failed

func anyInt(x: Double, y: Double, z: Double) -> Bool {
    if x.truncatingRemainder(dividingBy: 1) == 0 && y.truncatingRemainder(dividingBy: 1) == 0 && z.truncatingRemainder(dividingBy: 1) == 0 {
        let intX = Int(x)
        let intY = Int(y)
        let intZ = Int(z)
        return intX == intY + intZ || intY == intX + intZ || intZ == intX + intY
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false[/INST]  ```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
    if x.truncatingRemainder(dividingBy: 1) == 0 && y.truncatingRemainder(dividingBy: 1) == 0 && z.truncatingRemainder(dividingBy: 1) == 0 {
        let intX = Int(x)
        let intY = Int(y)
        let intZ = Int(z)
        return intX == intY + intZ || intY == intX + intZ || intZ == intX + intY
    }
    return false
}
```

func anyInt(x: Double, y: Double, z: Double) -> Bool {
    if x.truncatingRemainder(dividingBy: 1) == 0 && y.truncatingRemainder(dividingBy: 1) == 0 && z.truncatingRemainder(dividingBy: 1) == 0 {
        let intX = Int(x)
        let intY = Int(y)
        let intZ = Int(z)
        return intX == intY + intZ || intY == intX + intZ || intZ == intX + intY
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false[/INST]  ```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
    if x.truncatingRemainder(dividingBy: 1) == 0 && y.truncatingRemainder(dividingBy: 1) == 0 && z.truncatingRemainder(dividingBy: 1) == 0 {
        let intX = Int(x)
        let intY = Int(y)
        let intZ = Int(z)
        return intX == intY + intZ || intY == intX + intZ || intZ == intX + intY
    }
    return false
}
```

func anyInt(x: Double, y: Double, z: Double) -> Bool {
    if x.truncatingRemainder(dividingBy: 1) == 0 && y.truncatingRemainder(dividingBy: 1) == 0 && z.truncatingRemainder(dividingBy: 1) == 0 {
        let intX = Int(x)
        let intY = Int(y)
        let intZ = Int(z)
        return intX == intY + intZ || intY == intX + intZ || intZ == intX + intY
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false[/INST]  ```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
    if x.truncatingRemainder(dividingBy: 1) == 0 && y.truncatingRemainder(dividingBy: 1) == 0 && z.truncatingRemainder(dividingBy: 1) == 0 {
        let intX = Int(x)
        let intY = Int(y)
        let intZ = Int(z)
        return intX == intY + intZ || intY == intX + intZ || intZ == intX + intY
    }
    return false
}
```

func anyInt(x: Double, y: Double, z: Double) -> Bool {
    if x.truncatingRemainder(dividingBy: 1) == 0 && y.truncatingRemainder(dividingBy: 1) == 0 && z.truncatingRemainder(dividingBy: 1) == 0 {
        let intX = Int(x)
        let intY = Int(y)
        let intZ = Int(z)
        return intX == intY + intZ || intY == intX + intZ || intZ == intX + intY
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false[/INST]  ```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
    if x.truncatingRemainder(dividingBy: 1) == 0 && y.truncatingRemainder(dividingBy: 1) == 0 && z.truncatingRemainder(dividingBy: 1) == 0 {
        let intX = Int(x)
        let intY = Int(y)
        let intZ = Int(z)
        return intX == intY + intZ || intY == intX + intZ || intZ == intX + intY
    }
    return false
}
```

func anyInt(x: Double, y: Double, z: Double) -> Bool {
    if x.truncatingRemainder(dividingBy: 1) == 0 && y.truncatingRemainder(dividingBy: 1) == 0 && z.truncatingRemainder(dividingBy: 1) == 0 {
        let intX = Int(x)
        let intY = Int(y)
        let intZ = Int(z)
        return intX == intY + intZ || intY == intX + intZ || intZ == intX + intY
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false[/INST]  ```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
    if x.truncatingRemainder(dividingBy: 1) == 0 && y.truncatingRemainder(dividingBy: 1) == 0 && z.truncatingRemainder(dividingBy: 1) == 0 {
        let intX = Int(x)
        let intY = Int(y)
        let intZ = Int(z)
        return intX == intY + intZ || intY == intX + intZ || intZ == intX + intY
    }
    return false
}
```

func anyInt(x: Double, y: Double, z: Double) -> Bool {
    if x.truncatingRemainder(dividingBy: 1) == 0 && y.truncatingRemainder(dividingBy: 1) == 0 && z.truncatingRemainder(dividingBy: 1) == 0 {
        let intX = Int(x)
        let intY = Int(y)
        let intZ = Int(z)
        return intX == intY + intZ || intY == intX + intZ || intZ == intX + intY
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false[/INST]  ```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
    if x.truncatingRemainder(dividingBy: 1) == 0 && y.truncatingRemainder(dividingBy: 1) == 0 && z.truncatingRemainder(dividingBy: 1) == 0 {
        let intX = Int(x)
        let intY = Int(y)
        let intZ = Int(z)
        return intX == intY + intZ || intY == intX + intZ || intZ == intX + intY
    }
    return false
}
```

func anyInt(x: Double, y: Double, z: Double) -> Bool {
    if x.truncatingRemainder(dividingBy: 1) == 0 && y.truncatingRemainder(dividingBy: 1) == 0 && z.truncatingRemainder(dividingBy: 1) == 0 {
        let intX = Int(x)
        let intY = Int(y)
        let intZ = Int(z)
        return intX == intY + intZ || intY == intX + intZ || intZ == intX + intY
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false[/INST]  ```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
    if x.truncatingRemainder(dividingBy: 1) == 0 && y.truncatingRemainder(dividingBy: 1) == 0 && z.truncatingRemainder(dividingBy: 1) == 0 {
        let intX = Int(x)
        let intY = Int(y)
        let intZ = Int(z)
        return intX == intY + intZ || intY == intX + intZ || intZ == intX + intY
    }
    return false
}
```

func anyInt(x: Double, y: Double, z: Double) -> Bool {
    if x.truncatingRemainder(dividingBy: 1) == 0 && y.truncatingRemainder(dividingBy: 1) == 0 && z.truncatingRemainder(dividingBy: 1) == 0 {
        let intX = Int(x)
        let intY = Int(y)
        let intZ = Int(z)
        return intX == intY + intZ || intY == intX + intZ || intZ == intX + intY
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false[/INST]  ```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
    if x.truncatingRemainder(dividingBy: 1) == 0 && y.truncatingRemainder(dividingBy: 1) == 0 && z.truncatingRemainder(dividingBy: 1) == 0 {
        let intX = Int(x)
        let intY = Int(y)
        let intZ = Int(z)
        return intX == intY + intZ || intY == intX + intZ || intZ == intX + intY
    }
    return false
}
```

func anyInt(x: Double, y: Double, z: Double) -> Bool {
    if x.truncatingRemainder(dividingBy: 1) == 0 && y.truncatingRemainder(dividingBy: 1) == 0 && z.truncatingRemainder(dividingBy: 1) == 0 {
        let intX = Int(x)
        let intY = Int(y)
        let intZ = Int(z)
        return intX == intY + intZ || intY == intX + intZ || intZ == intX + intY
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false[/INST]  ```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
    if x.truncatingRemainder(dividingBy: 1) == 0 && y.truncatingRemainder(dividingBy: 1) == 0 && z.truncatingRemainder(dividingBy: 1) == 0 {
        let intX = Int(x)
        let intY = Int(y)
        let intZ = Int(z)
        return intX == intY + intZ || intY == intX + intZ || intZ == intX + intY
    }
    return false
}
```

func anyInt(x: Double, y: Double, z: Double) -> Bool {
    if x.truncatingRemainder(dividingBy: 1) == 0 && y.truncatingRemainder(dividingBy: 1) == 0 && z.truncatingRemainder(dividingBy: 1) == 0 {
        let intX = Int(x)
        let intY = Int(y)
        let intZ = Int(z)
        return intX == intY + intZ || intY == intX + intZ || intZ == intX + intY
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false[/INST]  ```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
    if x.truncatingRemainder(dividingBy: 1) == 0 && y.truncatingRemainder(dividingBy: 1) == 0 && z.truncatingRemainder(dividingBy: 1) == 0 {
        let intX = Int(x)
        let intY = Int(y)
        let intZ = Int(z)
        return intX == intY + intZ || intY == intX + intZ || intZ == intX + intY
    }
    return false
}
```

func encode(message: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let alphabet = Array("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ")

    var encodedMessage = ""
    for char in message {
        if vowels.contains(char) {
            if let index = alphabet.firstIndex(of: char) {
                let newIndex = (index + 2) % alphabet.count
                encodedMessage.append(alphabet[newIndex])
            }
        } else {
            encodedMessage.append(char.isUppercase ? Character(char.lowercased()) : Character(char.uppercased()))
        }
    }
    return encodedMessage
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a 
way that it swaps case of all letters, replaces all vowels in 
the message with the letter that appears 2 places ahead of that 
vowel in the english alphabet. 
Assume only letters. 
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"[/INST]  ```swift
func encode(message: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let alphabet = Array("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ")

    var encodedMessage = ""
    for char in message {
        if vowels.contains(char) {
            if let index = alphabet.firstIndex(of: char) {
                let newIndex = (index + 2) % alphabet.count
                encodedMessage.append(alphabet[newIndex])
            }
        } else {
            encodedMessage.append(char.isUppercase ? Character(char.lowercased()) : Character(char.uppercased()))
        }
    }
    return encodedMessage
}
```
 // XCTAssertTrue failed

func encode(message: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let alphabet = Array("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ")

    var encodedMessage = ""
    for char in message {
        if let index = alphabet.firstIndex(of: char) {
            let newIndex = (index + 2) % alphabet.count
            let newChar = vowels.contains(char) ? alphabet[newIndex] : char.isUppercase ? alphabet[newIndex].uppercased() : alphabet[newIndex].lowercased()
            encodedMessage.append(newChar)
        } else {
            encodedMessage.append(char)
        }
    }

    return encodedMessage
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a 
way that it swaps case of all letters, replaces all vowels in 
the message with the letter that appears 2 places ahead of that 
vowel in the english alphabet. 
Assume only letters. 
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"[/INST]  ```swift
func encode(message: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let alphabet = Array("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ")

    var encodedMessage = ""
    for char in message {
        if let index = alphabet.firstIndex(of: char) {
            let newIndex = (index + 2) % alphabet.count
            let newChar = vowels.contains(char) ? alphabet[newIndex] : char.isUppercase ? alphabet[newIndex].uppercased() : alphabet[newIndex].lowercased()
            encodedMessage.append(newChar)
        } else {
            encodedMessage.append(char)
        }
    }

    return encodedMessage
}
```
let newChar = vowels.contains(char) ? alphabet[newIndex] : char.isUppercase ? alphabet[newIndex].uppercased() : alphabet[newIndex].lowercased() // result values in '? :' expression have mismatching types 'String.Element' (aka 'Character') and 'String'

func encode(message: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let alphabet: [Character] = Array("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ")
    var encodedMessage = ""

    for char in message {
        if vowels.contains(char) {
            if let index = alphabet.firstIndex(of: char) {
                let newIndex = (index + 2) % alphabet.count
                encodedMessage.append(alphabet[newIndex])
            }
        } else {
            encodedMessage.append(char.isUppercase ? Character(char.lowercased()) : Character(char.uppercased()))
        }
    }

    return encodedMessage
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a 
way that it swaps case of all letters, replaces all vowels in 
the message with the letter that appears 2 places ahead of that 
vowel in the english alphabet. 
Assume only letters. 
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"[/INST]  ```swift
func encode(message: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let alphabet: [Character] = Array("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ")
    var encodedMessage = ""

    for char in message {
        if vowels.contains(char) {
            if let index = alphabet.firstIndex(of: char) {
                let newIndex = (index + 2) % alphabet.count
                encodedMessage.append(alphabet[newIndex])
            }
        } else {
            encodedMessage.append(char.isUppercase ? Character(char.lowercased()) : Character(char.uppercased()))
        }
    }

    return encodedMessage
}
```
 // XCTAssertTrue failed

func encode(message: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let alphabet: [Character] = Array("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ")

    var encodedMessage = ""

    for char in message {
        if let index = alphabet.firstIndex(of: char) {
            let newIndex = (index + 2) % alphabet.count
            let newChar = alphabet[newIndex]

            if vowels.contains(char) {
                encodedMessage.append(newChar.isUppercase ? newChar.lowercased() : newChar.uppercased())
            } else {
                encodedMessage.append(newChar)
            }
        } else {
            encodedMessage.append(char)
        }
    }

    return encodedMessage
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a 
way that it swaps case of all letters, replaces all vowels in 
the message with the letter that appears 2 places ahead of that 
vowel in the english alphabet. 
Assume only letters. 
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"[/INST]  ```swift
func encode(message: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let alphabet: [Character] = Array("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ")

    var encodedMessage = ""

    for char in message {
        if let index = alphabet.firstIndex(of: char) {
            let newIndex = (index + 2) % alphabet.count
            let newChar = alphabet[newIndex]

            if vowels.contains(char) {
                encodedMessage.append(newChar.isUppercase ? newChar.lowercased() : newChar.uppercased())
            } else {
                encodedMessage.append(newChar)
            }
        } else {
            encodedMessage.append(char)
        }
    }

    return encodedMessage
}
```
 // XCTAssertTrue failed

func encode(message: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let alphabet = Array("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ")

    var encodedMessage = ""
    for char in message {
        if vowels.contains(char) {
            if let index = alphabet.firstIndex(of: char) {
                let newIndex = (index + 2) % alphabet.count
                encodedMessage.append(alphabet[newIndex])
            }
        } else {
            encodedMessage.append(char.isUppercase ? Character(char.lowercased()) : Character(char.uppercased()))
        }
    }

    return encodedMessage
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a 
way that it swaps case of all letters, replaces all vowels in 
the message with the letter that appears 2 places ahead of that 
vowel in the english alphabet. 
Assume only letters. 
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"[/INST]  ```swift
func encode(message: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let alphabet = Array("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ")

    var encodedMessage = ""
    for char in message {
        if vowels.contains(char) {
            if let index = alphabet.firstIndex(of: char) {
                let newIndex = (index + 2) % alphabet.count
                encodedMessage.append(alphabet[newIndex])
            }
        } else {
            encodedMessage.append(char.isUppercase ? Character(char.lowercased()) : Character(char.uppercased()))
        }
    }

    return encodedMessage
}
```
 // XCTAssertTrue failed

func encode(message: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let alphabet = Array("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ")

    var encodedMessage = ""
    for char in message {
        if vowels.contains(char) {
            if let index = alphabet.firstIndex(of: char) {
                let newIndex = (index + 2) % alphabet.count
                encodedMessage.append(alphabet[newIndex])
            }
        } else {
            encodedMessage.append(char.isUppercase ? Character(char.lowercased()) : Character(char.uppercased()))
        }
    }
    return encodedMessage
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a 
way that it swaps case of all letters, replaces all vowels in 
the message with the letter that appears 2 places ahead of that 
vowel in the english alphabet. 
Assume only letters. 
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"[/INST]  ```swift
func encode(message: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let alphabet = Array("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ")

    var encodedMessage = ""
    for char in message {
        if vowels.contains(char) {
            if let index = alphabet.firstIndex(of: char) {
                let newIndex = (index + 2) % alphabet.count
                encodedMessage.append(alphabet[newIndex])
            }
        } else {
            encodedMessage.append(char.isUppercase ? Character(char.lowercased()) : Character(char.uppercased()))
        }
    }
    return encodedMessage
}
```
 // XCTAssertTrue failed

func encode(message: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let alphabet = Array("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ")

    var encodedMessage = ""
    for char in message {
        if vowels.contains(char) {
            if let index = alphabet.firstIndex(of: char) {
                let newIndex = (index + 2) % alphabet.count
                encodedMessage.append(alphabet[newIndex])
            }
        } else {
            encodedMessage.append(char.isUppercase ? Character(char.lowercased()) : Character(char.uppercased()))
        }
    }
    return encodedMessage
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a 
way that it swaps case of all letters, replaces all vowels in 
the message with the letter that appears 2 places ahead of that 
vowel in the english alphabet. 
Assume only letters. 
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"[/INST]  ```swift
func encode(message: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let alphabet = Array("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ")

    var encodedMessage = ""
    for char in message {
        if vowels.contains(char) {
            if let index = alphabet.firstIndex(of: char) {
                let newIndex = (index + 2) % alphabet.count
                encodedMessage.append(alphabet[newIndex])
            }
        } else {
            encodedMessage.append(char.isUppercase ? Character(char.lowercased()) : Character(char.uppercased()))
        }
    }
    return encodedMessage
}
```
 // XCTAssertTrue failed

func encode(message: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let alphabet = Array("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ")

    var encodedMessage = ""
    for char in message {
        if vowels.contains(char) {
            if let index = alphabet.firstIndex(of: char) {
                let newIndex = (index + 2) % alphabet.count
                encodedMessage.append(alphabet[newIndex])
            }
        } else {
            encodedMessage.append(char.isUppercase ? Character(char.lowercased()) : Character(char.uppercased()))
        }
    }

    return encodedMessage
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a 
way that it swaps case of all letters, replaces all vowels in 
the message with the letter that appears 2 places ahead of that 
vowel in the english alphabet. 
Assume only letters. 
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"[/INST]  ```swift
func encode(message: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let alphabet = Array("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ")

    var encodedMessage = ""
    for char in message {
        if vowels.contains(char) {
            if let index = alphabet.firstIndex(of: char) {
                let newIndex = (index + 2) % alphabet.count
                encodedMessage.append(alphabet[newIndex])
            }
        } else {
            encodedMessage.append(char.isUppercase ? Character(char.lowercased()) : Character(char.uppercased()))
        }
    }

    return encodedMessage
}
```
 // XCTAssertTrue failed

func encode(message: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let alphabet = Array("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ")

    var encodedMessage = ""
    for char in message {
        if let index = alphabet.firstIndex(of: char) {
            var newChar = alphabet[(index + alphabet.count - 23) % alphabet.count]
            if vowels.contains(char.lowercased()) {
                newChar = alphabet[(index + alphabet.count - 19) % alphabet.count]
            }
            encodedMessage.append(newChar)
        } else {
            encodedMessage.append(char)
        }
    }
    return encodedMessage
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a 
way that it swaps case of all letters, replaces all vowels in 
the message with the letter that appears 2 places ahead of that 
vowel in the english alphabet. 
Assume only letters. 
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"[/INST]  ```swift
func encode(message: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let alphabet = Array("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ")

    var encodedMessage = ""
    for char in message {
        if let index = alphabet.firstIndex(of: char) {
            var newChar = alphabet[(index + alphabet.count - 23) % alphabet.count]
            if vowels.contains(char.lowercased()) {
                newChar = alphabet[(index + alphabet.count - 19) % alphabet.count]
            }
            encodedMessage.append(newChar)
        } else {
            encodedMessage.append(char)
        }
    }
    return encodedMessage
}
```
 // XCTAssertTrue failed

func encode(message: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let alphabet: [Character] = Array("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ")
    var encodedMessage = ""

    for char in message {
        if vowels.contains(char) {
            if let index = alphabet.firstIndex(of: char) {
                let newIndex = (index + 2) % alphabet.count
                encodedMessage.append(alphabet[newIndex])
            }
        } else {
            encodedMessage.append(char.isUppercase ? Character(char.lowercased()) : Character(char.uppercased()))
        }
    }

    return encodedMessage
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a 
way that it swaps case of all letters, replaces all vowels in 
the message with the letter that appears 2 places ahead of that 
vowel in the english alphabet. 
Assume only letters. 
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"[/INST]  ```swift
func encode(message: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let alphabet: [Character] = Array("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ")
    var encodedMessage = ""

    for char in message {
        if vowels.contains(char) {
            if let index = alphabet.firstIndex(of: char) {
                let newIndex = (index + 2) % alphabet.count
                encodedMessage.append(alphabet[newIndex])
            }
        } else {
            encodedMessage.append(char.isUppercase ? Character(char.lowercased()) : Character(char.uppercased()))
        }
    }

    return encodedMessage
}
```
 // XCTAssertTrue failed

func skjkasdkd(lst: [Int]) -> Int {
    func isPrime(_ num: Int) -> Bool {
        if num <= 1 {
            return false
        }
        if num <= 3 {
            return true
        }
        var i = 2
        while i * i <= num {
            if num % i == 0 {
                return false
            }
            i = i + 1
        }
        return true
    }

    var largestPrime = -1
    for num in lst {
        if isPrime(num) && num > largestPrime {
            largestPrime = num
        }
    }

    if largestPrime == -1 {
        return 0
    }

    var sum = 0
    var temp = largestPrime
    while temp > 0 {
        sum += temp % 10
        temp /= 10
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7[/INST]  ```swift
func skjkasdkd(lst: [Int]) -> Int {
    func isPrime(_ num: Int) -> Bool {
        if num <= 1 {
            return false
        }
        if num <= 3 {
            return true
        }
        var i = 2
        while i * i <= num {
            if num % i == 0 {
                return false
            }
            i = i + 1
        }
        return true
    }

    var largestPrime = -1
    for num in lst {
        if isPrime(num) && num > largestPrime {
            largestPrime = num
        }
    }

    if largestPrime == -1 {
        return 0
    }

    var sum = 0
    var temp = largestPrime
    while temp > 0 {
        sum += temp % 10
        temp /= 10
    }
    return sum
}
```

func skjkasdkd(lst: [Int]) -> Int {
    func isPrime(_ num: Int) -> Bool {
        if num <= 1 {
            return false
        }
        if num <= 3 {
            return true
        }
        if num % 2 == 0 || num % 3 == 0 {
            return false
        }
        var i = 5
        while i * i <= num {
            if num % i == 0 || num % (i + 2) == 0 {
                return false
            }
            i += 6
        }
        return true
    }

    var largestPrime = -1
    for num in lst {
        if isPrime(num) && num > largestPrime {
            largestPrime = num
        }
    }

    if largestPrime == -1 {
        return 0
    }

    var sum = 0
    var prime = largestPrime
    while prime > 0 {
        sum += prime % 10
        prime /= 10
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7[/INST]  ```swift
func skjkasdkd(lst: [Int]) -> Int {
    func isPrime(_ num: Int) -> Bool {
        if num <= 1 {
            return false
        }
        if num <= 3 {
            return true
        }
        if num % 2 == 0 || num % 3 == 0 {
            return false
        }
        var i = 5
        while i * i <= num {
            if num % i == 0 || num % (i + 2) == 0 {
                return false
            }
            i += 6
        }
        return true
    }

    var largestPrime = -1
    for num in lst {
        if isPrime(num) && num > largestPrime {
            largestPrime = num
        }
    }

    if largestPrime == -1 {
        return 0
    }

    var sum = 0
    var prime = largestPrime
    while prime > 0 {
        sum += prime % 10
        prime /= 10
    }
    return sum
}
```

func skjkasdkd(lst: [Int]) -> Int {
    func isPrime(_ num: Int) -> Bool {
        if num <= 1 {
            return false
        }
        if num <= 3 {
            return true
        }
        if num % 2 == 0 || num % 3 == 0 {
            return false
        }
        var i = 5
        while i * i <= num {
            if num % i == 0 || num % (i + 2) == 0 {
                return false
            }
            i += 6
        }
        return true
    }

    var largestPrime = -1
    for num in lst {
        if isPrime(num) && num > largestPrime {
            largestPrime = num
        }
    }

    if largestPrime == -1 {
        return 0
    }

    var sum = 0
    var num = largestPrime
    while num > 0 {
        sum += num % 10
        num /= 10
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7[/INST]  ```swift
func skjkasdkd(lst: [Int]) -> Int {
    func isPrime(_ num: Int) -> Bool {
        if num <= 1 {
            return false
        }
        if num <= 3 {
            return true
        }
        if num % 2 == 0 || num % 3 == 0 {
            return false
        }
        var i = 5
        while i * i <= num {
            if num % i == 0 || num % (i + 2) == 0 {
                return false
            }
            i += 6
        }
        return true
    }

    var largestPrime = -1
    for num in lst {
        if isPrime(num) && num > largestPrime {
            largestPrime = num
        }
    }

    if largestPrime == -1 {
        return 0
    }

    var sum = 0
    var num = largestPrime
    while num > 0 {
        sum += num % 10
        num /= 10
    }
    return sum
}
```

func skjkasdkd(lst: [Int]) -> Int {
    func isPrime(_ num: Int) -> Bool {
        if num <= 1 {
            return false
        }
        if num <= 3 {
            return true
        }
        if num % 2 == 0 || num % 3 == 0 {
            return false
        }
        var i = 5
        while i * i <= num {
            if num % i == 0 || num % (i + 2) == 0 {
                return false
            }
            i += 6
        }
        return true
    }

    var largestPrime = -1
    for num in lst {
        if isPrime(num) && num > largestPrime {
            largestPrime = num
        }
    }

    if largestPrime == -1 {
        return 0
    }

    var sum = 0
    var num = largestPrime
    while num > 0 {
        sum += num % 10
        num /= 10
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7[/INST]  ```swift
func skjkasdkd(lst: [Int]) -> Int {
    func isPrime(_ num: Int) -> Bool {
        if num <= 1 {
            return false
        }
        if num <= 3 {
            return true
        }
        if num % 2 == 0 || num % 3 == 0 {
            return false
        }
        var i = 5
        while i * i <= num {
            if num % i == 0 || num % (i + 2) == 0 {
                return false
            }
            i += 6
        }
        return true
    }

    var largestPrime = -1
    for num in lst {
        if isPrime(num) && num > largestPrime {
            largestPrime = num
        }
    }

    if largestPrime == -1 {
        return 0
    }

    var sum = 0
    var num = largestPrime
    while num > 0 {
        sum += num % 10
        num /= 10
    }
    return sum
}
```

func skjkasdkd(lst: [Int]) -> Int {
    func isPrime(_ number: Int) -> Bool {
        if number <= 1 {
            return false
        }
        if number <= 3 {
            return true
        }
        if number % 2 == 0 || number % 3 == 0 {
            return false
        }
        var i = 5
        while i * i <= number {
            if number % i == 0 || number % (i + 2) == 0 {
                return false
            }
            i += 6
        }
        return true
    }

    var largestPrime = -1
    for num in lst {
        if isPrime(num) && num > largestPrime {
            largestPrime = num
        }
    }

    if largestPrime == -1 {
        return 0
    }

    var sum = 0
    var prime = largestPrime
    while prime > 0 {
        sum += prime % 10
        prime /= 10
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7[/INST]  ```swift
func skjkasdkd(lst: [Int]) -> Int {
    func isPrime(_ number: Int) -> Bool {
        if number <= 1 {
            return false
        }
        if number <= 3 {
            return true
        }
        if number % 2 == 0 || number % 3 == 0 {
            return false
        }
        var i = 5
        while i * i <= number {
            if number % i == 0 || number % (i + 2) == 0 {
                return false
            }
            i += 6
        }
        return true
    }

    var largestPrime = -1
    for num in lst {
        if isPrime(num) && num > largestPrime {
            largestPrime = num
        }
    }

    if largestPrime == -1 {
        return 0
    }

    var sum = 0
    var prime = largestPrime
    while prime > 0 {
        sum += prime % 10
        prime /= 10
    }
    return sum
}
```

func skjkasdkd(lst: [Int]) -> Int {
    func isPrime(_ num: Int) -> Bool {
        if num <= 1 {
            return false
        }
        if num <= 3 {
            return true
        }
        var i = 2
        while i * i <= num {
            if num % i == 0 {
                return false
            }
            i = i + 1
        }
        return true
    }

    var largestPrime = -1
    for num in lst {
        if isPrime(num) && num > largestPrime {
            largestPrime = num
        }
    }

    if largestPrime == -1 {
        return 0
    }

    var sum = 0
    var num = largestPrime
    while num > 0 {
        sum += num % 10
        num /= 10
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7[/INST]  ```swift
func skjkasdkd(lst: [Int]) -> Int {
    func isPrime(_ num: Int) -> Bool {
        if num <= 1 {
            return false
        }
        if num <= 3 {
            return true
        }
        var i = 2
        while i * i <= num {
            if num % i == 0 {
                return false
            }
            i = i + 1
        }
        return true
    }

    var largestPrime = -1
    for num in lst {
        if isPrime(num) && num > largestPrime {
            largestPrime = num
        }
    }

    if largestPrime == -1 {
        return 0
    }

    var sum = 0
    var num = largestPrime
    while num > 0 {
        sum += num % 10
        num /= 10
    }
    return sum
}
```

func skjkasdkd(lst: [Int]) -> Int {
    var largestPrime = -1
    var sumOfDigits = 0

    for num in lst {
        if num > 1 && isPrime(num) && num > largestPrime {
            largestPrime = num
            sumOfDigits = sumDigits(num)
        }
    }

    return sumOfDigits
}

func isPrime(_ num: Int) -> Bool {
    if num <= 1 {
        return false
    }

    if num <= 3 {
        return true
    }

    if num % 2 == 0 || num % 3 == 0 {
        return false
    }

    var i = 5
    while i * i <= num {
        if num % i == 0 || num % (i + 2) == 0 {
            return false
        }
        i += 6
    }

    return true
}

func sumDigits(_ num: Int) -> Int {
    var sum = 0
    var number = num

    while number > 0 {
        sum += number % 10
        number /= 10
    }

    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7[/INST]  ```swift
func skjkasdkd(lst: [Int]) -> Int {
    var largestPrime = -1
    var sumOfDigits = 0

    for num in lst {
        if num > 1 && isPrime(num) && num > largestPrime {
            largestPrime = num
            sumOfDigits = sumDigits(num)
        }
    }

    return sumOfDigits
}

func isPrime(_ num: Int) -> Bool {
    if num <= 1 {
        return false
    }

    if num <= 3 {
        return true
    }

    if num % 2 == 0 || num % 3 == 0 {
        return false
    }

    var i = 5
    while i * i <= num {
        if num % i == 0 || num % (i + 2) == 0 {
            return false
        }
        i += 6
    }

    return true
}

func sumDigits(_ num: Int) -> Int {
    var sum = 0
    var number = num

    while number > 0 {
        sum += number % 10
        number /= 10
    }

    return sum
}
```

func skjkasdkd(lst: [Int]) -> Int {
    func isPrime(_ num: Int) -> Bool {
        if num <= 1 {
            return false
        }
        if num <= 3 {
            return true
        }
        if num % 2 == 0 || num % 3 == 0 {
            return false
        }
        var i = 5
        while i * i <= num {
            if num % i == 0 || num % (i + 2) == 0 {
                return false
            }
            i += 6
        }
        return true
    }

    var largestPrime = -1
    for num in lst {
        if isPrime(num) && num > largestPrime {
            largestPrime = num
        }
    }

    if largestPrime == -1 {
        return 0
    }

    var sum = 0
    var prime = largestPrime
    while prime > 0 {
        sum += prime % 10
        prime /= 10
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7[/INST]  ```swift
func skjkasdkd(lst: [Int]) -> Int {
    func isPrime(_ num: Int) -> Bool {
        if num <= 1 {
            return false
        }
        if num <= 3 {
            return true
        }
        if num % 2 == 0 || num % 3 == 0 {
            return false
        }
        var i = 5
        while i * i <= num {
            if num % i == 0 || num % (i + 2) == 0 {
                return false
            }
            i += 6
        }
        return true
    }

    var largestPrime = -1
    for num in lst {
        if isPrime(num) && num > largestPrime {
            largestPrime = num
        }
    }

    if largestPrime == -1 {
        return 0
    }

    var sum = 0
    var prime = largestPrime
    while prime > 0 {
        sum += prime % 10
        prime /= 10
    }
    return sum
}
```

func skjkasdkd(lst: [Int]) -> Int {
    func isPrime(_ num: Int) -> Bool {
        if num <= 1 {
            return false
        }
        if num <= 3 {
            return true
        }
        if num % 2 == 0 || num % 3 == 0 {
            return false
        }
        var i = 5
        while i * i <= num {
            if num % i == 0 || num % (i + 2) == 0 {
                return false
            }
            i += 6
        }
        return true
    }

    var largestPrime = -1
    for num in lst {
        if isPrime(num) && num > largestPrime {
            largestPrime = num
        }
    }

    if largestPrime == -1 {
        return 0
    }

    var sum = 0
    var temp = largestPrime
    while temp > 0 {
        sum += temp % 10
        temp /= 10
    }

    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7[/INST]  ```swift
func skjkasdkd(lst: [Int]) -> Int {
    func isPrime(_ num: Int) -> Bool {
        if num <= 1 {
            return false
        }
        if num <= 3 {
            return true
        }
        if num % 2 == 0 || num % 3 == 0 {
            return false
        }
        var i = 5
        while i * i <= num {
            if num % i == 0 || num % (i + 2) == 0 {
                return false
            }
            i += 6
        }
        return true
    }

    var largestPrime = -1
    for num in lst {
        if isPrime(num) && num > largestPrime {
            largestPrime = num
        }
    }

    if largestPrime == -1 {
        return 0
    }

    var sum = 0
    var temp = largestPrime
    while temp > 0 {
        sum += temp % 10
        temp /= 10
    }

    return sum
}
```

func skjkasdkd(lst: [Int]) -> Int {
    func isPrime(_ num: Int) -> Bool {
        if num <= 1 {
            return false
        }
        if num <= 3 {
            return true
        }
        if num % 2 == 0 || num % 3 == 0 {
            return false
        }
        var i = 5
        while i * i <= num {
            if num % i == 0 || num % (i + 2) == 0 {
                return false
            }
            i += 6
        }
        return true
    }

    var largestPrime = -1
    for num in lst {
        if isPrime(num) && num > largestPrime {
            largestPrime = num
        }
    }

    if largestPrime == -1 {
        return 0
    }

    var sum = 0
    var temp = largestPrime
    while temp > 0 {
        sum += temp % 10
        temp /= 10
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7[/INST]  ```swift
func skjkasdkd(lst: [Int]) -> Int {
    func isPrime(_ num: Int) -> Bool {
        if num <= 1 {
            return false
        }
        if num <= 3 {
            return true
        }
        if num % 2 == 0 || num % 3 == 0 {
            return false
        }
        var i = 5
        while i * i <= num {
            if num % i == 0 || num % (i + 2) == 0 {
                return false
            }
            i += 6
        }
        return true
    }

    var largestPrime = -1
    for num in lst {
        if isPrime(num) && num > largestPrime {
            largestPrime = num
        }
    }

    if largestPrime == -1 {
        return 0
    }

    var sum = 0
    var temp = largestPrime
    while temp > 0 {
        sum += temp % 10
        temp /= 10
    }
    return sum
}
```

func countUpTo(n: Int) -> [Int] {
    var primes: [Int] = []
    for number in 2..<n {
        var isPrime = true
        for i in 2..<number {
            if number % i == 0 {
                isPrime = false
                break
            }
        }
        if isPrime {
            primes.append(number)
        }
    }
    return primes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17][/INST]  ```swift
func countUpTo(n: Int) -> [Int] {
    var primes: [Int] = []
    for number in 2..<n {
        var isPrime = true
        for i in 2..<number {
            if number % i == 0 {
                isPrime = false
                break
            }
        }
        if isPrime {
            primes.append(number)
        }
    }
    return primes
}
```
 // Fatal error: Range requires lowerBound <= upperBound

func countUpTo(n: Int) -> [Int] {
    var primes: [Int] = []
    for number in 2..<n {
        var isPrime = true
        for i in 2..<number {
            if number % i == 0 {
                isPrime = false
                break
            }
        }
        if isPrime {
            primes.append(number)
        }
    }
    return primes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17][/INST]  ```swift
func countUpTo(n: Int) -> [Int] {
    var primes: [Int] = []
    for number in 2..<n {
        var isPrime = true
        for i in 2..<number {
            if number % i == 0 {
                isPrime = false
                break
            }
        }
        if isPrime {
            primes.append(number)
        }
    }
    return primes
}
```
 // Fatal error: Range requires lowerBound <= upperBound

func countUpTo(n: Int) -> [Int] {
    var primes: [Int] = []
    for number in 2..<n {
        var isPrime = true
        for i in 2..<number {
            if number % i == 0 {
                isPrime = false
                break
            }
        }
        if isPrime {
            primes.append(number)
        }
    }
    return primes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17][/INST]  ```swift
func countUpTo(n: Int) -> [Int] {
    var primes: [Int] = []
    for number in 2..<n {
        var isPrime = true
        for i in 2..<number {
            if number % i == 0 {
                isPrime = false
                break
            }
        }
        if isPrime {
            primes.append(number)
        }
    }
    return primes
}
```
 // Fatal error: Range requires lowerBound <= upperBound

func countUpTo(n: Int) -> [Int] {
    var primes: [Int] = []
    for number in 2..<n {
        var isPrime = true
        for i in 2..<number {
            if number % i == 0 {
                isPrime = false
                break
            }
        }
        if isPrime {
            primes.append(number)
        }
    }
    return primes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17][/INST]  ```swift
func countUpTo(n: Int) -> [Int] {
    var primes: [Int] = []
    for number in 2..<n {
        var isPrime = true
        for i in 2..<number {
            if number % i == 0 {
                isPrime = false
                break
            }
        }
        if isPrime {
            primes.append(number)
        }
    }
    return primes
}
```
 // Fatal error: Range requires lowerBound <= upperBound

func countUpTo(n: Int) -> [Int] {
    var primes: [Int] = []
    for number in 2..<n {
        var isPrime = true
        for i in 2..<number {
            if number % i == 0 {
                isPrime = false
                break
            }
        }
        if isPrime {
            primes.append(number)
        }
    }
    return primes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17][/INST]  ```swift
func countUpTo(n: Int) -> [Int] {
    var primes: [Int] = []
    for number in 2..<n {
        var isPrime = true
        for i in 2..<number {
            if number % i == 0 {
                isPrime = false
                break
            }
        }
        if isPrime {
            primes.append(number)
        }
    }
    return primes
}
```
 // Fatal error: Range requires lowerBound <= upperBound

func countUpTo(n: Int) -> [Int] {
    var primes: [Int] = []
    for number in 2..<n {
        var isPrime = true
        for i in 2..<number {
            if number % i == 0 {
                isPrime = false
                break
            }
        }
        if isPrime {
            primes.append(number)
        }
    }
    return primes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17][/INST]  ```swift
func countUpTo(n: Int) -> [Int] {
    var primes: [Int] = []
    for number in 2..<n {
        var isPrime = true
        for i in 2..<number {
            if number % i == 0 {
                isPrime = false
                break
            }
        }
        if isPrime {
            primes.append(number)
        }
    }
    return primes
}
```
 // Fatal error: Range requires lowerBound <= upperBound

func countUpTo(n: Int) -> [Int] {
    var primes: [Int] = []
    for number in 2..<n {
        var isPrime = true
        for i in 2..<number {
            if number % i == 0 {
                isPrime = false
                break
            }
        }
        if isPrime {
            primes.append(number)
        }
    }
    return primes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17][/INST]  ```swift
func countUpTo(n: Int) -> [Int] {
    var primes: [Int] = []
    for number in 2..<n {
        var isPrime = true
        for i in 2..<number {
            if number % i == 0 {
                isPrime = false
                break
            }
        }
        if isPrime {
            primes.append(number)
        }
    }
    return primes
}
```
 // Fatal error: Range requires lowerBound <= upperBound

func countUpTo(n: Int) -> [Int] {
    var primes: [Int] = []
    for number in 2..<n {
        var isPrime = true
        for i in 2..<number {
            if number % i == 0 {
                isPrime = false
                break
            }
        }
        if isPrime {
            primes.append(number)
        }
    }
    return primes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17][/INST]  ```swift
func countUpTo(n: Int) -> [Int] {
    var primes: [Int] = []
    for number in 2..<n {
        var isPrime = true
        for i in 2..<number {
            if number % i == 0 {
                isPrime = false
                break
            }
        }
        if isPrime {
            primes.append(number)
        }
    }
    return primes
}
```
 // Fatal error: Range requires lowerBound <= upperBound

func countUpTo(n: Int) -> [Int] {
    var primes: [Int] = []
    for number in 2..<n {
        var isPrime = true
        for i in 2..<number {
            if number % i == 0 {
                isPrime = false
                break
            }
        }
        if isPrime {
            primes.append(number)
        }
    }
    return primes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17][/INST]  ```swift
func countUpTo(n: Int) -> [Int] {
    var primes: [Int] = []
    for number in 2..<n {
        var isPrime = true
        for i in 2..<number {
            if number % i == 0 {
                isPrime = false
                break
            }
        }
        if isPrime {
            primes.append(number)
        }
    }
    return primes
}
```
 // Fatal error: Range requires lowerBound <= upperBound

func countUpTo(n: Int) -> [Int] {
    var primes: [Int] = []
    for number in 2..<n {
        var isPrime = true
        for i in 2..<number {
            if number % i == 0 {
                isPrime = false
                break
            }
        }
        if isPrime {
            primes.append(number)
        }
    }
    return primes
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17][/INST]  ```swift
func countUpTo(n: Int) -> [Int] {
    var primes: [Int] = []
    for number in 2..<n {
        var isPrime = true
        for i in 2..<number {
            if number % i == 0 {
                isPrime = false
                break
            }
        }
        if isPrime {
            primes.append(number)
        }
    }
    return primes
}
```
 // Fatal error: Range requires lowerBound <= upperBound

func multiply(a: Int, b: Int) -> Int {
    let unitDigitA = abs(a % 10)
    let unitDigitB = abs(b % 10)
    return unitDigitA * unitDigitB
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns 
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20[/INST]  ```swift
func multiply(a: Int, b: Int) -> Int {
    let unitDigitA = abs(a % 10)
    let unitDigitB = abs(b % 10)
    return unitDigitA * unitDigitB
}
```

func multiply(a: Int, b: Int) -> Int {
    let unitDigitA = abs(a % 10)
    let unitDigitB = abs(b % 10)
    return unitDigitA * unitDigitB
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns 
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20[/INST]  ```swift
func multiply(a: Int, b: Int) -> Int {
    let unitDigitA = abs(a % 10)
    let unitDigitB = abs(b % 10)
    return unitDigitA * unitDigitB
}
```

func multiply(a: Int, b: Int) -> Int {
    let unitDigitA = abs(a % 10)
    let unitDigitB = abs(b % 10)
    return unitDigitA * unitDigitB
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns 
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20[/INST]  ```swift
func multiply(a: Int, b: Int) -> Int {
    let unitDigitA = abs(a % 10)
    let unitDigitB = abs(b % 10)
    return unitDigitA * unitDigitB
}
```

func multiply(a: Int, b: Int) -> Int {
    let unitDigitA = abs(a % 10)
    let unitDigitB = abs(b % 10)
    return unitDigitA * unitDigitB
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns 
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20[/INST]  ```swift
func multiply(a: Int, b: Int) -> Int {
    let unitDigitA = abs(a % 10)
    let unitDigitB = abs(b % 10)
    return unitDigitA * unitDigitB
}
```

func multiply(a: Int, b: Int) -> Int {
    let unitDigitA = abs(a % 10)
    let unitDigitB = abs(b % 10)
    return unitDigitA * unitDigitB
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns 
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20[/INST]  ```swift
func multiply(a: Int, b: Int) -> Int {
    let unitDigitA = abs(a % 10)
    let unitDigitB = abs(b % 10)
    return unitDigitA * unitDigitB
}
```

func multiply(a: Int, b: Int) -> Int {
    let unitDigitA = abs(a % 10)
    let unitDigitB = abs(b % 10)
    return unitDigitA * unitDigitB
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns 
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20[/INST]  ```swift
func multiply(a: Int, b: Int) -> Int {
    let unitDigitA = abs(a % 10)
    let unitDigitB = abs(b % 10)
    return unitDigitA * unitDigitB
}
```

func multiply(a: Int, b: Int) -> Int {
    let unitDigitA = abs(a % 10)
    let unitDigitB = abs(b % 10)
    return unitDigitA * unitDigitB
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns 
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20[/INST]  ```swift
func multiply(a: Int, b: Int) -> Int {
    let unitDigitA = abs(a % 10)
    let unitDigitB = abs(b % 10)
    return unitDigitA * unitDigitB
}
```

func multiply(a: Int, b: Int) -> Int {
    let unitDigitA = abs(a % 10)
    let unitDigitB = abs(b % 10)
    return unitDigitA * unitDigitB
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns 
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20[/INST]  ```swift
func multiply(a: Int, b: Int) -> Int {
    let unitDigitA = abs(a % 10)
    let unitDigitB = abs(b % 10)
    return unitDigitA * unitDigitB
}
```

func multiply(a: Int, b: Int) -> Int {
    let unitDigitA = abs(a % 10)
    let unitDigitB = abs(b % 10)
    return unitDigitA * unitDigitB
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns 
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20[/INST]  ```swift
func multiply(a: Int, b: Int) -> Int {
    let unitDigitA = abs(a % 10)
    let unitDigitB = abs(b % 10)
    return unitDigitA * unitDigitB
}
```

func multiply(a: Int, b: Int) -> Int {
    let unitDigitA = abs(a % 10)
    let unitDigitB = abs(b % 10)
    return unitDigitA * unitDigitB
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns 
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20[/INST]  ```swift
func multiply(a: Int, b: Int) -> Int {
    let unitDigitA = abs(a % 10)
    let unitDigitB = abs(b % 10)
    return unitDigitA * unitDigitB
}
```

func countUpper(s: String) -> Int {
    let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
    var count = 0
    for (index, char) in s.enumerated() {
        if index % 2 == 0 && vowels.contains(char) {
            count += 1
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0[/INST]  ```swift
func countUpper(s: String) -> Int {
    let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
    var count = 0
    for (index, char) in s.enumerated() {
        if index % 2 == 0 && vowels.contains(char) {
            count += 1
        }
    }
    return count
}
```

func countUpper(s: String) -> Int {
    let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
    var count = 0
    for (index, char) in s.enumerated() {
        if index % 2 == 0 && vowels.contains(char) {
            count += 1
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0[/INST]  ```swift
func countUpper(s: String) -> Int {
    let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
    var count = 0
    for (index, char) in s.enumerated() {
        if index % 2 == 0 && vowels.contains(char) {
            count += 1
        }
    }
    return count
}
```

func countUpper(s: String) -> Int {
    let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
    var count = 0
    for (index, char) in s.enumerated() {
        if index % 2 == 0 && vowels.contains(char) {
            count += 1
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0[/INST]  ```swift
func countUpper(s: String) -> Int {
    let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
    var count = 0
    for (index, char) in s.enumerated() {
        if index % 2 == 0 && vowels.contains(char) {
            count += 1
        }
    }
    return count
}
```

func countUpper(s: String) -> Int {
    var count = 0
    let vowels: Set<Character> = ["A", "E", "I", "O", "U"]

    for (index, char) in s.enumerated() {
        if index % 2 == 0 && vowels.contains(char) {
            count += 1
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0[/INST]  ```swift
func countUpper(s: String) -> Int {
    var count = 0
    let vowels: Set<Character> = ["A", "E", "I", "O", "U"]

    for (index, char) in s.enumerated() {
        if index % 2 == 0 && vowels.contains(char) {
            count += 1
        }
    }

    return count
}
```

func countUpper(s: String) -> Int {
    let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
    var count = 0
    for (index, char) in s.enumerated() {
        if index % 2 == 0 && vowels.contains(char) {
            count += 1
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0[/INST]  ```swift
func countUpper(s: String) -> Int {
    let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
    var count = 0
    for (index, char) in s.enumerated() {
        if index % 2 == 0 && vowels.contains(char) {
            count += 1
        }
    }
    return count
}
```

func countUpper(s: String) -> Int {
    let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
    var count = 0
    for (index, char) in s.enumerated() {
        if index % 2 == 0 && vowels.contains(char) {
            count += 1
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0[/INST]  ```swift
func countUpper(s: String) -> Int {
    let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
    var count = 0
    for (index, char) in s.enumerated() {
        if index % 2 == 0 && vowels.contains(char) {
            count += 1
        }
    }
    return count
}
```

func countUpper(s: String) -> Int {
    let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
    var count = 0
    for (index, char) in s.enumerated() {
        if index % 2 == 0 && vowels.contains(char) {
            count += 1
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0[/INST]  ```swift
func countUpper(s: String) -> Int {
    let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
    var count = 0
    for (index, char) in s.enumerated() {
        if index % 2 == 0 && vowels.contains(char) {
            count += 1
        }
    }
    return count
}
```

func countUpper(s: String) -> Int {
    var count = 0
    let vowels: Set<Character> = ["A", "E", "I", "O", "U"]

    for (index, char) in s.enumerated() {
        if index % 2 == 0 && vowels.contains(char) {
            count += 1
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0[/INST]  ```swift
func countUpper(s: String) -> Int {
    var count = 0
    let vowels: Set<Character> = ["A", "E", "I", "O", "U"]

    for (index, char) in s.enumerated() {
        if index % 2 == 0 && vowels.contains(char) {
            count += 1
        }
    }

    return count
}
```

func countUpper(s: String) -> Int {
    let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
    var count = 0
    for (index, char) in s.enumerated() {
        if index % 2 == 0 && vowels.contains(char) {
            count += 1
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0[/INST]  ```swift
func countUpper(s: String) -> Int {
    let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
    var count = 0
    for (index, char) in s.enumerated() {
        if index % 2 == 0 && vowels.contains(char) {
            count += 1
        }
    }
    return count
}
```

func countUpper(s: String) -> Int {
    let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
    var count = 0
    for (index, char) in s.enumerated() {
        if index % 2 == 0 && vowels.contains(char) {
            count += 1
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0[/INST]  ```swift
func countUpper(s: String) -> Int {
    let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
    var count = 0
    for (index, char) in s.enumerated() {
        if index % 2 == 0 && vowels.contains(char) {
            count += 1
        }
    }
    return count
}
```

func closestInteger(value: String) -> Int {
    if let number = Double(value) {
        if number >= 0 {
            return Int(number + 0.5)
        } else {
            return Int(number - 0.5)
        }
    } else {
        return 0
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15[/INST]  ```swift
func closestInteger(value: String) -> Int {
    if let number = Double(value) {
        if number >= 0 {
            return Int(number + 0.5)
        } else {
            return Int(number - 0.5)
        }
    } else {
        return 0
    }
}
```

func closestInteger(value: String) -> Int {
    if let number = Double(value) {
        if number >= 0 {
            return Int(number + 0.5)
        } else {
            return Int(number - 0.5)
        }
    } else {
        return 0
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15[/INST]  ```swift
func closestInteger(value: String) -> Int {
    if let number = Double(value) {
        if number >= 0 {
            return Int(number + 0.5)
        } else {
            return Int(number - 0.5)
        }
    } else {
        return 0
    }
}
```

func closestInteger(value: String) -> Int {
    if let number = Double(value) {
        if number >= 0 {
            return Int(number + 0.5)
        } else {
            return Int(number - 0.5)
        }
    } else {
        return 0
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15[/INST]  ```swift
func closestInteger(value: String) -> Int {
    if let number = Double(value) {
        if number >= 0 {
            return Int(number + 0.5)
        } else {
            return Int(number - 0.5)
        }
    } else {
        return 0
    }
}
```

func closestInteger(value: String) -> Int {
    if let number = Double(value) {
        if number >= 0 {
            return Int(number + 0.5)
        } else {
            return Int(number - 0.5)
        }
    } else {
        return 0
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15[/INST]  ```swift
func closestInteger(value: String) -> Int {
    if let number = Double(value) {
        if number >= 0 {
            return Int(number + 0.5)
        } else {
            return Int(number - 0.5)
        }
    } else {
        return 0
    }
}
```

func closestInteger(value: String) -> Int {
    if let number = Double(value) {
        if number >= 0 {
            return Int(number + 0.5)
        } else {
            return Int(number - 0.5)
        }
    }
    return 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15[/INST]  ```swift
func closestInteger(value: String) -> Int {
    if let number = Double(value) {
        if number >= 0 {
            return Int(number + 0.5)
        } else {
            return Int(number - 0.5)
        }
    }
    return 0
}
```

func closestInteger(value: String) -> Int {
    if let number = Double(value) {
        if number >= 0 {
            return Int(number + 0.5)
        } else {
            return Int(number - 0.5)
        }
    }
    return 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15[/INST]  ```swift
func closestInteger(value: String) -> Int {
    if let number = Double(value) {
        if number >= 0 {
            return Int(number + 0.5)
        } else {
            return Int(number - 0.5)
        }
    }
    return 0
}
```

func closestInteger(value: String) -> Int {
    if let number = Double(value) {
        if number >= 0 {
            return Int(number + 0.5)
        } else {
            return Int(number - 0.5)
        }
    } else {
        return 0
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15[/INST]  ```swift
func closestInteger(value: String) -> Int {
    if let number = Double(value) {
        if number >= 0 {
            return Int(number + 0.5)
        } else {
            return Int(number - 0.5)
        }
    } else {
        return 0
    }
}
```

func closestInteger(value: String) -> Int {
    if let number = Double(value) {
        if number >= 0 {
            return Int(number + 0.5)
        } else {
            return Int(number - 0.5)
        }
    } else {
        return 0
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15[/INST]  ```swift
func closestInteger(value: String) -> Int {
    if let number = Double(value) {
        if number >= 0 {
            return Int(number + 0.5)
        } else {
            return Int(number - 0.5)
        }
    } else {
        return 0
    }
}
```

func closestInteger(value: String) -> Int {
    if let number = Double(value) {
        if number >= 0 {
            return Int(number + 0.5)
        } else {
            return Int(number - 0.5)
        }
    } else {
        return 0
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15[/INST]  ```swift
func closestInteger(value: String) -> Int {
    if let number = Double(value) {
        if number >= 0 {
            return Int(number + 0.5)
        } else {
            return Int(number - 0.5)
        }
    } else {
        return 0
    }
}
```

func closestInteger(value: String) -> Int {
    if let number = Double(value) {
        if number >= 0 {
            return Int(number + 0.5)
        } else {
            return Int(number - 0.5)
        }
    } else {
        return 0
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15[/INST]  ```swift
func closestInteger(value: String) -> Int {
    if let number = Double(value) {
        if number >= 0 {
            return Int(number + 0.5)
        } else {
            return Int(number - 0.5)
        }
    } else {
        return 0
    }
}
```

func makeAPile(n: Int) -> [Int] {
    var pile = [Int]()
    var stones = n

    for _ in 1...n {
        pile.append(stones)
        stones += stones % 2 == 0 ? 2 : 1
    }

    return pile
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7][/INST]  ```swift
func makeAPile(n: Int) -> [Int] {
    var pile = [Int]()
    var stones = n

    for _ in 1...n {
        pile.append(stones)
        stones += stones % 2 == 0 ? 2 : 1
    }

    return pile
}
```
 // XCTAssertTrue failed

func makeAPile(n: Int) -> [Int] {
    var pile = [Int]()
    var stones = n

    for _ in 1...n {
        pile.append(stones)
        stones += stones % 2 == 0 ? 2 : 1
    }

    return pile
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7][/INST]  ```swift
func makeAPile(n: Int) -> [Int] {
    var pile = [Int]()
    var stones = n

    for _ in 1...n {
        pile.append(stones)
        stones += stones % 2 == 0 ? 2 : 1
    }

    return pile
}
```
 // XCTAssertTrue failed

func makeAPile(n: Int) -> [Int] {
    var pile = [Int]()
    var stones = n

    for _ in 1...n {
        pile.append(stones)
        stones += stones % 2 == 0 ? 2 : 1
    }

    return pile
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7][/INST]  ```swift
func makeAPile(n: Int) -> [Int] {
    var pile = [Int]()
    var stones = n

    for _ in 1...n {
        pile.append(stones)
        stones += stones % 2 == 0 ? 2 : 1
    }

    return pile
}
```
 // XCTAssertTrue failed

func makeAPile(n: Int) -> [Int] {
    var pile = [Int]()
    var stones = n

    for _ in 1...n {
        pile.append(stones)
        stones += stones % 2 == 0 ? 2 : 1
    }

    return pile
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7][/INST]  ```swift
func makeAPile(n: Int) -> [Int] {
    var pile = [Int]()
    var stones = n

    for _ in 1...n {
        pile.append(stones)
        stones += stones % 2 == 0 ? 2 : 1
    }

    return pile
}
```
 // XCTAssertTrue failed

func makeAPile(n: Int) -> [Int] {
    var pile = [Int]()
    var stones = n

    for _ in 1...n {
        pile.append(stones)
        stones += stones % 2 == 0 ? 2 : 1
    }

    return pile
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7][/INST]  ```swift
func makeAPile(n: Int) -> [Int] {
    var pile = [Int]()
    var stones = n

    for _ in 1...n {
        pile.append(stones)
        stones += stones % 2 == 0 ? 2 : 1
    }

    return pile
}
```
 // XCTAssertTrue failed

func makeAPile(n: Int) -> [Int] {
    var pile = [Int]()
    var stones = n

    for _ in 1...n {
        pile.append(stones)
        stones += stones % 2 == 0 ? 2 : 1
    }

    return pile
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7][/INST]  ```swift
func makeAPile(n: Int) -> [Int] {
    var pile = [Int]()
    var stones = n

    for _ in 1...n {
        pile.append(stones)
        stones += stones % 2 == 0 ? 2 : 1
    }

    return pile
}
```
 // XCTAssertTrue failed

func makeAPile(n: Int) -> [Int] {
    var pile = [Int]()
    var stones = n

    for _ in 1...n {
        pile.append(stones)
        stones += stones % 2 == 0 ? 2 : 1
    }

    return pile
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7][/INST]  ```swift
func makeAPile(n: Int) -> [Int] {
    var pile = [Int]()
    var stones = n

    for _ in 1...n {
        pile.append(stones)
        stones += stones % 2 == 0 ? 2 : 1
    }

    return pile
}
```
 // XCTAssertTrue failed

func makeAPile(n: Int) -> [Int] {
    var pile = [Int]()
    var stones = n

    for _ in 1...n {
        pile.append(stones)
        stones += stones % 2 == 0 ? 2 : 1
    }

    return pile
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7][/INST]  ```swift
func makeAPile(n: Int) -> [Int] {
    var pile = [Int]()
    var stones = n

    for _ in 1...n {
        pile.append(stones)
        stones += stones % 2 == 0 ? 2 : 1
    }

    return pile
}
```
 // XCTAssertTrue failed

func makeAPile(n: Int) -> [Int] {
    var pile = [Int]()
    var stones = n

    for _ in 1...n {
        pile.append(stones)
        stones += stones % 2 == 0 ? 2 : 1
    }

    return pile
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7][/INST]  ```swift
func makeAPile(n: Int) -> [Int] {
    var pile = [Int]()
    var stones = n

    for _ in 1...n {
        pile.append(stones)
        stones += stones % 2 == 0 ? 2 : 1
    }

    return pile
}
```
 // XCTAssertTrue failed

func makeAPile(n: Int) -> [Int] {
    var pile = [Int]()
    var stones = n

    for _ in 1...n {
        pile.append(stones)
        stones += stones % 2 == 0 ? 2 : 1
    }

    return pile
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7][/INST]  ```swift
func makeAPile(n: Int) -> [Int] {
    var pile = [Int]()
    var stones = n

    for _ in 1...n {
        pile.append(stones)
        stones += stones % 2 == 0 ? 2 : 1
    }

    return pile
}
```
 // XCTAssertTrue failed

func wordsString(s: String) -> [String] {
    return s.components(separatedBy: CharacterSet(charactersIn: ", ")).filter { !$0.isEmpty }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"][/INST]  ```swift
func wordsString(s: String) -> [String] {
    return s.components(separatedBy: CharacterSet(charactersIn: ", ")).filter { !$0.isEmpty }
}
```

func wordsString(s: String) -> [String] {
    let words = s.components(separatedBy: CharacterSet(charactersIn: ", "))
    return words.filter { !$0.isEmpty }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"][/INST]  ```swift
func wordsString(s: String) -> [String] {
    let words = s.components(separatedBy: CharacterSet(charactersIn: ", "))
    return words.filter { !$0.isEmpty }
}
```

func wordsString(s: String) -> [String] {
    let words = s.components(separatedBy: CharacterSet(charactersIn: ", "))
    return words.filter { !$0.isEmpty }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"][/INST]  ```swift
func wordsString(s: String) -> [String] {
    let words = s.components(separatedBy: CharacterSet(charactersIn: ", "))
    return words.filter { !$0.isEmpty }
}
```

func wordsString(s: String) -> [String] {
    let words = s.components(separatedBy: CharacterSet(charactersIn: ", "))
    return words.filter { !$0.isEmpty }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"][/INST]  ```swift
func wordsString(s: String) -> [String] {
    let words = s.components(separatedBy: CharacterSet(charactersIn: ", "))
    return words.filter { !$0.isEmpty }
}
```

func wordsString(s: String) -> [String] {
    let words = s.components(separatedBy: CharacterSet(charactersIn: ", "))
    return words.filter { !$0.isEmpty }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"][/INST]  ```swift
func wordsString(s: String) -> [String] {
    let words = s.components(separatedBy: CharacterSet(charactersIn: ", "))
    return words.filter { !$0.isEmpty }
}
```

func wordsString(s: String) -> [String] {
    let words = s.components(separatedBy: CharacterSet(charactersIn: ", "))
    return words.filter { !$0.isEmpty }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"][/INST]  ```swift
func wordsString(s: String) -> [String] {
    let words = s.components(separatedBy: CharacterSet(charactersIn: ", "))
    return words.filter { !$0.isEmpty }
}
```

func wordsString(s: String) -> [String] {
    let words = s.components(separatedBy: CharacterSet(charactersIn: ", "))
    return words.filter { !$0.isEmpty }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"][/INST]  ```swift
func wordsString(s: String) -> [String] {
    let words = s.components(separatedBy: CharacterSet(charactersIn: ", "))
    return words.filter { !$0.isEmpty }
}
```

func wordsString(s: String) -> [String] {
    let words = s.components(separatedBy: CharacterSet(charactersIn: ", "))
    return words.filter { !$0.isEmpty }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"][/INST]  ```swift
func wordsString(s: String) -> [String] {
    let words = s.components(separatedBy: CharacterSet(charactersIn: ", "))
    return words.filter { !$0.isEmpty }
}
```

func wordsString(s: String) -> [String] {
    let words = s.components(separatedBy: CharacterSet(charactersIn: ", "))
    return words.filter { !$0.isEmpty }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"][/INST]  ```swift
func wordsString(s: String) -> [String] {
    let words = s.components(separatedBy: CharacterSet(charactersIn: ", "))
    return words.filter { !$0.isEmpty }
}
```

func wordsString(s: String) -> [String] {
    let words = s.components(separatedBy: CharacterSet(charactersIn: ", "))
    return words.filter { !$0.isEmpty }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"][/INST]  ```swift
func wordsString(s: String) -> [String] {
    let words = s.components(separatedBy: CharacterSet(charactersIn: ", "))
    return words.filter { !$0.isEmpty }
}
```

func chooseNum(x: Int, y: Int) -> Int {
    var maxEven = -1
    for i in stride(from: y, through: x, by: -1) {
        if i % 2 == 0 {
            maxEven = i
            break
        }
    }
    return maxEven
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If 
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1[/INST]  ```swift
func chooseNum(x: Int, y: Int) -> Int {
    var maxEven = -1
    for i in stride(from: y, through: x, by: -1) {
        if i % 2 == 0 {
            maxEven = i
            break
        }
    }
    return maxEven
}
```

func chooseNum(x: Int, y: Int) -> Int {
    var maxEven = -1
    for num in stride(from: y, through: x, by: -1) {
        if num % 2 == 0 {
            maxEven = num
            break
        }
    }
    return maxEven
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If 
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1[/INST]  ```swift
func chooseNum(x: Int, y: Int) -> Int {
    var maxEven = -1
    for num in stride(from: y, through: x, by: -1) {
        if num % 2 == 0 {
            maxEven = num
            break
        }
    }
    return maxEven
}
```

func chooseNum(x: Int, y: Int) -> Int {
    if x > y {
        return -1
    }

    var maxEven = -1

    for i in x...y {
        if i % 2 == 0 {
            maxEven = max(maxEven, i)
        }
    }

    return maxEven
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If 
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1[/INST]  ```swift
func chooseNum(x: Int, y: Int) -> Int {
    if x > y {
        return -1
    }

    var maxEven = -1

    for i in x...y {
        if i % 2 == 0 {
            maxEven = max(maxEven, i)
        }
    }

    return maxEven
}
```

func chooseNum(x: Int, y: Int) -> Int {
    if x > y {
        return -1
    }

    var maxEven = -1
    for i in stride(from: y, through: x, by: -1) {
        if i % 2 == 0 {
            maxEven = i
            break
        }
    }

    return maxEven
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If 
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1[/INST]  ```swift
func chooseNum(x: Int, y: Int) -> Int {
    if x > y {
        return -1
    }

    var maxEven = -1
    for i in stride(from: y, through: x, by: -1) {
        if i % 2 == 0 {
            maxEven = i
            break
        }
    }

    return maxEven
}
```

func chooseNum(x: Int, y: Int) -> Int {
    if x > y {
        return -1
    }

    var maxEven = -1
    for i in stride(from: y, through: x, by: -1) {
        if i % 2 == 0 {
            maxEven = i
            break
        }
    }

    return maxEven
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If 
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1[/INST]  ```swift
func chooseNum(x: Int, y: Int) -> Int {
    if x > y {
        return -1
    }

    var maxEven = -1
    for i in stride(from: y, through: x, by: -1) {
        if i % 2 == 0 {
            maxEven = i
            break
        }
    }

    return maxEven
}
```

func chooseNum(x: Int, y: Int) -> Int {
    var maxEven = -1
    for num in max(x, y)...min(x, y) {
        if num % 2 == 0 {
            maxEven = num
            break
        }
    }
    return maxEven
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If 
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1[/INST]  ```swift
func chooseNum(x: Int, y: Int) -> Int {
    var maxEven = -1
    for num in max(x, y)...min(x, y) {
        if num % 2 == 0 {
            maxEven = num
            break
        }
    }
    return maxEven
}
```
 // Fatal error: Range requires lowerBound <= upperBound

func chooseNum(x: Int, y: Int) -> Int {
    if x > y {
        return -1
    }

    var maxEven = -1
    for i in stride(from: y, through: x, by: -1) {
        if i % 2 == 0 {
            maxEven = i
            break
        }
    }

    return maxEven
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If 
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1[/INST]  ```swift
func chooseNum(x: Int, y: Int) -> Int {
    if x > y {
        return -1
    }

    var maxEven = -1
    for i in stride(from: y, through: x, by: -1) {
        if i % 2 == 0 {
            maxEven = i
            break
        }
    }

    return maxEven
}
```

func chooseNum(x: Int, y: Int) -> Int {
    if x > y {
        return -1
    }

    var maxEven = -1
    for i in stride(from: y, through: x, by: -1) {
        if i % 2 == 0 {
            maxEven = i
            break
        }
    }

    return maxEven
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If 
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1[/INST]  ```swift
func chooseNum(x: Int, y: Int) -> Int {
    if x > y {
        return -1
    }

    var maxEven = -1
    for i in stride(from: y, through: x, by: -1) {
        if i % 2 == 0 {
            maxEven = i
            break
        }
    }

    return maxEven
}
```

func chooseNum(x: Int, y: Int) -> Int {
    var maxEven = -1
    for i in x...y {
        if i % 2 == 0 {
            maxEven = max(maxEven, i)
        }
    }
    return maxEven
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If 
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1[/INST]  ```swift
func chooseNum(x: Int, y: Int) -> Int {
    var maxEven = -1
    for i in x...y {
        if i % 2 == 0 {
            maxEven = max(maxEven, i)
        }
    }
    return maxEven
}
```
 // Fatal error: Range requires lowerBound <= upperBound

func chooseNum(x: Int, y: Int) -> Int {
    if x > y {
        return -1
    }

    var maxEven = -1
    for i in stride(from: y, through: x, by: -1) {
        if i % 2 == 0 {
            maxEven = i
            break
        }
    }

    return maxEven
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If 
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1[/INST]  ```swift
func chooseNum(x: Int, y: Int) -> Int {
    if x > y {
        return -1
    }

    var maxEven = -1
    for i in stride(from: y, through: x, by: -1) {
        if i % 2 == 0 {
            maxEven = i
            break
        }
    }

    return maxEven
}
```

extension Int: Error {

}

extension Int: Error {}

func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
    if n > m {
        return .failure(-1)
    }

    let sum = (n + m) * (m - n + 1) / 2
    let avg = Double(sum) / Double(m - n + 1)
    let roundedAvg = Int(avg.rounded())
    let binaryString = String(roundedAvg, radix: 2)

    return .success("0b" + binaryString)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m). 
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) == .success("0b11")
roundedAvg(n: 7, m: 5) == .failure(-1)
roundedAvg(n: 10, m: 20) == .success("0b1111")
roundedAvg(n: 20, m: 33) == .success("0b11010")[/INST]  ```swift
extension Int: Error {}

func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
    if n > m {
        return .failure(-1)
    }

    let sum = (n + m) * (m - n + 1) / 2
    let avg = Double(sum) / Double(m - n + 1)
    let roundedAvg = Int(avg.rounded())
    let binaryString = String(roundedAvg, radix: 2)

    return .success("0b" + binaryString)
}
```
extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'

extension Int: Error {

}

extension Int: Error {}

func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
    if n > m {
        return .failure(-1)
    }

    let sum = (n + m) * (m - n + 1) / 2
    let avg = Double(sum) / Double(m - n + 1)
    let roundedAvg = Int(round(avg))
    let binary = String(roundedAvg, radix: 2)

    return .success("0b" + binary)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m). 
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) == .success("0b11")
roundedAvg(n: 7, m: 5) == .failure(-1)
roundedAvg(n: 10, m: 20) == .success("0b1111")
roundedAvg(n: 20, m: 33) == .success("0b11010")[/INST]  ```swift
extension Int: Error {}

func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
    if n > m {
        return .failure(-1)
    }

    let sum = (n + m) * (m - n + 1) / 2
    let avg = Double(sum) / Double(m - n + 1)
    let roundedAvg = Int(round(avg))
    let binary = String(roundedAvg, radix: 2)

    return .success("0b" + binary)
}
```
extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'

extension Int: Error {

}

extension Int: Error {}

func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
    if n > m {
        return .failure(-1)
    }

    let sum = (n + m) * (m - n + 1) / 2
    let average = Double(sum) / Double(m - n + 1)
    let roundedAverage = Int(round(average))
    let binaryString = String(roundedAverage, radix: 2)

    return .success("0b" + binaryString)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m). 
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) == .success("0b11")
roundedAvg(n: 7, m: 5) == .failure(-1)
roundedAvg(n: 10, m: 20) == .success("0b1111")
roundedAvg(n: 20, m: 33) == .success("0b11010")[/INST]  ```swift
extension Int: Error {}

func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
    if n > m {
        return .failure(-1)
    }

    let sum = (n + m) * (m - n + 1) / 2
    let average = Double(sum) / Double(m - n + 1)
    let roundedAverage = Int(round(average))
    let binaryString = String(roundedAverage, radix: 2)

    return .success("0b" + binaryString)
}
```
extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'

extension Int: Error {

}

extension Int: Error {}

func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
    if n > m {
        return .failure(-1)
    }

    let sum = (n + m) * (m - n + 1) / 2
    let average = Double(sum) / Double(m - n + 1)
    let roundedAverage = Int(round(average))
    let binaryString = String(roundedAverage, radix: 2)

    return .success("0b" + binaryString)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m). 
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) == .success("0b11")
roundedAvg(n: 7, m: 5) == .failure(-1)
roundedAvg(n: 10, m: 20) == .success("0b1111")
roundedAvg(n: 20, m: 33) == .success("0b11010")[/INST]  ```swift
extension Int: Error {}

func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
    if n > m {
        return .failure(-1)
    }

    let sum = (n + m) * (m - n + 1) / 2
    let average = Double(sum) / Double(m - n + 1)
    let roundedAverage = Int(round(average))
    let binaryString = String(roundedAverage, radix: 2)

    return .success("0b" + binaryString)
}
```
extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'

extension Int: Error {

}

extension Int: Error {}

func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
    if n > m {
        return .failure(-1)
    }

    let sum = (n + m) * (m - n + 1) / 2
    let average = Double(sum) / Double(m - n + 1)
    let roundedAverage = Int(round(average))
    let binaryString = String(roundedAverage, radix: 2)

    return .success("0b" + binaryString)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m). 
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) == .success("0b11")
roundedAvg(n: 7, m: 5) == .failure(-1)
roundedAvg(n: 10, m: 20) == .success("0b1111")
roundedAvg(n: 20, m: 33) == .success("0b11010")[/INST]  ```swift
extension Int: Error {}

func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
    if n > m {
        return .failure(-1)
    }

    let sum = (n + m) * (m - n + 1) / 2
    let average = Double(sum) / Double(m - n + 1)
    let roundedAverage = Int(round(average))
    let binaryString = String(roundedAverage, radix: 2)

    return .success("0b" + binaryString)
}
```
extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'

extension Int: Error {

}

extension Int: Error {}

func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
    if n > m {
        return .failure(-1)
    }

    let sum = (n + m) * (m - n + 1) / 2
    let avg = Double(sum) / Double(m - n + 1)
    let roundedAvg = Int(avg.rounded())
    let binaryString = String(roundedAvg, radix: 2)

    return .success("0b" + binaryString)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m). 
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) == .success("0b11")
roundedAvg(n: 7, m: 5) == .failure(-1)
roundedAvg(n: 10, m: 20) == .success("0b1111")
roundedAvg(n: 20, m: 33) == .success("0b11010")[/INST]  ```swift
extension Int: Error {}

func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
    if n > m {
        return .failure(-1)
    }

    let sum = (n + m) * (m - n + 1) / 2
    let avg = Double(sum) / Double(m - n + 1)
    let roundedAvg = Int(avg.rounded())
    let binaryString = String(roundedAvg, radix: 2)

    return .success("0b" + binaryString)
}
```
extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'

extension Int: Error {

}

extension Int: Error {}

func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
    if n > m {
        return .failure(-1)
    }

    let sum = (n + m) * (m - n + 1) / 2
    let avg = Double(sum) / Double(m - n + 1)
    let roundedAvg = Int(avg.rounded())
    let binary = String(roundedAvg, radix: 2)

    return .success("0b" + binary)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m). 
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) == .success("0b11")
roundedAvg(n: 7, m: 5) == .failure(-1)
roundedAvg(n: 10, m: 20) == .success("0b1111")
roundedAvg(n: 20, m: 33) == .success("0b11010")[/INST]  ```swift
extension Int: Error {}

func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
    if n > m {
        return .failure(-1)
    }

    let sum = (n + m) * (m - n + 1) / 2
    let avg = Double(sum) / Double(m - n + 1)
    let roundedAvg = Int(avg.rounded())
    let binary = String(roundedAvg, radix: 2)

    return .success("0b" + binary)
}
```
extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'

extension Int: Error {

}

extension Int: Error {}

func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
    if n > m {
        return .failure(-1)
    }

    let sum = (n + m) * (m - n + 1) / 2
    let average = Double(sum) / Double(m - n + 1)
    let roundedAverage = Int(round(average))
    let binaryString = String(roundedAverage, radix: 2)

    return .success("0b" + binaryString)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m). 
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) == .success("0b11")
roundedAvg(n: 7, m: 5) == .failure(-1)
roundedAvg(n: 10, m: 20) == .success("0b1111")
roundedAvg(n: 20, m: 33) == .success("0b11010")[/INST]  ```swift
extension Int: Error {}

func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
    if n > m {
        return .failure(-1)
    }

    let sum = (n + m) * (m - n + 1) / 2
    let average = Double(sum) / Double(m - n + 1)
    let roundedAverage = Int(round(average))
    let binaryString = String(roundedAverage, radix: 2)

    return .success("0b" + binaryString)
}
```
extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'

extension Int: Error {

}

extension Int: Error {}

func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
    if n > m {
        return .failure(-1)
    }

    let sum = (n + m) * (m - n + 1) / 2
    let average = Double(sum) / Double(m - n + 1)
    let roundedAverage = Int(round(average))
    let binaryString = String(roundedAverage, radix: 2)

    return .success("0b" + binaryString)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m). 
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) == .success("0b11")
roundedAvg(n: 7, m: 5) == .failure(-1)
roundedAvg(n: 10, m: 20) == .success("0b1111")
roundedAvg(n: 20, m: 33) == .success("0b11010")[/INST]  ```swift
extension Int: Error {}

func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
    if n > m {
        return .failure(-1)
    }

    let sum = (n + m) * (m - n + 1) / 2
    let average = Double(sum) / Double(m - n + 1)
    let roundedAverage = Int(round(average))
    let binaryString = String(roundedAverage, radix: 2)

    return .success("0b" + binaryString)
}
```
extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'

extension Int: Error {

}

extension Int: Error {}

func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
    if n > m {
        return .failure(-1)
    }

    let sum = (n + m) * (m - n + 1) / 2
    let average = Double(sum) / Double(m - n + 1)
    let roundedAverage = Int(round(average))
    let binaryString = String(roundedAverage, radix: 2)

    return .success("0b" + binaryString)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m). 
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) == .success("0b11")
roundedAvg(n: 7, m: 5) == .failure(-1)
roundedAvg(n: 10, m: 20) == .success("0b1111")
roundedAvg(n: 20, m: 33) == .success("0b11010")[/INST]  ```swift
extension Int: Error {}

func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
    if n > m {
        return .failure(-1)
    }

    let sum = (n + m) * (m - n + 1) / 2
    let average = Double(sum) / Double(m - n + 1)
    let roundedAverage = Int(round(average))
    let binaryString = String(roundedAverage, radix: 2)

    return .success("0b" + binaryString)
}
```
extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'

func uniqueDigits(x: [Int]) -> [Int] {
    var result = [Int]()

    for num in x {
        var temp = num
        var hasEvenDigit = false

        while temp > 0 {
            if (temp % 10) % 2 == 0 {
                hasEvenDigit = true
                break
            }
            temp /= 10
        }

        if !hasEvenDigit {
            result.append(num)
        }
    }

    return result.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all 
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int][/INST]  ```swift
func uniqueDigits(x: [Int]) -> [Int] {
    var result = [Int]()

    for num in x {
        var temp = num
        var hasEvenDigit = false

        while temp > 0 {
            if (temp % 10) % 2 == 0 {
                hasEvenDigit = true
                break
            }
            temp /= 10
        }

        if !hasEvenDigit {
            result.append(num)
        }
    }

    return result.sorted()
}
```

func uniqueDigits(x: [Int]) -> [Int] {
    var result = [Int]()

    for num in x {
        var temp = num
        var hasEvenDigit = false

        while temp > 0 {
            if (temp % 10) % 2 == 0 {
                hasEvenDigit = true
                break
            }
            temp /= 10
        }

        if !hasEvenDigit {
            result.append(num)
        }
    }

    return result.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all 
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int][/INST]  ```swift
func uniqueDigits(x: [Int]) -> [Int] {
    var result = [Int]()

    for num in x {
        var temp = num
        var hasEvenDigit = false

        while temp > 0 {
            if (temp % 10) % 2 == 0 {
                hasEvenDigit = true
                break
            }
            temp /= 10
        }

        if !hasEvenDigit {
            result.append(num)
        }
    }

    return result.sorted()
}
```

func uniqueDigits(x: [Int]) -> [Int] {
    var result = [Int]()
    for num in x {
        var temp = num
        var hasEvenDigit = false
        while temp > 0 {
            if (temp % 10) % 2 == 0 {
                hasEvenDigit = true
                break
            }
            temp /= 10
        }
        if !hasEvenDigit {
            result.append(num)
        }
    }
    return result.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all 
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int][/INST]  ```swift
func uniqueDigits(x: [Int]) -> [Int] {
    var result = [Int]()
    for num in x {
        var temp = num
        var hasEvenDigit = false
        while temp > 0 {
            if (temp % 10) % 2 == 0 {
                hasEvenDigit = true
                break
            }
            temp /= 10
        }
        if !hasEvenDigit {
            result.append(num)
        }
    }
    return result.sorted()
}
```

func uniqueDigits(x: [Int]) -> [Int] {
    var result = [Int]()
    for num in x {
        var tempNum = num
        var hasEvenDigit = false
        while tempNum > 0 {
            if (tempNum % 10) % 2 == 0 {
                hasEvenDigit = true
                break
            }
            tempNum /= 10
        }
        if !hasEvenDigit {
            result.append(num)
        }
    }
    return result.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all 
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int][/INST]  ```swift
func uniqueDigits(x: [Int]) -> [Int] {
    var result = [Int]()
    for num in x {
        var tempNum = num
        var hasEvenDigit = false
        while tempNum > 0 {
            if (tempNum % 10) % 2 == 0 {
                hasEvenDigit = true
                break
            }
            tempNum /= 10
        }
        if !hasEvenDigit {
            result.append(num)
        }
    }
    return result.sorted()
}
```

func uniqueDigits(x: [Int]) -> [Int] {
    var result = [Int]()

    for num in x {
        var temp = num
        var hasEvenDigit = false

        while temp > 0 {
            if (temp % 10) % 2 == 0 {
                hasEvenDigit = true
                break
            }
            temp /= 10
        }

        if !hasEvenDigit {
            result.append(num)
        }
    }

    return result.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all 
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int][/INST]  ```swift
func uniqueDigits(x: [Int]) -> [Int] {
    var result = [Int]()

    for num in x {
        var temp = num
        var hasEvenDigit = false

        while temp > 0 {
            if (temp % 10) % 2 == 0 {
                hasEvenDigit = true
                break
            }
            temp /= 10
        }

        if !hasEvenDigit {
            result.append(num)
        }
    }

    return result.sorted()
}
```

func uniqueDigits(x: [Int]) -> [Int] {
    var result = [Int]()

    for num in x {
        var temp = num
        var hasEvenDigit = false

        while temp > 0 {
            if (temp % 10) % 2 == 0 {
                hasEvenDigit = true
                break
            }
            temp /= 10
        }

        if !hasEvenDigit {
            result.append(num)
        }
    }

    return result.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all 
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int][/INST]  ```swift
func uniqueDigits(x: [Int]) -> [Int] {
    var result = [Int]()

    for num in x {
        var temp = num
        var hasEvenDigit = false

        while temp > 0 {
            if (temp % 10) % 2 == 0 {
                hasEvenDigit = true
                break
            }
            temp /= 10
        }

        if !hasEvenDigit {
            result.append(num)
        }
    }

    return result.sorted()
}
```

func uniqueDigits(x: [Int]) -> [Int] {
    var result = [Int]()

    for num in x {
        var temp = num
        var hasEvenDigit = false

        while temp > 0 {
            if (temp % 10) % 2 == 0 {
                hasEvenDigit = true
                break
            }
            temp /= 10
        }

        if !hasEvenDigit {
            result.append(num)
        }
    }

    return result.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all 
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int][/INST]  ```swift
func uniqueDigits(x: [Int]) -> [Int] {
    var result = [Int]()

    for num in x {
        var temp = num
        var hasEvenDigit = false

        while temp > 0 {
            if (temp % 10) % 2 == 0 {
                hasEvenDigit = true
                break
            }
            temp /= 10
        }

        if !hasEvenDigit {
            result.append(num)
        }
    }

    return result.sorted()
}
```

func uniqueDigits(x: [Int]) -> [Int] {
    var result = [Int]()

    for num in x {
        var tempNum = num
        var hasEvenDigit = false

        while tempNum > 0 {
            if (tempNum % 10) % 2 == 0 {
                hasEvenDigit = true
                break
            }
            tempNum /= 10
        }

        if !hasEvenDigit {
            result.append(num)
        }
    }

    return result.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all 
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int][/INST]  ```swift
func uniqueDigits(x: [Int]) -> [Int] {
    var result = [Int]()

    for num in x {
        var tempNum = num
        var hasEvenDigit = false

        while tempNum > 0 {
            if (tempNum % 10) % 2 == 0 {
                hasEvenDigit = true
                break
            }
            tempNum /= 10
        }

        if !hasEvenDigit {
            result.append(num)
        }
    }

    return result.sorted()
}
```

func uniqueDigits(x: [Int]) -> [Int] {
    var result = [Int]()
    for num in x {
        var temp = num
        var hasEvenDigit = false
        while temp > 0 {
            if temp % 2 == 0 {
                hasEvenDigit = true
                break
            }
            temp /= 10
        }
        if !hasEvenDigit {
            result.append(num)
        }
    }
    return result.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all 
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int][/INST]  ```swift
func uniqueDigits(x: [Int]) -> [Int] {
    var result = [Int]()
    for num in x {
        var temp = num
        var hasEvenDigit = false
        while temp > 0 {
            if temp % 2 == 0 {
                hasEvenDigit = true
                break
            }
            temp /= 10
        }
        if !hasEvenDigit {
            result.append(num)
        }
    }
    return result.sorted()
}
```

func uniqueDigits(x: [Int]) -> [Int] {
    var result = [Int]()
    for num in x {
        var temp = num
        var hasEvenDigit = false
        while temp > 0 {
            if (temp % 10) % 2 == 0 {
                hasEvenDigit = true
                break
            }
            temp /= 10
        }
        if !hasEvenDigit {
            result.append(num)
        }
    }
    return result.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all 
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int][/INST]  ```swift
func uniqueDigits(x: [Int]) -> [Int] {
    var result = [Int]()
    for num in x {
        var temp = num
        var hasEvenDigit = false
        while temp > 0 {
            if (temp % 10) % 2 == 0 {
                hasEvenDigit = true
                break
            }
            temp /= 10
        }
        if !hasEvenDigit {
            result.append(num)
        }
    }
    return result.sorted()
}
```

func byLength(arr: [Int]) -> [String] {
    let numbers = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
    let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
    let sorted = filtered.sorted(by: >)
    return sorted.map { numbers[$0 - 1] }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"][/INST]  ```swift
func byLength(arr: [Int]) -> [String] {
    let numbers = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
    let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
    let sorted = filtered.sorted(by: >)
    return sorted.map { numbers[$0 - 1] }
}
```

func byLength(arr: [Int]) -> [String] {
    let numbers = [1: "One", 2: "Two", 3: "Three", 4: "Four", 5: "Five", 6: "Six", 7: "Seven", 8: "Eight", 9: "Nine"]
    let filtered = arr.filter { $0 >= 1 && $0 <= 9 }.sorted(by: >)
    return filtered.map { numbers[$0]! }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"][/INST]  ```swift
func byLength(arr: [Int]) -> [String] {
    let numbers = [1: "One", 2: "Two", 3: "Three", 4: "Four", 5: "Five", 6: "Six", 7: "Seven", 8: "Eight", 9: "Nine"]
    let filtered = arr.filter { $0 >= 1 && $0 <= 9 }.sorted(by: >)
    return filtered.map { numbers[$0]! }
}
```

func byLength(arr: [Int]) -> [String] {
    let numberNames = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
    let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
    let sorted = filtered.sorted(by: >)
    let named = sorted.map { numberNames[$0 - 1] }
    return named
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"][/INST]  ```swift
func byLength(arr: [Int]) -> [String] {
    let numberNames = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
    let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
    let sorted = filtered.sorted(by: >)
    let named = sorted.map { numberNames[$0 - 1] }
    return named
}
```

func byLength(arr: [Int]) -> [String] {
    let numberNames = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
    let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
    let sorted = filtered.sorted(by: >)
    return sorted.map { numberNames[$0 - 1] }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"][/INST]  ```swift
func byLength(arr: [Int]) -> [String] {
    let numberNames = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
    let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
    let sorted = filtered.sorted(by: >)
    return sorted.map { numberNames[$0 - 1] }
}
```

func byLength(arr: [Int]) -> [String] {
    let numberNames = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
    let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
    let sorted = filtered.sorted(by: >)
    return sorted.map { numberNames[$0 - 1] }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"][/INST]  ```swift
func byLength(arr: [Int]) -> [String] {
    let numberNames = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
    let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
    let sorted = filtered.sorted(by: >)
    return sorted.map { numberNames[$0 - 1] }
}
```

func byLength(arr: [Int]) -> [String] {
    let numberNames = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
    let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
    let sorted = filtered.sorted(by: >)
    return sorted.map { numberNames[$0 - 1] }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"][/INST]  ```swift
func byLength(arr: [Int]) -> [String] {
    let numberNames = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
    let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
    let sorted = filtered.sorted(by: >)
    return sorted.map { numberNames[$0 - 1] }
}
```

func byLength(arr: [Int]) -> [String] {
    let numberNames = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
    let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
    let sorted = filtered.sorted(by: >)
    return sorted.map { numberNames[$0 - 1] }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"][/INST]  ```swift
func byLength(arr: [Int]) -> [String] {
    let numberNames = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
    let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
    let sorted = filtered.sorted(by: >)
    return sorted.map { numberNames[$0 - 1] }
}
```

func byLength(arr: [Int]) -> [String] {
    let numberNames = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
    let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
    let sorted = filtered.sorted(by: >)
    return sorted.map { numberNames[$0 - 1] }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"][/INST]  ```swift
func byLength(arr: [Int]) -> [String] {
    let numberNames = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
    let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
    let sorted = filtered.sorted(by: >)
    return sorted.map { numberNames[$0 - 1] }
}
```

func byLength(arr: [Int]) -> [String] {
    let numberNames = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
    let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
    let sorted = filtered.sorted(by: >)
    return sorted.map { numberNames[$0 - 1] }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"][/INST]  ```swift
func byLength(arr: [Int]) -> [String] {
    let numberNames = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
    let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
    let sorted = filtered.sorted(by: >)
    return sorted.map { numberNames[$0 - 1] }
}
```

func byLength(arr: [Int]) -> [String] {
    let numbers = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
    let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
    let sorted = filtered.sorted(by: >)
    let named = sorted.map { numbers[$0 - 1] }
    return named
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"][/INST]  ```swift
func byLength(arr: [Int]) -> [String] {
    let numbers = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
    let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
    let sorted = filtered.sorted(by: >)
    let named = sorted.map { numbers[$0 - 1] }
    return named
}
```

func f(n: Int) -> [Int] {
    var result = [Int]()
    for i in 1...n {
        if i % 2 == 0 {
            result.append(factorial(i))
        } else {
            result.append(sum(i))
        }
    }
    return result
}

func factorial(_ n: Int) -> Int {
    if n == 0 {
        return 1
    }
    var result = 1
    for i in 1...n {
        result *= i
    }
    return result
}

func sum(_ n: Int) -> Int {
    var result = 0
    for i in 1...n {
        result += i
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15][/INST]  ```swift
func f(n: Int) -> [Int] {
    var result = [Int]()
    for i in 1...n {
        if i % 2 == 0 {
            result.append(factorial(i))
        } else {
            result.append(sum(i))
        }
    }
    return result
}

func factorial(_ n: Int) -> Int {
    if n == 0 {
        return 1
    }
    var result = 1
    for i in 1...n {
        result *= i
    }
    return result
}

func sum(_ n: Int) -> Int {
    var result = 0
    for i in 1...n {
        result += i
    }
    return result
}
```

func f(n: Int) -> [Int] {
    var result = [Int]()

    for i in 1...n {
        if i % 2 == 0 {
            var factorial = 1
            for j in 2...i {
                factorial *= j
            }
            result.append(factorial)
        } else {
            var sum = 0
            for j in 1...i {
                sum += j
            }
            result.append(sum)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15][/INST]  ```swift
func f(n: Int) -> [Int] {
    var result = [Int]()

    for i in 1...n {
        if i % 2 == 0 {
            var factorial = 1
            for j in 2...i {
                factorial *= j
            }
            result.append(factorial)
        } else {
            var sum = 0
            for j in 1...i {
                sum += j
            }
            result.append(sum)
        }
    }

    return result
}
```

func f(n: Int) -> [Int] {
    var result = [Int]()

    for i in 1...n {
        if i % 2 == 0 {
            var factorial = 1
            for j in 2...i {
                factorial *= j
            }
            result.append(factorial)
        } else {
            var sum = 0
            for j in 1...i {
                sum += j
            }
            result.append(sum)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15][/INST]  ```swift
func f(n: Int) -> [Int] {
    var result = [Int]()

    for i in 1...n {
        if i % 2 == 0 {
            var factorial = 1
            for j in 2...i {
                factorial *= j
            }
            result.append(factorial)
        } else {
            var sum = 0
            for j in 1...i {
                sum += j
            }
            result.append(sum)
        }
    }

    return result
}
```

func f(n: Int) -> [Int] {
    var result = [Int]()
    for i in 1...n {
        if i % 2 == 0 {
            var factorial = 1
            for j in 2...i {
                factorial *= j
            }
            result.append(factorial)
        } else {
            var sum = 0
            for j in 1...i {
                sum += j
            }
            result.append(sum)
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15][/INST]  ```swift
func f(n: Int) -> [Int] {
    var result = [Int]()
    for i in 1...n {
        if i % 2 == 0 {
            var factorial = 1
            for j in 2...i {
                factorial *= j
            }
            result.append(factorial)
        } else {
            var sum = 0
            for j in 1...i {
                sum += j
            }
            result.append(sum)
        }
    }
    return result
}
```

func f(n: Int) -> [Int] {
    var result = [Int]()
    for i in 1...n {
        if i % 2 == 0 {
            result.append(factorial(i))
        } else {
            result.append(sum(i))
        }
    }
    return result
}

func factorial(_ n: Int) -> Int {
    if n == 0 {
        return 1
    }
    var result = 1
    for i in 1...n {
        result *= i
    }
    return result
}

func sum(_ n: Int) -> Int {
    var result = 0
    for i in 1...n {
        result += i
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15][/INST]  ```swift
func f(n: Int) -> [Int] {
    var result = [Int]()
    for i in 1...n {
        if i % 2 == 0 {
            result.append(factorial(i))
        } else {
            result.append(sum(i))
        }
    }
    return result
}

func factorial(_ n: Int) -> Int {
    if n == 0 {
        return 1
    }
    var result = 1
    for i in 1...n {
        result *= i
    }
    return result
}

func sum(_ n: Int) -> Int {
    var result = 0
    for i in 1...n {
        result += i
    }
    return result
}
```

func f(n: Int) -> [Int] {
    var result = [Int]()
    for i in 1...n {
        if i % 2 == 0 {
            result.append(factorial(i))
        } else {
            result.append(sum(i))
        }
    }
    return result
}

func factorial(_ n: Int) -> Int {
    if n == 0 {
        return 1
    }
    var result = 1
    for i in 1...n {
        result *= i
    }
    return result
}

func sum(_ n: Int) -> Int {
    var result = 0
    for i in 1...n {
        result += i
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15][/INST]  ```swift
func f(n: Int) -> [Int] {
    var result = [Int]()
    for i in 1...n {
        if i % 2 == 0 {
            result.append(factorial(i))
        } else {
            result.append(sum(i))
        }
    }
    return result
}

func factorial(_ n: Int) -> Int {
    if n == 0 {
        return 1
    }
    var result = 1
    for i in 1...n {
        result *= i
    }
    return result
}

func sum(_ n: Int) -> Int {
    var result = 0
    for i in 1...n {
        result += i
    }
    return result
}
```

func f(n: Int) -> [Int] {
    var result = [Int]()
    for i in 1...n {
        if i % 2 == 0 {
            result.append(factorial(i))
        } else {
            result.append(sum(i))
        }
    }
    return result
}

func factorial(_ n: Int) -> Int {
    if n == 0 {
        return 1
    }
    var result = 1
    for i in 1...n {
        result *= i
    }
    return result
}

func sum(_ n: Int) -> Int {
    var result = 0
    for i in 1...n {
        result += i
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15][/INST]  ```swift
func f(n: Int) -> [Int] {
    var result = [Int]()
    for i in 1...n {
        if i % 2 == 0 {
            result.append(factorial(i))
        } else {
            result.append(sum(i))
        }
    }
    return result
}

func factorial(_ n: Int) -> Int {
    if n == 0 {
        return 1
    }
    var result = 1
    for i in 1...n {
        result *= i
    }
    return result
}

func sum(_ n: Int) -> Int {
    var result = 0
    for i in 1...n {
        result += i
    }
    return result
}
```

func f(n: Int) -> [Int] {
    var result = [Int]()

    for i in 1...n {
        if i % 2 == 0 {
            var factorial = 1
            for j in 2...i {
                factorial *= j
            }
            result.append(factorial)
        } else {
            var sum = 0
            for j in 1...i {
                sum += j
            }
            result.append(sum)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15][/INST]  ```swift
func f(n: Int) -> [Int] {
    var result = [Int]()

    for i in 1...n {
        if i % 2 == 0 {
            var factorial = 1
            for j in 2...i {
                factorial *= j
            }
            result.append(factorial)
        } else {
            var sum = 0
            for j in 1...i {
                sum += j
            }
            result.append(sum)
        }
    }

    return result
}
```

func f(n: Int) -> [Int] {
    var result = [Int]()
    for i in 1...n {
        if i % 2 == 0 {
            var factorial = 1
            for j in 2...i {
                factorial *= j
            }
            result.append(factorial)
        } else {
            var sum = 0
            for j in 1...i {
                sum += j
            }
            result.append(sum)
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15][/INST]  ```swift
func f(n: Int) -> [Int] {
    var result = [Int]()
    for i in 1...n {
        if i % 2 == 0 {
            var factorial = 1
            for j in 2...i {
                factorial *= j
            }
            result.append(factorial)
        } else {
            var sum = 0
            for j in 1...i {
                sum += j
            }
            result.append(sum)
        }
    }
    return result
}
```

func f(n: Int) -> [Int] {
    var result = [Int]()

    for i in 1...n {
        if i % 2 == 0 {
            var factorial = 1
            for j in 2...i {
                factorial *= j
            }
            result.append(factorial)
        } else {
            var sum = 0
            for j in 1...i {
                sum += j
            }
            result.append(sum)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15][/INST]  ```swift
func f(n: Int) -> [Int] {
    var result = [Int]()

    for i in 1...n {
        if i % 2 == 0 {
            var factorial = 1
            for j in 2...i {
                factorial *= j
            }
            result.append(factorial)
        } else {
            var sum = 0
            for j in 1...i {
                sum += j
            }
            result.append(sum)
        }
    }

    return result
}
```

func evenOddPalindrome(n: Int) -> (Int, Int) {
    var evenCount = 0
    var oddCount = 0

    for i in 1...n {
        let str = String(i)
        if str == String(str.reversed()) {
            if i % 2 == 0 {
                evenCount += 1
            } else {
                oddCount += 1
            }
        }
    }

    return (evenCount, oddCount)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)[/INST]  ```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
    var evenCount = 0
    var oddCount = 0

    for i in 1...n {
        let str = String(i)
        if str == String(str.reversed()) {
            if i % 2 == 0 {
                evenCount += 1
            } else {
                oddCount += 1
            }
        }
    }

    return (evenCount, oddCount)
}
```

func evenOddPalindrome(n: Int) -> (Int, Int) {
    var evenCount = 0
    var oddCount = 0

    for i in 1...n {
        let str = String(i)
        if str == String(str.reversed()) {
            if i % 2 == 0 {
                evenCount += 1
            } else {
                oddCount += 1
            }
        }
    }

    return (evenCount, oddCount)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)[/INST]  ```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
    var evenCount = 0
    var oddCount = 0

    for i in 1...n {
        let str = String(i)
        if str == String(str.reversed()) {
            if i % 2 == 0 {
                evenCount += 1
            } else {
                oddCount += 1
            }
        }
    }

    return (evenCount, oddCount)
}
```

func evenOddPalindrome(n: Int) -> (Int, Int) {
    var evenCount = 0
    var oddCount = 0

    for i in 1...n {
        let str = String(i)
        if str == String(str.reversed()) {
            if i % 2 == 0 {
                evenCount += 1
            } else {
                oddCount += 1
            }
        }
    }

    return (evenCount, oddCount)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)[/INST]  ```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
    var evenCount = 0
    var oddCount = 0

    for i in 1...n {
        let str = String(i)
        if str == String(str.reversed()) {
            if i % 2 == 0 {
                evenCount += 1
            } else {
                oddCount += 1
            }
        }
    }

    return (evenCount, oddCount)
}
```

func evenOddPalindrome(n: Int) -> (Int, Int) {
    var evenCount = 0
    var oddCount = 0

    for i in 1...n {
        let str = String(i)
        if str == String(str.reversed()) {
            if i % 2 == 0 {
                evenCount += 1
            } else {
                oddCount += 1
            }
        }
    }

    return (evenCount, oddCount)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)[/INST]  ```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
    var evenCount = 0
    var oddCount = 0

    for i in 1...n {
        let str = String(i)
        if str == String(str.reversed()) {
            if i % 2 == 0 {
                evenCount += 1
            } else {
                oddCount += 1
            }
        }
    }

    return (evenCount, oddCount)
}
```

func evenOddPalindrome(n: Int) -> (Int, Int) {
    var evenCount = 0
    var oddCount = 0

    for i in 1...n {
        let str = String(i)
        if str == String(str.reversed()) {
            if i % 2 == 0 {
                evenCount += 1
            } else {
                oddCount += 1
            }
        }
    }

    return (evenCount, oddCount)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)[/INST]  ```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
    var evenCount = 0
    var oddCount = 0

    for i in 1...n {
        let str = String(i)
        if str == String(str.reversed()) {
            if i % 2 == 0 {
                evenCount += 1
            } else {
                oddCount += 1
            }
        }
    }

    return (evenCount, oddCount)
}
```

func evenOddPalindrome(n: Int) -> (Int, Int) {
    var evenCount = 0
    var oddCount = 0

    for i in 1...n {
        let str = String(i)
        if str == String(str.reversed()) {
            if i % 2 == 0 {
                evenCount += 1
            } else {
                oddCount += 1
            }
        }
    }

    return (evenCount, oddCount)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)[/INST]  ```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
    var evenCount = 0
    var oddCount = 0

    for i in 1...n {
        let str = String(i)
        if str == String(str.reversed()) {
            if i % 2 == 0 {
                evenCount += 1
            } else {
                oddCount += 1
            }
        }
    }

    return (evenCount, oddCount)
}
```

func evenOddPalindrome(n: Int) -> (Int, Int) {
    var evenCount = 0
    var oddCount = 0

    for i in 1...n {
        let str = String(i)
        if str == String(str.reversed()) {
            if i % 2 == 0 {
                evenCount += 1
            } else {
                oddCount += 1
            }
        }
    }

    return (evenCount, oddCount)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)[/INST]  ```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
    var evenCount = 0
    var oddCount = 0

    for i in 1...n {
        let str = String(i)
        if str == String(str.reversed()) {
            if i % 2 == 0 {
                evenCount += 1
            } else {
                oddCount += 1
            }
        }
    }

    return (evenCount, oddCount)
}
```

func evenOddPalindrome(n: Int) -> (Int, Int) {
    var evenCount = 0
    var oddCount = 0

    for i in 1...n {
        let str = String(i)
        if str == String(str.reversed()) {
            if i % 2 == 0 {
                evenCount += 1
            } else {
                oddCount += 1
            }
        }
    }

    return (evenCount, oddCount)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)[/INST]  ```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
    var evenCount = 0
    var oddCount = 0

    for i in 1...n {
        let str = String(i)
        if str == String(str.reversed()) {
            if i % 2 == 0 {
                evenCount += 1
            } else {
                oddCount += 1
            }
        }
    }

    return (evenCount, oddCount)
}
```

func evenOddPalindrome(n: Int) -> (Int, Int) {
    var evenCount = 0
    var oddCount = 0

    for i in 1...n {
        let str = String(i)
        if str == String(str.reversed()) {
            if i % 2 == 0 {
                evenCount += 1
            } else {
                oddCount += 1
            }
        }
    }

    return (evenCount, oddCount)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)[/INST]  ```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
    var evenCount = 0
    var oddCount = 0

    for i in 1...n {
        let str = String(i)
        if str == String(str.reversed()) {
            if i % 2 == 0 {
                evenCount += 1
            } else {
                oddCount += 1
            }
        }
    }

    return (evenCount, oddCount)
}
```

func evenOddPalindrome(n: Int) -> (Int, Int) {
    var evenCount = 0
    var oddCount = 0

    for i in 1...n {
        let str = String(i)
        if str == String(str.reversed()) {
            if i % 2 == 0 {
                evenCount += 1
            } else {
                oddCount += 1
            }
        }
    }

    return (evenCount, oddCount)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)[/INST]  ```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
    var evenCount = 0
    var oddCount = 0

    for i in 1...n {
        let str = String(i)
        if str == String(str.reversed()) {
            if i % 2 == 0 {
                evenCount += 1
            } else {
                oddCount += 1
            }
        }
    }

    return (evenCount, oddCount)
}
```

func countNums(arr: [Int]) -> Int {
    var count = 0
    for num in arr {
        var sum = 0
        var n = abs(num)
        while n > 0 {
            sum += n % 10
            n /= 10
        }
        if sum > 0 {
            count += 1
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3[/INST]  ```swift
func countNums(arr: [Int]) -> Int {
    var count = 0
    for num in arr {
        var sum = 0
        var n = abs(num)
        while n > 0 {
            sum += n % 10
            n /= 10
        }
        if sum > 0 {
            count += 1
        }
    }
    return count
}
```
 // XCTAssertTrue failed

func countNums(arr: [Int]) -> Int {
    var count = 0
    for num in arr {
        var sum = 0
        var number = abs(num)
        while number > 0 {
            sum += number % 10
            number /= 10
        }
        if sum > 0 {
            count += 1
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3[/INST]  ```swift
func countNums(arr: [Int]) -> Int {
    var count = 0
    for num in arr {
        var sum = 0
        var number = abs(num)
        while number > 0 {
            sum += number % 10
            number /= 10
        }
        if sum > 0 {
            count += 1
        }
    }
    return count
}
```
 // XCTAssertTrue failed

func countNums(arr: [Int]) -> Int {
    var count = 0
    for num in arr {
        var sum = 0
        var n = abs(num)
        while n > 0 {
            sum += n % 10
            n /= 10
        }
        if sum > 0 {
            count += 1
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3[/INST]  ```swift
func countNums(arr: [Int]) -> Int {
    var count = 0
    for num in arr {
        var sum = 0
        var n = abs(num)
        while n > 0 {
            sum += n % 10
            n /= 10
        }
        if sum > 0 {
            count += 1
        }
    }
    return count
}
```
 // XCTAssertTrue failed

func countNums(arr: [Int]) -> Int {
    var count = 0
    for num in arr {
        var sum = 0
        var number = abs(num)
        while number > 0 {
            sum += number % 10
            number /= 10
        }
        if sum > 0 {
            count += 1
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3[/INST]  ```swift
func countNums(arr: [Int]) -> Int {
    var count = 0
    for num in arr {
        var sum = 0
        var number = abs(num)
        while number > 0 {
            sum += number % 10
            number /= 10
        }
        if sum > 0 {
            count += 1
        }
    }
    return count
}
```
 // XCTAssertTrue failed

func countNums(arr: [Int]) -> Int {
    var count = 0
    for num in arr {
        var sum = 0
        var number = abs(num)
        while number > 0 {
            sum += number % 10
            number /= 10
        }
        if sum > 0 {
            count += 1
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3[/INST]  ```swift
func countNums(arr: [Int]) -> Int {
    var count = 0
    for num in arr {
        var sum = 0
        var number = abs(num)
        while number > 0 {
            sum += number % 10
            number /= 10
        }
        if sum > 0 {
            count += 1
        }
    }
    return count
}
```
 // XCTAssertTrue failed

func countNums(arr: [Int]) -> Int {
    var count = 0
    for num in arr {
        var sum = 0
        var n = abs(num)
        while n > 0 {
            sum += n % 10
            n /= 10
        }
        if sum > 0 {
            count += 1
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3[/INST]  ```swift
func countNums(arr: [Int]) -> Int {
    var count = 0
    for num in arr {
        var sum = 0
        var n = abs(num)
        while n > 0 {
            sum += n % 10
            n /= 10
        }
        if sum > 0 {
            count += 1
        }
    }
    return count
}
```
 // XCTAssertTrue failed

func countNums(arr: [Int]) -> Int {
    var count = 0
    for num in arr {
        var sum = 0
        var n = abs(num)
        while n > 0 {
            sum += n % 10
            n /= 10
        }
        if sum > 0 {
            count += 1
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3[/INST]  ```swift
func countNums(arr: [Int]) -> Int {
    var count = 0
    for num in arr {
        var sum = 0
        var n = abs(num)
        while n > 0 {
            sum += n % 10
            n /= 10
        }
        if sum > 0 {
            count += 1
        }
    }
    return count
}
```
 // XCTAssertTrue failed

func countNums(arr: [Int]) -> Int {
    var count = 0
    for num in arr {
        var sum = 0
        var number = abs(num)
        while number > 0 {
            sum += number % 10
            number /= 10
        }
        if sum > 0 {
            count += 1
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3[/INST]  ```swift
func countNums(arr: [Int]) -> Int {
    var count = 0
    for num in arr {
        var sum = 0
        var number = abs(num)
        while number > 0 {
            sum += number % 10
            number /= 10
        }
        if sum > 0 {
            count += 1
        }
    }
    return count
}
```
 // XCTAssertTrue failed

func countNums(arr: [Int]) -> Int {
    var count = 0
    for num in arr {
        var sum = 0
        var n = abs(num)
        while n > 0 {
            sum += n % 10
            n /= 10
        }
        if sum > 0 {
            count += 1
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3[/INST]  ```swift
func countNums(arr: [Int]) -> Int {
    var count = 0
    for num in arr {
        var sum = 0
        var n = abs(num)
        while n > 0 {
            sum += n % 10
            n /= 10
        }
        if sum > 0 {
            count += 1
        }
    }
    return count
}
```
 // XCTAssertTrue failed

func countNums(arr: [Int]) -> Int {
    var count = 0
    for num in arr {
        var sum = 0
        var number = abs(num)
        while number > 0 {
            sum += number % 10
            number /= 10
        }
        if sum > 0 {
            count += 1
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3[/INST]  ```swift
func countNums(arr: [Int]) -> Int {
    var count = 0
    for num in arr {
        var sum = 0
        var number = abs(num)
        while number > 0 {
            sum += number % 10
            number /= 10
        }
        if sum > 0 {
            count += 1
        }
    }
    return count
}
```
 // XCTAssertTrue failed

func moveOneBall(arr: [Int]) -> Bool {
    if arr.isEmpty {
        return true
    }

    var sortedArr = arr.sorted()
    for _ in 0..<arr.count {
        if arr == sortedArr {
            return true
        }
        sortedArr.insert(sortedArr.removeLast(), at: 0)
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing 
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index. 
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false[/INST]  ```swift
func moveOneBall(arr: [Int]) -> Bool {
    if arr.isEmpty {
        return true
    }

    var sortedArr = arr.sorted()
    for _ in 0..<arr.count {
        if arr == sortedArr {
            return true
        }
        sortedArr.insert(sortedArr.removeLast(), at: 0)
    }
    return false
}
```

func moveOneBall(arr: [Int]) -> Bool {
    if arr.isEmpty {
        return true
    }

    var sortedArr = arr.sorted()
    for _ in 0..<arr.count {
        if arr == sortedArr {
            return true
        }
        sortedArr.insert(sortedArr.removeLast(), at: 0)
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing 
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index. 
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false[/INST]  ```swift
func moveOneBall(arr: [Int]) -> Bool {
    if arr.isEmpty {
        return true
    }

    var sortedArr = arr.sorted()
    for _ in 0..<arr.count {
        if arr == sortedArr {
            return true
        }
        sortedArr.insert(sortedArr.removeLast(), at: 0)
    }
    return false
}
```

func moveOneBall(arr: [Int]) -> Bool {
    let sortedArr = arr.sorted()
    for i in 0..<arr.count {
        var rotatedArr = Array(arr[i...] + arr[0..<i])
        if rotatedArr == sortedArr {
            return true
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing 
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index. 
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false[/INST]  ```swift
func moveOneBall(arr: [Int]) -> Bool {
    let sortedArr = arr.sorted()
    for i in 0..<arr.count {
        var rotatedArr = Array(arr[i...] + arr[0..<i])
        if rotatedArr == sortedArr {
            return true
        }
    }
    return false
}
```
var rotatedArr = Array(arr[i...] + arr[0..<i]) // variable 'rotatedArr' was never mutated; consider changing to 'let' constant
 // XCTAssertTrue failed

func moveOneBall(arr: [Int]) -> Bool {
    let sortedArr = arr.sorted()
    for i in 0..<arr.count {
        var shiftedArr = Array(arr[i...] + arr[0..<i])
        if shiftedArr == sortedArr {
            return true
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing 
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index. 
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false[/INST]  ```swift
func moveOneBall(arr: [Int]) -> Bool {
    let sortedArr = arr.sorted()
    for i in 0..<arr.count {
        var shiftedArr = Array(arr[i...] + arr[0..<i])
        if shiftedArr == sortedArr {
            return true
        }
    }
    return false
}
```
var shiftedArr = Array(arr[i...] + arr[0..<i]) // variable 'shiftedArr' was never mutated; consider changing to 'let' constant
 // XCTAssertTrue failed

func moveOneBall(arr: [Int]) -> Bool {
    if arr.isEmpty {
        return true
    }

    var sortedArray = arr.sorted()
    for _ in 0..<arr.count {
        if arr == sortedArray {
            return true
        }
        sortedArray.insert(sortedArray.removeLast(), at: 0)
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing 
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index. 
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false[/INST]  ```swift
func moveOneBall(arr: [Int]) -> Bool {
    if arr.isEmpty {
        return true
    }

    var sortedArray = arr.sorted()
    for _ in 0..<arr.count {
        if arr == sortedArray {
            return true
        }
        sortedArray.insert(sortedArray.removeLast(), at: 0)
    }
    return false
}
```

func moveOneBall(arr: [Int]) -> Bool {
    guard !arr.isEmpty else {
        return true
    }

    var sortedArr = arr.sorted()
    for _ in 0..<arr.count {
        if arr == sortedArr {
            return true
        }
        sortedArr.insert(sortedArr.removeLast(), at: 0)
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing 
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index. 
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false[/INST]  ```swift
func moveOneBall(arr: [Int]) -> Bool {
    guard !arr.isEmpty else {
        return true
    }

    var sortedArr = arr.sorted()
    for _ in 0..<arr.count {
        if arr == sortedArr {
            return true
        }
        sortedArr.insert(sortedArr.removeLast(), at: 0)
    }
    return false
}
```

func moveOneBall(arr: [Int]) -> Bool {
    guard !arr.isEmpty else {
        return true
    }

    var sortedArr = arr.sorted()
    for _ in 0..<arr.count {
        if arr == sortedArr {
            return true
        }
        sortedArr.insert(sortedArr.removeLast(), at: 0)
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing 
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index. 
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false[/INST]  ```swift
func moveOneBall(arr: [Int]) -> Bool {
    guard !arr.isEmpty else {
        return true
    }

    var sortedArr = arr.sorted()
    for _ in 0..<arr.count {
        if arr == sortedArr {
            return true
        }
        sortedArr.insert(sortedArr.removeLast(), at: 0)
    }
    return false
}
```

func moveOneBall(arr: [Int]) -> Bool {
    if arr.isEmpty {
        return true
    }

    var sortedArr = arr.sorted()
    for _ in 0..<arr.count {
        if arr == sortedArr {
            return true
        }
        sortedArr.insert(sortedArr.removeLast(), at: 0)
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing 
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index. 
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false[/INST]  ```swift
func moveOneBall(arr: [Int]) -> Bool {
    if arr.isEmpty {
        return true
    }

    var sortedArr = arr.sorted()
    for _ in 0..<arr.count {
        if arr == sortedArr {
            return true
        }
        sortedArr.insert(sortedArr.removeLast(), at: 0)
    }
    return false
}
```

func moveOneBall(arr: [Int]) -> Bool {
    if arr.isEmpty {
        return true
    }

    var sortedArr = arr.sorted()
    for _ in 0..<arr.count {
        if arr == sortedArr {
            return true
        }
        sortedArr.insert(sortedArr.removeLast(), at: 0)
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing 
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index. 
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false[/INST]  ```swift
func moveOneBall(arr: [Int]) -> Bool {
    if arr.isEmpty {
        return true
    }

    var sortedArr = arr.sorted()
    for _ in 0..<arr.count {
        if arr == sortedArr {
            return true
        }
        sortedArr.insert(sortedArr.removeLast(), at: 0)
    }
    return false
}
```

func moveOneBall(arr: [Int]) -> Bool {
    if arr.isEmpty {
        return true
    }

    var sortedArr = arr.sorted()
    for _ in 0..<arr.count {
        if arr == sortedArr {
            return true
        }
        sortedArr.insert(sortedArr.removeLast(), at: 0)
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing 
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index. 
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false[/INST]  ```swift
func moveOneBall(arr: [Int]) -> Bool {
    if arr.isEmpty {
        return true
    }

    var sortedArr = arr.sorted()
    for _ in 0..<arr.count {
        if arr == sortedArr {
            return true
        }
        sortedArr.insert(sortedArr.removeLast(), at: 0)
    }
    return false
}
```

func exchange(lst1: [Int], lst2: [Int]) -> String {
    var evenList1 = lst1.filter { $0 % 2 == 0 }
    var oddList1 = lst1.filter { $0 % 2 != 0 }
    let evenList2 = lst2.filter { $0 % 2 == 0 }

    if oddList1.count > evenList2.count {
        return "NO"
    }

    for odd in oddList1 {
        if let index = evenList2.firstIndex(where: { $0 > odd }) {
            evenList1.append(evenList2[index])
            evenList2.remove(at: index)
        } else {
            return "NO"
        }
    }

    return "YES"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"[/INST]  ```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
    var evenList1 = lst1.filter { $0 % 2 == 0 }
    var oddList1 = lst1.filter { $0 % 2 != 0 }
    let evenList2 = lst2.filter { $0 % 2 == 0 }

    if oddList1.count > evenList2.count {
        return "NO"
    }

    for odd in oddList1 {
        if let index = evenList2.firstIndex(where: { $0 > odd }) {
            evenList1.append(evenList2[index])
            evenList2.remove(at: index)
        } else {
            return "NO"
        }
    }

    return "YES"
}
```
evenList2.remove(at: index) // cannot use mutating member on immutable value: 'evenList2' is a 'let' constant

func exchange(lst1: [Int], lst2: [Int]) -> String {
    var evenNumbersInLst1 = lst1.filter { $0 % 2 == 0 }
    var oddNumbersInLst1 = lst1.filter { $0 % 2 != 0 }
    let evenNumbersInLst2 = lst2.filter { $0 % 2 == 0 }

    if oddNumbersInLst1.count > evenNumbersInLst2.count {
        return "NO"
    }

    for _ in 0..<oddNumbersInLst1.count {
        if let index = evenNumbersInLst2.firstIndex(where: { $0 > oddNumbersInLst1.removeFirst() }) {
            evenNumbersInLst1.append(evenNumbersInLst2[index])
        } else {
            return "NO"
        }
    }

    return "YES"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"[/INST]  ```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
    var evenNumbersInLst1 = lst1.filter { $0 % 2 == 0 }
    var oddNumbersInLst1 = lst1.filter { $0 % 2 != 0 }
    let evenNumbersInLst2 = lst2.filter { $0 % 2 == 0 }

    if oddNumbersInLst1.count > evenNumbersInLst2.count {
        return "NO"
    }

    for _ in 0..<oddNumbersInLst1.count {
        if let index = evenNumbersInLst2.firstIndex(where: { $0 > oddNumbersInLst1.removeFirst() }) {
            evenNumbersInLst1.append(evenNumbersInLst2[index])
        } else {
            return "NO"
        }
    }

    return "YES"
}
```
 // Fatal error: Can't remove first element from an empty collection

func exchange(lst1: [Int], lst2: [Int]) -> String {
    var evenNumbersInLst1 = lst1.filter { $0 % 2 == 0 }
    var oddNumbersInLst1 = lst1.filter { $0 % 2 != 0 }
    let evenNumbersInLst2 = lst2.filter { $0 % 2 == 0 }

    if oddNumbersInLst1.count > evenNumbersInLst2.count {
        return "NO"
    }

    for _ in 0..<oddNumbersInLst1.count {
        if let index = evenNumbersInLst2.firstIndex(where: { _ in true }) {
            evenNumbersInLst1.append(evenNumbersInLst2[index])
        } else {
            return "NO"
        }
    }

    return "YES"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"[/INST]  ```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
    var evenNumbersInLst1 = lst1.filter { $0 % 2 == 0 }
    var oddNumbersInLst1 = lst1.filter { $0 % 2 != 0 }
    let evenNumbersInLst2 = lst2.filter { $0 % 2 == 0 }

    if oddNumbersInLst1.count > evenNumbersInLst2.count {
        return "NO"
    }

    for _ in 0..<oddNumbersInLst1.count {
        if let index = evenNumbersInLst2.firstIndex(where: { _ in true }) {
            evenNumbersInLst1.append(evenNumbersInLst2[index])
        } else {
            return "NO"
        }
    }

    return "YES"
}
```
var oddNumbersInLst1 = lst1.filter { $0 % 2 != 0 } // variable 'oddNumbersInLst1' was never mutated; consider changing to 'let' constant

func exchange(lst1: [Int], lst2: [Int]) -> String {
    var evenNumbersInLst1 = lst1.filter { $0 % 2 == 0 }
    var oddNumbersInLst1 = lst1.filter { $0 % 2 != 0 }
    let evenNumbersInLst2 = lst2.filter { $0 % 2 == 0 }

    if oddNumbersInLst1.count > evenNumbersInLst2.count {
        return "NO"
    }

    for _ in 0..<oddNumbersInLst1.count {
        if let index = evenNumbersInLst2.firstIndex(where: { _ in true }) {
            evenNumbersInLst1.append(evenNumbersInLst2[index])
        } else {
            return "NO"
        }
    }

    return "YES"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"[/INST]  ```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
    var evenNumbersInLst1 = lst1.filter { $0 % 2 == 0 }
    var oddNumbersInLst1 = lst1.filter { $0 % 2 != 0 }
    let evenNumbersInLst2 = lst2.filter { $0 % 2 == 0 }

    if oddNumbersInLst1.count > evenNumbersInLst2.count {
        return "NO"
    }

    for _ in 0..<oddNumbersInLst1.count {
        if let index = evenNumbersInLst2.firstIndex(where: { _ in true }) {
            evenNumbersInLst1.append(evenNumbersInLst2[index])
        } else {
            return "NO"
        }
    }

    return "YES"
}
```
var oddNumbersInLst1 = lst1.filter { $0 % 2 != 0 } // variable 'oddNumbersInLst1' was never mutated; consider changing to 'let' constant

func exchange(lst1: [Int], lst2: [Int]) -> String {
    var oddNumbersInLst1 = lst1.filter { $0 % 2 != 0 }
    let evenNumbersInLst2 = lst2.filter { $0 % 2 == 0 }

    for evenNumber in evenNumbersInLst2 {
        if let index = oddNumbersInLst1.firstIndex(where: { $0 % 2 != 0 }) {
            oddNumbersInLst1[index] = evenNumber
        }
    }

    return oddNumbersInLst1.allSatisfy { $0 % 2 == 0 } ? "YES" : "NO"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"[/INST]  ```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
    var oddNumbersInLst1 = lst1.filter { $0 % 2 != 0 }
    let evenNumbersInLst2 = lst2.filter { $0 % 2 == 0 }

    for evenNumber in evenNumbersInLst2 {
        if let index = oddNumbersInLst1.firstIndex(where: { $0 % 2 != 0 }) {
            oddNumbersInLst1[index] = evenNumber
        }
    }

    return oddNumbersInLst1.allSatisfy { $0 % 2 == 0 } ? "YES" : "NO"
}
```

func exchange(lst1: [Int], lst2: [Int]) -> String {
    var evenNumbersInLst1 = lst1.filter { $0 % 2 == 0 }
    var oddNumbersInLst1 = lst1.filter { $0 % 2 != 0 }
    let evenNumbersInLst2 = lst2.filter { $0 % 2 == 0 }

    if oddNumbersInLst1.count > evenNumbersInLst2.count {
        return "NO"
    }

    for _ in 0..<oddNumbersInLst1.count {
        if let index = evenNumbersInLst2.firstIndex(where: { $0 > oddNumbersInLst1.removeFirst() }) {
            evenNumbersInLst1.append(evenNumbersInLst2[index])
        } else {
            return "NO"
        }
    }

    return "YES"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"[/INST]  ```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
    var evenNumbersInLst1 = lst1.filter { $0 % 2 == 0 }
    var oddNumbersInLst1 = lst1.filter { $0 % 2 != 0 }
    let evenNumbersInLst2 = lst2.filter { $0 % 2 == 0 }

    if oddNumbersInLst1.count > evenNumbersInLst2.count {
        return "NO"
    }

    for _ in 0..<oddNumbersInLst1.count {
        if let index = evenNumbersInLst2.firstIndex(where: { $0 > oddNumbersInLst1.removeFirst() }) {
            evenNumbersInLst1.append(evenNumbersInLst2[index])
        } else {
            return "NO"
        }
    }

    return "YES"
}
```
 // Fatal error: Can't remove first element from an empty collection

func exchange(lst1: [Int], lst2: [Int]) -> String {
    var evenNumbersInLst1 = lst1.filter { $0 % 2 == 0 }
    var oddNumbersInLst1 = lst1.filter { $0 % 2 != 0 }
    let evenNumbersInLst2 = lst2.filter { $0 % 2 == 0 }

    if oddNumbersInLst1.count > evenNumbersInLst2.count {
        return "NO"
    }

    for _ in 0..<oddNumbersInLst1.count {
        if let index = evenNumbersInLst2.firstIndex(where: { _ in true }) {
            evenNumbersInLst1.append(evenNumbersInLst2[index])
        } else {
            return "NO"
        }
    }

    return "YES"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"[/INST]  ```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
    var evenNumbersInLst1 = lst1.filter { $0 % 2 == 0 }
    var oddNumbersInLst1 = lst1.filter { $0 % 2 != 0 }
    let evenNumbersInLst2 = lst2.filter { $0 % 2 == 0 }

    if oddNumbersInLst1.count > evenNumbersInLst2.count {
        return "NO"
    }

    for _ in 0..<oddNumbersInLst1.count {
        if let index = evenNumbersInLst2.firstIndex(where: { _ in true }) {
            evenNumbersInLst1.append(evenNumbersInLst2[index])
        } else {
            return "NO"
        }
    }

    return "YES"
}
```
var oddNumbersInLst1 = lst1.filter { $0 % 2 != 0 } // variable 'oddNumbersInLst1' was never mutated; consider changing to 'let' constant

func exchange(lst1: [Int], lst2: [Int]) -> String {
    var oddNumbersInLst1 = lst1.filter { $0 % 2 != 0 }
    let evenNumbersInLst2 = lst2.filter { $0 % 2 == 0 }

    for evenNumber in evenNumbersInLst2 {
        if let index = oddNumbersInLst1.firstIndex(where: { $0 % 2 != 0 }) {
            oddNumbersInLst1[index] = evenNumber
        }
    }

    return oddNumbersInLst1.allSatisfy { $0 % 2 == 0 } ? "YES" : "NO"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"[/INST]  ```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
    var oddNumbersInLst1 = lst1.filter { $0 % 2 != 0 }
    let evenNumbersInLst2 = lst2.filter { $0 % 2 == 0 }

    for evenNumber in evenNumbersInLst2 {
        if let index = oddNumbersInLst1.firstIndex(where: { $0 % 2 != 0 }) {
            oddNumbersInLst1[index] = evenNumber
        }
    }

    return oddNumbersInLst1.allSatisfy { $0 % 2 == 0 } ? "YES" : "NO"
}
```

func exchange(lst1: [Int], lst2: [Int]) -> String {
    var oddNumbersInLst1 = lst1.filter { $0 % 2 != 0 }
    let evenNumbersInLst2 = lst2.filter { $0 % 2 == 0 }

    for evenNumber in evenNumbersInLst2 {
        if let index = oddNumbersInLst1.firstIndex(where: { $0 % 2 != 0 }) {
            oddNumbersInLst1[index] = evenNumber
        }
    }

    return oddNumbersInLst1.allSatisfy { $0 % 2 == 0 } ? "YES" : "NO"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"[/INST]  ```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
    var oddNumbersInLst1 = lst1.filter { $0 % 2 != 0 }
    let evenNumbersInLst2 = lst2.filter { $0 % 2 == 0 }

    for evenNumber in evenNumbersInLst2 {
        if let index = oddNumbersInLst1.firstIndex(where: { $0 % 2 != 0 }) {
            oddNumbersInLst1[index] = evenNumber
        }
    }

    return oddNumbersInLst1.allSatisfy { $0 % 2 == 0 } ? "YES" : "NO"
}
```

func exchange(lst1: [Int], lst2: [Int]) -> String {
    var evenNumbersInLst1 = lst1.filter { $0 % 2 == 0 }
    var oddNumbersInLst1 = lst1.filter { $0 % 2 != 0 }
    let evenNumbersInLst2 = lst2.filter { $0 % 2 == 0 }

    if oddNumbersInLst1.count > evenNumbersInLst2.count {
        return "NO"
    }

    for _ in 0..<oddNumbersInLst1.count {
        if let index = evenNumbersInLst2.firstIndex(where: { _ in true }) {
            evenNumbersInLst1.append(evenNumbersInLst2[index])
        } else {
            return "NO"
        }
    }

    return "YES"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"[/INST]  ```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
    var evenNumbersInLst1 = lst1.filter { $0 % 2 == 0 }
    var oddNumbersInLst1 = lst1.filter { $0 % 2 != 0 }
    let evenNumbersInLst2 = lst2.filter { $0 % 2 == 0 }

    if oddNumbersInLst1.count > evenNumbersInLst2.count {
        return "NO"
    }

    for _ in 0..<oddNumbersInLst1.count {
        if let index = evenNumbersInLst2.firstIndex(where: { _ in true }) {
            evenNumbersInLst1.append(evenNumbersInLst2[index])
        } else {
            return "NO"
        }
    }

    return "YES"
}
```
var oddNumbersInLst1 = lst1.filter { $0 % 2 != 0 } // variable 'oddNumbersInLst1' was never mutated; consider changing to 'let' constant

func histogram(test: String) -> [String : Int] {
    var dict = [String : Int]()
    let words = test.split(separator: " ")

    for word in words {
        let str = String(word)
        dict[str] = (dict[str] ?? 0) + 1
    }

    let maxValue = dict.values.max() ?? 0
    let result = dict.filter { $0.value == maxValue }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int][/INST]  ```swift
func histogram(test: String) -> [String : Int] {
    var dict = [String : Int]()
    let words = test.split(separator: " ")

    for word in words {
        let str = String(word)
        dict[str] = (dict[str] ?? 0) + 1
    }

    let maxValue = dict.values.max() ?? 0
    let result = dict.filter { $0.value == maxValue }

    return result
}
```

func histogram(test: String) -> [String : Int] {
    var dict = [String : Int]()
    let words = test.split(separator: " ")

    for word in words {
        let str = String(word)
        dict[str, default: 0] += 1
    }

    let maxCount = dict.values.max() ?? 0
    let result = dict.filter { $0.value == maxCount }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int][/INST]  ```swift
func histogram(test: String) -> [String : Int] {
    var dict = [String : Int]()
    let words = test.split(separator: " ")

    for word in words {
        let str = String(word)
        dict[str, default: 0] += 1
    }

    let maxCount = dict.values.max() ?? 0
    let result = dict.filter { $0.value == maxCount }

    return result
}
```

func histogram(test: String) -> [String : Int] {
    var dict = [String : Int]()
    let words = test.split(separator: " ")

    for word in words {
        let str = String(word)
        dict[str, default: 0] += 1
    }

    let maxCount = dict.values.max() ?? 0
    let result = dict.filter { $0.value == maxCount }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int][/INST]  ```swift
func histogram(test: String) -> [String : Int] {
    var dict = [String : Int]()
    let words = test.split(separator: " ")

    for word in words {
        let str = String(word)
        dict[str, default: 0] += 1
    }

    let maxCount = dict.values.max() ?? 0
    let result = dict.filter { $0.value == maxCount }

    return result
}
```

func histogram(test: String) -> [String : Int] {
    var dict = [String : Int]()
    let words = test.split(separator: " ")

    for word in words {
        let str = String(word)
        dict[str, default: 0] += 1
    }

    let maxValue = dict.values.max() ?? 0
    let result = dict.filter { $0.value == maxValue }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int][/INST]  ```swift
func histogram(test: String) -> [String : Int] {
    var dict = [String : Int]()
    let words = test.split(separator: " ")

    for word in words {
        let str = String(word)
        dict[str, default: 0] += 1
    }

    let maxValue = dict.values.max() ?? 0
    let result = dict.filter { $0.value == maxValue }

    return result
}
```

func histogram(test: String) -> [String : Int] {
    var dict = [String : Int]()
    let words = test.split(separator: " ")

    for word in words {
        let str = String(word)
        dict[str, default: 0] += 1
    }

    let maxValue = dict.values.max() ?? 0
    let result = dict.filter { $0.value == maxValue }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int][/INST]  ```swift
func histogram(test: String) -> [String : Int] {
    var dict = [String : Int]()
    let words = test.split(separator: " ")

    for word in words {
        let str = String(word)
        dict[str, default: 0] += 1
    }

    let maxValue = dict.values.max() ?? 0
    let result = dict.filter { $0.value == maxValue }

    return result
}
```

func histogram(test: String) -> [String : Int] {
    var dict = [String : Int]()
    let words = test.split(separator: " ")

    for word in words {
        let str = String(word)
        dict[str, default: 0] += 1
    }

    let maxCount = dict.values.max() ?? 0
    let result = dict.filter { $0.value == maxCount }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int][/INST]  ```swift
func histogram(test: String) -> [String : Int] {
    var dict = [String : Int]()
    let words = test.split(separator: " ")

    for word in words {
        let str = String(word)
        dict[str, default: 0] += 1
    }

    let maxCount = dict.values.max() ?? 0
    let result = dict.filter { $0.value == maxCount }

    return result
}
```

func histogram(test: String) -> [String : Int] {
    var dict = [String : Int]()
    let words = test.split(separator: " ")

    for word in words {
        let str = String(word)
        dict[str, default: 0] += 1
    }

    let maxCount = dict.values.max() ?? 0
    let result = dict.filter { $0.value == maxCount }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int][/INST]  ```swift
func histogram(test: String) -> [String : Int] {
    var dict = [String : Int]()
    let words = test.split(separator: " ")

    for word in words {
        let str = String(word)
        dict[str, default: 0] += 1
    }

    let maxCount = dict.values.max() ?? 0
    let result = dict.filter { $0.value == maxCount }

    return result
}
```

func histogram(test: String) -> [String : Int] {
    var dict = [String : Int]()
    let words = test.split(separator: " ")

    for word in words {
        let str = String(word)
        dict[str, default: 0] += 1
    }

    let maxValue = dict.values.max() ?? 0
    let result = dict.filter { $0.value == maxValue }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int][/INST]  ```swift
func histogram(test: String) -> [String : Int] {
    var dict = [String : Int]()
    let words = test.split(separator: " ")

    for word in words {
        let str = String(word)
        dict[str, default: 0] += 1
    }

    let maxValue = dict.values.max() ?? 0
    let result = dict.filter { $0.value == maxValue }

    return result
}
```

func histogram(test: String) -> [String : Int] {
    var dict = [String : Int]()
    let words = test.split(separator: " ")

    for word in words {
        let str = String(word)
        dict[str, default: 0] += 1
    }

    let maxCount = dict.values.max() ?? 0
    let result = dict.filter { $0.value == maxCount }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int][/INST]  ```swift
func histogram(test: String) -> [String : Int] {
    var dict = [String : Int]()
    let words = test.split(separator: " ")

    for word in words {
        let str = String(word)
        dict[str, default: 0] += 1
    }

    let maxCount = dict.values.max() ?? 0
    let result = dict.filter { $0.value == maxCount }

    return result
}
```

func histogram(test: String) -> [String : Int] {
    var dict = [String : Int]()
    let words = test.split(separator: " ")

    for word in words {
        let str = String(word)
        dict[str, default: 0] += 1
    }

    let maxCount = dict.values.max() ?? 0
    let result = dict.filter { $0.value == maxCount }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int][/INST]  ```swift
func histogram(test: String) -> [String : Int] {
    var dict = [String : Int]()
    let words = test.split(separator: " ")

    for word in words {
        let str = String(word)
        dict[str, default: 0] += 1
    }

    let maxCount = dict.values.max() ?? 0
    let result = dict.filter { $0.value == maxCount }

    return result
}
```

func reverseDelete(s: String, c: String) -> (String, Bool) {
    var result = s
    for char in c {
        result = result.filter { $0 != char }
    }
    let isPalindrome = result == String(result.reversed())
    return (result, isPalindrome)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)[/INST]  ```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
    var result = s
    for char in c {
        result = result.filter { $0 != char }
    }
    let isPalindrome = result == String(result.reversed())
    return (result, isPalindrome)
}
```

func reverseDelete(s: String, c: String) -> (String, Bool) {
    var result = s
    for char in c {
        result = result.filter { $0 != char }
    }
    let isPalindrome = result == String(result.reversed())
    return (result, isPalindrome)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)[/INST]  ```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
    var result = s
    for char in c {
        result = result.filter { $0 != char }
    }
    let isPalindrome = result == String(result.reversed())
    return (result, isPalindrome)
}
```

func reverseDelete(s: String, c: String) -> (String, Bool) {
    var result = s.filter { !c.contains($0) }
    let isPalindrome = result == String(result.reversed())
    return (result, isPalindrome)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)[/INST]  ```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
    var result = s.filter { !c.contains($0) }
    let isPalindrome = result == String(result.reversed())
    return (result, isPalindrome)
}
```
var result = s.filter { !c.contains($0) } // variable 'result' was never mutated; consider changing to 'let' constant

func reverseDelete(s: String, c: String) -> (String, Bool) {
    var result = s.filter { !c.contains($0) }
    let isPalindrome = result == String(result.reversed())
    return (result, isPalindrome)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)[/INST]  ```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
    var result = s.filter { !c.contains($0) }
    let isPalindrome = result == String(result.reversed())
    return (result, isPalindrome)
}
```
var result = s.filter { !c.contains($0) } // variable 'result' was never mutated; consider changing to 'let' constant

func reverseDelete(s: String, c: String) -> (String, Bool) {
    var result = s.filter { !c.contains($0) }
    let isPalindrome = result == String(result.reversed())
    return (result, isPalindrome)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)[/INST]  ```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
    var result = s.filter { !c.contains($0) }
    let isPalindrome = result == String(result.reversed())
    return (result, isPalindrome)
}
```
var result = s.filter { !c.contains($0) } // variable 'result' was never mutated; consider changing to 'let' constant

func reverseDelete(s: String, c: String) -> (String, Bool) {
    var result = s
    for char in c {
        result = result.filter { $0 != char }
    }
    let isPalindrome = result == String(result.reversed())
    return (result, isPalindrome)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)[/INST]  ```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
    var result = s
    for char in c {
        result = result.filter { $0 != char }
    }
    let isPalindrome = result == String(result.reversed())
    return (result, isPalindrome)
}
```

func reverseDelete(s: String, c: String) -> (String, Bool) {
    var result = s
    for char in c {
        result = result.filter { $0 != char }
    }
    let isPalindrome = result == String(result.reversed())
    return (result, isPalindrome)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)[/INST]  ```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
    var result = s
    for char in c {
        result = result.filter { $0 != char }
    }
    let isPalindrome = result == String(result.reversed())
    return (result, isPalindrome)
}
```

func reverseDelete(s: String, c: String) -> (String, Bool) {
    var result = s.filter { !c.contains($0) }
    let isPalindrome = result == String(result.reversed())
    return (result, isPalindrome)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)[/INST]  ```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
    var result = s.filter { !c.contains($0) }
    let isPalindrome = result == String(result.reversed())
    return (result, isPalindrome)
}
```
var result = s.filter { !c.contains($0) } // variable 'result' was never mutated; consider changing to 'let' constant

func reverseDelete(s: String, c: String) -> (String, Bool) {
    var result = s
    for char in c {
        result = result.filter { $0 != char }
    }
    let isPalindrome = result == String(result.reversed())
    return (result, isPalindrome)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)[/INST]  ```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
    var result = s
    for char in c {
        result = result.filter { $0 != char }
    }
    let isPalindrome = result == String(result.reversed())
    return (result, isPalindrome)
}
```

func reverseDelete(s: String, c: String) -> (String, Bool) {
    var result = s
    for char in c {
        result = result.filter { $0 != char }
    }
    let isPalindrome = result == String(result.reversed())
    return (result, isPalindrome)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)[/INST]  ```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
    var result = s
    for char in c {
        result = result.filter { $0 != char }
    }
    let isPalindrome = result == String(result.reversed())
    return (result, isPalindrome)
}
```

func oddCount(lst: [String]) -> [String] {
    var result: [String] = []
    for str in lst {
        var count = 0
        for char in str {
            if let num = Int(String(char)), num % 2 != 0 {
                count += 1
            }
        }
        let sentence = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
        result.append(sentence)
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."][/INST]  ```swift
func oddCount(lst: [String]) -> [String] {
    var result: [String] = []
    for str in lst {
        var count = 0
        for char in str {
            if let num = Int(String(char)), num % 2 != 0 {
                count += 1
            }
        }
        let sentence = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
        result.append(sentence)
    }
    return result
}
```

func oddCount(lst: [String]) -> [String] {
    var result = [String]()
    for str in lst {
        var count = 0
        for char in str {
            if let digit = Int(String(char)), digit % 2 != 0 {
                count += 1
            }
        }
        let output = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
        result.append(output)
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."][/INST]  ```swift
func oddCount(lst: [String]) -> [String] {
    var result = [String]()
    for str in lst {
        var count = 0
        for char in str {
            if let digit = Int(String(char)), digit % 2 != 0 {
                count += 1
            }
        }
        let output = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
        result.append(output)
    }
    return result
}
```

func oddCount(lst: [String]) -> [String] {
    var result = [String]()
    for str in lst {
        var count = 0
        for char in str {
            if let num = Int(String(char)), num % 2 != 0 {
                count += 1
            }
        }
        let sentence = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
        result.append(sentence)
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."][/INST]  ```swift
func oddCount(lst: [String]) -> [String] {
    var result = [String]()
    for str in lst {
        var count = 0
        for char in str {
            if let num = Int(String(char)), num % 2 != 0 {
                count += 1
            }
        }
        let sentence = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
        result.append(sentence)
    }
    return result
}
```

func oddCount(lst: [String]) -> [String] {
    var result: [String] = []

    for str in lst {
        var count = 0
        for char in str {
            if let digit = Int(String(char)), digit % 2 != 0 {
                count += 1
            }
        }
        let sentence = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
        result.append(sentence)
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."][/INST]  ```swift
func oddCount(lst: [String]) -> [String] {
    var result: [String] = []

    for str in lst {
        var count = 0
        for char in str {
            if let digit = Int(String(char)), digit % 2 != 0 {
                count += 1
            }
        }
        let sentence = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
        result.append(sentence)
    }

    return result
}
```

func oddCount(lst: [String]) -> [String] {
    var result = [String]()
    for (index, str) in lst.enumerated() {
        var count = 0
        for char in str {
            if let num = Int(String(char)), num % 2 != 0 {
                count += 1
            }
        }
        let sentence = "the number of odd elements \(count)n the str\(count)ng \(index + 1) of the \(index + 1)nput."
        result.append(sentence)
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."][/INST]  ```swift
func oddCount(lst: [String]) -> [String] {
    var result = [String]()
    for (index, str) in lst.enumerated() {
        var count = 0
        for char in str {
            if let num = Int(String(char)), num % 2 != 0 {
                count += 1
            }
        }
        let sentence = "the number of odd elements \(count)n the str\(count)ng \(index + 1) of the \(index + 1)nput."
        result.append(sentence)
    }
    return result
}
```
 // XCTAssertTrue failed

func oddCount(lst: [String]) -> [String] {
    var result: [String] = []
    for str in lst {
        var count = 0
        for char in str {
            if let num = Int(String(char)), num % 2 != 0 {
                count += 1
            }
        }
        let sentence = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
        result.append(sentence)
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."][/INST]  ```swift
func oddCount(lst: [String]) -> [String] {
    var result: [String] = []
    for str in lst {
        var count = 0
        for char in str {
            if let num = Int(String(char)), num % 2 != 0 {
                count += 1
            }
        }
        let sentence = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
        result.append(sentence)
    }
    return result
}
```

func oddCount(lst: [String]) -> [String] {
    var result = [String]()
    for str in lst {
        var count = 0
        for char in str {
            if let num = Int(String(char)), num % 2 != 0 {
                count += 1
            }
        }
        let output = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
        result.append(output)
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."][/INST]  ```swift
func oddCount(lst: [String]) -> [String] {
    var result = [String]()
    for str in lst {
        var count = 0
        for char in str {
            if let num = Int(String(char)), num % 2 != 0 {
                count += 1
            }
        }
        let output = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
        result.append(output)
    }
    return result
}
```

func oddCount(lst: [String]) -> [String] {
    var result = [String]()
    for str in lst {
        var count = 0
        for char in str {
            if let num = Int(String(char)), num % 2 != 0 {
                count += 1
            }
        }
        let sentence = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
        result.append(sentence)
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."][/INST]  ```swift
func oddCount(lst: [String]) -> [String] {
    var result = [String]()
    for str in lst {
        var count = 0
        for char in str {
            if let num = Int(String(char)), num % 2 != 0 {
                count += 1
            }
        }
        let sentence = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
        result.append(sentence)
    }
    return result
}
```

func oddCount(lst: [String]) -> [String] {
    var result = [String]()
    for str in lst {
        var count = 0
        for char in str {
            if let num = Int(String(char)), num % 2 != 0 {
                count += 1
            }
        }
        let outputStr = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
        result.append(outputStr)
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."][/INST]  ```swift
func oddCount(lst: [String]) -> [String] {
    var result = [String]()
    for str in lst {
        var count = 0
        for char in str {
            if let num = Int(String(char)), num % 2 != 0 {
                count += 1
            }
        }
        let outputStr = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
        result.append(outputStr)
    }
    return result
}
```

func oddCount(lst: [String]) -> [String] {
    var result = [String]()

    for str in lst {
        var count = 0
        for char in str {
            if let num = Int(String(char)), num % 2 != 0 {
                count += 1
            }
        }
        let sentence = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
        result.append(sentence)
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."][/INST]  ```swift
func oddCount(lst: [String]) -> [String] {
    var result = [String]()

    for str in lst {
        var count = 0
        for char in str {
            if let num = Int(String(char)), num % 2 != 0 {
                count += 1
            }
        }
        let sentence = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
        result.append(sentence)
    }

    return result
}
```

func minSubArraySum(nums: [Int]) -> Int {
    var minSum = Int.max
    var currentSum = 0

    for num in nums {
        currentSum += num
        minSum = min(minSum, currentSum)
        if currentSum > 0 {
            currentSum = 0
        }
    }

    return minSum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6[/INST]  ```swift
func minSubArraySum(nums: [Int]) -> Int {
    var minSum = Int.max
    var currentSum = 0

    for num in nums {
        currentSum += num
        minSum = min(minSum, currentSum)
        if currentSum > 0 {
            currentSum = 0
        }
    }

    return minSum
}
```

func minSubArraySum(nums: [Int]) -> Int {
    var minSum = nums[0]
    var currentSum = 0

    for num in nums {
        currentSum = max(num, currentSum + num)
        minSum = min(minSum, currentSum)
    }

    return minSum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6[/INST]  ```swift
func minSubArraySum(nums: [Int]) -> Int {
    var minSum = nums[0]
    var currentSum = 0

    for num in nums {
        currentSum = max(num, currentSum + num)
        minSum = min(minSum, currentSum)
    }

    return minSum
}
```
 // XCTAssertTrue failed

func minSubArraySum(nums: [Int]) -> Int {
    var minSum = Int.max
    var currentSum = 0

    for num in nums {
        currentSum += num
        if currentSum < minSum {
            minSum = currentSum
        }
        if currentSum > 0 {
            currentSum = 0
        }
    }

    return minSum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6[/INST]  ```swift
func minSubArraySum(nums: [Int]) -> Int {
    var minSum = Int.max
    var currentSum = 0

    for num in nums {
        currentSum += num
        if currentSum < minSum {
            minSum = currentSum
        }
        if currentSum > 0 {
            currentSum = 0
        }
    }

    return minSum
}
```

func minSubArraySum(nums: [Int]) -> Int {
    var minSum = nums[0]
    var currentSum = nums[0]

    for i in 1..<nums.count {
        currentSum = min(nums[i], currentSum + nums[i])
        minSum = min(minSum, currentSum)
    }

    return minSum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6[/INST]  ```swift
func minSubArraySum(nums: [Int]) -> Int {
    var minSum = nums[0]
    var currentSum = nums[0]

    for i in 1..<nums.count {
        currentSum = min(nums[i], currentSum + nums[i])
        minSum = min(minSum, currentSum)
    }

    return minSum
}
```

func minSubArraySum(nums: [Int]) -> Int {
    var minSum = Int.max
    var currentSum = 0

    for num in nums {
        currentSum += num
        minSum = min(minSum, currentSum)
        if currentSum > 0 {
            currentSum = 0
        }
    }

    return minSum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6[/INST]  ```swift
func minSubArraySum(nums: [Int]) -> Int {
    var minSum = Int.max
    var currentSum = 0

    for num in nums {
        currentSum += num
        minSum = min(minSum, currentSum)
        if currentSum > 0 {
            currentSum = 0
        }
    }

    return minSum
}
```

func minSubArraySum(nums: [Int]) -> Int {
    var minSum = nums[0]
    var currentSum = 0

    for num in nums {
        currentSum += num
        if currentSum < minSum {
            minSum = currentSum
        }
        if currentSum > 0 {
            currentSum = 0
        }
    }

    return minSum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6[/INST]  ```swift
func minSubArraySum(nums: [Int]) -> Int {
    var minSum = nums[0]
    var currentSum = 0

    for num in nums {
        currentSum += num
        if currentSum < minSum {
            minSum = currentSum
        }
        if currentSum > 0 {
            currentSum = 0
        }
    }

    return minSum
}
```

func minSubArraySum(nums: [Int]) -> Int {
    var minSum = Int.max
    var currentSum = 0

    for num in nums {
        currentSum += num

        if currentSum < minSum {
            minSum = currentSum
        }

        if currentSum > 0 {
            currentSum = 0
        }
    }

    return minSum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6[/INST]  ```swift
func minSubArraySum(nums: [Int]) -> Int {
    var minSum = Int.max
    var currentSum = 0

    for num in nums {
        currentSum += num

        if currentSum < minSum {
            minSum = currentSum
        }

        if currentSum > 0 {
            currentSum = 0
        }
    }

    return minSum
}
```

func minSubArraySum(nums: [Int]) -> Int {
    var minSum = Int.max
    var currentSum = 0

    for num in nums {
        currentSum += num
        minSum = min(minSum, currentSum)
        if currentSum > 0 {
            currentSum = 0
        }
    }

    return minSum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6[/INST]  ```swift
func minSubArraySum(nums: [Int]) -> Int {
    var minSum = Int.max
    var currentSum = 0

    for num in nums {
        currentSum += num
        minSum = min(minSum, currentSum)
        if currentSum > 0 {
            currentSum = 0
        }
    }

    return minSum
}
```

func minSubArraySum(nums: [Int]) -> Int {
    var minSum = nums[0]
    var currentSum = 0

    for num in nums {
        currentSum += num
        if currentSum < minSum {
            minSum = currentSum
        }
        if currentSum > 0 {
            currentSum = 0
        }
    }

    return minSum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6[/INST]  ```swift
func minSubArraySum(nums: [Int]) -> Int {
    var minSum = nums[0]
    var currentSum = 0

    for num in nums {
        currentSum += num
        if currentSum < minSum {
            minSum = currentSum
        }
        if currentSum > 0 {
            currentSum = 0
        }
    }

    return minSum
}
```

func minSubArraySum(nums: [Int]) -> Int {
    var minSum = Int.max
    var currentSum = 0

    for num in nums {
        currentSum += num
        minSum = min(minSum, currentSum)
        if currentSum > 0 {
            currentSum = 0
        }
    }

    return minSum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6[/INST]  ```swift
func minSubArraySum(nums: [Int]) -> Int {
    var minSum = Int.max
    var currentSum = 0

    for num in nums {
        currentSum += num
        minSum = min(minSum, currentSum)
        if currentSum > 0 {
            currentSum = 0
        }
    }

    return minSum
}
```

func maxFill(grid: [[Int]], capacity: Int) -> Int {
    var count = 0
    var currentCapacity = capacity
    for row in grid {
        for well in row {
            if well == 1 {
                if currentCapacity == 0 {
                    count += 1
                    currentCapacity = capacity
                }
                currentCapacity -= 1
            }
        }
    }
    if currentCapacity != capacity {
        count += 1
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it, 
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0[/INST]  ```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
    var count = 0
    var currentCapacity = capacity
    for row in grid {
        for well in row {
            if well == 1 {
                if currentCapacity == 0 {
                    count += 1
                    currentCapacity = capacity
                }
                currentCapacity -= 1
            }
        }
    }
    if currentCapacity != capacity {
        count += 1
    }
    return count
}
```
 // XCTAssertTrue failed

func maxFill(grid: [[Int]], capacity: Int) -> Int {
    var count = 0
    var currentCapacity = 0
    for row in grid {
        for well in row {
            if well == 1 {
                if currentCapacity == capacity {
                    count += 1
                    currentCapacity = 0
                }
                currentCapacity += 1
            }
        }
    }
    if currentCapacity > 0 {
        count += 1
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it, 
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0[/INST]  ```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
    var count = 0
    var currentCapacity = 0
    for row in grid {
        for well in row {
            if well == 1 {
                if currentCapacity == capacity {
                    count += 1
                    currentCapacity = 0
                }
                currentCapacity += 1
            }
        }
    }
    if currentCapacity > 0 {
        count += 1
    }
    return count
}
```
 // XCTAssertTrue failed

func maxFill(grid: [[Int]], capacity: Int) -> Int {
    var count = 0
    var bucket = 0
    for row in grid {
        for well in row {
            if well == 1 {
                if bucket == capacity {
                    count += 1
                    bucket = 0
                }
                bucket += 1
            }
        }
    }
    if bucket > 0 {
        count += 1
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it, 
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0[/INST]  ```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
    var count = 0
    var bucket = 0
    for row in grid {
        for well in row {
            if well == 1 {
                if bucket == capacity {
                    count += 1
                    bucket = 0
                }
                bucket += 1
            }
        }
    }
    if bucket > 0 {
        count += 1
    }
    return count
}
```
 // XCTAssertTrue failed

func maxFill(grid: [[Int]], capacity: Int) -> Int {
    var count = 0
    var bucket = capacity
    for row in grid {
        for well in row {
            if well == 1 {
                if bucket == 0 {
                    count += 1
                    bucket = capacity
                }
                bucket -= 1
            }
        }
    }
    if bucket < capacity {
        count += 1
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it, 
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0[/INST]  ```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
    var count = 0
    var bucket = capacity
    for row in grid {
        for well in row {
            if well == 1 {
                if bucket == 0 {
                    count += 1
                    bucket = capacity
                }
                bucket -= 1
            }
        }
    }
    if bucket < capacity {
        count += 1
    }
    return count
}
```
 // XCTAssertTrue failed

func maxFill(grid: [[Int]], capacity: Int) -> Int {
    var count = 0
    var bucket = capacity
    for row in grid {
        for well in row {
            if well == 1 {
                if bucket == 0 {
                    count += 1
                    bucket = capacity
                }
                bucket -= 1
            }
        }
    }
    if bucket < capacity {
        count += 1
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it, 
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0[/INST]  ```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
    var count = 0
    var bucket = capacity
    for row in grid {
        for well in row {
            if well == 1 {
                if bucket == 0 {
                    count += 1
                    bucket = capacity
                }
                bucket -= 1
            }
        }
    }
    if bucket < capacity {
        count += 1
    }
    return count
}
```
 // XCTAssertTrue failed

func maxFill(grid: [[Int]], capacity: Int) -> Int {
    var totalFills = 0
    var currentFill = 0

    for row in grid {
        for well in row {
            if well == 1 {
                currentFill += 1
                if currentFill == capacity {
                    totalFills += 1
                    currentFill = 0
                }
            }
        }
    }

    if currentFill > 0 {
        totalFills += 1
    }

    return totalFills
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it, 
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0[/INST]  ```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
    var totalFills = 0
    var currentFill = 0

    for row in grid {
        for well in row {
            if well == 1 {
                currentFill += 1
                if currentFill == capacity {
                    totalFills += 1
                    currentFill = 0
                }
            }
        }
    }

    if currentFill > 0 {
        totalFills += 1
    }

    return totalFills
}
```
 // XCTAssertTrue failed

func maxFill(grid: [[Int]], capacity: Int) -> Int {
    var count = 0
    var bucket = capacity
    for row in grid {
        for well in row {
            if well == 1 {
                if bucket == 0 {
                    count += 1
                    bucket = capacity
                }
                bucket -= 1
            }
        }
    }
    if bucket != capacity {
        count += 1
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it, 
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0[/INST]  ```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
    var count = 0
    var bucket = capacity
    for row in grid {
        for well in row {
            if well == 1 {
                if bucket == 0 {
                    count += 1
                    bucket = capacity
                }
                bucket -= 1
            }
        }
    }
    if bucket != capacity {
        count += 1
    }
    return count
}
```
 // XCTAssertTrue failed

func maxFill(grid: [[Int]], capacity: Int) -> Int {
    var count = 0
    var bucket = capacity
    for row in grid {
        for well in row {
            if well == 1 {
                if bucket == 0 {
                    count += 1
                    bucket = capacity
                }
                bucket -= 1
            }
        }
    }
    if bucket < capacity {
        count += 1
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it, 
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0[/INST]  ```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
    var count = 0
    var bucket = capacity
    for row in grid {
        for well in row {
            if well == 1 {
                if bucket == 0 {
                    count += 1
                    bucket = capacity
                }
                bucket -= 1
            }
        }
    }
    if bucket < capacity {
        count += 1
    }
    return count
}
```
 // XCTAssertTrue failed

func maxFill(grid: [[Int]], capacity: Int) -> Int {
    var count = 0
    var bucket = capacity
    for row in grid {
        for well in row {
            if well == 1 {
                if bucket == 0 {
                    count += 1
                    bucket = capacity
                }
                bucket -= 1
            }
        }
    }
    if bucket < capacity {
        count += 1
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it, 
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0[/INST]  ```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
    var count = 0
    var bucket = capacity
    for row in grid {
        for well in row {
            if well == 1 {
                if bucket == 0 {
                    count += 1
                    bucket = capacity
                }
                bucket -= 1
            }
        }
    }
    if bucket < capacity {
        count += 1
    }
    return count
}
```
 // XCTAssertTrue failed

func maxFill(grid: [[Int]], capacity: Int) -> Int {
    var grid = grid
    var operations = 0
    let rows = grid.count
    let cols = grid[0].count

    for col in 0..<cols {
        var bucket = capacity
        for row in 0..<rows {
            if grid[row][col] == 1 {
                if bucket == 0 {
                    operations += 1
                    bucket = capacity
                }
                grid[row][col] = 0
                bucket -= 1
            }
        }
        if bucket < capacity {
            operations += 1
        }
    }
    return operations
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it, 
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0[/INST]  ```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
    var grid = grid
    var operations = 0
    let rows = grid.count
    let cols = grid[0].count

    for col in 0..<cols {
        var bucket = capacity
        for row in 0..<rows {
            if grid[row][col] == 1 {
                if bucket == 0 {
                    operations += 1
                    bucket = capacity
                }
                grid[row][col] = 0
                bucket -= 1
            }
        }
        if bucket < capacity {
            operations += 1
        }
    }
    return operations
}
```
 // XCTAssertTrue failed

func sortArray(arr: [Int]) -> [Int] {
    return arr.sorted {
        let first = $0.nonzeroBitCount
        let second = $1.nonzeroBitCount
        if first == second {
            return $0 < $1
        } else {
            return first < second
        }
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4][/INST]  ```swift
func sortArray(arr: [Int]) -> [Int] {
    return arr.sorted {
        let first = $0.nonzeroBitCount
        let second = $1.nonzeroBitCount
        if first == second {
            return $0 < $1
        } else {
            return first < second
        }
    }
}
```
 // XCTAssertTrue failed

func sortArray(arr: [Int]) -> [Int] {
    return arr.sorted {
        let firstBinaryOnes = String($0, radix: 2).filter { $0 == "1" }.count
        let secondBinaryOnes = String($1, radix: 2).filter { $0 == "1" }.count
        if firstBinaryOnes == secondBinaryOnes {
            return $0 < $1
        } else {
            return firstBinaryOnes < secondBinaryOnes
        }
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4][/INST]  ```swift
func sortArray(arr: [Int]) -> [Int] {
    return arr.sorted {
        let firstBinaryOnes = String($0, radix: 2).filter { $0 == "1" }.count
        let secondBinaryOnes = String($1, radix: 2).filter { $0 == "1" }.count
        if firstBinaryOnes == secondBinaryOnes {
            return $0 < $1
        } else {
            return firstBinaryOnes < secondBinaryOnes
        }
    }
}
```

func sortArray(arr: [Int]) -> [Int] {
    return arr.sorted {
        let firstBinary = String($0, radix: 2)
        let secondBinary = String($1, radix: 2)
        let firstOnes = firstBinary.filter { $0 == "1" }.count
        let secondOnes = secondBinary.filter { $0 == "1" }.count
        if firstOnes == secondOnes {
            return $0 < $1
        } else {
            return firstOnes < secondOnes
        }
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4][/INST]  ```swift
func sortArray(arr: [Int]) -> [Int] {
    return arr.sorted {
        let firstBinary = String($0, radix: 2)
        let secondBinary = String($1, radix: 2)
        let firstOnes = firstBinary.filter { $0 == "1" }.count
        let secondOnes = secondBinary.filter { $0 == "1" }.count
        if firstOnes == secondOnes {
            return $0 < $1
        } else {
            return firstOnes < secondOnes
        }
    }
}
```

func sortArray(arr: [Int]) -> [Int] {
    return arr.sorted {
        let countOfOnesInFirst = String($0, radix: 2).filter { $0 == "1" }.count
        let countOfOnesInSecond = String($1, radix: 2).filter { $0 == "1" }.count
        if countOfOnesInFirst == countOfOnesInSecond {
            return $0 < $1
        } else {
            return countOfOnesInFirst < countOfOnesInSecond
        }
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4][/INST]  ```swift
func sortArray(arr: [Int]) -> [Int] {
    return arr.sorted {
        let countOfOnesInFirst = String($0, radix: 2).filter { $0 == "1" }.count
        let countOfOnesInSecond = String($1, radix: 2).filter { $0 == "1" }.count
        if countOfOnesInFirst == countOfOnesInSecond {
            return $0 < $1
        } else {
            return countOfOnesInFirst < countOfOnesInSecond
        }
    }
}
```

func sortArray(arr: [Int]) -> [Int] {
    return arr.sorted {
        let first = String($0, radix: 2).filter { $0 == "1" }.count
        let second = String($1, radix: 2).filter { $0 == "1" }.count
        if first == second {
            return $0 < $1
        } else {
            return first < second
        }
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4][/INST]  ```swift
func sortArray(arr: [Int]) -> [Int] {
    return arr.sorted {
        let first = String($0, radix: 2).filter { $0 == "1" }.count
        let second = String($1, radix: 2).filter { $0 == "1" }.count
        if first == second {
            return $0 < $1
        } else {
            return first < second
        }
    }
}
```

func sortArray(arr: [Int]) -> [Int] {
    return arr.sorted {
        let firstBinary = String($0, radix: 2)
        let secondBinary = String($1, radix: 2)
        let firstOnes = firstBinary.filter { $0 == "1" }.count
        let secondOnes = secondBinary.filter { $0 == "1" }.count
        if firstOnes == secondOnes {
            return $0 < $1
        } else {
            return firstOnes < secondOnes
        }
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4][/INST]  ```swift
func sortArray(arr: [Int]) -> [Int] {
    return arr.sorted {
        let firstBinary = String($0, radix: 2)
        let secondBinary = String($1, radix: 2)
        let firstOnes = firstBinary.filter { $0 == "1" }.count
        let secondOnes = secondBinary.filter { $0 == "1" }.count
        if firstOnes == secondOnes {
            return $0 < $1
        } else {
            return firstOnes < secondOnes
        }
    }
}
```

func sortArray(arr: [Int]) -> [Int] {
    return arr.sorted {
        let firstBinaryOnes = String($0, radix: 2).filter { $0 == "1" }.count
        let secondBinaryOnes = String($1, radix: 2).filter { $0 == "1" }.count
        if firstBinaryOnes == secondBinaryOnes {
            return $0 < $1
        } else {
            return firstBinaryOnes < secondBinaryOnes
        }
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4][/INST]  ```swift
func sortArray(arr: [Int]) -> [Int] {
    return arr.sorted {
        let firstBinaryOnes = String($0, radix: 2).filter { $0 == "1" }.count
        let secondBinaryOnes = String($1, radix: 2).filter { $0 == "1" }.count
        if firstBinaryOnes == secondBinaryOnes {
            return $0 < $1
        } else {
            return firstBinaryOnes < secondBinaryOnes
        }
    }
}
```

func sortArray(arr: [Int]) -> [Int] {
    return arr.sorted {
        let first = String($0, radix: 2).filter { $0 == "1" }.count
        let second = String($1, radix: 2).filter { $0 == "1" }.count
        if first == second {
            return $0 < $1
        } else {
            return first < second
        }
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4][/INST]  ```swift
func sortArray(arr: [Int]) -> [Int] {
    return arr.sorted {
        let first = String($0, radix: 2).filter { $0 == "1" }.count
        let second = String($1, radix: 2).filter { $0 == "1" }.count
        if first == second {
            return $0 < $1
        } else {
            return first < second
        }
    }
}
```

func sortArray(arr: [Int]) -> [Int] {
    return arr.sorted {
        let firstBinaryOnes = String($0, radix: 2).filter { $0 == "1" }.count
        let secondBinaryOnes = String($1, radix: 2).filter { $0 == "1" }.count
        if firstBinaryOnes == secondBinaryOnes {
            return $0 < $1
        } else {
            return firstBinaryOnes < secondBinaryOnes
        }
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4][/INST]  ```swift
func sortArray(arr: [Int]) -> [Int] {
    return arr.sorted {
        let firstBinaryOnes = String($0, radix: 2).filter { $0 == "1" }.count
        let secondBinaryOnes = String($1, radix: 2).filter { $0 == "1" }.count
        if firstBinaryOnes == secondBinaryOnes {
            return $0 < $1
        } else {
            return firstBinaryOnes < secondBinaryOnes
        }
    }
}
```

func sortArray(arr: [Int]) -> [Int] {
    return arr.sorted {
        let first = String($0, radix: 2).filter { $0 == "1" }.count
        let second = String($1, radix: 2).filter { $0 == "1" }.count
        if first == second {
            return $0 < $1
        } else {
            return first < second
        }
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4][/INST]  ```swift
func sortArray(arr: [Int]) -> [Int] {
    return arr.sorted {
        let first = String($0, radix: 2).filter { $0 == "1" }.count
        let second = String($1, radix: 2).filter { $0 == "1" }.count
        if first == second {
            return $0 < $1
        } else {
            return first < second
        }
    }
}
```

func selectWords(s: String, n: Int) -> [String] {
    let words = s.components(separatedBy: " ")
    var result: [String] = []

    for word in words {
        let consonants = word.filter { "bcdfghjklmnpqrstvwxyz".contains($0.lowercased()) }
        if consonants.count == n {
            result.append(word)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement 
a function that returns an array of all words from string s that contain exactly 
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"][/INST]  ```swift
func selectWords(s: String, n: Int) -> [String] {
    let words = s.components(separatedBy: " ")
    var result: [String] = []

    for word in words {
        let consonants = word.filter { "bcdfghjklmnpqrstvwxyz".contains($0.lowercased()) }
        if consonants.count == n {
            result.append(word)
        }
    }

    return result
}
```

func selectWords(s: String, n: Int) -> [String] {
    let words = s.components(separatedBy: " ")
    var result: [String] = []

    for word in words {
        let consonants = word.filter { "bcdfghjklmnpqrstvwxyz".contains($0.lowercased()) }
        if consonants.count == n {
            result.append(word)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement 
a function that returns an array of all words from string s that contain exactly 
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"][/INST]  ```swift
func selectWords(s: String, n: Int) -> [String] {
    let words = s.components(separatedBy: " ")
    var result: [String] = []

    for word in words {
        let consonants = word.filter { "bcdfghjklmnpqrstvwxyz".contains($0.lowercased()) }
        if consonants.count == n {
            result.append(word)
        }
    }

    return result
}
```

func selectWords(s: String, n: Int) -> [String] {
    let words = s.components(separatedBy: " ")
    var result: [String] = []

    for word in words {
        let consonants = word.filter { "bcdfghjklmnpqrstvwxyz".contains($0.lowercased()) }
        if consonants.count == n {
            result.append(word)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement 
a function that returns an array of all words from string s that contain exactly 
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"][/INST]  ```swift
func selectWords(s: String, n: Int) -> [String] {
    let words = s.components(separatedBy: " ")
    var result: [String] = []

    for word in words {
        let consonants = word.filter { "bcdfghjklmnpqrstvwxyz".contains($0.lowercased()) }
        if consonants.count == n {
            result.append(word)
        }
    }

    return result
}
```

func selectWords(s: String, n: Int) -> [String] {
    let words = s.components(separatedBy: " ")
    var result: [String] = []
    let consonants: Set<Character> = ["b", "c", "d", "f", "g", "h", "j", "k", "l", "m", "n", "p", "q", "r", "s", "t", "v", "w", "x", "y", "z"]

    for word in words {
        let consonantCount = word.lowercased().filter { consonants.contains($0) }.count
        if consonantCount == n {
            result.append(word)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement 
a function that returns an array of all words from string s that contain exactly 
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"][/INST]  ```swift
func selectWords(s: String, n: Int) -> [String] {
    let words = s.components(separatedBy: " ")
    var result: [String] = []
    let consonants: Set<Character> = ["b", "c", "d", "f", "g", "h", "j", "k", "l", "m", "n", "p", "q", "r", "s", "t", "v", "w", "x", "y", "z"]

    for word in words {
        let consonantCount = word.lowercased().filter { consonants.contains($0) }.count
        if consonantCount == n {
            result.append(word)
        }
    }

    return result
}
```

func selectWords(s: String, n: Int) -> [String] {
    let words = s.components(separatedBy: " ")
    var result: [String] = []

    for word in words {
        let consonants = word.filter { "bcdfghjklmnpqrstvwxyz".contains($0.lowercased()) }
        if consonants.count == n {
            result.append(word)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement 
a function that returns an array of all words from string s that contain exactly 
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"][/INST]  ```swift
func selectWords(s: String, n: Int) -> [String] {
    let words = s.components(separatedBy: " ")
    var result: [String] = []

    for word in words {
        let consonants = word.filter { "bcdfghjklmnpqrstvwxyz".contains($0.lowercased()) }
        if consonants.count == n {
            result.append(word)
        }
    }

    return result
}
```

func selectWords(s: String, n: Int) -> [String] {
    let words = s.components(separatedBy: " ")
    var result: [String] = []

    for word in words {
        let consonants = word.filter { "bcdfghjklmnpqrstvwxyz".contains($0.lowercased()) }
        if consonants.count == n {
            result.append(word)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement 
a function that returns an array of all words from string s that contain exactly 
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"][/INST]  ```swift
func selectWords(s: String, n: Int) -> [String] {
    let words = s.components(separatedBy: " ")
    var result: [String] = []

    for word in words {
        let consonants = word.filter { "bcdfghjklmnpqrstvwxyz".contains($0.lowercased()) }
        if consonants.count == n {
            result.append(word)
        }
    }

    return result
}
```

func selectWords(s: String, n: Int) -> [String] {
    let words = s.components(separatedBy: " ")
    var result = [String]()

    for word in words {
        let consonants = word.filter { "bcdfghjklmnpqrstvwxyz".contains($0.lowercased()) }
        if consonants.count == n {
            result.append(word)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement 
a function that returns an array of all words from string s that contain exactly 
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"][/INST]  ```swift
func selectWords(s: String, n: Int) -> [String] {
    let words = s.components(separatedBy: " ")
    var result = [String]()

    for word in words {
        let consonants = word.filter { "bcdfghjklmnpqrstvwxyz".contains($0.lowercased()) }
        if consonants.count == n {
            result.append(word)
        }
    }

    return result
}
```

func selectWords(s: String, n: Int) -> [String] {
    let words = s.components(separatedBy: " ")
    var result: [String] = []

    for word in words {
        let consonants = word.filter { "bcdfghjklmnpqrstvwxyz".contains($0.lowercased()) }
        if consonants.count == n {
            result.append(word)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement 
a function that returns an array of all words from string s that contain exactly 
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"][/INST]  ```swift
func selectWords(s: String, n: Int) -> [String] {
    let words = s.components(separatedBy: " ")
    var result: [String] = []

    for word in words {
        let consonants = word.filter { "bcdfghjklmnpqrstvwxyz".contains($0.lowercased()) }
        if consonants.count == n {
            result.append(word)
        }
    }

    return result
}
```

func selectWords(s: String, n: Int) -> [String] {
    let words = s.components(separatedBy: " ")
    var result: [String] = []

    for word in words {
        let consonants = word.filter { "bcdfghjklmnpqrstvwxyz".contains($0.lowercased()) }
        if consonants.count == n {
            result.append(word)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement 
a function that returns an array of all words from string s that contain exactly 
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"][/INST]  ```swift
func selectWords(s: String, n: Int) -> [String] {
    let words = s.components(separatedBy: " ")
    var result: [String] = []

    for word in words {
        let consonants = word.filter { "bcdfghjklmnpqrstvwxyz".contains($0.lowercased()) }
        if consonants.count == n {
            result.append(word)
        }
    }

    return result
}
```

func selectWords(s: String, n: Int) -> [String] {
    let words = s.components(separatedBy: " ")
    var result: [String] = []
    let consonants: Set<Character> = ["b", "c", "d", "f", "g", "h", "j", "k", "l", "m", "n", "p", "q", "r", "s", "t", "v", "w", "x", "y", "z"]

    for word in words {
        let consonantCount = word.lowercased().filter { consonants.contains($0) }.count
        if consonantCount == n {
            result.append(word)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement 
a function that returns an array of all words from string s that contain exactly 
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"][/INST]  ```swift
func selectWords(s: String, n: Int) -> [String] {
    let words = s.components(separatedBy: " ")
    var result: [String] = []
    let consonants: Set<Character> = ["b", "c", "d", "f", "g", "h", "j", "k", "l", "m", "n", "p", "q", "r", "s", "t", "v", "w", "x", "y", "z"]

    for word in words {
        let consonantCount = word.lowercased().filter { consonants.contains($0) }.count
        if consonantCount == n {
            result.append(word)
        }
    }

    return result
}
```

func getClosestVowel(word: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let consonants: Set<Character> = Set("bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ")

    var lastConsonant: Character?
    var closestVowel: Character?

    for char in word.reversed() {
        if consonants.contains(char) {
            lastConsonant = char
        } else if vowels.contains(char) {
            if lastConsonant != nil {
                closestVowel = char
                break
            }
        }
    }

    return closestVowel.map(String.init) ?? ""
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between 
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition. 
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""[/INST]  ```swift
func getClosestVowel(word: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let consonants: Set<Character> = Set("bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ")

    var lastConsonant: Character?
    var closestVowel: Character?

    for char in word.reversed() {
        if consonants.contains(char) {
            lastConsonant = char
        } else if vowels.contains(char) {
            if lastConsonant != nil {
                closestVowel = char
                break
            }
        }
    }

    return closestVowel.map(String.init) ?? ""
}
```
 // XCTAssertTrue failed

func getClosestVowel(word: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let consonants: Set<Character> = Set("bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ")

    for index in word.indices.reversed() {
        let char = word[index]
        if vowels.contains(char) {
            if index != word.startIndex && index != word.index(before: word.endIndex) {
                let prevChar = word[word.index(before: index)]
                let nextChar = word[word.index(after: index)]
                if consonants.contains(prevChar) && consonants.contains(nextChar) {
                    return String(char)
                }
            }
        }
    }
    return ""
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between 
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition. 
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""[/INST]  ```swift
func getClosestVowel(word: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let consonants: Set<Character> = Set("bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ")

    for index in word.indices.reversed() {
        let char = word[index]
        if vowels.contains(char) {
            if index != word.startIndex && index != word.index(before: word.endIndex) {
                let prevChar = word[word.index(before: index)]
                let nextChar = word[word.index(after: index)]
                if consonants.contains(prevChar) && consonants.contains(nextChar) {
                    return String(char)
                }
            }
        }
    }
    return ""
}
```

func getClosestVowel(word: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    var lastConsonantIndex = word.startIndex

    for index in word.indices.reversed() {
        let char = word[index]
        if !vowels.contains(char) {
            lastConsonantIndex = index
            break
        }
    }

    for index in word.indices.reversed() {
        let char = word[index]
        if vowels.contains(char) && index < lastConsonantIndex {
            return String(char)
        }
    }

    return ""
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between 
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition. 
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""[/INST]  ```swift
func getClosestVowel(word: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    var lastConsonantIndex = word.startIndex

    for index in word.indices.reversed() {
        let char = word[index]
        if !vowels.contains(char) {
            lastConsonantIndex = index
            break
        }
    }

    for index in word.indices.reversed() {
        let char = word[index]
        if vowels.contains(char) && index < lastConsonantIndex {
            return String(char)
        }
    }

    return ""
}
```
 // XCTAssertTrue failed

func getClosestVowel(word: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let consonants: Set<Character> = Set("bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ")

    for i in stride(from: word.count - 2, through: 1, by: -1) {
        let char = word[word.index(word.startIndex, offsetBy: i)]
        if vowels.contains(char) && consonants.contains(word[word.index(word.startIndex, offsetBy: i - 1)]) && consonants.contains(word[word.index(word.startIndex, offsetBy: i + 1)]) {
            return String(char)
        }
    }

    return ""
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between 
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition. 
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""[/INST]  ```swift
func getClosestVowel(word: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let consonants: Set<Character> = Set("bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ")

    for i in stride(from: word.count - 2, through: 1, by: -1) {
        let char = word[word.index(word.startIndex, offsetBy: i)]
        if vowels.contains(char) && consonants.contains(word[word.index(word.startIndex, offsetBy: i - 1)]) && consonants.contains(word[word.index(word.startIndex, offsetBy: i + 1)]) {
            return String(char)
        }
    }

    return ""
}
```

func getClosestVowel(word: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    var closestVowel = ""

    for char in word.reversed() {
        if vowels.contains(char) {
            closestVowel = String(char)
        } else if !closestVowel.isEmpty {
            return closestVowel
        }
    }

    return ""
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between 
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition. 
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""[/INST]  ```swift
func getClosestVowel(word: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    var closestVowel = ""

    for char in word.reversed() {
        if vowels.contains(char) {
            closestVowel = String(char)
        } else if !closestVowel.isEmpty {
            return closestVowel
        }
    }

    return ""
}
```
 // XCTAssertTrue failed

func getClosestVowel(word: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let consonants: Set<Character> = Set("bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ")

    for index in word.indices.reversed() {
        let char = word[index]
        if vowels.contains(char) && index != word.startIndex && index != word.index(before: word.endIndex) {
            let prevChar = word[word.index(before: index)]
            let nextChar = word[word.index(after: index)]
            if consonants.contains(prevChar) && consonants.contains(nextChar) {
                return String(char)
            }
        }
    }
    return ""
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between 
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition. 
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""[/INST]  ```swift
func getClosestVowel(word: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let consonants: Set<Character> = Set("bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ")

    for index in word.indices.reversed() {
        let char = word[index]
        if vowels.contains(char) && index != word.startIndex && index != word.index(before: word.endIndex) {
            let prevChar = word[word.index(before: index)]
            let nextChar = word[word.index(after: index)]
            if consonants.contains(prevChar) && consonants.contains(nextChar) {
                return String(char)
            }
        }
    }
    return ""
}
```

func getClosestVowel(word: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let consonants: Set<Character> = Set("bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ")

    var closestVowel: Character?

    for char in word.reversed() {
        if consonants.contains(char) {
            if let vowel = closestVowel {
                return String(vowel)
            }
        } else if vowels.contains(char) {
            closestVowel = char
        }
    }

    return ""
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between 
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition. 
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""[/INST]  ```swift
func getClosestVowel(word: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let consonants: Set<Character> = Set("bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ")

    var closestVowel: Character?

    for char in word.reversed() {
        if consonants.contains(char) {
            if let vowel = closestVowel {
                return String(vowel)
            }
        } else if vowels.contains(char) {
            closestVowel = char
        }
    }

    return ""
}
```
 // XCTAssertTrue failed

func getClosestVowel(word: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let reversedWord = String(word.reversed())

    for (index, char) in reversedWord.enumerated() {
        if index > 0 && index < reversedWord.count - 1 {
            let prevChar = reversedWord[reversedWord.index(reversedWord.startIndex, offsetBy: index - 1)]
            let nextChar = reversedWord[reversedWord.index(reversedWord.startIndex, offsetBy: index + 1)]

            if !vowels.contains(prevChar) && !vowels.contains(nextChar) && vowels.contains(char) {
                return String(char)
            }
        }
    }

    return ""
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between 
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition. 
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""[/INST]  ```swift
func getClosestVowel(word: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let reversedWord = String(word.reversed())

    for (index, char) in reversedWord.enumerated() {
        if index > 0 && index < reversedWord.count - 1 {
            let prevChar = reversedWord[reversedWord.index(reversedWord.startIndex, offsetBy: index - 1)]
            let nextChar = reversedWord[reversedWord.index(reversedWord.startIndex, offsetBy: index + 1)]

            if !vowels.contains(prevChar) && !vowels.contains(nextChar) && vowels.contains(char) {
                return String(char)
            }
        }
    }

    return ""
}
```

func getClosestVowel(word: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let reversedWord = String(word.reversed())

    for (index, char) in reversedWord.enumerated() {
        if index > 0 && index < reversedWord.count - 1 {
            let prevChar = reversedWord[reversedWord.index(reversedWord.startIndex, offsetBy: index - 1)]
            let nextChar = reversedWord[reversedWord.index(reversedWord.startIndex, offsetBy: index + 1)]

            if !vowels.contains(prevChar) && !vowels.contains(nextChar) && vowels.contains(char) {
                return String(char)
            }
        }
    }

    return ""
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between 
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition. 
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""[/INST]  ```swift
func getClosestVowel(word: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    let reversedWord = String(word.reversed())

    for (index, char) in reversedWord.enumerated() {
        if index > 0 && index < reversedWord.count - 1 {
            let prevChar = reversedWord[reversedWord.index(reversedWord.startIndex, offsetBy: index - 1)]
            let nextChar = reversedWord[reversedWord.index(reversedWord.startIndex, offsetBy: index + 1)]

            if !vowels.contains(prevChar) && !vowels.contains(nextChar) && vowels.contains(char) {
                return String(char)
            }
        }
    }

    return ""
}
```

func getClosestVowel(word: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    var closestVowel = ""

    for char in word.reversed() {
        if !vowels.contains(char) {
            if let lastVowel = closestVowel.last, vowels.contains(lastVowel) {
                return String(lastVowel)
            }
        } else {
            closestVowel.append(char)
        }
    }

    return ""
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between 
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition. 
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""[/INST]  ```swift
func getClosestVowel(word: String) -> String {
    let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    var closestVowel = ""

    for char in word.reversed() {
        if !vowels.contains(char) {
            if let lastVowel = closestVowel.last, vowels.contains(lastVowel) {
                return String(lastVowel)
            }
        } else {
            closestVowel.append(char)
        }
    }

    return ""
}
```
 // XCTAssertTrue failed

func matchParens(lst: [String]) -> String {
    var openCount = 0
    var closeCount = 0

    for str in lst {
        for char in str {
            if char == "(" {
                openCount += 1
            } else if char == ")" {
                if openCount > 0 {
                    openCount -= 1
                } else {
                    closeCount += 1
                }
            }
        }
    }

    return openCount == closeCount ? "Yes" : "No"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"[/INST]  ```swift
func matchParens(lst: [String]) -> String {
    var openCount = 0
    var closeCount = 0

    for str in lst {
        for char in str {
            if char == "(" {
                openCount += 1
            } else if char == ")" {
                if openCount > 0 {
                    openCount -= 1
                } else {
                    closeCount += 1
                }
            }
        }
    }

    return openCount == closeCount ? "Yes" : "No"
}
```
 // XCTAssertTrue failed

func matchParens(lst: [String]) -> String {
    var openCount = 0
    var closeCount = 0

    for str in lst {
        for char in str {
            if char == "(" {
                openCount += 1
            } else {
                if openCount > 0 {
                    openCount -= 1
                } else {
                    closeCount += 1
                }
            }
        }
    }

    return openCount == closeCount ? "Yes" : "No"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"[/INST]  ```swift
func matchParens(lst: [String]) -> String {
    var openCount = 0
    var closeCount = 0

    for str in lst {
        for char in str {
            if char == "(" {
                openCount += 1
            } else {
                if openCount > 0 {
                    openCount -= 1
                } else {
                    closeCount += 1
                }
            }
        }
    }

    return openCount == closeCount ? "Yes" : "No"
}
```
 // XCTAssertTrue failed

func matchParens(lst: [String]) -> String {
    var openCount = 0
    var closeCount = 0

    for str in lst {
        for char in str {
            if char == "(" {
                openCount += 1
            } else {
                if openCount > 0 {
                    openCount -= 1
                } else {
                    closeCount += 1
                }
            }
        }
    }

    return openCount == closeCount ? "Yes" : "No"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"[/INST]  ```swift
func matchParens(lst: [String]) -> String {
    var openCount = 0
    var closeCount = 0

    for str in lst {
        for char in str {
            if char == "(" {
                openCount += 1
            } else {
                if openCount > 0 {
                    openCount -= 1
                } else {
                    closeCount += 1
                }
            }
        }
    }

    return openCount == closeCount ? "Yes" : "No"
}
```
 // XCTAssertTrue failed

func matchParens(lst: [String]) -> String {
    var openCount = 0
    var closeCount = 0

    for str in lst {
        for char in str {
            if char == "(" {
                openCount += 1
            } else {
                if openCount > 0 {
                    openCount -= 1
                } else {
                    closeCount += 1
                }
            }
        }
    }

    return openCount == closeCount ? "Yes" : "No"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"[/INST]  ```swift
func matchParens(lst: [String]) -> String {
    var openCount = 0
    var closeCount = 0

    for str in lst {
        for char in str {
            if char == "(" {
                openCount += 1
            } else {
                if openCount > 0 {
                    openCount -= 1
                } else {
                    closeCount += 1
                }
            }
        }
    }

    return openCount == closeCount ? "Yes" : "No"
}
```
 // XCTAssertTrue failed

func matchParens(lst: [String]) -> String {
    var openCount = 0
    var closeCount = 0

    for str in lst {
        for char in str {
            if char == "(" {
                openCount += 1
            } else {
                if openCount > 0 {
                    openCount -= 1
                } else {
                    closeCount += 1
                }
            }
        }
    }

    return openCount == closeCount ? "Yes" : "No"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"[/INST]  ```swift
func matchParens(lst: [String]) -> String {
    var openCount = 0
    var closeCount = 0

    for str in lst {
        for char in str {
            if char == "(" {
                openCount += 1
            } else {
                if openCount > 0 {
                    openCount -= 1
                } else {
                    closeCount += 1
                }
            }
        }
    }

    return openCount == closeCount ? "Yes" : "No"
}
```
 // XCTAssertTrue failed

func matchParens(lst: [String]) -> String {
    var openCount = 0
    var closeCount = 0

    for str in lst {
        for char in str {
            if char == "(" {
                openCount += 1
            } else {
                if openCount > 0 {
                    openCount -= 1
                } else {
                    closeCount += 1
                }
            }
        }
    }

    return openCount == closeCount ? "Yes" : "No"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"[/INST]  ```swift
func matchParens(lst: [String]) -> String {
    var openCount = 0
    var closeCount = 0

    for str in lst {
        for char in str {
            if char == "(" {
                openCount += 1
            } else {
                if openCount > 0 {
                    openCount -= 1
                } else {
                    closeCount += 1
                }
            }
        }
    }

    return openCount == closeCount ? "Yes" : "No"
}
```
 // XCTAssertTrue failed

func matchParens(lst: [String]) -> String {
    var openCount = 0
    var closeCount = 0

    for str in lst {
        for char in str {
            if char == "(" {
                openCount += 1
            } else {
                if openCount > 0 {
                    openCount -= 1
                } else {
                    closeCount += 1
                }
            }
        }
    }

    return openCount == closeCount ? "Yes" : "No"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"[/INST]  ```swift
func matchParens(lst: [String]) -> String {
    var openCount = 0
    var closeCount = 0

    for str in lst {
        for char in str {
            if char == "(" {
                openCount += 1
            } else {
                if openCount > 0 {
                    openCount -= 1
                } else {
                    closeCount += 1
                }
            }
        }
    }

    return openCount == closeCount ? "Yes" : "No"
}
```
 // XCTAssertTrue failed

func matchParens(lst: [String]) -> String {
    var openCount = 0
    var closeCount = 0

    for str in lst {
        for char in str {
            if char == "(" {
                openCount += 1
            } else {
                if openCount > 0 {
                    openCount -= 1
                } else {
                    closeCount += 1
                }
            }
        }
    }

    return openCount == closeCount ? "Yes" : "No"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"[/INST]  ```swift
func matchParens(lst: [String]) -> String {
    var openCount = 0
    var closeCount = 0

    for str in lst {
        for char in str {
            if char == "(" {
                openCount += 1
            } else {
                if openCount > 0 {
                    openCount -= 1
                } else {
                    closeCount += 1
                }
            }
        }
    }

    return openCount == closeCount ? "Yes" : "No"
}
```
 // XCTAssertTrue failed

func matchParens(lst: [String]) -> String {
    var openCount = 0
    var closeCount = 0

    for str in lst {
        for char in str {
            if char == "(" {
                openCount += 1
            } else {
                if openCount > 0 {
                    openCount -= 1
                } else {
                    closeCount += 1
                }
            }
        }
    }

    return openCount == closeCount ? "Yes" : "No"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"[/INST]  ```swift
func matchParens(lst: [String]) -> String {
    var openCount = 0
    var closeCount = 0

    for str in lst {
        for char in str {
            if char == "(" {
                openCount += 1
            } else {
                if openCount > 0 {
                    openCount -= 1
                } else {
                    closeCount += 1
                }
            }
        }
    }

    return openCount == closeCount ? "Yes" : "No"
}
```
 // XCTAssertTrue failed

func matchParens(lst: [String]) -> String {
    var openCount = 0
    var closeCount = 0

    for str in lst {
        for char in str {
            if char == "(" {
                openCount += 1
            } else {
                if openCount > 0 {
                    openCount -= 1
                } else {
                    closeCount += 1
                }
            }
        }
    }

    return openCount == closeCount ? "Yes" : "No"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"[/INST]  ```swift
func matchParens(lst: [String]) -> String {
    var openCount = 0
    var closeCount = 0

    for str in lst {
        for char in str {
            if char == "(" {
                openCount += 1
            } else {
                if openCount > 0 {
                    openCount -= 1
                } else {
                    closeCount += 1
                }
            }
        }
    }

    return openCount == closeCount ? "Yes" : "No"
}
```
 // XCTAssertTrue failed

func maximum(arr: [Int], k: Int) -> [Int] {
    let sortedArr = arr.sorted(by: >)
    return Array(sortedArr.prefix(k))
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array 
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2][/INST]  ```swift
func maximum(arr: [Int], k: Int) -> [Int] {
    let sortedArr = arr.sorted(by: >)
    return Array(sortedArr.prefix(k))
}
```
 // XCTAssertTrue failed

func maximum(arr: [Int], k: Int) -> [Int] {
    let sortedArray = arr.sorted()
    return Array(sortedArray.suffix(k))
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array 
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2][/INST]  ```swift
func maximum(arr: [Int], k: Int) -> [Int] {
    let sortedArray = arr.sorted()
    return Array(sortedArray.suffix(k))
}
```

func maximum(arr: [Int], k: Int) -> [Int] {
    let sortedArr = arr.sorted()
    return Array(sortedArr.suffix(k))
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array 
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2][/INST]  ```swift
func maximum(arr: [Int], k: Int) -> [Int] {
    let sortedArr = arr.sorted()
    return Array(sortedArr.suffix(k))
}
```

func maximum(arr: [Int], k: Int) -> [Int] {
    let sortedArray = arr.sorted(by: >)
    return Array(sortedArray.prefix(k))
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array 
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2][/INST]  ```swift
func maximum(arr: [Int], k: Int) -> [Int] {
    let sortedArray = arr.sorted(by: >)
    return Array(sortedArray.prefix(k))
}
```
 // XCTAssertTrue failed

func maximum(arr: [Int], k: Int) -> [Int] {
    let sortedArr = arr.sorted()
    return Array(sortedArr.suffix(k))
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array 
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2][/INST]  ```swift
func maximum(arr: [Int], k: Int) -> [Int] {
    let sortedArr = arr.sorted()
    return Array(sortedArr.suffix(k))
}
```

func maximum(arr: [Int], k: Int) -> [Int] {
    let sortedArray = arr.sorted()
    return Array(sortedArray.suffix(k))
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array 
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2][/INST]  ```swift
func maximum(arr: [Int], k: Int) -> [Int] {
    let sortedArray = arr.sorted()
    return Array(sortedArray.suffix(k))
}
```

func maximum(arr: [Int], k: Int) -> [Int] {
    let sortedArr = arr.sorted(by: >)
    return Array(sortedArr.prefix(k))
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array 
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2][/INST]  ```swift
func maximum(arr: [Int], k: Int) -> [Int] {
    let sortedArr = arr.sorted(by: >)
    return Array(sortedArr.prefix(k))
}
```
 // XCTAssertTrue failed

func maximum(arr: [Int], k: Int) -> [Int] {
    let sortedArr = arr.sorted()
    return Array(sortedArr.suffix(k))
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array 
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2][/INST]  ```swift
func maximum(arr: [Int], k: Int) -> [Int] {
    let sortedArr = arr.sorted()
    return Array(sortedArr.suffix(k))
}
```

func maximum(arr: [Int], k: Int) -> [Int] {
    let sortedArr = arr.sorted()
    return Array(sortedArr.suffix(k))
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array 
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2][/INST]  ```swift
func maximum(arr: [Int], k: Int) -> [Int] {
    let sortedArr = arr.sorted()
    return Array(sortedArr.suffix(k))
}
```

func maximum(arr: [Int], k: Int) -> [Int] {
    let sortedArr = arr.sorted()
    return Array(sortedArr.suffix(k))
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array 
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2][/INST]  ```swift
func maximum(arr: [Int], k: Int) -> [Int] {
    let sortedArr = arr.sorted()
    return Array(sortedArr.suffix(k))
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0[/INST]  ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0[/INST]  ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0[/INST]  ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0[/INST]  ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0[/INST]  ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0[/INST]  ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0[/INST]  ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0[/INST]  ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0[/INST]  ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0[/INST]  ```swift
func solution(lst: [Int]) -> Int {
    var sum = 0
    for (index, element) in lst.enumerated() {
        if index % 2 == 0 && element % 2 != 0 {
            sum += element
        }
    }
    return sum
}
```

func addElements(arr: [Int], k: Int) -> Int {
    var sum = 0
    for i in 0..<k {
        if arr[i] >= 0 && arr[i] <= 99 {
            sum += arr[i]
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24[/INST]  ```swift
func addElements(arr: [Int], k: Int) -> Int {
    var sum = 0
    for i in 0..<k {
        if arr[i] >= 0 && arr[i] <= 99 {
            sum += arr[i]
        }
    }
    return sum
}
```
 // XCTAssertTrue failed

func addElements(arr: [Int], k: Int) -> Int {
    var sum = 0
    for i in 0..<k {
        if arr[i] >= 0 && arr[i] <= 99 {
            sum += arr[i]
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24[/INST]  ```swift
func addElements(arr: [Int], k: Int) -> Int {
    var sum = 0
    for i in 0..<k {
        if arr[i] >= 0 && arr[i] <= 99 {
            sum += arr[i]
        }
    }
    return sum
}
```
 // XCTAssertTrue failed

func addElements(arr: [Int], k: Int) -> Int {
    var sum = 0
    for i in 0..<k {
        if arr[i] >= 0 && arr[i] <= 99 {
            sum += arr[i]
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24[/INST]  ```swift
func addElements(arr: [Int], k: Int) -> Int {
    var sum = 0
    for i in 0..<k {
        if arr[i] >= 0 && arr[i] <= 99 {
            sum += arr[i]
        }
    }
    return sum
}
```
 // XCTAssertTrue failed

func addElements(arr: [Int], k: Int) -> Int {
    var sum = 0
    for i in 0..<k {
        if arr[i] >= 0 && arr[i] <= 99 {
            sum += arr[i]
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24[/INST]  ```swift
func addElements(arr: [Int], k: Int) -> Int {
    var sum = 0
    for i in 0..<k {
        if arr[i] >= 0 && arr[i] <= 99 {
            sum += arr[i]
        }
    }
    return sum
}
```
 // XCTAssertTrue failed

func addElements(arr: [Int], k: Int) -> Int {
    var sum = 0
    for i in 0..<k {
        if arr[i] >= 0 && arr[i] <= 99 {
            sum += arr[i]
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24[/INST]  ```swift
func addElements(arr: [Int], k: Int) -> Int {
    var sum = 0
    for i in 0..<k {
        if arr[i] >= 0 && arr[i] <= 99 {
            sum += arr[i]
        }
    }
    return sum
}
```
 // XCTAssertTrue failed

func addElements(arr: [Int], k: Int) -> Int {
    var sum = 0
    for i in 0..<k {
        if arr[i] >= 0 && arr[i] <= 99 {
            sum += arr[i]
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24[/INST]  ```swift
func addElements(arr: [Int], k: Int) -> Int {
    var sum = 0
    for i in 0..<k {
        if arr[i] >= 0 && arr[i] <= 99 {
            sum += arr[i]
        }
    }
    return sum
}
```
 // XCTAssertTrue failed

func addElements(arr: [Int], k: Int) -> Int {
    var sum = 0
    for i in 0..<k {
        if arr[i] >= 0 && arr[i] <= 99 {
            sum += arr[i]
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24[/INST]  ```swift
func addElements(arr: [Int], k: Int) -> Int {
    var sum = 0
    for i in 0..<k {
        if arr[i] >= 0 && arr[i] <= 99 {
            sum += arr[i]
        }
    }
    return sum
}
```
 // XCTAssertTrue failed

func addElements(arr: [Int], k: Int) -> Int {
    var sum = 0
    for i in 0..<k {
        if arr[i] >= 0 && arr[i] <= 99 {
            sum += arr[i]
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24[/INST]  ```swift
func addElements(arr: [Int], k: Int) -> Int {
    var sum = 0
    for i in 0..<k {
        if arr[i] >= 0 && arr[i] <= 99 {
            sum += arr[i]
        }
    }
    return sum
}
```
 // XCTAssertTrue failed

func addElements(arr: [Int], k: Int) -> Int {
    var sum = 0
    for i in 0..<k {
        if arr[i] >= 0 && arr[i] <= 99 {
            sum += arr[i]
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24[/INST]  ```swift
func addElements(arr: [Int], k: Int) -> Int {
    var sum = 0
    for i in 0..<k {
        if arr[i] >= 0 && arr[i] <= 99 {
            sum += arr[i]
        }
    }
    return sum
}
```
 // XCTAssertTrue failed

func addElements(arr: [Int], k: Int) -> Int {
    var sum = 0
    for i in 0..<k {
        if arr[i] >= 0 && arr[i] <= 99 {
            sum += arr[i]
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24[/INST]  ```swift
func addElements(arr: [Int], k: Int) -> Int {
    var sum = 0
    for i in 0..<k {
        if arr[i] >= 0 && arr[i] <= 99 {
            sum += arr[i]
        }
    }
    return sum
}
```
 // XCTAssertTrue failed

func getOddCollatz(n: Int) -> [Int] {
    var result = Set<Int>()
    var current = n

    while current != 1 {
        if current % 2 != 0 {
            result.insert(current)
        }

        if current % 2 == 0 {
            current = current / 2
        } else {
            current = 3 * current + 1
        }
    }

    result.insert(1)
    return result.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the 
previous term as follows: if the previous term is even, the next term is one half of 
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note: 
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5][/INST]  ```swift
func getOddCollatz(n: Int) -> [Int] {
    var result = Set<Int>()
    var current = n

    while current != 1 {
        if current % 2 != 0 {
            result.insert(current)
        }

        if current % 2 == 0 {
            current = current / 2
        } else {
            current = 3 * current + 1
        }
    }

    result.insert(1)
    return result.sorted()
}
```

func getOddCollatz(n: Int) -> [Int] {
    var sequence = [n]
    var current = n

    while current != 1 {
        if current % 2 == 0 {
            current = current / 2
        } else {
            current = 3 * current + 1
        }
        sequence.append(current)
    }

    return sequence.filter { $0 % 2 != 0 }.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the 
previous term as follows: if the previous term is even, the next term is one half of 
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note: 
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5][/INST]  ```swift
func getOddCollatz(n: Int) -> [Int] {
    var sequence = [n]
    var current = n

    while current != 1 {
        if current % 2 == 0 {
            current = current / 2
        } else {
            current = 3 * current + 1
        }
        sequence.append(current)
    }

    return sequence.filter { $0 % 2 != 0 }.sorted()
}
```

func getOddCollatz(n: Int) -> [Int] {
    var sequence = [n]
    var current = n

    while current != 1 {
        if current % 2 == 0 {
            current = current / 2
        } else {
            current = 3 * current + 1
        }
        sequence.append(current)
    }

    return sequence.filter { $0 % 2 != 0 }.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the 
previous term as follows: if the previous term is even, the next term is one half of 
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note: 
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5][/INST]  ```swift
func getOddCollatz(n: Int) -> [Int] {
    var sequence = [n]
    var current = n

    while current != 1 {
        if current % 2 == 0 {
            current = current / 2
        } else {
            current = 3 * current + 1
        }
        sequence.append(current)
    }

    return sequence.filter { $0 % 2 != 0 }.sorted()
}
```

func getOddCollatz(n: Int) -> [Int] {
    var sequence = [n]
    var current = n

    while current != 1 {
        current = current % 2 == 0 ? current / 2 : 3 * current + 1
        sequence.append(current)
    }

    return sequence.filter { $0 % 2 != 0 }.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the 
previous term as follows: if the previous term is even, the next term is one half of 
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note: 
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5][/INST]  ```swift
func getOddCollatz(n: Int) -> [Int] {
    var sequence = [n]
    var current = n

    while current != 1 {
        current = current % 2 == 0 ? current / 2 : 3 * current + 1
        sequence.append(current)
    }

    return sequence.filter { $0 % 2 != 0 }.sorted()
}
```

func getOddCollatz(n: Int) -> [Int] {
    var sequence = [n]
    var current = n

    while current != 1 {
        current = current % 2 == 0 ? current / 2 : 3 * current + 1
        sequence.append(current)
    }

    return sequence.filter { $0 % 2 != 0 }.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the 
previous term as follows: if the previous term is even, the next term is one half of 
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note: 
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5][/INST]  ```swift
func getOddCollatz(n: Int) -> [Int] {
    var sequence = [n]
    var current = n

    while current != 1 {
        current = current % 2 == 0 ? current / 2 : 3 * current + 1
        sequence.append(current)
    }

    return sequence.filter { $0 % 2 != 0 }.sorted()
}
```

func getOddCollatz(n: Int) -> [Int] {
    var sequence = [n]
    var current = n

    while current != 1 {
        if current % 2 == 0 {
            current = current / 2
        } else {
            current = 3 * current + 1
        }
        sequence.append(current)
    }

    return sequence.filter { $0 % 2 != 0 }.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the 
previous term as follows: if the previous term is even, the next term is one half of 
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note: 
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5][/INST]  ```swift
func getOddCollatz(n: Int) -> [Int] {
    var sequence = [n]
    var current = n

    while current != 1 {
        if current % 2 == 0 {
            current = current / 2
        } else {
            current = 3 * current + 1
        }
        sequence.append(current)
    }

    return sequence.filter { $0 % 2 != 0 }.sorted()
}
```

func getOddCollatz(n: Int) -> [Int] {
    var sequence = [n]
    var current = n

    while current != 1 {
        if current % 2 == 0 {
            current = current / 2
        } else {
            current = 3 * current + 1
        }
        sequence.append(current)
    }

    return sequence.filter { $0 % 2 != 0 }.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the 
previous term as follows: if the previous term is even, the next term is one half of 
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note: 
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5][/INST]  ```swift
func getOddCollatz(n: Int) -> [Int] {
    var sequence = [n]
    var current = n

    while current != 1 {
        if current % 2 == 0 {
            current = current / 2
        } else {
            current = 3 * current + 1
        }
        sequence.append(current)
    }

    return sequence.filter { $0 % 2 != 0 }.sorted()
}
```

func getOddCollatz(n: Int) -> [Int] {
    var sequence = [n]
    var current = n

    while current != 1 {
        if current % 2 == 0 {
            current = current / 2
        } else {
            current = 3 * current + 1
        }
        sequence.append(current)
    }

    return sequence.filter { $0 % 2 != 0 }.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the 
previous term as follows: if the previous term is even, the next term is one half of 
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note: 
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5][/INST]  ```swift
func getOddCollatz(n: Int) -> [Int] {
    var sequence = [n]
    var current = n

    while current != 1 {
        if current % 2 == 0 {
            current = current / 2
        } else {
            current = 3 * current + 1
        }
        sequence.append(current)
    }

    return sequence.filter { $0 % 2 != 0 }.sorted()
}
```

func getOddCollatz(n: Int) -> [Int] {
    var sequence = [n]
    var current = n

    while current != 1 {
        if current % 2 == 0 {
            current = current / 2
        } else {
            current = 3 * current + 1
        }
        sequence.append(current)
    }

    return sequence.filter { $0 % 2 != 0 }.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the 
previous term as follows: if the previous term is even, the next term is one half of 
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note: 
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5][/INST]  ```swift
func getOddCollatz(n: Int) -> [Int] {
    var sequence = [n]
    var current = n

    while current != 1 {
        if current % 2 == 0 {
            current = current / 2
        } else {
            current = 3 * current + 1
        }
        sequence.append(current)
    }

    return sequence.filter { $0 % 2 != 0 }.sorted()
}
```

func getOddCollatz(n: Int) -> [Int] {
    var sequence = [n]
    var current = n

    while current != 1 {
        current = current % 2 == 0 ? current / 2 : 3 * current + 1
        sequence.append(current)
    }

    return sequence.filter { $0 % 2 != 0 }.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the 
previous term as follows: if the previous term is even, the next term is one half of 
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note: 
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5][/INST]  ```swift
func getOddCollatz(n: Int) -> [Int] {
    var sequence = [n]
    var current = n

    while current != 1 {
        current = current % 2 == 0 ? current / 2 : 3 * current + 1
        sequence.append(current)
    }

    return sequence.filter { $0 % 2 != 0 }.sorted()
}
```

func validDate(date: String) -> Bool {
    let dateFormatter = DateFormatter()
    dateFormatter.dateFormat = "MM-dd-yyyy"
    dateFormatter.locale = Locale(identifier: "en_US_POSIX")
    dateFormatter.timeZone = TimeZone(secondsFromGMT: 0)
    dateFormatter.isLenient = false

    if let _ = dateFormatter.date(from: date) {
        let components = date.split(separator: "-").compactMap { Int($0) }
        guard components.count == 3 else { return false }

        let month = components[0]
        let day = components[1]
        let year = components[2]

        switch month {
        case 1, 3, 5, 7, 8, 10, 12:
            return day >= 1 && day <= 31
        case 4, 6, 9, 11:
            return day >= 1 && day <= 30
        case 2:
            if (year % 4 == 0 && year % 100 != 0) || (year % 400 == 0) {
                return day >= 1 && day <= 29
            } else {
                return day >= 1 && day <= 28
            }
        default:
            return false
        }
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false[/INST]  ```swift
func validDate(date: String) -> Bool {
    let dateFormatter = DateFormatter()
    dateFormatter.dateFormat = "MM-dd-yyyy"
    dateFormatter.locale = Locale(identifier: "en_US_POSIX")
    dateFormatter.timeZone = TimeZone(secondsFromGMT: 0)
    dateFormatter.isLenient = false

    if let _ = dateFormatter.date(from: date) {
        let components = date.split(separator: "-").compactMap { Int($0) }
        guard components.count == 3 else { return false }

        let month = components[0]
        let day = components[1]
        let year = components[2]

        switch month {
        case 1, 3, 5, 7, 8, 10, 12:
            return day >= 1 && day <= 31
        case 4, 6, 9, 11:
            return day >= 1 && day <= 30
        case 2:
            if (year % 4 == 0 && year % 100 != 0) || (year % 400 == 0) {
                return day >= 1 && day <= 29
            } else {
                return day >= 1 && day <= 28
            }
        default:
            return false
        }
    }

    return false
}
```

func validDate(date: String) -> Bool {
    let dateFormatter = DateFormatter()
    dateFormatter.dateFormat = "MM-dd-yyyy"
    dateFormatter.locale = Locale(identifier: "en_US_POSIX")
    dateFormatter.timeZone = TimeZone(secondsFromGMT: 0)
    dateFormatter.isLenient = false

    if let _ = dateFormatter.date(from: date) {
        let components = date.split(separator: "-").compactMap { Int($0) }
        guard components.count == 3 else { return false }
        let month = components[0]
        let day = components[1]

        switch month {
        case 1, 3, 5, 7, 8, 10, 12:
            return day >= 1 && day <= 31
        case 4, 6, 9, 11:
            return day >= 1 && day <= 30
        case 2:
            return day >= 1 && day <= 29
        default:
            return false
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false[/INST]  ```swift
func validDate(date: String) -> Bool {
    let dateFormatter = DateFormatter()
    dateFormatter.dateFormat = "MM-dd-yyyy"
    dateFormatter.locale = Locale(identifier: "en_US_POSIX")
    dateFormatter.timeZone = TimeZone(secondsFromGMT: 0)
    dateFormatter.isLenient = false

    if let _ = dateFormatter.date(from: date) {
        let components = date.split(separator: "-").compactMap { Int($0) }
        guard components.count == 3 else { return false }
        let month = components[0]
        let day = components[1]

        switch month {
        case 1, 3, 5, 7, 8, 10, 12:
            return day >= 1 && day <= 31
        case 4, 6, 9, 11:
            return day >= 1 && day <= 30
        case 2:
            return day >= 1 && day <= 29
        default:
            return false
        }
    }
    return false
}
```

func validDate(date: String) -> Bool {
    let dateFormatter = DateFormatter()
    dateFormatter.dateFormat = "MM-dd-yyyy"
    dateFormatter.locale = Locale(identifier: "en_US_POSIX")
    dateFormatter.timeZone = TimeZone(secondsFromGMT: 0)
    dateFormatter.isLenient = false

    if let _ = dateFormatter.date(from: date) {
        let components = date.components(separatedBy: "-").compactMap { Int($0) }
        guard components.count == 3 else { return false }
        let month = components[0]
        let day = components[1]
        let year = components[2]

        switch month {
        case 1, 3, 5, 7, 8, 10, 12:
            return day >= 1 && day <= 31
        case 4, 6, 9, 11:
            return day >= 1 && day <= 30
        case 2:
            if year % 4 == 0 && (year % 100 != 0 || year % 400 == 0) {
                return day >= 1 && day <= 29
            } else {
                return day >= 1 && day <= 28
            }
        default:
            return false
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false[/INST]  ```swift
func validDate(date: String) -> Bool {
    let dateFormatter = DateFormatter()
    dateFormatter.dateFormat = "MM-dd-yyyy"
    dateFormatter.locale = Locale(identifier: "en_US_POSIX")
    dateFormatter.timeZone = TimeZone(secondsFromGMT: 0)
    dateFormatter.isLenient = false

    if let _ = dateFormatter.date(from: date) {
        let components = date.components(separatedBy: "-").compactMap { Int($0) }
        guard components.count == 3 else { return false }
        let month = components[0]
        let day = components[1]
        let year = components[2]

        switch month {
        case 1, 3, 5, 7, 8, 10, 12:
            return day >= 1 && day <= 31
        case 4, 6, 9, 11:
            return day >= 1 && day <= 30
        case 2:
            if year % 4 == 0 && (year % 100 != 0 || year % 400 == 0) {
                return day >= 1 && day <= 29
            } else {
                return day >= 1 && day <= 28
            }
        default:
            return false
        }
    }
    return false
}
```

func validDate(date: String) -> Bool {
    let dateFormatter = DateFormatter()
    dateFormatter.dateFormat = "MM-dd-yyyy"
    dateFormatter.locale = Locale(identifier: "en_US_POSIX")
    dateFormatter.timeZone = TimeZone(secondsFromGMT: 0)
    dateFormatter.isLenient = false

    if let date = dateFormatter.date(from: date) {
        let calendar = Calendar.current
        let day = calendar.component(.day, from: date)
        let month = calendar.component(.month, from: date)
        let year = calendar.component(.year, from: date)

        switch month {
        case 1, 3, 5, 7, 8, 10, 12:
            return day >= 1 && day <= 31
        case 4, 6, 9, 11:
            return day >= 1 && day <= 30
        case 2:
            if (year % 4 == 0 && year % 100 != 0) || (year % 400 == 0) {
                return day >= 1 && day <= 29
            } else {
                return day >= 1 && day <= 28
            }
        default:
            return false
        }
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false[/INST]  ```swift
func validDate(date: String) -> Bool {
    let dateFormatter = DateFormatter()
    dateFormatter.dateFormat = "MM-dd-yyyy"
    dateFormatter.locale = Locale(identifier: "en_US_POSIX")
    dateFormatter.timeZone = TimeZone(secondsFromGMT: 0)
    dateFormatter.isLenient = false

    if let date = dateFormatter.date(from: date) {
        let calendar = Calendar.current
        let day = calendar.component(.day, from: date)
        let month = calendar.component(.month, from: date)
        let year = calendar.component(.year, from: date)

        switch month {
        case 1, 3, 5, 7, 8, 10, 12:
            return day >= 1 && day <= 31
        case 4, 6, 9, 11:
            return day >= 1 && day <= 30
        case 2:
            if (year % 4 == 0 && year % 100 != 0) || (year % 400 == 0) {
                return day >= 1 && day <= 29
            } else {
                return day >= 1 && day <= 28
            }
        default:
            return false
        }
    }

    return false
}
```

func validDate(date: String) -> Bool {
    let dateFormatter = DateFormatter()
    dateFormatter.dateFormat = "MM-dd-yyyy"
    dateFormatter.locale = Locale(identifier: "en_US_POSIX")
    dateFormatter.timeZone = TimeZone(secondsFromGMT: 0)
    dateFormatter.isLenient = false

    if let _ = dateFormatter.date(from: date) {
        let components = date.split(separator: "-").map { Int($0) }
        guard let month = components[0], let day = components[1], let year = components[2] else {
            return false
        }

        switch month {
        case 1, 3, 5, 7, 8, 10, 12:
            return day >= 1 && day <= 31
        case 4, 6, 9, 11:
            return day >= 1 && day <= 30
        case 2:
            if (year % 4 == 0 && year % 100 != 0) || (year % 400 == 0) {
                return day >= 1 && day <= 29
            } else {
                return day >= 1 && day <= 28
            }
        default:
            return false
        }
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false[/INST]  ```swift
func validDate(date: String) -> Bool {
    let dateFormatter = DateFormatter()
    dateFormatter.dateFormat = "MM-dd-yyyy"
    dateFormatter.locale = Locale(identifier: "en_US_POSIX")
    dateFormatter.timeZone = TimeZone(secondsFromGMT: 0)
    dateFormatter.isLenient = false

    if let _ = dateFormatter.date(from: date) {
        let components = date.split(separator: "-").map { Int($0) }
        guard let month = components[0], let day = components[1], let year = components[2] else {
            return false
        }

        switch month {
        case 1, 3, 5, 7, 8, 10, 12:
            return day >= 1 && day <= 31
        case 4, 6, 9, 11:
            return day >= 1 && day <= 30
        case 2:
            if (year % 4 == 0 && year % 100 != 0) || (year % 400 == 0) {
                return day >= 1 && day <= 29
            } else {
                return day >= 1 && day <= 28
            }
        default:
            return false
        }
    }

    return false
}
```

func validDate(date: String) -> Bool {
    let dateFormatter = DateFormatter()
    dateFormatter.dateFormat = "MM-dd-yyyy"
    dateFormatter.locale = Locale(identifier: "en_US_POSIX")
    dateFormatter.timeZone = TimeZone(secondsFromGMT: 0)
    dateFormatter.isLenient = false

    if let _ = dateFormatter.date(from: date) {
        let components = date.split(separator: "-").compactMap { Int($0) }
        guard components.count == 3 else { return false }

        let month = components[0]
        let day = components[1]
        let year = components[2]

        switch month {
        case 1, 3, 5, 7, 8, 10, 12:
            return day >= 1 && day <= 31
        case 4, 6, 9, 11:
            return day >= 1 && day <= 30
        case 2:
            if year % 400 == 0 || (year % 4 == 0 && year % 100 != 0) {
                return day >= 1 && day <= 29
            } else {
                return day >= 1 && day <= 28
            }
        default:
            return false
        }
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false[/INST]  ```swift
func validDate(date: String) -> Bool {
    let dateFormatter = DateFormatter()
    dateFormatter.dateFormat = "MM-dd-yyyy"
    dateFormatter.locale = Locale(identifier: "en_US_POSIX")
    dateFormatter.timeZone = TimeZone(secondsFromGMT: 0)
    dateFormatter.isLenient = false

    if let _ = dateFormatter.date(from: date) {
        let components = date.split(separator: "-").compactMap { Int($0) }
        guard components.count == 3 else { return false }

        let month = components[0]
        let day = components[1]
        let year = components[2]

        switch month {
        case 1, 3, 5, 7, 8, 10, 12:
            return day >= 1 && day <= 31
        case 4, 6, 9, 11:
            return day >= 1 && day <= 30
        case 2:
            if year % 400 == 0 || (year % 4 == 0 && year % 100 != 0) {
                return day >= 1 && day <= 29
            } else {
                return day >= 1 && day <= 28
            }
        default:
            return false
        }
    }

    return false
}
```

func validDate(date: String) -> Bool {
    let dateFormatter = DateFormatter()
    dateFormatter.dateFormat = "MM-dd-yyyy"
    dateFormatter.locale = Locale(identifier: "en_US_POSIX")
    dateFormatter.timeZone = TimeZone(secondsFromGMT: 0)
    dateFormatter.isLenient = false

    if let _ = dateFormatter.date(from: date) {
        let components = date.components(separatedBy: "-")
        guard components.count == 3 else { return false }

        let month = Int(components[0]) ?? 0
        let day = Int(components[1]) ?? 0
        let year = Int(components[2]) ?? 0

        if month < 1 || month > 12 || day < 1 {
            return false
        }

        switch month {
        case 1, 3, 5, 7, 8, 10, 12:
            return day <= 31
        case 4, 6, 9, 11:
            return day <= 30
        case 2:
            if year % 4 == 0 {
                if year % 100 == 0 {
                    return year % 400 == 0 && day <= 29
                }
                return day <= 29
            }
            return day <= 28
        default:
            return false
        }
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false[/INST]  ```swift
func validDate(date: String) -> Bool {
    let dateFormatter = DateFormatter()
    dateFormatter.dateFormat = "MM-dd-yyyy"
    dateFormatter.locale = Locale(identifier: "en_US_POSIX")
    dateFormatter.timeZone = TimeZone(secondsFromGMT: 0)
    dateFormatter.isLenient = false

    if let _ = dateFormatter.date(from: date) {
        let components = date.components(separatedBy: "-")
        guard components.count == 3 else { return false }

        let month = Int(components[0]) ?? 0
        let day = Int(components[1]) ?? 0
        let year = Int(components[2]) ?? 0

        if month < 1 || month > 12 || day < 1 {
            return false
        }

        switch month {
        case 1, 3, 5, 7, 8, 10, 12:
            return day <= 31
        case 4, 6, 9, 11:
            return day <= 30
        case 2:
            if year % 4 == 0 {
                if year % 100 == 0 {
                    return year % 400 == 0 && day <= 29
                }
                return day <= 29
            }
            return day <= 28
        default:
            return false
        }
    }

    return false
}
```

func validDate(date: String) -> Bool {
    let dateFormatter = DateFormatter()
    dateFormatter.dateFormat = "MM-dd-yyyy"
    dateFormatter.locale = Locale(identifier: "en_US_POSIX")
    dateFormatter.timeZone = TimeZone(secondsFromGMT: 0)
    dateFormatter.isLenient = false

    if let _ = dateFormatter.date(from: date) {
        let components = date.components(separatedBy: "-").compactMap { Int($0) }
        guard components.count == 3 else { return false }

        let month = components[0]
        let day = components[1]
        let year = components[2]

        switch month {
        case 1, 3, 5, 7, 8, 10, 12:
            return day >= 1 && day <= 31
        case 4, 6, 9, 11:
            return day >= 1 && day <= 30
        case 2:
            if (year % 4 == 0 && year % 100 != 0) || (year % 400 == 0) {
                return day >= 1 && day <= 29
            } else {
                return day >= 1 && day <= 28
            }
        default:
            return false
        }
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false[/INST]  ```swift
func validDate(date: String) -> Bool {
    let dateFormatter = DateFormatter()
    dateFormatter.dateFormat = "MM-dd-yyyy"
    dateFormatter.locale = Locale(identifier: "en_US_POSIX")
    dateFormatter.timeZone = TimeZone(secondsFromGMT: 0)
    dateFormatter.isLenient = false

    if let _ = dateFormatter.date(from: date) {
        let components = date.components(separatedBy: "-").compactMap { Int($0) }
        guard components.count == 3 else { return false }

        let month = components[0]
        let day = components[1]
        let year = components[2]

        switch month {
        case 1, 3, 5, 7, 8, 10, 12:
            return day >= 1 && day <= 31
        case 4, 6, 9, 11:
            return day >= 1 && day <= 30
        case 2:
            if (year % 4 == 0 && year % 100 != 0) || (year % 400 == 0) {
                return day >= 1 && day <= 29
            } else {
                return day >= 1 && day <= 28
            }
        default:
            return false
        }
    }

    return false
}
```

func validDate(date: String) -> Bool {
    let dateFormatter = DateFormatter()
    dateFormatter.dateFormat = "MM-dd-yyyy"
    dateFormatter.locale = Locale(identifier: "en_US_POSIX")
    dateFormatter.timeZone = TimeZone(secondsFromGMT: 0)
    dateFormatter.isLenient = false

    if let _ = dateFormatter.date(from: date) {
        let components = date.split(separator: "-").map { Int($0) }
        guard let month = components[0], let day = components[1], let year = components[2] else {
            return false
        }

        switch month {
        case 1, 3, 5, 7, 8, 10, 12:
            return day >= 1 && day <= 31
        case 4, 6, 9, 11:
            return day >= 1 && day <= 30
        case 2:
            let isLeapYear = (year % 4 == 0 && year % 100 != 0) || (year % 400 == 0)
            return day >= 1 && day <= (isLeapYear ? 29 : 28)
        default:
            return false
        }
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false[/INST]  ```swift
func validDate(date: String) -> Bool {
    let dateFormatter = DateFormatter()
    dateFormatter.dateFormat = "MM-dd-yyyy"
    dateFormatter.locale = Locale(identifier: "en_US_POSIX")
    dateFormatter.timeZone = TimeZone(secondsFromGMT: 0)
    dateFormatter.isLenient = false

    if let _ = dateFormatter.date(from: date) {
        let components = date.split(separator: "-").map { Int($0) }
        guard let month = components[0], let day = components[1], let year = components[2] else {
            return false
        }

        switch month {
        case 1, 3, 5, 7, 8, 10, 12:
            return day >= 1 && day <= 31
        case 4, 6, 9, 11:
            return day >= 1 && day <= 30
        case 2:
            let isLeapYear = (year % 4 == 0 && year % 100 != 0) || (year % 400 == 0)
            return day >= 1 && day <= (isLeapYear ? 29 : 28)
        default:
            return false
        }
    }

    return false
}
```

func validDate(date: String) -> Bool {
    let dateFormatter = DateFormatter()
    dateFormatter.dateFormat = "MM-dd-yyyy"
    dateFormatter.locale = Locale(identifier: "en_US_POSIX")
    dateFormatter.timeZone = TimeZone(secondsFromGMT: 0)
    dateFormatter.isLenient = false

    if let _ = dateFormatter.date(from: date) {
        let components = date.components(separatedBy: "-").compactMap { Int($0) }
        guard components.count == 3 else { return false }

        let month = components[0]
        let day = components[1]
        let year = components[2]

        switch month {
        case 1, 3, 5, 7, 8, 10, 12:
            return day >= 1 && day <= 31
        case 4, 6, 9, 11:
            return day >= 1 && day <= 30
        case 2:
            if (year % 4 == 0 && year % 100 != 0) || (year % 400 == 0) {
                return day >= 1 && day <= 29
            } else {
                return day >= 1 && day <= 28
            }
        default:
            return false
        }
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false[/INST]  ```swift
func validDate(date: String) -> Bool {
    let dateFormatter = DateFormatter()
    dateFormatter.dateFormat = "MM-dd-yyyy"
    dateFormatter.locale = Locale(identifier: "en_US_POSIX")
    dateFormatter.timeZone = TimeZone(secondsFromGMT: 0)
    dateFormatter.isLenient = false

    if let _ = dateFormatter.date(from: date) {
        let components = date.components(separatedBy: "-").compactMap { Int($0) }
        guard components.count == 3 else { return false }

        let month = components[0]
        let day = components[1]
        let year = components[2]

        switch month {
        case 1, 3, 5, 7, 8, 10, 12:
            return day >= 1 && day <= 31
        case 4, 6, 9, 11:
            return day >= 1 && day <= 30
        case 2:
            if (year % 4 == 0 && year % 100 != 0) || (year % 400 == 0) {
                return day >= 1 && day <= 29
            } else {
                return day >= 1 && day <= 28
            }
        default:
            return false
        }
    }

    return false
}
```

extension Int: Error {

}

extension Int: Error {}

func splitWords(txt: String) -> Result<[String], Int> {
    if let words = txt.split(separator: " ").map(String.init) {
        return .success(words)
    } else if let words = txt.split(separator: ",").map(String.init) {
        return .success(words)
    } else {
        let oddIndexLetters = txt.filter { $0.isLowercase && Int($0.asciiValue! - 97) % 2 != 0 }
        return .failure(oddIndexLetters.count)
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
Examples
splitWords(txt: "Hello world!") == .success(["Hello", "world!"])
splitWords(txt: "Hello,world!") == .success(["Hello", "world!"])
splitWords(txt: "abcdef") == .failure(3)[/INST]  ```swift
extension Int: Error {}

func splitWords(txt: String) -> Result<[String], Int> {
    if let words = txt.split(separator: " ").map(String.init) {
        return .success(words)
    } else if let words = txt.split(separator: ",").map(String.init) {
        return .success(words)
    } else {
        let oddIndexLetters = txt.filter { $0.isLowercase && Int($0.asciiValue! - 97) % 2 != 0 }
        return .failure(oddIndexLetters.count)
    }
}
```
extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'
if let words = txt.split(separator: " ").map(String.init) { // initializer for conditional binding must have Optional type, not '[String]'
} else if let words = txt.split(separator: ",").map(String.init) { // initializer for conditional binding must have Optional type, not '[String]'

extension Int: Error {

}

extension Int: Error {}

func splitWords(txt: String) -> Result<[String], Int> {
    if let words = txt.split(separator: " ").map(String.init), !words.isEmpty {
        return .success(words)
    } else if let words = txt.split(separator: ",").map(String.init), !words.isEmpty {
        return .success(words)
    } else {
        let oddIndexLetters = txt.filter { $0.isLowercase && Int($0.asciiValue! - 97) % 2 != 0 }
        return .failure(oddIndexLetters.count)
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
Examples
splitWords(txt: "Hello world!") == .success(["Hello", "world!"])
splitWords(txt: "Hello,world!") == .success(["Hello", "world!"])
splitWords(txt: "abcdef") == .failure(3)[/INST]  ```swift
extension Int: Error {}

func splitWords(txt: String) -> Result<[String], Int> {
    if let words = txt.split(separator: " ").map(String.init), !words.isEmpty {
        return .success(words)
    } else if let words = txt.split(separator: ",").map(String.init), !words.isEmpty {
        return .success(words)
    } else {
        let oddIndexLetters = txt.filter { $0.isLowercase && Int($0.asciiValue! - 97) % 2 != 0 }
        return .failure(oddIndexLetters.count)
    }
}
```
extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'
if let words = txt.split(separator: " ").map(String.init), !words.isEmpty { // initializer for conditional binding must have Optional type, not '[String]'
} else if let words = txt.split(separator: ",").map(String.init), !words.isEmpty { // initializer for conditional binding must have Optional type, not '[String]'

extension Int: Error {

}

extension Int: Error {}

func splitWords(txt: String) -> Result<[String], Int> {
    if let words = txt.split(separator: " ").map(String.init), !words.isEmpty {
        return .success(words)
    } else if let words = txt.split(separator: ",").map(String.init), !words.isEmpty {
        return .success(words)
    } else {
        let oddIndexedLetters = txt.filter { $0.isLowercase && Int($0.asciiValue! - 97) % 2 != 0 }
        return .failure(oddIndexedLetters.count)
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
Examples
splitWords(txt: "Hello world!") == .success(["Hello", "world!"])
splitWords(txt: "Hello,world!") == .success(["Hello", "world!"])
splitWords(txt: "abcdef") == .failure(3)[/INST]  ```swift
extension Int: Error {}

func splitWords(txt: String) -> Result<[String], Int> {
    if let words = txt.split(separator: " ").map(String.init), !words.isEmpty {
        return .success(words)
    } else if let words = txt.split(separator: ",").map(String.init), !words.isEmpty {
        return .success(words)
    } else {
        let oddIndexedLetters = txt.filter { $0.isLowercase && Int($0.asciiValue! - 97) % 2 != 0 }
        return .failure(oddIndexedLetters.count)
    }
}
```
extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'
if let words = txt.split(separator: " ").map(String.init), !words.isEmpty { // initializer for conditional binding must have Optional type, not '[String]'
} else if let words = txt.split(separator: ",").map(String.init), !words.isEmpty { // initializer for conditional binding must have Optional type, not '[String]'

extension Int: Error {

}

extension Int: Error {}

func splitWords(txt: String) -> Result<[String], Int> {
    if let words = txt.split(separator: " ").map({ String($0) }), !words.isEmpty {
        return .success(words)
    } else if let words = txt.split(separator: ",").map({ String($0) }), !words.isEmpty {
        return .success(words)
    } else {
        let oddIndexLetters = txt.filter { $0.isLowercase && Int($0.asciiValue! - 97) % 2 != 0 }
        return .failure(oddIndexLetters.count)
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
Examples
splitWords(txt: "Hello world!") == .success(["Hello", "world!"])
splitWords(txt: "Hello,world!") == .success(["Hello", "world!"])
splitWords(txt: "abcdef") == .failure(3)[/INST]  ```swift
extension Int: Error {}

func splitWords(txt: String) -> Result<[String], Int> {
    if let words = txt.split(separator: " ").map({ String($0) }), !words.isEmpty {
        return .success(words)
    } else if let words = txt.split(separator: ",").map({ String($0) }), !words.isEmpty {
        return .success(words)
    } else {
        let oddIndexLetters = txt.filter { $0.isLowercase && Int($0.asciiValue! - 97) % 2 != 0 }
        return .failure(oddIndexLetters.count)
    }
}
```
extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'
if let words = txt.split(separator: " ").map({ String($0) }), !words.isEmpty { // initializer for conditional binding must have Optional type, not '[String]'
} else if let words = txt.split(separator: ",").map({ String($0) }), !words.isEmpty { // initializer for conditional binding must have Optional type, not '[String]'

extension Int: Error {

}

extension Int: Error {}

func splitWords(txt: String) -> Result<[String], Int> {
    if let words = txt.split(separator: " ").map(String.init), !words.isEmpty {
        return .success(words)
    } else if let words = txt.split(separator: ",").map(String.init), !words.isEmpty {
        return .success(words)
    } else {
        let oddIndexLetters = txt.filter { $0.isLowercase && Int($0.asciiValue! - 97) % 2 != 0 }
        return .failure(oddIndexLetters.count)
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
Examples
splitWords(txt: "Hello world!") == .success(["Hello", "world!"])
splitWords(txt: "Hello,world!") == .success(["Hello", "world!"])
splitWords(txt: "abcdef") == .failure(3)[/INST]  ```swift
extension Int: Error {}

func splitWords(txt: String) -> Result<[String], Int> {
    if let words = txt.split(separator: " ").map(String.init), !words.isEmpty {
        return .success(words)
    } else if let words = txt.split(separator: ",").map(String.init), !words.isEmpty {
        return .success(words)
    } else {
        let oddIndexLetters = txt.filter { $0.isLowercase && Int($0.asciiValue! - 97) % 2 != 0 }
        return .failure(oddIndexLetters.count)
    }
}
```
extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'
if let words = txt.split(separator: " ").map(String.init), !words.isEmpty { // initializer for conditional binding must have Optional type, not '[String]'
} else if let words = txt.split(separator: ",").map(String.init), !words.isEmpty { // initializer for conditional binding must have Optional type, not '[String]'

extension Int: Error {

}

extension Int: Error {}

func splitWords(txt: String) -> Result<[String], Int> {
    if let words = txt.split(separator: " ").map({ String($0) }), !words.isEmpty {
        return .success(words)
    } else if let words = txt.split(separator: ",").map({ String($0) }), !words.isEmpty {
        return .success(words)
    } else {
        let oddIndexedLetters = txt.filter { $0.isLowercase && Int($0.asciiValue! - 97) % 2 != 0 }
        return .failure(oddIndexedLetters.count)
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
Examples
splitWords(txt: "Hello world!") == .success(["Hello", "world!"])
splitWords(txt: "Hello,world!") == .success(["Hello", "world!"])
splitWords(txt: "abcdef") == .failure(3)[/INST]  ```swift
extension Int: Error {}

func splitWords(txt: String) -> Result<[String], Int> {
    if let words = txt.split(separator: " ").map({ String($0) }), !words.isEmpty {
        return .success(words)
    } else if let words = txt.split(separator: ",").map({ String($0) }), !words.isEmpty {
        return .success(words)
    } else {
        let oddIndexedLetters = txt.filter { $0.isLowercase && Int($0.asciiValue! - 97) % 2 != 0 }
        return .failure(oddIndexedLetters.count)
    }
}
```
extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'
if let words = txt.split(separator: " ").map({ String($0) }), !words.isEmpty { // initializer for conditional binding must have Optional type, not '[String]'
} else if let words = txt.split(separator: ",").map({ String($0) }), !words.isEmpty { // initializer for conditional binding must have Optional type, not '[String]'

extension Int: Error {

}

extension Int: Error {}

func splitWords(txt: String) -> Result<[String], Int> {
    if let words = txt.split(separator: " ").map(String.init), !words.isEmpty {
        return .success(words)
    } else if let words = txt.split(separator: ",").map(String.init), !words.isEmpty {
        return .success(words)
    } else {
        let oddIndexLetters = txt.filter { $0.isLowercase && Int($0.asciiValue! - 97) % 2 != 0 }
        return .failure(oddIndexLetters.count)
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
Examples
splitWords(txt: "Hello world!") == .success(["Hello", "world!"])
splitWords(txt: "Hello,world!") == .success(["Hello", "world!"])
splitWords(txt: "abcdef") == .failure(3)[/INST]  ```swift
extension Int: Error {}

func splitWords(txt: String) -> Result<[String], Int> {
    if let words = txt.split(separator: " ").map(String.init), !words.isEmpty {
        return .success(words)
    } else if let words = txt.split(separator: ",").map(String.init), !words.isEmpty {
        return .success(words)
    } else {
        let oddIndexLetters = txt.filter { $0.isLowercase && Int($0.asciiValue! - 97) % 2 != 0 }
        return .failure(oddIndexLetters.count)
    }
}
```
extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'
if let words = txt.split(separator: " ").map(String.init), !words.isEmpty { // initializer for conditional binding must have Optional type, not '[String]'
} else if let words = txt.split(separator: ",").map(String.init), !words.isEmpty { // initializer for conditional binding must have Optional type, not '[String]'

extension Int: Error {

}

extension Int: Error {}

func splitWords(txt: String) -> Result<[String], Int> {
    if let words = txt.split(separator: " ").map({ String($0) }), !words.isEmpty {
        return .success(words)
    } else if let words = txt.split(separator: ",").map({ String($0) }), !words.isEmpty {
        return .success(words)
    } else {
        let oddIndexLetters = txt.filter { $0.isLowercase && Int($0.asciiValue! - 97) % 2 != 0 }
        return .failure(oddIndexLetters.count)
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
Examples
splitWords(txt: "Hello world!") == .success(["Hello", "world!"])
splitWords(txt: "Hello,world!") == .success(["Hello", "world!"])
splitWords(txt: "abcdef") == .failure(3)[/INST]  ```swift
extension Int: Error {}

func splitWords(txt: String) -> Result<[String], Int> {
    if let words = txt.split(separator: " ").map({ String($0) }), !words.isEmpty {
        return .success(words)
    } else if let words = txt.split(separator: ",").map({ String($0) }), !words.isEmpty {
        return .success(words)
    } else {
        let oddIndexLetters = txt.filter { $0.isLowercase && Int($0.asciiValue! - 97) % 2 != 0 }
        return .failure(oddIndexLetters.count)
    }
}
```
extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'
if let words = txt.split(separator: " ").map({ String($0) }), !words.isEmpty { // initializer for conditional binding must have Optional type, not '[String]'
} else if let words = txt.split(separator: ",").map({ String($0) }), !words.isEmpty { // initializer for conditional binding must have Optional type, not '[String]'

extension Int: Error {

}

extension Int: Error {}

func splitWords(txt: String) -> Result<[String], Int> {
    if let words = txt.split(separator: " ").map(String.init), !words.isEmpty {
        return .success(words)
    } else if let words = txt.split(separator: ",").map(String.init), !words.isEmpty {
        return .success(words)
    } else {
        let oddIndexLetters = txt.filter { $0.isLowercase && Int($0.asciiValue! - 97) % 2 != 0 }
        return .failure(oddIndexLetters.count)
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
Examples
splitWords(txt: "Hello world!") == .success(["Hello", "world!"])
splitWords(txt: "Hello,world!") == .success(["Hello", "world!"])
splitWords(txt: "abcdef") == .failure(3)[/INST]  ```swift
extension Int: Error {}

func splitWords(txt: String) -> Result<[String], Int> {
    if let words = txt.split(separator: " ").map(String.init), !words.isEmpty {
        return .success(words)
    } else if let words = txt.split(separator: ",").map(String.init), !words.isEmpty {
        return .success(words)
    } else {
        let oddIndexLetters = txt.filter { $0.isLowercase && Int($0.asciiValue! - 97) % 2 != 0 }
        return .failure(oddIndexLetters.count)
    }
}
```
extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'
if let words = txt.split(separator: " ").map(String.init), !words.isEmpty { // initializer for conditional binding must have Optional type, not '[String]'
} else if let words = txt.split(separator: ",").map(String.init), !words.isEmpty { // initializer for conditional binding must have Optional type, not '[String]'

extension Int: Error {

}

extension Int: Error {}

func splitWords(txt: String) -> Result<[String], Int> {
    if let words = txt.split(separator: " ").map(String.init), !words.isEmpty {
        return .success(words)
    } else if let words = txt.split(separator: ",").map(String.init), !words.isEmpty {
        return .success(words)
    } else {
        let oddIndexLetters = txt.filter { $0.isLowercase && Int($0.asciiValue! - 97) % 2 != 0 }
        return .failure(oddIndexLetters.count)
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
Examples
splitWords(txt: "Hello world!") == .success(["Hello", "world!"])
splitWords(txt: "Hello,world!") == .success(["Hello", "world!"])
splitWords(txt: "abcdef") == .failure(3)[/INST]  ```swift
extension Int: Error {}

func splitWords(txt: String) -> Result<[String], Int> {
    if let words = txt.split(separator: " ").map(String.init), !words.isEmpty {
        return .success(words)
    } else if let words = txt.split(separator: ",").map(String.init), !words.isEmpty {
        return .success(words)
    } else {
        let oddIndexLetters = txt.filter { $0.isLowercase && Int($0.asciiValue! - 97) % 2 != 0 }
        return .failure(oddIndexLetters.count)
    }
}
```
extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'
if let words = txt.split(separator: " ").map(String.init), !words.isEmpty { // initializer for conditional binding must have Optional type, not '[String]'
} else if let words = txt.split(separator: ",").map(String.init), !words.isEmpty { // initializer for conditional binding must have Optional type, not '[String]'

func isSorted(lst: [Int]) -> Bool {
    if lst.count <= 1 {
        return true
    }

    var previous = lst[0]
    var duplicateCount = 0

    for num in lst {
        if num < previous {
            return false
        } else if num == previous {
            duplicateCount += 1
            if duplicateCount > 1 {
                return false
            }
        } else {
            duplicateCount = 0
        }
        previous = num
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false[/INST]  ```swift
func isSorted(lst: [Int]) -> Bool {
    if lst.count <= 1 {
        return true
    }

    var previous = lst[0]
    var duplicateCount = 0

    for num in lst {
        if num < previous {
            return false
        } else if num == previous {
            duplicateCount += 1
            if duplicateCount > 1 {
                return false
            }
        } else {
            duplicateCount = 0
        }
        previous = num
    }

    return true
}
```

func isSorted(lst: [Int]) -> Bool {
    if lst.count <= 1 {
        return true
    }

    var prev = lst[0]
    var count = 1

    for i in 1..<lst.count {
        if lst[i] < prev {
            return false
        } else if lst[i] == prev {
            count += 1
        } else {
            count = 1
        }

        if count > 1 {
            return false
        }

        prev = lst[i]
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false[/INST]  ```swift
func isSorted(lst: [Int]) -> Bool {
    if lst.count <= 1 {
        return true
    }

    var prev = lst[0]
    var count = 1

    for i in 1..<lst.count {
        if lst[i] < prev {
            return false
        } else if lst[i] == prev {
            count += 1
        } else {
            count = 1
        }

        if count > 1 {
            return false
        }

        prev = lst[i]
    }

    return true
}
```
 // XCTAssertTrue failed

func isSorted(lst: [Int]) -> Bool {
    if lst.count <= 1 {
        return true
    }

    var previous = lst[0]
    var duplicates = Set<Int>()

    for number in lst {
        if number < previous {
            return false
        } else if number == previous {
            if duplicates.contains(number) {
                return false
            }
            duplicates.insert(number)
        } else {
            duplicates.removeAll()
        }
        previous = number
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false[/INST]  ```swift
func isSorted(lst: [Int]) -> Bool {
    if lst.count <= 1 {
        return true
    }

    var previous = lst[0]
    var duplicates = Set<Int>()

    for number in lst {
        if number < previous {
            return false
        } else if number == previous {
            if duplicates.contains(number) {
                return false
            }
            duplicates.insert(number)
        } else {
            duplicates.removeAll()
        }
        previous = number
    }

    return true
}
```

func isSorted(lst: [Int]) -> Bool {
    if lst.count <= 1 {
        return true
    }

    var last = lst[0]
    var count = 1

    for i in 1..<lst.count {
        if lst[i] < last {
            return false
        } else if lst[i] == last {
            count += 1
            if count > 1 {
                return false
            }
        } else {
            last = lst[i]
            count = 1
        }
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false[/INST]  ```swift
func isSorted(lst: [Int]) -> Bool {
    if lst.count <= 1 {
        return true
    }

    var last = lst[0]
    var count = 1

    for i in 1..<lst.count {
        if lst[i] < last {
            return false
        } else if lst[i] == last {
            count += 1
            if count > 1 {
                return false
            }
        } else {
            last = lst[i]
            count = 1
        }
    }

    return true
}
```
 // XCTAssertTrue failed

func isSorted(lst: [Int]) -> Bool {
    if lst.count <= 1 {
        return true
    }

    var lastNumber = lst[0]
    var duplicateCount = 0

    for number in lst {
        if number < lastNumber {
            return false
        } else if number == lastNumber {
            duplicateCount += 1
            if duplicateCount > 1 {
                return false
            }
        } else {
            duplicateCount = 0
        }
        lastNumber = number
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false[/INST]  ```swift
func isSorted(lst: [Int]) -> Bool {
    if lst.count <= 1 {
        return true
    }

    var lastNumber = lst[0]
    var duplicateCount = 0

    for number in lst {
        if number < lastNumber {
            return false
        } else if number == lastNumber {
            duplicateCount += 1
            if duplicateCount > 1 {
                return false
            }
        } else {
            duplicateCount = 0
        }
        lastNumber = number
    }

    return true
}
```

func isSorted(lst: [Int]) -> Bool {
    if lst.count <= 1 {
        return true
    }

    var previous = lst[0]
    var duplicates = Set<Int>()

    for number in lst {
        if number < previous {
            return false
        } else if number == previous {
            if duplicates.contains(number) {
                return false
            }
            duplicates.insert(number)
        } else {
            duplicates.removeAll()
        }
        previous = number
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false[/INST]  ```swift
func isSorted(lst: [Int]) -> Bool {
    if lst.count <= 1 {
        return true
    }

    var previous = lst[0]
    var duplicates = Set<Int>()

    for number in lst {
        if number < previous {
            return false
        } else if number == previous {
            if duplicates.contains(number) {
                return false
            }
            duplicates.insert(number)
        } else {
            duplicates.removeAll()
        }
        previous = number
    }

    return true
}
```

func isSorted(lst: [Int]) -> Bool {
    if lst.count <= 1 {
        return true
    }

    var lastNumber = lst[0]
    var duplicateCount = 0

    for number in lst {
        if number < lastNumber {
            return false
        } else if number == lastNumber {
            duplicateCount += 1
            if duplicateCount > 1 {
                return false
            }
        } else {
            duplicateCount = 0
        }
        lastNumber = number
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false[/INST]  ```swift
func isSorted(lst: [Int]) -> Bool {
    if lst.count <= 1 {
        return true
    }

    var lastNumber = lst[0]
    var duplicateCount = 0

    for number in lst {
        if number < lastNumber {
            return false
        } else if number == lastNumber {
            duplicateCount += 1
            if duplicateCount > 1 {
                return false
            }
        } else {
            duplicateCount = 0
        }
        lastNumber = number
    }

    return true
}
```

func isSorted(lst: [Int]) -> Bool {
    if lst.count <= 1 {
        return true
    }

    var previous = lst[0]
    var duplicates = Set<Int>()

    for num in lst {
        if num < previous {
            return false
        } else if num == previous {
            if duplicates.contains(num) {
                return false
            }
            duplicates.insert(num)
        } else {
            duplicates.removeAll()
        }
        previous = num
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false[/INST]  ```swift
func isSorted(lst: [Int]) -> Bool {
    if lst.count <= 1 {
        return true
    }

    var previous = lst[0]
    var duplicates = Set<Int>()

    for num in lst {
        if num < previous {
            return false
        } else if num == previous {
            if duplicates.contains(num) {
                return false
            }
            duplicates.insert(num)
        } else {
            duplicates.removeAll()
        }
        previous = num
    }

    return true
}
```

func isSorted(lst: [Int]) -> Bool {
    if lst.count <= 1 {
        return true
    }

    var prev = lst[0]
    var duplicates = Set<Int>()

    for num in lst {
        if num < prev {
            return false
        } else if num == prev {
            if duplicates.contains(num) {
                return false
            }
            duplicates.insert(num)
        } else {
            duplicates.removeAll()
        }
        prev = num
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false[/INST]  ```swift
func isSorted(lst: [Int]) -> Bool {
    if lst.count <= 1 {
        return true
    }

    var prev = lst[0]
    var duplicates = Set<Int>()

    for num in lst {
        if num < prev {
            return false
        } else if num == prev {
            if duplicates.contains(num) {
                return false
            }
            duplicates.insert(num)
        } else {
            duplicates.removeAll()
        }
        prev = num
    }

    return true
}
```

func isSorted(lst: [Int]) -> Bool {
    if lst.count <= 1 {
        return true
    }

    var last = lst[0]
    var count = 1

    for i in 1..<lst.count {
        if lst[i] < last {
            return false
        } else if lst[i] == last {
            count += 1
            if count > 1 {
                return false
            }
        } else {
            last = lst[i]
            count = 1
        }
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false[/INST]  ```swift
func isSorted(lst: [Int]) -> Bool {
    if lst.count <= 1 {
        return true
    }

    var last = lst[0]
    var count = 1

    for i in 1..<lst.count {
        if lst[i] < last {
            return false
        } else if lst[i] == last {
            count += 1
            if count > 1 {
                return false
            }
        } else {
            last = lst[i]
            count = 1
        }
    }

    return true
}
```
 // XCTAssertTrue failed

func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
    let start = max(interval1.0, interval2.0)
    let end = min(interval1.1, interval2.1)

    if start > end {
        return "NO"
    }

    let length = end - start + 1

    if length < 2 {
        return "NO"
    }

    for i in 2..<length {
        if length % i == 0 {
            return "NO"
        }
    }

    return "YES"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two 
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"[/INST]  ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
    let start = max(interval1.0, interval2.0)
    let end = min(interval1.1, interval2.1)

    if start > end {
        return "NO"
    }

    let length = end - start + 1

    if length < 2 {
        return "NO"
    }

    for i in 2..<length {
        if length % i == 0 {
            return "NO"
        }
    }

    return "YES"
}
```
 // XCTAssertTrue failed

func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
    let start = max(interval1.0, interval2.0)
    let end = min(interval1.1, interval2.1)

    if start > end {
        return "NO"
    }

    let length = end - start + 1

    if length < 2 {
        return "NO"
    }

    for i in 2..<length {
        if length % i == 0 {
            return "NO"
        }
    }

    return "YES"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two 
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"[/INST]  ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
    let start = max(interval1.0, interval2.0)
    let end = min(interval1.1, interval2.1)

    if start > end {
        return "NO"
    }

    let length = end - start + 1

    if length < 2 {
        return "NO"
    }

    for i in 2..<length {
        if length % i == 0 {
            return "NO"
        }
    }

    return "YES"
}
```
 // XCTAssertTrue failed

func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
    let start = max(interval1.0, interval2.0)
    let end = min(interval1.1, interval2.1)

    if start > end {
        return "NO"
    }

    let length = end - start + 1

    if length < 2 {
        return "NO"
    }

    for i in 2..<length {
        if length % i == 0 {
            return "NO"
        }
    }

    return "YES"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two 
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"[/INST]  ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
    let start = max(interval1.0, interval2.0)
    let end = min(interval1.1, interval2.1)

    if start > end {
        return "NO"
    }

    let length = end - start + 1

    if length < 2 {
        return "NO"
    }

    for i in 2..<length {
        if length % i == 0 {
            return "NO"
        }
    }

    return "YES"
}
```
 // XCTAssertTrue failed

func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
    let start = max(interval1.0, interval2.0)
    let end = min(interval1.1, interval2.1)

    if start > end {
        return "NO"
    }

    let length = end - start + 1

    if length < 2 {
        return "NO"
    }

    for i in 2..<length {
        if length % i == 0 {
            return "NO"
        }
    }

    return "YES"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two 
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"[/INST]  ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
    let start = max(interval1.0, interval2.0)
    let end = min(interval1.1, interval2.1)

    if start > end {
        return "NO"
    }

    let length = end - start + 1

    if length < 2 {
        return "NO"
    }

    for i in 2..<length {
        if length % i == 0 {
            return "NO"
        }
    }

    return "YES"
}
```
 // XCTAssertTrue failed

func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
    let start = max(interval1.0, interval2.0)
    let end = min(interval1.1, interval2.1)

    if start > end {
        return "NO"
    }

    let length = end - start + 1

    if length < 2 {
        return "NO"
    }

    for i in 2..<length {
        if length % i == 0 {
            return "NO"
        }
    }

    return "YES"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two 
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"[/INST]  ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
    let start = max(interval1.0, interval2.0)
    let end = min(interval1.1, interval2.1)

    if start > end {
        return "NO"
    }

    let length = end - start + 1

    if length < 2 {
        return "NO"
    }

    for i in 2..<length {
        if length % i == 0 {
            return "NO"
        }
    }

    return "YES"
}
```
 // XCTAssertTrue failed

func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
    let start = max(interval1.0, interval2.0)
    let end = min(interval1.1, interval2.1)

    if start > end {
        return "NO"
    }

    let length = end - start

    if length < 2 {
        return "NO"
    }

    for i in 2..<length {
        if length % i == 0 {
            return "NO"
        }
    }

    return "YES"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two 
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"[/INST]  ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
    let start = max(interval1.0, interval2.0)
    let end = min(interval1.1, interval2.1)

    if start > end {
        return "NO"
    }

    let length = end - start

    if length < 2 {
        return "NO"
    }

    for i in 2..<length {
        if length % i == 0 {
            return "NO"
        }
    }

    return "YES"
}
```

func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
    let start = max(interval1.0, interval2.0)
    let end = min(interval1.1, interval2.1)

    if start > end {
        return "NO"
    }

    let length = end - start + 1

    if length < 2 {
        return "NO"
    }

    for i in 2..<length {
        if length % i == 0 {
            return "NO"
        }
    }

    return "YES"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two 
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"[/INST]  ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
    let start = max(interval1.0, interval2.0)
    let end = min(interval1.1, interval2.1)

    if start > end {
        return "NO"
    }

    let length = end - start + 1

    if length < 2 {
        return "NO"
    }

    for i in 2..<length {
        if length % i == 0 {
            return "NO"
        }
    }

    return "YES"
}
```
 // XCTAssertTrue failed

func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
    let start = max(interval1.0, interval2.0)
    let end = min(interval1.1, interval2.1)

    if start > end {
        return "NO"
    }

    let length = end - start + 1

    if length < 2 {
        return "NO"
    }

    for i in 2..<length {
        if length % i == 0 {
            return "NO"
        }
    }

    return "YES"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two 
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"[/INST]  ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
    let start = max(interval1.0, interval2.0)
    let end = min(interval1.1, interval2.1)

    if start > end {
        return "NO"
    }

    let length = end - start + 1

    if length < 2 {
        return "NO"
    }

    for i in 2..<length {
        if length % i == 0 {
            return "NO"
        }
    }

    return "YES"
}
```
 // XCTAssertTrue failed

func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
    let start = max(interval1.0, interval2.0)
    let end = min(interval1.1, interval2.1)

    if start > end {
        return "NO"
    }

    let length = end - start + 1

    if length < 2 {
        return "NO"
    }

    for i in 2..<length {
        if length % i == 0 {
            return "NO"
        }
    }

    return "YES"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two 
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"[/INST]  ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
    let start = max(interval1.0, interval2.0)
    let end = min(interval1.1, interval2.1)

    if start > end {
        return "NO"
    }

    let length = end - start + 1

    if length < 2 {
        return "NO"
    }

    for i in 2..<length {
        if length % i == 0 {
            return "NO"
        }
    }

    return "YES"
}
```
 // XCTAssertTrue failed

func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
    let start = max(interval1.0, interval2.0)
    let end = min(interval1.1, interval2.1)

    if start > end {
        return "NO"
    }

    let length = end - start + 1

    if length < 2 {
        return "NO"
    }

    for i in 2..<length {
        if length % i == 0 {
            return "NO"
        }
    }

    return "YES"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two 
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"[/INST]  ```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
    let start = max(interval1.0, interval2.0)
    let end = min(interval1.1, interval2.1)

    if start > end {
        return "NO"
    }

    let length = end - start + 1

    if length < 2 {
        return "NO"
    }

    for i in 2..<length {
        if length % i == 0 {
            return "NO"
        }
    }

    return "YES"
}
```
 // XCTAssertTrue failed

func prodSigns(arr: [Int]) -> Int? {
    if arr.isEmpty {
        return nil
    }

    var product = 1
    var sum = 0

    for num in arr {
        if num > 0 {
            product *= 1
        } else if num < 0 {
            product *= -1
        }
        sum += abs(num)
    }

    return sum * product
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil[/INST]  ```swift
func prodSigns(arr: [Int]) -> Int? {
    if arr.isEmpty {
        return nil
    }

    var product = 1
    var sum = 0

    for num in arr {
        if num > 0 {
            product *= 1
        } else if num < 0 {
            product *= -1
        }
        sum += abs(num)
    }

    return sum * product
}
```
 // XCTAssertTrue failed

func prodSigns(arr: [Int]) -> Int? {
    if arr.isEmpty {
        return nil
    }

    var product = 1
    var sum = 0

    for num in arr {
        if num < 0 {
            product *= -1
        } else if num > 0 {
            product *= 1
        }
        sum += abs(num)
    }

    return sum * product
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil[/INST]  ```swift
func prodSigns(arr: [Int]) -> Int? {
    if arr.isEmpty {
        return nil
    }

    var product = 1
    var sum = 0

    for num in arr {
        if num < 0 {
            product *= -1
        } else if num > 0 {
            product *= 1
        }
        sum += abs(num)
    }

    return sum * product
}
```
 // XCTAssertTrue failed

func prodSigns(arr: [Int]) -> Int? {
    if arr.isEmpty {
        return nil
    }

    var product = 1
    var sum = 0

    for num in arr {
        if num > 0 {
            product *= 1
            sum += num
        } else if num < 0 {
            product *= -1
            sum += -num
        }
    }

    return sum * product
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil[/INST]  ```swift
func prodSigns(arr: [Int]) -> Int? {
    if arr.isEmpty {
        return nil
    }

    var product = 1
    var sum = 0

    for num in arr {
        if num > 0 {
            product *= 1
            sum += num
        } else if num < 0 {
            product *= -1
            sum += -num
        }
    }

    return sum * product
}
```
 // XCTAssertTrue failed

func prodSigns(arr: [Int]) -> Int? {
    if arr.isEmpty {
        return nil
    }

    var product = 1
    var sum = 0

    for num in arr {
        if num > 0 {
            product *= 1
        } else if num < 0 {
            product *= -1
        }

        sum += abs(num)
    }

    return product * sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil[/INST]  ```swift
func prodSigns(arr: [Int]) -> Int? {
    if arr.isEmpty {
        return nil
    }

    var product = 1
    var sum = 0

    for num in arr {
        if num > 0 {
            product *= 1
        } else if num < 0 {
            product *= -1
        }

        sum += abs(num)
    }

    return product * sum
}
```
 // XCTAssertTrue failed

func prodSigns(arr: [Int]) -> Int? {
    if arr.isEmpty {
        return nil
    }

    var product = 1
    var sum = 0

    for num in arr {
        if num > 0 {
            product *= 1
        } else if num < 0 {
            product *= -1
        }
        sum += abs(num)
    }

    return sum * product
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil[/INST]  ```swift
func prodSigns(arr: [Int]) -> Int? {
    if arr.isEmpty {
        return nil
    }

    var product = 1
    var sum = 0

    for num in arr {
        if num > 0 {
            product *= 1
        } else if num < 0 {
            product *= -1
        }
        sum += abs(num)
    }

    return sum * product
}
```
 // XCTAssertTrue failed

func prodSigns(arr: [Int]) -> Int? {
    if arr.isEmpty {
        return nil
    }

    var product = 1
    var sum = 0

    for num in arr {
        if num > 0 {
            product *= 1
        } else if num < 0 {
            product *= -1
        }
        sum += abs(num)
    }

    return sum * product
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil[/INST]  ```swift
func prodSigns(arr: [Int]) -> Int? {
    if arr.isEmpty {
        return nil
    }

    var product = 1
    var sum = 0

    for num in arr {
        if num > 0 {
            product *= 1
        } else if num < 0 {
            product *= -1
        }
        sum += abs(num)
    }

    return sum * product
}
```
 // XCTAssertTrue failed

func prodSigns(arr: [Int]) -> Int? {
    if arr.isEmpty {
        return nil
    }

    var product = 1
    var sum = 0

    for num in arr {
        if num < 0 {
            product *= -1
        } else if num > 0 {
            product *= 1
        }
        sum += abs(num)
    }

    return sum * product
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil[/INST]  ```swift
func prodSigns(arr: [Int]) -> Int? {
    if arr.isEmpty {
        return nil
    }

    var product = 1
    var sum = 0

    for num in arr {
        if num < 0 {
            product *= -1
        } else if num > 0 {
            product *= 1
        }
        sum += abs(num)
    }

    return sum * product
}
```
 // XCTAssertTrue failed

func prodSigns(arr: [Int]) -> Int? {
    if arr.isEmpty {
        return nil
    }

    var product = 1
    var sum = 0

    for num in arr {
        if num < 0 {
            product *= -1
        } else if num > 0 {
            product *= 1
        }
        sum += abs(num)
    }

    return sum * product
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil[/INST]  ```swift
func prodSigns(arr: [Int]) -> Int? {
    if arr.isEmpty {
        return nil
    }

    var product = 1
    var sum = 0

    for num in arr {
        if num < 0 {
            product *= -1
        } else if num > 0 {
            product *= 1
        }
        sum += abs(num)
    }

    return sum * product
}
```
 // XCTAssertTrue failed

func prodSigns(arr: [Int]) -> Int? {
    if arr.isEmpty {
        return nil
    }

    var product = 1
    var sum = 0

    for num in arr {
        if num > 0 {
            product *= 1
            sum += num
        } else if num < 0 {
            product *= -1
            sum += -num
        }
    }

    return product * sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil[/INST]  ```swift
func prodSigns(arr: [Int]) -> Int? {
    if arr.isEmpty {
        return nil
    }

    var product = 1
    var sum = 0

    for num in arr {
        if num > 0 {
            product *= 1
            sum += num
        } else if num < 0 {
            product *= -1
            sum += -num
        }
    }

    return product * sum
}
```
 // XCTAssertTrue failed

func prodSigns(arr: [Int]) -> Int? {
    if arr.isEmpty {
        return nil
    }

    var product = 1
    var sum = 0

    for num in arr {
        if num > 0 {
            product *= 1
        } else if num < 0 {
            product *= -1
        }
        sum += abs(num)
    }

    return product * sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil[/INST]  ```swift
func prodSigns(arr: [Int]) -> Int? {
    if arr.isEmpty {
        return nil
    }

    var product = 1
    var sum = 0

    for num in arr {
        if num > 0 {
            product *= 1
        } else if num < 0 {
            product *= -1
        }
        sum += abs(num)
    }

    return product * sum
}
```
 // XCTAssertTrue failed

func minPath(grid: [[Int]], k: Int) -> [Int] {
    let n = grid.count
    var visited = Array(repeating: Array(repeating: false, count: n), count: n)
    var path = [Int]()
    var minPath = Array(repeating: Int.max, count: k)

    func dfs(i: Int, j: Int, count: Int) {
        if count == k {
            if path < minPath {
                minPath = path
            }
            return
        }

        visited[i][j] = true
        path.append(grid[i][j])

        let directions = [(0, 1), (0, -1), (1, 0), (-1, 0)]
        for direction in directions {
            let newI = i + direction.0
            let newJ = j + direction.1

            if newI >= 0 && newI < n && newJ >= 0 && newJ < n && !visited[newI][newJ] {
                dfs(i: newI, j: newJ, count: count + 1)
            }
        }

        path.removeLast()
        visited[i][j] = false
    }

    for i in 0..<n {
        for j in 0..<n {
            dfs(i: i, j: j, count: 0)
        }
    }

    return minPath
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k, 
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:    
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1][/INST]  ```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
    let n = grid.count
    var visited = Array(repeating: Array(repeating: false, count: n), count: n)
    var path = [Int]()
    var minPath = Array(repeating: Int.max, count: k)

    func dfs(i: Int, j: Int, count: Int) {
        if count == k {
            if path < minPath {
                minPath = path
            }
            return
        }

        visited[i][j] = true
        path.append(grid[i][j])

        let directions = [(0, 1), (0, -1), (1, 0), (-1, 0)]
        for direction in directions {
            let newI = i + direction.0
            let newJ = j + direction.1

            if newI >= 0 && newI < n && newJ >= 0 && newJ < n && !visited[newI][newJ] {
                dfs(i: newI, j: newJ, count: count + 1)
            }
        }

        path.removeLast()
        visited[i][j] = false
    }

    for i in 0..<n {
        for j in 0..<n {
            dfs(i: i, j: j, count: 0)
        }
    }

    return minPath
}
```
if path < minPath { // binary operator '<' cannot be applied to two '[Int]' operands

func minPath(grid: [[Int]], k: Int) -> [Int] {
    let n = grid.count
    var path = [Int]()
    var visited = Array(repeating: Array(repeating: false, count: n), count: n)
    var minPath = Array(repeating: Int.max, count: k)

    func dfs(i: Int, j: Int, depth: Int) {
        if depth == k {
            if path < minPath {
                minPath = path
            }
            return
        }

        let directions = [(0, 1), (0, -1), (1, 0), (-1, 0)]
        for dir in directions {
            let newI = i + dir.0
            let newJ = j + dir.1

            if newI >= 0 && newI < n && newJ >= 0 && newJ < n && !visited[newI][newJ] {
                visited[newI][newJ] = true
                path.append(grid[newI][newJ])
                dfs(i: newI, j: newJ, depth: depth + 1)
                visited[newI][newJ] = false
                path.removeLast()
            }
        }
    }

    for i in 0..<n {
        for j in 0..<n {
            visited[i][j] = true
            path.append(grid[i][j])
            dfs(i: i, j: j, depth: 1)
            visited[i][j] = false
            path.removeLast()
        }
    }

    return minPath
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k, 
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:    
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1][/INST]  ```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
    let n = grid.count
    var path = [Int]()
    var visited = Array(repeating: Array(repeating: false, count: n), count: n)
    var minPath = Array(repeating: Int.max, count: k)

    func dfs(i: Int, j: Int, depth: Int) {
        if depth == k {
            if path < minPath {
                minPath = path
            }
            return
        }

        let directions = [(0, 1), (0, -1), (1, 0), (-1, 0)]
        for dir in directions {
            let newI = i + dir.0
            let newJ = j + dir.1

            if newI >= 0 && newI < n && newJ >= 0 && newJ < n && !visited[newI][newJ] {
                visited[newI][newJ] = true
                path.append(grid[newI][newJ])
                dfs(i: newI, j: newJ, depth: depth + 1)
                visited[newI][newJ] = false
                path.removeLast()
            }
        }
    }

    for i in 0..<n {
        for j in 0..<n {
            visited[i][j] = true
            path.append(grid[i][j])
            dfs(i: i, j: j, depth: 1)
            visited[i][j] = false
            path.removeLast()
        }
    }

    return minPath
}
```
if path < minPath { // binary operator '<' cannot be applied to two '[Int]' operands

func minPath(grid: [[Int]], k: Int) -> [Int] {
    let n = grid.count
    var visited = Array(repeating: Array(repeating: false, count: n), count: n)
    var path = [Int]()
    var minPath = Array(repeating: Int.max, count: k)

    func dfs(i: Int, j: Int, count: Int) {
        if count == k {
            if path < minPath {
                minPath = path
            }
            return
        }

        let directions = [(0, 1), (0, -1), (1, 0), (-1, 0)]
        for dir in directions {
            let newI = i + dir.0
            let newJ = j + dir.1

            if newI >= 0 && newI < n && newJ >= 0 && newJ < n && !visited[newI][newJ] {
                visited[newI][newJ] = true
                path.append(grid[newI][newJ])
                dfs(i: newI, j: newJ, count: count + 1)
                visited[newI][newJ] = false
                path.removeLast()
            }
        }
    }

    for i in 0..<n {
        for j in 0..<n {
            visited[i][j] = true
            path.append(grid[i][j])
            dfs(i: i, j: j, count: 1)
            visited[i][j] = false
            path.removeLast()
        }
    }

    return minPath
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k, 
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:    
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1][/INST]  ```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
    let n = grid.count
    var visited = Array(repeating: Array(repeating: false, count: n), count: n)
    var path = [Int]()
    var minPath = Array(repeating: Int.max, count: k)

    func dfs(i: Int, j: Int, count: Int) {
        if count == k {
            if path < minPath {
                minPath = path
            }
            return
        }

        let directions = [(0, 1), (0, -1), (1, 0), (-1, 0)]
        for dir in directions {
            let newI = i + dir.0
            let newJ = j + dir.1

            if newI >= 0 && newI < n && newJ >= 0 && newJ < n && !visited[newI][newJ] {
                visited[newI][newJ] = true
                path.append(grid[newI][newJ])
                dfs(i: newI, j: newJ, count: count + 1)
                visited[newI][newJ] = false
                path.removeLast()
            }
        }
    }

    for i in 0..<n {
        for j in 0..<n {
            visited[i][j] = true
            path.append(grid[i][j])
            dfs(i: i, j: j, count: 1)
            visited[i][j] = false
            path.removeLast()
        }
    }

    return minPath
}
```
if path < minPath { // binary operator '<' cannot be applied to two '[Int]' operands

func minPath(grid: [[Int]], k: Int) -> [Int] {
    let n = grid.count
    var path = [Int]()
    var visited = Array(repeating: Array(repeating: false, count: n), count: n)
    var minPath = Array(repeating: Int.max, count: k)

    func dfs(i: Int, j: Int, depth: Int, currentPath: [Int]) {
        if depth == k {
            if currentPath < minPath {
                minPath = currentPath
            }
            return
        }

        let directions = [(0, 1), (0, -1), (1, 0), (-1, 0)]
        for dir in directions {
            let newI = i + dir.0
            let newJ = j + dir.1

            if newI >= 0 && newI < n && newJ >= 0 && newJ < n && !visited[newI][newJ] {
                visited[newI][newJ] = true
                dfs(i: newI, j: newJ, depth: depth + 1, currentPath: currentPath + [grid[newI][newJ]])
                visited[newI][newJ] = false
            }
        }
    }

    for i in 0..<n {
        for j in 0..<n {
            visited[i][j] = true
            dfs(i: i, j: j, depth: 1, currentPath: [grid[i][j]])
            visited[i][j] = false
        }
    }

    return minPath
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k, 
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:    
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1][/INST]  ```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
    let n = grid.count
    var path = [Int]()
    var visited = Array(repeating: Array(repeating: false, count: n), count: n)
    var minPath = Array(repeating: Int.max, count: k)

    func dfs(i: Int, j: Int, depth: Int, currentPath: [Int]) {
        if depth == k {
            if currentPath < minPath {
                minPath = currentPath
            }
            return
        }

        let directions = [(0, 1), (0, -1), (1, 0), (-1, 0)]
        for dir in directions {
            let newI = i + dir.0
            let newJ = j + dir.1

            if newI >= 0 && newI < n && newJ >= 0 && newJ < n && !visited[newI][newJ] {
                visited[newI][newJ] = true
                dfs(i: newI, j: newJ, depth: depth + 1, currentPath: currentPath + [grid[newI][newJ]])
                visited[newI][newJ] = false
            }
        }
    }

    for i in 0..<n {
        for j in 0..<n {
            visited[i][j] = true
            dfs(i: i, j: j, depth: 1, currentPath: [grid[i][j]])
            visited[i][j] = false
        }
    }

    return minPath
}
```
if currentPath < minPath { // binary operator '<' cannot be applied to two '[Int]' operands

func minPath(grid: [[Int]], k: Int) -> [Int] {
    let n = grid.count
    var path = [Int]()
    var visited = Array(repeating: Array(repeating: false, count: n), count: n)
    var minPath = Array(repeating: Int.max, count: k)

    func dfs(i: Int, j: Int, count: Int, currentPath: [Int]) {
        if count == k {
            if currentPath < minPath {
                minPath = currentPath
            }
            return
        }

        let directions = [(0, 1), (0, -1), (1, 0), (-1, 0)]
        for dir in directions {
            let newI = i + dir.0
            let newJ = j + dir.1

            if newI >= 0 && newI < n && newJ >= 0 && newJ < n && !visited[newI][newJ] {
                visited[newI][newJ] = true
                dfs(i: newI, j: newJ, count: count + 1, currentPath: currentPath + [grid[newI][newJ]])
                visited[newI][newJ] = false
            }
        }
    }

    for i in 0..<n {
        for j in 0..<n {
            visited[i][j] = true
            dfs(i: i, j: j, count: 1, currentPath: [grid[i][j]])
            visited[i][j] = false
        }
    }

    return minPath
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k, 
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:    
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1][/INST]  ```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
    let n = grid.count
    var path = [Int]()
    var visited = Array(repeating: Array(repeating: false, count: n), count: n)
    var minPath = Array(repeating: Int.max, count: k)

    func dfs(i: Int, j: Int, count: Int, currentPath: [Int]) {
        if count == k {
            if currentPath < minPath {
                minPath = currentPath
            }
            return
        }

        let directions = [(0, 1), (0, -1), (1, 0), (-1, 0)]
        for dir in directions {
            let newI = i + dir.0
            let newJ = j + dir.1

            if newI >= 0 && newI < n && newJ >= 0 && newJ < n && !visited[newI][newJ] {
                visited[newI][newJ] = true
                dfs(i: newI, j: newJ, count: count + 1, currentPath: currentPath + [grid[newI][newJ]])
                visited[newI][newJ] = false
            }
        }
    }

    for i in 0..<n {
        for j in 0..<n {
            visited[i][j] = true
            dfs(i: i, j: j, count: 1, currentPath: [grid[i][j]])
            visited[i][j] = false
        }
    }

    return minPath
}
```
if currentPath < minPath { // binary operator '<' cannot be applied to two '[Int]' operands

func minPath(grid: [[Int]], k: Int) -> [Int] {
    let n = grid.count
    var path = [Int]()
    var visited = Array(repeating: Array(repeating: false, count: n), count: n)
    var minPath = Array(repeating: Int.max, count: k)

    func dfs(x: Int, y: Int, depth: Int) {
        if depth == k {
            if path < minPath {
                minPath = path
            }
            return
        }

        let directions = [(0, 1), (0, -1), (1, 0), (-1, 0)]
        for dir in directions {
            let newX = x + dir.0
            let newY = y + dir.1

            if newX >= 0 && newX < n && newY >= 0 && newY < n && !visited[newX][newY] {
                visited[newX][newY] = true
                path.append(grid[newX][newY])
                dfs(x: newX, y: newY, depth: depth + 1)
                path.removeLast()
                visited[newX][newY] = false
            }
        }
    }

    for i in 0..<n {
        for j in 0..<n {
            visited[i][j] = true
            path.append(grid[i][j])
            dfs(x: i, y: j, depth: 1)
            path.removeLast()
            visited[i][j] = false
        }
    }

    return minPath
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k, 
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:    
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1][/INST]  ```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
    let n = grid.count
    var path = [Int]()
    var visited = Array(repeating: Array(repeating: false, count: n), count: n)
    var minPath = Array(repeating: Int.max, count: k)

    func dfs(x: Int, y: Int, depth: Int) {
        if depth == k {
            if path < minPath {
                minPath = path
            }
            return
        }

        let directions = [(0, 1), (0, -1), (1, 0), (-1, 0)]
        for dir in directions {
            let newX = x + dir.0
            let newY = y + dir.1

            if newX >= 0 && newX < n && newY >= 0 && newY < n && !visited[newX][newY] {
                visited[newX][newY] = true
                path.append(grid[newX][newY])
                dfs(x: newX, y: newY, depth: depth + 1)
                path.removeLast()
                visited[newX][newY] = false
            }
        }
    }

    for i in 0..<n {
        for j in 0..<n {
            visited[i][j] = true
            path.append(grid[i][j])
            dfs(x: i, y: j, depth: 1)
            path.removeLast()
            visited[i][j] = false
        }
    }

    return minPath
}
```
if path < minPath { // binary operator '<' cannot be applied to two '[Int]' operands

func minPath(grid: [[Int]], k: Int) -> [Int] {
    let n = grid.count
    var path = [Int]()
    var visited = Array(repeating: Array(repeating: false, count: n), count: n)
    var minPath = Array(repeating: Int.max, count: k)

    func dfs(_ i: Int, _ j: Int, _ count: Int) {
        if count == k {
            if path < minPath {
                minPath = path
            }
            return
        }

        let directions = [(0, 1), (0, -1), (1, 0), (-1, 0)]
        for dir in directions {
            let newI = i + dir.0
            let newJ = j + dir.1
            if newI >= 0 && newI < n && newJ >= 0 && newJ < n && !visited[newI][newJ] {
                visited[newI][newJ] = true
                path.append(grid[newI][newJ])
                dfs(newI, newJ, count + 1)
                path.removeLast()
                visited[newI][newJ] = false
            }
        }
    }

    for i in 0..<n {
        for j in 0..<n {
            visited[i][j] = true
            path.append(grid[i][j])
            dfs(i, j, 1)
            path.removeLast()
            visited[i][j] = false
        }
    }

    return minPath
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k, 
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:    
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1][/INST]  ```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
    let n = grid.count
    var path = [Int]()
    var visited = Array(repeating: Array(repeating: false, count: n), count: n)
    var minPath = Array(repeating: Int.max, count: k)

    func dfs(_ i: Int, _ j: Int, _ count: Int) {
        if count == k {
            if path < minPath {
                minPath = path
            }
            return
        }

        let directions = [(0, 1), (0, -1), (1, 0), (-1, 0)]
        for dir in directions {
            let newI = i + dir.0
            let newJ = j + dir.1
            if newI >= 0 && newI < n && newJ >= 0 && newJ < n && !visited[newI][newJ] {
                visited[newI][newJ] = true
                path.append(grid[newI][newJ])
                dfs(newI, newJ, count + 1)
                path.removeLast()
                visited[newI][newJ] = false
            }
        }
    }

    for i in 0..<n {
        for j in 0..<n {
            visited[i][j] = true
            path.append(grid[i][j])
            dfs(i, j, 1)
            path.removeLast()
            visited[i][j] = false
        }
    }

    return minPath
}
```
if path < minPath { // binary operator '<' cannot be applied to two '[Int]' operands

func minPath(grid: [[Int]], k: Int) -> [Int] {
    let n = grid.count
    var path = [Int]()
    var visited = Array(repeating: Array(repeating: false, count: n), count: n)
    var minPath = Array(repeating: Int.max, count: k)

    func dfs(_ i: Int, _ j: Int, _ step: Int) {
        if step == k {
            if path < minPath {
                minPath = path
            }
            return
        }

        let directions = [(0, 1), (0, -1), (1, 0), (-1, 0)]
        for dir in directions {
            let newI = i + dir.0
            let newJ = j + dir.1
            if newI >= 0 && newI < n && newJ >= 0 && newJ < n && !visited[newI][newJ] {
                visited[newI][newJ] = true
                path.append(grid[newI][newJ])
                dfs(newI, newJ, step + 1)
                visited[newI][newJ] = false
                path.removeLast()
            }
        }
    }

    for i in 0..<n {
        for j in 0..<n {
            visited[i][j] = true
            path.append(grid[i][j])
            dfs(i, j, 1)
            visited[i][j] = false
            path.removeLast()
        }
    }

    return minPath
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k, 
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:    
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1][/INST]  ```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
    let n = grid.count
    var path = [Int]()
    var visited = Array(repeating: Array(repeating: false, count: n), count: n)
    var minPath = Array(repeating: Int.max, count: k)

    func dfs(_ i: Int, _ j: Int, _ step: Int) {
        if step == k {
            if path < minPath {
                minPath = path
            }
            return
        }

        let directions = [(0, 1), (0, -1), (1, 0), (-1, 0)]
        for dir in directions {
            let newI = i + dir.0
            let newJ = j + dir.1
            if newI >= 0 && newI < n && newJ >= 0 && newJ < n && !visited[newI][newJ] {
                visited[newI][newJ] = true
                path.append(grid[newI][newJ])
                dfs(newI, newJ, step + 1)
                visited[newI][newJ] = false
                path.removeLast()
            }
        }
    }

    for i in 0..<n {
        for j in 0..<n {
            visited[i][j] = true
            path.append(grid[i][j])
            dfs(i, j, 1)
            visited[i][j] = false
            path.removeLast()
        }
    }

    return minPath
}
```
if path < minPath { // binary operator '<' cannot be applied to two '[Int]' operands

func minPath(grid: [[Int]], k: Int) -> [Int] {
    let n = grid.count
    var path = [Int]()
    var visited = Array(repeating: Array(repeating: false, count: n), count: n)
    var minPath = Array(repeating: Int.max, count: k)

    func dfs(i: Int, j: Int, depth: Int) {
        if depth == k {
            if path < minPath {
                minPath = path
            }
            return
        }

        let directions = [(0, 1), (0, -1), (1, 0), (-1, 0)]
        for dir in directions {
            let newI = i + dir.0
            let newJ = j + dir.1
            if newI >= 0 && newI < n && newJ >= 0 && newJ < n && !visited[newI][newJ] {
                visited[newI][newJ] = true
                path.append(grid[newI][newJ])
                dfs(i: newI, j: newJ, depth: depth + 1)
                visited[newI][newJ] = false
                path.removeLast()
            }
        }
    }

    for i in 0..<n {
        for j in 0..<n {
            visited[i][j] = true
            path.append(grid[i][j])
            dfs(i: i, j: j, depth: 1)
            visited[i][j] = false
            path.removeLast()
        }
    }

    return minPath
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k, 
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:    
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1][/INST]  ```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
    let n = grid.count
    var path = [Int]()
    var visited = Array(repeating: Array(repeating: false, count: n), count: n)
    var minPath = Array(repeating: Int.max, count: k)

    func dfs(i: Int, j: Int, depth: Int) {
        if depth == k {
            if path < minPath {
                minPath = path
            }
            return
        }

        let directions = [(0, 1), (0, -1), (1, 0), (-1, 0)]
        for dir in directions {
            let newI = i + dir.0
            let newJ = j + dir.1
            if newI >= 0 && newI < n && newJ >= 0 && newJ < n && !visited[newI][newJ] {
                visited[newI][newJ] = true
                path.append(grid[newI][newJ])
                dfs(i: newI, j: newJ, depth: depth + 1)
                visited[newI][newJ] = false
                path.removeLast()
            }
        }
    }

    for i in 0..<n {
        for j in 0..<n {
            visited[i][j] = true
            path.append(grid[i][j])
            dfs(i: i, j: j, depth: 1)
            visited[i][j] = false
            path.removeLast()
        }
    }

    return minPath
}
```
if path < minPath { // binary operator '<' cannot be applied to two '[Int]' operands

func minPath(grid: [[Int]], k: Int) -> [Int] {
    let n = grid.count
    var minPath = Array(repeating: 0, count: k)
    var minValue = Int.max
    var startRow = 0
    var startCol = 0

    // Find the smallest value in the grid and its position
    for i in 0..<n {
        for j in 0..<n {
            if grid[i][j] < minValue {
                minValue = grid[i][j]
                startRow = i
                startCol = j
            }
        }
    }

    // Define the directions to move in the grid
    let directions = [(0, 1), (0, -1), (1, 0), (-1, 0)]

    // Perform a depth-first search to find the minimum path
    func dfs(row: Int, col: Int, path: [Int], length: Int) {
        if length == k {
            if path < minPath {
                minPath = path
            }
            return
        }

        for dir in directions {
            let newRow = row + dir.0
            let newCol = col + dir.1

            // Check if the new position is valid
            if newRow >= 0 && newRow < n && newCol >= 0 && newCol < n {
                dfs(row: newRow, col: newCol, path: path + [grid[newRow][newCol]], length: length + 1)
            }
        }
    }

    // Start the depth-first search from the position of the smallest value
    dfs(row: startRow, col: startCol, path: [minValue], length: 1)

    return minPath
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k, 
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:    
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1][/INST]  ```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
    let n = grid.count
    var minPath = Array(repeating: 0, count: k)
    var minValue = Int.max
    var startRow = 0
    var startCol = 0

    // Find the smallest value in the grid and its position
    for i in 0..<n {
        for j in 0..<n {
            if grid[i][j] < minValue {
                minValue = grid[i][j]
                startRow = i
                startCol = j
            }
        }
    }

    // Define the directions to move in the grid
    let directions = [(0, 1), (0, -1), (1, 0), (-1, 0)]

    // Perform a depth-first search to find the minimum path
    func dfs(row: Int, col: Int, path: [Int], length: Int) {
        if length == k {
            if path < minPath {
                minPath = path
            }
            return
        }

        for dir in directions {
            let newRow = row + dir.0
            let newCol = col + dir.1

            // Check if the new position is valid
            if newRow >= 0 && newRow < n && newCol >= 0 && newCol < n {
                dfs(row: newRow, col: newCol, path: path + [grid[newRow][newCol]], length: length + 1)
            }
        }
    }

    // Start the depth-first search from the position of the smallest value
    dfs(row: startRow, col: startCol, path: [minValue], length: 1)

    return minPath
}
```
if path < minPath { // binary operator '<' cannot be applied to two '[Int]' operands

func tri(n: Int) -> [Int] {
    var sequence = [1, 3]
    if n == 0 {
        return [1]
    } else if n == 1 {
        return sequence
    }

    for i in 2...n {
        if i % 2 == 0 {
            sequence.append(1 + i / 2)
        } else {
            sequence.append(sequence[i - 1] + sequence[i - 2] + sequence[i - 3])
        }
    }

    return sequence
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in 
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) =  tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8 
You are given a non-negative integer number n, you have to a return an array of the 
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8][/INST]  ```swift
func tri(n: Int) -> [Int] {
    var sequence = [1, 3]
    if n == 0 {
        return [1]
    } else if n == 1 {
        return sequence
    }

    for i in 2...n {
        if i % 2 == 0 {
            sequence.append(1 + i / 2)
        } else {
            sequence.append(sequence[i - 1] + sequence[i - 2] + sequence[i - 3])
        }
    }

    return sequence
}
```
 // XCTAssertTrue failed

func tri(n: Int) -> [Int] {
    var sequence = [1, 3]

    if n == 0 {
        return [1]
    } else if n == 1 {
        return sequence
    }

    for i in 2...n {
        if i % 2 == 0 {
            sequence.append(1 + i / 2)
        } else {
            sequence.append(sequence[i - 1] + sequence[i - 2] + sequence[(i + 1) % 3])
        }
    }

    return sequence
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in 
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) =  tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8 
You are given a non-negative integer number n, you have to a return an array of the 
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8][/INST]  ```swift
func tri(n: Int) -> [Int] {
    var sequence = [1, 3]

    if n == 0 {
        return [1]
    } else if n == 1 {
        return sequence
    }

    for i in 2...n {
        if i % 2 == 0 {
            sequence.append(1 + i / 2)
        } else {
            sequence.append(sequence[i - 1] + sequence[i - 2] + sequence[(i + 1) % 3])
        }
    }

    return sequence
}
```
 // XCTAssertTrue failed

func tri(n: Int) -> [Int] {
    var sequence = [1, 3]
    if n == 0 {
        return [1]
    } else if n == 1 {
        return sequence
    }
    for i in 2...n {
        if i % 2 == 0 {
            sequence.append(1 + i / 2)
        } else {
            sequence.append(sequence[i - 1] + sequence[i - 2] + sequence[i - 3])
        }
    }
    return sequence
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in 
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) =  tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8 
You are given a non-negative integer number n, you have to a return an array of the 
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8][/INST]  ```swift
func tri(n: Int) -> [Int] {
    var sequence = [1, 3]
    if n == 0 {
        return [1]
    } else if n == 1 {
        return sequence
    }
    for i in 2...n {
        if i % 2 == 0 {
            sequence.append(1 + i / 2)
        } else {
            sequence.append(sequence[i - 1] + sequence[i - 2] + sequence[i - 3])
        }
    }
    return sequence
}
```
 // XCTAssertTrue failed

func tri(n: Int) -> [Int] {
    var sequence = [1, 3]
    if n == 0 {
        return [1]
    } else if n == 1 {
        return sequence
    }

    for i in 2...n {
        if i % 2 == 0 {
            sequence.append(1 + i / 2)
        } else {
            sequence.append(sequence[i - 1] + sequence[i - 2] + (1 + (i + 1) / 2))
        }
    }

    return sequence
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in 
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) =  tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8 
You are given a non-negative integer number n, you have to a return an array of the 
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8][/INST]  ```swift
func tri(n: Int) -> [Int] {
    var sequence = [1, 3]
    if n == 0 {
        return [1]
    } else if n == 1 {
        return sequence
    }

    for i in 2...n {
        if i % 2 == 0 {
            sequence.append(1 + i / 2)
        } else {
            sequence.append(sequence[i - 1] + sequence[i - 2] + (1 + (i + 1) / 2))
        }
    }

    return sequence
}
```

func tri(n: Int) -> [Int] {
    var sequence = [Int](repeating: 0, count: n + 1)
    sequence[0] = 1
    if n >= 1 {
        sequence[1] = 3
    }
    if n >= 2 {
        sequence[2] = 2
    }
    for i in 3...n {
        if i % 2 == 0 {
            sequence[i] = 1 + i / 2
        } else {
            sequence[i] = sequence[i - 1] + sequence[i - 2] + sequence[i - 3]
        }
    }
    return sequence
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in 
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) =  tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8 
You are given a non-negative integer number n, you have to a return an array of the 
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8][/INST]  ```swift
func tri(n: Int) -> [Int] {
    var sequence = [Int](repeating: 0, count: n + 1)
    sequence[0] = 1
    if n >= 1 {
        sequence[1] = 3
    }
    if n >= 2 {
        sequence[2] = 2
    }
    for i in 3...n {
        if i % 2 == 0 {
            sequence[i] = 1 + i / 2
        } else {
            sequence[i] = sequence[i - 1] + sequence[i - 2] + sequence[i - 3]
        }
    }
    return sequence
}
```
 // XCTAssertTrue failed

func tri(n: Int) -> [Int] {
    var sequence = [1, 3]
    if n == 0 {
        return [1]
    } else if n == 1 {
        return sequence
    } else {
        for i in 2...n {
            if i % 2 == 0 {
                sequence.append(1 + i / 2)
            } else {
                sequence.append(sequence[i - 1] + sequence[i - 2] + sequence[i - 3])
            }
        }
        return sequence
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in 
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) =  tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8 
You are given a non-negative integer number n, you have to a return an array of the 
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8][/INST]  ```swift
func tri(n: Int) -> [Int] {
    var sequence = [1, 3]
    if n == 0 {
        return [1]
    } else if n == 1 {
        return sequence
    } else {
        for i in 2...n {
            if i % 2 == 0 {
                sequence.append(1 + i / 2)
            } else {
                sequence.append(sequence[i - 1] + sequence[i - 2] + sequence[i - 3])
            }
        }
        return sequence
    }
}
```
 // XCTAssertTrue failed

func tri(n: Int) -> [Int] {
    var sequence = [1, 3]
    if n == 0 {
        return [1]
    } else if n == 1 {
        return sequence
    }

    for i in 2...n {
        if i % 2 == 0 {
            sequence.append(1 + i / 2)
        } else {
            sequence.append(sequence[i - 1] + sequence[i - 2] + sequence[i - 3])
        }
    }

    return sequence
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in 
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) =  tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8 
You are given a non-negative integer number n, you have to a return an array of the 
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8][/INST]  ```swift
func tri(n: Int) -> [Int] {
    var sequence = [1, 3]
    if n == 0 {
        return [1]
    } else if n == 1 {
        return sequence
    }

    for i in 2...n {
        if i % 2 == 0 {
            sequence.append(1 + i / 2)
        } else {
            sequence.append(sequence[i - 1] + sequence[i - 2] + sequence[i - 3])
        }
    }

    return sequence
}
```
 // XCTAssertTrue failed

func tri(n: Int) -> [Int] {
    var sequence = [1, 3]
    if n == 0 {
        return [1]
    } else if n == 1 {
        return sequence
    }
    for i in 2...n {
        if i % 2 == 0 {
            sequence.append(1 + i / 2)
        } else {
            sequence.append(sequence[i - 1] + sequence[i - 2] + sequence[i - 3])
        }
    }
    return sequence
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in 
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) =  tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8 
You are given a non-negative integer number n, you have to a return an array of the 
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8][/INST]  ```swift
func tri(n: Int) -> [Int] {
    var sequence = [1, 3]
    if n == 0 {
        return [1]
    } else if n == 1 {
        return sequence
    }
    for i in 2...n {
        if i % 2 == 0 {
            sequence.append(1 + i / 2)
        } else {
            sequence.append(sequence[i - 1] + sequence[i - 2] + sequence[i - 3])
        }
    }
    return sequence
}
```
 // XCTAssertTrue failed

func tri(n: Int) -> [Int] {
    var sequence = [1, 3]

    if n == 0 {
        return [1]
    } else if n == 1 {
        return sequence
    }

    for i in 2...n {
        if i % 2 == 0 {
            sequence.append(1 + i / 2)
        } else {
            sequence.append(sequence[i - 1] + sequence[i - 2] + sequence[i - 3])
        }
    }

    return sequence
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in 
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) =  tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8 
You are given a non-negative integer number n, you have to a return an array of the 
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8][/INST]  ```swift
func tri(n: Int) -> [Int] {
    var sequence = [1, 3]

    if n == 0 {
        return [1]
    } else if n == 1 {
        return sequence
    }

    for i in 2...n {
        if i % 2 == 0 {
            sequence.append(1 + i / 2)
        } else {
            sequence.append(sequence[i - 1] + sequence[i - 2] + sequence[i - 3])
        }
    }

    return sequence
}
```
 // XCTAssertTrue failed

func tri(n: Int) -> [Int] {
    var sequence = [1, 3]
    if n == 0 {
        return [1]
    } else if n == 1 {
        return sequence
    } else {
        for i in 2...n {
            if i % 2 == 0 {
                sequence.append(1 + i / 2)
            } else {
                sequence.append(sequence[i - 1] + sequence[i - 2] + sequence[i - 3])
            }
        }
        return sequence
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in 
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) =  tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8 
You are given a non-negative integer number n, you have to a return an array of the 
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8][/INST]  ```swift
func tri(n: Int) -> [Int] {
    var sequence = [1, 3]
    if n == 0 {
        return [1]
    } else if n == 1 {
        return sequence
    } else {
        for i in 2...n {
            if i % 2 == 0 {
                sequence.append(1 + i / 2)
            } else {
                sequence.append(sequence[i - 1] + sequence[i - 2] + sequence[i - 3])
            }
        }
        return sequence
    }
}
```
 // XCTAssertTrue failed

func digits(n: Int) -> Int {
    var product = 1
    var hasOddDigit = false
    var number = n

    while number > 0 {
        let digit = number % 10
        if digit % 2 != 0 {
            product *= digit
            hasOddDigit = true
        }
        number /= 10
    }

    return hasOddDigit ? product : 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15[/INST]  ```swift
func digits(n: Int) -> Int {
    var product = 1
    var hasOddDigit = false
    var number = n

    while number > 0 {
        let digit = number % 10
        if digit % 2 != 0 {
            product *= digit
            hasOddDigit = true
        }
        number /= 10
    }

    return hasOddDigit ? product : 0
}
```

func digits(n: Int) -> Int {
    var product = 1
    var hasOddDigit = false
    var number = n

    while number > 0 {
        let digit = number % 10
        if digit % 2 != 0 {
            product *= digit
            hasOddDigit = true
        }
        number /= 10
    }

    return hasOddDigit ? product : 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15[/INST]  ```swift
func digits(n: Int) -> Int {
    var product = 1
    var hasOddDigit = false
    var number = n

    while number > 0 {
        let digit = number % 10
        if digit % 2 != 0 {
            product *= digit
            hasOddDigit = true
        }
        number /= 10
    }

    return hasOddDigit ? product : 0
}
```

func digits(n: Int) -> Int {
    var number = n
    var product = 1
    var hasOddDigit = false

    while number > 0 {
        let digit = number % 10
        if digit % 2 != 0 {
            product *= digit
            hasOddDigit = true
        }
        number /= 10
    }

    return hasOddDigit ? product : 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15[/INST]  ```swift
func digits(n: Int) -> Int {
    var number = n
    var product = 1
    var hasOddDigit = false

    while number > 0 {
        let digit = number % 10
        if digit % 2 != 0 {
            product *= digit
            hasOddDigit = true
        }
        number /= 10
    }

    return hasOddDigit ? product : 0
}
```

func digits(n: Int) -> Int {
    var product = 1
    var hasOddDigit = false
    var number = n

    while number > 0 {
        let digit = number % 10
        if digit % 2 != 0 {
            product *= digit
            hasOddDigit = true
        }
        number /= 10
    }

    return hasOddDigit ? product : 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15[/INST]  ```swift
func digits(n: Int) -> Int {
    var product = 1
    var hasOddDigit = false
    var number = n

    while number > 0 {
        let digit = number % 10
        if digit % 2 != 0 {
            product *= digit
            hasOddDigit = true
        }
        number /= 10
    }

    return hasOddDigit ? product : 0
}
```

func digits(n: Int) -> Int {
    var product = 1
    var isOddFound = false
    var number = n

    while number > 0 {
        let digit = number % 10
        if digit % 2 != 0 {
            product *= digit
            isOddFound = true
        }
        number /= 10
    }

    return isOddFound ? product : 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15[/INST]  ```swift
func digits(n: Int) -> Int {
    var product = 1
    var isOddFound = false
    var number = n

    while number > 0 {
        let digit = number % 10
        if digit % 2 != 0 {
            product *= digit
            isOddFound = true
        }
        number /= 10
    }

    return isOddFound ? product : 0
}
```

func digits(n: Int) -> Int {
    var product = 1
    var hasOddDigit = false
    var num = n

    while num > 0 {
        let digit = num % 10
        if digit % 2 != 0 {
            product *= digit
            hasOddDigit = true
        }
        num /= 10
    }

    return hasOddDigit ? product : 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15[/INST]  ```swift
func digits(n: Int) -> Int {
    var product = 1
    var hasOddDigit = false
    var num = n

    while num > 0 {
        let digit = num % 10
        if digit % 2 != 0 {
            product *= digit
            hasOddDigit = true
        }
        num /= 10
    }

    return hasOddDigit ? product : 0
}
```

func digits(n: Int) -> Int {
    var product = 1
    var hasOddDigit = false
    var num = n

    while num > 0 {
        let digit = num % 10
        if digit % 2 != 0 {
            product *= digit
            hasOddDigit = true
        }
        num /= 10
    }

    return hasOddDigit ? product : 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15[/INST]  ```swift
func digits(n: Int) -> Int {
    var product = 1
    var hasOddDigit = false
    var num = n

    while num > 0 {
        let digit = num % 10
        if digit % 2 != 0 {
            product *= digit
            hasOddDigit = true
        }
        num /= 10
    }

    return hasOddDigit ? product : 0
}
```

func digits(n: Int) -> Int {
    var product = 1
    var hasOddDigit = false
    var number = n

    while number > 0 {
        let digit = number % 10
        if digit % 2 != 0 {
            product *= digit
            hasOddDigit = true
        }
        number /= 10
    }

    return hasOddDigit ? product : 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15[/INST]  ```swift
func digits(n: Int) -> Int {
    var product = 1
    var hasOddDigit = false
    var number = n

    while number > 0 {
        let digit = number % 10
        if digit % 2 != 0 {
            product *= digit
            hasOddDigit = true
        }
        number /= 10
    }

    return hasOddDigit ? product : 0
}
```

func digits(n: Int) -> Int {
    var product = 1
    var hasOddDigit = false
    var num = n

    while num > 0 {
        let digit = num % 10
        if digit % 2 != 0 {
            product *= digit
            hasOddDigit = true
        }
        num /= 10
    }

    return hasOddDigit ? product : 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15[/INST]  ```swift
func digits(n: Int) -> Int {
    var product = 1
    var hasOddDigit = false
    var num = n

    while num > 0 {
        let digit = num % 10
        if digit % 2 != 0 {
            product *= digit
            hasOddDigit = true
        }
        num /= 10
    }

    return hasOddDigit ? product : 0
}
```

func digits(n: Int) -> Int {
    var number = n
    var product = 1
    var hasOddDigit = false

    while number > 0 {
        let digit = number % 10
        if digit % 2 != 0 {
            product *= digit
            hasOddDigit = true
        }
        number /= 10
    }

    return hasOddDigit ? product : 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15[/INST]  ```swift
func digits(n: Int) -> Int {
    var number = n
    var product = 1
    var hasOddDigit = false

    while number > 0 {
        let digit = number % 10
        if digit % 2 != 0 {
            product *= digit
            hasOddDigit = true
        }
        number /= 10
    }

    return hasOddDigit ? product : 0
}
```

func isNested(string: String) -> Bool {
    var stack = [Character]()

    for char in string {
        if char == "[" {
            stack.append(char)
        } else if char == "]" {
            if stack.isEmpty {
                return false
            } else if stack.last == "[" {
                stack.removeLast()
                if !stack.isEmpty {
                    return true
                }
            } else {
                return false
            }
        }
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets 
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true[/INST]  ```swift
func isNested(string: String) -> Bool {
    var stack = [Character]()

    for char in string {
        if char == "[" {
            stack.append(char)
        } else if char == "]" {
            if stack.isEmpty {
                return false
            } else if stack.last == "[" {
                stack.removeLast()
                if !stack.isEmpty {
                    return true
                }
            } else {
                return false
            }
        }
    }

    return false
}
```
 // XCTAssertTrue failed

func isNested(string: String) -> Bool {
    var stack = [Character]()

    for char in string {
        if char == "[" {
            stack.append(char)
        } else if char == "]" {
            if stack.isEmpty {
                return false
            } else if stack.last == "[" {
                stack.removeLast()
                if !stack.isEmpty {
                    return true
                }
            } else {
                return false
            }
        }
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets 
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true[/INST]  ```swift
func isNested(string: String) -> Bool {
    var stack = [Character]()

    for char in string {
        if char == "[" {
            stack.append(char)
        } else if char == "]" {
            if stack.isEmpty {
                return false
            } else if stack.last == "[" {
                stack.removeLast()
                if !stack.isEmpty {
                    return true
                }
            } else {
                return false
            }
        }
    }

    return false
}
```
 // XCTAssertTrue failed

func isNested(string: String) -> Bool {
    var stack = [Character]()

    for char in string {
        if char == "[" {
            stack.append(char)
        } else if char == "]" {
            if stack.isEmpty {
                return false
            } else if stack.last == "[" {
                stack.removeLast()
                if !stack.isEmpty {
                    return true
                }
            }
        }
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets 
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true[/INST]  ```swift
func isNested(string: String) -> Bool {
    var stack = [Character]()

    for char in string {
        if char == "[" {
            stack.append(char)
        } else if char == "]" {
            if stack.isEmpty {
                return false
            } else if stack.last == "[" {
                stack.removeLast()
                if !stack.isEmpty {
                    return true
                }
            }
        }
    }

    return false
}
```
 // XCTAssertTrue failed

func isNested(string: String) -> Bool {
    var openBrackets = 0
    var nestedBrackets = 0

    for char in string {
        if char == "[" {
            openBrackets += 1
        } else if char == "]" {
            if openBrackets > 0 {
                openBrackets -= 1
                nestedBrackets += 1
            } else {
                return false
            }
        }
    }

    return openBrackets == 0 && nestedBrackets > 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets 
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true[/INST]  ```swift
func isNested(string: String) -> Bool {
    var openBrackets = 0
    var nestedBrackets = 0

    for char in string {
        if char == "[" {
            openBrackets += 1
        } else if char == "]" {
            if openBrackets > 0 {
                openBrackets -= 1
                nestedBrackets += 1
            } else {
                return false
            }
        }
    }

    return openBrackets == 0 && nestedBrackets > 0
}
```
 // XCTAssertTrue failed

func isNested(string: String) -> Bool {
    var openBrackets = 0
    var nestedBrackets = 0

    for char in string {
        if char == "[" {
            openBrackets += 1
        } else if char == "]" {
            if openBrackets > 0 {
                openBrackets -= 1
                nestedBrackets += 1
            } else {
                return false
            }
        }
    }

    return openBrackets == 0 && nestedBrackets > 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets 
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true[/INST]  ```swift
func isNested(string: String) -> Bool {
    var openBrackets = 0
    var nestedBrackets = 0

    for char in string {
        if char == "[" {
            openBrackets += 1
        } else if char == "]" {
            if openBrackets > 0 {
                openBrackets -= 1
                nestedBrackets += 1
            } else {
                return false
            }
        }
    }

    return openBrackets == 0 && nestedBrackets > 0
}
```
 // XCTAssertTrue failed

func isNested(string: String) -> Bool {
    var stack = [Character]()

    for char in string {
        if char == "[" {
            stack.append(char)
        } else if char == "]" {
            if stack.isEmpty || stack.last != "[" {
                return false
            }
            stack.removeLast()
            if !stack.isEmpty && stack.last == "[" {
                return true
            }
        }
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets 
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true[/INST]  ```swift
func isNested(string: String) -> Bool {
    var stack = [Character]()

    for char in string {
        if char == "[" {
            stack.append(char)
        } else if char == "]" {
            if stack.isEmpty || stack.last != "[" {
                return false
            }
            stack.removeLast()
            if !stack.isEmpty && stack.last == "[" {
                return true
            }
        }
    }

    return false
}
```
 // XCTAssertTrue failed

func isNested(string: String) -> Bool {
    var stack = [Character]()

    for char in string {
        if char == "[" {
            stack.append(char)
        } else if char == "]" {
            if stack.isEmpty {
                return false
            } else if stack.last == "[" {
                stack.removeLast()
                if !stack.isEmpty {
                    return true
                }
            }
        }
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets 
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true[/INST]  ```swift
func isNested(string: String) -> Bool {
    var stack = [Character]()

    for char in string {
        if char == "[" {
            stack.append(char)
        } else if char == "]" {
            if stack.isEmpty {
                return false
            } else if stack.last == "[" {
                stack.removeLast()
                if !stack.isEmpty {
                    return true
                }
            }
        }
    }

    return false
}
```
 // XCTAssertTrue failed

func isNested(string: String) -> Bool {
    var stack = [Character]()

    for char in string {
        if char == "[" {
            stack.append(char)
        } else if char == "]" {
            if stack.isEmpty || stack.last != "[" {
                return false
            }
            stack.removeLast()
            if !stack.isEmpty && stack.last == "[" {
                return true
            }
        }
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets 
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true[/INST]  ```swift
func isNested(string: String) -> Bool {
    var stack = [Character]()

    for char in string {
        if char == "[" {
            stack.append(char)
        } else if char == "]" {
            if stack.isEmpty || stack.last != "[" {
                return false
            }
            stack.removeLast()
            if !stack.isEmpty && stack.last == "[" {
                return true
            }
        }
    }

    return false
}
```
 // XCTAssertTrue failed

func isNested(string: String) -> Bool {
    var stack = [Character]()

    for char in string {
        if char == "[" {
            stack.append(char)
        } else if char == "]" {
            if stack.isEmpty {
                return false
            } else if stack.last == "[" {
                stack.removeLast()
                if !stack.isEmpty {
                    return true
                }
            } else {
                return false
            }
        }
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets 
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true[/INST]  ```swift
func isNested(string: String) -> Bool {
    var stack = [Character]()

    for char in string {
        if char == "[" {
            stack.append(char)
        } else if char == "]" {
            if stack.isEmpty {
                return false
            } else if stack.last == "[" {
                stack.removeLast()
                if !stack.isEmpty {
                    return true
                }
            } else {
                return false
            }
        }
    }

    return false
}
```
 // XCTAssertTrue failed

func isNested(string: String) -> Bool {
    var openBrackets = 0
    var nestedBrackets = 0

    for char in string {
        if char == "[" {
            openBrackets += 1
        } else if char == "]" {
            if openBrackets > 0 {
                openBrackets -= 1
                nestedBrackets += 1
            } else {
                return false
            }
        }
    }

    return openBrackets == 0 && nestedBrackets > 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets 
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true[/INST]  ```swift
func isNested(string: String) -> Bool {
    var openBrackets = 0
    var nestedBrackets = 0

    for char in string {
        if char == "[" {
            openBrackets += 1
        } else if char == "]" {
            if openBrackets > 0 {
                openBrackets -= 1
                nestedBrackets += 1
            } else {
                return false
            }
        }
    }

    return openBrackets == 0 && nestedBrackets > 0
}
```
 // XCTAssertTrue failed

func sumSquares(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        let roundedNum = Int(ceil(num))
        sum += roundedNum * roundedNum
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6[/INST]  ```swift
func sumSquares(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        let roundedNum = Int(ceil(num))
        sum += roundedNum * roundedNum
    }
    return sum
}
```

func sumSquares(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        let ceilNum = Int(ceil(num))
        sum += ceilNum * ceilNum
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6[/INST]  ```swift
func sumSquares(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        let ceilNum = Int(ceil(num))
        sum += ceilNum * ceilNum
    }
    return sum
}
```

func sumSquares(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        let ceilNum = Int(ceil(num))
        sum += ceilNum * ceilNum
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6[/INST]  ```swift
func sumSquares(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        let ceilNum = Int(ceil(num))
        sum += ceilNum * ceilNum
    }
    return sum
}
```

func sumSquares(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        let ceilNum = Int(ceil(num))
        sum += ceilNum * ceilNum
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6[/INST]  ```swift
func sumSquares(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        let ceilNum = Int(ceil(num))
        sum += ceilNum * ceilNum
    }
    return sum
}
```

func sumSquares(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        let ceilNum = Int(ceil(num))
        sum += ceilNum * ceilNum
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6[/INST]  ```swift
func sumSquares(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        let ceilNum = Int(ceil(num))
        sum += ceilNum * ceilNum
    }
    return sum
}
```

func sumSquares(lst: [Double]) -> Int {
    return lst.map { Int(ceil($0)) }.reduce(0) { $0 + $1 * $1 }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6[/INST]  ```swift
func sumSquares(lst: [Double]) -> Int {
    return lst.map { Int(ceil($0)) }.reduce(0) { $0 + $1 * $1 }
}
```

func sumSquares(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        let ceilNum = Int(ceil(num))
        sum += ceilNum * ceilNum
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6[/INST]  ```swift
func sumSquares(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        let ceilNum = Int(ceil(num))
        sum += ceilNum * ceilNum
    }
    return sum
}
```

func sumSquares(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        let roundedNum = Int(ceil(num))
        sum += roundedNum * roundedNum
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6[/INST]  ```swift
func sumSquares(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        let roundedNum = Int(ceil(num))
        sum += roundedNum * roundedNum
    }
    return sum
}
```

func sumSquares(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        let roundedNum = Int(ceil(num))
        sum += roundedNum * roundedNum
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6[/INST]  ```swift
func sumSquares(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        let roundedNum = Int(ceil(num))
        sum += roundedNum * roundedNum
    }
    return sum
}
```

func sumSquares(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        let ceilNum = Int(ceil(num))
        sum += ceilNum * ceilNum
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6[/INST]  ```swift
func sumSquares(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        let ceilNum = Int(ceil(num))
        sum += ceilNum * ceilNum
    }
    return sum
}
```

func checkIfLastCharIsALetter(txt: String) -> Bool {
    guard let lastChar = txt.last else {
        return false
    }

    let lastCharString = String(lastChar)
    let lastCharIsLetter = lastCharString.rangeOfCharacter(from: .letters) != nil
    let lastCharIsNotPartOfWord = txt.split(separator: " ").last != lastCharString

    return lastCharIsLetter && lastCharIsNotPartOfWord
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false[/INST]  ```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
    guard let lastChar = txt.last else {
        return false
    }

    let lastCharString = String(lastChar)
    let lastCharIsLetter = lastCharString.rangeOfCharacter(from: .letters) != nil
    let lastCharIsNotPartOfWord = txt.split(separator: " ").last != lastCharString

    return lastCharIsLetter && lastCharIsNotPartOfWord
}
```
let lastCharIsNotPartOfWord = txt.split(separator: " ").last != lastCharString // value of optional type 'String.SubSequence?' (aka 'Optional<Substring>') must be unwrapped to a value of type 'String.SubSequence' (aka 'Substring')

func checkIfLastCharIsALetter(txt: String) -> Bool {
    guard let lastChar = txt.last else {
        return false
    }
    let lastCharString = String(lastChar)
    let lastCharIsLetter = lastCharString.range(of: "\\p{L}", options: .regularExpression) != nil
    let lastCharIsNotPartOfWord = txt.split(separator: " ").last != lastCharString
    return lastCharIsLetter && lastCharIsNotPartOfWord
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false[/INST]  ```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
    guard let lastChar = txt.last else {
        return false
    }
    let lastCharString = String(lastChar)
    let lastCharIsLetter = lastCharString.range(of: "\\p{L}", options: .regularExpression) != nil
    let lastCharIsNotPartOfWord = txt.split(separator: " ").last != lastCharString
    return lastCharIsLetter && lastCharIsNotPartOfWord
}
```
let lastCharIsNotPartOfWord = txt.split(separator: " ").last != lastCharString // value of optional type 'String.SubSequence?' (aka 'Optional<Substring>') must be unwrapped to a value of type 'String.SubSequence' (aka 'Substring')

func checkIfLastCharIsALetter(txt: String) -> Bool {
    guard let lastChar = txt.last else {
        return false
    }
    let lastCharString = String(lastChar)
    let lastCharIsLetter = lastCharString.range(of: "\\p{L}", options: .regularExpression) != nil
    let lastCharIsNotPartOfWord = txt.split(separator: " ").last != lastCharString
    return lastCharIsLetter && lastCharIsNotPartOfWord
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false[/INST]  ```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
    guard let lastChar = txt.last else {
        return false
    }
    let lastCharString = String(lastChar)
    let lastCharIsLetter = lastCharString.range(of: "\\p{L}", options: .regularExpression) != nil
    let lastCharIsNotPartOfWord = txt.split(separator: " ").last != lastCharString
    return lastCharIsLetter && lastCharIsNotPartOfWord
}
```
let lastCharIsNotPartOfWord = txt.split(separator: " ").last != lastCharString // value of optional type 'String.SubSequence?' (aka 'Optional<Substring>') must be unwrapped to a value of type 'String.SubSequence' (aka 'Substring')

func checkIfLastCharIsALetter(txt: String) -> Bool {
    guard let lastChar = txt.last else {
        return false
    }

    if lastChar.isLetter && txt.hasSuffix(" \(lastChar)") == false {
        return true
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false[/INST]  ```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
    guard let lastChar = txt.last else {
        return false
    }

    if lastChar.isLetter && txt.hasSuffix(" \(lastChar)") == false {
        return true
    }

    return false
}
```
 // XCTAssertTrue failed

func checkIfLastCharIsALetter(txt: String) -> Bool {
    guard let lastChar = txt.last else {
        return false
    }
    let lastCharString = String(lastChar)
    return lastCharString.rangeOfCharacter(from: CharacterSet.letters) != nil && txt.lastIndex(of: " ") != txt.index(before: txt.endIndex)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false[/INST]  ```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
    guard let lastChar = txt.last else {
        return false
    }
    let lastCharString = String(lastChar)
    return lastCharString.rangeOfCharacter(from: CharacterSet.letters) != nil && txt.lastIndex(of: " ") != txt.index(before: txt.endIndex)
}
```
 // XCTAssertTrue failed

func checkIfLastCharIsALetter(txt: String) -> Bool {
    guard let lastChar = txt.last else {
        return false
    }

    if lastChar.isLetter {
        if txt.count > 1 && txt[txt.index(before: txt.endIndex)] == " " {
            return false
        }
        return true
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false[/INST]  ```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
    guard let lastChar = txt.last else {
        return false
    }

    if lastChar.isLetter {
        if txt.count > 1 && txt[txt.index(before: txt.endIndex)] == " " {
            return false
        }
        return true
    }
    return false
}
```
 // XCTAssertTrue failed

func checkIfLastCharIsALetter(txt: String) -> Bool {
    guard let lastChar = txt.last else {
        return false
    }

    let isLetter = lastChar.isLetter
    let isSpaceOrEmpty = txt.isEmpty || txt.last == " "

    return isLetter && isSpaceOrEmpty
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false[/INST]  ```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
    guard let lastChar = txt.last else {
        return false
    }

    let isLetter = lastChar.isLetter
    let isSpaceOrEmpty = txt.isEmpty || txt.last == " "

    return isLetter && isSpaceOrEmpty
}
```
 // XCTAssertTrue failed

func checkIfLastCharIsALetter(txt: String) -> Bool {
    guard let lastChar = txt.last else {
        return false
    }

    let lastCharString = String(lastChar)
    let lastCharIsLetter = lastCharString.range(of: "\\p{L}", options: .regularExpression) != nil
    let lastCharIsNotPartOfWord = txt.hasSuffix(" \(lastCharString)") == false

    return lastCharIsLetter && lastCharIsNotPartOfWord
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false[/INST]  ```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
    guard let lastChar = txt.last else {
        return false
    }

    let lastCharString = String(lastChar)
    let lastCharIsLetter = lastCharString.range(of: "\\p{L}", options: .regularExpression) != nil
    let lastCharIsNotPartOfWord = txt.hasSuffix(" \(lastCharString)") == false

    return lastCharIsLetter && lastCharIsNotPartOfWord
}
```
 // XCTAssertTrue failed

func checkIfLastCharIsALetter(txt: String) -> Bool {
    guard let lastChar = txt.last else {
        return false
    }

    if lastChar.isLetter && txt.hasSuffix(" \(lastChar)") == false {
        return true
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false[/INST]  ```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
    guard let lastChar = txt.last else {
        return false
    }

    if lastChar.isLetter && txt.hasSuffix(" \(lastChar)") == false {
        return true
    }

    return false
}
```
 // XCTAssertTrue failed

func checkIfLastCharIsALetter(txt: String) -> Bool {
    guard let lastChar = txt.last else {
        return false
    }

    if lastChar.isLetter && txt.hasSuffix(" \(lastChar)") == false {
        return true
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false[/INST]  ```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
    guard let lastChar = txt.last else {
        return false
    }

    if lastChar.isLetter && txt.hasSuffix(" \(lastChar)") == false {
        return true
    }

    return false
}
```
 // XCTAssertTrue failed

func canArrange(arr: [Int]) -> Int {
    for i in stride(from: arr.count - 1, through: 1, by: -1) {
        if arr[i] < arr[i - 1] {
            return i
        }
    }
    return -1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1[/INST]  ```swift
func canArrange(arr: [Int]) -> Int {
    for i in stride(from: arr.count - 1, through: 1, by: -1) {
        if arr[i] < arr[i - 1] {
            return i
        }
    }
    return -1
}
```

func canArrange(arr: [Int]) -> Int {
    for i in (1..<arr.count).reversed() {
        if arr[i] < arr[i - 1] {
            return i
        }
    }
    return -1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1[/INST]  ```swift
func canArrange(arr: [Int]) -> Int {
    for i in (1..<arr.count).reversed() {
        if arr[i] < arr[i - 1] {
            return i
        }
    }
    return -1
}
```
 // Fatal error: Range requires lowerBound <= upperBound

func canArrange(arr: [Int]) -> Int {
    for i in stride(from: arr.count - 1, through: 1, by: -1) {
        if arr[i] < arr[i - 1] {
            return i
        }
    }
    return -1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1[/INST]  ```swift
func canArrange(arr: [Int]) -> Int {
    for i in stride(from: arr.count - 1, through: 1, by: -1) {
        if arr[i] < arr[i - 1] {
            return i
        }
    }
    return -1
}
```

func canArrange(arr: [Int]) -> Int {
    for i in stride(from: arr.count - 1, through: 1, by: -1) {
        if arr[i] < arr[i - 1] {
            return i
        }
    }
    return -1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1[/INST]  ```swift
func canArrange(arr: [Int]) -> Int {
    for i in stride(from: arr.count - 1, through: 1, by: -1) {
        if arr[i] < arr[i - 1] {
            return i
        }
    }
    return -1
}
```

func canArrange(arr: [Int]) -> Int {
    for i in (1..<arr.count).reversed() {
        if arr[i] < arr[i - 1] {
            return i
        }
    }
    return -1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1[/INST]  ```swift
func canArrange(arr: [Int]) -> Int {
    for i in (1..<arr.count).reversed() {
        if arr[i] < arr[i - 1] {
            return i
        }
    }
    return -1
}
```
 // Fatal error: Range requires lowerBound <= upperBound

func canArrange(arr: [Int]) -> Int {
    for i in (1..<arr.count).reversed() {
        if arr[i] < arr[i - 1] {
            return i
        }
    }
    return -1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1[/INST]  ```swift
func canArrange(arr: [Int]) -> Int {
    for i in (1..<arr.count).reversed() {
        if arr[i] < arr[i - 1] {
            return i
        }
    }
    return -1
}
```
 // Fatal error: Range requires lowerBound <= upperBound

func canArrange(arr: [Int]) -> Int {
    for i in stride(from: arr.count - 1, through: 1, by: -1) {
        if arr[i] < arr[i - 1] {
            return i
        }
    }
    return -1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1[/INST]  ```swift
func canArrange(arr: [Int]) -> Int {
    for i in stride(from: arr.count - 1, through: 1, by: -1) {
        if arr[i] < arr[i - 1] {
            return i
        }
    }
    return -1
}
```

func canArrange(arr: [Int]) -> Int {
    for i in stride(from: arr.count - 1, through: 1, by: -1) {
        if arr[i] < arr[i - 1] {
            return i
        }
    }
    return -1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1[/INST]  ```swift
func canArrange(arr: [Int]) -> Int {
    for i in stride(from: arr.count - 1, through: 1, by: -1) {
        if arr[i] < arr[i - 1] {
            return i
        }
    }
    return -1
}
```

func canArrange(arr: [Int]) -> Int {
    for i in stride(from: arr.count - 1, through: 1, by: -1) {
        if arr[i] < arr[i - 1] {
            return i
        }
    }
    return -1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1[/INST]  ```swift
func canArrange(arr: [Int]) -> Int {
    for i in stride(from: arr.count - 1, through: 1, by: -1) {
        if arr[i] < arr[i - 1] {
            return i
        }
    }
    return -1
}
```

func canArrange(arr: [Int]) -> Int {
    for i in stride(from: arr.count - 1, through: 1, by: -1) {
        if arr[i] < arr[i - 1] {
            return i
        }
    }
    return -1
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1[/INST]  ```swift
func canArrange(arr: [Int]) -> Int {
    for i in stride(from: arr.count - 1, through: 1, by: -1) {
        if arr[i] < arr[i - 1] {
            return i
        }
    }
    return -1
}
```

func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
    var largestNegative: Int? = nil
    var smallestPositive: Int? = nil

    for num in lst {
        if num < 0 {
            if largestNegative == nil || num > largestNegative! {
                largestNegative = num
            }
        } else if num > 0 {
            if smallestPositive == nil || num < smallestPositive! {
                smallestPositive = num
            }
        }
    }

    return (largestNegative, smallestPositive)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)[/INST]  ```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
    var largestNegative: Int? = nil
    var smallestPositive: Int? = nil

    for num in lst {
        if num < 0 {
            if largestNegative == nil || num > largestNegative! {
                largestNegative = num
            }
        } else if num > 0 {
            if smallestPositive == nil || num < smallestPositive! {
                smallestPositive = num
            }
        }
    }

    return (largestNegative, smallestPositive)
}
```

func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
    var largestNegative: Int? = nil
    var smallestPositive: Int? = nil

    for num in lst {
        if num < 0 {
            if let largest = largestNegative {
                largestNegative = max(largest, num)
            } else {
                largestNegative = num
            }
        } else if num > 0 {
            if let smallest = smallestPositive {
                smallestPositive = min(smallest, num)
            } else {
                smallestPositive = num
            }
        }
    }

    return (largestNegative, smallestPositive)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)[/INST]  ```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
    var largestNegative: Int? = nil
    var smallestPositive: Int? = nil

    for num in lst {
        if num < 0 {
            if let largest = largestNegative {
                largestNegative = max(largest, num)
            } else {
                largestNegative = num
            }
        } else if num > 0 {
            if let smallest = smallestPositive {
                smallestPositive = min(smallest, num)
            } else {
                smallestPositive = num
            }
        }
    }

    return (largestNegative, smallestPositive)
}
```

func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
    var largestNegative: Int? = nil
    var smallestPositive: Int? = nil

    for num in lst {
        if num < 0 {
            if let currentLargest = largestNegative {
                largestNegative = max(currentLargest, num)
            } else {
                largestNegative = num
            }
        } else if num > 0 {
            if let currentSmallest = smallestPositive {
                smallestPositive = min(currentSmallest, num)
            } else {
                smallestPositive = num
            }
        }
    }

    return (largestNegative, smallestPositive)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)[/INST]  ```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
    var largestNegative: Int? = nil
    var smallestPositive: Int? = nil

    for num in lst {
        if num < 0 {
            if let currentLargest = largestNegative {
                largestNegative = max(currentLargest, num)
            } else {
                largestNegative = num
            }
        } else if num > 0 {
            if let currentSmallest = smallestPositive {
                smallestPositive = min(currentSmallest, num)
            } else {
                smallestPositive = num
            }
        }
    }

    return (largestNegative, smallestPositive)
}
```

func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
    var largestNegative: Int? = nil
    var smallestPositive: Int? = nil

    for num in lst {
        if num < 0 {
            if let currentLargest = largestNegative {
                if num > currentLargest {
                    largestNegative = num
                }
            } else {
                largestNegative = num
            }
        } else if num > 0 {
            if let currentSmallest = smallestPositive {
                if num < currentSmallest {
                    smallestPositive = num
                }
            } else {
                smallestPositive = num
            }
        }
    }

    return (largestNegative, smallestPositive)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)[/INST]  ```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
    var largestNegative: Int? = nil
    var smallestPositive: Int? = nil

    for num in lst {
        if num < 0 {
            if let currentLargest = largestNegative {
                if num > currentLargest {
                    largestNegative = num
                }
            } else {
                largestNegative = num
            }
        } else if num > 0 {
            if let currentSmallest = smallestPositive {
                if num < currentSmallest {
                    smallestPositive = num
                }
            } else {
                smallestPositive = num
            }
        }
    }

    return (largestNegative, smallestPositive)
}
```

func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
    var largestNegative: Int? = nil
    var smallestPositive: Int? = nil

    for num in lst {
        if num < 0 {
            if largestNegative == nil || num > largestNegative! {
                largestNegative = num
            }
        } else if num > 0 {
            if smallestPositive == nil || num < smallestPositive! {
                smallestPositive = num
            }
        }
    }

    return (largestNegative, smallestPositive)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)[/INST]  ```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
    var largestNegative: Int? = nil
    var smallestPositive: Int? = nil

    for num in lst {
        if num < 0 {
            if largestNegative == nil || num > largestNegative! {
                largestNegative = num
            }
        } else if num > 0 {
            if smallestPositive == nil || num < smallestPositive! {
                smallestPositive = num
            }
        }
    }

    return (largestNegative, smallestPositive)
}
```

func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
    var largestNegative: Int? = nil
    var smallestPositive: Int? = nil

    for num in lst {
        if num < 0 {
            if let largest = largestNegative {
                largestNegative = max(largest, num)
            } else {
                largestNegative = num
            }
        } else if num > 0 {
            if let smallest = smallestPositive {
                smallestPositive = min(smallest, num)
            } else {
                smallestPositive = num
            }
        }
    }

    return (largestNegative, smallestPositive)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)[/INST]  ```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
    var largestNegative: Int? = nil
    var smallestPositive: Int? = nil

    for num in lst {
        if num < 0 {
            if let largest = largestNegative {
                largestNegative = max(largest, num)
            } else {
                largestNegative = num
            }
        } else if num > 0 {
            if let smallest = smallestPositive {
                smallestPositive = min(smallest, num)
            } else {
                smallestPositive = num
            }
        }
    }

    return (largestNegative, smallestPositive)
}
```

func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
    var largestNegative: Int? = nil
    var smallestPositive: Int? = nil

    for num in lst {
        if num < 0 {
            if let currentLargest = largestNegative {
                if num > currentLargest {
                    largestNegative = num
                }
            } else {
                largestNegative = num
            }
        } else if num > 0 {
            if let currentSmallest = smallestPositive {
                if num < currentSmallest {
                    smallestPositive = num
                }
            } else {
                smallestPositive = num
            }
        }
    }

    return (largestNegative, smallestPositive)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)[/INST]  ```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
    var largestNegative: Int? = nil
    var smallestPositive: Int? = nil

    for num in lst {
        if num < 0 {
            if let currentLargest = largestNegative {
                if num > currentLargest {
                    largestNegative = num
                }
            } else {
                largestNegative = num
            }
        } else if num > 0 {
            if let currentSmallest = smallestPositive {
                if num < currentSmallest {
                    smallestPositive = num
                }
            } else {
                smallestPositive = num
            }
        }
    }

    return (largestNegative, smallestPositive)
}
```

func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
    var largestNegative: Int? = nil
    var smallestPositive: Int? = nil

    for num in lst {
        if num < 0 {
            if largestNegative == nil || num > largestNegative! {
                largestNegative = num
            }
        } else if num > 0 {
            if smallestPositive == nil || num < smallestPositive! {
                smallestPositive = num
            }
        }
    }

    return (largestNegative, smallestPositive)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)[/INST]  ```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
    var largestNegative: Int? = nil
    var smallestPositive: Int? = nil

    for num in lst {
        if num < 0 {
            if largestNegative == nil || num > largestNegative! {
                largestNegative = num
            }
        } else if num > 0 {
            if smallestPositive == nil || num < smallestPositive! {
                smallestPositive = num
            }
        }
    }

    return (largestNegative, smallestPositive)
}
```

func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
    var largestNegative: Int? = nil
    var smallestPositive: Int? = nil

    for num in lst {
        if num < 0 {
            if largestNegative == nil || num > largestNegative! {
                largestNegative = num
            }
        } else if num > 0 {
            if smallestPositive == nil || num < smallestPositive! {
                smallestPositive = num
            }
        }
    }

    return (largestNegative, smallestPositive)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)[/INST]  ```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
    var largestNegative: Int? = nil
    var smallestPositive: Int? = nil

    for num in lst {
        if num < 0 {
            if largestNegative == nil || num > largestNegative! {
                largestNegative = num
            }
        } else if num > 0 {
            if smallestPositive == nil || num < smallestPositive! {
                smallestPositive = num
            }
        }
    }

    return (largestNegative, smallestPositive)
}
```

func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
    var largestNegative: Int? = nil
    var smallestPositive: Int? = nil

    for num in lst {
        if num < 0 {
            if let currentLargest = largestNegative {
                if num > currentLargest {
                    largestNegative = num
                }
            } else {
                largestNegative = num
            }
        } else if num > 0 {
            if let currentSmallest = smallestPositive {
                if num < currentSmallest {
                    smallestPositive = num
                }
            } else {
                smallestPositive = num
            }
        }
    }

    return (largestNegative, smallestPositive)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)[/INST]  ```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
    var largestNegative: Int? = nil
    var smallestPositive: Int? = nil

    for num in lst {
        if num < 0 {
            if let currentLargest = largestNegative {
                if num > currentLargest {
                    largestNegative = num
                }
            } else {
                largestNegative = num
            }
        } else if num > 0 {
            if let currentSmallest = smallestPositive {
                if num < currentSmallest {
                    smallestPositive = num
                }
            } else {
                smallestPositive = num
            }
        }
    }

    return (largestNegative, smallestPositive)
}
```

enum Value: Equatable, Hashable {
    case intValue(Int)
    case doubleValue(Double)
    case stringValue(String)
}

func compareOne(a: Value, b: Value) -> Value? {
    switch (a, b) {
    case (.intValue(let aInt), .intValue(let bInt)):
        return aInt > bInt ? .intValue(aInt) : aInt < bInt ? .intValue(bInt) : nil
    case (.doubleValue(let aDouble), .doubleValue(let bDouble)):
        return aDouble > bDouble ? .doubleValue(aDouble) : aDouble < bDouble ? .doubleValue(bDouble) : nil
    case (.stringValue(let aString), .stringValue(let bString)):
        let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aDouble > bDouble ? .stringValue(aString) : aDouble < bDouble ? .stringValue(bString) : nil
    case (.intValue(let aInt), .doubleValue(let bDouble)):
        return Double(aInt) > bDouble ? .intValue(aInt) : Double(aInt) < bDouble ? .doubleValue(bDouble) : nil
    case (.intValue(let aInt), .stringValue(let bString)):
        let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return Double(aInt) > bDouble ? .intValue(aInt) : Double(aInt) < bDouble ? .stringValue(bString) : nil
    case (.doubleValue(let aDouble), .stringValue(let bString)):
        let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aDouble > bDouble ? .doubleValue(aDouble) : aDouble < bDouble ? .stringValue(bString) : nil
    default:
        return nil
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be . or ,
compareOne(a: .intValue(1), b: .doubleValue(2.5)) == .doubleValue(2.5)
compareOne(a: .intValue(1), b: .stringValue("2,3")) == .stringValue("2,3")
compareOne(a: .stringValue("5,1"), b: .stringValue("6")) == .stringValue("6")
compareOne(a: .stringValue("1"), b: .intValue(1)) == nil[/INST]  ```swift
enum Value: Equatable, Hashable {
    case intValue(Int)
    case doubleValue(Double)
    case stringValue(String)
}

func compareOne(a: Value, b: Value) -> Value? {
    switch (a, b) {
    case (.intValue(let aInt), .intValue(let bInt)):
        return aInt > bInt ? .intValue(aInt) : aInt < bInt ? .intValue(bInt) : nil
    case (.doubleValue(let aDouble), .doubleValue(let bDouble)):
        return aDouble > bDouble ? .doubleValue(aDouble) : aDouble < bDouble ? .doubleValue(bDouble) : nil
    case (.stringValue(let aString), .stringValue(let bString)):
        let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aDouble > bDouble ? .stringValue(aString) : aDouble < bDouble ? .stringValue(bString) : nil
    case (.intValue(let aInt), .doubleValue(let bDouble)):
        return Double(aInt) > bDouble ? .intValue(aInt) : Double(aInt) < bDouble ? .doubleValue(bDouble) : nil
    case (.intValue(let aInt), .stringValue(let bString)):
        let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return Double(aInt) > bDouble ? .intValue(aInt) : Double(aInt) < bDouble ? .stringValue(bString) : nil
    case (.doubleValue(let aDouble), .stringValue(let bString)):
        let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aDouble > bDouble ? .doubleValue(aDouble) : aDouble < bDouble ? .stringValue(bString) : nil
    default:
        return nil
    }
}
```

enum Value: Equatable, Hashable {
    case intValue(Int)
    case doubleValue(Double)
    case stringValue(String)
}

func compareOne(a: Value, b: Value) -> Value? {
    switch (a, b) {
    case let (.intValue(aInt), .intValue(bInt)):
        return aInt > bInt ? .intValue(aInt) : aInt < bInt ? .intValue(bInt) : nil
    case let (.doubleValue(aDouble), .doubleValue(bDouble)):
        return aDouble > bDouble ? .doubleValue(aDouble) : aDouble < bDouble ? .doubleValue(bDouble) : nil
    case let (.stringValue(aString), .stringValue(bString)):
        let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aDouble > bDouble ? .stringValue(aString) : aDouble < bDouble ? .stringValue(bString) : nil
    case let (.intValue(intValue), .doubleValue(doubleValue)):
        return Double(intValue) > doubleValue ? .intValue(intValue) : Double(intValue) < doubleValue ? .doubleValue(doubleValue) : nil
    case let (.intValue(intValue), .stringValue(stringValue)):
        let doubleValue = Double(stringValue.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return Double(intValue) > doubleValue ? .intValue(intValue) : Double(intValue) < doubleValue ? .stringValue(stringValue) : nil
    case let (.doubleValue(doubleValue), .stringValue(stringValue)):
        let intValue = Int(doubleValue)
        let stringDoubleValue = Double(stringValue.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return doubleValue > stringDoubleValue ? .doubleValue(doubleValue) : doubleValue < stringDoubleValue ? .stringValue(stringValue) : nil
    default:
        return nil
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be . or ,
compareOne(a: .intValue(1), b: .doubleValue(2.5)) == .doubleValue(2.5)
compareOne(a: .intValue(1), b: .stringValue("2,3")) == .stringValue("2,3")
compareOne(a: .stringValue("5,1"), b: .stringValue("6")) == .stringValue("6")
compareOne(a: .stringValue("1"), b: .intValue(1)) == nil[/INST]  ```swift
enum Value: Equatable, Hashable {
    case intValue(Int)
    case doubleValue(Double)
    case stringValue(String)
}

func compareOne(a: Value, b: Value) -> Value? {
    switch (a, b) {
    case let (.intValue(aInt), .intValue(bInt)):
        return aInt > bInt ? .intValue(aInt) : aInt < bInt ? .intValue(bInt) : nil
    case let (.doubleValue(aDouble), .doubleValue(bDouble)):
        return aDouble > bDouble ? .doubleValue(aDouble) : aDouble < bDouble ? .doubleValue(bDouble) : nil
    case let (.stringValue(aString), .stringValue(bString)):
        let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aDouble > bDouble ? .stringValue(aString) : aDouble < bDouble ? .stringValue(bString) : nil
    case let (.intValue(intValue), .doubleValue(doubleValue)):
        return Double(intValue) > doubleValue ? .intValue(intValue) : Double(intValue) < doubleValue ? .doubleValue(doubleValue) : nil
    case let (.intValue(intValue), .stringValue(stringValue)):
        let doubleValue = Double(stringValue.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return Double(intValue) > doubleValue ? .intValue(intValue) : Double(intValue) < doubleValue ? .stringValue(stringValue) : nil
    case let (.doubleValue(doubleValue), .stringValue(stringValue)):
        let intValue = Int(doubleValue)
        let stringDoubleValue = Double(stringValue.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return doubleValue > stringDoubleValue ? .doubleValue(doubleValue) : doubleValue < stringDoubleValue ? .stringValue(stringValue) : nil
    default:
        return nil
    }
}
```
let intValue = Int(doubleValue) // initialization of immutable value 'intValue' was never used; consider replacing with assignment to '_' or removing it

enum Value: Equatable, Hashable {
    case intValue(Int)
    case doubleValue(Double)
    case stringValue(String)
}

func compareOne(a: Value, b: Value) -> Value? {
    switch (a, b) {
    case let (.intValue(aInt), .intValue(bInt)):
        return aInt > bInt ? .intValue(aInt) : aInt < bInt ? .intValue(bInt) : nil
    case let (.intValue(aInt), .doubleValue(bDouble)):
        return Double(aInt) > bDouble ? .intValue(aInt) : Double(aInt) < bDouble ? .doubleValue(bDouble) : nil
    case let (.doubleValue(aDouble), .intValue(bInt)):
        return aDouble > Double(bInt) ? .doubleValue(aDouble) : aDouble < Double(bInt) ? .intValue(bInt) : nil
    case let (.doubleValue(aDouble), .doubleValue(bDouble)):
        return aDouble > bDouble ? .doubleValue(aDouble) : aDouble < bDouble ? .doubleValue(bDouble) : nil
    case let (.intValue(aInt), .stringValue(bString)):
        if let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
            return Double(aInt) > bDouble ? .intValue(aInt) : Double(aInt) < bDouble ? .stringValue(bString) : nil
        }
    case let (.stringValue(aString), .intValue(bInt)):
        if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")) {
            return aDouble > Double(bInt) ? .stringValue(aString) : aDouble < Double(bInt) ? .intValue(bInt) : nil
        }
    case let (.doubleValue(aDouble), .stringValue(bString)):
        if let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
            return aDouble > bDouble ? .doubleValue(aDouble) : aDouble < bDouble ? .stringValue(bString) : nil
        }
    case let (.stringValue(aString), .doubleValue(bDouble)):
        if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")) {
            return aDouble > bDouble ? .stringValue(aString) : aDouble < bDouble ? .doubleValue(bDouble) : nil
        }
    case let (.stringValue(aString), .stringValue(bString)):
        if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")), let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
            return aDouble > bDouble ? .stringValue(aString) : aDouble < bDouble ? .stringValue(bString) : nil
        }
    default:
        return nil
    }
    return nil
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be . or ,
compareOne(a: .intValue(1), b: .doubleValue(2.5)) == .doubleValue(2.5)
compareOne(a: .intValue(1), b: .stringValue("2,3")) == .stringValue("2,3")
compareOne(a: .stringValue("5,1"), b: .stringValue("6")) == .stringValue("6")
compareOne(a: .stringValue("1"), b: .intValue(1)) == nil[/INST]  ```swift
enum Value: Equatable, Hashable {
    case intValue(Int)
    case doubleValue(Double)
    case stringValue(String)
}

func compareOne(a: Value, b: Value) -> Value? {
    switch (a, b) {
    case let (.intValue(aInt), .intValue(bInt)):
        return aInt > bInt ? .intValue(aInt) : aInt < bInt ? .intValue(bInt) : nil
    case let (.intValue(aInt), .doubleValue(bDouble)):
        return Double(aInt) > bDouble ? .intValue(aInt) : Double(aInt) < bDouble ? .doubleValue(bDouble) : nil
    case let (.doubleValue(aDouble), .intValue(bInt)):
        return aDouble > Double(bInt) ? .doubleValue(aDouble) : aDouble < Double(bInt) ? .intValue(bInt) : nil
    case let (.doubleValue(aDouble), .doubleValue(bDouble)):
        return aDouble > bDouble ? .doubleValue(aDouble) : aDouble < bDouble ? .doubleValue(bDouble) : nil
    case let (.intValue(aInt), .stringValue(bString)):
        if let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
            return Double(aInt) > bDouble ? .intValue(aInt) : Double(aInt) < bDouble ? .stringValue(bString) : nil
        }
    case let (.stringValue(aString), .intValue(bInt)):
        if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")) {
            return aDouble > Double(bInt) ? .stringValue(aString) : aDouble < Double(bInt) ? .intValue(bInt) : nil
        }
    case let (.doubleValue(aDouble), .stringValue(bString)):
        if let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
            return aDouble > bDouble ? .doubleValue(aDouble) : aDouble < bDouble ? .stringValue(bString) : nil
        }
    case let (.stringValue(aString), .doubleValue(bDouble)):
        if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")) {
            return aDouble > bDouble ? .stringValue(aString) : aDouble < bDouble ? .doubleValue(bDouble) : nil
        }
    case let (.stringValue(aString), .stringValue(bString)):
        if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")), let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
            return aDouble > bDouble ? .stringValue(aString) : aDouble < bDouble ? .stringValue(bString) : nil
        }
    default:
        return nil
    }
    return nil
}
```
default: // default will never be executed

enum Value: Equatable, Hashable {
    case intValue(Int)
    case doubleValue(Double)
    case stringValue(String)
}

func compareOne(a: Value, b: Value) -> Value? {
    switch (a, b) {
    case let (.intValue(a), .intValue(b)):
        return a > b ? .intValue(a) : (a < b ? .intValue(b) : nil)
    case let (.doubleValue(a), .doubleValue(b)):
        return a > b ? .doubleValue(a) : (a < b ? .doubleValue(b) : nil)
    case let (.stringValue(a), .stringValue(b)):
        let aDouble = Double(a.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        let bDouble = Double(b.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aDouble > bDouble ? .stringValue(a) : (aDouble < bDouble ? .stringValue(b) : nil)
    case let (.intValue(a), .doubleValue(b)):
        return Double(a) > b ? .intValue(a) : (Double(a) < b ? .doubleValue(b) : nil)
    case let (.intValue(a), .stringValue(b)):
        let bDouble = Double(b.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return Double(a) > bDouble ? .intValue(a) : (Double(a) < bDouble ? .stringValue(b) : nil)
    case let (.doubleValue(a), .stringValue(b)):
        let bDouble = Double(b.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return a > bDouble ? .doubleValue(a) : (a < bDouble ? .stringValue(b) : nil)
    default:
        return nil
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be . or ,
compareOne(a: .intValue(1), b: .doubleValue(2.5)) == .doubleValue(2.5)
compareOne(a: .intValue(1), b: .stringValue("2,3")) == .stringValue("2,3")
compareOne(a: .stringValue("5,1"), b: .stringValue("6")) == .stringValue("6")
compareOne(a: .stringValue("1"), b: .intValue(1)) == nil[/INST]  ```swift
enum Value: Equatable, Hashable {
    case intValue(Int)
    case doubleValue(Double)
    case stringValue(String)
}

func compareOne(a: Value, b: Value) -> Value? {
    switch (a, b) {
    case let (.intValue(a), .intValue(b)):
        return a > b ? .intValue(a) : (a < b ? .intValue(b) : nil)
    case let (.doubleValue(a), .doubleValue(b)):
        return a > b ? .doubleValue(a) : (a < b ? .doubleValue(b) : nil)
    case let (.stringValue(a), .stringValue(b)):
        let aDouble = Double(a.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        let bDouble = Double(b.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aDouble > bDouble ? .stringValue(a) : (aDouble < bDouble ? .stringValue(b) : nil)
    case let (.intValue(a), .doubleValue(b)):
        return Double(a) > b ? .intValue(a) : (Double(a) < b ? .doubleValue(b) : nil)
    case let (.intValue(a), .stringValue(b)):
        let bDouble = Double(b.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return Double(a) > bDouble ? .intValue(a) : (Double(a) < bDouble ? .stringValue(b) : nil)
    case let (.doubleValue(a), .stringValue(b)):
        let bDouble = Double(b.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return a > bDouble ? .doubleValue(a) : (a < bDouble ? .stringValue(b) : nil)
    default:
        return nil
    }
}
```

enum Value: Equatable, Hashable {
    case intValue(Int)
    case doubleValue(Double)
    case stringValue(String)
}

func compareOne(a: Value, b: Value) -> Value? {
    switch (a, b) {
    case let (.intValue(aInt), .intValue(bInt)):
        return aInt > bInt ? .intValue(aInt) : aInt < bInt ? .intValue(bInt) : nil
    case let (.doubleValue(aDouble), .doubleValue(bDouble)):
        return aDouble > bDouble ? .doubleValue(aDouble) : aDouble < bDouble ? .doubleValue(bDouble) : nil
    case let (.stringValue(aString), .stringValue(bString)):
        let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")) ?? 0
        let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) ?? 0
        return aDouble > bDouble ? .stringValue(aString) : aDouble < bDouble ? .stringValue(bString) : nil
    case let (.intValue(aInt), .doubleValue(bDouble)):
        return Double(aInt) > bDouble ? .intValue(aInt) : Double(aInt) < bDouble ? .doubleValue(bDouble) : nil
    case let (.doubleValue(aDouble), .intValue(bInt)):
        return aDouble > Double(bInt) ? .doubleValue(aDouble) : aDouble < Double(bInt) ? .intValue(bInt) : nil
    case let (.intValue(aInt), .stringValue(bString)):
        let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) ?? 0
        return Double(aInt) > bDouble ? .intValue(aInt) : Double(aInt) < bDouble ? .stringValue(bString) : nil
    case let (.stringValue(aString), .intValue(bInt)):
        let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")) ?? 0
        return aDouble > Double(bInt) ? .stringValue(aString) : aDouble < Double(bInt) ? .intValue(bInt) : nil
    case let (.doubleValue(aDouble), .stringValue(bString)):
        let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) ?? 0
        return aDouble > bDouble ? .doubleValue(aDouble) : aDouble < bDouble ? .stringValue(bString) : nil
    case let (.stringValue(aString), .doubleValue(bDouble)):
        let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")) ?? 0
        return aDouble > bDouble ? .stringValue(aString) : aDouble < bDouble ? .doubleValue(bDouble) : nil
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be . or ,
compareOne(a: .intValue(1), b: .doubleValue(2.5)) == .doubleValue(2.5)
compareOne(a: .intValue(1), b: .stringValue("2,3")) == .stringValue("2,3")
compareOne(a: .stringValue("5,1"), b: .stringValue("6")) == .stringValue("6")
compareOne(a: .stringValue("1"), b: .intValue(1)) == nil[/INST]  ```swift
enum Value: Equatable, Hashable {
    case intValue(Int)
    case doubleValue(Double)
    case stringValue(String)
}

func compareOne(a: Value, b: Value) -> Value? {
    switch (a, b) {
    case let (.intValue(aInt), .intValue(bInt)):
        return aInt > bInt ? .intValue(aInt) : aInt < bInt ? .intValue(bInt) : nil
    case let (.doubleValue(aDouble), .doubleValue(bDouble)):
        return aDouble > bDouble ? .doubleValue(aDouble) : aDouble < bDouble ? .doubleValue(bDouble) : nil
    case let (.stringValue(aString), .stringValue(bString)):
        let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")) ?? 0
        let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) ?? 0
        return aDouble > bDouble ? .stringValue(aString) : aDouble < bDouble ? .stringValue(bString) : nil
    case let (.intValue(aInt), .doubleValue(bDouble)):
        return Double(aInt) > bDouble ? .intValue(aInt) : Double(aInt) < bDouble ? .doubleValue(bDouble) : nil
    case let (.doubleValue(aDouble), .intValue(bInt)):
        return aDouble > Double(bInt) ? .doubleValue(aDouble) : aDouble < Double(bInt) ? .intValue(bInt) : nil
    case let (.intValue(aInt), .stringValue(bString)):
        let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) ?? 0
        return Double(aInt) > bDouble ? .intValue(aInt) : Double(aInt) < bDouble ? .stringValue(bString) : nil
    case let (.stringValue(aString), .intValue(bInt)):
        let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")) ?? 0
        return aDouble > Double(bInt) ? .stringValue(aString) : aDouble < Double(bInt) ? .intValue(bInt) : nil
    case let (.doubleValue(aDouble), .stringValue(bString)):
        let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) ?? 0
        return aDouble > bDouble ? .doubleValue(aDouble) : aDouble < bDouble ? .stringValue(bString) : nil
    case let (.stringValue(aString), .doubleValue(bDouble)):
        let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")) ?? 0
        return aDouble > bDouble ? .stringValue(aString) : aDouble < bDouble ? .doubleValue(bDouble) : nil
    }
}
```

enum Value: Equatable, Hashable {
    case intValue(Int)
    case doubleValue(Double)
    case stringValue(String)
}

func compareOne(a: Value, b: Value) -> Value? {
    switch (a, b) {
    case (.intValue(let a), .intValue(let b)):
        return a > b ? .intValue(a) : a < b ? .intValue(b) : nil
    case (.doubleValue(let a), .doubleValue(let b)):
        return a > b ? .doubleValue(a) : a < b ? .doubleValue(b) : nil
    case (.stringValue(let a), .stringValue(let b)):
        let aDouble = Double(a.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        let bDouble = Double(b.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aDouble > bDouble ? .stringValue(a) : aDouble < bDouble ? .stringValue(b) : nil
    case (.intValue(let a), .doubleValue(let b)):
        return Double(a) > b ? .intValue(a) : Double(a) < b ? .doubleValue(b) : nil
    case (.doubleValue(let a), .intValue(let b)):
        return a > Double(b) ? .doubleValue(a) : a < Double(b) ? .intValue(b) : nil
    case (.intValue(let a), .stringValue(let b)):
        let bDouble = Double(b.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return Double(a) > bDouble ? .intValue(a) : Double(a) < bDouble ? .stringValue(b) : nil
    case (.stringValue(let a), .intValue(let b)):
        let aDouble = Double(a.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aDouble > Double(b) ? .stringValue(a) : aDouble < Double(b) ? .intValue(b) : nil
    case (.doubleValue(let a), .stringValue(let b)):
        let bDouble = Double(b.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return a > bDouble ? .doubleValue(a) : a < bDouble ? .stringValue(b) : nil
    case (.stringValue(let a), .doubleValue(let b)):
        let aDouble = Double(a.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aDouble > b ? .stringValue(a) : aDouble < b ? .doubleValue(b) : nil
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be . or ,
compareOne(a: .intValue(1), b: .doubleValue(2.5)) == .doubleValue(2.5)
compareOne(a: .intValue(1), b: .stringValue("2,3")) == .stringValue("2,3")
compareOne(a: .stringValue("5,1"), b: .stringValue("6")) == .stringValue("6")
compareOne(a: .stringValue("1"), b: .intValue(1)) == nil[/INST]  ```swift
enum Value: Equatable, Hashable {
    case intValue(Int)
    case doubleValue(Double)
    case stringValue(String)
}

func compareOne(a: Value, b: Value) -> Value? {
    switch (a, b) {
    case (.intValue(let a), .intValue(let b)):
        return a > b ? .intValue(a) : a < b ? .intValue(b) : nil
    case (.doubleValue(let a), .doubleValue(let b)):
        return a > b ? .doubleValue(a) : a < b ? .doubleValue(b) : nil
    case (.stringValue(let a), .stringValue(let b)):
        let aDouble = Double(a.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        let bDouble = Double(b.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aDouble > bDouble ? .stringValue(a) : aDouble < bDouble ? .stringValue(b) : nil
    case (.intValue(let a), .doubleValue(let b)):
        return Double(a) > b ? .intValue(a) : Double(a) < b ? .doubleValue(b) : nil
    case (.doubleValue(let a), .intValue(let b)):
        return a > Double(b) ? .doubleValue(a) : a < Double(b) ? .intValue(b) : nil
    case (.intValue(let a), .stringValue(let b)):
        let bDouble = Double(b.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return Double(a) > bDouble ? .intValue(a) : Double(a) < bDouble ? .stringValue(b) : nil
    case (.stringValue(let a), .intValue(let b)):
        let aDouble = Double(a.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aDouble > Double(b) ? .stringValue(a) : aDouble < Double(b) ? .intValue(b) : nil
    case (.doubleValue(let a), .stringValue(let b)):
        let bDouble = Double(b.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return a > bDouble ? .doubleValue(a) : a < bDouble ? .stringValue(b) : nil
    case (.stringValue(let a), .doubleValue(let b)):
        let aDouble = Double(a.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aDouble > b ? .stringValue(a) : aDouble < b ? .doubleValue(b) : nil
    }
}
```

enum Value: Equatable, Hashable {
    case intValue(Int)
    case doubleValue(Double)
    case stringValue(String)
}

func compareOne(a: Value, b: Value) -> Value? {
    switch (a, b) {
    case (.intValue(let aValue), .intValue(let bValue)):
        return aValue > bValue ? .intValue(aValue) : (aValue < bValue ? .intValue(bValue) : nil)
    case (.doubleValue(let aValue), .doubleValue(let bValue)):
        return aValue > bValue ? .doubleValue(aValue) : (aValue < bValue ? .doubleValue(bValue) : nil)
    case (.stringValue(let aValue), .stringValue(let bValue)):
        let aDouble = Double(aValue.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        let bDouble = Double(bValue.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aDouble > bDouble ? .stringValue(aValue) : (aDouble < bDouble ? .stringValue(bValue) : nil)
    case (.intValue(let aValue), .doubleValue(let bValue)):
        return Double(aValue) > bValue ? .doubleValue(Double(aValue)) : (Double(aValue) < bValue ? .doubleValue(bValue) : nil)
    case (.intValue(let aValue), .stringValue(let bValue)):
        let bDouble = Double(bValue.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return Double(aValue) > bDouble ? .stringValue(String(aValue)) : (Double(aValue) < bDouble ? .stringValue(bValue) : nil)
    case (.doubleValue(let aValue), .intValue(let bValue)):
        return aValue > Double(bValue) ? .doubleValue(aValue) : (aValue < Double(bValue) ? .doubleValue(Double(bValue)) : nil)
    case (.doubleValue(let aValue), .stringValue(let bValue)):
        let bDouble = Double(bValue.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aValue > bDouble ? .doubleValue(aValue) : (aValue < bDouble ? .stringValue(bValue) : nil)
    case (.stringValue(let aValue), .intValue(let bValue)):
        let aDouble = Double(aValue.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aDouble > Double(bValue) ? .stringValue(aValue) : (aDouble < Double(bValue) ? .intValue(bValue) : nil)
    case (.stringValue(let aValue), .doubleValue(let bValue)):
        let aDouble = Double(aValue.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aDouble > bValue ? .stringValue(aValue) : (aDouble < bValue ? .doubleValue(bValue) : nil)
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be . or ,
compareOne(a: .intValue(1), b: .doubleValue(2.5)) == .doubleValue(2.5)
compareOne(a: .intValue(1), b: .stringValue("2,3")) == .stringValue("2,3")
compareOne(a: .stringValue("5,1"), b: .stringValue("6")) == .stringValue("6")
compareOne(a: .stringValue("1"), b: .intValue(1)) == nil[/INST]  ```swift
enum Value: Equatable, Hashable {
    case intValue(Int)
    case doubleValue(Double)
    case stringValue(String)
}

func compareOne(a: Value, b: Value) -> Value? {
    switch (a, b) {
    case (.intValue(let aValue), .intValue(let bValue)):
        return aValue > bValue ? .intValue(aValue) : (aValue < bValue ? .intValue(bValue) : nil)
    case (.doubleValue(let aValue), .doubleValue(let bValue)):
        return aValue > bValue ? .doubleValue(aValue) : (aValue < bValue ? .doubleValue(bValue) : nil)
    case (.stringValue(let aValue), .stringValue(let bValue)):
        let aDouble = Double(aValue.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        let bDouble = Double(bValue.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aDouble > bDouble ? .stringValue(aValue) : (aDouble < bDouble ? .stringValue(bValue) : nil)
    case (.intValue(let aValue), .doubleValue(let bValue)):
        return Double(aValue) > bValue ? .doubleValue(Double(aValue)) : (Double(aValue) < bValue ? .doubleValue(bValue) : nil)
    case (.intValue(let aValue), .stringValue(let bValue)):
        let bDouble = Double(bValue.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return Double(aValue) > bDouble ? .stringValue(String(aValue)) : (Double(aValue) < bDouble ? .stringValue(bValue) : nil)
    case (.doubleValue(let aValue), .intValue(let bValue)):
        return aValue > Double(bValue) ? .doubleValue(aValue) : (aValue < Double(bValue) ? .doubleValue(Double(bValue)) : nil)
    case (.doubleValue(let aValue), .stringValue(let bValue)):
        let bDouble = Double(bValue.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aValue > bDouble ? .doubleValue(aValue) : (aValue < bDouble ? .stringValue(bValue) : nil)
    case (.stringValue(let aValue), .intValue(let bValue)):
        let aDouble = Double(aValue.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aDouble > Double(bValue) ? .stringValue(aValue) : (aDouble < Double(bValue) ? .intValue(bValue) : nil)
    case (.stringValue(let aValue), .doubleValue(let bValue)):
        let aDouble = Double(aValue.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aDouble > bValue ? .stringValue(aValue) : (aDouble < bValue ? .doubleValue(bValue) : nil)
    }
}
```

enum Value: Equatable, Hashable {
    case intValue(Int)
    case doubleValue(Double)
    case stringValue(String)
}

func compareOne(a: Value, b: Value) -> Value? {
    switch (a, b) {
    case let (.intValue(a), .intValue(b)):
        return a > b ? .intValue(a) : a < b ? .intValue(b) : nil
    case let (.doubleValue(a), .doubleValue(b)):
        return a > b ? .doubleValue(a) : a < b ? .doubleValue(b) : nil
    case let (.stringValue(a), .stringValue(b)):
        let aDouble = Double(a.replacingOccurrences(of: ",", with: ".")) ?? 0
        let bDouble = Double(b.replacingOccurrences(of: ",", with: ".")) ?? 0
        return aDouble > bDouble ? .stringValue(a) : aDouble < bDouble ? .stringValue(b) : nil
    case let (.intValue(a), .doubleValue(b)):
        return Double(a) > b ? .intValue(a) : Double(a) < b ? .doubleValue(b) : nil
    case let (.doubleValue(a), .intValue(b)):
        return a > Double(b) ? .doubleValue(a) : a < Double(b) ? .intValue(b) : nil
    case let (.intValue(a), .stringValue(b)):
        let bDouble = Double(b.replacingOccurrences(of: ",", with: ".")) ?? 0
        return Double(a) > bDouble ? .intValue(a) : Double(a) < bDouble ? .stringValue(b) : nil
    case let (.stringValue(a), .intValue(b)):
        let aDouble = Double(a.replacingOccurrences(of: ",", with: ".")) ?? 0
        return aDouble > Double(b) ? .stringValue(a) : aDouble < Double(b) ? .intValue(b) : nil
    case let (.doubleValue(a), .stringValue(b)):
        let bDouble = Double(b.replacingOccurrences(of: ",", with: ".")) ?? 0
        return a > bDouble ? .doubleValue(a) : a < bDouble ? .stringValue(b) : nil
    case let (.stringValue(a), .doubleValue(b)):
        let aDouble = Double(a.replacingOccurrences(of: ",", with: ".")) ?? 0
        return aDouble > b ? .stringValue(a) : aDouble < b ? .doubleValue(b) : nil
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be . or ,
compareOne(a: .intValue(1), b: .doubleValue(2.5)) == .doubleValue(2.5)
compareOne(a: .intValue(1), b: .stringValue("2,3")) == .stringValue("2,3")
compareOne(a: .stringValue("5,1"), b: .stringValue("6")) == .stringValue("6")
compareOne(a: .stringValue("1"), b: .intValue(1)) == nil[/INST]  ```swift
enum Value: Equatable, Hashable {
    case intValue(Int)
    case doubleValue(Double)
    case stringValue(String)
}

func compareOne(a: Value, b: Value) -> Value? {
    switch (a, b) {
    case let (.intValue(a), .intValue(b)):
        return a > b ? .intValue(a) : a < b ? .intValue(b) : nil
    case let (.doubleValue(a), .doubleValue(b)):
        return a > b ? .doubleValue(a) : a < b ? .doubleValue(b) : nil
    case let (.stringValue(a), .stringValue(b)):
        let aDouble = Double(a.replacingOccurrences(of: ",", with: ".")) ?? 0
        let bDouble = Double(b.replacingOccurrences(of: ",", with: ".")) ?? 0
        return aDouble > bDouble ? .stringValue(a) : aDouble < bDouble ? .stringValue(b) : nil
    case let (.intValue(a), .doubleValue(b)):
        return Double(a) > b ? .intValue(a) : Double(a) < b ? .doubleValue(b) : nil
    case let (.doubleValue(a), .intValue(b)):
        return a > Double(b) ? .doubleValue(a) : a < Double(b) ? .intValue(b) : nil
    case let (.intValue(a), .stringValue(b)):
        let bDouble = Double(b.replacingOccurrences(of: ",", with: ".")) ?? 0
        return Double(a) > bDouble ? .intValue(a) : Double(a) < bDouble ? .stringValue(b) : nil
    case let (.stringValue(a), .intValue(b)):
        let aDouble = Double(a.replacingOccurrences(of: ",", with: ".")) ?? 0
        return aDouble > Double(b) ? .stringValue(a) : aDouble < Double(b) ? .intValue(b) : nil
    case let (.doubleValue(a), .stringValue(b)):
        let bDouble = Double(b.replacingOccurrences(of: ",", with: ".")) ?? 0
        return a > bDouble ? .doubleValue(a) : a < bDouble ? .stringValue(b) : nil
    case let (.stringValue(a), .doubleValue(b)):
        let aDouble = Double(a.replacingOccurrences(of: ",", with: ".")) ?? 0
        return aDouble > b ? .stringValue(a) : aDouble < b ? .doubleValue(b) : nil
    }
}
```

enum Value: Equatable, Hashable {
    case intValue(Int)
    case doubleValue(Double)
    case stringValue(String)
}

func compareOne(a: Value, b: Value) -> Value? {
    switch (a, b) {
    case let (.intValue(a), .intValue(b)):
        return a > b ? .intValue(a) : a < b ? .intValue(b) : nil
    case let (.intValue(a), .doubleValue(b)):
        return Double(a) > b ? .intValue(a) : Double(a) < b ? .doubleValue(b) : nil
    case let (.intValue(a), .stringValue(b)):
        if let bDouble = Double(b.replacingOccurrences(of: ",", with: ".")) {
            return Double(a) > bDouble ? .intValue(a) : Double(a) < bDouble ? .stringValue(b) : nil
        }
        return nil
    case let (.doubleValue(a), .doubleValue(b)):
        return a > b ? .doubleValue(a) : a < b ? .doubleValue(b) : nil
    case let (.doubleValue(a), .intValue(b)):
        return a > Double(b) ? .doubleValue(a) : a < Double(b) ? .intValue(b) : nil
    case let (.doubleValue(a), .stringValue(b)):
        if let bDouble = Double(b.replacingOccurrences(of: ",", with: ".")) {
            return a > bDouble ? .doubleValue(a) : a < bDouble ? .stringValue(b) : nil
        }
        return nil
    case let (.stringValue(a), .stringValue(b)):
        if let aDouble = Double(a.replacingOccurrences(of: ",", with: ".")),
           let bDouble = Double(b.replacingOccurrences(of: ",", with: ".")) {
            return aDouble > bDouble ? .stringValue(a) : aDouble < bDouble ? .stringValue(b) : nil
        }
        return nil
    case let (.stringValue(a), .intValue(b)):
        if let aDouble = Double(a.replacingOccurrences(of: ",", with: ".")) {
            return aDouble > Double(b) ? .stringValue(a) : aDouble < Double(b) ? .intValue(b) : nil
        }
        return nil
    case let (.stringValue(a), .doubleValue(b)):
        if let aDouble = Double(a.replacingOccurrences(of: ",", with: ".")) {
            return aDouble > b ? .stringValue(a) : aDouble < b ? .doubleValue(b) : nil
        }
        return nil
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be . or ,
compareOne(a: .intValue(1), b: .doubleValue(2.5)) == .doubleValue(2.5)
compareOne(a: .intValue(1), b: .stringValue("2,3")) == .stringValue("2,3")
compareOne(a: .stringValue("5,1"), b: .stringValue("6")) == .stringValue("6")
compareOne(a: .stringValue("1"), b: .intValue(1)) == nil[/INST]  ```swift
enum Value: Equatable, Hashable {
    case intValue(Int)
    case doubleValue(Double)
    case stringValue(String)
}

func compareOne(a: Value, b: Value) -> Value? {
    switch (a, b) {
    case let (.intValue(a), .intValue(b)):
        return a > b ? .intValue(a) : a < b ? .intValue(b) : nil
    case let (.intValue(a), .doubleValue(b)):
        return Double(a) > b ? .intValue(a) : Double(a) < b ? .doubleValue(b) : nil
    case let (.intValue(a), .stringValue(b)):
        if let bDouble = Double(b.replacingOccurrences(of: ",", with: ".")) {
            return Double(a) > bDouble ? .intValue(a) : Double(a) < bDouble ? .stringValue(b) : nil
        }
        return nil
    case let (.doubleValue(a), .doubleValue(b)):
        return a > b ? .doubleValue(a) : a < b ? .doubleValue(b) : nil
    case let (.doubleValue(a), .intValue(b)):
        return a > Double(b) ? .doubleValue(a) : a < Double(b) ? .intValue(b) : nil
    case let (.doubleValue(a), .stringValue(b)):
        if let bDouble = Double(b.replacingOccurrences(of: ",", with: ".")) {
            return a > bDouble ? .doubleValue(a) : a < bDouble ? .stringValue(b) : nil
        }
        return nil
    case let (.stringValue(a), .stringValue(b)):
        if let aDouble = Double(a.replacingOccurrences(of: ",", with: ".")),
           let bDouble = Double(b.replacingOccurrences(of: ",", with: ".")) {
            return aDouble > bDouble ? .stringValue(a) : aDouble < bDouble ? .stringValue(b) : nil
        }
        return nil
    case let (.stringValue(a), .intValue(b)):
        if let aDouble = Double(a.replacingOccurrences(of: ",", with: ".")) {
            return aDouble > Double(b) ? .stringValue(a) : aDouble < Double(b) ? .intValue(b) : nil
        }
        return nil
    case let (.stringValue(a), .doubleValue(b)):
        if let aDouble = Double(a.replacingOccurrences(of: ",", with: ".")) {
            return aDouble > b ? .stringValue(a) : aDouble < b ? .doubleValue(b) : nil
        }
        return nil
    }
}
```

enum Value: Equatable, Hashable {
    case intValue(Int)
    case doubleValue(Double)
    case stringValue(String)
}

func compareOne(a: Value, b: Value) -> Value? {
    switch (a, b) {
    case (.intValue(let aValue), .intValue(let bValue)):
        return aValue > bValue ? .intValue(aValue) : aValue < bValue ? .intValue(bValue) : nil
    case (.doubleValue(let aValue), .doubleValue(let bValue)):
        return aValue > bValue ? .doubleValue(aValue) : aValue < bValue ? .doubleValue(bValue) : nil
    case (.stringValue(let aValue), .stringValue(let bValue)):
        let aDouble = Double(aValue.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        let bDouble = Double(bValue.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aDouble > bDouble ? .stringValue(aValue) : aDouble < bDouble ? .stringValue(bValue) : nil
    case (.intValue(let aValue), .doubleValue(let bValue)):
        return Double(aValue) > bValue ? .doubleValue(Double(aValue)) : Double(aValue) < bValue ? .doubleValue(bValue) : nil
    case (.intValue(let aValue), .stringValue(let bValue)):
        let bDouble = Double(bValue.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return Double(aValue) > bDouble ? .stringValue(String(aValue)) : Double(aValue) < bDouble ? .stringValue(bValue) : nil
    case (.doubleValue(let aValue), .intValue(let bValue)):
        return aValue > Double(bValue) ? .doubleValue(aValue) : aValue < Double(bValue) ? .doubleValue(Double(bValue)) : nil
    case (.doubleValue(let aValue), .stringValue(let bValue)):
        let bDouble = Double(bValue.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aValue > bDouble ? .stringValue(String(aValue)) : aValue < bDouble ? .stringValue(bValue) : nil
    case (.stringValue(let aValue), .intValue(let bValue)):
        let aDouble = Double(aValue.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aDouble > Double(bValue) ? .stringValue(aValue) : aDouble < Double(bValue) ? .stringValue(String(bValue)) : nil
    case (.stringValue(let aValue), .doubleValue(let bValue)):
        let aDouble = Double(aValue.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aDouble > bValue ? .stringValue(aValue) : aDouble < bValue ? .stringValue(String(bValue)) : nil
    default:
        return nil
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be . or ,
compareOne(a: .intValue(1), b: .doubleValue(2.5)) == .doubleValue(2.5)
compareOne(a: .intValue(1), b: .stringValue("2,3")) == .stringValue("2,3")
compareOne(a: .stringValue("5,1"), b: .stringValue("6")) == .stringValue("6")
compareOne(a: .stringValue("1"), b: .intValue(1)) == nil[/INST]  ```swift
enum Value: Equatable, Hashable {
    case intValue(Int)
    case doubleValue(Double)
    case stringValue(String)
}

func compareOne(a: Value, b: Value) -> Value? {
    switch (a, b) {
    case (.intValue(let aValue), .intValue(let bValue)):
        return aValue > bValue ? .intValue(aValue) : aValue < bValue ? .intValue(bValue) : nil
    case (.doubleValue(let aValue), .doubleValue(let bValue)):
        return aValue > bValue ? .doubleValue(aValue) : aValue < bValue ? .doubleValue(bValue) : nil
    case (.stringValue(let aValue), .stringValue(let bValue)):
        let aDouble = Double(aValue.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        let bDouble = Double(bValue.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aDouble > bDouble ? .stringValue(aValue) : aDouble < bDouble ? .stringValue(bValue) : nil
    case (.intValue(let aValue), .doubleValue(let bValue)):
        return Double(aValue) > bValue ? .doubleValue(Double(aValue)) : Double(aValue) < bValue ? .doubleValue(bValue) : nil
    case (.intValue(let aValue), .stringValue(let bValue)):
        let bDouble = Double(bValue.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return Double(aValue) > bDouble ? .stringValue(String(aValue)) : Double(aValue) < bDouble ? .stringValue(bValue) : nil
    case (.doubleValue(let aValue), .intValue(let bValue)):
        return aValue > Double(bValue) ? .doubleValue(aValue) : aValue < Double(bValue) ? .doubleValue(Double(bValue)) : nil
    case (.doubleValue(let aValue), .stringValue(let bValue)):
        let bDouble = Double(bValue.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aValue > bDouble ? .stringValue(String(aValue)) : aValue < bDouble ? .stringValue(bValue) : nil
    case (.stringValue(let aValue), .intValue(let bValue)):
        let aDouble = Double(aValue.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aDouble > Double(bValue) ? .stringValue(aValue) : aDouble < Double(bValue) ? .stringValue(String(bValue)) : nil
    case (.stringValue(let aValue), .doubleValue(let bValue)):
        let aDouble = Double(aValue.replacingOccurrences(of: ",", with: ".")) ?? 0.0
        return aDouble > bValue ? .stringValue(aValue) : aDouble < bValue ? .stringValue(String(bValue)) : nil
    default:
        return nil
    }
}
```
default: // default will never be executed

func isEqualToSumEven(n: Int) -> Bool {
    if n < 8 || n % 2 != 0 {
        return false
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true[/INST]  ```swift
func isEqualToSumEven(n: Int) -> Bool {
    if n < 8 || n % 2 != 0 {
        return false
    }
    return true
}
```

func isEqualToSumEven(n: Int) -> Bool {
    if n < 8 || n % 2 != 0 {
        return false
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true[/INST]  ```swift
func isEqualToSumEven(n: Int) -> Bool {
    if n < 8 || n % 2 != 0 {
        return false
    }
    return true
}
```

func isEqualToSumEven(n: Int) -> Bool {
    if n < 8 || n % 2 != 0 {
        return false
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true[/INST]  ```swift
func isEqualToSumEven(n: Int) -> Bool {
    if n < 8 || n % 2 != 0 {
        return false
    }
    return true
}
```

func isEqualToSumEven(n: Int) -> Bool {
    if n < 8 || n % 2 != 0 {
        return false
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true[/INST]  ```swift
func isEqualToSumEven(n: Int) -> Bool {
    if n < 8 || n % 2 != 0 {
        return false
    }
    return true
}
```

func isEqualToSumEven(n: Int) -> Bool {
    if n < 8 || n % 2 != 0 {
        return false
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true[/INST]  ```swift
func isEqualToSumEven(n: Int) -> Bool {
    if n < 8 || n % 2 != 0 {
        return false
    }
    return true
}
```

func isEqualToSumEven(n: Int) -> Bool {
    if n < 8 || n % 2 != 0 {
        return false
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true[/INST]  ```swift
func isEqualToSumEven(n: Int) -> Bool {
    if n < 8 || n % 2 != 0 {
        return false
    }
    return true
}
```

func isEqualToSumEven(n: Int) -> Bool {
    if n < 8 || n % 2 != 0 {
        return false
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true[/INST]  ```swift
func isEqualToSumEven(n: Int) -> Bool {
    if n < 8 || n % 2 != 0 {
        return false
    }
    return true
}
```

func isEqualToSumEven(n: Int) -> Bool {
    if n < 8 || n % 2 != 0 {
        return false
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true[/INST]  ```swift
func isEqualToSumEven(n: Int) -> Bool {
    if n < 8 || n % 2 != 0 {
        return false
    }
    return true
}
```

func isEqualToSumEven(n: Int) -> Bool {
    if n < 8 || n % 2 != 0 {
        return false
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true[/INST]  ```swift
func isEqualToSumEven(n: Int) -> Bool {
    if n < 8 || n % 2 != 0 {
        return false
    }
    return true
}
```

func isEqualToSumEven(n: Int) -> Bool {
    if n < 8 || n % 2 != 0 {
        return false
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true[/INST]  ```swift
func isEqualToSumEven(n: Int) -> Bool {
    if n < 8 || n % 2 != 0 {
        return false
    }
    return true
}
```

func specialFactorial(n: Int) -> Int {
    var result = 1
    for i in 1...n {
        result *= factorial(i)
    }
    return result
}

func factorial(_ n: Int) -> Int {
    if n == 0 {
        return 1
    }
    return n * factorial(n - 1)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288[/INST]  ```swift
func specialFactorial(n: Int) -> Int {
    var result = 1
    for i in 1...n {
        result *= factorial(i)
    }
    return result
}

func factorial(_ n: Int) -> Int {
    if n == 0 {
        return 1
    }
    return n * factorial(n - 1)
}
```

func specialFactorial(n: Int) -> Int {
    var result = 1
    for i in 1...n {
        result *= factorial(i)
    }
    return result
}

func factorial(_ n: Int) -> Int {
    if n == 0 {
        return 1
    }
    return n * factorial(n - 1)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288[/INST]  ```swift
func specialFactorial(n: Int) -> Int {
    var result = 1
    for i in 1...n {
        result *= factorial(i)
    }
    return result
}

func factorial(_ n: Int) -> Int {
    if n == 0 {
        return 1
    }
    return n * factorial(n - 1)
}
```

func specialFactorial(n: Int) -> Int {
    var result = 1
    for i in 1...n {
        result *= factorial(i)
    }
    return result
}

func factorial(_ n: Int) -> Int {
    if n == 0 {
        return 1
    }
    return n * factorial(n - 1)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288[/INST]  ```swift
func specialFactorial(n: Int) -> Int {
    var result = 1
    for i in 1...n {
        result *= factorial(i)
    }
    return result
}

func factorial(_ n: Int) -> Int {
    if n == 0 {
        return 1
    }
    return n * factorial(n - 1)
}
```

func specialFactorial(n: Int) -> Int {
    var result = 1
    for i in 1...n {
        result *= factorial(i)
    }
    return result
}

func factorial(_ n: Int) -> Int {
    if n == 0 {
        return 1
    }
    return n * factorial(n - 1)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288[/INST]  ```swift
func specialFactorial(n: Int) -> Int {
    var result = 1
    for i in 1...n {
        result *= factorial(i)
    }
    return result
}

func factorial(_ n: Int) -> Int {
    if n == 0 {
        return 1
    }
    return n * factorial(n - 1)
}
```

func specialFactorial(n: Int) -> Int {
    var result = 1
    for i in 1...n {
        result *= factorial(i)
    }
    return result
}

func factorial(_ n: Int) -> Int {
    if n == 0 {
        return 1
    }
    return n * factorial(n - 1)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288[/INST]  ```swift
func specialFactorial(n: Int) -> Int {
    var result = 1
    for i in 1...n {
        result *= factorial(i)
    }
    return result
}

func factorial(_ n: Int) -> Int {
    if n == 0 {
        return 1
    }
    return n * factorial(n - 1)
}
```

func specialFactorial(n: Int) -> Int {
    var result = 1
    for i in 1...n {
        result *= factorial(i)
    }
    return result
}

func factorial(_ n: Int) -> Int {
    if n == 0 {
        return 1
    }
    return n * factorial(n - 1)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288[/INST]  ```swift
func specialFactorial(n: Int) -> Int {
    var result = 1
    for i in 1...n {
        result *= factorial(i)
    }
    return result
}

func factorial(_ n: Int) -> Int {
    if n == 0 {
        return 1
    }
    return n * factorial(n - 1)
}
```

func specialFactorial(n: Int) -> Int {
    var result = 1
    for i in 1...n {
        result *= factorial(i)
    }
    return result
}

func factorial(_ n: Int) -> Int {
    if n == 0 {
        return 1
    }
    return n * factorial(n - 1)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288[/INST]  ```swift
func specialFactorial(n: Int) -> Int {
    var result = 1
    for i in 1...n {
        result *= factorial(i)
    }
    return result
}

func factorial(_ n: Int) -> Int {
    if n == 0 {
        return 1
    }
    return n * factorial(n - 1)
}
```

func specialFactorial(n: Int) -> Int {
    var result = 1
    for i in 1...n {
        result *= factorial(i)
    }
    return result
}

func factorial(_ n: Int) -> Int {
    if n == 0 {
        return 1
    }
    return n * factorial(n - 1)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288[/INST]  ```swift
func specialFactorial(n: Int) -> Int {
    var result = 1
    for i in 1...n {
        result *= factorial(i)
    }
    return result
}

func factorial(_ n: Int) -> Int {
    if n == 0 {
        return 1
    }
    return n * factorial(n - 1)
}
```

func specialFactorial(n: Int) -> Int {
    var result = 1
    for i in 1...n {
        result *= factorial(i)
    }
    return result
}

func factorial(_ n: Int) -> Int {
    if n == 0 {
        return 1
    }
    return n * factorial(n - 1)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288[/INST]  ```swift
func specialFactorial(n: Int) -> Int {
    var result = 1
    for i in 1...n {
        result *= factorial(i)
    }
    return result
}

func factorial(_ n: Int) -> Int {
    if n == 0 {
        return 1
    }
    return n * factorial(n - 1)
}
```

func specialFactorial(n: Int) -> Int {
    var result = 1
    for i in 1...n {
        result *= factorial(i)
    }
    return result
}

func factorial(_ n: Int) -> Int {
    if n == 0 {
        return 1
    }
    return n * factorial(n - 1)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288[/INST]  ```swift
func specialFactorial(n: Int) -> Int {
    var result = 1
    for i in 1...n {
        result *= factorial(i)
    }
    return result
}

func factorial(_ n: Int) -> Int {
    if n == 0 {
        return 1
    }
    return n * factorial(n - 1)
}
```

func fixSpaces(text: String) -> String {
    var result = text.replacingOccurrences(of: " ", with: "_")
    while result.contains("__") {
        result = result.replacingOccurrences(of: "__", with: "-")
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores, 
and if a string has more than 2 consecutive spaces, 
then replace all consecutive spaces with - 
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"[/INST]  ```swift
func fixSpaces(text: String) -> String {
    var result = text.replacingOccurrences(of: " ", with: "_")
    while result.contains("__") {
        result = result.replacingOccurrences(of: "__", with: "-")
    }
    return result
}
```
 // XCTAssertTrue failed

func fixSpaces(text: String) -> String {
    var result = text.replacingOccurrences(of: " ", with: "_")
    while result.contains("__") {
        result = result.replacingOccurrences(of: "__", with: "-")
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores, 
and if a string has more than 2 consecutive spaces, 
then replace all consecutive spaces with - 
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"[/INST]  ```swift
func fixSpaces(text: String) -> String {
    var result = text.replacingOccurrences(of: " ", with: "_")
    while result.contains("__") {
        result = result.replacingOccurrences(of: "__", with: "-")
    }
    return result
}
```
 // XCTAssertTrue failed

func fixSpaces(text: String) -> String {
    var result = text.replacingOccurrences(of: " ", with: "_")
    while result.contains("__") {
        result = result.replacingOccurrences(of: "__", with: "-")
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores, 
and if a string has more than 2 consecutive spaces, 
then replace all consecutive spaces with - 
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"[/INST]  ```swift
func fixSpaces(text: String) -> String {
    var result = text.replacingOccurrences(of: " ", with: "_")
    while result.contains("__") {
        result = result.replacingOccurrences(of: "__", with: "-")
    }
    return result
}
```
 // XCTAssertTrue failed

func fixSpaces(text: String) -> String {
    var result = text.replacingOccurrences(of: " ", with: "_")
    while result.contains("__") {
        result = result.replacingOccurrences(of: "__", with: "-")
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores, 
and if a string has more than 2 consecutive spaces, 
then replace all consecutive spaces with - 
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"[/INST]  ```swift
func fixSpaces(text: String) -> String {
    var result = text.replacingOccurrences(of: " ", with: "_")
    while result.contains("__") {
        result = result.replacingOccurrences(of: "__", with: "-")
    }
    return result
}
```
 // XCTAssertTrue failed

func fixSpaces(text: String) -> String {
    var result = text.replacingOccurrences(of: " ", with: "_")
    while result.contains("__") {
        result = result.replacingOccurrences(of: "__", with: "-")
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores, 
and if a string has more than 2 consecutive spaces, 
then replace all consecutive spaces with - 
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"[/INST]  ```swift
func fixSpaces(text: String) -> String {
    var result = text.replacingOccurrences(of: " ", with: "_")
    while result.contains("__") {
        result = result.replacingOccurrences(of: "__", with: "-")
    }
    return result
}
```
 // XCTAssertTrue failed

func fixSpaces(text: String) -> String {
    var result = text.replacingOccurrences(of: " ", with: "_")
    while result.contains("__") {
        result = result.replacingOccurrences(of: "__", with: "-")
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores, 
and if a string has more than 2 consecutive spaces, 
then replace all consecutive spaces with - 
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"[/INST]  ```swift
func fixSpaces(text: String) -> String {
    var result = text.replacingOccurrences(of: " ", with: "_")
    while result.contains("__") {
        result = result.replacingOccurrences(of: "__", with: "-")
    }
    return result
}
```
 // XCTAssertTrue failed

func fixSpaces(text: String) -> String {
    var result = text.replacingOccurrences(of: " ", with: "_")
    while result.contains("__") {
        result = result.replacingOccurrences(of: "__", with: "-")
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores, 
and if a string has more than 2 consecutive spaces, 
then replace all consecutive spaces with - 
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"[/INST]  ```swift
func fixSpaces(text: String) -> String {
    var result = text.replacingOccurrences(of: " ", with: "_")
    while result.contains("__") {
        result = result.replacingOccurrences(of: "__", with: "-")
    }
    return result
}
```
 // XCTAssertTrue failed

func fixSpaces(text: String) -> String {
    var result = text.replacingOccurrences(of: " ", with: "_")
    while result.contains("__") {
        result = result.replacingOccurrences(of: "__", with: "-")
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores, 
and if a string has more than 2 consecutive spaces, 
then replace all consecutive spaces with - 
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"[/INST]  ```swift
func fixSpaces(text: String) -> String {
    var result = text.replacingOccurrences(of: " ", with: "_")
    while result.contains("__") {
        result = result.replacingOccurrences(of: "__", with: "-")
    }
    return result
}
```
 // XCTAssertTrue failed

func fixSpaces(text: String) -> String {
    var result = text.replacingOccurrences(of: " ", with: "_")
    while result.contains("__") {
        result = result.replacingOccurrences(of: "__", with: "-")
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores, 
and if a string has more than 2 consecutive spaces, 
then replace all consecutive spaces with - 
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"[/INST]  ```swift
func fixSpaces(text: String) -> String {
    var result = text.replacingOccurrences(of: " ", with: "_")
    while result.contains("__") {
        result = result.replacingOccurrences(of: "__", with: "-")
    }
    return result
}
```
 // XCTAssertTrue failed

func fixSpaces(text: String) -> String {
    var result = text.replacingOccurrences(of: " ", with: "_")
    while result.contains("__") {
        result = result.replacingOccurrences(of: "__", with: "-")
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores, 
and if a string has more than 2 consecutive spaces, 
then replace all consecutive spaces with - 
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"[/INST]  ```swift
func fixSpaces(text: String) -> String {
    var result = text.replacingOccurrences(of: " ", with: "_")
    while result.contains("__") {
        result = result.replacingOccurrences(of: "__", with: "-")
    }
    return result
}
```
 // XCTAssertTrue failed

func fileNameCheck(fileName: String) -> String {
    let components = fileName.components(separatedBy: ".")
    guard components.count == 2 else {
        return "No"
    }

    let name = components[0]
    let extension = components[1]

    guard name.range(of: "^[a-zA-Z].*$", options: .regularExpression) != nil else {
        return "No"
    }

    guard name.filter({ $0.isNumber }).count <= 3 else {
        return "No"
    }

    guard ["txt", "exe", "dll"].contains(extension) else {
        return "No"
    }

    return "Yes"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions 
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from 
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"[/INST]  ```swift
func fileNameCheck(fileName: String) -> String {
    let components = fileName.components(separatedBy: ".")
    guard components.count == 2 else {
        return "No"
    }

    let name = components[0]
    let extension = components[1]

    guard name.range(of: "^[a-zA-Z].*$", options: .regularExpression) != nil else {
        return "No"
    }

    guard name.filter({ $0.isNumber }).count <= 3 else {
        return "No"
    }

    guard ["txt", "exe", "dll"].contains(extension) else {
        return "No"
    }

    return "Yes"
}
```
let extension = components[1] // keyword 'extension' cannot be used as an identifier here
guard ["txt", "exe", "dll"].contains(extension) else { // expected expression in list of expressions
guard ["txt", "exe", "dll"].contains(extension) else { // declaration is only valid at file scope
guard ["txt", "exe", "dll"].contains(extension) else { // expected '{' in extension
guard ["txt", "exe", "dll"].contains(extension) else { // missing argument for parameter 'where' in call
guard ["txt", "exe", "dll"].contains(extension) else { // expected type name in extension declaration

func fileNameCheck(fileName: String) -> String {
    let validExtensions = ["txt", "exe", "dll"]
    let components = fileName.components(separatedBy: ".")

    guard components.count == 2 else {
        return "No"
    }

    let name = components[0]
    let extension = components[1]

    guard let firstChar = name.first, firstChar.isLetter else {
        return "No"
    }

    guard name.filter({ $0.isNumber }).count <= 3 else {
        return "No"
    }

    guard validExtensions.contains(extension) else {
        return "No"
    }

    return "Yes"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions 
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from 
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"[/INST]  ```swift
func fileNameCheck(fileName: String) -> String {
    let validExtensions = ["txt", "exe", "dll"]
    let components = fileName.components(separatedBy: ".")

    guard components.count == 2 else {
        return "No"
    }

    let name = components[0]
    let extension = components[1]

    guard let firstChar = name.first, firstChar.isLetter else {
        return "No"
    }

    guard name.filter({ $0.isNumber }).count <= 3 else {
        return "No"
    }

    guard validExtensions.contains(extension) else {
        return "No"
    }

    return "Yes"
}
```
let extension = components[1] // keyword 'extension' cannot be used as an identifier here
guard validExtensions.contains(extension) else { // expected type name in extension declaration
guard validExtensions.contains(extension) else { // missing argument for parameter 'where' in call
guard validExtensions.contains(extension) else { // expected expression in list of expressions
guard validExtensions.contains(extension) else { // declaration is only valid at file scope
guard validExtensions.contains(extension) else { // expected '{' in extension

func fileNameCheck(fileName: String) -> String {
    let validExtensions = ["txt", "exe", "dll"]
    let components = fileName.components(separatedBy: ".")

    guard components.count == 2 else {
        return "No"
    }

    let name = components[0]
    let extension = components[1]

    guard let firstChar = name.first, firstChar.isLetter else {
        return "No"
    }

    guard name.filter({ $0.isNumber }).count <= 3 else {
        return "No"
    }

    guard validExtensions.contains(extension) else {
        return "No"
    }

    return "Yes"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions 
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from 
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"[/INST]  ```swift
func fileNameCheck(fileName: String) -> String {
    let validExtensions = ["txt", "exe", "dll"]
    let components = fileName.components(separatedBy: ".")

    guard components.count == 2 else {
        return "No"
    }

    let name = components[0]
    let extension = components[1]

    guard let firstChar = name.first, firstChar.isLetter else {
        return "No"
    }

    guard name.filter({ $0.isNumber }).count <= 3 else {
        return "No"
    }

    guard validExtensions.contains(extension) else {
        return "No"
    }

    return "Yes"
}
```
let extension = components[1] // keyword 'extension' cannot be used as an identifier here
guard validExtensions.contains(extension) else { // expected type name in extension declaration
guard validExtensions.contains(extension) else { // missing argument for parameter 'where' in call
guard validExtensions.contains(extension) else { // expected expression in list of expressions
guard validExtensions.contains(extension) else { // declaration is only valid at file scope
guard validExtensions.contains(extension) else { // expected '{' in extension

func fileNameCheck(fileName: String) -> String {
    let validExtensions = ["txt", "exe", "dll"]
    let components = fileName.components(separatedBy: ".")

    guard components.count == 2 else {
        return "No"
    }

    let name = components[0]
    let extension = components[1]

    guard let firstChar = name.first, firstChar.isLetter else {
        return "No"
    }

    guard name.filter({ $0.isNumber }).count <= 3 else {
        return "No"
    }

    guard validExtensions.contains(extension) else {
        return "No"
    }

    return "Yes"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions 
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from 
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"[/INST]  ```swift
func fileNameCheck(fileName: String) -> String {
    let validExtensions = ["txt", "exe", "dll"]
    let components = fileName.components(separatedBy: ".")

    guard components.count == 2 else {
        return "No"
    }

    let name = components[0]
    let extension = components[1]

    guard let firstChar = name.first, firstChar.isLetter else {
        return "No"
    }

    guard name.filter({ $0.isNumber }).count <= 3 else {
        return "No"
    }

    guard validExtensions.contains(extension) else {
        return "No"
    }

    return "Yes"
}
```
let extension = components[1] // keyword 'extension' cannot be used as an identifier here
guard validExtensions.contains(extension) else { // expected type name in extension declaration
guard validExtensions.contains(extension) else { // missing argument for parameter 'where' in call
guard validExtensions.contains(extension) else { // expected expression in list of expressions
guard validExtensions.contains(extension) else { // declaration is only valid at file scope
guard validExtensions.contains(extension) else { // expected '{' in extension

func fileNameCheck(fileName: String) -> String {
    let validExtensions = ["txt", "exe", "dll"]
    let components = fileName.components(separatedBy: ".")

    guard components.count == 2 else {
        return "No"
    }

    let name = components[0]
    let extension = components[1]

    guard let firstChar = name.first, firstChar.isLetter else {
        return "No"
    }

    guard name.filter({ $0.isNumber }).count <= 3 else {
        return "No"
    }

    guard validExtensions.contains(extension) else {
        return "No"
    }

    return "Yes"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions 
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from 
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"[/INST]  ```swift
func fileNameCheck(fileName: String) -> String {
    let validExtensions = ["txt", "exe", "dll"]
    let components = fileName.components(separatedBy: ".")

    guard components.count == 2 else {
        return "No"
    }

    let name = components[0]
    let extension = components[1]

    guard let firstChar = name.first, firstChar.isLetter else {
        return "No"
    }

    guard name.filter({ $0.isNumber }).count <= 3 else {
        return "No"
    }

    guard validExtensions.contains(extension) else {
        return "No"
    }

    return "Yes"
}
```
let extension = components[1] // keyword 'extension' cannot be used as an identifier here
guard validExtensions.contains(extension) else { // expected type name in extension declaration
guard validExtensions.contains(extension) else { // missing argument for parameter 'where' in call
guard validExtensions.contains(extension) else { // expected expression in list of expressions
guard validExtensions.contains(extension) else { // declaration is only valid at file scope
guard validExtensions.contains(extension) else { // expected '{' in extension

func fileNameCheck(fileName: String) -> String {
    let components = fileName.components(separatedBy: ".")
    guard components.count == 2 else {
        return "No"
    }

    let name = components[0]
    let extension = components[1]

    guard let firstChar = name.first, firstChar.isLetter else {
        return "No"
    }

    let digitCount = name.filter { $0.isNumber }.count
    guard digitCount <= 3 else {
        return "No"
    }

    guard ["txt", "exe", "dll"].contains(extension) else {
        return "No"
    }

    return "Yes"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions 
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from 
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"[/INST]  ```swift
func fileNameCheck(fileName: String) -> String {
    let components = fileName.components(separatedBy: ".")
    guard components.count == 2 else {
        return "No"
    }

    let name = components[0]
    let extension = components[1]

    guard let firstChar = name.first, firstChar.isLetter else {
        return "No"
    }

    let digitCount = name.filter { $0.isNumber }.count
    guard digitCount <= 3 else {
        return "No"
    }

    guard ["txt", "exe", "dll"].contains(extension) else {
        return "No"
    }

    return "Yes"
}
```
let extension = components[1] // keyword 'extension' cannot be used as an identifier here
guard ["txt", "exe", "dll"].contains(extension) else { // missing argument for parameter 'where' in call
guard ["txt", "exe", "dll"].contains(extension) else { // expected type name in extension declaration
guard ["txt", "exe", "dll"].contains(extension) else { // expected expression in list of expressions
guard ["txt", "exe", "dll"].contains(extension) else { // expected '{' in extension
guard ["txt", "exe", "dll"].contains(extension) else { // declaration is only valid at file scope

func fileNameCheck(fileName: String) -> String {
    let validExtensions = ["txt", "exe", "dll"]
    let components = fileName.components(separatedBy: ".")

    guard components.count == 2 else {
        return "No"
    }

    let name = components[0]
    let extension = components[1]

    guard let firstChar = name.first, firstChar.isLetter else {
        return "No"
    }

    guard name.filter({ $0.isNumber }).count <= 3 else {
        return "No"
    }

    guard validExtensions.contains(extension) else {
        return "No"
    }

    return "Yes"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions 
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from 
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"[/INST]  ```swift
func fileNameCheck(fileName: String) -> String {
    let validExtensions = ["txt", "exe", "dll"]
    let components = fileName.components(separatedBy: ".")

    guard components.count == 2 else {
        return "No"
    }

    let name = components[0]
    let extension = components[1]

    guard let firstChar = name.first, firstChar.isLetter else {
        return "No"
    }

    guard name.filter({ $0.isNumber }).count <= 3 else {
        return "No"
    }

    guard validExtensions.contains(extension) else {
        return "No"
    }

    return "Yes"
}
```
let extension = components[1] // keyword 'extension' cannot be used as an identifier here
guard validExtensions.contains(extension) else { // expected type name in extension declaration
guard validExtensions.contains(extension) else { // missing argument for parameter 'where' in call
guard validExtensions.contains(extension) else { // expected expression in list of expressions
guard validExtensions.contains(extension) else { // declaration is only valid at file scope
guard validExtensions.contains(extension) else { // expected '{' in extension

func fileNameCheck(fileName: String) -> String {
    let validExtensions = ["txt", "exe", "dll"]
    let components = fileName.components(separatedBy: ".")

    guard components.count == 2,
          let prefix = components.first,
          let suffix = components.last,
          !prefix.isEmpty,
          prefix.first!.isLetter,
          validExtensions.contains(suffix),
          fileName.filter({ $0.isNumber }).count <= 3 else {
        return "No"
    }

    return "Yes"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions 
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from 
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"[/INST]  ```swift
func fileNameCheck(fileName: String) -> String {
    let validExtensions = ["txt", "exe", "dll"]
    let components = fileName.components(separatedBy: ".")

    guard components.count == 2,
          let prefix = components.first,
          let suffix = components.last,
          !prefix.isEmpty,
          prefix.first!.isLetter,
          validExtensions.contains(suffix),
          fileName.filter({ $0.isNumber }).count <= 3 else {
        return "No"
    }

    return "Yes"
}
```

func fileNameCheck(fileName: String) -> String {
    let validExtensions = ["txt", "exe", "dll"]
    let components = fileName.components(separatedBy: ".")

    guard components.count == 2 else {
        return "No"
    }

    let name = components[0]
    let ext = components[1]

    guard let firstChar = name.first, firstChar.isLetter else {
        return "No"
    }

    guard name.filter({ $0.isNumber }).count <= 3 else {
        return "No"
    }

    guard validExtensions.contains(ext) else {
        return "No"
    }

    return "Yes"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions 
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from 
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"[/INST]  ```swift
func fileNameCheck(fileName: String) -> String {
    let validExtensions = ["txt", "exe", "dll"]
    let components = fileName.components(separatedBy: ".")

    guard components.count == 2 else {
        return "No"
    }

    let name = components[0]
    let ext = components[1]

    guard let firstChar = name.first, firstChar.isLetter else {
        return "No"
    }

    guard name.filter({ $0.isNumber }).count <= 3 else {
        return "No"
    }

    guard validExtensions.contains(ext) else {
        return "No"
    }

    return "Yes"
}
```

func fileNameCheck(fileName: String) -> String {
    let validExtensions = ["txt", "exe", "dll"]
    let components = fileName.components(separatedBy: ".")

    guard components.count == 2,
          let prefix = components.first,
          let suffix = components.last,
          !prefix.isEmpty,
          validExtensions.contains(suffix),
          prefix.range(of: "^[a-zA-Z].*", options: .regularExpression) != nil,
          fileName.filter({ $0.isNumber }).count <= 3 else {
        return "No"
    }

    return "Yes"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions 
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from 
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"[/INST]  ```swift
func fileNameCheck(fileName: String) -> String {
    let validExtensions = ["txt", "exe", "dll"]
    let components = fileName.components(separatedBy: ".")

    guard components.count == 2,
          let prefix = components.first,
          let suffix = components.last,
          !prefix.isEmpty,
          validExtensions.contains(suffix),
          prefix.range(of: "^[a-zA-Z].*", options: .regularExpression) != nil,
          fileName.filter({ $0.isNumber }).count <= 3 else {
        return "No"
    }

    return "Yes"
}
```

func wordsInSentence(sentence: String) -> String {
    let words = sentence.split(separator: " ")
    var primeWords: [String] = []

    for word in words {
        if isPrime(word.count) {
            primeWords.append(String(word))
        }
    }

    return primeWords.joined(separator: " ")
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }

    for i in 2..<number {
        if number % i == 0 {
            return false
        }
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"[/INST]  ```swift
func wordsInSentence(sentence: String) -> String {
    let words = sentence.split(separator: " ")
    var primeWords: [String] = []

    for word in words {
        if isPrime(word.count) {
            primeWords.append(String(word))
        }
    }

    return primeWords.joined(separator: " ")
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }

    for i in 2..<number {
        if number % i == 0 {
            return false
        }
    }

    return true
}
```

func wordsInSentence(sentence: String) -> String {
    func isPrime(_ number: Int) -> Bool {
        if number <= 1 {
            return false
        }
        if number <= 3 {
            return true
        }
        var i = 2
        while i * i <= number {
            if number % i == 0 {
                return false
            }
            i = i + 1
        }
        return true
    }

    let words = sentence.split(separator: " ")
    var primeWords: [String] = []
    for word in words {
        if isPrime(word.count) {
            primeWords.append(String(word))
        }
    }
    return primeWords.joined(separator: " ")
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"[/INST]  ```swift
func wordsInSentence(sentence: String) -> String {
    func isPrime(_ number: Int) -> Bool {
        if number <= 1 {
            return false
        }
        if number <= 3 {
            return true
        }
        var i = 2
        while i * i <= number {
            if number % i == 0 {
                return false
            }
            i = i + 1
        }
        return true
    }

    let words = sentence.split(separator: " ")
    var primeWords: [String] = []
    for word in words {
        if isPrime(word.count) {
            primeWords.append(String(word))
        }
    }
    return primeWords.joined(separator: " ")
}
```

func wordsInSentence(sentence: String) -> String {
    func isPrime(_ n: Int) -> Bool {
        if n <= 1 {
            return false
        }
        if n <= 3 {
            return true
        }
        var i = 2
        while i * i <= n {
            if n % i == 0 {
                return false
            }
            i = i + 1
        }
        return true
    }

    let words = sentence.split(separator: " ")
    var primeWords: [String] = []
    for word in words {
        if isPrime(word.count) {
            primeWords.append(String(word))
        }
    }
    return primeWords.joined(separator: " ")
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"[/INST]  ```swift
func wordsInSentence(sentence: String) -> String {
    func isPrime(_ n: Int) -> Bool {
        if n <= 1 {
            return false
        }
        if n <= 3 {
            return true
        }
        var i = 2
        while i * i <= n {
            if n % i == 0 {
                return false
            }
            i = i + 1
        }
        return true
    }

    let words = sentence.split(separator: " ")
    var primeWords: [String] = []
    for word in words {
        if isPrime(word.count) {
            primeWords.append(String(word))
        }
    }
    return primeWords.joined(separator: " ")
}
```

func wordsInSentence(sentence: String) -> String {
    let words = sentence.split(separator: " ")
    var primeWords = [String]()

    for word in words {
        if isPrime(word.count) {
            primeWords.append(String(word))
        }
    }

    return primeWords.joined(separator: " ")
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }

    if number <= 3 {
        return true
    }

    if number % 2 == 0 || number % 3 == 0 {
        return false
    }

    var i = 5
    while i * i <= number {
        if number % i == 0 || number % (i + 2) == 0 {
            return false
        }
        i += 6
    }

    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"[/INST]  ```swift
func wordsInSentence(sentence: String) -> String {
    let words = sentence.split(separator: " ")
    var primeWords = [String]()

    for word in words {
        if isPrime(word.count) {
            primeWords.append(String(word))
        }
    }

    return primeWords.joined(separator: " ")
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }

    if number <= 3 {
        return true
    }

    if number % 2 == 0 || number % 3 == 0 {
        return false
    }

    var i = 5
    while i * i <= number {
        if number % i == 0 || number % (i + 2) == 0 {
            return false
        }
        i += 6
    }

    return true
}
```

func wordsInSentence(sentence: String) -> String {
    func isPrime(_ number: Int) -> Bool {
        if number <= 1 {
            return false
        }
        if number <= 3 {
            return true
        }
        var i = 2
        while i * i <= number {
            if number % i == 0 {
                return false
            }
            i = i + 1
        }
        return true
    }

    let words = sentence.split(separator: " ")
    var primeWords: [String] = []
    for word in words {
        if isPrime(word.count) {
            primeWords.append(String(word))
        }
    }
    return primeWords.joined(separator: " ")
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"[/INST]  ```swift
func wordsInSentence(sentence: String) -> String {
    func isPrime(_ number: Int) -> Bool {
        if number <= 1 {
            return false
        }
        if number <= 3 {
            return true
        }
        var i = 2
        while i * i <= number {
            if number % i == 0 {
                return false
            }
            i = i + 1
        }
        return true
    }

    let words = sentence.split(separator: " ")
    var primeWords: [String] = []
    for word in words {
        if isPrime(word.count) {
            primeWords.append(String(word))
        }
    }
    return primeWords.joined(separator: " ")
}
```

func wordsInSentence(sentence: String) -> String {
    func isPrime(_ n: Int) -> Bool {
        if n <= 1 {
            return false
        }
        if n <= 3 {
            return true
        }
        var i = 2
        while i * i <= n {
            if n % i == 0 {
                return false
            }
            i = i + 1
        }
        return true
    }

    let words = sentence.split(separator: " ")
    var primeWords: [String] = []
    for word in words {
        if isPrime(word.count) {
            primeWords.append(String(word))
        }
    }
    return primeWords.joined(separator: " ")
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"[/INST]  ```swift
func wordsInSentence(sentence: String) -> String {
    func isPrime(_ n: Int) -> Bool {
        if n <= 1 {
            return false
        }
        if n <= 3 {
            return true
        }
        var i = 2
        while i * i <= n {
            if n % i == 0 {
                return false
            }
            i = i + 1
        }
        return true
    }

    let words = sentence.split(separator: " ")
    var primeWords: [String] = []
    for word in words {
        if isPrime(word.count) {
            primeWords.append(String(word))
        }
    }
    return primeWords.joined(separator: " ")
}
```

func wordsInSentence(sentence: String) -> String {
    func isPrime(_ n: Int) -> Bool {
        if n <= 1 {
            return false
        }
        if n <= 3 {
            return true
        }
        var i = 2
        while i * i <= n {
            if n % i == 0 {
                return false
            }
            i = i + 1
        }
        return true
    }

    let words = sentence.split(separator: " ")
    var primeWords: [String] = []
    for word in words {
        if isPrime(word.count) {
            primeWords.append(String(word))
        }
    }
    return primeWords.joined(separator: " ")
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"[/INST]  ```swift
func wordsInSentence(sentence: String) -> String {
    func isPrime(_ n: Int) -> Bool {
        if n <= 1 {
            return false
        }
        if n <= 3 {
            return true
        }
        var i = 2
        while i * i <= n {
            if n % i == 0 {
                return false
            }
            i = i + 1
        }
        return true
    }

    let words = sentence.split(separator: " ")
    var primeWords: [String] = []
    for word in words {
        if isPrime(word.count) {
            primeWords.append(String(word))
        }
    }
    return primeWords.joined(separator: " ")
}
```

func wordsInSentence(sentence: String) -> String {
    func isPrime(_ number: Int) -> Bool {
        if number <= 1 {
            return false
        }
        if number <= 3 {
            return true
        }
        var i = 2
        while i * i <= number {
            if number % i == 0 {
                return false
            }
            i = i + 1
        }
        return true
    }

    let words = sentence.split(separator: " ")
    var primeWords: [String] = []
    for word in words {
        if isPrime(word.count) {
            primeWords.append(String(word))
        }
    }
    return primeWords.joined(separator: " ")
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"[/INST]  ```swift
func wordsInSentence(sentence: String) -> String {
    func isPrime(_ number: Int) -> Bool {
        if number <= 1 {
            return false
        }
        if number <= 3 {
            return true
        }
        var i = 2
        while i * i <= number {
            if number % i == 0 {
                return false
            }
            i = i + 1
        }
        return true
    }

    let words = sentence.split(separator: " ")
    var primeWords: [String] = []
    for word in words {
        if isPrime(word.count) {
            primeWords.append(String(word))
        }
    }
    return primeWords.joined(separator: " ")
}
```

func wordsInSentence(sentence: String) -> String {
    func isPrime(_ number: Int) -> Bool {
        if number <= 1 {
            return false
        }
        if number <= 3 {
            return true
        }
        var i = 2
        while i * i <= number {
            if number % i == 0 {
                return false
            }
            i = i + 1
        }
        return true
    }

    let words = sentence.split(separator: " ")
    var primeWords: [String] = []

    for word in words {
        if isPrime(word.count) {
            primeWords.append(String(word))
        }
    }

    return primeWords.joined(separator: " ")
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"[/INST]  ```swift
func wordsInSentence(sentence: String) -> String {
    func isPrime(_ number: Int) -> Bool {
        if number <= 1 {
            return false
        }
        if number <= 3 {
            return true
        }
        var i = 2
        while i * i <= number {
            if number % i == 0 {
                return false
            }
            i = i + 1
        }
        return true
    }

    let words = sentence.split(separator: " ")
    var primeWords: [String] = []

    for word in words {
        if isPrime(word.count) {
            primeWords.append(String(word))
        }
    }

    return primeWords.joined(separator: " ")
}
```

func wordsInSentence(sentence: String) -> String {
    func isPrime(_ n: Int) -> Bool {
        if n <= 1 {
            return false
        }
        if n <= 3 {
            return true
        }
        var i = 2
        while i * i <= n {
            if n % i == 0 {
                return false
            }
            i = i + 1
        }
        return true
    }

    let words = sentence.split(separator: " ")
    var primeWords: [String] = []

    for word in words {
        if isPrime(word.count) {
            primeWords.append(String(word))
        }
    }

    return primeWords.joined(separator: " ")
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"[/INST]  ```swift
func wordsInSentence(sentence: String) -> String {
    func isPrime(_ n: Int) -> Bool {
        if n <= 1 {
            return false
        }
        if n <= 3 {
            return true
        }
        var i = 2
        while i * i <= n {
            if n % i == 0 {
                return false
            }
            i = i + 1
        }
        return true
    }

    let words = sentence.split(separator: " ")
    var primeWords: [String] = []

    for word in words {
        if isPrime(word.count) {
            primeWords.append(String(word))
        }
    }

    return primeWords.joined(separator: " ")
}
```

func simplify(x: String, n: String) -> Bool {
    let xComponents = x.split(separator: "/").map { Int($0)! }
    let nComponents = n.split(separator: "/").map { Int($0)! }

    let numerator = xComponents[0] * nComponents[0]
    let denominator = xComponents[1] * nComponents[1]

    return numerator % denominator == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false[/INST]  ```swift
func simplify(x: String, n: String) -> Bool {
    let xComponents = x.split(separator: "/").map { Int($0)! }
    let nComponents = n.split(separator: "/").map { Int($0)! }

    let numerator = xComponents[0] * nComponents[0]
    let denominator = xComponents[1] * nComponents[1]

    return numerator % denominator == 0
}
```

func simplify(x: String, n: String) -> Bool {
    let xComponents = x.split(separator: "/").map { Int($0)! }
    let nComponents = n.split(separator: "/").map { Int($0)! }

    let resultNumerator = xComponents[0] * nComponents[0]
    let resultDenominator = xComponents[1] * nComponents[1]

    return resultNumerator % resultDenominator == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false[/INST]  ```swift
func simplify(x: String, n: String) -> Bool {
    let xComponents = x.split(separator: "/").map { Int($0)! }
    let nComponents = n.split(separator: "/").map { Int($0)! }

    let resultNumerator = xComponents[0] * nComponents[0]
    let resultDenominator = xComponents[1] * nComponents[1]

    return resultNumerator % resultDenominator == 0
}
```

func simplify(x: String, n: String) -> Bool {
    let xComponents = x.split(separator: "/").map { Int($0)! }
    let nComponents = n.split(separator: "/").map { Int($0)! }

    let numerator = xComponents[0] * nComponents[0]
    let denominator = xComponents[1] * nComponents[1]

    return numerator % denominator == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false[/INST]  ```swift
func simplify(x: String, n: String) -> Bool {
    let xComponents = x.split(separator: "/").map { Int($0)! }
    let nComponents = n.split(separator: "/").map { Int($0)! }

    let numerator = xComponents[0] * nComponents[0]
    let denominator = xComponents[1] * nComponents[1]

    return numerator % denominator == 0
}
```

func simplify(x: String, n: String) -> Bool {
    let xComponents = x.split(separator: "/").map { Int($0)! }
    let nComponents = n.split(separator: "/").map { Int($0)! }

    let numerator = xComponents[0] * nComponents[0]
    let denominator = xComponents[1] * nComponents[1]

    return numerator % denominator == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false[/INST]  ```swift
func simplify(x: String, n: String) -> Bool {
    let xComponents = x.split(separator: "/").map { Int($0)! }
    let nComponents = n.split(separator: "/").map { Int($0)! }

    let numerator = xComponents[0] * nComponents[0]
    let denominator = xComponents[1] * nComponents[1]

    return numerator % denominator == 0
}
```

func simplify(x: String, n: String) -> Bool {
    let xComponents = x.split(separator: "/").map { Int($0)! }
    let nComponents = n.split(separator: "/").map { Int($0)! }

    let numerator = xComponents[0] * nComponents[0]
    let denominator = xComponents[1] * nComponents[1]

    return numerator % denominator == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false[/INST]  ```swift
func simplify(x: String, n: String) -> Bool {
    let xComponents = x.split(separator: "/").map { Int($0)! }
    let nComponents = n.split(separator: "/").map { Int($0)! }

    let numerator = xComponents[0] * nComponents[0]
    let denominator = xComponents[1] * nComponents[1]

    return numerator % denominator == 0
}
```

func simplify(x: String, n: String) -> Bool {
    let xComponents = x.split(separator: "/").map { Int($0)! }
    let nComponents = n.split(separator: "/").map { Int($0)! }

    let numerator = xComponents[0] * nComponents[0]
    let denominator = xComponents[1] * nComponents[1]

    return numerator % denominator == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false[/INST]  ```swift
func simplify(x: String, n: String) -> Bool {
    let xComponents = x.split(separator: "/").map { Int($0)! }
    let nComponents = n.split(separator: "/").map { Int($0)! }

    let numerator = xComponents[0] * nComponents[0]
    let denominator = xComponents[1] * nComponents[1]

    return numerator % denominator == 0
}
```

func simplify(x: String, n: String) -> Bool {
    let xComponents = x.split(separator: "/").map { Int($0)! }
    let nComponents = n.split(separator: "/").map { Int($0)! }

    let numerator = xComponents[0] * nComponents[0]
    let denominator = xComponents[1] * nComponents[1]

    return numerator % denominator == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false[/INST]  ```swift
func simplify(x: String, n: String) -> Bool {
    let xComponents = x.split(separator: "/").map { Int($0)! }
    let nComponents = n.split(separator: "/").map { Int($0)! }

    let numerator = xComponents[0] * nComponents[0]
    let denominator = xComponents[1] * nComponents[1]

    return numerator % denominator == 0
}
```

func simplify(x: String, n: String) -> Bool {
    let xComponents = x.split(separator: "/").map { Int($0)! }
    let nComponents = n.split(separator: "/").map { Int($0)! }

    let numerator = xComponents[0] * nComponents[0]
    let denominator = xComponents[1] * nComponents[1]

    return numerator % denominator == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false[/INST]  ```swift
func simplify(x: String, n: String) -> Bool {
    let xComponents = x.split(separator: "/").map { Int($0)! }
    let nComponents = n.split(separator: "/").map { Int($0)! }

    let numerator = xComponents[0] * nComponents[0]
    let denominator = xComponents[1] * nComponents[1]

    return numerator % denominator == 0
}
```

func simplify(x: String, n: String) -> Bool {
    let xComponents = x.split(separator: "/").map { Int($0)! }
    let nComponents = n.split(separator: "/").map { Int($0)! }

    let numerator = xComponents[0] * nComponents[0]
    let denominator = xComponents[1] * nComponents[1]

    return numerator % denominator == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false[/INST]  ```swift
func simplify(x: String, n: String) -> Bool {
    let xComponents = x.split(separator: "/").map { Int($0)! }
    let nComponents = n.split(separator: "/").map { Int($0)! }

    let numerator = xComponents[0] * nComponents[0]
    let denominator = xComponents[1] * nComponents[1]

    return numerator % denominator == 0
}
```

func simplify(x: String, n: String) -> Bool {
    let xComponents = x.split(separator: "/").map { Int($0)! }
    let nComponents = n.split(separator: "/").map { Int($0)! }

    let numerator = xComponents[0] * nComponents[0]
    let denominator = xComponents[1] * nComponents[1]

    return numerator % denominator == 0
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false[/INST]  ```swift
func simplify(x: String, n: String) -> Bool {
    let xComponents = x.split(separator: "/").map { Int($0)! }
    let nComponents = n.split(separator: "/").map { Int($0)! }

    let numerator = xComponents[0] * nComponents[0]
    let denominator = xComponents[1] * nComponents[1]

    return numerator % denominator == 0
}
```

func orderByPoints(nums: [Int]) -> [Int] {
    return nums.sorted {
        let sum1 = String($0).reduce(0, { $0 + Int(String($1))! })
        let sum2 = String($1).reduce(0, { $0 + Int(String($1))! })
        if sum1 == sum2 {
            return nums.firstIndex(of: $0)! < nums.firstIndex(of: $1)!
        }
        return sum1 < sum2
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int][/INST]  ```swift
func orderByPoints(nums: [Int]) -> [Int] {
    return nums.sorted {
        let sum1 = String($0).reduce(0, { $0 + Int(String($1))! })
        let sum2 = String($1).reduce(0, { $0 + Int(String($1))! })
        if sum1 == sum2 {
            return nums.firstIndex(of: $0)! < nums.firstIndex(of: $1)!
        }
        return sum1 < sum2
    }
}
```
 // Fatal error: Unexpectedly found nil while unwrapping an Optional value

func orderByPoints(nums: [Int]) -> [Int] {
    return nums.sorted {
        let sum1 = String($0).reduce(0, { $0 + Int(String($1))! })
        let sum2 = String($1).reduce(0, { $0 + Int(String($1))! })
        if sum1 == sum2 {
            return nums.firstIndex(of: $0)! < nums.firstIndex(of: $1)!
        }
        return sum1 < sum2
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int][/INST]  ```swift
func orderByPoints(nums: [Int]) -> [Int] {
    return nums.sorted {
        let sum1 = String($0).reduce(0, { $0 + Int(String($1))! })
        let sum2 = String($1).reduce(0, { $0 + Int(String($1))! })
        if sum1 == sum2 {
            return nums.firstIndex(of: $0)! < nums.firstIndex(of: $1)!
        }
        return sum1 < sum2
    }
}
```
 // Fatal error: Unexpectedly found nil while unwrapping an Optional value

func orderByPoints(nums: [Int]) -> [Int] {
    return nums.sorted {
        let sum1 = String($0).reduce(0, { $0 + Int(String($1))! })
        let sum2 = String($1).reduce(0, { $0 + Int(String($1))! })
        if sum1 == sum2 {
            return nums.firstIndex(of: $0)! < nums.firstIndex(of: $1)!
        } else {
            return sum1 < sum2
        }
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int][/INST]  ```swift
func orderByPoints(nums: [Int]) -> [Int] {
    return nums.sorted {
        let sum1 = String($0).reduce(0, { $0 + Int(String($1))! })
        let sum2 = String($1).reduce(0, { $0 + Int(String($1))! })
        if sum1 == sum2 {
            return nums.firstIndex(of: $0)! < nums.firstIndex(of: $1)!
        } else {
            return sum1 < sum2
        }
    }
}
```
 // Fatal error: Unexpectedly found nil while unwrapping an Optional value

func orderByPoints(nums: [Int]) -> [Int] {
    return nums.sorted {
        let sum1 = String($0).reduce(0, { $0 + Int(String($1))! })
        let sum2 = String($1).reduce(0, { $0 + Int(String($1))! })
        if sum1 == sum2 {
            return nums.firstIndex(of: $0)! < nums.firstIndex(of: $1)!
        } else {
            return sum1 < sum2
        }
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int][/INST]  ```swift
func orderByPoints(nums: [Int]) -> [Int] {
    return nums.sorted {
        let sum1 = String($0).reduce(0, { $0 + Int(String($1))! })
        let sum2 = String($1).reduce(0, { $0 + Int(String($1))! })
        if sum1 == sum2 {
            return nums.firstIndex(of: $0)! < nums.firstIndex(of: $1)!
        } else {
            return sum1 < sum2
        }
    }
}
```
 // Fatal error: Unexpectedly found nil while unwrapping an Optional value

func orderByPoints(nums: [Int]) -> [Int] {
    return nums.sorted {
        let sum1 = String($0).reduce(0, { $0 + Int(String($1))! })
        let sum2 = String($1).reduce(0, { $0 + Int(String($1))! })
        if sum1 != sum2 {
            return sum1 < sum2
        } else {
            return nums.firstIndex(of: $0)! < nums.firstIndex(of: $1)!
        }
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int][/INST]  ```swift
func orderByPoints(nums: [Int]) -> [Int] {
    return nums.sorted {
        let sum1 = String($0).reduce(0, { $0 + Int(String($1))! })
        let sum2 = String($1).reduce(0, { $0 + Int(String($1))! })
        if sum1 != sum2 {
            return sum1 < sum2
        } else {
            return nums.firstIndex(of: $0)! < nums.firstIndex(of: $1)!
        }
    }
}
```
 // Fatal error: Unexpectedly found nil while unwrapping an Optional value

func orderByPoints(nums: [Int]) -> [Int] {
    return nums.sorted {
        let sum1 = String($0).reduce(0, { $0 + Int(String($1))! })
        let sum2 = String($1).reduce(0, { $0 + Int(String($1))! })
        if sum1 == sum2 {
            return nums.firstIndex(of: $0)! < nums.firstIndex(of: $1)!
        }
        return sum1 < sum2
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int][/INST]  ```swift
func orderByPoints(nums: [Int]) -> [Int] {
    return nums.sorted {
        let sum1 = String($0).reduce(0, { $0 + Int(String($1))! })
        let sum2 = String($1).reduce(0, { $0 + Int(String($1))! })
        if sum1 == sum2 {
            return nums.firstIndex(of: $0)! < nums.firstIndex(of: $1)!
        }
        return sum1 < sum2
    }
}
```
 // Fatal error: Unexpectedly found nil while unwrapping an Optional value

func orderByPoints(nums: [Int]) -> [Int] {
    return nums.sorted {
        let sum1 = String($0).reduce(0, { $0 + Int(String($1))! })
        let sum2 = String($1).reduce(0, { $0 + Int(String($1))! })
        if sum1 == sum2 {
            return nums.firstIndex(of: $0)! < nums.firstIndex(of: $1)!
        }
        return sum1 < sum2
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int][/INST]  ```swift
func orderByPoints(nums: [Int]) -> [Int] {
    return nums.sorted {
        let sum1 = String($0).reduce(0, { $0 + Int(String($1))! })
        let sum2 = String($1).reduce(0, { $0 + Int(String($1))! })
        if sum1 == sum2 {
            return nums.firstIndex(of: $0)! < nums.firstIndex(of: $1)!
        }
        return sum1 < sum2
    }
}
```
 // Fatal error: Unexpectedly found nil while unwrapping an Optional value

func orderByPoints(nums: [Int]) -> [Int] {
    return nums.sorted {
        let sum1 = String($0).reduce(0, { $0 + Int(String($1))! })
        let sum2 = String($1).reduce(0, { $0 + Int(String($1))! })
        if sum1 == sum2 {
            return nums.firstIndex(of: $0)! < nums.firstIndex(of: $1)!
        } else {
            return sum1 < sum2
        }
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int][/INST]  ```swift
func orderByPoints(nums: [Int]) -> [Int] {
    return nums.sorted {
        let sum1 = String($0).reduce(0, { $0 + Int(String($1))! })
        let sum2 = String($1).reduce(0, { $0 + Int(String($1))! })
        if sum1 == sum2 {
            return nums.firstIndex(of: $0)! < nums.firstIndex(of: $1)!
        } else {
            return sum1 < sum2
        }
    }
}
```
 // Fatal error: Unexpectedly found nil while unwrapping an Optional value

func orderByPoints(nums: [Int]) -> [Int] {
    return nums.sorted {
        let sum1 = String($0).reduce(0, { $0 + Int(String($1))! })
        let sum2 = String($1).reduce(0, { $0 + Int(String($1))! })
        if sum1 == sum2 {
            return nums.firstIndex(of: $0)! < nums.firstIndex(of: $1)!
        }
        return sum1 < sum2
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int][/INST]  ```swift
func orderByPoints(nums: [Int]) -> [Int] {
    return nums.sorted {
        let sum1 = String($0).reduce(0, { $0 + Int(String($1))! })
        let sum2 = String($1).reduce(0, { $0 + Int(String($1))! })
        if sum1 == sum2 {
            return nums.firstIndex(of: $0)! < nums.firstIndex(of: $1)!
        }
        return sum1 < sum2
    }
}
```
 // Fatal error: Unexpectedly found nil while unwrapping an Optional value

func orderByPoints(nums: [Int]) -> [Int] {
    return nums.sorted { (a, b) -> Bool in
        let sumA = String(abs(a)).reduce(0, { $0 + Int(String($1))! })
        let sumB = String(abs(b)).reduce(0, { $0 + Int(String($1))! })
        if sumA == sumB {
            return nums.firstIndex(of: a)! < nums.firstIndex(of: b)!
        }
        return sumA < sumB
    }
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int][/INST]  ```swift
func orderByPoints(nums: [Int]) -> [Int] {
    return nums.sorted { (a, b) -> Bool in
        let sumA = String(abs(a)).reduce(0, { $0 + Int(String($1))! })
        let sumB = String(abs(b)).reduce(0, { $0 + Int(String($1))! })
        if sumA == sumB {
            return nums.firstIndex(of: a)! < nums.firstIndex(of: b)!
        }
        return sumA < sumB
    }
}
```
 // XCTAssertTrue failed

func specialFilter(nums: [Int]) -> Int {
    var count = 0
    for num in nums {
        if num > 10 {
            let firstDigit = abs(num) / 10 % 10
            let lastDigit = abs(num) % 10
            if firstDigit % 2 != 0 && lastDigit % 2 != 0 {
                count += 1
            }
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns 
the number of elements in the array that are greater than 10 and both 
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2[/INST]  ```swift
func specialFilter(nums: [Int]) -> Int {
    var count = 0
    for num in nums {
        if num > 10 {
            let firstDigit = abs(num) / 10 % 10
            let lastDigit = abs(num) % 10
            if firstDigit % 2 != 0 && lastDigit % 2 != 0 {
                count += 1
            }
        }
    }
    return count
}
```
 // XCTAssertTrue failed

func specialFilter(nums: [Int]) -> Int {
    var count = 0
    for num in nums {
        if num > 10 {
            let firstDigit = abs(num / 10) % 10
            let lastDigit = abs(num % 10)
            if firstDigit % 2 != 0 && lastDigit % 2 != 0 {
                count += 1
            }
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns 
the number of elements in the array that are greater than 10 and both 
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2[/INST]  ```swift
func specialFilter(nums: [Int]) -> Int {
    var count = 0
    for num in nums {
        if num > 10 {
            let firstDigit = abs(num / 10) % 10
            let lastDigit = abs(num % 10)
            if firstDigit % 2 != 0 && lastDigit % 2 != 0 {
                count += 1
            }
        }
    }
    return count
}
```
 // XCTAssertTrue failed

func specialFilter(nums: [Int]) -> Int {
    var count = 0
    for num in nums {
        if num > 10 {
            let firstDigit = abs(num) / 10 % 10
            let lastDigit = abs(num) % 10
            if firstDigit % 2 != 0 && lastDigit % 2 != 0 {
                count += 1
            }
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns 
the number of elements in the array that are greater than 10 and both 
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2[/INST]  ```swift
func specialFilter(nums: [Int]) -> Int {
    var count = 0
    for num in nums {
        if num > 10 {
            let firstDigit = abs(num) / 10 % 10
            let lastDigit = abs(num) % 10
            if firstDigit % 2 != 0 && lastDigit % 2 != 0 {
                count += 1
            }
        }
    }
    return count
}
```
 // XCTAssertTrue failed

func specialFilter(nums: [Int]) -> Int {
    var count = 0
    for num in nums {
        if num > 10 {
            let firstDigit = abs(num) / 10 % 10
            let lastDigit = abs(num) % 10
            if firstDigit % 2 != 0 && lastDigit % 2 != 0 {
                count += 1
            }
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns 
the number of elements in the array that are greater than 10 and both 
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2[/INST]  ```swift
func specialFilter(nums: [Int]) -> Int {
    var count = 0
    for num in nums {
        if num > 10 {
            let firstDigit = abs(num) / 10 % 10
            let lastDigit = abs(num) % 10
            if firstDigit % 2 != 0 && lastDigit % 2 != 0 {
                count += 1
            }
        }
    }
    return count
}
```
 // XCTAssertTrue failed

func specialFilter(nums: [Int]) -> Int {
    var count = 0
    for num in nums {
        if num > 10 {
            let firstDigit = abs(num) / 10 % 10
            let lastDigit = abs(num) % 10
            if firstDigit % 2 != 0 && lastDigit % 2 != 0 {
                count += 1
            }
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns 
the number of elements in the array that are greater than 10 and both 
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2[/INST]  ```swift
func specialFilter(nums: [Int]) -> Int {
    var count = 0
    for num in nums {
        if num > 10 {
            let firstDigit = abs(num) / 10 % 10
            let lastDigit = abs(num) % 10
            if firstDigit % 2 != 0 && lastDigit % 2 != 0 {
                count += 1
            }
        }
    }
    return count
}
```
 // XCTAssertTrue failed

func specialFilter(nums: [Int]) -> Int {
    var count = 0
    for num in nums {
        if num > 10 {
            let firstDigit = abs(num / 10) % 10
            let lastDigit = abs(num % 10)
            if firstDigit % 2 != 0 && lastDigit % 2 != 0 {
                count += 1
            }
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns 
the number of elements in the array that are greater than 10 and both 
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2[/INST]  ```swift
func specialFilter(nums: [Int]) -> Int {
    var count = 0
    for num in nums {
        if num > 10 {
            let firstDigit = abs(num / 10) % 10
            let lastDigit = abs(num % 10)
            if firstDigit % 2 != 0 && lastDigit % 2 != 0 {
                count += 1
            }
        }
    }
    return count
}
```
 // XCTAssertTrue failed

func specialFilter(nums: [Int]) -> Int {
    var count = 0
    for num in nums {
        if num > 10 {
            let firstDigit = abs(num / 10) % 10
            let lastDigit = abs(num % 10)
            if firstDigit % 2 != 0 && lastDigit % 2 != 0 {
                count += 1
            }
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns 
the number of elements in the array that are greater than 10 and both 
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2[/INST]  ```swift
func specialFilter(nums: [Int]) -> Int {
    var count = 0
    for num in nums {
        if num > 10 {
            let firstDigit = abs(num / 10) % 10
            let lastDigit = abs(num % 10)
            if firstDigit % 2 != 0 && lastDigit % 2 != 0 {
                count += 1
            }
        }
    }
    return count
}
```
 // XCTAssertTrue failed

func specialFilter(nums: [Int]) -> Int {
    var count = 0
    for num in nums {
        if num > 10 {
            let firstDigit = abs(num) / 10 % 10
            let lastDigit = abs(num) % 10
            if firstDigit % 2 != 0 && lastDigit % 2 != 0 {
                count += 1
            }
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns 
the number of elements in the array that are greater than 10 and both 
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2[/INST]  ```swift
func specialFilter(nums: [Int]) -> Int {
    var count = 0
    for num in nums {
        if num > 10 {
            let firstDigit = abs(num) / 10 % 10
            let lastDigit = abs(num) % 10
            if firstDigit % 2 != 0 && lastDigit % 2 != 0 {
                count += 1
            }
        }
    }
    return count
}
```
 // XCTAssertTrue failed

func specialFilter(nums: [Int]) -> Int {
    var count = 0
    for num in nums {
        if num > 10 {
            let firstDigit = abs(num) / 10 % 10
            let lastDigit = abs(num) % 10
            if firstDigit % 2 != 0 && lastDigit % 2 != 0 {
                count += 1
            }
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns 
the number of elements in the array that are greater than 10 and both 
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2[/INST]  ```swift
func specialFilter(nums: [Int]) -> Int {
    var count = 0
    for num in nums {
        if num > 10 {
            let firstDigit = abs(num) / 10 % 10
            let lastDigit = abs(num) % 10
            if firstDigit % 2 != 0 && lastDigit % 2 != 0 {
                count += 1
            }
        }
    }
    return count
}
```
 // XCTAssertTrue failed

func specialFilter(nums: [Int]) -> Int {
    var count = 0
    for num in nums {
        if num > 10 {
            let firstDigit = abs(num) / 10 % 10
            let lastDigit = abs(num) % 10
            if firstDigit % 2 != 0 && lastDigit % 2 != 0 {
                count += 1
            }
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns 
the number of elements in the array that are greater than 10 and both 
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2[/INST]  ```swift
func specialFilter(nums: [Int]) -> Int {
    var count = 0
    for num in nums {
        if num > 10 {
            let firstDigit = abs(num) / 10 % 10
            let lastDigit = abs(num) % 10
            if firstDigit % 2 != 0 && lastDigit % 2 != 0 {
                count += 1
            }
        }
    }
    return count
}
```
 // XCTAssertTrue failed

func getMaxTriples(n: Int) -> Int {
    var a = [Int](repeating: 0, count: n)
    var count = 0

    for i in 0..<n {
        a[i] = i * i - i + 1
    }

    for i in 0..<n {
        for j in (i+1)..<n {
            for k in (j+1)..<n {
                if (a[i] + a[j] + a[k]) % 3 == 0 {
                    count += 1
                }
            }
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, 
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation: 
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1[/INST]  ```swift
func getMaxTriples(n: Int) -> Int {
    var a = [Int](repeating: 0, count: n)
    var count = 0

    for i in 0..<n {
        a[i] = i * i - i + 1
    }

    for i in 0..<n {
        for j in (i+1)..<n {
            for k in (j+1)..<n {
                if (a[i] + a[j] + a[k]) % 3 == 0 {
                    count += 1
                }
            }
        }
    }

    return count
}
```
 // XCTAssertTrue failed

func getMaxTriples(n: Int) -> Int {
    var a = [Int](repeating: 0, count: n)
    var count = 0
    for i in 0..<n {
        a[i] = i * i - i + 1
    }
    for i in 0..<n {
        for j in (i+1)..<n {
            for k in (j+1)..<n {
                if (a[i] + a[j] + a[k]) % 3 == 0 {
                    count += 1
                }
            }
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, 
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation: 
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1[/INST]  ```swift
func getMaxTriples(n: Int) -> Int {
    var a = [Int](repeating: 0, count: n)
    var count = 0
    for i in 0..<n {
        a[i] = i * i - i + 1
    }
    for i in 0..<n {
        for j in (i+1)..<n {
            for k in (j+1)..<n {
                if (a[i] + a[j] + a[k]) % 3 == 0 {
                    count += 1
                }
            }
        }
    }
    return count
}
```
 // XCTAssertTrue failed

func getMaxTriples(n: Int) -> Int {
    var a = [Int](repeating: 0, count: n)
    var count = 0
    var modCount = [0, 0, 0]

    for i in 0..<n {
        a[i] = i * i - i + 1
        modCount[a[i] % 3] += 1
    }

    count += modCount[0] * (modCount[0] - 1) * (modCount[0] - 2) / 6
    count += modCount[1] * (modCount[1] - 1) / 2 * modCount[2]
    count += modCount[2] * (modCount[2] - 1) / 2 * modCount[1]

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, 
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation: 
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1[/INST]  ```swift
func getMaxTriples(n: Int) -> Int {
    var a = [Int](repeating: 0, count: n)
    var count = 0
    var modCount = [0, 0, 0]

    for i in 0..<n {
        a[i] = i * i - i + 1
        modCount[a[i] % 3] += 1
    }

    count += modCount[0] * (modCount[0] - 1) * (modCount[0] - 2) / 6
    count += modCount[1] * (modCount[1] - 1) / 2 * modCount[2]
    count += modCount[2] * (modCount[2] - 1) / 2 * modCount[1]

    return count
}
```
 // XCTAssertTrue failed

func getMaxTriples(n: Int) -> Int {
    var a = [Int](repeating: 0, count: n)
    var count = 0

    for i in 0..<n {
        a[i] = (i + 1) * (i + 1) - (i + 1) + 1
    }

    for i in 0..<n {
        for j in (i + 1)..<n {
            for k in (j + 1)..<n {
                if (a[i] + a[j] + a[k]) % 3 == 0 {
                    count += 1
                }
            }
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, 
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation: 
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1[/INST]  ```swift
func getMaxTriples(n: Int) -> Int {
    var a = [Int](repeating: 0, count: n)
    var count = 0

    for i in 0..<n {
        a[i] = (i + 1) * (i + 1) - (i + 1) + 1
    }

    for i in 0..<n {
        for j in (i + 1)..<n {
            for k in (j + 1)..<n {
                if (a[i] + a[j] + a[k]) % 3 == 0 {
                    count += 1
                }
            }
        }
    }

    return count
}
```

func getMaxTriples(n: Int) -> Int {
    var a = [Int](repeating: 0, count: n)
    var count = 0

    for i in 0..<n {
        a[i] = i * i - i + 1
    }

    for i in 0..<n {
        for j in (i+1)..<n {
            for k in (j+1)..<n {
                if (a[i] + a[j] + a[k]) % 3 == 0 {
                    count += 1
                }
            }
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, 
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation: 
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1[/INST]  ```swift
func getMaxTriples(n: Int) -> Int {
    var a = [Int](repeating: 0, count: n)
    var count = 0

    for i in 0..<n {
        a[i] = i * i - i + 1
    }

    for i in 0..<n {
        for j in (i+1)..<n {
            for k in (j+1)..<n {
                if (a[i] + a[j] + a[k]) % 3 == 0 {
                    count += 1
                }
            }
        }
    }

    return count
}
```
 // XCTAssertTrue failed

func getMaxTriples(n: Int) -> Int {
    var a = [Int](repeating: 0, count: n)
    var count = 0

    for i in 0..<n {
        a[i] = i * i - i + 1
    }

    for i in 0..<n {
        for j in (i+1)..<n {
            for k in (j+1)..<n {
                if (a[i] + a[j] + a[k]) % 3 == 0 {
                    count += 1
                }
            }
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, 
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation: 
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1[/INST]  ```swift
func getMaxTriples(n: Int) -> Int {
    var a = [Int](repeating: 0, count: n)
    var count = 0

    for i in 0..<n {
        a[i] = i * i - i + 1
    }

    for i in 0..<n {
        for j in (i+1)..<n {
            for k in (j+1)..<n {
                if (a[i] + a[j] + a[k]) % 3 == 0 {
                    count += 1
                }
            }
        }
    }

    return count
}
```
 // XCTAssertTrue failed

func getMaxTriples(n: Int) -> Int {
    var a = [Int](repeating: 0, count: n)
    var count = 0
    for i in 0..<n {
        a[i] = i * i - i + 1
    }
    for i in 0..<n {
        for j in (i+1)..<n {
            for k in (j+1)..<n {
                if (a[i] + a[j] + a[k]) % 3 == 0 {
                    count += 1
                }
            }
        }
    }
    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, 
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation: 
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1[/INST]  ```swift
func getMaxTriples(n: Int) -> Int {
    var a = [Int](repeating: 0, count: n)
    var count = 0
    for i in 0..<n {
        a[i] = i * i - i + 1
    }
    for i in 0..<n {
        for j in (i+1)..<n {
            for k in (j+1)..<n {
                if (a[i] + a[j] + a[k]) % 3 == 0 {
                    count += 1
                }
            }
        }
    }
    return count
}
```
 // XCTAssertTrue failed

func getMaxTriples(n: Int) -> Int {
    var a = [Int](repeating: 0, count: n)
    var count = 0

    for i in 0..<n {
        a[i] = (i + 1) * (i + 1) - (i + 1) + 1
    }

    for i in 0..<n {
        for j in (i + 1)..<n {
            for k in (j + 1)..<n {
                if (a[i] + a[j] + a[k]) % 3 == 0 {
                    count += 1
                }
            }
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, 
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation: 
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1[/INST]  ```swift
func getMaxTriples(n: Int) -> Int {
    var a = [Int](repeating: 0, count: n)
    var count = 0

    for i in 0..<n {
        a[i] = (i + 1) * (i + 1) - (i + 1) + 1
    }

    for i in 0..<n {
        for j in (i + 1)..<n {
            for k in (j + 1)..<n {
                if (a[i] + a[j] + a[k]) % 3 == 0 {
                    count += 1
                }
            }
        }
    }

    return count
}
```

func getMaxTriples(n: Int) -> Int {
    var a = [Int](repeating: 0, count: n)
    var count = 0
    var modCount = [0, 0, 0]

    for i in 0..<n {
        a[i] = i * i - i + 1
        modCount[a[i] % 3] += 1
    }

    count += modCount[0] * (modCount[0] - 1) * (modCount[0] - 2) / 6
    count += modCount[1] * (modCount[1] - 1) / 2 * modCount[2]
    count += modCount[2] * (modCount[2] - 1) / 2 * modCount[1]

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, 
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation: 
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1[/INST]  ```swift
func getMaxTriples(n: Int) -> Int {
    var a = [Int](repeating: 0, count: n)
    var count = 0
    var modCount = [0, 0, 0]

    for i in 0..<n {
        a[i] = i * i - i + 1
        modCount[a[i] % 3] += 1
    }

    count += modCount[0] * (modCount[0] - 1) * (modCount[0] - 2) / 6
    count += modCount[1] * (modCount[1] - 1) / 2 * modCount[2]
    count += modCount[2] * (modCount[2] - 1) / 2 * modCount[1]

    return count
}
```
 // XCTAssertTrue failed

func getMaxTriples(n: Int) -> Int {
    var a = [Int](repeating: 0, count: n)
    var count = 0

    for i in 0..<n {
        a[i] = (i + 1) * (i + 1) - (i + 1) + 1
    }

    for i in 0..<n {
        for j in (i + 1)..<n {
            for k in (j + 1)..<n {
                if (a[i] + a[j] + a[k]) % 3 == 0 {
                    count += 1
                }
            }
        }
    }

    return count
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, 
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation: 
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1[/INST]  ```swift
func getMaxTriples(n: Int) -> Int {
    var a = [Int](repeating: 0, count: n)
    var count = 0

    for i in 0..<n {
        a[i] = (i + 1) * (i + 1) - (i + 1) + 1
    }

    for i in 0..<n {
        for j in (i + 1)..<n {
            for k in (j + 1)..<n {
                if (a[i] + a[j] + a[k]) % 3 == 0 {
                    count += 1
                }
            }
        }
    }

    return count
}
```

func sortedListSum(lst: [String]) -> [String] {
    var filteredList = lst.filter { $0.count % 2 == 0 }
    filteredList.sort {
        if $0.count == $1.count {
            return $0 < $1
        } else {
            return $0.count < $1.count
        }
    }
    return filteredList
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"][/INST]  ```swift
func sortedListSum(lst: [String]) -> [String] {
    var filteredList = lst.filter { $0.count % 2 == 0 }
    filteredList.sort {
        if $0.count == $1.count {
            return $0 < $1
        } else {
            return $0.count < $1.count
        }
    }
    return filteredList
}
```

func sortedListSum(lst: [String]) -> [String] {
    var filteredList = lst.filter { $0.count % 2 == 0 }
    filteredList.sort {
        if $0.count == $1.count {
            return $0 < $1
        } else {
            return $0.count < $1.count
        }
    }
    return filteredList
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"][/INST]  ```swift
func sortedListSum(lst: [String]) -> [String] {
    var filteredList = lst.filter { $0.count % 2 == 0 }
    filteredList.sort {
        if $0.count == $1.count {
            return $0 < $1
        } else {
            return $0.count < $1.count
        }
    }
    return filteredList
}
```

func sortedListSum(lst: [String]) -> [String] {
    var filteredList = lst.filter { $0.count % 2 == 0 }
    filteredList.sort {
        if $0.count == $1.count {
            return $0 < $1
        } else {
            return $0.count < $1.count
        }
    }
    return filteredList
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"][/INST]  ```swift
func sortedListSum(lst: [String]) -> [String] {
    var filteredList = lst.filter { $0.count % 2 == 0 }
    filteredList.sort {
        if $0.count == $1.count {
            return $0 < $1
        } else {
            return $0.count < $1.count
        }
    }
    return filteredList
}
```

func sortedListSum(lst: [String]) -> [String] {
    var filteredList = lst.filter { $0.count % 2 == 0 }
    filteredList.sort {
        if $0.count == $1.count {
            return $0 < $1
        } else {
            return $0.count < $1.count
        }
    }
    return filteredList
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"][/INST]  ```swift
func sortedListSum(lst: [String]) -> [String] {
    var filteredList = lst.filter { $0.count % 2 == 0 }
    filteredList.sort {
        if $0.count == $1.count {
            return $0 < $1
        } else {
            return $0.count < $1.count
        }
    }
    return filteredList
}
```

func sortedListSum(lst: [String]) -> [String] {
    var filteredList = lst.filter { $0.count % 2 == 0 }
    filteredList.sort {
        if $0.count == $1.count {
            return $0 < $1
        } else {
            return $0.count < $1.count
        }
    }
    return filteredList
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"][/INST]  ```swift
func sortedListSum(lst: [String]) -> [String] {
    var filteredList = lst.filter { $0.count % 2 == 0 }
    filteredList.sort {
        if $0.count == $1.count {
            return $0 < $1
        } else {
            return $0.count < $1.count
        }
    }
    return filteredList
}
```

func sortedListSum(lst: [String]) -> [String] {
    var filteredList = lst.filter { $0.count % 2 == 0 }
    filteredList.sort {
        if $0.count == $1.count {
            return $0 < $1
        } else {
            return $0.count < $1.count
        }
    }
    return filteredList
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"][/INST]  ```swift
func sortedListSum(lst: [String]) -> [String] {
    var filteredList = lst.filter { $0.count % 2 == 0 }
    filteredList.sort {
        if $0.count == $1.count {
            return $0 < $1
        } else {
            return $0.count < $1.count
        }
    }
    return filteredList
}
```

func sortedListSum(lst: [String]) -> [String] {
    var filteredList = lst.filter { $0.count % 2 == 0 }
    filteredList.sort {
        if $0.count == $1.count {
            return $0 < $1
        } else {
            return $0.count < $1.count
        }
    }
    return filteredList
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"][/INST]  ```swift
func sortedListSum(lst: [String]) -> [String] {
    var filteredList = lst.filter { $0.count % 2 == 0 }
    filteredList.sort {
        if $0.count == $1.count {
            return $0 < $1
        } else {
            return $0.count < $1.count
        }
    }
    return filteredList
}
```

func sortedListSum(lst: [String]) -> [String] {
    var filteredList = lst.filter { $0.count % 2 == 0 }
    filteredList.sort {
        if $0.count == $1.count {
            return $0 < $1
        } else {
            return $0.count < $1.count
        }
    }
    return filteredList
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"][/INST]  ```swift
func sortedListSum(lst: [String]) -> [String] {
    var filteredList = lst.filter { $0.count % 2 == 0 }
    filteredList.sort {
        if $0.count == $1.count {
            return $0 < $1
        } else {
            return $0.count < $1.count
        }
    }
    return filteredList
}
```

func sortedListSum(lst: [String]) -> [String] {
    var filteredList = lst.filter { $0.count % 2 == 0 }
    filteredList.sort {
        if $0.count == $1.count {
            return $0 < $1
        } else {
            return $0.count < $1.count
        }
    }
    return filteredList
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"][/INST]  ```swift
func sortedListSum(lst: [String]) -> [String] {
    var filteredList = lst.filter { $0.count % 2 == 0 }
    filteredList.sort {
        if $0.count == $1.count {
            return $0 < $1
        } else {
            return $0.count < $1.count
        }
    }
    return filteredList
}
```

func sortedListSum(lst: [String]) -> [String] {
    var filteredList = lst.filter { $0.count % 2 == 0 }
    filteredList.sort {
        if $0.count == $1.count {
            return $0 < $1
        } else {
            return $0.count < $1.count
        }
    }
    return filteredList
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"][/INST]  ```swift
func sortedListSum(lst: [String]) -> [String] {
    var filteredList = lst.filter { $0.count % 2 == 0 }
    filteredList.sort {
        if $0.count == $1.count {
            return $0 < $1
        } else {
            return $0.count < $1.count
        }
    }
    return filteredList
}
```

func xOrY(n: Int, x: Int, y: Int) -> Int {
    if isPrime(n) {
        return x
    } else {
        return y
    }
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    if number <= 3 {
        return true
    }
    var i = 2
    while i * i <= number {
        if number % i == 0 {
            return false
        }
        i = i + 1
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is 
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5[/INST]  ```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
    if isPrime(n) {
        return x
    } else {
        return y
    }
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    if number <= 3 {
        return true
    }
    var i = 2
    while i * i <= number {
        if number % i == 0 {
            return false
        }
        i = i + 1
    }
    return true
}
```

func xOrY(n: Int, x: Int, y: Int) -> Int {
    if isPrime(n) {
        return x
    } else {
        return y
    }
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    if number <= 3 {
        return true
    }
    var i = 2
    while i * i <= number {
        if number % i == 0 {
            return false
        }
        i = i + 1
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is 
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5[/INST]  ```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
    if isPrime(n) {
        return x
    } else {
        return y
    }
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    if number <= 3 {
        return true
    }
    var i = 2
    while i * i <= number {
        if number % i == 0 {
            return false
        }
        i = i + 1
    }
    return true
}
```

func xOrY(n: Int, x: Int, y: Int) -> Int {
    if isPrime(n) {
        return x
    } else {
        return y
    }
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    if number <= 3 {
        return true
    }
    var i = 2
    while i * i <= number {
        if number % i == 0 {
            return false
        }
        i = i + 1
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is 
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5[/INST]  ```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
    if isPrime(n) {
        return x
    } else {
        return y
    }
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    if number <= 3 {
        return true
    }
    var i = 2
    while i * i <= number {
        if number % i == 0 {
            return false
        }
        i = i + 1
    }
    return true
}
```

func xOrY(n: Int, x: Int, y: Int) -> Int {
    if isPrime(n) {
        return x
    } else {
        return y
    }
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            return false
        }
        i = i + 1
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is 
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5[/INST]  ```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
    if isPrime(n) {
        return x
    } else {
        return y
    }
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            return false
        }
        i = i + 1
    }
    return true
}
```

func xOrY(n: Int, x: Int, y: Int) -> Int {
    if isPrime(n) {
        return x
    } else {
        return y
    }
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    if number <= 3 {
        return true
    }
    var i = 2
    while i * i <= number {
        if number % i == 0 {
            return false
        }
        i = i + 1
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is 
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5[/INST]  ```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
    if isPrime(n) {
        return x
    } else {
        return y
    }
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    if number <= 3 {
        return true
    }
    var i = 2
    while i * i <= number {
        if number % i == 0 {
            return false
        }
        i = i + 1
    }
    return true
}
```

func xOrY(n: Int, x: Int, y: Int) -> Int {
    if isPrime(n) {
        return x
    } else {
        return y
    }
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            return false
        }
        i = i + 1
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is 
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5[/INST]  ```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
    if isPrime(n) {
        return x
    } else {
        return y
    }
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            return false
        }
        i = i + 1
    }
    return true
}
```

func xOrY(n: Int, x: Int, y: Int) -> Int {
    if isPrime(n) {
        return x
    } else {
        return y
    }
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    if number <= 3 {
        return true
    }
    var i = 2
    while i * i <= number {
        if number % i == 0 {
            return false
        }
        i = i + 1
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is 
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5[/INST]  ```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
    if isPrime(n) {
        return x
    } else {
        return y
    }
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    if number <= 3 {
        return true
    }
    var i = 2
    while i * i <= number {
        if number % i == 0 {
            return false
        }
        i = i + 1
    }
    return true
}
```

func xOrY(n: Int, x: Int, y: Int) -> Int {
    if isPrime(n) {
        return x
    } else {
        return y
    }
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            return false
        }
        i = i + 1
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is 
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5[/INST]  ```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
    if isPrime(n) {
        return x
    } else {
        return y
    }
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            return false
        }
        i = i + 1
    }
    return true
}
```

func xOrY(n: Int, x: Int, y: Int) -> Int {
    if isPrime(n) {
        return x
    } else {
        return y
    }
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            return false
        }
        i = i + 1
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is 
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5[/INST]  ```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
    if isPrime(n) {
        return x
    } else {
        return y
    }
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            return false
        }
        i = i + 1
    }
    return true
}
```

func xOrY(n: Int, x: Int, y: Int) -> Int {
    if isPrime(n) {
        return x
    } else {
        return y
    }
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    if number <= 3 {
        return true
    }
    var i = 2
    while i * i <= number {
        if number % i == 0 {
            return false
        }
        i = i + 1
    }
    return true
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is 
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5[/INST]  ```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
    if isPrime(n) {
        return x
    } else {
        return y
    }
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    if number <= 3 {
        return true
    }
    var i = 2
    while i * i <= number {
        if number % i == 0 {
            return false
        }
        i = i + 1
    }
    return true
}
```

func doubleTheDifference(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        if num > 0, num.truncatingRemainder(dividingBy: 1) == 0, num.truncatingRemainder(dividingBy: 2) == 1 {
            let square = Int(pow(num, 2))
            sum += square
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0[/INST]  ```swift
func doubleTheDifference(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        if num > 0, num.truncatingRemainder(dividingBy: 1) == 0, num.truncatingRemainder(dividingBy: 2) == 1 {
            let square = Int(pow(num, 2))
            sum += square
        }
    }
    return sum
}
```

func doubleTheDifference(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        if num > 0 && num.truncatingRemainder(dividingBy: 1) == 0 && num.truncatingRemainder(dividingBy: 2) == 1 {
            let square = Int(num * num)
            sum += square
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0[/INST]  ```swift
func doubleTheDifference(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        if num > 0 && num.truncatingRemainder(dividingBy: 1) == 0 && num.truncatingRemainder(dividingBy: 2) == 1 {
            let square = Int(num * num)
            sum += square
        }
    }
    return sum
}
```

func doubleTheDifference(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        if num > 0, num.truncatingRemainder(dividingBy: 1) == 0, num.truncatingRemainder(dividingBy: 2) == 1 {
            let square = Int(pow(num, 2))
            sum += square
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0[/INST]  ```swift
func doubleTheDifference(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        if num > 0, num.truncatingRemainder(dividingBy: 1) == 0, num.truncatingRemainder(dividingBy: 2) == 1 {
            let square = Int(pow(num, 2))
            sum += square
        }
    }
    return sum
}
```

func doubleTheDifference(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        if num > 0, num.truncatingRemainder(dividingBy: 1) == 0, num.truncatingRemainder(dividingBy: 2) == 1 {
            let square = Int(pow(num, 2))
            sum += square
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0[/INST]  ```swift
func doubleTheDifference(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        if num > 0, num.truncatingRemainder(dividingBy: 1) == 0, num.truncatingRemainder(dividingBy: 2) == 1 {
            let square = Int(pow(num, 2))
            sum += square
        }
    }
    return sum
}
```

func doubleTheDifference(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        if num > 0 && num.truncatingRemainder(dividingBy: 1) == 0 && num.truncatingRemainder(dividingBy: 2) == 1 {
            let square = Int(pow(num, 2))
            sum += square
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0[/INST]  ```swift
func doubleTheDifference(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        if num > 0 && num.truncatingRemainder(dividingBy: 1) == 0 && num.truncatingRemainder(dividingBy: 2) == 1 {
            let square = Int(pow(num, 2))
            sum += square
        }
    }
    return sum
}
```

func doubleTheDifference(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        if num > 0, num.truncatingRemainder(dividingBy: 1) == 0, num.truncatingRemainder(dividingBy: 2) == 1 {
            let square = Int(num * num)
            sum += square
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0[/INST]  ```swift
func doubleTheDifference(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        if num > 0, num.truncatingRemainder(dividingBy: 1) == 0, num.truncatingRemainder(dividingBy: 2) == 1 {
            let square = Int(num * num)
            sum += square
        }
    }
    return sum
}
```

func doubleTheDifference(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        if num > 0, num.truncatingRemainder(dividingBy: 1) == 0, num.truncatingRemainder(dividingBy: 2) == 1 {
            let square = Int(pow(num, 2))
            sum += square
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0[/INST]  ```swift
func doubleTheDifference(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        if num > 0, num.truncatingRemainder(dividingBy: 1) == 0, num.truncatingRemainder(dividingBy: 2) == 1 {
            let square = Int(pow(num, 2))
            sum += square
        }
    }
    return sum
}
```

func doubleTheDifference(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        if num > 0, num.truncatingRemainder(dividingBy: 1) == 0, num.truncatingRemainder(dividingBy: 2) == 1 {
            let square = Int(pow(num, 2))
            sum += square
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0[/INST]  ```swift
func doubleTheDifference(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        if num > 0, num.truncatingRemainder(dividingBy: 1) == 0, num.truncatingRemainder(dividingBy: 2) == 1 {
            let square = Int(pow(num, 2))
            sum += square
        }
    }
    return sum
}
```

func doubleTheDifference(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        if num > 0, num.truncatingRemainder(dividingBy: 1) == 0, num.truncatingRemainder(dividingBy: 2) == 1 {
            let square = Int(num * num)
            sum += square
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0[/INST]  ```swift
func doubleTheDifference(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        if num > 0, num.truncatingRemainder(dividingBy: 1) == 0, num.truncatingRemainder(dividingBy: 2) == 1 {
            let square = Int(num * num)
            sum += square
        }
    }
    return sum
}
```

func doubleTheDifference(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        if num > 0, num.truncatingRemainder(dividingBy: 1) == 0, num.truncatingRemainder(dividingBy: 2) == 1 {
            let square = Int(num * num)
            sum += square
        }
    }
    return sum
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0[/INST]  ```swift
func doubleTheDifference(lst: [Double]) -> Int {
    var sum = 0
    for num in lst {
        if num > 0, num.truncatingRemainder(dividingBy: 1) == 0, num.truncatingRemainder(dividingBy: 2) == 1 {
            let square = Int(num * num)
            sum += square
        }
    }
    return sum
}
```

func compare(game: [Int], guess: [Int]) -> [Int] {
    var result = [Int]()
    for i in 0..<game.count {
        result.append(abs(game[i] - guess[i]))
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match. 
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6][/INST]  ```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
    var result = [Int]()
    for i in 0..<game.count {
        result.append(abs(game[i] - guess[i]))
    }
    return result
}
```

func compare(game: [Int], guess: [Int]) -> [Int] {
    var result = [Int]()
    for i in 0..<game.count {
        result.append(abs(game[i] - guess[i]))
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match. 
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6][/INST]  ```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
    var result = [Int]()
    for i in 0..<game.count {
        result.append(abs(game[i] - guess[i]))
    }
    return result
}
```

func compare(game: [Int], guess: [Int]) -> [Int] {
    var result = [Int]()
    for i in 0..<game.count {
        result.append(abs(game[i] - guess[i]))
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match. 
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6][/INST]  ```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
    var result = [Int]()
    for i in 0..<game.count {
        result.append(abs(game[i] - guess[i]))
    }
    return result
}
```

func compare(game: [Int], guess: [Int]) -> [Int] {
    var result = [Int]()
    for i in 0..<game.count {
        result.append(abs(game[i] - guess[i]))
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match. 
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6][/INST]  ```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
    var result = [Int]()
    for i in 0..<game.count {
        result.append(abs(game[i] - guess[i]))
    }
    return result
}
```

func compare(game: [Int], guess: [Int]) -> [Int] {
    var result = [Int]()
    for i in 0..<game.count {
        result.append(abs(game[i] - guess[i]))
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match. 
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6][/INST]  ```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
    var result = [Int]()
    for i in 0..<game.count {
        result.append(abs(game[i] - guess[i]))
    }
    return result
}
```

func compare(game: [Int], guess: [Int]) -> [Int] {
    var result = [Int]()
    for i in 0..<game.count {
        result.append(abs(game[i] - guess[i]))
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match. 
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6][/INST]  ```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
    var result = [Int]()
    for i in 0..<game.count {
        result.append(abs(game[i] - guess[i]))
    }
    return result
}
```

func compare(game: [Int], guess: [Int]) -> [Int] {
    var result = [Int]()
    for i in 0..<game.count {
        result.append(abs(game[i] - guess[i]))
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match. 
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6][/INST]  ```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
    var result = [Int]()
    for i in 0..<game.count {
        result.append(abs(game[i] - guess[i]))
    }
    return result
}
```

func compare(game: [Int], guess: [Int]) -> [Int] {
    var result = [Int]()
    for i in 0..<game.count {
        result.append(abs(game[i] - guess[i]))
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match. 
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6][/INST]  ```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
    var result = [Int]()
    for i in 0..<game.count {
        result.append(abs(game[i] - guess[i]))
    }
    return result
}
```

func compare(game: [Int], guess: [Int]) -> [Int] {
    var result = [Int]()
    for i in 0..<game.count {
        result.append(abs(game[i] - guess[i]))
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match. 
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6][/INST]  ```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
    var result = [Int]()
    for i in 0..<game.count {
        result.append(abs(game[i] - guess[i]))
    }
    return result
}
```

func compare(game: [Int], guess: [Int]) -> [Int] {
    var result = [Int]()
    for i in 0..<game.count {
        result.append(abs(game[i] - guess[i]))
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match. 
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6][/INST]  ```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
    var result = [Int]()
    for i in 0..<game.count {
        result.append(abs(game[i] - guess[i]))
    }
    return result
}
```

extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension 
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"[/INST]  ```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
    var strongestExtension = ""
    var maxStrength = Int.min

    for extension in extensions {
        var uppercaseCount = 0
        var lowercaseCount = 0

        for char in extension {
            if char.isUppercase {
                uppercaseCount += 1
            } else if char.isLowercase {
                lowercaseCount += 1
            }
        }

        let strength = uppercaseCount - lowercaseCount
        if strength > maxStrength {
            maxStrength = strength
            strongestExtension = extension
        }
    }

    return "\(className).\(strongestExtension)"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters 
in the extension's name, the strength is given by the fraction CAP - SM. 
You should find the strongest extension and return a string in this 
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension 
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"[/INST]  ```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
    var strongestExtension = ""
    var maxStrength = Int.min

    for extension in extensions {
        var uppercaseCount = 0
        var lowercaseCount = 0

        for char in extension {
            if char.isUppercase {
                uppercaseCount += 1
            } else if char.isLowercase {
                lowercaseCount += 1
            }
        }

        let strength = uppercaseCount - lowercaseCount
        if strength > maxStrength {
            maxStrength = strength
            strongestExtension = extension
        }
    }

    return "\(className).\(strongestExtension)"
}
```
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expression
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a func
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope
(its strength is -1). // expected ',' separator
(its strength is -1). // expected '{' in extension
(its strength is -1). // expected member name following '.'
(its strength is -1). // expected type
(its strength is -1). // expected ':' following argument label and parameter name
(its strength is -1). // expected type
for extension in extensions { // expected pattern
for extension in extensions { // expected Sequence expression for for-each loop
for extension in extensions { // expected '{' to start the body of for-each loop
for char in extension { // expected Sequence expression for for-each loop
for char in extension { // expected '{' to start the body of for-each loop
strongestExtension = extension // expected expression in assignment
strongestExtension = extension // expected '{' in extension
strongestExtension = extension // declaration is only valid at file scope
} // expected type name in extension declaration

extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension 
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"[/INST]  ```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
    var strongestExtension = ""
    var maxStrength = Int.min

    for extension in extensions {
        var uppercaseCount = 0
        var lowercaseCount = 0

        for char in extension {
            if char.isUppercase {
                uppercaseCount += 1
            } else if char.isLowercase {
                lowercaseCount += 1
            }
        }

        let strength = uppercaseCount - lowercaseCount

        if strength > maxStrength {
            maxStrength = strength
            strongestExtension = extension
        }
    }

    return "\(className).\(strongestExtension)"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters 
in the extension's name, the strength is given by the fraction CAP - SM. 
You should find the strongest extension and return a string in this 
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension 
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"[/INST]  ```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
    var strongestExtension = ""
    var maxStrength = Int.min

    for extension in extensions {
        var uppercaseCount = 0
        var lowercaseCount = 0

        for char in extension {
            if char.isUppercase {
                uppercaseCount += 1
            } else if char.isLowercase {
                lowercaseCount += 1
            }
        }

        let strength = uppercaseCount - lowercaseCount

        if strength > maxStrength {
            maxStrength = strength
            strongestExtension = extension
        }
    }

    return "\(className).\(strongestExtension)"
}
```
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expression
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a func
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope
(its strength is -1). // expected ',' separator
(its strength is -1). // expected '{' in extension
(its strength is -1). // expected member name following '.'
(its strength is -1). // expected type
(its strength is -1). // expected ':' following argument label and parameter name
(its strength is -1). // expected type
for extension in extensions { // expected pattern
for extension in extensions { // expected Sequence expression for for-each loop
for extension in extensions { // expected '{' to start the body of for-each loop
for char in extension { // expected Sequence expression for for-each loop
for char in extension { // expected '{' to start the body of for-each loop
strongestExtension = extension // expected '{' in extension
strongestExtension = extension // expected expression in assignment
strongestExtension = extension // declaration is only valid at file scope
} // expected type name in extension declaration

extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension 
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"[/INST]  ```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
    var strongestExtension = ""
    var maxStrength = Int.min

    for extension in extensions {
        var uppercaseCount = 0
        var lowercaseCount = 0

        for char in extension {
            if char.isUppercase {
                uppercaseCount += 1
            } else if char.isLowercase {
                lowercaseCount += 1
            }
        }

        let strength = uppercaseCount - lowercaseCount
        if strength > maxStrength {
            maxStrength = strength
            strongestExtension = extension
        }
    }

    return "\(className).\(strongestExtension)"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters 
in the extension's name, the strength is given by the fraction CAP - SM. 
You should find the strongest extension and return a string in this 
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension 
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"[/INST]  ```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
    var strongestExtension = ""
    var maxStrength = Int.min

    for extension in extensions {
        var uppercaseCount = 0
        var lowercaseCount = 0

        for char in extension {
            if char.isUppercase {
                uppercaseCount += 1
            } else if char.isLowercase {
                lowercaseCount += 1
            }
        }

        let strength = uppercaseCount - lowercaseCount
        if strength > maxStrength {
            maxStrength = strength
            strongestExtension = extension
        }
    }

    return "\(className).\(strongestExtension)"
}
```
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expression
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a func
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope
(its strength is -1). // expected ',' separator
(its strength is -1). // expected '{' in extension
(its strength is -1). // expected member name following '.'
(its strength is -1). // expected type
(its strength is -1). // expected ':' following argument label and parameter name
(its strength is -1). // expected type
for extension in extensions { // expected pattern
for extension in extensions { // expected Sequence expression for for-each loop
for extension in extensions { // expected '{' to start the body of for-each loop
for char in extension { // expected Sequence expression for for-each loop
for char in extension { // expected '{' to start the body of for-each loop
strongestExtension = extension // expected expression in assignment
strongestExtension = extension // expected '{' in extension
strongestExtension = extension // declaration is only valid at file scope
} // expected type name in extension declaration

extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension 
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"[/INST]  ```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
    var strongestExtension = ""
    var maxStrength = Int.min

    for extensionName in extensions {
        var uppercaseCount = 0
        var lowercaseCount = 0

        for char in extensionName {
            if char.isUppercase {
                uppercaseCount += 1
            } else if char.isLowercase {
                lowercaseCount += 1
            }
        }

        let strength = uppercaseCount - lowercaseCount
        if strength > maxStrength {
            maxStrength = strength
            strongestExtension = extensionName
        }
    }

    return "\(className).\(strongestExtension)"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters 
in the extension's name, the strength is given by the fraction CAP - SM. 
You should find the strongest extension and return a string in this 
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension 
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"[/INST]  ```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
    var strongestExtension = ""
    var maxStrength = Int.min

    for extensionName in extensions {
        var uppercaseCount = 0
        var lowercaseCount = 0

        for char in extensionName {
            if char.isUppercase {
                uppercaseCount += 1
            } else if char.isLowercase {
                lowercaseCount += 1
            }
        }

        let strength = uppercaseCount - lowercaseCount
        if strength > maxStrength {
            maxStrength = strength
            strongestExtension = extensionName
        }
    }

    return "\(className).\(strongestExtension)"
}
```
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expression
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a func
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope
(its strength is -1). // expected ',' separator
(its strength is -1). // expected '{' in extension
(its strength is -1). // expected member name following '.'
(its strength is -1). // expected type
(its strength is -1). // expected ':' following argument label and parameter name
(its strength is -1). // expected type

extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension 
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"[/INST]  ```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
    var strongestExtension = ""
    var maxStrength = Int.min

    for extensionName in extensions {
        var uppercaseCount = 0
        var lowercaseCount = 0

        for char in extensionName {
            if char.isUppercase {
                uppercaseCount += 1
            } else if char.isLowercase {
                lowercaseCount += 1
            }
        }

        let strength = uppercaseCount - lowercaseCount
        if strength > maxStrength {
            maxStrength = strength
            strongestExtension = extensionName
        }
    }

    return "\(className).\(strongestExtension)"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters 
in the extension's name, the strength is given by the fraction CAP - SM. 
You should find the strongest extension and return a string in this 
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension 
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"[/INST]  ```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
    var strongestExtension = ""
    var maxStrength = Int.min

    for extensionName in extensions {
        var uppercaseCount = 0
        var lowercaseCount = 0

        for char in extensionName {
            if char.isUppercase {
                uppercaseCount += 1
            } else if char.isLowercase {
                lowercaseCount += 1
            }
        }

        let strength = uppercaseCount - lowercaseCount
        if strength > maxStrength {
            maxStrength = strength
            strongestExtension = extensionName
        }
    }

    return "\(className).\(strongestExtension)"
}
```
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expression
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a func
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope
(its strength is -1). // expected ',' separator
(its strength is -1). // expected '{' in extension
(its strength is -1). // expected member name following '.'
(its strength is -1). // expected type
(its strength is -1). // expected ':' following argument label and parameter name
(its strength is -1). // expected type

extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension 
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"[/INST]  ```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
    var strongestExtension = ""
    var maxStrength = Int.min

    for extensionName in extensions {
        var uppercaseCount = 0
        var lowercaseCount = 0

        for char in extensionName {
            if char.isUppercase {
                uppercaseCount += 1
            } else if char.isLowercase {
                lowercaseCount += 1
            }
        }

        let strength = uppercaseCount - lowercaseCount
        if strength > maxStrength {
            maxStrength = strength
            strongestExtension = extensionName
        }
    }

    return "\(className).\(strongestExtension)"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters 
in the extension's name, the strength is given by the fraction CAP - SM. 
You should find the strongest extension and return a string in this 
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension 
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"[/INST]  ```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
    var strongestExtension = ""
    var maxStrength = Int.min

    for extensionName in extensions {
        var uppercaseCount = 0
        var lowercaseCount = 0

        for char in extensionName {
            if char.isUppercase {
                uppercaseCount += 1
            } else if char.isLowercase {
                lowercaseCount += 1
            }
        }

        let strength = uppercaseCount - lowercaseCount
        if strength > maxStrength {
            maxStrength = strength
            strongestExtension = extensionName
        }
    }

    return "\(className).\(strongestExtension)"
}
```
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expression
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a func
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope
(its strength is -1). // expected ',' separator
(its strength is -1). // expected '{' in extension
(its strength is -1). // expected member name following '.'
(its strength is -1). // expected type
(its strength is -1). // expected ':' following argument label and parameter name
(its strength is -1). // expected type

extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension 
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"[/INST]  ```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
    var strongestExtension = ""
    var maxStrength = Int.min

    for extension in extensions {
        var uppercaseCount = 0
        var lowercaseCount = 0

        for char in extension {
            if char.isUppercase {
                uppercaseCount += 1
            } else if char.isLowercase {
                lowercaseCount += 1
            }
        }

        let strength = uppercaseCount - lowercaseCount
        if strength > maxStrength {
            maxStrength = strength
            strongestExtension = extension
        }
    }

    return "\(className).\(strongestExtension)"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters 
in the extension's name, the strength is given by the fraction CAP - SM. 
You should find the strongest extension and return a string in this 
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension 
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"[/INST]  ```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
    var strongestExtension = ""
    var maxStrength = Int.min

    for extension in extensions {
        var uppercaseCount = 0
        var lowercaseCount = 0

        for char in extension {
            if char.isUppercase {
                uppercaseCount += 1
            } else if char.isLowercase {
                lowercaseCount += 1
            }
        }

        let strength = uppercaseCount - lowercaseCount
        if strength > maxStrength {
            maxStrength = strength
            strongestExtension = extension
        }
    }

    return "\(className).\(strongestExtension)"
}
```
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expression
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a func
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope
(its strength is -1). // expected ',' separator
(its strength is -1). // expected '{' in extension
(its strength is -1). // expected member name following '.'
(its strength is -1). // expected type
(its strength is -1). // expected ':' following argument label and parameter name
(its strength is -1). // expected type
for extension in extensions { // expected pattern
for extension in extensions { // expected Sequence expression for for-each loop
for extension in extensions { // expected '{' to start the body of for-each loop
for char in extension { // expected Sequence expression for for-each loop
for char in extension { // expected '{' to start the body of for-each loop
strongestExtension = extension // expected expression in assignment
strongestExtension = extension // expected '{' in extension
strongestExtension = extension // declaration is only valid at file scope
} // expected type name in extension declaration

extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension 
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"[/INST]  ```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
    var strongestExtension = ""
    var maxStrength = Int.min

    for extensionName in extensions {
        var uppercaseCount = 0
        var lowercaseCount = 0

        for char in extensionName {
            if char.isUppercase {
                uppercaseCount += 1
            } else if char.isLowercase {
                lowercaseCount += 1
            }
        }

        let strength = uppercaseCount - lowercaseCount

        if strength > maxStrength {
            maxStrength = strength
            strongestExtension = extensionName
        }
    }

    return "\(className).\(strongestExtension)"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters 
in the extension's name, the strength is given by the fraction CAP - SM. 
You should find the strongest extension and return a string in this 
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension 
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"[/INST]  ```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
    var strongestExtension = ""
    var maxStrength = Int.min

    for extensionName in extensions {
        var uppercaseCount = 0
        var lowercaseCount = 0

        for char in extensionName {
            if char.isUppercase {
                uppercaseCount += 1
            } else if char.isLowercase {
                lowercaseCount += 1
            }
        }

        let strength = uppercaseCount - lowercaseCount

        if strength > maxStrength {
            maxStrength = strength
            strongestExtension = extensionName
        }
    }

    return "\(className).\(strongestExtension)"
}
```
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expression
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a func
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope
(its strength is -1). // expected ',' separator
(its strength is -1). // expected '{' in extension
(its strength is -1). // expected member name following '.'
(its strength is -1). // expected type
(its strength is -1). // expected ':' following argument label and parameter name
(its strength is -1). // expected type

extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension 
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"[/INST]  ```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
    var strongestExtension = ""
    var maxStrength = Int.min

    for extension in extensions {
        var cap = 0
        var sm = 0

        for char in extension {
            if char.isUppercase {
                cap += 1
            } else if char.isLowercase {
                sm += 1
            }
        }

        let strength = cap - sm

        if strength > maxStrength {
            maxStrength = strength
            strongestExtension = extension
        }
    }

    return "\(className).\(strongestExtension)"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters 
in the extension's name, the strength is given by the fraction CAP - SM. 
You should find the strongest extension and return a string in this 
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension 
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"[/INST]  ```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
    var strongestExtension = ""
    var maxStrength = Int.min

    for extension in extensions {
        var cap = 0
        var sm = 0

        for char in extension {
            if char.isUppercase {
                cap += 1
            } else if char.isLowercase {
                sm += 1
            }
        }

        let strength = cap - sm

        if strength > maxStrength {
            maxStrength = strength
            strongestExtension = extension
        }
    }

    return "\(className).\(strongestExtension)"
}
```
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expression
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a func
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope
(its strength is -1). // expected ',' separator
(its strength is -1). // expected '{' in extension
(its strength is -1). // expected member name following '.'
(its strength is -1). // expected type
(its strength is -1). // expected ':' following argument label and parameter name
(its strength is -1). // expected type
for extension in extensions { // expected pattern
for extension in extensions { // expected Sequence expression for for-each loop
for extension in extensions { // expected '{' to start the body of for-each loop
for char in extension { // expected Sequence expression for for-each loop
for char in extension { // expected '{' to start the body of for-each loop
strongestExtension = extension // expected '{' in extension
strongestExtension = extension // expected expression in assignment
strongestExtension = extension // declaration is only valid at file scope
} // expected type name in extension declaration

extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension 
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"[/INST]  ```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
    var strongestExtension = ""
    var maxStrength = Int.min

    for extension in extensions {
        var uppercaseCount = 0
        var lowercaseCount = 0

        for char in extension {
            if char.isUppercase {
                uppercaseCount += 1
            } else if char.isLowercase {
                lowercaseCount += 1
            }
        }

        let strength = uppercaseCount - lowercaseCount
        if strength > maxStrength {
            maxStrength = strength
            strongestExtension = extension
        }
    }

    return "\(className).\(strongestExtension)"
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters 
in the extension's name, the strength is given by the fraction CAP - SM. 
You should find the strongest extension and return a string in this 
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension 
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"[/INST]  ```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
    var strongestExtension = ""
    var maxStrength = Int.min

    for extension in extensions {
        var uppercaseCount = 0
        var lowercaseCount = 0

        for char in extension {
            if char.isUppercase {
                uppercaseCount += 1
            } else if char.isLowercase {
                lowercaseCount += 1
            }
        }

        let strength = uppercaseCount - lowercaseCount
        if strength > maxStrength {
            maxStrength = strength
            strongestExtension = extension
        }
    }

    return "\(className).\(strongestExtension)"
}
```
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expression
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scope
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a func
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope
(its strength is -1). // expected ',' separator
(its strength is -1). // expected '{' in extension
(its strength is -1). // expected member name following '.'
(its strength is -1). // expected type
(its strength is -1). // expected ':' following argument label and parameter name
(its strength is -1). // expected type
for extension in extensions { // expected pattern
for extension in extensions { // expected Sequence expression for for-each loop
for extension in extensions { // expected '{' to start the body of for-each loop
for char in extension { // expected Sequence expression for for-each loop
for char in extension { // expected '{' to start the body of for-each loop
strongestExtension = extension // expected expression in assignment
strongestExtension = extension // expected '{' in extension
strongestExtension = extension // declaration is only valid at file scope
} // expected type name in extension declaration

func cycpatternCheck(a: String, b: String) -> Bool {
    if a.count < b.count {
        return false
    }

    let bDouble = b + b
    for i in 0..<b.count {
        let rotation = String(bDouble[i..<i+b.count])
        if a.contains(rotation) {
            return true
        }
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true[/INST]  ```swift
func cycpatternCheck(a: String, b: String) -> Bool {
    if a.count < b.count {
        return false
    }

    let bDouble = b + b
    for i in 0..<b.count {
        let rotation = String(bDouble[i..<i+b.count])
        if a.contains(rotation) {
            return true
        }
    }

    return false
}
```
let rotation = String(bDouble[i..<i+b.count]) // 'subscript(_:)' is unavailable: cannot subscript String with an integer range, use a String.Index range instead.

func cycpatternCheck(a: String, b: String) -> Bool {
    if a.count < b.count {
        return false
    }

    let aa = a + a
    var bb = b

    for _ in 0..<b.count {
        if aa.contains(bb) {
            return true
        }
        bb = String(bb.dropFirst()) + String(bb.first!)
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true[/INST]  ```swift
func cycpatternCheck(a: String, b: String) -> Bool {
    if a.count < b.count {
        return false
    }

    let aa = a + a
    var bb = b

    for _ in 0..<b.count {
        if aa.contains(bb) {
            return true
        }
        bb = String(bb.dropFirst()) + String(bb.first!)
    }

    return false
}
```
 // XCTAssertTrue failed

func cycpatternCheck(a: String, b: String) -> Bool {
    if a.count < b.count {
        return false
    }

    let extendedA = a + a

    for i in 0..<b.count {
        var rotatedB = String(b.dropFirst(i)) + String(b.prefix(i))
        if extendedA.contains(rotatedB) {
            return true
        }
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true[/INST]  ```swift
func cycpatternCheck(a: String, b: String) -> Bool {
    if a.count < b.count {
        return false
    }

    let extendedA = a + a

    for i in 0..<b.count {
        var rotatedB = String(b.dropFirst(i)) + String(b.prefix(i))
        if extendedA.contains(rotatedB) {
            return true
        }
    }

    return false
}
```
var rotatedB = String(b.dropFirst(i)) + String(b.prefix(i)) // variable 'rotatedB' was never mutated; consider changing to 'let' constant
 // XCTAssertTrue failed

func cycpatternCheck(a: String, b: String) -> Bool {
    if a.count < b.count {
        return false
    }

    let extendedA = a + a
    var rotatedB = b

    for _ in 0..<b.count {
        if extendedA.contains(rotatedB) {
            return true
        }
        rotatedB = String(rotatedB.dropFirst()) + String(rotatedB.first!)
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true[/INST]  ```swift
func cycpatternCheck(a: String, b: String) -> Bool {
    if a.count < b.count {
        return false
    }

    let extendedA = a + a
    var rotatedB = b

    for _ in 0..<b.count {
        if extendedA.contains(rotatedB) {
            return true
        }
        rotatedB = String(rotatedB.dropFirst()) + String(rotatedB.first!)
    }

    return false
}
```
 // XCTAssertTrue failed

func cycpatternCheck(a: String, b: String) -> Bool {
    if a.count < b.count {
        return false
    }
    let aa = a + a
    for i in 0..<b.count {
        let rotatedB = String(b.dropFirst(i)) + String(b.prefix(i))
        if aa.contains(rotatedB) {
            return true
        }
    }
    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true[/INST]  ```swift
func cycpatternCheck(a: String, b: String) -> Bool {
    if a.count < b.count {
        return false
    }
    let aa = a + a
    for i in 0..<b.count {
        let rotatedB = String(b.dropFirst(i)) + String(b.prefix(i))
        if aa.contains(rotatedB) {
            return true
        }
    }
    return false
}
```
 // XCTAssertTrue failed

func cycpatternCheck(a: String, b: String) -> Bool {
    if a.count < b.count {
        return false
    }

    let aa = a + a
    var bb = b

    for _ in 0..<b.count {
        if aa.contains(bb) {
            return true
        }
        bb = String(bb.dropFirst()) + String(bb.first!)
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true[/INST]  ```swift
func cycpatternCheck(a: String, b: String) -> Bool {
    if a.count < b.count {
        return false
    }

    let aa = a + a
    var bb = b

    for _ in 0..<b.count {
        if aa.contains(bb) {
            return true
        }
        bb = String(bb.dropFirst()) + String(bb.first!)
    }

    return false
}
```
 // XCTAssertTrue failed

func cycpatternCheck(a: String, b: String) -> Bool {
    if a.count < b.count {
        return false
    }

    let aa = a + a
    var bb = b

    for _ in 0..<b.count {
        if aa.contains(bb) {
            return true
        }
        bb = String(bb.dropFirst()) + String(bb.first!)
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true[/INST]  ```swift
func cycpatternCheck(a: String, b: String) -> Bool {
    if a.count < b.count {
        return false
    }

    let aa = a + a
    var bb = b

    for _ in 0..<b.count {
        if aa.contains(bb) {
            return true
        }
        bb = String(bb.dropFirst()) + String(bb.first!)
    }

    return false
}
```
 // XCTAssertTrue failed

func cycpatternCheck(a: String, b: String) -> Bool {
    if a.count < b.count {
        return false
    }

    let extendedA = a + a
    var rotations = [String]()

    for i in 0..<b.count {
        let rotation = String(b[b.index(b.startIndex, offsetBy: i)...]) + String(b[..<b.index(b.startIndex, offsetBy: i)])
        rotations.append(rotation)
    }

    for rotation in rotations {
        if extendedA.contains(rotation) {
            return true
        }
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true[/INST]  ```swift
func cycpatternCheck(a: String, b: String) -> Bool {
    if a.count < b.count {
        return false
    }

    let extendedA = a + a
    var rotations = [String]()

    for i in 0..<b.count {
        let rotation = String(b[b.index(b.startIndex, offsetBy: i)...]) + String(b[..<b.index(b.startIndex, offsetBy: i)])
        rotations.append(rotation)
    }

    for rotation in rotations {
        if extendedA.contains(rotation) {
            return true
        }
    }

    return false
}
```
 // XCTAssertTrue failed

func cycpatternCheck(a: String, b: String) -> Bool {
    if a.count < b.count {
        return false
    }

    let extendedA = a + a
    var rotations = [String]()

    for i in 0..<b.count {
        let rotation = String(b[b.index(b.startIndex, offsetBy: i)...]) + String(b[..<b.index(b.startIndex, offsetBy: i)])
        rotations.append(rotation)
    }

    for rotation in rotations {
        if extendedA.contains(rotation) {
            return true
        }
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true[/INST]  ```swift
func cycpatternCheck(a: String, b: String) -> Bool {
    if a.count < b.count {
        return false
    }

    let extendedA = a + a
    var rotations = [String]()

    for i in 0..<b.count {
        let rotation = String(b[b.index(b.startIndex, offsetBy: i)...]) + String(b[..<b.index(b.startIndex, offsetBy: i)])
        rotations.append(rotation)
    }

    for rotation in rotations {
        if extendedA.contains(rotation) {
            return true
        }
    }

    return false
}
```
 // XCTAssertTrue failed

func cycpatternCheck(a: String, b: String) -> Bool {
    if a.count < b.count {
        return false
    }

    let extendedA = a + a
    var rotations = [String]()

    for i in 0..<b.count {
        let rotation = String(b[b.index(b.startIndex, offsetBy: i)...]) + String(b[..<b.index(b.startIndex, offsetBy: i)])
        rotations.append(rotation)
    }

    for rotation in rotations {
        if extendedA.contains(rotation) {
            return true
        }
    }

    return false
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true[/INST]  ```swift
func cycpatternCheck(a: String, b: String) -> Bool {
    if a.count < b.count {
        return false
    }

    let extendedA = a + a
    var rotations = [String]()

    for i in 0..<b.count {
        let rotation = String(b[b.index(b.startIndex, offsetBy: i)...]) + String(b[..<b.index(b.startIndex, offsetBy: i)])
        rotations.append(rotation)
    }

    for rotation in rotations {
        if extendedA.contains(rotation) {
            return true
        }
    }

    return false
}
```
 // XCTAssertTrue failed

func evenOddCount(num: Int) -> (Int, Int) {
    var number = abs(num)
    var evenCount = 0
    var oddCount = 0

    while number > 0 {
        let digit = number % 10
        if digit % 2 == 0 {
            evenCount += 1
        } else {
            oddCount += 1
        }
        number /= 10
    }

    return (evenCount, oddCount)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)[/INST]  ```swift
func evenOddCount(num: Int) -> (Int, Int) {
    var number = abs(num)
    var evenCount = 0
    var oddCount = 0

    while number > 0 {
        let digit = number % 10
        if digit % 2 == 0 {
            evenCount += 1
        } else {
            oddCount += 1
        }
        number /= 10
    }

    return (evenCount, oddCount)
}
```
 // XCTAssertTrue failed

func evenOddCount(num: Int) -> (Int, Int) {
    var number = abs(num)
    var evenCount = 0
    var oddCount = 0

    while number > 0 {
        let digit = number % 10
        if digit % 2 == 0 {
            evenCount += 1
        } else {
            oddCount += 1
        }
        number /= 10
    }

    return (evenCount, oddCount)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)[/INST]  ```swift
func evenOddCount(num: Int) -> (Int, Int) {
    var number = abs(num)
    var evenCount = 0
    var oddCount = 0

    while number > 0 {
        let digit = number % 10
        if digit % 2 == 0 {
            evenCount += 1
        } else {
            oddCount += 1
        }
        number /= 10
    }

    return (evenCount, oddCount)
}
```
 // XCTAssertTrue failed

func evenOddCount(num: Int) -> (Int, Int) {
    var number = abs(num)
    var evenCount = 0
    var oddCount = 0

    while number > 0 {
        let digit = number % 10
        if digit % 2 == 0 {
            evenCount += 1
        } else {
            oddCount += 1
        }
        number /= 10
    }

    return (evenCount, oddCount)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)[/INST]  ```swift
func evenOddCount(num: Int) -> (Int, Int) {
    var number = abs(num)
    var evenCount = 0
    var oddCount = 0

    while number > 0 {
        let digit = number % 10
        if digit % 2 == 0 {
            evenCount += 1
        } else {
            oddCount += 1
        }
        number /= 10
    }

    return (evenCount, oddCount)
}
```
 // XCTAssertTrue failed

func evenOddCount(num: Int) -> (Int, Int) {
    var number = abs(num)
    var evenCount = 0
    var oddCount = 0

    while number > 0 {
        let digit = number % 10
        if digit % 2 == 0 {
            evenCount += 1
        } else {
            oddCount += 1
        }
        number /= 10
    }

    return (evenCount, oddCount)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)[/INST]  ```swift
func evenOddCount(num: Int) -> (Int, Int) {
    var number = abs(num)
    var evenCount = 0
    var oddCount = 0

    while number > 0 {
        let digit = number % 10
        if digit % 2 == 0 {
            evenCount += 1
        } else {
            oddCount += 1
        }
        number /= 10
    }

    return (evenCount, oddCount)
}
```
 // XCTAssertTrue failed

func evenOddCount(num: Int) -> (Int, Int) {
    var number = abs(num)
    var evenCount = 0
    var oddCount = 0

    while number > 0 {
        let digit = number % 10
        if digit % 2 == 0 {
            evenCount += 1
        } else {
            oddCount += 1
        }
        number /= 10
    }

    return (evenCount, oddCount)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)[/INST]  ```swift
func evenOddCount(num: Int) -> (Int, Int) {
    var number = abs(num)
    var evenCount = 0
    var oddCount = 0

    while number > 0 {
        let digit = number % 10
        if digit % 2 == 0 {
            evenCount += 1
        } else {
            oddCount += 1
        }
        number /= 10
    }

    return (evenCount, oddCount)
}
```
 // XCTAssertTrue failed

func evenOddCount(num: Int) -> (Int, Int) {
    var number = abs(num)
    var evenCount = 0
    var oddCount = 0

    while number > 0 {
        let digit = number % 10
        if digit % 2 == 0 {
            evenCount += 1
        } else {
            oddCount += 1
        }
        number /= 10
    }

    return (evenCount, oddCount)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)[/INST]  ```swift
func evenOddCount(num: Int) -> (Int, Int) {
    var number = abs(num)
    var evenCount = 0
    var oddCount = 0

    while number > 0 {
        let digit = number % 10
        if digit % 2 == 0 {
            evenCount += 1
        } else {
            oddCount += 1
        }
        number /= 10
    }

    return (evenCount, oddCount)
}
```
 // XCTAssertTrue failed

func evenOddCount(num: Int) -> (Int, Int) {
    var number = abs(num)
    var evenCount = 0
    var oddCount = 0

    while number > 0 {
        let digit = number % 10
        if digit % 2 == 0 {
            evenCount += 1
        } else {
            oddCount += 1
        }
        number /= 10
    }

    return (evenCount, oddCount)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)[/INST]  ```swift
func evenOddCount(num: Int) -> (Int, Int) {
    var number = abs(num)
    var evenCount = 0
    var oddCount = 0

    while number > 0 {
        let digit = number % 10
        if digit % 2 == 0 {
            evenCount += 1
        } else {
            oddCount += 1
        }
        number /= 10
    }

    return (evenCount, oddCount)
}
```
 // XCTAssertTrue failed

func evenOddCount(num: Int) -> (Int, Int) {
    var number = abs(num)
    var evenCount = 0
    var oddCount = 0

    while number > 0 {
        let digit = number % 10
        if digit % 2 == 0 {
            evenCount += 1
        } else {
            oddCount += 1
        }
        number /= 10
    }

    return (evenCount, oddCount)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)[/INST]  ```swift
func evenOddCount(num: Int) -> (Int, Int) {
    var number = abs(num)
    var evenCount = 0
    var oddCount = 0

    while number > 0 {
        let digit = number % 10
        if digit % 2 == 0 {
            evenCount += 1
        } else {
            oddCount += 1
        }
        number /= 10
    }

    return (evenCount, oddCount)
}
```
 // XCTAssertTrue failed

func evenOddCount(num: Int) -> (Int, Int) {
    var number = abs(num)
    var evenCount = 0
    var oddCount = 0

    while number > 0 {
        let digit = number % 10
        if digit % 2 == 0 {
            evenCount += 1
        } else {
            oddCount += 1
        }
        number /= 10
    }

    return (evenCount, oddCount)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)[/INST]  ```swift
func evenOddCount(num: Int) -> (Int, Int) {
    var number = abs(num)
    var evenCount = 0
    var oddCount = 0

    while number > 0 {
        let digit = number % 10
        if digit % 2 == 0 {
            evenCount += 1
        } else {
            oddCount += 1
        }
        number /= 10
    }

    return (evenCount, oddCount)
}
```
 // XCTAssertTrue failed

func evenOddCount(num: Int) -> (Int, Int) {
    var number = abs(num)
    var evenCount = 0
    var oddCount = 0

    while number > 0 {
        let digit = number % 10
        if digit % 2 == 0 {
            evenCount += 1
        } else {
            oddCount += 1
        }
        number /= 10
    }

    return (evenCount, oddCount)
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)[/INST]  ```swift
func evenOddCount(num: Int) -> (Int, Int) {
    var number = abs(num)
    var evenCount = 0
    var oddCount = 0

    while number > 0 {
        let digit = number % 10
        if digit % 2 == 0 {
            evenCount += 1
        } else {
            oddCount += 1
        }
        number /= 10
    }

    return (evenCount, oddCount)
}
```
 // XCTAssertTrue failed

func intToMiniRoman(number: Int) -> String {
    let values = [1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1]
    let symbols = ["m", "cm", "d", "cd", "c", "xc", "l", "xl", "x", "ix", "v", "iv", "i"]

    var num = number
    var roman = ""

    for (index, value) in values.enumerated() {
        while num >= value {
            roman += symbols[index]
            num -= value
        }
    }

    return roman
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"[/INST]  ```swift
func intToMiniRoman(number: Int) -> String {
    let values = [1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1]
    let symbols = ["m", "cm", "d", "cd", "c", "xc", "l", "xl", "x", "ix", "v", "iv", "i"]

    var num = number
    var roman = ""

    for (index, value) in values.enumerated() {
        while num >= value {
            roman += symbols[index]
            num -= value
        }
    }

    return roman
}
```

func intToMiniRoman(number: Int) -> String {
    let values = [1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1]
    let symbols = ["m", "cm", "d", "cd", "c", "xc", "l", "xl", "x", "ix", "v", "iv", "i"]

    var num = number
    var roman = ""

    for (index, value) in values.enumerated() {
        while num >= value {
            roman += symbols[index]
            num -= value
        }
    }

    return roman
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"[/INST]  ```swift
func intToMiniRoman(number: Int) -> String {
    let values = [1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1]
    let symbols = ["m", "cm", "d", "cd", "c", "xc", "l", "xl", "x", "ix", "v", "iv", "i"]

    var num = number
    var roman = ""

    for (index, value) in values.enumerated() {
        while num >= value {
            roman += symbols[index]
            num -= value
        }
    }

    return roman
}
```

func intToMiniRoman(number: Int) -> String {
    let romanNumerals: [(Int, String)] = [
        (1000, "m"),
        (900, "cm"),
        (500, "d"),
        (400, "cd"),
        (100, "c"),
        (90, "xc"),
        (50, "l"),
        (40, "xl"),
        (10, "x"),
        (9, "ix"),
        (5, "v"),
        (4, "iv"),
        (1, "i")
    ]

    var number = number
    var result = ""

    for (value, numeral) in romanNumerals {
        while number >= value {
            result += numeral
            number -= value
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"[/INST]  ```swift
func intToMiniRoman(number: Int) -> String {
    let romanNumerals: [(Int, String)] = [
        (1000, "m"),
        (900, "cm"),
        (500, "d"),
        (400, "cd"),
        (100, "c"),
        (90, "xc"),
        (50, "l"),
        (40, "xl"),
        (10, "x"),
        (9, "ix"),
        (5, "v"),
        (4, "iv"),
        (1, "i")
    ]

    var number = number
    var result = ""

    for (value, numeral) in romanNumerals {
        while number >= value {
            result += numeral
            number -= value
        }
    }

    return result
}
```

func intToMiniRoman(number: Int) -> String {
    let values = [1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1]
    let symbols = ["m", "cm", "d", "cd", "c", "xc", "l", "xl", "x", "ix", "v", "iv", "i"]

    var result = ""
    var num = number

    for (index, value) in values.enumerated() {
        while num >= value {
            result += symbols[index]
            num -= value
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"[/INST]  ```swift
func intToMiniRoman(number: Int) -> String {
    let values = [1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1]
    let symbols = ["m", "cm", "d", "cd", "c", "xc", "l", "xl", "x", "ix", "v", "iv", "i"]

    var result = ""
    var num = number

    for (index, value) in values.enumerated() {
        while num >= value {
            result += symbols[index]
            num -= value
        }
    }

    return result
}
```

func intToMiniRoman(number: Int) -> String {
    let values = [1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1]
    let symbols = ["m", "cm", "d", "cd", "c", "xc", "l", "xl", "x", "ix", "v", "iv", "i"]
    var num = number
    var roman = ""
    for (index, value) in values.enumerated() {
        while num >= value {
            roman += symbols[index]
            num -= value
        }
    }
    return roman
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"[/INST]  ```swift
func intToMiniRoman(number: Int) -> String {
    let values = [1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1]
    let symbols = ["m", "cm", "d", "cd", "c", "xc", "l", "xl", "x", "ix", "v", "iv", "i"]
    var num = number
    var roman = ""
    for (index, value) in values.enumerated() {
        while num >= value {
            roman += symbols[index]
            num -= value
        }
    }
    return roman
}
```

func intToMiniRoman(number: Int) -> String {
    let values = [1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1]
    let symbols = ["m", "cm", "d", "cd", "c", "xc", "l", "xl", "x", "ix", "v", "iv", "i"]
    var num = number
    var roman = ""

    for (index, value) in values.enumerated() {
        while num >= value {
            roman += symbols[index]
            num -= value
        }
    }

    return roman
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"[/INST]  ```swift
func intToMiniRoman(number: Int) -> String {
    let values = [1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1]
    let symbols = ["m", "cm", "d", "cd", "c", "xc", "l", "xl", "x", "ix", "v", "iv", "i"]
    var num = number
    var roman = ""

    for (index, value) in values.enumerated() {
        while num >= value {
            roman += symbols[index]
            num -= value
        }
    }

    return roman
}
```

func intToMiniRoman(number: Int) -> String {
    let romanNumerals: [(Int, String)] = [
        (1000, "m"), (900, "cm"), (500, "d"), (400, "cd"),
        (100, "c"), (90, "xc"), (50, "l"), (40, "xl"),
        (10, "x"), (9, "ix"), (5, "v"), (4, "iv"), (1, "i")
    ]

    var result = ""
    var num = number

    for (value, numeral) in romanNumerals {
        while num >= value {
            result += numeral
            num -= value
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"[/INST]  ```swift
func intToMiniRoman(number: Int) -> String {
    let romanNumerals: [(Int, String)] = [
        (1000, "m"), (900, "cm"), (500, "d"), (400, "cd"),
        (100, "c"), (90, "xc"), (50, "l"), (40, "xl"),
        (10, "x"), (9, "ix"), (5, "v"), (4, "iv"), (1, "i")
    ]

    var result = ""
    var num = number

    for (value, numeral) in romanNumerals {
        while num >= value {
            result += numeral
            num -= value
        }
    }

    return result
}
```

func intToMiniRoman(number: Int) -> String {
    let values = [1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1]
    let symbols = ["m", "cm", "d", "cd", "c", "xc", "l", "xl", "x", "ix", "v", "iv", "i"]

    var num = number
    var roman = ""

    for (index, value) in values.enumerated() {
        while num >= value {
            roman += symbols[index]
            num -= value
        }
    }

    return roman
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"[/INST]  ```swift
func intToMiniRoman(number: Int) -> String {
    let values = [1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1]
    let symbols = ["m", "cm", "d", "cd", "c", "xc", "l", "xl", "x", "ix", "v", "iv", "i"]

    var num = number
    var roman = ""

    for (index, value) in values.enumerated() {
        while num >= value {
            roman += symbols[index]
            num -= value
        }
    }

    return roman
}
```

func intToMiniRoman(number: Int) -> String {
    let romanNumerals: [(Int, String)] = [
        (1000, "m"),
        (900, "cm"),
        (500, "d"),
        (400, "cd"),
        (100, "c"),
        (90, "xc"),
        (50, "l"),
        (40, "xl"),
        (10, "x"),
        (9, "ix"),
        (5, "v"),
        (4, "iv"),
        (1, "i")
    ]

    var num = number
    var result = ""

    for (value, numeral) in romanNumerals {
        while num >= value {
            result += numeral
            num -= value
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"[/INST]  ```swift
func intToMiniRoman(number: Int) -> String {
    let romanNumerals: [(Int, String)] = [
        (1000, "m"),
        (900, "cm"),
        (500, "d"),
        (400, "cd"),
        (100, "c"),
        (90, "xc"),
        (50, "l"),
        (40, "xl"),
        (10, "x"),
        (9, "ix"),
        (5, "v"),
        (4, "iv"),
        (1, "i")
    ]

    var num = number
    var result = ""

    for (value, numeral) in romanNumerals {
        while num >= value {
            result += numeral
            num -= value
        }
    }

    return result
}
```

func intToMiniRoman(number: Int) -> String {
    let values = [1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1]
    let symbols = ["m", "cm", "d", "cd", "c", "xc", "l", "xl", "x", "ix", "v", "iv", "i"]

    var num = number
    var roman = ""

    for (index, value) in values.enumerated() {
        while num >= value {
            roman += symbols[index]
            num -= value
        }
    }

    return roman
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"[/INST]  ```swift
func intToMiniRoman(number: Int) -> String {
    let values = [1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1]
    let symbols = ["m", "cm", "d", "cd", "c", "xc", "l", "xl", "x", "ix", "v", "iv", "i"]

    var num = number
    var roman = ""

    for (index, value) in values.enumerated() {
        while num >= value {
            roman += symbols[index]
            num -= value
        }
    }

    return roman
}
```

func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
    let sides = [a, b, c].sorted()
    return sides[0] * sides[0] + sides[1] * sides[1] == sides[2] * sides[2]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or 
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false[/INST]  ```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
    let sides = [a, b, c].sorted()
    return sides[0] * sides[0] + sides[1] * sides[1] == sides[2] * sides[2]
}
```

func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
    let sides = [a, b, c].sorted()
    return sides[0] * sides[0] + sides[1] * sides[1] == sides[2] * sides[2]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or 
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false[/INST]  ```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
    let sides = [a, b, c].sorted()
    return sides[0] * sides[0] + sides[1] * sides[1] == sides[2] * sides[2]
}
```

func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
    let sides = [a, b, c].sorted()
    return sides[0] * sides[0] + sides[1] * sides[1] == sides[2] * sides[2]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or 
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false[/INST]  ```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
    let sides = [a, b, c].sorted()
    return sides[0] * sides[0] + sides[1] * sides[1] == sides[2] * sides[2]
}
```

func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
    let sides = [a, b, c].sorted()
    return sides[0] * sides[0] + sides[1] * sides[1] == sides[2] * sides[2]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or 
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false[/INST]  ```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
    let sides = [a, b, c].sorted()
    return sides[0] * sides[0] + sides[1] * sides[1] == sides[2] * sides[2]
}
```

func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
    let sides = [a, b, c].sorted()
    return sides[0]*sides[0] + sides[1]*sides[1] == sides[2]*sides[2]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or 
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false[/INST]  ```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
    let sides = [a, b, c].sorted()
    return sides[0]*sides[0] + sides[1]*sides[1] == sides[2]*sides[2]
}
```

func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
    let sides = [a, b, c].sorted()
    return (sides[0] * sides[0] + sides[1] * sides[1] == sides[2] * sides[2])
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or 
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false[/INST]  ```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
    let sides = [a, b, c].sorted()
    return (sides[0] * sides[0] + sides[1] * sides[1] == sides[2] * sides[2])
}
```

func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
    let sides = [a, b, c].sorted()
    return sides[0] * sides[0] + sides[1] * sides[1] == sides[2] * sides[2]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or 
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false[/INST]  ```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
    let sides = [a, b, c].sorted()
    return sides[0] * sides[0] + sides[1] * sides[1] == sides[2] * sides[2]
}
```

func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
    let sides = [a, b, c].sorted()
    return (sides[0] * sides[0] + sides[1] * sides[1] == sides[2] * sides[2])
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or 
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false[/INST]  ```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
    let sides = [a, b, c].sorted()
    return (sides[0] * sides[0] + sides[1] * sides[1] == sides[2] * sides[2])
}
```

func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
    let sides = [a, b, c].sorted()
    return sides[0] * sides[0] + sides[1] * sides[1] == sides[2] * sides[2]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or 
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false[/INST]  ```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
    let sides = [a, b, c].sorted()
    return sides[0] * sides[0] + sides[1] * sides[1] == sides[2] * sides[2]
}
```

func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
    let sides = [a, b, c].sorted()
    return sides[0]*sides[0] + sides[1]*sides[1] == sides[2]*sides[2]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or 
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false[/INST]  ```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
    let sides = [a, b, c].sorted()
    return sides[0]*sides[0] + sides[1]*sides[1] == sides[2]*sides[2]
}
```

func findMax(words: [String]) -> String {
    var maxUniqueChars = 0
    var maxUniqueWord = ""

    for word in words {
        let uniqueChars = Set(word).count
        if uniqueChars > maxUniqueChars {
            maxUniqueChars = uniqueChars
            maxUniqueWord = word
        } else if uniqueChars == maxUniqueChars {
            if word < maxUniqueWord {
                maxUniqueWord = word
            }
        }
    }

    return maxUniqueWord
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"[/INST]  ```swift
func findMax(words: [String]) -> String {
    var maxUniqueChars = 0
    var maxUniqueWord = ""

    for word in words {
        let uniqueChars = Set(word).count
        if uniqueChars > maxUniqueChars {
            maxUniqueChars = uniqueChars
            maxUniqueWord = word
        } else if uniqueChars == maxUniqueChars {
            if word < maxUniqueWord {
                maxUniqueWord = word
            }
        }
    }

    return maxUniqueWord
}
```

func findMax(words: [String]) -> String {
    var maxUniqueChars = 0
    var maxUniqueWord = ""

    for word in words {
        let uniqueChars = Set(word).count
        if uniqueChars > maxUniqueChars {
            maxUniqueChars = uniqueChars
            maxUniqueWord = word
        } else if uniqueChars == maxUniqueChars {
            if word < maxUniqueWord {
                maxUniqueWord = word
            }
        }
    }

    return maxUniqueWord
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"[/INST]  ```swift
func findMax(words: [String]) -> String {
    var maxUniqueChars = 0
    var maxUniqueWord = ""

    for word in words {
        let uniqueChars = Set(word).count
        if uniqueChars > maxUniqueChars {
            maxUniqueChars = uniqueChars
            maxUniqueWord = word
        } else if uniqueChars == maxUniqueChars {
            if word < maxUniqueWord {
                maxUniqueWord = word
            }
        }
    }

    return maxUniqueWord
}
```

func findMax(words: [String]) -> String {
    var maxUniqueChars = 0
    var maxUniqueWord = ""

    for word in words {
        let uniqueChars = Set(word).count
        if uniqueChars > maxUniqueChars {
            maxUniqueChars = uniqueChars
            maxUniqueWord = word
        } else if uniqueChars == maxUniqueChars {
            if word < maxUniqueWord {
                maxUniqueWord = word
            }
        }
    }

    return maxUniqueWord
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"[/INST]  ```swift
func findMax(words: [String]) -> String {
    var maxUniqueChars = 0
    var maxUniqueWord = ""

    for word in words {
        let uniqueChars = Set(word).count
        if uniqueChars > maxUniqueChars {
            maxUniqueChars = uniqueChars
            maxUniqueWord = word
        } else if uniqueChars == maxUniqueChars {
            if word < maxUniqueWord {
                maxUniqueWord = word
            }
        }
    }

    return maxUniqueWord
}
```

func findMax(words: [String]) -> String {
    var maxUniqueChars = 0
    var maxUniqueWord = ""

    for word in words {
        let uniqueChars = Set(word).count
        if uniqueChars > maxUniqueChars {
            maxUniqueChars = uniqueChars
            maxUniqueWord = word
        } else if uniqueChars == maxUniqueChars {
            if word < maxUniqueWord {
                maxUniqueWord = word
            }
        }
    }

    return maxUniqueWord
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"[/INST]  ```swift
func findMax(words: [String]) -> String {
    var maxUniqueChars = 0
    var maxUniqueWord = ""

    for word in words {
        let uniqueChars = Set(word).count
        if uniqueChars > maxUniqueChars {
            maxUniqueChars = uniqueChars
            maxUniqueWord = word
        } else if uniqueChars == maxUniqueChars {
            if word < maxUniqueWord {
                maxUniqueWord = word
            }
        }
    }

    return maxUniqueWord
}
```

func findMax(words: [String]) -> String {
    var maxUniqueChars = 0
    var maxUniqueWord = ""

    for word in words {
        let uniqueChars = Set(word).count
        if uniqueChars > maxUniqueChars {
            maxUniqueChars = uniqueChars
            maxUniqueWord = word
        } else if uniqueChars == maxUniqueChars {
            if word < maxUniqueWord {
                maxUniqueWord = word
            }
        }
    }

    return maxUniqueWord
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"[/INST]  ```swift
func findMax(words: [String]) -> String {
    var maxUniqueChars = 0
    var maxUniqueWord = ""

    for word in words {
        let uniqueChars = Set(word).count
        if uniqueChars > maxUniqueChars {
            maxUniqueChars = uniqueChars
            maxUniqueWord = word
        } else if uniqueChars == maxUniqueChars {
            if word < maxUniqueWord {
                maxUniqueWord = word
            }
        }
    }

    return maxUniqueWord
}
```

func findMax(words: [String]) -> String {
    var maxUniqueChars = 0
    var maxUniqueWord = ""

    for word in words {
        let uniqueChars = Set(word).count
        if uniqueChars > maxUniqueChars {
            maxUniqueChars = uniqueChars
            maxUniqueWord = word
        } else if uniqueChars == maxUniqueChars {
            if word < maxUniqueWord {
                maxUniqueWord = word
            }
        }
    }

    return maxUniqueWord
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"[/INST]  ```swift
func findMax(words: [String]) -> String {
    var maxUniqueChars = 0
    var maxUniqueWord = ""

    for word in words {
        let uniqueChars = Set(word).count
        if uniqueChars > maxUniqueChars {
            maxUniqueChars = uniqueChars
            maxUniqueWord = word
        } else if uniqueChars == maxUniqueChars {
            if word < maxUniqueWord {
                maxUniqueWord = word
            }
        }
    }

    return maxUniqueWord
}
```

func findMax(words: [String]) -> String {
    var maxUniqueChars = 0
    var maxUniqueWord = ""

    for word in words {
        let uniqueChars = Set(word).count
        if uniqueChars > maxUniqueChars {
            maxUniqueChars = uniqueChars
            maxUniqueWord = word
        } else if uniqueChars == maxUniqueChars {
            if word < maxUniqueWord {
                maxUniqueWord = word
            }
        }
    }

    return maxUniqueWord
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"[/INST]  ```swift
func findMax(words: [String]) -> String {
    var maxUniqueChars = 0
    var maxUniqueWord = ""

    for word in words {
        let uniqueChars = Set(word).count
        if uniqueChars > maxUniqueChars {
            maxUniqueChars = uniqueChars
            maxUniqueWord = word
        } else if uniqueChars == maxUniqueChars {
            if word < maxUniqueWord {
                maxUniqueWord = word
            }
        }
    }

    return maxUniqueWord
}
```

func findMax(words: [String]) -> String {
    var maxUniqueChars = 0
    var maxUniqueWord = ""

    for word in words {
        let uniqueChars = Set(word).count
        if uniqueChars > maxUniqueChars {
            maxUniqueChars = uniqueChars
            maxUniqueWord = word
        } else if uniqueChars == maxUniqueChars {
            if word < maxUniqueWord {
                maxUniqueWord = word
            }
        }
    }

    return maxUniqueWord
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"[/INST]  ```swift
func findMax(words: [String]) -> String {
    var maxUniqueChars = 0
    var maxUniqueWord = ""

    for word in words {
        let uniqueChars = Set(word).count
        if uniqueChars > maxUniqueChars {
            maxUniqueChars = uniqueChars
            maxUniqueWord = word
        } else if uniqueChars == maxUniqueChars {
            if word < maxUniqueWord {
                maxUniqueWord = word
            }
        }
    }

    return maxUniqueWord
}
```

func findMax(words: [String]) -> String {
    var maxUniqueChars = 0
    var maxUniqueWord = ""

    for word in words {
        let uniqueChars = Set(word).count
        if uniqueChars > maxUniqueChars {
            maxUniqueChars = uniqueChars
            maxUniqueWord = word
        } else if uniqueChars == maxUniqueChars {
            if word < maxUniqueWord {
                maxUniqueWord = word
            }
        }
    }

    return maxUniqueWord
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"[/INST]  ```swift
func findMax(words: [String]) -> String {
    var maxUniqueChars = 0
    var maxUniqueWord = ""

    for word in words {
        let uniqueChars = Set(word).count
        if uniqueChars > maxUniqueChars {
            maxUniqueChars = uniqueChars
            maxUniqueWord = word
        } else if uniqueChars == maxUniqueChars {
            if word < maxUniqueWord {
                maxUniqueWord = word
            }
        }
    }

    return maxUniqueWord
}
```

func findMax(words: [String]) -> String {
    var maxUniqueChars = 0
    var maxUniqueWord = ""

    for word in words {
        let uniqueChars = Set(word).count
        if uniqueChars > maxUniqueChars {
            maxUniqueChars = uniqueChars
            maxUniqueWord = word
        } else if uniqueChars == maxUniqueChars {
            if word < maxUniqueWord {
                maxUniqueWord = word
            }
        }
    }

    return maxUniqueWord
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"[/INST]  ```swift
func findMax(words: [String]) -> String {
    var maxUniqueChars = 0
    var maxUniqueWord = ""

    for word in words {
        let uniqueChars = Set(word).count
        if uniqueChars > maxUniqueChars {
            maxUniqueChars = uniqueChars
            maxUniqueWord = word
        } else if uniqueChars == maxUniqueChars {
            if word < maxUniqueWord {
                maxUniqueWord = word
            }
        }
    }

    return maxUniqueWord
}
```

@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0][/INST]  ```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
    let carrotsToEat = min(need, remaining)
    let totalEaten = number + carrotsToEat
    let remainingCarrots = remaining - carrotsToEat
    return [totalEaten, remainingCarrots]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0][/INST]  ```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
    let carrotsToEat = min(need, remaining)
    let totalEaten = number + carrotsToEat
    let remainingCarrots = remaining - carrotsToEat
    return [totalEaten, remainingCarrots]
}
```
@number : integer // expected expression
the number of carrots that you have eaten. // expected member name following '.'
the number of carrots that you need to eat. // expected member name following '.'

@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0][/INST]  ```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
    let carrotsEaten = min(need, remaining)
    let totalEaten = number + carrotsEaten
    let carrotsLeft = remaining - carrotsEaten
    return [totalEaten, carrotsLeft]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0][/INST]  ```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
    let carrotsEaten = min(need, remaining)
    let totalEaten = number + carrotsEaten
    let carrotsLeft = remaining - carrotsEaten
    return [totalEaten, carrotsLeft]
}
```
@number : integer // expected expression
the number of carrots that you have eaten. // expected member name following '.'
the number of carrots that you need to eat. // expected member name following '.'

@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0][/INST]  ```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
    let carrotsToEat = min(need, remaining)
    let totalEaten = number + carrotsToEat
    let remainingCarrots = remaining - carrotsToEat
    return [totalEaten, remainingCarrots]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0][/INST]  ```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
    let carrotsToEat = min(need, remaining)
    let totalEaten = number + carrotsToEat
    let remainingCarrots = remaining - carrotsToEat
    return [totalEaten, remainingCarrots]
}
```
@number : integer // expected expression
the number of carrots that you have eaten. // expected member name following '.'
the number of carrots that you need to eat. // expected member name following '.'

@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0][/INST]  ```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
    let carrotsEaten = min(need, remaining)
    let totalEaten = number + carrotsEaten
    let remainingCarrots = remaining - carrotsEaten
    return [totalEaten, remainingCarrots]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0][/INST]  ```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
    let carrotsEaten = min(need, remaining)
    let totalEaten = number + carrotsEaten
    let remainingCarrots = remaining - carrotsEaten
    return [totalEaten, remainingCarrots]
}
```
@number : integer // expected expression
the number of carrots that you have eaten. // expected member name following '.'
the number of carrots that you need to eat. // expected member name following '.'

@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0][/INST]  ```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
    let carrotsEaten = min(need, remaining)
    let totalEaten = number + carrotsEaten
    let remainingCarrots = remaining - carrotsEaten
    return [totalEaten, remainingCarrots]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0][/INST]  ```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
    let carrotsEaten = min(need, remaining)
    let totalEaten = number + carrotsEaten
    let remainingCarrots = remaining - carrotsEaten
    return [totalEaten, remainingCarrots]
}
```
@number : integer // expected expression
the number of carrots that you have eaten. // expected member name following '.'
the number of carrots that you need to eat. // expected member name following '.'

@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0][/INST]  ```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
    let carrotsEaten = min(need, remaining)
    let totalEaten = number + carrotsEaten
    let remainingCarrots = remaining - carrotsEaten
    return [totalEaten, remainingCarrots]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0][/INST]  ```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
    let carrotsEaten = min(need, remaining)
    let totalEaten = number + carrotsEaten
    let remainingCarrots = remaining - carrotsEaten
    return [totalEaten, remainingCarrots]
}
```
@number : integer // expected expression
the number of carrots that you have eaten. // expected member name following '.'
the number of carrots that you need to eat. // expected member name following '.'

@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0][/INST]  ```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
    let carrotsEaten = min(need, remaining)
    let totalEaten = number + carrotsEaten
    let remainingCarrots = remaining - carrotsEaten
    return [totalEaten, remainingCarrots]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0][/INST]  ```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
    let carrotsEaten = min(need, remaining)
    let totalEaten = number + carrotsEaten
    let remainingCarrots = remaining - carrotsEaten
    return [totalEaten, remainingCarrots]
}
```
@number : integer // expected expression
the number of carrots that you have eaten. // expected member name following '.'
the number of carrots that you need to eat. // expected member name following '.'

@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0][/INST]  ```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
    let carrotsEaten = min(need, remaining)
    let totalEaten = number + carrotsEaten
    let remainingCarrots = remaining - carrotsEaten
    return [totalEaten, remainingCarrots]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0][/INST]  ```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
    let carrotsEaten = min(need, remaining)
    let totalEaten = number + carrotsEaten
    let remainingCarrots = remaining - carrotsEaten
    return [totalEaten, remainingCarrots]
}
```
@number : integer // expected expression
the number of carrots that you have eaten. // expected member name following '.'
the number of carrots that you need to eat. // expected member name following '.'

@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0][/INST]  ```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
    let carrotsEaten = min(need, remaining)
    let totalEaten = number + carrotsEaten
    let remainingCarrots = remaining - carrotsEaten
    return [totalEaten, remainingCarrots]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0][/INST]  ```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
    let carrotsEaten = min(need, remaining)
    let totalEaten = number + carrotsEaten
    let remainingCarrots = remaining - carrotsEaten
    return [totalEaten, remainingCarrots]
}
```
@number : integer // expected expression
the number of carrots that you have eaten. // expected member name following '.'
the number of carrots that you need to eat. // expected member name following '.'

@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0][/INST]  ```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
    let carrotsToEat = min(need, remaining)
    let totalEaten = number + carrotsToEat
    let remainingCarrots = remaining - carrotsToEat
    return [totalEaten, remainingCarrots]
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0][/INST]  ```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
    let carrotsToEat = min(need, remaining)
    let totalEaten = number + carrotsToEat
    let remainingCarrots = remaining - carrotsToEat
    return [totalEaten, remainingCarrots]
}
```
@number : integer // expected expression
the number of carrots that you have eaten. // expected member name following '.'
the number of carrots that you need to eat. // expected member name following '.'

func doAlgebra(operators: [String], operands: [Int]) -> Int {
    var result = operands[0]
    for i in 0..<operators.count {
        let operator = operators[i]
        let operand = operands[i + 1]
        switch operator {
        case "+":
            result += operand
        case "-":
            result -= operand
        case "*":
            result *= operand
        case "//":
            result /= operand
        case "**":
            result = Int(pow(Double(result), Double(operand)))
        default:
            fatalError("Invalid operator: \(operator)")
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and 
the second array is an array of integers. Use the two given arrays to build the algebric 
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + ) 
Subtraction ( - ) 
Multiplication ( * ) 
Floor division ( // ) 
Exponentiation ( ** ) 
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
[/INST]  ```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
    var result = operands[0]
    for i in 0..<operators.count {
        let operator = operators[i]
        let operand = operands[i + 1]
        switch operator {
        case "+":
            result += operand
        case "-":
            result -= operand
        case "*":
            result *= operand
        case "//":
            result /= operand
        case "**":
            result = Int(pow(Double(result), Double(operand)))
        default:
            fatalError("Invalid operator: \(operator)")
        }
    }
    return result
}
```
let operator = operators[i] // keyword 'operator' cannot be used as an identifier here
switch operator { // expected operator name in operator declaration
switch operator { // expected expression in 'switch' statement

func doAlgebra(operators: [String], operands: [Int]) -> Int {
    var result = operands[0]
    for i in 0..<operators.count {
        let operator = operators[i]
        let operand = operands[i + 1]
        switch operator {
        case "+":
            result += operand
        case "-":
            result -= operand
        case "*":
            result *= operand
        case "//":
            result /= operand
        case "**":
            result = Int(pow(Double(result), Double(operand)))
        default:
            fatalError("Invalid operator: \(operator)")
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and 
the second array is an array of integers. Use the two given arrays to build the algebric 
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + ) 
Subtraction ( - ) 
Multiplication ( * ) 
Floor division ( // ) 
Exponentiation ( ** ) 
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
[/INST]  ```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
    var result = operands[0]
    for i in 0..<operators.count {
        let operator = operators[i]
        let operand = operands[i + 1]
        switch operator {
        case "+":
            result += operand
        case "-":
            result -= operand
        case "*":
            result *= operand
        case "//":
            result /= operand
        case "**":
            result = Int(pow(Double(result), Double(operand)))
        default:
            fatalError("Invalid operator: \(operator)")
        }
    }
    return result
}
```
let operator = operators[i] // keyword 'operator' cannot be used as an identifier here
switch operator { // expected operator name in operator declaration
switch operator { // expected expression in 'switch' statement

func doAlgebra(operators: [String], operands: [Int]) -> Int {
    var result = operands[0]
    for i in 0..<operators.count {
        switch operators[i] {
        case "+":
            result += operands[i+1]
        case "-":
            result -= operands[i+1]
        case "*":
            result *= operands[i+1]
        case "//":
            result /= operands[i+1]
        case "**":
            result = Int(pow(Double(result), Double(operands[i+1])))
        default:
            fatalError("Invalid operator")
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and 
the second array is an array of integers. Use the two given arrays to build the algebric 
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + ) 
Subtraction ( - ) 
Multiplication ( * ) 
Floor division ( // ) 
Exponentiation ( ** ) 
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
[/INST]  ```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
    var result = operands[0]
    for i in 0..<operators.count {
        switch operators[i] {
        case "+":
            result += operands[i+1]
        case "-":
            result -= operands[i+1]
        case "*":
            result *= operands[i+1]
        case "//":
            result /= operands[i+1]
        case "**":
            result = Int(pow(Double(result), Double(operands[i+1])))
        default:
            fatalError("Invalid operator")
        }
    }
    return result
}
```
 // XCTAssertTrue failed

func doAlgebra(operators: [String], operands: [Int]) -> Int {
    var result = operands[0]
    for i in 0..<operators.count {
        switch operators[i] {
        case "+":
            result += operands[i + 1]
        case "-":
            result -= operands[i + 1]
        case "*":
            result *= operands[i + 1]
        case "//":
            result /= operands[i + 1]
        case "**":
            result = Int(pow(Double(result), Double(operands[i + 1])))
        default:
            fatalError("Invalid operator")
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and 
the second array is an array of integers. Use the two given arrays to build the algebric 
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + ) 
Subtraction ( - ) 
Multiplication ( * ) 
Floor division ( // ) 
Exponentiation ( ** ) 
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
[/INST]  ```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
    var result = operands[0]
    for i in 0..<operators.count {
        switch operators[i] {
        case "+":
            result += operands[i + 1]
        case "-":
            result -= operands[i + 1]
        case "*":
            result *= operands[i + 1]
        case "//":
            result /= operands[i + 1]
        case "**":
            result = Int(pow(Double(result), Double(operands[i + 1])))
        default:
            fatalError("Invalid operator")
        }
    }
    return result
}
```
 // XCTAssertTrue failed

func doAlgebra(operators: [String], operands: [Int]) -> Int {
    var result = operands[0]
    for i in 0..<operators.count {
        switch operators[i] {
        case "+":
            result += operands[i+1]
        case "-":
            result -= operands[i+1]
        case "*":
            result *= operands[i+1]
        case "//":
            result /= operands[i+1]
        case "**":
            result = Int(pow(Double(result), Double(operands[i+1])))
        default:
            fatalError("Invalid operator")
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and 
the second array is an array of integers. Use the two given arrays to build the algebric 
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + ) 
Subtraction ( - ) 
Multiplication ( * ) 
Floor division ( // ) 
Exponentiation ( ** ) 
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
[/INST]  ```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
    var result = operands[0]
    for i in 0..<operators.count {
        switch operators[i] {
        case "+":
            result += operands[i+1]
        case "-":
            result -= operands[i+1]
        case "*":
            result *= operands[i+1]
        case "//":
            result /= operands[i+1]
        case "**":
            result = Int(pow(Double(result), Double(operands[i+1])))
        default:
            fatalError("Invalid operator")
        }
    }
    return result
}
```
 // XCTAssertTrue failed

func doAlgebra(operators: [String], operands: [Int]) -> Int {
    var result = operands[0]
    for i in 0..<operators.count {
        switch operators[i] {
        case "+":
            result += operands[i + 1]
        case "-":
            result -= operands[i + 1]
        case "*":
            result *= operands[i + 1]
        case "//":
            result /= operands[i + 1]
        case "**":
            result = Int(pow(Double(result), Double(operands[i + 1])))
        default:
            break
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and 
the second array is an array of integers. Use the two given arrays to build the algebric 
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + ) 
Subtraction ( - ) 
Multiplication ( * ) 
Floor division ( // ) 
Exponentiation ( ** ) 
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
[/INST]  ```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
    var result = operands[0]
    for i in 0..<operators.count {
        switch operators[i] {
        case "+":
            result += operands[i + 1]
        case "-":
            result -= operands[i + 1]
        case "*":
            result *= operands[i + 1]
        case "//":
            result /= operands[i + 1]
        case "**":
            result = Int(pow(Double(result), Double(operands[i + 1])))
        default:
            break
        }
    }
    return result
}
```
 // XCTAssertTrue failed

func doAlgebra(operators: [String], operands: [Int]) -> Int {
    var result = operands[0]
    for i in 0..<operators.count {
        switch operators[i] {
        case "+":
            result += operands[i+1]
        case "-":
            result -= operands[i+1]
        case "*":
            result *= operands[i+1]
        case "//":
            result /= operands[i+1]
        case "**":
            result = Int(pow(Double(result), Double(operands[i+1])))
        default:
            fatalError("Invalid operator")
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and 
the second array is an array of integers. Use the two given arrays to build the algebric 
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + ) 
Subtraction ( - ) 
Multiplication ( * ) 
Floor division ( // ) 
Exponentiation ( ** ) 
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
[/INST]  ```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
    var result = operands[0]
    for i in 0..<operators.count {
        switch operators[i] {
        case "+":
            result += operands[i+1]
        case "-":
            result -= operands[i+1]
        case "*":
            result *= operands[i+1]
        case "//":
            result /= operands[i+1]
        case "**":
            result = Int(pow(Double(result), Double(operands[i+1])))
        default:
            fatalError("Invalid operator")
        }
    }
    return result
}
```
 // XCTAssertTrue failed

func doAlgebra(operators: [String], operands: [Int]) -> Int {
    var result = operands[0]
    for i in 0..<operators.count {
        switch operators[i] {
        case "+":
            result += operands[i + 1]
        case "-":
            result -= operands[i + 1]
        case "*":
            result *= operands[i + 1]
        case "//":
            result /= operands[i + 1]
        case "**":
            result = Int(pow(Double(result), Double(operands[i + 1])))
        default:
            fatalError("Invalid operator")
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and 
the second array is an array of integers. Use the two given arrays to build the algebric 
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + ) 
Subtraction ( - ) 
Multiplication ( * ) 
Floor division ( // ) 
Exponentiation ( ** ) 
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
[/INST]  ```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
    var result = operands[0]
    for i in 0..<operators.count {
        switch operators[i] {
        case "+":
            result += operands[i + 1]
        case "-":
            result -= operands[i + 1]
        case "*":
            result *= operands[i + 1]
        case "//":
            result /= operands[i + 1]
        case "**":
            result = Int(pow(Double(result), Double(operands[i + 1])))
        default:
            fatalError("Invalid operator")
        }
    }
    return result
}
```
 // XCTAssertTrue failed

func doAlgebra(operators: [String], operands: [Int]) -> Int {
    var result = operands[0]
    for i in 0..<operators.count {
        switch operators[i] {
        case "+":
            result += operands[i+1]
        case "-":
            result -= operands[i+1]
        case "*":
            result *= operands[i+1]
        case "//":
            result /= operands[i+1]
        case "**":
            result = Int(pow(Double(result), Double(operands[i+1])))
        default:
            fatalError("Invalid operator: \(operators[i])")
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and 
the second array is an array of integers. Use the two given arrays to build the algebric 
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + ) 
Subtraction ( - ) 
Multiplication ( * ) 
Floor division ( // ) 
Exponentiation ( ** ) 
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
[/INST]  ```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
    var result = operands[0]
    for i in 0..<operators.count {
        switch operators[i] {
        case "+":
            result += operands[i+1]
        case "-":
            result -= operands[i+1]
        case "*":
            result *= operands[i+1]
        case "//":
            result /= operands[i+1]
        case "**":
            result = Int(pow(Double(result), Double(operands[i+1])))
        default:
            fatalError("Invalid operator: \(operators[i])")
        }
    }
    return result
}
```
 // XCTAssertTrue failed

func doAlgebra(operators: [String], operands: [Int]) -> Int {
    var result = operands[0]
    for i in 0..<operators.count {
        switch operators[i] {
        case "+":
            result += operands[i+1]
        case "-":
            result -= operands[i+1]
        case "*":
            result *= operands[i+1]
        case "//":
            result /= operands[i+1]
        case "**":
            result = Int(pow(Double(result), Double(operands[i+1])))
        default:
            print("Invalid operator")
        }
    }
    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and 
the second array is an array of integers. Use the two given arrays to build the algebric 
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + ) 
Subtraction ( - ) 
Multiplication ( * ) 
Floor division ( // ) 
Exponentiation ( ** ) 
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
[/INST]  ```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
    var result = operands[0]
    for i in 0..<operators.count {
        switch operators[i] {
        case "+":
            result += operands[i+1]
        case "-":
            result -= operands[i+1]
        case "*":
            result *= operands[i+1]
        case "//":
            result /= operands[i+1]
        case "**":
            result = Int(pow(Double(result), Double(operands[i+1])))
        default:
            print("Invalid operator")
        }
    }
    return result
}
```
 // XCTAssertTrue failed

func solve(s: String) -> String {
    var result = ""
    var hasLetter = false

    for char in s {
        if char.isLetter {
            hasLetter = true
            if char.isUppercase {
                result.append(char.lowercased())
            } else {
                result.append(char.uppercased())
            }
        } else {
            result.append(char)
        }
    }

    if !hasLetter {
        result = String(result.reversed())
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa, 
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"[/INST]  ```swift
func solve(s: String) -> String {
    var result = ""
    var hasLetter = false

    for char in s {
        if char.isLetter {
            hasLetter = true
            if char.isUppercase {
                result.append(char.lowercased())
            } else {
                result.append(char.uppercased())
            }
        } else {
            result.append(char)
        }
    }

    if !hasLetter {
        result = String(result.reversed())
    }

    return result
}
```

func solve(s: String) -> String {
    var result = ""
    var hasLetter = false

    for char in s {
        if char.isLetter {
            hasLetter = true
            if char.isUppercase {
                result.append(char.lowercased())
            } else {
                result.append(char.uppercased())
            }
        } else {
            result.append(char)
        }
    }

    if !hasLetter {
        result = String(result.reversed())
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa, 
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"[/INST]  ```swift
func solve(s: String) -> String {
    var result = ""
    var hasLetter = false

    for char in s {
        if char.isLetter {
            hasLetter = true
            if char.isUppercase {
                result.append(char.lowercased())
            } else {
                result.append(char.uppercased())
            }
        } else {
            result.append(char)
        }
    }

    if !hasLetter {
        result = String(result.reversed())
    }

    return result
}
```

func solve(s: String) -> String {
    var result = ""
    var hasLetter = false

    for char in s {
        if char.isLetter {
            hasLetter = true
            if char.isUppercase {
                result.append(char.lowercased())
            } else {
                result.append(char.uppercased())
            }
        } else {
            result.append(char)
        }
    }

    if !hasLetter {
        result = String(result.reversed())
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa, 
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"[/INST]  ```swift
func solve(s: String) -> String {
    var result = ""
    var hasLetter = false

    for char in s {
        if char.isLetter {
            hasLetter = true
            if char.isUppercase {
                result.append(char.lowercased())
            } else {
                result.append(char.uppercased())
            }
        } else {
            result.append(char)
        }
    }

    if !hasLetter {
        result = String(result.reversed())
    }

    return result
}
```

func solve(s: String) -> String {
    var result = ""
    var hasLetter = false

    for char in s {
        if char.isLetter {
            hasLetter = true
            if char.isUppercase {
                result.append(char.lowercased())
            } else {
                result.append(char.uppercased())
            }
        } else {
            result.append(char)
        }
    }

    if !hasLetter {
        result = String(result.reversed())
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa, 
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"[/INST]  ```swift
func solve(s: String) -> String {
    var result = ""
    var hasLetter = false

    for char in s {
        if char.isLetter {
            hasLetter = true
            if char.isUppercase {
                result.append(char.lowercased())
            } else {
                result.append(char.uppercased())
            }
        } else {
            result.append(char)
        }
    }

    if !hasLetter {
        result = String(result.reversed())
    }

    return result
}
```

func solve(s: String) -> String {
    var result = ""
    var hasLetter = false

    for char in s {
        if char.isLetter {
            hasLetter = true
            if char.isUppercase {
                result.append(char.lowercased())
            } else {
                result.append(char.uppercased())
            }
        } else {
            result.append(char)
        }
    }

    if !hasLetter {
        result = String(result.reversed())
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa, 
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"[/INST]  ```swift
func solve(s: String) -> String {
    var result = ""
    var hasLetter = false

    for char in s {
        if char.isLetter {
            hasLetter = true
            if char.isUppercase {
                result.append(char.lowercased())
            } else {
                result.append(char.uppercased())
            }
        } else {
            result.append(char)
        }
    }

    if !hasLetter {
        result = String(result.reversed())
    }

    return result
}
```

func solve(s: String) -> String {
    var result = ""
    var hasLetter = false

    for char in s {
        if char.isLetter {
            hasLetter = true
            if char.isUppercase {
                result.append(char.lowercased())
            } else {
                result.append(char.uppercased())
            }
        } else {
            result.append(char)
        }
    }

    if !hasLetter {
        result = String(result.reversed())
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa, 
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"[/INST]  ```swift
func solve(s: String) -> String {
    var result = ""
    var hasLetter = false

    for char in s {
        if char.isLetter {
            hasLetter = true
            if char.isUppercase {
                result.append(char.lowercased())
            } else {
                result.append(char.uppercased())
            }
        } else {
            result.append(char)
        }
    }

    if !hasLetter {
        result = String(result.reversed())
    }

    return result
}
```

func solve(s: String) -> String {
    var result = ""
    var hasLetter = false

    for char in s {
        if char.isLetter {
            hasLetter = true
            if char.isUppercase {
                result.append(char.lowercased())
            } else {
                result.append(char.uppercased())
            }
        } else {
            result.append(char)
        }
    }

    if !hasLetter {
        result = String(result.reversed())
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa, 
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"[/INST]  ```swift
func solve(s: String) -> String {
    var result = ""
    var hasLetter = false

    for char in s {
        if char.isLetter {
            hasLetter = true
            if char.isUppercase {
                result.append(char.lowercased())
            } else {
                result.append(char.uppercased())
            }
        } else {
            result.append(char)
        }
    }

    if !hasLetter {
        result = String(result.reversed())
    }

    return result
}
```

func solve(s: String) -> String {
    var result = ""
    var hasLetter = false

    for char in s {
        if char.isLetter {
            hasLetter = true
            if char.isLowercase {
                result.append(char.uppercased())
            } else {
                result.append(char.lowercased())
            }
        } else {
            result.append(char)
        }
    }

    if !hasLetter {
        result = String(result.reversed())
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa, 
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"[/INST]  ```swift
func solve(s: String) -> String {
    var result = ""
    var hasLetter = false

    for char in s {
        if char.isLetter {
            hasLetter = true
            if char.isLowercase {
                result.append(char.uppercased())
            } else {
                result.append(char.lowercased())
            }
        } else {
            result.append(char)
        }
    }

    if !hasLetter {
        result = String(result.reversed())
    }

    return result
}
```

func solve(s: String) -> String {
    var result = ""
    var hasLetter = false

    for char in s {
        if char.isLetter {
            hasLetter = true
            if char.isUppercase {
                result.append(char.lowercased())
            } else {
                result.append(char.uppercased())
            }
        } else {
            result.append(char)
        }
    }

    if !hasLetter {
        result = String(result.reversed())
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa, 
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"[/INST]  ```swift
func solve(s: String) -> String {
    var result = ""
    var hasLetter = false

    for char in s {
        if char.isLetter {
            hasLetter = true
            if char.isUppercase {
                result.append(char.lowercased())
            } else {
                result.append(char.uppercased())
            }
        } else {
            result.append(char)
        }
    }

    if !hasLetter {
        result = String(result.reversed())
    }

    return result
}
```

func solve(s: String) -> String {
    var result = ""
    var hasLetter = false

    for char in s {
        if char.isLetter {
            hasLetter = true
            if char.isUppercase {
                result.append(char.lowercased())
            } else {
                result.append(char.uppercased())
            }
        } else {
            result.append(char)
        }
    }

    if !hasLetter {
        result = String(result.reversed())
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa, 
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"[/INST]  ```swift
func solve(s: String) -> String {
    var result = ""
    var hasLetter = false

    for char in s {
        if char.isLetter {
            hasLetter = true
            if char.isUppercase {
                result.append(char.lowercased())
            } else {
                result.append(char.uppercased())
            }
        } else {
            result.append(char)
        }
    }

    if !hasLetter {
        result = String(result.reversed())
    }

    return result
}
```

import CommonCrypto

func stringToMd5(text: String) -> String? {
    guard !text.isEmpty else {
        return nil
    }

    let data = Data(text.utf8)
    var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))

    data.withUnsafeBytes {
        _ = CC_MD5($0.baseAddress, CC_LONG(data.count), &digest)
    }

    return digest.map { String(format: "%02hhx", $0) }.joined()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"[/INST]  ```swift
func stringToMd5(text: String) -> String? {
    guard !text.isEmpty else {
        return nil
    }

    let data = Data(text.utf8)
    var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))

    data.withUnsafeBytes {
        _ = CC_MD5($0.baseAddress, CC_LONG(data.count), &digest)
    }

    return digest.map { String(format: "%02hhx", $0) }.joined()
}
```
_ = CC_MD5($0.baseAddress, CC_LONG(data.count), &digest) // 'CC_MD5' was deprecated in macOS 10.15: This function is cryptographically broken and should not be used in security contexts. Clients should migrate to SHA256 (or stronger).

import CommonCrypto

func stringToMd5(text: String) -> String? {
    guard !text.isEmpty else {
        return nil
    }

    let data = Data(text.utf8)
    var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))

    data.withUnsafeBytes {
        _ = CC_MD5($0.baseAddress, CC_LONG(data.count), &digest)
    }

    return digest.map { String(format: "%02hhx", $0) }.joined()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"[/INST]  ```swift
func stringToMd5(text: String) -> String? {
    guard !text.isEmpty else {
        return nil
    }

    let data = Data(text.utf8)
    var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))

    data.withUnsafeBytes {
        _ = CC_MD5($0.baseAddress, CC_LONG(data.count), &digest)
    }

    return digest.map { String(format: "%02hhx", $0) }.joined()
}
```
_ = CC_MD5($0.baseAddress, CC_LONG(data.count), &digest) // 'CC_MD5' was deprecated in macOS 10.15: This function is cryptographically broken and should not be used in security contexts. Clients should migrate to SHA256 (or stronger).

import CommonCrypto

func stringToMd5(text: String) -> String? {
    guard !text.isEmpty else {
        return nil
    }

    let data = Data(text.utf8)
    let hash = data.withUnsafeBytes { (bytes: UnsafeRawBufferPointer) -> [UInt8] in
        var hash = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
        CC_MD5(bytes.baseAddress, CC_LONG(data.count), &hash)
        return hash
    }

    return hash.map { String(format: "%02x", $0) }.joined()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"[/INST]  ```swift
func stringToMd5(text: String) -> String? {
    guard !text.isEmpty else {
        return nil
    }

    let data = Data(text.utf8)
    let hash = data.withUnsafeBytes { (bytes: UnsafeRawBufferPointer) -> [UInt8] in
        var hash = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
        CC_MD5(bytes.baseAddress, CC_LONG(data.count), &hash)
        return hash
    }

    return hash.map { String(format: "%02x", $0) }.joined()
}
```
CC_MD5(bytes.baseAddress, CC_LONG(data.count), &hash) // 'CC_MD5' was deprecated in macOS 10.15: This function is cryptographically broken and should not be used in security contexts. Clients should migrate to SHA256 (or stronger).

import CommonCrypto

func stringToMd5(text: String) -> String? {
    guard !text.isEmpty else {
        return nil
    }

    let data = Data(text.utf8)
    var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))

    data.withUnsafeBytes {
        _ = CC_MD5($0.baseAddress, CC_LONG(data.count), &digest)
    }

    return digest.map { String(format: "%02hhx", $0) }.joined()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"[/INST]  ```swift
func stringToMd5(text: String) -> String? {
    guard !text.isEmpty else {
        return nil
    }

    let data = Data(text.utf8)
    var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))

    data.withUnsafeBytes {
        _ = CC_MD5($0.baseAddress, CC_LONG(data.count), &digest)
    }

    return digest.map { String(format: "%02hhx", $0) }.joined()
}
```
_ = CC_MD5($0.baseAddress, CC_LONG(data.count), &digest) // 'CC_MD5' was deprecated in macOS 10.15: This function is cryptographically broken and should not be used in security contexts. Clients should migrate to SHA256 (or stronger).

import CommonCrypto

func stringToMd5(text: String) -> String? {
    guard !text.isEmpty else {
        return nil
    }

    let data = Data(text.utf8)
    let hash = data.withUnsafeBytes { (bytes: UnsafeRawBufferPointer) -> [UInt8] in
        var hash = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
        CC_MD5(bytes.baseAddress, CC_LONG(data.count), &hash)
        return hash
    }

    return hash.map { String(format: "%02x", $0) }.joined()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"[/INST]  ```swift
func stringToMd5(text: String) -> String? {
    guard !text.isEmpty else {
        return nil
    }

    let data = Data(text.utf8)
    let hash = data.withUnsafeBytes { (bytes: UnsafeRawBufferPointer) -> [UInt8] in
        var hash = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
        CC_MD5(bytes.baseAddress, CC_LONG(data.count), &hash)
        return hash
    }

    return hash.map { String(format: "%02x", $0) }.joined()
}
```
CC_MD5(bytes.baseAddress, CC_LONG(data.count), &hash) // 'CC_MD5' was deprecated in macOS 10.15: This function is cryptographically broken and should not be used in security contexts. Clients should migrate to SHA256 (or stronger).

import CommonCrypto

func stringToMd5(text: String) -> String? {
    guard !text.isEmpty else {
        return nil
    }

    let data = Data(text.utf8)
    let hash = data.withUnsafeBytes { (bytes: UnsafeRawBufferPointer) -> [UInt8] in
        var hash = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
        CC_MD5(bytes.baseAddress, CC_LONG(data.count), &hash)
        return hash
    }

    return hash.map { String(format: "%02x", $0) }.joined()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"[/INST]  ```swift
func stringToMd5(text: String) -> String? {
    guard !text.isEmpty else {
        return nil
    }

    let data = Data(text.utf8)
    let hash = data.withUnsafeBytes { (bytes: UnsafeRawBufferPointer) -> [UInt8] in
        var hash = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
        CC_MD5(bytes.baseAddress, CC_LONG(data.count), &hash)
        return hash
    }

    return hash.map { String(format: "%02x", $0) }.joined()
}
```
CC_MD5(bytes.baseAddress, CC_LONG(data.count), &hash) // 'CC_MD5' was deprecated in macOS 10.15: This function is cryptographically broken and should not be used in security contexts. Clients should migrate to SHA256 (or stronger).

import CommonCrypto

func stringToMd5(text: String) -> String? {
    guard !text.isEmpty else {
        return nil
    }

    let data = Data(text.utf8)
    var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))

    data.withUnsafeBytes {
        _ = CC_MD5($0.baseAddress, CC_LONG(data.count), &digest)
    }

    return digest.map { String(format: "%02hhx", $0) }.joined()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"[/INST]  ```swift
func stringToMd5(text: String) -> String? {
    guard !text.isEmpty else {
        return nil
    }

    let data = Data(text.utf8)
    var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))

    data.withUnsafeBytes {
        _ = CC_MD5($0.baseAddress, CC_LONG(data.count), &digest)
    }

    return digest.map { String(format: "%02hhx", $0) }.joined()
}
```
_ = CC_MD5($0.baseAddress, CC_LONG(data.count), &digest) // 'CC_MD5' was deprecated in macOS 10.15: This function is cryptographically broken and should not be used in security contexts. Clients should migrate to SHA256 (or stronger).

import CommonCrypto

func stringToMd5(text: String) -> String? {
    guard !text.isEmpty else {
        return nil
    }

    let data = Data(text.utf8)
    var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))

    data.withUnsafeBytes {
        _ = CC_MD5($0.baseAddress, CC_LONG(data.count), &digest)
    }

    return digest.map { String(format: "%02hhx", $0) }.joined()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"[/INST]  ```swift
func stringToMd5(text: String) -> String? {
    guard !text.isEmpty else {
        return nil
    }

    let data = Data(text.utf8)
    var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))

    data.withUnsafeBytes {
        _ = CC_MD5($0.baseAddress, CC_LONG(data.count), &digest)
    }

    return digest.map { String(format: "%02hhx", $0) }.joined()
}
```
_ = CC_MD5($0.baseAddress, CC_LONG(data.count), &digest) // 'CC_MD5' was deprecated in macOS 10.15: This function is cryptographically broken and should not be used in security contexts. Clients should migrate to SHA256 (or stronger).

import CommonCrypto

func stringToMd5(text: String) -> String? {
    guard !text.isEmpty else {
        return nil
    }

    let data = Data(text.utf8)
    var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))

    data.withUnsafeBytes {
        _ = CC_MD5($0.baseAddress, CC_LONG(data.count), &digest)
    }

    return digest.map { String(format: "%02hhx", $0) }.joined()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"[/INST]  ```swift
func stringToMd5(text: String) -> String? {
    guard !text.isEmpty else {
        return nil
    }

    let data = Data(text.utf8)
    var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))

    data.withUnsafeBytes {
        _ = CC_MD5($0.baseAddress, CC_LONG(data.count), &digest)
    }

    return digest.map { String(format: "%02hhx", $0) }.joined()
}
```
_ = CC_MD5($0.baseAddress, CC_LONG(data.count), &digest) // 'CC_MD5' was deprecated in macOS 10.15: This function is cryptographically broken and should not be used in security contexts. Clients should migrate to SHA256 (or stronger).

import CommonCrypto

func stringToMd5(text: String) -> String? {
    guard !text.isEmpty else {
        return nil
    }

    let data = Data(text.utf8)
    let hash = data.withUnsafeBytes { (bytes: UnsafeRawBufferPointer) -> [UInt8] in
        var hash = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
        CC_MD5(bytes.baseAddress, CC_LONG(data.count), &hash)
        return hash
    }

    return hash.map { String(format: "%02x", $0) }.joined()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"[/INST]  ```swift
func stringToMd5(text: String) -> String? {
    guard !text.isEmpty else {
        return nil
    }

    let data = Data(text.utf8)
    let hash = data.withUnsafeBytes { (bytes: UnsafeRawBufferPointer) -> [UInt8] in
        var hash = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
        CC_MD5(bytes.baseAddress, CC_LONG(data.count), &hash)
        return hash
    }

    return hash.map { String(format: "%02x", $0) }.joined()
}
```
CC_MD5(bytes.baseAddress, CC_LONG(data.count), &hash) // 'CC_MD5' was deprecated in macOS 10.15: This function is cryptographically broken and should not be used in security contexts. Clients should migrate to SHA256 (or stronger).

func generateIntegers(a: Int, b: Int) -> [Int] {
    let start = max(a, b)
    let end = min(a, b)
    var result = [Int]()

    for i in stride(from: start, through: end, by: -1) {
        let digit = i % 10
        if digit % 2 == 0 {
            result.append(i)
        }
    }

    return result.sorted()
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int][/INST]  ```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
    let start = max(a, b)
    let end = min(a, b)
    var result = [Int]()

    for i in stride(from: start, through: end, by: -1) {
        let digit = i % 10
        if digit % 2 == 0 {
            result.append(i)
        }
    }

    return result.sorted()
}
```

func generateIntegers(a: Int, b: Int) -> [Int] {
    var result = [Int]()
    let start = min(a, b)
    let end = max(a, b)

    for i in start...end {
        if i % 2 == 0 {
            result.append(i)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int][/INST]  ```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
    var result = [Int]()
    let start = min(a, b)
    let end = max(a, b)

    for i in start...end {
        if i % 2 == 0 {
            result.append(i)
        }
    }

    return result
}
```

func generateIntegers(a: Int, b: Int) -> [Int] {
    var result = [Int]()
    let start = min(a, b)
    let end = max(a, b)

    for i in start...end {
        if i % 2 == 0 {
            result.append(i)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int][/INST]  ```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
    var result = [Int]()
    let start = min(a, b)
    let end = max(a, b)

    for i in start...end {
        if i % 2 == 0 {
            result.append(i)
        }
    }

    return result
}
```

func generateIntegers(a: Int, b: Int) -> [Int] {
    var result = [Int]()
    let start = min(a, b)
    let end = max(a, b)

    for i in start...end {
        if i % 2 == 0 {
            result.append(i)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int][/INST]  ```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
    var result = [Int]()
    let start = min(a, b)
    let end = max(a, b)

    for i in start...end {
        if i % 2 == 0 {
            result.append(i)
        }
    }

    return result
}
```

func generateIntegers(a: Int, b: Int) -> [Int] {
    var result = [Int]()
    let start = min(a, b)
    let end = max(a, b)

    for i in start...end {
        if i % 2 == 0 {
            result.append(i)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int][/INST]  ```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
    var result = [Int]()
    let start = min(a, b)
    let end = max(a, b)

    for i in start...end {
        if i % 2 == 0 {
            result.append(i)
        }
    }

    return result
}
```

func generateIntegers(a: Int, b: Int) -> [Int] {
    var result = [Int]()
    let start = min(a, b)
    let end = max(a, b)

    for i in start...end {
        if i % 2 == 0 {
            result.append(i)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int][/INST]  ```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
    var result = [Int]()
    let start = min(a, b)
    let end = max(a, b)

    for i in start...end {
        if i % 2 == 0 {
            result.append(i)
        }
    }

    return result
}
```

func generateIntegers(a: Int, b: Int) -> [Int] {
    var result = [Int]()
    let start = min(a, b)
    let end = max(a, b)

    for i in start...end {
        if i % 2 == 0 {
            result.append(i)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int][/INST]  ```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
    var result = [Int]()
    let start = min(a, b)
    let end = max(a, b)

    for i in start...end {
        if i % 2 == 0 {
            result.append(i)
        }
    }

    return result
}
```

func generateIntegers(a: Int, b: Int) -> [Int] {
    var result = [Int]()
    let start = min(a, b)
    let end = max(a, b)

    for i in start...end {
        if i % 2 == 0 {
            result.append(i)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int][/INST]  ```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
    var result = [Int]()
    let start = min(a, b)
    let end = max(a, b)

    for i in start...end {
        if i % 2 == 0 {
            result.append(i)
        }
    }

    return result
}
```

func generateIntegers(a: Int, b: Int) -> [Int] {
    var result = [Int]()
    let start = min(a, b)
    let end = max(a, b)

    for i in start...end {
        if i % 2 == 0 {
            result.append(i)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int][/INST]  ```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
    var result = [Int]()
    let start = min(a, b)
    let end = max(a, b)

    for i in start...end {
        if i % 2 == 0 {
            result.append(i)
        }
    }

    return result
}
```

func generateIntegers(a: Int, b: Int) -> [Int] {
    let start = max(a, b)
    let end = min(a, b)
    var result = [Int]()

    for i in stride(from: start, through: end, by: 1) {
        if i % 2 == 0 {
            result.append(i)
        }
    }

    return result
}
[INST]  Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int][/INST]  ```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
    let start = max(a, b)
    let end = min(a, b)
    var result = [Int]()

    for i in stride(from: start, through: end, by: 1) {
        if i % 2 == 0 {
            result.append(i)
        }
    }

    return result
}
```
 // XCTAssertTrue failed