func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var temp: String = ""
    var stack: Stack = Stack()

    for char in parenString {
        if char == "(" {
            stack.push(char)
            temp += char
        } else if char == ")" {
            if stack.isEmpty {
                temp += char
            } else {
                stack.pop()
                temp += char
            }
        } else {
            temp += char
        }
    }

    if temp.count > 0 {
        result.append(temp)
    }

    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var temp: String = ""
    var stack: Stack = Stack()

    for char in parenString {
        if char == "(" {
            stack.push(char)
            temp += char
        } else if char == ")" {
            if stack.isEmpty {
                temp += char
            } else {
                stack.pop()
                temp += char
            }
        } else {
            temp += char
        }
    }

    if temp.count > 0 {
        result.append(temp)
    }

    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var temp = ""
    var stack = [Character]()
    
    for char in parenString {
        if char == "(" {
            stack.append(char)
            temp.append(char)
        } else if char == ")" {
            if stack.count > 0 {
                stack.removeLast()
                temp.append(char)
            } else {
                result.append(temp)
                temp = ""
            }
        } else {
            temp.append(char)
        }
    }
    
    if temp!= "" {
        result.append(temp)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var temp = ""
    var stack = [Character]()
    
    for char in parenString {
        if char == "(" {
            stack.append(char)
            temp.append(char)
        } else if char == ")" {
            if stack.count > 0 {
                stack.removeLast()
                temp.append(char)
            } else {
                result.append(temp)
                temp = ""
            }
        } else {
            temp.append(char)
        }
    }
    
    if temp!= "" {
        result.append(temp)
    }
    
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var temp = ""
    var openCount = 0
    
    for char in parenString {
        if char == "(" {
            openCount += 1
        } else if char == ")" {
            openCount -= 1
        }
        temp.append(char)
        if openCount == 0 {
            result.append(String(temp))
            temp = ""
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var temp = ""
    var openCount = 0
    
    for char in parenString {
        if char == "(" {
            openCount += 1
        } else if char == ")" {
            openCount -= 1
        }
        temp.append(char)
        if openCount == 0 {
            result.append(String(temp))
            temp = ""
        }
    }
    
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var temp: String = ""
    var openCount: Int = 0
    
    for char in parenString {
        if char == "(" {
            openCount += 1
        } else if char == ")" {
            openCount -= 1
        }
        temp.append(char)
        if openCount == 0 {
            result.append(String(temp))
            temp = ""
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var temp: String = ""
    var openCount: Int = 0
    
    for char in parenString {
        if char == "(" {
            openCount += 1
        } else if char == ")" {
            openCount -= 1
        }
        temp.append(char)
        if openCount == 0 {
            result.append(String(temp))
            temp = ""
        }
    }
    
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup: String = ""
    var openCount: Int = 0
    
    for char in parenString {
        if char == "(" {
            openCount += 1
            currentGroup.append(char)
        } else if char == ")" {
            openCount -= 1
            currentGroup.append(char)
        }
        
        if openCount == 0 {
            result.append(currentGroup)
            currentGroup = ""
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup: String = ""
    var openCount: Int = 0
    
    for char in parenString {
        if char == "(" {
            openCount += 1
            currentGroup.append(char)
        } else if char == ")" {
            openCount -= 1
            currentGroup.append(char)
        }
        
        if openCount == 0 {
            result.append(currentGroup)
            currentGroup = ""
        }
    }
    
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var openCount = 0
    var group = ""
    
    for char in parenString {
        if char == "(" {
            openCount += 1
        } else if char == ")" {
            openCount -= 1
        }
        
        group.append(char)
        
        if openCount == 0 {
            result.append(group)
            group = ""
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var openCount = 0
    var group = ""
    
    for char in parenString {
        if char == "(" {
            openCount += 1
        } else if char == ")" {
            openCount -= 1
        }
        
        group.append(char)
        
        if openCount == 0 {
            result.append(group)
            group = ""
        }
    }
    
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var temp = ""
    var balance = 0

    for char in parenString {
        if char == "(" {
            balance += 1
        } else if char == ")" {
            balance -= 1
        }
        temp.append(char)
        if balance == 0 {
            result.append(String(temp))
            temp = ""
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var temp = ""
    var balance = 0

    for char in parenString {
        if char == "(" {
            balance += 1
        } else if char == ")" {
            balance -= 1
        }
        temp.append(char)
        if balance == 0 {
            result.append(String(temp))
            temp = ""
        }
    }
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var stack: [Character] = []

    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            if let top = stack.popLast() {
                if top!= "(" {
                    stack.append(top)
                    stack.append(char)
                }
            }
        }
    }

    var group: String = ""
    for char in stack {
        group.append(char)
    }
    result.append(group)

    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var stack: [Character] = []

    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            if let top = stack.popLast() {
                if top!= "(" {
                    stack.append(top)
                    stack.append(char)
                }
            }
        }
    }

    var group: String = ""
    for char in stack {
        group.append(char)
    }
    result.append(group)

    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var temp: String = ""
    var openCount: Int = 0
    
    for char in parenString {
        if char == "(" {
            openCount += 1
            temp.append(char)
        } else if char == ")" {
            openCount -= 1
            temp.append(char)
        }
        
        if openCount == 0 {
            result.append(temp)
            temp = ""
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var temp: String = ""
    var openCount: Int = 0
    
    for char in parenString {
        if char == "(" {
            openCount += 1
            temp.append(char)
        } else if char == ")" {
            openCount -= 1
            temp.append(char)
        }
        
        if openCount == 0 {
            result.append(temp)
            temp = ""
        }
    }
    
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var temp = ""
    var balance = 0
    
    for char in parenString {
        if char == "(" {
            balance += 1
        } else if char == ")" {
            balance -= 1
        }
        temp.append(char)
        if balance == 0 {
            result.append(String(temp))
            temp = ""
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var temp = ""
    var balance = 0
    
    for char in parenString {
        if char == "(" {
            balance += 1
        } else if char == ")" {
            balance -= 1
        }
        temp.append(char)
        if balance == 0 {
            result.append(String(temp))
            temp = ""
        }
    }
    
    return result
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    var sum = 0.0
    for number in numbers {
        sum += abs(number - mean)
    }
    return sum / Double(numbers.count)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    var sum = 0.0
    for number in numbers {
        sum += abs(number - mean)
    }
    return sum / Double(numbers.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    var sum = 0.0
    for number in numbers {
        sum += abs(number - mean)
    }
    return sum / Double(numbers.count)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    var sum = 0.0
    for number in numbers {
        sum += abs(number - mean)
    }
    return sum / Double(numbers.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    var sum = 0.0
    for number in numbers {
        sum += abs(number - mean)
    }
    return sum / Double(numbers.count)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    var sum = 0.0
    for number in numbers {
        sum += abs(number - mean)
    }
    return sum / Double(numbers.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    var sum = 0.0
    for number in numbers {
        sum += abs(number - mean)
    }
    return sum / Double(numbers.count)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    var sum = 0.0
    for number in numbers {
        sum += abs(number - mean)
    }
    return sum / Double(numbers.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    var sum = 0.0
    for number in numbers {
        sum += abs(number - mean)
    }
    return sum / Double(numbers.count)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    var sum = 0.0
    for number in numbers {
        sum += abs(number - mean)
    }
    return sum / Double(numbers.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    var sum = 0.0
    for number in numbers {
        sum += abs(number - mean)
    }
    return sum / Double(numbers.count)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    var sum = 0.0
    for number in numbers {
        sum += abs(number - mean)
    }
    return sum / Double(numbers.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    var sum = 0.0
    for number in numbers {
        sum += abs(number - mean)
    }
    return sum / Double(numbers.count)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    var sum = 0.0
    for number in numbers {
        sum += abs(number - mean)
    }
    return sum / Double(numbers.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    var sum = 0.0
    for number in numbers {
        sum += abs(number - mean)
    }
    return sum / Double(numbers.count)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    var sum = 0.0
    for number in numbers {
        sum += abs(number - mean)
    }
    return sum / Double(numbers.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    var sum = 0.0
    for number in numbers {
        sum += abs(number - mean)
    }
    return sum / Double(numbers.count)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    var sum = 0.0
    for number in numbers {
        sum += abs(number - mean)
    }
    return sum / Double(numbers.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    var sum = 0.0
    for number in numbers {
        sum += abs(number - mean)
    }
    return sum / Double(numbers.count)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    var sum = 0.0
    for number in numbers {
        sum += abs(number - mean)
    }
    return sum / Double(numbers.count)
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var stack: [Int] = []
    var maxDepth: Int = 0
    var depth: Int = 0
    
    for char in parenString {
        if char == "(" {
            stack.append(depth)
            depth += 1
            maxDepth = max(maxDepth, depth)
        } else if char == ")" {
            depth = stack.removeLast()
        }
    }
    
    return Array(repeating: maxDepth, count: stack.count)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var stack: [Int] = []
    var maxDepth: Int = 0
    var depth: Int = 0
    
    for char in parenString {
        if char == "(" {
            stack.append(depth)
            depth += 1
            maxDepth = max(maxDepth, depth)
        } else if char == ")" {
            depth = stack.removeLast()
        }
    }
    
    return Array(repeating: maxDepth, count: stack.count)
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var stack: [Int] = []
    var maxDepth: [Int] = []
    
    for char in parenString {
        if char == "(" {
            stack.append(1)
        } else {
            if let top = stack.popLast() {
                if let lastMax = maxDepth.last {
                    maxDepth.append(max(lastMax, top + 1))
                } else {
                    maxDepth.append(top + 1)
                }
            }
        }
    }
    
    return maxDepth
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var stack: [Int] = []
    var maxDepth: [Int] = []
    
    for char in parenString {
        if char == "(" {
            stack.append(1)
        } else {
            if let top = stack.popLast() {
                if let lastMax = maxDepth.last {
                    maxDepth.append(max(lastMax, top + 1))
                } else {
                    maxDepth.append(top + 1)
                }
            }
        }
    }
    
    return maxDepth
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var maxDepth = 0
    var stack = [Int]()
    var results = [Int]()
    
    for char in parenString {
        if char == "(" {
            stack.append(maxDepth)
            maxDepth += 1
        } else if char == ")" {
            maxDepth = stack.removeLast()
        }
        results.append(maxDepth)
    }
    
    return results
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var maxDepth = 0
    var stack = [Int]()
    var results = [Int]()
    
    for char in parenString {
        if char == "(" {
            stack.append(maxDepth)
            maxDepth += 1
        } else if char == ")" {
            maxDepth = stack.removeLast()
        }
        results.append(maxDepth)
    }
    
    return results
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var stack: [Int] = []
    var maxDepth: Int = 0
    var depth: Int = 0
    
    for char in parenString {
        if char == "(" {
            stack.append(depth)
            depth += 1
            maxDepth = max(maxDepth, depth)
        } else if char == ")" {
            depth = stack.removeLast()
        }
    }
    
    return Array(repeating: maxDepth, count: stack.count)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var stack: [Int] = []
    var maxDepth: Int = 0
    var depth: Int = 0
    
    for char in parenString {
        if char == "(" {
            stack.append(depth)
            depth += 1
            maxDepth = max(maxDepth, depth)
        } else if char == ")" {
            depth = stack.removeLast()
        }
    }
    
    return Array(repeating: maxDepth, count: stack.count)
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var maxDepth = 0
    var stack = [Int]()
    var results = [Int]()
    
    for char in parenString {
        if char == "(" {
            stack.append(maxDepth)
            maxDepth += 1
        } else if char == ")" {
            maxDepth = stack.removeLast()
        }
        results.append(maxDepth)
    }
    
    return results
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var maxDepth = 0
    var stack = [Int]()
    var results = [Int]()
    
    for char in parenString {
        if char == "(" {
            stack.append(maxDepth)
            maxDepth += 1
        } else if char == ")" {
            maxDepth = stack.removeLast()
        }
        results.append(maxDepth)
    }
    
    return results
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var maxDepth = 0
    var currentDepth = 0
    var results = [Int]()
    
    for char in parenString {
        if char == "(" {
            currentDepth += 1
            maxDepth = max(maxDepth, currentDepth)
        } else if char == ")" {
            currentDepth -= 1
        }
        results.append(maxDepth)
    }
    
    return results
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var maxDepth = 0
    var currentDepth = 0
    var results = [Int]()
    
    for char in parenString {
        if char == "(" {
            currentDepth += 1
            maxDepth = max(maxDepth, currentDepth)
        } else if char == ")" {
            currentDepth -= 1
        }
        results.append(maxDepth)
    }
    
    return results
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var stack = [Int]()
    var maxDepth = 0
    var depth = 0

    for char in parenString {
        if char == "(" {
            depth += 1
            stack.append(depth)
        } else if char == ")" {
            depth -= 1
            if depth < maxDepth {
                maxDepth = depth
            }
        }
    }

    return stack.map { maxDepth - $0 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var stack = [Int]()
    var maxDepth = 0
    var depth = 0

    for char in parenString {
        if char == "(" {
            depth += 1
            stack.append(depth)
        } else if char == ")" {
            depth -= 1
            if depth < maxDepth {
                maxDepth = depth
            }
        }
    }

    return stack.map { maxDepth - $0 }
}
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var maxDepth = 0
    var currentDepth = 0
    var results = [Int]()

    for char in parenString {
        if char == "(" {
            currentDepth += 1
            maxDepth = max(maxDepth, currentDepth)
        } else if char == ")" {
            currentDepth -= 1
        }

        if char == " " {
            results.append(maxDepth)
            maxDepth = 0
        }
    }

    return results
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var maxDepth = 0
    var currentDepth = 0
    var results = [Int]()

    for char in parenString {
        if char == "(" {
            currentDepth += 1
            maxDepth = max(maxDepth, currentDepth)
        } else if char == ")" {
            currentDepth -= 1
        }

        if char == " " {
            results.append(maxDepth)
            maxDepth = 0
        }
    }

    return results
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var maxDepth = 0
    var depth = 0
    var results = [Int]()

    for char in parenString {
        switch char {
        case "(":
            depth += 1
            maxDepth = max(maxDepth, depth)
        case ")":
            depth -= 1
        default:
            break
        }
    }

    results.append(maxDepth)

    let subString = String(parenString.dropFirst(1))
    let subResults = parseNestedParens(parenString: subString)
    results.append(contentsOf: subResults)

    return results
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var maxDepth = 0
    var depth = 0
    var results = [Int]()

    for char in parenString {
        switch char {
        case "(":
            depth += 1
            maxDepth = max(maxDepth, depth)
        case ")":
            depth -= 1
        default:
            break
        }
    }

    results.append(maxDepth)

    let subString = String(parenString.dropFirst(1))
    let subResults = parseNestedParens(parenString: subString)
    results.append(contentsOf: subResults)

    return results
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var maxDepth = 0
    var currentDepth = 0
    var results = [Int]()
    
    for char in parenString {
        if char == "(" {
            currentDepth += 1
            maxDepth = max(maxDepth, currentDepth)
        } else if char == ")" {
            currentDepth -= 1
        }
        results.append(maxDepth)
    }
    
    return results
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var maxDepth = 0
    var currentDepth = 0
    var results = [Int]()
    
    for char in parenString {
        if char == "(" {
            currentDepth += 1
            maxDepth = max(maxDepth, currentDepth)
        } else if char == ")" {
            currentDepth -= 1
        }
        results.append(maxDepth)
    }
    
    return results
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    var result: [String] = []
    for string in strings {
        if string.rangeOfString(substring)!= nil {
            result.append(string)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    var result: [String] = []
    for string in strings {
        if string.rangeOfString(substring)!= nil {
            result.append(string)
        }
    }
    return result
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { string in string.rangeOfString(substring)!= nil }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { string in string.rangeOfString(substring)!= nil }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { string in string.rangeOfString(substring)!= nil }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { string in string.rangeOfString(substring)!= nil }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.rangeOfString(substring)!= nil }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.rangeOfString(substring)!= nil }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    var result: [String] = []
    for string in strings {
        if string.rangeOfString(substring)!= nil {
            result.append(string)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    var result: [String] = []
    for string in strings {
        if string.rangeOfString(substring)!= nil {
            result.append(string)
        }
    }
    return result
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { string in string.rangeOfString(substring)!= nil }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { string in string.rangeOfString(substring)!= nil }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { string in string.rangeOfString(substring)!= nil }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { string in string.rangeOfString(substring)!= nil }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { string in string.rangeOfString(substring)!= nil }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { string in string.rangeOfString(substring)!= nil }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { string in string.containsString(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { string in string.containsString(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.rangeOfString(substring)!= nil }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.rangeOfString(substring)!= nil }
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    if numbers.count == 0 {
        return (0, 1)
    }
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    if numbers.count == 0 {
        return (0, 1)
    }
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    if numbers.count == 0 {
        return (0, 1)
    }
    
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    if numbers.count == 0 {
        return (0, 1)
    }
    
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    if numbers.count == 0 {
        return (0, 1)
    }
    
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    if numbers.count == 0 {
        return (0, 1)
    }
    
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var rollingMax = [Int]()
    var max = Int.min
    
    for number in numbers {
        max = max < number? number : max
        rollingMax.append(max)
    }
    
    return rollingMax
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var rollingMax = [Int]()
    var max = Int.min
    
    for number in numbers {
        max = max < number? number : max
        rollingMax.append(max)
    }
    
    return rollingMax
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = Int.min
    
    for number in numbers {
        max = max < number? number : max
        result.append(max)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = Int.min
    
    for number in numbers {
        max = max < number? number : max
        result.append(max)
    }
    
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = Int.min
    
    for number in numbers {
        max = max < number? number : max
        result.append(max)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = Int.min
    
    for number in numbers {
        max = max < number? number : max
        result.append(max)
    }
    
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = Int.min
    
    for number in numbers {
        max = max < number? number : max
        result.append(max)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = Int.min
    
    for number in numbers {
        max = max < number? number : max
        result.append(max)
    }
    
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = Int.min
    
    for number in numbers {
        max = max < number? number : max
        result.append(max)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = Int.min
    
    for number in numbers {
        max = max < number? number : max
        result.append(max)
    }
    
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = Int.min
    
    for number in numbers {
        max = max < number? number : max
        result.append(max)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = Int.min
    
    for number in numbers {
        max = max < number? number : max
        result.append(max)
    }
    
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = numbers[0]
    result.append(max)
    for i in 1..<numbers.count {
        max = max(max, numbers[i])
        result.append(max)
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = numbers[0]
    result.append(max)
    for i in 1..<numbers.count {
        max = max(max, numbers[i])
        result.append(max)
    }
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = Int.min
    
    for number in numbers {
        max = max < number? number : max
        result.append(max)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = Int.min
    
    for number in numbers {
        max = max < number? number : max
        result.append(max)
    }
    
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = Int.min
    
    for number in numbers {
        max = max < number? number : max
        result.append(max)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = Int.min
    
    for number in numbers {
        max = max < number? number : max
        result.append(max)
    }
    
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = Int.min
    
    for number in numbers {
        max = max < number? number : max
        result.append(max)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = Int.min
    
    for number in numbers {
        max = max < number? number : max
        result.append(max)
    }
    
    return result
}
```

func makePalindrome(string: String) -> String {
    let reverse = String(string.reversed())
    let prefix = string.prefix(string.index(string.startIndex, offsetBy: 1))
    let postfix = reverse.prefix(reverse.distance(from: reverse.startIndex, to: reverse.index(before: reverse.endIndex)))
    
    let palindrome = prefix + postfix
    let index = string.distance(from: string.startIndex, to: reverse.startIndex)
    let result = string.prefix(index) + palindrome
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let reverse = String(string.reversed())
    let prefix = string.prefix(string.index(string.startIndex, offsetBy: 1))
    let postfix = reverse.prefix(reverse.distance(from: reverse.startIndex, to: reverse.index(before: reverse.endIndex)))
    
    let palindrome = prefix + postfix
    let index = string.distance(from: string.startIndex, to: reverse.startIndex)
    let result = string.prefix(index) + palindrome
    
    return result
}
```

func makePalindrome(string: String) -> String {
    let reverseString = String(string.reversed())
    let length = string.count
    var prefix = ""
    var postfix = ""
    
    for i in 0..<length {
        if string[i] == reverseString[i] {
            prefix += string[i]
        } else {
            postfix = reverseString[i..<length]
            break
        }
    }
    
    return prefix + String(postfix.reversed())
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let reverseString = String(string.reversed())
    let length = string.count
    var prefix = ""
    var postfix = ""
    
    for i in 0..<length {
        if string[i] == reverseString[i] {
            prefix += string[i]
        } else {
            postfix = reverseString[i..<length]
            break
        }
    }
    
    return prefix + String(postfix.reversed())
}
```

func makePalindrome(string: String) -> String {
    let reverse = String(string.reversed())
    let length = string.count
    var prefix = ""
    var postfix = ""
    
    for i in stride(from: length - 1, to: 0, by: -1) {
        if string[string.index(string.startIndex, offsetBy: i)] == reverse[reverse.index(reverse.startIndex, offsetBy: length - i - 1)] {
            postfix = reverse[reverse.index(reverse.startIndex, offsetBy: length - i - 1)] + postfix
        } else {
            prefix = reverse[reverse.index(reverse.startIndex, offsetBy: length - i)] + prefix
            break
        }
    }
    
    return prefix + string + postfix
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let reverse = String(string.reversed())
    let length = string.count
    var prefix = ""
    var postfix = ""
    
    for i in stride(from: length - 1, to: 0, by: -1) {
        if string[string.index(string.startIndex, offsetBy: i)] == reverse[reverse.index(reverse.startIndex, offsetBy: length - i - 1)] {
            postfix = reverse[reverse.index(reverse.startIndex, offsetBy: length - i - 1)] + postfix
        } else {
            prefix = reverse[reverse.index(reverse.startIndex, offsetBy: length - i)] + prefix
            break
        }
    }
    
    return prefix + string + postfix
}
```

func makePalindrome(string: String) -> String {
    let length = string.count
    guard length > 0 else { return "" }
    
    let prefix = string.prefix(length / 2)
    let postfix = string.suffix(length / 2)
    
    let reversePrefix = String(prefix.reversed())
    
    let palindromicSuffix = length % 2 == 0? postfix : postfix.dropFirst()
    
    return string + reversePrefix + String(palindromicSuffix)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let length = string.count
    guard length > 0 else { return "" }
    
    let prefix = string.prefix(length / 2)
    let postfix = string.suffix(length / 2)
    
    let reversePrefix = String(prefix.reversed())
    
    let palindromicSuffix = length % 2 == 0? postfix : postfix.dropFirst()
    
    return string + reversePrefix + String(palindromicSuffix)
}
```

func makePalindrome(string: String) -> String {
    let string = string.trimmingCharacters(in:.whitespacesAndNewlines)
    guard!string.isEmpty else { return "" }
    
    let longestPalindromicSuffix = findLongestPalindromicSuffix(in: string)
    let prefix = String(string.prefix(string.index(before: longestPalindromicSuffix.startIndex)))
    let reversedPrefix = String(prefix.reversed())
    
    return string + reversedPrefix
}

func findLongestPalindromicSuffix(in string: String) -> String {
    let characters = Array(string.reversed())
    var longestPalindromicSuffix = ""
    
    for i in 0..<characters.count {
        let substring = String(characters[i..<characters.count])
        if substring == String(substring.reversed()) && substring.count > longestPalindromicSuffix.count {
            longestPalindromicSuffix = substring
        }
    }
    
    return longestPalindromicSuffix
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let string = string.trimmingCharacters(in:.whitespacesAndNewlines)
    guard!string.isEmpty else { return "" }
    
    let longestPalindromicSuffix = findLongestPalindromicSuffix(in: string)
    let prefix = String(string.prefix(string.index(before: longestPalindromicSuffix.startIndex)))
    let reversedPrefix = String(prefix.reversed())
    
    return string + reversedPrefix
}

func findLongestPalindromicSuffix(in string: String) -> String {
    let characters = Array(string.reversed())
    var longestPalindromicSuffix = ""
    
    for i in 0..<characters.count {
        let substring = String(characters[i..<characters.count])
        if substring == String(substring.reversed()) && substring.count > longestPalindromicSuffix.count {
            longestPalindromicSuffix = substring
        }
    }
    
    return longestPalindromicSuffix
}
```

func makePalindrome(string: String) -> String {
    let reverse = String(string.reversed())
    let prefix = string.prefix(string.distance(from: string.startIndex, to: string.index(of: reverse.first!, from: reverse.startIndex)))
    let palindromicSuffix = reverse.prefix(reverse.distance(from: reverse.startIndex, to: reverse.index(of: prefix.last!, from: prefix.startIndex)))
    let result = string + String(palindromicSuffix.reversed())
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let reverse = String(string.reversed())
    let prefix = string.prefix(string.distance(from: string.startIndex, to: string.index(of: reverse.first!, from: reverse.startIndex)))
    let palindromicSuffix = reverse.prefix(reverse.distance(from: reverse.startIndex, to: reverse.index(of: prefix.last!, from: prefix.startIndex)))
    let result = string + String(palindromicSuffix.reversed())
    return result
}
```

func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    let length = string.count
    var prefix = ""
    var postfix = ""
    
    for i in stride(from: length - 1, to: 0, by: -1) {
        let substring = String(string[string.index(string.startIndex, offsetBy: i)...string.index(string.startIndex, offsetBy: length - 1)])
        if isPalindrome(substring) {
            postfix = substring
            break
        } else {
            prefix.append(string[string.index(string.startIndex, offsetBy: i)])
        }
    }
    
    let result = prefix + String(reversed) + postfix
    return result
}

func isPalindrome(_ string: String) -> Bool {
    let characters = Array(string.lowercased())
    let reversed = characters.reversed()
    return characters == reversed
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    let length = string.count
    var prefix = ""
    var postfix = ""
    
    for i in stride(from: length - 1, to: 0, by: -1) {
        let substring = String(string[string.index(string.startIndex, offsetBy: i)...string.index(string.startIndex, offsetBy: length - 1)])
        if isPalindrome(substring) {
            postfix = substring
            break
        } else {
            prefix.append(string[string.index(string.startIndex, offsetBy: i)])
        }
    }
    
    let result = prefix + String(reversed) + postfix
    return result
}

func isPalindrome(_ string: String) -> Bool {
    let characters = Array(string.lowercased())
    let reversed = characters.reversed()
    return characters == reversed
}
```

func makePalindrome(string: String) -> String {
    let reverse = String(string.reversed())
    let length = string.count
    var prefix = ""
    var postfix = ""
    for i in 0..<length {
        if string[i] == reverse[i] {
            prefix += string[i]
        } else {
            postfix = reverse[i..<length]
            break
        }
    }
    return prefix + String(postfix.reversed())
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let reverse = String(string.reversed())
    let length = string.count
    var prefix = ""
    var postfix = ""
    for i in 0..<length {
        if string[i] == reverse[i] {
            prefix += string[i]
        } else {
            postfix = reverse[i..<length]
            break
        }
    }
    return prefix + String(postfix.reversed())
}
```

func makePalindrome(string: String) -> String {
    let reverseString = String(string.reversed())
    let length = string.count
    let prefix = string.prefix(length / 2)
    let postfix = reverseString.prefix(length / 2)
    
    if string == reverseString {
        return string
    } else if length % 2 == 0 {
        return prefix + reverseString + postfix
    } else {
        return prefix + reverseString + postfix.dropFirst()
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let reverseString = String(string.reversed())
    let length = string.count
    let prefix = string.prefix(length / 2)
    let postfix = reverseString.prefix(length / 2)
    
    if string == reverseString {
        return string
    } else if length % 2 == 0 {
        return prefix + reverseString + postfix
    } else {
        return prefix + reverseString + postfix.dropFirst()
    }
}
```

func makePalindrome(string: String) -> String {
    let reverseString = String(string.reversed())
    let palindromicSuffix = findLongestPalindromicSuffix(string: string)
    let prefix = String(string.dropLast(palindromicSuffix.count))
    let reversedPrefix = String(prefix.reversed())
    return string + reversedPrefix + palindromicSuffix
}

func findLongestPalindromicSuffix(string: String) -> String {
    let reverseString = String(string.reversed())
    let length = string.count
    for i in 0..<length {
        let prefix = String(string.prefix(i + 1))
        let reversedPrefix = String(reverseString.prefix(i + 1))
        if prefix == reversedPrefix {
            return prefix
        }
    }
    return ""
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let reverseString = String(string.reversed())
    let palindromicSuffix = findLongestPalindromicSuffix(string: string)
    let prefix = String(string.dropLast(palindromicSuffix.count))
    let reversedPrefix = String(prefix.reversed())
    return string + reversedPrefix + palindromicSuffix
}

func findLongestPalindromicSuffix(string: String) -> String {
    let reverseString = String(string.reversed())
    let length = string.count
    for i in 0..<length {
        let prefix = String(string.prefix(i + 1))
        let reversedPrefix = String(reverseString.prefix(i + 1))
        if prefix == reversedPrefix {
            return prefix
        }
    }
    return ""
}
```

func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    
    let xorData = aData.xor(bData)
    
    return String(data: xorData, encoding:.utf8)!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    
    let xorData = aData.xor(bData)
    
    return String(data: xorData, encoding:.utf8)!
}
```

func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let aBytes = aData.map { $0.bytes.first! }
    let bBytes = bData.map { $0.bytes.first! }
    let resultBytes = aBytes.enumerated().map { index, byte in
        let a = byte.element; let b = bBytes[index].element; return a ^ b
    }
    let resultData = Data(bytes: resultBytes)
    let resultString = String(data: resultData, encoding:.utf8)
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let aBytes = aData.map { $0.bytes.first! }
    let bBytes = bData.map { $0.bytes.first! }
    let resultBytes = aBytes.enumerated().map { index, byte in
        let a = byte.element; let b = bBytes[index].element; return a ^ b
    }
    let resultData = Data(bytes: resultBytes)
    let resultString = String(data: resultData, encoding:.utf8)
    return result
}
```

func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let resultData = aData.xor(bData)
    return String(data: resultData, encoding:.utf8)!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let resultData = aData.xor(bData)
    return String(data: resultData, encoding:.utf8)!
}
```

func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    
    let aBytes = Array(aData.bytes)
    let bBytes = Array(bData.bytes)
    
    var resultBytes = [UInt8]()
    
    for i in 0..<aBytes.count {
        let aByte = aBytes[i]
        let bByte = bBytes[i]
        
        let xorByte = aByte ^ bByte
        resultBytes.append(xorByte)
    }
    
    let resultData = Data(bytes: resultBytes)
    let resultString = String(data: resultData, encoding:.utf8Bit)?? ""
    
    return resultString
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    
    let aBytes = Array(aData.bytes)
    let bBytes = Array(bData.bytes)
    
    var resultBytes = [UInt8]()
    
    for i in 0..<aBytes.count {
        let aByte = aBytes[i]
        let bByte = bBytes[i]
        
        let xorByte = aByte ^ bByte
        resultBytes.append(xorByte)
    }
    
    let resultData = Data(bytes: resultBytes)
    let resultString = String(data: resultData, encoding:.utf8Bit)?? ""
    
    return resultString
}
```

func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    
    let aBytes = aData.map { $0.bytes }
    let bBytes = bData.map { $0.bytes }
    
    let maxBytes = max(aBytes.count, bBytes.count)
    
    var aBytes padded = aBytes
    var bBytes padded = bBytes
    
    if aBytes.count < maxBytes {
        aBytes.append(repeating: 0, count: maxBytes - aBytes.count)
    } else {
        bBytes.append(repeating: 0, count: maxBytes - bBytes.count)
    }
    
    let resultBytes = zip(aBytes, bBytes).map { $0 ^ $1 }
    
    let resultData = Data(bytes: resultBytes)
    let result = String(data: resultData, encoding:.utf8Bit)
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    
    let aBytes = aData.map { $0.bytes }
    let bBytes = bData.map { $0.bytes }
    
    let maxBytes = max(aBytes.count, bBytes.count)
    
    var aBytes padded = aBytes
    var bBytes padded = bBytes
    
    if aBytes.count < maxBytes {
        aBytes.append(repeating: 0, count: maxBytes - aBytes.count)
    } else {
        bBytes.append(repeating: 0, count: maxBytes - bBytes.count)
    }
    
    let resultBytes = zip(aBytes, bBytes).map { $0 ^ $1 }
    
    let resultData = Data(bytes: resultBytes)
    let result = String(data: resultData, encoding:.utf8Bit)
    
    return result
}
```

func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let aBytes = aData.map { $0.bytes.first! }
    let bBytes = bData.map { $0.bytes.first! }
    let resultBytes = aBytes.enumerated().map { index, byte in
        let a = byte.element, let b = bBytes[index].element, let c = a ^ b {
            return c
        }
    }
    let resultData = Data(bytes: resultBytes)
    let result = String(data: resultData, encoding:.utf8Bit)
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let aBytes = aData.map { $0.bytes.first! }
    let bBytes = bData.map { $0.bytes.first! }
    let resultBytes = aBytes.enumerated().map { index, byte in
        let a = byte.element, let b = bBytes[index].element, let c = a ^ b {
            return c
        }
    }
    let resultData = Data(bytes: resultBytes)
    let result = String(data: resultData, encoding:.utf8Bit)
    return result
}
```

func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let aBytes = aData.map { $0.bytes }
    let bBytes = bData.map { $0.bytes }
    let resultBytes = aBytes.enumerated().map { index, byte in
        let a = byte.element
        let b = bBytes[index].element
        return a ^ b
    }
    let resultData = Data(bytes: resultBytes)
    let result = String(data: resultData, encoding:.utf8Bit)
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let aBytes = aData.map { $0.bytes }
    let bBytes = bData.map { $0.bytes }
    let resultBytes = aBytes.enumerated().map { index, byte in
        let a = byte.element
        let b = bBytes[index].element
        return a ^ b
    }
    let resultData = Data(bytes: resultBytes)
    let result = String(data: resultData, encoding:.utf8Bit)
    return result
}
```

func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    
    let aBytes = aData.map { $0.bytes }
    let bBytes = bData.map { $0.bytes }
    
    let resultBytes = aBytes.enumerated().map { index, byte in
        let a = byte.element, let b = bBytes[index].element in
        return a ^ b
    }
    
    let resultData = Data(bytes: resultBytes)
    let resultString = String(data: resultData, encoding:.utf8Bit)
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    
    let aBytes = aData.map { $0.bytes }
    let bBytes = bData.map { $0.bytes }
    
    let resultBytes = aBytes.enumerated().map { index, byte in
        let a = byte.element, let b = bBytes[index].element in
        return a ^ b
    }
    
    let resultData = Data(bytes: resultBytes)
    let resultString = String(data: resultData, encoding:.utf8Bit)
    
    return result
}
```

func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    
    let xorData = aData.xor(bData)
    
    return String(data: xorData, encoding:.utf8)!
}

extension Data {
    func xor(_ other: Data) -> Data {
        var result = [UInt8](repeating: 0, count: self.count)
        
        for i in 0..<self.count {
            result[i] = self[i] ^ other[i]
        }
        
        return Data(bytes: result)
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    
    let xorData = aData.xor(bData)
    
    return String(data: xorData, encoding:.utf8)!
}

extension Data {
    func xor(_ other: Data) -> Data {
        var result = [UInt8](repeating: 0, count: self.count)
        
        for i in 0..<self.count {
            result[i] = self[i] ^ other[i]
        }
        
        return Data(bytes: result)
    }
}
```

func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let aBytes = Array(aData)
    let bBytes = Array(bData)
    let maxBytes = max(aBytes.count, bBytes.count)
    let aPadded = aBytes + Array(repeating: 0, count: maxBytes - aBytes.count)
    let bPadded = bBytes + Array(repeating: 0, count: maxBytes - bBytes.count)
    let resultBytes = zip(aPadded, bPadded).map { $0 ^ $1 }
    let resultData = Data(bytes: resultBytes)
    let resultString = String(data: resultData, encoding:.utf8Bit)
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let aBytes = Array(aData)
    let bBytes = Array(bData)
    let maxBytes = max(aBytes.count, bBytes.count)
    let aPadded = aBytes + Array(repeating: 0, count: maxBytes - aBytes.count)
    let bPadded = bBytes + Array(repeating: 0, count: maxBytes - bBytes.count)
    let resultBytes = zip(aPadded, bPadded).map { $0 ^ $1 }
    let resultData = Data(bytes: resultBytes)
    let resultString = String(data: resultData, encoding:.utf8Bit)
    return result
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else {
        return nil
    }
    
    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }
    
    return longestString
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else {
        return nil
    }
    
    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }
    
    return longestString
}
```

func longest(strings: [String]) -> String? {
    if strings.isEmpty {
        return nil
    }
    
    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }
    
    return longestString
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    if strings.isEmpty {
        return nil
    }
    
    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }
    
    return longestString
}
```

func longest(strings: [String]) -> String? {
    if strings.count == 0 {
        return nil
    }
    
    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }
    
    return longestString
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    if strings.count == 0 {
        return nil
    }
    
    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }
    
    return longestString
}
```

func longest(strings: [String]) -> String? {
    if strings.count == 0 {
        return nil
    }
    
    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }
    
    return longestString
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    if strings.count == 0 {
        return nil
    }
    
    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }
    
    return longestString
}
```

func longest(strings: [String]) -> String? {
    if strings.count == 0 {
        return nil
    }
    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }
    return longestString
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    if strings.count == 0 {
        return nil
    }
    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }
    return longestString
}
```

func longest(strings: [String]) -> String? {
    if strings.count == 0 {
        return nil
    }
    
    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }
    
    return longestString
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    if strings.count == 0 {
        return nil
    }
    
    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }
    
    return longestString
}
```

func longest(strings: [String]) -> String? {
    if strings.isEmpty {
        return nil
    }
    
    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }
    
    return longestString
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    if strings.isEmpty {
        return nil
    }
    
    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }
    
    return longestString
}
```

func longest(strings: [String]) -> String? {
    if strings.count == 0 {
        return nil
    }
    
    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }
    
    return longestString
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    if strings.count == 0 {
        return nil
    }
    
    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }
    
    return longestString
}
```

func longest(strings: [String]) -> String? {
    guard strings.count > 0 else { return nil }
    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }
    return longestString
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard strings.count > 0 else { return nil }
    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }
    return longestString
}
```

func longest(strings: [String]) -> String? {
    if strings.count == 0 {
        return nil
    }
    
    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }
    
    return longestString
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    if strings.count == 0 {
        return nil
    }
    
    var longestString = strings[0]
    for string in strings {
        if string.count > longestString.count {
            longestString = string
        }
    }
    
    return longestString
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var x = a, y = b
    while y!= 0 {
        let tmp = y
        y = x % y
        x = tmp
    }
    return x
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var x = a, y = b
    while y!= 0 {
        let tmp = y
        y = x % y
        x = tmp
    }
    return x
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var divisor = a
    var dividend = b
    while divisor!= 0 {
        (divisor, dividend) = (dividend % divisor, divisor)
    }
    return dividend
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var divisor = a
    var dividend = b
    while divisor!= 0 {
        (divisor, dividend) = (dividend % divisor, divisor)
    }
    return dividend
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var x = a
    var y = b
    while y!= 0 {
        let t = y
        y = x % y
        x = t
    }
    return x
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var x = a
    var y = b
    while y!= 0 {
        let t = y
        y = x % y
        x = t
    }
    return x
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var x = a
    var y = b
    while y!= 0 {
        let t = y
        y = x % y
        x = t
    }
    return x
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var x = a
    var y = b
    while y!= 0 {
        let t = y
        y = x % y
        x = t
    }
    return x
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var x = a
    var y = b
    
    while y!= 0 {
        let remainder = x % y
        x = y
        y = remainder
    }
    
    return x
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var x = a
    var y = b
    
    while y!= 0 {
        let remainder = x % y
        x = y
        y = remainder
    }
    
    return x
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var x = a
    var y = b
    while y!= 0 {
        let tmp = y
        y = x % y
        x = tmp
    }
    return x
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var x = a
    var y = b
    while y!= 0 {
        let tmp = y
        y = x % y
        x = tmp
    }
    return x
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a, b = b
    while b!= 0 {
        let tmp = b
        b = a % b
        a = tmp
    }
    return a
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a, b = b
    while b!= 0 {
        let tmp = b
        b = a % b
        a = tmp
    }
    return a
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var x = a
    var y = b
    while y!= 0 {
        let tmp = y
        y = x % y
        x = tmp
    }
    return x
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var x = a
    var y = b
    while y!= 0 {
        let tmp = y
        y = x % y
        x = tmp
    }
    return x
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var x = a
    var y = b
    while y!= 0 {
        let tmp = y
        y = x % y
        x = tmp
    }
    return x
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var x = a
    var y = b
    while y!= 0 {
        let tmp = y
        y = x % y
        x = tmp
    }
    return x
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var x = a
    var y = b
    while y!= 0 {
        let t = y
        y = x % y
        x = t
    }
    return x
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var x = a
    var y = b
    while y!= 0 {
        let t = y
        y = x % y
        x = t
    }
    return x
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(string[string.index(string.startIndex, offsetBy: i)...])
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(string[string.index(string.startIndex, offsetBy: i)...])
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(string[string.index(string.startIndex, offsetBy: i)...])
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(string[string.index(string.startIndex, offsetBy: i)...])
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        let prefix = String(string.prefix(i + 1))
        prefixes.append(prefix)
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        let prefix = String(string.prefix(i + 1))
        prefixes.append(prefix)
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        let prefix = String(string.prefix(i + 1))
        prefixes.append(prefix)
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        let prefix = String(string.prefix(i + 1))
        prefixes.append(prefix)
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(string[string.index(string.startIndex, offsetBy: i)...])
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(string[string.index(string.startIndex, offsetBy: i)...])
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        let prefix = String(string[string.index(string.startIndex, offsetBy: i)...])
        prefixes.append(prefix)
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        let prefix = String(string[string.index(string.startIndex, offsetBy: i)...])
        prefixes.append(prefix)
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(string[string.index(string.startIndex, offsetBy: i)...])
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(string[string.index(string.startIndex, offsetBy: i)...])
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        let prefix = String(string.prefix(i + 1))
        prefixes.append(prefix)
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        let prefix = String(string.prefix(i + 1))
        prefixes.append(prefix)
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        let prefix = String(string.prefix(i + 1))
        prefixes.append(prefix)
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        let prefix = String(string.prefix(i + 1))
        prefixes.append(prefix)
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        let prefix = String(string[string.index(string.startIndex, offsetBy: i)])
        prefixes.append(prefix)
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        let prefix = String(string[string.index(string.startIndex, offsetBy: i)])
        prefixes.append(prefix)
    }
    return prefixes
}
```

func stringSequence(n: Int) -> String {
    var numbers = [String]()
    for i in 0...n {
        numbers.append("\(i)")
    }
    return numbers.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var numbers = [String]()
    for i in 0...n {
        numbers.append("\(i)")
    }
    return numbers.joined(separator: " ")
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespaces)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespaces)
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespaces)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespaces)
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespaces)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespaces)
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespaces)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespaces)
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespaces)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespaces)
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespaces)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespaces)
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespaces)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespaces)
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespaces)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespaces)
}
```

func stringSequence(n: Int) -> String {
    var numbers = [String]()
    for i in 0...n {
        numbers.append("\(i)")
    }
    return numbers.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var numbers = [String]()
    for i in 0...n {
        numbers.append("\(i)")
    }
    return numbers.joined(separator: " ")
}
```

func countDistinctCharacters(string: String) -> Int {
    let characters = string.lowercased().characters
    var distinctCharacters: Set<Character> = []
    for character in characters {
        distinctCharacters.insert(character)
    }
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let characters = string.lowercased().characters
    var distinctCharacters: Set<Character> = []
    for character in characters {
        distinctCharacters.insert(character)
    }
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let characters = string.lowercased().characters
    var distinctCharacters = Set<Character>()
    
    for character in characters {
        distinctCharacters.insert(character)
    }
    
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let characters = string.lowercased().characters
    var distinctCharacters = Set<Character>()
    
    for character in characters {
        distinctCharacters.insert(character)
    }
    
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let lowerCaseString = string.lowercased()
    var distinctCharacters: Set<Character> = []
    
    for character in lowerCaseString {
        distinctCharacters.insert(character)
    }
    
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let lowerCaseString = string.lowercased()
    var distinctCharacters: Set<Character> = []
    
    for character in lowerCaseString {
        distinctCharacters.insert(character)
    }
    
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let characters = string.lowercased().map { $0 }
    let unique = characters.distinct()
    return unique.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let characters = string.lowercased().map { $0 }
    let unique = characters.distinct()
    return unique.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let characters = string.lowercased().map { $0 }
    let unique = Set(characters)
    return unique.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let characters = string.lowercased().map { $0 }
    let unique = Set(characters)
    return unique.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let characters = string.lowercased().characters
    var distinctCharacters = Set<Character>()
    
    for character in characters {
        distinctCharacters.insert(character)
    }
    
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let characters = string.lowercased().characters
    var distinctCharacters = Set<Character>()
    
    for character in characters {
        distinctCharacters.insert(character)
    }
    
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let characters = string.lowercased().map { $0 }
    let unique = Set(characters)
    return unique.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let characters = string.lowercased().map { $0 }
    let unique = Set(characters)
    return unique.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let lowerCaseString = string.lowercased()
    var distinctCharacters: Set<Character> = []
    
    for character in lowerCaseString {
        distinctCharacters.insert(character)
    }
    
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let lowerCaseString = string.lowercased()
    var distinctCharacters: Set<Character> = []
    
    for character in lowerCaseString {
        distinctCharacters.insert(character)
    }
    
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let characters = string.lowercased().map { $0 }
    let unique = Set(characters)
    return unique.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let characters = string.lowercased().map { $0 }
    let unique = Set(characters)
    return unique.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let characters = string.lowercased().map { $0 }
    let unique = Set(characters)
    return unique.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let characters = string.lowercased().map { $0 }
    let unique = Set(characters)
    return unique.count
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats: [Int] = []
    var currentNoteLength = 0
    var isHalfNote = false
    
    for char in musicString {
        switch char {
        case "o":
            currentNoteLength = isHalfNote? 3 : 4
            isHalfNote = false
        case "o":
            currentNoteLength = 2
            isHalfNote = true
        case ".":
            currentNoteLength = 1
        case "|":
            beats.append(currentNoteLength)
            currentNoteLength = 0
        default:
            break
        }
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats: [Int] = []
    var currentNoteLength = 0
    var isHalfNote = false
    
    for char in musicString {
        switch char {
        case "o":
            currentNoteLength = isHalfNote? 3 : 4
            isHalfNote = false
        case "o":
            currentNoteLength = 2
            isHalfNote = true
        case ".":
            currentNoteLength = 1
        case "|":
            beats.append(currentNoteLength)
            currentNoteLength = 0
        default:
            break
        }
    }
    
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats: [Int] = []
    var currentNoteBeats: Int = 0
    
    for char in musicString {
        switch char {
        case "o":
            currentNoteBeats = 4
        case "o|":
            currentNoteBeats = 2
        case ".|":
            currentNoteBeats = 1
        default:
            break
        }
        
        beats.append(currentNoteBeats)
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats: [Int] = []
    var currentNoteBeats: Int = 0
    
    for char in musicString {
        switch char {
        case "o":
            currentNoteBeats = 4
        case "o|":
            currentNoteBeats = 2
        case ".|":
            currentNoteBeats = 1
        default:
            break
        }
        
        beats.append(currentNoteBeats)
    }
    
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats: [Int] = []
    var currentNoteBeats: Int = 0
    
    for char in musicString {
        switch char {
        case "o":
            currentNoteBeats = 4
        case "o|":
            currentNoteBeats = 2
        case ".|":
            currentNoteBeats = 1
        default:
            break
        }
        beats.append(currentNoteBeats)
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats: [Int] = []
    var currentNoteBeats: Int = 0
    
    for char in musicString {
        switch char {
        case "o":
            currentNoteBeats = 4
        case "o|":
            currentNoteBeats = 2
        case ".|":
            currentNoteBeats = 1
        default:
            break
        }
        beats.append(currentNoteBeats)
    }
    
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats: [Int] = []
    var currentNoteLength = 0
    
    for char in musicString {
        switch char {
        case "o":
            currentNoteLength = 4
        case "o|":
            currentNoteLength = 2
        case ".|":
            currentNoteLength = 1
        default:
            break
        }
        beats.append(currentNoteLength)
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats: [Int] = []
    var currentNoteLength = 0
    
    for char in musicString {
        switch char {
        case "o":
            currentNoteLength = 4
        case "o|":
            currentNoteLength = 2
        case ".|":
            currentNoteLength = 1
        default:
            break
        }
        beats.append(currentNoteLength)
    }
    
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats: [Int] = []
    var currentNoteLength: Int = 0
    
    for character in musicString {
        switch character {
        case "o":
            currentNoteLength = 4
        case "o|":
            currentNoteLength = 2
        case ".|":
            currentNoteLength = 1
        default:
            break
        }
        
        if currentNoteLength > 0 {
            beats.append(currentNoteLength)
            currentNoteLength = 0
        }
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats: [Int] = []
    var currentNoteLength: Int = 0
    
    for character in musicString {
        switch character {
        case "o":
            currentNoteLength = 4
        case "o|":
            currentNoteLength = 2
        case ".|":
            currentNoteLength = 1
        default:
            break
        }
        
        if currentNoteLength > 0 {
            beats.append(currentNoteLength)
            currentNoteLength = 0
        }
    }
    
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats: [Int] = []
    var currentNoteLength: Int = 0
    
    for char in musicString {
        switch char {
        case "o":
            currentNoteLength = 4
        case "o|":
            currentNoteLength = 2
        case ".|":
            currentNoteLength = 1
        default:
            break
        }
        
        if currentNoteLength > 0 {
            beats.append(currentNoteLength)
            currentNoteLength = 0
        }
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats: [Int] = []
    var currentNoteLength: Int = 0
    
    for char in musicString {
        switch char {
        case "o":
            currentNoteLength = 4
        case "o|":
            currentNoteLength = 2
        case ".|":
            currentNoteLength = 1
        default:
            break
        }
        
        if currentNoteLength > 0 {
            beats.append(currentNoteLength)
            currentNoteLength = 0
        }
    }
    
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats: [Int] = []
    var currentNoteLength = 0
    
    for char in musicString {
        switch char {
        case "o":
            currentNoteLength = 4
        case "o|":
            currentNoteLength = 2
        case ".|":
            currentNoteLength = 1
        default:
            break
        }
        
        if currentNoteLength > 0 {
            beats.append(currentNoteLength)
            currentNoteLength = 0
        }
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats: [Int] = []
    var currentNoteLength = 0
    
    for char in musicString {
        switch char {
        case "o":
            currentNoteLength = 4
        case "o|":
            currentNoteLength = 2
        case ".|":
            currentNoteLength = 1
        default:
            break
        }
        
        if currentNoteLength > 0 {
            beats.append(currentNoteLength)
            currentNoteLength = 0
        }
    }
    
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats: [Int] = []
    var currentNoteLength = 0
    
    for char in musicString {
        switch char {
        case "o":
            currentNoteLength = 4
        case "o|":
            currentNoteLength = 2
        case ".|":
            currentNoteLength = 1
        default:
            break
        }
        
        if currentNoteLength > 0 {
            beats.append(currentNoteLength)
            currentNoteLength = 0
        }
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats: [Int] = []
    var currentNoteLength = 0
    
    for char in musicString {
        switch char {
        case "o":
            currentNoteLength = 4
        case "o|":
            currentNoteLength = 2
        case ".|":
            currentNoteLength = 1
        default:
            break
        }
        
        if currentNoteLength > 0 {
            beats.append(currentNoteLength)
            currentNoteLength = 0
        }
    }
    
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats: [Int] = []
    var currentNoteLength: Int = 0
    
    for char in musicString {
        switch char {
        case "o":
            currentNoteLength = 4
        case "o|":
            currentNoteLength = 2
        case ".|":
            currentNoteLength = 1
        default:
            break
        }
        
        if currentNoteLength > 0 {
            beats.append(currentNoteLength)
            currentNoteLength = 0
        }
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats: [Int] = []
    var currentNoteLength: Int = 0
    
    for char in musicString {
        switch char {
        case "o":
            currentNoteLength = 4
        case "o|":
            currentNoteLength = 2
        case ".|":
            currentNoteLength = 1
        default:
            break
        }
        
        if currentNoteLength > 0 {
            beats.append(currentNoteLength)
            currentNoteLength = 0
        }
    }
    
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.components(separatedBy: " ")
    var beats: [Int] = []
    
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.components(separatedBy: " ")
    var beats: [Int] = []
    
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    
    return beats
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.caseInsensitive, range: index..<string.endIndex) {
        count += 1
        index = range.upperBound
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.caseInsensitive, range: index..<string.endIndex) {
        count += 1
        index = range.upperBound
    }
    
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.index(string.startIndex, offsetBy: 0)
    
    while let range = string.range(of: substring, options:.caseInsensitive, range: index..<string.endIndex) {
        count += 1
        index = string.index(after: range.upperBound)
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.index(string.startIndex, offsetBy: 0)
    
    while let range = string.range(of: substring, options:.caseInsensitive, range: index..<string.endIndex) {
        count += 1
        index = string.index(after: range.upperBound)
    }
    
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.caseInsensitive, range: index..<string.endIndex) {
        count += 1
        index = range.upperBound
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.caseInsensitive, range: index..<string.endIndex) {
        count += 1
        index = range.upperBound
    }
    
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.index(string.startIndex, offsetBy: 0)
    while let range = string.range(of: substring, options:.caseInsensitive, range: index..<string.endIndex) {
        count += 1
        index = string.index(after: range.upperBound)
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.index(string.startIndex, offsetBy: 0)
    while let range = string.range(of: substring, options:.caseInsensitive, range: index..<string.endIndex) {
        count += 1
        index = string.index(after: range.upperBound)
    }
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.index(string.startIndex, offsetBy: 0)
    
    while let range = string.range(of: substring, options:.caseInsensitive, range: index..<string.endIndex) {
        count += 1
        index = string.index(after: range.upperBound)
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.index(string.startIndex, offsetBy: 0)
    
    while let range = string.range(of: substring, options:.caseInsensitive, range: index..<string.endIndex) {
        count += 1
        index = string.index(after: range.upperBound)
    }
    
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.index(string.startIndex, offsetBy: 0)
    
    while let range = string.range(of: substring, options:.caseInsensitive, range: index..<string.endIndex) {
        count += 1
        index = string.index(after: range.upperBound)
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.index(string.startIndex, offsetBy: 0)
    
    while let range = string.range(of: substring, options:.caseInsensitive, range: index..<string.endIndex) {
        count += 1
        index = string.index(after: range.upperBound)
    }
    
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.index(string.startIndex, offsetBy: 0)
    while let range = string.range(of: substring, options:.caseInsensitive, range: index..<string.endIndex) {
        count += 1
        index = string.index(after: range.upperBound)
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.index(string.startIndex, offsetBy: 0)
    while let range = string.range(of: substring, options:.caseInsensitive, range: index..<string.endIndex) {
        count += 1
        index = string.index(after: range.upperBound)
    }
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.index(string.startIndex, offsetBy: 0)
    
    while let range = string.range(of: substring, options:.caseInsensitive, range: index..<string.endIndex) {
        count += 1
        index = string.index(after: range.upperBound)
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.index(string.startIndex, offsetBy: 0)
    
    while let range = string.range(of: substring, options:.caseInsensitive, range: index..<string.endIndex) {
        count += 1
        index = string.index(after: range.upperBound)
    }
    
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.caseInsensitive, range: index..<string.endIndex) {
        count += 1
        index = range.upperBound
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.caseInsensitive, range: index..<string.endIndex) {
        count += 1
        index = range.upperBound
    }
    
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.caseInsensitive, range: index..<string.endIndex) {
        count += 1
        index = range.upperBound
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.caseInsensitive, range: index..<string.endIndex) {
        count += 1
        index = range.upperBound
    }
    
    return count
}
```

func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let sortedNumberals = numberals.sorted { numberal1, numberal2 in
        let value1 = Int(numberal1.rawValue)?? 0
        let value2 = Int(numberal2.rawValue)?? 0
        return value1 < value2
    }
    return sortedNumberals.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let sortedNumberals = numberals.sorted { numberal1, numberal2 in
        let value1 = Int(numberal1.rawValue)?? 0
        let value2 = Int(numberal2.rawValue)?? 0
        return value1 < value2
    }
    return sortedNumberals.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let sortedNumberals = numberals.sorted { numberal1, numberal2 in
        let order1 = order(for: numberal1)
        let order2 = order(for: numberal2)
        return order1 < order2
    }
    return sortedNumberals.joined(separator: " ")
}

func order(for numberal: String) -> Int {
    switch numberal {
    case "zero":
        return 0
    case "one":
        return 1
    case "two":
        return 2
    case "three":
        return 3
    case "four":
        return 4
    case "five":
        return 5
    case "six":
        return 6
    case "seven":
        return 7
    case "eight":
        return 8
    case "nine":
        return 9
    default:
        fatalError("Invalid numberal: \(numberal)")
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let sortedNumberals = numberals.sorted { numberal1, numberal2 in
        let order1 = order(for: numberal1)
        let order2 = order(for: numberal2)
        return order1 < order2
    }
    return sortedNumberals.joined(separator: " ")
}

func order(for numberal: String) -> Int {
    switch numberal {
    case "zero":
        return 0
    case "one":
        return 1
    case "two":
        return 2
    case "three":
        return 3
    case "four":
        return 4
    case "five":
        return 5
    case "six":
        return 6
    case "seven":
        return 7
    case "eight":
        return 8
    case "nine":
        return 9
    default:
        fatalError("Invalid numberal: \(numberal)")
    }
}
```

func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let sortedNumberals = numberals.sorted()
    return sortedNumberals.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let sortedNumberals = numberals.sorted()
    return sortedNumberals.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let sortedNumberals = numberals.sorted { numberal1, numberal2 in
        let order1 = order(for: numberal1)
        let order2 = order(for: numberal2)
        return order1 < order2
    }
    return sortedNumberals.joined(separator: " ")
}

func order(for numberal: String) -> Int {
    switch numberal {
    case "zero":
        return 0
    case "one":
        return 1
    case "two":
        return 2
    case "three":
        return 3
    case "four":
        return 4
    case "five":
        return 5
    case "six":
        return 6
    case "seven":
        return 7
    case "eight":
        return 8
    case "nine":
        return 9
    default:
        fatalError("Invalid numberal: \(numberal)")
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let sortedNumberals = numberals.sorted { numberal1, numberal2 in
        let order1 = order(for: numberal1)
        let order2 = order(for: numberal2)
        return order1 < order2
    }
    return sortedNumberals.joined(separator: " ")
}

func order(for numberal: String) -> Int {
    switch numberal {
    case "zero":
        return 0
    case "one":
        return 1
    case "two":
        return 2
    case "three":
        return 3
    case "four":
        return 4
    case "five":
        return 5
    case "six":
        return 6
    case "seven":
        return 7
    case "eight":
        return 8
    case "nine":
        return 9
    default:
        fatalError("Invalid numberal: \(numberal)")
    }
}
```

func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let sortedNumberals = numberals.sorted { numberal1, numberal2 in
        let order1 = order(for: numberal1)
        let order2 = order(for: numberal2)
        return order1 < order2
    }
    return sortedNumberals.joined(separator: " ")
}

func order(for numberal: String) -> Int {
    switch numberal {
    case "zero":
        return 0
    case "one":
        return 1
    case "two":
        return 2
    case "three":
        return 3
    case "four":
        return 4
    case "five":
        return 5
    case "six":
        return 6
    case "seven":
        return 7
    case "eight":
        return 8
    case "nine":
        return 9
    default:
        fatalError("Invalid numberal: \(numberal)")
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let sortedNumberals = numberals.sorted { numberal1, numberal2 in
        let order1 = order(for: numberal1)
        let order2 = order(for: numberal2)
        return order1 < order2
    }
    return sortedNumberals.joined(separator: " ")
}

func order(for numberal: String) -> Int {
    switch numberal {
    case "zero":
        return 0
    case "one":
        return 1
    case "two":
        return 2
    case "three":
        return 3
    case "four":
        return 4
    case "five":
        return 5
    case "six":
        return 6
    case "seven":
        return 7
    case "eight":
        return 8
    case "nine":
        return 9
    default:
        fatalError("Invalid numberal: \(numberal)")
    }
}
```

func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let sortedNumberals = numberals.sorted()
    let sortedNumbers = sortedNumberals.joined(separator: " ")
    return sortedNumbers
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let sortedNumberals = numberals.sorted()
    let sortedNumbers = sortedNumberals.joined(separator: " ")
    return sortedNumbers
}
```

func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let sortedNumberals = numberals.sorted { numberal1, numberal2 in
        let order1 = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"].firstIndex(of: numberal1)!
        let order2 = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"].firstIndex(of: numberal2)!
        return order1 < order2
    }
    return sortedNumberals.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let sortedNumberals = numberals.sorted { numberal1, numberal2 in
        let order1 = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"].firstIndex(of: numberal1)!
        let order2 = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"].firstIndex(of: numberal2)!
        return order1 < order2
    }
    return sortedNumberals.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let sortedNumberals = numberals.sorted { numberal1, numberal2 in
        let order1 = order(for: numberal1)
        let order2 = order(for: numberal2)
        return order1 < order2
    }
    return sortedNumberals.joined(separator: " ")
}

func order(for numberal: String) -> Int {
    switch numberal {
    case "zero":
        return 0
    case "one":
        return 1
    case "two":
        return 2
    case "three":
        return 3
    case "four":
        return 4
    case "five":
        return 5
    case "six":
        return 6
    case "seven":
        return 7
    case "eight":
        return 8
    case "nine":
        return 9
    default:
        fatalError("Invalid numberal: \(numberal)")
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let sortedNumberals = numberals.sorted { numberal1, numberal2 in
        let order1 = order(for: numberal1)
        let order2 = order(for: numberal2)
        return order1 < order2
    }
    return sortedNumberals.joined(separator: " ")
}

func order(for numberal: String) -> Int {
    switch numberal {
    case "zero":
        return 0
    case "one":
        return 1
    case "two":
        return 2
    case "three":
        return 3
    case "four":
        return 4
    case "five":
        return 5
    case "six":
        return 6
    case "seven":
        return 7
    case "eight":
        return 8
    case "nine":
        return 9
    default:
        fatalError("Invalid numberal: \(numberal)")
    }
}
```

func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let sortedNumberals = numberals.sorted { numberal1, numberal2 in
        let order1 = order(for: numberal1)
        let order2 = order(for: numberal2)
        return order1 < order2
    }
    return sortedNumberals.joined(separator: " ")
}

func order(for numberal: String) -> Int {
    switch numberal {
    case "zero":
        return 0
    case "one":
        return 1
    case "two":
        return 2
    case "three":
        return 3
    case "four":
        return 4
    case "five":
        return 5
    case "six":
        return 6
    case "seven":
        return 7
    case "eight":
        return 8
    case "nine":
        return 9
    default:
        return 0
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let sortedNumberals = numberals.sorted { numberal1, numberal2 in
        let order1 = order(for: numberal1)
        let order2 = order(for: numberal2)
        return order1 < order2
    }
    return sortedNumberals.joined(separator: " ")
}

func order(for numberal: String) -> Int {
    switch numberal {
    case "zero":
        return 0
    case "one":
        return 1
    case "two":
        return 2
    case "three":
        return 3
    case "four":
        return 4
    case "five":
        return 5
    case "six":
        return 6
    case "seven":
        return 7
    case "eight":
        return 8
    case "nine":
        return 9
    default:
        return 0
    }
}
```

func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let numberalsArray = numberals.map { numberal -> Int in
        switch numberal {
        case "zero":
            return 0
        case "one":
            return 1
        case "two":
            return 2
        case "three":
            return 3
        case "four":
            return 4
        case "five":
            return 5
        case "six":
            return 6
        case "seven":
            return 7
        case "eight":
            return 8
        case "nine":
            return 9
        default:
            return 0
        }
    }
    let sortedNumberals = numberalsArray.sorted()
    let sortedNumberalsString = sortedNumberals.map { numberal -> String in
        switch numberal {
        case 0:
            return "zero"
        case 1:
            return "one"
        case 2:
            return "two"
        case 3:
            return "three"
        case 4:
            return "four"
        case 5:
            return "five"
        case 6:
            return "six"
        case 7:
            return "seven"
        case 8:
            return "eight"
        case 9:
            return "nine"
        default:
            return ""
        }
    }
    return sortedNumberalsString.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let numberalsArray = numberals.map { numberal -> Int in
        switch numberal {
        case "zero":
            return 0
        case "one":
            return 1
        case "two":
            return 2
        case "three":
            return 3
        case "four":
            return 4
        case "five":
            return 5
        case "six":
            return 6
        case "seven":
            return 7
        case "eight":
            return 8
        case "nine":
            return 9
        default:
            return 0
        }
    }
    let sortedNumberals = numberalsArray.sorted()
    let sortedNumberalsString = sortedNumberals.map { numberal -> String in
        switch numberal {
        case 0:
            return "zero"
        case 1:
            return "one"
        case 2:
            return "two"
        case 3:
            return "three"
        case 4:
            return "four"
        case 5:
            return "five"
        case 6:
            return "six"
        case 7:
            return "seven"
        case 8:
            return "eight"
        case 9:
            return "nine"
        default:
            return ""
        }
    }
    return sortedNumberalsString.joined(separator: " ")
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDiff = Double.max
    var closestElements: (Double, Double)?
    
    for i in 0..<numbers.count-1 {
        let diff = numbers[i+1] - numbers[i]
        if diff < minDiff {
            minDiff = diff
            closestElements = (numbers[i], numbers[i+1])
        }
    }
    
    return closestElements!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDiff = Double.max
    var closestElements: (Double, Double)?
    
    for i in 0..<numbers.count-1 {
        let diff = numbers[i+1] - numbers[i]
        if diff < minDiff {
            minDiff = diff
            closestElements = (numbers[i], numbers[i+1])
        }
    }
    
    return closestElements!
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = Double.max
    var closestElements: (Double, Double)?
    
    for i in 0..<numbers.count {
        for j in (i+1)..<numbers.count {
            let difference = abs(numbers[i] - numbers[j])
            if difference < minDifference {
                minDifference = difference
                closestElements = (numbers[i], numbers[j])
            }
        }
    }
    
    return closestElements!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = Double.max
    var closestElements: (Double, Double)?
    
    for i in 0..<numbers.count {
        for j in (i+1)..<numbers.count {
            let difference = abs(numbers[i] - numbers[j])
            if difference < minDifference {
                minDifference = difference
                closestElements = (numbers[i], numbers[j])
            }
        }
    }
    
    return closestElements!
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = Double.max
    var closestElements: (Double, Double)?
    
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            let difference = abs(numbers[i] - numbers[j])
            if difference < minDifference {
                minDifference = difference
                closestElements = (numbers[i], numbers[j])
            }
        }
    }
    
    return closestElements!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = Double.max
    var closestElements: (Double, Double)?
    
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            let difference = abs(numbers[i] - numbers[j])
            if difference < minDifference {
                minDifference = difference
                closestElements = (numbers[i], numbers[j])
            }
        }
    }
    
    return closestElements!
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    let sortedNumbers = numbers.sorted()
    let firstIndex = sortedNumbers.firstIndex(of: sortedNumbers[1])!
    let secondIndex = sortedNumbers.firstIndex(of: sortedNumbers[0])!
    let firstElement = sortedNumbers[firstIndex]
    let secondElement = sortedNumbers[secondIndex]
    return firstElement < secondElement? (firstElement, secondElement) : (secondElement, firstElement)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    let sortedNumbers = numbers.sorted()
    let firstIndex = sortedNumbers.firstIndex(of: sortedNumbers[1])!
    let secondIndex = sortedNumbers.firstIndex(of: sortedNumbers[0])!
    let firstElement = sortedNumbers[firstIndex]
    let secondElement = sortedNumbers[secondIndex]
    return firstElement < secondElement? (firstElement, secondElement) : (secondElement, firstElement)
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = Double.max
    var closestElements: (Double, Double)?
    
    for i in 0..<numbers.count - 1 {
        let difference = numbers[i+1] - numbers[i]
        if difference < minDifference {
            minDifference = difference
            closestElements = (numbers[i], numbers[i+1])
        }
    }
    
    return closestElements!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = Double.max
    var closestElements: (Double, Double)?
    
    for i in 0..<numbers.count - 1 {
        let difference = numbers[i+1] - numbers[i]
        if difference < minDifference {
            minDifference = difference
            closestElements = (numbers[i], numbers[i+1])
        }
    }
    
    return closestElements!
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = Double.greatestFiniteMagnitude
    var closestElements: (Double, Double)?
    
    for i in 0..<numbers.count {
        for j in (i+1)..<numbers.count {
            let difference = abs(numbers[i] - numbers[j])
            if difference < minDifference {
                minDifference = difference
                closestElements = (numbers[i], numbers[j])
            }
        }
    }
    
    return closestElements!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = Double.greatestFiniteMagnitude
    var closestElements: (Double, Double)?
    
    for i in 0..<numbers.count {
        for j in (i+1)..<numbers.count {
            let difference = abs(numbers[i] - numbers[j])
            if difference < minDifference {
                minDifference = difference
                closestElements = (numbers[i], numbers[j])
            }
        }
    }
    
    return closestElements!
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = Double.max
    var closestElements: (Double, Double)?
    
    for i in 0..<numbers.count - 1 {
        let difference = numbers[i+1] - numbers[i]
        if difference < minDifference {
            minDifference = difference
            closestElements = (numbers[i], numbers[i+1])
        }
    }
    
    return closestElements!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = Double.max
    var closestElements: (Double, Double)?
    
    for i in 0..<numbers.count - 1 {
        let difference = numbers[i+1] - numbers[i]
        if difference < minDifference {
            minDifference = difference
            closestElements = (numbers[i], numbers[i+1])
        }
    }
    
    return closestElements!
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDiff = Double.max
    var closestElements: (Double, Double)?
    
    for i in 0..<numbers.count {
        for j in (i+1)..<numbers.count {
            let diff = abs(numbers[i] - numbers[j])
            if diff < minDiff {
                minDiff = diff
                closestElements = (numbers[i], numbers[j])
            }
        }
    }
    
    return closestElements!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDiff = Double.max
    var closestElements: (Double, Double)?
    
    for i in 0..<numbers.count {
        for j in (i+1)..<numbers.count {
            let diff = abs(numbers[i] - numbers[j])
            if diff < minDiff {
                minDiff = diff
                closestElements = (numbers[i], numbers[j])
            }
        }
    }
    
    return closestElements!
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = Double.greatestFiniteMagnitude
    var closestElements: (Double, Double)?
    
    for i in 0..<numbers.count - 1 {
        let difference = numbers[i+1] - numbers[i]
        if difference < minDifference {
            minDifference = difference
            closestElements = (numbers[i], numbers[i+1])
        }
    }
    
    return closestElements!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = Double.greatestFiniteMagnitude
    var closestElements: (Double, Double)?
    
    for i in 0..<numbers.count - 1 {
        let difference = numbers[i+1] - numbers[i]
        if difference < minDifference {
            minDifference = difference
            closestElements = (numbers[i], numbers[i+1])
        }
    }
    
    return closestElements!
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = Double.greatestFiniteMagnitude
    var closestElements: (Double, Double)?
    
    for i in 0..<numbers.count-1 {
        let difference = numbers[i+1] - numbers[i]
        if difference < minDifference {
            minDifference = difference
            closestElements = (numbers[i], numbers[i+1])
        }
    }
    
    return closestElements!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = Double.greatestFiniteMagnitude
    var closestElements: (Double, Double)?
    
    for i in 0..<numbers.count-1 {
        let difference = numbers[i+1] - numbers[i]
        if difference < minDifference {
            minDifference = difference
            closestElements = (numbers[i], numbers[i+1])
        }
    }
    
    return closestElements!
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int } as [Int]
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int } as [Int]
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int } as [Int]
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int } as [Int]
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int } as [Int]
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int } as [Int]
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    var filtered = [Int]()
    for value in values {
        if let intValue = value as? Int {
            filtered.append(intValue)
        }
    }
    return filtered
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    var filtered = [Int]()
    for value in values {
        if let intValue = value as? Int {
            filtered.append(intValue)
        }
    }
    return filtered
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int } as [Int]
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int } as [Int]
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    var filtered = [Int]()
    for value in values {
        if let intValue = value as? Int {
            filtered.append(intValue)
        }
    }
    return filtered
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    var filtered = [Int]()
    for value in values {
        if let intValue = value as? Int {
            filtered.append(intValue)
        }
    }
    return filtered
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int } as [Int]
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int } as [Int]
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    var filtered = [Int]()
    for value in values {
        if let intValue = value as? Int {
            filtered.append(intValue)
        }
    }
    return filtered
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    var filtered = [Int]()
    for value in values {
        if let intValue = value as? Int {
            filtered.append(intValue)
        }
    }
    return filtered
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int } as [Int]
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int } as [Int]
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int } as [Int]
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.filter { $0 is Int } as [Int]
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func largestDivisor(n: Int) -> Int {
    for i in stride(from: n, to: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    for i in stride(from: n, to: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    for i in stride(from: n, to: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    for i in stride(from: n, to: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    for i in stride(from: n, to: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    for i in stride(from: n, to: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    for i in stride(from: n, to: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    for i in stride(from: n, to: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    for i in stride(from: n, to: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    for i in stride(from: n, to: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    for i in stride(from: n, to: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    for i in stride(from: n, to: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    for i in stride(from: n, to: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    for i in stride(from: n, to: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    for i in stride(from: n, to: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    for i in stride(from: n, to: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    for i in stride(from: n, to: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    for i in stride(from: n, to: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    for i in stride(from: n, to: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    for i in stride(from: n, to: 1, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return 1
}
```

func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var divisor = 2
    while divisor <= n {
        var count = 0
        while n % divisor == 0 {
            n /= divisor
            count += 1
        }
        if count > 0 {
            factors.append(divisor)
            factors.append(count)
        }
        divisor += 1
    }
    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var divisor = 2
    while divisor <= n {
        var count = 0
        while n % divisor == 0 {
            n /= divisor
            count += 1
        }
        if count > 0 {
            factors.append(divisor)
            factors.append(count)
        }
        divisor += 1
    }
    return factors
}
```

func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var divisor = 2
    while divisor <= n {
        if n % divisor == 0 {
            factors.append(divisor)
            n /= divisor
        } else {
            divisor += 1
        }
    }
    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var divisor = 2
    while divisor <= n {
        if n % divisor == 0 {
            factors.append(divisor)
            n /= divisor
        } else {
            divisor += 1
        }
    }
    return factors
}
```

func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var divisor = 2
    while divisor <= n {
        if n % divisor == 0 {
            factors.append(divisor)
            n /= divisor
        } else {
            divisor += 1
        }
    }
    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var divisor = 2
    while divisor <= n {
        if n % divisor == 0 {
            factors.append(divisor)
            n /= divisor
        } else {
            divisor += 1
        }
    }
    return factors
}
```

func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var divisor = 2

    while divisor <= n {
        var count = 0

        while n % divisor == 0 {
            n /= divisor
            count += 1
        }

        if count > 0 {
            factors.append(divisor)
            factors.append(count)
        }

        divisor += 1
    }

    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var divisor = 2

    while divisor <= n {
        var count = 0

        while n % divisor == 0 {
            n /= divisor
            count += 1
        }

        if count > 0 {
            factors.append(divisor)
            factors.append(count)
        }

        divisor += 1
    }

    return factors
}
```

func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var divisor = 2
    while divisor <= n {
        if n % divisor == 0 {
            factors.append(divisor)
            n /= divisor
        } else {
            divisor += 1
        }
    }
    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var divisor = 2
    while divisor <= n {
        if n % divisor == 0 {
            factors.append(divisor)
            n /= divisor
        } else {
            divisor += 1
        }
    }
    return factors
}
```

func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var divisor = 2
    while divisor <= n {
        if n % divisor == 0 {
            factors.append(divisor)
            n /= divisor
        } else {
            divisor += 1
        }
    }
    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var divisor = 2
    while divisor <= n {
        if n % divisor == 0 {
            factors.append(divisor)
            n /= divisor
        } else {
            divisor += 1
        }
    }
    return factors
}
```

func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var divisor = 2
    while divisor <= n {
        var count = 0
        while n % divisor == 0 {
            n /= divisor
            count += 1
        }
        if count > 0 {
            factors.append(divisor)
            factors.append(count)
        }
        divisor += 1
    }
    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var divisor = 2
    while divisor <= n {
        var count = 0
        while n % divisor == 0 {
            n /= divisor
            count += 1
        }
        if count > 0 {
            factors.append(divisor)
            factors.append(count)
        }
        divisor += 1
    }
    return factors
}
```

func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var divisor = 2

    while divisor <= n {
        var count = 0

        while n % divisor == 0 {
            n /= divisor
            count += 1
        }

        if count > 0 {
            factors.append(divisor)
            factors.append(count)
        }

        divisor += 1
    }

    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var divisor = 2

    while divisor <= n {
        var count = 0

        while n % divisor == 0 {
            n /= divisor
            count += 1
        }

        if count > 0 {
            factors.append(divisor)
            factors.append(count)
        }

        divisor += 1
    }

    return factors
}
```

func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var divisor = 2
    while divisor <= n {
        var count = 0
        while n % divisor == 0 {
            n /= divisor
            count += 1
        }
        if count > 0 {
            factors.append(divisor)
            factors.append(count)
        }
        divisor += 1
    }
    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var divisor = 2
    while divisor <= n {
        var count = 0
        while n % divisor == 0 {
            n /= divisor
            count += 1
        }
        if count > 0 {
            factors.append(divisor)
            factors.append(count)
        }
        divisor += 1
    }
    return factors
}
```

func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var divisor = 2
    while divisor <= n {
        var count = 0
        while n % divisor == 0 {
            n /= divisor
            count += 1
        }
        if count > 0 {
            factors.append(divisor)
            factors.append(count)
        }
        divisor += 1
    }
    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var divisor = 2
    while divisor <= n {
        var count = 0
        while n % divisor == 0 {
            n /= divisor
            count += 1
        }
        if count > 0 {
            factors.append(divisor)
            factors.append(count)
        }
        divisor += 1
    }
    return factors
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var seen = Set<Int>()
    var result = [Int]()
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var seen = Set<Int>()
    var result = [Int]()
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var seen = Set<Int>()
    var result = [Int]()
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var seen = Set<Int>()
    var result = [Int]()
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var seen = Set<Int>()
    var result = [Int]()
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var seen = Set<Int>()
    var result = [Int]()
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var seen = Set<Int>()
    var result = [Int]()
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var seen = Set<Int>()
    var result = [Int]()
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var seen = Set<Int>()
    var result = [Int]()
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var seen = Set<Int>()
    var result = [Int]()
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var seen = Set<Int>()
    var result = [Int]()
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var seen = Set<Int>()
    var result = [Int]()
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var seen = Set<Int>()
    var result = [Int]()
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var seen = Set<Int>()
    var result = [Int]()
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var seen = Set<Int>()
    var result = [Int]()
    
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var seen = Set<Int>()
    var result = [Int]()
    
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var seen = Set<Int>()
    var result = [Int]()
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var seen = Set<Int>()
    var result = [Int]()
    for number in numbers {
        if!seen.contains(number) {
            seen.insert(number)
            result.append(number)
        }
    }
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var seen = Set<Int>()
    var result = [Int]()
    for num in numbers {
        if!seen.contains(num) {
            seen.insert(num)
            result.append(num)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var seen = Set<Int>()
    var result = [Int]()
    for num in numbers {
        if!seen.contains(num) {
            seen.insert(num)
            result.append(num)
        }
    }
    return result
}
```

func flipCase(string: String) -> String {
    return string.map { $0.toggleCase() }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    return string.map { $0.toggleCase() }
}
```

func flipCase(string: String) -> String {
    return string.map { $0.toggleCase() }
}

extension Character {
    func toggleCase() -> Character {
        return self.isLowercase? self.uppercased() : self.lowercased()
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    return string.map { $0.toggleCase() }
}

extension Character {
    func toggleCase() -> Character {
        return self.isLowercase? self.uppercased() : self.lowercased()
    }
}
```

func flipCase(string: String) -> String {
    var flippedString = ""
    
    for character in string {
        if character.isLowercase {
            flippedString.append(character.uppercased())
        } else {
            flippedString.append(character.lowercased())
        }
    }
    
    return flippedString
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    var flippedString = ""
    
    for character in string {
        if character.isLowercase {
            flippedString.append(character.uppercased())
        } else {
            flippedString.append(character.lowercased())
        }
    }
    
    return flippedString
}
```

func flipCase(string: String) -> String {
    var flippedString = ""
    for character in string {
        if character.isLowercase {
            flippedString.append(character.uppercased())
        } else {
            flippedString.append(character.lowercased())
        }
    }
    return flippedString
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    var flippedString = ""
    for character in string {
        if character.isLowercase {
            flippedString.append(character.uppercased())
        } else {
            flippedString.append(character.lowercased())
        }
    }
    return flippedString
}
```

func flipCase(string: String) -> String {
    return string.map { $0.toggleCase() }
}

extension Character {
    func toggleCase() -> Character {
        return self.isLowercase? self.uppercased() : self.lowercased()
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    return string.map { $0.toggleCase() }
}

extension Character {
    func toggleCase() -> Character {
        return self.isLowercase? self.uppercased() : self.lowercased()
    }
}
```

func flipCase(string: String) -> String {
    var flippedString = ""
    for character in string {
        if character.isLowercase {
            flippedString.append(character.uppercased())
        } else {
            flippedString.append(character.lowercased())
        }
    }
    return flippedString
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    var flippedString = ""
    for character in string {
        if character.isLowercase {
            flippedString.append(character.uppercased())
        } else {
            flippedString.append(character.lowercased())
        }
    }
    return flippedString
}
```

func flipCase(string: String) -> String {
    var flippedString = ""
    for character in string {
        if character.isLowercase {
            flippedString.append(character.uppercased())
        } else {
            flippedString.append(character.lowercased())
        }
    }
    return flippedString
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    var flippedString = ""
    for character in string {
        if character.isLowercase {
            flippedString.append(character.uppercased())
        } else {
            flippedString.append(character.lowercased())
        }
    }
    return flippedString
}
```

func flipCase(string: String) -> String {
    var flippedString = ""
    for character in string {
        if character.isLowercase {
            flippedString.append(character.uppercased())
        } else {
            flippedString.append(character.lowercased())
        }
    }
    return flippedString
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    var flippedString = ""
    for character in string {
        if character.isLowercase {
            flippedString.append(character.uppercased())
        } else {
            flippedString.append(character.lowercased())
        }
    }
    return flippedString
}
```

func flipCase(string: String) -> String {
    var flippedString = ""
    for character in string {
        if character.isLowercase {
            flippedString.append(character.uppercased())
        } else {
            flippedString.append(character.lowercased())
        }
    }
    return flippedString
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    var flippedString = ""
    for character in string {
        if character.isLowercase {
            flippedString.append(character.uppercased())
        } else {
            flippedString.append(character.lowercased())
        }
    }
    return flippedString
}
```

func flipCase(string: String) -> String {
    var flippedString = ""
    for character in string {
        if character.isLowercase {
            flippedString.append(character.uppercased())
        } else {
            flippedString.append(character.lowercased())
        }
    }
    return flippedString
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    var flippedString = ""
    for character in string {
        if character.isLowercase {
            flippedString.append(character.uppercased())
        } else {
            flippedString.append(character.lowercased())
        }
    }
    return flippedString
}
```

func concatenate(strings: [String]) -> String {
    var result = ""
    for string in strings {
        result += string
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    var result = ""
    for string in strings {
        result += string
    }
    return result
}
```

func concatenate(strings: [String]) -> String {
    var result = ""
    for string in strings {
        result += string
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    var result = ""
    for string in strings {
        result += string
    }
    return result
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
```

func concatenate(strings: [String]) -> String {
    var result = ""
    for string in strings {
        result += string
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    var result = ""
    for string in strings {
        result += string
    }
    return result
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
```

func concatenate(strings: [String]) -> String {
    var result = ""
    for string in strings {
        result += string
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    var result = ""
    for string in strings {
        result += string
    }
    return result
}
```

func concatenate(strings: [String]) -> String {
    var result = ""
    for string in strings {
        result += string
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    var result = ""
    for string in strings {
        result += string
    }
    return result
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
```

func concatenate(strings: [String]) -> String {
    var result = ""
    for string in strings {
        result += string
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    var result = ""
    for string in strings {
        result += string
    }
    return result
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { string in string.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { string in string.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    var result: [String] = []
    for string in strings {
        if string.hasPrefix(prefix) {
            result.append(string)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    var result: [String] = []
    for string in strings {
        if string.hasPrefix(prefix) {
            result.append(string)
        }
    }
    return result
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { string in string.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { string in string.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { string in string.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { string in string.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { string in string.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { string in string.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { string in string.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { string in string.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    var result: [String] = []
    for string in strings {
        if string.hasPrefix(prefix) {
            result.append(string)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    var result: [String] = []
    for string in strings {
        if string.hasPrefix(prefix) {
            result.append(string)
        }
    }
    return result
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { string in string.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { string in string.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    var result: [String] = []
    for string in strings {
        if string.hasPrefix(prefix) {
            result.append(string)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    var result: [String] = []
    for string in strings {
        if string.hasPrefix(prefix) {
            result.append(string)
        }
    }
    return result
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { string in string.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { string in string.hasPrefix(prefix) }
}
```

func getPositive(l: [Int]) -> [Int] {
    var positiveNumbers: [Int] = []
    for number in l {
        if number > 0 {
            positiveNumbers.append(number)
        }
    }
    return positiveNumbers
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    var positiveNumbers: [Int] = []
    for number in l {
        if number > 0 {
            positiveNumbers.append(number)
        }
    }
    return positiveNumbers
}
```

func getPositive(l: [Int]) -> [Int] {
    var positive = [Int]()
    for num in l {
        if num > 0 {
            positive.append(num)
        }
    }
    return positive
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    var positive = [Int]()
    for num in l {
        if num > 0 {
            positive.append(num)
        }
    }
    return positive
}
```

func getPositive(l: [Int]) -> [Int] {
    var positive = [Int]()
    for num in l {
        if num > 0 {
            positive.append(num)
        }
    }
    return positive
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    var positive = [Int]()
    for num in l {
        if num > 0 {
            positive.append(num)
        }
    }
    return positive
}
```

func getPositive(l: [Int]) -> [Int] {
    var positiveNumbers: [Int] = []
    for number in l {
        if number > 0 {
            positiveNumbers.append(number)
        }
    }
    return positiveNumbers
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    var positiveNumbers: [Int] = []
    for number in l {
        if number > 0 {
            positiveNumbers.append(number)
        }
    }
    return positiveNumbers
}
```

func getPositive(l: [Int]) -> [Int] {
    var positive = [Int]()
    for num in l {
        if num > 0 {
            positive.append(num)
        }
    }
    return positive
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    var positive = [Int]()
    for num in l {
        if num > 0 {
            positive.append(num)
        }
    }
    return positive
}
```

func getPositive(l: [Int]) -> [Int] {
    var positive = [Int]()
    for num in l {
        if num > 0 {
            positive.append(num)
        }
    }
    return positive
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    var positive = [Int]()
    for num in l {
        if num > 0 {
            positive.append(num)
        }
    }
    return positive
}
```

func getPositive(l: [Int]) -> [Int] {
    var positive = [Int]()
    for num in l {
        if num > 0 {
            positive.append(num)
        }
    }
    return positive
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    var positive = [Int]()
    for num in l {
        if num > 0 {
            positive.append(num)
        }
    }
    return positive
}
```

func getPositive(l: [Int]) -> [Int] {
    var positive = [Int]()
    for num in l {
        if num > 0 {
            positive.append(num)
        }
    }
    return positive
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    var positive = [Int]()
    for num in l {
        if num > 0 {
            positive.append(num)
        }
    }
    return positive
}
```

func getPositive(l: [Int]) -> [Int] {
    var positive = [Int]()
    for num in l {
        if num > 0 {
            positive.append(num)
        }
    }
    return positive
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    var positive = [Int]()
    for num in l {
        if num > 0 {
            positive.append(num)
        }
    }
    return positive
}
```

func getPositive(l: [Int]) -> [Int] {
    var positiveNumbers = [Int]()
    for number in l {
        if number > 0 {
            positiveNumbers.append(number)
        }
    }
    return positiveNumbers
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    var positiveNumbers = [Int]()
    for number in l {
        if number > 0 {
            positiveNumbers.append(number)
        }
    }
    return positiveNumbers
}
```

func isPrime(n: Int) -> Bool {
    guard n > 1 else { return false }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    guard n > 1 else { return false }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    guard n > 1 else { return false }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    guard n > 1 else { return false }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    guard n > 1 else { return false }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    guard n > 1 else { return false }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}
```

func isPrime(n: Int) -> Bool {
    guard n > 1 else { return false }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    guard n > 1 else { return false }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    guard n > 1 else { return false }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    guard n > 1 else { return false }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}
```

func isPrime(n: Int) -> Bool {
    guard n > 1 else { return false }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    guard n > 1 else { return false }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}
```

func isPrime(n: Int) -> Bool {
    guard n > 1 else { return false }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    guard n > 1 else { return false }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    guard n > 1 else { return false }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    guard n > 1 else { return false }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    guard n > 1 else { return false }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    guard n > 1 else { return false }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        l.swapAt(i, i - 1)
    }
    return l
}

extension Array where Element == Int {
    mutating func swapAt(_ i: Int, _ j: Int) {
        let temp = self[i]
        self[i] = self[j]
        self[j] = temp
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        l.swapAt(i, i - 1)
    }
    return l
}

extension Array where Element == Int {
    mutating func swapAt(_ i: Int, _ j: Int) {
        let temp = self[i]
        self[i] = self[j]
        self[j] = temp
    }
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        let temp = l[i]
        l[i] = l[i - 1]
        l[i - 1] = temp
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        let temp = l[i]
        l[i] = l[i - 1]
        l[i - 1] = temp
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for (i, e) in l.enumerated() {
        if i % 3 == 2 {
            l.swapAt(i, l.first(where: { $0 % 3 == 0 })!)
        }
    }
    return l
}

extension Array where Element: Comparable {
    func swapAt(_ i: Int, _ j: Int) {
        (self[i], self[j]) = (self[j], self[i])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for (i, e) in l.enumerated() {
        if i % 3 == 2 {
            l.swapAt(i, l.first(where: { $0 % 3 == 0 })!)
        }
    }
    return l
}

extension Array where Element: Comparable {
    func swapAt(_ i: Int, _ j: Int) {
        (self[i], self[j]) = (self[j], self[i])
    }
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        l.swapAt(i, i - 1)
    }
    return l
}

extension Array where Element == Int {
    mutating func swapAt(_ i: Int, _ j: Int) {
        let temp = self[i]
        self[i] = self[j]
        self[j] = temp
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        l.swapAt(i, i - 1)
    }
    return l
}

extension Array where Element == Int {
    mutating func swapAt(_ i: Int, _ j: Int) {
        let temp = self[i]
        self[i] = self[j]
        self[j] = temp
    }
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        l.swapAt(i, i - 1)
    }
    return l
}

extension Array where Element == Int {
    mutating func swapAt(_ i: Int, _ j: Int) {
        let temp = self[i]
        self[i] = self[j]
        self[j] = temp
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        l.swapAt(i, i - 1)
    }
    return l
}

extension Array where Element == Int {
    mutating func swapAt(_ i: Int, _ j: Int) {
        let temp = self[i]
        self[i] = self[j]
        self[j] = temp
    }
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        l.swapAt(i, i - 1)
    }
    return l
}

extension Array where Element == Int {
    mutating func swapAt(_ i: Int, _ j: Int) {
        let temp = self[i]
        self[i] = self[j]
        self[j] = temp
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        l.swapAt(i, i - 1)
    }
    return l
}

extension Array where Element == Int {
    mutating func swapAt(_ i: Int, _ j: Int) {
        let temp = self[i]
        self[i] = self[j]
        self[j] = temp
    }
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        l.swapAt(i, i - 1)
    }
    return l
}

extension Array where Element == Int {
    mutating func swapAt(_ i: Int, _ j: Int) {
        let temp = self[i]
        self[i] = self[j]
        self[j] = temp
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        l.swapAt(i, i - 1)
    }
    return l
}

extension Array where Element == Int {
    mutating func swapAt(_ i: Int, _ j: Int) {
        let temp = self[i]
        self[i] = self[j]
        self[j] = temp
    }
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        l.swapAt(i, i - 1)
    }
    return l
}

extension Array where Element == Int {
    mutating func swapAt(_ i: Int, _ j: Int) {
        let temp = self[i]
        self[i] = self[j]
        self[j] = temp
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        l.swapAt(i, i - 1)
    }
    return l
}

extension Array where Element == Int {
    mutating func swapAt(_ i: Int, _ j: Int) {
        let temp = self[i]
        self[i] = self[j]
        self[j] = temp
    }
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        l.swapAt(i, i - 1)
    }
    return l
}

extension Array where Element == Int {
    mutating func swapAt(_ i: Int, _ j: Int) {
        let temp = self[i]
        self[i] = self[j]
        self[j] = temp
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        l.swapAt(i, i - 1)
    }
    return l
}

extension Array where Element == Int {
    mutating func swapAt(_ i: Int, _ j: Int) {
        let temp = self[i]
        self[i] = self[j]
        self[j] = temp
    }
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        let temp = l[i]
        l[i] = l[i - 1]
        l[i - 1] = temp
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        let temp = l[i]
        l[i] = l[i - 1]
        l[i - 1] = temp
    }
    return l
}
```

func unique(l: [Int]) -> [Int] {
    var unique = [Int]()
    for item in l {
        if!unique.contains(item) {
            unique.append(item)
        }
    }
    return unique.sorted()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var unique = [Int]()
    for item in l {
        if!unique.contains(item) {
            unique.append(item)
        }
    }
    return unique.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var uniqueList = [Int]()
    for item in l {
        if!uniqueList.contains(item) {
            uniqueList.append(item)
        }
    }
    return uniqueList.sorted()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var uniqueList = [Int]()
    for item in l {
        if!uniqueList.contains(item) {
            uniqueList.append(item)
        }
    }
    return uniqueList.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var uniqueList = [Int]()
    for num in l {
        if!uniqueList.contains(num) {
            uniqueList.append(num)
        }
    }
    return uniqueList.sorted()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var uniqueList = [Int]()
    for num in l {
        if!uniqueList.contains(num) {
            uniqueList.append(num)
        }
    }
    return uniqueList.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var uniqueList = [Int]()
    for num in l {
        if!uniqueList.contains(num) {
            uniqueList.append(num)
        }
    }
    return uniqueList.sorted()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var uniqueList = [Int]()
    for num in l {
        if!uniqueList.contains(num) {
            uniqueList.append(num)
        }
    }
    return uniqueList.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var uniqueList = [Int]()
    for item in l {
        if!uniqueList.contains(item) {
            uniqueList.append(item)
        }
    }
    return uniqueList.sorted()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var uniqueList = [Int]()
    for item in l {
        if!uniqueList.contains(item) {
            uniqueList.append(item)
        }
    }
    return uniqueList.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var unique = [Int]()
    for item in l {
        if!unique.contains(item) {
            unique.append(item)
        }
    }
    return unique.sorted()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var unique = [Int]()
    for item in l {
        if!unique.contains(item) {
            unique.append(item)
        }
    }
    return unique.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var uniqueList = [Int]()
    for item in l {
        if!uniqueList.contains(item) {
            uniqueList.append(item)
        }
    }
    return uniqueList.sorted()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var uniqueList = [Int]()
    for item in l {
        if!uniqueList.contains(item) {
            uniqueList.append(item)
        }
    }
    return uniqueList.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var unique = [Int]()
    for num in l {
        if!unique.contains(num) {
            unique.append(num)
        }
    }
    return unique.sorted()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var unique = [Int]()
    for num in l {
        if!unique.contains(num) {
            unique.append(num)
        }
    }
    return unique.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var uniqueList = [Int]()
    for num in l {
        if!uniqueList.contains(num) {
            uniqueList.append(num)
        }
    }
    return uniqueList.sorted()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var uniqueList = [Int]()
    for num in l {
        if!uniqueList.contains(num) {
            uniqueList.append(num)
        }
    }
    return uniqueList.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var uniqueList = [Int]()
    for num in l {
        if!uniqueList.contains(num) {
            uniqueList.append(num)
        }
    }
    return uniqueList.sorted()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var uniqueList = [Int]()
    for num in l {
        if!uniqueList.contains(num) {
            uniqueList.append(num)
        }
    }
    return uniqueList.sorted()
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = Int.min
    for num in l {
        if num > max {
            max = num
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = Int.min
    for num in l {
        if num > max {
            max = num
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = Int.min
    for element in l {
        if element > max {
            max = element
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = Int.min
    for element in l {
        if element > max {
            max = element
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = "\(i)"
            if str.contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = "\(i)"
            if str.contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = "\(i)"
            count += str.filter { $0 == "7" }.count
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = "\(i)"
            count += str.filter { $0 == "7" }.count
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = "\(i)"
            count += str.filter { $0 == "7" }.count
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = "\(i)"
            count += str.filter { $0 == "7" }.count
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = "\(i)"
            if str.rangeOfCharacter(from: "7")!= nil {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = "\(i)"
            if str.rangeOfCharacter(from: "7")!= nil {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = "\(i)"
            count += str.filter { $0 == "7" }.count
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = "\(i)"
            count += str.filter { $0 == "7" }.count
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = "\(i)"
            if str.rangeOfCharacter(from: "7")!= nil {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = "\(i)"
            if str.rangeOfCharacter(from: "7")!= nil {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = "\(i)"
            count += str.filter { $0 == "7" }.count
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = "\(i)"
            count += str.filter { $0 == "7" }.count
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = "\(i)"
            count += str.filter { $0 == "7" }.count
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = "\(i)"
            count += str.filter { $0 == "7" }.count
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = "\(i)"
            count += str.filter { $0 == "7" }.count
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = "\(i)"
            count += str.filter { $0 == "7" }.count
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            if str.contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            if str.contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenIndex = i + 1
        if evenIndex < l.count {
            let evenValue = l[evenIndex]
            let sortedEvenValue = l[l.count - 1 - evenIndex]
            l[evenIndex] = sortedEvenValue
            l[l.count - 1 - evenIndex] = evenValue
        }
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenIndex = i + 1
        if evenIndex < l.count {
            let evenValue = l[evenIndex]
            let sortedEvenValue = l[l.count - 1 - evenIndex]
            l[evenIndex] = sortedEvenValue
            l[l.count - 1 - evenIndex] = evenValue
        }
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenIndex = i
        let oddIndex = i + 1
        if oddIndex < l.count {
            let evenValue = l[evenIndex]
            let oddValue = l[oddIndex]
            l.swapAt(evenIndex, oddIndex)
            let sortedEvenValue = [oddValue, evenValue].sorted().first!
            l[evenIndex] = sortedEvenValue
        }
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenIndex = i
        let oddIndex = i + 1
        if oddIndex < l.count {
            let evenValue = l[evenIndex]
            let oddValue = l[oddIndex]
            l.swapAt(evenIndex, oddIndex)
            let sortedEvenValue = [oddValue, evenValue].sorted().first!
            l[evenIndex] = sortedEvenValue
        }
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenIndex = i + 1
        if evenIndex < l.count {
            let evenValue = l[evenIndex]
            let left = i - 1
            let right = i + 2
            var j = left
            while j < right && l[j] < evenValue {
                j += 1
            }
            l.remove(at: evenIndex)
            l.insert(evenValue, at: j)
        }
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenIndex = i + 1
        if evenIndex < l.count {
            let evenValue = l[evenIndex]
            let left = i - 1
            let right = i + 2
            var j = left
            while j < right && l[j] < evenValue {
                j += 1
            }
            l.remove(at: evenIndex)
            l.insert(evenValue, at: j)
        }
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let even = l[i]
        let odd = l[i + 1]
        let sorted = [even, odd].sorted()
        l[i] = sorted[0]
        l[i + 1] = sorted[1]
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let even = l[i]
        let odd = l[i + 1]
        let sorted = [even, odd].sorted()
        l[i] = sorted[0]
        l[i + 1] = sorted[1]
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenIndex = i
        let oddIndex = i + 1
        if oddIndex < l.count {
            let evenValue = l[evenIndex]
            let oddValue = l[oddIndex]
            let sortedEvenValue = [oddValue, evenValue].sorted()[0]
            l[evenIndex] = sortedEvenValue
        }
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenIndex = i
        let oddIndex = i + 1
        if oddIndex < l.count {
            let evenValue = l[evenIndex]
            let oddValue = l[oddIndex]
            let sortedEvenValue = [oddValue, evenValue].sorted()[0]
            l[evenIndex] = sortedEvenValue
        }
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenIndex = i + 1
        let evenValue = l[evenIndex]
        let left = i - 1
        let right = i + 2
        if left >= 0 && right < l.count {
            if l[left] > evenValue {
                l.swapAt(left, evenIndex)
            } else if l[right] < evenValue {
                l.swapAt(right, evenIndex)
            }
        } else if left >= 0 && l[left] > evenValue {
            l.swapAt(left, evenIndex)
        } else if right < l.count && l[right] < evenValue {
            l.swapAt(right, evenIndex)
        }
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenIndex = i + 1
        let evenValue = l[evenIndex]
        let left = i - 1
        let right = i + 2
        if left >= 0 && right < l.count {
            if l[left] > evenValue {
                l.swapAt(left, evenIndex)
            } else if l[right] < evenValue {
                l.swapAt(right, evenIndex)
            }
        } else if left >= 0 && l[left] > evenValue {
            l.swapAt(left, evenIndex)
        } else if right < l.count && l[right] < evenValue {
            l.swapAt(right, evenIndex)
        }
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let even = l[i]
        let odd = l[i + 1]
        let sorted = [even, odd].sorted()
        l[i] = sorted[0]
        l[i + 1] = sorted[1]
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let even = l[i]
        let odd = l[i + 1]
        let sorted = [even, odd].sorted()
        l[i] = sorted[0]
        l[i + 1] = sorted[1]
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenIndex = i
        let oddIndex = i + 1
        if evenIndex < l.count && oddIndex < l.count {
            let evenValue = l[evenIndex]
            let oddValue = l[oddIndex]
            if evenValue > oddValue {
                l.swapAt(evenIndex, oddIndex)
            }
        }
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenIndex = i
        let oddIndex = i + 1
        if evenIndex < l.count && oddIndex < l.count {
            let evenValue = l[evenIndex]
            let oddValue = l[oddIndex]
            if evenValue > oddValue {
                l.swapAt(evenIndex, oddIndex)
            }
        }
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let even = l[i]
        let odd = l[i + 1]
        let sorted = [even, odd].sorted()
        l[i] = sorted[0]
        l[i + 1] = sorted[1]
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let even = l[i]
        let odd = l[i + 1]
        let sorted = [even, odd].sorted()
        l[i] = sorted[0]
        l[i + 1] = sorted[1]
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenIndex = i
        let oddIndex = i + 1
        if oddIndex < l.count {
            let temp = l[evenIndex]
            l[evenIndex] = l[oddIndex]
            l[oddIndex] = temp
        }
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenIndex = i
        let oddIndex = i + 1
        if oddIndex < l.count {
            let temp = l[evenIndex]
            l[evenIndex] = l[oddIndex]
            l[oddIndex] = temp
        }
    }
    return l
}
```

func primeFib(n: Int) -> Int {
    var fibonacci = [0, 1]
    var primeNumbers = [2]
    
    while primeNumbers.count < n {
        let nextNumber = fibonacci.last! + fibonacci[fibonacci.count - 2]
        fibonacci.append(nextNumber)
        
        if isPrime(nextNumber) {
            primeNumbers.append(nextNumber)
        }
    }
    
    return primeNumbers.last!
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    
    for i in 2..<number {
        if number % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var fibonacci = [0, 1]
    var primeNumbers = [2]
    
    while primeNumbers.count < n {
        let nextNumber = fibonacci.last! + fibonacci[fibonacci.count - 2]
        fibonacci.append(nextNumber)
        
        if isPrime(nextNumber) {
            primeNumbers.append(nextNumber)
        }
    }
    
    return primeNumbers.last!
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    
    for i in 2..<number {
        if number % i == 0 {
            return false
        }
    }
    
    return true
}
```

func primeFib(n: Int) -> Int {
    var a = 0, b = 1, c: Int
    var count = 0
    while count < n {
        c = a + b
        a = b
        b = c
        if isPrime(c) {
            count += 1
        }
    }
    return c
}

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var a = 0, b = 1, c: Int
    var count = 0
    while count < n {
        c = a + b
        a = b
        b = c
        if isPrime(c) {
            count += 1
        }
    }
    return c
}

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```

func primeFib(n: Int) -> Int {
    var fibonacci = [0, 1]
    var primeNumbers = [2]
    
    while primeNumbers.count < n {
        let nextNumber = fibonacci.last! + fibonacci[fibonacci.count - 2]
        fibonacci.append(nextNumber)
        
        if isPrime(nextNumber) {
            primeNumbers.append(nextNumber)
        }
    }
    
    return primeNumbers.last!
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    
    for i in 2..<number {
        if number % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var fibonacci = [0, 1]
    var primeNumbers = [2]
    
    while primeNumbers.count < n {
        let nextNumber = fibonacci.last! + fibonacci[fibonacci.count - 2]
        fibonacci.append(nextNumber)
        
        if isPrime(nextNumber) {
            primeNumbers.append(nextNumber)
        }
    }
    
    return primeNumbers.last!
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    
    for i in 2..<number {
        if number % i == 0 {
            return false
        }
    }
    
    return true
}
```

func primeFib(n: Int) -> Int {
    var fib = [0, 1]
    var prime = [2]
    
    while prime.count < n {
        let next = fib[fib.count - 1] + fib[fib.count - 2]
        fib.append(next)
        
        if isPrime(next) {
            prime.append(next)
        }
    }
    
    return prime[n - 1]
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var fib = [0, 1]
    var prime = [2]
    
    while prime.count < n {
        let next = fib[fib.count - 1] + fib[fib.count - 2]
        fib.append(next)
        
        if isPrime(next) {
            prime.append(next)
        }
    }
    
    return prime[n - 1]
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}
```

func primeFib(n: Int) -> Int {
    var fibonacci = [0, 1]
    var primeNumbers = [2]
    
    while primeNumbers.count < n {
        let nextNumber = fibonacci.last! + fibonacci[fibonacci.count - 2]
        fibonacci.append(nextNumber)
        
        if isPrime(number: nextNumber) {
            primeNumbers.append(nextNumber)
        }
    }
    
    return primeNumbers.last!
}

func isPrime(number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    
    for i in 2..<number {
        if number % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var fibonacci = [0, 1]
    var primeNumbers = [2]
    
    while primeNumbers.count < n {
        let nextNumber = fibonacci.last! + fibonacci[fibonacci.count - 2]
        fibonacci.append(nextNumber)
        
        if isPrime(number: nextNumber) {
            primeNumbers.append(nextNumber)
        }
    }
    
    return primeNumbers.last!
}

func isPrime(number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    
    for i in 2..<number {
        if number % i == 0 {
            return false
        }
    }
    
    return true
}
```

func primeFib(n: Int) -> Int {
    var fibonacci = [0, 1]
    var primeNumbers = [2]
    
    while primeNumbers.count < n {
        let nextFibonacci = fibonacci.last! + fibonacci[fibonacci.count - 2]
        fibonacci.append(nextFibonacci)
        
        if isPrime(nextFibonacci) {
            primeNumbers.append(nextFibonacci)
        }
    }
    
    return primeNumbers.last!
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    
    for i in 2..<number {
        if number % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var fibonacci = [0, 1]
    var primeNumbers = [2]
    
    while primeNumbers.count < n {
        let nextFibonacci = fibonacci.last! + fibonacci[fibonacci.count - 2]
        fibonacci.append(nextFibonacci)
        
        if isPrime(nextFibonacci) {
            primeNumbers.append(nextFibonacci)
        }
    }
    
    return primeNumbers.last!
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    
    for i in 2..<number {
        if number % i == 0 {
            return false
        }
    }
    
    return true
}
```

func primeFib(n: Int) -> Int {
    var fibonacci = [0, 1]
    var primeNumbers = [2]
    
    while primeNumbers.count < n {
        let nextNumber = fibonacci.last! + fibonacci[fibonacci.count - 2]
        fibonacci.append(nextNumber)
        
        if isPrime(nextNumber) {
            primeNumbers.append(nextNumber)
        }
    }
    
    return primeNumbers.last!
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    
    for i in 2..<number {
        if number % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var fibonacci = [0, 1]
    var primeNumbers = [2]
    
    while primeNumbers.count < n {
        let nextNumber = fibonacci.last! + fibonacci[fibonacci.count - 2]
        fibonacci.append(nextNumber)
        
        if isPrime(nextNumber) {
            primeNumbers.append(nextNumber)
        }
    }
    
    return primeNumbers.last!
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    
    for i in 2..<number {
        if number % i == 0 {
            return false
        }
    }
    
    return true
}
```

func primeFib(n: Int) -> Int {
    var fibonacci = [0, 1]
    var primeNumbers = [2]
    
    while primeNumbers.count < n {
        let nextNumber = fibonacci.last! + fibonacci[fibonacci.count - 2]
        fibonacci.append(nextNumber)
        
        if isPrime(nextNumber) {
            primeNumbers.append(nextNumber)
        }
    }
    
    return primeNumbers.last!
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    
    for i in 2..<number {
        if number % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var fibonacci = [0, 1]
    var primeNumbers = [2]
    
    while primeNumbers.count < n {
        let nextNumber = fibonacci.last! + fibonacci[fibonacci.count - 2]
        fibonacci.append(nextNumber)
        
        if isPrime(nextNumber) {
            primeNumbers.append(nextNumber)
        }
    }
    
    return primeNumbers.last!
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    
    for i in 2..<number {
        if number % i == 0 {
            return false
        }
    }
    
    return true
}
```

func primeFib(n: Int) -> Int {
    var fibonacci = [0, 1]
    var primeNumbers = [2]
    
    while primeNumbers.count < n {
        let nextNumber = fibonacci.last! + fibonacci[fibonacci.count - 2]
        fibonacci.append(nextNumber)
        
        if isPrime(nextNumber) {
            primeNumbers.append(nextNumber)
        }
    }
    
    return primeNumbers.last!
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    
    for i in 2..<number {
        if number % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var fibonacci = [0, 1]
    var primeNumbers = [2]
    
    while primeNumbers.count < n {
        let nextNumber = fibonacci.last! + fibonacci[fibonacci.count - 2]
        fibonacci.append(nextNumber)
        
        if isPrime(nextNumber) {
            primeNumbers.append(nextNumber)
        }
    }
    
    return primeNumbers.last!
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    
    for i in 2..<number {
        if number % i == 0 {
            return false
        }
    }
    
    return true
}
```

func primeFib(n: Int) -> Int {
    var fibonacci = [0, 1]
    var primeNumbers = [2]
    
    while primeNumbers.count < n {
        let nextNumber = fibonacci.last! + fibonacci[fibonacci.count - 2]
        fibonacci.append(nextNumber)
        
        if isPrime(nextNumber) {
            primeNumbers.append(nextNumber)
        }
    }
    
    return primeNumbers.last!
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    
    for i in 2..<number {
        if number % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var fibonacci = [0, 1]
    var primeNumbers = [2]
    
    while primeNumbers.count < n {
        let nextNumber = fibonacci.last! + fibonacci[fibonacci.count - 2]
        fibonacci.append(nextNumber)
        
        if isPrime(nextNumber) {
            primeNumbers.append(nextNumber)
        }
    }
    
    return primeNumbers.last!
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 {
        return false
    }
    
    for i in 2..<number {
        if number % i == 0 {
            return false
        }
    }
    
    return true
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..< l.count {
        for j in (i+1)..< l.count {
            for k in (j+1)..< l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..< l.count {
        for j in (i+1)..< l.count {
            for k in (j+1)..< l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for (i, first) in l.enumerated() {
        for (j, second) in l.enumerated() {
            for (k, third) in l.enumerated() {
                if first + second + third == 0 && i!= j && j!= k && k!= i {
                    return true
                }
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for (i, first) in l.enumerated() {
        for (j, second) in l.enumerated() {
            for (k, third) in l.enumerated() {
                if first + second + third == 0 && i!= j && j!= k && k!= i {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..< l.count {
        for j in (i + 1)..< l.count {
            for k in (j + 1)..< l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..< l.count {
        for j in (i + 1)..< l.count {
            for k in (j + 1)..< l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            for k in (j+1)..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            for k in (j+1)..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            for k in (j+1)..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            for k in (j+1)..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            for k in (j+1)..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            for k in (j+1)..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for (i, a) in l.enumerated() {
        for (j, b) in l.enumerated() {
            for (k, c) in l.enumerated() {
                if a + b + c == 0 && i!= j && j!= k && k!= i {
                    return true
                }
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for (i, a) in l.enumerated() {
        for (j, b) in l.enumerated() {
            for (k, c) in l.enumerated() {
                if a + b + c == 0 && i!= j && j!= k && k!= i {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            for k in (j+1)..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            for k in (j+1)..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i + 1)..<l.count {
            for k in (j + 1)..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i + 1)..<l.count {
            for k in (j + 1)..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            for k in (j+1)..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            for k in (j+1)..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func carRaceCollision(n: Int) -> Int {
    var left = 0
    var right = 0
    var collisions = 0

    for i in 1...n {
        left += i
        right += n - i + 1

        if left >= right {
            collisions += left - right
            left = right
        }
    }

    return collisions
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var left = 0
    var right = 0
    var collisions = 0

    for i in 1...n {
        left += i
        right += n - i + 1

        if left >= right {
            collisions += left - right
            left = right
        }
    }

    return collisions
}
```

func carRaceCollision(n: Int) -> Int {
    var left = 0
    var right = 0
    var collisions = 0

    for _ in 1...n {
        left += 1
        right += 1

        if left == right {
            collisions += 1
        }
    }

    return collisions
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var left = 0
    var right = 0
    var collisions = 0

    for _ in 1...n {
        left += 1
        right += 1

        if left == right {
            collisions += 1
        }
    }

    return collisions
}
```

func carRaceCollision(n: Int) -> Int {
    var leftToRight = [Int](count: n, repeatedValue: 0)
    var rightToLeft = [Int](count: n, repeatedValue: 0)
    var leftToRightIndex = 0
    var rightToLeftIndex = n - 1
    var collisions = 0

    for _ in 1...2*n {
        if leftToRight[leftToRightIndex] == 1 && rightToLeft[rightToLeftIndex] == 1 {
            collisions += 1
        }
        leftToRight[leftToRightIndex] = 1
        rightToLeft[rightToLeftIndex] = 1
        leftToRightIndex = (leftToRightIndex + 1) % n
        rightToLeftIndex = (rightToLeftIndex -  + n - 1) % n
    }

    return collisions
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var leftToRight = [Int](count: n, repeatedValue: 0)
    var rightToLeft = [Int](count: n, repeatedValue: 0)
    var leftToRightIndex = 0
    var rightToLeftIndex = n - 1
    var collisions = 0

    for _ in 1...2*n {
        if leftToRight[leftToRightIndex] == 1 && rightToLeft[rightToLeftIndex] == 1 {
            collisions += 1
        }
        leftToRight[leftToRightIndex] = 1
        rightToLeft[rightToLeftIndex] = 1
        leftToRightIndex = (leftToRightIndex + 1) % n
        rightToLeftIndex = (rightToLeftIndex -  + n - 1) % n
    }

    return collisions
}
```

func carRaceCollision(n: Int) -> Int {
    var leftToRight = Array(repeating: 0, count: n)
    var rightToLeft = Array(repeating: 0, count: n)
    
    var collisions = 0
    var leftIndex = 0
    var rightIndex = n - 1
    
    while leftIndex < rightIndex {
        if leftToRight[leftIndex] == 0 && rightToLeft[rightIndex] == 0 {
            leftToRight[leftIndex] = 1
            rightToLeft[rightIndex] = 1
            collisions += 1
        }
        if leftToRight[leftIndex] == 1 {
            leftIndex += 1
        }
        if rightToLeft[rightIndex] == 1 {
            rightIndex -= 1
        }
    }
    
    return collisions
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var leftToRight = Array(repeating: 0, count: n)
    var rightToLeft = Array(repeating: 0, count: n)
    
    var collisions = 0
    var leftIndex = 0
    var rightIndex = n - 1
    
    while leftIndex < rightIndex {
        if leftToRight[leftIndex] == 0 && rightToLeft[rightIndex] == 0 {
            leftToRight[leftIndex] = 1
            rightToLeft[rightIndex] = 1
            collisions += 1
        }
        if leftToRight[leftIndex] == 1 {
            leftIndex += 1
        }
        if rightToLeft[rightIndex] == 1 {
            rightIndex -= 1
        }
    }
    
    return collisions
}
```

func carRaceCollision(n: Int) -> Int {
    var left = 0
    var right = n
    var collisions = 0

    while left < right {
        left += 1
        right -= 1

        if left < right {
            collisions += 1
        }
    }

    return collisions
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var left = 0
    var right = n
    var collisions = 0

    while left < right {
        left += 1
        right -= 1

        if left < right {
            collisions += 1
        }
    }

    return collisions
}
```

func carRaceCollision(n: Int) -> Int {
    var left = 0
    var right = 0
    var collisions = 0

    for i in 1...n {
        left += i
        right += n - i + 1

        if left >= right {
            collisions += left - right
            left = right
        }
    }

    return collisions
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var left = 0
    var right = 0
    var collisions = 0

    for i in 1...n {
        left += i
        right += n - i + 1

        if left >= right {
            collisions += left - right
            left = right
        }
    }

    return collisions
}
```

func carRaceCollision(n: Int) -> Int {
    var left = 0
    var right = 0
    var collisions = 0

    for i in 1...n {
        left += i
        right += n - i + 1
        if left >= right {
            collisions += left - right
        }
    }

    return collisions
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var left = 0
    var right = 0
    var collisions = 0

    for i in 1...n {
        left += i
        right += n - i + 1
        if left >= right {
            collisions += left - right
        }
    }

    return collisions
}
```

func carRaceCollision(n: Int) -> Int {
    var leftToRight = Array(repeating: 0, count: n)
    var rightToLeft = Array(repeating: 0, count: n)
    var collisions = 0

    for i in 0..<n {
        leftToRight[i] = i
        rightToLeft[i] = i
    }

    var leftIndex = 0
    var rightIndex = n - 1

    while leftIndex < rightIndex {
        if leftToRight[leftIndex] < rightToLeft[rightIndex] {
            leftIndex += 1
        } else if leftToRight[leftIndex] > rightToLeft[rightIndex] {
            rightIndex -= 1
        } else {
            collisions += 1
            leftIndex += 1
            rightIndex -= 1
        }
    }

    return collisions
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var leftToRight = Array(repeating: 0, count: n)
    var rightToLeft = Array(repeating: 0, count: n)
    var collisions = 0

    for i in 0..<n {
        leftToRight[i] = i
        rightToLeft[i] = i
    }

    var leftIndex = 0
    var rightIndex = n - 1

    while leftIndex < rightIndex {
        if leftToRight[leftIndex] < rightToLeft[rightIndex] {
            leftIndex += 1
        } else if leftToRight[leftIndex] > rightToLeft[rightIndex] {
            rightIndex -= 1
        } else {
            collisions += 1
            leftIndex += 1
            rightIndex -= 1
        }
    }

    return collisions
}
```

func carRaceCollision(n: Int) -> Int {
    var leftToRight = Array(repeating: 0, count: n)
    var rightToLeft = Array(repeating: 0, count: n)
    var collisions = 0

    for i in 0..<n {
        leftToRight[i] = i
        rightToLeft[i] = i
    }

    var leftIndex = 0
    var rightIndex = n - 1

    while leftIndex < rightIndex {
        if leftToRight[leftIndex] < rightToLeft[rightIndex] {
            leftIndex += 1
        } else if leftToRight[leftIndex] > rightToLeft[rightIndex] {
            rightIndex -= 1
        } else {
            collisions += 1
            leftIndex += 1
            rightIndex -= 1
        }
    }

    return collisions
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var leftToRight = Array(repeating: 0, count: n)
    var rightToLeft = Array(repeating: 0, count: n)
    var collisions = 0

    for i in 0..<n {
        leftToRight[i] = i
        rightToLeft[i] = i
    }

    var leftIndex = 0
    var rightIndex = n - 1

    while leftIndex < rightIndex {
        if leftToRight[leftIndex] < rightToLeft[rightIndex] {
            leftIndex += 1
        } else if leftToRight[leftIndex] > rightToLeft[rightIndex] {
            rightIndex -= 1
        } else {
            collisions += 1
            leftIndex += 1
            rightIndex -= 1
        }
    }

    return collisions
}
```

func carRaceCollision(n: Int) -> Int {
    var leftToRight = Array(repeating: 0, count: n)
    var rightToLeft = Array(repeating: 0, count: n)
    var collisions = 0

    for i in 0..<n {
        leftToRight[i] = i
        rightToLeft[i] = i
    }

    var left = 0
    var right = n - 1

    while left < right {
        if leftToRight[left] < rightToLeft[right] {
            left += 1
        } else if leftToRight[left] > rightToLeft[right] {
            right -= 1
        } else {
            collisions += 1
            left += 1
            right -= 1
        }
    }

    return collisions
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var leftToRight = Array(repeating: 0, count: n)
    var rightToLeft = Array(repeating: 0, count: n)
    var collisions = 0

    for i in 0..<n {
        leftToRight[i] = i
        rightToLeft[i] = i
    }

    var left = 0
    var right = n - 1

    while left < right {
        if leftToRight[left] < rightToLeft[right] {
            left += 1
        } else if leftToRight[left] > rightToLeft[right] {
            right -= 1
        } else {
            collisions += 1
            left += 1
            right -= 1
        }
    }

    return collisions
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    var result = [Int]()
    for i in 0..<l.count {
        result.append(l[i] + 1)
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    var result = [Int]()
    for i in 0..<l.count {
        result.append(l[i] + 1)
    }
    return result
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..< l.count {
        for j in (i + 1)..< l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..< l.count {
        for j in (i + 1)..< l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..< l.count {
        for j in (i + 1)..< l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..< l.count {
        for j in (i + 1)..< l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i + 1)..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i + 1)..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for (i, a) in l.enumerated() {
        for b in l[i+1..<l.count] {
            if a + b == 0 {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for (i, a) in l.enumerated() {
        for b in l[i+1..<l.count] {
            if a + b == 0 {
                return true
            }
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i + 1)..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i + 1)..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in (i+1)..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for (i, a) in l.enumerated() {
        for b in l[i+1..<l.count] {
            if a + b == 0 {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for (i, a) in l.enumerated() {
        for b in l[i+1..<l.count] {
            if a + b == 0 {
                return true
            }
        }
    }
    return false
}
```

func changeBase(x: Int, base: Int) -> String {
    var x = x
    var result = ""
    
    while x > 0 {
        let remainder = x % base
        result = String(remainder) + result
        x /= base
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var x = x
    var result = ""
    
    while x > 0 {
        let remainder = x % base
        result = String(remainder) + result
        x /= base
    }
    
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var x = x
    var result = ""
    while x > 0 {
        let remainder = x % base
        result = String(remainder) + result
        x /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var x = x
    var result = ""
    while x > 0 {
        let remainder = x % base
        result = String(remainder) + result
        x /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var x = x
    var result = ""
    while x > 0 {
        let remainder = x % base
        result = String(remainder) + result
        x /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var x = x
    var result = ""
    while x > 0 {
        let remainder = x % base
        result = String(remainder) + result
        x /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var x = x
    var result = ""
    while x > 0 {
        let remainder = x % base
        result = String(remainder) + result
        x /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var x = x
    var result = ""
    while x > 0 {
        let remainder = x % base
        result = String(remainder) + result
        x /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var x = x
    var result = ""
    
    while x > 0 {
        let remainder = x % base
        result = String(remainder) + result
        x /= base
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var x = x
    var result = ""
    
    while x > 0 {
        let remainder = x % base
        result = String(remainder) + result
        x /= base
    }
    
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var n = x
    while n > 0 {
        let remainder = n % base
        result = String(remainder) + result
        n /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var n = x
    while n > 0 {
        let remainder = n % base
        result = String(remainder) + result
        n /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var x = x
    var result = ""
    
    while x > 0 {
        let remainder = x % base
        result = String(remainder) + result
        x /= base
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var x = x
    var result = ""
    
    while x > 0 {
        let remainder = x % base
        result = String(remainder) + result
        x /= base
    }
    
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var x = x
    var result = ""
    while x > 0 {
        let remainder = x % base
        result = String(remainder) + result
        x /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var x = x
    var result = ""
    while x > 0 {
        let remainder = x % base
        result = String(remainder) + result
        x /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var x = x
    var result = ""
    while x > 0 {
        let remainder = x % base
        result = String(remainder) + result
        x /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var x = x
    var result = ""
    while x > 0 {
        let remainder = x % base
        result = String(remainder) + result
        x /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var x = x
    var result = ""
    
    while x > 0 {
        let remainder = x % base
        result = String(remainder) + result
        x /= base
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var x = x
    var result = ""
    
    while x > 0 {
        let remainder = x % base
        result = String(remainder) + result
        x /= base
    }
    
    return result
}
```

func triangleArea(a: Int, h: Int) -> Double {
    let area = 0.5 * Double(a) * Double(h)
    return area
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    let area = 0.5 * Double(a) * Double(h)
    return area
}
```

func triangleArea(a: Int, h: Int) -> Double {
    let area = 0.5 * Double(a) * Double(h)
    return area
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    let area = 0.5 * Double(a) * Double(h)
    return area
}
```

func triangleArea(a: Int, h: Int) -> Double {
    let area = 0.5 * Double(a) * Double(h)
    return area
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    let area = 0.5 * Double(a) * Double(h)
    return area
}
```

func triangleArea(a: Int, h: Int) -> Double {
    let area = 0.5 * Double(a) * Double(h)
    return area
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    let area = 0.5 * Double(a) * Double(h)
    return area
}
```

func triangleArea(a: Int, h: Int) -> Double {
    let area = 0.5 * Double(a) * Double(h)
    return area
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    let area = 0.5 * Double(a) * Double(h)
    return area
}
```

func triangleArea(a: Int, h: Int) -> Double {
    let area = Double(a * h) / 2
    return area
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    let area = Double(a * h) / 2
    return area
}
```

func triangleArea(a: Int, h: Int) -> Double {
    let area = 0.5 * Double(a) * Double(h)
    return area
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    let area = 0.5 * Double(a) * Double(h)
    return area
}
```

func triangleArea(a: Int, h: Int) -> Double {
    let area = 0.5 * Double(a) * Double(h)
    return area
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    let area = 0.5 * Double(a) * Double(h)
    return area
}
```

func triangleArea(a: Int, h: Int) -> Double {
    let area = Double(0.5) * Double(a) * Double(h)
    return area
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    let area = Double(0.5) * Double(a) * Double(h)
    return area
}
```

func triangleArea(a: Int, h: Int) -> Double {
    let area = 0.5 * Double(a) * Double(h)
    return area
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    let area = 0.5 * Double(a) * Double(h)
    return area
}
```

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    
    for _ in 0..<n {
        d = a + b + c + d
        a = b
        b = c
        c = d
    }
    
    return d
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    
    for _ in 0..<n {
        d = a + b + c + d
        a = b
        b = c
        c = d
    }
    
    return d
}
```

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    
    for _ in 1...n {
        let next = a + b + c + d
        a = b
        b = c
        c = d
        d = next
    }
    
    return d
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    
    for _ in 1...n {
        let next = a + b + c + d
        a = b
        b = c
        c = d
        d = next
    }
    
    return d
}
```

func fib4(n: Int) -> Int {
    guard n >= 0 else {
        return 0
    }
    
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    
    for _ in 0..<n {
        d = a + b + c + d
        a = b
        b = c
        c = d
    }
    
    return d
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    guard n >= 0 else {
        return 0
    }
    
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    
    for _ in 0..<n {
        d = a + b + c + d
        a = b
        b = c
        c = d
    }
    
    return d
}
```

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    
    for _ in 0..<n {
        d = a + b + c + d
        a = b
        b = c
        c = d
    }
    
    return d
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    
    for _ in 0..<n {
        d = a + b + c + d
        a = b
        b = c
        c = d
    }
    
    return d
}
```

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    
    for _ in 0..<n {
        d = a + b + c + d
        a = b
        b = c
        c = d
    }
    
    return d
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    
    for _ in 0..<n {
        d = a + b + c + d
        a = b
        b = c
        c = d
    }
    
    return d
}
```

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    
    for _ in 0..<n {
        let next = a + b + c + d
        a = b
        b = c
        c = d
        d = next
    }
    
    return d
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    
    for _ in 0..<n {
        let next = a + b + c + d
        a = b
        b = c
        c = d
        d = next
    }
    
    return d
}
```

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    
    for _ in 1...n {
        let next = a + b + c + d
        a = b
        b = c
        c = d
        d = next
    }
    
    return d
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    
    for _ in 1...n {
        let next = a + b + c + d
        a = b
        b = c
        c = d
        d = next
    }
    
    return d
}
```

func fib4(n: Int) -> Int {
    guard n >= 0 else { return 0 }
    
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    
    for _ in 0..<n {
        d = a + b + c + d
        a = b
        b = c
        c = d
    }
    
    return d
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    guard n >= 0 else { return 0 }
    
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    
    for _ in 0..<n {
        d = a + b + c + d
        a = b
        b = c
        c = d
    }
    
    return d
}
```

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    
    for _ in 1...n {
        let next = a + b + c + d
        a = b
        b = c
        c = d
        d = next
    }
    
    return d
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    
    for _ in 1...n {
        let next = a + b + c + d
        a = b
        b = c
        c = d
        d = next
    }
    
    return d
}
```

func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    
    for _ in 0..<n {
        d = a + b + c + d
        a = b
        b = c
        c = d
    }
    
    return d
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    var a = 0
    var b = 0
    var c = 0
    var d = 0
    
    for _ in 0..<n {
        d = a + b + c + d
        a = b
        b = c
        c = d
    }
    
    return d
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[middle - 1] + sorted[middle]) / 2
    } else {
        return Double(sorted[middle])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[middle - 1] + sorted[middle]) / 2
    } else {
        return Double(sorted[middle])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        let left = sorted[mid - 1]
        let right = sorted[mid]
        return Double(left + right) / 2
    } else {
        return Double(sorted[mid])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        let left = sorted[mid - 1]
        let right = sorted[mid]
        return Double(left + right) / 2
    } else {
        return Double(sorted[mid])
    }
}
```