func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    guard numbers.count > 1 else {
        return false
    }
    
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    guard numbers.count > 1 else {
        return false
    }
    
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    guard numbers.count > 1 else {
        return false
    }
    
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    guard numbers.count > 1 else {
        return false
    }
    
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    guard numbers.count > 1 else {
        return false
    }
    
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    guard numbers.count > 1 else {
        return false
    }
    
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    guard numbers.count > 1 else {
        return false
    }
    
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    guard numbers.count > 1 else {
        return false
    }
    
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    guard numbers.count > 1 else {
        return false
    }
    
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    guard numbers.count > 1 else {
        return false
    }
    
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) <= threshold {
                return true
            }
        }
    }
    return false
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var currentGroup = ""
    
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            if stack.isEmpty || stack.last!= "(" {
                return []
            } else {
                stack.removeLast()
            }
        } else {
            currentGroup.append(char)
        }
        
        if stack.isEmpty {
            result.append(currentGroup)
            currentGroup = ""
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var currentGroup = ""
    
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            if stack.isEmpty || stack.last!= "(" {
                return []
            } else {
                stack.removeLast()
            }
        } else {
            currentGroup.append(char)
        }
        
        if stack.isEmpty {
            result.append(currentGroup)
            currentGroup = ""
        }
    }
    
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            if stack.isEmpty || stack.last!= "(" {
                return []
            } else {
                stack.removeLast()
            }
        }
    }
    
    if stack.isEmpty {
        return result
    } else {
        return []
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            if stack.isEmpty || stack.last!= "(" {
                return []
            } else {
                stack.removeLast()
            }
        }
    }
    
    if stack.isEmpty {
        return result
    } else {
        return []
    }
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var currentGroup = ""
    
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            if stack.isEmpty || stack.last!= "(" {
                return []
            } else {
                stack.removeLast()
                result.append(currentGroup)
                currentGroup = ""
            }
        } else {
            currentGroup.append(char)
        }
    }
    
    if!stack.isEmpty {
        return []
    } else {
        result.append(currentGroup)
        return result
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var currentGroup = ""
    
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            if stack.isEmpty || stack.last!= "(" {
                return []
            } else {
                stack.removeLast()
                result.append(currentGroup)
                currentGroup = ""
            }
        } else {
            currentGroup.append(char)
        }
    }
    
    if!stack.isEmpty {
        return []
    } else {
        result.append(currentGroup)
        return result
    }
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var currentGroup = ""
    
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            if stack.isEmpty || stack.last!= "(" {
                return []
            } else {
                stack.removeLast()
            }
        } else {
            currentGroup.append(char)
        }
        
        if stack.isEmpty {
            result.append(currentGroup)
            currentGroup = ""
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var currentGroup = ""
    
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            if stack.isEmpty || stack.last!= "(" {
                return []
            } else {
                stack.removeLast()
            }
        } else {
            currentGroup.append(char)
        }
        
        if stack.isEmpty {
            result.append(currentGroup)
            currentGroup = ""
        }
    }
    
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var currentGroup = ""
    
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            if stack.isEmpty {
                result.append(currentGroup)
                currentGroup = ""
            } else {
                stack.removeLast()
                currentGroup += char
            }
        }
    }
    
    if!stack.isEmpty {
        result.append(currentGroup)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var currentGroup = ""
    
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            if stack.isEmpty {
                result.append(currentGroup)
                currentGroup = ""
            } else {
                stack.removeLast()
                currentGroup += char
            }
        }
    }
    
    if!stack.isEmpty {
        result.append(currentGroup)
    }
    
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var currentGroup = ""
    
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            if stack.isEmpty || stack.last!= "(" {
                return []
            } else {
                stack.removeLast()
            }
        } else {
            currentGroup.append(char)
        }
        
        if stack.isEmpty {
            result.append(currentGroup)
            currentGroup = ""
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var currentGroup = ""
    
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            if stack.isEmpty || stack.last!= "(" {
                return []
            } else {
                stack.removeLast()
            }
        } else {
            currentGroup.append(char)
        }
        
        if stack.isEmpty {
            result.append(currentGroup)
            currentGroup = ""
        }
    }
    
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var currentGroup = ""
    
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            if stack.isEmpty {
                result.append(currentGroup)
                currentGroup = ""
            } else {
                stack.removeLast()
                currentGroup += char
            }
        }
    }
    
    if!stack.isEmpty {
        result.append(currentGroup)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var currentGroup = ""
    
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            if stack.isEmpty {
                result.append(currentGroup)
                currentGroup = ""
            } else {
                stack.removeLast()
                currentGroup += char
            }
        }
    }
    
    if!stack.isEmpty {
        result.append(currentGroup)
    }
    
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var currentGroup = ""
    
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            if stack.isEmpty || stack.last!= "(" {
                return []
            }
            stack.removeLast()
            if stack.isEmpty {
                result.append(currentGroup)
                currentGroup = ""
            }
        } else {
            currentGroup.append(char)
        }
    }
    
    if!stack.isEmpty {
        return []
    }
    
    result.append(currentGroup)
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    var currentGroup = ""
    
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            if stack.isEmpty || stack.last!= "(" {
                return []
            }
            stack.removeLast()
            if stack.isEmpty {
                result.append(currentGroup)
                currentGroup = ""
            }
        } else {
            currentGroup.append(char)
        }
    }
    
    if!stack.isEmpty {
        return []
    }
    
    result.append(currentGroup)
    
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            if stack.last == "(" {
                stack.removeLast()
            } else {
                stack.append(char)
            }
        } else {
            stack.append(char)
        }
        
        if stack.count == 0 {
            let group = String(stack)
            result.append(group)
            stack.removeAll()
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            if stack.last == "(" {
                stack.removeLast()
            } else {
                stack.append(char)
            }
        } else {
            stack.append(char)
        }
        
        if stack.count == 0 {
            let group = String(stack)
            result.append(group)
            stack.removeAll()
        }
    }
    
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            if stack.last == "(" {
                stack.removeLast()
            } else {
                stack.append(char)
            }
        } else if char == " " {
            continue
        } else {
            result.append(String(char))
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var stack = [Character]()
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            if stack.last == "(" {
                stack.removeLast()
            } else {
                stack.append(char)
            }
        } else if char == " " {
            continue
        } else {
            result.append(String(char))
        }
    }
    return result
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    return number - Int(number)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    return number - Int(number)
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = floor(number)
    let decimalPart = number - integerPart
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = floor(number)
    let decimalPart = number - integerPart
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    return number - floor(number)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    return number - floor(number)
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDifferences = numbers.map { abs($0 - mean) }
    let averageAbsoluteDifferences = absoluteDifferences.reduce(0, +) / Double(absoluteDifferences.count)
    return averageAbsoluteDifferences
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDifferences = numbers.map { abs($0 - mean) }
    let averageAbsoluteDifferences = absoluteDifferences.reduce(0, +) / Double(absoluteDifferences.count)
    return averageAbsoluteDifferences
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDifferences = numbers.map { abs($0 - mean) }
    let averageAbsoluteDifferences = absoluteDifferences.reduce(0, +) / Double(absoluteDifferences.count)
    return averageAbsoluteDifferences
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDifferences = numbers.map { abs($0 - mean) }
    let averageAbsoluteDifferences = absoluteDifferences.reduce(0, +) / Double(absoluteDifferences.count)
    return averageAbsoluteDifferences
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDifferences = numbers.map { abs($0 - mean) }
    let averageAbsoluteDifferences = absoluteDifferences.reduce(0, +) / Double(absoluteDifferences.count)
    return averageAbsoluteDifferences
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDifferences = numbers.map { abs($0 - mean) }
    let averageAbsoluteDifferences = absoluteDifferences.reduce(0, +) / Double(absoluteDifferences.count)
    return averageAbsoluteDifferences
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0.0, { $0 + $1 }) / Double(numbers.count)
    let absoluteDifferences = numbers.map { abs($0 - mean) }
    let averageAbsoluteDifferences = absoluteDifferences.reduce(0.0, { $0 + $1 }) / Double(absoluteDifferences.count)
    return averageAbsoluteDifferences
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0.0, { $0 + $1 }) / Double(numbers.count)
    let absoluteDifferences = numbers.map { abs($0 - mean) }
    let averageAbsoluteDifferences = absoluteDifferences.reduce(0.0, { $0 + $1 }) / Double(absoluteDifferences.count)
    return averageAbsoluteDifferences
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0.0, { $0 + $1 }) / Double(numbers.count)
    let absoluteDifferences = numbers.map { abs($0 - mean) }
    let averageAbsoluteDifferences = absoluteDifferences.reduce(0.0, { $0 + $1 }) / Double(absoluteDifferences.count)
    return averageAbsoluteDifferences
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0.0, { $0 + $1 }) / Double(numbers.count)
    let absoluteDifferences = numbers.map { abs($0 - mean) }
    let averageAbsoluteDifferences = absoluteDifferences.reduce(0.0, { $0 + $1 }) / Double(absoluteDifferences.count)
    return averageAbsoluteDifferences
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDifferences = numbers.map { abs($0 - mean) }
    let averageAbsoluteDifferences = absoluteDifferences.reduce(0, +) / Double(absoluteDifferences.count)
    return averageAbsoluteDifferences
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDifferences = numbers.map { abs($0 - mean) }
    let averageAbsoluteDifferences = absoluteDifferences.reduce(0, +) / Double(absoluteDifferences.count)
    return averageAbsoluteDifferences
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDifferences = numbers.map { abs($0 - mean) }
    let averageAbsoluteDifferences = absoluteDifferences.reduce(0, +) / Double(absoluteDifferences.count)
    return averageAbsoluteDifferences
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDifferences = numbers.map { abs($0 - mean) }
    let averageAbsoluteDifferences = absoluteDifferences.reduce(0, +) / Double(absoluteDifferences.count)
    return averageAbsoluteDifferences
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDifferences = numbers.map { abs($0 - mean) }
    let averageAbsoluteDifferences = absoluteDifferences.reduce(0, +) / Double(absoluteDifferences.count)
    return averageAbsoluteDifferences
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDifferences = numbers.map { abs($0 - mean) }
    let averageAbsoluteDifferences = absoluteDifferences.reduce(0, +) / Double(absoluteDifferences.count)
    return averageAbsoluteDifferences
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDifferences = numbers.map { abs($0 - mean) }
    let averageAbsoluteDifferences = absoluteDifferences.reduce(0, +) / Double(absoluteDifferences.count)
    return averageAbsoluteDifferences
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDifferences = numbers.map { abs($0 - mean) }
    let averageAbsoluteDifferences = absoluteDifferences.reduce(0, +) / Double(absoluteDifferences.count)
    return averageAbsoluteDifferences
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0.0, { $0 + $1 }) / Double(numbers.count)
    let absoluteDifferences = numbers.map { abs($0 - mean) }
    let averageAbsoluteDifferences = absoluteDifferences.reduce(0.0, { $0 + $1 }) / Double(absoluteDifferences.count)
    return averageAbsoluteDifferences
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0.0, { $0 + $1 }) / Double(numbers.count)
    let absoluteDifferences = numbers.map { abs($0 - mean) }
    let averageAbsoluteDifferences = absoluteDifferences.reduce(0.0, { $0 + $1 }) / Double(absoluteDifferences.count)
    return averageAbsoluteDifferences
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        if index > 0 {
            result.append(delimeter)
        }
        result.append(number)
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        if index > 0 {
            result.append(delimeter)
        }
        result.append(number)
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        if index > 0 {
            result.append(delimeter)
        }
        result.append(number)
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        if index > 0 {
            result.append(delimeter)
        }
        result.append(number)
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        if index > 0 {
            result.append(delimeter)
        }
        result.append(number)
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        if index > 0 {
            result.append(delimeter)
        }
        result.append(number)
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        if index > 0 {
            result.append(delimeter)
        }
        result.append(number)
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        if index > 0 {
            result.append(delimeter)
        }
        result.append(number)
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        if index > 0 {
            result.append(delimeter)
        }
        result.append(number)
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        if index > 0 {
            result.append(delimeter)
        }
        result.append(number)
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var stack = [Int]()
    var currentDepth = 0
    
    for char in parenString {
        if char == "(" {
            stack.append(currentDepth)
            currentDepth += 1
        } else if char == ")" {
            currentDepth = stack.popLast()?? 0
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var stack = [Int]()
    var currentDepth = 0
    
    for char in parenString {
        if char == "(" {
            stack.append(currentDepth)
            currentDepth += 1
        } else if char == ")" {
            currentDepth = stack.popLast()?? 0
        }
    }
    
    return result
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var result: [Int] = []
    var stack: [Int] = []
    var maxDepth: Int = 0
    
    for char in parenString {
        if char == "(" {
            stack.append(maxDepth)
            maxDepth += 1
        } else if char == ")" {
            maxDepth = stack.popLast()?? 0
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result: [Int] = []
    var stack: [Int] = []
    var maxDepth: Int = 0
    
    for char in parenString {
        if char == "(" {
            stack.append(maxDepth)
            maxDepth += 1
        } else if char == ")" {
            maxDepth = stack.popLast()?? 0
        }
    }
    
    return result
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var levels = [Int]()
    var currentLevel = 0
    var inParens = false
    
    for char in parenString {
        if char == "(" {
            inParens = true
            currentLevel += 1
        } else if char == ")" {
            inParens = false
            levels.append(currentLevel)
            currentLevel -= 1
        }
    }
    
    return levels
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var levels = [Int]()
    var currentLevel = 0
    var inParens = false
    
    for char in parenString {
        if char == "(" {
            inParens = true
            currentLevel += 1
        } else if char == ")" {
            inParens = false
            levels.append(currentLevel)
            currentLevel -= 1
        }
    }
    
    return levels
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var stack = [Int]()
    var currentDepth = 0
    
    for char in parenString {
        if char == "(" {
            stack.append(currentDepth)
            currentDepth += 1
        } else if char == ")" {
            currentDepth = stack.popLast()?? 0
        }
    }
    
    return stack
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var stack = [Int]()
    var currentDepth = 0
    
    for char in parenString {
        if char == "(" {
            stack.append(currentDepth)
            currentDepth += 1
        } else if char == ")" {
            currentDepth = stack.popLast()?? 0
        }
    }
    
    return stack
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var stack = [Int]()
    var maxDepth = 0
    
    for (index, char) in parenString.enumerated() {
        if char == "(" {
            stack.append(index)
        } else if char == ")" {
            if stack.isEmpty {
                result.append(0)
            } else {
                let depth = stack.popLast()!
                result[depth] = max(result[depth], index - depth)
                maxDepth = max(maxDepth, index - depth)
            }
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var stack = [Int]()
    var maxDepth = 0
    
    for (index, char) in parenString.enumerated() {
        if char == "(" {
            stack.append(index)
        } else if char == ")" {
            if stack.isEmpty {
                result.append(0)
            } else {
                let depth = stack.popLast()!
                result[depth] = max(result[depth], index - depth)
                maxDepth = max(maxDepth, index - depth)
            }
        }
    }
    
    return result
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var result: [Int] = []
    var stack: [Int] = []
    
    for (index, char) in parenString.enumerated() {
        if char == "(" {
            stack.append(index)
        } else if char == ")" {
            if stack.isEmpty {
                result.append(0)
            } else {
                let maxIndex = stack.removeLast()
                let maxLevel = result[maxIndex]
                result[maxIndex] = max(maxLevel, index - maxIndex)
            }
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result: [Int] = []
    var stack: [Int] = []
    
    for (index, char) in parenString.enumerated() {
        if char == "(" {
            stack.append(index)
        } else if char == ")" {
            if stack.isEmpty {
                result.append(0)
            } else {
                let maxIndex = stack.removeLast()
                let maxLevel = result[maxIndex]
                result[maxIndex] = max(maxLevel, index - maxIndex)
            }
        }
    }
    
    return result
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var stack = [Int]()
    var maxDepth = 0
    
    for (index, char) in parenString.enumerated() {
        if char == "(" {
            stack.append(index)
        } else if char == ")" {
            if stack.isEmpty {
                result.append(0)
            } else {
                let depth = stack.popLast()!
                result[depth] = max(result[depth], index - depth)
                maxDepth = max(maxDepth, index - depth)
            }
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var stack = [Int]()
    var maxDepth = 0
    
    for (index, char) in parenString.enumerated() {
        if char == "(" {
            stack.append(index)
        } else if char == ")" {
            if stack.isEmpty {
                result.append(0)
            } else {
                let depth = stack.popLast()!
                result[depth] = max(result[depth], index - depth)
                maxDepth = max(maxDepth, index - depth)
            }
        }
    }
    
    return result
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var stack = [Int]()

    for (index, char) in parenString.enumerated() {
        if char == "(" {
            stack.append(index)
        } else if char == ")" {
            if stack.isEmpty {
                result.append(0)
            } else {
                let openingIndex = stack.removeLast()
                let nestingLevel = index - openingIndex - 1
                result.append(nestingLevel)
            }
        }
    }

    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var stack = [Int]()

    for (index, char) in parenString.enumerated() {
        if char == "(" {
            stack.append(index)
        } else if char == ")" {
            if stack.isEmpty {
                result.append(0)
            } else {
                let openingIndex = stack.removeLast()
                let nestingLevel = index - openingIndex - 1
                result.append(nestingLevel)
            }
        }
    }

    return result
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var stack = [Int]()
    
    for (index, char) in parenString.enumerated() {
        if char == "(" {
            stack.append(index)
        } else if char == ")" {
            if stack.isEmpty {
                result.append(0)
            } else {
                let lastIndex = stack.removeLast()
                result[lastIndex] = max(result[lastIndex], index - lastIndex)
            }
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var stack = [Int]()
    
    for (index, char) in parenString.enumerated() {
        if char == "(" {
            stack.append(index)
        } else if char == ")" {
            if stack.isEmpty {
                result.append(0)
            } else {
                let lastIndex = stack.removeLast()
                result[lastIndex] = max(result[lastIndex], index - lastIndex)
            }
        }
    }
    
    return result
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var levels = [Int]()
    var currentLevel = 0
    var inParens = false
    
    for char in parenString {
        if char == "(" {
            inParens = true
            currentLevel += 1
        } else if char == ")" {
            inParens = false
            levels.append(currentLevel)
            currentLevel -= 1
        }
    }
    
    return levels
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var levels = [Int]()
    var currentLevel = 0
    var inParens = false
    
    for char in parenString {
        if char == "(" {
            inParens = true
            currentLevel += 1
        } else if char == ")" {
            inParens = false
            levels.append(currentLevel)
            currentLevel -= 1
        }
    }
    
    return levels
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var maxElement = numbers[0]
    var result = [Int]()
    
    for number in numbers {
        maxElement = max(maxElement, number)
        result.append(maxElement)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var maxElement = numbers[0]
    var result = [Int]()
    
    for number in numbers {
        maxElement = max(maxElement, number)
        result.append(maxElement)
    }
    
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var maxElement = numbers[0]
    var rollingMax = [Int]()
    
    for number in numbers {
        maxElement = max(maxElement, number)
        rollingMax.append(maxElement)
    }
    
    return rollingMax
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var maxElement = numbers[0]
    var rollingMax = [Int]()
    
    for number in numbers {
        maxElement = max(maxElement, number)
        rollingMax.append(maxElement)
    }
    
    return rollingMax
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var maxElement = numbers.first!
    var result = [maxElement]
    
    for number in numbers.dropFirst() {
        if number > maxElement {
            maxElement = number
        }
        result.append(maxElement)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var maxElement = numbers.first!
    var result = [maxElement]
    
    for number in numbers.dropFirst() {
        if number > maxElement {
            maxElement = number
        }
        result.append(maxElement)
    }
    
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var maxElement = numbers.first!
    var result = [Int]()
    
    for number in numbers {
        if number > maxElement {
            maxElement = number
        }
        result.append(maxElement)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var maxElement = numbers.first!
    var result = [Int]()
    
    for number in numbers {
        if number > maxElement {
            maxElement = number
        }
        result.append(maxElement)
    }
    
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var maxElement = numbers.first!
    var result = [Int]()
    
    for number in numbers {
        maxElement = max(maxElement, number)
        result.append(maxElement)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var maxElement = numbers.first!
    var result = [Int]()
    
    for number in numbers {
        maxElement = max(maxElement, number)
        result.append(maxElement)
    }
    
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var maxElement = numbers[0]
    var result = [Int]()
    
    for number in numbers {
        maxElement = max(maxElement, number)
        result.append(maxElement)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var maxElement = numbers[0]
    var result = [Int]()
    
    for number in numbers {
        maxElement = max(maxElement, number)
        result.append(maxElement)
    }
    
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var maxElement = numbers[0]
    var result = [Int]()
    
    for number in numbers {
        maxElement = max(maxElement, number)
        result.append(maxElement)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var maxElement = numbers[0]
    var result = [Int]()
    
    for number in numbers {
        maxElement = max(maxElement, number)
        result.append(maxElement)
    }
    
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var maxElement = numbers[0]
    var result = [Int]()
    
    for number in numbers {
        maxElement = max(maxElement, number)
        result.append(maxElement)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var maxElement = numbers[0]
    var result = [Int]()
    
    for number in numbers {
        maxElement = max(maxElement, number)
        result.append(maxElement)
    }
    
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var maxElement = numbers[0]
    var result = [Int]()
    
    for number in numbers {
        if number > maxElement {
            maxElement = number
        }
        result.append(maxElement)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var maxElement = numbers[0]
    var result = [Int]()
    
    for number in numbers {
        if number > maxElement {
            maxElement = number
        }
        result.append(maxElement)
    }
    
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var maxElement = numbers.first!
    var result = [Int]()
    
    for number in numbers {
        maxElement = max(maxElement, number)
        result.append(maxElement)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var maxElement = numbers.first!
    var result = [Int]()
    
    for number in numbers {
        maxElement = max(maxElement, number)
        result.append(maxElement)
    }
    
    return result
}
```

func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    let longestPalindrome = longestPalindrome(string: string)
    let prefix = String(string.prefix(upTo: string.index(string.startIndex, offsetBy: string.count - longestPalindrome.count)))
    return prefix + reversed
}

func longestPalindrome(string: String) -> String {
    var longestPalindrome = ""
    for i in 0..<string.count {
        for j in i..<string.count {
            let substring = String(string[i..<j])
            if substring == String(substring.reversed()) && substring.count > longestPalindrome.count {
                longestPalindrome = substring
            }
        }
    }
    return longestPalindrome
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    let longestPalindrome = longestPalindrome(string: string)
    let prefix = String(string.prefix(upTo: string.index(string.startIndex, offsetBy: string.count - longestPalindrome.count)))
    return prefix + reversed
}

func longestPalindrome(string: String) -> String {
    var longestPalindrome = ""
    for i in 0..<string.count {
        for j in i..<string.count {
            let substring = String(string[i..<j])
            if substring == String(substring.reversed()) && substring.count > longestPalindrome.count {
                longestPalindrome = substring
            }
        }
    }
    return longestPalindrome
}
```

func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    let longestPalindrome = longestPalindrome(string: string)
    let prefix = String(string.prefix(upTo: string.index(string.startIndex, offsetBy: string.count - longestPalindrome.count)))
    return prefix + reversed
}

func longestPalindrome(string: String) -> String {
    var longestPalindrome = ""
    for i in 0..<string.count {
        for j in i..<string.count {
            let substring = String(string[i..<j])
            if substring == substring.reversed() && substring.count > longestPalindrome.count {
                longestPalindrome = substring
            }
        }
    }
    return longestPalindrome
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    let longestPalindrome = longestPalindrome(string: string)
    let prefix = String(string.prefix(upTo: string.index(string.startIndex, offsetBy: string.count - longestPalindrome.count)))
    return prefix + reversed
}

func longestPalindrome(string: String) -> String {
    var longestPalindrome = ""
    for i in 0..<string.count {
        for j in i..<string.count {
            let substring = String(string[i..<j])
            if substring == substring.reversed() && substring.count > longestPalindrome.count {
                longestPalindrome = substring
            }
        }
    }
    return longestPalindrome
}
```

func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    let longestPalindrome = longestPalindrome(string: string)
    let prefix = String(string.prefix(upTo: string.index(string.startIndex, offsetBy: string.count - longestPalindrome.count)))
    return prefix + reversed
}

func longestPalindrome(string: String) -> String {
    var longestPalindrome = ""
    for i in 0..<string.count {
        for j in i..<string.count {
            let substring = String(string[i..<j])
            if substring == substring.reversed() && substring.count > longestPalindrome.count {
                longestPalindrome = substring
            }
        }
    }
    return longestPalindrome
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    let longestPalindrome = longestPalindrome(string: string)
    let prefix = String(string.prefix(upTo: string.index(string.startIndex, offsetBy: string.count - longestPalindrome.count)))
    return prefix + reversed
}

func longestPalindrome(string: String) -> String {
    var longestPalindrome = ""
    for i in 0..<string.count {
        for j in i..<string.count {
            let substring = String(string[i..<j])
            if substring == substring.reversed() && substring.count > longestPalindrome.count {
                longestPalindrome = substring
            }
        }
    }
    return longestPalindrome
}
```

func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    let longestPalindrome = longestPalindrome(string: string)
    let prefix = String(string.prefix(upTo: string.index(string.startIndex, offsetBy: string.count - longestPalindrome.count)))
    return prefix + reversed
}

func longestPalindrome(string: String) -> String {
    var longestPalindrome = ""
    for i in 0..<string.count {
        for j in i..<string.count {
            let substring = String(string[i..<j])
            if substring == substring.reversed() && substring.count > longestPalindrome.count {
                longestPalindrome = substring
            }
        }
    }
    return longestPalindrome
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    let longestPalindrome = longestPalindrome(string: string)
    let prefix = String(string.prefix(upTo: string.index(string.startIndex, offsetBy: string.count - longestPalindrome.count)))
    return prefix + reversed
}

func longestPalindrome(string: String) -> String {
    var longestPalindrome = ""
    for i in 0..<string.count {
        for j in i..<string.count {
            let substring = String(string[i..<j])
            if substring == substring.reversed() && substring.count > longestPalindrome.count {
                longestPalindrome = substring
            }
        }
    }
    return longestPalindrome
}
```

func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    let longestPalindrome = longestPalindrome(string: string)
    let prefix = String(string.prefix(while: { $0 == reversed[$0.distance(to: string.endIndex)] }))
    return prefix + reversed
}

func longestPalindrome(string: String) -> String {
    var longestPalindrome = ""
    for i in 0..<string.count {
        for j in i..<string.count {
            let substring = String(string[i..<j])
            if substring == substring.reversed() && substring.count > longestPalindrome.count {
                longestPalindrome = substring
            }
        }
    }
    return longestPalindrome
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    let longestPalindrome = longestPalindrome(string: string)
    let prefix = String(string.prefix(while: { $0 == reversed[$0.distance(to: string.endIndex)] }))
    return prefix + reversed
}

func longestPalindrome(string: String) -> String {
    var longestPalindrome = ""
    for i in 0..<string.count {
        for j in i..<string.count {
            let substring = String(string[i..<j])
            if substring == substring.reversed() && substring.count > longestPalindrome.count {
                longestPalindrome = substring
            }
        }
    }
    return longestPalindrome
}
```

func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    let longestPalindrome = longestPalindrome(string: string)
    let prefix = String(string.prefix(upTo: string.index(string.startIndex, offsetBy: string.count - longestPalindrome.count)))
    return prefix + reversed
}

func longestPalindrome(string: String) -> String {
    var longestPalindrome = ""
    for i in 0..<string.count {
        for j in i..<string.count {
            let substring = String(string[i..<j])
            if substring == String(substring.reversed()) && substring.count > longestPalindrome.count {
                longestPalindrome = substring
            }
        }
    }
    return longestPalindrome
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    let longestPalindrome = longestPalindrome(string: string)
    let prefix = String(string.prefix(upTo: string.index(string.startIndex, offsetBy: string.count - longestPalindrome.count)))
    return prefix + reversed
}

func longestPalindrome(string: String) -> String {
    var longestPalindrome = ""
    for i in 0..<string.count {
        for j in i..<string.count {
            let substring = String(string[i..<j])
            if substring == String(substring.reversed()) && substring.count > longestPalindrome.count {
                longestPalindrome = substring
            }
        }
    }
    return longestPalindrome
}
```

func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    let longestPalindrome = longestPalindrome(string: string)
    let prefix = String(string.prefix(upTo: string.index(string.startIndex, offsetBy: string.count - longestPalindrome.count)))
    return prefix + reversed
}

func longestPalindrome(string: String) -> String {
    var longestPalindrome = ""
    for i in 0..<string.count {
        for j in i..<string.count {
            let substring = String(string[i..<j])
            if substring == substring.reversed() && substring.count > longestPalindrome.count {
                longestPalindrome = substring
            }
        }
    }
    return longestPalindrome
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    let longestPalindrome = longestPalindrome(string: string)
    let prefix = String(string.prefix(upTo: string.index(string.startIndex, offsetBy: string.count - longestPalindrome.count)))
    return prefix + reversed
}

func longestPalindrome(string: String) -> String {
    var longestPalindrome = ""
    for i in 0..<string.count {
        for j in i..<string.count {
            let substring = String(string[i..<j])
            if substring == substring.reversed() && substring.count > longestPalindrome.count {
                longestPalindrome = substring
            }
        }
    }
    return longestPalindrome
}
```

func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    let longestPalindrome = longestPalindrome(string: string)
    let prefix = String(string.prefix(upTo: string.index(string.startIndex, offsetBy: string.count - longestPalindrome.count)))
    return prefix + reversed
}

func longestPalindrome(string: String) -> String {
    var longestPalindrome = ""
    for i in 0..<string.count {
        for j in i..<string.count {
            let substring = String(string[i..<j])
            if substring == substring.reversed() && substring.count > longestPalindrome.count {
                longestPalindrome = substring
            }
        }
    }
    return longestPalindrome
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    let longestPalindrome = longestPalindrome(string: string)
    let prefix = String(string.prefix(upTo: string.index(string.startIndex, offsetBy: string.count - longestPalindrome.count)))
    return prefix + reversed
}

func longestPalindrome(string: String) -> String {
    var longestPalindrome = ""
    for i in 0..<string.count {
        for j in i..<string.count {
            let substring = String(string[i..<j])
            if substring == substring.reversed() && substring.count > longestPalindrome.count {
                longestPalindrome = substring
            }
        }
    }
    return longestPalindrome
}
```

func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    let longestPalindrome = longestPalindrome(string: string)
    let prefix = String(string.prefix(while: {!$0 == reversed[$0.distance(to: string.endIndex)] }))
    return prefix + reversed
}

func longestPalindrome(string: String) -> String {
    var longestPalindrome = ""
    for i in 0..<string.count {
        for j in i..<string.count {
            let substring = String(string[i..<j])
            if substring == substring.reversed() && substring.count > longestPalindrome.count {
                longestPalindrome = substring
            }
        }
    }
    return longestPalindrome
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    let longestPalindrome = longestPalindrome(string: string)
    let prefix = String(string.prefix(while: {!$0 == reversed[$0.distance(to: string.endIndex)] }))
    return prefix + reversed
}

func longestPalindrome(string: String) -> String {
    var longestPalindrome = ""
    for i in 0..<string.count {
        for j in i..<string.count {
            let substring = String(string[i..<j])
            if substring == substring.reversed() && substring.count > longestPalindrome.count {
                longestPalindrome = substring
            }
        }
    }
    return longestPalindrome
}
```

func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    let longestPalindrome = longestPalindrome(string: string)
    let prefix = String(string.prefix(while: { $0 == reversed[$0.distance(to: string.endIndex)] }))
    return prefix + reversed
}

func longestPalindrome(string: String) -> String {
    var longestPalindrome = ""
    for i in 0..<string.count {
        for j in i..<string.count {
            let substring = String(string[i..<j])
            if substring == substring.reversed() && substring.count > longestPalindrome.count {
                longestPalindrome = substring
            }
        }
    }
    return longestPalindrome
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    let longestPalindrome = longestPalindrome(string: string)
    let prefix = String(string.prefix(while: { $0 == reversed[$0.distance(to: string.endIndex)] }))
    return prefix + reversed
}

func longestPalindrome(string: String) -> String {
    var longestPalindrome = ""
    for i in 0..<string.count {
        for j in i..<string.count {
            let substring = String(string[i..<j])
            if substring == substring.reversed() && substring.count > longestPalindrome.count {
                longestPalindrome = substring
            }
        }
    }
    return longestPalindrome
}
```

func stringXor(a: String, b: String) -> String {
    let aAsBits = Array(a.reversed())
    let bAsBits = Array(b.reversed())
    
    var result = ""
    
    for i in 0..<max(aAsBits.count, bAsBits.count) {
        let aBit = aAsBits.count > i? aAsBits[i] : "0"
        let bBit = bAsBits.count > i? bAsBits[i] : "0"
        
        let xorBit = aBit == "1"? (bBit == "1"? "0" : "1") : (bBit == "1"? "1" : "0")
        
        result = "\(xorBit)\(result)"
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aAsBits = Array(a.reversed())
    let bAsBits = Array(b.reversed())
    
    var result = ""
    
    for i in 0..<max(aAsBits.count, bAsBits.count) {
        let aBit = aAsBits.count > i? aAsBits[i] : "0"
        let bBit = bAsBits.count > i? bAsBits[i] : "0"
        
        let xorBit = aBit == "1"? (bBit == "1"? "0" : "1") : (bBit == "1"? "1" : "0")
        
        result = "\(xorBit)\(result)"
    }
    
    return result
}
```

func stringXor(a: String, b: String) -> String {
    let aAsBits = Array(a.reversed())
    let bAsBits = Array(b.reversed())
    
    var result = ""
    
    for i in 0..<max(aAsBits.count, bAsBits.count) {
        let aBit = aAsBits.count > i? aAsBits[i] : "0"
        let bBit = bAsBits.count > i? bAsBits[i] : "0"
        
        let xorBit = (aBit == "1" && bBit == "0") || (aBit == "0" && bBit == "1")? "1" : "0"
        
        result = "\(xorBit)\(result)"
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aAsBits = Array(a.reversed())
    let bAsBits = Array(b.reversed())
    
    var result = ""
    
    for i in 0..<max(aAsBits.count, bAsBits.count) {
        let aBit = aAsBits.count > i? aAsBits[i] : "0"
        let bBit = bAsBits.count > i? bAsBits[i] : "0"
        
        let xorBit = (aBit == "1" && bBit == "0") || (aBit == "0" && bBit == "1")? "1" : "0"
        
        result = "\(xorBit)\(result)"
    }
    
    return result
}
```

func stringXor(a: String, b: String) -> String {
    let aAsBits = Array(a.reversed())
    let bAsBits = Array(b.reversed())
    
    var result = Array(repeating: 0, count: max(aAsBits.count, bAsBits.count))
    
    for i in 0..<result.count {
        let aBit = aAsBits.count > i? aAsBits[i] : 0
        let bBit = bAsBits.count > i? bAsBits[i] : 0
        
        result[i] = aBit ^ bBit
    }
    
    return String(result.reversed())
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aAsBits = Array(a.reversed())
    let bAsBits = Array(b.reversed())
    
    var result = Array(repeating: 0, count: max(aAsBits.count, bAsBits.count))
    
    for i in 0..<result.count {
        let aBit = aAsBits.count > i? aAsBits[i] : 0
        let bBit = bAsBits.count > i? bAsBits[i] : 0
        
        result[i] = aBit ^ bBit
    }
    
    return String(result.reversed())
}
```

func stringXor(a: String, b: String) -> String {
    let aAsBits = Array(a.reversed())
    let bAsBits = Array(b.reversed())
    
    var resultBits = Array(repeating: 0, count: max(aAsBits.count, bAsBits.count))
    
    for i in 0..<resultBits.count {
        if aAsBits.count > i {
            resultBits[i] ^= aAsBits[i]
        }
        if bAsBits.count > i {
            resultBits[i] ^= bAsBits[i]
        }
    }
    
    return String(resultBits.reversed())
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aAsBits = Array(a.reversed())
    let bAsBits = Array(b.reversed())
    
    var resultBits = Array(repeating: 0, count: max(aAsBits.count, bAsBits.count))
    
    for i in 0..<resultBits.count {
        if aAsBits.count > i {
            resultBits[i] ^= aAsBits[i]
        }
        if bAsBits.count > i {
            resultBits[i] ^= bAsBits[i]
        }
    }
    
    return String(resultBits.reversed())
}
```

func stringXor(a: String, b: String) -> String {
    guard a.count == b.count else {
        return ""
    }
    
    var result = ""
    for i in 0..<a.count {
        let aChar = a[a.index(a.startIndex, offsetBy: i)]
        let bChar = b[b.index(b.startIndex, offsetBy: i)]
        
        let xorResult = Int(String(aChar))! ^ Int(String(bChar))!
        result += String(xorResult)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    guard a.count == b.count else {
        return ""
    }
    
    var result = ""
    for i in 0..<a.count {
        let aChar = a[a.index(a.startIndex, offsetBy: i)]
        let bChar = b[b.index(b.startIndex, offsetBy: i)]
        
        let xorResult = Int(String(aChar))! ^ Int(String(bChar))!
        result += String(xorResult)
    }
    
    return result
}
```

func stringXor(a: String, b: String) -> String {
    let aAsBits = Array(a.reversed())
    let bAsBits = Array(b.reversed())
    
    var result = ""
    
    for i in 0..<max(aAsBits.count, bAsBits.count) {
        let aBit = aAsBits.count > i? aAsBits[i] : "0"
        let bBit = bAsBits.count > i? bAsBits[i] : "0"
        
        let xorBit = (aBit == "1" && bBit == "0") || (aBit == "0" && bBit == "1")? "1" : "0"
        
        result = "\(xorBit)\(result)"
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aAsBits = Array(a.reversed())
    let bAsBits = Array(b.reversed())
    
    var result = ""
    
    for i in 0..<max(aAsBits.count, bAsBits.count) {
        let aBit = aAsBits.count > i? aAsBits[i] : "0"
        let bBit = bAsBits.count > i? bAsBits[i] : "0"
        
        let xorBit = (aBit == "1" && bBit == "0") || (aBit == "0" && bBit == "1")? "1" : "0"
        
        result = "\(xorBit)\(result)"
    }
    
    return result
}
```

func stringXor(a: String, b: String) -> String {
    let aInt = Int(a, radix: 2)!
    let bInt = Int(b, radix: 2)!
    let resultInt = aInt ^ bInt
    return String(resultInt, radix: 2)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aInt = Int(a, radix: 2)!
    let bInt = Int(b, radix: 2)!
    let resultInt = aInt ^ bInt
    return String(resultInt, radix: 2)
}
```

func stringXor(a: String, b: String) -> String {
    guard a.count == b.count else {
        return ""
    }
    
    var result = ""
    for i in 0..<a.count {
        let aChar = a[a.index(a.startIndex, offsetBy: i)]
        let bChar = b[b.index(b.startIndex, offsetBy: i)]
        
        let xorChar = Int(String(aChar))! ^ Int(String(bChar))!
        result += String(xorChar)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    guard a.count == b.count else {
        return ""
    }
    
    var result = ""
    for i in 0..<a.count {
        let aChar = a[a.index(a.startIndex, offsetBy: i)]
        let bChar = b[b.index(b.startIndex, offsetBy: i)]
        
        let xorChar = Int(String(aChar))! ^ Int(String(bChar))!
        result += String(xorChar)
    }
    
    return result
}
```

func stringXor(a: String, b: String) -> String {
    guard a.count == b.count else {
        return ""
    }
    
    var result = ""
    for i in 0..<a.count {
        let bitA = a[a.index(a.startIndex, offsetBy: i)]
        let bitB = b[b.index(b.startIndex, offsetBy: i)]
        
        if bitA == "1" && bitB == "1" {
            result.append("0")
        } else if bitA == "0" && bitB == "0" {
            result.append("0")
        } else {
            result.append("1")
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    guard a.count == b.count else {
        return ""
    }
    
    var result = ""
    for i in 0..<a.count {
        let bitA = a[a.index(a.startIndex, offsetBy: i)]
        let bitB = b[b.index(b.startIndex, offsetBy: i)]
        
        if bitA == "1" && bitB == "1" {
            result.append("0")
        } else if bitA == "0" && bitB == "0" {
            result.append("0")
        } else {
            result.append("1")
        }
    }
    
    return result
}
```

func stringXor(a: String, b: String) -> String {
    guard a.count == b.count else {
        return ""
    }
    
    var result = ""
    for i in 0..<a.count {
        let aChar = a[a.index(a.startIndex, offsetBy: i)]
        let bChar = b[b.index(b.startIndex, offsetBy: i)]
        
        let xorResult = Int(String(aChar))! ^ Int(String(bChar))!
        result += String(xorResult)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    guard a.count == b.count else {
        return ""
    }
    
    var result = ""
    for i in 0..<a.count {
        let aChar = a[a.index(a.startIndex, offsetBy: i)]
        let bChar = b[b.index(b.startIndex, offsetBy: i)]
        
        let xorResult = Int(String(aChar))! ^ Int(String(bChar))!
        result += String(xorResult)
    }
    
    return result
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else {
        return nil
    }
    
    var longestString: String?
    
    for string in strings {
        if longestString == nil || string.count > longestString!.count {
            longestString = string
        }
    }
    
    return longestString
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else {
        return nil
    }
    
    var longestString: String?
    
    for string in strings {
        if longestString == nil || string.count > longestString!.count {
            longestString = string
        }
    }
    
    return longestString
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else {
        return nil
    }
    
    var longestString: String?
    
    for string in strings {
        if longestString == nil || string.count > longestString!.count {
            longestString = string
        }
    }
    
    return longestString
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else {
        return nil
    }
    
    var longestString: String?
    
    for string in strings {
        if longestString == nil || string.count > longestString!.count {
            longestString = string
        }
    }
    
    return longestString
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.sorted { $0.count > $1.count }.first
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.sorted { $0.count > $1.count }.first
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else {
        return nil
    }
    var longest: String?
    for string in strings {
        if longest == nil || string.count > longest!.count {
            longest = string
        }
    }
    return longest
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else {
        return nil
    }
    var longest: String?
    for string in strings {
        if longest == nil || string.count > longest!.count {
            longest = string
        }
    }
    return longest
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else {
        return nil
    }
    
    var longestString: String?
    
    for string in strings {
        if longestString == nil || string.count > longestString!.count {
            longestString = string
        }
    }
    
    return longestString
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else {
        return nil
    }
    
    var longestString: String?
    
    for string in strings {
        if longestString == nil || string.count > longestString!.count {
            longestString = string
        }
    }
    
    return longestString
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    var longest: String?
    for string in strings {
        if longest == nil || string.count > longest!.count {
            longest = string
        }
    }
    return longest
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    var longest: String?
    for string in strings {
        if longest == nil || string.count > longest!.count {
            longest = string
        }
    }
    return longest
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else {
        return nil
    }

    var longestString: String?
    for string in strings {
        if longestString == nil || string.count > longestString!.count {
            longestString = string
        }
    }

    return longestString
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else {
        return nil
    }

    var longestString: String?
    for string in strings {
        if longestString == nil || string.count > longestString!.count {
            longestString = string
        }
    }

    return longestString
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else {
        return nil
    }
    
    var longestString: String?
    
    for string in strings {
        if longestString == nil || string.count > longestString!.count {
            longestString = string
        }
    }
    
    return longestString
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else {
        return nil
    }
    
    var longestString: String?
    
    for string in strings {
        if longestString == nil || string.count > longestString!.count {
            longestString = string
        }
    }
    
    return longestString
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else {
        return nil
    }
    
    var longestString: String?
    
    for string in strings {
        if longestString == nil || string.count > longestString!.count {
            longestString = string
        }
    }
    
    return longestString
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else {
        return nil
    }
    
    var longestString: String?
    
    for string in strings {
        if longestString == nil || string.count > longestString!.count {
            longestString = string
        }
    }
    
    return longestString
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else {
        return nil
    }

    var longestString: String?
    var maxLength = 0

    for string in strings {
        if string.count > maxLength {
            maxLength = string.count
            longestString = string
        }
    }

    return longestString
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else {
        return nil
    }

    var longestString: String?
    var maxLength = 0

    for string in strings {
        if string.count > maxLength {
            maxLength = string.count
            longestString = string
        }
    }

    return longestString
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    } else {
        return greatestCommonDivisor(a: b, b: a % b)
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    } else {
        return greatestCommonDivisor(a: b, b: a % b)
    }
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    }
    return greatestCommonDivisor(a: b, b: a % b)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    }
    return greatestCommonDivisor(a: b, b: a % b)
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    } else {
        return greatestCommonDivisor(a: b, b: a % b)
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    } else {
        return greatestCommonDivisor(a: b, b: a % b)
    }
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    }
    return greatestCommonDivisor(a: b, b: a % b)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    }
    return greatestCommonDivisor(a: b, b: a % b)
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    }
    return greatestCommonDivisor(a: b, b: a % b)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    }
    return greatestCommonDivisor(a: b, b: a % b)
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    }
    return greatestCommonDivisor(a: b, b: a % b)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    }
    return greatestCommonDivisor(a: b, b: a % b)
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    }
    return greatestCommonDivisor(a: b, b: a % b)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    }
    return greatestCommonDivisor(a: b, b: a % b)
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    } else {
        return greatestCommonDivisor(a: b, b: a % b)
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    } else {
        return greatestCommonDivisor(a: b, b: a % b)
    }
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    } else {
        return greatestCommonDivisor(a: b, b: a % b)
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    } else {
        return greatestCommonDivisor(a: b, b: a % b)
    }
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    } else {
        return greatestCommonDivisor(a: b, b: a % b)
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    } else {
        return greatestCommonDivisor(a: b, b: a % b)
    }
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string[0..<i]))
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string[0..<i]))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string[0..<i]))
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string[0..<i]))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string[0..<i]))
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string[0..<i]))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string[0..<i]))
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string[0..<i]))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string[0..<i]))
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string[0..<i]))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string[0..<i]))
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string[0..<i]))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string[0..<i]))
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string[0..<i]))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 0..<string.count {
        let prefix = String(string.prefix(i))
        prefixes.append(prefix)
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 0..<string.count {
        let prefix = String(string.prefix(i))
        prefixes.append(prefix)
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string[0..<i]))
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string[0..<i]))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string[0..<i]))
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string[0..<i]))
    }
    return prefixes
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
```

func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters = Set<Character>()
    for character in string {
        distinctCharacters.insert(character.lowercased())
    }
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters = Set<Character>()
    for character in string {
        distinctCharacters.insert(character.lowercased())
    }
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters = Set<Character>()
    for character in string {
        distinctCharacters.insert(character.lowercased())
    }
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters = Set<Character>()
    for character in string {
        distinctCharacters.insert(character.lowercased())
    }
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters = Set<Character>()
    for character in string {
        distinctCharacters.insert(character.lowercased())
    }
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters = Set<Character>()
    for character in string {
        distinctCharacters.insert(character.lowercased())
    }
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters = Set<Character>()
    for character in string {
        distinctCharacters.insert(character.lowercased())
    }
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters = Set<Character>()
    for character in string {
        distinctCharacters.insert(character.lowercased())
    }
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters = Set<Character>()
    for character in string {
        distinctCharacters.insert(character.lowercased())
    }
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters = Set<Character>()
    for character in string {
        distinctCharacters.insert(character.lowercased())
    }
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters = Set<Character>()
    
    for character in string {
        distinctCharacters.insert(character.lowercased())
    }
    
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters = Set<Character>()
    
    for character in string {
        distinctCharacters.insert(character.lowercased())
    }
    
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters = Set<Character>()
    for character in string {
        distinctCharacters.insert(character.lowercased())
    }
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters = Set<Character>()
    for character in string {
        distinctCharacters.insert(character.lowercased())
    }
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters = Set<Character>()
    
    for character in string {
        distinctCharacters.insert(character.lowercased())
    }
    
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters = Set<Character>()
    
    for character in string {
        distinctCharacters.insert(character.lowercased())
    }
    
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters = Set<Character>()
    
    for character in string {
        distinctCharacters.insert(character.lowercased())
    }
    
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters = Set<Character>()
    
    for character in string {
        distinctCharacters.insert(character.lowercased())
    }
    
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters = Set<Character>()
    
    for character in string {
        distinctCharacters.insert(character.lowercased())
    }
    
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters = Set<Character>()
    
    for character in string {
        distinctCharacters.insert(character.lowercased())
    }
    
    return distinctCharacters.count
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var noteLength = 4
    
    for char in musicString {
        if char == "o" {
            beats.append(noteLength)
        } else if char == "o|" {
            noteLength = 2
        } else if char == ".|" {
            noteLength = 1
        }
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var noteLength = 4
    
    for char in musicString {
        if char == "o" {
            beats.append(noteLength)
        } else if char == "o|" {
            noteLength = 2
        } else if char == ".|" {
            noteLength = 1
        }
    }
    
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentBeat = 0
    
    for note in musicString {
        switch note {
        case "o":
            currentBeat += 4
        case "o|":
            currentBeat += 2
        case ".|":
            currentBeat += 1
        default:
            break
        }
        beats.append(currentBeat)
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentBeat = 0
    
    for note in musicString {
        switch note {
        case "o":
            currentBeat += 4
        case "o|":
            currentBeat += 2
        case ".|":
            currentBeat += 1
        default:
            break
        }
        beats.append(currentBeat)
    }
    
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentBeat = 0
    var currentNote = 0
    
    for char in musicString {
        if char == "o" {
            currentBeat += 4
        } else if char == "o|" {
            currentBeat += 2
        } else if char == ".|" {
            currentBeat += 1
        } else if char == "|" {
            beats.append(currentBeat)
            currentBeat = 0
        }
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentBeat = 0
    var currentNote = 0
    
    for char in musicString {
        if char == "o" {
            currentBeat += 4
        } else if char == "o|" {
            currentBeat += 2
        } else if char == ".|" {
            currentBeat += 1
        } else if char == "|" {
            beats.append(currentBeat)
            currentBeat = 0
        }
    }
    
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var noteLength = 4
    
    for char in musicString {
        if char == "o" {
            beats.append(noteLength)
        } else if char == "o|" {
            noteLength = 2
        } else if char == ".|" {
            noteLength = 1
        }
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var noteLength = 4
    
    for char in musicString {
        if char == "o" {
            beats.append(noteLength)
        } else if char == "o|" {
            noteLength = 2
        } else if char == ".|" {
            noteLength = 1
        }
    }
    
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentBeat = 0
    
    for char in musicString {
        if char == "o" {
            currentBeat += 4
        } else if char == "o|" {
            currentBeat += 2
        } else if char == ".|" {
            currentBeat += 1
        }
        beats.append(currentBeat)
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentBeat = 0
    
    for char in musicString {
        if char == "o" {
            currentBeat += 4
        } else if char == "o|" {
            currentBeat += 2
        } else if char == ".|" {
            currentBeat += 1
        }
        beats.append(currentBeat)
    }
    
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentBeat = 0
    
    for char in musicString {
        switch char {
        case "o":
            currentBeat += 4
        case "o|":
            currentBeat += 2
        case ".|":
            currentBeat += 1
        default:
            break
        }
        beats.append(currentBeat)
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentBeat = 0
    
    for char in musicString {
        switch char {
        case "o":
            currentBeat += 4
        case "o|":
            currentBeat += 2
        case ".|":
            currentBeat += 1
        default:
            break
        }
        beats.append(currentBeat)
    }
    
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentBeat = 0
    
    for note in musicString {
        if note == "o" {
            currentBeat += 4
        } else if note == "o|" {
            currentBeat += 2
        } else if note == ".|" {
            currentBeat += 1
        }
        beats.append(currentBeat)
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentBeat = 0
    
    for note in musicString {
        if note == "o" {
            currentBeat += 4
        } else if note == "o|" {
            currentBeat += 2
        } else if note == ".|" {
            currentBeat += 1
        }
        beats.append(currentBeat)
    }
    
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentBeat = 0
    var currentNote = ""
    
    for char in musicString {
        if char == "o" {
            currentBeat += 4
        } else if char == "o|" {
            currentBeat += 2
        } else if char == ".|" {
            currentBeat += 1
        }
        
        if currentBeat > 0 {
            beats.append(currentBeat)
            currentBeat = 0
        }
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var currentBeat = 0
    var currentNote = ""
    
    for char in musicString {
        if char == "o" {
            currentBeat += 4
        } else if char == "o|" {
            currentBeat += 2
        } else if char == ".|" {
            currentBeat += 1
        }
        
        if currentBeat > 0 {
            beats.append(currentBeat)
            currentBeat = 0
        }
    }
    
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var noteLength = 4
    
    for char in musicString {
        if char == "o" {
            beats.append(noteLength)
        } else if char == "|" {
            noteLength = 2
        } else if char == "." {
            noteLength = 1
        }
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var noteLength = 4
    
    for char in musicString {
        if char == "o" {
            beats.append(noteLength)
        } else if char == "|" {
            noteLength = 2
        } else if char == "." {
            noteLength = 1
        }
    }
    
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var noteLength = 4
    var currentBeat = 0
    
    for char in musicString {
        if char == "o" {
            beats.append(currentBeat)
            currentBeat = 0
        } else if char == "|" {
            currentBeat += noteLength
        }
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    var noteLength = 4
    var currentBeat = 0
    
    for char in musicString {
        if char == "o" {
            beats.append(currentBeat)
            currentBeat = 0
        } else if char == "|" {
            currentBeat += noteLength
        }
    }
    
    return beats
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    
    while index < string.endIndex {
        let range = string.index(index, offsetBy: substring.count, limitedBy: string.endIndex)?? string.endIndex
        let substringRange = string[index..<range]
        
        if substringRange == substring {
            count += 1
        }
        
        index = string.index(after: range)
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    
    while index < string.endIndex {
        let range = string.index(index, offsetBy: substring.count, limitedBy: string.endIndex)?? string.endIndex
        let substringRange = string[index..<range]
        
        if substringRange == substring {
            count += 1
        }
        
        index = string.index(after: range)
    }
    
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    
    while index < string.endIndex {
        let range = string.index(index, offsetBy: substring.count, limitedBy: string.endIndex)?? string.endIndex
        if string[index..<range] == substring {
            count += 1
        }
        index = string.index(after: range)
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    
    while index < string.endIndex {
        let range = string.index(index, offsetBy: substring.count, limitedBy: string.endIndex)?? string.endIndex
        if string[index..<range] == substring {
            count += 1
        }
        index = string.index(after: range)
    }
    
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    while let range = string.range(of: substring, options:.backwards, range: index..<string.endIndex) {
        count += 1
        index = string.index(after: range.upperBound)
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    while let range = string.range(of: substring, options:.backwards, range: index..<string.endIndex) {
        count += 1
        index = string.index(after: range.upperBound)
    }
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    while let range = string.range(of: substring, options:.backwards, range: index..<string.endIndex) {
        count += 1
        index = string.index(after: range.upperBound)
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    while let range = string.range(of: substring, options:.backwards, range: index..<string.endIndex) {
        count += 1
        index = string.index(after: range.upperBound)
    }
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.backwards, range: index..<string.endIndex) {
        count += 1
        index = string.index(after: range.upperBound)
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.backwards, range: index..<string.endIndex) {
        count += 1
        index = string.index(after: range.upperBound)
    }
    
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.backwards, range: index..<string.endIndex) {
        count += 1
        index = string.index(after: range.upperBound)
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.backwards, range: index..<string.endIndex) {
        count += 1
        index = string.index(after: range.upperBound)
    }
    
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.backwards, range: index..<string.endIndex) {
        count += 1
        index = string.index(after: range.upperBound)
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.backwards, range: index..<string.endIndex) {
        count += 1
        index = string.index(after: range.upperBound)
    }
    
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    for i in 0..<string.count {
        if string.index(string.startIndex, offsetBy: i)..<string.index(string.startIndex, offsetBy: i + substring.count) ~= string.startIndex..<string.endIndex {
            count += 1
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    for i in 0..<string.count {
        if string.index(string.startIndex, offsetBy: i)..<string.index(string.startIndex, offsetBy: i + substring.count) ~= string.startIndex..<string.endIndex {
            count += 1
        }
    }
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.backwards, range: index..<string.endIndex) {
        count += 1
        index = string.index(before: range.lowerBound)
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.backwards, range: index..<string.endIndex) {
        count += 1
        index = string.index(before: range.lowerBound)
    }
    
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.backwards, range: index..<string.endIndex) {
        count += 1
        index = string.index(before: range.lowerBound)
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.backwards, range: index..<string.endIndex) {
        count += 1
        index = string.index(before: range.lowerBound)
    }
    
    return count
}
```

func sortNumbers(numbers: String) -> String {
    let numberArray = numbers.components(separatedBy: " ")
    let sortedArray = numberArray.sorted { (number1: String, number2: String) -> Bool in
        let number1Int = Int(number1)?? 0
        let number2Int = Int(number2)?? 0
        return number1Int < number2Int
    }
    return sortedArray.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberArray = numbers.components(separatedBy: " ")
    let sortedArray = numberArray.sorted { (number1: String, number2: String) -> Bool in
        let number1Int = Int(number1)?? 0
        let number2Int = Int(number2)?? 0
        return number1Int < number2Int
    }
    return sortedArray.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numberals = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
    let numberalsMap = numberals.enumerated().reduce(into: [:]) { (result, element) in
        result[element.element] = element.offset
    }
    let sortedNumbers = numbers.components(separatedBy: " ").sorted { numberalsMap[String($0)]! < numberalsMap[String($1)]! }
    return sortedNumbers.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberals = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
    let numberalsMap = numberals.enumerated().reduce(into: [:]) { (result, element) in
        result[element.element] = element.offset
    }
    let sortedNumbers = numbers.components(separatedBy: " ").sorted { numberalsMap[String($0)]! < numberalsMap[String($1)]! }
    return sortedNumbers.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numberMap = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
    let sortedNumbers = numbers.components(separatedBy: " ").sorted { numberMap[$0]! < numberMap[$1]! }
    return sortedNumbers.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberMap = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
    let sortedNumbers = numbers.components(separatedBy: " ").sorted { numberMap[$0]! < numberMap[$1]! }
    return sortedNumbers.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numberMap = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
    let numberArray = numbers.components(separatedBy: " ")
    let sortedArray = numberArray.sorted { numberMap[$0]! < numberMap[$1]! }
    return sortedArray.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberMap = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
    let numberArray = numbers.components(separatedBy: " ")
    let sortedArray = numberArray.sorted { numberMap[$0]! < numberMap[$1]! }
    return sortedArray.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numberMap = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
    let numberArray = numbers.components(separatedBy: " ")
    let sortedArray = numberArray.sorted { numberMap[$0]! < numberMap[$1]! }
    return sortedArray.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberMap = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
    let numberArray = numbers.components(separatedBy: " ")
    let sortedArray = numberArray.sorted { numberMap[$0]! < numberMap[$1]! }
    return sortedArray.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numberArray = numbers.components(separatedBy: " ")
    let sortedArray = numberArray.sorted { $0 < $1 }
    return sortedArray.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberArray = numbers.components(separatedBy: " ")
    let sortedArray = numberArray.sorted { $0 < $1 }
    return sortedArray.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numberMap = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
    let sortedNumbers = numbers.components(separatedBy: " ").sorted { numberMap[$0]! < numberMap[$1]! }
    return sortedNumbers.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberMap = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
    let sortedNumbers = numbers.components(separatedBy: " ").sorted { numberMap[$0]! < numberMap[$1]! }
    return sortedNumbers.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numberMap = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
    let numberArray = numbers.components(separatedBy: " ")
    let sortedArray = numberArray.sorted { numberMap[$0]! < numberMap[$1]! }
    return sortedArray.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberMap = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
    let numberArray = numbers.components(separatedBy: " ")
    let sortedArray = numberArray.sorted { numberMap[$0]! < numberMap[$1]! }
    return sortedArray.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numberMap = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
    let numberArray = numbers.components(separatedBy: " ")
    let sortedArray = numberArray.sorted { numberMap[$0]! < numberMap[$1]! }
    return sortedArray.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberMap = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
    let numberArray = numbers.components(separatedBy: " ")
    let sortedArray = numberArray.sorted { numberMap[$0]! < numberMap[$1]! }
    return sortedArray.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numberArray = numbers.components(separatedBy: " ")
    let sortedArray = numberArray.sorted { $0 < $1 }
    return sortedArray.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberArray = numbers.components(separatedBy: " ")
    let sortedArray = numberArray.sorted { $0 < $1 }
    return sortedArray.joined(separator: " ")
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must contain at least two elements.")
    }
    
    var minDistance = Double.greatestFiniteMagnitude
    var closestElements = (Double, Double)()
    
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            let distance = abs(numbers[i] - numbers[j])
            if distance < minDistance {
                minDistance = distance
                closestElements = (numbers[i], numbers[j])
            }
        }
    }
    
    return closestElements
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must contain at least two elements.")
    }
    
    var minDistance = Double.greatestFiniteMagnitude
    var closestElements = (Double, Double)()
    
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            let distance = abs(numbers[i] - numbers[j])
            if distance < minDistance {
                minDistance = distance
                closestElements = (numbers[i], numbers[j])
            }
        }
    }
    
    return closestElements
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must contain at least two elements")
    }
    
    var minDiff = Double.greatestFiniteMagnitude
    var closestElements: (Double, Double) = (0.0, 0.0)
    
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            let diff = abs(numbers[i] - numbers[j])
            if diff < minDiff {
                minDiff = diff
                closestElements = (numbers[i], numbers[j])
            }
        }
    }
    
    return closestElements
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must contain at least two elements")
    }
    
    var minDiff = Double.greatestFiniteMagnitude
    var closestElements: (Double, Double) = (0.0, 0.0)
    
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            let diff = abs(numbers[i] - numbers[j])
            if diff < minDiff {
                minDiff = diff
                closestElements = (numbers[i], numbers[j])
            }
        }
    }
    
    return closestElements
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must have at least two elements")
    }
    
    var minDiff = Double.greatestFiniteMagnitude
    var closestElements = (Double, Double)()
    
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            let diff = abs(numbers[i] - numbers[j])
            if diff < minDiff {
                minDiff = diff
                closestElements = (numbers[i], numbers[j])
            }
        }
    }
    
    return closestElements
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must have at least two elements")
    }
    
    var minDiff = Double.greatestFiniteMagnitude
    var closestElements = (Double, Double)()
    
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            let diff = abs(numbers[i] - numbers[j])
            if diff < minDiff {
                minDiff = diff
                closestElements = (numbers[i], numbers[j])
            }
        }
    }
    
    return closestElements
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("At least two numbers are required.")
    }
    
    var closestPair = (numbers[0], numbers[1])
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            let currentPair = (numbers[i], numbers[j])
            if abs(currentPair.0 - currentPair.1) < abs(closestPair.0 - closestPair.1) {
                closestPair = currentPair
            }
        }
    }
    
    return closestPair
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("At least two numbers are required.")
    }
    
    var closestPair = (numbers[0], numbers[1])
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            let currentPair = (numbers[i], numbers[j])
            if abs(currentPair.0 - currentPair.1) < abs(closestPair.0 - closestPair.1) {
                closestPair = currentPair
            }
        }
    }
    
    return closestPair
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must contain at least two elements")
    }
    
    var closestPair = (numbers[0], numbers[1])
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            let currentPair = (numbers[i], numbers[j])
            if abs(currentPair.0 - currentPair.1) < abs(closestPair.0 - closestPair.1) {
                closestPair = currentPair
            }
        }
    }
    
    return closestPair
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must contain at least two elements")
    }
    
    var closestPair = (numbers[0], numbers[1])
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            let currentPair = (numbers[i], numbers[j])
            if abs(currentPair.0 - currentPair.1) < abs(closestPair.0 - closestPair.1) {
                closestPair = currentPair
            }
        }
    }
    
    return closestPair
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must contain at least two numbers")
    }
    
    var minDiff = Double.greatestFiniteMagnitude
    var minDiffElements = (Double, Double)()
    
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            let diff = abs(numbers[i] - numbers[j])
            if diff < minDiff {
                minDiff = diff
                minDiffElements = (numbers[i], numbers[j])
            }
        }
    }
    
    return minDiffElements
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must contain at least two numbers")
    }
    
    var minDiff = Double.greatestFiniteMagnitude
    var minDiffElements = (Double, Double)()
    
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            let diff = abs(numbers[i] - numbers[j])
            if diff < minDiff {
                minDiff = diff
                minDiffElements = (numbers[i], numbers[j])
            }
        }
    }
    
    return minDiffElements
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must have at least two elements")
    }
    
    var minDistance = Double.infinity
    var closestPair = (Double.greatestFiniteMagnitude, Double.greatestFiniteMagnitude)
    
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            let distance = abs(numbers[i] - numbers[j])
            if distance < minDistance {
                minDistance = distance
                closestPair = (numbers[i], numbers[j])
            }
        }
    }
    
    return closestPair
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must have at least two elements")
    }
    
    var minDistance = Double.infinity
    var closestPair = (Double.greatestFiniteMagnitude, Double.greatestFiniteMagnitude)
    
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            let distance = abs(numbers[i] - numbers[j])
            if distance < minDistance {
                minDistance = distance
                closestPair = (numbers[i], numbers[j])
            }
        }
    }
    
    return closestPair
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("At least two numbers are required.")
    }
    
    var minDistance: Double = Double.infinity
    var closestElements: (Double, Double) = (0.0, 0.0)
    
    for i in 0..<numbers.count - 1 {
        for j in i + 1..<numbers.count {
            let distance = abs(numbers[i] - numbers[j])
            if distance < minDistance {
                minDistance = distance
                closestElements = (numbers[i], numbers[j])
            }
        }
    }
    
    return closestElements
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("At least two numbers are required.")
    }
    
    var minDistance: Double = Double.infinity
    var closestElements: (Double, Double) = (0.0, 0.0)
    
    for i in 0..<numbers.count - 1 {
        for j in i + 1..<numbers.count {
            let distance = abs(numbers[i] - numbers[j])
            if distance < minDistance {
                minDistance = distance
                closestElements = (numbers[i], numbers[j])
            }
        }
    }
    
    return closestElements
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must contain at least two numbers")
    }
    
    var smallest = numbers[0]
    var largest = numbers[0]
    
    for number in numbers {
        if number < smallest {
            smallest = number
        }
        
        if number > largest {
            largest = number
        }
    }
    
    return (smallest, largest)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must contain at least two numbers")
    }
    
    var smallest = numbers[0]
    var largest = numbers[0]
    
    for number in numbers {
        if number < smallest {
            smallest = number
        }
        
        if number > largest {
            largest = number
        }
    }
    
    return (smallest, largest)
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("At least two numbers are required")
    }
    
    var closestPair = (numbers[0], numbers[1])
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            let currentPair = (numbers[i], numbers[j])
            if abs(currentPair.0 - currentPair.1) < abs(closestPair.0 - closestPair.1) {
                closestPair = currentPair
            }
        }
    }
    
    return closestPair
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("At least two numbers are required")
    }
    
    var closestPair = (numbers[0], numbers[1])
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            let currentPair = (numbers[i], numbers[j])
            if abs(currentPair.0 - currentPair.1) < abs(closestPair.0 - closestPair.1) {
                closestPair = currentPair
            }
        }
    }
    
    return closestPair
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()?? 0
    let max = numbers.max()?? 0
    let range = max - min
    return (numbers - min) / range
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()?? 0
    let max = numbers.max()?? 0
    let range = max - min
    return (numbers - min) / range
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()?? 0
    let max = numbers.max()?? 0
    let range = max - min
    return (numbers.map { ($0 - min) / range } as [Double])
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()?? 0
    let max = numbers.max()?? 0
    let range = max - min
    return (numbers.map { ($0 - min) / range } as [Double])
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return (numbers.map { ($0 - min) / (max - min) } as [Double])
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return (numbers.map { ($0 - min) / (max - min) } as [Double])
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return (numbers.map { ($0 - min) / range } as [Double])
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return (numbers.map { ($0 - min) / range } as [Double])
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return (numbers.map { ($0 - min) / range } as [Double])
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return (numbers.map { ($0 - min) / range } as [Double])
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return (numbers - min) / (max - min)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return (numbers - min) / (max - min)
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return (numbers - min) / (max - min)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return (numbers - min) / (max - min)
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return (numbers - min) / (max - min)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return (numbers - min) / (max - min)
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return (numbers - min) / (max - min)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return (numbers - min) / (max - min)
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return (numbers - min) / (max - min)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return (numbers - min) / (max - min)
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    var result: [Int] = []
    for value in values {
        if let intValue = value as? Int {
            result.append(intValue)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    var result: [Int] = []
    for value in values {
        if let intValue = value as? Int {
            result.append(intValue)
        }
    }
    return result
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    var result: [Int] = []
    for value in values {
        if let integerValue = value as? Int {
            result.append(integerValue)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    var result: [Int] = []
    for value in values {
        if let integerValue = value as? Int {
            result.append(integerValue)
        }
    }
    return result
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    var filteredIntegers = [Int]()
    for value in values {
        if let integerValue = value as? Int {
            filteredIntegers.append(integerValue)
        }
    }
    return filteredIntegers
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    var filteredIntegers = [Int]()
    for value in values {
        if let integerValue = value as? Int {
            filteredIntegers.append(integerValue)
        }
    }
    return filteredIntegers
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    var result = [Int]()
    for value in values {
        if let intValue = value as? Int {
            result.append(intValue)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    var result = [Int]()
    for value in values {
        if let intValue = value as? Int {
            result.append(intValue)
        }
    }
    return result
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    var integers = [Int]()
    for value in values {
        if let intValue = value as? Int {
            integers.append(intValue)
        }
    }
    return integers
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    var integers = [Int]()
    for value in values {
        if let intValue = value as? Int {
            integers.append(intValue)
        }
    }
    return integers
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    var result: [Int] = []
    for value in values {
        if let intValue = value as? Int {
            result.append(intValue)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    var result: [Int] = []
    for value in values {
        if let intValue = value as? Int {
            result.append(intValue)
        }
    }
    return result
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    var integers = [Int]()
    for value in values {
        if let intValue = value as? Int {
            integers.append(intValue)
        }
    }
    return integers
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    var integers = [Int]()
    for value in values {
        if let intValue = value as? Int {
            integers.append(intValue)
        }
    }
    return integers
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    var integers = [Int]()
    for value in values {
        if let intValue = value as? Int {
            integers.append(intValue)
        }
    }
    return integers
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    var integers = [Int]()
    for value in values {
        if let intValue = value as? Int {
            integers.append(intValue)
        }
    }
    return integers
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        divisor -= 1
        if n % divisor == 0 {
            return divisor
        }
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        divisor -= 1
        if n % divisor == 0 {
            return divisor
        }
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        divisor -= 1
        if n % divisor == 0 {
            return divisor
        }
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        divisor -= 1
        if n % divisor == 0 {
            return divisor
        }
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        divisor -= 1
        if n % divisor == 0 {
            return divisor
        }
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        divisor -= 1
        if n % divisor == 0 {
            return divisor
        }
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        divisor -= 1
        if n % divisor == 0 {
            return divisor
        }
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        divisor -= 1
        if n % divisor == 0 {
            return divisor
        }
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        divisor -= 1
        if n % divisor == 0 {
            return divisor
        }
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        divisor -= 1
        if n % divisor == 0 {
            return divisor
        }
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        divisor -= 1
        if n % divisor == 0 {
            return divisor
        }
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        divisor -= 1
        if n % divisor == 0 {
            return divisor
        }
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        divisor -= 1
        if n % divisor == 0 {
            return divisor
        }
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        divisor -= 1
        if n % divisor == 0 {
            return divisor
        }
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        divisor -= 1
        if n % divisor == 0 {
            return divisor
        }
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        divisor -= 1
        if n % divisor == 0 {
            return divisor
        }
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        divisor -= 1
        if n % divisor == 0 {
            return divisor
        }
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        divisor -= 1
        if n % divisor == 0 {
            return divisor
        }
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        divisor -= 1
        if n % divisor == 0 {
            return divisor
        }
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        divisor -= 1
        if n % divisor == 0 {
            return divisor
        }
    }
    return 1
}
```

func factorize(n: Int) -> [Int] {
    var factors = [Int: Int]()
    var i = 2
    while i * i <= n {
        while n % i == 0 {
            factors[i, default: 0] += 1
            n /= i
        }
        i += 1
    }
    if n > 1 {
        factors[n, default: 0] += 1
    }
    return factors.sorted { $0.key < $1.key }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var factors = [Int: Int]()
    var i = 2
    while i * i <= n {
        while n % i == 0 {
            factors[i, default: 0] += 1
            n /= i
        }
        i += 1
    }
    if n > 1 {
        factors[n, default: 0] += 1
    }
    return factors.sorted { $0.key < $1.key }
}
```

func factorize(n: Int) -> [Int] {
    var factors = [Int: Int]()
    var num = n
    for i in 2...sqrt(Double(n)) {
        while num % i == 0 {
            factors[i, default: 0] += 1
            num /= i
        }
    }
    if num > 1 {
        factors[num, default: 0] += 1
    }
    return factors.sorted { $0.key < $1.key }.map { $0.key }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var factors = [Int: Int]()
    var num = n
    for i in 2...sqrt(Double(n)) {
        while num % i == 0 {
            factors[i, default: 0] += 1
            num /= i
        }
    }
    if num > 1 {
        factors[num, default: 0] += 1
    }
    return factors.sorted { $0.key < $1.key }.map { $0.key }
}
```

func factorize(n: Int) -> [Int] {
    var factors = [Int: Int]()
    var i = 2
    while i * i <= n {
        while n % i == 0 {
            factors[i, default: 0] += 1
            n /= i
        }
        i += 1
    }
    if n > 1 {
        factors[n, default: 0] += 1
    }
    return factors.sorted { $0.key < $1.key }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var factors = [Int: Int]()
    var i = 2
    while i * i <= n {
        while n % i == 0 {
            factors[i, default: 0] += 1
            n /= i
        }
        i += 1
    }
    if n > 1 {
        factors[n, default: 0] += 1
    }
    return factors.sorted { $0.key < $1.key }
}
```

func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            var count = 0
            while n % i == 0 {
                count += 1
                n /= i
            }
            factors.append(contentsOf: Array(repeating: i, count: count))
        }
        i += 1
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            var count = 0
            while n % i == 0 {
                count += 1
                n /= i
            }
            factors.append(contentsOf: Array(repeating: i, count: count))
        }
        i += 1
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}
```

func factorize(n: Int) -> [Int] {
    var factors = [Int: Int]()
    var i = 2
    while i * i <= n {
        while n % i == 0 {
            factors[i, default: 0] += 1
            n /= i
        }
        i += 1
    }
    if n > 1 {
        factors[n, default: 0] += 1
    }
    return factors.sorted { $0.key < $1.key }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var factors = [Int: Int]()
    var i = 2
    while i * i <= n {
        while n % i == 0 {
            factors[i, default: 0] += 1
            n /= i
        }
        i += 1
    }
    if n > 1 {
        factors[n, default: 0] += 1
    }
    return factors.sorted { $0.key < $1.key }
}
```

func factorize(n: Int) -> [Int] {
    var factors = [Int: Int]()
    var i = 2
    while i * i <= n {
        while n % i == 0 {
            factors[i, default: 0] += 1
            n /= i
        }
        i += 1
    }
    if n > 1 {
        factors[n, default: 0] += 1
    }
    return factors.map { $0.key }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var factors = [Int: Int]()
    var i = 2
    while i * i <= n {
        while n % i == 0 {
            factors[i, default: 0] += 1
            n /= i
        }
        i += 1
    }
    if n > 1 {
        factors[n, default: 0] += 1
    }
    return factors.map { $0.key }
}
```

func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            var count = 0
            while n % i == 0 {
                n /= i
                count += 1
            }
            factors.append((i, count))
        }
        i += 1
    }
    if n > 1 {
        factors.append((n, 1))
    }
    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            var count = 0
            while n % i == 0 {
                n /= i
                count += 1
            }
            factors.append((i, count))
        }
        i += 1
    }
    if n > 1 {
        factors.append((n, 1))
    }
    return factors
}
```

func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var num = n
    var i = 2

    while num > 1 {
        while num % i == 0 {
            factors.append(i)
            num /= i
        }
        i += 1
    }

    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var num = n
    var i = 2

    while num > 1 {
        while num % i == 0 {
            factors.append(i)
            num /= i
        }
        i += 1
    }

    return factors
}
```

func factorize(n: Int) -> [Int] {
    var factors = [Int: Int]()
    var i = 2
    while i * i <= n {
        while n % i == 0 {
            factors[i, default: 0] += 1
            n /= i
        }
        i += 1
    }
    if n > 1 {
        factors[n, default: 0] += 1
    }
    return factors.map { $0.value == 1? $0.key : [$0.key, $0.value] }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var factors = [Int: Int]()
    var i = 2
    while i * i <= n {
        while n % i == 0 {
            factors[i, default: 0] += 1
            n /= i
        }
        i += 1
    }
    if n > 1 {
        factors[n, default: 0] += 1
    }
    return factors.map { $0.value == 1? $0.key : [$0.key, $0.value] }
}
```

func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            var count = 0
            while n % i == 0 {
                count += 1
                n /= i
            }
            factors.append(contentsOf: Array(repeating: i, count: count))
        }
        i += 1
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            var count = 0
            while n % i == 0 {
                count += 1
                n /= i
            }
            factors.append(contentsOf: Array(repeating: i, count: count))
        }
        i += 1
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = [Int: Bool]()
    
    for number in numbers {
        if seen[number] == nil {
            seen[number] = true
            result.append(number)
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = [Int: Bool]()
    
    for number in numbers {
        if seen[number] == nil {
            seen[number] = true
            result.append(number)
        }
    }
    
    return result
}
```

func flipCase(string: String) -> String {
    return string.map { character in
        character.isLowercase? character.uppercased() : character.lowercased()
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    return string.map { character in
        character.isLowercase? character.uppercased() : character.lowercased()
    }
}
```

func flipCase(string: String) -> String {
    return string.map { String($0).toggleCase() }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    return string.map { String($0).toggleCase() }
}
```

func flipCase(string: String) -> String {
    var result = ""
    for character in string {
        if character.isLowercase {
            result.append(character.uppercased())
        } else {
            result.append(character.lowercased())
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    var result = ""
    for character in string {
        if character.isLowercase {
            result.append(character.uppercased())
        } else {
            result.append(character.lowercased())
        }
    }
    return result
}
```

func flipCase(string: String) -> String {
    var result = ""
    for character in string {
        if character.isLowercase {
            result.append(character.uppercased())
        } else {
            result.append(character.lowercased())
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    var result = ""
    for character in string {
        if character.isLowercase {
            result.append(character.uppercased())
        } else {
            result.append(character.lowercased())
        }
    }
    return result
}
```

func flipCase(string: String) -> String {
    var result = ""
    for character in string {
        if character.isLowercase {
            result.append(character.uppercased())
        } else {
            result.append(character.lowercased())
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    var result = ""
    for character in string {
        if character.isLowercase {
            result.append(character.uppercased())
        } else {
            result.append(character.lowercased())
        }
    }
    return result
}
```

func flipCase(string: String) -> String {
    var result = ""
    for character in string {
        if character.isLowercase {
            result.append(character.uppercased())
        } else {
            result.append(character.lowercased())
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    var result = ""
    for character in string {
        if character.isLowercase {
            result.append(character.uppercased())
        } else {
            result.append(character.lowercased())
        }
    }
    return result
}
```

func flipCase(string: String) -> String {
    var result = ""
    for character in string {
        if character.isLowercase {
            result.append(character.uppercased())
        } else {
            result.append(character.lowercased())
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    var result = ""
    for character in string {
        if character.isLowercase {
            result.append(character.uppercased())
        } else {
            result.append(character.lowercased())
        }
    }
    return result
}
```

func flipCase(string: String) -> String {
    var result = ""
    for character in string {
        if character.isLowercase {
            result.append(character.uppercased())
        } else {
            result.append(character.lowercased())
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    var result = ""
    for character in string {
        if character.isLowercase {
            result.append(character.uppercased())
        } else {
            result.append(character.lowercased())
        }
    }
    return result
}
```

func flipCase(string: String) -> String {
    var result = ""
    for character in string {
        if character.isLowercase {
            result.append(character.uppercased())
        } else {
            result.append(character.lowercased())
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    var result = ""
    for character in string {
        if character.isLowercase {
            result.append(character.uppercased())
        } else {
            result.append(character.lowercased())
        }
    }
    return result
}
```

func flipCase(string: String) -> String {
    var result = ""
    for character in string {
        if character.isLowercase {
            result.append(character.uppercased())
        } else {
            result.append(character.lowercased())
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    var result = ""
    for character in string {
        if character.isLowercase {
            result.append(character.uppercased())
        } else {
            result.append(character.lowercased())
        }
    }
    return result
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("") { $0 + $1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("") { $0 + $1 }
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("") { $0 + $1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("") { $0 + $1 }
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("") { $0 + $1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("") { $0 + $1 }
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("") { $0 + $1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("") { $0 + $1 }
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("") { $0 + $1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("") { $0 + $1 }
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("") { $0 + $1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("") { $0 + $1 }
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("") { $0 + $1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("") { $0 + $1 }
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("") { $0 + $1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("") { $0 + $1 }
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("") { $0 + $1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("") { $0 + $1 }
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("") { $0 + $1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("") { $0 + $1 }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func getPositive(l: [Int]) -> [Int] {
    var result = [Int]()
    for i in l {
        if i > 0 {
            result.append(i)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    var result = [Int]()
    for i in l {
        if i > 0 {
            result.append(i)
        }
    }
    return result
}
```

func getPositive(l: [Int]) -> [Int] {
    var result = [Int]()
    for num in l {
        if num > 0 {
            result.append(num)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    var result = [Int]()
    for num in l {
        if num > 0 {
            result.append(num)
        }
    }
    return result
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    var result: [Int] = []
    for num in l {
        if num > 0 {
            result.append(num)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    var result: [Int] = []
    for num in l {
        if num > 0 {
            result.append(num)
        }
    }
    return result
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    
    for i in 2...(n-1) {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    
    for i in 2...(n-1) {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```

func sortThird(l: [Int]) -> [Int] {
    var lCopy = l
    for i in stride(from: 0, to: lCopy.count, by: 3) {
        let sortedThird = lCopy[i..<i+3].sorted()
        lCopy[i..<i+3] = sortedThird
    }
    return lCopy
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var lCopy = l
    for i in stride(from: 0, to: lCopy.count, by: 3) {
        let sortedThird = lCopy[i..<i+3].sorted()
        lCopy[i..<i+3] = sortedThird
    }
    return lCopy
}
```

func sortThird(l: [Int]) -> [Int] {
    var l2 = l
    for i in 0..<l2.count {
        if i % 3 == 0 {
            let sorted = l2[i..<l2.count].sorted()
            l2[i..<l2.count] = sorted
        }
    }
    return l2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l2 = l
    for i in 0..<l2.count {
        if i % 3 == 0 {
            let sorted = l2[i..<l2.count].sorted()
            l2[i..<l2.count] = sorted
        }
    }
    return l2
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        let sorted = l[i..<i+3].sorted()
        l[i..<i+3] = sorted
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        let sorted = l[i..<i+3].sorted()
        l[i..<i+3] = sorted
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l2 = l
    for i in stride(from: 0, to: l2.count, by: 3) {
        let sorted = l2[i..<i+3].sorted()
        l2[i..<i+3] = sorted
    }
    return l2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l2 = l
    for i in stride(from: 0, to: l2.count, by: 3) {
        let sorted = l2[i..<i+3].sorted()
        l2[i..<i+3] = sorted
    }
    return l2
}
```

func sortThird(l: [Int]) -> [Int] {
    var l2 = l
    for i in stride(from: 0, to: l.count, by: 3) {
        let sorted = l2[i..<i+3].sorted()
        l2[i..<i+3] = sorted
    }
    return l2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l2 = l
    for i in stride(from: 0, to: l.count, by: 3) {
        let sorted = l2[i..<i+3].sorted()
        l2[i..<i+3] = sorted
    }
    return l2
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        let indices = Array(stride(from: i, to: min(i + 3, l.count), by: 1))
        let values = indices.map { l[$0] }
        let sortedValues = values.sorted()
        for j in 0..<sortedValues.count {
            l[indices[j]] = sortedValues[j]
        }
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        let indices = Array(stride(from: i, to: min(i + 3, l.count), by: 1))
        let values = indices.map { l[$0] }
        let sortedValues = values.sorted()
        for j in 0..<sortedValues.count {
            l[indices[j]] = sortedValues[j]
        }
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        let sorted = l[i..<i+3].sorted()
        l[i..<i+3] = sorted
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        let sorted = l[i..<i+3].sorted()
        l[i..<i+3] = sorted
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l2 = l
    for i in stride(from: 0, to: l2.count, by: 3) {
        let start = i
        let end = min(start + 3, l2.count)
        let sorted = l2[start..<end].sorted()
        l2[start..<end] = sorted
    }
    return l2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l2 = l
    for i in stride(from: 0, to: l2.count, by: 3) {
        let start = i
        let end = min(start + 3, l2.count)
        let sorted = l2[start..<end].sorted()
        l2[start..<end] = sorted
    }
    return l2
}
```

func sortThird(l: [Int]) -> [Int] {
    var l2 = l
    for i in 0..<l2.count {
        if i % 3 == 0 {
            let sorted = l2[i..<l2.count].sorted()
            l2[i..<l2.count] = sorted
        }
    }
    return l2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l2 = l
    for i in 0..<l2.count {
        if i % 3 == 0 {
            let sorted = l2[i..<l2.count].sorted()
            l2[i..<l2.count] = sorted
        }
    }
    return l2
}
```

func sortThird(l: [Int]) -> [Int] {
    var l2 = l
    for i in 0..<l2.count {
        if i % 3 == 0 {
            l2.swapAt(i, i + 1)
        }
    }
    return l2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l2 = l
    for i in 0..<l2.count {
        if i % 3 == 0 {
            l2.swapAt(i, i + 1)
        }
    }
    return l2
}
```

func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    for element in l {
        if!seen.contains(element) {
            seen.insert(element)
            result.append(element)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    for element in l {
        if!seen.contains(element) {
            seen.insert(element)
            result.append(element)
        }
    }
    return result
}
```

func unique(l: [Int]) -> [Int] {
    var uniqueElements = [Int]()
    for element in l {
        if!uniqueElements.contains(element) {
            uniqueElements.append(element)
        }
    }
    return uniqueElements.sorted()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var uniqueElements = [Int]()
    for element in l {
        if!uniqueElements.contains(element) {
            uniqueElements.append(element)
        }
    }
    return uniqueElements.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for element in l {
        if!seen.contains(element) {
            seen.insert(element)
            result.append(element)
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for element in l {
        if!seen.contains(element) {
            seen.insert(element)
            result.append(element)
        }
    }
    
    return result
}
```

func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    for element in l {
        if!seen.contains(element) {
            seen.insert(element)
            result.append(element)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    for element in l {
        if!seen.contains(element) {
            seen.insert(element)
            result.append(element)
        }
    }
    return result
}
```

func unique(l: [Int]) -> [Int] {
    var uniqueElements = Set<Int>()
    for element in l {
        if!uniqueElements.contains(element) {
            uniqueElements.insert(element)
        }
    }
    return Array(uniqueElements)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var uniqueElements = Set<Int>()
    for element in l {
        if!uniqueElements.contains(element) {
            uniqueElements.insert(element)
        }
    }
    return Array(uniqueElements)
}
```

func unique(l: [Int]) -> [Int] {
    var uniqueElements = Set<Int>()
    for element in l {
        if!uniqueElements.contains(element) {
            uniqueElements.insert(element)
        }
    }
    return Array(uniqueElements)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var uniqueElements = Set<Int>()
    for element in l {
        if!uniqueElements.contains(element) {
            uniqueElements.insert(element)
        }
    }
    return Array(uniqueElements)
}
```

func unique(l: [Int]) -> [Int] {
    var uniqueElements = Set<Int>()
    for element in l {
        uniqueElements.insert(element)
    }
    return Array(uniqueElements)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var uniqueElements = Set<Int>()
    for element in l {
        uniqueElements.insert(element)
    }
    return Array(uniqueElements)
}
```

func unique(l: [Int]) -> [Int] {
    var uniqueElements = [Int]()
    for element in l {
        if!uniqueElements.contains(element) {
            uniqueElements.append(element)
        }
    }
    return uniqueElements
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var uniqueElements = [Int]()
    for element in l {
        if!uniqueElements.contains(element) {
            uniqueElements.append(element)
        }
    }
    return uniqueElements
}
```

func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for element in l {
        if!seen.contains(element) {
            seen.insert(element)
            result.append(element)
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for element in l {
        if!seen.contains(element) {
            seen.insert(element)
            result.append(element)
        }
    }
    
    return result
}
```

func unique(l: [Int]) -> [Int] {
    var uniqueElements = Set<Int>()
    for element in l {
        uniqueElements.insert(element)
    }
    return Array(uniqueElements)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var uniqueElements = Set<Int>()
    for element in l {
        uniqueElements.insert(element)
    }
    return Array(uniqueElements)
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for num in l {
        if num > max {
            max = num
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for num in l {
        if num > max {
            max = num
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for num in l {
        if num > max {
            max = num
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for num in l {
        if num > max {
            max = num
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for num in l {
        if num > max {
            max = num
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for num in l {
        if num > max {
            max = num
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for element in l {
        if element > max {
            max = element
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for element in l {
        if element > max {
            max = element
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func sortEven(l: [Int]) -> [Int] {
    var lPrime = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenIndex = i + 1
        if evenIndex < lPrime.count {
            let evenValue = lPrime[evenIndex]
            let evenIndex = i + 1
            while evenIndex < lPrime.count && lPrime[evenIndex] < evenValue {
                let temp = lPrime[evenIndex]
                lPrime[evenIndex] = evenValue
                evenValue = temp
                evenIndex += 1
            }
        }
    }
    return lPrime
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var lPrime = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenIndex = i + 1
        if evenIndex < lPrime.count {
            let evenValue = lPrime[evenIndex]
            let evenIndex = i + 1
            while evenIndex < lPrime.count && lPrime[evenIndex] < evenValue {
                let temp = lPrime[evenIndex]
                lPrime[evenIndex] = evenValue
                evenValue = temp
                evenIndex += 1
            }
        }
    }
    return lPrime
}
```

func sortEven(l: [Int]) -> [Int] {
    var lPrime = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenIndices = stride(from: i, to: l.count, by: 2)
        let evenValues = lPrime[evenIndices]
        let sortedEvenValues = evenValues.sorted()
        lPrime[i] = sortedEvenValues.first!
        lPrime[i + 1] = sortedEvenValues.last!
    }
    return lPrime
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var lPrime = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenIndices = stride(from: i, to: l.count, by: 2)
        let evenValues = lPrime[evenIndices]
        let sortedEvenValues = evenValues.sorted()
        lPrime[i] = sortedEvenValues.first!
        lPrime[i + 1] = sortedEvenValues.last!
    }
    return lPrime
}
```

func sortEven(l: [Int]) -> [Int] {
    var lPrime = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenIndex = lPrime.index(lPrime.startIndex, offsetBy: i + 1)
        let evenValue = lPrime[evenIndex]
        let evenValues = lPrime[i..<i+2].sorted()
        lPrime[i..<i+2] = evenValues
    }
    return lPrime
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var lPrime = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenIndex = lPrime.index(lPrime.startIndex, offsetBy: i + 1)
        let evenValue = lPrime[evenIndex]
        let evenValues = lPrime[i..<i+2].sorted()
        lPrime[i..<i+2] = evenValues
    }
    return lPrime
}
```

func sortEven(l: [Int]) -> [Int] {
    var lPrime = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenIndices = stride(from: i, to: l.count, by: 2)
        let evenValues = lPrime[evenIndices]
        let sortedEvenValues = evenValues.sorted()
        lPrime[i] = sortedEvenValues.first!
        lPrime[i + 1] = sortedEvenValues.last!
    }
    return lPrime
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var lPrime = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenIndices = stride(from: i, to: l.count, by: 2)
        let evenValues = lPrime[evenIndices]
        let sortedEvenValues = evenValues.sorted()
        lPrime[i] = sortedEvenValues.first!
        lPrime[i + 1] = sortedEvenValues.last!
    }
    return lPrime
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenIndex = i + 1
        if evenIndex < l.count {
            let evenValue = l[evenIndex]
            var j = i + 1
            while j < l.count && l[j] < evenValue {
                j += 2
            }
            l.insert(evenValue, at: j)
        }
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenIndex = i + 1
        if evenIndex < l.count {
            let evenValue = l[evenIndex]
            var j = i + 1
            while j < l.count && l[j] < evenValue {
                j += 2
            }
            l.insert(evenValue, at: j)
        }
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l2 = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let j = l2.index(l2.startIndex, offsetBy: i + 1)
        let minIndex = l2.indices.first(where: { l2[$0] > l2[j] })
        if let minIndex = minIndex {
            l2.swapAt(i, minIndex)
        }
    }
    return l2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l2 = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let j = l2.index(l2.startIndex, offsetBy: i + 1)
        let minIndex = l2.indices.first(where: { l2[$0] > l2[j] })
        if let minIndex = minIndex {
            l2.swapAt(i, minIndex)
        }
    }
    return l2
}
```

func sortEven(l: [Int]) -> [Int] {
    var lPrime = l
    for i in stride(from: 0, to: lPrime.count, by: 2) {
        let evenIndices = stride(from: i, to: lPrime.count, by: 2)
        let sortedEvenValues = lPrime[evenIndices].sorted()
        lPrime[i..<i+sortedEvenValues.count] = sortedEvenValues
    }
    return lPrime
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var lPrime = l
    for i in stride(from: 0, to: lPrime.count, by: 2) {
        let evenIndices = stride(from: i, to: lPrime.count, by: 2)
        let sortedEvenValues = lPrime[evenIndices].sorted()
        lPrime[i..<i+sortedEvenValues.count] = sortedEvenValues
    }
    return lPrime
}
```

func sortEven(l: [Int]) -> [Int] {
    var lPrime = l
    for i in stride(from: 0, to: lPrime.count, by: 2) {
        let evenIndex = i + 1
        if evenIndex < lPrime.count {
            let evenValue = lPrime[evenIndex]
            var j = i + 1
            while j < lPrime.count && lPrime[j] < evenValue {
                j += 2
            }
            lPrime.insert(evenValue, at: j)
        }
    }
    return lPrime
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var lPrime = l
    for i in stride(from: 0, to: lPrime.count, by: 2) {
        let evenIndex = i + 1
        if evenIndex < lPrime.count {
            let evenValue = lPrime[evenIndex]
            var j = i + 1
            while j < lPrime.count && lPrime[j] < evenValue {
                j += 2
            }
            lPrime.insert(evenValue, at: j)
        }
    }
    return lPrime
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenIndex = l.index(l.startIndex, offsetBy: i + 1)
        let evenValue = l[evenIndex]
        var j = i + 1
        while j < l.count, l[j] < evenValue {
            j += 2
        }
        l.swapAt(i, j)
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenIndex = l.index(l.startIndex, offsetBy: i + 1)
        let evenValue = l[evenIndex]
        var j = i + 1
        while j < l.count, l[j] < evenValue {
            j += 2
        }
        l.swapAt(i, j)
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenIndex = l.index(l.startIndex, offsetBy: i + 1)
        let evenValue = l[evenIndex]
        var j = i + 1
        while j < l.count, l[j] < evenValue {
            j += 2
        }
        l.swapAt(i, j)
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenIndex = l.index(l.startIndex, offsetBy: i + 1)
        let evenValue = l[evenIndex]
        var j = i + 1
        while j < l.count, l[j] < evenValue {
            j += 2
        }
        l.swapAt(i, j)
    }
    return l
}
```

func primeFib(n: Int) -> Int {
    var a = 0, b = 1, c = 0
    for _ in 0..<n {
        c = a + b
        a = b
        b = c
        while b % 2 == 0 {
            b /= 2
        }
    }
    return c
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var a = 0, b = 1, c = 0
    for _ in 0..<n {
        c = a + b
        a = b
        b = c
        while b % 2 == 0 {
            b /= 2
        }
    }
    return c
}
```

func primeFib(n: Int) -> Int {
    var a = 0, b = 1, c = 0
    for _ in 0..<n {
        c = a + b
        a = b
        b = c
        if isPrime(c) {
            return c
        }
    }
    return 0
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    for i in 2..<number {
        if number % i == 0 {
            return false
        }
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var a = 0, b = 1, c = 0
    for _ in 0..<n {
        c = a + b
        a = b
        b = c
        if isPrime(c) {
            return c
        }
    }
    return 0
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    for i in 2..<number {
        if number % i == 0 {
            return false
        }
    }
    return true
}
```

func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var c = 0
    for _ in 1...n {
        c = a + b
        a = b
        b = c
        if isPrime(c) {
            return c
        }
    }
    return 0
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    for i in 2...Int(sqrt(Double(number))) {
        if number % i == 0 {
            return false
        }
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var c = 0
    for _ in 1...n {
        c = a + b
        a = b
        b = c
        if isPrime(c) {
            return c
        }
    }
    return 0
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    for i in 2...Int(sqrt(Double(number))) {
        if number % i == 0 {
            return false
        }
    }
    return true
}
```

func primeFib(n: Int) -> Int {
    var a = 0, b = 1, c = 0
    for _ in 0..<n {
        c = a + b
        a = b
        b = c
        while b % 2 == 0 {
            b /= 2
        }
    }
    return c
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var a = 0, b = 1, c = 0
    for _ in 0..<n {
        c = a + b
        a = b
        b = c
        while b % 2 == 0 {
            b /= 2
        }
    }
    return c
}
```

func primeFib(n: Int) -> Int {
    var a = 0, b = 1, c = 0
    for _ in 0..<n {
        c = a + b
        a = b
        b = c
    }
    return c
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var a = 0, b = 1, c = 0
    for _ in 0..<n {
        c = a + b
        a = b
        b = c
    }
    return c
}
```

func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var c = 0
    for _ in 0..<n {
        c = a + b
        a = b
        b = c
    }
    return c
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var c = 0
    for _ in 0..<n {
        c = a + b
        a = b
        b = c
    }
    return c
}
```

func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var c = 0
    for _ in 0..<n {
        c = a + b
        a = b
        b = c
    }
    return c
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var c = 0
    for _ in 0..<n {
        c = a + b
        a = b
        b = c
    }
    return c
}
```

func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var c = 0

    for _ in 0..<n {
        c = a + b
        a = b
        b = c
    }

    while c % 2 == 0 {
        c /= 2
    }

    return c
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var c = 0

    for _ in 0..<n {
        c = a + b
        a = b
        b = c
    }

    while c % 2 == 0 {
        c /= 2
    }

    return c
}
```

func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var c = 0
    for _ in 0..<n {
        c = a + b
        a = b
        b = c
    }
    return c
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var c = 0
    for _ in 0..<n {
        c = a + b
        a = b
        b = c
    }
    return c
}
```

func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var c = 0

    for _ in 0..<n {
        c = a + b
        a = b
        b = c
    }

    return c
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var c = 0

    for _ in 0..<n {
        c = a + b
        a = b
        b = c
    }

    return c
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for (i, num1) in l.enumerated() {
        for (j, num2) in l.enumerated() {
            if i!= j {
                for num3 in l {
                    if num1 + num2 + num3 == 0 {
                        return true
                    }
                }
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for (i, num1) in l.enumerated() {
        for (j, num2) in l.enumerated() {
            if i!= j {
                for num3 in l {
                    if num1 + num2 + num3 == 0 {
                        return true
                    }
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in 0..<l.count {
            for k in 0..<l.count {
                if i!= j && j!= k && i!= k {
                    if l[i] + l[j] + l[k] == 0 {
                        return true
                    }
                }
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in 0..<l.count {
            for k in 0..<l.count {
                if i!= j && j!= k && i!= k {
                    if l[i] + l[j] + l[k] == 0 {
                        return true
                    }
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            for k in (j+1)..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            for k in (j+1)..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            for k in (j+1)..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            for k in (j+1)..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            for k in (j+1)..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            for k in (j+1)..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i + 1)..<l.count {
            for k in (j + 1)..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i + 1)..<l.count {
            for k in (j + 1)..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func carRaceCollision(n: Int) -> Int {
    var cars = Array(repeating: 0, count: n * 2)
    var left = 0
    var right = n

    for i in 0..<n * 2 {
        cars[i] = i % 2 == 0? 1 : -1
    }

    var collisions = 0

    while left < n * 2 && right < n * 2 {
        if cars[left] == 1 && cars[right] == -1 {
            collisions += 1
            cars[left] = 0
            cars[right] = 0
            left += 1
            right += 1
        } else if cars[left] == 1 {
            left += 1
        } else {
            right += 1
        }
    }

    return collisions
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var cars = Array(repeating: 0, count: n * 2)
    var left = 0
    var right = n

    for i in 0..<n * 2 {
        cars[i] = i % 2 == 0? 1 : -1
    }

    var collisions = 0

    while left < n * 2 && right < n * 2 {
        if cars[left] == 1 && cars[right] == -1 {
            collisions += 1
            cars[left] = 0
            cars[right] = 0
            left += 1
            right += 1
        } else if cars[left] == 1 {
            left += 1
        } else {
            right += 1
        }
    }

    return collisions
}
```

func carRaceCollision(n: Int) -> Int {
    var cars = [Int](repeating: 0, count: n)
    var collisions = 0
    
    for i in 0..<n {
        cars[i] = 1
    }
    
    for i in 0..<n {
        for j in 0..<n {
            if cars[i] == 1 && cars[j] == -1 {
                collisions += 1
            }
        }
    }
    
    return collisions
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var cars = [Int](repeating: 0, count: n)
    var collisions = 0
    
    for i in 0..<n {
        cars[i] = 1
    }
    
    for i in 0..<n {
        for j in 0..<n {
            if cars[i] == 1 && cars[j] == -1 {
                collisions += 1
            }
        }
    }
    
    return collisions
}
```

func carRaceCollision(n: Int) -> Int {
    var cars = [Int](repeating: 0, count: n)
    var left = 0
    var right = n - 1
    var collisions = 0

    while left < right {
        if cars[left] == 0 {
            cars[left] = 1
            left += 1
        } else if cars[right] == 0 {
            cars[right] = 1
            right -= 1
        } else {
            collisions += 1
            cars[left] = 0
            cars[right] = 0
            left += 1
            right -= 1
        }
    }

    return collisions
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var cars = [Int](repeating: 0, count: n)
    var left = 0
    var right = n - 1
    var collisions = 0

    while left < right {
        if cars[left] == 0 {
            cars[left] = 1
            left += 1
        } else if cars[right] == 0 {
            cars[right] = 1
            right -= 1
        } else {
            collisions += 1
            cars[left] = 0
            cars[right] = 0
            left += 1
            right -= 1
        }
    }

    return collisions
}
```

func carRaceCollision(n: Int) -> Int {
    var cars = Array(repeating: 0, count: n)
    var collisions = 0
    var i = 0
    var j = n - 1

    while i < j {
        if cars[i] == 0 {
            cars[i] = 1
            i += 1
        } else {
            cars[j] = 1
            j -= 1
        }
        collisions += 1
    }

    return collisions
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var cars = Array(repeating: 0, count: n)
    var collisions = 0
    var i = 0
    var j = n - 1

    while i < j {
        if cars[i] == 0 {
            cars[i] = 1
            i += 1
        } else {
            cars[j] = 1
            j -= 1
        }
        collisions += 1
    }

    return collisions
}
```

func carRaceCollision(n: Int) -> Int {
    var cars = Array(repeating: 0, count: n)
    var collisions = 0

    for i in 0..<n {
        cars[i] = 1
    }

    for i in 0..<n {
        for j in 0..<n {
            if cars[i] == 1 && cars[j] == -1 {
                collisions += 1
                cars[i] = -1
                cars[j] = 1
            }
        }
    }

    return collisions
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var cars = Array(repeating: 0, count: n)
    var collisions = 0

    for i in 0..<n {
        cars[i] = 1
    }

    for i in 0..<n {
        for j in 0..<n {
            if cars[i] == 1 && cars[j] == -1 {
                collisions += 1
                cars[i] = -1
                cars[j] = 1
            }
        }
    }

    return collisions
}
```

func carRaceCollision(n: Int) -> Int {
    var cars = Array(repeating: 0, count: n)
    var collisions = 0
    for i in 0..<n {
        cars[i] = 1
    }
    for i in 0..<n {
        for j in 0..<n {
            if cars[i] == 1 && cars[j] == -1 {
                collisions += 1
            }
        }
    }
    return collisions
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var cars = Array(repeating: 0, count: n)
    var collisions = 0
    for i in 0..<n {
        cars[i] = 1
    }
    for i in 0..<n {
        for j in 0..<n {
            if cars[i] == 1 && cars[j] == -1 {
                collisions += 1
            }
        }
    }
    return collisions
}
```

func carRaceCollision(n: Int) -> Int {
    var cars = Array(repeating: 0, count: n)
    var collisions = 0
    var left = 0
    var right = n - 1
    
    while left < right {
        if cars[left] == 0 {
            cars[left] = 1
            left += 1
        } else if cars[right] == 0 {
            cars[right] = 1
            right -= 1
        } else {
            collisions += 1
            left += 1
            right -= 1
        }
    }
    
    return collisions
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var cars = Array(repeating: 0, count: n)
    var collisions = 0
    var left = 0
    var right = n - 1
    
    while left < right {
        if cars[left] == 0 {
            cars[left] = 1
            left += 1
        } else if cars[right] == 0 {
            cars[right] = 1
            right -= 1
        } else {
            collisions += 1
            left += 1
            right -= 1
        }
    }
    
    return collisions
}
```

func carRaceCollision(n: Int) -> Int {
    var cars = Array(repeating: 0, count: n)
    var collisions = 0
    for i in 0..<n {
        cars[i] = 1
        for j in 0..<n {
            if cars[j] == 1 {
                collisions += 1
                cars[j] = -1
            }
        }
    }
    return collisions
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var cars = Array(repeating: 0, count: n)
    var collisions = 0
    for i in 0..<n {
        cars[i] = 1
        for j in 0..<n {
            if cars[j] == 1 {
                collisions += 1
                cars[j] = -1
            }
        }
    }
    return collisions
}
```

func carRaceCollision(n: Int) -> Int {
    var cars = [Int](repeating: 0, count: n)
    var left = 0
    var right = n - 1
    var collisions = 0

    while left < right {
        if cars[left] == 0 {
            cars[left] = 1
            left += 1
        } else if cars[right] == 0 {
            cars[right] = 1
            right -= 1
        } else {
            collisions += 1
            left += 1
            right -= 1
        }
    }

    return collisions
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var cars = [Int](repeating: 0, count: n)
    var left = 0
    var right = n - 1
    var collisions = 0

    while left < right {
        if cars[left] == 0 {
            cars[left] = 1
            left += 1
        } else if cars[right] == 0 {
            cars[right] = 1
            right -= 1
        } else {
            collisions += 1
            left += 1
            right -= 1
        }
    }

    return collisions
}
```

func carRaceCollision(n: Int) -> Int {
    var cars = Array(repeating: 0, count: n)
    var collisions = 0
    for i in 0..<n {
        cars[i] = 1
    }
    for i in 0..<n {
        if cars[i] == 1 {
            collisions += 1
            cars[i] = -1
        }
        for j in (i + 1)..<n {
            if cars[j] == -1 {
                continue
            }
            cars[j] += cars[i]
            if cars[j] == 0 {
                collisions += 1
                cars[j] = -1
            }
        }
    }
    return collisions
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var cars = Array(repeating: 0, count: n)
    var collisions = 0
    for i in 0..<n {
        cars[i] = 1
    }
    for i in 0..<n {
        if cars[i] == 1 {
            collisions += 1
            cars[i] = -1
        }
        for j in (i + 1)..<n {
            if cars[j] == -1 {
                continue
            }
            cars[j] += cars[i]
            if cars[j] == 0 {
                collisions += 1
                cars[j] = -1
            }
        }
    }
    return collisions
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i + 1)..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i + 1)..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i + 1)..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i + 1)..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var seen = Set<Int>()
    for num in l {
        if let complement = seen.subtracting([num]).first {
            return true
        }
        seen.insert(num)
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var seen = Set<Int>()
    for num in l {
        if let complement = seen.subtracting([num]).first {
            return true
        }
        seen.insert(num)
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var dict = [Int: Int]()
    for num in l {
        if let count = dict[num] {
            dict[num] = count + 1
        } else {
            dict[num] = 1
        }
    }
    for (num, count) in dict {
        if let otherCount = dict[num * -1] {
            if otherCount > 1 || (otherCount == 1 && count > 1) {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var dict = [Int: Int]()
    for num in l {
        if let count = dict[num] {
            dict[num] = count + 1
        } else {
            dict[num] = 1
        }
    }
    for (num, count) in dict {
        if let otherCount = dict[num * -1] {
            if otherCount > 1 || (otherCount == 1 && count > 1) {
                return true
            }
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i + 1)..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i + 1)..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        let remainder = num % base
        result = "\(remainder)" + result
        num /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        let remainder = num % base
        result = "\(remainder)" + result
        num /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var remainder = x
    while remainder > 0 {
        let digit = remainder % base
        result = "\(digit)" + result
        remainder /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var remainder = x
    while remainder > 0 {
        let digit = remainder % base
        result = "\(digit)" + result
        remainder /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    guard x >= 0 && base >= 2 && base <= 10 else {
        return "Invalid input"
    }
    
    var result = ""
    var num = x
    
    while num > 0 {
        let remainder = num % base
        result = "\(remainder)" + result
        num /= base
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    guard x >= 0 && base >= 2 && base <= 10 else {
        return "Invalid input"
    }
    
    var result = ""
    var num = x
    
    while num > 0 {
        let remainder = num % base
        result = "\(remainder)" + result
        num /= base
    }
    
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        result = "\(num % base)" + result
        num /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        result = "\(num % base)" + result
        num /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        let remainder = num % base
        result = "\(remainder)" + result
        num /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        let remainder = num % base
        result = "\(remainder)" + result
        num /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        let remainder = num % base
        result = "\(remainder)" + result
        num /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        let remainder = num % base
        result = "\(remainder)" + result
        num /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var temp = x
    while temp > 0 {
        result = "\(temp % base)" + result
        temp /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var temp = x
    while temp > 0 {
        result = "\(temp % base)" + result
        temp /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        let remainder = num % base
        result = "\(remainder)" + result
        num /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var num = x
    while num > 0 {
        let remainder = num % base
        result = "\(remainder)" + result
        num /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var temp = x
    while temp > 0 {
        let remainder = temp % base
        result = "\(remainder)" + result
        temp /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var temp = x
    while temp > 0 {
        let remainder = temp % base
        result = "\(remainder)" + result
        temp /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var temp = x
    while temp > 0 {
        let remainder = temp % base
        result = "\(remainder)" + result
        temp = temp / base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var temp = x
    while temp > 0 {
        let remainder = temp % base
        result = "\(remainder)" + result
        temp = temp / base
    }
    return result
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return 0.5 * Double(a) * Double(h)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return 0.5 * Double(a) * Double(h)
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return 0.5 * Double(a) * Double(h)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return 0.5 * Double(a) * Double(h)
}
```

func triangleArea(a: Int, h: Int) -> Double {
    let s = (a + a + h) / 2
    return sqrt(Double(s) * (s - a) * (s - a) * (s - h))
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    let s = (a + a + h) / 2
    return sqrt(Double(s) * (s - a) * (s - a) * (s - h))
}
```

func triangleArea(a: Int, h: Int) -> Double {
    let s = (a + a + h) / 2
    return (s * (s - a) * (s - h)) / 2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    let s = (a + a + h) / 2
    return (s * (s - a) * (s - h)) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    let s = (a + a + h) / 2
    return sqrt(Double(s) * (s - a) * (s - a) * (s - h))
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    let s = (a + a + h) / 2
    return sqrt(Double(s) * (s - a) * (s - a) * (s - h))
}
```

func triangleArea(a: Int, h: Int) -> Double {
    let s = (a + a + h) / 2
    return sqrt(Double(s) * (s - a) * (s - a) * (s - h))
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    let s = (a + a + h) / 2
    return sqrt(Double(s) * (s - a) * (s - a) * (s - h))
}
```

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 1

    for _ in 0..<n {
        c = a + b + c + d
        a = b
        b = c
        d = c
    }

    return c
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 1

    for _ in 0..<n {
        c = a + b + c + d
        a = b
        b = c
        d = c
    }

    return c
}
```

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 1

    for _ in 0..<n {
        c = d
        d = a + b + c + d
        a = b
        b = c
    }

    return d
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 1

    for _ in 0..<n {
        c = d
        d = a + b + c + d
        a = b
        b = c
    }

    return d
}
```

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 1
    for _ in 0..<n {
        c = d
        d = a + b + c + d
        a = b
        b = c
    }
    return d
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 1
    for _ in 0..<n {
        c = d
        d = a + b + c + d
        a = b
        b = c
    }
    return d
}
```

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 1
    for _ in 0..<n {
        let temp = c
        c = d
        d = temp + b + a
        a = b
        b = c
    }
    return d
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 1
    for _ in 0..<n {
        let temp = c
        c = d
        d = temp + b + a
        a = b
        b = c
    }
    return d
}
```

func fib4(n: Int) -> Int {
    if n == 0 {
        return 0
    } else if n == 1 {
        return 0
    } else if n == 2 {
        return 2
    } else if n == 3 {
        return 0
    } else {
        var a = 0
        var b = 0
        var c = 0
        var d = 0
        for _ in 0..<n {
            d = a + b + c + d
            a = b
            b = c
            c = d
        }
        return d
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    if n == 0 {
        return 0
    } else if n == 1 {
        return 0
    } else if n == 2 {
        return 2
    } else if n == 3 {
        return 0
    } else {
        var a = 0
        var b = 0
        var c = 0
        var d = 0
        for _ in 0..<n {
            d = a + b + c + d
            a = b
            b = c
            c = d
        }
        return d
    }
}
```

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 1

    for _ in 0..<n {
        c = d
        d = a + b + c + d
        a = b
        b = c
    }

    return d
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 1

    for _ in 0..<n {
        c = d
        d = a + b + c + d
        a = b
        b = c
    }

    return d
}
```

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 1

    for _ in 0..<n {
        c = d
        d = a + b + c + d
        a = b
        b = c
    }

    return d
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 1

    for _ in 0..<n {
        c = d
        d = a + b + c + d
        a = b
        b = c
    }

    return d
}
```

func fib4(n: Int) -> Int {
    if n == 0 {
        return 0
    } else if n == 1 {
        return 0
    } else if n == 2 {
        return 2
    } else if n == 3 {
        return 0
    } else {
        var a = 0
        var b = 0
        var c = 0
        var d = 0
        for _ in 0..<n {
            d = a + b + c + d
            a = b
            b = c
            c = d
        }
        return d
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    if n == 0 {
        return 0
    } else if n == 1 {
        return 0
    } else if n == 2 {
        return 2
    } else if n == 3 {
        return 0
    } else {
        var a = 0
        var b = 0
        var c = 0
        var d = 0
        for _ in 0..<n {
            d = a + b + c + d
            a = b
            b = c
            c = d
        }
        return d
    }
}
```

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 1

    for _ in 0..<n {
        c = d
        d = a + b + c
        a = b
        b = c
    }

    return d
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 1

    for _ in 0..<n {
        c = d
        d = a + b + c
        a = b
        b = c
    }

    return d
}
```

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 1
    for _ in 0..<n {
        c = d
        d = a + b + c + d
        a = b
        b = c
    }
    return d
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 1
    for _ in 0..<n {
        c = d
        d = a + b + c + d
        a = b
        b = c
    }
    return d
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let count = sorted.count
    if count % 2 == 0 {
        let mid = count / 2
        return Double(sorted[mid] + sorted[mid - 1]) / 2
    } else {
        return Double(sorted[count / 2])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let count = sorted.count
    if count % 2 == 0 {
        let mid = count / 2
        return Double(sorted[mid] + sorted[mid - 1]) / 2
    } else {
        return Double(sorted[count / 2])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let count = sorted.count
    let middleIndex = count / 2
    
    if count % 2 == 0 {
        let firstHalf = Double(sorted[middleIndex - 1] + sorted[middleIndex]) / 2
        let secondHalf = Double(sorted[middleIndex])
        return (firstHalf + secondHalf) / 2
    } else {
        return Double(sorted[middleIndex])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let count = sorted.count
    let middleIndex = count / 2
    
    if count % 2 == 0 {
        let firstHalf = Double(sorted[middleIndex - 1] + sorted[middleIndex]) / 2
        let secondHalf = Double(sorted[middleIndex])
        return (firstHalf + secondHalf) / 2
    } else {
        return Double(sorted[middleIndex])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let count = sorted.count
    let middleIndex = count / 2
    
    if count % 2 == 0 {
        let firstHalf = Double(sorted[middleIndex - 1] + sorted[middleIndex]) / 2
        let secondHalf = Double(sorted[middleIndex])
        return (firstHalf + secondHalf) / 2
    } else {
        return Double(sorted[middleIndex])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let count = sorted.count
    let middleIndex = count / 2
    
    if count % 2 == 0 {
        let firstHalf = Double(sorted[middleIndex - 1] + sorted[middleIndex]) / 2
        let secondHalf = Double(sorted[middleIndex])
        return (firstHalf + secondHalf) / 2
    } else {
        return Double(sorted[middleIndex])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let count = sorted.count
    let middleIndex = count / 2
    if count % 2 == 0 {
        return Double(sorted[middleIndex - 1] + sorted[middleIndex]) / 2.0
    } else {
        return Double(sorted[middleIndex])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let count = sorted.count
    let middleIndex = count / 2
    if count % 2 == 0 {
        return Double(sorted[middleIndex - 1] + sorted[middleIndex]) / 2.0
    } else {
        return Double(sorted[middleIndex])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let count = sorted.count
    if count % 2 == 0 {
        let index = count / 2
        return Double(sorted[index] + sorted[index - 1]) / 2
    } else {
        return Double(sorted[count / 2])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let count = sorted.count
    if count % 2 == 0 {
        let index = count / 2
        return Double(sorted[index] + sorted[index - 1]) / 2
    } else {
        return Double(sorted[count / 2])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let count = sorted.count
    let mid = count / 2
    if count % 2 == 0 {
        return Double(sorted[mid - 1] + sorted[mid]) / 2
    } else {
        return Double(sorted[mid])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let count = sorted.count
    let mid = count / 2
    if count % 2 == 0 {
        return Double(sorted[mid - 1] + sorted[mid]) / 2
    } else {
        return Double(sorted[mid])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let count = sorted.count
    if count % 2 == 1 {
        return Double(sorted[count / 2])
    } else {
        let mid = count / 2
        return Double((sorted[mid] + sorted[mid - 1]) / 2)
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let count = sorted.count
    if count % 2 == 1 {
        return Double(sorted[count / 2])
    } else {
        let mid = count / 2
        return Double((sorted[mid] + sorted[mid - 1]) / 2)
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let count = sorted.count
    if count % 2 == 0 {
        let index = count / 2
        return Double(sorted[index - 1] + sorted[index]) / 2
    } else {
        return Double(sorted[count / 2])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let count = sorted.count
    if count % 2 == 0 {
        let index = count / 2
        return Double(sorted[index - 1] + sorted[index]) / 2
    } else {
        return Double(sorted[count / 2])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let count = sorted.count
    let middleIndex = count / 2
    if count % 2 == 0 {
        return Double(sorted[middleIndex - 1] + sorted[middleIndex]) / 2
    } else {
        return Double(sorted[middleIndex])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let count = sorted.count
    let middleIndex = count / 2
    if count % 2 == 0 {
        return Double(sorted[middleIndex - 1] + sorted[middleIndex]) / 2
    } else {
        return Double(sorted[middleIndex])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let count = sorted.count
    let middleIndex = count / 2
    if count % 2 == 0 {
        return Double(sorted[middleIndex - 1] + sorted[middleIndex]) / 2
    } else {
        return Double(sorted[middleIndex])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let count = sorted.count
    let middleIndex = count / 2
    if count % 2 == 0 {
        return Double(sorted[middleIndex - 1] + sorted[middleIndex]) / 2
    } else {
        return Double(sorted[middleIndex])
    }
}
```