Problem
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] { ...
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17])
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5])
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5])
XCTAssertTrue(getOddCollatz(n: 1) == [1])
- 0.62 Compiled
- 0.27 Passed
Solutions
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num != 1 {
arr.append(num)
if num % 2 == 0 {
num /= 2
} else {
num = (num * 3) + 1
}
}
arr.append(1)
return arr.sorted()
}
func getOddCollatzSum(arr: [Int]) -> Int {
var sum = 0
for i in arr {
if i % 2 != 0 {
sum += i
}
}
return sum
}
func getEvenCollatzSum(arr: [Int]) -> Int {
var sum = 0
for i in arr {
if i % 2 == 0 {
sum += i
}
}
return sum
}
func getCollatzSum(arr: [Int]) -> Int {
var sum = 0
for i in arr {
sum += i
}
return sum
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num != 1 {
arr.append(num)
if num % 2 == 0 {
num /= 2
} else {
num = (num * 3) + 1
}
}
arr.append(1)
return arr.sorted()
}
// Given an array of positive integers, return the sum of the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatzSum(arr: [Int]) -> Int {
var sum = 0
for i in arr {
if i % 2 != 0 {
sum += i
}
}
return sum
}
// Given an array of positive integers, return the sum of the even numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getEvenCollatzSum(arr: [Int]) -> Int {
var sum = 0
for i in arr {
if i % 2 == 0 {
sum += i
}
}
return sum
}
// Given an array of positive integers, return the sum of the collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getCollatzSum(arr: [Int]) -> Int {
var sum = 0
for i in arr {
sum += i
}
return sum
}
// Given an array of positive integers, return the sum of the collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
result.append(num)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
result.append(num)
}
return result
}
<|file_separator|>
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = (3 * num) + 1
}
result.append(num)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = (3 * num) + 1
}
result.append(num)
}
return result
}
<|file_separator|>
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num != 1 {
arr.append(num)
if num % 2 == 0 {
num = num / 2
} else {
num = (num * 3) + 1
}
}
arr.append(1)
return arr
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num != 1 {
arr.append(num)
if num % 2 == 0 {
num = num / 2
} else {
num = (num * 3) + 1
}
}
arr.append(1)
return arr
}
<|file_separator|>
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
<|file_separator|>
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
result.append(num)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
result.append(num)
}
return result
}
<|file_separator|>
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
collatz.append(num)
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
}
collatz.append(1)
return collatz.filter { $0 % 2 != 0 }
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
collatz.append(num)
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
}
collatz.append(1)
return collatz.filter { $0 % 2 != 0 }
}
<|file_separator|>
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
<|file_separator|>
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num != 1 {
arr.append(num)
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
}
arr.append(1)
return arr
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num != 1 {
arr.append(num)
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
}
arr.append(1)
return arr
}
<|file_separator|>
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
result.append(num)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
result.append(num)
}
return result
}
<|file_separator|>
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var number = n
while number != 1 {
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
if number % 2 != 0 {
sequence.append(number)
}
}
return sequence
}
<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var number = n
while number != 1 {
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
if number % 2 != 0 {
sequence.append(number)
}
}
return sequence
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
<bos><start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
if num % 2!= 0 {
result.append(num)
}
}
result.append(1)
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
if num % 2!= 0 {
result.append(num)
}
}
result.append(1)
return result
}
```
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
if num % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if num % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if num % 2!= 0 { // '=' must have consistent whitespace on both sides
if num % 2!= 0 { // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = num * 3 + 1
}
if num % 2!= 0 {
result.append(num)
}
}
result.append(num)
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = num * 3 + 1
}
if num % 2!= 0 {
result.append(num)
}
}
result.append(num)
return result
}
```
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
if num % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if num % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if num % 2!= 0 { // '=' must have consistent whitespace on both sides
if num % 2!= 0 { // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = num * 3 + 1
}
if num % 2!= 0 {
result.append(num)
}
}
result.append(1)
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = num * 3 + 1
}
if num % 2!= 0 {
result.append(num)
}
}
result.append(1)
return result
}
```
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
if num % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if num % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if num % 2!= 0 { // '=' must have consistent whitespace on both sides
if num % 2!= 0 { // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result
}
```
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = num * 3 + 1
}
if num % 2!= 0 {
result.append(num)
}
}
result.append(1)
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = num * 3 + 1
}
if num % 2!= 0 {
result.append(num)
}
}
result.append(1)
return result
}
```
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
if num % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if num % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if num % 2!= 0 { // '=' must have consistent whitespace on both sides
if num % 2!= 0 { // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var temp = n
while temp!= 1 {
if temp % 2 == 0 {
temp = temp / 2
} else {
temp = (3 * temp) + 1
}
if temp % 2!= 0 {
result.append(temp)
}
}
result.append(1)
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var temp = n
while temp!= 1 {
if temp % 2 == 0 {
temp = temp / 2
} else {
temp = (3 * temp) + 1
}
if temp % 2!= 0 {
result.append(temp)
}
}
result.append(1)
return result
}
```
while temp!= 1 { // '=' must have consistent whitespace on both sides
while temp!= 1 { // cannot force unwrap value of non-optional type 'Int'
while temp!= 1 { // use of '=' in a boolean context, did you mean '=='?
if temp % 2!= 0 { // '=' must have consistent whitespace on both sides
if temp % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if temp % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if temp % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
if num % 2!= 0 {
result.append(num)
}
}
result.append(num)
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
if num % 2!= 0 {
result.append(num)
}
}
result.append(num)
return result
}
```
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
if num % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if num % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if num % 2!= 0 { // '=' must have consistent whitespace on both sides
if num % 2!= 0 { // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = num * 3 + 1
}
if num % 2!= 0 {
result.append(num)
}
}
result.append(num)
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = num * 3 + 1
}
if num % 2!= 0 {
result.append(num)
}
}
result.append(num)
return result
}
```
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
if num % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if num % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if num % 2!= 0 { // '=' must have consistent whitespace on both sides
if num % 2!= 0 { // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = num * 3 + 1
}
if num % 2!= 0 {
result.append(num)
}
}
result.append(1)
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = num * 3 + 1
}
if num % 2!= 0 {
result.append(num)
}
}
result.append(1)
return result
}
```
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
if num % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if num % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if num % 2!= 0 { // '=' must have consistent whitespace on both sides
if num % 2!= 0 { // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = num * 3 + 1
}
if num % 2!= 0 {
result.append(num)
}
}
result.append(1)
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = num * 3 + 1
}
if num % 2!= 0 {
result.append(num)
}
}
result.append(1)
return result
}
```
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
if num % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if num % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if num % 2!= 0 { // '=' must have consistent whitespace on both sides
if num % 2!= 0 { // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
result.append(num)
}
return result.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
result.append(num)
}
return result.sorted()
}
```
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result
}
```
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
result.append(num)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
result.append(num)
}
return result
}
```
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
result.append(num)
}
return result.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
result.append(num)
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
result.append(num)
}
return result.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
result.append(num)
}
return result.sorted()
}
```
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
result.append(num)
}
return result.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
result.append(num)
}
return result.sorted()
}
```
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
result.append(num)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
result.append(num)
}
return result
}
```
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num > 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
result.append(num)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num > 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
result.append(num)
}
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num > 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
result.append(num)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num > 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
result.append(num)
}
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
result.append(num)
}
return result.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
result.append(num)
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num!= 1 {
arr.append(num)
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
}
arr.append(1)
return arr.filter { $0 % 2!= 0 }.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num!= 1 {
arr.append(num)
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
}
arr.append(1)
return arr.filter { $0 % 2!= 0 }.sorted()
}
```
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
return arr.filter { $0 % 2!= 0 }.sorted() // expression is not assignable: binary operator returns immutable value
return arr.filter { $0 % 2!= 0 }.sorted() // cannot convert value of type '()' to closure result type 'Bool'
return arr.filter { $0 % 2!= 0 }.sorted() // cannot force unwrap value of non-optional type 'Int'
return arr.filter { $0 % 2!= 0 }.sorted() // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
result.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
}
result.append(1)
return result.filter { $0 % 2!= 0 }
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
result.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
}
result.append(1)
return result.filter { $0 % 2!= 0 }
}
```
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
return result.filter { $0 % 2!= 0 } // cannot convert value of type '()' to closure result type 'Bool'
return result.filter { $0 % 2!= 0 } // cannot force unwrap value of non-optional type 'Int'
return result.filter { $0 % 2!= 0 } // expression is not assignable: binary operator returns immutable value
return result.filter { $0 % 2!= 0 } // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
arr.append(num)
}
return arr.filter { $0 % 2!= 0 }.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
arr.append(num)
}
return arr.filter { $0 % 2!= 0 }.sorted()
}
```
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
return arr.filter { $0 % 2!= 0 }.sorted() // cannot force unwrap value of non-optional type 'Int'
return arr.filter { $0 % 2!= 0 }.sorted() // '=' must have consistent whitespace on both sides
return arr.filter { $0 % 2!= 0 }.sorted() // cannot convert value of type '()' to closure result type 'Bool'
return arr.filter { $0 % 2!= 0 }.sorted() // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
var collatz = [Int]()
var num = n
while num!= 1 {
collatz.append(num)
if num % 2 == 0 {
num = num / 2
} else {
num = num * 3 + 1
}
}
collatz.append(1)
for i in 0..<collatz.count {
if collatz[i] % 2!= 0 {
oddCollatz.append(collatz[i])
}
}
return oddCollatz
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
var collatz = [Int]()
var num = n
while num!= 1 {
collatz.append(num)
if num % 2 == 0 {
num = num / 2
} else {
num = num * 3 + 1
}
}
collatz.append(1)
for i in 0..<collatz.count {
if collatz[i] % 2!= 0 {
oddCollatz.append(collatz[i])
}
}
return oddCollatz
}
```
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
if collatz[i] % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if collatz[i] % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if collatz[i] % 2!= 0 { // '=' must have consistent whitespace on both sides
if collatz[i] % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
arr.append(num)
}
return arr.filter { $0 % 2!= 0 }.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
arr.append(num)
}
return arr.filter { $0 % 2!= 0 }.sorted()
}
```
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
return arr.filter { $0 % 2!= 0 }.sorted() // cannot force unwrap value of non-optional type 'Int'
return arr.filter { $0 % 2!= 0 }.sorted() // '=' must have consistent whitespace on both sides
return arr.filter { $0 % 2!= 0 }.sorted() // cannot convert value of type '()' to closure result type 'Bool'
return arr.filter { $0 % 2!= 0 }.sorted() // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var n = n
while n!= 1 {
if n % 2 == 0 {
n /= 2
} else {
n = n * 3 + 1
}
if n % 2 == 1 {
result.append(n)
}
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var n = n
while n!= 1 {
if n % 2 == 0 {
n /= 2
} else {
n = n * 3 + 1
}
if n % 2 == 1 {
result.append(n)
}
}
return result
}
```
while n!= 1 { // use of '=' in a boolean context, did you mean '=='?
while n!= 1 { // '=' must have consistent whitespace on both sides
while n!= 1 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result
}
```
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var odds = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
if current % 2 == 1 {
odds.append(current)
}
}
return odds.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var odds = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
if current % 2 == 1 {
odds.append(current)
}
}
return odds.sorted()
}
```
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
var n = n
while n!= 1 {
if n % 2 == 0 {
n = n / 2
} else {
n = 3 * n + 1
}
if n % 2!= 0 {
oddCollatz.append(n)
}
}
return oddCollatz.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
var n = n
while n!= 1 {
if n % 2 == 0 {
n = n / 2
} else {
n = 3 * n + 1
}
if n % 2!= 0 {
oddCollatz.append(n)
}
}
return oddCollatz.sorted()
}
```
while n!= 1 { // cannot force unwrap value of non-optional type 'Int'
while n!= 1 { // use of '=' in a boolean context, did you mean '=='?
while n!= 1 { // '=' must have consistent whitespace on both sides
if n % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if n % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if n % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if n % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
if num % 2!= 0 {
arr.append(num)
}
}
return arr.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
if num % 2!= 0 {
arr.append(num)
}
}
return arr.sorted()
}
```
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
if num % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if num % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if num % 2!= 0 { // '=' must have consistent whitespace on both sides
if num % 2!= 0 { // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var currentNumber = n
while currentNumber!= 1 {
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = currentNumber * 3 + 1
}
if currentNumber % 2!= 0 {
result.append(currentNumber)
}
}
return result
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var currentNumber = n
while currentNumber!= 1 {
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = currentNumber * 3 + 1
}
if currentNumber % 2!= 0 {
result.append(currentNumber)
}
}
return result
}
```
while currentNumber!= 1 { // cannot force unwrap value of non-optional type 'Int'
while currentNumber!= 1 { // use of '=' in a boolean context, did you mean '=='?
while currentNumber!= 1 { // '=' must have consistent whitespace on both sides
if currentNumber % 2!= 0 { // '=' must have consistent whitespace on both sides
if currentNumber % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if currentNumber % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if currentNumber % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var currentNumber = n
while currentNumber!= 1 {
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = currentNumber * 3 + 1
}
if currentNumber % 2!= 0 {
result.append(currentNumber)
}
}
return result
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var currentNumber = n
while currentNumber!= 1 {
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = currentNumber * 3 + 1
}
if currentNumber % 2!= 0 {
result.append(currentNumber)
}
}
return result
}
```
while currentNumber!= 1 { // cannot force unwrap value of non-optional type 'Int'
while currentNumber!= 1 { // use of '=' in a boolean context, did you mean '=='?
while currentNumber!= 1 { // '=' must have consistent whitespace on both sides
if currentNumber % 2!= 0 { // '=' must have consistent whitespace on both sides
if currentNumber % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if currentNumber % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if currentNumber % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
result.append(current)
current = current % 2 == 0? current / 2 : 3 * current + 1
}
return result
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
result.append(current)
current = current % 2 == 0? current / 2 : 3 * current + 1
}
return result
}
```
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot assign value of type 'Bool' to type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // expected expression
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot use optional chaining on non-optional value of type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // result of operator '/' is unused
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
result.append(current)
current = current % 2 == 0? current / 2 : 3 * current + 1
}
return result
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
result.append(current)
current = current % 2 == 0? current / 2 : 3 * current + 1
}
return result
}
```
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot assign value of type 'Bool' to type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // expected expression
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot use optional chaining on non-optional value of type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // result of operator '/' is unused
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var currentNumber = n
while currentNumber!= 1 {
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = currentNumber * 3 + 1
}
if currentNumber % 2 == 1 {
result.append(currentNumber)
}
}
return result
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var currentNumber = n
while currentNumber!= 1 {
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = currentNumber * 3 + 1
}
if currentNumber % 2 == 1 {
result.append(currentNumber)
}
}
return result
}
```
while currentNumber!= 1 { // cannot force unwrap value of non-optional type 'Int'
while currentNumber!= 1 { // '=' must have consistent whitespace on both sides
while currentNumber!= 1 { // use of '=' in a boolean context, did you mean '=='?
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = (current * 3) + 1
}
if current % 2!= 0 {
result.append(current)
}
}
return result
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = (current * 3) + 1
}
if current % 2!= 0 {
result.append(current)
}
}
return result
}
```
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = (current * 3) + 1
}
result.append(current)
}
return result
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = (current * 3) + 1
}
result.append(current)
}
return result
}
```
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
result.append(current)
current = current % 2 == 0? current / 2 : 3 * current + 1
}
return result
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
result.append(current)
current = current % 2 == 0? current / 2 : 3 * current + 1
}
return result
}
```
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot assign value of type 'Bool' to type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // expected expression
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot use optional chaining on non-optional value of type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // result of operator '/' is unused
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
return result
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
return result
}
```
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = (current * 3) + 1
}
if current % 2!= 0 {
result.append(current)
}
}
return result
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = (current * 3) + 1
}
if current % 2!= 0 {
result.append(current)
}
}
return result
}
```
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : 3 * current + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : 3 * current + 1
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // expected expression
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot use optional chaining on non-optional value of type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot assign value of type 'Bool' to type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // result of operator '/' is unused
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : 3 * current + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : 3 * current + 1
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // expected expression
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot use optional chaining on non-optional value of type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot assign value of type 'Bool' to type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // result of operator '/' is unused
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : 3 * current + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : 3 * current + 1
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // expected expression
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot use optional chaining on non-optional value of type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot assign value of type 'Bool' to type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // result of operator '/' is unused
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num!= 1 {
if num % 2 == 1 {
result.append(num)
}
num = num % 2 == 0? num / 2 : num * 3 + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num!= 1 {
if num % 2 == 1 {
result.append(num)
}
num = num % 2 == 0? num / 2 : num * 3 + 1
}
result.append(1)
return result.sorted()
}
```
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
num = num % 2 == 0? num / 2 : num * 3 + 1 // consecutive statements on a line must be separated by ';'
num = num % 2 == 0? num / 2 : num * 3 + 1 // cannot use optional chaining on non-optional value of type 'Int'
num = num % 2 == 0? num / 2 : num * 3 + 1 // expected expression
num = num % 2 == 0? num / 2 : num * 3 + 1 // cannot assign value of type 'Bool' to type 'Int'
num = num % 2 == 0? num / 2 : num * 3 + 1 // result of operator '/' is unused
num = num % 2 == 0? num / 2 : num * 3 + 1 // consecutive statements on a line must be separated by ';'
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : 3 * current + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : 3 * current + 1
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // expected expression
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot use optional chaining on non-optional value of type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot assign value of type 'Bool' to type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // result of operator '/' is unused
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : current * 3 + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : current * 3 + 1
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
current = current % 2 == 0? current / 2 : current * 3 + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : current * 3 + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : current * 3 + 1 // cannot assign value of type 'Bool' to type 'Int'
current = current % 2 == 0? current / 2 : current * 3 + 1 // expected expression
current = current % 2 == 0? current / 2 : current * 3 + 1 // cannot use optional chaining on non-optional value of type 'Int'
current = current % 2 == 0? current / 2 : current * 3 + 1 // result of operator '/' is unused
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num!= 1 {
if num % 2 == 1 {
result.append(num)
}
num = num % 2 == 0? num / 2 : num * 3 + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num!= 1 {
if num % 2 == 1 {
result.append(num)
}
num = num % 2 == 0? num / 2 : num * 3 + 1
}
result.append(1)
return result.sorted()
}
```
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
num = num % 2 == 0? num / 2 : num * 3 + 1 // consecutive statements on a line must be separated by ';'
num = num % 2 == 0? num / 2 : num * 3 + 1 // cannot use optional chaining on non-optional value of type 'Int'
num = num % 2 == 0? num / 2 : num * 3 + 1 // expected expression
num = num % 2 == 0? num / 2 : num * 3 + 1 // cannot assign value of type 'Bool' to type 'Int'
num = num % 2 == 0? num / 2 : num * 3 + 1 // result of operator '/' is unused
num = num % 2 == 0? num / 2 : num * 3 + 1 // consecutive statements on a line must be separated by ';'
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : 3 * current + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : 3 * current + 1
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // expected expression
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot use optional chaining on non-optional value of type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot assign value of type 'Bool' to type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // result of operator '/' is unused
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : 3 * current + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : 3 * current + 1
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // expected expression
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot use optional chaining on non-optional value of type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot assign value of type 'Bool' to type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // result of operator '/' is unused
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : 3 * current + 1
}
result.append(current)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : 3 * current + 1
}
result.append(current)
return result.sorted()
}
```
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // expected expression
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot use optional chaining on non-optional value of type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot assign value of type 'Bool' to type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // result of operator '/' is unused
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 1 {
result.append(number)
}
number = number % 2 == 0? number / 2 : number * 3 + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 1 {
result.append(number)
}
number = number % 2 == 0? number / 2 : number * 3 + 1
}
result.append(1)
return result.sorted()
}
```
while number!= 1 { // use of '=' in a boolean context, did you mean '=='?
while number!= 1 { // '=' must have consistent whitespace on both sides
while number!= 1 { // cannot force unwrap value of non-optional type 'Int'
number = number % 2 == 0? number / 2 : number * 3 + 1 // consecutive statements on a line must be separated by ';'
number = number % 2 == 0? number / 2 : number * 3 + 1 // expected expression
number = number % 2 == 0? number / 2 : number * 3 + 1 // result of operator '/' is unused
number = number % 2 == 0? number / 2 : number * 3 + 1 // cannot use optional chaining on non-optional value of type 'Int'
number = number % 2 == 0? number / 2 : number * 3 + 1 // cannot assign value of type 'Bool' to type 'Int'
number = number % 2 == 0? number / 2 : number * 3 + 1 // consecutive statements on a line must be separated by ';'
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num!= 1 {
if num % 2 == 1 {
result.append(num)
}
num = (num % 2 == 0)? num / 2 : num * 3 + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num!= 1 {
if num % 2 == 1 {
result.append(num)
}
num = (num % 2 == 0)? num / 2 : num * 3 + 1
}
result.append(1)
return result.sorted()
}
```
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // '=' must have consistent whitespace on both sides
num = (num % 2 == 0)? num / 2 : num * 3 + 1 // consecutive statements on a line must be separated by ';'
num = (num % 2 == 0)? num / 2 : num * 3 + 1 // expected expression
num = (num % 2 == 0)? num / 2 : num * 3 + 1 // cannot assign value of type 'Bool?' to type 'Int'
num = (num % 2 == 0)? num / 2 : num * 3 + 1 // consecutive statements on a line must be separated by ';'
num = (num % 2 == 0)? num / 2 : num * 3 + 1 // cannot use optional chaining on non-optional value of type 'Bool'
num = (num % 2 == 0)? num / 2 : num * 3 + 1 // result of operator '/' is unused
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 1 {
result.append(number)
}
number = number % 2 == 0? number / 2 : 3 * number + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 1 {
result.append(number)
}
number = number % 2 == 0? number / 2 : 3 * number + 1
}
result.append(1)
return result.sorted()
}
```
while number!= 1 { // use of '=' in a boolean context, did you mean '=='?
while number!= 1 { // '=' must have consistent whitespace on both sides
while number!= 1 { // cannot force unwrap value of non-optional type 'Int'
number = number % 2 == 0? number / 2 : 3 * number + 1 // cannot use optional chaining on non-optional value of type 'Int'
number = number % 2 == 0? number / 2 : 3 * number + 1 // consecutive statements on a line must be separated by ';'
number = number % 2 == 0? number / 2 : 3 * number + 1 // expected expression
number = number % 2 == 0? number / 2 : 3 * number + 1 // result of operator '/' is unused
number = number % 2 == 0? number / 2 : 3 * number + 1 // consecutive statements on a line must be separated by ';'
number = number % 2 == 0? number / 2 : 3 * number + 1 // cannot assign value of type 'Bool' to type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 1 {
result.append(num)
}
num = (num % 2 == 0)? num / 2 : num * 3 + 1
}
result.append(1)
return result
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 1 {
result.append(num)
}
num = (num % 2 == 0)? num / 2 : num * 3 + 1
}
result.append(1)
return result
}
```
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // '=' must have consistent whitespace on both sides
num = (num % 2 == 0)? num / 2 : num * 3 + 1 // consecutive statements on a line must be separated by ';'
num = (num % 2 == 0)? num / 2 : num * 3 + 1 // expected expression
num = (num % 2 == 0)? num / 2 : num * 3 + 1 // cannot assign value of type 'Bool?' to type 'Int'
num = (num % 2 == 0)? num / 2 : num * 3 + 1 // consecutive statements on a line must be separated by ';'
num = (num % 2 == 0)? num / 2 : num * 3 + 1 // cannot use optional chaining on non-optional value of type 'Bool'
num = (num % 2 == 0)? num / 2 : num * 3 + 1 // result of operator '/' is unused
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num!= 1 {
if num % 2 == 1 {
result.append(num)
}
num = (num % 2 == 0)? num / 2 : num * 3 + 1
}
result.append(1)
return result
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num!= 1 {
if num % 2 == 1 {
result.append(num)
}
num = (num % 2 == 0)? num / 2 : num * 3 + 1
}
result.append(1)
return result
}
```
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // '=' must have consistent whitespace on both sides
num = (num % 2 == 0)? num / 2 : num * 3 + 1 // consecutive statements on a line must be separated by ';'
num = (num % 2 == 0)? num / 2 : num * 3 + 1 // expected expression
num = (num % 2 == 0)? num / 2 : num * 3 + 1 // cannot assign value of type 'Bool?' to type 'Int'
num = (num % 2 == 0)? num / 2 : num * 3 + 1 // consecutive statements on a line must be separated by ';'
num = (num % 2 == 0)? num / 2 : num * 3 + 1 // cannot use optional chaining on non-optional value of type 'Bool'
num = (num % 2 == 0)? num / 2 : num * 3 + 1 // result of operator '/' is unused
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var number = n
while number!= 1 {
if number % 2 == 1 {
result.append(number)
}
number = number % 2 == 0? number / 2 : (3 * number + 1)
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var number = n
while number!= 1 {
if number % 2 == 1 {
result.append(number)
}
number = number % 2 == 0? number / 2 : (3 * number + 1)
}
result.append(1)
return result.sorted()
}
```
while number!= 1 { // use of '=' in a boolean context, did you mean '=='?
while number!= 1 { // '=' must have consistent whitespace on both sides
while number!= 1 { // cannot force unwrap value of non-optional type 'Int'
number = number % 2 == 0? number / 2 : (3 * number + 1) // cannot assign value of type 'Bool' to type 'Int'
number = number % 2 == 0? number / 2 : (3 * number + 1) // cannot use optional chaining on non-optional value of type 'Int'
number = number % 2 == 0? number / 2 : (3 * number + 1) // result of operator '/' is unused
number = number % 2 == 0? number / 2 : (3 * number + 1) // expected expression
number = number % 2 == 0? number / 2 : (3 * number + 1) // consecutive statements on a line must be separated by ';'
number = number % 2 == 0? number / 2 : (3 * number + 1) // consecutive statements on a line must be separated by ';'
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 1 {
result.append(number)
}
number = number % 2 == 0? number / 2 : 3 * number + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 1 {
result.append(number)
}
number = number % 2 == 0? number / 2 : 3 * number + 1
}
result.append(1)
return result.sorted()
}
```
while number!= 1 { // use of '=' in a boolean context, did you mean '=='?
while number!= 1 { // '=' must have consistent whitespace on both sides
while number!= 1 { // cannot force unwrap value of non-optional type 'Int'
number = number % 2 == 0? number / 2 : 3 * number + 1 // cannot use optional chaining on non-optional value of type 'Int'
number = number % 2 == 0? number / 2 : 3 * number + 1 // consecutive statements on a line must be separated by ';'
number = number % 2 == 0? number / 2 : 3 * number + 1 // expected expression
number = number % 2 == 0? number / 2 : 3 * number + 1 // result of operator '/' is unused
number = number % 2 == 0? number / 2 : 3 * number + 1 // consecutive statements on a line must be separated by ';'
number = number % 2 == 0? number / 2 : 3 * number + 1 // cannot assign value of type 'Bool' to type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num!= 1 {
if num % 2 == 1 {
result.append(num)
}
num = (num % 2 == 0)? num / 2 : num * 3 + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num!= 1 {
if num % 2 == 1 {
result.append(num)
}
num = (num % 2 == 0)? num / 2 : num * 3 + 1
}
result.append(1)
return result.sorted()
}
```
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // '=' must have consistent whitespace on both sides
num = (num % 2 == 0)? num / 2 : num * 3 + 1 // consecutive statements on a line must be separated by ';'
num = (num % 2 == 0)? num / 2 : num * 3 + 1 // expected expression
num = (num % 2 == 0)? num / 2 : num * 3 + 1 // cannot assign value of type 'Bool?' to type 'Int'
num = (num % 2 == 0)? num / 2 : num * 3 + 1 // consecutive statements on a line must be separated by ';'
num = (num % 2 == 0)? num / 2 : num * 3 + 1 // cannot use optional chaining on non-optional value of type 'Bool'
num = (num % 2 == 0)? num / 2 : num * 3 + 1 // result of operator '/' is unused
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var number = n
while number!= 1 {
if number % 2 == 1 {
result.append(number)
}
number = number % 2 == 0? number / 2 : number * 3 + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var number = n
while number!= 1 {
if number % 2 == 1 {
result.append(number)
}
number = number % 2 == 0? number / 2 : number * 3 + 1
}
result.append(1)
return result.sorted()
}
```
while number!= 1 { // use of '=' in a boolean context, did you mean '=='?
while number!= 1 { // '=' must have consistent whitespace on both sides
while number!= 1 { // cannot force unwrap value of non-optional type 'Int'
number = number % 2 == 0? number / 2 : number * 3 + 1 // consecutive statements on a line must be separated by ';'
number = number % 2 == 0? number / 2 : number * 3 + 1 // expected expression
number = number % 2 == 0? number / 2 : number * 3 + 1 // result of operator '/' is unused
number = number % 2 == 0? number / 2 : number * 3 + 1 // cannot use optional chaining on non-optional value of type 'Int'
number = number % 2 == 0? number / 2 : number * 3 + 1 // cannot assign value of type 'Bool' to type 'Int'
number = number % 2 == 0? number / 2 : number * 3 + 1 // consecutive statements on a line must be separated by ';'
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var number = n
while number!= 1 {
if number % 2 == 1 {
result.append(number)
}
number = number % 2 == 0? number / 2 : 3 * number + 1
}
result.append(1)
return result
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var number = n
while number!= 1 {
if number % 2 == 1 {
result.append(number)
}
number = number % 2 == 0? number / 2 : 3 * number + 1
}
result.append(1)
return result
}
```
while number!= 1 { // use of '=' in a boolean context, did you mean '=='?
while number!= 1 { // '=' must have consistent whitespace on both sides
while number!= 1 { // cannot force unwrap value of non-optional type 'Int'
number = number % 2 == 0? number / 2 : 3 * number + 1 // cannot use optional chaining on non-optional value of type 'Int'
number = number % 2 == 0? number / 2 : 3 * number + 1 // consecutive statements on a line must be separated by ';'
number = number % 2 == 0? number / 2 : 3 * number + 1 // expected expression
number = number % 2 == 0? number / 2 : 3 * number + 1 // result of operator '/' is unused
number = number % 2 == 0? number / 2 : 3 * number + 1 // consecutive statements on a line must be separated by ';'
number = number % 2 == 0? number / 2 : 3 * number + 1 // cannot assign value of type 'Bool' to type 'Int'
import Foundation
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
```swift
import Foundation
/*
Function to multiply two matrices represented as 2D arrays of Doubles.
Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
*/
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
/*
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
*/
func getOddCollatz(n: Int) -> [Int] {
return [1].map {
guard n in
return [1
guard
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
import Foundation
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
```swift
import Foundation
/*
Function to multiply two matrices represented as 2D arrays of Doubles.
Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
*/
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
/*
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
*/
func getOddCollatz(n: Int) -> [Int] {
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
import Foundation
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
```swift
import Foundation
/*
Function to multiply two matrices represented as 2D arrays of Doubles.
Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
*/
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
/*
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
*/
func getOddCollatz(n: Int) -> [Int] {
return [1]
var arr = [
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
import Foundation
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
```swift
import Foundation
/*
Function to multiply two matrices represented as 2D arrays of Doubles.
Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
*/
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
/*
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
*/
func getOddCollatz(n: Int) -> [Int] {
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
import Foundation
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
```swift
import Foundation
/*
Function to multiply two matrices represented as 2D arrays of Doubles.
Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
*/
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
/*
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
*/
func getOddCollatz(n: Int) -> [Int] {
return [1].map {
return [1, 3, 3, 4
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
import Foundation
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
```swift
import Foundation
/*
Function to multiply two matrices represented as 2D arrays of Doubles.
Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
*/
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
/*
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
*/
func getOddCollatz(n: Int) -> [Int] {
guard n = [1]
var arr = [1]
var arr = [
var arr = [1
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
import Foundation
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
```swift
import Foundation
/*
Function to multiply two matrices represented as 2D arrays of Doubles.
Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
*/
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
/*
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
*/
func getOddCollatz(n: Int) -> [Int] {
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
import Foundation
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
```swift
import Foundation
/*
Function to multiply two matrices represented as 2D arrays of Doubles.
Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
*/
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
/*
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
*/
func getOddCollatz(n: Int) -> [Int] {
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
import Foundation
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
```swift
import Foundation
/*
Function to multiply two matrices represented as 2D arrays of Doubles.
Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
*/
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
/*
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
*/
func getOddCollatz(n: Int) -> [Int] {
var arr = [1]
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
import Foundation
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
```swift
import Foundation
/*
Function to multiply two matrices represented as 2D arrays of Doubles.
Returns a new matrix that is the product of `lhs` and `rhs`, or `nil` if the matrices cannot be multiplied.
*/
func multiply(_ lhs: [[Double]], _ rhs: [[Double]]) -> [[Double]]? {
guard lhs[0].count == rhs.count else {
return nil
}
var result = [[Double]](repeating: [Double](repeating: 0, count: rhs[0].count), count: lhs.count)
for i in 0..<lhs.count {
for j in 0..<rhs[0].count {
for k in 0..<rhs.count {
result[i][j] += lhs[i][k] * rhs[k][j]
}
}
}
return result
}
/*
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
*/
func getOddCollatz(n: Int) -> [Int] {
return [
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
1/2, or (n/2, if it is even. If it is even, and if it is odd, multiply by 1/2, multiply
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
1/2, if the previous term
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
1/2, or if the previous
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
1/1/2, or if the previous term is even. Otherwise, 1 + 1/1/3*2. If it is odd*1/
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
1. If the previous term is even, half of the previous term is obtained, if it is even. If it is odd, multiply by 1 plus 1. If it is 3 times two times 1 plus 1. If it is odd.
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
1/2, if the previous term is even; if it is odd, multiply by 1/3 plus 1/2 if it is even.
return the sequence is odd
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
1/1/2 of the previous term. If it is even, else, multiply by 3 followed by 1 +1 the previous term and add 1. The
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
1/2 of the previous term is obtained by taking the previous term, and if it is even. If it is odd, otherwise, multiply by 3 times 1 plus 1.
1.
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
1/2, if the previous term is even. If the previous term is odd, multiply by 2, else, multiply by 3 and add 1.
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
1/2 of the previous term is obtained (n/2, if it is even, if it is odd divide by 2, and if it is odd then
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return sequence.sorted()
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return sequence.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return sequence.sorted()
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return sequence.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return sequence.sorted()
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return sequence.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return sequence.sorted()
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return sequence.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
result.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
result.append(1)
return result.sorted()
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
result.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
result.append(1)
return result.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return sequence.sorted()
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return sequence.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return sequence.sorted()
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return sequence.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
result.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return result.sorted()
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
result.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 != 0 {
sequence.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
return sequence.sorted()
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 != 0 {
sequence.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
return sequence.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
result.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = (3 * current) + 1
}
}
return result.sorted()
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
result.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = (3 * current) + 1
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var current = n
while current != 1 {
if current % 2 == 1 {
collatzSequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
}
collatzSequence.append(1)
collatzSequence.sort()
return collatzSequence
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var current = n
while current != 1 {
if current % 2 == 1 {
collatzSequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
}
collatzSequence.append(1)
collatzSequence.sort()
return collatzSequence
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var current = n
while current != 1 {
collatzSequence.append(current)
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
collatzSequence.append(1)
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var current = n
while current != 1 {
collatzSequence.append(current)
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
collatzSequence.append(1)
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var current = n
while current != 1 {
collatzSequence.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
}
collatzSequence.append(1)
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var current = n
while current != 1 {
collatzSequence.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
}
collatzSequence.append(1)
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
collatzSequence.append(currentNumber)
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
}
collatzSequence.append(1)
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
collatzSequence.append(currentNumber)
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
}
collatzSequence.append(1)
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var current = n
while current != 1 {
collatzSequence.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
}
collatzSequence.append(1)
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var current = n
while current != 1 {
collatzSequence.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
}
collatzSequence.append(1)
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
collatzSequence.append(currentNumber)
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
}
collatzSequence.append(1)
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
collatzSequence.append(currentNumber)
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
}
collatzSequence.append(1)
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var current = n
while current != 1 {
collatzSequence.append(current)
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
collatzSequence.append(1)
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var current = n
while current != 1 {
collatzSequence.append(current)
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
collatzSequence.append(1)
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
collatz.append(current)
}
current = current % 2 == 0 ? current / 2 : current * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
collatz.append(current)
}
current = current % 2 == 0 ? current / 2 : current * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
collatzSequence.append(currentNumber)
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
}
collatzSequence.append(1)
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
<|begin▁of▁sentence|>You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
collatzSequence.append(currentNumber)
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
}
collatzSequence.append(1)
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
import Foundation
func getOddCollatz(n: Int) -> [Int] {
var result = Set<Int>()
var current = n
while current != 1 {
if current % 2 != 0 {
result.insert(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
result.insert(1)
return result.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
import Foundation
func getOddCollatz(n: Int) -> [Int] {
var result = Set<Int>()
var current = n
while current != 1 {
if current % 2 != 0 {
result.insert(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
result.insert(1)
return result.sorted()
}
```
import Foundation
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
let oddSequence = sequence.filter { $0 % 2 != 0 }
return oddSequence.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
import Foundation
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
let oddSequence = sequence.filter { $0 % 2 != 0 }
return oddSequence.sorted()
}
```
import Foundation
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
result.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
result.append(1)
result.sort()
return result
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
import Foundation
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
result.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
result.append(1)
result.sort()
return result
}
```
import Foundation
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
let oddSequence = sequence.filter { $0 % 2 != 0 }
return oddSequence.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
import Foundation
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
let oddSequence = sequence.filter { $0 % 2 != 0 }
return oddSequence.sorted()
}
```
import Foundation
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
result.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
result.append(1)
result.sort()
return result
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
import Foundation
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
result.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
result.append(1)
result.sort()
return result
}
```
import Foundation
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
let oddSequence = sequence.filter { $0 % 2 != 0 }
return oddSequence.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
import Foundation
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
let oddSequence = sequence.filter { $0 % 2 != 0 }
return oddSequence.sorted()
}
```
import Foundation
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
sequence.append(current)
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
let oddSequence = sequence.filter { $0 % 2 != 0 }
return oddSequence.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
import Foundation
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
sequence.append(current)
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
let oddSequence = sequence.filter { $0 % 2 != 0 }
return oddSequence.sorted()
}
```
import Foundation
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
sequence.append(current)
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.filter { $0 % 2 != 0 }.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
import Foundation
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
sequence.append(current)
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.filter { $0 % 2 != 0 }.sorted()
}
```
import Foundation
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
sequence.append(current)
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
let oddSequence = sequence.filter { $0 % 2 != 0 }
return oddSequence.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
import Foundation
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
sequence.append(current)
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
let oddSequence = sequence.filter { $0 % 2 != 0 }
return oddSequence.sorted()
}
```
import Foundation
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
current = current % 2 == 0 ? current / 2 : 3 * current + 1
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
import Foundation
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
current = current % 2 == 0 ? current / 2 : 3 * current + 1
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current > 1 {
collatz.append(current)
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
}
collatz.append(1)
return collatz.filter { $0 % 2 != 0 }
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current > 1 {
collatz.append(current)
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
}
collatz.append(1)
return collatz.filter { $0 % 2 != 0 }
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
if current % 2 == 1 {
result.append(current)
}
}
result.append(1)
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
if current % 2 == 1 {
result.append(current)
}
}
result.append(1)
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = num * 3 + 1
}
if num % 2 != 0 {
arr.append(num)
}
}
return arr
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = num * 3 + 1
}
if num % 2 != 0 {
arr.append(num)
}
}
return arr
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var i = n
while i != 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = i * 3 + 1
}
if i % 2 != 0 {
arr.append(i)
}
}
return arr
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var i = n
while i != 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = i * 3 + 1
}
if i % 2 != 0 {
arr.append(i)
}
}
return arr
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current != 1 {
collatz.append(current)
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
}
collatz.append(1)
return collatz.filter { $0 % 2 != 0 }
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current != 1 {
collatz.append(current)
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
}
collatz.append(1)
return collatz.filter { $0 % 2 != 0 }
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [1]
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
result.append(current)
}
return result.filter { $0 % 2 != 0 }
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [1]
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
result.append(current)
}
return result.filter { $0 % 2 != 0 }
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current != 1 {
collatz.append(current)
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
}
collatz.append(1)
collatz = collatz.filter { $0 % 2 != 0 }
return collatz.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current != 1 {
collatz.append(current)
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
}
collatz.append(1)
collatz = collatz.filter { $0 % 2 != 0 }
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current > 1 {
collatz.append(current)
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
}
collatz.append(1)
return collatz.filter { $0 % 2 != 0 }
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current > 1 {
collatz.append(current)
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
}
collatz.append(1)
return collatz.filter { $0 % 2 != 0 }
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
collatz.append(current)
}
}
collatz.append(1)
return collatz.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
collatz.append(current)
}
}
collatz.append(1)
return collatz.sorted()
}
```
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
collatz.append(current)
}
}
return collatz
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
collatz.append(current)
}
}
return collatz
}
```
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
collatz.append(current)
}
}
return collatz
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
collatz.append(current)
}
}
return collatz
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
collatz.append(current)
}
}
return collatz
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
collatz.append(current)
}
}
return collatz
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var i = n
while i!= 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
collatz.append(i)
}
collatz.append(1)
return collatz.filter { $0 % 2!= 0 }
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var i = n
while i!= 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
collatz.append(i)
}
collatz.append(1)
return collatz.filter { $0 % 2!= 0 }
}
```
while i!= 1 { // '=' must have consistent whitespace on both sides
while i!= 1 { // use of '=' in a boolean context, did you mean '=='?
while i!= 1 { // cannot force unwrap value of non-optional type 'Int'
return collatz.filter { $0 % 2!= 0 } // '=' must have consistent whitespace on both sides
return collatz.filter { $0 % 2!= 0 } // cannot convert value of type '()' to closure result type 'Bool'
return collatz.filter { $0 % 2!= 0 } // cannot force unwrap value of non-optional type 'Int'
return collatz.filter { $0 % 2!= 0 } // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var i = n
while i!= 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
if i % 2 == 1 {
collatz.append(i)
}
}
collatz.append(1)
return collatz.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var i = n
while i!= 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
if i % 2 == 1 {
collatz.append(i)
}
}
collatz.append(1)
return collatz.sorted()
}
```
while i!= 1 { // cannot force unwrap value of non-optional type 'Int'
while i!= 1 { // '=' must have consistent whitespace on both sides
while i!= 1 { // use of '=' in a boolean context, did you mean '=='?
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var i = n
while i!= 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
if i % 2!= 0 {
collatz.append(i)
}
}
collatz.append(1)
return collatz.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var i = n
while i!= 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
if i % 2!= 0 {
collatz.append(i)
}
}
collatz.append(1)
return collatz.sorted()
}
```
while i!= 1 { // '=' must have consistent whitespace on both sides
while i!= 1 { // use of '=' in a boolean context, did you mean '=='?
while i!= 1 { // cannot force unwrap value of non-optional type 'Int'
if i % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if i % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if i % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if i % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
collatz.append(current)
}
}
return collatz
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
collatz.append(current)
}
}
return collatz
}
```
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
collatz.append(current)
}
}
collatz.append(current)
return collatz.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
collatz.append(current)
}
}
collatz.append(current)
return collatz.sorted()
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
collatz.append(current)
}
}
collatz.append(1)
return collatz.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
collatz.append(current)
}
}
collatz.append(1)
return collatz.sorted()
}
```
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2!= 0 {
collatz.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
collatz.append(1)
collatz.sort()
return collatz
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2!= 0 {
collatz.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
collatz.append(1)
collatz.sort()
return collatz
}
```
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2!= 0 {
collatz.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
collatz.append(1)
collatz.sort()
return collatz
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2!= 0 {
collatz.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
collatz.append(1)
collatz.sort()
return collatz
}
```
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2!= 0 {
collatz.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
collatz.append(1)
collatz.sort()
return collatz
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2!= 0 {
collatz.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
collatz.append(1)
collatz.sort()
return collatz
}
```
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var currentNumber = n
while currentNumber!= 1 {
if currentNumber % 2!= 0 {
collatz.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
collatz.append(1)
collatz.sort()
return collatz
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var currentNumber = n
while currentNumber!= 1 {
if currentNumber % 2!= 0 {
collatz.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
collatz.append(1)
collatz.sort()
return collatz
}
```
while currentNumber!= 1 { // cannot force unwrap value of non-optional type 'Int'
while currentNumber!= 1 { // use of '=' in a boolean context, did you mean '=='?
while currentNumber!= 1 { // '=' must have consistent whitespace on both sides
if currentNumber % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if currentNumber % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if currentNumber % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if currentNumber % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2!= 0 {
collatz.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
collatz.append(1)
collatz.sort()
return collatz
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2!= 0 {
collatz.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
collatz.append(1)
collatz.sort()
return collatz
}
```
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var currentNumber = n
while currentNumber!= 1 {
if currentNumber % 2!= 0 {
sequence.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
sequence.append(1)
return sequence.sorted()
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var currentNumber = n
while currentNumber!= 1 {
if currentNumber % 2!= 0 {
sequence.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
sequence.append(1)
return sequence.sorted()
}
```
while currentNumber!= 1 { // cannot force unwrap value of non-optional type 'Int'
while currentNumber!= 1 { // use of '=' in a boolean context, did you mean '=='?
while currentNumber!= 1 { // '=' must have consistent whitespace on both sides
if currentNumber % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if currentNumber % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if currentNumber % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if currentNumber % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var currentNumber = n
while currentNumber!= 1 {
if currentNumber % 2!= 0 {
collatz.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
collatz.append(1)
collatz.sort()
return collatz
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var currentNumber = n
while currentNumber!= 1 {
if currentNumber % 2!= 0 {
collatz.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
collatz.append(1)
collatz.sort()
return collatz
}
```
while currentNumber!= 1 { // cannot force unwrap value of non-optional type 'Int'
while currentNumber!= 1 { // use of '=' in a boolean context, did you mean '=='?
while currentNumber!= 1 { // '=' must have consistent whitespace on both sides
if currentNumber % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if currentNumber % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if currentNumber % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if currentNumber % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var currentNumber = n
var collatzSequence = [Int]()
while currentNumber!= 1 {
if currentNumber % 2!= 0 {
collatzSequence.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
collatzSequence.append(1)
collatzSequence.sort()
return collatzSequence
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var currentNumber = n
var collatzSequence = [Int]()
while currentNumber!= 1 {
if currentNumber % 2!= 0 {
collatzSequence.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
collatzSequence.append(1)
collatzSequence.sort()
return collatzSequence
}
```
while currentNumber!= 1 { // cannot force unwrap value of non-optional type 'Int'
while currentNumber!= 1 { // use of '=' in a boolean context, did you mean '=='?
while currentNumber!= 1 { // '=' must have consistent whitespace on both sides
if currentNumber % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if currentNumber % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if currentNumber % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if currentNumber % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2!= 0 {
collatz.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
collatz.append(1)
collatz.sort()
return collatz
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2!= 0 {
collatz.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
collatz.append(1)
collatz.sort()
return collatz
}
```
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2!= 0 {
collatz.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
collatz.append(1)
collatz.sort()
return collatz
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2!= 0 {
collatz.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
collatz.append(1)
collatz.sort()
return collatz
}
```
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
collatz.append(num)
}
return collatz.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
collatz.append(num)
}
return collatz.sorted()
}
```
### Challenge
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var i = n
while i != 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
collatz.append(i)
}
return collatz.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var i = n
while i != 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
collatz.append(i)
}
return collatz.sorted()
}
```
### Test
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var i = n
while i > 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
collatz.append(i)
}
return collatz
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var i = n
while i > 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
collatz.append(i)
}
return collatz
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var i = n
while i != 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
collatz.append(i)
}
return collatz.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var i = n
while i != 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
collatz.append(i)
}
return collatz.sorted()
}
```
### Problem
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var i = n
while i != 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
collatz.append(i)
}
return collatz.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var i = n
while i != 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
collatz.append(i)
}
return collatz.sorted()
}
```
### Challenge
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var i = n
while i != 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
collatz.append(i)
}
return collatz.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var i = n
while i != 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
collatz.append(i)
}
return collatz.sorted()
}
```
### Test
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var i = n
while i > 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
collatz.append(i)
}
return collatz.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var i = n
while i > 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
collatz.append(i)
}
return collatz.sorted()
}
```
### Challenge
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var i = n
while i != 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
collatz.append(i)
}
return collatz.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var i = n
while i != 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
collatz.append(i)
}
return collatz.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
result.append(num)
}
return result.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
result.append(num)
}
return result.sorted()
}
```
### Challenge
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
collatz.append(num)
}
return collatz.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
collatz.append(num)
}
return collatz.sorted()
}
```
### Challenge
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
```
### Test
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
```
### Test
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
```
### Test
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
```
### Test
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result.filter { $0 % 2 != 0 }.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result.filter { $0 % 2 != 0 }.sorted()
}
```
### Test
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num > 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
if num % 2 != 0 {
result.append(num)
}
}
return result.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num > 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
if num % 2 != 0 {
result.append(num)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: [Int] = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = n * 3 + 1
}
collatzSequence.append(n)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: [Int] = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = n * 3 + 1
}
collatzSequence.append(n)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```
n /= 2 // left side of mutating operator isn't mutable: 'n' is a 'let' constant
n = n * 3 + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: [Int] = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
collatzSequence.append(n)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: [Int] = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
collatzSequence.append(n)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```
n /= 2 // left side of mutating operator isn't mutable: 'n' is a 'let' constant
n = 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: [Int] = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = n * 3 + 1
}
collatzSequence.append(n)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: [Int] = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = n * 3 + 1
}
collatzSequence.append(n)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```
n /= 2 // left side of mutating operator isn't mutable: 'n' is a 'let' constant
n = n * 3 + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: [Int] = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = n * 3 + 1
}
collatzSequence.append(n)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: [Int] = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = n * 3 + 1
}
collatzSequence.append(n)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```
n /= 2 // left side of mutating operator isn't mutable: 'n' is a 'let' constant
n = n * 3 + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: [Int] = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
collatzSequence.append(n)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: [Int] = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
collatzSequence.append(n)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```
n /= 2 // left side of mutating operator isn't mutable: 'n' is a 'let' constant
n = 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: [Int] = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = n * 3 + 1
}
collatzSequence.append(n)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: [Int] = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = n * 3 + 1
}
collatzSequence.append(n)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```
n /= 2 // left side of mutating operator isn't mutable: 'n' is a 'let' constant
n = n * 3 + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: [Int] = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = n * 3 + 1
}
collatzSequence.append(n)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: [Int] = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = n * 3 + 1
}
collatzSequence.append(n)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```
n /= 2 // left side of mutating operator isn't mutable: 'n' is a 'let' constant
n = n * 3 + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: [Int] = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = n * 3 + 1
}
collatzSequence.append(n)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: [Int] = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = n * 3 + 1
}
collatzSequence.append(n)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```
n /= 2 // left side of mutating operator isn't mutable: 'n' is a 'let' constant
n = n * 3 + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: [Int] = [n]
while n > 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
collatzSequence.append(n)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: [Int] = [n]
while n > 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
collatzSequence.append(n)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
// Example usage:
let result = getOddCollatz(n: 5)
print(result) // Output: [1, 5]
```
n /= 2 // left side of mutating operator isn't mutable: 'n' is a 'let' constant
n = 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: [Int] = [n]
while collatzSequence.last != 1 {
let lastElement = collatzSequence.last!
if lastElement % 2 == 0 {
collatzSequence.append(lastElement / 2)
} else {
collatzSequence.append(3 * lastElement + 1)
}
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: [Int] = [n]
while collatzSequence.last != 1 {
let lastElement = collatzSequence.last!
if lastElement % 2 == 0 {
collatzSequence.append(lastElement / 2)
} else {
collatzSequence.append(3 * lastElement + 1)
}
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = (current * 3) + 1
}
result.append(current)
}
return result.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = (current * 3) + 1
}
result.append(current)
}
return result.sorted()
}
<|file_separator|>
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
result.append(num)
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
}
result.append(1)
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
result.append(num)
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
}
result.append(1)
return result
}
<|file_separator|>
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
result.append(num)
if num % 2 == 0 {
num = num / 2
} else {
num = num * 3 + 1
}
}
result.append(1)
return result.filter { $0 % 2 != 0 }.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
result.append(num)
if num % 2 == 0 {
num = num / 2
} else {
num = num * 3 + 1
}
}
result.append(1)
return result.filter { $0 % 2 != 0 }.sorted()
}
<|file_separator|>
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
result.append(current)
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
result.append(1)
return result.filter { $0 % 2 != 0 }
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
result.append(current)
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
result.append(1)
return result.filter { $0 % 2 != 0 }
}
<|file_separator|>
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
result.append(num)
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
}
result.append(1)
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
result.append(num)
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
}
result.append(1)
return result
}
<|file_separator|>
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result.filter { $0 % 2 == 1 }
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result.filter { $0 % 2 == 1 }
}
<|file_separator|>
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
result.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = (3 * current) + 1
}
}
result.append(1)
return result.filter { $0 % 2 == 1 }
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
result.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = (3 * current) + 1
}
}
result.append(1)
return result.filter { $0 % 2 == 1 }
}
<|file_separator|>
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
result.append(num)
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
}
result.append(1)
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
result.append(num)
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
}
result.append(1)
return result
}
<|file_separator|>
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
result.append(num)
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
}
result.append(1)
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
result.append(num)
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
}
result.append(1)
return result
}
<|file_separator|>
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
result.append(num)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
result.append(num)
}
return result
}
<|file_separator|>
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
result.append(num)
}
return result.filter { $0 % 2 == 1 }
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
result.append(num)
}
return result.filter { $0 % 2 == 1 }
}
<|file_separator|>
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
result.append(num)
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
}
result.append(1)
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
result.append(num)
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
}
result.append(1)
return result
}
<|file_separator|>
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
result.append(num)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
result.append(num)
}
return result
}
<|file_separator|>
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
result.append(num)
if num % 2 == 0 {
num = num / 2
} else {
num = (num * 3) + 1
}
}
result.append(1)
return result.filter { $0 % 2 != 0 }.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
result.append(num)
if num % 2 == 0 {
num = num / 2
} else {
num = (num * 3) + 1
}
}
result.append(1)
return result.filter { $0 % 2 != 0 }.sorted()
}
<|file_separator|>
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = (3 * current) + 1
}
result.append(current)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = (3 * current) + 1
}
result.append(current)
}
return result
}
<|file_separator|>
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
result.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
}
result.append(1)
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
result.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
}
result.append(1)
return result
}
<|file_separator|>
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num /= 2
} else {
num = (num * 3) + 1
}
result.append(num)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num /= 2
} else {
num = (num * 3) + 1
}
result.append(num)
}
return result
}
<|file_separator|>
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = (num * 3) + 1
}
result.append(num)
}
return result
}
func getEvenCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = (num * 3) + 1
}
result.append(num)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = (num * 3) + 1
}
result.append(num)
}
return result
}
// Given a positive integer n, return a sorted array that has the even numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_even_collatz(5) returns [2, 4] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the even numbers are only 2, and 4.
// getEvenCollatz(n: 5) == [2, 4]
func getEvenCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = (num * 3) + 1
}
result.append(num)
}
return result
}
// Given a positive integer n, return a sorted array that has the even numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_even_collatz(5) returns [2, 4] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the even numbers are only 2, and 4.
// getEvenCollatz(n: 5) == [2, 4]
func getEvenCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = (num * 3) + 1
}
result.append(num)
}
return result
}
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num =
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num /= 2
} else {
num = (num * 3) + 1
}
result.append(num)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num /= 2
} else {
num = (num * 3) + 1
}
result.append(num)
}
return result
}
<|file_separator|>
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
result.append(current)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
result.append(current)
}
return result
}
<|file_separator|>
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current != 1 {
collatz.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
}
collatz.append(1)
collatz = collatz.filter { $0 % 2 != 0 }
return collatz.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current != 1 {
collatz.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
}
collatz.append(1)
collatz = collatz.filter { $0 % 2 != 0 }
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
collatz.append(current)
}
collatz.reverse()
return collatz.filter { $0 % 2 != 0 }
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
collatz.append(current)
}
collatz.reverse()
return collatz.filter { $0 % 2 != 0 }
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var number = n
while number != 1 {
if number % 2 == 0 {
number = number / 2
} else {
number = (number * 3) + 1
}
collatz.append(number)
}
return collatz.filter { $0 % 2 != 0 }.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var number = n
while number != 1 {
if number % 2 == 0 {
number = number / 2
} else {
number = (number * 3) + 1
}
collatz.append(number)
}
return collatz.filter { $0 % 2 != 0 }.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
collatz.append(current)
}
}
return collatz
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
collatz.append(current)
}
}
return collatz
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var arr = [n]
var i = n
while i != 1 {
if i % 2 == 0 {
i /= 2
} else {
i = i * 3 + 1
}
arr.append(i)
}
return arr.filter { $0 % 2 != 0 }
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [n]
var i = n
while i != 1 {
if i % 2 == 0 {
i /= 2
} else {
i = i * 3 + 1
}
arr.append(i)
}
return arr.filter { $0 % 2 != 0 }
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
collatz.append(num)
if num % 2 == 0 {
num = num / 2
} else {
num = num * 3 + 1
}
}
collatz.append(1)
return collatz.filter { $0 % 2 != 0 }
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
collatz.append(num)
if num % 2 == 0 {
num = num / 2
} else {
num = num * 3 + 1
}
}
collatz.append(1)
return collatz.filter { $0 % 2 != 0 }
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
collatz.append(current)
}
collatz.reverse()
let oddCollatz = collatz.filter { $0 % 2 == 1 }
return oddCollatz
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
collatz.append(current)
}
collatz.reverse()
let oddCollatz = collatz.filter { $0 % 2 == 1 }
return oddCollatz
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var number = n
while number != 1 {
result.append(number)
number = number % 2 == 0 ? number / 2 : 3 * number + 1
}
result.append(1)
return result.filter { $0 % 2 != 0 }
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var number = n
while number != 1 {
result.append(number)
number = number % 2 == 0 ? number / 2 : 3 * number + 1
}
result.append(1)
return result.filter { $0 % 2 != 0 }
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current != 1 {
collatz.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
}
collatz.append(1)
return collatz.filter { $0 % 2 != 0 }
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current != 1 {
collatz.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
}
collatz.append(1)
return collatz.filter { $0 % 2 != 0 }
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current != 1 {
collatz.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
}
collatz.append(1)
collatz = collatz.filter { $0 % 2 != 0 }
return collatz
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current != 1 {
collatz.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
}
collatz.append(1)
collatz = collatz.filter { $0 % 2 != 0 }
return collatz
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
while n != 1 {
if n % 2 == 0 {
n = n / 2
} else {
n = 3 * n + 1
}
arr.append(n)
}
return arr
}
func getEvenCollatz(n: Int) -> [Int] {
var arr = [Int]()
while n != 1 {
if n % 2 == 0 {
n = n / 2
} else {
n = 3 * n + 1
}
arr.append(n)
}
return arr
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
while n != 1 {
if n % 2 == 0 {
n = n / 2
} else {
n = 3 * n + 1
}
arr.append(n)
}
return arr
}
// Given a positive integer n, return a sorted array that has the even numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_even_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the even numbers are only 1, and 5.
// getEvenCollatz(n: 5) == [1, 5]
func getEvenCollatz(n: Int) -> [Int] {
var arr = [Int]()
while n != 1 {
if n % 2 == 0 {
n = n / 2
} else {
n = 3 * n + 1
}
arr.append(n)
}
return arr
}
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
while n != 1 {
if n % 2 == 0 {
n = n / 2
} else {
n = 3 * n + 1
}
arr.append(n)
}
return arr
}
// Given a positive integer n, return a sorted array that has the even numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_even_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the even numbers are only 1, and 5.
// getEvenCollatz(n: 5) == [1, 5]
func getEvenCollatz(n: Int) -> [Int] {
var arr = [Int]()
while n != 1 {
if n % 2 == 0 {
n = n / 2
n = n / 2 // cannot assign to value: 'n' is a 'let' constant
n = 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
n = n / 2 // cannot assign to value: 'n' is a 'let' constant
n = 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
while n != 1 {
if n % 2 == 0 {
n = n / 2
} else {
n = n * 3 + 1
}
result.append(n)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
while n != 1 {
if n % 2 == 0 {
n = n / 2
} else {
n = n * 3 + 1
}
result.append(n)
}
return result
}
// getOddCollatz(5) == [1, 5]
// getOddCollatz(10) == [1, 10, 5, 16, 8, 4, 2, 1]
// getOddCollatz(1) == [1]
```
n = n / 2 // cannot assign to value: 'n' is a 'let' constant
n = n * 3 + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
while n != 1 {
if n % 2 == 0 {
n = n / 2
} else {
n = 3 * n + 1
}
oddCollatz.append(n)
}
return oddCollatz
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
while n != 1 {
if n % 2 == 0 {
n = n / 2
} else {
n = 3 * n + 1
}
oddCollatz.append(n)
}
return oddCollatz
}
// Test cases
print(getOddCollatz(5)) // [1, 5]
print(getOddCollatz(10)) // [1, 10]
print(getOddCollatz(15)) // [1, 15]
print(getOddCollatz(20)) // [1, 20]
print(getOddCollatz(25)) // [1, 25]
print(getOddCollatz(30)) // [1, 30]
print(getOddCollatz(35)) // [1, 35]
print(getOddCollatz(40)) // [1, 40]
print(getOddCollatz(45)) // [1, 45]
print(getOddCollatz(50)) // [1, 50]
print(getOddCollatz(55)) // [1, 55]
print(getOddCollatz(60)) // [1, 60]
print(getOddCollatz(65)) // [1, 65]
print(getOddCollatz(70)) // [1, 70]
print(getOddCollatz(75)) // [1, 75]
print(getOddCollatz(80)) // [1, 80]
print(getOddCollatz(85)) // [1, 85]
print(getOddCollatz(90)) // [1, 90]
print(getOddCollatz(95)) // [1, 95]
print(getOddCollatz(100)) // [1, 100]
print(getOddCollatz(105)) // [1, 105]
print(getOddCollatz(110)) // [1, 110]
print(getOddCollatz(115)) // [1, 115]
print(getOddCollatz(120)) // [1, 120]
print(getOddCollatz(125)) // [1, 125]
print(getOddCollatz(130)) // [1, 130]
print(getOddCollatz(135)) // [1, 135]
print(getOddCollatz(140)) // [1, 140]
print(getOddCollatz(145)) // [1, 145]
print(getOddCollatz(150)) // [1, 150]
print(getOddCollatz(155)) // [1, 155]
print(getOddCollatz(160)) // [1, 160]
print(getOddCollatz(165)) // [1, 165]
print(getOddCollatz(170)) // [1, 170]
print(getOddCollatz(175)) // [1, 175]
print(getOddCollatz(180)) // [1, 180]
print(getOddCollatz(185)) // [1, 185]
print(getOddCollatz(190)) // [1, 190]
print(getOddCollatz(195)) // [1, 195]
print(getOddCollatz(200)) // [1, 200]
print(getOddCollatz(205)) // [1, 205]
print(getOddCollatz(210)) // [1, 210]
print(getOddCollatz(215)) // [1, 215]
print(getOddCollatz(220)) // [1, 220]
print(getOddCollatz(225)) // [1, 225]
print(getOddCollatz(230)) // [1, 230]
print(getOddCollatz(235)) // [1,
n = n / 2 // cannot assign to value: 'n' is a 'let' constant
n = 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
while n != 1 {
if n % 2 == 0 {
n = n / 2
} else {
n = 3 * n + 1
}
arr.append(n)
}
return arr.sorted()
}
func getEvenCollatz(n: Int) -> [Int] {
var arr = [Int]()
while n != 1 {
if n % 2 == 0 {
n = n / 2
} else {
n = 3 * n + 1
}
arr.append(n)
}
return arr.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
while n != 1 {
if n % 2 == 0 {
n = n / 2
} else {
n = 3 * n + 1
}
arr.append(n)
}
return arr.sorted()
}
// Given a positive integer n, return a sorted array that has the even numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_even_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the even numbers are only 1, and 5.
// getEvenCollatz(n: 5) == [1, 5]
func getEvenCollatz(n: Int) -> [Int] {
var arr = [Int]()
while n != 1 {
if n % 2 == 0 {
n = n / 2
} else {
n = 3 * n + 1
}
arr.append(n)
}
return arr.sorted()
}
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
while n != 1 {
if n % 2 == 0 {
n = n / 2
} else {
n = 3 * n + 1
}
arr.append(n)
}
return arr.sorted()
}
// Given a positive integer n, return a sorted array that has the even numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_even_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the even numbers are only 1, and 5.
// getEvenCollatz(n: 5) == [1, 5]
func getEvenCollatz(n: Int) -> [Int] {
var arr = [Int]()
while n != 1 {
if n % 2 == 0 {
n = n / 2 // cannot assign to value: 'n' is a 'let' constant
n = 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
n = n / 2 // cannot assign to value: 'n' is a 'let' constant
n = 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
while n != 1 {
if n % 2 == 1 {
n = 3 * n + 1
} else {
n = n / 2
}
result.append(n)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
while n != 1 {
if n % 2 == 1 {
n = 3 * n + 1
} else {
n = n / 2
}
result.append(n)
}
return result
}
// Test cases
print(getOddCollatz(5)) // [1, 5]
print(getOddCollatz(1)) // [1]
print(getOddCollatz(10)) // [1, 10]
print(getOddCollatz(15)) // [1, 15]
print(getOddCollatz(20)) // [1, 10, 5, 16, 8, 4, 2, 1]
print(getOddCollatz(25)) // [1, 25]
print(getOddCollatz(30)) // [1, 10, 5, 16, 8, 4, 2, 1]
print(getOddCollatz(35)) // [1, 10, 5, 16, 8, 4, 2, 1]
print(getOddCollatz(40)) // [1, 10, 5, 16, 8, 4, 2, 1]
print(getOddCollatz(45)) // [1, 10, 5, 16, 8, 4, 2, 1]
print(getOddCollatz(50)) // [1, 10, 5, 16, 8, 4, 2, 1]
print(getOddCollatz(55)) // [1, 10, 5, 16, 8, 4, 2, 1]
print(getOddCollatz(60)) // [1, 10, 5, 16, 8, 4, 2, 1]
print(getOddCollatz(65)) // [1, 10, 5, 16, 8, 4, 2, 1]
print(getOddCollatz(70)) // [1, 10, 5, 16, 8, 4, 2, 1]
print(getOddCollatz(75)) // [1, 10, 5, 16, 8, 4, 2, 1]
print(getOddCollatz(80)) // [1, 10, 5, 16, 8, 4, 2, 1]
print(getOddCollatz(85)) // [1, 10, 5, 16, 8, 4, 2, 1]
print(getOddCollatz(90)) // [1, 10, 5, 16, 8, 4, 2, 1]
print(getOddCollatz(95)) // [1, 10, 5, 16, 8, 4, 2, 1]
print(getOddCollatz(100)) // [1, 10, 5, 16, 8, 4, 2, 1]
print(getOddCollatz(105)) // [1, 10, 5, 16, 8, 4, 2, 1]
print(getOddCollatz(110)) // [1, 10, 5, 16, 8, 4, 2, 1]
print(getOddCollatz(115)) // [1, 10, 5, 16, 8, 4, 2, 1]
print(getOddCollatz(120)) // [1, 10, 5, 16, 8, 4, 2, 1]
print(getOddCollatz(125)) // [1, 10, 5, 16, 8, 4, 2, 1]
print(getOddCollatz(130)) // [1, 10, 5, 16, 8, 4, 2, 1]
print(getOddCollatz(135)) // [1, 1
n = 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
n = n / 2 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: [Int] = [n]
while n != 1 {
if n % 2 == 0 {
n = n / 2
} else {
n = (3 * n) + 1
}
collatzSequence.append(n)
}
var oddCollatzSequence: [Int] = []
for i in collatzSequence {
if i % 2 == 1 {
oddCollatzSequence.append(i)
}
}
return oddCollatzSequence
}
func getOddCollatzCount(n: Int) -> Int {
return getOddCollatz(n).count()
}
func getEvenCollatzCount(n: Int) -> Int {
return getOddCollatz(n).count()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: [Int] = [n]
while n != 1 {
if n % 2 == 0 {
n = n / 2
} else {
n = (3 * n) + 1
}
collatzSequence.append(n)
}
var oddCollatzSequence: [Int] = []
for i in collatzSequence {
if i % 2 == 1 {
oddCollatzSequence.append(i)
}
}
return oddCollatzSequence
}
// Given a positive integer n, return the number of odd numbers in the Collatz sequence.
// Note:
// 1. Collatz(1) is 0.
// 2. returned number is positive.
// For example:
// getOddCollatzCount(5) returns 1 # The Collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so there is 1 odd number.
// getOddCollatzCount(n: 5) == 1
func getOddCollatzCount(n: Int) -> Int {
return getOddCollatz(n).count()
}
// Given a positive integer n, return the number of even numbers in the Collatz sequence.
// Note:
// 1. Collatz(1) is 0.
// 2. returned number is positive.
// For example:
// getEvenCollatzCount(5) returns 1 # The Collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so there is 1 even number.
// getEvenCollatzCount(n: 5) == 1
func getEvenCollatzCount(n: Int) -> Int {
return getOddCollatz(n).count()
}
// Given a positive integer n, return the number of odd numbers in the Collatz sequence.
// Note:
// 1. Collatz(1) is 0.
// 2. returned number is positive.
// For example:
// getOddCollatzCount(5) returns 1 # The Collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so there is 1 odd number.
// getOddCollatzCount(n: 5) == 1
func getOddCollatzCount(n: Int) -> Int {
return getOddCollatz(n).count()
}
// Given a positive integer n, return the number of even numbers in the Collatz sequence.
// Note:
// 1. Collatz(1) is 0.
// 2. returned number is positive.
// For example:
// getEvenCollatzCount(5) returns 1 # The Collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so there is 1 even number.
// getEvenCollatzCount(n: 5) == 1
func getEvenCollatzCount(n: Int) -> Int {
return getOddCollatz(n).count()
}
// Given a positive integer n, return the number of odd numbers in the Collatz sequence.
// Note:
// 1. Collatz(1) is 0.
// 2. returned number is positive.
// For example:
// getOddCollatzCount(5) returns 1 # The Collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so there is 1 odd number.
// getOddCollatzCount(n: 5) == 1
func getOddCollatzCount(n: Int) -> Int {
return getOddCollatz(n).count()
}
// Given a positive integer n, return the number of even numbers in the Collatz sequence.
// Note:
// 1. Collatz(1) is 0.
// 2. returned number is positive.
// For example:
// getEvenCollatzCount(5) returns 1 # The Collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so there is 1 even number.
// getEvenCollatzCount(n: 5) == 1
func getEvenCollatzCount(n: Int) -> Int {
return getOddCollatz(n).count()
}
// Given a positive integer n, return
n = n / 2 // cannot assign to value: 'n' is a 'let' constant
n = (3 * n) + 1 // cannot assign to value: 'n' is a 'let' constant
return getOddCollatz(n).count() // missing argument label 'n:' in call
return getOddCollatz(n).count() // cannot call value of non-function type 'Int'
return getOddCollatz(n).count() // cannot call value of non-function type 'Int'
return getOddCollatz(n).count() // missing argument label 'n:' in call
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
num = num * 3 + 1
} else {
num = num / 2
}
arr.append(num)
}
return arr
}
func getUniqueIntegers(nums: [Int]) -> Int {
var arr = [Int]()
for i in 0..<nums.count {
if !arr.contains(nums[i]) {
arr.append(nums[i])
}
}
return arr.count
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
num = num * 3 + 1
} else {
num = num / 2
}
arr.append(num)
}
return arr
}
// Given an array of integers nums, return the number of unique integers in the array.
// Note:
// 1. The order of the integers in the return integer does not matter.
// 2. Return 0 if the array is empty.
// For example:
// getUniqueIntegers([1, 1, 2, 2, 3]) returns 3
// getUniqueIntegers([1, 2, 3]) returns 3
// getUniqueIntegers([]) returns 0
func getUniqueIntegers(nums: [Int]) -> Int {
var arr = [Int]()
for i in 0..<nums.count {
if !arr.contains(nums[i]) {
arr.append(nums[i])
}
}
return arr.count
}
// Given an array of integers nums, return the number of unique integers in the array.
// Note:
// 1. The order of the integers in the return integer does not matter.
// 2. Return 0 if the array is empty.
// For example:
// getUniqueIntegers([1, 1, 2, 2, 3]) returns 3
// getUniqueIntegers([1, 2, 3]) returns 3
// getUniqueIntegers([]) returns 0
func getUniqueIntegers(nums: [Int]) -> Int {
var arr = [Int]()
for i in 0..<nums.count {
if !arr.contains(nums[i]) {
arr.append(nums[i])
}
}
return arr.count
}
// Given an array of integers nums, return the number of unique integers in the array.
// Note:
// 1. The order of the integers in the return integer does not matter.
// 2. Return 0 if the array is empty.
// For example:
// getUniqueIntegers([1, 1, 2, 2, 3]) returns 3
// getUniqueIntegers([1, 2, 3]) returns 3
// getUniqueIntegers([]) returns 0
func getUniqueIntegers(nums: [Int]) -> Int {
var arr = [Int]()
for i in 0..<nums.count {
if !arr.contains(nums[i]) {
arr.append(nums[i])
}
}
return arr.count
}
// Given an array of integers nums, return the number of unique integers in the array.
// Note:
// 1. The order of the integers in the return integer does not matter.
// 2. Return 0 if the array is empty.
// For example:
// getUniqueIntegers([1, 1, 2, 2, 3]) returns 3
// getUniqueIntegers([1, 2, 3]) returns 3
// getUniqueIntegers([]) returns 0
func getUniqueIntegers(nums: [Int]) -> Int {
var arr = [Int]()
for i in 0..<nums.count {
if !arr.contains(nums[i]) {
arr.append(nums[i])
}
}
return arr.count
}
// Given an array of integers nums, return the number of unique integers in the array.
// Note:
// 1. The order of the integers in the return integer does not matter.
// 2. Return 0 if the array is empty.
// For example:
// getUniqueIntegers([1, 1, 2, 2, 3]) returns 3
// getUniqueIntegers([1, 2, 3]) returns 3
// getUniqueIntegers([]) returns 0
func getUniqueIntegers(nums: [Int]) -> Int {
var arr = [Int]()
for i in 0..<nums.count {
if !arr.contains(nums[i]) {
arr.append(nums[i])
}
}
return arr.count
}
// Given an array of integers nums, return the number of unique integers in the array.
// Note:
// 1
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
var i = n
while i > 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
oddCollatz.append(i)
}
return oddCollatz
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
var i = n
while i > 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
oddCollatz.append(i)
}
return oddCollatz
}
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
var i = n
while i > 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
oddCollatz.append(i)
}
return oddCollatz
}
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
var i = n
while i > 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
oddCollatz.append(i)
}
return oddCollatz
}
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]([])
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = (num * 3) + 1
}
arr.append(num)
}
return arr
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]([])
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = (num * 3) + 1
}
arr.append(num)
}
return arr
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var i = n
while i > 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
if i % 2 == 1 {
arr.append(i)
}
}
return arr
}
func getRepeated(arr: [Int], n: Int) -> [Int] {
var newArr = [Int]()
for i in 1...n {
for j in arr {
newArr.append(j)
}
}
return newArr
}
func longestPalindromic(s: String) -> String {
var maxLen = 0
var maxStr = ""
for i in 0..<s.count {
for j in i..<s.count {
var subStr = s[i...j]
if isPalindrome(subStr) && subStr.count > maxLen {
maxLen = subStr.count
maxStr = subStr
}
}
}
return maxStr
}
func isPalindrome(s: String) -> Bool {
var i = 0
var j = s.count - 1
while i < j {
if s[i] != s[j] {
return false
}
i += 1
j -= 1
}
return true
}
func twoSum(nums: [Int], target: Int) -> [Int] {
var map = [Int: Int]()
for i in 0..<nums.count {
var complement = target - nums[i]
if map.contains(complement) {
return [i, map[complement]!]
}
map[nums[i]] = i
}
return [Int]()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var i = n
while i > 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
if i % 2 == 1 {
arr.append(i)
}
}
return arr
}
// Given an array of integers, return a new array of length n2 with the elements of the original array n times.
// For example:
// get_repeated([1, 2, 3], 2) returns [1, 1, 2, 2, 3, 3]
// get_repeated([1, 2, 3], 3) returns [1, 1, 1, 2, 2, 2, 3, 3, 3]
func getRepeated(arr: [Int], n: Int) -> [Int] {
var newArr = [Int]()
for i in 1...n {
for j in arr {
newArr.append(j)
}
}
return newArr
}
// Given a string s, return the longest palindromic substring in s.
// For example:
// longest_palindromic("babad") returns "bab"
// longest_palindromic("cbbd") returns "bb"
// longest_palindromic("a") returns "a"
// longest_palindromic("ac") returns "a"
func longestPalindromic(s: String) -> String {
var maxLen = 0
var maxStr = ""
for i in 0..<s.count {
for j in i..<s.count {
var subStr = s[i...j]
if isPalindrome(subStr) && subStr.count > maxLen {
maxLen = subStr.count
maxStr = subStr
}
}
}
return maxStr
}
func isPalindrome(s: String) -> Bool {
var i = 0
var j = s.count - 1
while i < j {
if s[i] != s[j] {
return false
}
i += 1
j -= 1
}
return true
}
// Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target.
// You may assume that each input would have exactly one solution, and you may not use the same element twice.
// You can return the answer in any order.
// For example:
// twoSum([2, 7, 11, 15], 9) returns [0, 1]
// twoSum([3, 2, 4], 6) returns [1, 2]
// twoSum([3, 3], 6) returns [0, 1]
func twoSum(nums: [Int], target: Int) -> [Int] {
var map = [Int: Int]()
for i in 0..<nums.count {
var complement = target - nums[i]
if map.contains(complement) {
return [i, map[complement]!]
}
map[nums[i]] = i
}
return [Int]()
}
// Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target.
// You may assume that each input would have exactly one solution, and you may not use the same element twice.
// You can return the answer in any order.
// For example:
// twoSum([2, 7, 11, 15], 9) returns [0, 1]
// twoSum([3, 2, 4], 6) returns [1, 2]
// twoSum([3, 3], 6) returns [0, 1]
func twoSum(nums: [Int], target: Int) -> [Int] {
var map = [Int: Int]()
for i in 0..<nums.count {
var complement = target - nums[i]
if map.contains(complement) {
return [i, map[complement]!]
}
map[nums[i]] = i
}
return [Int]()
}
// Given an array of integers nums and an integer target, return
for i in 1...n { // immutable value 'i' was never used; consider replacing with '_' or removing it
var subStr = s[i...j] // 'subscript(_:)' is unavailable: cannot subscript String with an integer range, use a String.Index range instead.
if isPalindrome(subStr) && subStr.count > maxLen { // missing argument label 's:' in call
if s[i] != s[j] { // 'subscript(_:)' is unavailable: cannot subscript String with an Int, use a String.Index instead.
if s[i] != s[j] { // 'subscript(_:)' is unavailable: cannot subscript String with an Int, use a String.Index instead.
if map.contains(complement) { // cannot convert value of type 'Int' to expected argument type '(Dictionary<Int, Int>.Element) throws -> Bool' (aka '((key: Int, value: Int)) throws -> Bool')
if map.contains(complement) { // missing argument label 'where:' in call
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence: [Int] = [n]
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
sequence.append(currentNumber)
}
return sequence.filter { $0 % 2 != 0 }
}
<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence: [Int] = [n]
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
sequence.append(currentNumber)
}
return sequence.filter { $0 % 2 != 0 }
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.reversed()
}
<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result.reversed()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence: [Int] = []
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
if !sequence.contains(currentNumber) {
sequence.append(currentNumber)
}
}
return sequence.reversed()
}
<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence: [Int] = []
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
if !sequence.contains(currentNumber) {
sequence.append(currentNumber)
}
}
return sequence.reversed()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result
}
<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence: [Int] = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = (current * 3) + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }
}
<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence: [Int] = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = (current * 3) + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
if currentNumber % 2 != 0 {
sequence.append(currentNumber)
}
}
return sequence.sorted()
}
<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
if currentNumber % 2 != 0 {
sequence.append(currentNumber)
}
}
return sequence.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence: [Int] = []
var number = n
while number != 1 {
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
sequence.append(number)
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence: [Int] = []
var number = n
while number != 1 {
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
sequence.append(number)
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
sequence.append(currentNumber)
}
return sequence.filter { $0 % 2 != 0 }
}
<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
sequence.append(currentNumber)
}
return sequence.filter { $0 % 2 != 0 }
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
if currentNumber % 2 != 0 {
sequence.append(currentNumber)
}
}
return sequence.sorted()
}
<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
if currentNumber % 2 != 0 {
sequence.append(currentNumber)
}
}
return sequence.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }
}
<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }
}
<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }
}
<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var number = n
while number != 1 {
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
sequence.append(number)
}
return sequence.filter { $0 % 2 != 0 }
}
<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var number = n
while number != 1 {
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
sequence.append(number)
}
return sequence.filter { $0 % 2 != 0 }
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }
}
<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
result.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
return result.sorted()
}
<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
result.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
result.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
return result.sorted()
}
<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
result.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 1 {
result.append(current)
current = 3 * current + 1
} else {
current /= 2
}
}
return result.reversed()
}
<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 1 {
result.append(current)
current = 3 * current + 1
} else {
current /= 2
}
}
return result.reversed()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 1 {
result.append(current)
current = 3 * current + 1
} else {
current /= 2
}
}
result.append(1)
return result.reversed()
}
<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 1 {
result.append(current)
current = 3 * current + 1
} else {
current /= 2
}
}
result.append(1)
return result.reversed()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }
}
<start_of_turn>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<end_of_turn>
<start_of_turn>model
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
collatzSequence.append(currentNumber)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
collatzSequence.append(currentNumber)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
collatzSequence.append(currentNumber)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
collatzSequence.append(currentNumber)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
sequence.append(currentNumber)
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
sequence.append(currentNumber)
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
sequence.append(currentNumber)
}
return sequence.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
sequence.append(currentNumber)
}
return sequence.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
collatzSequence.append(currentNumber)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
collatzSequence.append(currentNumber)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while sequence.last != 1 {
let current = sequence.removeLast()
if current % 2 == 0 {
sequence.append(current / 2)
} else {
sequence.append(3 * current + 1)
}
}
return sequence.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while sequence.last != 1 {
let current = sequence.removeLast()
if current % 2 == 0 {
sequence.append(current / 2)
} else {
sequence.append(3 * current + 1)
}
}
return sequence.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while sequence.last != 1 {
let lastNumber = sequence.last!
if lastNumber % 2 == 0 {
sequence.append(lastNumber / 2)
} else {
sequence.append(3 * lastNumber + 1)
}
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while sequence.last != 1 {
let lastNumber = sequence.last!
if lastNumber % 2 == 0 {
sequence.append(lastNumber / 2)
} else {
sequence.append(3 * lastNumber + 1)
}
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
collatzSequence.append(currentNumber)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
collatzSequence.append(currentNumber)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
sequence.append(currentNumber)
}
return sequence.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
sequence.append(currentNumber)
}
return sequence.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
collatzSequence.append(currentNumber)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
collatzSequence.append(currentNumber)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var oddNumbers = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 1 {
oddNumbers.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
return oddNumbers
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var oddNumbers = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 1 {
oddNumbers.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
return oddNumbers
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 == 1 {
sequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
sequence.append(1)
return sequence.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 == 1 {
sequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
sequence.append(1)
return sequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var oddNumbers = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 1 {
oddNumbers.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
return oddNumbers
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var oddNumbers = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 1 {
oddNumbers.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
return oddNumbers
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 == 1 {
sequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
sequence.append(1)
return sequence.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 == 1 {
sequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
sequence.append(1)
return sequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 1 {
result.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return result
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 1 {
result.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var oddNumbers = [Int]()
var currentNumber = n
while currentNumber > 1 {
if currentNumber % 2 == 1 {
oddNumbers.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
return oddNumbers.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var oddNumbers = [Int]()
var currentNumber = n
while currentNumber > 1 {
if currentNumber % 2 == 1 {
oddNumbers.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
return oddNumbers.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current > 1 {
if current % 2 == 1 {
sequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return sequence.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current > 1 {
if current % 2 == 1 {
sequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return sequence.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5] [/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while n!= 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
sequence.append(n)
}
return sequence.filter { $0 % 2!= 0 }
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while n!= 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
sequence.append(n)
}
return sequence.filter { $0 % 2!= 0 }
}
```
while n!= 1 { // cannot force unwrap value of non-optional type 'Int'
while n!= 1 { // use of '=' in a boolean context, did you mean '=='?
while n!= 1 { // '=' must have consistent whitespace on both sides
n /= 2 // left side of mutating operator isn't mutable: 'n' is a 'let' constant
n = 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
return sequence.filter { $0 % 2!= 0 } // cannot convert value of type '()' to closure result type 'Bool'
return sequence.filter { $0 % 2!= 0 } // '=' must have consistent whitespace on both sides
return sequence.filter { $0 % 2!= 0 } // cannot force unwrap value of non-optional type 'Int'
return sequence.filter { $0 % 2!= 0 } // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 == 1 }
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 == 1 }
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while n!= 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
sequence.append(n)
}
return sequence.filter { $0 % 2!= 0 }
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while n!= 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
sequence.append(n)
}
return sequence.filter { $0 % 2!= 0 }
}
```
while n!= 1 { // cannot force unwrap value of non-optional type 'Int'
while n!= 1 { // use of '=' in a boolean context, did you mean '=='?
while n!= 1 { // '=' must have consistent whitespace on both sides
n /= 2 // left side of mutating operator isn't mutable: 'n' is a 'let' constant
n = 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
return sequence.filter { $0 % 2!= 0 } // cannot convert value of type '()' to closure result type 'Bool'
return sequence.filter { $0 % 2!= 0 } // '=' must have consistent whitespace on both sides
return sequence.filter { $0 % 2!= 0 } // cannot force unwrap value of non-optional type 'Int'
return sequence.filter { $0 % 2!= 0 } // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while n!= 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
sequence.append(n)
}
return sequence.filter { $0 % 2!= 0 }
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while n!= 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
sequence.append(n)
}
return sequence.filter { $0 % 2!= 0 }
}
```
while n!= 1 { // cannot force unwrap value of non-optional type 'Int'
while n!= 1 { // use of '=' in a boolean context, did you mean '=='?
while n!= 1 { // '=' must have consistent whitespace on both sides
n /= 2 // left side of mutating operator isn't mutable: 'n' is a 'let' constant
n = 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
return sequence.filter { $0 % 2!= 0 } // cannot convert value of type '()' to closure result type 'Bool'
return sequence.filter { $0 % 2!= 0 } // '=' must have consistent whitespace on both sides
return sequence.filter { $0 % 2!= 0 } // cannot force unwrap value of non-optional type 'Int'
return sequence.filter { $0 % 2!= 0 } // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
collatz.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
collatz.append(1)
return collatz.filter { $0 % 2 == 1 }
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
collatz.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
collatz.append(1)
return collatz.filter { $0 % 2 == 1 }
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
collatz.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
}
collatz.append(1)
return collatz.filter { $0 % 2!= 0 }
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
collatz.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
}
collatz.append(1)
return collatz.filter { $0 % 2!= 0 }
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
return collatz.filter { $0 % 2!= 0 } // cannot force unwrap value of non-optional type 'Int'
return collatz.filter { $0 % 2!= 0 } // '=' must have consistent whitespace on both sides
return collatz.filter { $0 % 2!= 0 } // cannot convert value of type '()' to closure result type 'Bool'
return collatz.filter { $0 % 2!= 0 } // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
collatz.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
collatz.append(1)
return collatz.filter { $0 % 2!= 0 }
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
collatz.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
collatz.append(1)
return collatz.filter { $0 % 2!= 0 }
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
return collatz.filter { $0 % 2!= 0 } // cannot force unwrap value of non-optional type 'Int'
return collatz.filter { $0 % 2!= 0 } // '=' must have consistent whitespace on both sides
return collatz.filter { $0 % 2!= 0 } // cannot convert value of type '()' to closure result type 'Bool'
return collatz.filter { $0 % 2!= 0 } // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 == 1 }
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 == 1 }
}
```
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
sequence.append(current)
}
var oddNumbers = [Int]()
for number in sequence {
if number % 2!= 0 {
oddNumbers.append(number)
}
}
return oddNumbers.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
sequence.append(current)
}
var oddNumbers = [Int]()
for number in sequence {
if number % 2!= 0 {
oddNumbers.append(number)
}
}
return oddNumbers.sorted()
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
if number % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if number % 2!= 0 { // '=' must have consistent whitespace on both sides
if number % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if number % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var collatz = [Int]()
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var result = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
result.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return result.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
result.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
result.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = (3 * current) + 1
}
}
return result.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
result.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = (3 * current) + 1
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 != 0 {
sequence.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
return sequence.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 != 0 {
sequence.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
return sequence.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return sequence.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return sequence.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return sequence.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return sequence.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
result.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return result.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
result.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return sequence.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return sequence.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return sequence.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return sequence.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return sequence.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return sequence.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
result.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return result.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [n]
var current = n
while current != 1 {
if current % 2 != 0 {
result.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var number = n
while number!= 1 {
if number % 2 == 0 {
number /= 2
} else {
number = (number * 3) + 1
}
if number % 2!= 0 {
result.append(number)
}
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var number = n
while number!= 1 {
if number % 2 == 0 {
number /= 2
} else {
number = (number * 3) + 1
}
if number % 2!= 0 {
result.append(number)
}
}
return result
}
```
while number!= 1 { // cannot force unwrap value of non-optional type 'Int'
while number!= 1 { // use of '=' in a boolean context, did you mean '=='?
while number!= 1 { // '=' must have consistent whitespace on both sides
if number % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if number % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if number % 2!= 0 { // '=' must have consistent whitespace on both sides
if number % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
if num % 2!= 0 {
arr.append(num)
}
}
return arr
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
if num % 2!= 0 {
arr.append(num)
}
}
return arr
}
// Test
getOddCollatz(n: 5) == [1, 5]
getOddCollatz(n: 10) == [1, 5, 8, 4, 2, 1]
```
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
if num % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if num % 2!= 0 { // '=' must have consistent whitespace on both sides
if num % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if num % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
if num % 2!= 0 {
arr.append(num)
}
}
return arr
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
if num % 2!= 0 {
arr.append(num)
}
}
return arr
}
```
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
if num % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if num % 2!= 0 { // '=' must have consistent whitespace on both sides
if num % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if num % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = (num * 3) + 1
}
if num % 2!= 0 {
result.append(num)
}
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = (num * 3) + 1
}
if num % 2!= 0 {
result.append(num)
}
}
return result
}
```
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
if num % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if num % 2!= 0 { // '=' must have consistent whitespace on both sides
if num % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if num % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
collatz.append(num)
}
return collatz.filter({$0 % 2!= 0}).sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
collatz.append(num)
}
return collatz.filter({$0 % 2!= 0}).sorted()
}
```
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
return collatz.filter({$0 % 2!= 0}).sorted() // cannot force unwrap value of non-optional type 'Int'
return collatz.filter({$0 % 2!= 0}).sorted() // '=' must have consistent whitespace on both sides
return collatz.filter({$0 % 2!= 0}).sorted() // cannot convert value of type '()' to closure result type 'Bool'
return collatz.filter({$0 % 2!= 0}).sorted() // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num > 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = (num * 3) + 1
}
result.append(num)
}
return result.filter({$0 % 2!= 0}).sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num > 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = (num * 3) + 1
}
result.append(num)
}
return result.filter({$0 % 2!= 0}).sorted()
}
// Test
getOddCollatz(n: 5)
```
return result.filter({$0 % 2!= 0}).sorted() // cannot force unwrap value of non-optional type 'Int'
return result.filter({$0 % 2!= 0}).sorted() // expression is not assignable: binary operator returns immutable value
return result.filter({$0 % 2!= 0}).sorted() // '=' must have consistent whitespace on both sides
return result.filter({$0 % 2!= 0}).sorted() // cannot convert value of type '()' to closure result type 'Bool'
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
return result
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
if num % 2 == 1 {
result.append(num)
}
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
if num % 2 == 1 {
result.append(num)
}
}
return result
}
```
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
if num % 2!= 0 {
result.append(num)
}
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
if num % 2!= 0 {
result.append(num)
}
}
return result
}
```
if num % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if num % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if num % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if num % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
arr.append(num)
}
return arr.filter { $0 % 2!= 0 }
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
arr.append(num)
}
return arr.filter { $0 % 2!= 0 }
}
```
return arr.filter { $0 % 2!= 0 } // cannot force unwrap value of non-optional type 'Int'
return arr.filter { $0 % 2!= 0 } // expression is not assignable: binary operator returns immutable value
return arr.filter { $0 % 2!= 0 } // cannot convert value of type '()' to closure result type 'Bool'
return arr.filter { $0 % 2!= 0 } // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
if result.contains(num) {
break
}
result.append(num)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
if result.contains(num) {
break
}
result.append(num)
}
return result
}
```
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
if result.contains(num) {
break
}
result.append(num)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
if result.contains(num) {
break
}
result.append(num)
}
return result
}
```
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
if result.contains(num) {
break
}
result.append(num)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
if result.contains(num) {
break
}
result.append(num)
}
return result
}
```
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
if result.contains(num) {
break
}
result.append(num)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
if result.contains(num) {
break
}
result.append(num)
}
return result
}
```
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
result.append(num)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
result.append(num)
}
return result
}
```
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
if num % 2!= 0 {
result.append(num)
}
}
return result.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
if num % 2!= 0 {
result.append(num)
}
}
return result.sorted()
}
```
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
if num % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if num % 2!= 0 { // '=' must have consistent whitespace on both sides
if num % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if num % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
if num % 2!= 0 {
result.append(num)
}
}
return result.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
if num % 2!= 0 {
result.append(num)
}
}
return result.sorted()
}
```
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
if num % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if num % 2!= 0 { // '=' must have consistent whitespace on both sides
if num % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if num % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
if num % 2 == 1 {
result.append(num)
}
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
if num % 2 == 1 {
result.append(num)
}
}
return result
}
```
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
if num % 2 == 1 {
result.append(num)
}
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
if num % 2 == 1 {
result.append(num)
}
}
return result
}
```
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = num * 3 + 1
}
result.append(num)
}
return result.filter { $0 % 2 == 1 }.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = num * 3 + 1
}
result.append(num)
}
return result.filter { $0 % 2 == 1 }.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = num * 3 + 1
}
if num % 2!= 0 {
result.append(num)
}
}
result.append(1)
return result.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = num * 3 + 1
}
if num % 2!= 0 {
result.append(num)
}
}
result.append(1)
return result.sorted()
}
```
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
if num % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if num % 2!= 0 { // '=' must have consistent whitespace on both sides
if num % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if num % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
if current % 2!= 0 {
result.append(current)
}
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
if current % 2!= 0 {
result.append(current)
}
}
return result
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var n = n
while n!= 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
if n % 2!= 0 {
result.append(n)
}
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var n = n
while n!= 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
if n % 2!= 0 {
result.append(n)
}
}
return result
}
```
while n!= 1 { // use of '=' in a boolean context, did you mean '=='?
while n!= 1 { // cannot force unwrap value of non-optional type 'Int'
while n!= 1 { // '=' must have consistent whitespace on both sides
if n % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if n % 2!= 0 { // '=' must have consistent whitespace on both sides
if n % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if n % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
func getOddCollatz(n: Int) -> [Int] {
var collatz = [n]
var i = n
while i!= 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
collatz.append(i)
}
return collatz.filter { $0 % 2!= 0 }.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [n]
var i = n
while i!= 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
collatz.append(i)
}
return collatz.filter { $0 % 2!= 0 }.sorted()
}
```
while i!= 1 { // '=' must have consistent whitespace on both sides
while i!= 1 { // use of '=' in a boolean context, did you mean '=='?
while i!= 1 { // cannot force unwrap value of non-optional type 'Int'
return collatz.filter { $0 % 2!= 0 }.sorted() // cannot force unwrap value of non-optional type 'Int'
return collatz.filter { $0 % 2!= 0 }.sorted() // '=' must have consistent whitespace on both sides
return collatz.filter { $0 % 2!= 0 }.sorted() // cannot convert value of type '()' to closure result type 'Bool'
return collatz.filter { $0 % 2!= 0 }.sorted() // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
if current % 2!= 0 {
result.append(current)
}
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
if current % 2!= 0 {
result.append(current)
}
}
return result
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
result.append(current)
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
}
result.append(1)
return result.filter { $0 % 2!= 0 }.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
result.append(current)
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
}
result.append(1)
return result.filter { $0 % 2!= 0 }.sorted()
}
```
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
return result.filter { $0 % 2!= 0 }.sorted() // '=' must have consistent whitespace on both sides
return result.filter { $0 % 2!= 0 }.sorted() // cannot convert value of type '()' to closure result type 'Bool'
return result.filter { $0 % 2!= 0 }.sorted() // cannot force unwrap value of non-optional type 'Int'
return result.filter { $0 % 2!= 0 }.sorted() // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var n = n
while n!= 1 {
if n % 2 == 0 {
n = n / 2
} else {
n = 3 * n + 1
}
if n % 2!= 0 {
collatz.append(n)
}
}
collatz.append(1)
return collatz
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var n = n
while n!= 1 {
if n % 2 == 0 {
n = n / 2
} else {
n = 3 * n + 1
}
if n % 2!= 0 {
collatz.append(n)
}
}
collatz.append(1)
return collatz
}
```
while n!= 1 { // use of '=' in a boolean context, did you mean '=='?
while n!= 1 { // cannot force unwrap value of non-optional type 'Int'
while n!= 1 { // '=' must have consistent whitespace on both sides
if n % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if n % 2!= 0 { // '=' must have consistent whitespace on both sides
if n % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if n % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
result.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
}
result.append(1)
return result.filter { $0 % 2!= 0 }.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
result.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
}
result.append(1)
return result.filter { $0 % 2!= 0 }.sorted()
}
```
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
return result.filter { $0 % 2!= 0 }.sorted() // '=' must have consistent whitespace on both sides
return result.filter { $0 % 2!= 0 }.sorted() // cannot convert value of type '()' to closure result type 'Bool'
return result.filter { $0 % 2!= 0 }.sorted() // cannot force unwrap value of non-optional type 'Int'
return result.filter { $0 % 2!= 0 }.sorted() // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
if num % 2!= 0 {
result.append(num)
}
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
if num % 2!= 0 {
result.append(num)
}
}
return result
}
```
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
if num % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if num % 2!= 0 { // '=' must have consistent whitespace on both sides
if num % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if num % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = num * 3 + 1
}
if num % 2!= 0 {
result.append(num)
}
}
result.append(1)
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = num * 3 + 1
}
if num % 2!= 0 {
result.append(num)
}
}
result.append(1)
return result
}
```
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
if num % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if num % 2!= 0 { // '=' must have consistent whitespace on both sides
if num % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if num % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var i = n
while i!= 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
if i % 2 == 1 {
arr.append(i)
}
}
return arr
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var i = n
while i!= 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
if i % 2 == 1 {
arr.append(i)
}
}
return arr
}
```
while i!= 1 { // use of '=' in a boolean context, did you mean '=='?
while i!= 1 { // cannot force unwrap value of non-optional type 'Int'
while i!= 1 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
collatz.append(current)
}
}
return collatz
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
collatz.append(current)
}
}
return collatz
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
collatz.append(current)
}
}
collatz.append(1)
return collatz.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
collatz.append(current)
}
}
collatz.append(1)
return collatz.sorted()
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
collatz.append(current)
}
}
return collatz
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
collatz.append(current)
}
}
return collatz
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
collatz.append(current)
}
}
collatz.append(current)
return collatz.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
collatz.append(current)
}
}
collatz.append(current)
return collatz.sorted()
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
collatz.append(current)
}
}
return collatz
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
collatz.append(current)
}
}
return collatz
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
collatz.append(current)
}
}
return collatz
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
collatz.append(current)
}
}
return collatz
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
collatz.append(current)
}
}
collatz.append(current)
return collatz.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
collatz.append(current)
}
}
collatz.append(current)
return collatz.sorted()
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
collatz.append(current)
}
}
return collatz
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
collatz.append(current)
}
}
return collatz
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var i = n
while i!= 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
collatz.append(i)
}
collatz.append(1)
return collatz.filter { $0 % 2!= 0 }
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var i = n
while i!= 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
collatz.append(i)
}
collatz.append(1)
return collatz.filter { $0 % 2!= 0 }
}
```
while i!= 1 { // '=' must have consistent whitespace on both sides
while i!= 1 { // use of '=' in a boolean context, did you mean '=='?
while i!= 1 { // cannot force unwrap value of non-optional type 'Int'
return collatz.filter { $0 % 2!= 0 } // cannot force unwrap value of non-optional type 'Int'
return collatz.filter { $0 % 2!= 0 } // cannot convert value of type '()' to closure result type 'Bool'
return collatz.filter { $0 % 2!= 0 } // '=' must have consistent whitespace on both sides
return collatz.filter { $0 % 2!= 0 } // expression is not assignable: binary operator returns immutable value
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var num = n
while num!= 1 {
if num % 2!= 0 {
sequence.append(num)
}
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
}
sequence.append(1)
return sequence.sorted()
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var num = n
while num!= 1 {
if num % 2!= 0 {
sequence.append(num)
}
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
}
sequence.append(1)
return sequence.sorted()
}
```
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
if num % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if num % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if num % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if num % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var currentNumber = n
while currentNumber!= 1 {
if currentNumber % 2!= 0 {
collatz.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
collatz.append(1)
collatz.sort()
return collatz
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var currentNumber = n
while currentNumber!= 1 {
if currentNumber % 2!= 0 {
collatz.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
collatz.append(1)
collatz.sort()
return collatz
}
```
while currentNumber!= 1 { // '=' must have consistent whitespace on both sides
while currentNumber!= 1 { // use of '=' in a boolean context, did you mean '=='?
while currentNumber!= 1 { // cannot force unwrap value of non-optional type 'Int'
if currentNumber % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if currentNumber % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if currentNumber % 2!= 0 { // '=' must have consistent whitespace on both sides
if currentNumber % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var currentNumber = n
while currentNumber!= 1 {
if currentNumber % 2!= 0 {
sequence.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
sequence.append(1)
return sequence.sorted()
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var currentNumber = n
while currentNumber!= 1 {
if currentNumber % 2!= 0 {
sequence.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
sequence.append(1)
return sequence.sorted()
}
```
while currentNumber!= 1 { // '=' must have consistent whitespace on both sides
while currentNumber!= 1 { // use of '=' in a boolean context, did you mean '=='?
while currentNumber!= 1 { // cannot force unwrap value of non-optional type 'Int'
if currentNumber % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if currentNumber % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if currentNumber % 2!= 0 { // '=' must have consistent whitespace on both sides
if currentNumber % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2!= 0 {
collatz.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
collatz.append(1)
collatz.sort()
return collatz
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2!= 0 {
collatz.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
collatz.append(1)
collatz.sort()
return collatz
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2!= 0 {
collatz.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
collatz.append(1)
collatz.sort()
return collatz
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2!= 0 {
collatz.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
collatz.append(1)
collatz.sort()
return collatz
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var currentNumber = n
while currentNumber!= 1 {
if currentNumber % 2!= 0 {
collatz.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
collatz.append(1)
collatz.sort()
return collatz
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var currentNumber = n
while currentNumber!= 1 {
if currentNumber % 2!= 0 {
collatz.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
collatz.append(1)
collatz.sort()
return collatz
}
```
while currentNumber!= 1 { // '=' must have consistent whitespace on both sides
while currentNumber!= 1 { // use of '=' in a boolean context, did you mean '=='?
while currentNumber!= 1 { // cannot force unwrap value of non-optional type 'Int'
if currentNumber % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if currentNumber % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if currentNumber % 2!= 0 { // '=' must have consistent whitespace on both sides
if currentNumber % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2!= 0 {
collatz.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
collatz.append(1)
collatz.sort()
return collatz
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current!= 1 {
if current % 2!= 0 {
collatz.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
collatz.append(1)
collatz.sort()
return collatz
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
if current % 2!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var currentNumber = n
var collatzSequence: [Int] = []
while currentNumber!= 1 {
if currentNumber % 2!= 0 {
collatzSequence.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
collatzSequence.append(1)
return collatzSequence.sorted()
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var currentNumber = n
var collatzSequence: [Int] = []
while currentNumber!= 1 {
if currentNumber % 2!= 0 {
collatzSequence.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
collatzSequence.append(1)
return collatzSequence.sorted()
}
```
while currentNumber!= 1 { // '=' must have consistent whitespace on both sides
while currentNumber!= 1 { // use of '=' in a boolean context, did you mean '=='?
while currentNumber!= 1 { // cannot force unwrap value of non-optional type 'Int'
if currentNumber % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if currentNumber % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if currentNumber % 2!= 0 { // '=' must have consistent whitespace on both sides
if currentNumber % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var currentNumber = n
var collatzSequence: [Int] = []
while currentNumber!= 1 {
if currentNumber % 2!= 0 {
collatzSequence.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
collatzSequence.append(1)
return collatzSequence.sorted()
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var currentNumber = n
var collatzSequence: [Int] = []
while currentNumber!= 1 {
if currentNumber % 2!= 0 {
collatzSequence.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
collatzSequence.append(1)
return collatzSequence.sorted()
}
```
while currentNumber!= 1 { // '=' must have consistent whitespace on both sides
while currentNumber!= 1 { // use of '=' in a boolean context, did you mean '=='?
while currentNumber!= 1 { // cannot force unwrap value of non-optional type 'Int'
if currentNumber % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if currentNumber % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if currentNumber % 2!= 0 { // '=' must have consistent whitespace on both sides
if currentNumber % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var currentNumber = n
while currentNumber!= 1 {
if currentNumber % 2!= 0 {
collatz.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
collatz.append(1)
collatz.sort()
return collatz
}
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]<|im_end|>
<|im_start|>assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var currentNumber = n
while currentNumber!= 1 {
if currentNumber % 2!= 0 {
collatz.append(currentNumber)
}
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
}
collatz.append(1)
collatz.sort()
return collatz
}
```
while currentNumber!= 1 { // '=' must have consistent whitespace on both sides
while currentNumber!= 1 { // use of '=' in a boolean context, did you mean '=='?
while currentNumber!= 1 { // cannot force unwrap value of non-optional type 'Int'
if currentNumber % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if currentNumber % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if currentNumber % 2!= 0 { // '=' must have consistent whitespace on both sides
if currentNumber % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 1 {
result.append(current)
}
current = collatz(current)
}
result.append(1)
return result.sorted()
}
func collatz(_ n: Int) -> Int {
if n % 2 == 0 {
return n / 2
} else {
return 3 * n + 1
}
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 1 {
result.append(current)
}
current = collatz(current)
}
result.append(1)
return result.sorted()
}
func collatz(_ n: Int) -> Int {
if n % 2 == 0 {
return n / 2
} else {
return 3 * n + 1
}
}
// Example usage:
print(getOddCollatz(5)) // Output: [1, 5]
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
while collatzSequence.last != 1 {
let lastNumber = collatzSequence.last!
if lastNumber % 2 == 0 {
collatzSequence.append(lastNumber / 2)
} else {
collatzSequence.append(lastNumber * 3 + 1)
}
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
while collatzSequence.last != 1 {
let lastNumber = collatzSequence.last!
if lastNumber % 2 == 0 {
collatzSequence.append(lastNumber / 2)
} else {
collatzSequence.append(lastNumber * 3 + 1)
}
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
// Example usage:
print(getOddCollatz(n: 5)) // Output: [1, 5]
print(getOddCollatz(n: 6)) // Output: [1, 3, 5]
print(getOddCollatz(n: 7)) // Output: [1, 7]
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
while collatzSequence.last != 1 {
let lastNumber = collatzSequence.last!
if lastNumber % 2 == 0 {
collatzSequence.append(lastNumber / 2)
} else {
collatzSequence.append((lastNumber * 3) + 1)
}
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
while collatzSequence.last != 1 {
let lastNumber = collatzSequence.last!
if lastNumber % 2 == 0 {
collatzSequence.append(lastNumber / 2)
} else {
collatzSequence.append((lastNumber * 3) + 1)
}
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while sequence.last != 1 {
let last = sequence.last!
if last % 2 == 0 {
sequence.append(last / 2)
} else {
sequence.append((last * 3) + 1)
}
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while sequence.last != 1 {
let last = sequence.last!
if last % 2 == 0 {
sequence.append(last / 2)
} else {
sequence.append((last * 3) + 1)
}
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
// Example usage:
print(getOddCollatz(n: 5)) // Output: [1, 5]
```
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 1 {
result.append(current)
}
current = collatz(current)
}
result.append(1)
return result.sorted()
}
func collatz(_ n: Int) -> Int {
if n % 2 == 0 {
return n / 2
} else {
return 3 * n + 1
}
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 1 {
result.append(current)
}
current = collatz(current)
}
result.append(1)
return result.sorted()
}
func collatz(_ n: Int) -> Int {
if n % 2 == 0 {
return n / 2
} else {
return 3 * n + 1
}
}
// Example usage:
print(getOddCollatz(5)) // Output: [1, 5]
print(getOddCollatz(6)) // Output: [1]
print(getOddCollatz(7)) // Output: [1, 7]
```
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
result.append(current)
}
current = collatzStep(current)
}
result.append(1)
return result.sorted()
}
func collatzStep(n: Int) -> Int {
if n % 2 == 0 {
return n / 2
} else {
return 3 * n + 1
}
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
result.append(current)
}
current = collatzStep(current)
}
result.append(1)
return result.sorted()
}
func collatzStep(n: Int) -> Int {
if n % 2 == 0 {
return n / 2
} else {
return 3 * n + 1
}
}
// Example usage:
print(getOddCollatz(5)) // Output: [1, 5]
print(getOddCollatz(6)) // Output: [1]
print(getOddCollatz(7)) // Output: [1, 7]
```
current = collatzStep(current) // missing argument label 'n:' in call
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 1 {
result.append(current)
}
current = collatz(current)
}
result.append(1)
return result.sorted()
}
func collatz(_ n: Int) -> Int {
if n % 2 == 0 {
return n / 2
} else {
return 3 * n + 1
}
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 1 {
result.append(current)
}
current = collatz(current)
}
result.append(1)
return result.sorted()
}
func collatz(_ n: Int) -> Int {
if n % 2 == 0 {
return n / 2
} else {
return 3 * n + 1
}
}
// Example usage:
print(getOddCollatz(5)) // Output: [1, 5]
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
while collatzSequence.last != 1 {
let last = collatzSequence.last!
if last % 2 == 0 {
collatzSequence.append(last / 2)
} else {
collatzSequence.append(last * 3 + 1)
}
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
while collatzSequence.last != 1 {
let last = collatzSequence.last!
if last % 2 == 0 {
collatzSequence.append(last / 2)
} else {
collatzSequence.append(last * 3 + 1)
}
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
while collatzSequence.last != 1 {
let lastNumber = collatzSequence.last!
if lastNumber % 2 == 0 {
collatzSequence.append(lastNumber / 2)
} else {
collatzSequence.append(lastNumber * 3 + 1)
}
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
while collatzSequence.last != 1 {
let lastNumber = collatzSequence.last!
if lastNumber % 2 == 0 {
collatzSequence.append(lastNumber / 2)
} else {
collatzSequence.append(lastNumber * 3 + 1)
}
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
// Example usage:
print(getOddCollatz(n: 5)) // Output: [1, 5]
print(getOddCollatz(n: 10)) // Output: [1, 3, 5, 7, 9]
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
while collatzSequence.last != 1 {
let last = collatzSequence.last!
if last % 2 == 0 {
collatzSequence.append(last / 2)
} else {
collatzSequence.append(3 * last + 1)
}
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
while collatzSequence.last != 1 {
let last = collatzSequence.last!
if last % 2 == 0 {
collatzSequence.append(last / 2)
} else {
collatzSequence.append(3 * last + 1)
}
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
sequence.append(n)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
sequence.append(n)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
n /= 2 // left side of mutating operator isn't mutable: 'n' is a 'let' constant
n = 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
sequence.append(n)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
sequence.append(n)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
n /= 2 // left side of mutating operator isn't mutable: 'n' is a 'let' constant
n = 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatz = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
collatz.append(current)
}
return collatz.filter { $0 % 2 != 0 }.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
collatz.append(current)
}
return collatz.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 != 0 {
collatzSequence.append(currentNumber)
}
currentNumber = currentNumber % 2 == 0 ? currentNumber / 2 : currentNumber * 3 + 1
}
collatzSequence.append(1)
return collatzSequence.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 != 0 {
collatzSequence.append(currentNumber)
}
currentNumber = currentNumber % 2 == 0 ? currentNumber / 2 : currentNumber * 3 + 1
}
collatzSequence.append(1)
return collatzSequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
collatzSequence.append(currentNumber)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = 3 * currentNumber + 1
}
collatzSequence.append(currentNumber)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
}
collatz.append(1)
return collatz.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
collatz.append(num)
num = 3 * num + 1
}
}
collatz.append(1)
return collatz.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
collatz.append(num)
num = 3 * num + 1
}
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
collatz.append(current)
}
current = current % 2 == 0 ? current / 2 : current * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
collatz.append(current)
}
current = current % 2 == 0 ? current / 2 : current * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 != 0 {
collatzSequence.append(currentNumber)
}
currentNumber = currentNumber % 2 == 0 ? currentNumber / 2 : currentNumber * 3 + 1
}
collatzSequence.append(1)
return collatzSequence.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 != 0 {
collatzSequence.append(currentNumber)
}
currentNumber = currentNumber % 2 == 0 ? currentNumber / 2 : currentNumber * 3 + 1
}
collatzSequence.append(1)
return collatzSequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
arr.append(num)
}
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
}
arr.append(1)
return arr.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
arr.append(num)
}
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
}
arr.append(1)
return arr.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
collatz.append(current)
}
current = current % 2 == 0 ? current / 2 : current * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
collatz.append(current)
}
current = current % 2 == 0 ? current / 2 : current * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : current * 3 + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : current * 3 + 1
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
current = current % 2 == 0? current / 2 : current * 3 + 1 // result of operator '/' is unused
current = current % 2 == 0? current / 2 : current * 3 + 1 // cannot use optional chaining on non-optional value of type 'Int'
current = current % 2 == 0? current / 2 : current * 3 + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : current * 3 + 1 // expected expression
current = current % 2 == 0? current / 2 : current * 3 + 1 // cannot assign value of type 'Bool' to type 'Int'
current = current % 2 == 0? current / 2 : current * 3 + 1 // consecutive statements on a line must be separated by ';'
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 1 {
result.append(num)
}
num = num % 2 == 0? num / 2 : 3 * num + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 1 {
result.append(num)
}
num = num % 2 == 0? num / 2 : 3 * num + 1
}
result.append(1)
return result.sorted()
}
```
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
num = num % 2 == 0? num / 2 : 3 * num + 1 // cannot use optional chaining on non-optional value of type 'Int'
num = num % 2 == 0? num / 2 : 3 * num + 1 // result of operator '/' is unused
num = num % 2 == 0? num / 2 : 3 * num + 1 // consecutive statements on a line must be separated by ';'
num = num % 2 == 0? num / 2 : 3 * num + 1 // expected expression
num = num % 2 == 0? num / 2 : 3 * num + 1 // cannot assign value of type 'Bool' to type 'Int'
num = num % 2 == 0? num / 2 : 3 * num + 1 // consecutive statements on a line must be separated by ';'
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num!= 1 {
if num % 2 == 1 {
result.append(num)
}
num = num % 2 == 0? num / 2 : 3 * num + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num!= 1 {
if num % 2 == 1 {
result.append(num)
}
num = num % 2 == 0? num / 2 : 3 * num + 1
}
result.append(1)
return result.sorted()
}
```
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
num = num % 2 == 0? num / 2 : 3 * num + 1 // cannot use optional chaining on non-optional value of type 'Int'
num = num % 2 == 0? num / 2 : 3 * num + 1 // result of operator '/' is unused
num = num % 2 == 0? num / 2 : 3 * num + 1 // consecutive statements on a line must be separated by ';'
num = num % 2 == 0? num / 2 : 3 * num + 1 // expected expression
num = num % 2 == 0? num / 2 : 3 * num + 1 // cannot assign value of type 'Bool' to type 'Int'
num = num % 2 == 0? num / 2 : 3 * num + 1 // consecutive statements on a line must be separated by ';'
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : 3 * current + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : 3 * current + 1
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot assign value of type 'Bool' to type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // result of operator '/' is unused
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot use optional chaining on non-optional value of type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // expected expression
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : 3 * current + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : 3 * current + 1
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot assign value of type 'Bool' to type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // result of operator '/' is unused
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot use optional chaining on non-optional value of type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // expected expression
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : current * 3 + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : current * 3 + 1
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
current = current % 2 == 0? current / 2 : current * 3 + 1 // result of operator '/' is unused
current = current % 2 == 0? current / 2 : current * 3 + 1 // cannot use optional chaining on non-optional value of type 'Int'
current = current % 2 == 0? current / 2 : current * 3 + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : current * 3 + 1 // expected expression
current = current % 2 == 0? current / 2 : current * 3 + 1 // cannot assign value of type 'Bool' to type 'Int'
current = current % 2 == 0? current / 2 : current * 3 + 1 // consecutive statements on a line must be separated by ';'
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : 3 * current + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : 3 * current + 1
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot assign value of type 'Bool' to type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // result of operator '/' is unused
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot use optional chaining on non-optional value of type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // expected expression
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num!= 1 {
if num % 2 == 1 {
result.append(num)
}
num = num % 2 == 0? num / 2 : num * 3 + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num!= 1 {
if num % 2 == 1 {
result.append(num)
}
num = num % 2 == 0? num / 2 : num * 3 + 1
}
result.append(1)
return result.sorted()
}
```
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
num = num % 2 == 0? num / 2 : num * 3 + 1 // consecutive statements on a line must be separated by ';'
num = num % 2 == 0? num / 2 : num * 3 + 1 // cannot use optional chaining on non-optional value of type 'Int'
num = num % 2 == 0? num / 2 : num * 3 + 1 // result of operator '/' is unused
num = num % 2 == 0? num / 2 : num * 3 + 1 // cannot assign value of type 'Bool' to type 'Int'
num = num % 2 == 0? num / 2 : num * 3 + 1 // expected expression
num = num % 2 == 0? num / 2 : num * 3 + 1 // consecutive statements on a line must be separated by ';'
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : current * 3 + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : current * 3 + 1
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
current = current % 2 == 0? current / 2 : current * 3 + 1 // result of operator '/' is unused
current = current % 2 == 0? current / 2 : current * 3 + 1 // cannot use optional chaining on non-optional value of type 'Int'
current = current % 2 == 0? current / 2 : current * 3 + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : current * 3 + 1 // expected expression
current = current % 2 == 0? current / 2 : current * 3 + 1 // cannot assign value of type 'Bool' to type 'Int'
current = current % 2 == 0? current / 2 : current * 3 + 1 // consecutive statements on a line must be separated by ';'
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : 3 * current + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : 3 * current + 1
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot assign value of type 'Bool' to type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // result of operator '/' is unused
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot use optional chaining on non-optional value of type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // expected expression
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 0 {
number /= 2
} else {
number = (3 * number) + 1
}
if number % 2!= 0 {
result.append(number)
}
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 0 {
number /= 2
} else {
number = (3 * number) + 1
}
if number % 2!= 0 {
result.append(number)
}
}
result.append(1)
return result.sorted()
}
```
while number!= 1 { // cannot force unwrap value of non-optional type 'Int'
while number!= 1 { // use of '=' in a boolean context, did you mean '=='?
while number!= 1 { // '=' must have consistent whitespace on both sides
if number % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if number % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if number % 2!= 0 { // '=' must have consistent whitespace on both sides
if number % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
if number % 2!= 0 {
result.append(number)
}
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
if number % 2!= 0 {
result.append(number)
}
}
result.append(1)
return result.sorted()
}
```
while number!= 1 { // cannot force unwrap value of non-optional type 'Int'
while number!= 1 { // use of '=' in a boolean context, did you mean '=='?
while number!= 1 { // '=' must have consistent whitespace on both sides
if number % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if number % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if number % 2!= 0 { // '=' must have consistent whitespace on both sides
if number % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var number = n
while number!= 1 {
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
if number % 2!= 0 {
result.append(number)
}
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var number = n
while number!= 1 {
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
if number % 2!= 0 {
result.append(number)
}
}
result.append(1)
return result.sorted()
}
```
while number!= 1 { // cannot force unwrap value of non-optional type 'Int'
while number!= 1 { // use of '=' in a boolean context, did you mean '=='?
while number!= 1 { // '=' must have consistent whitespace on both sides
if number % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if number % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if number % 2!= 0 { // '=' must have consistent whitespace on both sides
if number % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
if num % 2 == 1 {
result.append(num)
}
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
if num % 2 == 1 {
result.append(num)
}
}
result.append(1)
return result.sorted()
}
```
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
if number % 2!= 0 {
result.append(number)
}
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
if number % 2!= 0 {
result.append(number)
}
}
result.append(1)
return result.sorted()
}
```
while number!= 1 { // cannot force unwrap value of non-optional type 'Int'
while number!= 1 { // use of '=' in a boolean context, did you mean '=='?
while number!= 1 { // '=' must have consistent whitespace on both sides
if number % 2!= 0 { // expression is not assignable: binary operator returns immutable value
if number % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?
if number % 2!= 0 { // '=' must have consistent whitespace on both sides
if number % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 1 {
result.append(number)
}
number = number % 2 == 0? number / 2 : 3 * number + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 1 {
result.append(number)
}
number = number % 2 == 0? number / 2 : 3 * number + 1
}
result.append(1)
return result.sorted()
}
```
while number!= 1 { // cannot force unwrap value of non-optional type 'Int'
while number!= 1 { // use of '=' in a boolean context, did you mean '=='?
while number!= 1 { // '=' must have consistent whitespace on both sides
number = number % 2 == 0? number / 2 : 3 * number + 1 // consecutive statements on a line must be separated by ';'
number = number % 2 == 0? number / 2 : 3 * number + 1 // consecutive statements on a line must be separated by ';'
number = number % 2 == 0? number / 2 : 3 * number + 1 // cannot assign value of type 'Bool' to type 'Int'
number = number % 2 == 0? number / 2 : 3 * number + 1 // expected expression
number = number % 2 == 0? number / 2 : 3 * number + 1 // cannot use optional chaining on non-optional value of type 'Int'
number = number % 2 == 0? number / 2 : 3 * number + 1 // result of operator '/' is unused
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : 3 * current + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : 3 * current + 1
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // '=' must have consistent whitespace on both sides
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot assign value of type 'Bool' to type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // result of operator '/' is unused
current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'
current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot use optional chaining on non-optional value of type 'Int'
current = current % 2 == 0? current / 2 : 3 * current + 1 // expected expression
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 1 {
result.append(number)
}
number = number % 2 == 0? number / 2 : 3 * number + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 1 {
result.append(number)
}
number = number % 2 == 0? number / 2 : 3 * number + 1
}
result.append(1)
return result.sorted()
}
```
while number!= 1 { // cannot force unwrap value of non-optional type 'Int'
while number!= 1 { // use of '=' in a boolean context, did you mean '=='?
while number!= 1 { // '=' must have consistent whitespace on both sides
number = number % 2 == 0? number / 2 : 3 * number + 1 // consecutive statements on a line must be separated by ';'
number = number % 2 == 0? number / 2 : 3 * number + 1 // consecutive statements on a line must be separated by ';'
number = number % 2 == 0? number / 2 : 3 * number + 1 // cannot assign value of type 'Bool' to type 'Int'
number = number % 2 == 0? number / 2 : 3 * number + 1 // expected expression
number = number % 2 == 0? number / 2 : 3 * number + 1 // cannot use optional chaining on non-optional value of type 'Int'
number = number % 2 == 0? number / 2 : 3 * number + 1 // result of operator '/' is unused
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 1 {
result.append(number)
}
number = number % 2 == 0? number / 2 : 3 * number + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 1 {
result.append(number)
}
number = number % 2 == 0? number / 2 : 3 * number + 1
}
result.append(1)
return result.sorted()
}
```
while number!= 1 { // cannot force unwrap value of non-optional type 'Int'
while number!= 1 { // use of '=' in a boolean context, did you mean '=='?
while number!= 1 { // '=' must have consistent whitespace on both sides
number = number % 2 == 0? number / 2 : 3 * number + 1 // consecutive statements on a line must be separated by ';'
number = number % 2 == 0? number / 2 : 3 * number + 1 // consecutive statements on a line must be separated by ';'
number = number % 2 == 0? number / 2 : 3 * number + 1 // cannot assign value of type 'Bool' to type 'Int'
number = number % 2 == 0? number / 2 : 3 * number + 1 // expected expression
number = number % 2 == 0? number / 2 : 3 * number + 1 // cannot use optional chaining on non-optional value of type 'Int'
number = number % 2 == 0? number / 2 : 3 * number + 1 // result of operator '/' is unused
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 1 {
result.append(num)
}
num = num % 2 == 0? num / 2 : num * 3 + 1
}
result.append(1)
return result.sorted()
}
Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 1 {
result.append(num)
}
num = num % 2 == 0? num / 2 : num * 3 + 1
}
result.append(1)
return result.sorted()
}
```
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
num = num % 2 == 0? num / 2 : num * 3 + 1 // consecutive statements on a line must be separated by ';'
num = num % 2 == 0? num / 2 : num * 3 + 1 // cannot use optional chaining on non-optional value of type 'Int'
num = num % 2 == 0? num / 2 : num * 3 + 1 // result of operator '/' is unused
num = num % 2 == 0? num / 2 : num * 3 + 1 // cannot assign value of type 'Bool' to type 'Int'
num = num % 2 == 0? num / 2 : num * 3 + 1 // expected expression
num = num % 2 == 0? num / 2 : num * 3 + 1 // consecutive statements on a line must be separated by ';'
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
collatzSequence.append(currentNumber)
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
}
collatzSequence.append(1)
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
collatzSequence.append(currentNumber)
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
}
collatzSequence.append(1)
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
collatzSequence.append(currentNumber)
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
}
collatzSequence.append(1)
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
collatzSequence.append(currentNumber)
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
}
collatzSequence.append(1)
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var number = n
while number != 1 {
if number % 2 != 0 {
result.append(number)
}
if number % 2 == 0 {
number = number / 2
} else {
number = number * 3 + 1
}
}
result.append(1)
return result.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var number = n
while number != 1 {
if number % 2 != 0 {
result.append(number)
}
if number % 2 == 0 {
number = number / 2
} else {
number = number * 3 + 1
}
}
result.append(1)
return result.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 != 0 {
result.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
result.append(1)
return result.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 != 0 {
result.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
result.append(1)
return result.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
if currentNumber % 2 != 0 {
collatzSequence.append(currentNumber)
}
}
collatzSequence.append(1)
return collatzSequence.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
if currentNumber % 2 != 0 {
collatzSequence.append(currentNumber)
}
}
collatzSequence.append(1)
return collatzSequence.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
collatzSequence.append(currentNumber)
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
}
collatzSequence.append(1)
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
collatzSequence.append(currentNumber)
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
}
collatzSequence.append(1)
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
collatzSequence.append(currentNumber)
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
}
collatzSequence.append(1)
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
collatzSequence.append(currentNumber)
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
}
collatzSequence.append(1)
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
collatzSequence.append(currentNumber)
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
}
collatzSequence.append(1)
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
collatzSequence.append(currentNumber)
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
}
collatzSequence.append(1)
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
collatzSequence.append(currentNumber)
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
}
collatzSequence.append(1)
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
collatzSequence.append(currentNumber)
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
}
collatzSequence.append(1)
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
collatzSequence.append(currentNumber)
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
}
collatzSequence.append(1)
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
You are an AI programming assistant, utilizing the Deepseek Coder model, developed by Deepseek Company, and you only answer questions related to computer science. For politically sensitive questions, security and privacy issues, and other non-computer science questions, you will refuse to answer
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [Int]()
var currentNumber = n
while currentNumber != 1 {
collatzSequence.append(currentNumber)
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
}
collatzSequence.append(1)
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var result = Set<Int>()
var current = n
while current != 1 {
if current % 2 != 0 {
result.insert(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
result.insert(1)
return result.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5][/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var result = Set<Int>()
var current = n
while current != 1 {
if current % 2 != 0 {
result.insert(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
result.insert(1)
return result.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5][/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5][/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
current = current % 2 == 0 ? current / 2 : 3 * current + 1
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5][/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
current = current % 2 == 0 ? current / 2 : 3 * current + 1
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
current = current % 2 == 0 ? current / 2 : 3 * current + 1
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5][/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
current = current % 2 == 0 ? current / 2 : 3 * current + 1
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5][/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5][/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5][/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5][/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
current = current % 2 == 0 ? current / 2 : 3 * current + 1
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
[INST] Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5][/INST] ```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
current = current % 2 == 0 ? current / 2 : 3 * current + 1
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
sequence.append(n)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
sequence.append(n)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
n /= 2 // left side of mutating operator isn't mutable: 'n' is a 'let' constant
n = 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
sequence.append(n)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
sequence.append(n)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
n /= 2 // left side of mutating operator isn't mutable: 'n' is a 'let' constant
n = 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
sequence.append(1)
return sequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
system
You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
sequence.append(current)
}
}
return sequence.filter { $0 % 2 != 0 }.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
collatz.append(current)
}
}
return collatz.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
collatz.append(current)
}
}
return collatz.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
if num % 2 == 1 {
collatz.append(num)
}
}
return collatz.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
if num % 2 == 1 {
collatz.append(num)
}
}
return collatz.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var num = n
var sequence = [Int]()
while num != 1 {
if num % 2 != 0 {
sequence.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
sequence.append(1)
sequence.sort()
return sequence
}
Here is the Swift code that implements the Collatz sequence and returns the odd numbers in the sequence in increasing order:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var sequence = [Int]()
while num != 1 {
if num % 2 != 0 {
sequence.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
sequence.append(1)
sequence.sort()
return sequence
}
func getOddCollatz(n: Int) -> [Int] {
var num = n
var sequence = [Int]()
while num != 1 {
if num % 2 != 0 {
sequence.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
sequence.append(1)
return sequence.sorted()
}
Here is the Swift code for the problem:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var sequence = [Int]()
while num != 1 {
if num % 2 != 0 {
sequence.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
sequence.append(1)
return sequence.sorted()
}
func getOddCollatz(n: Int) -> [Int] {
var num = n
var sequence = [Int]()
while num != 1 {
if num % 2 != 0 {
sequence.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
sequence.append(1)
return sequence.sorted()
}
Here is the Swift code for the problem:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var sequence = [Int]()
while num != 1 {
if num % 2 != 0 {
sequence.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
sequence.append(1)
return sequence.sorted()
}
func getOddCollatz(n: Int) -> [Int] {
var num = n
var oddNumbers = [Int]()
while num != 1 {
if num % 2 != 0 {
oddNumbers.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
oddNumbers.append(1)
oddNumbers.sort()
return oddNumbers
}
Here is the Swift code that implements the Collatz sequence and returns the odd numbers in the sequence in increasing order:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var oddNumbers = [Int]()
while num != 1 {
if num % 2 != 0 {
oddNumbers.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
oddNumbers.append(1)
oddNumbers.sort()
return oddNumbers
}
func getOddCollatz(n: Int) -> [Int] {
var num = n
var sequence = [Int]()
while num != 1 {
if num % 2 != 0 {
sequence.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
sequence.append(1)
return sequence.sorted()
}
Here is the Swift code:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var sequence = [Int]()
while num != 1 {
if num % 2 != 0 {
sequence.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
sequence.append(1)
return sequence.sorted()
}
func getOddCollatz(n: Int) -> [Int] {
var num = n
var sequence = [Int]()
while num != 1 {
if num % 2 != 0 {
sequence.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
sequence.append(1)
sequence.sort()
return sequence
}
Here is the Swift code for the function:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var sequence = [Int]()
while num != 1 {
if num % 2 != 0 {
sequence.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
sequence.append(1)
sequence.sort()
return sequence
}
func getOddCollatz(n: Int) -> [Int] {
var num = n
var sequence = [Int]()
while num != 1 {
if num % 2 != 0 {
sequence.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
sequence.append(1)
sequence.sort()
return sequence
}
Here is the Swift code to solve the problem:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var sequence = [Int]()
while num != 1 {
if num % 2 != 0 {
sequence.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
sequence.append(1)
sequence.sort()
return sequence
}
func getOddCollatz(n: Int) -> [Int] {
var num = n
var oddNumbers = [Int]()
while num != 1 {
if num % 2 != 0 {
oddNumbers.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
oddNumbers.append(1)
oddNumbers.sort()
return oddNumbers
}
Here is the Swift code that implements the Collatz sequence and returns the odd numbers in increasing order:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var oddNumbers = [Int]()
while num != 1 {
if num % 2 != 0 {
oddNumbers.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
oddNumbers.append(1)
oddNumbers.sort()
return oddNumbers
}
func getOddCollatz(n: Int) -> [Int] {
var num = n
var oddNumbers = [Int]()
while num != 1 {
if num % 2 != 0 {
oddNumbers.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
oddNumbers.append(1)
oddNumbers.sort()
return oddNumbers
}
Here is the Swift code that implements the Collatz sequence and returns the odd numbers in increasing order:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var oddNumbers = [Int]()
while num != 1 {
if num % 2 != 0 {
oddNumbers.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
oddNumbers.append(1)
oddNumbers.sort()
return oddNumbers
}
func getOddCollatz(n: Int) -> [Int] {
var num = n
var oddNumbers = [Int]()
while num != 1 {
if num % 2 != 0 {
oddNumbers.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
oddNumbers.append(1)
oddNumbers.sort()
return oddNumbers
}
Here is the Swift code for the given problem:
```swift
func getOddCollatz(n: Int) -> [Int] {
var num = n
var oddNumbers = [Int]()
while num != 1 {
if num % 2 != 0 {
oddNumbers.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
oddNumbers.append(1)
oddNumbers.sort()
return oddNumbers
}
func getOddCollatz(n: Int) -> [Int] {
var current = n
var oddNumbers = [Int]()
while current != 1 {
if current % 2 != 0 {
oddNumbers.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
oddNumbers.append(1) // Add the final 1 to the list
return oddNumbers.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var current = n
var oddNumbers = [Int]()
while current != 1 {
if current % 2 != 0 {
oddNumbers.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
oddNumbers.append(1) // Add the final 1 to the list
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var current = n
var oddNumbers = [Int]()
while current != 1 {
if current % 2 != 0 {
oddNumbers.append(current)
}
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
oddNumbers.append(1) // Add the final 1 to the list of odd numbers
return oddNumbers.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var current = n
var oddNumbers = [Int]()
while current != 1 {
if current % 2 != 0 {
oddNumbers.append(current)
}
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
oddNumbers.append(1) // Add the final 1 to the list of odd numbers
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var current = n
var oddNumbers = [Int]()
while current != 1 {
if current % 2 != 0 {
oddNumbers.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
oddNumbers.append(1) // Include the final 1 in the sequence
return oddNumbers.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var current = n
var oddNumbers = [Int]()
while current != 1 {
if current % 2 != 0 {
oddNumbers.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
oddNumbers.append(1) // Include the final 1 in the sequence
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var current = n
var oddNumbers = [Int]()
while current != 1 {
if current % 2 != 0 {
oddNumbers.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
oddNumbers.append(1) // Add the final 1 to the list of odd numbers
return oddNumbers.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var current = n
var oddNumbers = [Int]()
while current != 1 {
if current % 2 != 0 {
oddNumbers.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
oddNumbers.append(1) // Add the final 1 to the list of odd numbers
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var current = n
var oddNumbers = [Int]()
while current != 1 {
if current % 2 != 0 {
oddNumbers.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
oddNumbers.append(1) // Add the final 1 to the list
return oddNumbers.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var current = n
var oddNumbers = [Int]()
while current != 1 {
if current % 2 != 0 {
oddNumbers.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
oddNumbers.append(1) // Add the final 1 to the list
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var current = n
var oddNumbers = [Int]()
while current != 1 {
if current % 2 != 0 {
oddNumbers.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
oddNumbers.append(1) // Include the last number, which is 1
return oddNumbers.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var current = n
var oddNumbers = [Int]()
while current != 1 {
if current % 2 != 0 {
oddNumbers.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
oddNumbers.append(1) // Include the last number, which is 1
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var current = n
var oddNumbers = [Int]()
while current != 1 {
if current % 2 != 0 {
oddNumbers.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
oddNumbers.append(1) // Add the final 1 to the list
return oddNumbers.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var current = n
var oddNumbers = [Int]()
while current != 1 {
if current % 2 != 0 {
oddNumbers.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
oddNumbers.append(1) // Add the final 1 to the list
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var current = n
var oddNumbers = [Int]()
while current != 1 {
if current % 2 != 0 {
oddNumbers.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
oddNumbers.append(1) // Add the final 1 to the list
return oddNumbers.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var current = n
var oddNumbers = [Int]()
while current != 1 {
if current % 2 != 0 {
oddNumbers.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
oddNumbers.append(1) // Add the final 1 to the list
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var current = n
var oddNumbers = [Int]()
while current != 1 {
if current % 2 != 0 {
oddNumbers.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
oddNumbers.append(1) // Add the final 1 to the list of odd numbers
return oddNumbers.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var current = n
var oddNumbers = [Int]()
while current != 1 {
if current % 2 != 0 {
oddNumbers.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
oddNumbers.append(1) // Add the final 1 to the list of odd numbers
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var current = n
var oddNumbers = [Int]()
while current != 1 {
if current % 2 != 0 {
oddNumbers.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
oddNumbers.append(1) // Add the final 1 to the list of odd numbers
return oddNumbers.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var current = n
var oddNumbers = [Int]()
while current != 1 {
if current % 2 != 0 {
oddNumbers.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
oddNumbers.append(1) // Add the final 1 to the list of odd numbers
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: [Int] = []
var current = n
while current != 1 {
if current % 2 != 0 {
collatzSequence.append(current)
}
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
// Add the final 1 to the sequence
collatzSequence.append(1)
// Sort the array in increasing order
collatzSequence.sort()
return collatzSequence
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: [Int] = []
var current = n
while current != 1 {
if current % 2 != 0 {
collatzSequence.append(current)
}
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
// Add the final 1 to the sequence
collatzSequence.append(1)
// Sort the array in increasing order
collatzSequence.sort()
return collatzSequence
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: [Int] = []
var current = n
while current != 1 {
if current % 2 != 0 {
collatzSequence.append(current)
}
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
// Add the final 1 to the sequence
collatzSequence.append(1)
// Sort the array in increasing order
collatzSequence.sort()
return collatzSequence
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: [Int] = []
var current = n
while current != 1 {
if current % 2 != 0 {
collatzSequence.append(current)
}
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
// Add the final 1 to the sequence
collatzSequence.append(1)
// Sort the array in increasing order
collatzSequence.sort()
return collatzSequence
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence: [Int] = []
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
// Add the final 1 to the sequence
sequence.append(1)
// Sort the sequence in increasing order
sequence.sort()
return sequence
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence: [Int] = []
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
// Add the final 1 to the sequence
sequence.append(1)
// Sort the sequence in increasing order
sequence.sort()
return sequence
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence: [Int] = []
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
// Add the final 1 to the sequence
sequence.append(1)
// Sort the sequence in increasing order
sequence.sort()
return sequence
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence: [Int] = []
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
// Add the final 1 to the sequence
sequence.append(1)
// Sort the sequence in increasing order
sequence.sort()
return sequence
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence: [Int] = []
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
// Add the final 1 to the sequence
sequence.append(1)
// Sort the sequence in increasing order
sequence.sort()
return sequence
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence: [Int] = []
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
// Add the final 1 to the sequence
sequence.append(1)
// Sort the sequence in increasing order
sequence.sort()
return sequence
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence: [Int] = []
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
// Add the final 1 to the sequence if it's not already included
if !sequence.contains(1) {
sequence.append(1)
}
// Sort the sequence in increasing order
return sequence.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence: [Int] = []
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
// Add the final 1 to the sequence if it's not already included
if !sequence.contains(1) {
sequence.append(1)
}
// Sort the sequence in increasing order
return sequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence: [Int] = []
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
// Add the final 1 to the sequence
sequence.append(1)
// Sort the sequence in increasing order
sequence.sort()
return sequence
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence: [Int] = []
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
// Add the final 1 to the sequence
sequence.append(1)
// Sort the sequence in increasing order
sequence.sort()
return sequence
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence: [Int] = []
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
// Add the final 1 to the sequence
sequence.append(1)
// Sort the sequence in increasing order
sequence.sort()
return sequence
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence: [Int] = []
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
// Add the final 1 to the sequence
sequence.append(1)
// Sort the sequence in increasing order
sequence.sort()
return sequence
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence: [Int] = []
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
sequence.append(1) // Add the last term which is always 1
return sequence.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence: [Int] = []
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
sequence.append(1) // Add the last term which is always 1
return sequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
// Append 1 to the sequence as the Collatz sequence always ends at 1
sequence.append(1)
// Sort the sequence in increasing order
sequence.sort()
return sequence
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 != 0 {
sequence.append(current)
}
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
// Append 1 to the sequence as the Collatz sequence always ends at 1
sequence.append(1)
// Sort the sequence in increasing order
sequence.sort()
return sequence
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: Set<Int> = []
var current = n
while current != 1 {
if current % 2 == 1 {
collatzSequence.insert(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
collatzSequence.insert(1) // Include 1 in the sequence
return collatzSequence.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: Set<Int> = []
var current = n
while current != 1 {
if current % 2 == 1 {
collatzSequence.insert(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
collatzSequence.insert(1) // Include 1 in the sequence
return collatzSequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: Set<Int> = []
var current = n
while current != 1 {
if current % 2 == 1 {
collatzSequence.insert(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
collatzSequence.insert(1) // Include 1 in the sequence
return collatzSequence.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: Set<Int> = []
var current = n
while current != 1 {
if current % 2 == 1 {
collatzSequence.insert(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
collatzSequence.insert(1) // Include 1 in the sequence
return collatzSequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: Set<Int> = []
var current = n
while current != 1 {
if current % 2 == 1 {
collatzSequence.insert(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
collatzSequence.insert(1) // Include 1 in the sequence
return collatzSequence.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: Set<Int> = []
var current = n
while current != 1 {
if current % 2 == 1 {
collatzSequence.insert(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
collatzSequence.insert(1) // Include 1 in the sequence
return collatzSequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: Set<Int> = []
var current = n
while current != 1 {
if current % 2 == 1 {
collatzSequence.insert(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
collatzSequence.insert(1) // Include 1 as it is part of the sequence
return collatzSequence.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: Set<Int> = []
var current = n
while current != 1 {
if current % 2 == 1 {
collatzSequence.insert(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
collatzSequence.insert(1) // Include 1 as it is part of the sequence
return collatzSequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence: [Int] = []
var current = n
while current != 1 {
sequence.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
sequence.append(1) // Include the last term which is 1
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence: [Int] = []
var current = n
while current != 1 {
sequence.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
sequence.append(1) // Include the last term which is 1
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: Set<Int> = []
var current = n
while current != 1 {
if current % 2 == 1 {
collatzSequence.insert(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
collatzSequence.insert(1) // Include 1 as it's part of the sequence
return collatzSequence.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: Set<Int> = []
var current = n
while current != 1 {
if current % 2 == 1 {
collatzSequence.insert(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
collatzSequence.insert(1) // Include 1 as it's part of the sequence
return collatzSequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzNumbers: Set<Int> = []
var current = n
while current != 1 {
if current % 2 != 0 {
collatzNumbers.insert(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
collatzNumbers.insert(1) // Include 1 as it is part of the sequence
return collatzNumbers.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzNumbers: Set<Int> = []
var current = n
while current != 1 {
if current % 2 != 0 {
collatzNumbers.insert(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
collatzNumbers.insert(1) // Include 1 as it is part of the sequence
return collatzNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: Set<Int> = []
var current = n
while current != 1 {
if current % 2 == 1 {
collatzSequence.insert(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
collatzSequence.insert(1) // Include 1 in the sequence
return collatzSequence.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: Set<Int> = []
var current = n
while current != 1 {
if current % 2 == 1 {
collatzSequence.insert(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
collatzSequence.insert(1) // Include 1 in the sequence
return collatzSequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: Set<Int> = []
var current = n
while current != 1 {
if current % 2 == 1 {
collatzSequence.insert(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
collatzSequence.insert(1) // Include 1 in the sequence
return collatzSequence.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: Set<Int> = []
var current = n
while current != 1 {
if current % 2 == 1 {
collatzSequence.insert(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
collatzSequence.insert(1) // Include 1 in the sequence
return collatzSequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: Set<Int> = []
var current = n
while current != 1 {
if current % 2 == 1 {
collatzSequence.insert(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
collatzSequence.insert(1) // Include 1 in the sequence
return collatzSequence.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: Set<Int> = []
var current = n
while current != 1 {
if current % 2 == 1 {
collatzSequence.insert(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
collatzSequence.insert(1) // Include 1 in the sequence
return collatzSequence.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: [Int] = [n]
while collatzSequence.last != 1 {
if collatzSequence.last! % 2 == 0 {
collatzSequence.append(collatzSequence.last! / 2)
} else {
collatzSequence.append(3 * collatzSequence.last! + 1)
}
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence: [Int] = [n]
while collatzSequence.last != 1 {
if collatzSequence.last! % 2 == 0 {
collatzSequence.append(collatzSequence.last! / 2)
} else {
collatzSequence.append(3 * collatzSequence.last! + 1)
}
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
result.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
result.append(1)
return result.filter { $0 % 2 != 0 }.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
result.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
result.append(1)
return result.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
result.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
result.append(1)
return result.filter { $0 % 2 != 0 }.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
result.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
result.append(1)
return result.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
result.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
result.append(1)
return result.filter { $0 % 2 != 0 }.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
result.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
result.append(1)
return result.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
while collatzSequence.last != 1 {
if collatzSequence.last! % 2 == 0 {
collatzSequence.append(collatzSequence.last! / 2)
} else {
collatzSequence.append(3 * collatzSequence.last! + 1)
}
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
while collatzSequence.last != 1 {
if collatzSequence.last! % 2 == 0 {
collatzSequence.append(collatzSequence.last! / 2)
} else {
collatzSequence.append(3 * collatzSequence.last! + 1)
}
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num != 1 {
result.append(num)
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
}
result.append(1)
return result.filter { $0 % 2 != 0 }.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num != 1 {
result.append(num)
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
}
result.append(1)
return result.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
result.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
result.append(1)
return result.filter { $0 % 2 != 0 }.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
result.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
result.append(1)
return result.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
result.append(1)
return result.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
result.append(1)
return result.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
result.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
result.append(1)
return result.filter { $0 % 2 != 0 }.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
result.append(current)
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
}
result.append(1)
return result.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
while collatzSequence.last != 1 {
if collatzSequence.last! % 2 == 0 {
collatzSequence.append(collatzSequence.last! / 2)
} else {
collatzSequence.append(3 * collatzSequence.last! + 1)
}
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
while collatzSequence.last != 1 {
if collatzSequence.last! % 2 == 0 {
collatzSequence.append(collatzSequence.last! / 2)
} else {
collatzSequence.append(3 * collatzSequence.last! + 1)
}
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
if num % 2 == 1 {
result.append(num)
}
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
if num % 2 == 1 {
result.append(num)
}
}
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
result.append(current)
}
}
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
if num % 2 == 1 {
result.append(num)
}
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
if num % 2 == 1 {
result.append(num)
}
}
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = num * 3 + 1
}
if num % 2 != 0 {
result.append(num)
}
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = num * 3 + 1
}
if num % 2 != 0 {
result.append(num)
}
}
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
result.append(1)
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
result.append(1)
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 1 {
result.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
result.append(1)
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 1 {
result.append(current)
}
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
result.append(1)
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
result.append(num)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num /= 2
} else {
num = num * 3 + 1
}
result.append(num)
}
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
result.append(1)
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
result.append(1)
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
oddCollatz.append(current)
}
}
return oddCollatz
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 != 0 {
oddCollatz.append(current)
}
}
return oddCollatz
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
var temp = i
while temp != 1 {
if temp % 2 == 0 {
temp /= 2
} else {
temp = 3 * temp + 1
}
}
if i % 2 != 0 {
result.append(i)
}
}
return result
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
var temp = i
while temp != 1 {
if temp % 2 == 0 {
temp /= 2
} else {
temp = 3 * temp + 1
}
}
if i % 2 != 0 {
result.append(i)
}
}
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
var num = i
while num != 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
}
if i % 2 != 0 {
result.append(i)
}
}
return result
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
var num = i
while num != 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
}
if i % 2 != 0 {
result.append(i)
}
}
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
if i % 2 != 0 {
result.append(i)
}
}
return result
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
if i % 2 != 0 {
result.append(i)
}
}
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
var num = i
while num != 1 {
if num % 2 == 1 {
result.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
}
return result.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
var num = i
while num != 1 {
if num % 2 == 1 {
result.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
var temp = i
while temp != 1 {
if temp % 2 == 0 {
temp = temp / 2
} else {
temp = (3 * temp) + 1
}
}
if temp % 2 == 1 {
result.append(i)
}
}
return result.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
var temp = i
while temp != 1 {
if temp % 2 == 0 {
temp = temp / 2
} else {
temp = (3 * temp) + 1
}
}
if temp % 2 == 1 {
result.append(i)
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
if i % 2 != 0 {
result.append(i)
}
}
return result
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
if i % 2 != 0 {
result.append(i)
}
}
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
var num = i
while num != 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
}
if i % 2 != 0 {
result.append(i)
}
}
return result
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
var num = i
while num != 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
}
if i % 2 != 0 {
result.append(i)
}
}
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
var num = i
while num != 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
}
if i % 2 != 0 {
result.append(i)
}
}
return result
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
var num = i
while num != 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
}
if i % 2 != 0 {
result.append(i)
}
}
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
var num = i
while num != 1 {
if num % 2 == 1 {
result.append(num)
break
}
num = num / 2
}
}
return result.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
var num = i
while num != 1 {
if num % 2 == 1 {
result.append(num)
break
}
num = num / 2
}
}
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var number = n
while number > 0 {
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
if number % 2 == 1 {
result.append(number)
}
}
return result
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var number = n
while number > 0 {
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
if number % 2 == 1 {
result.append(number)
}
}
return result
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatz = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
collatz.append(current)
}
return collatz.filter { $0 % 2 != 0 }.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
collatz.append(current)
}
return collatz.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var result = Set<Int>()
var num = n
while num != 1 {
if num % 2 != 0 {
result.insert(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
result.insert(1)
return Array(result).sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = Set<Int>()
var num = n
while num != 1 {
if num % 2 != 0 {
result.insert(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
result.insert(1)
return Array(result).sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
collatz.append(1)
return collatz.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatz = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
collatz.append(current)
}
return collatz.filter { $0 % 2 != 0 }.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
collatz.append(current)
}
return collatz.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
collatz.append(1)
return collatz.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
collatz.append(1)
return collatz.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatz = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
collatz.append(current)
}
return Array(Set(collatz.filter { $0 % 2 != 0 }.sorted()))
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
collatz.append(current)
}
return Array(Set(collatz.filter { $0 % 2 != 0 }.sorted()))
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
collatz.append(1)
return Array(Set(collatz)).sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
collatz.append(1)
return Array(Set(collatz)).sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
collatz.append(1)
return collatz.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
collatz.append(1)
return collatz.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 != 0 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : 3 * num + 1
}
collatz.append(1)
return collatz.sorted()
}
```
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var i
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var x
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var x
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
arr.append(num)
}
return arr
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
arr.append(num)
}
return arr
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
arr.append(num)
}
return arr
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
arr.append(num)
}
return arr
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
result.append(num)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
result.append(num)
}
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var i = n
while i > 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
collatz.append(i)
}
return collatz
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var i = n
while i > 1 {
if i % 2 == 0 {
i = i / 2
} else {
i = 3 * i + 1
}
collatz.append(i)
}
return collatz
}
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
arr.append(num)
}
return arr
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
arr.append(num)
}
return arr
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
arr.append(num)
}
return arr
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
arr.append(num)
}
return arr
}
```
// XCTAssertTrue failed
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
arr.append(num)
}
arr.append(1)
XCTAssertTrue(getOddCollatz(n: 14) == [1, 5, 7, 11, 13, 17]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 5) == [1, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 12) == [1, 3, 5]) // cannot find 'getOddCollatz' in scope
XCTAssertTrue(getOddCollatz(n: 1) == [1]) // cannot find 'getOddCollatz' in scope
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
arr.append(num)
}
return arr
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
arr.append(num)
}
return arr
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
arr.append(num)
}
return arr
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
arr.append(num)
}
return arr
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
collatz.append(num)
}
return collatz
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
collatz.append(num)
}
return collatz
}
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
``````
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
``````
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
getOddCollatz(n: 5)
```
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
``````
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
``````
```swift
// Test cases
print(getOddCollatz(n: 5)) // [1, 5]
print(getOddCollatz(n: 10)) // [1, 10]
print(getOddCollatz(n: 15)) // [1, 15]
print(getOddCollatz(n: 20)) // [1, 20]
print(getOddCollatz(n: 25)) // [1, 25]
```
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
``````
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
``````
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
getOddCollatz(n: 5)
```
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
``````
```swift
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
getOddCollatz(n: 5)
```
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
``````
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
getOddCollatz(n: 5)
`````````python
def get_odd_collatz(n):
collatz = []
while n != 1:
if n % 2 == 1:
collatz.append(n)
n = n // 2 if n % 2 == 0 else n * 3 + 1
collatz.append(1)
return sorted(collatz)
get_odd_collatz(5)
```
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num != 1 {
if num % 2 == 1 {
collatz.append(num)
}
num = num % 2 == 0 ? num / 2 : num * 3 + 1
}
collatz.append(1)
return collatz.sorted()
}
``````
```python
def get_odd_collatz(n):
collatz = []
while n != 1:
if n % 2 == 1:
collatz.append(n)
n = n // 2 if n % 2 == 0 else n * 3 + 1
collatz.append(1)
return sorted(collatz)
get_odd_collatz(5)
```
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
result.append(num)
}
result.append(1)
return result.reversed()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
result.append(num)
}
result.append(1)
return result.reversed()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
arr.append(num)
}
return arr
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
arr.append(num)
}
return arr
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
collatz.append(num)
}
return collatz
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
collatz.append(num)
}
return collatz
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
arr.append(num)
}
return arr
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
arr.append(num)
}
return arr
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
result.append(num)
}
result.append(1)
return result.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
result.append(num)
}
result.append(1)
return result.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
result.append(num)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
result.append(num)
}
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
result.append(num)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
result.append(num)
}
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
arr.append(num)
}
return arr
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num > 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
arr.append(num)
}
return arr
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
arr.append(num)
}
arr.append(1)
return arr.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
arr.append(num)
}
arr.append(1)
return arr.sorted()
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
arr.append(num)
}
return arr
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var arr = [Int]()
var num = n
while num != 1 {
if num % 2 == 0 {
num = num / 2
} else {
num = 3 * num + 1
}
arr.append(num)
}
return arr
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var i = n
while i > 1 {
if i % 2 == 0 {
i /= 2
} else {
i = 3 * i + 1
}
result.append(i)
}
return result
}
func getCollatzLength(n: Int) -> Int {
var i = n
var count = 0
while i > 1 {
if i % 2 == 0 {
i /= 2
} else {
i = 3 * i + 1
}
count += 1
}
return count
}
func getCollatzConjectureLength(n: Int) -> Int {
var max = 0
var i = 1
while i <= n {
let length = getCollatzLength(i)
if length > max {
max = length
}
i += 1
}
return max
}
func getCollatzConjectureUpTo(n: Int) -> Int {
var sum = 0
var i = 1
while i <= n {
sum += getCollatzLength(i)
i += 1
}
return sum
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var i = n
while i > 1 {
if i % 2 == 0 {
i /= 2
} else {
i = 3 * i + 1
}
result.append(i)
}
return result
}
// Given a positive integer n, return the number of steps in the Collatz sequence,
// where each step is either a division by 2 or a multiplication by 3 and addition of 1.
// Note: If the number cannot be reached, return -1.
// For example:
// getCollatzLength(10) returns 10 # 10 -> 5 -> 16 -> 8 -> 4 -> 2 -> 1
// getCollatzLength(15) returns 5 # 15 -> 10 -> 5 -> 16 -> 8 -> 4 -> 2 -> 1
// getCollatzLength(12) returns -1
func getCollatzLength(n: Int) -> Int {
var i = n
var count = 0
while i > 1 {
if i % 2 == 0 {
i /= 2
} else {
i = 3 * i + 1
}
count += 1
}
return count
}
// Given a positive integer n, return the number of terms in the longest Collatz sequence
// with less than or equal to n terms.
// Note: If the number cannot be reached, return 0.
// For example:
// getCollatzConjectureLength(10) returns 8 # The longest Collatz sequence with less than or equal to 10 terms is 8, and its sequence is 10 -> 5 -> 16 -> 8 -> 4 -> 2 -> 1.
// getCollatzConjectureLength(15) returns 5 # The longest Collatz sequence with less than or equal to 15 terms is 5, and its sequence is 15 -> 10 -> 5 -> 16 -> 8 -> 4 -> 2 -> 1.
// getCollatzConjectureLength(12) returns 0
func getCollatzConjectureLength(n: Int) -> Int {
var max = 0
var i = 1
while i <= n {
let length = getCollatzLength(i)
if length > max {
max = length
}
i += 1
}
return max
}
// Given a positive integer n, return the sum of the Collatz sequence up to n.
// Note: If the number cannot be reached, return -1.
// For example:
// getCollatzConjectureUpTo(10) returns 1 + 3 + 5 + 16 + 8 + 4 + 2 + 1 + 5 + 16 + 8 + 4 + 2 + 1 = 14
// getCollatzConjectureUpTo(15) returns 1 + 3 + 5 + 16 + 8 + 4 + 2 + 1 + 5 + 16 + 8 + 4 + 2 + 1 + 3 + 5 + 16 + 8 + 4 + 2 + 1 = 14
// getCollatzConjectureUpTo(12) returns -1
func getCollatzConjectureUpTo(n: Int) -> Int {
var sum = 0
var i = 1
while i <= n {
sum += getCollatzLength(i)
i += 1
}
return sum
}
// Given a positive integer n, return the sum of the Fibonacci sequence up to n.
// Note: If the number cannot be reached, return -1.
// For example:
// getFibonacciUpTo(10) returns 1 + 1 + 2 + 3 + 5 + 8 + 13 = 31
// getFibonacciUpTo(15) returns 1 + 1 + 2 + 3 + 5 + 8 + 13 + 21 = 58
// getFibonacciUpTo(12) returns -1
func getFibonacciUpTo(n: Int) -> Int {
var sum = 0
var a = 1
var b = 1
while
let length = getCollatzLength(i) // missing argument label 'n:' in call
sum += getCollatzLength(i) // missing argument label 'n:' in call
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var x = n
while x!= 1 {
if x % 2 == 0 {
x /= 2
} else {
x = 3 * x + 1
}
result.append(x)
}
return result
}
func collatzLength(n: Int) -> Int {
if n <= 0 {
return 0
}
if n == 1 {
return 0
}
var count = 1
var x = n
while x!= 1 {
if x % 2 == 0 {
x /= 2
} else {
x = 3 * x + 1
}
count += 1
}
return count
}
func sameNumberOfDigits(n: Int) -> Int {
if n <= 0 {
return 0
}
if n == 1 {
return 1
}
var count = 0
var x = n
while x!= 0 {
count += 1
x /= 10
}
var y = n
var result = 0
while y!= 0 {
result *= 10
y /= 10
}
return result / 10 ** (count - 1)
}
func sameNumberOfDigits2(n: Int) -> Int {
if n <= 0 {
return 0
}
if n == 1 {
return 0
}
var count = 0
var x = n
while x!= 0 {
count += 1
x /= 10
}
var y = n
var result = 0
while y!= 0 {
result *= 10
y /= 10
}
return result / 10 ** (count - 1) - 1
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var x = n
while x!= 1 {
if x % 2 == 0 {
x /= 2
} else {
x = 3 * x + 1
}
result.append(x)
}
return result
}
// Given a positive integer n, return the number of steps required to reach 1.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. If n <= 0, then return 0.
// 2. If n == 1, then return 0.
// For example:
// collatz_length(5) returns 9 # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the number of steps is 9.
// collatzLength(5) == 9
func collatzLength(n: Int) -> Int {
if n <= 0 {
return 0
}
if n == 1 {
return 0
}
var count = 1
var x = n
while x!= 1 {
if x % 2 == 0 {
x /= 2
} else {
x = 3 * x + 1
}
count += 1
}
return count
}
// Given a positive integer n, return the smallest number m such that m and n have the same
// number of digits.
// Note:
// 1. If n <= 0, then return 0.
// 2. If n == 1, then return 1.
// For example:
// same_number_of_digits(123) returns 12.
// sameNumberOfDigits(123) == 12
func sameNumberOfDigits(n: Int) -> Int {
if n <= 0 {
return 0
}
if n == 1 {
return 1
}
var count = 0
var x = n
while x!= 0 {
count += 1
x /= 10
}
var y = n
var result = 0
while y!= 0 {
result *= 10
y /= 10
}
return result / 10 ** (count - 1)
}
// Given a positive integer n, return the largest number that is less than or equal to n
// with the same number of digits as n.
// Note:
// 1. If n <= 0, then return 0.
// 2. If n == 1, then return 0.
// For example:
// same_number_of_digits(123) returns 122.
// sameNumberOfDigits(123) == 122
func sameNumberOfDigits2(n: Int) -> Int {
if n <= 0 {
return 0
}
if n == 1 {
return 0
}
var count = 0
var x = n
while x!= 0 {
count += 1
x /= 10
}
var y = n
var result = 0
while y!= 0 {
result *= 10
y /= 10
}
return result / 10 ** (count - 1) - 1
}
// Given a positive integer n, return true if it contains an odd number of digits.
// Note:
// 1. If n <= 0, then return false.
// 2. If n == 1, then return false.
// For example:
// has_odd_number_of_digits(12345) returns true.
// hasOddNumberOfDigits(12345) == true
func hasOddNumberOfDigits(n: Int) -> Bool {
if n <= 0 {
return false
}
if n == 1 {
return false
}
var count = 0
var x = n
while x!= 0 {
count += 1
x /= 10
}
return
while x!= 1 { // use of '=' in a boolean context, did you mean '=='?
while x!= 1 { // cannot force unwrap value of non-optional type 'Int'
while x!= 1 { // '=' must have consistent whitespace on both sides
while x!= 1 { // '=' must have consistent whitespace on both sides
while x!= 1 { // cannot force unwrap value of non-optional type 'Int'
while x!= 1 { // use of '=' in a boolean context, did you mean '=='?
while x!= 0 { // cannot force unwrap value of non-optional type 'Int'
while x!= 0 { // use of '=' in a boolean context, did you mean '=='?
while x!= 0 { // '=' must have consistent whitespace on both sides
while y!= 0 { // '=' must have consistent whitespace on both sides
while y!= 0 { // cannot force unwrap value of non-optional type 'Int'
while y!= 0 { // use of '=' in a boolean context, did you mean '=='?
return result / 10 ** (count - 1) // no operator '**' is defined; did you mean 'pow(_:_:)'?
while x!= 0 { // '=' must have consistent whitespace on both sides
while x!= 0 { // use of '=' in a boolean context, did you mean '=='?
while x!= 0 { // cannot force unwrap value of non-optional type 'Int'
while y!= 0 { // cannot force unwrap value of non-optional type 'Int'
while y!= 0 { // '=' must have consistent whitespace on both sides
while y!= 0 { // use of '=' in a boolean context, did you mean '=='?
return result / 10 ** (count - 1) - 1 // no operator '**' is defined; did you mean 'pow(_:_:)'?
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
result.append(num)
} else {
num = (3 * num) + 1
result.append(num)
}
}
return result
}
func collatzLength(n: Int) -> Int {
if n <= 0 {
return 0
}
if n == 1 {
return 0
}
var count = 0
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = (3 * num) + 1
}
count += 1
}
return count
}
func nextOdd(n: Int) -> Int {
if n % 2 == 0 {
return n + 1
}
return (n + 1) + ((n + 1) % 2)
}
func prevEven(n: Int) -> Int {
if n % 2 == 0 {
return n - 1
}
return (n - 1) - ((n - 1) % 2)
}
func numDigits(n: Int) -> Int {
var count = 0
var num = n
while num!= 0 {
count += 1
num /= 10
}
return count
}
func digitSum(n: Int) -> Int {
var sum = 0
var num = n
while num!= 0 {
sum += num % 10
num /= 10
}
return sum
}
func isPowerOfTwo(n: Int) -> Bool {
return n > 0 && (n & (n - 1)) == 0
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
result.append(num)
} else {
num = (3 * num) + 1
result.append(num)
}
}
return result
}
// Given a positive integer n, return the number of steps required to reach 1.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. If n <= 0, then return 0.
// 2. If n == 1, then return 0.
// For example:
// collatz_length(5) returns 9 # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the number of steps is 9.
// collatzLength(5) == 9
func collatzLength(n: Int) -> Int {
if n <= 0 {
return 0
}
if n == 1 {
return 0
}
var count = 0
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = (3 * num) + 1
}
count += 1
}
return count
}
// Given a positive integer n, return the smallest odd number greater than n.
// Note: If there is no odd number greater than n in the range, return -1.
// For example:
// next_odd(5) returns 7 # The odd number greater than 5 is 7.
// nextOdd(5) == 7
func nextOdd(n: Int) -> Int {
if n % 2 == 0 {
return n + 1
}
return (n + 1) + ((n + 1) % 2)
}
// Given a positive integer n, return the largest even number less than or equal to n.
// Note: If there is no even number less than or equal to n in the range, return -1.
// For example:
// prev_even(5) returns 4 # The even number less than or equal to 5 is 4.
// prevEven(5) == 4
func prevEven(n: Int) -> Int {
if n % 2 == 0 {
return n - 1
}
return (n - 1) - ((n - 1) % 2)
}
// Given a positive integer n, return the number of digits in n.
// For example:
// num_digits(1234) returns 4
// numDigits(1234) == 4
func numDigits(n: Int) -> Int {
var count = 0
var num = n
while num!= 0 {
count += 1
num /= 10
}
return count
}
// Given a positive integer n, return the sum of the digits of n.
// For example:
// digit_sum(1234) returns 10
// digitSum(1234) == 10
func digitSum(n: Int) -> Int {
var sum = 0
var num = n
while num!= 0 {
sum += num % 10
num /= 10
}
return sum
}
// Given a positive integer n, return true if it is a power of 2.
// For example:
// is_power_of_two(16) returns true
// isPowerOfTwo(16) == true
func isPowerOfTwo(n: Int) -> Bool {
return n > 0 && (n & (n - 1)) == 0
}
// Given a positive integer n, return the next smallest number that have the same number of 1s
// as n. If n has no 1s, return -1.
// Note: 1 is considered as a one bit.
//
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 0 { // cannot force unwrap value of non-optional type 'Int'
while num!= 0 { // '=' must have consistent whitespace on both sides
while num!= 0 { // use of '=' in a boolean context, did you mean '=='?
while num!= 0 { // cannot force unwrap value of non-optional type 'Int'
while num!= 0 { // use of '=' in a boolean context, did you mean '=='?
while num!= 0 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
result.append(num)
} else {
num = (3 * num) + 1
result.append(num)
}
}
return result
}
func collatzLength(n: Int) -> Int {
if n <= 0 {
return 0
}
if n == 1 {
return 0
}
var length = 1
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = (3 * num) + 1
}
length += 1
}
return length
}
func nextOdd(n: Int) -> Int {
if n % 2 == 0 {
return -1
}
var num = n + 2
while num % 2 == 0 {
num += 2
}
return num
}
func prevEven(n: Int) -> Int {
if n % 2 == 1 {
return -1
}
var num = n - 2
while num % 2 == 1 {
num -= 2
}
return num
}
func prevPrime(n: Int) -> Int {
if n <= 1 {
return -1
}
var num = n - 1
while!isPrime(num) {
num -= 1
}
return num
}
func nextPrime(n: Int) -> Int {
if n <= 1 {
return -1
}
var num = n + 1
while!isPrime(num) {
num += 1
}
return num
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
result.append(num)
} else {
num = (3 * num) + 1
result.append(num)
}
}
return result
}
// Given a positive integer n, return the number of steps required to reach 1.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. If n <= 0, then return 0.
// 2. If n == 1, then return 0.
// For example:
// collatz_length(5) returns 9 # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the number of steps is 9.
// collatzLength(5) == 9
func collatzLength(n: Int) -> Int {
if n <= 0 {
return 0
}
if n == 1 {
return 0
}
var length = 1
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = (3 * num) + 1
}
length += 1
}
return length
}
// Given a positive integer n, return the smallest odd number greater than n.
// Note: If there is no odd number greater than n in the range, return -1.
// For example:
// next_odd(5) returns 7 # The odd number greater than 5 is 7.
// nextOdd(5) == 7
func nextOdd(n: Int) -> Int {
if n % 2 == 0 {
return -1
}
var num = n + 2
while num % 2 == 0 {
num += 2
}
return num
}
// Given a positive integer n, return the largest even number less than or equal to n.
// Note: If there is no even number less than or equal to n in the range, return -1.
// For example:
// prev_even(5) returns 4 # The even number less than or equal to 5 is 4.
// prevEven(5) == 4
func prevEven(n: Int) -> Int {
if n % 2 == 1 {
return -1
}
var num = n - 2
while num % 2 == 1 {
num -= 2
}
return num
}
// Given a positive integer n, return the largest prime less than or equal to n.
// Note: If there is no prime less than or equal to n in the range, return -1.
// For example:
// prev_prime(5) returns 4 # The prime less than or equal to 5 is 4.
// prevPrime(5) == 4
func prevPrime(n: Int) -> Int {
if n <= 1 {
return -1
}
var num = n - 1
while!isPrime(num) {
num -= 1
}
return num
}
// Given a positive integer n, return the smallest prime greater than or equal to n.
// Note: If there is no prime greater than or equal to n in the range, return -1.
// For example:
// next_prime(5) returns 7 # The prime greater than or equal to 5 is 7.
// nextPrime(5) == 7
func nextPrime(n: Int) -> Int {
if n <= 1 {
return -1
}
var num = n + 1
while!isPrime(num) {
num += 1
}
return num
}
// Given a positive integer n, return the number of prime numbers that are strictly less than n.
// Note: If there is no prime number strictly less than n in the range, return 0.
// For example:
// count
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
while!isPrime(num) { // expected expression, var, or let in 'while' condition
while!isPrime(num) { // expected expression, var, or let in 'while' condition
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
result.append(num)
} else {
num = (3 * num) + 1
result.append(num)
}
}
return result
}
func collatzSteps(n: Int) -> Int {
if n <= 0 {
return 0
} else if n == 1 {
return 0
}
var result = 0
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = (3 * num) + 1
}
result += 1
}
return result
}
func collatzSum(n: Int) -> Int {
if n <= 0 {
return 0
} else if n == 1 {
return 0
}
var result = 0
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = (3 * num) + 1
}
result += num
}
return result
}
func collatzLength(n: Int) -> Int {
if n <= 0 {
return 0
} else if n == 1 {
return 1
}
var result = 0
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = (3 * num) + 1
}
result += 1
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
result.append(num)
} else {
num = (3 * num) + 1
result.append(num)
}
}
return result
}
// Given a positive integer n, return the number of steps required to reach 1.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. If n <= 0, then return 0.
// 2. If n == 1, then return 0.
// For example:
// collatz_steps(5) returns 9.
// collatz_steps(10) returns 17.
func collatzSteps(n: Int) -> Int {
if n <= 0 {
return 0
} else if n == 1 {
return 0
}
var result = 0
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = (3 * num) + 1
}
result += 1
}
return result
}
// Given a positive integer n, return the sum of all odd numbers in the Collatz sequence up to n.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. If n <= 0, then return 0.
// 2. If n == 1, then return 0.
// For example:
// collatz_sum(5) returns 10.
// collatz_sum(10) returns 19.
func collatzSum(n: Int) -> Int {
if n <= 0 {
return 0
} else if n == 1 {
return 0
}
var result = 0
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = (3 * num) + 1
}
result += num
}
return result
}
// Given a positive integer n, return the number of terms in the Collatz sequence up to n.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. If n <= 0, then return 0.
// 2. If n == 1, then return 1.
// For example:
// collatz_length(5) returns 9.
// collatz_length(10) returns 17.
func collatzLength(n: Int) -> Int {
if n <= 0 {
return 0
} else if n == 1 {
return 1
}
var result = 0
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = (3 * num) + 1
}
result += 1
}
return result
}
// Given a positive integer n, return the n
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var x = n
while x!= 1 {
if x % 2 == 0 {
x = x / 2
} else {
x = 3 * x + 1
}
result.append(x)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var x = n
while x!= 1 {
if x % 2 == 0 {
x = x / 2
} else {
x = 3 * x + 1
}
result.append(x)
}
return result
}
// Test Cases
assert(getOddCollatz(n: 1) == [1])
assert(getOddCollatz(n: 5) == [1, 5, 16, 8, 4, 2, 1])
assert(getOddCollatz(n: 10) == [1, 5, 16, 8, 4, 2, 1])
assert(getOddCollatz(n: 100) == [1, 5, 16, 8, 4, 2, 1])
assert(getOddCollatz(n: 1000) == [1, 5, 16, 8, 4, 2, 1])
assert(getOddCollatz(n: 10000) == [1, 5, 16, 8, 4, 2, 1])
assert(getOddCollatz(n: 100000) == [1, 5, 16, 8, 4, 2, 1])
assert(getOddCollatz(n: 1000000) == [1, 5, 16, 8, 4, 2, 1])
assert(getOddCollatz(n: 10000000) == [1, 5, 16, 8, 4, 2, 1])
assert(getOddCollatz(n: 100000000) == [1, 5, 16, 8, 4, 2, 1])
assert(getOddCollatz(n: 1000000000) == [1, 5, 16, 8, 4, 2, 1])
assert(getOddCollatz(n: 10000000000) == [1, 5, 16, 8, 4, 2, 1])
assert(getOddCollatz(n: 100000000000) == [1, 5, 16, 8, 4, 2, 1])
assert(getOddCollatz(n: 1000000000000) == [1, 5, 16, 8, 4, 2, 1])
assert(getOddCollatz(n: 10000000000000) == [1, 5, 16, 8, 4, 2, 1])
assert(getOddCollatz(n: 100000000000000) == [1, 5, 16, 8, 4, 2, 1])
assert(getOddCollatz(n: 1000000000000000) == [1, 5, 16, 8, 4, 2, 1])
assert(getOddCollatz(n: 10000000000000000) == [1, 5, 16, 8, 4, 2, 1])
assert(getOddCollatz(n: 100000000000000000) == [1, 5, 16, 8, 4, 2, 1])
assert(getOddCollatz(n: 1000000000000000000) == [1, 5, 16, 8, 4, 2, 1])
assert(getOddCollatz(n: 10000000000000000000) == [1, 5
while x!= 1 { // '=' must have consistent whitespace on both sides
while x!= 1 { // cannot force unwrap value of non-optional type 'Int'
while x!= 1 { // use of '=' in a boolean context, did you mean '=='?
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
result.append(num)
} else {
num = 3 * num + 1
result.append(num)
}
}
return result
}
func getCollatzSteps(n: Int) -> Int {
var num = n
var count = 0
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
count += 1
}
return count
}
func getOddCollatzSteps(n: Int) -> (Int, [Int]) {
var result = (0, [Int]())
var num = n
var count = 0
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
result.1.append(num)
}
count += 1
}
result.0 = count
return result
}
func getPrintOddCollatzSteps(n: Int) -> (Int, [Int]) {
var result = (0, [Int]())
var num = n
var count = 0
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
result.1.append(num)
}
count += 1
print(num)
}
result.0 = count
return result
}
func getEvenCollatzSteps(n: Int) -> (Int, [Int]) {
var result = (0, [Int]())
var num = n
var count = 0
while num!= 1 {
if num % 2 == 0 {
num /= 2
result.1.append(num)
} else {
num = 3 * num + 1
}
count += 1
}
result.0 = count
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
result.append(num)
} else {
num = 3 * num + 1
result.append(num)
}
}
return result
}
// Given a positive integer n, return the number of steps it takes to reach 1.
// If the number cannot be reached, return -1.
// For example:
// get_collatz_steps(5) returns 6 # 5 -> 16 -> 8 -> 4 -> 2 -> 1
// getCollatzSteps(n: 5) == 6
func getCollatzSteps(n: Int) -> Int {
var num = n
var count = 0
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
count += 1
}
return count
}
// Given a positive integer n, return the number of steps it takes to reach 1.
// If the number cannot be reached, return -1.
// Also, return the list of all odd numbers in the collatz sequence.
// For example:
// get_odd_collatz_steps(5) returns (6, [5, 16, 8, 4, 2, 1]) # 5 -> 16 -> 8 -> 4 -> 2 -> 1
// getOddCollatzSteps(n: 5) == (6, [5, 16, 8, 4, 2, 1])
func getOddCollatzSteps(n: Int) -> (Int, [Int]) {
var result = (0, [Int]())
var num = n
var count = 0
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
result.1.append(num)
}
count += 1
}
result.0 = count
return result
}
// Given a positive integer n, return the number of steps it takes to reach 1.
// If the number cannot be reached, return -1.
// Also, return the list of all odd numbers in the collatz sequence.
// Also, print the collatz sequence.
// For example:
// get_print_odd_collatz_steps(5) prints:
// 5 -> 16 -> 8 -> 4 -> 2 -> 1
// getPrintOddCollatzSteps(n: 5) == (6, [5, 16, 8, 4, 2, 1])
func getPrintOddCollatzSteps(n: Int) -> (Int, [Int]) {
var result = (0, [Int]())
var num = n
var count = 0
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
result.1.append(num)
}
count += 1
print(num)
}
result.0 = count
return result
}
// Given a positive integer n, return the number of steps it takes to reach 1.
// If the number cannot be reached, return -1.
// Also, return the list of all even numbers in the collatz sequence.
// For example:
// get_even_collatz_steps(5) returns (5, [5, 2, 1]) # 5 -> 2 -> 1
// getEvenCollatzSteps(n: 5) == (5, [5, 2, 1])
func getEvenCollatzSteps(n: Int) -> (Int, [Int]) {
var result = (0, [Int]())
var num = n
var count = 0
while num!= 1 {
if num % 2 == 0 {
num /= 2
result.1.append(num)
} else {
num = 3 * num + 1
}
count += 1
}
result.0 = count
return result
}
// Given a positive integer n, return the number of steps it takes to reach 1.
// If the number cannot be reached, return -1.
// Also, return the list of all even
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // '=' must have consistent whitespace on both sides
while num!= 1 { // cannot force unwrap value of non-optional type 'Int'
while num!= 1 { // use of '=' in a boolean context, did you mean '=='?
while num!= 1 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var i = n
while i > 1 {
if i % 2 == 0 {
i /= 2
} else {
i = (3 * i) + 1
}
result.append(i)
}
return result
}
func collatzLength(n: Int) -> Int {
if n <= 0 {
return 0
}
if n == 1 {
return 0
}
var count = 0
var i = n
while i > 1 {
if i % 2 == 0 {
i /= 2
} else {
i = (3 * i) + 1
}
count += 1
}
return count
}
func nextOdd(n: Int) -> Int {
if n % 2 == 0 {
return n + 1
}
return n
}
func prevEven(n: Int) -> Int {
if n % 2 == 1 {
return n - 1
}
return n
}
func prevEvenEqualTo(n: Int) -> Int {
if n % 2 == 1 {
return n - 1
}
return n
}
func nextOddEqualTo(n: Int) -> Int {
if n % 2 == 0 {
return n + 1
}
return n
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var i = n
while i > 1 {
if i % 2 == 0 {
i /= 2
} else {
i = (3 * i) + 1
}
result.append(i)
}
return result
}
// Given a positive integer n, return the number of steps required to reach 1.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. If n <= 0, then return 0.
// 2. If n == 1, then return 0.
// For example:
// collatz_length(5) returns 9 # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the length is 9.
// collatzLength(5) == 9
func collatzLength(n: Int) -> Int {
if n <= 0 {
return 0
}
if n == 1 {
return 0
}
var count = 0
var i = n
while i > 1 {
if i % 2 == 0 {
i /= 2
} else {
i = (3 * i) + 1
}
count += 1
}
return count
}
// Given a positive integer n, return the smallest odd number greater than n.
// Note: if n is already odd, return n.
// For example:
// next_odd(5) returns 7 # The odd numbers greater than 5 are [7, 9, 11, 13, 15, 17, 19],
// the smallest is 7.
// nextOdd(5) == 7
func nextOdd(n: Int) -> Int {
if n % 2 == 0 {
return n + 1
}
return n
}
// Given a positive integer n, return the largest even number less than n.
// Note: if n is already even, return n.
// For example:
// prev_even(5) returns 4 # The even numbers less than 5 are [4, 2, 0, -2, -4, -6],
// the largest is 4.
// prevEven(5) == 4
func prevEven(n: Int) -> Int {
if n % 2 == 1 {
return n - 1
}
return n
}
// Given a positive integer n, return the largest even number less than or equal to n.
// Note: if n is already even, return n.
// For example:
// prev_even(5) returns 4 # The even numbers less than or equal to 5 are [4, 2, 0, -2],
// the largest is 4.
// prevEven(5) == 4
func prevEvenEqualTo(n: Int) -> Int {
if n % 2 == 1 {
return n - 1
}
return n
}
// Given a positive integer n, return the smallest odd number greater than or equal to n.
// Note: if n is already odd, return n.
// For example:
// next_odd(5) returns 7 # The odd numbers greater than or equal to 5 are [7, 9, 11, 13, 15, 17, 19],
// the smallest is 7.
// nextOdd(5) == 7
func nextOddEqualTo(n: Int) -> Int {
if n % 2 == 0 {
return n + 1
}
return n
}
// Given a positive integer n, return the number of digits in n.
// For example:
// num_digits(1234) returns 4
// numDigits(1234) == 4
func numDigits(n: Int) -> Int {
var count = 0
var i = n
while i > 0
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var i = n
while i > 1 {
if i % 2 == 0 {
i /= 2
} else {
i = (3 * i) + 1
}
result.append(i)
}
return result
}
func collatzLength(n: Int) -> Int {
var result = 0
var i = n
while i > 1 {
if i % 2 == 0 {
i /= 2
} else {
i = (3 * i) + 1
}
result += 1
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var i = n
while i > 1 {
if i % 2 == 0 {
i /= 2
} else {
i = (3 * i) + 1
}
result.append(i)
}
return result
}
// Given a positive integer n, return the number of steps required to reach 1.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. If n <= 0, then return 0.
// 2. If n == 1, then return 0.
// For example:
// collatz_length(5) returns 9 # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the length is 9.
// collatzLength(5) == 9
func collatzLength(n: Int) -> Int {
var result = 0
var i = n
while i > 1 {
if i % 2 == 0 {
i /= 2
} else {
i = (3 * i) + 1
}
result += 1
}
return result
}
// Given a positive integer n, return the sum of all odd numbers in the Collatz sequence up to n.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. If n <= 0, then return 0.
// 2. If n == 1, then return 0.
// For example:
// sum_of_odd_numbers(5) returns 10 # The Collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are 1, 5, 17, 8, 4, 2, 1, 5, 17, 8, 4, 2, 1, 5, 17, 8, 4, 2, 1, 5, 17, 8, 4, 2, 1, 5, 17, 8, 4, 2, 1, 5, 17, 8, 4, 2, 1, 5, 17, 8, 4, 2, 1, 5, 17, 8, 4, 2, 1, 5, 17, 8, 4, 2, 1, 5, 17, 8, 4, 2, 1, 5, 17, 8, 4, 2, 1, 5, 17, 8, 4, 2, 1, 5, 17, 8, 4, 2, 1, 5, 17, 8, 4, 2, 1, 5, 17, 8, 4, 2, 1, 5, 17, 8, 4, 2, 1, 5, 17, 8, 4, 2, 1, 5, 17, 8, 4, 2, 1, 5, 17, 8, 4, 2, 1, 5, 17, 8, 4, 2, 1, 5, 17, 8, 4, 2, 1, 5, 17,
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var x = n
while x!= 1 {
if x % 2 == 0 {
x = x / 2
} else {
x = (3 * x) + 1
}
result.append(x)
}
return result
}
func collatzLength(n: Int) -> Int {
if n <= 0 {
return 0
}
if n == 1 {
return 0
}
var x = n
var count = 0
while x!= 1 {
if x % 2 == 0 {
x = x / 2
} else {
x = (3 * x) + 1
}
count += 1
}
return count
}
func collatzMinSteps(n: Int) -> Int {
if n <= 0 {
return 0
}
if n == 1 {
return 0
}
var x = n
var count = 0
var minCount = Int.max
while x!= 1 {
if x % 2 == 0 {
x = x / 2
} else {
x = (3 * x) + 1
}
count += 1
if count < minCount {
minCount = count
}
}
return minCount
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var x = n
while x!= 1 {
if x % 2 == 0 {
x = x / 2
} else {
x = (3 * x) + 1
}
result.append(x)
}
return result
}
// Given a positive integer n, return the number of steps required to reach 1.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. If n <= 0, then return 0.
// 2. If n == 1, then return 0.
// For example:
// collatz_length(5) returns 9 # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the number of steps is 9.
// collatzLength(n: 5) == 9
func collatzLength(n: Int) -> Int {
if n <= 0 {
return 0
}
if n == 1 {
return 0
}
var x = n
var count = 0
while x!= 1 {
if x % 2 == 0 {
x = x / 2
} else {
x = (3 * x) + 1
}
count += 1
}
return count
}
// Given a positive integer n, return the smallest number of steps that need to be
// taken to reach 1. The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. If n <= 0, then return 0.
// 2. If n == 1, then return 0.
// For example:
// collatz_min_steps(5) returns 3 # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the smallest number of steps to reach 1 is 3.
// collatzMinSteps(n: 5) == 3
func collatzMinSteps(n: Int) -> Int {
if n <= 0 {
return 0
}
if n == 1 {
return 0
}
var x = n
var count = 0
var minCount = Int.max
while x!= 1 {
if x % 2 == 0 {
x = x / 2
} else {
x = (3 * x) + 1
}
count += 1
if count < minCount {
minCount = count
}
}
return minCount
}
// Given a positive integer n, return the number of odd numbers in the Collatz sequence up to n.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. If n <= 0, then return 0.
// 2. If n == 1, then return 0.
// For example:
// collatz_odd_count(5) returns 3 # The odd numbers in the collatz sequence for 5 are 5, 16, and 1.
while x!= 1 { // '=' must have consistent whitespace on both sides
while x!= 1 { // use of '=' in a boolean context, did you mean '=='?
while x!= 1 { // cannot force unwrap value of non-optional type 'Int'
while x!= 1 { // cannot force unwrap value of non-optional type 'Int'
while x!= 1 { // '=' must have consistent whitespace on both sides
while x!= 1 { // use of '=' in a boolean context, did you mean '=='?
while x!= 1 { // cannot force unwrap value of non-optional type 'Int'
while x!= 1 { // '=' must have consistent whitespace on both sides
while x!= 1 { // use of '=' in a boolean context, did you mean '=='?
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result.sorted()
}
```
### Test:
```swift
print(getOddCollatz(n: 5)) // [1, 5]
print(getOddCollatz(n: 10)) // [1, 5, 16, 8, 4, 2, 1]
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
oddCollatz.append(current)
}
return oddCollatz.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
oddCollatz.append(current)
}
return oddCollatz.sorted()
}
```
### Test Cases:
```swift
print(getOddCollatz(n: 1)) // [1]
print(getOddCollatz(n: 2)) // [1, 2]
print(getOddCollatz(n: 3)) // [1, 3]
print(getOddCollatz(n: 4)) // [1, 4, 2, 1]
print(getOddCollatz(n: 5)) // [1, 5]
print(getOddCollatz(n: 6)) // [1, 6, 3, 10, 5, 16, 8, 4, 2, 1]
```
### Complexity:
Time: O(n)
Space: O(n)
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result.sorted()
}
```
### Test:
```swift
print(getOddCollatz(n: 5)) // [1, 5]
print(getOddCollatz(n: 10)) // [1, 5, 16, 8, 4, 2, 1]
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
var currentNumber = n
while currentNumber > 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
oddCollatz.append(currentNumber)
}
return oddCollatz.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
var currentNumber = n
while currentNumber > 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
oddCollatz.append(currentNumber)
}
return oddCollatz.sorted()
}
```
### Test:
```swift
print(getOddCollatz(n: 5)) // [1, 5]
print(getOddCollatz(n: 10)) // [1, 5, 16, 8, 4, 2, 1]
print(getOddCollatz(n: 20)) // [1, 5, 16, 8, 4, 2, 1]
```
### Analysis:
The given problem statement is to find the odd numbers in the collatz sequence for a given positive integer n. The collatz sequence is defined as follows:
```
start with any positive integer n. Then each term is obtained from the previous term as follows:
if the previous term is even, the next term is one half of the previous term.
if the previous term is odd, the next term is 3 times the previous term plus 1.
```
The conjecture is that no matter what value of n, the sequence will always reach 1.
To solve this problem, we can use a while loop to iterate through the sequence and keep appending the odd numbers to an array. We also need to keep track of the current number and check if it is odd or even. If it is odd, we can divide it by 2 and update the current number. If it is even, we can set the current number to 3 \* currentNumber + 1.
After the loop finishes, we can sort the array and return it.
The time complexity of this solution is O(log n) because we are iterating through the sequence logarithmically. The space complexity is also O(log n) because we are using a while loop to iterate through the sequence and storing the odd numbers in an array.
### Conclusion:
This problem can be solved using a while loop and a sorted array to find the odd numbers in the collatz sequence. The time and space complexity of the solution are O(log n) which is optimal.
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
oddCollatz.append(current)
}
return oddCollatz.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
oddCollatz.append(current)
}
return oddCollatz.sorted()
}
```
### Time Complexity:
O(n)
### Space Complexity:
O(n)
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
oddCollatz.append(current)
}
return oddCollatz.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
oddCollatz.append(current)
}
return oddCollatz.sorted()
}
```
### Test:
```swift
print(getOddCollatz(n: 5)) // [1, 5]
print(getOddCollatz(n: 10)) // [1, 3, 5, 7, 9, 11, 13, 15, 17, 19]
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
var currentNumber = n
while currentNumber > 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
oddCollatz.append(currentNumber)
}
return oddCollatz.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
var currentNumber = n
while currentNumber > 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
oddCollatz.append(currentNumber)
}
return oddCollatz.sorted()
}
```
### Test:
```swift
print(getOddCollatz(n: 5)) // [1, 5]
print(getOddCollatz(n: 10)) // [1, 5, 16, 8, 4, 2, 1]
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
oddCollatz.append(current)
}
return oddCollatz.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
oddCollatz.append(current)
}
return oddCollatz.sorted()
}
```
### Test Cases:
```swift
print(getOddCollatz(n: 1)) // [1]
print(getOddCollatz(n: 5)) // [1, 5]
print(getOddCollatz(n: 10)) // [1, 5, 16, 8, 4, 2, 1]
```
### Complexity:
Time: O(n)
Space: O(n)
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
oddCollatz.append(current)
}
return oddCollatz.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
oddCollatz.append(current)
}
return oddCollatz.sorted()
}
```
### Test:
```swift
print(getOddCollatz(n: 5)) // [1, 5]
print(getOddCollatz(n: 10)) // [1, 5, 16, 8, 4, 2, 1]
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
oddCollatz.append(current)
}
return oddCollatz.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var oddCollatz = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
oddCollatz.append(current)
}
return oddCollatz.sorted()
}
```
### Test:
```swift
print(getOddCollatz(n: 5)) // [1, 5]
print(getOddCollatz(n: 10)) // [1, 5, 16, 8, 4, 2, 1]
print(getOddCollatz(n: 20)) // [1, 5, 16, 8, 4, 2, 1]
```
### Analysis:
The given problem can be solved using a recursive approach. The basic idea is to check if the current number is even or odd, and based on that, perform the appropriate operation. If the current number is even, divide it by 2, otherwise, multiply it by 3 and add 1. The result is then added to the oddCollatz array and the process is repeated with the new value. The array is sorted at the end to return the desired result.
### Time Complexity:
The time complexity of the above solution is O(log n) as it takes logarithmic time to divide the number by 2 and 3 respectively.
### Space Complexity:
The space complexity of the above solution is O(1) as it only uses constant amount of memory to store the oddCollatz array.
### Conclusion:
The above solution solves the problem of finding the odd numbers in the collatz sequence using a recursive approach. The time and space complexity are both O(log n) which makes it efficient and scalable.
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
// 2. Given an array of integers, return the sum of all the positive integers in the array.
// For example:
// sum_positive([1,2,3,4,5]) returns 15
// sumPositive([1,-2,3,-4,5]) returns 12
// sumPositive([]) returns 0
// sumPositive([-1,2,-3,4,-5]) returns 6
// sumPositive([-1,2,-3,-4,5]) returns 12
// sumPositive([-1,2,3,-4,5,-6]) returns 15
// sumPositive([1,2,3,4,5,-6]) returns 15
// sumPositive([1,2,3,4,5,6]) returns 21
// sumPositive([1,2,3,4,5,6,-7]) returns 30
// sumPositive([1,2,3,4,5,6,-7,-8]) returns 40
// sumPosimple([1,2,3,4,5,6,-7,-8,-9]) returns 45
// sumPositive([1,2,3,4,5,6,-7,-8,-9,-10]) returns 55
// sumPositive([1,2,3,4,5,6,-7,-8,-9,-10,-11]) returns 66
// sumPositive([1,2,3,4,5,6,-7,-8,-9,-10,-11,-12]) returns 78
// sumPositive([1,2,3,4,5,6,-7,-8,-9,-10,-11,-12,-13]) returns 90
// sumPositive([1,2,3,4,5,6,-7,-8,-9,-10,-11,-12,-13,-14]) returns 104
// sumPositive([1,2,3,4,5,6,-7,-8,-9,-10,-11,-12,-13,-14,-15]) returns 120
// sumPositive([1,2,3,4,5,6,-7,-8,-9,-10,-11,-12,-13,-14,-15,-16]) returns 136
// sumPositive([1,2,3,4,5,6,-7,-8,-9,-10,-11,-12,-13,-14,-15,-16,-17]) returns 152
// sumPositive([1,2,3,4,5,6,-7,-8,-9,-10,-11,-12,-13,-14,-15,-16,-17,-18]) returns 168
// sumPositive([1,2,3,4,5,6,-7,-8,-9,-10,-11,-12,-13,-14,-15,-16,-17,-18,-19]) returns 184
// sumPositive([1,2,3,4,5,6,-7,-8,-9,-10,-11,-12,-13,-14,-15,-16,-17,-18,-19,-20]) returns 200
// sumPositive([1,2,3,4,5,6,-7,-8,-9,-10,-11,-12,-13,-14,-15,-16
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ---------------------------------------------------
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
func sum_of_first_even_numbers(n: Int) -> Int {
return (n * (n + 1)) / 2
}
func sum_of_first_odd_numbers(n: Int) -> Int {
return (n * (n + 1)) / 2 * 2
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
// 2. Given a positive integer n, return the sum of the first n even numbers.
// For example:
// sum_of_first_even_numbers(5) returns 10 # 2 + 4 + 6 + 8 + 10 = 10
func sum_of_first_even_numbers(n: Int) -> Int {
return (n * (n + 1)) / 2
}
// 3. Given a positive integer n, return the sum of the first n odd numbers.
// For example:
// sum_of_first_odd_numbers(5) returns 9 # 1 + 3 + 5 + 7 + 9 = 9
func sum_of_first_odd_numbers(n: Int) -> Int {
return (n * (n + 1)) / 2 * 2
}
// 4. Given a positive integer n, return the sum of the first n even numbers.
// For example:
// sum_of_first_even_numbers(5) returns 10 # 2 + 4 + 6 + 8 + 10 = 10
func sum_of_first_even_numbers(n: Int) -> Int {
return (n * (n + 1)) / 2
}
// 5. Given a positive integer n, return the sum of the first n odd numbers.
// For example:
// sum_of_first_odd_numbers(5) returns 9 # 1 + 3 + 5 + 7 + 9 = 9
func sum_of_first_odd_numbers(n: Int) -> Int {
return (n * (n + 1)) / 2 * 2
}
// 6. Given a positive integer n, return the sum of the first n even numbers.
// For example:
// sum_of_first_even_numbers(5) returns 10 # 2 + 4 + 6 + 8 + 10 = 10
func sum_of_first_even_numbers(n: Int) -> Int {
return (n * (n + 1)) / 2
}
// 7. Given a positive integer n, return the sum of the first n odd numbers.
// For example:
// sum_of_first_odd_numbers(5) returns 9 # 1 + 3 + 5 + 7 + 9 = 9
func sum_of_first_odd_numbers(n: Int) -> Int {
return (n * (n + 1)) / 2 * 2
}
// 8. Given a positive integer n, return the sum of the first n even numbers.
// For example:
// sum_of_first_even_numbers(5) returns 10 # 2 + 4 + 6 + 8 + 10 = 10
func sum_of_first_even_numbers(n: Int) -> Int {
return (n * (n + 1)) / 2
}
// 9. Given a positive integer n, return the sum of the first n odd numbers.
// For example:
// sum_of_first_odd_numbers(5) returns 9 # 1 + 3 + 5 + 7 + 9 = 9
func sum_of_first_odd_numbers(n: Int) -> Int {
return (n * (n + 1)) / 2 * 2
}
// 10. Given a positive integer n, return the sum of the first n even numbers.
// For example:
// sum_of_first_even_numbers(5) returns 10 # 2 + 4 + 6 + 8 + 10 = 10
func sum_of_first_even_numbers(n: Int) -> Int {
return (n * (n + 1)) / 2
}
// 11. Given a positive integer n, return the sum of the first n odd numbers.
// For example:
// sum_of_first
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var i = n
while i > 1 {
if i % 2 == 0 {
i /= 2
} else {
i = 3 * i + 1
}
result.append(i)
}
return result
}
func getOddCollatz(n: Int) -> Int {
var result = 0
var i = 1
while i <= n {
if i % 2 == 0 {
i /= 2
} else {
i = 3 * i + 1
}
result += i
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var i = n
while i > 1 {
if i % 2 == 0 {
i /= 2
} else {
i = 3 * i + 1
}
result.append(i)
}
return result
}
// 2. Given a positive integer n, return the sum of all integers in the range [1, n] that are not in the Collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note: 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> Int {
var result = 0
var i = 1
while i <= n {
if i % 2 == 0 {
i /= 2
} else {
i = 3 * i + 1
}
result += i
}
return result
}
// 3. Given a positive integer n, return the sum of all integers in the range [1, n] that are not in the Collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note: 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> Int {
var result = 0
var i = 1
while i <= n {
if i % 2 == 0 {
i /= 2
} else {
i = 3 * i + 1
}
result += i
}
return result
}
// 4. Given a positive integer n, return the sum of all integers in the range [1, n] that are not in the Collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note: 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var i = n
while i > 1 {
if i % 2 == 0 {
i /= 2
} else {
i = 3 * i + 1
}
collatz.append(i)
}
return collatz
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var i = n
while i > 1 {
if i % 2 == 0 {
i /= 2
} else {
i = 3 * i + 1
}
collatz.append(i)
}
return collatz
}
// ----------------------------------------------------------------------------------------------------------------------
// 1. Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note: 1. Collatz(1) is [1]. 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var i = n
while i > 1 {
if i % 2 == 0 {
i /= 2
} else {
i = 3 * i + 1
}
collatz.append(i)
}
return collatz
}
// ----------------------------------------------------------------------------------------------------------------------
// 1. Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note: 1. Collatz(1) is [1]. 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatz = [Int]()
var i = n
while i > 1 {
if i % 2 == 0 {
i /= 2
} else {
i = 3 * i + 1
}
collatz.append(i)
}
return collatz
}
// ----------------------------------------------------------------------------------------------------------------------
// 1. Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
func getEvenCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 0 {
result.append(current)
}
}
return result
}
func getOddEvenCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
// 2. Given a positive integer n, return a sorted array that has the even numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_even_collatz(5) returns [2, 4] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the even numbers are only 2, and 4.
// getEvenCollatz(n: 5) == [2, 4]
func getEvenCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
if current % 2 == 0 {
result.append(current)
}
}
return result
}
// 3. Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence and the even numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_even_collatz(5) returns [1, 5, 2, 4] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddEvenCollatz(n: 5) == [1, 5, 2, 4]
func getOddEvenCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
// 4. Given a positive integer n, return a sorted array that has the even numbers in collatz sequence and the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_even_odd_collatz(5) returns [2, 4, 1, 3] # The collatz sequence for 5 is [5, 16,
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
func sumNotMultiple(n: Int) -> Int {
var result = 0
for i in 1...n {
if i % 3 != 0 && i % 5 != 0 && i % 7 != 0 {
result += i
}
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
// 2. Given a positive integer n, return the sum of all integers in the range [1, n] that are not a multiple of 3, 5, or 7.
// For example:
// sum_not_multiple(10) returns 20 # 1 + 2 + 4 + 7 + 8 + 11 + 13 + 14 + 16 + 18 = 20
// sumNotMultiple(n: 10) == 20
func sumNotMultiple(n: Int) -> Int {
var result = 0
for i in 1...n {
if i % 3 != 0 && i % 5 != 0 && i % 7 != 0 {
result += i
}
}
return result
}
// 3. Given a positive integer n, return the sum of all integers in the range [1, n] that are not a multiple of 3, 5, or 7.
// For example:
// sum_not_multiple(10) returns 20 # 1 + 2 + 4 + 7 + 8 + 11 + 13 + 14 + 16 + 18 = 20
// sumNotMultiple(n: 10) == 20
func sumNotMultiple(n: Int) -> Int {
var result = 0
for i in 1...n {
if i % 3 != 0 && i % 5 != 0 && i % 7 != 0 {
result += i
}
}
return result
}
// 4. Given a positive integer n, return the sum of all integers in the range [1, n] that are not a multiple of 3, 5, or 7.
// For example:
// sum_not_multiple(10) returns 20 # 1 + 2 + 4 + 7 + 8 + 11 + 13 + 14 + 16 + 18 = 20
// sumNotMultiple(n: 10) == 20
func sumNotMultiple(n: Int) -> Int {
var result = 0
for i in 1...n {
if i % 3 != 0 && i % 5 != 0 && i % 7 != 0 {
result += i
}
}
return result
}
// 5. Given a positive integer n, return the sum of all integers in the range [1, n] that are not a multiple of 3, 5, or 7.
// For example:
// sum_not_multiple(10) returns 20 # 1 + 2 + 4 + 7 + 8 + 11 + 13 + 14 + 16 + 18 = 20
// sumNotMultiple(n: 10) == 20
func sumNotMultiple(n: Int) -> Int {
var result = 0
for i in 1...n {
if i % 3 != 0 && i % 5 != 0 && i % 7 != 0 {
result += i
}
}
return result
}
// 6. Given a positive integer n, return the sum of all integers in the range [1, n] that are not a multiple of 3, 5, or 7.
// For example:
// sum_not_multiple(10) returns 20 # 1 + 2 + 4 + 7 + 8 + 11 + 13 + 14 + 16 + 18 = 20
// sumNotMultiple(n: 10) == 20
func sumNotMultiple(n: Int) -> Int {
var result = 0
for i in 1...n {
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
func getOddCollatz(n: Int) -> Int {
var result = 0
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result += current
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
// 2. Given a positive integer n, return the sum of all integers in the range [1, n] that are not in the Collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> Int {
var result = 0
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result += current
}
return result
}
// 3. Given a positive integer n, return the sum of all integers in the range [1, n] that are not in the Collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> Int {
var result = 0
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result += current
}
return result
}
// 4. Given a positive integer n, return the sum of all integers in the range [1, n] that are not in the Collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
result.append(current)
}
return result
}
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------------------------------------
// ---------------------------------------------------------
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
result.append(current)
}
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = current * 3 + 1
}
result.append(current)
}
return result
}
// ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var number = n
while number != 1 {
sequence.append(number)
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
}
sequence.append(1)
return sequence.filter { $0 % 2 != 0 }.sorted()
}
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var number = n
while number != 1 {
sequence.append(number)
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
}
sequence.append(1)
return sequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var number = n
while number != 1 {
sequence.append(number)
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
}
sequence.append(1)
return sequence.filter { $0 % 2 != 0 }.sorted()
}
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var number = n
while number != 1 {
sequence.append(number)
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
}
sequence.append(1)
return sequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var number = n
while number != 1 {
sequence.append(number)
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
}
sequence.append(1)
return sequence.filter { $0 % 2 != 0 }.sorted()
}
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var number = n
while number != 1 {
sequence.append(number)
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
}
sequence.append(1)
return sequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var number = n
while number != 1 {
sequence.append(number)
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
}
sequence.append(1)
return sequence.filter { $0 % 2 != 0 }.sorted()
}
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var number = n
while number != 1 {
sequence.append(number)
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
}
sequence.append(1)
return sequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var number = n
while number != 1 {
sequence.append(number)
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
}
sequence.append(1)
return sequence.filter { $0 % 2 != 0 }.sorted()
}
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var number = n
while number != 1 {
sequence.append(number)
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
}
sequence.append(1)
return sequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
sequence.append(current)
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
sequence.append(1)
return sequence.filter { $0 % 2 != 0 }.sorted()
}
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
sequence.append(current)
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
}
sequence.append(1)
return sequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var number = n
while number != 1 {
sequence.append(number)
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
}
sequence.append(1)
return sequence.filter { $0 % 2 != 0 }.sorted()
}
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var number = n
while number != 1 {
sequence.append(number)
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
}
sequence.append(1)
return sequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var number = n
while number != 1 {
sequence.append(number)
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
}
sequence.append(1)
return sequence.filter { $0 % 2 != 0 }.sorted()
}
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var number = n
while number != 1 {
sequence.append(number)
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
}
sequence.append(1)
return sequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var number = n
while number != 1 {
sequence.append(number)
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
}
sequence.append(1)
return sequence.filter { $0 % 2 != 0 }.sorted()
}
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var number = n
while number != 1 {
sequence.append(number)
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
}
sequence.append(1)
return sequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var number = n
while number != 1 {
sequence.append(number)
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
}
sequence.append(1)
return sequence.filter { $0 % 2 != 0 }.sorted()
}
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var number = n
while number != 1 {
sequence.append(number)
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
}
sequence.append(1)
return sequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var number = n
var oddNumbers = [Int]()
while number != 1 {
if number % 2 != 0 && !oddNumbers.contains(number) {
oddNumbers.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
if !oddNumbers.contains(1) {
oddNumbers.append(1)
}
return oddNumbers.sorted()
}
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var number = n
var oddNumbers = [Int]()
while number != 1 {
if number % 2 != 0 && !oddNumbers.contains(number) {
oddNumbers.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
if !oddNumbers.contains(1) {
oddNumbers.append(1)
}
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var number = n
var oddNumbers = [Int]()
while number != 1 {
if number % 2 != 0 && !oddNumbers.contains(number) {
oddNumbers.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
if !oddNumbers.contains(1) {
oddNumbers.append(1)
}
return oddNumbers.sorted()
}
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var number = n
var oddNumbers = [Int]()
while number != 1 {
if number % 2 != 0 && !oddNumbers.contains(number) {
oddNumbers.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
if !oddNumbers.contains(1) {
oddNumbers.append(1)
}
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var number = n
var oddNumbers = [Int]()
while number != 1 {
if number % 2 != 0 && !oddNumbers.contains(number) {
oddNumbers.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
if !oddNumbers.contains(1) {
oddNumbers.append(1)
}
return oddNumbers.sorted()
}
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var number = n
var oddNumbers = [Int]()
while number != 1 {
if number % 2 != 0 && !oddNumbers.contains(number) {
oddNumbers.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
if !oddNumbers.contains(1) {
oddNumbers.append(1)
}
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var number = n
var oddNumbers = [Int]()
while number != 1 {
if number % 2 != 0 && !oddNumbers.contains(number) {
oddNumbers.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
if !oddNumbers.contains(1) {
oddNumbers.append(1)
}
return oddNumbers.sorted()
}
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var number = n
var oddNumbers = [Int]()
while number != 1 {
if number % 2 != 0 && !oddNumbers.contains(number) {
oddNumbers.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
if !oddNumbers.contains(1) {
oddNumbers.append(1)
}
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var number = n
var oddNumbers = [Int]()
while number != 1 {
if number % 2 != 0 && !oddNumbers.contains(number) {
oddNumbers.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
if !oddNumbers.contains(1) {
oddNumbers.append(1)
}
return oddNumbers.sorted()
}
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var number = n
var oddNumbers = [Int]()
while number != 1 {
if number % 2 != 0 && !oddNumbers.contains(number) {
oddNumbers.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
if !oddNumbers.contains(1) {
oddNumbers.append(1)
}
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var number = n
var collatzArray: [Int] = []
while number != 1 {
if number % 2 != 0 {
collatzArray.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
collatzArray.append(1)
return collatzArray.sorted()
}
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var number = n
var collatzArray: [Int] = []
while number != 1 {
if number % 2 != 0 {
collatzArray.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
collatzArray.append(1)
return collatzArray.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var number = n
var collatzArray: [Int] = []
while number != 1 {
if number % 2 != 0 {
collatzArray.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
collatzArray.append(1)
return collatzArray.sorted()
}
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var number = n
var collatzArray: [Int] = []
while number != 1 {
if number % 2 != 0 {
collatzArray.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
collatzArray.append(1)
return collatzArray.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var number = n
var collatzArray: [Int] = []
while number != 1 {
if number % 2 != 0 {
collatzArray.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
collatzArray.append(1)
return collatzArray.sorted()
}
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var number = n
var collatzArray: [Int] = []
while number != 1 {
if number % 2 != 0 {
collatzArray.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
collatzArray.append(1)
return collatzArray.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var current = n
var oddNumbers = Set<Int>()
while current != 1 {
if current % 2 != 0 {
oddNumbers.insert(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
oddNumbers.insert(1)
return oddNumbers.sorted()
}
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var current = n
var oddNumbers = Set<Int>()
while current != 1 {
if current % 2 != 0 {
oddNumbers.insert(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
oddNumbers.insert(1)
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var number = n
var collatzSequence: [Int] = []
while number != 1 {
if number % 2 != 0 {
collatzSequence.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
collatzSequence.append(1) // Add 1 to the sequence as per the Collatz conjecture
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var number = n
var collatzSequence: [Int] = []
while number != 1 {
if number % 2 != 0 {
collatzSequence.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
collatzSequence.append(1) // Add 1 to the sequence as per the Collatz conjecture
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 1 {
result.append(current)
}
current = collatz(current)
}
result.append(1)
return result.sorted()
}
func collatz(n: Int) -> Int {
if n % 2 == 0 {
return n / 2
} else {
return 3 * n + 1
}
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 1 {
result.append(current)
}
current = collatz(current)
}
result.append(1)
return result.sorted()
}
func collatz(n: Int) -> Int {
if n % 2 == 0 {
return n / 2
} else {
return 3 * n + 1
}
}
```
current = collatz(current) // missing argument label 'n:' in call
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 == 1 {
sequence.append(current)
}
current = collatz(current)
}
sequence.append(1)
return sequence.sorted()
}
func collatz(n: Int) -> Int {
if n % 2 == 0 {
return n / 2
} else {
return 3 * n + 1
}
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 == 1 {
sequence.append(current)
}
current = collatz(current)
}
sequence.append(1)
return sequence.sorted()
}
func collatz(n: Int) -> Int {
if n % 2 == 0 {
return n / 2
} else {
return 3 * n + 1
}
}
```
current = collatz(current) // missing argument label 'n:' in call
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 1 {
result.append(current)
}
current = current / 2
}
result.append(1)
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current != 1 {
if current % 2 == 1 {
result.append(current)
}
current = current / 2
}
result.append(1)
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 == 1 {
sequence.append(current)
}
current = current / 2
}
sequence.append(1)
return sequence
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 == 1 {
sequence.append(current)
}
current = current / 2
}
sequence.append(1)
return sequence
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 1 {
result.append(current)
}
current = current / 2
}
result.append(1)
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 1 {
result.append(current)
}
current = current / 2
}
result.append(1)
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 1 {
result.append(current)
}
current = current / 2
}
result.append(1)
return result
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current != 1 {
if current % 2 == 1 {
result.append(current)
}
current = current / 2
}
result.append(1)
return result
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var sequence = [Int]()
var current = n
while current != 1 {
if current % 2 == 0 {
current /= 2
} else {
current = 3 * current + 1
}
sequence.append(current)
}
return sequence.filter { $0 % 2 != 0 }
}
```
// XCTAssertTrue failed
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
collatzSequence.append(n)
}
return Array(Set(collatzSequence.filter { $0 % 2 != 0 })).sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
collatzSequence.append(n)
}
return Array(Set(collatzSequence.filter { $0 % 2 != 0 })).sorted()
}
```
n /= 2 // left side of mutating operator isn't mutable: 'n' is a 'let' constant
n = 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
collatzSequence.append(n)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
collatzSequence.append(n)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```
n /= 2 // left side of mutating operator isn't mutable: 'n' is a 'let' constant
n = 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
collatzSequence.append(n)
}
return Array(Set(collatzSequence.filter { $0 % 2 != 0 })).sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
collatzSequence.append(n)
}
return Array(Set(collatzSequence.filter { $0 % 2 != 0 })).sorted()
}
```
n /= 2 // left side of mutating operator isn't mutable: 'n' is a 'let' constant
n = 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
collatzSequence.append(currentNumber)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
collatzSequence.append(currentNumber)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
collatzSequence.append(n)
}
return Array(Set(collatzSequence.filter { $0 % 2 != 0 })).sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
collatzSequence.append(n)
}
return Array(Set(collatzSequence.filter { $0 % 2 != 0 })).sorted()
}
```
n /= 2 // left side of mutating operator isn't mutable: 'n' is a 'let' constant
n = 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
collatzSequence.append(currentNumber)
}
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
collatzSequence.append(currentNumber)
}
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
collatzSequence.append(currentNumber)
}
return Array(Set(collatzSequence.filter { $0 % 2 != 0 })).sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
collatzSequence.append(currentNumber)
}
return Array(Set(collatzSequence.filter { $0 % 2 != 0 })).sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
collatzSequence.append(currentNumber)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
collatzSequence.append(currentNumber)
}
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
// Check function to verify the correctness of the solution
func check() {
assert(getOddCollatz(n: 5) == [1, 5], "Test case 1 failed")
assert(getOddCollatz(n: 10) == [1, 5], "Test case 2 failed")
assert(getOddCollatz(n: 1) == [1], "Test case 3 failed")
assert(getOddCollatz(n: 7) == [1, 7, 11, 17, 25, 37, 55, 83, 125, 189, 285, 429, 645, 969, 1455, 2183, 3275, 4913, 7371, 11059, 16591, 24887, 37331, 56001, 84003, 126005, 189009, 283515, 425273, 637911, 956867, 1435301, 2152953, 3229431, 4844147, 7266221, 10899333, 16349001, 24523503, 36785255, 55177883, 82766825, 124150239, 186225359, 279338039, 418907059, 628360639, 942541019, 1413811529, 2120717295, 3181075943, 4771613915, 7157420873, 10736131311, 16104196967, 24156295451, 36234443177, 54351664767, 81527497151, 122291245727, 183436868591, 275155302887, 412732954331, 619099431501, 928649147253, 1392973720881, 2089460581323, 3134190871985, 4701286307977, 7051929461967, 10577894192951, 15866841289429, 23799761934143, 35699642901215, 53549464351823, 80324196527735, 120486294791599, 180729442187399, 271094163281099, 406641244921649, 609961867382475, 914
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
collatzSequence.append(currentNumber)
}
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = 3 * currentNumber + 1
}
collatzSequence.append(currentNumber)
}
let oddNumbers = collatzSequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
collatzSequence.append(currentNumber)
}
return Array(Set(collatzSequence.filter { $0 % 2 != 0 })).sorted()
}
```swift
// Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous term is even, the next term is one half of
// the previous term. If the previous term is odd, the next term is 3 times the previous
// term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
// Note:
// 1. Collatz(1) is [1].
// 2. returned array sorted in increasing order.
// For example:
// get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
// getOddCollatz(n: 5) == [1, 5]
func getOddCollatz(n: Int) -> [Int] {
var collatzSequence = [n]
var currentNumber = n
while currentNumber != 1 {
if currentNumber % 2 == 0 {
currentNumber /= 2
} else {
currentNumber = currentNumber * 3 + 1
}
collatzSequence.append(currentNumber)
}
return Array(Set(collatzSequence.filter { $0 % 2 != 0 })).sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
while n != 1 {
if n % 2 != 0 {
result.append(n)
}
n = n % 2 == 0 ? n / 2 : 3 * n + 1
}
result.append(1)
return result.sorted()
}
system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
while n != 1 {
if n % 2 != 0 {
result.append(n)
}
n = n % 2 == 0 ? n / 2 : 3 * n + 1
}
result.append(1)
return result.sorted()
}
```
n = n % 2 == 0 ? n / 2 : 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
while n != 1 {
if n % 2 != 0 {
result.append(n)
}
n = n % 2 == 0 ? n / 2 : 3 * n + 1
}
result.append(1)
return result.sorted()
}
system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
while n != 1 {
if n % 2 != 0 {
result.append(n)
}
n = n % 2 == 0 ? n / 2 : 3 * n + 1
}
result.append(1)
return result.sorted()
}
```
n = n % 2 == 0 ? n / 2 : 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
while n != 1 {
if n % 2 != 0 {
result.append(n)
}
n = (n % 2 == 0) ? n / 2 : 3 * n + 1
}
result.append(1)
return result.sorted()
}
system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
while n != 1 {
if n % 2 != 0 {
result.append(n)
}
n = (n % 2 == 0) ? n / 2 : 3 * n + 1
}
result.append(1)
return result.sorted()
}
```
n = (n % 2 == 0) ? n / 2 : 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
while n != 1 {
if n % 2 != 0 {
result.append(n)
}
n = (n % 2 == 0) ? n / 2 : 3 * n + 1
}
result.append(1)
return result.sorted()
}
system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
while n != 1 {
if n % 2 != 0 {
result.append(n)
}
n = (n % 2 == 0) ? n / 2 : 3 * n + 1
}
result.append(1)
return result.sorted()
}
```
n = (n % 2 == 0) ? n / 2 : 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
while n != 1 {
if n % 2 != 0 {
result.append(n)
}
n = n % 2 == 0 ? n / 2 : 3 * n + 1
}
result.append(1)
return result.sorted()
}
system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
while n != 1 {
if n % 2 != 0 {
result.append(n)
}
n = n % 2 == 0 ? n / 2 : 3 * n + 1
}
result.append(1)
return result.sorted()
}
```
n = n % 2 == 0 ? n / 2 : 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var result = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
result.append(n)
}
return result.filter { $0 % 2 != 0 }.sorted()
}
system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
result.append(n)
}
return result.filter { $0 % 2 != 0 }.sorted()
}
```
n /= 2 // left side of mutating operator isn't mutable: 'n' is a 'let' constant
n = 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
while n != 1 {
if n % 2 != 0 {
result.append(n)
}
n = n % 2 == 0 ? n / 2 : 3 * n + 1
}
result.append(1)
return result.sorted()
}
system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
while n != 1 {
if n % 2 != 0 {
result.append(n)
}
n = n % 2 == 0 ? n / 2 : 3 * n + 1
}
result.append(1)
return result.sorted()
}
```
n = n % 2 == 0 ? n / 2 : 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
while n != 1 {
if n % 2 != 0 {
result.append(n)
}
n = (n % 2 == 0) ? n / 2 : 3 * n + 1
}
result.append(1)
return result.sorted()
}
system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
while n != 1 {
if n % 2 != 0 {
result.append(n)
}
n = (n % 2 == 0) ? n / 2 : 3 * n + 1
}
result.append(1)
return result.sorted()
}
```
n = (n % 2 == 0) ? n / 2 : 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
while n != 1 {
if n % 2 != 0 {
result.append(n)
}
n = n % 2 == 0 ? n / 2 : 3 * n + 1
}
result.append(1)
return result.sorted()
}
system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
while n != 1 {
if n % 2 != 0 {
result.append(n)
}
n = n % 2 == 0 ? n / 2 : 3 * n + 1
}
result.append(1)
return result.sorted()
}
```
n = n % 2 == 0 ? n / 2 : 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
while n != 1 {
if n % 2 != 0 {
result.append(n)
}
n = n % 2 == 0 ? n / 2 : 3 * n + 1
}
result.append(1)
return result.sorted()
}
system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
while n != 1 {
if n % 2 != 0 {
result.append(n)
}
n = n % 2 == 0 ? n / 2 : 3 * n + 1
}
result.append(1)
return result.sorted()
}
```
n = n % 2 == 0 ? n / 2 : 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
sequence.append(n)
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
sequence.append(n)
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
n /= 2 // left side of mutating operator isn't mutable: 'n' is a 'let' constant
n = 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
sequence.append(n)
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
sequence.append(n)
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
n /= 2 // left side of mutating operator isn't mutable: 'n' is a 'let' constant
n = 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
sequence.append(n)
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
sequence.append(n)
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
n /= 2 // left side of mutating operator isn't mutable: 'n' is a 'let' constant
n = 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
sequence.append(n)
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
sequence.append(n)
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
n /= 2 // left side of mutating operator isn't mutable: 'n' is a 'let' constant
n = 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var result = Set<Int>()
var current = n
while current != 1 {
if current % 2 != 0 {
result.insert(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
result.insert(1) // Adding 1 to the set since it's always part of the sequence
return Array(result).sorted()
}
system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = Set<Int>()
var current = n
while current != 1 {
if current % 2 != 0 {
result.insert(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
result.insert(1) // Adding 1 to the set since it's always part of the sequence
return Array(result).sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
sequence.append(n)
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
sequence.append(n)
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
n /= 2 // left side of mutating operator isn't mutable: 'n' is a 'let' constant
n = 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
sequence.append(n)
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
sequence.append(n)
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
n /= 2 // left side of mutating operator isn't mutable: 'n' is a 'let' constant
n = 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
sequence.append(n)
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var sequence = [n]
while n != 1 {
if n % 2 == 0 {
n /= 2
} else {
n = 3 * n + 1
}
sequence.append(n)
}
let oddNumbers = sequence.filter { $0 % 2 != 0 }
return oddNumbers.sorted()
}
```
n /= 2 // left side of mutating operator isn't mutable: 'n' is a 'let' constant
n = 3 * n + 1 // cannot assign to value: 'n' is a 'let' constant
func getOddCollatz(n: Int) -> [Int] {
var result = Set<Int>()
var current = n
while current != 1 {
if current % 2 != 0 {
result.insert(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
result.insert(1) // Adding 1 to the set as per the problem statement
return Array(result).sorted()
}
system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = Set<Int>()
var current = n
while current != 1 {
if current % 2 != 0 {
result.insert(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
result.insert(1) // Adding 1 to the set as per the problem statement
return Array(result).sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var result = Set<Int>()
var current = n
while current != 1 {
if current % 2 != 0 {
result.insert(current)
}
current = current % 2 == 0 ? current / 2 : current * 3 + 1
}
result.insert(1) // Adding 1 to the set since it's part of the sequence and odd
return Array(result).sorted()
}
system
You are Qwen, created by Alibaba Cloud. You are a helpful assistant.
user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = Set<Int>()
var current = n
while current != 1 {
if current % 2 != 0 {
result.insert(current)
}
current = current % 2 == 0 ? current / 2 : current * 3 + 1
}
result.insert(1) // Adding 1 to the set since it's part of the sequence and odd
return Array(result).sorted()
}
```
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
if current % 2 == 1 {
result.append(current)
}
}
result.append(1)
return result
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
if current % 2 == 1 {
result.append(current)
}
}
result.append(1)
return result
}
```
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
result.append(1)
return result
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
result.append(1)
return result
}
```
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
result.append(1)
return result
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
result.append(1)
return result
}
```
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
result.append(1)
return result
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
result.append(1)
return result
}
```
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
result.append(1)
return result.sorted()
}
```
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
result.append(1)
return result
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
result.append(1)
return result
}
```
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
result.append(1)
return result
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
result.append(1)
return result
}
```
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
result.append(1)
return result
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
result.append(1)
return result
}
```
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
result.append(1)
return result
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2 == 1 {
result.append(current)
}
}
result.append(1)
return result
}
```
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'
while current!= 1 { // '=' must have consistent whitespace on both sides
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
if current % 2 == 1 {
result.append(current)
}
}
result.append(1)
return result
}
### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
### Response:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = current * 3 + 1
}
if current % 2 == 1 {
result.append(current)
}
}
result.append(1)
return result
}
```
while current!= 1 { // '=' must have consistent whitespace on both sides
while current!= 1 { // use of '=' in a boolean context, did you mean '=='?
while current!= 1 { // cannot force unwrap value of non-optional type 'Int'