Metadata
| Key | Value |
|---|---|
| engine | mlx |
| prompt | default |
| temp | 0.2 |
| top_p | 0.95 |
| max_new_tokens | 1024 |
| n_completions | 10 |
Solutions
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
guard numbers.count > 1 else {
return false
}
for i in 0..<numbers.count {
for j in (i + 1)..<numbers.count {
let distance = abs(numbers[i] - numbers[j])
if distance <= threshold {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
guard numbers.count > 1 else {
return false
}
for i in 0..<numbers.count {
for j in (i + 1)..<numbers.count {
let distance = abs(numbers[i] - numbers[j])
if distance <= threshold {
return true
}
}
}
return false
}
```func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
guard numbers.count > 1 else {
return false
}
for i in 0..<numbers.count {
for j in (i + 1)..<numbers.count {
let distance = abs(numbers[i] - numbers[j])
if distance <= threshold {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
guard numbers.count > 1 else {
return false
}
for i in 0..<numbers.count {
for j in (i + 1)..<numbers.count {
let distance = abs(numbers[i] - numbers[j])
if distance <= threshold {
return true
}
}
}
return false
}
```func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count {
for j in (i + 1)..<numbers.count {
if abs(numbers[i] - numbers[j]) <= threshold {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count {
for j in (i + 1)..<numbers.count {
if abs(numbers[i] - numbers[j]) <= threshold {
return true
}
}
}
return false
}
```func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
guard numbers.count > 1 else {
return false
}
for i in 0..<numbers.count {
for j in (i + 1)..<numbers.count {
let difference = abs(numbers[i] - numbers[j])
if difference <= threshold {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
guard numbers.count > 1 else {
return false
}
for i in 0..<numbers.count {
for j in (i + 1)..<numbers.count {
let difference = abs(numbers[i] - numbers[j])
if difference <= threshold {
return true
}
}
}
return false
}
```func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
guard numbers.count > 1 else {
return false
}
for i in 0..<numbers.count {
for j in (i + 1)..<numbers.count {
let difference = abs(numbers[i] - numbers[j])
if difference <= threshold {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
guard numbers.count > 1 else {
return false
}
for i in 0..<numbers.count {
for j in (i + 1)..<numbers.count {
let difference = abs(numbers[i] - numbers[j])
if difference <= threshold {
return true
}
}
}
return false
}
```func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count {
for j in (i + 1)..<numbers.count {
if abs(numbers[i] - numbers[j]) <= threshold {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count {
for j in (i + 1)..<numbers.count {
if abs(numbers[i] - numbers[j]) <= threshold {
return true
}
}
}
return false
}
```func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count {
for j in (i + 1)..<numbers.count {
if abs(numbers[i] - numbers[j]) <= threshold {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count {
for j in (i + 1)..<numbers.count {
if abs(numbers[i] - numbers[j]) <= threshold {
return true
}
}
}
return false
}
```func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
guard numbers.count > 1 else {
return false
}
for i in 0..<numbers.count {
for j in (i + 1)..<numbers.count {
let difference = abs(numbers[i] - numbers[j])
if difference <= threshold {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
guard numbers.count > 1 else {
return false
}
for i in 0..<numbers.count {
for j in (i + 1)..<numbers.count {
let difference = abs(numbers[i] - numbers[j])
if difference <= threshold {
return true
}
}
}
return false
}
```func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count {
for j in (i + 1)..<numbers.count {
let difference = abs(numbers[i] - numbers[j])
if difference <= threshold {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count {
for j in (i + 1)..<numbers.count {
let difference = abs(numbers[i] - numbers[j])
if difference <= threshold {
return true
}
}
}
return false
}
```func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count {
for j in (i + 1)..<numbers.count {
if abs(numbers[i] - numbers[j]) <= threshold {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count {
for j in (i + 1)..<numbers.count {
if abs(numbers[i] - numbers[j]) <= threshold {
return true
}
}
}
return false
}
```func separateParenGroups(parenString: String) -> [String] {
var result = [String]()
var stack = [Character]()
for char in parenString {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.last == "(" {
stack.removeLast()
} else {
stack.append(char)
}
}
}
while!stack.isEmpty {
result.append(String(stack.removeLast()))
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
var result = [String]()
var stack = [Character]()
for char in parenString {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.last == "(" {
stack.removeLast()
} else {
stack.append(char)
}
}
}
while!stack.isEmpty {
result.append(String(stack.removeLast()))
}
return result
}
```while!stack.isEmpty { // expected expression, var, or let in 'while' conditionfunc separateParenGroups(parenString: String) -> [String] {
var result = [String]()
var stack = [Character]()
for char in parenString {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.last == "(" {
stack.removeLast()
} else {
return []
}
}
}
if stack.count == 0 {
return result
} else {
return []
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
var result = [String]()
var stack = [Character]()
for char in parenString {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.last == "(" {
stack.removeLast()
} else {
return []
}
}
}
if stack.count == 0 {
return result
} else {
return []
}
}
```var result = [String]() // variable 'result' was never mutated; consider changing to 'let' constant // XCTAssertTrue failedfunc separateParenGroups(parenString: String) -> [String] {
var result = [String]()
var stack = [Character]()
for char in parenString {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.last == "(" {
stack.removeLast()
} else {
stack.append(char)
}
}
if stack.isEmpty {
result.append(String(char))
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
var result = [String]()
var stack = [Character]()
for char in parenString {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.last == "(" {
stack.removeLast()
} else {
stack.append(char)
}
}
if stack.isEmpty {
result.append(String(char))
}
}
return result
}
``` // XCTAssertTrue failedfunc separateParenGroups(parenString: String) -> [String] {
var result = [String]()
var stack = [Character]()
for char in parenString {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.last == "(" {
stack.removeLast()
} else {
stack.append(char)
}
} else {
stack.append(char)
}
if stack.isEmpty {
let group = String(stack)
result.append(group)
stack.removeAll()
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
var result = [String]()
var stack = [Character]()
for char in parenString {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.last == "(" {
stack.removeLast()
} else {
stack.append(char)
}
} else {
stack.append(char)
}
if stack.isEmpty {
let group = String(stack)
result.append(group)
stack.removeAll()
}
}
return result
}
``` // XCTAssertTrue failedfunc separateParenGroups(parenString: String) -> [String] {
let scanner = Scanner(string: parenString)
var result = [String]()
var stack = [Character]()
while scanner.scanCharacter(from:.parentheses) {
let currentChar = scanner.characters.first!
if currentChar == "(" {
stack.append(currentChar)
} else if currentChar == ")" {
if stack.last == "(" {
stack.removeLast()
} else {
result.append(String(currentChar))
}
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
let scanner = Scanner(string: parenString)
var result = [String]()
var stack = [Character]()
while scanner.scanCharacter(from:.parentheses) {
let currentChar = scanner.characters.first!
if currentChar == "(" {
stack.append(currentChar)
} else if currentChar == ")" {
if stack.last == "(" {
stack.removeLast()
} else {
result.append(String(currentChar))
}
}
}
return result
}
```while scanner.scanCharacter(from:.parentheses) { // argument passed to call that takes no argumentswhile scanner.scanCharacter(from:.parentheses) { // cannot infer contextual base in reference to member 'parentheses'while scanner.scanCharacter(from:.parentheses) { // optional type 'Character?' cannot be used as a boolean; test for '!= nil' insteadlet currentChar = scanner.characters.first! // value of type 'Scanner' has no member 'characters'func separateParenGroups(parenString: String) -> [String] {
var result = [String]()
var stack = [Character]()
var currentGroup = ""
for char in parenString {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.last == "(" {
stack.removeLast()
} else {
stack.append(char)
}
} else if char == " " {
continue
} else {
currentGroup.append(char)
}
if stack.isEmpty {
result.append(currentGroup)
currentGroup = ""
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
var result = [String]()
var stack = [Character]()
var currentGroup = ""
for char in parenString {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.last == "(" {
stack.removeLast()
} else {
stack.append(char)
}
} else if char == " " {
continue
} else {
currentGroup.append(char)
}
if stack.isEmpty {
result.append(currentGroup)
currentGroup = ""
}
}
return result
}
``` // XCTAssertTrue failedfunc separateParenGroups(parenString: String) -> [String] {
var result = [String]()
var stack = [Character]()
var currentGroup = ""
for char in parenString {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.last == "(" {
stack.removeLast()
} else {
stack.append(char)
}
} else {
currentGroup.append(char)
}
if stack.isEmpty {
result.append(currentGroup)
currentGroup = ""
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
var result = [String]()
var stack = [Character]()
var currentGroup = ""
for char in parenString {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.last == "(" {
stack.removeLast()
} else {
stack.append(char)
}
} else {
currentGroup.append(char)
}
if stack.isEmpty {
result.append(currentGroup)
currentGroup = ""
}
}
return result
}
``` // XCTAssertTrue failedfunc separateParenGroups(parenString: String) -> [String] {
var result = [String]()
var stack = [Character]()
for char in parenString {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.last == "(" {
stack.removeLast()
} else {
return []
}
}
}
if stack.count == 0 {
return result
} else {
return []
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
var result = [String]()
var stack = [Character]()
for char in parenString {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.last == "(" {
stack.removeLast()
} else {
return []
}
}
}
if stack.count == 0 {
return result
} else {
return []
}
}
```var result = [String]() // variable 'result' was never mutated; consider changing to 'let' constant // XCTAssertTrue failedfunc separateParenGroups(parenString: String) -> [String] {
var result = [String]()
var stack = [Character]()
for char in parenString {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.last == "(" {
stack.removeLast()
} else {
stack.append(char)
}
}
if stack.isEmpty {
result.append(String(char))
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
var result = [String]()
var stack = [Character]()
for char in parenString {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.last == "(" {
stack.removeLast()
} else {
stack.append(char)
}
}
if stack.isEmpty {
result.append(String(char))
}
}
return result
}
``` // XCTAssertTrue failedfunc separateParenGroups(parenString: String) -> [String] {
var result = [String]()
var stack = [Character]()
var currentGroup = ""
for char in parenString {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.last == "(" {
stack.removeLast()
} else {
stack.append(char)
}
} else {
currentGroup.append(char)
}
if stack.isEmpty {
result.append(currentGroup)
currentGroup = ""
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
var result = [String]()
var stack = [Character]()
var currentGroup = ""
for char in parenString {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.last == "(" {
stack.removeLast()
} else {
stack.append(char)
}
} else {
currentGroup.append(char)
}
if stack.isEmpty {
result.append(currentGroup)
currentGroup = ""
}
}
return result
}
``` // XCTAssertTrue failedfunc truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
Answer:
```swift
func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}
```func truncateNumber(number: Double) -> Double {
return number - Int(number)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
Answer:
```swift
func truncateNumber(number: Double) -> Double {
return number - Int(number)
}
```return number - Int(number) // cannot convert value of type 'Int' to expected argument type 'Double'func truncateNumber(number: Double) -> Double {
return number - Int(number)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
Answer:
```swift
func truncateNumber(number: Double) -> Double {
return number - Int(number)
}
```return number - Int(number) // cannot convert value of type 'Int' to expected argument type 'Double'func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
Answer:
```swift
func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}
```func truncateNumber(number: Double) -> Double {
return number - Int(number)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
Answer:
```swift
func truncateNumber(number: Double) -> Double {
return number - Int(number)
}
```return number - Int(number) // cannot convert value of type 'Int' to expected argument type 'Double'func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
Answer:
```swift
func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}
```func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
Answer:
```swift
func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}
```func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
Answer:
```swift
func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}
```func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
Answer:
```swift
func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}
```func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
Answer:
```swift
func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDifferences = numbers.map { abs($0 - mean) }
let averageAbsoluteDifference = absoluteDifferences.reduce(0, +) / Double(absoluteDifferences.count)
return averageAbsoluteDifference
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDifferences = numbers.map { abs($0 - mean) }
let averageAbsoluteDifference = absoluteDifferences.reduce(0, +) / Double(absoluteDifferences.count)
return averageAbsoluteDifference
}
```func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDifferences = numbers.map { |x - mean| }
let meanAbsoluteDeviation = absoluteDifferences.reduce(0, +) / Double(numbers.count)
return meanAbsoluteDeviation
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDifferences = numbers.map { |x - mean| }
let meanAbsoluteDeviation = absoluteDifferences.reduce(0, +) / Double(numbers.count)
return meanAbsoluteDeviation
}
```let absoluteDifferences = numbers.map { |x - mean| } // contextual type for closure argument list expects 1 argument, which cannot be implicitly ignoredlet absoluteDifferences = numbers.map { |x - mean| } // '|' is not a prefix unary operatorlet absoluteDifferences = numbers.map { |x - mean| } // cannot find 'x' in scopelet absoluteDifferences = numbers.map { |x - mean| } // '|' is not a postfix unary operatorfunc meanAbsoluteDeviation(numbers: [Double]) -> Double {
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDifferences = numbers.map { abs($0 - mean) }
let averageAbsoluteDifference = absoluteDifferences.reduce(0, +) / Double(absoluteDifferences.count)
return averageAbsoluteDifference
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDifferences = numbers.map { abs($0 - mean) }
let averageAbsoluteDifference = absoluteDifferences.reduce(0, +) / Double(absoluteDifferences.count)
return averageAbsoluteDifference
}
```func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDifferences = numbers.map { |x - mean| }
let meanAbsoluteDeviation = absoluteDifferences.reduce(0, +) / Double(numbers.count)
return meanAbsoluteDeviation
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDifferences = numbers.map { |x - mean| }
let meanAbsoluteDeviation = absoluteDifferences.reduce(0, +) / Double(numbers.count)
return meanAbsoluteDeviation
}
```let absoluteDifferences = numbers.map { |x - mean| } // contextual type for closure argument list expects 1 argument, which cannot be implicitly ignoredlet absoluteDifferences = numbers.map { |x - mean| } // '|' is not a prefix unary operatorlet absoluteDifferences = numbers.map { |x - mean| } // cannot find 'x' in scopelet absoluteDifferences = numbers.map { |x - mean| } // '|' is not a postfix unary operatorfunc meanAbsoluteDeviation(numbers: [Double]) -> Double {
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDifferences = numbers.map { |x - mean| }
let averageAbsoluteDifference = absoluteDifferences.reduce(0, +) / Double(numbers.count)
return averageAbsoluteDifference
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDifferences = numbers.map { |x - mean| }
let averageAbsoluteDifference = absoluteDifferences.reduce(0, +) / Double(numbers.count)
return averageAbsoluteDifference
}
```let absoluteDifferences = numbers.map { |x - mean| } // contextual type for closure argument list expects 1 argument, which cannot be implicitly ignoredlet absoluteDifferences = numbers.map { |x - mean| } // '|' is not a prefix unary operatorlet absoluteDifferences = numbers.map { |x - mean| } // cannot find 'x' in scopelet absoluteDifferences = numbers.map { |x - mean| } // '|' is not a postfix unary operatorfunc meanAbsoluteDeviation(numbers: [Double]) -> Double {
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDifferences = numbers.map { |x - mean| }
let averageAbsoluteDifference = absoluteDifferences.reduce(0, +) / Double(numbers.count)
return averageAbsoluteDifference
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDifferences = numbers.map { |x - mean| }
let averageAbsoluteDifference = absoluteDifferences.reduce(0, +) / Double(numbers.count)
return averageAbsoluteDifference
}
```let absoluteDifferences = numbers.map { |x - mean| } // contextual type for closure argument list expects 1 argument, which cannot be implicitly ignoredlet absoluteDifferences = numbers.map { |x - mean| } // '|' is not a prefix unary operatorlet absoluteDifferences = numbers.map { |x - mean| } // cannot find 'x' in scopelet absoluteDifferences = numbers.map { |x - mean| } // '|' is not a postfix unary operatorfunc meanAbsoluteDeviation(numbers: [Double]) -> Double {
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDifferences = numbers.map { abs($0 - mean) }
let averageAbsoluteDifference = absoluteDifferences.reduce(0, +) / Double(absoluteDifferences.count)
return averageAbsoluteDifference
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDifferences = numbers.map { abs($0 - mean) }
let averageAbsoluteDifference = absoluteDifferences.reduce(0, +) / Double(absoluteDifferences.count)
return averageAbsoluteDifference
}
```func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDifferences = numbers.map { abs($0 - mean) }
let averageAbsoluteDifference = absoluteDifferences.reduce(0, +) / Double(absoluteDifferences.count)
return averageAbsoluteDifference
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDifferences = numbers.map { abs($0 - mean) }
let averageAbsoluteDifference = absoluteDifferences.reduce(0, +) / Double(absoluteDifferences.count)
return averageAbsoluteDifference
}
```func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDifferences = numbers.map { abs($0 - mean) }
return absoluteDifferences.reduce(0, +) / Double(numbers.count)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDifferences = numbers.map { abs($0 - mean) }
return absoluteDifferences.reduce(0, +) / Double(numbers.count)
}
```func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDifferences = numbers.map { |x - mean| }
let averageAbsoluteDifference = absoluteDifferences.reduce(0, +) / Double(absoluteDifferences.count)
return averageAbsoluteDifference
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDifferences = numbers.map { |x - mean| }
let averageAbsoluteDifference = absoluteDifferences.reduce(0, +) / Double(absoluteDifferences.count)
return averageAbsoluteDifference
}
```let absoluteDifferences = numbers.map { |x - mean| } // contextual type for closure argument list expects 1 argument, which cannot be implicitly ignoredlet absoluteDifferences = numbers.map { |x - mean| } // '|' is not a prefix unary operatorlet absoluteDifferences = numbers.map { |x - mean| } // cannot find 'x' in scopelet absoluteDifferences = numbers.map { |x - mean| } // '|' is not a postfix unary operatorfunc intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}
```func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
if index > 0 {
result.append(delimeter)
}
result.append(number)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
if index > 0 {
result.append(delimeter)
}
result.append(number)
}
return result
}
```func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}
```func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
if index > 0 {
result.append(delimeter)
}
result.append(number)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
if index > 0 {
result.append(delimeter)
}
result.append(number)
}
return result
}
```func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
if index > 0 {
result.append(delimeter)
}
result.append(number)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
if index > 0 {
result.append(delimeter)
}
result.append(number)
}
return result
}
```func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}
```func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}
```func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
if index > 0 {
result.append(delimeter)
}
result.append(number)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
if index > 0 {
result.append(delimeter)
}
result.append(number)
}
return result
}
```func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}
```func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
if index > 0 {
result.append(delimeter)
}
result.append(number)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
if index > 0 {
result.append(delimeter)
}
result.append(number)
}
return result
}
```func parseNestedParens(parenString: String) -> [Int] {
let parenGroups = parenString.components(separatedBy: " ")
var nestingLevels = [Int]()
for group in parenGroups {
var currentNestingLevel = 0
for char in group {
if char == "(" {
currentNestingLevel += 1
} else if char == ")" {
currentNestingLevel -= 1
}
nestingLevels.append(currentNestingLevel)
}
}
return nestingLevels
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
let parenGroups = parenString.components(separatedBy: " ")
var nestingLevels = [Int]()
for group in parenGroups {
var currentNestingLevel = 0
for char in group {
if char == "(" {
currentNestingLevel += 1
} else if char == ")" {
currentNestingLevel -= 1
}
nestingLevels.append(currentNestingLevel)
}
}
return nestingLevels
}
``` // XCTAssertTrue failedfunc parseNestedParens(parenString: String) -> [Int] {
let parenRegex = try! NSRegularExpression(pattern: "\\((.*?)\\)")
let parenMatches = parenRegex.matches(in: parenString, options: [], range: NSRange(location: 0, length: parenString.utf16.count))
var result = [Int]()
for match in parenMatches {
let nestedParens = parseNestedParens(parenString: String(parenString[Range(match.range, in: parenString)!]))
result.append(nestedParens.max()?? 0)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
let parenRegex = try! NSRegularExpression(pattern: "\\((.*?)\\)")
let parenMatches = parenRegex.matches(in: parenString, options: [], range: NSRange(location: 0, length: parenString.utf16.count))
var result = [Int]()
for match in parenMatches {
let nestedParens = parseNestedParens(parenString: String(parenString[Range(match.range, in: parenString)!]))
result.append(nestedParens.max()?? 0)
}
return result
}
```result.append(nestedParens.max()?? 0) // cannot use optional chaining on non-optional value of type 'Int'result.append(nestedParens.max()?? 0) // no exact matches in call to instance method 'append'result.append(nestedParens.max()?? 0) // expected ',' separatorfunc parseNestedParens(parenString: String) -> [Int] {
var nestingLevel = 0
var result = [Int]()
for char in parenString {
if char == "(" {
nestingLevel += 1
} else if char == ")" {
nestingLevel -= 1
}
result.append(nestingLevel)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
var nestingLevel = 0
var result = [Int]()
for char in parenString {
if char == "(" {
nestingLevel += 1
} else if char == ")" {
nestingLevel -= 1
}
result.append(nestingLevel)
}
return result
}
``` // XCTAssertTrue failedfunc parseNestedParens(parenString: String) -> [Int] {
let parenGroups = parenString.components(separatedBy: " ")
var maxNestingLevel = 0
var nestingLevels = [Int]()
for group in parenGroups {
var currentNestingLevel = 0
for char in group {
if char == "(" {
currentNestingLevel += 1
} else if char == ")" {
currentNestingLevel -= 1
}
}
nestingLevels.append(currentNestingLevel)
maxNestingLevel = max(maxNestingLevel, currentNestingLevel)
}
return nestingLevels
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
let parenGroups = parenString.components(separatedBy: " ")
var maxNestingLevel = 0
var nestingLevels = [Int]()
for group in parenGroups {
var currentNestingLevel = 0
for char in group {
if char == "(" {
currentNestingLevel += 1
} else if char == ")" {
currentNestingLevel -= 1
}
}
nestingLevels.append(currentNestingLevel)
maxNestingLevel = max(maxNestingLevel, currentNestingLevel)
}
return nestingLevels
}
``` // XCTAssertTrue failedfunc parseNestedParens(parenString: String) -> [Int] {
let groups = parenString.components(separatedBy: " ")
var result = [Int]()
for group in groups {
var level = 0
for char in group {
if char == "(" {
level += 1
} else if char == ")" {
level -= 1
}
result.append(level)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
let groups = parenString.components(separatedBy: " ")
var result = [Int]()
for group in groups {
var level = 0
for char in group {
if char == "(" {
level += 1
} else if char == ")" {
level -= 1
}
result.append(level)
}
}
return result
}
``` // XCTAssertTrue failedfunc parseNestedParens(parenString: String) -> [Int] {
let groups = parenString.components(separatedBy: " ")
var result = [Int]()
for group in groups {
var level = 0
for char in group {
if char == "(" {
level += 1
} else if char == ")" {
level -= 1
}
result.append(level)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
let groups = parenString.components(separatedBy: " ")
var result = [Int]()
for group in groups {
var level = 0
for char in group {
if char == "(" {
level += 1
} else if char == ")" {
level -= 1
}
result.append(level)
}
}
return result
}
``` // XCTAssertTrue failedfunc parseNestedParens(parenString: String) -> [Int] {
let groups = parenString.components(separatedBy: " ")
var result = [Int]()
for group in groups {
var count = 0
for char in group {
if char == "(" {
count += 1
} else if char == ")" {
count -= 1
}
}
result.append(count)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
let groups = parenString.components(separatedBy: " ")
var result = [Int]()
for group in groups {
var count = 0
for char in group {
if char == "(" {
count += 1
} else if char == ")" {
count -= 1
}
}
result.append(count)
}
return result
}
``` // XCTAssertTrue failedfunc parseNestedParens(parenString: String) -> [Int] {
let parenGroups = parenString.components(separatedBy: " ")
var nestingLevels = [Int]()
for group in parenGroups {
var currentNestingLevel = 0
for char in group {
if char == "(" {
currentNestingLevel += 1
} else if char == ")" {
currentNestingLevel -= 1
}
}
nestingLevels.append(currentNestingLevel)
}
return nestingLevels
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
let parenGroups = parenString.components(separatedBy: " ")
var nestingLevels = [Int]()
for group in parenGroups {
var currentNestingLevel = 0
for char in group {
if char == "(" {
currentNestingLevel += 1
} else if char == ")" {
currentNestingLevel -= 1
}
}
nestingLevels.append(currentNestingLevel)
}
return nestingLevels
}
``` // XCTAssertTrue failedfunc parseNestedParens(parenString: String) -> [Int] {
let parenGroups = parenString.components(separatedBy: " ")
var nestingLevels = [Int]()
for group in parenGroups {
var currentNestingLevel = 0
for char in group {
if char == "(" {
currentNestingLevel += 1
} else if char == ")" {
currentNestingLevel -= 1
}
}
nestingLevels.append(currentNestingLevel)
}
return nestingLevels
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
let parenGroups = parenString.components(separatedBy: " ")
var nestingLevels = [Int]()
for group in parenGroups {
var currentNestingLevel = 0
for char in group {
if char == "(" {
currentNestingLevel += 1
} else if char == ")" {
currentNestingLevel -= 1
}
}
nestingLevels.append(currentNestingLevel)
}
return nestingLevels
}
``` // XCTAssertTrue failedfunc parseNestedParens(parenString: String) -> [Int] {
let groups = parenString.components(separatedBy: " ")
var result = [Int]()
for group in groups {
var currentLevel = 0
var nestedParens = 0
for char in group {
if char == "(" {
currentLevel += 1
nestedParens += 1
} else if char == ")" {
currentLevel -= 1
nestedParens -= 1
}
}
result.append(nestedParens)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
let groups = parenString.components(separatedBy: " ")
var result = [Int]()
for group in groups {
var currentLevel = 0
var nestedParens = 0
for char in group {
if char == "(" {
currentLevel += 1
nestedParens += 1
} else if char == ")" {
currentLevel -= 1
nestedParens -= 1
}
}
result.append(nestedParens)
}
return result
}
``` // XCTAssertTrue failedfunc filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var max = numbers.first?? 0
for number in numbers {
if number > max {
max = number
}
result.append(max)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var max = numbers.first?? 0
for number in numbers {
if number > max {
max = number
}
result.append(max)
}
return result
}
```var max = numbers.first?? 0 // cannot use optional chaining on non-optional value of type 'Int'var max = numbers.first?? 0 // consecutive statements on a line must be separated by ';'var max = numbers.first?? 0 // integer literal is unusedfunc rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var max = numbers[0]
for number in numbers {
if number > max {
max = number
}
result.append(max)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var max = numbers[0]
for number in numbers {
if number > max {
max = number
}
result.append(max)
}
return result
}
``` // Fatal error: Index out of rangefunc rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var max = numbers[0]
for number in numbers {
if number > max {
max = number
}
result.append(max)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var max = numbers[0]
for number in numbers {
if number > max {
max = number
}
result.append(max)
}
return result
}
``` // Fatal error: Index out of rangefunc rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var max = numbers[0]
for number in numbers {
if number > max {
max = number
}
result.append(max)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var max = numbers[0]
for number in numbers {
if number > max {
max = number
}
result.append(max)
}
return result
}
``` // Fatal error: Index out of rangefunc rollingMax(numbers: [Int]) -> [Int] {
var rollingMax = [Int]()
var currentMax = numbers.first!
rollingMax.append(currentMax)
for number in numbers.dropFirst() {
currentMax = max(currentMax, number)
rollingMax.append(currentMax)
}
return rollingMax
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var rollingMax = [Int]()
var currentMax = numbers.first!
rollingMax.append(currentMax)
for number in numbers.dropFirst() {
currentMax = max(currentMax, number)
rollingMax.append(currentMax)
}
return rollingMax
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var max = numbers.first!
for number in numbers {
if number > max {
max = number
}
result.append(max)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var max = numbers.first!
for number in numbers {
if number > max {
max = number
}
result.append(max)
}
return result
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var max = numbers.first?? 0
for number in numbers {
if number > max {
max = number
}
result.append(max)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var max = numbers.first?? 0
for number in numbers {
if number > max {
max = number
}
result.append(max)
}
return result
}
```var max = numbers.first?? 0 // cannot use optional chaining on non-optional value of type 'Int'var max = numbers.first?? 0 // consecutive statements on a line must be separated by ';'var max = numbers.first?? 0 // integer literal is unusedfunc rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var maxElement = numbers.first!
for number in numbers {
if number > maxElement {
maxElement = number
}
result.append(maxElement)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var maxElement = numbers.first!
for number in numbers {
if number > maxElement {
maxElement = number
}
result.append(maxElement)
}
return result
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var max = numbers[0]
for number in numbers {
if number > max {
max = number
}
result.append(max)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var max = numbers[0]
for number in numbers {
if number > max {
max = number
}
result.append(max)
}
return result
}
``` // Fatal error: Index out of rangefunc rollingMax(numbers: [Int]) -> [Int] {
var rollingMax = [Int]()
var max = numbers.first!
for number in numbers {
if number > max {
max = number
}
rollingMax.append(max)
}
return rollingMax
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var rollingMax = [Int]()
var max = numbers.first!
for number in numbers {
if number > max {
max = number
}
rollingMax.append(max)
}
return rollingMax
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc makePalindrome(string: String) -> String {
let reversed = String(string.reversed())
let longestPalindrome = longestPalindrome(string: string)
let prefix = String(string.prefix(upTo: string.index(before: longestPalindrome.startIndex)))
return prefix + reversed
}
func longestPalindrome(string: String) -> String {
var longestPalindrome = ""
for i in 0..<string.count {
for j in i..<string.count {
let substring = String(string[i..<j])
if substring == substring.reversed() && substring.count > longestPalindrome.count {
longestPalindrome = substring
}
}
}
return longestPalindrome
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
Answer:
```swift
func makePalindrome(string: String) -> String {
let reversed = String(string.reversed())
let longestPalindrome = longestPalindrome(string: string)
let prefix = String(string.prefix(upTo: string.index(before: longestPalindrome.startIndex)))
return prefix + reversed
}
func longestPalindrome(string: String) -> String {
var longestPalindrome = ""
for i in 0..<string.count {
for j in i..<string.count {
let substring = String(string[i..<j])
if substring == substring.reversed() && substring.count > longestPalindrome.count {
longestPalindrome = substring
}
}
}
return longestPalindrome
}
```let substring = String(string[i..<j]) // 'subscript(_:)' is unavailable: cannot subscript String with an integer range, use a String.Index range instead.if substring == substring.reversed() && substring.count > longestPalindrome.count { // cannot convert value of type 'ReversedCollection<String>' to expected argument type 'String'func makePalindrome(string: String) -> String {
let reversed = String(string.reversed())
let longestPalindrome = longestPalindrome(string: string)
return string + reversed.prefix(string.count - longestPalindrome.count)
}
func longestPalindrome(string: String) -> String {
var longestPalindrome = ""
for i in 0..<string.count {
for j in i..<string.count {
let substring = String(string[i..<j])
if substring == substring.reversed() && substring.count > longestPalindrome.count {
longestPalindrome = substring
}
}
}
return longestPalindrome
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
Answer:
```swift
func makePalindrome(string: String) -> String {
let reversed = String(string.reversed())
let longestPalindrome = longestPalindrome(string: string)
return string + reversed.prefix(string.count - longestPalindrome.count)
}
func longestPalindrome(string: String) -> String {
var longestPalindrome = ""
for i in 0..<string.count {
for j in i..<string.count {
let substring = String(string[i..<j])
if substring == substring.reversed() && substring.count > longestPalindrome.count {
longestPalindrome = substring
}
}
}
return longestPalindrome
}
```let substring = String(string[i..<j]) // 'subscript(_:)' is unavailable: cannot subscript String with an integer range, use a String.Index range instead.if substring == substring.reversed() && substring.count > longestPalindrome.count { // cannot convert value of type 'ReversedCollection<String>' to expected argument type 'String'func makePalindrome(string: String) -> String {
let reversed = String(string.reversed())
let longestPalindrome = longestPalindrome(string: string)
let prefix = String(string.prefix(while: {!$0.isPalindrome }))
return prefix + reversed
}
func longestPalindrome(string: String) -> String {
var longestPalindrome = ""
for i in 0..<string.count {
let substring = String(string[string.index(string.startIndex, offsetBy: i)..<string.index(string.startIndex, offsetBy: string.count - i)])
if substring.isPalindrome && substring.count > longestPalindrome.count {
longestPalindrome = substring
}
}
return longestPalindrome
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
Answer:
```swift
func makePalindrome(string: String) -> String {
let reversed = String(string.reversed())
let longestPalindrome = longestPalindrome(string: string)
let prefix = String(string.prefix(while: {!$0.isPalindrome }))
return prefix + reversed
}
func longestPalindrome(string: String) -> String {
var longestPalindrome = ""
for i in 0..<string.count {
let substring = String(string[string.index(string.startIndex, offsetBy: i)..<string.index(string.startIndex, offsetBy: string.count - i)])
if substring.isPalindrome && substring.count > longestPalindrome.count {
longestPalindrome = substring
}
}
return longestPalindrome
}
```let prefix = String(string.prefix(while: {!$0.isPalindrome })) // value of type 'String.Element' (aka 'Character') has no member 'isPalindrome'if substring.isPalindrome && substring.count > longestPalindrome.count { // value of type 'String' has no member 'isPalindrome'func makePalindrome(string: String) -> String {
let reversed = String(string.reversed())
let longestPalindrome = longestPalindrome(string: string)
let prefix = String(string.prefix(upTo: string.index(string.startIndex, offsetBy: string.count - longestPalindrome.count)))
return prefix + reversed
}
func longestPalindrome(string: String) -> String {
var longestPalindrome = ""
for i in 0..<string.count {
for j in i..<string.count {
let substring = String(string[i..<j])
if substring == substring.reversed() && substring.count > longestPalindrome.count {
longestPalindrome = substring
}
}
}
return longestPalindrome
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
Answer:
```swift
func makePalindrome(string: String) -> String {
let reversed = String(string.reversed())
let longestPalindrome = longestPalindrome(string: string)
let prefix = String(string.prefix(upTo: string.index(string.startIndex, offsetBy: string.count - longestPalindrome.count)))
return prefix + reversed
}
func longestPalindrome(string: String) -> String {
var longestPalindrome = ""
for i in 0..<string.count {
for j in i..<string.count {
let substring = String(string[i..<j])
if substring == substring.reversed() && substring.count > longestPalindrome.count {
longestPalindrome = substring
}
}
}
return longestPalindrome
}
```let substring = String(string[i..<j]) // 'subscript(_:)' is unavailable: cannot subscript String with an integer range, use a String.Index range instead.if substring == substring.reversed() && substring.count > longestPalindrome.count { // cannot convert value of type 'ReversedCollection<String>' to expected argument type 'String'func makePalindrome(string: String) -> String {
let reversedString = String(string.reversed())
let longestPalindrome = longestPalindrome(string: string)
let prefix = String(string.prefix(upTo: string.count - longestPalindrome.count))
return prefix + reversedString
}
func longestPalindrome(string: String) -> String {
var longestPalindrome = ""
for i in 0..<string.count {
for j in i..<string.count {
let substring = String(string[i..<j])
if substring == substring.reversed() && substring.count > longestPalindrome.count {
longestPalindrome = substring
}
}
}
return longestPalindrome
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
Answer:
```swift
func makePalindrome(string: String) -> String {
let reversedString = String(string.reversed())
let longestPalindrome = longestPalindrome(string: string)
let prefix = String(string.prefix(upTo: string.count - longestPalindrome.count))
return prefix + reversedString
}
func longestPalindrome(string: String) -> String {
var longestPalindrome = ""
for i in 0..<string.count {
for j in i..<string.count {
let substring = String(string[i..<j])
if substring == substring.reversed() && substring.count > longestPalindrome.count {
longestPalindrome = substring
}
}
}
return longestPalindrome
}
```let prefix = String(string.prefix(upTo: string.count - longestPalindrome.count)) // cannot convert value of type 'Int' to expected argument type 'String.Index'let substring = String(string[i..<j]) // 'subscript(_:)' is unavailable: cannot subscript String with an integer range, use a String.Index range instead.if substring == substring.reversed() && substring.count > longestPalindrome.count { // cannot convert value of type 'ReversedCollection<String>' to expected argument type 'String'func makePalindrome(string: String) -> String {
let reversed = String(string.reversed())
let longestPalindrome = longestPalindrome(string: string)
let prefix = string.prefix(upTo: string.index(before: longestPalindrome.startIndex))
return prefix + reversed
}
func longestPalindrome(string: String) -> String {
var longestPalindrome = ""
for i in 0..<string.count {
for j in i..<string.count {
let substring = String(string[i..<j])
if substring == substring.reversed() && substring.count > longestPalindrome.count {
longestPalindrome = substring
}
}
}
return longestPalindrome
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
Answer:
```swift
func makePalindrome(string: String) -> String {
let reversed = String(string.reversed())
let longestPalindrome = longestPalindrome(string: string)
let prefix = string.prefix(upTo: string.index(before: longestPalindrome.startIndex))
return prefix + reversed
}
func longestPalindrome(string: String) -> String {
var longestPalindrome = ""
for i in 0..<string.count {
for j in i..<string.count {
let substring = String(string[i..<j])
if substring == substring.reversed() && substring.count > longestPalindrome.count {
longestPalindrome = substring
}
}
}
return longestPalindrome
}
```let substring = String(string[i..<j]) // 'subscript(_:)' is unavailable: cannot subscript String with an integer range, use a String.Index range instead.if substring == substring.reversed() && substring.count > longestPalindrome.count { // cannot convert value of type 'ReversedCollection<String>' to expected argument type 'String'func makePalindrome(string: String) -> String {
let reversed = String(string.reversed())
let longestPalindrome = longestPalindrome(string: string)
let prefix = String(string.prefix(upTo: string.index(before: string.endIndex)))
return prefix + reversed
}
func longestPalindrome(string: String) -> String {
var longestPalindrome = ""
for i in 0..<string.count {
let substring = String(string[string.index(string.startIndex, offsetBy: i)..<string.index(string.startIndex, offsetBy: string.count - i)])
if isPalindrome(string: substring) && substring.count > longestPalindrome.count {
longestPalindrome = substring
}
}
return longestPalindrome
}
func isPalindrome(string: String) -> Bool {
let reversed = String(string.reversed())
return string == reversed
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
Answer:
```swift
func makePalindrome(string: String) -> String {
let reversed = String(string.reversed())
let longestPalindrome = longestPalindrome(string: string)
let prefix = String(string.prefix(upTo: string.index(before: string.endIndex)))
return prefix + reversed
}
func longestPalindrome(string: String) -> String {
var longestPalindrome = ""
for i in 0..<string.count {
let substring = String(string[string.index(string.startIndex, offsetBy: i)..<string.index(string.startIndex, offsetBy: string.count - i)])
if isPalindrome(string: substring) && substring.count > longestPalindrome.count {
longestPalindrome = substring
}
}
return longestPalindrome
}
func isPalindrome(string: String) -> Bool {
let reversed = String(string.reversed())
return string == reversed
}
```let longestPalindrome = longestPalindrome(string: string) // initialization of immutable value 'longestPalindrome' was never used; consider replacing with assignment to '_' or removing it // Fatal error: String index is out of boundsfunc makePalindrome(string: String) -> String {
let reversed = String(string.reversed())
let longestPalindrome = longestPalindrome(string: string)
let prefix = String(string.prefix(upTo: string.index(string.startIndex, offsetBy: string.count - longestPalindrome.count)))
return prefix + reversed
}
func longestPalindrome(string: String) -> String {
var longestPalindrome = ""
for i in 0..<string.count {
for j in i..<string.count {
let substring = String(string[i..<j])
if substring == substring.reversed() && substring.count > longestPalindrome.count {
longestPalindrome = substring
}
}
}
return longestPalindrome
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
Answer:
```swift
func makePalindrome(string: String) -> String {
let reversed = String(string.reversed())
let longestPalindrome = longestPalindrome(string: string)
let prefix = String(string.prefix(upTo: string.index(string.startIndex, offsetBy: string.count - longestPalindrome.count)))
return prefix + reversed
}
func longestPalindrome(string: String) -> String {
var longestPalindrome = ""
for i in 0..<string.count {
for j in i..<string.count {
let substring = String(string[i..<j])
if substring == substring.reversed() && substring.count > longestPalindrome.count {
longestPalindrome = substring
}
}
}
return longestPalindrome
}
```let substring = String(string[i..<j]) // 'subscript(_:)' is unavailable: cannot subscript String with an integer range, use a String.Index range instead.if substring == substring.reversed() && substring.count > longestPalindrome.count { // cannot convert value of type 'ReversedCollection<String>' to expected argument type 'String'func makePalindrome(string: String) -> String {
let reversed = String(string.reversed())
let longestPalindrome = longestPalindrome(string: string)
return string + reversed.prefix(longestPalindrome.count)
}
func longestPalindrome(string: String) -> String {
var longestPalindrome = ""
for i in 0..<string.count {
for j in i..<string.count {
let substring = String(string[i..<j])
if substring == substring.reversed() && substring.count > longestPalindrome.count {
longestPalindrome = substring
}
}
}
return longestPalindrome
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
Answer:
```swift
func makePalindrome(string: String) -> String {
let reversed = String(string.reversed())
let longestPalindrome = longestPalindrome(string: string)
return string + reversed.prefix(longestPalindrome.count)
}
func longestPalindrome(string: String) -> String {
var longestPalindrome = ""
for i in 0..<string.count {
for j in i..<string.count {
let substring = String(string[i..<j])
if substring == substring.reversed() && substring.count > longestPalindrome.count {
longestPalindrome = substring
}
}
}
return longestPalindrome
}
```let substring = String(string[i..<j]) // 'subscript(_:)' is unavailable: cannot subscript String with an integer range, use a String.Index range instead.if substring == substring.reversed() && substring.count > longestPalindrome.count { // cannot convert value of type 'ReversedCollection<String>' to expected argument type 'String'func makePalindrome(string: String) -> String {
let reversed = String(string.reversed())
let longestPalindrome = longestPalindrome(string: string)
return string + reversed.prefix(string.count - longestPalindrome.count)
}
func longestPalindrome(string: String) -> String {
var longestPalindrome = ""
for i in 0..<string.count {
for j in i..<string.count {
let substring = String(string[i..<j])
if substring == substring.reversed() && substring.count > longestPalindrome.count {
longestPalindrome = substring
}
}
}
return longestPalindrome
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
Answer:
```swift
func makePalindrome(string: String) -> String {
let reversed = String(string.reversed())
let longestPalindrome = longestPalindrome(string: string)
return string + reversed.prefix(string.count - longestPalindrome.count)
}
func longestPalindrome(string: String) -> String {
var longestPalindrome = ""
for i in 0..<string.count {
for j in i..<string.count {
let substring = String(string[i..<j])
if substring == substring.reversed() && substring.count > longestPalindrome.count {
longestPalindrome = substring
}
}
}
return longestPalindrome
}
```let substring = String(string[i..<j]) // 'subscript(_:)' is unavailable: cannot subscript String with an integer range, use a String.Index range instead.if substring == substring.reversed() && substring.count > longestPalindrome.count { // cannot convert value of type 'ReversedCollection<String>' to expected argument type 'String'func stringXor(a: String, b: String) -> String {
let aChars = a.characters.map { String(format: "%04b", $0.value) }
let bChars = b.characters.map { String(format: "%04b", $0.value) }
let resultChars = aChars.enumerated().map { (index, aChar) in
let bChar = bChars[index]
let result = aChar.binaryXOR(bChar)
return String(format: "%04b", result)
}
return String(resultChars)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
Answer:
```swift
func stringXor(a: String, b: String) -> String {
let aChars = a.characters.map { String(format: "%04b", $0.value) }
let bChars = b.characters.map { String(format: "%04b", $0.value) }
let resultChars = aChars.enumerated().map { (index, aChar) in
let bChar = bChars[index]
let result = aChar.binaryXOR(bChar)
return String(format: "%04b", result)
}
return String(resultChars)
}
```let aChars = a.characters.map { String(format: "%04b", $0.value) } // value of type 'String.Element' (aka 'Character') has no member 'value'let bChars = b.characters.map { String(format: "%04b", $0.value) } // value of type 'String.Element' (aka 'Character') has no member 'value'func stringXor(a: String, b: String) -> String {
let aAsBits = a.map { String(format: "%04b", $0) }
let bAsBits = b.map { String(format: "%04b", $0) }
let result = aAsBits.enumerated().map { index, bit in
let aBit = bit == "1"? 1 : 0
let bBit = bAsBits[index] == "1"? 1 : 0
return (aBit ^ bBit).description
}
return result.joined()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
Answer:
```swift
func stringXor(a: String, b: String) -> String {
let aAsBits = a.map { String(format: "%04b", $0) }
let bAsBits = b.map { String(format: "%04b", $0) }
let result = aAsBits.enumerated().map { index, bit in
let aBit = bit == "1"? 1 : 0
let bBit = bAsBits[index] == "1"? 1 : 0
return (aBit ^ bBit).description
}
return result.joined()
}
```let aAsBits = a.map { String(format: "%04b", $0) } // argument type 'String.Element' (aka 'Character') does not conform to expected type 'CVarArg'let bAsBits = b.map { String(format: "%04b", $0) } // argument type 'String.Element' (aka 'Character') does not conform to expected type 'CVarArg'let aBit = bit == "1"? 1 : 0 // consecutive statements on a line must be separated by ';'let aBit = bit == "1"? 1 : 0 // cannot use optional chaining on non-optional value of type 'String'let aBit = bit == "1"? 1 : 0 // consecutive statements on a line must be separated by ';'let aBit = bit == "1"? 1 : 0 // expected expressionlet bBit = bAsBits[index] == "1"? 1 : 0 // consecutive statements on a line must be separated by ';'let bBit = bAsBits[index] == "1"? 1 : 0 // expected expressionlet bBit = bAsBits[index] == "1"? 1 : 0 // consecutive statements on a line must be separated by ';'func stringXor(a: String, b: String) -> String {
let aAsBits = a.map { String(format: "%04b", $0) }
let bAsBits = b.map { String(format: "%04b", $0) }
let result = aAsBits.enumerated().map { index, bit in
bit == "1"? bAsBits[index] == "1"? "0" : "1" : bAsBits[index]
}
return result.joined()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
Answer:
```swift
func stringXor(a: String, b: String) -> String {
let aAsBits = a.map { String(format: "%04b", $0) }
let bAsBits = b.map { String(format: "%04b", $0) }
let result = aAsBits.enumerated().map { index, bit in
bit == "1"? bAsBits[index] == "1"? "0" : "1" : bAsBits[index]
}
return result.joined()
}
```let aAsBits = a.map { String(format: "%04b", $0) } // argument type 'String.Element' (aka 'Character') does not conform to expected type 'CVarArg'let bAsBits = b.map { String(format: "%04b", $0) } // argument type 'String.Element' (aka 'Character') does not conform to expected type 'CVarArg'bit == "1"? bAsBits[index] == "1"? "0" : "1" : bAsBits[index] // cannot use optional chaining on non-optional value of type 'String'bit == "1"? bAsBits[index] == "1"? "0" : "1" : bAsBits[index] // consecutive statements on a line must be separated by ';'bit == "1"? bAsBits[index] == "1"? "0" : "1" : bAsBits[index] // expected expressionbit == "1"? bAsBits[index] == "1"? "0" : "1" : bAsBits[index] // consecutive statements on a line must be separated by ';'bit == "1"? bAsBits[index] == "1"? "0" : "1" : bAsBits[index] // consecutive statements on a line must be separated by ';'func stringXor(a: String, b: String) -> String {
let aInt = a.reduce(0) { $0 * 2 + Int(String($1), radix: 2)! }
let bInt = b.reduce(0) { $0 * 2 + Int(String($1), radix: 2)! }
let resultInt = aInt ^ bInt
let resultString = String(resultInt, radix: 2)
return resultString
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
Answer:
```swift
func stringXor(a: String, b: String) -> String {
let aInt = a.reduce(0) { $0 * 2 + Int(String($1), radix: 2)! }
let bInt = b.reduce(0) { $0 * 2 + Int(String($1), radix: 2)! }
let resultInt = aInt ^ bInt
let resultString = String(resultInt, radix: 2)
return resultString
}
``` // XCTAssertTrue failedfunc stringXor(a: String, b: String) -> String {
let aChars = Array(a.characters)
let bChars = Array(b.characters)
guard aChars.count == bChars.count else {
return ""
}
var resultChars = [Character]()
for i in 0..<aChars.count {
let aChar = aChars[i]
let bChar = bChars[i]
let xorResult = Character(aChar.unicodeScalars.first! ^ bChar.unicodeScalars.first!)
resultChars.append(xorResult)
}
return String(resultChars)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
Answer:
```swift
func stringXor(a: String, b: String) -> String {
let aChars = Array(a.characters)
let bChars = Array(b.characters)
guard aChars.count == bChars.count else {
return ""
}
var resultChars = [Character]()
for i in 0..<aChars.count {
let aChar = aChars[i]
let bChar = bChars[i]
let xorResult = Character(aChar.unicodeScalars.first! ^ bChar.unicodeScalars.first!)
resultChars.append(xorResult)
}
return String(resultChars)
}
```let aChars = Array(a.characters) // 'characters' is unavailable: Please use String directlylet bChars = Array(b.characters) // 'characters' is unavailable: Please use String directlylet xorResult = Character(aChar.unicodeScalars.first! ^ bChar.unicodeScalars.first!) // binary operator '^' cannot be applied to two 'String.UnicodeScalarView.Element' (aka 'Unicode.Scalar') operandsfunc stringXor(a: String, b: String) -> String {
let aAsBits = a.map { String(format: "%04b", $0) }
let bAsBits = b.map { String(format: "%04b", $0) }
let result = aAsBits.enumerated().map { (index, bit) in
let aBit = bit
let bBit = bAsBits[index]
let resultBit = aBit == "1"? (bBit == "1"? "0" : "1") : (bBit == "1"? "1" : "0")
return String(format: "%04b", resultBit)
}
return result.joined()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
Answer:
```swift
func stringXor(a: String, b: String) -> String {
let aAsBits = a.map { String(format: "%04b", $0) }
let bAsBits = b.map { String(format: "%04b", $0) }
let result = aAsBits.enumerated().map { (index, bit) in
let aBit = bit
let bBit = bAsBits[index]
let resultBit = aBit == "1"? (bBit == "1"? "0" : "1") : (bBit == "1"? "1" : "0")
return String(format: "%04b", resultBit)
}
return result.joined()
}
```let aAsBits = a.map { String(format: "%04b", $0) } // argument type 'String.Element' (aka 'Character') does not conform to expected type 'CVarArg'let bAsBits = b.map { String(format: "%04b", $0) } // argument type 'String.Element' (aka 'Character') does not conform to expected type 'CVarArg'let resultBit = aBit == "1"? (bBit == "1"? "0" : "1") : (bBit == "1"? "1" : "0") // consecutive statements on a line must be separated by ';'let resultBit = aBit == "1"? (bBit == "1"? "0" : "1") : (bBit == "1"? "1" : "0") // expected ',' separatorlet resultBit = aBit == "1"? (bBit == "1"? "0" : "1") : (bBit == "1"? "1" : "0") // expected expressionfunc stringXor(a: String, b: String) -> String {
let aAsBits = a.map { String($0) }
let bAsBits = b.map { String($0) }
let result = aAsBits.enumerated().map { index, bit in
let aBit = bit == "1"? 1 : 0
let bBit = bAsBits[index] == "1"? 1 : 0
return (aBit ^ bBit) == 1? "1" : "0"
}
return result.joined()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
Answer:
```swift
func stringXor(a: String, b: String) -> String {
let aAsBits = a.map { String($0) }
let bAsBits = b.map { String($0) }
let result = aAsBits.enumerated().map { index, bit in
let aBit = bit == "1"? 1 : 0
let bBit = bAsBits[index] == "1"? 1 : 0
return (aBit ^ bBit) == 1? "1" : "0"
}
return result.joined()
}
```let aBit = bit == "1"? 1 : 0 // consecutive statements on a line must be separated by ';'let aBit = bit == "1"? 1 : 0 // cannot use optional chaining on non-optional value of type 'String'let aBit = bit == "1"? 1 : 0 // consecutive statements on a line must be separated by ';'let aBit = bit == "1"? 1 : 0 // expected expressionlet bBit = bAsBits[index] == "1"? 1 : 0 // consecutive statements on a line must be separated by ';'let bBit = bAsBits[index] == "1"? 1 : 0 // expected expressionlet bBit = bAsBits[index] == "1"? 1 : 0 // consecutive statements on a line must be separated by ';'return (aBit ^ bBit) == 1? "1" : "0" // expected expressionreturn (aBit ^ bBit) == 1? "1" : "0" // consecutive statements on a line must be separated by ';'return (aBit ^ bBit) == 1? "1" : "0" // consecutive statements on a line must be separated by ';'func stringXor(a: String, b: String) -> String {
let aChars = a.characters.map { String(format: "%04b", $0.value) }
let bChars = b.characters.map { String(format: "%04b", $0.value) }
var resultChars = [Character]()
for i in 0..<aChars.count {
let aChar = aChars[i]
let bChar = bChars[i]
let aInt = Int(aChar, radix: 2)!
let bInt = Int(bChar, radix: 2)!
let resultInt = aInt ^ bInt
let resultChar = String(format: "%04b", resultInt)
resultChars.append(Character(resultChar))
}
return String(resultChars)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
Answer:
```swift
func stringXor(a: String, b: String) -> String {
let aChars = a.characters.map { String(format: "%04b", $0.value) }
let bChars = b.characters.map { String(format: "%04b", $0.value) }
var resultChars = [Character]()
for i in 0..<aChars.count {
let aChar = aChars[i]
let bChar = bChars[i]
let aInt = Int(aChar, radix: 2)!
let bInt = Int(bChar, radix: 2)!
let resultInt = aInt ^ bInt
let resultChar = String(format: "%04b", resultInt)
resultChars.append(Character(resultChar))
}
return String(resultChars)
}
```let aChars = a.characters.map { String(format: "%04b", $0.value) } // value of type 'String.Element' (aka 'Character') has no member 'value'let bChars = b.characters.map { String(format: "%04b", $0.value) } // value of type 'String.Element' (aka 'Character') has no member 'value'func stringXor(a: String, b: String) -> String {
let aBinary = a.map { String(format: "%04b", $0) }
let bBinary = b.map { String(format: "%04b", $0) }
let resultBinary = aBinary.enumerated().map { index, value in
let aBit = value.first?? "0"
let bBit = bBinary[index].first?? "0"
return String(format: "%04b", Int(aBit) ^ Int(bBit))
}
return resultBinary.joined()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
Answer:
```swift
func stringXor(a: String, b: String) -> String {
let aBinary = a.map { String(format: "%04b", $0) }
let bBinary = b.map { String(format: "%04b", $0) }
let resultBinary = aBinary.enumerated().map { index, value in
let aBit = value.first?? "0"
let bBit = bBinary[index].first?? "0"
return String(format: "%04b", Int(aBit) ^ Int(bBit))
}
return resultBinary.joined()
}
```let aBinary = a.map { String(format: "%04b", $0) } // argument type 'String.Element' (aka 'Character') does not conform to expected type 'CVarArg'let bBinary = b.map { String(format: "%04b", $0) } // argument type 'String.Element' (aka 'Character') does not conform to expected type 'CVarArg'let resultBinary = aBinary.enumerated().map { index, value in // type of expression is ambiguous without a type annotationlet aBit = value.first?? "0" // consecutive statements on a line must be separated by ';'let bBit = bBinary[index].first?? "0" // consecutive statements on a line must be separated by ';'func stringXor(a: String, b: String) -> String {
let aBinary = a.map { String(format: "%08b", $0) }
let bBinary = b.map { String(format: "%08b", $0) }
let resultBinary = aBinary.enumerated().map { index, value in
let bit = value.bit(at: index)
return bit == 1? "0" : "1"
}
return String(format: "%08b", resultBinary.reduce(0, +))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
Answer:
```swift
func stringXor(a: String, b: String) -> String {
let aBinary = a.map { String(format: "%08b", $0) }
let bBinary = b.map { String(format: "%08b", $0) }
let resultBinary = aBinary.enumerated().map { index, value in
let bit = value.bit(at: index)
return bit == 1? "0" : "1"
}
return String(format: "%08b", resultBinary.reduce(0, +))
}
```let aBinary = a.map { String(format: "%08b", $0) } // argument type 'String.Element' (aka 'Character') does not conform to expected type 'CVarArg'let bBinary = b.map { String(format: "%08b", $0) } // argument type 'String.Element' (aka 'Character') does not conform to expected type 'CVarArg'return bit == 1? "0" : "1" // cannot use optional chaining on non-optional value of type 'Int'return bit == 1? "0" : "1" // expected expressionreturn bit == 1? "0" : "1" // consecutive statements on a line must be separated by ';'return bit == 1? "0" : "1" // consecutive statements on a line must be separated by ';'func longest(strings: [String]) -> String? {
guard!strings.isEmpty else {
return nil
}
var longestString: String?
var maxLength = 0
for string in strings {
let length = string.count
if length > maxLength {
maxLength = length
longestString = string
}
}
return longestString
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
Answer:
```swift
func longest(strings: [String]) -> String? {
guard!strings.isEmpty else {
return nil
}
var longestString: String?
var maxLength = 0
for string in strings {
let length = string.count
if length > maxLength {
maxLength = length
longestString = string
}
}
return longestString
}
```guard!strings.isEmpty else { // expected expression, var, let or case in 'guard' conditionfunc longest(strings: [String]) -> String? {
guard!strings.isEmpty else {
return nil
}
var longestString = strings.first
var maxLength = longestString?.count?? 0
for string in strings {
if string.count > maxLength {
maxLength = string.count
longestString = string
}
}
return longestString
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
Answer:
```swift
func longest(strings: [String]) -> String? {
guard!strings.isEmpty else {
return nil
}
var longestString = strings.first
var maxLength = longestString?.count?? 0
for string in strings {
if string.count > maxLength {
maxLength = string.count
longestString = string
}
}
return longestString
}
```guard!strings.isEmpty else { // expected expression, var, let or case in 'guard' conditionvar maxLength = longestString?.count?? 0 // cannot use optional chaining on non-optional value of type 'Int'var maxLength = longestString?.count?? 0 // integer literal is unusedvar maxLength = longestString?.count?? 0 // cannot use optional chaining on non-optional value of type 'Int'var maxLength = longestString?.count?? 0 // consecutive statements on a line must be separated by ';'func longest(strings: [String]) -> String? {
guard!strings.isEmpty else {
return nil
}
return strings.sorted { $0.count > $1.count }.first
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
Answer:
```swift
func longest(strings: [String]) -> String? {
guard!strings.isEmpty else {
return nil
}
return strings.sorted { $0.count > $1.count }.first
}
```guard!strings.isEmpty else { // expected expression, var, let or case in 'guard' conditionfunc longest(strings: [String]) -> String? {
guard!strings.isEmpty else {
return nil
}
var longestString = strings.first
var maxLength = longestString?.count?? 0
for string in strings {
if string.count > maxLength {
maxLength = string.count
longestString = string
}
}
return longestString
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
Answer:
```swift
func longest(strings: [String]) -> String? {
guard!strings.isEmpty else {
return nil
}
var longestString = strings.first
var maxLength = longestString?.count?? 0
for string in strings {
if string.count > maxLength {
maxLength = string.count
longestString = string
}
}
return longestString
}
```guard!strings.isEmpty else { // expected expression, var, let or case in 'guard' conditionvar maxLength = longestString?.count?? 0 // cannot use optional chaining on non-optional value of type 'Int'var maxLength = longestString?.count?? 0 // integer literal is unusedvar maxLength = longestString?.count?? 0 // cannot use optional chaining on non-optional value of type 'Int'var maxLength = longestString?.count?? 0 // consecutive statements on a line must be separated by ';'func longest(strings: [String]) -> String? {
guard!strings.isEmpty else {
return nil
}
var longestString = strings[0]
var maxLength = longestString.count
for string in strings {
if string.count > maxLength {
maxLength = string.count
longestString = string
}
}
return longestString
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
Answer:
```swift
func longest(strings: [String]) -> String? {
guard!strings.isEmpty else {
return nil
}
var longestString = strings[0]
var maxLength = longestString.count
for string in strings {
if string.count > maxLength {
maxLength = string.count
longestString = string
}
}
return longestString
}
```guard!strings.isEmpty else { // expected expression, var, let or case in 'guard' conditionfunc longest(strings: [String]) -> String? {
guard!strings.isEmpty else {
return nil
}
var longestString: String?
for string in strings {
if longestString == nil || string.count > longestString!.count {
longestString = string
}
}
return longestString
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
Answer:
```swift
func longest(strings: [String]) -> String? {
guard!strings.isEmpty else {
return nil
}
var longestString: String?
for string in strings {
if longestString == nil || string.count > longestString!.count {
longestString = string
}
}
return longestString
}
```guard!strings.isEmpty else { // expected expression, var, let or case in 'guard' conditionfunc longest(strings: [String]) -> String? {
guard!strings.isEmpty else {
return nil
}
return strings.sorted { $0.count > $1.count }.first
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
Answer:
```swift
func longest(strings: [String]) -> String? {
guard!strings.isEmpty else {
return nil
}
return strings.sorted { $0.count > $1.count }.first
}
```guard!strings.isEmpty else { // expected expression, var, let or case in 'guard' conditionfunc longest(strings: [String]) -> String? {
guard!strings.isEmpty else {
return nil
}
return strings.sorted { $0.count > $1.count }.first
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
Answer:
```swift
func longest(strings: [String]) -> String? {
guard!strings.isEmpty else {
return nil
}
return strings.sorted { $0.count > $1.count }.first
}
```guard!strings.isEmpty else { // expected expression, var, let or case in 'guard' conditionfunc longest(strings: [String]) -> String? {
guard!strings.isEmpty else {
return nil
}
var longestString: String?
for string in strings {
if longestString == nil || string.count > longestString!.count {
longestString = string
}
}
return longestString
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
Answer:
```swift
func longest(strings: [String]) -> String? {
guard!strings.isEmpty else {
return nil
}
var longestString: String?
for string in strings {
if longestString == nil || string.count > longestString!.count {
longestString = string
}
}
return longestString
}
```guard!strings.isEmpty else { // expected expression, var, let or case in 'guard' conditionfunc longest(strings: [String]) -> String? {
guard!strings.isEmpty else {
return nil
}
var longestString: String?
for string in strings {
if longestString == nil || string.count > longestString!.count {
longestString = string
}
}
return longestString
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
Answer:
```swift
func longest(strings: [String]) -> String? {
guard!strings.isEmpty else {
return nil
}
var longestString: String?
for string in strings {
if longestString == nil || string.count > longestString!.count {
longestString = string
}
}
return longestString
}
```guard!strings.isEmpty else { // expected expression, var, let or case in 'guard' conditionfunc greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b!= 0 {
let remainder = a % b
a = b
b = remainder
}
return a
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b!= 0 {
let remainder = a % b
a = b
b = remainder
}
return a
}
```while b!= 0 { // cannot force unwrap value of non-optional type 'Int'while b!= 0 { // use of '=' in a boolean context, did you mean '=='?while b!= 0 { // '=' must have consistent whitespace on both sidesfunc greatestCommonDivisor(a: Int, b: Int) -> Int {
if a == 0 {
return b
}
if b == 0 {
return a
}
if a == b {
return a
}
if a > b {
return greatestCommonDivisor(a: a - b, b: b)
} else {
return greatestCommonDivisor(a: b - a, b: a)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
if a == 0 {
return b
}
if b == 0 {
return a
}
if a == b {
return a
}
if a > b {
return greatestCommonDivisor(a: a - b, b: b)
} else {
return greatestCommonDivisor(a: b - a, b: a)
}
}
```func greatestCommonDivisor(a: Int, b: Int) -> Int {
if a == 0 {
return b
}
if b == 0 {
return a
}
if a == b {
return a
}
if a > b {
return greatestCommonDivisor(a: a - b, b: b)
}
return greatestCommonDivisor(a: b - a, b: a)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
if a == 0 {
return b
}
if b == 0 {
return a
}
if a == b {
return a
}
if a > b {
return greatestCommonDivisor(a: a - b, b: b)
}
return greatestCommonDivisor(a: b - a, b: a)
}
```func greatestCommonDivisor(a: Int, b: Int) -> Int {
if a == 0 {
return b
}
if b == 0 {
return a
}
if a == b {
return a
}
if a > b {
return greatestCommonDivisor(a: a - b, b: b)
} else {
return greatestCommonDivisor(a: b - a, b: a)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
if a == 0 {
return b
}
if b == 0 {
return a
}
if a == b {
return a
}
if a > b {
return greatestCommonDivisor(a: a - b, b: b)
} else {
return greatestCommonDivisor(a: b - a, b: a)
}
}
```func greatestCommonDivisor(a: Int, b: Int) -> Int {
if a == 0 {
return b
}
if b == 0 {
return a
}
if a == b {
return a
}
if a > b {
return greatestCommonDivisor(a: a - b, b: b)
}
return greatestCommonDivisor(a: b - a, b: a)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
if a == 0 {
return b
}
if b == 0 {
return a
}
if a == b {
return a
}
if a > b {
return greatestCommonDivisor(a: a - b, b: b)
}
return greatestCommonDivisor(a: b - a, b: a)
}
```func greatestCommonDivisor(a: Int, b: Int) -> Int {
if b == 0 {
return a
}
return greatestCommonDivisor(a: b, b: a % b)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
if b == 0 {
return a
}
return greatestCommonDivisor(a: b, b: a % b)
}
```func greatestCommonDivisor(a: Int, b: Int) -> Int {
if a == 0 {
return b
}
if b == 0 {
return a
}
if a > b {
return greatestCommonDivisor(a: a - b, b: b)
}
return greatestCommonDivisor(a: b - a, b: a)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
if a == 0 {
return b
}
if b == 0 {
return a
}
if a > b {
return greatestCommonDivisor(a: a - b, b: b)
}
return greatestCommonDivisor(a: b - a, b: a)
}
```func greatestCommonDivisor(a: Int, b: Int) -> Int {
if a == 0 {
return b
}
if b == 0 {
return a
}
if a == b {
return a
}
if a > b {
return greatestCommonDivisor(a: a - b, b: b)
} else {
return greatestCommonDivisor(a: b - a, b: a)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
if a == 0 {
return b
}
if b == 0 {
return a
}
if a == b {
return a
}
if a > b {
return greatestCommonDivisor(a: a - b, b: b)
} else {
return greatestCommonDivisor(a: b - a, b: a)
}
}
```func greatestCommonDivisor(a: Int, b: Int) -> Int {
if a == 0 {
return b
}
if b == 0 {
return a
}
if a == b {
return a
}
if a > b {
return greatestCommonDivisor(a: a - b, b: b)
}
return greatestCommonDivisor(a: b - a, b: a)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
if a == 0 {
return b
}
if b == 0 {
return a
}
if a == b {
return a
}
if a > b {
return greatestCommonDivisor(a: a - b, b: b)
}
return greatestCommonDivisor(a: b - a, b: a)
}
```func greatestCommonDivisor(a: Int, b: Int) -> Int {
if a == 0 {
return b
}
if b == 0 {
return a
}
if a == b {
return a
}
if a > b {
return greatestCommonDivisor(a: a - b, b: b)
} else {
return greatestCommonDivisor(a: b - a, b: a)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
if a == 0 {
return b
}
if b == 0 {
return a
}
if a == b {
return a
}
if a > b {
return greatestCommonDivisor(a: a - b, b: b)
} else {
return greatestCommonDivisor(a: b - a, b: a)
}
}
```func allPrefixes(string: String) -> [String] {
var prefixes = [String]()
for i in 0..<string.count {
let prefix = String(string[0..<i])
prefixes.append(prefix)
}
return prefixes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
Answer:
```swift
func allPrefixes(string: String) -> [String] {
var prefixes = [String]()
for i in 0..<string.count {
let prefix = String(string[0..<i])
prefixes.append(prefix)
}
return prefixes
}
```let prefix = String(string[0..<i]) // 'subscript(_:)' is unavailable: cannot subscript String with an integer range, use a String.Index range instead.func allPrefixes(string: String) -> [String] {
var prefixes: [String] = []
var currentPrefix: String = ""
for character in string {
currentPrefix.append(character)
prefixes.append(currentPrefix)
currentPrefix = currentPrefix.dropLast()
}
return prefixes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
Answer:
```swift
func allPrefixes(string: String) -> [String] {
var prefixes: [String] = []
var currentPrefix: String = ""
for character in string {
currentPrefix.append(character)
prefixes.append(currentPrefix)
currentPrefix = currentPrefix.dropLast()
}
return prefixes
}
```currentPrefix = currentPrefix.dropLast() // no 'dropLast' candidates produce the expected contextual result type 'String'func allPrefixes(string: String) -> [String] {
var prefixes = [String]()
for i in 0..<string.count {
let prefix = String(string[0..<i])
prefixes.append(prefix)
}
return prefixes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
Answer:
```swift
func allPrefixes(string: String) -> [String] {
var prefixes = [String]()
for i in 0..<string.count {
let prefix = String(string[0..<i])
prefixes.append(prefix)
}
return prefixes
}
```let prefix = String(string[0..<i]) // 'subscript(_:)' is unavailable: cannot subscript String with an integer range, use a String.Index range instead.func allPrefixes(string: String) -> [String] {
var prefixes: [String] = []
for i in 0..<string.count {
let prefix = String(string.prefix(i))
prefixes.append(prefix)
}
return prefixes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
Answer:
```swift
func allPrefixes(string: String) -> [String] {
var prefixes: [String] = []
for i in 0..<string.count {
let prefix = String(string.prefix(i))
prefixes.append(prefix)
}
return prefixes
}
``` // XCTAssertTrue failedfunc allPrefixes(string: String) -> [String] {
var prefixes = [String]()
for i in 0..<string.count {
prefixes.append(String(string[0..<i]))
}
return prefixes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
Answer:
```swift
func allPrefixes(string: String) -> [String] {
var prefixes = [String]()
for i in 0..<string.count {
prefixes.append(String(string[0..<i]))
}
return prefixes
}
```prefixes.append(String(string[0..<i])) // 'subscript(_:)' is unavailable: cannot subscript String with an integer range, use a String.Index range instead.func allPrefixes(string: String) -> [String] {
var prefixes = [String]()
var currentPrefix = ""
for char in string {
currentPrefix.append(char)
prefixes.append(currentPrefix)
}
return prefixes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
Answer:
```swift
func allPrefixes(string: String) -> [String] {
var prefixes = [String]()
var currentPrefix = ""
for char in string {
currentPrefix.append(char)
prefixes.append(currentPrefix)
}
return prefixes
}
```func allPrefixes(string: String) -> [String] {
var prefixes = [String]()
for i in 0..<string.count {
let prefix = String(string.prefix(i))
prefixes.append(prefix)
}
return prefixes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
Answer:
```swift
func allPrefixes(string: String) -> [String] {
var prefixes = [String]()
for i in 0..<string.count {
let prefix = String(string.prefix(i))
prefixes.append(prefix)
}
return prefixes
}
``` // XCTAssertTrue failedfunc allPrefixes(string: String) -> [String] {
var prefixes = [String]()
for i in 0..<string.count {
prefixes.append(String(string[0..<i]))
}
return prefixes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
Answer:
```swift
func allPrefixes(string: String) -> [String] {
var prefixes = [String]()
for i in 0..<string.count {
prefixes.append(String(string[0..<i]))
}
return prefixes
}
```prefixes.append(String(string[0..<i])) // 'subscript(_:)' is unavailable: cannot subscript String with an integer range, use a String.Index range instead.func allPrefixes(string: String) -> [String] {
var prefixes = [String]()
for i in 0..<string.count {
prefixes.append(String(string[0..<i]))
}
return prefixes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
Answer:
```swift
func allPrefixes(string: String) -> [String] {
var prefixes = [String]()
for i in 0..<string.count {
prefixes.append(String(string[0..<i]))
}
return prefixes
}
```prefixes.append(String(string[0..<i])) // 'subscript(_:)' is unavailable: cannot subscript String with an integer range, use a String.Index range instead.func allPrefixes(string: String) -> [String] {
var prefixes = [String]()
for i in 0..<string.count {
let prefix = String(string.prefix(i))
prefixes.append(prefix)
}
return prefixes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
Answer:
```swift
func allPrefixes(string: String) -> [String] {
var prefixes = [String]()
for i in 0..<string.count {
let prefix = String(string.prefix(i))
prefixes.append(prefix)
}
return prefixes
}
``` // XCTAssertTrue failedfunc stringSequence(n: Int) -> String {
var result = ""
for i in 0...n {
result += "\(i) "
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
Answer:
```swift
func stringSequence(n: Int) -> String {
var result = ""
for i in 0...n {
result += "\(i) "
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
```func stringSequence(n: Int) -> String {
var result = ""
for i in 0...n {
result += "\(i) "
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
Answer:
```swift
func stringSequence(n: Int) -> String {
var result = ""
for i in 0...n {
result += "\(i) "
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
```func stringSequence(n: Int) -> String {
var result = ""
for i in 0...n {
result += "\(i) "
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
Answer:
```swift
func stringSequence(n: Int) -> String {
var result = ""
for i in 0...n {
result += "\(i) "
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
```func stringSequence(n: Int) -> String {
var result = ""
for i in 0...n {
result += "\(i) "
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
Answer:
```swift
func stringSequence(n: Int) -> String {
var result = ""
for i in 0...n {
result += "\(i) "
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
```func stringSequence(n: Int) -> String {
var result = ""
for i in 0...n {
result += "\(i) "
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
Answer:
```swift
func stringSequence(n: Int) -> String {
var result = ""
for i in 0...n {
result += "\(i) "
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
```func stringSequence(n: Int) -> String {
var result = ""
for i in 0...n {
result += "\(i) "
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
Answer:
```swift
func stringSequence(n: Int) -> String {
var result = ""
for i in 0...n {
result += "\(i) "
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
```func stringSequence(n: Int) -> String {
var result = ""
for i in 0...n {
result += "\(i) "
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
Answer:
```swift
func stringSequence(n: Int) -> String {
var result = ""
for i in 0...n {
result += "\(i) "
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
```func stringSequence(n: Int) -> String {
var result = ""
for i in 0...n {
result += "\(i) "
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
Answer:
```swift
func stringSequence(n: Int) -> String {
var result = ""
for i in 0...n {
result += "\(i) "
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
```func stringSequence(n: Int) -> String {
var result = ""
for i in 0...n {
result += "\(i) "
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
Answer:
```swift
func stringSequence(n: Int) -> String {
var result = ""
for i in 0...n {
result += "\(i) "
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
```func stringSequence(n: Int) -> String {
var result = ""
for i in 0...n {
result += "\(i) "
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
Answer:
```swift
func stringSequence(n: Int) -> String {
var result = ""
for i in 0...n {
result += "\(i) "
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
```func countDistinctCharacters(string: String) -> Int {
var distinctCharacters = Set<Character>()
for character in string {
distinctCharacters.insert(character.lowercased())
}
return distinctCharacters.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
var distinctCharacters = Set<Character>()
for character in string {
distinctCharacters.insert(character.lowercased())
}
return distinctCharacters.count
}
```distinctCharacters.insert(character.lowercased()) // cannot convert value of type 'String' to expected argument type 'Character'func countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
let uniqueCharacters = Set(lowercaseString)
return uniqueCharacters.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
let uniqueCharacters = Set(lowercaseString)
return uniqueCharacters.count
}
```func countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
let uniqueCharacters = Set(lowercaseString.characters)
return uniqueCharacters.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
let uniqueCharacters = Set(lowercaseString.characters)
return uniqueCharacters.count
}
```let uniqueCharacters = Set(lowercaseString.characters) // 'characters' is unavailable: Please use String directlyfunc countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
let uniqueCharacters = Set(lowercaseString.characters)
return uniqueCharacters.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
let uniqueCharacters = Set(lowercaseString.characters)
return uniqueCharacters.count
}
```let uniqueCharacters = Set(lowercaseString.characters) // 'characters' is unavailable: Please use String directlyfunc countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
let uniqueCharacters = Set(lowercaseString.characters)
return uniqueCharacters.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
let uniqueCharacters = Set(lowercaseString.characters)
return uniqueCharacters.count
}
```let uniqueCharacters = Set(lowercaseString.characters) // 'characters' is unavailable: Please use String directlyfunc countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
let uniqueCharacters = Set(lowercaseString)
return uniqueCharacters.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
let uniqueCharacters = Set(lowercaseString)
return uniqueCharacters.count
}
```func countDistinctCharacters(string: String) -> Int {
var distinctChars = Set<Character>()
for char in string {
distinctChars.insert(char.lowercased())
}
return distinctChars.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
var distinctChars = Set<Character>()
for char in string {
distinctChars.insert(char.lowercased())
}
return distinctChars.count
}
```distinctChars.insert(char.lowercased()) // cannot convert value of type 'String' to expected argument type 'Character'func countDistinctCharacters(string: String) -> Int {
var distinctCharacters = Set<Character>()
for character in string {
distinctCharacters.insert(character.lowercased())
}
return distinctCharacters.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
var distinctCharacters = Set<Character>()
for character in string {
distinctCharacters.insert(character.lowercased())
}
return distinctCharacters.count
}
```distinctCharacters.insert(character.lowercased()) // cannot convert value of type 'String' to expected argument type 'Character'func countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
let distinctCharacters = Set(lowercaseString)
return distinctCharacters.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
let distinctCharacters = Set(lowercaseString)
return distinctCharacters.count
}
```func countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
var distinctCharacters = Set<Character>()
for character in lowercaseString {
distinctCharacters.insert(character)
}
return distinctCharacters.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
var distinctCharacters = Set<Character>()
for character in lowercaseString {
distinctCharacters.insert(character)
}
return distinctCharacters.count
}
```func parseMusic(musicString: String) -> [Int] {
let noteDurationMap = [
"o": 4,
"o|": 2,
".|": 1
]
let noteDurations = musicString.components(separatedBy: " ")
.map { noteDurationMap[$0]?? 0 }
return noteDurations
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
let noteDurationMap = [
"o": 4,
"o|": 2,
".|": 1
]
let noteDurations = musicString.components(separatedBy: " ")
.map { noteDurationMap[$0]?? 0 }
return noteDurations
}
```.map { noteDurationMap[$0]?? 0 } // consecutive statements on a line must be separated by ';'.map { noteDurationMap[$0]?? 0 } // cannot use optional chaining on non-optional value of type 'Int'func parseMusic(musicString: String) -> [Int] {
var result = [Int]()
var currentBeat = 0
var currentNote = 0
for character in musicString {
switch character {
case "o":
currentBeat += 4
case "o|":
currentBeat += 2
case ".|":
currentBeat += 1
default:
break
}
result.append(currentBeat)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
var result = [Int]()
var currentBeat = 0
var currentNote = 0
for character in musicString {
switch character {
case "o":
currentBeat += 4
case "o|":
currentBeat += 2
case ".|":
currentBeat += 1
default:
break
}
result.append(currentBeat)
}
return result
}
```case "o|": // expression pattern of type 'String' cannot match values of type 'Character'case ".|": // expression pattern of type 'String' cannot match values of type 'Character'func parseMusic(musicString: String) -> [Int] {
let noteDuration = [4, 2, 1]
var result = [Int]()
for note in musicString.components(separatedBy: " ") {
let duration = noteDuration[note == "o"? 0 : note == "o|"? 1 : note == ".|"? 2 : 0]
result.append(duration)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
let noteDuration = [4, 2, 1]
var result = [Int]()
for note in musicString.components(separatedBy: " ") {
let duration = noteDuration[note == "o"? 0 : note == "o|"? 1 : note == ".|"? 2 : 0]
result.append(duration)
}
return result
}
```let duration = noteDuration[note == "o"? 0 : note == "o|"? 1 : note == ".|"? 2 : 0] // cannot use optional chaining on non-optional value of type 'String'let duration = noteDuration[note == "o"? 0 : note == "o|"? 1 : note == ".|"? 2 : 0] // expected ',' separatorlet duration = noteDuration[note == "o"? 0 : note == "o|"? 1 : note == ".|"? 2 : 0] // no exact matches in call to subscriptfunc parseMusic(musicString: String) -> [Int] {
var result: [Int] = []
var currentBeat = 0
for note in musicString {
switch note {
case "o":
currentBeat += 4
case "o|":
currentBeat += 2
case ".|":
currentBeat += 1
default:
break
}
result.append(currentBeat)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
var result: [Int] = []
var currentBeat = 0
for note in musicString {
switch note {
case "o":
currentBeat += 4
case "o|":
currentBeat += 2
case ".|":
currentBeat += 1
default:
break
}
result.append(currentBeat)
}
return result
}
```case "o|": // expression pattern of type 'String' cannot match values of type 'Character'case ".|": // expression pattern of type 'String' cannot match values of type 'Character'func parseMusic(musicString: String) -> [Int] {
var result = [Int]()
var currentBeat = 0
for note in musicString {
switch note {
case "o":
currentBeat += 4
case "o|":
currentBeat += 2
case ".|":
currentBeat += 1
default:
break
}
result.append(currentBeat)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
var result = [Int]()
var currentBeat = 0
for note in musicString {
switch note {
case "o":
currentBeat += 4
case "o|":
currentBeat += 2
case ".|":
currentBeat += 1
default:
break
}
result.append(currentBeat)
}
return result
}
```case "o|": // expression pattern of type 'String' cannot match values of type 'Character'case ".|": // expression pattern of type 'String' cannot match values of type 'Character'func parseMusic(musicString: String) -> [Int] {
var result = [Int]()
var noteCount = 0
var beatCount = 0
for character in musicString {
switch character {
case "o":
noteCount += 1
beatCount += 4
case "o|":
noteCount += 1
beatCount += 2
case ".|":
noteCount += 1
beatCount += 1
default:
break
}
if noteCount == 4 {
result.append(beatCount)
noteCount = 0
beatCount = 0
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
var result = [Int]()
var noteCount = 0
var beatCount = 0
for character in musicString {
switch character {
case "o":
noteCount += 1
beatCount += 4
case "o|":
noteCount += 1
beatCount += 2
case ".|":
noteCount += 1
beatCount += 1
default:
break
}
if noteCount == 4 {
result.append(beatCount)
noteCount = 0
beatCount = 0
}
}
return result
}
```case "o|": // expression pattern of type 'String' cannot match values of type 'Character'case ".|": // expression pattern of type 'String' cannot match values of type 'Character'func parseMusic(musicString: String) -> [Int] {
var result = [Int]()
var noteCount = 0
var noteType = ""
for character in musicString {
if character == "o" {
noteType = "whole"
noteCount = 4
} else if character == "o" {
noteType = "half"
noteCount = 2
} else if character == "." {
noteType = "quarter"
noteCount = 1
} else if character == "|" {
result.append(noteCount)
noteCount = 0
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
var result = [Int]()
var noteCount = 0
var noteType = ""
for character in musicString {
if character == "o" {
noteType = "whole"
noteCount = 4
} else if character == "o" {
noteType = "half"
noteCount = 2
} else if character == "." {
noteType = "quarter"
noteCount = 1
} else if character == "|" {
result.append(noteCount)
noteCount = 0
}
}
return result
}
```var noteType = "" // variable 'noteType' was written to, but never read // XCTAssertTrue failedfunc parseMusic(musicString: String) -> [Int] {
let noteDuration = [4, 2, 1]
var result: [Int] = []
for note in musicString.components(separatedBy: " ") {
let duration = noteDuration[note == "o"? 0 : note == "o|"? 1 : note == ".|"? 2 : 0]
result.append(duration)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
let noteDuration = [4, 2, 1]
var result: [Int] = []
for note in musicString.components(separatedBy: " ") {
let duration = noteDuration[note == "o"? 0 : note == "o|"? 1 : note == ".|"? 2 : 0]
result.append(duration)
}
return result
}
```let duration = noteDuration[note == "o"? 0 : note == "o|"? 1 : note == ".|"? 2 : 0] // cannot use optional chaining on non-optional value of type 'String'let duration = noteDuration[note == "o"? 0 : note == "o|"? 1 : note == ".|"? 2 : 0] // expected ',' separatorlet duration = noteDuration[note == "o"? 0 : note == "o|"? 1 : note == ".|"? 2 : 0] // no exact matches in call to subscriptfunc parseMusic(musicString: String) -> [Int] {
var result = [Int]()
var currentBeat = 0
var noteCount = 0
for character in musicString {
switch character {
case "o":
currentBeat += 4
noteCount += 1
case "o|":
currentBeat += 2
noteCount += 1
case ".|":
currentBeat += 1
noteCount += 1
default:
break
}
result.append(currentBeat)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
var result = [Int]()
var currentBeat = 0
var noteCount = 0
for character in musicString {
switch character {
case "o":
currentBeat += 4
noteCount += 1
case "o|":
currentBeat += 2
noteCount += 1
case ".|":
currentBeat += 1
noteCount += 1
default:
break
}
result.append(currentBeat)
}
return result
}
```case "o|": // expression pattern of type 'String' cannot match values of type 'Character'case ".|": // expression pattern of type 'String' cannot match values of type 'Character'func parseMusic(musicString: String) -> [Int] {
var result = [Int]()
var currentBeat = 0
var currentNote = ""
for character in musicString {
if character == "o" {
currentBeat += 4
currentNote = "o"
} else if character == "o|" {
currentBeat += 2
currentNote = "o|"
} else if character == ".|" {
currentBeat += 1
currentNote = ".|"
}
if currentNote == "o" {
result.append(currentBeat)
currentBeat = 0
currentNote = ""
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
var result = [Int]()
var currentBeat = 0
var currentNote = ""
for character in musicString {
if character == "o" {
currentBeat += 4
currentNote = "o"
} else if character == "o|" {
currentBeat += 2
currentNote = "o|"
} else if character == ".|" {
currentBeat += 1
currentNote = ".|"
}
if currentNote == "o" {
result.append(currentBeat)
currentBeat = 0
currentNote = ""
}
}
return result
}
```} else if character == "o|" { // binary operator '==' cannot be applied to operands of type 'Character' and 'String'} else if character == ".|" { // binary operator '==' cannot be applied to operands of type 'Character' and 'String'func howManyTimes(string: String, substring: String) -> Int {
var count = 0
let index = string.startIndex
while let range = string.range(of: substring, options:.backwards, range: index..<string.endIndex) {
count += 1
index = range.lowerBound
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
let index = string.startIndex
while let range = string.range(of: substring, options:.backwards, range: index..<string.endIndex) {
count += 1
index = range.lowerBound
}
return count
}
```index = range.lowerBound // cannot assign to value: 'index' is a 'let' constantfunc howManyTimes(string: String, substring: String) -> Int {
var count = 0
let index = string.startIndex
while let range = string.range(of: substring, options:.backwards, range: index..<string.endIndex) {
count += 1
index = string.index(before: range.lowerBound)
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
let index = string.startIndex
while let range = string.range(of: substring, options:.backwards, range: index..<string.endIndex) {
count += 1
index = string.index(before: range.lowerBound)
}
return count
}
```index = string.index(before: range.lowerBound) // cannot assign to value: 'index' is a 'let' constantfunc howManyTimes(string: String, substring: String) -> Int {
var count = 0
let index = string.startIndex
while let range = string.range(of: substring, options:.backwards, range: index..<string.endIndex) {
count += 1
index = range.lowerBound
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
let index = string.startIndex
while let range = string.range(of: substring, options:.backwards, range: index..<string.endIndex) {
count += 1
index = range.lowerBound
}
return count
}
```index = range.lowerBound // cannot assign to value: 'index' is a 'let' constantfunc howManyTimes(string: String, substring: String) -> Int {
var count = 0
let index = string.range(of: substring, options:.backwards)
while let range = index {
count += 1
string = String(string.dropFirst(range.lowerBound))
index = string.range(of: substring, options:.backwards)
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
let index = string.range(of: substring, options:.backwards)
while let range = index {
count += 1
string = String(string.dropFirst(range.lowerBound))
index = string.range(of: substring, options:.backwards)
}
return count
}
```string = String(string.dropFirst(range.lowerBound)) // cannot assign to value: 'string' is a 'let' constantstring = String(string.dropFirst(range.lowerBound)) // cannot convert value of type 'String.Index' to expected argument type 'Int'index = string.range(of: substring, options:.backwards) // cannot assign to value: 'index' is a 'let' constantfunc howManyTimes(string: String, substring: String) -> Int {
var count = 0
let index = string.range(of: substring, options:.backwards)
while let range = index {
count += 1
string = String(string.dropFirst(range.lowerBound))
index = string.range(of: substring, options:.backwards)
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
let index = string.range(of: substring, options:.backwards)
while let range = index {
count += 1
string = String(string.dropFirst(range.lowerBound))
index = string.range(of: substring, options:.backwards)
}
return count
}
```string = String(string.dropFirst(range.lowerBound)) // cannot assign to value: 'string' is a 'let' constantstring = String(string.dropFirst(range.lowerBound)) // cannot convert value of type 'String.Index' to expected argument type 'Int'index = string.range(of: substring, options:.backwards) // cannot assign to value: 'index' is a 'let' constantfunc howManyTimes(string: String, substring: String) -> Int {
var count = 0
let index = string.range(of: substring, options:.backwards)
while let range = index {
count += 1
string = String(string.dropFirst(range.lowerBound))
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
let index = string.range(of: substring, options:.backwards)
while let range = index {
count += 1
string = String(string.dropFirst(range.lowerBound))
}
return count
}
```string = String(string.dropFirst(range.lowerBound)) // cannot assign to value: 'string' is a 'let' constantstring = String(string.dropFirst(range.lowerBound)) // cannot convert value of type 'String.Index' to expected argument type 'Int'func howManyTimes(string: String, substring: String) -> Int {
var count = 0
let index = string.startIndex
while let range = string.range(of: substring, options:.backwards, range: index..<string.endIndex) {
count += 1
index = string.index(before: range.lowerBound)
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
let index = string.startIndex
while let range = string.range(of: substring, options:.backwards, range: index..<string.endIndex) {
count += 1
index = string.index(before: range.lowerBound)
}
return count
}
```index = string.index(before: range.lowerBound) // cannot assign to value: 'index' is a 'let' constantfunc howManyTimes(string: String, substring: String) -> Int {
var count = 0
let index = string.startIndex
while let range = string.range(of: substring, options:.backwards, range: index..<string.endIndex) {
count += 1
index = string.index(before: range.lowerBound)
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
let index = string.startIndex
while let range = string.range(of: substring, options:.backwards, range: index..<string.endIndex) {
count += 1
index = string.index(before: range.lowerBound)
}
return count
}
```index = string.index(before: range.lowerBound) // cannot assign to value: 'index' is a 'let' constantfunc howManyTimes(string: String, substring: String) -> Int {
var count = 0
let index = string.startIndex
while let range = string.range(of: substring, options:.backwards, range: index..<string.endIndex) {
count += 1
index = string.index(before: range.lowerBound)
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
let index = string.startIndex
while let range = string.range(of: substring, options:.backwards, range: index..<string.endIndex) {
count += 1
index = string.index(before: range.lowerBound)
}
return count
}
```index = string.index(before: range.lowerBound) // cannot assign to value: 'index' is a 'let' constantfunc howManyTimes(string: String, substring: String) -> Int {
var count = 0
var index = string.startIndex
while let range = string.range(of: substring, options:.backwards, range: index..<string.endIndex) {
count += 1
index = string.index(before: range.lowerBound)
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var index = string.startIndex
while let range = string.range(of: substring, options:.backwards, range: index..<string.endIndex) {
count += 1
index = string.index(before: range.lowerBound)
}
return count
}
```func sortNumbers(numbers: String) -> String {
let numberArray = numbers.components(separatedBy: " ")
let sortedArray = numberArray.sorted()
return sortedArray.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
Answer:
```swift
func sortNumbers(numbers: String) -> String {
let numberArray = numbers.components(separatedBy: " ")
let sortedArray = numberArray.sorted()
return sortedArray.joined(separator: " ")
}
``` // XCTAssertTrue failedfunc sortNumbers(numbers: String) -> String {
let numberArray = numbers.components(separatedBy: " ")
let sortedNumberArray = numberArray.sorted()
return sortedNumberArray.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
Answer:
```swift
func sortNumbers(numbers: String) -> String {
let numberArray = numbers.components(separatedBy: " ")
let sortedNumberArray = numberArray.sorted()
return sortedNumberArray.joined(separator: " ")
}
``` // XCTAssertTrue failedfunc sortNumbers(numbers: String) -> String {
let numberList = numbers.components(separatedBy: " ")
let sortedNumberList = numberList.sorted { $0 < $1 }
return sortedNumberList.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
Answer:
```swift
func sortNumbers(numbers: String) -> String {
let numberList = numbers.components(separatedBy: " ")
let sortedNumberList = numberList.sorted { $0 < $1 }
return sortedNumberList.joined(separator: " ")
}
``` // XCTAssertTrue failedfunc sortNumbers(numbers: String) -> String {
let numberArray = numbers.components(separatedBy: " ")
let sortedArray = numberArray.sorted()
return sortedArray.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
Answer:
```swift
func sortNumbers(numbers: String) -> String {
let numberArray = numbers.components(separatedBy: " ")
let sortedArray = numberArray.sorted()
return sortedArray.joined(separator: " ")
}
``` // XCTAssertTrue failedfunc sortNumbers(numbers: String) -> String {
let numberArray = numbers.components(separatedBy: " ")
let sortedArray = numberArray.sorted()
return sortedArray.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
Answer:
```swift
func sortNumbers(numbers: String) -> String {
let numberArray = numbers.components(separatedBy: " ")
let sortedArray = numberArray.sorted()
return sortedArray.joined(separator: " ")
}
``` // XCTAssertTrue failedfunc sortNumbers(numbers: String) -> String {
let numberArray = numbers.components(separatedBy: " ")
let sortedArray = numberArray.sorted()
return sortedArray.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
Answer:
```swift
func sortNumbers(numbers: String) -> String {
let numberArray = numbers.components(separatedBy: " ")
let sortedArray = numberArray.sorted()
return sortedArray.joined(separator: " ")
}
``` // XCTAssertTrue failedfunc sortNumbers(numbers: String) -> String {
let numberArray = numbers.components(separatedBy: " ")
let sortedArray = numberArray.sorted()
return sortedArray.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
Answer:
```swift
func sortNumbers(numbers: String) -> String {
let numberArray = numbers.components(separatedBy: " ")
let sortedArray = numberArray.sorted()
return sortedArray.joined(separator: " ")
}
``` // XCTAssertTrue failedfunc sortNumbers(numbers: String) -> String {
let numberArray = numbers.components(separatedBy: " ")
let sortedArray = numberArray.sorted()
return sortedArray.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
Answer:
```swift
func sortNumbers(numbers: String) -> String {
let numberArray = numbers.components(separatedBy: " ")
let sortedArray = numberArray.sorted()
return sortedArray.joined(separator: " ")
}
``` // XCTAssertTrue failedfunc sortNumbers(numbers: String) -> String {
let numberArray = numbers.components(separatedBy: " ")
let sortedArray = numberArray.sorted()
return sortedArray.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
Answer:
```swift
func sortNumbers(numbers: String) -> String {
let numberArray = numbers.components(separatedBy: " ")
let sortedArray = numberArray.sorted()
return sortedArray.joined(separator: " ")
}
``` // XCTAssertTrue failedfunc sortNumbers(numbers: String) -> String {
let numberArray = numbers.components(separatedBy: " ")
let sortedArray = numberArray.sorted { $0 < $1 }
return sortedArray.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
Answer:
```swift
func sortNumbers(numbers: String) -> String {
let numberArray = numbers.components(separatedBy: " ")
let sortedArray = numberArray.sorted { $0 < $1 }
return sortedArray.joined(separator: " ")
}
``` // XCTAssertTrue failedfunc findClosestElements(numbers: [Double]) -> (Double, Double) {
guard numbers.count > 1 else {
fatalError("Array must have at least two elements")
}
var minDistance = Double.greatestFiniteMagnitude
var minDistanceElements: (Double, Double)?
for i in 0..<numbers.count {
for j in (i + 1)..<numbers.count {
let distance = abs(numbers[i] - numbers[j])
if distance < minDistance {
minDistance = distance
minDistanceElements = (numbers[i], numbers[j])
}
}
}
return minDistanceElements!
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
guard numbers.count > 1 else {
fatalError("Array must have at least two elements")
}
var minDistance = Double.greatestFiniteMagnitude
var minDistanceElements: (Double, Double)?
for i in 0..<numbers.count {
for j in (i + 1)..<numbers.count {
let distance = abs(numbers[i] - numbers[j])
if distance < minDistance {
minDistance = distance
minDistanceElements = (numbers[i], numbers[j])
}
}
}
return minDistanceElements!
}
``` // XCTAssertTrue failedfunc findClosestElements(numbers: [Double]) -> (Double, Double) {
guard numbers.count > 1 else {
return (0.0, 0.0)
}
var minDiff = Double.greatestFiniteMagnitude
var minDiffElements: (Double, Double)?
for i in 0..<numbers.count-1 {
let diff = abs(numbers[i] - numbers[i+1])
if diff < minDiff {
minDiff = diff
minDiffElements = (numbers[i], numbers[i+1])
}
}
return minDiffElements!
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
guard numbers.count > 1 else {
return (0.0, 0.0)
}
var minDiff = Double.greatestFiniteMagnitude
var minDiffElements: (Double, Double)?
for i in 0..<numbers.count-1 {
let diff = abs(numbers[i] - numbers[i+1])
if diff < minDiff {
minDiff = diff
minDiffElements = (numbers[i], numbers[i+1])
}
}
return minDiffElements!
}
``` // XCTAssertTrue failedfunc findClosestElements(numbers: [Double]) -> (Double, Double) {
guard numbers.count >= 2 else {
fatalError("Array must contain at least two numbers")
}
var closestPair = (numbers[0], numbers[1])
for i in 0..<numbers.count-1 {
for j in i+1..<numbers.count {
let currentPair = (numbers[i], numbers[j])
let currentDistance = abs(currentPair.0 - currentPair.1)
let closestDistance = abs(closestPair.0 - closestPair.1)
if currentDistance < closestDistance {
closestPair = currentPair
}
}
}
return closestPair
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
guard numbers.count >= 2 else {
fatalError("Array must contain at least two numbers")
}
var closestPair = (numbers[0], numbers[1])
for i in 0..<numbers.count-1 {
for j in i+1..<numbers.count {
let currentPair = (numbers[i], numbers[j])
let currentDistance = abs(currentPair.0 - currentPair.1)
let closestDistance = abs(closestPair.0 - closestPair.1)
if currentDistance < closestDistance {
closestPair = currentPair
}
}
}
return closestPair
}
``` // XCTAssertTrue failedfunc findClosestElements(numbers: [Double]) -> (Double, Double) {
guard numbers.count >= 2 else {
fatalError("Array must contain at least two numbers")
}
var closestPair = (numbers[0], numbers[1])
for i in 0..<numbers.count-1 {
for j in i+1..<numbers.count {
let currentPair = (numbers[i], numbers[j])
if abs(currentPair.0 - currentPair.1) < abs(closestPair.0 - closestPair.1) {
closestPair = currentPair
}
}
}
return closestPair
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
guard numbers.count >= 2 else {
fatalError("Array must contain at least two numbers")
}
var closestPair = (numbers[0], numbers[1])
for i in 0..<numbers.count-1 {
for j in i+1..<numbers.count {
let currentPair = (numbers[i], numbers[j])
if abs(currentPair.0 - currentPair.1) < abs(closestPair.0 - closestPair.1) {
closestPair = currentPair
}
}
}
return closestPair
}
``` // XCTAssertTrue failedfunc findClosestElements(numbers: [Double]) -> (Double, Double) {
guard numbers.count >= 2 else {
fatalError("Array must have at least two elements")
}
var minDiff = Double.greatestFiniteMagnitude
var minDiffElements: (Double, Double)?
for i in 0..<numbers.count-1 {
let diff = abs(numbers[i] - numbers[i+1])
if diff < minDiff {
minDiff = diff
minDiffElements = (numbers[i], numbers[i+1])
}
}
return minDiffElements!
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
guard numbers.count >= 2 else {
fatalError("Array must have at least two elements")
}
var minDiff = Double.greatestFiniteMagnitude
var minDiffElements: (Double, Double)?
for i in 0..<numbers.count-1 {
let diff = abs(numbers[i] - numbers[i+1])
if diff < minDiff {
minDiff = diff
minDiffElements = (numbers[i], numbers[i+1])
}
}
return minDiffElements!
}
``` // XCTAssertTrue failedfunc findClosestElements(numbers: [Double]) -> (Double, Double) {
guard numbers.count >= 2 else {
fatalError("Array must have at least two elements")
}
var minDiff = Double.greatestFiniteMagnitude
var minDiffElements: (Double, Double)?
for i in 0..<numbers.count-1 {
let diff = abs(numbers[i] - numbers[i+1])
if diff < minDiff {
minDiff = diff
minDiffElements = (numbers[i], numbers[i+1])
}
}
return minDiffElements!
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
guard numbers.count >= 2 else {
fatalError("Array must have at least two elements")
}
var minDiff = Double.greatestFiniteMagnitude
var minDiffElements: (Double, Double)?
for i in 0..<numbers.count-1 {
let diff = abs(numbers[i] - numbers[i+1])
if diff < minDiff {
minDiff = diff
minDiffElements = (numbers[i], numbers[i+1])
}
}
return minDiffElements!
}
``` // XCTAssertTrue failedfunc findClosestElements(numbers: [Double]) -> (Double, Double) {
guard numbers.count >= 2 else {
fatalError("Array must contain at least two numbers")
}
var minDistance = Double.greatestFiniteMagnitude
var closestElements: (Double, Double)?
for i in 0..<numbers.count {
for j in (i + 1)..<numbers.count {
let currentDistance = abs(numbers[i] - numbers[j])
if currentDistance < minDistance {
minDistance = currentDistance
closestElements = (numbers[i], numbers[j])
}
}
}
return closestElements!
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
guard numbers.count >= 2 else {
fatalError("Array must contain at least two numbers")
}
var minDistance = Double.greatestFiniteMagnitude
var closestElements: (Double, Double)?
for i in 0..<numbers.count {
for j in (i + 1)..<numbers.count {
let currentDistance = abs(numbers[i] - numbers[j])
if currentDistance < minDistance {
minDistance = currentDistance
closestElements = (numbers[i], numbers[j])
}
}
}
return closestElements!
}
``` // XCTAssertTrue failedfunc findClosestElements(numbers: [Double]) -> (Double, Double) {
guard numbers.count >= 2 else {
fatalError("Array must contain at least two numbers")
}
var minDistance = Double.greatestFiniteMagnitude
var closestNumbers = (Double.greatestFiniteMagnitude, Double.greatestFiniteMagnitude)
for i in 0..<numbers.count-1 {
let currentDistance = abs(numbers[i] - numbers[i+1])
if currentDistance < minDistance {
minDistance = currentDistance
closestNumbers = (numbers[i], numbers[i+1])
}
}
return closestNumbers
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
guard numbers.count >= 2 else {
fatalError("Array must contain at least two numbers")
}
var minDistance = Double.greatestFiniteMagnitude
var closestNumbers = (Double.greatestFiniteMagnitude, Double.greatestFiniteMagnitude)
for i in 0..<numbers.count-1 {
let currentDistance = abs(numbers[i] - numbers[i+1])
if currentDistance < minDistance {
minDistance = currentDistance
closestNumbers = (numbers[i], numbers[i+1])
}
}
return closestNumbers
}
``` // XCTAssertTrue failedfunc findClosestElements(numbers: [Double]) -> (Double, Double) {
guard numbers.count >= 2 else {
fatalError("Array must contain at least two elements.")
}
var minDiff = Double.greatestFiniteMagnitude
var minDiffElements: (Double, Double)?
for i in 0..<numbers.count - 1 {
let diff = abs(numbers[i] - numbers[i+1])
if diff < minDiff {
minDiff = diff
minDiffElements = (numbers[i], numbers[i+1])
}
}
return minDiffElements!
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
guard numbers.count >= 2 else {
fatalError("Array must contain at least two elements.")
}
var minDiff = Double.greatestFiniteMagnitude
var minDiffElements: (Double, Double)?
for i in 0..<numbers.count - 1 {
let diff = abs(numbers[i] - numbers[i+1])
if diff < minDiff {
minDiff = diff
minDiffElements = (numbers[i], numbers[i+1])
}
}
return minDiffElements!
}
``` // XCTAssertTrue failedfunc findClosestElements(numbers: [Double]) -> (Double, Double) {
guard numbers.count >= 2 else {
fatalError("Array must contain at least two numbers")
}
var minDiff: Double = Double.infinity
var minDiffElements: (Double, Double)?
for i in 0..<numbers.count - 1 {
for j in i + 1..<numbers.count {
let diff = abs(numbers[i] - numbers[j])
if diff < minDiff {
minDiff = diff
minDiffElements = (numbers[i], numbers[j])
}
}
}
return minDiffElements!
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
guard numbers.count >= 2 else {
fatalError("Array must contain at least two numbers")
}
var minDiff: Double = Double.infinity
var minDiffElements: (Double, Double)?
for i in 0..<numbers.count - 1 {
for j in i + 1..<numbers.count {
let diff = abs(numbers[i] - numbers[j])
if diff < minDiff {
minDiff = diff
minDiffElements = (numbers[i], numbers[j])
}
}
}
return minDiffElements!
}
``` // XCTAssertTrue failedfunc rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min()!
let max = numbers.max()!
return (numbers - min) / (max - min)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min()!
let max = numbers.max()!
return (numbers - min) / (max - min)
}
```return (numbers - min) / (max - min) // cannot convert return expression of type 'Double' to return type '[Double]'return (numbers - min) / (max - min) // cannot convert value of type '[Double]' to expected argument type 'Double'func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min()!
let max = numbers.max()!
return numbers.map { (max - $0) / (max - min) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min()!
let max = numbers.max()!
return numbers.map { (max - $0) / (max - min) }
}
``` // XCTAssertTrue failedfunc rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min()!
let max = numbers.max()!
return (numbers - min) / (max - min)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min()!
let max = numbers.max()!
return (numbers - min) / (max - min)
}
```return (numbers - min) / (max - min) // cannot convert return expression of type 'Double' to return type '[Double]'return (numbers - min) / (max - min) // cannot convert value of type '[Double]' to expected argument type 'Double'func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min()!
let max = numbers.max()!
return numbers.map { (max - $0) / (max - min) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min()!
let max = numbers.max()!
return numbers.map { (max - $0) / (max - min) }
}
``` // XCTAssertTrue failedfunc rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min()!
let max = numbers.max()!
return numbers.map { (max - $0) / (max - min) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min()!
let max = numbers.max()!
return numbers.map { (max - $0) / (max - min) }
}
``` // XCTAssertTrue failedfunc rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min()!
let max = numbers.max()!
return (numbers - min) / (max - min)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min()!
let max = numbers.max()!
return (numbers - min) / (max - min)
}
```return (numbers - min) / (max - min) // cannot convert return expression of type 'Double' to return type '[Double]'return (numbers - min) / (max - min) // cannot convert value of type '[Double]' to expected argument type 'Double'func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min()!
let max = numbers.max()!
return numbers.map { (max - $0) / (max - min) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min()!
let max = numbers.max()!
return numbers.map { (max - $0) / (max - min) }
}
``` // XCTAssertTrue failedfunc rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min()!
let max = numbers.max()!
return (numbers - min) / (max - min)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min()!
let max = numbers.max()!
return (numbers - min) / (max - min)
}
```return (numbers - min) / (max - min) // cannot convert return expression of type 'Double' to return type '[Double]'return (numbers - min) / (max - min) // cannot convert value of type '[Double]' to expected argument type 'Double'func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min()!
let max = numbers.max()!
return numbers.map { (max - $0) / (max - min) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min()!
let max = numbers.max()!
return numbers.map { (max - $0) / (max - min) }
}
``` // XCTAssertTrue failedfunc rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min()!
let max = numbers.max()!
return numbers.map { (max - min) * $0 / max }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min()!
let max = numbers.max()!
return numbers.map { (max - min) * $0 / max }
}
``` // XCTAssertTrue failedfunc filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}
```func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}
```func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}
```func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}
```func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}
```func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}
```func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}
```func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}
```func filterIntegers(values: [AnyHashable]) -> [Int] {
var result = [Int]()
for value in values {
if let integer = value as? Int {
result.append(integer)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
var result = [Int]()
for value in values {
if let integer = value as? Int {
result.append(integer)
}
}
return result
}
```func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}
```func strlen(string: String) -> Int {
return string.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
Answer:
```swift
func strlen(string: String) -> Int {
return string.count
}
```func strlen(string: String) -> Int {
return string.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
Answer:
```swift
func strlen(string: String) -> Int {
return string.count
}
```func strlen(string: String) -> Int {
return string.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
Answer:
```swift
func strlen(string: String) -> Int {
return string.count
}
```func strlen(string: String) -> Int {
return string.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
Answer:
```swift
func strlen(string: String) -> Int {
return string.count
}
```func strlen(string: String) -> Int {
return string.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
Answer:
```swift
func strlen(string: String) -> Int {
return string.count
}
```func strlen(string: String) -> Int {
return string.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
Answer:
```swift
func strlen(string: String) -> Int {
return string.count
}
```func strlen(string: String) -> Int {
return string.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
Answer:
```swift
func strlen(string: String) -> Int {
return string.count
}
```func strlen(string: String) -> Int {
return string.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
Answer:
```swift
func strlen(string: String) -> Int {
return string.count
}
```func strlen(string: String) -> Int {
return string.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
Answer:
```swift
func strlen(string: String) -> Int {
return string.count
}
```func strlen(string: String) -> Int {
return string.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
Answer:
```swift
func strlen(string: String) -> Int {
return string.count
}
```func largestDivisor(n: Int) -> Int {
var divisor = n
while divisor > 1 {
if n % divisor == 0 {
return divisor
}
divisor -= 1
}
return 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
Answer:
```swift
func largestDivisor(n: Int) -> Int {
var divisor = n
while divisor > 1 {
if n % divisor == 0 {
return divisor
}
divisor -= 1
}
return 1
}
``` // XCTAssertTrue failedfunc largestDivisor(n: Int) -> Int {
var divisor = n
while divisor > 1 {
divisor -= 1
if n % divisor == 0 {
return divisor
}
}
return 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
Answer:
```swift
func largestDivisor(n: Int) -> Int {
var divisor = n
while divisor > 1 {
divisor -= 1
if n % divisor == 0 {
return divisor
}
}
return 1
}
```func largestDivisor(n: Int) -> Int {
var divisor = n
while divisor > 1 {
divisor -= 1
if n % divisor == 0 {
return divisor
}
}
return 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
Answer:
```swift
func largestDivisor(n: Int) -> Int {
var divisor = n
while divisor > 1 {
divisor -= 1
if n % divisor == 0 {
return divisor
}
}
return 1
}
```func largestDivisor(n: Int) -> Int {
var divisor = n
while divisor > 1 {
divisor -= 1
if n % divisor == 0 {
return divisor
}
}
return 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
Answer:
```swift
func largestDivisor(n: Int) -> Int {
var divisor = n
while divisor > 1 {
divisor -= 1
if n % divisor == 0 {
return divisor
}
}
return 1
}
```func largestDivisor(n: Int) -> Int {
var divisor = n
while divisor > 1 {
if n % divisor == 0 {
return divisor
}
divisor -= 1
}
return 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
Answer:
```swift
func largestDivisor(n: Int) -> Int {
var divisor = n
while divisor > 1 {
if n % divisor == 0 {
return divisor
}
divisor -= 1
}
return 1
}
``` // XCTAssertTrue failedfunc largestDivisor(n: Int) -> Int {
var divisor = n
while divisor > 1 {
divisor -= 1
if n % divisor == 0 {
return divisor
}
}
return 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
Answer:
```swift
func largestDivisor(n: Int) -> Int {
var divisor = n
while divisor > 1 {
divisor -= 1
if n % divisor == 0 {
return divisor
}
}
return 1
}
```func largestDivisor(n: Int) -> Int {
var divisor = n
while divisor > 1 {
if n % divisor == 0 {
return divisor
}
divisor -= 1
}
return 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
Answer:
```swift
func largestDivisor(n: Int) -> Int {
var divisor = n
while divisor > 1 {
if n % divisor == 0 {
return divisor
}
divisor -= 1
}
return 1
}
``` // XCTAssertTrue failedfunc largestDivisor(n: Int) -> Int {
var divisor = n
while divisor > 1 {
divisor -= 1
if n % divisor == 0 {
return divisor
}
}
return 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
Answer:
```swift
func largestDivisor(n: Int) -> Int {
var divisor = n
while divisor > 1 {
divisor -= 1
if n % divisor == 0 {
return divisor
}
}
return 1
}
```func largestDivisor(n: Int) -> Int {
var divisor = n
while divisor > 1 {
divisor -= 1
if n % divisor == 0 {
return divisor
}
}
return 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
Answer:
```swift
func largestDivisor(n: Int) -> Int {
var divisor = n
while divisor > 1 {
divisor -= 1
if n % divisor == 0 {
return divisor
}
}
return 1
}
```func largestDivisor(n: Int) -> Int {
var divisor = n
while divisor > 0 {
if n % divisor == 0 {
return divisor
}
divisor -= 1
}
return 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
Answer:
```swift
func largestDivisor(n: Int) -> Int {
var divisor = n
while divisor > 0 {
if n % divisor == 0 {
return divisor
}
divisor -= 1
}
return 1
}
``` // XCTAssertTrue failedfunc factorize(n: Int) -> [Int] {
var factors = [Int]()
var num = n
var i = 2
while num > 1 {
while num % i == 0 {
factors.append(i)
num /= i
}
i += 1
}
return factors
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
Answer:
```swift
func factorize(n: Int) -> [Int] {
var factors = [Int]()
var num = n
var i = 2
while num > 1 {
while num % i == 0 {
factors.append(i)
num /= i
}
i += 1
}
return factors
}
```func factorize(n: Int) -> [Int] {
var factors = [Int]()
var num = n
while num > 1 {
for i in 2...num {
while num % i == 0 {
factors.append(i)
num /= i
}
}
}
return factors
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
Answer:
```swift
func factorize(n: Int) -> [Int] {
var factors = [Int]()
var num = n
while num > 1 {
for i in 2...num {
while num % i == 0 {
factors.append(i)
num /= i
}
}
}
return factors
}
```func factorize(n: Int) -> [Int] {
var factors = [Int]()
var i = 2
while i * i <= n {
if n % i == 0 {
var count = 0
while n % i == 0 {
n /= i
count += 1
}
factors.append(contentsOf: Array(repeating: i, count: count))
}
i += 1
}
if n > 1 {
factors.append(n)
}
return factors
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
Answer:
```swift
func factorize(n: Int) -> [Int] {
var factors = [Int]()
var i = 2
while i * i <= n {
if n % i == 0 {
var count = 0
while n % i == 0 {
n /= i
count += 1
}
factors.append(contentsOf: Array(repeating: i, count: count))
}
i += 1
}
if n > 1 {
factors.append(n)
}
return factors
}
```n /= i // left side of mutating operator isn't mutable: 'n' is a 'let' constantfunc factorize(n: Int) -> [Int] {
var factors = [Int]()
var num = n
while num > 1 {
let prime = findNextPrime(num)
factors.append(prime)
num /= prime
}
return factors
}
func findNextPrime(_ n: Int) -> Int {
var num = n
while true {
if isPrime(num) {
return num
}
num += 1
}
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
Answer:
```swift
func factorize(n: Int) -> [Int] {
var factors = [Int]()
var num = n
while num > 1 {
let prime = findNextPrime(num)
factors.append(prime)
num /= prime
}
return factors
}
func findNextPrime(_ n: Int) -> Int {
var num = n
while true {
if isPrime(num) {
return num
}
num += 1
}
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc factorize(n: Int) -> [Int] {
var factors = [Int]()
var num = n
var i = 2
while num > 1 {
while num % i == 0 {
factors.append(i)
num /= i
}
i += 1
}
return factors
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
Answer:
```swift
func factorize(n: Int) -> [Int] {
var factors = [Int]()
var num = n
var i = 2
while num > 1 {
while num % i == 0 {
factors.append(i)
num /= i
}
i += 1
}
return factors
}
```func factorize(n: Int) -> [Int] {
var factors = [Int]()
var num = n
var i = 2
while i * i <= num {
while num % i == 0 {
factors.append(i)
num /= i
}
i += 1
}
if num > 1 {
factors.append(num)
}
return factors
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
Answer:
```swift
func factorize(n: Int) -> [Int] {
var factors = [Int]()
var num = n
var i = 2
while i * i <= num {
while num % i == 0 {
factors.append(i)
num /= i
}
i += 1
}
if num > 1 {
factors.append(num)
}
return factors
}
```func factorize(n: Int) -> [Int] {
var factors = [Int]()
var num = n
while num > 1 {
var i = 2
while num % i == 0 {
factors.append(i)
num /= i
}
i += 1
}
return factors
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
Answer:
```swift
func factorize(n: Int) -> [Int] {
var factors = [Int]()
var num = n
while num > 1 {
var i = 2
while num % i == 0 {
factors.append(i)
num /= i
}
i += 1
}
return factors
}
```func factorize(n: Int) -> [Int] {
var factors = [Int]()
var num = n
while num > 1 {
var divisor = 2
while num % divisor == 0 {
factors.append(divisor)
num /= divisor
}
divisor += 1
}
return factors
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
Answer:
```swift
func factorize(n: Int) -> [Int] {
var factors = [Int]()
var num = n
while num > 1 {
var divisor = 2
while num % divisor == 0 {
factors.append(divisor)
num /= divisor
}
divisor += 1
}
return factors
}
```func factorize(n: Int) -> [Int] {
var factors = [Int]()
var num = n
while num > 1 {
var divisor = 2
while num % divisor == 0 {
factors.append(divisor)
num /= divisor
}
divisor += 1
}
return factors
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
Answer:
```swift
func factorize(n: Int) -> [Int] {
var factors = [Int]()
var num = n
while num > 1 {
var divisor = 2
while num % divisor == 0 {
factors.append(divisor)
num /= divisor
}
divisor += 1
}
return factors
}
```func factorize(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
var i = 2
while num % i == 0 {
result.append(i)
num /= i
}
i += 1
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
Answer:
```swift
func factorize(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num > 1 {
var i = 2
while num % i == 0 {
result.append(i)
num /= i
}
i += 1
}
return result
}
```func removeDuplicates(numbers: [Int]) -> [Int] {
var result = [Int]()
for number in numbers {
if!result.contains(number) {
result.append(number)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var result = [Int]()
for number in numbers {
if!result.contains(number) {
result.append(number)
}
}
return result
}
```if!result.contains(number) { // expected expression, var, or let in 'if' conditionfunc removeDuplicates(numbers: [Int]) -> [Int] {
var result = [Int]()
for number in numbers {
if!result.contains(number) {
result.append(number)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var result = [Int]()
for number in numbers {
if!result.contains(number) {
result.append(number)
}
}
return result
}
```if!result.contains(number) { // expected expression, var, or let in 'if' conditionfunc removeDuplicates(numbers: [Int]) -> [Int] {
var result = [Int]()
for number in numbers {
if!result.contains(number) {
result.append(number)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var result = [Int]()
for number in numbers {
if!result.contains(number) {
result.append(number)
}
}
return result
}
```if!result.contains(number) { // expected expression, var, or let in 'if' conditionfunc removeDuplicates(numbers: [Int]) -> [Int] {
var result = [Int]()
for number in numbers {
if!result.contains(number) {
result.append(number)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var result = [Int]()
for number in numbers {
if!result.contains(number) {
result.append(number)
}
}
return result
}
```if!result.contains(number) { // expected expression, var, or let in 'if' conditionfunc removeDuplicates(numbers: [Int]) -> [Int] {
var result = [Int]()
for number in numbers {
if!result.contains(number) {
result.append(number)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var result = [Int]()
for number in numbers {
if!result.contains(number) {
result.append(number)
}
}
return result
}
```if!result.contains(number) { // expected expression, var, or let in 'if' conditionfunc removeDuplicates(numbers: [Int]) -> [Int] {
var result = [Int]()
var seen = Set<Int>()
for number in numbers {
if!seen.contains(number) {
seen.insert(number)
result.append(number)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var result = [Int]()
var seen = Set<Int>()
for number in numbers {
if!seen.contains(number) {
seen.insert(number)
result.append(number)
}
}
return result
}
```if!seen.contains(number) { // expected expression, var, or let in 'if' conditionfunc removeDuplicates(numbers: [Int]) -> [Int] {
var result = [Int]()
for number in numbers {
if!result.contains(number) {
result.append(number)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var result = [Int]()
for number in numbers {
if!result.contains(number) {
result.append(number)
}
}
return result
}
```if!result.contains(number) { // expected expression, var, or let in 'if' conditionfunc removeDuplicates(numbers: [Int]) -> [Int] {
var result = [Int]()
for number in numbers {
if!result.contains(number) {
result.append(number)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var result = [Int]()
for number in numbers {
if!result.contains(number) {
result.append(number)
}
}
return result
}
```if!result.contains(number) { // expected expression, var, or let in 'if' conditionfunc removeDuplicates(numbers: [Int]) -> [Int] {
var result = [Int]()
for number in numbers {
if!result.contains(number) {
result.append(number)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var result = [Int]()
for number in numbers {
if!result.contains(number) {
result.append(number)
}
}
return result
}
```if!result.contains(number) { // expected expression, var, or let in 'if' conditionfunc removeDuplicates(numbers: [Int]) -> [Int] {
var result = [Int]()
for number in numbers {
if!result.contains(number) {
result.append(number)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var result = [Int]()
for number in numbers {
if!result.contains(number) {
result.append(number)
}
}
return result
}
```if!result.contains(number) { // expected expression, var, or let in 'if' conditionfunc flipCase(string: String) -> String {
return string.replacingOccurrences(of: "a-z", with: "A-Z", options:.literal, range: nil)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
Answer:
```swift
func flipCase(string: String) -> String {
return string.replacingOccurrences(of: "a-z", with: "A-Z", options:.literal, range: nil)
}
``` // XCTAssertTrue failedfunc flipCase(string: String) -> String {
return string.replacingOccurrences(of: "a-z", with: "A-Z", options:.literal, range: nil)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
Answer:
```swift
func flipCase(string: String) -> String {
return string.replacingOccurrences(of: "a-z", with: "A-Z", options:.literal, range: nil)
}
``` // XCTAssertTrue failedfunc flipCase(string: String) -> String {
return string.replacingOccurrences(of: "a-z", with: "A-Z", options:.literal, range: nil)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
Answer:
```swift
func flipCase(string: String) -> String {
return string.replacingOccurrences(of: "a-z", with: "A-Z", options:.literal, range: nil)
}
``` // XCTAssertTrue failedfunc flipCase(string: String) -> String {
var result = ""
for character in string {
if character.isLowercase {
result.append(character.uppercased())
} else {
result.append(character.lowercased())
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
Answer:
```swift
func flipCase(string: String) -> String {
var result = ""
for character in string {
if character.isLowercase {
result.append(character.uppercased())
} else {
result.append(character.lowercased())
}
}
return result
}
```func flipCase(string: String) -> String {
return string.replacingOccurrences(of: "a-z", with: "A-Z", options:.literal, range: nil)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
Answer:
```swift
func flipCase(string: String) -> String {
return string.replacingOccurrences(of: "a-z", with: "A-Z", options:.literal, range: nil)
}
``` // XCTAssertTrue failedfunc flipCase(string: String) -> String {
return string.replacingOccurrences(of: "a-z", with: "A-Z", options:.literal, range: nil)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
Answer:
```swift
func flipCase(string: String) -> String {
return string.replacingOccurrences(of: "a-z", with: "A-Z", options:.literal, range: nil)
}
``` // XCTAssertTrue failedfunc flipCase(string: String) -> String {
return string.replacingOccurrences(of: "a-z", with: "A-Z", options:.literal, range: nil)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
Answer:
```swift
func flipCase(string: String) -> String {
return string.replacingOccurrences(of: "a-z", with: "A-Z", options:.literal, range: nil)
}
``` // XCTAssertTrue failedfunc flipCase(string: String) -> String {
return string.replacingOccurrences(of: "a-z", with: "A-Z", options:.literal, range: nil)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
Answer:
```swift
func flipCase(string: String) -> String {
return string.replacingOccurrences(of: "a-z", with: "A-Z", options:.literal, range: nil)
}
``` // XCTAssertTrue failedfunc flipCase(string: String) -> String {
return string.map {
switch $0 {
case let character where character.isLowercase:
return character.uppercased()
case let character where character.isUppercase:
return character.lowercased()
default:
return character
}
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
Answer:
```swift
func flipCase(string: String) -> String {
return string.map {
switch $0 {
case let character where character.isLowercase:
return character.uppercased()
case let character where character.isUppercase:
return character.lowercased()
default:
return character
}
}
}
```return string.map { // cannot convert return expression of type '[String]' to return type 'String'return character // cannot find 'character' in scopefunc flipCase(string: String) -> String {
return string.replacingOccurrences(of: "a-z", with: "A-Z", options:.literal, range: nil)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
Answer:
```swift
func flipCase(string: String) -> String {
return string.replacingOccurrences(of: "a-z", with: "A-Z", options:.literal, range: nil)
}
``` // XCTAssertTrue failedfunc concatenate(strings: [String]) -> String {
return strings.reduce("") { $0 + $1 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
Answer:
```swift
func concatenate(strings: [String]) -> String {
return strings.reduce("") { $0 + $1 }
}
```func concatenate(strings: [String]) -> String {
return String(strings.joined())
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
Answer:
```swift
func concatenate(strings: [String]) -> String {
return String(strings.joined())
}
```func concatenate(strings: [String]) -> String {
return strings.reduce("") { result, string in
result + string
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
Answer:
```swift
func concatenate(strings: [String]) -> String {
return strings.reduce("") { result, string in
result + string
}
}
```func concatenate(strings: [String]) -> String {
return strings.reduce("") { result, string in
result + string
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
Answer:
```swift
func concatenate(strings: [String]) -> String {
return strings.reduce("") { result, string in
result + string
}
}
```func concatenate(strings: [String]) -> String {
return strings.reduce("") { $0 + $1 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
Answer:
```swift
func concatenate(strings: [String]) -> String {
return strings.reduce("") { $0 + $1 }
}
```func concatenate(strings: [String]) -> String {
return strings.reduce("") { $0 + $1 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
Answer:
```swift
func concatenate(strings: [String]) -> String {
return strings.reduce("") { $0 + $1 }
}
```func concatenate(strings: [String]) -> String {
return strings.reduce("") { $0 + $1 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
Answer:
```swift
func concatenate(strings: [String]) -> String {
return strings.reduce("") { $0 + $1 }
}
```func concatenate(strings: [String]) -> String {
return strings.reduce("") { $0 + $1 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
Answer:
```swift
func concatenate(strings: [String]) -> String {
return strings.reduce("") { $0 + $1 }
}
```func concatenate(strings: [String]) -> String {
return strings.reduce("") { $0 + $1 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
Answer:
```swift
func concatenate(strings: [String]) -> String {
return strings.reduce("") { $0 + $1 }
}
```func concatenate(strings: [String]) -> String {
return strings.reduce("") { result, string in
result + string
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
Answer:
```swift
func concatenate(strings: [String]) -> String {
return strings.reduce("") { result, string in
result + string
}
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
Answer:
```swift
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
```func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
Answer:
```swift
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
Answer:
```swift
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
Answer:
```swift
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
Answer:
```swift
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n == 2 {
return true
}
if n % 2 == 0 {
return false
}
var i = 3
while i * i <= n {
if n % i == 0 {
return false
}
i += 2
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
Answer:
```swift
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n == 2 {
return true
}
if n % 2 == 0 {
return false
}
var i = 3
while i * i <= n {
if n % i == 0 {
return false
}
i += 2
}
return true
}
```func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
Answer:
```swift
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n == 2 {
return true
}
if n % 2 == 0 {
return false
}
for i in 3..<Int(sqrt(Double(n))) + 1 {
if n % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
Answer:
```swift
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n == 2 {
return true
}
if n % 2 == 0 {
return false
}
for i in 3..<Int(sqrt(Double(n))) + 1 {
if n % i == 0 {
return false
}
}
return true
}
```func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
Answer:
```swift
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
```func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
Answer:
```swift
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func sortThird(l: [Int]) -> [Int] {
var lCopy = l
for i in 0..<l.count {
if i % 3 == 0 {
let value = lCopy[i]
lCopy[i] = lCopy[i + 1]
lCopy[i + 1] = value
}
}
return lCopy
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
var lCopy = l
for i in 0..<l.count {
if i % 3 == 0 {
let value = lCopy[i]
lCopy[i] = lCopy[i + 1]
lCopy[i + 1] = value
}
}
return lCopy
}
``` // Fatal error: Index out of rangefunc sortThird(l: [Int]) -> [Int] {
var l2 = l
for i in 0..<l.count {
if i % 3 == 0 {
l2[i] = l[i]
l2[i+1] = l[i+1]
l2[i+2] = l[i+2]
l2.sort()
}
}
return l2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
var l2 = l
for i in 0..<l.count {
if i % 3 == 0 {
l2[i] = l[i]
l2[i+1] = l[i+1]
l2[i+2] = l[i+2]
l2.sort()
}
}
return l2
}
``` // Fatal error: Index out of rangefunc sortThird(l: [Int]) -> [Int] {
var l2 = l
for i in 0..<l.count {
if i % 3 == 0 {
let value = l2[i]
l2[i] = l2[i + 1]
l2[i + 1] = value
}
}
return l2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
var l2 = l
for i in 0..<l.count {
if i % 3 == 0 {
let value = l2[i]
l2[i] = l2[i + 1]
l2[i + 1] = value
}
}
return l2
}
``` // Fatal error: Index out of rangefunc sortThird(l: [Int]) -> [Int] {
var lCopy = l
for i in 0..<lCopy.count {
if i % 3 == 0 {
lCopy[i] = lCopy[i].sorted()
}
}
return lCopy
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
var lCopy = l
for i in 0..<lCopy.count {
if i % 3 == 0 {
lCopy[i] = lCopy[i].sorted()
}
}
return lCopy
}
```lCopy[i] = lCopy[i].sorted() // value of type 'Int' has no member 'sorted'func sortThird(l: [Int]) -> [Int] {
var lCopy = l
for i in 0..<lCopy.count {
if i % 3 == 0 {
lCopy.swapAt(i, i + 1)
}
}
return lCopy
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
var lCopy = l
for i in 0..<lCopy.count {
if i % 3 == 0 {
lCopy.swapAt(i, i + 1)
}
}
return lCopy
}
``` // Fatal error: Index out of rangefunc sortThird(l: [Int]) -> [Int] {
var lCopy = l
for i in 0..<l.count {
if i % 3 == 0 {
let value = lCopy[i]
lCopy[i] = lCopy[i + 1]
lCopy[i + 1] = value
}
}
return lCopy
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
var lCopy = l
for i in 0..<l.count {
if i % 3 == 0 {
let value = lCopy[i]
lCopy[i] = lCopy[i + 1]
lCopy[i + 1] = value
}
}
return lCopy
}
``` // Fatal error: Index out of rangefunc sortThird(l: [Int]) -> [Int] {
var lCopy = l
for i in 0..<lCopy.count {
if i % 3 == 0 {
lCopy.swapAt(i, i + 1)
}
}
return lCopy
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
var lCopy = l
for i in 0..<lCopy.count {
if i % 3 == 0 {
lCopy.swapAt(i, i + 1)
}
}
return lCopy
}
``` // Fatal error: Index out of rangefunc sortThird(l: [Int]) -> [Int] {
var lCopy = l
for i in 0..<lCopy.count {
if i % 3 == 0 {
let first = lCopy[i]
let second = lCopy[i + 1]
let third = lCopy[i + 2]
lCopy[i] = third
lCopy[i + 1] = first
lCopy[i + 2] = second
}
}
return lCopy
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
var lCopy = l
for i in 0..<lCopy.count {
if i % 3 == 0 {
let first = lCopy[i]
let second = lCopy[i + 1]
let third = lCopy[i + 2]
lCopy[i] = third
lCopy[i + 1] = first
lCopy[i + 2] = second
}
}
return lCopy
}
``` // Fatal error: Index out of rangefunc sortThird(l: [Int]) -> [Int] {
var lCopy = l
for i in 0..<l.count {
if i % 3 == 0 {
let value = lCopy[i]
lCopy[i] = lCopy[i + 1]
lCopy[i + 1] = value
}
}
return lCopy
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
var lCopy = l
for i in 0..<l.count {
if i % 3 == 0 {
let value = lCopy[i]
lCopy[i] = lCopy[i + 1]
lCopy[i + 1] = value
}
}
return lCopy
}
``` // Fatal error: Index out of rangefunc sortThird(l: [Int]) -> [Int] {
var l2 = l
for i in 0..<l.count {
if i % 3 == 0 {
let value = l2[i]
l2[i] = l2[i + 1]
l2[i + 1] = value
}
}
return l2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
var l2 = l
for i in 0..<l.count {
if i % 3 == 0 {
let value = l2[i]
l2[i] = l2[i + 1]
l2[i + 1] = value
}
}
return l2
}
``` // Fatal error: Index out of rangefunc unique(l: [Int]) -> [Int] {
var result = [Int]()
for num in l {
if!result.contains(num) {
result.append(num)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
Answer:
```swift
func unique(l: [Int]) -> [Int] {
var result = [Int]()
for num in l {
if!result.contains(num) {
result.append(num)
}
}
return result
}
```if!result.contains(num) { // expected expression, var, or let in 'if' conditionfunc unique(l: [Int]) -> [Int] {
var result = [Int]()
for element in l {
if!result.contains(element) {
result.append(element)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
Answer:
```swift
func unique(l: [Int]) -> [Int] {
var result = [Int]()
for element in l {
if!result.contains(element) {
result.append(element)
}
}
return result
}
```if!result.contains(element) { // expected expression, var, or let in 'if' conditionfunc unique(l: [Int]) -> [Int] {
var result = [Int]()
for element in l {
if!result.contains(element) {
result.append(element)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
Answer:
```swift
func unique(l: [Int]) -> [Int] {
var result = [Int]()
for element in l {
if!result.contains(element) {
result.append(element)
}
}
return result
}
```if!result.contains(element) { // expected expression, var, or let in 'if' conditionfunc unique(l: [Int]) -> [Int] {
var result = [Int]()
for i in l {
if!result.contains(i) {
result.append(i)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
Answer:
```swift
func unique(l: [Int]) -> [Int] {
var result = [Int]()
for i in l {
if!result.contains(i) {
result.append(i)
}
}
return result
}
```if!result.contains(i) { // expected expression, var, or let in 'if' conditionfunc unique(l: [Int]) -> [Int] {
var uniqueElements = Set<Int>()
for element in l {
if!uniqueElements.contains(element) {
uniqueElements.insert(element)
}
}
return Array(uniqueElements)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
Answer:
```swift
func unique(l: [Int]) -> [Int] {
var uniqueElements = Set<Int>()
for element in l {
if!uniqueElements.contains(element) {
uniqueElements.insert(element)
}
}
return Array(uniqueElements)
}
```if!uniqueElements.contains(element) { // expected expression, var, or let in 'if' conditionfunc unique(l: [Int]) -> [Int] {
var result = [Int]()
for i in l {
if!result.contains(i) {
result.append(i)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
Answer:
```swift
func unique(l: [Int]) -> [Int] {
var result = [Int]()
for i in l {
if!result.contains(i) {
result.append(i)
}
}
return result
}
```if!result.contains(i) { // expected expression, var, or let in 'if' conditionfunc unique(l: [Int]) -> [Int] {
var result = [Int]()
for element in l {
if!result.contains(element) {
result.append(element)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
Answer:
```swift
func unique(l: [Int]) -> [Int] {
var result = [Int]()
for element in l {
if!result.contains(element) {
result.append(element)
}
}
return result
}
```if!result.contains(element) { // expected expression, var, or let in 'if' conditionfunc unique(l: [Int]) -> [Int] {
var result = [Int]()
var seen = Set<Int>()
for element in l {
if!seen.contains(element) {
seen.insert(element)
result.append(element)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
Answer:
```swift
func unique(l: [Int]) -> [Int] {
var result = [Int]()
var seen = Set<Int>()
for element in l {
if!seen.contains(element) {
seen.insert(element)
result.append(element)
}
}
return result
}
```if!seen.contains(element) { // expected expression, var, or let in 'if' conditionfunc unique(l: [Int]) -> [Int] {
var result = [Int]()
for i in l {
if!result.contains(i) {
result.append(i)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
Answer:
```swift
func unique(l: [Int]) -> [Int] {
var result = [Int]()
for i in l {
if!result.contains(i) {
result.append(i)
}
}
return result
}
```if!result.contains(i) { // expected expression, var, or let in 'if' conditionfunc unique(l: [Int]) -> [Int] {
var result = [Int]()
for element in l {
if!result.contains(element) {
result.append(element)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
Answer:
```swift
func unique(l: [Int]) -> [Int] {
var result = [Int]()
for element in l {
if!result.contains(element) {
result.append(element)
}
}
return result
}
```if!result.contains(element) { // expected expression, var, or let in 'if' conditionfunc maxElement(l: [Int]) -> Int {
return l.reduce(Int.min) { (max, current) in
return max > current? max : current
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
Answer:
```swift
func maxElement(l: [Int]) -> Int {
return l.reduce(Int.min) { (max, current) in
return max > current? max : current
}
}
```return max > current? max : current // consecutive statements on a line must be separated by ';'return max > current? max : current // cannot convert value of type 'Bool' to closure result type 'Int'return max > current? max : current // cannot use optional chaining on non-optional value of type 'Int'return max > current? max : current // consecutive statements on a line must be separated by ';'return max > current? max : current // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return max > current? max : current // expected expressionfunc maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
Answer:
```swift
func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}
```func maxElement(l: [Int]) -> Int {
return l.reduce(Int.min) { (max, element) in
return max > element? max : element
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
Answer:
```swift
func maxElement(l: [Int]) -> Int {
return l.reduce(Int.min) { (max, element) in
return max > element? max : element
}
}
```return max > element? max : element // consecutive statements on a line must be separated by ';'return max > element? max : element // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return max > element? max : element // expected expressionreturn max > element? max : element // cannot convert value of type 'Bool' to closure result type 'Int'return max > element? max : element // consecutive statements on a line must be separated by ';'return max > element? max : element // cannot use optional chaining on non-optional value of type 'Int'func maxElement(l: [Int]) -> Int {
var max = l[0]
for num in l {
if num > max {
max = num
}
}
return max
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
Answer:
```swift
func maxElement(l: [Int]) -> Int {
var max = l[0]
for num in l {
if num > max {
max = num
}
}
return max
}
```func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
Answer:
```swift
func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}
```func maxElement(l: [Int]) -> Int {
var max = l[0]
for element in l {
if element > max {
max = element
}
}
return max
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
Answer:
```swift
func maxElement(l: [Int]) -> Int {
var max = l[0]
for element in l {
if element > max {
max = element
}
}
return max
}
```func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
Answer:
```swift
func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}
```func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
Answer:
```swift
func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}
```func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in l {
if i > max {
max = i
}
}
return max
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
Answer:
```swift
func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in l {
if i > max {
max = i
}
}
return max
}
```func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in l {
if i > max {
max = i
}
}
return max
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
Answer:
```swift
func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in l {
if i > max {
max = i
}
}
return max
}
```func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n {
if i % 11 == 0 || i % 13 == 0 {
let numberString = String(i)
if numberString.contains("7") {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
Answer:
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n {
if i % 11 == 0 || i % 13 == 0 {
let numberString = String(i)
if numberString.contains("7") {
count += 1
}
}
}
return count
}
``` // XCTAssertTrue failedfunc fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n {
if i % 11 == 0 || i % 13 == 0 {
let string = String(i)
if string.contains("7") {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
Answer:
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n {
if i % 11 == 0 || i % 13 == 0 {
let string = String(i)
if string.contains("7") {
count += 1
}
}
}
return count
}
``` // XCTAssertTrue failedfunc fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n {
if i % 11 == 0 || i % 13 == 0 {
let string = String(i)
if string.contains("7") {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
Answer:
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n {
if i % 11 == 0 || i % 13 == 0 {
let string = String(i)
if string.contains("7") {
count += 1
}
}
}
return count
}
``` // XCTAssertTrue failedfunc fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n {
if i % 11 == 0 || i % 13 == 0 {
let string = String(i)
if string.contains("7") {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
Answer:
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n {
if i % 11 == 0 || i % 13 == 0 {
let string = String(i)
if string.contains("7") {
count += 1
}
}
}
return count
}
``` // XCTAssertTrue failedfunc fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n {
if i % 11 == 0 || i % 13 == 0 {
let numberString = String(i)
if numberString.contains("7") {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
Answer:
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n {
if i % 11 == 0 || i % 13 == 0 {
let numberString = String(i)
if numberString.contains("7") {
count += 1
}
}
}
return count
}
``` // XCTAssertTrue failedfunc fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n {
if i % 11 == 0 || i % 13 == 0 {
if String(i).contains("7") {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
Answer:
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n {
if i % 11 == 0 || i % 13 == 0 {
if String(i).contains("7") {
count += 1
}
}
}
return count
}
``` // XCTAssertTrue failedfunc fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n {
if i % 11 == 0 || i % 13 == 0 {
if String(i).contains("7") {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
Answer:
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n {
if i % 11 == 0 || i % 13 == 0 {
if String(i).contains("7") {
count += 1
}
}
}
return count
}
``` // XCTAssertTrue failedfunc fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n {
if i % 11 == 0 || i % 13 == 0 {
let string = String(i)
if string.contains("7") {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
Answer:
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n {
if i % 11 == 0 || i % 13 == 0 {
let string = String(i)
if string.contains("7") {
count += 1
}
}
}
return count
}
``` // XCTAssertTrue failedfunc fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n {
if i % 11 == 0 || i % 13 == 0 {
if String(i).contains("7") {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
Answer:
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n {
if i % 11 == 0 || i % 13 == 0 {
if String(i).contains("7") {
count += 1
}
}
}
return count
}
``` // XCTAssertTrue failedfunc fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n {
if i % 11 == 0 || i % 13 == 0 {
let s = String(i)
if s.contains("7") {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
Answer:
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n {
if i % 11 == 0 || i % 13 == 0 {
let s = String(i)
if s.contains("7") {
count += 1
}
}
}
return count
}
``` // XCTAssertTrue failedfunc sortEven(l: [Int]) -> [Int] {
var l = l
for i in stride(from: 0, to: l.count, by: 2) {
let evenIndex = i + 1
let evenValue = l[evenIndex]
var j = i
while j > 0 && l[j - 1] > evenValue {
l[j] = l[j - 1]
j -= 1
}
l[j] = evenValue
}
return l
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
var l = l
for i in stride(from: 0, to: l.count, by: 2) {
let evenIndex = i + 1
let evenValue = l[evenIndex]
var j = i
while j > 0 && l[j - 1] > evenValue {
l[j] = l[j - 1]
j -= 1
}
l[j] = evenValue
}
return l
}
``` // Fatal error: Index out of rangefunc sortEven(l: [Int]) -> [Int] {
var lCopy = l
for i in stride(from: 0, to: l.count, by: 2) {
let evenIndex = l.index(l.startIndex, offsetBy: i + 1)
let evenValue = l[evenIndex]
let oddIndex = l.index(l.startIndex, offsetBy: i)
let oddValue = l[oddIndex]
lCopy[oddIndex] = evenValue
lCopy[evenIndex] = oddValue
}
return lCopy
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
var lCopy = l
for i in stride(from: 0, to: l.count, by: 2) {
let evenIndex = l.index(l.startIndex, offsetBy: i + 1)
let evenValue = l[evenIndex]
let oddIndex = l.index(l.startIndex, offsetBy: i)
let oddValue = l[oddIndex]
lCopy[oddIndex] = evenValue
lCopy[evenIndex] = oddValue
}
return lCopy
}
``` // Fatal error: Index out of rangefunc sortEven(l: [Int]) -> [Int] {
var l2 = l
for i in stride(from: 0, to: l.count, by: 2) {
let evenIndex = i + 1
let evenValue = l2[evenIndex]
let oddIndex = i
l2[oddIndex] = evenValue
}
return l2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
var l2 = l
for i in stride(from: 0, to: l.count, by: 2) {
let evenIndex = i + 1
let evenValue = l2[evenIndex]
let oddIndex = i
l2[oddIndex] = evenValue
}
return l2
}
``` // Fatal error: Index out of rangefunc sortEven(l: [Int]) -> [Int] {
var lCopy = l
for i in stride(from: 0, to: lCopy.count, by: 2) {
let evenIndex = i + 1
let evenValue = lCopy[evenIndex]
var j = i
while j > 0 && lCopy[j - 1] > evenValue {
lCopy[j] = lCopy[j - 1]
j -= 1
}
lCopy[j] = evenValue
}
return lCopy
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
var lCopy = l
for i in stride(from: 0, to: lCopy.count, by: 2) {
let evenIndex = i + 1
let evenValue = lCopy[evenIndex]
var j = i
while j > 0 && lCopy[j - 1] > evenValue {
lCopy[j] = lCopy[j - 1]
j -= 1
}
lCopy[j] = evenValue
}
return lCopy
}
``` // Fatal error: Index out of rangefunc sortEven(l: [Int]) -> [Int] {
var l2 = l
for i in stride(from: 0, to: l.count, by: 2) {
let evenIndex = i + 1
let evenValue = l2[evenIndex]
l2[evenIndex] = l2[i]
l2[i] = evenValue
}
return l2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
var l2 = l
for i in stride(from: 0, to: l.count, by: 2) {
let evenIndex = i + 1
let evenValue = l2[evenIndex]
l2[evenIndex] = l2[i]
l2[i] = evenValue
}
return l2
}
``` // Fatal error: Index out of rangefunc sortEven(l: [Int]) -> [Int] {
var result = [Int]()
for i in 0..<l.count {
if i % 2 == 0 {
result.append(l[i])
} else {
result.append(l[i].sorted())
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
var result = [Int]()
for i in 0..<l.count {
if i % 2 == 0 {
result.append(l[i])
} else {
result.append(l[i].sorted())
}
}
return result
}
```result.append(l[i].sorted()) // value of type 'Int' has no member 'sorted'func sortEven(l: [Int]) -> [Int] {
var result = [Int]()
for i in 0..<l.count {
if i % 2 == 0 {
result.append(l[i])
} else {
result.append(l[i].sorted())
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
var result = [Int]()
for i in 0..<l.count {
if i % 2 == 0 {
result.append(l[i])
} else {
result.append(l[i].sorted())
}
}
return result
}
```result.append(l[i].sorted()) // value of type 'Int' has no member 'sorted'func sortEven(l: [Int]) -> [Int] {
var result = [Int]()
for i in 0..<l.count {
if i % 2 == 0 {
result.append(l[i])
} else {
result.append(l[i].sorted())
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
var result = [Int]()
for i in 0..<l.count {
if i % 2 == 0 {
result.append(l[i])
} else {
result.append(l[i].sorted())
}
}
return result
}
```result.append(l[i].sorted()) // value of type 'Int' has no member 'sorted'func sortEven(l: [Int]) -> [Int] {
var lCopy = l
for i in stride(from: 0, to: l.count, by: 2) {
let evenIndex = i + 1
let evenValue = lCopy[evenIndex]
var j = i
while j > 0 && lCopy[j - 1] > evenValue {
lCopy[j] = lCopy[j - 1]
j -= 1
}
lCopy[j] = evenValue
}
return lCopy
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
var lCopy = l
for i in stride(from: 0, to: l.count, by: 2) {
let evenIndex = i + 1
let evenValue = lCopy[evenIndex]
var j = i
while j > 0 && lCopy[j - 1] > evenValue {
lCopy[j] = lCopy[j - 1]
j -= 1
}
lCopy[j] = evenValue
}
return lCopy
}
``` // Fatal error: Index out of rangefunc sortEven(l: [Int]) -> [Int] {
var l = l
for i in stride(from: 0, to: l.count, by: 2) {
let evenIndex = i + 1
let evenValue = l[evenIndex]
var j = i
while j > 0 && l[j - 1] > evenValue {
l[j] = l[j - 1]
j -= 1
}
l[j] = evenValue
}
return l
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
var l = l
for i in stride(from: 0, to: l.count, by: 2) {
let evenIndex = i + 1
let evenValue = l[evenIndex]
var j = i
while j > 0 && l[j - 1] > evenValue {
l[j] = l[j - 1]
j -= 1
}
l[j] = evenValue
}
return l
}
``` // Fatal error: Index out of rangefunc primeFib(n: Int) -> Int {
var a = 0
var b = 1
var c = 0
for _ in 1...n {
c = a + b
a = b
b = c
}
return c
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
Answer:
```swift
func primeFib(n: Int) -> Int {
var a = 0
var b = 1
var c = 0
for _ in 1...n {
c = a + b
a = b
b = c
}
return c
}
``` // XCTAssertTrue failedfunc primeFib(n: Int) -> Int {
var a = 0
var b = 1
var c = 0
var i = 1
while i < n {
c = a + b
a = b
b = c
i += 1
}
return c
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
Answer:
```swift
func primeFib(n: Int) -> Int {
var a = 0
var b = 1
var c = 0
var i = 1
while i < n {
c = a + b
a = b
b = c
i += 1
}
return c
}
``` // XCTAssertTrue failedfunc primeFib(n: Int) -> Int {
var a = 0
var b = 1
var result = 0
for _ in 0..<n {
result = a + b
a = b
b = result
while result % 2 == 0 {
result /= 2
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
Answer:
```swift
func primeFib(n: Int) -> Int {
var a = 0
var b = 1
var result = 0
for _ in 0..<n {
result = a + b
a = b
b = result
while result % 2 == 0 {
result /= 2
}
}
return result
}
``` // XCTAssertTrue failedfunc primeFib(n: Int) -> Int {
var a = 0
var b = 1
var c = 0
var i = 1
while i < n {
c = a + b
a = b
b = c
i += 1
}
return c
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
Answer:
```swift
func primeFib(n: Int) -> Int {
var a = 0
var b = 1
var c = 0
var i = 1
while i < n {
c = a + b
a = b
b = c
i += 1
}
return c
}
``` // XCTAssertTrue failedfunc primeFib(n: Int) -> Int {
var a = 0
var b = 1
var c = 0
for _ in 1...n {
c = a + b
a = b
b = c
}
return c
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
Answer:
```swift
func primeFib(n: Int) -> Int {
var a = 0
var b = 1
var c = 0
for _ in 1...n {
c = a + b
a = b
b = c
}
return c
}
``` // XCTAssertTrue failedfunc primeFib(n: Int) -> Int {
var a = 0
var b = 1
var c = 0
for _ in 0..<n {
c = a + b
a = b
b = c
}
return c
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
Answer:
```swift
func primeFib(n: Int) -> Int {
var a = 0
var b = 1
var c = 0
for _ in 0..<n {
c = a + b
a = b
b = c
}
return c
}
``` // XCTAssertTrue failedfunc primeFib(n: Int) -> Int {
var a = 0
var b = 1
var c = 0
for _ in 1...n {
c = a + b
a = b
b = c
}
return c
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
Answer:
```swift
func primeFib(n: Int) -> Int {
var a = 0
var b = 1
var c = 0
for _ in 1...n {
c = a + b
a = b
b = c
}
return c
}
``` // XCTAssertTrue failedfunc primeFib(n: Int) -> Int {
var a = 0
var b = 1
var c = 0
for _ in 0..<n {
c = a + b
a = b
b = c
}
return c
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
Answer:
```swift
func primeFib(n: Int) -> Int {
var a = 0
var b = 1
var c = 0
for _ in 0..<n {
c = a + b
a = b
b = c
}
return c
}
``` // XCTAssertTrue failedfunc primeFib(n: Int) -> Int {
var a = 0
var b = 1
var result = 0
var i = 0
while i < n {
result = a + b
a = b
b = result
i += 1
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
Answer:
```swift
func primeFib(n: Int) -> Int {
var a = 0
var b = 1
var result = 0
var i = 0
while i < n {
result = a + b
a = b
b = result
i += 1
}
return result
}
``` // XCTAssertTrue failedfunc primeFib(n: Int) -> Int {
var a = 0
var b = 1
var result = 0
for _ in 0..<n {
result = a + b
a = b
b = result
if isPrime(number: result) {
return result
}
}
return 0
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
Answer:
```swift
func primeFib(n: Int) -> Int {
var a = 0
var b = 1
var result = 0
for _ in 0..<n {
result = a + b
a = b
b = result
if isPrime(number: result) {
return result
}
}
return 0
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc triplesSumToZero(l: [Int]) -> Bool {
let set = Set(l)
for i in 0..<l.count {
let complement = -l[i]
if set.contains(complement) && complement!= l[i] {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
let set = Set(l)
for i in 0..<l.count {
let complement = -l[i]
if set.contains(complement) && complement!= l[i] {
return true
}
}
return false
}
```if set.contains(complement) && complement!= l[i] { // use of '=' in a boolean context, did you mean '=='?if set.contains(complement) && complement!= l[i] { // cannot force unwrap value of non-optional type 'Int'if set.contains(complement) && complement!= l[i] { // '=' must have consistent whitespace on both sidesif set.contains(complement) && complement!= l[i] { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadfunc triplesSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count {
for j in (i + 1)..<l.count {
for k in (j + 1)..<l.count {
if l[i] + l[j] + l[k] == 0 {
return true
}
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count {
for j in (i + 1)..<l.count {
for k in (j + 1)..<l.count {
if l[i] + l[j] + l[k] == 0 {
return true
}
}
}
}
return false
}
```func triplesSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count {
for j in (i+1)..<l.count {
for k in (j+1)..<l.count {
if l[i] + l[j] + l[k] == 0 {
return true
}
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count {
for j in (i+1)..<l.count {
for k in (j+1)..<l.count {
if l[i] + l[j] + l[k] == 0 {
return true
}
}
}
}
return false
}
```func triplesSumToZero(l: [Int]) -> Bool {
let set = Set(l)
for i in 0..<l.count {
let complement = -l[i]
if set.contains(complement) && complement!= l[i] {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
let set = Set(l)
for i in 0..<l.count {
let complement = -l[i]
if set.contains(complement) && complement!= l[i] {
return true
}
}
return false
}
```if set.contains(complement) && complement!= l[i] { // use of '=' in a boolean context, did you mean '=='?if set.contains(complement) && complement!= l[i] { // cannot force unwrap value of non-optional type 'Int'if set.contains(complement) && complement!= l[i] { // '=' must have consistent whitespace on both sidesif set.contains(complement) && complement!= l[i] { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadfunc triplesSumToZero(l: [Int]) -> Bool {
let set = Set(l)
for i in 0..<l.count {
for j in i+1..<l.count {
for k in j+1..<l.count {
if set.contains(-(l[i] + l[j] + l[k])) {
return true
}
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
let set = Set(l)
for i in 0..<l.count {
for j in i+1..<l.count {
for k in j+1..<l.count {
if set.contains(-(l[i] + l[j] + l[k])) {
return true
}
}
}
}
return false
}
```func triplesSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count {
for j in (i+1)..<l.count {
for k in (j+1)..<l.count {
if l[i] + l[j] + l[k] == 0 {
return true
}
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count {
for j in (i+1)..<l.count {
for k in (j+1)..<l.count {
if l[i] + l[j] + l[k] == 0 {
return true
}
}
}
}
return false
}
```func triplesSumToZero(l: [Int]) -> Bool {
let set = Set(l)
for i in 0..<l.count {
let complement = -l[i]
if set.contains(complement) {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
let set = Set(l)
for i in 0..<l.count {
let complement = -l[i]
if set.contains(complement) {
return true
}
}
return false
}
``` // XCTAssertTrue failedfunc triplesSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count {
for j in (i + 1)..<l.count {
for k in (j + 1)..<l.count {
if l[i] + l[j] + l[k] == 0 {
return true
}
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count {
for j in (i + 1)..<l.count {
for k in (j + 1)..<l.count {
if l[i] + l[j] + l[k] == 0 {
return true
}
}
}
}
return false
}
```func triplesSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count {
for j in (i + 1)..<l.count {
for k in (j + 1)..<l.count {
if l[i] + l[j] + l[k] == 0 {
return true
}
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count {
for j in (i + 1)..<l.count {
for k in (j + 1)..<l.count {
if l[i] + l[j] + l[k] == 0 {
return true
}
}
}
}
return false
}
```func triplesSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count {
for j in (i + 1)..<l.count {
for k in (j + 1)..<l.count {
if l[i] + l[j] + l[k] == 0 {
return true
}
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count {
for j in (i + 1)..<l.count {
for k in (j + 1)..<l.count {
if l[i] + l[j] + l[k] == 0 {
return true
}
}
}
}
return false
}
```func carRaceCollision(n: Int) -> Int {
return n * (n - 1) / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
Answer:
```swift
func carRaceCollision(n: Int) -> Int {
return n * (n - 1) / 2
}
``` // XCTAssertTrue failedfunc carRaceCollision(n: Int) -> Int {
return n * (n - 1) / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
Answer:
```swift
func carRaceCollision(n: Int) -> Int {
return n * (n - 1) / 2
}
``` // XCTAssertTrue failedfunc carRaceCollision(n: Int) -> Int {
return n * (n - 1) / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
Answer:
```swift
func carRaceCollision(n: Int) -> Int {
return n * (n - 1) / 2
}
``` // XCTAssertTrue failedfunc carRaceCollision(n: Int) -> Int {
var cars = [Int](repeating: 0, count: n)
var collisions = 0
var i = 0
var j = 0
while i < n && j < n {
if cars[i] == 0 {
i += 1
} else if cars[j] == 1 {
j += 1
} else {
collisions += 1
cars[i] = 1
cars[j] = 0
i += 1
j += 1
}
}
return collisions
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
Answer:
```swift
func carRaceCollision(n: Int) -> Int {
var cars = [Int](repeating: 0, count: n)
var collisions = 0
var i = 0
var j = 0
while i < n && j < n {
if cars[i] == 0 {
i += 1
} else if cars[j] == 1 {
j += 1
} else {
collisions += 1
cars[i] = 1
cars[j] = 0
i += 1
j += 1
}
}
return collisions
}
``` // XCTAssertTrue failedfunc carRaceCollision(n: Int) -> Int {
return n * (n - 1) / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
Answer:
```swift
func carRaceCollision(n: Int) -> Int {
return n * (n - 1) / 2
}
``` // XCTAssertTrue failedfunc carRaceCollision(n: Int) -> Int {
var total = 0
var cars = [Int](repeating: 0, count: n)
var cars2 = [Int](repeating: 0, count: n)
var i = 0
var j = 0
while i < n && j < n {
if cars[i] < cars2[j] {
cars[i] += 1
i += 1
} else if cars[i] > cars2[j] {
cars2[j] += 1
j += 1
} else {
total += 1
i += 1
j += 1
}
}
return total
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
Answer:
```swift
func carRaceCollision(n: Int) -> Int {
var total = 0
var cars = [Int](repeating: 0, count: n)
var cars2 = [Int](repeating: 0, count: n)
var i = 0
var j = 0
while i < n && j < n {
if cars[i] < cars2[j] {
cars[i] += 1
i += 1
} else if cars[i] > cars2[j] {
cars2[j] += 1
j += 1
} else {
total += 1
i += 1
j += 1
}
}
return total
}
``` // XCTAssertTrue failedfunc carRaceCollision(n: Int) -> Int {
return n * (n - 1) / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
Answer:
```swift
func carRaceCollision(n: Int) -> Int {
return n * (n - 1) / 2
}
``` // XCTAssertTrue failedfunc carRaceCollision(n: Int) -> Int {
var cars = [Int](repeating: 0, count: n)
var collisions = 0
var left = 0
var right = n - 1
while left < right {
if cars[left] == 0 {
cars[left] = 1
left += 1
} else {
cars[right] = 1
right -= 1
collisions += 1
}
}
return collisions
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
Answer:
```swift
func carRaceCollision(n: Int) -> Int {
var cars = [Int](repeating: 0, count: n)
var collisions = 0
var left = 0
var right = n - 1
while left < right {
if cars[left] == 0 {
cars[left] = 1
left += 1
} else {
cars[right] = 1
right -= 1
collisions += 1
}
}
return collisions
}
``` // XCTAssertTrue failedfunc carRaceCollision(n: Int) -> Int {
var count = 0
var cars = [Int](repeating: 0, count: n)
var cars2 = [Int](repeating: 0, count: n)
var i = 0
var j = 0
while i < n && j < n {
if cars[i] == 0 {
cars[i] = 1
i += 1
} else if cars2[j] == 0 {
cars2[j] = 1
j += 1
} else {
cars[i] = 0
cars2[j] = 0
count += 1
i += 1
j += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
Answer:
```swift
func carRaceCollision(n: Int) -> Int {
var count = 0
var cars = [Int](repeating: 0, count: n)
var cars2 = [Int](repeating: 0, count: n)
var i = 0
var j = 0
while i < n && j < n {
if cars[i] == 0 {
cars[i] = 1
i += 1
} else if cars2[j] == 0 {
cars2[j] = 1
j += 1
} else {
cars[i] = 0
cars2[j] = 0
count += 1
i += 1
j += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc carRaceCollision(n: Int) -> Int {
var collisions = 0
var cars = [Int](repeating: 0, count: n)
var carsIndex = 0
var carsSpeed = 1
while carsIndex < n {
cars[carsIndex] += carsSpeed
carsIndex += carsSpeed
carsSpeed *= -1
}
carsIndex = 0
carsSpeed = 1
while carsIndex < n {
collisions += cars[carsIndex]
carsIndex += carsSpeed
carsSpeed *= -1
}
return collisions
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
Answer:
```swift
func carRaceCollision(n: Int) -> Int {
var collisions = 0
var cars = [Int](repeating: 0, count: n)
var carsIndex = 0
var carsSpeed = 1
while carsIndex < n {
cars[carsIndex] += carsSpeed
carsIndex += carsSpeed
carsSpeed *= -1
}
carsIndex = 0
carsSpeed = 1
while carsIndex < n {
collisions += cars[carsIndex]
carsIndex += carsSpeed
carsSpeed *= -1
}
return collisions
}
```func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
Answer:
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
Answer:
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
Answer:
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
Answer:
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
Answer:
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
Answer:
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
Answer:
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
Answer:
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
Answer:
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
Answer:
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func pairsSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count {
for j in (i + 1)..<l.count {
if l[i] + l[j] == 0 {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count {
for j in (i + 1)..<l.count {
if l[i] + l[j] == 0 {
return true
}
}
}
return false
}
```func pairsSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count {
for j in (i + 1)..<l.count {
if l[i] + l[j] == 0 {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count {
for j in (i + 1)..<l.count {
if l[i] + l[j] == 0 {
return true
}
}
}
return false
}
```func pairsSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count {
for j in (i+1)..<l.count {
if l[i] + l[j] == 0 {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count {
for j in (i+1)..<l.count {
if l[i] + l[j] == 0 {
return true
}
}
}
return false
}
```func pairsSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count {
for j in (i + 1)..<l.count {
if l[i] + l[j] == 0 {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count {
for j in (i + 1)..<l.count {
if l[i] + l[j] == 0 {
return true
}
}
}
return false
}
```func pairsSumToZero(l: [Int]) -> Bool {
for (i, num) in l.enumerated() {
for (j, otherNum) in l.enumerated() {
if i!= j && num + otherNum == 0 {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
for (i, num) in l.enumerated() {
for (j, otherNum) in l.enumerated() {
if i!= j && num + otherNum == 0 {
return true
}
}
}
return false
}
```if i!= j && num + otherNum == 0 { // cannot force unwrap value of non-optional type 'Int'if i!= j && num + otherNum == 0 { // use of '=' in a boolean context, did you mean '=='?if i!= j && num + otherNum == 0 { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadif i!= j && num + otherNum == 0 { // '=' must have consistent whitespace on both sidesif i!= j && num + otherNum == 0 { // cannot assign value of type 'Bool' to type 'Int'func pairsSumToZero(l: [Int]) -> Bool {
let set = Set(l)
for i in l {
if set.contains(-i) {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
let set = Set(l)
for i in l {
if set.contains(-i) {
return true
}
}
return false
}
``` // XCTAssertTrue failedfunc pairsSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count {
for j in (i + 1)..<l.count {
if l[i] + l[j] == 0 {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count {
for j in (i + 1)..<l.count {
if l[i] + l[j] == 0 {
return true
}
}
}
return false
}
```func pairsSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count {
for j in (i + 1)..<l.count {
if l[i] + l[j] == 0 {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count {
for j in (i + 1)..<l.count {
if l[i] + l[j] == 0 {
return true
}
}
}
return false
}
```func pairsSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count {
for j in (i + 1)..<l.count {
if l[i] + l[j] == 0 {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count {
for j in (i + 1)..<l.count {
if l[i] + l[j] == 0 {
return true
}
}
}
return false
}
```func pairsSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count {
for j in (i+1)..<l.count {
if l[i] + l[j] == 0 {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count {
for j in (i+1)..<l.count {
if l[i] + l[j] == 0 {
return true
}
}
}
return false
}
```func changeBase(x: Int, base: Int) -> String {
var result = ""
var remainder = x
while remainder > 0 {
let remainderInt = remainder % base
result = "\(remainderInt)" + result
remainder = remainder / base
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
var result = ""
var remainder = x
while remainder > 0 {
let remainderInt = remainder % base
result = "\(remainderInt)" + result
remainder = remainder / base
}
return result
}
```func changeBase(x: Int, base: Int) -> String {
var result = ""
var remainder = x
while remainder > 0 {
let remainderInt = remainder % base
result = "\(remainderInt)" + result
remainder = remainder / base
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
var result = ""
var remainder = x
while remainder > 0 {
let remainderInt = remainder % base
result = "\(remainderInt)" + result
remainder = remainder / base
}
return result
}
```func changeBase(x: Int, base: Int) -> String {
guard x >= 0 else {
return "Invalid input"
}
guard base >= 2 && base <= 36 else {
return "Invalid base"
}
var result = ""
var x = x
while x > 0 {
let remainder = x % base
result = String(remainder) + result
x /= base
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
guard x >= 0 else {
return "Invalid input"
}
guard base >= 2 && base <= 36 else {
return "Invalid base"
}
var result = ""
var x = x
while x > 0 {
let remainder = x % base
result = String(remainder) + result
x /= base
}
return result
}
```func changeBase(x: Int, base: Int) -> String {
var result = ""
var num = x
while num > 0 {
result = "\(num % base)" + result
num /= base
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
var result = ""
var num = x
while num > 0 {
result = "\(num % base)" + result
num /= base
}
return result
}
```func changeBase(x: Int, base: Int) -> String {
var result = ""
var x = x
while x > 0 {
let remainder = x % base
result = "\(remainder)" + result
x /= base
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
var result = ""
var x = x
while x > 0 {
let remainder = x % base
result = "\(remainder)" + result
x /= base
}
return result
}
```func changeBase(x: Int, base: Int) -> String {
var result = ""
var num = x
while num > 0 {
let remainder = num % base
result = String(remainder) + result
num /= base
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
var result = ""
var num = x
while num > 0 {
let remainder = num % base
result = String(remainder) + result
num /= base
}
return result
}
```func changeBase(x: Int, base: Int) -> String {
var result = ""
var num = x
while num > 0 {
result = "\(num % base)" + result
num /= base
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
var result = ""
var num = x
while num > 0 {
result = "\(num % base)" + result
num /= base
}
return result
}
```func changeBase(x: Int, base: Int) -> String {
var result = ""
var currentNumber = x
while currentNumber > 0 {
let remainder = currentNumber % base
result = String(remainder) + result
currentNumber /= base
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
var result = ""
var currentNumber = x
while currentNumber > 0 {
let remainder = currentNumber % base
result = String(remainder) + result
currentNumber /= base
}
return result
}
```func changeBase(x: Int, base: Int) -> String {
var result = ""
var currentNumber = x
while currentNumber > 0 {
let remainder = currentNumber % base
result = "\(remainder)" + result
currentNumber /= base
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
var result = ""
var currentNumber = x
while currentNumber > 0 {
let remainder = currentNumber % base
result = "\(remainder)" + result
currentNumber /= base
}
return result
}
```func changeBase(x: Int, base: Int) -> String {
var result = ""
var remainder = x
while remainder > 0 {
let remainderBase = remainder % base
result = "\(remainderBase)" + result
remainder /= base
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
var result = ""
var remainder = x
while remainder > 0 {
let remainderBase = remainder % base
result = "\(remainderBase)" + result
remainder /= base
}
return result
}
```func triangleArea(a: Int, h: Int) -> Double {
return (1/2) * Double(a) * Double(h)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
return (1/2) * Double(a) * Double(h)
}
```func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}
```func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}
```func triangleArea(a: Int, h: Int) -> Double {
return (1/2) * Double(a) * Double(h)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
return (1/2) * Double(a) * Double(h)
}
```func triangleArea(a: Int, h: Int) -> Double {
return 0.5 * Double(a) * Double(h)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
return 0.5 * Double(a) * Double(h)
}
```func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}
```func triangleArea(a: Int, h: Int) -> Double {
return 0.5 * Double(a) * Double(h)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
return 0.5 * Double(a) * Double(h)
}
```func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}
```func triangleArea(a: Int, h: Int) -> Double {
return (1/2) * Double(a) * Double(h)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
return (1/2) * Double(a) * Double(h)
}
```func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}
```func fib4(n: Int) -> Int {
var a = 0
var b = 0
var c = 0
var d = 0
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 2
} else if n == 3 {
return 0
} else {
for i in 1...n {
c = a + b + d
d = b + c + d
a = b
b = c
}
return c
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
Answer:
```swift
func fib4(n: Int) -> Int {
var a = 0
var b = 0
var c = 0
var d = 0
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 2
} else if n == 3 {
return 0
} else {
for i in 1...n {
c = a + b + d
d = b + c + d
a = b
b = c
}
return c
}
}
```for i in 1...n { // immutable value 'i' was never used; consider replacing with '_' or removing it // XCTAssertTrue failedfunc fib4(n: Int) -> Int {
var a = 0
var b = 0
var c = 0
var d = 1
for _ in 0..<n {
(a, b, c, d) = (b, c, d, a + b + c + d)
}
return d
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
Answer:
```swift
func fib4(n: Int) -> Int {
var a = 0
var b = 0
var c = 0
var d = 1
for _ in 0..<n {
(a, b, c, d) = (b, c, d, a + b + c + d)
}
return d
}
``` // XCTAssertTrue failedfunc fib4(n: Int) -> Int {
var a = 0
var b = 0
var c = 0
var d = 0
for _ in 0..<n {
c = a + b + d
d = a + b + c
a = b
b = c
}
return c
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
Answer:
```swift
func fib4(n: Int) -> Int {
var a = 0
var b = 0
var c = 0
var d = 0
for _ in 0..<n {
c = a + b + d
d = a + b + c
a = b
b = c
}
return c
}
``` // XCTAssertTrue failedfunc fib4(n: Int) -> Int {
var a = 0
var b = 0
var c = 0
var d = 0
for _ in 0..<n {
let temp = c
c = d
d = temp + b + a
a = b
b = c
}
return d
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
Answer:
```swift
func fib4(n: Int) -> Int {
var a = 0
var b = 0
var c = 0
var d = 0
for _ in 0..<n {
let temp = c
c = d
d = temp + b + a
a = b
b = c
}
return d
}
``` // XCTAssertTrue failedfunc fib4(n: Int) -> Int {
var a = 0
var b = 0
var c = 0
var d = 0
for _ in 0..<n {
c = a + b + d
d = a + b + c
a = b
b = c
}
return c
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
Answer:
```swift
func fib4(n: Int) -> Int {
var a = 0
var b = 0
var c = 0
var d = 0
for _ in 0..<n {
c = a + b + d
d = a + b + c
a = b
b = c
}
return c
}
``` // XCTAssertTrue failedfunc fib4(n: Int) -> Int {
var a = 0
var b = 0
var c = 0
var d = 1
for _ in 0..<n {
let temp = c
c = d
d = temp + b + a
a = b
b = c
}
return d
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
Answer:
```swift
func fib4(n: Int) -> Int {
var a = 0
var b = 0
var c = 0
var d = 1
for _ in 0..<n {
let temp = c
c = d
d = temp + b + a
a = b
b = c
}
return d
}
``` // XCTAssertTrue failedfunc fib4(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 2
} else if n == 3 {
return 0
} else {
var a = 0
var b = 0
var c = 0
var d = 0
for _ in 0..<n {
d = a + b + c + d
c = b
b = a
a = d
}
return a
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
Answer:
```swift
func fib4(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 2
} else if n == 3 {
return 0
} else {
var a = 0
var b = 0
var c = 0
var d = 0
for _ in 0..<n {
d = a + b + c + d
c = b
b = a
a = d
}
return a
}
}
``` // XCTAssertTrue failedfunc fib4(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 2
} else if n == 3 {
return 0
} else {
var a = 0
var b = 0
var c = 0
var d = 0
for _ in 0..<n {
d = a + b + c + d
a = b
b = c
c = d
}
return d
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
Answer:
```swift
func fib4(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 2
} else if n == 3 {
return 0
} else {
var a = 0
var b = 0
var c = 0
var d = 0
for _ in 0..<n {
d = a + b + c + d
a = b
b = c
c = d
}
return d
}
}
``` // XCTAssertTrue failedfunc fib4(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 2
} else if n == 3 {
return 0
} else {
var a = 0
var b = 0
var c = 0
var d = 0
for i in 0..<n {
d = a + b + c
c = b
b = a
a = d
}
return d
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
Answer:
```swift
func fib4(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 2
} else if n == 3 {
return 0
} else {
var a = 0
var b = 0
var c = 0
var d = 0
for i in 0..<n {
d = a + b + c
c = b
b = a
a = d
}
return d
}
}
```for i in 0..<n { // immutable value 'i' was never used; consider replacing with '_' or removing it // XCTAssertTrue failedfunc fib4(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 2
} else if n == 3 {
return 0
} else {
var a = 0
var b = 0
var c = 0
var d = 0
for _ in 0..<n {
d = a + b + c + d
c = b
b = a
a = d
}
return a
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
Answer:
```swift
func fib4(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 2
} else if n == 3 {
return 0
} else {
var a = 0
var b = 0
var c = 0
var d = 0
for _ in 0..<n {
d = a + b + c + d
c = b
b = a
a = d
}
return a
}
}
``` // XCTAssertTrue failedfunc median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
let middleIndex = count / 2
if count % 2 == 0 {
return Double(sorted[middleIndex] + sorted[middleIndex - 1]) / 2
} else {
return Double(sorted[middleIndex])
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
Answer:
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
let middleIndex = count / 2
if count % 2 == 0 {
return Double(sorted[middleIndex] + sorted[middleIndex - 1]) / 2
} else {
return Double(sorted[middleIndex])
}
}
```func median(l: [Int]) -> Double {
let sorted = l.sorted()
let middle = sorted.count / 2
let firstHalf = sorted.prefix(middle)
let secondHalf = sorted.suffix(from: middle)
let median = Double(firstHalf.last?? 0) + Double(secondHalf.first?? 0) / 2
return median
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
Answer:
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let middle = sorted.count / 2
let firstHalf = sorted.prefix(middle)
let secondHalf = sorted.suffix(from: middle)
let median = Double(firstHalf.last?? 0) + Double(secondHalf.first?? 0) / 2
return median
}
```let median = Double(firstHalf.last?? 0) + Double(secondHalf.first?? 0) / 2 // expected ',' separatorlet median = Double(firstHalf.last?? 0) + Double(secondHalf.first?? 0) / 2 // expected ',' separatorlet median = Double(firstHalf.last?? 0) + Double(secondHalf.first?? 0) / 2 // missing argument labels 'signOf:magnitudeOf:' in calllet median = Double(firstHalf.last?? 0) + Double(secondHalf.first?? 0) / 2 // no exact matches in call to initializerlet median = Double(firstHalf.last?? 0) + Double(secondHalf.first?? 0) / 2 // cannot use optional chaining on non-optional value of type 'Int'let median = Double(firstHalf.last?? 0) + Double(secondHalf.first?? 0) / 2 // cannot use optional chaining on non-optional value of type 'Int'let median = Double(firstHalf.last?? 0) + Double(secondHalf.first?? 0) / 2 // cannot convert value of type 'Int?' to expected argument type 'Double'func median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
let middleIndex = count / 2
if count % 2 == 0 {
let firstHalf = Double(sorted[middleIndex - 1] + sorted[middleIndex]) / 2
return firstHalf
} else {
return Double(sorted[middleIndex])
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
Answer:
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
let middleIndex = count / 2
if count % 2 == 0 {
let firstHalf = Double(sorted[middleIndex - 1] + sorted[middleIndex]) / 2
return firstHalf
} else {
return Double(sorted[middleIndex])
}
}
```func median(l: [Int]) -> Double {
let sorted = l.sorted()
let middle = sorted.count / 2
if sorted.count % 2 == 0 {
return Double(sorted[middle - 1] + sorted[middle]) / 2
} else {
return Double(sorted[middle])
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
Answer:
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let middle = sorted.count / 2
if sorted.count % 2 == 0 {
return Double(sorted[middle - 1] + sorted[middle]) / 2
} else {
return Double(sorted[middle])
}
}
```func median(l: [Int]) -> Double {
let sorted = l.sorted()
let middleIndex = sorted.count / 2
let isEven = sorted.count % 2 == 0
let median = isEven? Double(sorted[middleIndex] + sorted[middleIndex - 1]) / 2 : Double(sorted[middleIndex])
return median
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
Answer:
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let middleIndex = sorted.count / 2
let isEven = sorted.count % 2 == 0
let median = isEven? Double(sorted[middleIndex] + sorted[middleIndex - 1]) / 2 : Double(sorted[middleIndex])
return median
}
```let median = isEven? Double(sorted[middleIndex] + sorted[middleIndex - 1]) / 2 : Double(sorted[middleIndex]) // consecutive statements on a line must be separated by ';'let median = isEven? Double(sorted[middleIndex] + sorted[middleIndex - 1]) / 2 : Double(sorted[middleIndex]) // cannot use optional chaining on non-optional value of type 'Bool'let median = isEven? Double(sorted[middleIndex] + sorted[middleIndex - 1]) / 2 : Double(sorted[middleIndex]) // result of operator '/' is unusedlet median = isEven? Double(sorted[middleIndex] + sorted[middleIndex - 1]) / 2 : Double(sorted[middleIndex]) // consecutive statements on a line must be separated by ';'let median = isEven? Double(sorted[middleIndex] + sorted[middleIndex - 1]) / 2 : Double(sorted[middleIndex]) // expected expressionfunc median(l: [Int]) -> Double {
let sorted = l.sorted()
let middle = sorted.count / 2
if sorted.count % 2 == 0 {
return Double(sorted[middle - 1] + sorted[middle]) / 2
} else {
return Double(sorted[middle])
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
Answer:
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let middle = sorted.count / 2
if sorted.count % 2 == 0 {
return Double(sorted[middle - 1] + sorted[middle]) / 2
} else {
return Double(sorted[middle])
}
}
```func median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
let middleIndex = count / 2
if count % 2 == 0 {
return Double(sorted[middleIndex] + sorted[middleIndex - 1]) / 2
} else {
return Double(sorted[middleIndex])
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
Answer:
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
let middleIndex = count / 2
if count % 2 == 0 {
return Double(sorted[middleIndex] + sorted[middleIndex - 1]) / 2
} else {
return Double(sorted[middleIndex])
}
}
```func median(l: [Int]) -> Double {
let sorted = l.sorted()
let middleIndex = sorted.count / 2
let isEven = sorted.count % 2 == 0
let median = isEven? Double(sorted[middleIndex] + sorted[middleIndex - 1]) / 2 : Double(sorted[middleIndex])
return median
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
Answer:
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let middleIndex = sorted.count / 2
let isEven = sorted.count % 2 == 0
let median = isEven? Double(sorted[middleIndex] + sorted[middleIndex - 1]) / 2 : Double(sorted[middleIndex])
return median
}
```let median = isEven? Double(sorted[middleIndex] + sorted[middleIndex - 1]) / 2 : Double(sorted[middleIndex]) // consecutive statements on a line must be separated by ';'let median = isEven? Double(sorted[middleIndex] + sorted[middleIndex - 1]) / 2 : Double(sorted[middleIndex]) // cannot use optional chaining on non-optional value of type 'Bool'let median = isEven? Double(sorted[middleIndex] + sorted[middleIndex - 1]) / 2 : Double(sorted[middleIndex]) // result of operator '/' is unusedlet median = isEven? Double(sorted[middleIndex] + sorted[middleIndex - 1]) / 2 : Double(sorted[middleIndex]) // consecutive statements on a line must be separated by ';'let median = isEven? Double(sorted[middleIndex] + sorted[middleIndex - 1]) / 2 : Double(sorted[middleIndex]) // expected expressionfunc median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
let middleIndex = count / 2
if count % 2 == 0 {
let firstHalf = Double(sorted[middleIndex - 1] + sorted[middleIndex]) / 2
return firstHalf
} else {
return Double(sorted[middleIndex])
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
Answer:
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
let middleIndex = count / 2
if count % 2 == 0 {
let firstHalf = Double(sorted[middleIndex - 1] + sorted[middleIndex]) / 2
return firstHalf
} else {
return Double(sorted[middleIndex])
}
}
```func median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
let middle = count / 2
if count % 2 == 0 {
let first = Double(sorted[middle - 1])
let second = Double(sorted[middle])
return (first + second) / 2
} else {
return Double(sorted[middle])
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
Answer:
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
let middle = count / 2
if count % 2 == 0 {
let first = Double(sorted[middle - 1])
let second = Double(sorted[middle])
return (first + second) / 2
} else {
return Double(sorted[middle])
}
}
```func isPalindrome(text: String) -> Bool {
let cleanText = text.replacingOccurrences(of: " ", with: "").lowercased()
let reversedText = String(cleanText.reversed())
return cleanText == reversedText
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
Answer:
```swift
func isPalindrome(text: String) -> Bool {
let cleanText = text.replacingOccurrences(of: " ", with: "").lowercased()
let reversedText = String(cleanText.reversed())
return cleanText == reversedText
}
```func isPalindrome(text: String) -> Bool {
let cleanText = text.replacingOccurrences(of: " ", with: "").lowercased()
let reversedText = String(cleanText.reversed())
return cleanText == reversedText
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
Answer:
```swift
func isPalindrome(text: String) -> Bool {
let cleanText = text.replacingOccurrences(of: " ", with: "").lowercased()
let reversedText = String(cleanText.reversed())
return cleanText == reversedText
}
```func isPalindrome(text: String) -> Bool {
let cleanText = text.replacingOccurrences(of: " ", with: "").lowercased()
return cleanText == String(cleanText.reversed())
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
Answer:
```swift
func isPalindrome(text: String) -> Bool {
let cleanText = text.replacingOccurrences(of: " ", with: "").lowercased()
return cleanText == String(cleanText.reversed())
}
```func isPalindrome(text: String) -> Bool {
let cleanText = text.replacingOccurrences(of: " ", with: "").lowercased()
let reversedText = String(cleanText.reversed())
return cleanText == reversedText
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
Answer:
```swift
func isPalindrome(text: String) -> Bool {
let cleanText = text.replacingOccurrences(of: " ", with: "").lowercased()
let reversedText = String(cleanText.reversed())
return cleanText == reversedText
}
```func isPalindrome(text: String) -> Bool {
let cleanText = text.replacingOccurrences(of: " ", with: "").lowercased()
let reversedText = String(cleanText.reversed())
return cleanText == reversedText
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
Answer:
```swift
func isPalindrome(text: String) -> Bool {
let cleanText = text.replacingOccurrences(of: " ", with: "").lowercased()
let reversedText = String(cleanText.reversed())
return cleanText == reversedText
}
```func isPalindrome(text: String) -> Bool {
let cleanText = text.replacingOccurrences(of: " ", with: "").lowercased()
let reversedText = String(cleanText.reversed())
return cleanText == reversedText
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
Answer:
```swift
func isPalindrome(text: String) -> Bool {
let cleanText = text.replacingOccurrences(of: " ", with: "").lowercased()
let reversedText = String(cleanText.reversed())
return cleanText == reversedText
}
```func isPalindrome(text: String) -> Bool {
let cleanText = text.replacingOccurrences(of: " ", with: "").lowercased()
let reversedText = String(cleanText.reversed())
return cleanText == reversedText
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
Answer:
```swift
func isPalindrome(text: String) -> Bool {
let cleanText = text.replacingOccurrences(of: " ", with: "").lowercased()
let reversedText = String(cleanText.reversed())
return cleanText == reversedText
}
```func isPalindrome(text: String) -> Bool {
let cleanText = text.replacingOccurrences(of: " ", with: "").lowercased()
let reversedText = String(cleanText.reversed())
return cleanText == reversedText
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
Answer:
```swift
func isPalindrome(text: String) -> Bool {
let cleanText = text.replacingOccurrences(of: " ", with: "").lowercased()
let reversedText = String(cleanText.reversed())
return cleanText == reversedText
}
```func isPalindrome(text: String) -> Bool {
let cleanText = text.replacingOccurrences(of: " ", with: "").lowercased()
let reversedText = String(cleanText.reversed())
return cleanText == reversedText
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
Answer:
```swift
func isPalindrome(text: String) -> Bool {
let cleanText = text.replacingOccurrences(of: " ", with: "").lowercased()
let reversedText = String(cleanText.reversed())
return cleanText == reversedText
}
```func isPalindrome(text: String) -> Bool {
let cleanText = text.replacingOccurrences(of: " ", with: "").lowercased()
let reversedText = String(cleanText.reversed())
return cleanText == reversedText
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
Answer:
```swift
func isPalindrome(text: String) -> Bool {
let cleanText = text.replacingOccurrences(of: " ", with: "").lowercased()
let reversedText = String(cleanText.reversed())
return cleanText == reversedText
}
```func modp(n: Int, p: Int) -> Int {
var result = 1
var power = n
while power > 0 {
if power % 2 == 1 {
result = (result * n) % p
}
power /= 2
n = (n * n) % p
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
Answer:
```swift
func modp(n: Int, p: Int) -> Int {
var result = 1
var power = n
while power > 0 {
if power % 2 == 1 {
result = (result * n) % p
}
power /= 2
n = (n * n) % p
}
return result
}
```n = (n * n) % p // cannot assign to value: 'n' is a 'let' constantfunc modp(n: Int, p: Int) -> Int {
var result = 1
var power = n
while power > 0 {
if power % 2 == 1 {
result = (result * n) % p
}
power /= 2
n = (n * n) % p
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
Answer:
```swift
func modp(n: Int, p: Int) -> Int {
var result = 1
var power = n
while power > 0 {
if power % 2 == 1 {
result = (result * n) % p
}
power /= 2
n = (n * n) % p
}
return result
}
```n = (n * n) % p // cannot assign to value: 'n' is a 'let' constantfunc modp(n: Int, p: Int) -> Int {
var result = 1
var power = n
while power > 0 {
if power % 2 == 1 {
result = (result * n) % p
}
power /= 2
n = (n * n) % p
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
Answer:
```swift
func modp(n: Int, p: Int) -> Int {
var result = 1
var power = n
while power > 0 {
if power % 2 == 1 {
result = (result * n) % p
}
power /= 2
n = (n * n) % p
}
return result
}
```n = (n * n) % p // cannot assign to value: 'n' is a 'let' constantfunc modp(n: Int, p: Int) -> Int {
var result = 1
var power = n
while power > 0 {
if power % 2 == 1 {
result = (result * n) % p
}
power /= 2
n = (n * n) % p
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
Answer:
```swift
func modp(n: Int, p: Int) -> Int {
var result = 1
var power = n
while power > 0 {
if power % 2 == 1 {
result = (result * n) % p
}
power /= 2
n = (n * n) % p
}
return result
}
```n = (n * n) % p // cannot assign to value: 'n' is a 'let' constantfunc modp(n: Int, p: Int) -> Int {
var result = 1
var power = n
while power > 0 {
if power % 2 == 1 {
result = (result * n) % p
}
power = power / 2
n = (n * n) % p
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
Answer:
```swift
func modp(n: Int, p: Int) -> Int {
var result = 1
var power = n
while power > 0 {
if power % 2 == 1 {
result = (result * n) % p
}
power = power / 2
n = (n * n) % p
}
return result
}
```n = (n * n) % p // cannot assign to value: 'n' is a 'let' constantfunc modp(n: Int, p: Int) -> Int {
var result = 1
var power = n
while power > 0 {
if power % 2 == 1 {
result = (result * n) % p
}
power = power / 2
n = (n * n) % p
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
Answer:
```swift
func modp(n: Int, p: Int) -> Int {
var result = 1
var power = n
while power > 0 {
if power % 2 == 1 {
result = (result * n) % p
}
power = power / 2
n = (n * n) % p
}
return result
}
```n = (n * n) % p // cannot assign to value: 'n' is a 'let' constantfunc modp(n: Int, p: Int) -> Int {
var result = 1
var power = n
while power > 0 {
if power % 2 == 1 {
result = (result * n) % p
}
power /= 2
n = (n * n) % p
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
Answer:
```swift
func modp(n: Int, p: Int) -> Int {
var result = 1
var power = n
while power > 0 {
if power % 2 == 1 {
result = (result * n) % p
}
power /= 2
n = (n * n) % p
}
return result
}
```n = (n * n) % p // cannot assign to value: 'n' is a 'let' constantfunc modp(n: Int, p: Int) -> Int {
var result = 1
var power = n
while power > 0 {
if power % 2 == 1 {
result = (result * n) % p
}
power = power / 2
n = (n * n) % p
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
Answer:
```swift
func modp(n: Int, p: Int) -> Int {
var result = 1
var power = n
while power > 0 {
if power % 2 == 1 {
result = (result * n) % p
}
power = power / 2
n = (n * n) % p
}
return result
}
```n = (n * n) % p // cannot assign to value: 'n' is a 'let' constantfunc modp(n: Int, p: Int) -> Int {
var result = 1
var power = n
while power > 0 {
if power % 2 == 1 {
result = (result * n) % p
}
power /= 2
n = (n * n) % p
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
Answer:
```swift
func modp(n: Int, p: Int) -> Int {
var result = 1
var power = n
while power > 0 {
if power % 2 == 1 {
result = (result * n) % p
}
power /= 2
n = (n * n) % p
}
return result
}
```n = (n * n) % p // cannot assign to value: 'n' is a 'let' constantfunc modp(n: Int, p: Int) -> Int {
var result = 1
var power = n
while power > 0 {
if power % 2 == 1 {
result = (result * n) % p
}
power /= 2
n = (n * n) % p
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
Answer:
```swift
func modp(n: Int, p: Int) -> Int {
var result = 1
var power = n
while power > 0 {
if power % 2 == 1 {
result = (result * n) % p
}
power /= 2
n = (n * n) % p
}
return result
}
```n = (n * n) % p // cannot assign to value: 'n' is a 'let' constantfunc removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for character in text {
if!vowels.contains(character) {
result.append(character)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
Answer:
```swift
func removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for character in text {
if!vowels.contains(character) {
result.append(character)
}
}
return result
}
```if!vowels.contains(character) { // expected expression, var, or let in 'if' conditionfunc removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for character in text {
if!vowels.contains(character) {
result.append(character)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
Answer:
```swift
func removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for character in text {
if!vowels.contains(character) {
result.append(character)
}
}
return result
}
```if!vowels.contains(character) { // expected expression, var, or let in 'if' conditionfunc removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for character in text {
if!vowels.contains(character) {
result.append(character)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
Answer:
```swift
func removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for character in text {
if!vowels.contains(character) {
result.append(character)
}
}
return result
}
```if!vowels.contains(character) { // expected expression, var, or let in 'if' conditionfunc removeVowels(text: String) -> String {
let vowels = ["a", "e", "i", "o", "u"]
var result = ""
for character in text {
if!vowels.contains(character) {
result.append(character)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
Answer:
```swift
func removeVowels(text: String) -> String {
let vowels = ["a", "e", "i", "o", "u"]
var result = ""
for character in text {
if!vowels.contains(character) {
result.append(character)
}
}
return result
}
```if!vowels.contains(character) { // expected expression, var, or let in 'if' conditionfunc removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for character in text {
if!vowels.contains(character) {
result.append(character)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
Answer:
```swift
func removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for character in text {
if!vowels.contains(character) {
result.append(character)
}
}
return result
}
```if!vowels.contains(character) { // expected expression, var, or let in 'if' conditionfunc removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for character in text {
if!vowels.contains(character) {
result.append(character)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
Answer:
```swift
func removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for character in text {
if!vowels.contains(character) {
result.append(character)
}
}
return result
}
```if!vowels.contains(character) { // expected expression, var, or let in 'if' conditionfunc removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for character in text {
if!vowels.contains(character) {
result.append(character)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
Answer:
```swift
func removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for character in text {
if!vowels.contains(character) {
result.append(character)
}
}
return result
}
```if!vowels.contains(character) { // expected expression, var, or let in 'if' conditionfunc removeVowels(text: String) -> String {
let vowels = ["a", "e", "i", "o", "u"]
var result = ""
for character in text {
if!vowels.contains(character) {
result.append(character)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
Answer:
```swift
func removeVowels(text: String) -> String {
let vowels = ["a", "e", "i", "o", "u"]
var result = ""
for character in text {
if!vowels.contains(character) {
result.append(character)
}
}
return result
}
```if!vowels.contains(character) { // expected expression, var, or let in 'if' conditionfunc removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for character in text {
if!vowels.contains(character) {
result.append(character)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
Answer:
```swift
func removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for character in text {
if!vowels.contains(character) {
result.append(character)
}
}
return result
}
```if!vowels.contains(character) { // expected expression, var, or let in 'if' conditionfunc removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for character in text {
if!vowels.contains(character) {
result.append(character)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
Answer:
```swift
func removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for character in text {
if!vowels.contains(character) {
result.append(character)
}
}
return result
}
```if!vowels.contains(character) { // expected expression, var, or let in 'if' conditionfunc belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num > t {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
Answer:
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num > t {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc belowThreshold(l: [Int], t: Int) -> Bool {
return l.allSatisfy { $0 < t }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
Answer:
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
return l.allSatisfy { $0 < t }
}
```func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num > t {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
Answer:
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num > t {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num > t {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
Answer:
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num > t {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num > t {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
Answer:
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num > t {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc belowThreshold(l: [Int], t: Int) -> Bool {
return l.allSatisfy { $0 < t }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
Answer:
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
return l.allSatisfy { $0 < t }
}
```func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num > t {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
Answer:
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num > t {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc belowThreshold(l: [Int], t: Int) -> Bool {
for i in l {
if i > t {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
Answer:
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
for i in l {
if i > t {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num > t {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
Answer:
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num > t {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num > t {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
Answer:
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num > t {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc add(x: Int, y: Int) -> Int {
return x + y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
Answer:
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func add(x: Int, y: Int) -> Int {
return x + y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
Answer:
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func add(x: Int, y: Int) -> Int {
return x + y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
Answer:
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func add(x: Int, y: Int) -> Int {
return x + y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
Answer:
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func add(x: Int, y: Int) -> Int {
return x + y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
Answer:
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func add(x: Int, y: Int) -> Int {
return x + y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
Answer:
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func add(x: Int, y: Int) -> Int {
return x + y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
Answer:
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func add(x: Int, y: Int) -> Int {
return x + y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
Answer:
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func add(x: Int, y: Int) -> Int {
return x + y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
Answer:
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func add(x: Int, y: Int) -> Int {
return x + y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
Answer:
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
if s0Chars.count!= s1Chars.count {
return false
}
for (i, char) in s0Chars.enumerated() {
if s1Chars[i]!= char {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
Answer:
```swift
func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
if s0Chars.count!= s1Chars.count {
return false
}
for (i, char) in s0Chars.enumerated() {
if s1Chars[i]!= char {
return false
}
}
return true
}
```if s0Chars.count!= s1Chars.count { // cannot force unwrap value of non-optional type 'Int'if s0Chars.count!= s1Chars.count { // '=' must have consistent whitespace on both sidesif s0Chars.count!= s1Chars.count { // use of '=' in a boolean context, did you mean '=='?if s1Chars[i]!= char { // '=' must have consistent whitespace on both sidesif s1Chars[i]!= char { // use of '=' in a boolean context, did you mean '=='?if s1Chars[i]!= char { // cannot force unwrap value of non-optional type 'String.Element' (aka 'Character')func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
if s0Chars.count!= s1Chars.count {
return false
}
for (i, char) in s0Chars.enumerated() {
if s1Chars[i]!= char {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
Answer:
```swift
func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
if s0Chars.count!= s1Chars.count {
return false
}
for (i, char) in s0Chars.enumerated() {
if s1Chars[i]!= char {
return false
}
}
return true
}
```if s0Chars.count!= s1Chars.count { // cannot force unwrap value of non-optional type 'Int'if s0Chars.count!= s1Chars.count { // '=' must have consistent whitespace on both sidesif s0Chars.count!= s1Chars.count { // use of '=' in a boolean context, did you mean '=='?if s1Chars[i]!= char { // '=' must have consistent whitespace on both sidesif s1Chars[i]!= char { // use of '=' in a boolean context, did you mean '=='?if s1Chars[i]!= char { // cannot force unwrap value of non-optional type 'String.Element' (aka 'Character')func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
return s0Chars.sorted() == s1Chars.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
Answer:
```swift
func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
return s0Chars.sorted() == s1Chars.sorted()
}
``` // XCTAssertTrue failedfunc sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
return s0Chars.sorted() == s1Chars.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
Answer:
```swift
func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
return s0Chars.sorted() == s1Chars.sorted()
}
``` // XCTAssertTrue failedfunc sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
if s0Chars.count!= s1Chars.count {
return false
}
for (i, char) in s0Chars.enumerated() {
if s1Chars[i]!= char {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
Answer:
```swift
func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
if s0Chars.count!= s1Chars.count {
return false
}
for (i, char) in s0Chars.enumerated() {
if s1Chars[i]!= char {
return false
}
}
return true
}
```if s0Chars.count!= s1Chars.count { // cannot force unwrap value of non-optional type 'Int'if s0Chars.count!= s1Chars.count { // '=' must have consistent whitespace on both sidesif s0Chars.count!= s1Chars.count { // use of '=' in a boolean context, did you mean '=='?if s1Chars[i]!= char { // '=' must have consistent whitespace on both sidesif s1Chars[i]!= char { // use of '=' in a boolean context, did you mean '=='?if s1Chars[i]!= char { // cannot force unwrap value of non-optional type 'String.Element' (aka 'Character')func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
return s0Chars.sorted() == s1Chars.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
Answer:
```swift
func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
return s0Chars.sorted() == s1Chars.sorted()
}
``` // XCTAssertTrue failedfunc sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
if s0Chars.count!= s1Chars.count {
return false
}
for (i, char) in s0Chars.enumerated() {
if s1Chars[i]!= char {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
Answer:
```swift
func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
if s0Chars.count!= s1Chars.count {
return false
}
for (i, char) in s0Chars.enumerated() {
if s1Chars[i]!= char {
return false
}
}
return true
}
```if s0Chars.count!= s1Chars.count { // cannot force unwrap value of non-optional type 'Int'if s0Chars.count!= s1Chars.count { // '=' must have consistent whitespace on both sidesif s0Chars.count!= s1Chars.count { // use of '=' in a boolean context, did you mean '=='?if s1Chars[i]!= char { // '=' must have consistent whitespace on both sidesif s1Chars[i]!= char { // use of '=' in a boolean context, did you mean '=='?if s1Chars[i]!= char { // cannot force unwrap value of non-optional type 'String.Element' (aka 'Character')func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
if s0Chars.count!= s1Chars.count {
return false
}
for (i, char) in s0Chars.enumerated() {
if s1Chars[i]!= char {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
Answer:
```swift
func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
if s0Chars.count!= s1Chars.count {
return false
}
for (i, char) in s0Chars.enumerated() {
if s1Chars[i]!= char {
return false
}
}
return true
}
```if s0Chars.count!= s1Chars.count { // cannot force unwrap value of non-optional type 'Int'if s0Chars.count!= s1Chars.count { // '=' must have consistent whitespace on both sidesif s0Chars.count!= s1Chars.count { // use of '=' in a boolean context, did you mean '=='?if s1Chars[i]!= char { // '=' must have consistent whitespace on both sidesif s1Chars[i]!= char { // use of '=' in a boolean context, did you mean '=='?if s1Chars[i]!= char { // cannot force unwrap value of non-optional type 'String.Element' (aka 'Character')func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0.characters)
let s1Chars = Array(s1.characters)
return s0Chars.sorted() == s1Chars.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
Answer:
```swift
func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0.characters)
let s1Chars = Array(s1.characters)
return s0Chars.sorted() == s1Chars.sorted()
}
```let s0Chars = Array(s0.characters) // 'characters' is unavailable: Please use String directlylet s1Chars = Array(s1.characters) // 'characters' is unavailable: Please use String directlyfunc sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
if s0Chars.count!= s1Chars.count {
return false
}
for (i, char) in s0Chars.enumerated() {
if s1Chars[i]!= char {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
Answer:
```swift
func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
if s0Chars.count!= s1Chars.count {
return false
}
for (i, char) in s0Chars.enumerated() {
if s1Chars[i]!= char {
return false
}
}
return true
}
```if s0Chars.count!= s1Chars.count { // cannot force unwrap value of non-optional type 'Int'if s0Chars.count!= s1Chars.count { // '=' must have consistent whitespace on both sidesif s0Chars.count!= s1Chars.count { // use of '=' in a boolean context, did you mean '=='?if s1Chars[i]!= char { // '=' must have consistent whitespace on both sidesif s1Chars[i]!= char { // use of '=' in a boolean context, did you mean '=='?if s1Chars[i]!= char { // cannot force unwrap value of non-optional type 'String.Element' (aka 'Character')func fib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 1
} else {
return fib(n - 1) + fib(n - 2)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
Answer:
```swift
func fib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 1
} else {
return fib(n - 1) + fib(n - 2)
}
}
```return fib(n - 1) + fib(n - 2) // missing argument label 'n:' in callreturn fib(n - 1) + fib(n - 2) // missing argument label 'n:' in callfunc fib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 1
} else {
return fib(n: n - 1) + fib(n: n - 2)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
Answer:
```swift
func fib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 1
} else {
return fib(n: n - 1) + fib(n: n - 2)
}
}
```func fib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 1
} else {
return fib(n - 1) + fib(n - 2)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
Answer:
```swift
func fib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 1
} else {
return fib(n - 1) + fib(n - 2)
}
}
```return fib(n - 1) + fib(n - 2) // missing argument label 'n:' in callreturn fib(n - 1) + fib(n - 2) // missing argument label 'n:' in callfunc fib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 1
} else {
return fib(n: n - 1) + fib(n: n - 2)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
Answer:
```swift
func fib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 1
} else {
return fib(n: n - 1) + fib(n: n - 2)
}
}
```func fib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 1
} else {
return fib(n: n - 1) + fib(n: n - 2)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
Answer:
```swift
func fib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 1
} else {
return fib(n: n - 1) + fib(n: n - 2)
}
}
```func fib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 1
} else {
return fib(n: n - 1) + fib(n: n - 2)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
Answer:
```swift
func fib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 1
} else {
return fib(n: n - 1) + fib(n: n - 2)
}
}
```func fib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 1
} else {
return fib(n - 1) + fib(n - 2)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
Answer:
```swift
func fib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 1
} else {
return fib(n - 1) + fib(n - 2)
}
}
```return fib(n - 1) + fib(n - 2) // missing argument label 'n:' in callreturn fib(n - 1) + fib(n - 2) // missing argument label 'n:' in callfunc fib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 1
} else {
return fib(n: n - 1) + fib(n: n - 2)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
Answer:
```swift
func fib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 1
} else {
return fib(n: n - 1) + fib(n: n - 2)
}
}
```func fib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 1
} else {
return fib(n: n - 1) + fib(n: n - 2)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
Answer:
```swift
func fib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 1
} else {
return fib(n: n - 1) + fib(n: n - 2)
}
}
```func fib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 1
} else {
return fib(n: n - 1) + fib(n: n - 2)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
Answer:
```swift
func fib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 1
} else {
return fib(n: n - 1) + fib(n: n - 2)
}
}
```func correctBracketing(brackets: String) -> Bool {
let openingBrackets = ["<", "{", "["]
let closingBrackets = [">", "}", "]"]
var stack = [Character]()
for char in brackets {
if openingBrackets.contains(char) {
stack.append(char)
} else if closingBrackets.contains(char) {
if stack.isEmpty || openingBrackets[openingBrackets.firstIndex(of: stack.last)!]!= char {
return false
} else {
stack.removeLast()
}
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
let openingBrackets = ["<", "{", "["]
let closingBrackets = [">", "}", "]"]
var stack = [Character]()
for char in brackets {
if openingBrackets.contains(char) {
stack.append(char)
} else if closingBrackets.contains(char) {
if stack.isEmpty || openingBrackets[openingBrackets.firstIndex(of: stack.last)!]!= char {
return false
} else {
stack.removeLast()
}
}
}
return stack.isEmpty
}
```if openingBrackets.contains(char) { // cannot convert value of type 'Character' to expected argument type 'String'} else if closingBrackets.contains(char) { // cannot convert value of type 'Character' to expected argument type 'String'if stack.isEmpty || openingBrackets[openingBrackets.firstIndex(of: stack.last)!]!= char { // '=' must have consistent whitespace on both sidesif stack.isEmpty || openingBrackets[openingBrackets.firstIndex(of: stack.last)!]!= char { // cannot convert value of type 'String' to expected argument type 'Bool'if stack.isEmpty || openingBrackets[openingBrackets.firstIndex(of: stack.last)!]!= char { // cannot convert value of type 'Character?' to expected argument type 'String'if stack.isEmpty || openingBrackets[openingBrackets.firstIndex(of: stack.last)!]!= char { // cannot force unwrap value of non-optional type 'String'if stack.isEmpty || openingBrackets[openingBrackets.firstIndex(of: stack.last)!]!= char { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || openingBrackets[openingBrackets.firstIndex(of: stack.last)!]!= char { // expression is not assignable: '||' returns immutable valuefunc correctBracketing(brackets: String) -> Bool {
let openingBrackets = ["<", "{", "["]
let closingBrackets = [">", "}", "]"]
var stack = [Character]()
for character in brackets {
if openingBrackets.contains(character) {
stack.append(character)
} else if closingBrackets.contains(character) {
if stack.isEmpty || openingBrackets.firstIndex(of: stack.last!)!= openingBrackets.firstIndex(of: character) {
return false
} else {
stack.removeLast()
}
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
let openingBrackets = ["<", "{", "["]
let closingBrackets = [">", "}", "]"]
var stack = [Character]()
for character in brackets {
if openingBrackets.contains(character) {
stack.append(character)
} else if closingBrackets.contains(character) {
if stack.isEmpty || openingBrackets.firstIndex(of: stack.last!)!= openingBrackets.firstIndex(of: character) {
return false
} else {
stack.removeLast()
}
}
}
return stack.isEmpty
}
```if openingBrackets.contains(character) { // cannot convert value of type 'Character' to expected argument type 'String'} else if closingBrackets.contains(character) { // cannot convert value of type 'Character' to expected argument type 'String'if stack.isEmpty || openingBrackets.firstIndex(of: stack.last!)!= openingBrackets.firstIndex(of: character) { // type 'Array<String>.Index' (aka 'Int') cannot be used as a boolean; test for '!= 0' insteadif stack.isEmpty || openingBrackets.firstIndex(of: stack.last!)!= openingBrackets.firstIndex(of: character) { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || openingBrackets.firstIndex(of: stack.last!)!= openingBrackets.firstIndex(of: character) { // cannot convert value of type 'Character' to expected argument type 'String'if stack.isEmpty || openingBrackets.firstIndex(of: stack.last!)!= openingBrackets.firstIndex(of: character) { // '=' must have consistent whitespace on both sidesif stack.isEmpty || openingBrackets.firstIndex(of: stack.last!)!= openingBrackets.firstIndex(of: character) { // cannot convert value of type 'Character' to expected argument type 'String'func correctBracketing(brackets: String) -> Bool {
let stack = [Character]()
for char in brackets {
switch char {
case "<":
stack.append(char)
case ">":
if stack.isEmpty || stack.last!= "<" {
return false
} else {
stack.removeLast()
}
default:
return false
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
let stack = [Character]()
for char in brackets {
switch char {
case "<":
stack.append(char)
case ">":
if stack.isEmpty || stack.last!= "<" {
return false
} else {
stack.removeLast()
}
default:
return false
}
}
return stack.isEmpty
}
```stack.append(char) // cannot use mutating member on immutable value: 'stack' is a 'let' constantif stack.isEmpty || stack.last!= "<" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.last!= "<" { // '=' must have consistent whitespace on both sidesif stack.isEmpty || stack.last!= "<" { // cannot convert value of type 'Character' to expected argument type 'Bool'if stack.isEmpty || stack.last!= "<" { // expression is not assignable: '||' returns immutable valuestack.removeLast() // cannot use mutating member on immutable value: 'stack' is a 'let' constantfunc correctBracketing(brackets: String) -> Bool {
let stack = Stack<Character>()
for char in brackets {
switch char {
case "<":
stack.push(char)
case ">":
if stack.isEmpty || stack.pop()!= "<" {
return false
}
default:
return false
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
let stack = Stack<Character>()
for char in brackets {
switch char {
case "<":
stack.push(char)
case ">":
if stack.isEmpty || stack.pop()!= "<" {
return false
}
default:
return false
}
}
return stack.isEmpty
}
```let stack = Stack<Character>() // cannot find 'Stack' in scopeif stack.isEmpty || stack.pop()!= "<" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.pop()!= "<" { // '=' must have consistent whitespace on both sidesfunc correctBracketing(brackets: String) -> Bool {
let openingBrackets = ["<", "{", "["]
let closingBrackets = [">", "}", "]"]
var stack = [Character]()
for char in brackets {
if openingBrackets.contains(char) {
stack.append(char)
} else if closingBrackets.contains(char) {
if stack.isEmpty || openingBrackets[openingBrackets.firstIndex(of: stack.last)!]!= char {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
let openingBrackets = ["<", "{", "["]
let closingBrackets = [">", "}", "]"]
var stack = [Character]()
for char in brackets {
if openingBrackets.contains(char) {
stack.append(char)
} else if closingBrackets.contains(char) {
if stack.isEmpty || openingBrackets[openingBrackets.firstIndex(of: stack.last)!]!= char {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}
```if openingBrackets.contains(char) { // cannot convert value of type 'Character' to expected argument type 'String'} else if closingBrackets.contains(char) { // cannot convert value of type 'Character' to expected argument type 'String'if stack.isEmpty || openingBrackets[openingBrackets.firstIndex(of: stack.last)!]!= char { // '=' must have consistent whitespace on both sidesif stack.isEmpty || openingBrackets[openingBrackets.firstIndex(of: stack.last)!]!= char { // cannot convert value of type 'String' to expected argument type 'Bool'if stack.isEmpty || openingBrackets[openingBrackets.firstIndex(of: stack.last)!]!= char { // cannot convert value of type 'Character?' to expected argument type 'String'if stack.isEmpty || openingBrackets[openingBrackets.firstIndex(of: stack.last)!]!= char { // cannot force unwrap value of non-optional type 'String'if stack.isEmpty || openingBrackets[openingBrackets.firstIndex(of: stack.last)!]!= char { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || openingBrackets[openingBrackets.firstIndex(of: stack.last)!]!= char { // expression is not assignable: '||' returns immutable valuefunc correctBracketing(brackets: String) -> Bool {
let stack = Stack<Character>()
for char in brackets {
switch char {
case "<":
stack.push(char)
case ">":
if stack.isEmpty || stack.pop()!= "<" {
return false
}
default:
return false
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
let stack = Stack<Character>()
for char in brackets {
switch char {
case "<":
stack.push(char)
case ">":
if stack.isEmpty || stack.pop()!= "<" {
return false
}
default:
return false
}
}
return stack.isEmpty
}
```let stack = Stack<Character>() // cannot find 'Stack' in scopeif stack.isEmpty || stack.pop()!= "<" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.pop()!= "<" { // '=' must have consistent whitespace on both sidesfunc correctBracketing(brackets: String) -> Bool {
let stack = Stack<Character>()
for char in brackets {
if char == "<" {
stack.push(char)
} else if char == ">" {
if stack.isEmpty || stack.pop()!= "<" {
return false
}
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
let stack = Stack<Character>()
for char in brackets {
if char == "<" {
stack.push(char)
} else if char == ">" {
if stack.isEmpty || stack.pop()!= "<" {
return false
}
}
}
return stack.isEmpty
}
```let stack = Stack<Character>() // cannot find 'Stack' in scopeif stack.isEmpty || stack.pop()!= "<" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.pop()!= "<" { // '=' must have consistent whitespace on both sidesfunc correctBracketing(brackets: String) -> Bool {
let stack = Stack<Character>()
for char in brackets {
switch char {
case "<":
stack.push(char)
case ">":
if stack.isEmpty || stack.pop()!= "<" {
return false
}
default:
return false
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
let stack = Stack<Character>()
for char in brackets {
switch char {
case "<":
stack.push(char)
case ">":
if stack.isEmpty || stack.pop()!= "<" {
return false
}
default:
return false
}
}
return stack.isEmpty
}
```let stack = Stack<Character>() // cannot find 'Stack' in scopeif stack.isEmpty || stack.pop()!= "<" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.pop()!= "<" { // '=' must have consistent whitespace on both sidesfunc correctBracketing(brackets: String) -> Bool {
let stack = Stack<Character>()
for char in brackets {
switch char {
case "<":
stack.push(char)
case ">":
if stack.isEmpty || stack.pop()!= "<" {
return false
}
default:
return false
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
let stack = Stack<Character>()
for char in brackets {
switch char {
case "<":
stack.push(char)
case ">":
if stack.isEmpty || stack.pop()!= "<" {
return false
}
default:
return false
}
}
return stack.isEmpty
}
```let stack = Stack<Character>() // cannot find 'Stack' in scopeif stack.isEmpty || stack.pop()!= "<" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.pop()!= "<" { // '=' must have consistent whitespace on both sidesfunc correctBracketing(brackets: String) -> Bool {
let stack = Stack<Character>()
for char in brackets {
switch char {
case "<":
stack.push(char)
case ">":
if stack.isEmpty || stack.pop()!= "<" {
return false
}
default:
return false
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
let stack = Stack<Character>()
for char in brackets {
switch char {
case "<":
stack.push(char)
case ">":
if stack.isEmpty || stack.pop()!= "<" {
return false
}
default:
return false
}
}
return stack.isEmpty
}
```let stack = Stack<Character>() // cannot find 'Stack' in scopeif stack.isEmpty || stack.pop()!= "<" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.pop()!= "<" { // '=' must have consistent whitespace on both sidesfunc monotonic(l: [Int]) -> Bool {
let first = l.first!
let last = l.last!
return (first <= last) || (first >= last)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
Answer:
```swift
func monotonic(l: [Int]) -> Bool {
let first = l.first!
let last = l.last!
return (first <= last) || (first >= last)
}
``` // XCTAssertTrue failedfunc monotonic(l: [Int]) -> Bool {
let first = l.first!
let last = l.last!
return (first <= last) || (first >= last)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
Answer:
```swift
func monotonic(l: [Int]) -> Bool {
let first = l.first!
let last = l.last!
return (first <= last) || (first >= last)
}
``` // XCTAssertTrue failedfunc monotonic(l: [Int]) -> Bool {
let first = l.first!
let last = l.last!
return first <= last
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
Answer:
```swift
func monotonic(l: [Int]) -> Bool {
let first = l.first!
let last = l.last!
return first <= last
}
``` // XCTAssertTrue failedfunc monotonic(l: [Int]) -> Bool {
let first = l.first!
let last = l.last!
return (first <= last) || (first >= last)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
Answer:
```swift
func monotonic(l: [Int]) -> Bool {
let first = l.first!
let last = l.last!
return (first <= last) || (first >= last)
}
``` // XCTAssertTrue failedfunc monotonic(l: [Int]) -> Bool {
let first = l.first!
let last = l.last!
return (first <= last) || (first >= last)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
Answer:
```swift
func monotonic(l: [Int]) -> Bool {
let first = l.first!
let last = l.last!
return (first <= last) || (first >= last)
}
``` // XCTAssertTrue failedfunc monotonic(l: [Int]) -> Bool {
let first = l.first!
let last = l.last!
return (first <= last) || (first >= last)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
Answer:
```swift
func monotonic(l: [Int]) -> Bool {
let first = l.first!
let last = l.last!
return (first <= last) || (first >= last)
}
``` // XCTAssertTrue failedfunc monotonic(l: [Int]) -> Bool {
let first = l.first!
let last = l.last!
return (first <= last) || (first >= last)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
Answer:
```swift
func monotonic(l: [Int]) -> Bool {
let first = l.first!
let last = l.last!
return (first <= last) || (first >= last)
}
``` // XCTAssertTrue failedfunc monotonic(l: [Int]) -> Bool {
let first = l.first!
let last = l.last!
return (first <= last) || (first >= last)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
Answer:
```swift
func monotonic(l: [Int]) -> Bool {
let first = l.first!
let last = l.last!
return (first <= last) || (first >= last)
}
``` // XCTAssertTrue failedfunc monotonic(l: [Int]) -> Bool {
let first = l.first!
let last = l.last!
return first <= last
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
Answer:
```swift
func monotonic(l: [Int]) -> Bool {
let first = l.first!
let last = l.last!
return first <= last
}
``` // XCTAssertTrue failedfunc monotonic(l: [Int]) -> Bool {
let first = l.first!
let last = l.last!
return (first <= last) || (first >= last)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
Answer:
```swift
func monotonic(l: [Int]) -> Bool {
let first = l.first!
let last = l.last!
return (first <= last) || (first >= last)
}
``` // XCTAssertTrue failedfunc common(l1: [Int], l2: [Int]) -> [Int] {
var result = [Int]()
for element in l1 {
if l2.contains(element) {
result.append(element)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
Answer:
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
var result = [Int]()
for element in l1 {
if l2.contains(element) {
result.append(element)
}
}
return result
}
``` // XCTAssertTrue failedfunc common(l1: [Int], l2: [Int]) -> [Int] {
var result = [Int]()
var l1Set = Set(l1)
var l2Set = Set(l2)
for element in l1Set.intersection(l2Set) {
result.append(element)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
Answer:
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
var result = [Int]()
var l1Set = Set(l1)
var l2Set = Set(l2)
for element in l1Set.intersection(l2Set) {
result.append(element)
}
return result
}
```var l1Set = Set(l1) // variable 'l1Set' was never mutated; consider changing to 'let' constantvar l2Set = Set(l2) // variable 'l2Set' was never mutated; consider changing to 'let' constant // XCTAssertTrue failedfunc common(l1: [Int], l2: [Int]) -> [Int] {
var result = [Int]()
var l1Set = Set(l1)
var l2Set = Set(l2)
for element in l1Set.intersection(l2Set) {
result.append(element)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
Answer:
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
var result = [Int]()
var l1Set = Set(l1)
var l2Set = Set(l2)
for element in l1Set.intersection(l2Set) {
result.append(element)
}
return result
}
```var l1Set = Set(l1) // variable 'l1Set' was never mutated; consider changing to 'let' constantvar l2Set = Set(l2) // variable 'l2Set' was never mutated; consider changing to 'let' constant // XCTAssertTrue failedfunc common(l1: [Int], l2: [Int]) -> [Int] {
var result = [Int]()
var l1Set = Set(l1)
var l2Set = Set(l2)
for element in l1Set.intersection(l2Set) {
result.append(element)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
Answer:
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
var result = [Int]()
var l1Set = Set(l1)
var l2Set = Set(l2)
for element in l1Set.intersection(l2Set) {
result.append(element)
}
return result
}
```var l1Set = Set(l1) // variable 'l1Set' was never mutated; consider changing to 'let' constantvar l2Set = Set(l2) // variable 'l2Set' was never mutated; consider changing to 'let' constant // XCTAssertTrue failedfunc common(l1: [Int], l2: [Int]) -> [Int] {
var result = [Int]()
var l1Set = Set(l1)
var l2Set = Set(l2)
for element in l1Set.intersection(l2Set) {
result.append(element)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
Answer:
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
var result = [Int]()
var l1Set = Set(l1)
var l2Set = Set(l2)
for element in l1Set.intersection(l2Set) {
result.append(element)
}
return result
}
```var l1Set = Set(l1) // variable 'l1Set' was never mutated; consider changing to 'let' constantvar l2Set = Set(l2) // variable 'l2Set' was never mutated; consider changing to 'let' constant // XCTAssertTrue failedfunc common(l1: [Int], l2: [Int]) -> [Int] {
var result = [Int]()
for i in l1 {
if l2.contains(i) {
result.append(i)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
Answer:
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
var result = [Int]()
for i in l1 {
if l2.contains(i) {
result.append(i)
}
}
return result
}
``` // XCTAssertTrue failedfunc common(l1: [Int], l2: [Int]) -> [Int] {
var result = [Int]()
var l1Set = Set(l1)
var l2Set = Set(l2)
for element in l1Set.intersection(l2Set) {
result.append(element)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
Answer:
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
var result = [Int]()
var l1Set = Set(l1)
var l2Set = Set(l2)
for element in l1Set.intersection(l2Set) {
result.append(element)
}
return result
}
```var l1Set = Set(l1) // variable 'l1Set' was never mutated; consider changing to 'let' constantvar l2Set = Set(l2) // variable 'l2Set' was never mutated; consider changing to 'let' constant // XCTAssertTrue failedfunc common(l1: [Int], l2: [Int]) -> [Int] {
var result = [Int]()
var l1Set = Set(l1)
var l2Set = Set(l2)
for element in l1Set.intersection(l2Set) {
result.append(element)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
Answer:
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
var result = [Int]()
var l1Set = Set(l1)
var l2Set = Set(l2)
for element in l1Set.intersection(l2Set) {
result.append(element)
}
return result
}
```var l1Set = Set(l1) // variable 'l1Set' was never mutated; consider changing to 'let' constantvar l2Set = Set(l2) // variable 'l2Set' was never mutated; consider changing to 'let' constant // XCTAssertTrue failedfunc common(l1: [Int], l2: [Int]) -> [Int] {
var result = [Int]()
var l1Set = Set(l1)
var l2Set = Set(l2)
for element in l1Set.intersection(l2Set) {
result.append(element)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
Answer:
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
var result = [Int]()
var l1Set = Set(l1)
var l2Set = Set(l2)
for element in l1Set.intersection(l2Set) {
result.append(element)
}
return result
}
```var l1Set = Set(l1) // variable 'l1Set' was never mutated; consider changing to 'let' constantvar l2Set = Set(l2) // variable 'l2Set' was never mutated; consider changing to 'let' constant // XCTAssertTrue failedfunc common(l1: [Int], l2: [Int]) -> [Int] {
var result = [Int]()
for i in l1 {
if l2.contains(i) {
result.append(i)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
Answer:
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
var result = [Int]()
for i in l1 {
if l2.contains(i) {
result.append(i)
}
}
return result
}
``` // XCTAssertTrue failedfunc largestPrimeFactor(n: Int) -> Int {
var i = 2
while i * i <= n {
if n % i == 0 {
n /= i
} else {
i += 1
}
}
return n
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
Answer:
```swift
func largestPrimeFactor(n: Int) -> Int {
var i = 2
while i * i <= n {
if n % i == 0 {
n /= i
} else {
i += 1
}
}
return n
}
```n /= i // left side of mutating operator isn't mutable: 'n' is a 'let' constantfunc largestPrimeFactor(n: Int) -> Int {
var n = n
var largestPrime = 0
while n % 2 == 0 {
largestPrime = 2
n /= 2
}
for i in 3...Int(sqrt(Double(n))) {
while n % i == 0 {
largestPrime = i
n /= i
}
}
return largestPrime
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
Answer:
```swift
func largestPrimeFactor(n: Int) -> Int {
var n = n
var largestPrime = 0
while n % 2 == 0 {
largestPrime = 2
n /= 2
}
for i in 3...Int(sqrt(Double(n))) {
while n % i == 0 {
largestPrime = i
n /= i
}
}
return largestPrime
}
``` // XCTAssertTrue failedfunc largestPrimeFactor(n: Int) -> Int {
var n = n
var largestPrimeFactor = 1
while n % 2 == 0 {
largestPrimeFactor = 2
n /= 2
}
for i in 3...(Int(sqrt(Double(n))) + 1) {
while n % i == 0 {
largestPrimeFactor = i
n /= i
}
}
return largestPrimeFactor
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
Answer:
```swift
func largestPrimeFactor(n: Int) -> Int {
var n = n
var largestPrimeFactor = 1
while n % 2 == 0 {
largestPrimeFactor = 2
n /= 2
}
for i in 3...(Int(sqrt(Double(n))) + 1) {
while n % i == 0 {
largestPrimeFactor = i
n /= i
}
}
return largestPrimeFactor
}
``` // XCTAssertTrue failedfunc largestPrimeFactor(n: Int) -> Int {
var largestPrime = 0
var divisor = 2
while divisor <= n {
if n % divisor == 0 {
largestPrime = divisor
n /= divisor
} else {
divisor += 1
}
}
return largestPrime
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
Answer:
```swift
func largestPrimeFactor(n: Int) -> Int {
var largestPrime = 0
var divisor = 2
while divisor <= n {
if n % divisor == 0 {
largestPrime = divisor
n /= divisor
} else {
divisor += 1
}
}
return largestPrime
}
```n /= divisor // left side of mutating operator isn't mutable: 'n' is a 'let' constantfunc largestPrimeFactor(n: Int) -> Int {
var n = n
var largestPrimeFactor = 0
while n % 2 == 0 {
largestPrimeFactor = 2
n /= 2
}
for i in 3...Int(sqrt(Double(n))) {
while n % i == 0 {
largestPrimeFactor = i
n /= i
}
}
if n > 2 {
largestPrimeFactor = n
}
return largestPrimeFactor
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
Answer:
```swift
func largestPrimeFactor(n: Int) -> Int {
var n = n
var largestPrimeFactor = 0
while n % 2 == 0 {
largestPrimeFactor = 2
n /= 2
}
for i in 3...Int(sqrt(Double(n))) {
while n % i == 0 {
largestPrimeFactor = i
n /= i
}
}
if n > 2 {
largestPrimeFactor = n
}
return largestPrimeFactor
}
```func largestPrimeFactor(n: Int) -> Int {
var n = n
var largestPrimeFactor = 0
while n % 2 == 0 {
largestPrimeFactor = 2
n /= 2
}
for i in 3...Int(sqrt(Double(n))) {
while n % i == 0 {
largestPrimeFactor = i
n /= i
}
}
if n > 2 {
largestPrimeFactor = n
}
return largestPrimeFactor
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
Answer:
```swift
func largestPrimeFactor(n: Int) -> Int {
var n = n
var largestPrimeFactor = 0
while n % 2 == 0 {
largestPrimeFactor = 2
n /= 2
}
for i in 3...Int(sqrt(Double(n))) {
while n % i == 0 {
largestPrimeFactor = i
n /= i
}
}
if n > 2 {
largestPrimeFactor = n
}
return largestPrimeFactor
}
```func largestPrimeFactor(n: Int) -> Int {
var i = 2
while i * i <= n {
if n % i == 0 {
while n % i == 0 {
n /= i
}
}
i += 1
}
return n
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
Answer:
```swift
func largestPrimeFactor(n: Int) -> Int {
var i = 2
while i * i <= n {
if n % i == 0 {
while n % i == 0 {
n /= i
}
}
i += 1
}
return n
}
```n /= i // left side of mutating operator isn't mutable: 'n' is a 'let' constantfunc largestPrimeFactor(n: Int) -> Int {
var n = n
var largestPrimeFactor = 1
while n % 2 == 0 {
largestPrimeFactor = 2
n /= 2
}
for i in 3...(Int(sqrt(Double(n))) + 1) {
while n % i == 0 {
largestPrimeFactor = i
n /= i
}
}
return largestPrimeFactor
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
Answer:
```swift
func largestPrimeFactor(n: Int) -> Int {
var n = n
var largestPrimeFactor = 1
while n % 2 == 0 {
largestPrimeFactor = 2
n /= 2
}
for i in 3...(Int(sqrt(Double(n))) + 1) {
while n % i == 0 {
largestPrimeFactor = i
n /= i
}
}
return largestPrimeFactor
}
``` // XCTAssertTrue failedfunc largestPrimeFactor(n: Int) -> Int {
var n = n
var largestPrimeFactor = 1
while n % 2 == 0 {
largestPrimeFactor = 2
n /= 2
}
for i in 3...(Int(sqrt(Double(n))) + 1) {
while n % i == 0 {
largestPrimeFactor = i
n /= i
}
}
return largestPrimeFactor
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
Answer:
```swift
func largestPrimeFactor(n: Int) -> Int {
var n = n
var largestPrimeFactor = 1
while n % 2 == 0 {
largestPrimeFactor = 2
n /= 2
}
for i in 3...(Int(sqrt(Double(n))) + 1) {
while n % i == 0 {
largestPrimeFactor = i
n /= i
}
}
return largestPrimeFactor
}
``` // XCTAssertTrue failedfunc largestPrimeFactor(n: Int) -> Int {
var n = n
var largestPrime = 0
while n % 2 == 0 {
largestPrime = 2
n /= 2
}
for i in 3...Int(sqrt(Double(n))) {
while n % i == 0 {
largestPrime = i
n /= i
}
}
return largestPrime
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
Answer:
```swift
func largestPrimeFactor(n: Int) -> Int {
var n = n
var largestPrime = 0
while n % 2 == 0 {
largestPrime = 2
n /= 2
}
for i in 3...Int(sqrt(Double(n))) {
while n % i == 0 {
largestPrime = i
n /= i
}
}
return largestPrime
}
``` // XCTAssertTrue failedfunc sumToN(n: Int) -> Int {
return (n * (n + 1)) / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
Answer:
```swift
func sumToN(n: Int) -> Int {
return (n * (n + 1)) / 2
}
```func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
Answer:
```swift
func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}
```func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
Answer:
```swift
func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}
```func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
Answer:
```swift
func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}
```func sumToN(n: Int) -> Int {
return (n * (n + 1)) / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
Answer:
```swift
func sumToN(n: Int) -> Int {
return (n * (n + 1)) / 2
}
```func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
Answer:
```swift
func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}
```func sumToN(n: Int) -> Int {
return (n * (n + 1)) / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
Answer:
```swift
func sumToN(n: Int) -> Int {
return (n * (n + 1)) / 2
}
```func sumToN(n: Int) -> Int {
return (n * (n + 1)) / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
Answer:
```swift
func sumToN(n: Int) -> Int {
return (n * (n + 1)) / 2
}
```func sumToN(n: Int) -> Int {
return (n * (n + 1)) / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
Answer:
```swift
func sumToN(n: Int) -> Int {
return (n * (n + 1)) / 2
}
```func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
Answer:
```swift
func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}
```func correctBracketing(brackets: String) -> Bool {
let stack = Stack<Character>()
for char in brackets {
switch char {
case "(":
stack.push(char)
case ")":
if stack.isEmpty || stack.pop()!= "(" {
return false
}
default:
return false
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
let stack = Stack<Character>()
for char in brackets {
switch char {
case "(":
stack.push(char)
case ")":
if stack.isEmpty || stack.pop()!= "(" {
return false
}
default:
return false
}
}
return stack.isEmpty
}
```let stack = Stack<Character>() // cannot find 'Stack' in scopeif stack.isEmpty || stack.pop()!= "(" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.pop()!= "(" { // '=' must have consistent whitespace on both sidesfunc correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
switch char {
case "(":
stack.append(char)
case ")":
if stack.isEmpty || stack.last!= "(" {
return false
}
stack.removeLast()
default:
return false
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
switch char {
case "(":
stack.append(char)
case ")":
if stack.isEmpty || stack.last!= "(" {
return false
}
stack.removeLast()
default:
return false
}
}
return stack.isEmpty
}
```if stack.isEmpty || stack.last!= "(" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.last!= "(" { // cannot convert value of type 'Character' to expected argument type 'Bool'if stack.isEmpty || stack.last!= "(" { // '=' must have consistent whitespace on both sidesif stack.isEmpty || stack.last!= "(" { // expression is not assignable: '||' returns immutable valuefunc correctBracketing(brackets: String) -> Bool {
let stack = Stack<Character>()
for character in brackets {
switch character {
case "(":
stack.push(character)
case ")":
if stack.isEmpty || stack.pop()!= "(" {
return false
}
default:
return false
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
let stack = Stack<Character>()
for character in brackets {
switch character {
case "(":
stack.push(character)
case ")":
if stack.isEmpty || stack.pop()!= "(" {
return false
}
default:
return false
}
}
return stack.isEmpty
}
```let stack = Stack<Character>() // cannot find 'Stack' in scopeif stack.isEmpty || stack.pop()!= "(" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.pop()!= "(" { // '=' must have consistent whitespace on both sidesfunc correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
switch char {
case "(":
stack.append(char)
case ")":
if stack.isEmpty || stack.last!= "(" {
return false
}
stack.removeLast()
default:
return false
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
switch char {
case "(":
stack.append(char)
case ")":
if stack.isEmpty || stack.last!= "(" {
return false
}
stack.removeLast()
default:
return false
}
}
return stack.isEmpty
}
```if stack.isEmpty || stack.last!= "(" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.last!= "(" { // cannot convert value of type 'Character' to expected argument type 'Bool'if stack.isEmpty || stack.last!= "(" { // '=' must have consistent whitespace on both sidesif stack.isEmpty || stack.last!= "(" { // expression is not assignable: '||' returns immutable valuefunc correctBracketing(brackets: String) -> Bool {
let stack = [Character]()
for char in brackets {
switch char {
case "(":
stack.append(char)
case ")":
if stack.isEmpty || stack.last!= "(" {
return false
}
stack.removeLast()
default:
return false
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
let stack = [Character]()
for char in brackets {
switch char {
case "(":
stack.append(char)
case ")":
if stack.isEmpty || stack.last!= "(" {
return false
}
stack.removeLast()
default:
return false
}
}
return stack.isEmpty
}
```stack.append(char) // cannot use mutating member on immutable value: 'stack' is a 'let' constantif stack.isEmpty || stack.last!= "(" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.last!= "(" { // expression is not assignable: '||' returns immutable valueif stack.isEmpty || stack.last!= "(" { // cannot convert value of type 'Character' to expected argument type 'Bool'if stack.isEmpty || stack.last!= "(" { // '=' must have consistent whitespace on both sidesstack.removeLast() // cannot use mutating member on immutable value: 'stack' is a 'let' constantfunc correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
switch char {
case "(":
stack.append(char)
case ")":
if stack.isEmpty || stack.last!= "(" {
return false
}
stack.removeLast()
default:
return false
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
switch char {
case "(":
stack.append(char)
case ")":
if stack.isEmpty || stack.last!= "(" {
return false
}
stack.removeLast()
default:
return false
}
}
return stack.isEmpty
}
```if stack.isEmpty || stack.last!= "(" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.last!= "(" { // cannot convert value of type 'Character' to expected argument type 'Bool'if stack.isEmpty || stack.last!= "(" { // '=' must have consistent whitespace on both sidesif stack.isEmpty || stack.last!= "(" { // expression is not assignable: '||' returns immutable valuefunc correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.isEmpty || stack.last!= "(" {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.isEmpty || stack.last!= "(" {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}
```if stack.isEmpty || stack.last!= "(" { // '=' must have consistent whitespace on both sidesif stack.isEmpty || stack.last!= "(" { // expression is not assignable: '||' returns immutable valueif stack.isEmpty || stack.last!= "(" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.last!= "(" { // cannot convert value of type 'Character' to expected argument type 'Bool'func correctBracketing(brackets: String) -> Bool {
let stack = Stack<Character>()
for char in brackets {
switch char {
case "(":
stack.push(char)
case ")":
if stack.isEmpty || stack.pop()!= "(" {
return false
}
default:
return false
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
let stack = Stack<Character>()
for char in brackets {
switch char {
case "(":
stack.push(char)
case ")":
if stack.isEmpty || stack.pop()!= "(" {
return false
}
default:
return false
}
}
return stack.isEmpty
}
```let stack = Stack<Character>() // cannot find 'Stack' in scopeif stack.isEmpty || stack.pop()!= "(" { // '=' must have consistent whitespace on both sidesif stack.isEmpty || stack.pop()!= "(" { // use of '=' in a boolean context, did you mean '=='?func correctBracketing(brackets: String) -> Bool {
let stack = Stack<Character>()
for character in brackets {
switch character {
case "(":
stack.push(character)
case ")":
if stack.isEmpty || stack.pop()!= "(" {
return false
}
default:
return false
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
let stack = Stack<Character>()
for character in brackets {
switch character {
case "(":
stack.push(character)
case ")":
if stack.isEmpty || stack.pop()!= "(" {
return false
}
default:
return false
}
}
return stack.isEmpty
}
```let stack = Stack<Character>() // cannot find 'Stack' in scopeif stack.isEmpty || stack.pop()!= "(" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.pop()!= "(" { // '=' must have consistent whitespace on both sidesfunc correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for character in brackets {
switch character {
case "(":
stack.append(character)
case ")":
if stack.isEmpty || stack.last!= "(" {
return false
}
stack.removeLast()
default:
return false
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for character in brackets {
switch character {
case "(":
stack.append(character)
case ")":
if stack.isEmpty || stack.last!= "(" {
return false
}
stack.removeLast()
default:
return false
}
}
return stack.isEmpty
}
```if stack.isEmpty || stack.last!= "(" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.last!= "(" { // cannot convert value of type 'Character' to expected argument type 'Bool'if stack.isEmpty || stack.last!= "(" { // '=' must have consistent whitespace on both sidesif stack.isEmpty || stack.last!= "(" { // expression is not assignable: '||' returns immutable valuefunc derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else {
return []
}
var derivative: [Int] = []
for i in 1..<xs.count {
derivative.append(xs[i] * Int(i))
}
return derivative
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 +....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
Answer:
```swift
func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else {
return []
}
var derivative: [Int] = []
for i in 1..<xs.count {
derivative.append(xs[i] * Int(i))
}
return derivative
}
```func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else {
return []
}
var derivative: [Int] = []
for i in 1..<xs.count {
derivative.append(xs[i] * Int(i))
}
return derivative
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 +....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
Answer:
```swift
func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else {
return []
}
var derivative: [Int] = []
for i in 1..<xs.count {
derivative.append(xs[i] * Int(i))
}
return derivative
}
```func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else {
return []
}
var derivative = [Int](repeating: 0, count: xs.count - 1)
for i in 1..<xs.count {
derivative[i - 1] = xs[i] * Int(i)
}
return derivative
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 +....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
Answer:
```swift
func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else {
return []
}
var derivative = [Int](repeating: 0, count: xs.count - 1)
for i in 1..<xs.count {
derivative[i - 1] = xs[i] * Int(i)
}
return derivative
}
```func derivative(xs: [Int]) -> [Int] {
var derivative = [Int]()
for i in 1..<xs.count {
derivative.append(xs[i] * Int(i))
}
return derivative
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 +....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
Answer:
```swift
func derivative(xs: [Int]) -> [Int] {
var derivative = [Int]()
for i in 1..<xs.count {
derivative.append(xs[i] * Int(i))
}
return derivative
}
```func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else {
return []
}
var derivative: [Int] = []
for i in 1..<xs.count {
derivative.append(xs[i] * Int(i))
}
return derivative
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 +....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
Answer:
```swift
func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else {
return []
}
var derivative: [Int] = []
for i in 1..<xs.count {
derivative.append(xs[i] * Int(i))
}
return derivative
}
```func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else {
return []
}
var derivative: [Int] = []
for i in 1..<xs.count {
derivative.append(xs[i] * Int(i))
}
return derivative
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 +....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
Answer:
```swift
func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else {
return []
}
var derivative: [Int] = []
for i in 1..<xs.count {
derivative.append(xs[i] * Int(i))
}
return derivative
}
```func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else {
return []
}
var derivative: [Int] = []
for i in 1..<xs.count {
derivative.append(xs[i] * Int(i))
}
return derivative
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 +....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
Answer:
```swift
func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else {
return []
}
var derivative: [Int] = []
for i in 1..<xs.count {
derivative.append(xs[i] * Int(i))
}
return derivative
}
```func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else {
return []
}
var derivative: [Int] = []
for i in 1..<xs.count {
derivative.append(xs[i] * Int(i))
}
return derivative
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 +....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
Answer:
```swift
func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else {
return []
}
var derivative: [Int] = []
for i in 1..<xs.count {
derivative.append(xs[i] * Int(i))
}
return derivative
}
```func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else {
return []
}
var derivative: [Int] = []
for i in 1..<xs.count {
derivative.append(xs[i] * Int(i))
}
return derivative
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 +....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
Answer:
```swift
func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else {
return []
}
var derivative: [Int] = []
for i in 1..<xs.count {
derivative.append(xs[i] * Int(i))
}
return derivative
}
```func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else {
return []
}
var derivative: [Int] = []
for i in 1..<xs.count {
derivative.append(xs[i] * Int(i))
}
return derivative
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 +....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
Answer:
```swift
func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else {
return []
}
var derivative: [Int] = []
for i in 1..<xs.count {
derivative.append(xs[i] * Int(i))
}
return derivative
}
```func fibfib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 1
} else {
var a = 0
var b = 0
var c = 1
for _ in 0..<n {
c = a + b + c
a = b
b = c
}
return c
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
Answer:
```swift
func fibfib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 1
} else {
var a = 0
var b = 0
var c = 1
for _ in 0..<n {
c = a + b + c
a = b
b = c
}
return c
}
}
``` // XCTAssertTrue failedfunc fibfib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 1
} else {
var a = 0
var b = 0
var c = 1
for _ in 0..<n {
let temp = c
c = a + b + c
a = b
b = temp
}
return c
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
Answer:
```swift
func fibfib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 1
} else {
var a = 0
var b = 0
var c = 1
for _ in 0..<n {
let temp = c
c = a + b + c
a = b
b = temp
}
return c
}
}
``` // XCTAssertTrue failedfunc fibfib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 1
} else {
var a = 0
var b = 0
var c = 1
for _ in 3...n {
c = a + b + c
a = b
b = c
}
return c
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
Answer:
```swift
func fibfib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 1
} else {
var a = 0
var b = 0
var c = 1
for _ in 3...n {
c = a + b + c
a = b
b = c
}
return c
}
}
``` // XCTAssertTrue failedfunc fibfib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 1
} else {
var a = 0
var b = 0
var c = 1
for _ in 3...n {
c = a + b + c
a = b
b = c
}
return c
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
Answer:
```swift
func fibfib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 1
} else {
var a = 0
var b = 0
var c = 1
for _ in 3...n {
c = a + b + c
a = b
b = c
}
return c
}
}
``` // XCTAssertTrue failedfunc fibfib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 1
} else {
var a = 0
var b = 0
var c = 1
for _ in 0..<n {
let temp = c
c = a + b + c
a = b
b = temp
}
return c
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
Answer:
```swift
func fibfib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 1
} else {
var a = 0
var b = 0
var c = 1
for _ in 0..<n {
let temp = c
c = a + b + c
a = b
b = temp
}
return c
}
}
``` // XCTAssertTrue failedfunc fibfib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 1
} else {
var a = 0
var b = 0
var c = 1
for _ in 0..<n {
let temp = c
c = a + b + c
a = b
b = temp
}
return c
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
Answer:
```swift
func fibfib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 1
} else {
var a = 0
var b = 0
var c = 1
for _ in 0..<n {
let temp = c
c = a + b + c
a = b
b = temp
}
return c
}
}
``` // XCTAssertTrue failedfunc fibfib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 1
} else {
var a = 0
var b = 0
var c = 1
for _ in 3...n {
c = a + b + c
a = b
b = c
}
return c
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
Answer:
```swift
func fibfib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 1
} else {
var a = 0
var b = 0
var c = 1
for _ in 3...n {
c = a + b + c
a = b
b = c
}
return c
}
}
``` // XCTAssertTrue failedfunc fibfib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 1
} else {
var a = 0
var b = 0
var c = 1
for _ in 3...n {
c = a + b + c
a = b
b = c
}
return c
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
Answer:
```swift
func fibfib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 1
} else {
var a = 0
var b = 0
var c = 1
for _ in 3...n {
c = a + b + c
a = b
b = c
}
return c
}
}
``` // XCTAssertTrue failedfunc fibfib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 1
} else {
var a = 0
var b = 0
var c = 1
for _ in 0..<n {
let temp = c
c = a + b + c
a = b
b = temp
}
return c
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
Answer:
```swift
func fibfib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 1
} else {
var a = 0
var b = 0
var c = 1
for _ in 0..<n {
let temp = c
c = a + b + c
a = b
b = temp
}
return c
}
}
``` // XCTAssertTrue failedfunc fibfib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 1
} else {
var a = 0
var b = 0
var c = 1
for _ in 3...n {
c = a + b + c
a = b
b = c
}
return c
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
Answer:
```swift
func fibfib(n: Int) -> Int {
if n == 0 {
return 0
} else if n == 1 {
return 0
} else if n == 2 {
return 1
} else {
var a = 0
var b = 0
var c = 1
for _ in 3...n {
c = a + b + c
a = b
b = c
}
return c
}
}
``` // XCTAssertTrue failedfunc vowelsCount(s: String) -> Int {
let vowels = "aeiou"
var count = 0
for char in s {
if vowels.contains(char) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
Answer:
```swift
func vowelsCount(s: String) -> Int {
let vowels = "aeiou"
var count = 0
for char in s {
if vowels.contains(char) {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc vowelsCount(s: String) -> Int {
let vowels = "aeiou"
var count = 0
for char in s {
if vowels.contains(char) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
Answer:
```swift
func vowelsCount(s: String) -> Int {
let vowels = "aeiou"
var count = 0
for char in s {
if vowels.contains(char) {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc vowelsCount(s: String) -> Int {
let vowels = "aeiou"
var count = 0
for char in s {
if vowels.contains(char) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
Answer:
```swift
func vowelsCount(s: String) -> Int {
let vowels = "aeiou"
var count = 0
for char in s {
if vowels.contains(char) {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc vowelsCount(s: String) -> Int {
var count = 0
for c in s {
if "aeiou".contains(String(c)) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
Answer:
```swift
func vowelsCount(s: String) -> Int {
var count = 0
for c in s {
if "aeiou".contains(String(c)) {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc vowelsCount(s: String) -> Int {
var count = 0
for char in s {
if "aeiou".contains(String(char)) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
Answer:
```swift
func vowelsCount(s: String) -> Int {
var count = 0
for char in s {
if "aeiou".contains(String(char)) {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc vowelsCount(s: String) -> Int {
let vowels = "aeiou"
var count = 0
for char in s {
if vowels.contains(char) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
Answer:
```swift
func vowelsCount(s: String) -> Int {
let vowels = "aeiou"
var count = 0
for char in s {
if vowels.contains(char) {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc vowelsCount(s: String) -> Int {
let vowels = "aeiou"
var count = 0
for char in s {
if vowels.contains(char) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
Answer:
```swift
func vowelsCount(s: String) -> Int {
let vowels = "aeiou"
var count = 0
for char in s {
if vowels.contains(char) {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc vowelsCount(s: String) -> Int {
var count = 0
for c in s {
if "aeiou".contains(String(c)) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
Answer:
```swift
func vowelsCount(s: String) -> Int {
var count = 0
for c in s {
if "aeiou".contains(String(c)) {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc vowelsCount(s: String) -> Int {
let vowels = "aeiou"
var count = 0
for char in s {
if vowels.contains(char) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
Answer:
```swift
func vowelsCount(s: String) -> Int {
let vowels = "aeiou"
var count = 0
for char in s {
if vowels.contains(char) {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc vowelsCount(s: String) -> Int {
let vowels = "aeiou"
var count = 0
for char in s {
if vowels.contains(char) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
Answer:
```swift
func vowelsCount(s: String) -> Int {
let vowels = "aeiou"
var count = 0
for char in s {
if vowels.contains(char) {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedQuestion:
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
Answer:
```swift
func circularShift(x: Int, shift: Int) -> String {
let string = String(x)
let length = string.count
let shiftedString = String(string.characters.map { String(UnicodeScalar($0)!) })
let shiftedChars = shiftedString.characters.map { String(UnicodeScalar($0)!) }
let shiftedCharsArray = Array(shiftedChars)
let shiftedCharsArrayCount = shiftedCharsArray.count
let shiftedCharsArrayReversed = shiftedCharsArray.reversed()
let shiftedCharsArrayReversedCount = shiftedCharsArrayReversed.count
let shiftedCharsArrayReversedFirst = shiftedCharsArrayReversed.first!
let shiftedCharsArrayReversedLast = shiftedCharsArrayReversed.last!
let shiftedCharsArrayReversedFirstIndex = shiftedCharsArrayReversed.firstIndex(of: shiftedCharsArrayReversedFirst)!
let shiftedCharsArrayReversedLastIndex = shiftedCharsArrayReversed.lastIndex(of: shiftedCharsArrayReversedLast)!
let shiftedCharsArrayReversedFirstIndexPlusShift = shiftedCharsArrayReversedFirstIndex + shift
let shiftedCharsArrayReversedLastIndexPlusShift = shiftedCharsArrayReversedLastIndex + shift
let shiftedCharsArrayReversedFirstIndexPlusShiftMod = shiftedCharsArrayReversedFirstIndexPlusShift % shiftedCharsArrayReversedCount
let shiftedCharsArrayReversedLastIndexPlusShiftMod = shiftedCharsArrayReversedLastIndexPlusShift % shiftedCharsArrayReversedCount
let shiftedCharsArrayReversedFirstIndexPlusShiftModString = String(UnicodeScalar(shiftedCharsArrayReversedFirstIndexPlusShiftMod)!)
let shiftedCharsArrayReversedLastIndexPlusShiftModString = String(UnicodeScalar(shiftedCharsArrayReversedLastIndexPlusShiftMod)!)
let shiftedCharsArrayReversedFirstIndexPlusShiftModStringCharacter = shiftedCharsArrayReversedFirstIndexPlusShiftModString.first!
let shiftedCharsArrayReversedLastIndexPlusShiftModStringCharacter = shiftedCharsArrayReversedLastIndexPlusShiftModString.first!
let shiftedCharsArrayReversedFirstIndexPlusShiftModStringCharacterUnicodeScalar = UnicodeScalar(shiftedCharsArrayReversedFirstIndexPlusShiftModStringCharacter)!
let shiftedCharsArrayReversedLastIndexPlusShiftModStringCharacterUnicodeScalar = UnicodeScalar(shiftedCharsArrayReversedLastIndexPlusShiftModStringCharacter)!
let shiftedCharsArrayReversedFirstIndexPlusShiftModStringCharacterInt = Int(shiftedCharsArrayReversedFirstIndexPlusShiftModStringCharacterUnicodeScalar)!
let shiftedCharsArrayReversedLastIndexPlusShiftModStringCharacterInt = Int(shiftedCharsArrayReversedLastIndexPlusShiftModStringCharacterUnicodeScalar)!
let shiftedCharsArrayReversedFirstIndexPlusShiftModStringCharacterIntString = String(shiftedCharsArrayReversedFirstIndexPlusShiftModStringCharacterInt)
let shiftedCharsArrayReversedLastIndexPlusShiftModStringCharacterIntString = String(shiftedCharsArrayReversedLastIndexPlusShiftModStringCharacterInt)
let shiftedCharsArrayReversedFirstIndexPlusShiftModStringCharacterIntStringCharacter = shiftedCharsArrayReversedFirstIndexPlusShiftModStringCharacterIntString.first!
let shiftedCharsArrayReversedLastIndexPlusShiftModStringCharacterIntStringCharacter = shiftedCharsArrayReversedLastIndexPlusShiftModStringCharacterIntString.first!
let shiftedCharsArrayReversedFirstIndexPlusShiftModStringCharacterIntStringCharacterUnicodeScalar = UnicodeScalar(shiftedCharsArrayReversedFirstIndexPlusShiftModStringCharacterIntStringCharacter)!
let shiftedCharsArrayReversedLastIndexPlusShiftModStringCharacterIntStringCharacterUnicodeScalar = UnicodeScalar(shiftedCharsArrayReversedLastIndexPlusShiftModStringCharacterIntStringCharacter)!
let shiftedCharsArrayReversedFirstIndexPlusShiftModStringCharacterIntStringCharacterInt = Int(shiftedCharsArrayReversedFirstIndexPlusShiftModStringCharacterIntStringCharacterUnicodeScalar)!
let shiftedCharsArrayReversedLastIndexPlusShiftModStringCharacterIntStringCharacterInt = Int(shiftedCharsArrayReversedLastIndexPlusShiftModStringCharacterIntStringCharacterUnicodeScalar)!
let shiftedCharsArrayReversedFirstIndexPlusShiftModStringCharacterIntStringCharacterIntString = String(shiftedCharsArrayReversedFirstIndexPlusShiftModStringCharacterIntStringCharacterInt)
let shiftedCharsArrayReversedLastIndexPlusShiftModStringCharacterIntStringCharacterIntString = String(shiftedCharsArrayReversedLastIndexPlusShiftModStringCharacterIntStringCharacterInt)
let shiftedCharsArrayReversedFirstIndexPlusShiftModStringCharacterIntStringCharacterIntStringCharacter = shiftedCharsArrayReversedFirstIndexPlusShiftModStringCharacterIntStringCharacterIntString.first!
let shiftedCharsArrayReversedLastIndexPlusShiftModStringCharacterIntStringCharacterIntStringCharacter = shiftedCharsArrayReversedLastIndexPlusShiftModStringCharacterIntStringCharacterIntString.first!
let shiftedCharsXCTAssertTrue(circularShift(x: 100, shift: 2) == "001") // cannot find 'circularShift' in scopeXCTAssertTrue(circularShift(x: 12, shift: 2) == "12") // cannot find 'circularShift' in scopeXCTAssertTrue(circularShift(x: 97, shift: 8) == "79") // cannot find 'circularShift' in scopeXCTAssertTrue(circularShift(x: 12, shift: 1) == "21") // cannot find 'circularShift' in scopeXCTAssertTrue(circularShift(x: 11, shift: 101) == "11") // cannot find 'circularShift' in scopefunc circularShift(x: Int, shift: Int) -> String {
let stringX = String(x)
let stringShift = String(shift)
let stringResult = String(stringX.characters.reversed().prefix(stringX.count - stringShift.count).suffix(stringShift.count))
return stringResult
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
Answer:
```swift
func circularShift(x: Int, shift: Int) -> String {
let stringX = String(x)
let stringShift = String(shift)
let stringResult = String(stringX.characters.reversed().prefix(stringX.count - stringShift.count).suffix(stringShift.count))
return stringResult
}
```let stringResult = String(stringX.characters.reversed().prefix(stringX.count - stringShift.count).suffix(stringShift.count)) // 'characters' is unavailable: Please use String directlyfunc circularShift(x: Int, shift: Int) -> String {
let string = String(x)
let length = string.count
let shiftedString = String(string.characters.map { String($0).padding(toLength: length, withPad: "0", startingAt: 0) })
let shiftedChars = shiftedString.characters.map { String($0) }.reversed()
return String(shiftedChars)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
Answer:
```swift
func circularShift(x: Int, shift: Int) -> String {
let string = String(x)
let length = string.count
let shiftedString = String(string.characters.map { String($0).padding(toLength: length, withPad: "0", startingAt: 0) })
let shiftedChars = shiftedString.characters.map { String($0) }.reversed()
return String(shiftedChars)
}
```let shiftedString = String(string.characters.map { String($0).padding(toLength: length, withPad: "0", startingAt: 0) }) // no exact matches in call to initializerfunc circularShift(x: Int, shift: Int) -> String {
let string = String(x)
let length = string.count
let shiftedString = String(string.characters.map { String($0) }.reversed().dropFirst(shift).reversed())
return shiftedString.count < length? shiftedString + String(repeating: "0", count: length - shiftedString.count) : shiftedString
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
Answer:
```swift
func circularShift(x: Int, shift: Int) -> String {
let string = String(x)
let length = string.count
let shiftedString = String(string.characters.map { String($0) }.reversed().dropFirst(shift).reversed())
return shiftedString.count < length? shiftedString + String(repeating: "0", count: length - shiftedString.count) : shiftedString
}
```let shiftedString = String(string.characters.map { String($0) }.reversed().dropFirst(shift).reversed()) // no exact matches in call to initializerreturn shiftedString.count < length? shiftedString + String(repeating: "0", count: length - shiftedString.count) : shiftedString // consecutive statements on a line must be separated by ';'return shiftedString.count < length? shiftedString + String(repeating: "0", count: length - shiftedString.count) : shiftedString // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return shiftedString.count < length? shiftedString + String(repeating: "0", count: length - shiftedString.count) : shiftedString // expected expressionreturn shiftedString.count < length? shiftedString + String(repeating: "0", count: length - shiftedString.count) : shiftedString // cannot use optional chaining on non-optional value of type 'Int'return shiftedString.count < length? shiftedString + String(repeating: "0", count: length - shiftedString.count) : shiftedString // consecutive statements on a line must be separated by ';'return shiftedString.count < length? shiftedString + String(repeating: "0", count: length - shiftedString.count) : shiftedString // cannot convert return expression of type 'Bool' to return type 'String'func circularShift(x: Int, shift: Int) -> String {
let string = String(x)
let digits = Array(string.characters)
let shiftedDigits = digits.suffix(from: digits.count - shift) + digits.prefix(from: 0)
return String(shiftedDigits)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
Answer:
```swift
func circularShift(x: Int, shift: Int) -> String {
let string = String(x)
let digits = Array(string.characters)
let shiftedDigits = digits.suffix(from: digits.count - shift) + digits.prefix(from: 0)
return String(shiftedDigits)
}
```let digits = Array(string.characters) // 'characters' is unavailable: Please use String directlylet shiftedDigits = digits.suffix(from: digits.count - shift) + digits.prefix(from: 0) // extraneous argument label 'from:' in callfunc circularShift(x: Int, shift: Int) -> String {
let string = String(x)
let reversed = String(string.reversed())
let shifted = String(reversed.dropFirst(shift).dropLast(string.count - shift))
return shifted
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
Answer:
```swift
func circularShift(x: Int, shift: Int) -> String {
let string = String(x)
let reversed = String(string.reversed())
let shifted = String(reversed.dropFirst(shift).dropLast(string.count - shift))
return shifted
}
``` // XCTAssertTrue failedfunc circularShift(x: Int, shift: Int) -> String {
let string = String(x)
let array = Array(string)
let shiftedArray = array.suffix(from: array.count - shift) + array.prefix(from: 0)
return String(shiftedArray)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
Answer:
```swift
func circularShift(x: Int, shift: Int) -> String {
let string = String(x)
let array = Array(string)
let shiftedArray = array.suffix(from: array.count - shift) + array.prefix(from: 0)
return String(shiftedArray)
}
```let shiftedArray = array.suffix(from: array.count - shift) + array.prefix(from: 0) // extraneous argument label 'from:' in callfunc circularShift(x: Int, shift: Int) -> String {
let string = String(x)
let digits = Array(string.characters)
let shiftedDigits = digits.suffix(from: digits.count - shift) + digits.prefix(from: 0)
return String(shiftedDigits)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
Answer:
```swift
func circularShift(x: Int, shift: Int) -> String {
let string = String(x)
let digits = Array(string.characters)
let shiftedDigits = digits.suffix(from: digits.count - shift) + digits.prefix(from: 0)
return String(shiftedDigits)
}
```let digits = Array(string.characters) // 'characters' is unavailable: Please use String directlylet shiftedDigits = digits.suffix(from: digits.count - shift) + digits.prefix(from: 0) // extraneous argument label 'from:' in callQuestion:
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
Answer:
```swift
func circularShift(x: Int, shift: Int) -> String {
let string = String(x)
let length = string.count
let shiftedString = String(string.characters.map { String(UnicodeScalar($0)!) })
let shiftedChars = shiftedString.characters.map { String(UnicodeScalar($0)!) }
let shiftedCharsArray = Array(shiftedChars)
let shiftedCharsArrayCount = shiftedCharsArray.count
let shiftedCharsArrayReversed = shiftedCharsArray.reversed()
let shiftedCharsArrayReversedString = String(shiftedCharsArrayReversed)
let shiftedCharsArrayReversedChars = shiftedCharsArrayReversedString.characters.map { String(UnicodeScalar($0)!) }
let shiftedCharsArrayReversedCharsArray = Array(shiftedCharsArrayReversedChars)
let shiftedCharsArrayReversedCharsArrayCount = shiftedCharsArrayReversedCharsArray.count
let shiftedCharsArrayReversedCharsArrayReversed = shiftedCharsArrayReversedCharsArray.reversed()
let shiftedCharsArrayReversedCharsArrayReversedString = String(shiftedCharsArrayReversedCharsArrayReversed)
let shiftedCharsArrayReversedCharsArrayReversedChars = shiftedCharsArrayReversedCharsArrayReversedString.characters.map { String(UnicodeScalar($0)!) }
let shiftedCharsArrayReversedCharsArrayReversedCharsArray = Array(shiftedCharsArrayReversedCharsArrayReversedChars)
let shiftedCharsArrayReversedCharsArrayReversedCharsArrayCount = shiftedCharsArrayReversedCharsArrayReversedCharsArray.count
let shiftedCharsArrayReversedCharsArrayReversedCharsArrayReversed = shiftedCharsArrayReversedCharsArrayReversedCharsArray.reversed()
let shiftedCharsArrayReversedCharsArrayReversedCharsArrayReversedString = String(shiftedCharsArrayReversedCharsArrayReversedCharsArrayReversed)
let shiftedCharsArrayReversedCharsArrayReversedCharsArrayReversedChars = shiftedCharsArrayReversedCharsArrayReversedCharsArrayReversedString.characters.map { String(UnicodeScalar($0)!) }
let shiftedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArray = Array(shiftedCharsArrayReversedCharsArrayReversedCharsArrayReversedChars)
let shiftedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayCount = shiftedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArray.count
let shiftedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversed = shiftedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArray.reversed()
let shiftedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversedString = String(shiftedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversed)
let shiftedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversedChars = shiftedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversedString.characters.map { String(UnicodeScalar($0)!) }
let shiftedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArray = Array(shiftedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversedChars)
let shiftedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayCount = shiftedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArray.count
let shiftedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversed = shiftedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversedString.characters.map { String(UnicodeScalar($0)!) }
let shiftedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversedChars = shiftedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversedString.characters.map { String(UnicodeScalar($0)!) }
let shiftedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayCount = shiftedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArray.count
let shiftedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversed = shiftedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversedString.characters.map { String(UnicodeScalar($0)!) }
let shiftedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversedChars = shiftedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArrayReversedCharsArray.XCTAssertTrue(circularShift(x: 100, shift: 2) == "001") // cannot find 'circularShift' in scopeXCTAssertTrue(circularShift(x: 12, shift: 2) == "12") // cannot find 'circularShift' in scopeXCTAssertTrue(circularShift(x: 97, shift: 8) == "79") // cannot find 'circularShift' in scopeXCTAssertTrue(circularShift(x: 12, shift: 1) == "21") // cannot find 'circularShift' in scopeXCTAssertTrue(circularShift(x: 11, shift: 101) == "11") // cannot find 'circularShift' in scopeQuestion:
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
Answer:
```swift
func circularShift(x: Int, shift: Int) -> String {
let string = String(x)
let length = string.count
let shiftedString = String(string.characters.map { String(UnicodeScalar($0)!) })
let shiftedChars = shiftedString.characters.map { String(UnicodeScalar($0)!) }
let shiftedCharsArray = Array(shiftedChars)
let shiftedCharsArrayCount = shiftedCharsArray.count
let shiftedCharsArrayReversed = shiftedCharsArray.reversed()
let shiftedCharsArrayReversedString = String(shiftedCharsArrayReversed)
let shiftedCharsArrayReversedStringChars = shiftedCharsArrayReversedString.characters
let shiftedCharsArrayReversedStringCharsArray = Array(shiftedCharsArrayReversedStringChars)
let shiftedCharsArrayReversedStringCharsArrayCount = shiftedCharsArrayReversedStringCharsArray.count
let shiftedCharsArrayReversedStringCharsArrayFirst = shiftedCharsArrayReversedStringCharsArray[0]
let shiftedCharsArrayReversedStringCharsArrayFirstString = String(shiftedCharsArrayReversedStringCharsArrayFirst)
let shiftedCharsArrayReversedStringCharsArrayFirstStringChars = shiftedCharsArrayReversedStringCharsArrayFirstString.characters
let shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArray = Array(shiftedCharsArrayReversedStringCharsArrayFirstStringChars)
let shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayCount = shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArray.count
let shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayFirst = shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArray[0]
let shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayFirstString = String(shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayFirst)
let shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayFirstStringChars = shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayFirst.characters
let shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayFirstStringCharsArray = Array(shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayFirstStringChars)
let shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayFirstStringCharsArrayCount = shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayFirstStringCharsArray.count
let shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayFirstStringCharsArrayFirst = shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayFirstStringCharsArray[0]
let shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayFirstStringCharsArrayFirstString = String(shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayFirstStringCharsArrayFirst)
let shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayFirstStringCharsArrayFirstString = String(shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayFirstStringCharsArrayFirst.unicodeScalarView.first!)
let shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayFirstStringCharsArrayFirstStringString = String(shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayFirstStringCharsArrayFirstString.unicodeScalarView.first!)
let shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayFirstStringCharsArrayFirstStringStringString = String(shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayFirstStringCharsArrayFirstStringString.unicodeScalarView.first!)
let shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayFirstStringCharsArrayFirstStringStringStringString = String(shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayFirstStringCharsArrayFirstStringStringString.unicodeScalarView.first!)
let shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayFirstStringCharsArrayFirstStringStringStringStringString = String(shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayFirstStringCharsArrayFirstStringStringStringString.unicodeScalarView.first!)
let shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayFirstStringCharsArrayFirstStringStringStringStringStringString = String(shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayFirstStringCharsArrayFirstStringStringStringStringStringString.unicodeScalarView.first!)
let shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayFirstStringCharsArrayFirstStringStringStringStringStringStringStringString = String(shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayFirstStringCharsArrayFirstStringStringStringStringStringStringStringString.unicodeScalarView.first!)
let shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayFirstStringCharsArrayFirstStringStringStringStringStringStringStringStringString = String(shiftedCharsArrayReversedStringCharsArrayFirstStringCharsArrayFirstStringCharsArrayFirstStringStringStringStringStringStringStringStringStringString.unicodeScalarView.first!)
let shiftedCharsArrayReversedStringCharsArrayXCTAssertTrue(circularShift(x: 100, shift: 2) == "001") // cannot find 'circularShift' in scopeXCTAssertTrue(circularShift(x: 12, shift: 2) == "12") // cannot find 'circularShift' in scopeXCTAssertTrue(circularShift(x: 97, shift: 8) == "79") // cannot find 'circularShift' in scopeXCTAssertTrue(circularShift(x: 12, shift: 1) == "21") // cannot find 'circularShift' in scopeXCTAssertTrue(circularShift(x: 11, shift: 101) == "11") // cannot find 'circularShift' in scopefunc digitSum(s: String) -> Int {
return s.filter { $0.isUpper }.map { Int($0.asciiValue?? 0) }.reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
Answer:
```swift
func digitSum(s: String) -> Int {
return s.filter { $0.isUpper }.map { Int($0.asciiValue?? 0) }.reduce(0, +)
}
```return s.filter { $0.isUpper }.map { Int($0.asciiValue?? 0) }.reduce(0, +) // cannot use optional chaining on non-optional value of type 'UInt8'return s.filter { $0.isUpper }.map { Int($0.asciiValue?? 0) }.reduce(0, +) // missing argument label 'strategy:' in callreturn s.filter { $0.isUpper }.map { Int($0.asciiValue?? 0) }.reduce(0, +) // value of type 'String.Element' (aka 'Character') has no member 'isUpper'return s.filter { $0.isUpper }.map { Int($0.asciiValue?? 0) }.reduce(0, +) // initializer 'init(_:strategy:)' requires that 'Int' conform to 'ParseStrategy'return s.filter { $0.isUpper }.map { Int($0.asciiValue?? 0) }.reduce(0, +) // expected ',' separatorfunc digitSum(s: String) -> Int {
return s.filter { $0.isUpper }.map { Int($0.asciiValue?? 0) }.reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
Answer:
```swift
func digitSum(s: String) -> Int {
return s.filter { $0.isUpper }.map { Int($0.asciiValue?? 0) }.reduce(0, +)
}
```return s.filter { $0.isUpper }.map { Int($0.asciiValue?? 0) }.reduce(0, +) // cannot use optional chaining on non-optional value of type 'UInt8'return s.filter { $0.isUpper }.map { Int($0.asciiValue?? 0) }.reduce(0, +) // missing argument label 'strategy:' in callreturn s.filter { $0.isUpper }.map { Int($0.asciiValue?? 0) }.reduce(0, +) // value of type 'String.Element' (aka 'Character') has no member 'isUpper'return s.filter { $0.isUpper }.map { Int($0.asciiValue?? 0) }.reduce(0, +) // initializer 'init(_:strategy:)' requires that 'Int' conform to 'ParseStrategy'return s.filter { $0.isUpper }.map { Int($0.asciiValue?? 0) }.reduce(0, +) // expected ',' separatorfunc digitSum(s: String) -> Int {
return s.reduce(0) { $0 + Int(UnicodeScalar($1).value.description.first!)! }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
Answer:
```swift
func digitSum(s: String) -> Int {
return s.reduce(0) { $0 + Int(UnicodeScalar($1).value.description.first!)! }
}
```return s.reduce(0) { $0 + Int(UnicodeScalar($1).value.description.first!)! } // no exact matches in call to initializerreturn s.reduce(0) { $0 + Int(UnicodeScalar($1).value.description.first!)! } // cannot convert value of type 'String.Element' (aka 'Character') to expected argument type 'String'func digitSum(s: String) -> Int {
return s.uppercased().reduce(0) { $0 + Int(UnicodeScalar($1).value) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
Answer:
```swift
func digitSum(s: String) -> Int {
return s.uppercased().reduce(0) { $0 + Int(UnicodeScalar($1).value) }
}
```return s.uppercased().reduce(0) { $0 + Int(UnicodeScalar($1).value) } // no exact matches in call to initializerfunc digitSum(s: String) -> Int {
var sum = 0
for c in s {
if c.isUpper {
sum += Int(c.asciiValue! - 64)
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
Answer:
```swift
func digitSum(s: String) -> Int {
var sum = 0
for c in s {
if c.isUpper {
sum += Int(c.asciiValue! - 64)
}
}
return sum
}
```if c.isUpper { // value of type 'Character' has no member 'isUpper'func digitSum(s: String) -> Int {
var sum = 0
for char in s {
if let asciiCode = String(char).first?.asciiValue {
if asciiCode >= 65 && asciiCode <= 90 {
sum += asciiCode
}
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
Answer:
```swift
func digitSum(s: String) -> Int {
var sum = 0
for char in s {
if let asciiCode = String(char).first?.asciiValue {
if asciiCode >= 65 && asciiCode <= 90 {
sum += asciiCode
}
}
}
return sum
}
```sum += asciiCode // cannot convert value of type 'UInt8' to expected argument type 'Int'func digitSum(s: String) -> Int {
return s.uppercased().reduce(0, { $0 + Int(UnicodeScalar($1).value) })
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
Answer:
```swift
func digitSum(s: String) -> Int {
return s.uppercased().reduce(0, { $0 + Int(UnicodeScalar($1).value) })
}
```return s.uppercased().reduce(0, { $0 + Int(UnicodeScalar($1).value) }) // no exact matches in call to initializerfunc digitSum(s: String) -> Int {
var sum = 0
for c in s.uppercased() {
sum += Int(String(c).unicodeScalars.first!.value)
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
Answer:
```swift
func digitSum(s: String) -> Int {
var sum = 0
for c in s.uppercased() {
sum += Int(String(c).unicodeScalars.first!.value)
}
return sum
}
``` // XCTAssertTrue failedfunc digitSum(s: String) -> Int {
var sum = 0
for char in s {
if let ascii = Int(String(char).unicodeScalars.first!), ascii >= 65 && ascii <= 90 {
sum += ascii
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
Answer:
```swift
func digitSum(s: String) -> Int {
var sum = 0
for char in s {
if let ascii = Int(String(char).unicodeScalars.first!), ascii >= 65 && ascii <= 90 {
sum += ascii
}
}
return sum
}
```if let ascii = Int(String(char).unicodeScalars.first!), ascii >= 65 && ascii <= 90 { // initializer 'init(_:radix:)' requires that 'String.UnicodeScalarView.Element' (aka 'Unicode.Scalar') conform to 'StringProtocol'func digitSum(s: String) -> Int {
var sum = 0
for char in s.uppercased() {
sum += Int(String(char).unicodeScalars.first!.value)
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
Answer:
```swift
func digitSum(s: String) -> Int {
var sum = 0
for char in s.uppercased() {
sum += Int(String(char).unicodeScalars.first!.value)
}
return sum
}
``` // XCTAssertTrue failedfunc fruitDistribution(s: String, n: Int) -> Int {
let applesAndOranges = s.components(separatedBy: " ")
let apples = Int(applesAndOranges[0])?? 0
let oranges = Int(applesAndOranges[2])?? 0
let mangoes = n - apples - oranges
return mangoes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
Answer:
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let applesAndOranges = s.components(separatedBy: " ")
let apples = Int(applesAndOranges[0])?? 0
let oranges = Int(applesAndOranges[2])?? 0
let mangoes = n - apples - oranges
return mangoes
}
```let apples = Int(applesAndOranges[0])?? 0 // integer literal is unusedlet apples = Int(applesAndOranges[0])?? 0 // consecutive statements on a line must be separated by ';'let apples = Int(applesAndOranges[0])?? 0 // cannot use optional chaining on non-optional value of type 'Int'let oranges = Int(applesAndOranges[2])?? 0 // consecutive statements on a line must be separated by ';'let oranges = Int(applesAndOranges[2])?? 0 // integer literal is unusedlet oranges = Int(applesAndOranges[2])?? 0 // cannot use optional chaining on non-optional value of type 'Int'func fruitDistribution(s: String, n: Int) -> Int {
let applesAndOranges = s.components(separatedBy: " and ")
let apples = Int(applesAndOranges[0].replacingOccurrences(of: " apples", with: ""))?? 0
let oranges = Int(applesAndOranges[1].replacingOccurrences(of: " oranges", with: ""))?? 0
let mangoes = n - apples - oranges
return mangoes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
Answer:
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let applesAndOranges = s.components(separatedBy: " and ")
let apples = Int(applesAndOranges[0].replacingOccurrences(of: " apples", with: ""))?? 0
let oranges = Int(applesAndOranges[1].replacingOccurrences(of: " oranges", with: ""))?? 0
let mangoes = n - apples - oranges
return mangoes
}
```let apples = Int(applesAndOranges[0].replacingOccurrences(of: " apples", with: ""))?? 0 // cannot use optional chaining on non-optional value of type 'Int'let apples = Int(applesAndOranges[0].replacingOccurrences(of: " apples", with: ""))?? 0 // integer literal is unusedlet apples = Int(applesAndOranges[0].replacingOccurrences(of: " apples", with: ""))?? 0 // consecutive statements on a line must be separated by ';'let oranges = Int(applesAndOranges[1].replacingOccurrences(of: " oranges", with: ""))?? 0 // cannot use optional chaining on non-optional value of type 'Int'let oranges = Int(applesAndOranges[1].replacingOccurrences(of: " oranges", with: ""))?? 0 // consecutive statements on a line must be separated by ';'let oranges = Int(applesAndOranges[1].replacingOccurrences(of: " oranges", with: ""))?? 0 // integer literal is unusedfunc fruitDistribution(s: String, n: Int) -> Int {
let applesAndOranges = s.components(separatedBy: " ")
let apples = Int(applesAndOranges[0])?? 0
let oranges = Int(applesAndOranges[2])?? 0
let mangoes = n - (apples + oranges)
return mangoes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
Answer:
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let applesAndOranges = s.components(separatedBy: " ")
let apples = Int(applesAndOranges[0])?? 0
let oranges = Int(applesAndOranges[2])?? 0
let mangoes = n - (apples + oranges)
return mangoes
}
```let apples = Int(applesAndOranges[0])?? 0 // integer literal is unusedlet apples = Int(applesAndOranges[0])?? 0 // consecutive statements on a line must be separated by ';'let apples = Int(applesAndOranges[0])?? 0 // cannot use optional chaining on non-optional value of type 'Int'let oranges = Int(applesAndOranges[2])?? 0 // consecutive statements on a line must be separated by ';'let oranges = Int(applesAndOranges[2])?? 0 // integer literal is unusedlet oranges = Int(applesAndOranges[2])?? 0 // cannot use optional chaining on non-optional value of type 'Int'let mangoes = n - (apples + oranges) // cannot convert value of type 'String' to expected argument type 'Int'func fruitDistribution(s: String, n: Int) -> Int {
let applesAndOranges = s.components(separatedBy: " ")
let apples = Int(applesAndOranges[0])?? 0
let oranges = Int(applesAndOranges[2])?? 0
let mangoes = n - (apples + oranges)
return mangoes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
Answer:
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let applesAndOranges = s.components(separatedBy: " ")
let apples = Int(applesAndOranges[0])?? 0
let oranges = Int(applesAndOranges[2])?? 0
let mangoes = n - (apples + oranges)
return mangoes
}
```let apples = Int(applesAndOranges[0])?? 0 // integer literal is unusedlet apples = Int(applesAndOranges[0])?? 0 // consecutive statements on a line must be separated by ';'let apples = Int(applesAndOranges[0])?? 0 // cannot use optional chaining on non-optional value of type 'Int'let oranges = Int(applesAndOranges[2])?? 0 // consecutive statements on a line must be separated by ';'let oranges = Int(applesAndOranges[2])?? 0 // integer literal is unusedlet oranges = Int(applesAndOranges[2])?? 0 // cannot use optional chaining on non-optional value of type 'Int'let mangoes = n - (apples + oranges) // cannot convert value of type 'String' to expected argument type 'Int'func fruitDistribution(s: String, n: Int) -> Int {
let applesAndOranges = s.components(separatedBy: " ")
let apples = Int(applesAndOranges[0])?? 0
let oranges = Int(applesAndOranges[2])?? 0
let mangoes = n - (apples + oranges)
return mangoes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
Answer:
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let applesAndOranges = s.components(separatedBy: " ")
let apples = Int(applesAndOranges[0])?? 0
let oranges = Int(applesAndOranges[2])?? 0
let mangoes = n - (apples + oranges)
return mangoes
}
```let apples = Int(applesAndOranges[0])?? 0 // integer literal is unusedlet apples = Int(applesAndOranges[0])?? 0 // consecutive statements on a line must be separated by ';'let apples = Int(applesAndOranges[0])?? 0 // cannot use optional chaining on non-optional value of type 'Int'let oranges = Int(applesAndOranges[2])?? 0 // consecutive statements on a line must be separated by ';'let oranges = Int(applesAndOranges[2])?? 0 // integer literal is unusedlet oranges = Int(applesAndOranges[2])?? 0 // cannot use optional chaining on non-optional value of type 'Int'let mangoes = n - (apples + oranges) // cannot convert value of type 'String' to expected argument type 'Int'func fruitDistribution(s: String, n: Int) -> Int {
let applesAndOranges = s.components(separatedBy: " ")
let apples = Int(applesAndOranges[0])?? 0
let oranges = Int(applesAndOranges[2])?? 0
let mangoes = n - (apples + oranges)
return mangoes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
Answer:
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let applesAndOranges = s.components(separatedBy: " ")
let apples = Int(applesAndOranges[0])?? 0
let oranges = Int(applesAndOranges[2])?? 0
let mangoes = n - (apples + oranges)
return mangoes
}
```let apples = Int(applesAndOranges[0])?? 0 // integer literal is unusedlet apples = Int(applesAndOranges[0])?? 0 // consecutive statements on a line must be separated by ';'let apples = Int(applesAndOranges[0])?? 0 // cannot use optional chaining on non-optional value of type 'Int'let oranges = Int(applesAndOranges[2])?? 0 // consecutive statements on a line must be separated by ';'let oranges = Int(applesAndOranges[2])?? 0 // integer literal is unusedlet oranges = Int(applesAndOranges[2])?? 0 // cannot use optional chaining on non-optional value of type 'Int'let mangoes = n - (apples + oranges) // cannot convert value of type 'String' to expected argument type 'Int'func fruitDistribution(s: String, n: Int) -> Int {
let applesAndOranges = s.components(separatedBy: " and ")
let apples = Int(applesAndOranges[0].replacingOccurrences(of: " apples", with: ""))?? 0
let oranges = Int(applesAndOranges[1].replacingOccurrences(of: " oranges", with: ""))?? 0
let mangoes = n - (apples + oranges)
return mangoes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
Answer:
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let applesAndOranges = s.components(separatedBy: " and ")
let apples = Int(applesAndOranges[0].replacingOccurrences(of: " apples", with: ""))?? 0
let oranges = Int(applesAndOranges[1].replacingOccurrences(of: " oranges", with: ""))?? 0
let mangoes = n - (apples + oranges)
return mangoes
}
```let apples = Int(applesAndOranges[0].replacingOccurrences(of: " apples", with: ""))?? 0 // cannot use optional chaining on non-optional value of type 'Int'let apples = Int(applesAndOranges[0].replacingOccurrences(of: " apples", with: ""))?? 0 // integer literal is unusedlet apples = Int(applesAndOranges[0].replacingOccurrences(of: " apples", with: ""))?? 0 // consecutive statements on a line must be separated by ';'let oranges = Int(applesAndOranges[1].replacingOccurrences(of: " oranges", with: ""))?? 0 // cannot use optional chaining on non-optional value of type 'Int'let oranges = Int(applesAndOranges[1].replacingOccurrences(of: " oranges", with: ""))?? 0 // consecutive statements on a line must be separated by ';'let oranges = Int(applesAndOranges[1].replacingOccurrences(of: " oranges", with: ""))?? 0 // integer literal is unusedlet mangoes = n - (apples + oranges) // cannot convert value of type 'String' to expected argument type 'Int'func fruitDistribution(s: String, n: Int) -> Int {
let applesAndOranges = s.components(separatedBy: " ")
let apples = Int(applesAndOranges[0])?? 0
let oranges = Int(applesAndOranges[2])?? 0
let mangoes = n - apples - oranges
return mangoes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
Answer:
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let applesAndOranges = s.components(separatedBy: " ")
let apples = Int(applesAndOranges[0])?? 0
let oranges = Int(applesAndOranges[2])?? 0
let mangoes = n - apples - oranges
return mangoes
}
```let apples = Int(applesAndOranges[0])?? 0 // integer literal is unusedlet apples = Int(applesAndOranges[0])?? 0 // consecutive statements on a line must be separated by ';'let apples = Int(applesAndOranges[0])?? 0 // cannot use optional chaining on non-optional value of type 'Int'let oranges = Int(applesAndOranges[2])?? 0 // consecutive statements on a line must be separated by ';'let oranges = Int(applesAndOranges[2])?? 0 // integer literal is unusedlet oranges = Int(applesAndOranges[2])?? 0 // cannot use optional chaining on non-optional value of type 'Int'func fruitDistribution(s: String, n: Int) -> Int {
let applesAndOranges = s.components(separatedBy: " ")
let apples = Int(applesAndOranges[0])!
let oranges = Int(applesAndOranges[2])!
let mangoes = n - apples - oranges
return mangoes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
Answer:
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let applesAndOranges = s.components(separatedBy: " ")
let apples = Int(applesAndOranges[0])!
let oranges = Int(applesAndOranges[2])!
let mangoes = n - apples - oranges
return mangoes
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc fruitDistribution(s: String, n: Int) -> Int {
let applesAndOranges = s.components(separatedBy: " ")
let apples = Int(applesAndOranges[0])!
let oranges = Int(applesAndOranges[2])!
let mangoes = n - (apples + oranges)
return mangoes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
Answer:
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let applesAndOranges = s.components(separatedBy: " ")
let apples = Int(applesAndOranges[0])!
let oranges = Int(applesAndOranges[2])!
let mangoes = n - (apples + oranges)
return mangoes
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc pluck(arr: [Int]) -> [Int] {
guard arr.count > 0 else {
return []
}
var minEven = Int.max
var minEvenIndex = 0
var minValue = Int.max
var minValueIndex = 0
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value < minValue {
minValue = value
minValueIndex = index
}
if value % 2 == 0 {
minEven = value
minEvenIndex = index
}
}
return minEvenIndex < minValueIndex? [minEven, minEvenIndex] : [minValue, minValueIndex]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
Answer:
```swift
func pluck(arr: [Int]) -> [Int] {
guard arr.count > 0 else {
return []
}
var minEven = Int.max
var minEvenIndex = 0
var minValue = Int.max
var minValueIndex = 0
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value < minValue {
minValue = value
minValueIndex = index
}
if value % 2 == 0 {
minEven = value
minEvenIndex = index
}
}
return minEvenIndex < minValueIndex? [minEven, minEvenIndex] : [minValue, minValueIndex]
}
```return minEvenIndex < minValueIndex? [minEven, minEvenIndex] : [minValue, minValueIndex] // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return minEvenIndex < minValueIndex? [minEven, minEvenIndex] : [minValue, minValueIndex] // cannot convert return expression of type 'Bool' to return type '[Int]'return minEvenIndex < minValueIndex? [minEven, minEvenIndex] : [minValue, minValueIndex] // consecutive statements on a line must be separated by ';'return minEvenIndex < minValueIndex? [minEven, minEvenIndex] : [minValue, minValueIndex] // expected expressionreturn minEvenIndex < minValueIndex? [minEven, minEvenIndex] : [minValue, minValueIndex] // cannot use optional chaining on non-optional value of type 'Int'return minEvenIndex < minValueIndex? [minEven, minEvenIndex] : [minValue, minValueIndex] // value of type 'Int' has no subscriptsfunc pluck(arr: [Int]) -> [Int] {
guard!arr.isEmpty else {
return []
}
var minEvenValue = Int.max
var minEvenIndex = 0
var minValue = Int.max
var minIndex = 0
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value < minEvenValue {
minEvenValue = value
minEvenIndex = index
}
if value < minValue {
minValue = value
minIndex = index
}
}
return [minValue, minIndex]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
Answer:
```swift
func pluck(arr: [Int]) -> [Int] {
guard!arr.isEmpty else {
return []
}
var minEvenValue = Int.max
var minEvenIndex = 0
var minValue = Int.max
var minIndex = 0
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value < minEvenValue {
minEvenValue = value
minEvenIndex = index
}
if value < minValue {
minValue = value
minIndex = index
}
}
return [minValue, minIndex]
}
```guard!arr.isEmpty else { // expected expression, var, let or case in 'guard' conditionfunc pluck(arr: [Int]) -> [Int] {
guard arr.count > 0 else {
return []
}
var minEven = Int.max
var minEvenIndex = -1
var minValue = Int.max
var minValueIndex = -1
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value < minEven {
minEven = value
minEvenIndex = index
}
if value < minValue {
minValue = value
minValueIndex = index
}
}
return [minValue, minValueIndex]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
Answer:
```swift
func pluck(arr: [Int]) -> [Int] {
guard arr.count > 0 else {
return []
}
var minEven = Int.max
var minEvenIndex = -1
var minValue = Int.max
var minValueIndex = -1
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value < minEven {
minEven = value
minEvenIndex = index
}
if value < minValue {
minValue = value
minValueIndex = index
}
}
return [minValue, minValueIndex]
}
```var minEvenIndex = -1 // variable 'minEvenIndex' was written to, but never read // XCTAssertTrue failedfunc pluck(arr: [Int]) -> [Int] {
guard arr.count > 0 else {
return []
}
var minEven = Int.max
var minEvenIndex = 0
var minEvenValue = Int.max
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value < minEvenValue {
minEvenValue = value
minEvenIndex = index
minEven = value
}
}
return [minEven, minEvenIndex]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
Answer:
```swift
func pluck(arr: [Int]) -> [Int] {
guard arr.count > 0 else {
return []
}
var minEven = Int.max
var minEvenIndex = 0
var minEvenValue = Int.max
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value < minEvenValue {
minEvenValue = value
minEvenIndex = index
minEven = value
}
}
return [minEven, minEvenIndex]
}
``` // XCTAssertTrue failedfunc pluck(arr: [Int]) -> [Int] {
guard arr.count > 0 else {
return []
}
var minEven = Int.max
var minEvenIndex = 0
var minValue = Int.max
var minValueIndex = 0
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value < minEven {
minEven = value
minEvenIndex = index
}
if value < minValue {
minValue = value
minValueIndex = index
}
}
return [minValue, minValueIndex]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
Answer:
```swift
func pluck(arr: [Int]) -> [Int] {
guard arr.count > 0 else {
return []
}
var minEven = Int.max
var minEvenIndex = 0
var minValue = Int.max
var minValueIndex = 0
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value < minEven {
minEven = value
minEvenIndex = index
}
if value < minValue {
minValue = value
minValueIndex = index
}
}
return [minValue, minValueIndex]
}
```var minEvenIndex = 0 // variable 'minEvenIndex' was written to, but never read // XCTAssertTrue failedfunc pluck(arr: [Int]) -> [Int] {
guard arr.count > 0 else {
return []
}
var minEvenValue = Int.max
var minEvenIndex = 0
var minValue = Int.max
var minIndex = 0
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value < minEvenValue {
minEvenValue = value
minEvenIndex = index
}
if value < minValue {
minValue = value
minIndex = index
}
}
return [minValue, minIndex]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
Answer:
```swift
func pluck(arr: [Int]) -> [Int] {
guard arr.count > 0 else {
return []
}
var minEvenValue = Int.max
var minEvenIndex = 0
var minValue = Int.max
var minIndex = 0
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value < minEvenValue {
minEvenValue = value
minEvenIndex = index
}
if value < minValue {
minValue = value
minIndex = index
}
}
return [minValue, minIndex]
}
```var minEvenIndex = 0 // variable 'minEvenIndex' was written to, but never read // XCTAssertTrue failedfunc pluck(arr: [Int]) -> [Int] {
guard arr.count > 0 else {
return []
}
var minEvenValue = Int.max
var minEvenIndex = 0
var minValue = Int.max
var minIndex = 0
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value < minEvenValue {
minEvenValue = value
minEvenIndex = index
}
if value < minValue {
minValue = value
minIndex = index
}
}
return [minValue, minIndex]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
Answer:
```swift
func pluck(arr: [Int]) -> [Int] {
guard arr.count > 0 else {
return []
}
var minEvenValue = Int.max
var minEvenIndex = 0
var minValue = Int.max
var minIndex = 0
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value < minEvenValue {
minEvenValue = value
minEvenIndex = index
}
if value < minValue {
minValue = value
minIndex = index
}
}
return [minValue, minIndex]
}
```var minEvenIndex = 0 // variable 'minEvenIndex' was written to, but never read // XCTAssertTrue failedfunc pluck(arr: [Int]) -> [Int] {
guard arr.count > 0 else {
return []
}
var minEven = Int.max
var minEvenIndex = 0
var minValue = Int.max
var minValueIndex = 0
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value < minValue {
minValue = value
minValueIndex = index
}
if value % 2 == 0 && value < minEven {
minEven = value
minEvenIndex = index
}
}
return [minValue, minValueIndex]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
Answer:
```swift
func pluck(arr: [Int]) -> [Int] {
guard arr.count > 0 else {
return []
}
var minEven = Int.max
var minEvenIndex = 0
var minValue = Int.max
var minValueIndex = 0
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value < minValue {
minValue = value
minValueIndex = index
}
if value % 2 == 0 && value < minEven {
minEven = value
minEvenIndex = index
}
}
return [minValue, minValueIndex]
}
```var minEvenIndex = 0 // variable 'minEvenIndex' was written to, but never read // XCTAssertTrue failedfunc pluck(arr: [Int]) -> [Int] {
guard arr.count > 0 else {
return []
}
var minEven = Int.max
var minEvenIndex = 0
var minValue = Int.max
var minValueIndex = 0
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value < minValue {
minValue = value
minValueIndex = index
}
if value % 2 == 0 && value < minEven {
minEven = value
minEvenIndex = index
}
}
return [minValue, minValueIndex]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
Answer:
```swift
func pluck(arr: [Int]) -> [Int] {
guard arr.count > 0 else {
return []
}
var minEven = Int.max
var minEvenIndex = 0
var minValue = Int.max
var minValueIndex = 0
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value < minValue {
minValue = value
minValueIndex = index
}
if value % 2 == 0 && value < minEven {
minEven = value
minEvenIndex = index
}
}
return [minValue, minValueIndex]
}
```var minEvenIndex = 0 // variable 'minEvenIndex' was written to, but never read // XCTAssertTrue failedfunc pluck(arr: [Int]) -> [Int] {
guard arr.count > 0 else {
return []
}
var minEven = Int.max
var minEvenIndex = 0
var minEvenValue = Int.max
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value < minEvenValue {
minEven = value
minEvenIndex = index
minEvenValue = value
}
}
return [minEven, minEvenIndex]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
Answer:
```swift
func pluck(arr: [Int]) -> [Int] {
guard arr.count > 0 else {
return []
}
var minEven = Int.max
var minEvenIndex = 0
var minEvenValue = Int.max
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value < minEvenValue {
minEven = value
minEvenIndex = index
minEvenValue = value
}
}
return [minEven, minEvenIndex]
}
``` // XCTAssertTrue failedfunc search(lst: [Int]) -> Int {
var max = 0
var count = [Int: Int]()
for num in lst {
count[num, default: 0] += 1
if num > 0 && count[num] >= num {
max = num
}
}
return max == 0? -1 : max
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
Answer:
```swift
func search(lst: [Int]) -> Int {
var max = 0
var count = [Int: Int]()
for num in lst {
count[num, default: 0] += 1
if num > 0 && count[num] >= num {
max = num
}
}
return max == 0? -1 : max
}
```if num > 0 && count[num] >= num { // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return max == 0? -1 : max // expected expressionreturn max == 0? -1 : max // cannot use optional chaining on non-optional value of type 'Int'return max == 0? -1 : max // consecutive statements on a line must be separated by ';'return max == 0? -1 : max // consecutive statements on a line must be separated by ';'return max == 0? -1 : max // integer literal is unusedreturn max == 0? -1 : max // cannot convert return expression of type 'Bool' to return type 'Int'func search(lst: [Int]) -> Int {
var max = 0
var count = [Int: Int]()
for num in lst {
count[num, default: 0] += 1
max = max(max, num)
}
for i in 1...max {
if count[i]! >= i {
return i
}
}
return -1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
Answer:
```swift
func search(lst: [Int]) -> Int {
var max = 0
var count = [Int: Int]()
for num in lst {
count[num, default: 0] += 1
max = max(max, num)
}
for i in 1...max {
if count[i]! >= i {
return i
}
}
return -1
}
```max = max(max, num) // cannot call value of non-function type 'Int'func search(lst: [Int]) -> Int {
var max = 0
var count = [Int: Int]()
for num in lst {
count[num, default: 0] += 1
if num > 0 && count[num] >= num {
max = num
}
}
return max
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
Answer:
```swift
func search(lst: [Int]) -> Int {
var max = 0
var count = [Int: Int]()
for num in lst {
count[num, default: 0] += 1
if num > 0 && count[num] >= num {
max = num
}
}
return max
}
```if num > 0 && count[num] >= num { // value of optional type 'Int?' must be unwrapped to a value of type 'Int'func search(lst: [Int]) -> Int {
var max = 0
var count = [Int: Int]()
for num in lst {
count[num, default: 0] += 1
if num > 0 && count[num] >= num {
max = num
}
}
return max
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
Answer:
```swift
func search(lst: [Int]) -> Int {
var max = 0
var count = [Int: Int]()
for num in lst {
count[num, default: 0] += 1
if num > 0 && count[num] >= num {
max = num
}
}
return max
}
```if num > 0 && count[num] >= num { // value of optional type 'Int?' must be unwrapped to a value of type 'Int'func search(lst: [Int]) -> Int {
var max = 0
var count = [Int: Int]()
for num in lst {
count[num, default: 0] += 1
if num > 0 && count[num] >= num {
max = num
}
}
return max
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
Answer:
```swift
func search(lst: [Int]) -> Int {
var max = 0
var count = [Int: Int]()
for num in lst {
count[num, default: 0] += 1
if num > 0 && count[num] >= num {
max = num
}
}
return max
}
```if num > 0 && count[num] >= num { // value of optional type 'Int?' must be unwrapped to a value of type 'Int'func search(lst: [Int]) -> Int {
var max = 0
var count = [Int: Int]()
for num in lst {
count[num, default: 0] += 1
if num > 0 && count[num] >= num {
max = num
}
}
return max == 0? -1 : max
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
Answer:
```swift
func search(lst: [Int]) -> Int {
var max = 0
var count = [Int: Int]()
for num in lst {
count[num, default: 0] += 1
if num > 0 && count[num] >= num {
max = num
}
}
return max == 0? -1 : max
}
```if num > 0 && count[num] >= num { // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return max == 0? -1 : max // expected expressionreturn max == 0? -1 : max // cannot use optional chaining on non-optional value of type 'Int'return max == 0? -1 : max // consecutive statements on a line must be separated by ';'return max == 0? -1 : max // consecutive statements on a line must be separated by ';'return max == 0? -1 : max // integer literal is unusedreturn max == 0? -1 : max // cannot convert return expression of type 'Bool' to return type 'Int'func search(lst: [Int]) -> Int {
var max = 0
var count = [Int: Int]()
for num in lst {
count[num, default: 0] += 1
max = max(max, num)
}
for i in 1...max {
if count[i]! >= i {
return i
}
}
return -1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
Answer:
```swift
func search(lst: [Int]) -> Int {
var max = 0
var count = [Int: Int]()
for num in lst {
count[num, default: 0] += 1
max = max(max, num)
}
for i in 1...max {
if count[i]! >= i {
return i
}
}
return -1
}
```max = max(max, num) // cannot call value of non-function type 'Int'func search(lst: [Int]) -> Int {
var max = 0
var count = [Int: Int]()
for num in lst {
count[num, default: 0] += 1
if num > 0 && count[num] >= num {
max = num
}
}
return max
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
Answer:
```swift
func search(lst: [Int]) -> Int {
var max = 0
var count = [Int: Int]()
for num in lst {
count[num, default: 0] += 1
if num > 0 && count[num] >= num {
max = num
}
}
return max
}
```if num > 0 && count[num] >= num { // value of optional type 'Int?' must be unwrapped to a value of type 'Int'func search(lst: [Int]) -> Int {
var max = 0
var count = [Int: Int]()
for num in lst {
count[num, default: 0] += 1
if num > 0 && count[num] >= num {
max = num
}
}
return max
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
Answer:
```swift
func search(lst: [Int]) -> Int {
var max = 0
var count = [Int: Int]()
for num in lst {
count[num, default: 0] += 1
if num > 0 && count[num] >= num {
max = num
}
}
return max
}
```if num > 0 && count[num] >= num { // value of optional type 'Int?' must be unwrapped to a value of type 'Int'func search(lst: [Int]) -> Int {
var max = 0
var count = [Int: Int]()
for num in lst {
count[num, default: 0] += 1
max = max(max, num)
}
for i in 1...max {
if count[i]! >= i {
return i
}
}
return -1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
Answer:
```swift
func search(lst: [Int]) -> Int {
var max = 0
var count = [Int: Int]()
for num in lst {
count[num, default: 0] += 1
max = max(max, num)
}
for i in 1...max {
if count[i]! >= i {
return i
}
}
return -1
}
```max = max(max, num) // cannot call value of non-function type 'Int'func strangeSortList(lst: [Int]) -> [Int] {
guard lst.count > 0 else {
return []
}
var min = lst[0]
var max = lst[0]
var result = [Int]()
for num in lst {
if num < min {
min = num
}
if num > max {
max = num
}
}
for num in lst {
if num == min {
result.append(num)
}
if num == max {
result.append(num)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
Answer:
```swift
func strangeSortList(lst: [Int]) -> [Int] {
guard lst.count > 0 else {
return []
}
var min = lst[0]
var max = lst[0]
var result = [Int]()
for num in lst {
if num < min {
min = num
}
if num > max {
max = num
}
}
for num in lst {
if num == min {
result.append(num)
}
if num == max {
result.append(num)
}
}
return result
}
``` // XCTAssertTrue failedfunc strangeSortList(lst: [Int]) -> [Int] {
guard lst.count > 0 else {
return []
}
var result = [Int]()
var min = lst[0]
var max = lst[0]
for num in lst {
if num < min {
min = num
} else if num > max {
max = num
}
}
result.append(min)
result.append(max)
for num in lst {
if num!= min && num!= max {
result.append(num)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
Answer:
```swift
func strangeSortList(lst: [Int]) -> [Int] {
guard lst.count > 0 else {
return []
}
var result = [Int]()
var min = lst[0]
var max = lst[0]
for num in lst {
if num < min {
min = num
} else if num > max {
max = num
}
}
result.append(min)
result.append(max)
for num in lst {
if num!= min && num!= max {
result.append(num)
}
}
return result
}
```if num!= min && num!= max { // '=' must have consistent whitespace on both sidesif num!= min && num!= max { // use of '=' in a boolean context, did you mean '=='?if num!= min && num!= max { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadif num!= min && num!= max { // cannot force unwrap value of non-optional type 'Int'if num!= min && num!= max { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadif num!= min && num!= max { // cannot force unwrap value of non-optional type 'Int'if num!= min && num!= max { // '=' must have consistent whitespace on both sidesif num!= min && num!= max { // cannot assign value of type '()' to type 'Int'func strangeSortList(lst: [Int]) -> [Int] {
guard!lst.isEmpty else {
return []
}
var min = lst[0]
var max = lst[0]
var result = [Int]()
for num in lst {
if num < min {
min = num
}
if num > max {
max = num
}
}
for num in lst {
if num == min {
result.append(num)
}
if num == max {
result.append(num)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
Answer:
```swift
func strangeSortList(lst: [Int]) -> [Int] {
guard!lst.isEmpty else {
return []
}
var min = lst[0]
var max = lst[0]
var result = [Int]()
for num in lst {
if num < min {
min = num
}
if num > max {
max = num
}
}
for num in lst {
if num == min {
result.append(num)
}
if num == max {
result.append(num)
}
}
return result
}
```guard!lst.isEmpty else { // expected expression, var, let or case in 'guard' conditionfunc strangeSortList(lst: [Int]) -> [Int] {
guard lst.count > 0 else {
return []
}
let min = lst.min()!
let max = lst.max()!
let minIndex = lst.firstIndex(of: min)!
let maxIndex = lst.firstIndex(of: max)!
let minList = lst.prefix(minIndex)
let maxList = lst.suffix(lst.count - minIndex - 1)
return [min] + maxList + [max] + minList
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
Answer:
```swift
func strangeSortList(lst: [Int]) -> [Int] {
guard lst.count > 0 else {
return []
}
let min = lst.min()!
let max = lst.max()!
let minIndex = lst.firstIndex(of: min)!
let maxIndex = lst.firstIndex(of: max)!
let minList = lst.prefix(minIndex)
let maxList = lst.suffix(lst.count - minIndex - 1)
return [min] + maxList + [max] + minList
}
```let maxIndex = lst.firstIndex(of: max)! // initialization of immutable value 'maxIndex' was never used; consider replacing with assignment to '_' or removing it // XCTAssertTrue failedfunc strangeSortList(lst: [Int]) -> [Int] {
guard lst.count > 0 else {
return []
}
let min = lst.min()!
let max = lst.max()!
let minIndex = lst.firstIndex(of: min)!
let maxIndex = lst.firstIndex(of: max)!
let minList = lst.prefix(minIndex)
let maxList = lst.suffix(lst.count - minIndex - 1)
let minMaxList = minList + [max] + maxList
return minMaxList
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
Answer:
```swift
func strangeSortList(lst: [Int]) -> [Int] {
guard lst.count > 0 else {
return []
}
let min = lst.min()!
let max = lst.max()!
let minIndex = lst.firstIndex(of: min)!
let maxIndex = lst.firstIndex(of: max)!
let minList = lst.prefix(minIndex)
let maxList = lst.suffix(lst.count - minIndex - 1)
let minMaxList = minList + [max] + maxList
return minMaxList
}
```return minMaxList // cannot convert return expression of type 'Array<Int>.SubSequence' (aka 'ArraySlice<Int>') to return type '[Int]'func strangeSortList(lst: [Int]) -> [Int] {
guard lst.count > 0 else {
return lst
}
var min = lst[0]
var max = lst[0]
var result = [Int]()
for num in lst {
if num < min {
min = num
}
if num > max {
max = num
}
}
result.append(min)
result.append(max)
for num in lst {
if num!= min && num!= max {
result.append(num)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
Answer:
```swift
func strangeSortList(lst: [Int]) -> [Int] {
guard lst.count > 0 else {
return lst
}
var min = lst[0]
var max = lst[0]
var result = [Int]()
for num in lst {
if num < min {
min = num
}
if num > max {
max = num
}
}
result.append(min)
result.append(max)
for num in lst {
if num!= min && num!= max {
result.append(num)
}
}
return result
}
```if num!= min && num!= max { // cannot force unwrap value of non-optional type 'Int'if num!= min && num!= max { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadif num!= min && num!= max { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadif num!= min && num!= max { // cannot assign value of type '()' to type 'Int'if num!= min && num!= max { // use of '=' in a boolean context, did you mean '=='?if num!= min && num!= max { // '=' must have consistent whitespace on both sidesif num!= min && num!= max { // '=' must have consistent whitespace on both sidesif num!= min && num!= max { // cannot force unwrap value of non-optional type 'Int'func strangeSortList(lst: [Int]) -> [Int] {
guard lst.count > 0 else {
return []
}
var min = lst[0]
var max = lst[0]
var result = [Int]()
for num in lst {
if num < min {
min = num
}
if num > max {
max = num
}
}
result.append(min)
result.append(max)
for num in lst {
if num!= min && num!= max {
result.append(num)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
Answer:
```swift
func strangeSortList(lst: [Int]) -> [Int] {
guard lst.count > 0 else {
return []
}
var min = lst[0]
var max = lst[0]
var result = [Int]()
for num in lst {
if num < min {
min = num
}
if num > max {
max = num
}
}
result.append(min)
result.append(max)
for num in lst {
if num!= min && num!= max {
result.append(num)
}
}
return result
}
```if num!= min && num!= max { // cannot force unwrap value of non-optional type 'Int'if num!= min && num!= max { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadif num!= min && num!= max { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadif num!= min && num!= max { // cannot assign value of type '()' to type 'Int'if num!= min && num!= max { // use of '=' in a boolean context, did you mean '=='?if num!= min && num!= max { // '=' must have consistent whitespace on both sidesif num!= min && num!= max { // '=' must have consistent whitespace on both sidesif num!= min && num!= max { // cannot force unwrap value of non-optional type 'Int'func strangeSortList(lst: [Int]) -> [Int] {
guard lst.count > 0 else {
return []
}
var min = lst[0]
var max = lst[0]
var result = [Int]()
for num in lst {
if num < min {
min = num
}
if num > max {
max = num
}
}
for num in lst {
if num == min {
result.append(num)
}
if num == max {
result.append(num)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
Answer:
```swift
func strangeSortList(lst: [Int]) -> [Int] {
guard lst.count > 0 else {
return []
}
var min = lst[0]
var max = lst[0]
var result = [Int]()
for num in lst {
if num < min {
min = num
}
if num > max {
max = num
}
}
for num in lst {
if num == min {
result.append(num)
}
if num == max {
result.append(num)
}
}
return result
}
``` // XCTAssertTrue failedfunc strangeSortList(lst: [Int]) -> [Int] {
guard lst.count > 0 else {
return []
}
let min = lst.min()!
let max = lst.max()!
let minIndex = lst.firstIndex(of: min)!
let maxIndex = lst.firstIndex(of: max)!
let minSublist = lst[minIndex..<maxIndex]
let maxSublist = lst[maxIndex..<lst.count]
let sortedMinSublist = minSublist.sorted()
let sortedMaxSublist = maxSublist.sorted()
let result = sortedMinSublist + sortedMaxSublist
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
Answer:
```swift
func strangeSortList(lst: [Int]) -> [Int] {
guard lst.count > 0 else {
return []
}
let min = lst.min()!
let max = lst.max()!
let minIndex = lst.firstIndex(of: min)!
let maxIndex = lst.firstIndex(of: max)!
let minSublist = lst[minIndex..<maxIndex]
let maxSublist = lst[maxIndex..<lst.count]
let sortedMinSublist = minSublist.sorted()
let sortedMaxSublist = maxSublist.sorted()
let result = sortedMinSublist + sortedMaxSublist
return result
}
``` // XCTAssertTrue failedfunc strangeSortList(lst: [Int]) -> [Int] {
guard lst.count > 0 else {
return []
}
var result = [Int]()
var min = lst[0]
var max = lst[0]
for num in lst {
if num < min {
min = num
} else if num > max {
max = num
}
}
result.append(min)
result.append(max)
for num in lst {
if num!= min && num!= max {
result.append(num)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
Answer:
```swift
func strangeSortList(lst: [Int]) -> [Int] {
guard lst.count > 0 else {
return []
}
var result = [Int]()
var min = lst[0]
var max = lst[0]
for num in lst {
if num < min {
min = num
} else if num > max {
max = num
}
}
result.append(min)
result.append(max)
for num in lst {
if num!= min && num!= max {
result.append(num)
}
}
return result
}
```if num!= min && num!= max { // '=' must have consistent whitespace on both sidesif num!= min && num!= max { // use of '=' in a boolean context, did you mean '=='?if num!= min && num!= max { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadif num!= min && num!= max { // cannot force unwrap value of non-optional type 'Int'if num!= min && num!= max { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadif num!= min && num!= max { // cannot force unwrap value of non-optional type 'Int'if num!= min && num!= max { // '=' must have consistent whitespace on both sidesif num!= min && num!= max { // cannot assign value of type '()' to type 'Int'func triangleArea(a: Int, b: Int, c: Int) -> Double {
guard a + b > c && a + c > b && b + c > a else {
return -1
}
let s = (a + b + c) / 2
let area = (s * (s - a) * (s - b) * (s - c)) ** 0.5
return round(area * 100) / 100
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
Answer:
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
guard a + b > c && a + c > b && b + c > a else {
return -1
}
let s = (a + b + c) / 2
let area = (s * (s - a) * (s - b) * (s - c)) ** 0.5
return round(area * 100) / 100
}
```let area = (s * (s - a) * (s - b) * (s - c)) ** 0.5 // no operator '**' is defined; did you mean 'pow(_:_:)'?func triangleArea(a: Int, b: Int, c: Int) -> Double {
let sumAB = a + b
let sumBC = b + c
let sumCA = c + a
if sumAB <= sumBC && sumAB <= sumCA {
return -1
}
let s = (a + b + c) / 2
let area = (s * (s - a) * (s - b) * (s - c)) ** 0.5
return round(area, toPlaces: 2)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
Answer:
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
let sumAB = a + b
let sumBC = b + c
let sumCA = c + a
if sumAB <= sumBC && sumAB <= sumCA {
return -1
}
let s = (a + b + c) / 2
let area = (s * (s - a) * (s - b) * (s - c)) ** 0.5
return round(area, toPlaces: 2)
}
```let area = (s * (s - a) * (s - b) * (s - c)) ** 0.5 // no operator '**' is defined; did you mean 'pow(_:_:)'?return round(area, toPlaces: 2) // extra argument 'toPlaces' in callfunc triangleArea(a: Int, b: Int, c: Int) -> Double {
let sumAB = a + b
let sumBC = b + c
let sumCA = c + a
if sumAB <= c || sumBC <= a || sumCA <= b {
return -1
}
let s = (a + b + c) / 2
let area = (s * (s - a) * (s - b) * (s - c)) ** 0.5
return round(area * 100) / 100
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
Answer:
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
let sumAB = a + b
let sumBC = b + c
let sumCA = c + a
if sumAB <= c || sumBC <= a || sumCA <= b {
return -1
}
let s = (a + b + c) / 2
let area = (s * (s - a) * (s - b) * (s - c)) ** 0.5
return round(area * 100) / 100
}
```let area = (s * (s - a) * (s - b) * (s - c)) ** 0.5 // no operator '**' is defined; did you mean 'pow(_:_:)'?func triangleArea(a: Int, b: Int, c: Int) -> Double {
let s = (a + b + c) / 2
let area = (s * (s - a) * (s - b) * (s - c)) ** 0.5
return area.rounded(toPlaces: 2)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
Answer:
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
let s = (a + b + c) / 2
let area = (s * (s - a) * (s - b) * (s - c)) ** 0.5
return area.rounded(toPlaces: 2)
}
```let area = (s * (s - a) * (s - b) * (s - c)) ** 0.5 // no operator '**' is defined; did you mean 'pow(_:_:)'?func triangleArea(a: Int, b: Int, c: Int) -> Double {
guard a + b > c && a + c > b && b + c > a else {
return -1
}
let s = (a + b + c) / 2
let area = (s * (s - a) * (s - b) * (s - c)) ** 0.5
return round(area * 100) / 100
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
Answer:
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
guard a + b > c && a + c > b && b + c > a else {
return -1
}
let s = (a + b + c) / 2
let area = (s * (s - a) * (s - b) * (s - c)) ** 0.5
return round(area * 100) / 100
}
```let area = (s * (s - a) * (s - b) * (s - c)) ** 0.5 // no operator '**' is defined; did you mean 'pow(_:_:)'?func triangleArea(a: Int, b: Int, c: Int) -> Double {
let sumAB = a + b
let sumBC = b + c
let sumCA = c + a
if sumAB <= sumBC && sumAB <= sumCA {
return -1
}
let s = (a + b + c) / 2
let area = (s * (s - a) * (s - b) * (s - c)) ** 0.5
return round(area, toPlaces: 2)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
Answer:
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
let sumAB = a + b
let sumBC = b + c
let sumCA = c + a
if sumAB <= sumBC && sumAB <= sumCA {
return -1
}
let s = (a + b + c) / 2
let area = (s * (s - a) * (s - b) * (s - c)) ** 0.5
return round(area, toPlaces: 2)
}
```let area = (s * (s - a) * (s - b) * (s - c)) ** 0.5 // no operator '**' is defined; did you mean 'pow(_:_:)'?return round(area, toPlaces: 2) // extra argument 'toPlaces' in callfunc triangleArea(a: Int, b: Int, c: Int) -> Double {
let s = (a + b + c) / 2
let area = (s * (s - a) * (s - b) * (s - c)) ** 0.5
return area.rounded(toPlaces: 2)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
Answer:
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
let s = (a + b + c) / 2
let area = (s * (s - a) * (s - b) * (s - c)) ** 0.5
return area.rounded(toPlaces: 2)
}
```let area = (s * (s - a) * (s - b) * (s - c)) ** 0.5 // no operator '**' is defined; did you mean 'pow(_:_:)'?func triangleArea(a: Int, b: Int, c: Int) -> Double {
let s = (a + b + c) / 2
let area = sqrt(s * (s - a) * (s - b) * (s - c))
return round(area * 100) / 100
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
Answer:
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
let s = (a + b + c) / 2
let area = sqrt(s * (s - a) * (s - b) * (s - c))
return round(area * 100) / 100
}
```let area = sqrt(s * (s - a) * (s - b) * (s - c)) // cannot convert value of type 'Int' to expected argument type 'Double'func triangleArea(a: Int, b: Int, c: Int) -> Double {
guard a + b > c && a + c > b && b + c > a else {
return -1
}
let s = (a + b + c) / 2
let area = sqrt(s * (s - a) * (s - b) * (s - c))
return round(area * 100) / 100
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
Answer:
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
guard a + b > c && a + c > b && b + c > a else {
return -1
}
let s = (a + b + c) / 2
let area = sqrt(s * (s - a) * (s - b) * (s - c))
return round(area * 100) / 100
}
```let area = sqrt(s * (s - a) * (s - b) * (s - c)) // cannot convert value of type 'Int' to expected argument type 'Double'func triangleArea(a: Int, b: Int, c: Int) -> Double {
guard a + b > c, a + c > b, b + c > a else {
return -1
}
let s = (a + b + c) / 2
let area = sqrt(s * (s - a) * (s - b) * (s - c))
return round(area * 100) / 100
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
Answer:
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
guard a + b > c, a + c > b, b + c > a else {
return -1
}
let s = (a + b + c) / 2
let area = sqrt(s * (s - a) * (s - b) * (s - c))
return round(area * 100) / 100
}
```let area = sqrt(s * (s - a) * (s - b) * (s - c)) // cannot convert value of type 'Int' to expected argument type 'Double'func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let isBalanced = q == q.reversed()
return isBalanced && sum <= w
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
Answer:
```swift
func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let isBalanced = q == q.reversed()
return isBalanced && sum <= w
}
```func willItFly(q: [Int], w: Int) -> Bool {
let qCopy = q.sorted()
let sum = qCopy.reduce(0, +)
return sum <= w && qCopy == qCopy.reversed()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
Answer:
```swift
func willItFly(q: [Int], w: Int) -> Bool {
let qCopy = q.sorted()
let sum = qCopy.reduce(0, +)
return sum <= w && qCopy == qCopy.reversed()
}
``` // XCTAssertTrue failedfunc willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let isBalanced = q.count == q.reversed().count
return isBalanced && sum <= w
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
Answer:
```swift
func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let isBalanced = q.count == q.reversed().count
return isBalanced && sum <= w
}
``` // XCTAssertTrue failedfunc willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let isBalanced = q == q.reversed()
return isBalanced && sum <= w
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
Answer:
```swift
func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let isBalanced = q == q.reversed()
return isBalanced && sum <= w
}
```func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let isBalanced = q == q.reversed()
return isBalanced && sum <= w
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
Answer:
```swift
func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let isBalanced = q == q.reversed()
return isBalanced && sum <= w
}
```func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let maxSum = w / 2
return sum <= maxSum && q.isPalindrome
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
Answer:
```swift
func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let maxSum = w / 2
return sum <= maxSum && q.isPalindrome
}
```return sum <= maxSum && q.isPalindrome // value of type '[Int]' has no member 'isPalindrome'func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let isBalanced = q == q.reversed()
return isBalanced && sum <= w
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
Answer:
```swift
func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let isBalanced = q == q.reversed()
return isBalanced && sum <= w
}
```func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let isBalanced = q == q.reversed()
return isBalanced && sum <= w
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
Answer:
```swift
func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let isBalanced = q == q.reversed()
return isBalanced && sum <= w
}
```func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let balanced = q == q.reversed()
return balanced && sum <= w
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
Answer:
```swift
func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let balanced = q == q.reversed()
return balanced && sum <= w
}
```func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let isBalanced = q.count == q.reversed().count
return isBalanced && sum <= w
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
Answer:
```swift
func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let isBalanced = q.count == q.reversed().count
return isBalanced && sum <= w
}
``` // XCTAssertTrue failedfunc smallestChange(arr: [Int]) -> Int {
let n = arr.count
var left = 0
var right = n - 1
var count = 0
while left < right {
if arr[left]!= arr[right] {
count += 1
if arr[left] == arr[left + 1] {
left += 1
} else if arr[right] == arr[right - 1] {
right -= 1
} else {
left += 1
right -= 1
}
} else {
left += 1
right -= 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
Answer:
```swift
func smallestChange(arr: [Int]) -> Int {
let n = arr.count
var left = 0
var right = n - 1
var count = 0
while left < right {
if arr[left]!= arr[right] {
count += 1
if arr[left] == arr[left + 1] {
left += 1
} else if arr[right] == arr[right - 1] {
right -= 1
} else {
left += 1
right -= 1
}
} else {
left += 1
right -= 1
}
}
return count
}
```if arr[left]!= arr[right] { // cannot force unwrap value of non-optional type 'Int'if arr[left]!= arr[right] { // '=' must have consistent whitespace on both sidesif arr[left]!= arr[right] { // use of '=' in a boolean context, did you mean '=='?func smallestChange(arr: [Int]) -> Int {
let n = arr.count
var oddCount = 0
var evenCount = 0
for num in arr {
if num % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return abs(oddCount - evenCount)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
Answer:
```swift
func smallestChange(arr: [Int]) -> Int {
let n = arr.count
var oddCount = 0
var evenCount = 0
for num in arr {
if num % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return abs(oddCount - evenCount)
}
```let n = arr.count // initialization of immutable value 'n' was never used; consider replacing with assignment to '_' or removing it // XCTAssertTrue failedfunc smallestChange(arr: [Int]) -> Int {
var oddCount = 0
var evenCount = 0
for num in arr {
if num % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return abs(oddCount - evenCount)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
Answer:
```swift
func smallestChange(arr: [Int]) -> Int {
var oddCount = 0
var evenCount = 0
for num in arr {
if num % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return abs(oddCount - evenCount)
}
``` // XCTAssertTrue failedfunc smallestChange(arr: [Int]) -> Int {
let n = arr.count
var left = 0
var right = n - 1
var result = 0
while left < right {
if arr[left]!= arr[right] {
result += 1
}
left += 1
right -= 1
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
Answer:
```swift
func smallestChange(arr: [Int]) -> Int {
let n = arr.count
var left = 0
var right = n - 1
var result = 0
while left < right {
if arr[left]!= arr[right] {
result += 1
}
left += 1
right -= 1
}
return result
}
```if arr[left]!= arr[right] { // '=' must have consistent whitespace on both sidesif arr[left]!= arr[right] { // use of '=' in a boolean context, did you mean '=='?if arr[left]!= arr[right] { // cannot force unwrap value of non-optional type 'Int'func smallestChange(arr: [Int]) -> Int {
let n = arr.count
var oddCount = 0
var evenCount = 0
for num in arr {
if num % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return abs(oddCount - evenCount)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
Answer:
```swift
func smallestChange(arr: [Int]) -> Int {
let n = arr.count
var oddCount = 0
var evenCount = 0
for num in arr {
if num % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return abs(oddCount - evenCount)
}
```let n = arr.count // initialization of immutable value 'n' was never used; consider replacing with assignment to '_' or removing it // XCTAssertTrue failedfunc smallestChange(arr: [Int]) -> Int {
let n = arr.count
var oddCount = 0
var evenCount = 0
for num in arr {
if num % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (oddCount - evenCount) / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
Answer:
```swift
func smallestChange(arr: [Int]) -> Int {
let n = arr.count
var oddCount = 0
var evenCount = 0
for num in arr {
if num % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (oddCount - evenCount) / 2
}
```let n = arr.count // initialization of immutable value 'n' was never used; consider replacing with assignment to '_' or removing it // XCTAssertTrue failedfunc smallestChange(arr: [Int]) -> Int {
var oddCount = 0
var evenCount = 0
for num in arr {
if num % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return abs(oddCount - evenCount)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
Answer:
```swift
func smallestChange(arr: [Int]) -> Int {
var oddCount = 0
var evenCount = 0
for num in arr {
if num % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return abs(oddCount - evenCount)
}
``` // XCTAssertTrue failedfunc smallestChange(arr: [Int]) -> Int {
let n = arr.count
var oddCount = 0
var evenCount = 0
for num in arr {
if num % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return abs(oddCount - evenCount)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
Answer:
```swift
func smallestChange(arr: [Int]) -> Int {
let n = arr.count
var oddCount = 0
var evenCount = 0
for num in arr {
if num % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return abs(oddCount - evenCount)
}
```let n = arr.count // initialization of immutable value 'n' was never used; consider replacing with assignment to '_' or removing it // XCTAssertTrue failedfunc smallestChange(arr: [Int]) -> Int {
let n = arr.count
var oddCount = 0
var evenCount = 0
for num in arr {
if num % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (oddCount - evenCount) / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
Answer:
```swift
func smallestChange(arr: [Int]) -> Int {
let n = arr.count
var oddCount = 0
var evenCount = 0
for num in arr {
if num % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (oddCount - evenCount) / 2
}
```let n = arr.count // initialization of immutable value 'n' was never used; consider replacing with assignment to '_' or removing it // XCTAssertTrue failedfunc smallestChange(arr: [Int]) -> Int {
var oddCount = 0
var evenCount = 0
for num in arr {
if num % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return abs(oddCount - evenCount)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
Answer:
```swift
func smallestChange(arr: [Int]) -> Int {
var oddCount = 0
var evenCount = 0
for num in arr {
if num % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return abs(oddCount - evenCount)
}
``` // XCTAssertTrue failedfunc totalMatch(lst1: [String], lst2: [String]) -> [String] {
var result = [String]()
var lst1 = lst1
var lst2 = lst2
while!lst1.isEmpty &&!lst2.isEmpty {
let firstCharOfList1 = String(lst1.first!)
let firstCharOfList2 = String(lst2.first!)
if firstCharOfList1 < firstCharOfList2 {
lst1.removeFirst()
} else if firstCharOfList1 > firstCharOfList2 {
lst2.removeFirst()
} else {
result.append(firstCharOfList1)
lst1.removeFirst()
lst2.removeFirst()
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
Answer:
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
var result = [String]()
var lst1 = lst1
var lst2 = lst2
while!lst1.isEmpty &&!lst2.isEmpty {
let firstCharOfList1 = String(lst1.first!)
let firstCharOfList2 = String(lst2.first!)
if firstCharOfList1 < firstCharOfList2 {
lst1.removeFirst()
} else if firstCharOfList1 > firstCharOfList2 {
lst2.removeFirst()
} else {
result.append(firstCharOfList1)
lst1.removeFirst()
lst2.removeFirst()
}
}
return result
}
```while!lst1.isEmpty &&!lst2.isEmpty { // expected expression, var, or let in 'while' conditionfunc totalMatch(lst1: [String], lst2: [String]) -> [String] {
var result = [String]()
var lst1Chars = 0
var lst2Chars = 0
for str in lst1 {
lst1Chars += str.count
}
for str in lst2 {
lst2Chars += str.count
}
if lst1Chars < lst2Chars {
result = lst1
} else {
result = lst2
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
Answer:
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
var result = [String]()
var lst1Chars = 0
var lst2Chars = 0
for str in lst1 {
lst1Chars += str.count
}
for str in lst2 {
lst2Chars += str.count
}
if lst1Chars < lst2Chars {
result = lst1
} else {
result = lst2
}
return result
}
``` // XCTAssertTrue failedfunc totalMatch(lst1: [String], lst2: [String]) -> [String] {
var result = [String]()
var min = lst1.count
for str in lst2 {
if str.count < min {
min = str.count
result = [str]
} else if str.count == min {
result.append(str)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
Answer:
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
var result = [String]()
var min = lst1.count
for str in lst2 {
if str.count < min {
min = str.count
result = [str]
} else if str.count == min {
result.append(str)
}
}
return result
}
``` // XCTAssertTrue failedfunc totalMatch(lst1: [String], lst2: [String]) -> [String] {
var result = [String]()
var lst1Chars = 0
var lst2Chars = 0
for str in lst1 {
lst1Chars += str.count
}
for str in lst2 {
lst2Chars += str.count
}
if lst1Chars < lst2Chars {
return lst1
} else {
return lst2
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
Answer:
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
var result = [String]()
var lst1Chars = 0
var lst2Chars = 0
for str in lst1 {
lst1Chars += str.count
}
for str in lst2 {
lst2Chars += str.count
}
if lst1Chars < lst2Chars {
return lst1
} else {
return lst2
}
}
```var result = [String]() // initialization of variable 'result' was never used; consider replacing with assignment to '_' or removing it // XCTAssertTrue failedfunc totalMatch(lst1: [String], lst2: [String]) -> [String] {
var result = [String]()
var lst1Chars = 0
var lst2Chars = 0
for str in lst1 {
lst1Chars += str.count
}
for str in lst2 {
lst2Chars += str.count
}
if lst1Chars < lst2Chars {
result = lst1
} else {
result = lst2
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
Answer:
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
var result = [String]()
var lst1Chars = 0
var lst2Chars = 0
for str in lst1 {
lst1Chars += str.count
}
for str in lst2 {
lst2Chars += str.count
}
if lst1Chars < lst2Chars {
result = lst1
} else {
result = lst2
}
return result
}
``` // XCTAssertTrue failedfunc totalMatch(lst1: [String], lst2: [String]) -> [String] {
var result = [String]()
var lst1Chars = 0
var lst2Chars = 0
for str in lst1 {
lst1Chars += str.count
}
for str in lst2 {
lst2Chars += str.count
}
if lst1Chars < lst2Chars {
result = lst1
} else {
result = lst2
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
Answer:
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
var result = [String]()
var lst1Chars = 0
var lst2Chars = 0
for str in lst1 {
lst1Chars += str.count
}
for str in lst2 {
lst2Chars += str.count
}
if lst1Chars < lst2Chars {
result = lst1
} else {
result = lst2
}
return result
}
``` // XCTAssertTrue failedfunc totalMatch(lst1: [String], lst2: [String]) -> [String] {
var result = [String]()
var lst1Chars = 0
var lst2Chars = 0
for str in lst1 {
lst1Chars += str.count
}
for str in lst2 {
lst2Chars += str.count
}
if lst1Chars < lst2Chars {
result = lst1
} else {
result = lst2
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
Answer:
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
var result = [String]()
var lst1Chars = 0
var lst2Chars = 0
for str in lst1 {
lst1Chars += str.count
}
for str in lst2 {
lst2Chars += str.count
}
if lst1Chars < lst2Chars {
result = lst1
} else {
result = lst2
}
return result
}
``` // XCTAssertTrue failedfunc totalMatch(lst1: [String], lst2: [String]) -> [String] {
var result = [String]()
var lst1Chars = 0
var lst2Chars = 0
for str in lst1 {
lst1Chars += str.count
}
for str in lst2 {
lst2Chars += str.count
}
if lst1Chars < lst2Chars {
result = lst1
} else {
result = lst2
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
Answer:
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
var result = [String]()
var lst1Chars = 0
var lst2Chars = 0
for str in lst1 {
lst1Chars += str.count
}
for str in lst2 {
lst2Chars += str.count
}
if lst1Chars < lst2Chars {
result = lst1
} else {
result = lst2
}
return result
}
``` // XCTAssertTrue failedfunc totalMatch(lst1: [String], lst2: [String]) -> [String] {
var result = [String]()
var lst1Chars = 0
var lst2Chars = 0
for str in lst1 {
lst1Chars += str.count
}
for str in lst2 {
lst2Chars += str.count
}
if lst1Chars < lst2Chars {
result = lst1
} else {
result = lst2
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
Answer:
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
var result = [String]()
var lst1Chars = 0
var lst2Chars = 0
for str in lst1 {
lst1Chars += str.count
}
for str in lst2 {
lst2Chars += str.count
}
if lst1Chars < lst2Chars {
result = lst1
} else {
result = lst2
}
return result
}
``` // XCTAssertTrue failedfunc totalMatch(lst1: [String], lst2: [String]) -> [String] {
var result = [String]()
var lst1Chars = 0
var lst2Chars = 0
for str in lst1 {
lst1Chars += str.count
}
for str in lst2 {
lst2Chars += str.count
}
if lst1Chars < lst2Chars {
result = lst1
} else {
result = lst2
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
Answer:
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
var result = [String]()
var lst1Chars = 0
var lst2Chars = 0
for str in lst1 {
lst1Chars += str.count
}
for str in lst2 {
lst2Chars += str.count
}
if lst1Chars < lst2Chars {
result = lst1
} else {
result = lst2
}
return result
}
``` // XCTAssertTrue failedfunc isMultiplyPrime(a: Int) -> Bool {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29]
var result = false
for i in 0..<primes.count {
for j in 0..<primes.count {
for k in 0..<primes.count {
if primes[i] * primes[j] * primes[k] == a {
result = true
break
}
}
if result {
break
}
}
if result {
break
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
Answer:
```swift
func isMultiplyPrime(a: Int) -> Bool {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29]
var result = false
for i in 0..<primes.count {
for j in 0..<primes.count {
for k in 0..<primes.count {
if primes[i] * primes[j] * primes[k] == a {
result = true
break
}
}
if result {
break
}
}
if result {
break
}
}
return result
}
```func isMultiplyPrime(a: Int) -> Bool {
if a < 2 {
return false
}
for i in 2...a {
if a % i == 0 {
let aDividedByI = a / i
if aDividedByI < 2 {
return false
}
for j in 2...aDividedByI {
if aDividedByI % j == 0 {
return false
}
}
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
Answer:
```swift
func isMultiplyPrime(a: Int) -> Bool {
if a < 2 {
return false
}
for i in 2...a {
if a % i == 0 {
let aDividedByI = a / i
if aDividedByI < 2 {
return false
}
for j in 2...aDividedByI {
if aDividedByI % j == 0 {
return false
}
}
}
}
return true
}
``` // XCTAssertTrue failedfunc isMultiplyPrime(a: Int) -> Bool {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29]
var result = false
for i in primes {
if a % i == 0 {
let newA = a / i
for j in primes {
if newA % j == 0 {
let newNewA = newA / j
if primes.contains(newNewA) {
result = true
break
}
}
}
if result {
break
}
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
Answer:
```swift
func isMultiplyPrime(a: Int) -> Bool {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29]
var result = false
for i in primes {
if a % i == 0 {
let newA = a / i
for j in primes {
if newA % j == 0 {
let newNewA = newA / j
if primes.contains(newNewA) {
result = true
break
}
}
}
if result {
break
}
}
}
return result
}
```func isMultiplyPrime(a: Int) -> Bool {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29]
var result = false
for i in 0..<primes.count {
for j in 0..<primes.count {
for k in 0..<primes.count {
if primes[i] * primes[j] * primes[k] == a {
result = true
}
}
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
Answer:
```swift
func isMultiplyPrime(a: Int) -> Bool {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29]
var result = false
for i in 0..<primes.count {
for j in 0..<primes.count {
for k in 0..<primes.count {
if primes[i] * primes[j] * primes[k] == a {
result = true
}
}
}
}
return result
}
```func isMultiplyPrime(a: Int) -> Bool {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29]
var result = false
for prime in primes {
if a % prime == 0 {
result = true
break
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
Answer:
```swift
func isMultiplyPrime(a: Int) -> Bool {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29]
var result = false
for prime in primes {
if a % prime == 0 {
result = true
break
}
}
return result
}
``` // XCTAssertTrue failedfunc isMultiplyPrime(a: Int) -> Bool {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29]
var product = 1
for prime in primes {
if a % prime == 0 {
product *= prime
}
}
return product == a
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
Answer:
```swift
func isMultiplyPrime(a: Int) -> Bool {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29]
var product = 1
for prime in primes {
if a % prime == 0 {
product *= prime
}
}
return product == a
}
``` // XCTAssertTrue failedfunc isMultiplyPrime(a: Int) -> Bool {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29]
var result = false
for i in primes {
if a % i == 0 {
for j in primes {
if a % j == 0 {
for k in primes {
if a % k == 0 {
result = true
break
}
}
break
}
}
break
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
Answer:
```swift
func isMultiplyPrime(a: Int) -> Bool {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29]
var result = false
for i in primes {
if a % i == 0 {
for j in primes {
if a % j == 0 {
for k in primes {
if a % k == 0 {
result = true
break
}
}
break
}
}
break
}
}
return result
}
``` // XCTAssertTrue failedfunc isMultiplyPrime(a: Int) -> Bool {
let numbers = [2, 3, 5]
var result = true
var number = a
for num in numbers {
while number % num == 0 {
number /= num
}
if number == 1 {
result = false
break
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
Answer:
```swift
func isMultiplyPrime(a: Int) -> Bool {
let numbers = [2, 3, 5]
var result = true
var number = a
for num in numbers {
while number % num == 0 {
number /= num
}
if number == 1 {
result = false
break
}
}
return result
}
``` // XCTAssertTrue failedfunc isMultiplyPrime(a: Int) -> Bool {
let numbers = [2, 3, 5]
var result = true
var number = a
for num in numbers {
while number % num == 0 {
number /= num
}
}
return number == 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
Answer:
```swift
func isMultiplyPrime(a: Int) -> Bool {
let numbers = [2, 3, 5]
var result = true
var number = a
for num in numbers {
while number % num == 0 {
number /= num
}
}
return number == 1
}
```var result = true // initialization of variable 'result' was never used; consider replacing with assignment to '_' or removing it // XCTAssertTrue failedfunc isMultiplyPrime(a: Int) -> Bool {
let numbers = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29]
var result = false
for i in numbers {
if a % i == 0 {
result = true
break
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
Answer:
```swift
func isMultiplyPrime(a: Int) -> Bool {
let numbers = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29]
var result = false
for i in numbers {
if a % i == 0 {
result = true
break
}
}
return result
}
``` // XCTAssertTrue failedfunc isSimplePower(x: Int, n: Int) -> Bool {
let power = Int(log(Double(x)) / log(Double(n)))
return power * n == x
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
Answer:
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
let power = Int(log(Double(x)) / log(Double(n)))
return power * n == x
}
``` // XCTAssertTrue failedfunc isSimplePower(x: Int, n: Int) -> Bool {
let logX = log(Double(x)) / log(Double(n))
return abs(logX - round(logX)) < 0.0001
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
Answer:
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
let logX = log(Double(x)) / log(Double(n))
return abs(logX - round(logX)) < 0.0001
}
``` // XCTAssertTrue failedfunc isSimplePower(x: Int, n: Int) -> Bool {
return pow(Double(n), Double(x)) == Double(x)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
Answer:
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
return pow(Double(n), Double(x)) == Double(x)
}
``` // XCTAssertTrue failedfunc isSimplePower(x: Int, n: Int) -> Bool {
return pow(Double(n), Double(x)) == Double(x)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
Answer:
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
return pow(Double(n), Double(x)) == Double(x)
}
``` // XCTAssertTrue failedfunc isSimplePower(x: Int, n: Int) -> Bool {
let power = Int(log(Double(x)) / log(Double(n)))
return x == pow(Double(n), Double(power))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
Answer:
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
let power = Int(log(Double(x)) / log(Double(n)))
return x == pow(Double(n), Double(power))
}
```return x == pow(Double(n), Double(power)) // cannot convert value of type 'Double' to expected argument type 'Int'func isSimplePower(x: Int, n: Int) -> Bool {
let logX = log(Double(x)) / log(Double(n))
return (logX - floor(logX)) == 0
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
Answer:
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
let logX = log(Double(x)) / log(Double(n))
return (logX - floor(logX)) == 0
}
``` // XCTAssertTrue failedfunc isSimplePower(x: Int, n: Int) -> Bool {
let logN = log(Double(n))
let logX = log(Double(x))
return abs(logX / logN - round(logX / logN)) < 0.00001
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
Answer:
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
let logN = log(Double(n))
let logX = log(Double(x))
return abs(logX / logN - round(logX / logN)) < 0.00001
}
``` // XCTAssertTrue failedfunc isSimplePower(x: Int, n: Int) -> Bool {
let power = Int(log(Double(x)) / log(Double(n)))
return power * n == x
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
Answer:
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
let power = Int(log(Double(x)) / log(Double(n)))
return power * n == x
}
``` // XCTAssertTrue failedfunc isSimplePower(x: Int, n: Int) -> Bool {
return pow(Double(n), Double(x)) == Double(x)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
Answer:
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
return pow(Double(n), Double(x)) == Double(x)
}
``` // XCTAssertTrue failedfunc isSimplePower(x: Int, n: Int) -> Bool {
let logX = log(Double(x)) / log(Double(n))
return abs(logX - round(logX)) < 0.00001
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
Answer:
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
let logX = log(Double(x)) / log(Double(n))
return abs(logX - round(logX)) < 0.00001
}
``` // XCTAssertTrue failedfunc iscube(a: Int) -> Bool {
let root = Int(sqrt(Double(a)))
return a == root * root * root
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
Answer:
```swift
func iscube(a: Int) -> Bool {
let root = Int(sqrt(Double(a)))
return a == root * root * root
}
``` // Fatal error: Double value cannot be converted to Int because it is either infinite or NaNfunc iscube(a: Int) -> Bool {
let root = Int(sqrt(Double(a)))
return a == root * root * root
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
Answer:
```swift
func iscube(a: Int) -> Bool {
let root = Int(sqrt(Double(a)))
return a == root * root * root
}
``` // Fatal error: Double value cannot be converted to Int because it is either infinite or NaNfunc iscube(a: Int) -> Bool {
let root = Int(sqrt(Double(a)))
return a == root * root * root
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
Answer:
```swift
func iscube(a: Int) -> Bool {
let root = Int(sqrt(Double(a)))
return a == root * root * root
}
``` // Fatal error: Double value cannot be converted to Int because it is either infinite or NaNfunc iscube(a: Int) -> Bool {
let root = Int(sqrt(Double(a)))
return a == root * root * root
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
Answer:
```swift
func iscube(a: Int) -> Bool {
let root = Int(sqrt(Double(a)))
return a == root * root * root
}
``` // Fatal error: Double value cannot be converted to Int because it is either infinite or NaNfunc iscube(a: Int) -> Bool {
let root = Int(sqrt(Double(a)))
return root * root * root == a
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
Answer:
```swift
func iscube(a: Int) -> Bool {
let root = Int(sqrt(Double(a)))
return root * root * root == a
}
``` // Fatal error: Double value cannot be converted to Int because it is either infinite or NaNfunc iscube(a: Int) -> Bool {
let root = Int(sqrt(Double(a)))
return root * root * root == a
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
Answer:
```swift
func iscube(a: Int) -> Bool {
let root = Int(sqrt(Double(a)))
return root * root * root == a
}
``` // Fatal error: Double value cannot be converted to Int because it is either infinite or NaNfunc iscube(a: Int) -> Bool {
let root = Int(sqrt(Double(a)))
return root * root * root == a
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
Answer:
```swift
func iscube(a: Int) -> Bool {
let root = Int(sqrt(Double(a)))
return root * root * root == a
}
``` // Fatal error: Double value cannot be converted to Int because it is either infinite or NaNfunc iscube(a: Int) -> Bool {
let root = Int(sqrt(Double(a)))
return root * root * root == a
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
Answer:
```swift
func iscube(a: Int) -> Bool {
let root = Int(sqrt(Double(a)))
return root * root * root == a
}
``` // Fatal error: Double value cannot be converted to Int because it is either infinite or NaNfunc iscube(a: Int) -> Bool {
let root = Int(sqrt(Double(a)))
return a == root * root * root
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
Answer:
```swift
func iscube(a: Int) -> Bool {
let root = Int(sqrt(Double(a)))
return a == root * root * root
}
``` // Fatal error: Double value cannot be converted to Int because it is either infinite or NaNfunc iscube(a: Int) -> Bool {
let root = Int(sqrt(Double(a)))
return a == root * root * root
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
Answer:
```swift
func iscube(a: Int) -> Bool {
let root = Int(sqrt(Double(a)))
return a == root * root * root
}
``` // Fatal error: Double value cannot be converted to Int because it is either infinite or NaNfunc hexKey(num: String) -> Int {
var count = 0
for digit in num {
let decimalValue = Int(String(digit), radix: 16)!
if decimalValue == 2 || decimalValue == 3 || decimalValue == 5 || decimalValue == 7 || decimalValue == 11 || decimalValue == 13 {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
Answer:
```swift
func hexKey(num: String) -> Int {
var count = 0
for digit in num {
let decimalValue = Int(String(digit), radix: 16)!
if decimalValue == 2 || decimalValue == 3 || decimalValue == 5 || decimalValue == 7 || decimalValue == 11 || decimalValue == 13 {
count += 1
}
}
return count
}
```func hexKey(num: String) -> Int {
let hexChars = num.uppercased().map { String($0) }
let hexNumbers = hexChars.map { Int($0, radix: 16)! }
let primes = [2, 3, 5, 7, 11, 13]
return hexNumbers.filter { primes.contains($0) }.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
Answer:
```swift
func hexKey(num: String) -> Int {
let hexChars = num.uppercased().map { String($0) }
let hexNumbers = hexChars.map { Int($0, radix: 16)! }
let primes = [2, 3, 5, 7, 11, 13]
return hexNumbers.filter { primes.contains($0) }.count
}
```func hexKey(num: String) -> Int {
let hex = num.uppercased()
var count = 0
for digit in hex {
let decimal = Int(String(digit), radix: 16)!
if decimal == 2 || decimal == 3 || decimal == 5 || decimal == 7 || decimal == 11 || decimal == 13 {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
Answer:
```swift
func hexKey(num: String) -> Int {
let hex = num.uppercased()
var count = 0
for digit in hex {
let decimal = Int(String(digit), radix: 16)!
if decimal == 2 || decimal == 3 || decimal == 5 || decimal == 7 || decimal == 11 || decimal == 13 {
count += 1
}
}
return count
}
```func hexKey(num: String) -> Int {
let hexChars = num.uppercased().map { String($0) }
let hexNumbers = hexChars.map { Int($0, radix: 16)! }
let primes = Set([2, 3, 5, 7, 11, 13])
return hexNumbers.filter { primes.contains($0) }.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
Answer:
```swift
func hexKey(num: String) -> Int {
let hexChars = num.uppercased().map { String($0) }
let hexNumbers = hexChars.map { Int($0, radix: 16)! }
let primes = Set([2, 3, 5, 7, 11, 13])
return hexNumbers.filter { primes.contains($0) }.count
}
```func hexKey(num: String) -> Int {
var count = 0
for char in num {
if let decimal = Int(String(char), radix: 16) {
if isPrime(decimal) {
count += 1
}
}
}
return count
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
var i = 3
while i * i <= number {
if number % i == 0 {
return false
}
i += 2
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
Answer:
```swift
func hexKey(num: String) -> Int {
var count = 0
for char in num {
if let decimal = Int(String(char), radix: 16) {
if isPrime(decimal) {
count += 1
}
}
}
return count
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
var i = 3
while i * i <= number {
if number % i == 0 {
return false
}
i += 2
}
return true
}
```func hexKey(num: String) -> Int {
var count = 0
for digit in num {
let decimalValue = Int(String(digit), radix: 16)!
if decimalValue == 2 || decimalValue == 3 || decimalValue == 5 || decimalValue == 7 || decimalValue == 11 || decimalValue == 13 {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
Answer:
```swift
func hexKey(num: String) -> Int {
var count = 0
for digit in num {
let decimalValue = Int(String(digit), radix: 16)!
if decimalValue == 2 || decimalValue == 3 || decimalValue == 5 || decimalValue == 7 || decimalValue == 11 || decimalValue == 13 {
count += 1
}
}
return count
}
```func hexKey(num: String) -> Int {
let hexChars = num.uppercased().components(separatedBy: " ")
var count = 0
for hexChar in hexChars {
let decimalValue = Int(String(hexChar), radix: 16)!
if isPrime(decimalValue) {
count += 1
}
}
return count
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
Answer:
```swift
func hexKey(num: String) -> Int {
let hexChars = num.uppercased().components(separatedBy: " ")
var count = 0
for hexChar in hexChars {
let decimalValue = Int(String(hexChar), radix: 16)!
if isPrime(decimalValue) {
count += 1
}
}
return count
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc hexKey(num: String) -> Int {
var count = 0
for digit in num {
let decimalValue = Int(String(digit), radix: 16)!
if decimalValue == 2 || decimalValue == 3 || decimalValue == 5 || decimalValue == 7 || decimalValue == 11 || decimalValue == 13 {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
Answer:
```swift
func hexKey(num: String) -> Int {
var count = 0
for digit in num {
let decimalValue = Int(String(digit), radix: 16)!
if decimalValue == 2 || decimalValue == 3 || decimalValue == 5 || decimalValue == 7 || decimalValue == 11 || decimalValue == 13 {
count += 1
}
}
return count
}
```func hexKey(num: String) -> Int {
var count = 0
let hexChars = num.uppercased().map { String($0) }
let hexNumbers = hexChars.map { Int($0, radix: 16)! }
for number in hexNumbers {
if isPrime(number) {
count += 1
}
}
return count
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
Answer:
```swift
func hexKey(num: String) -> Int {
var count = 0
let hexChars = num.uppercased().map { String($0) }
let hexNumbers = hexChars.map { Int($0, radix: 16)! }
for number in hexNumbers {
if isPrime(number) {
count += 1
}
}
return count
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```func hexKey(num: String) -> Int {
let hexChars = num.uppercased().map { String($0) }
let hexNumbers = hexChars.map { Int($0, radix: 16)! }
let primes = [2, 3, 5, 7, 11, 13]
return hexNumbers.filter { primes.contains($0) }.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
Answer:
```swift
func hexKey(num: String) -> Int {
let hexChars = num.uppercased().map { String($0) }
let hexNumbers = hexChars.map { Int($0, radix: 16)! }
let primes = [2, 3, 5, 7, 11, 13]
return hexNumbers.filter { primes.contains($0) }.count
}
```func decimalToBinary(decimal: Int) -> String {
let binaryString = String(format: "%08d", decimal)
let binaryArray = Array(binaryString.utf8)
let binaryStringWithPrefixAndSuffix = "db" + String(binaryArray) + "db"
return binaryStringWithPrefixAndSuffix
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
Answer:
```swift
func decimalToBinary(decimal: Int) -> String {
let binaryString = String(format: "%08d", decimal)
let binaryArray = Array(binaryString.utf8)
let binaryStringWithPrefixAndSuffix = "db" + String(binaryArray) + "db"
return binaryStringWithPrefixAndSuffix
}
```let binaryStringWithPrefixAndSuffix = "db" + String(binaryArray) + "db" // no exact matches in call to initializerfunc decimalToBinary(decimal: Int) -> String {
let binaryString = String(format: "%08d", decimal)
let binaryArray = Array(binaryString.utf8)
let binaryStringWithExtraChars = "db\(binaryArray.joined())db"
return binaryStringWithExtraChars
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
Answer:
```swift
func decimalToBinary(decimal: Int) -> String {
let binaryString = String(format: "%08d", decimal)
let binaryArray = Array(binaryString.utf8)
let binaryStringWithExtraChars = "db\(binaryArray.joined())db"
return binaryStringWithExtraChars
}
```let binaryStringWithExtraChars = "db\(binaryArray.joined())db" // referencing instance method 'joined(separator:)' on 'BidirectionalCollection' requires the types 'String.UTF8View.Element' (aka 'UInt8') and 'String' be equivalentfunc decimalToBinary(decimal: Int) -> String {
let binaryString = String(format: "%08d", decimal)
let binaryArray = Array(binaryString.utf8)
let binaryStringWithPrefixAndSuffix = "db\(binaryArray.joined())db"
return binaryStringWithPrefixAndSuffix
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
Answer:
```swift
func decimalToBinary(decimal: Int) -> String {
let binaryString = String(format: "%08d", decimal)
let binaryArray = Array(binaryString.utf8)
let binaryStringWithPrefixAndSuffix = "db\(binaryArray.joined())db"
return binaryStringWithPrefixAndSuffix
}
```let binaryStringWithPrefixAndSuffix = "db\(binaryArray.joined())db" // referencing instance method 'joined(separator:)' on 'BidirectionalCollection' requires the types 'String.UTF8View.Element' (aka 'UInt8') and 'String' be equivalentfunc decimalToBinary(decimal: Int) -> String {
let binaryString = String(format: "%08d", decimal)
let binaryArray = Array(binaryString.utf8)
let binaryStringWithPrefixAndSuffix = "db" + String(binaryArray) + "db"
return binaryStringWithPrefixAndSuffix
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
Answer:
```swift
func decimalToBinary(decimal: Int) -> String {
let binaryString = String(format: "%08d", decimal)
let binaryArray = Array(binaryString.utf8)
let binaryStringWithPrefixAndSuffix = "db" + String(binaryArray) + "db"
return binaryStringWithPrefixAndSuffix
}
```let binaryStringWithPrefixAndSuffix = "db" + String(binaryArray) + "db" // no exact matches in call to initializerfunc decimalToBinary(decimal: Int) -> String {
let binaryString = String(format: "%08d", decimal)
return "db\(binaryString)db"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
Answer:
```swift
func decimalToBinary(decimal: Int) -> String {
let binaryString = String(format: "%08d", decimal)
return "db\(binaryString)db"
}
``` // XCTAssertTrue failedfunc decimalToBinary(decimal: Int) -> String {
let binaryString = String(format: "%08d", decimal)
return "db\(binaryString)db"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
Answer:
```swift
func decimalToBinary(decimal: Int) -> String {
let binaryString = String(format: "%08d", decimal)
return "db\(binaryString)db"
}
``` // XCTAssertTrue failedfunc decimalToBinary(decimal: Int) -> String {
var binary = ""
var decimalNumber = decimal
while decimalNumber > 0 {
let remainder = decimalNumber % 2
binary = String(remainder) + binary
decimalNumber /= 2
}
return "db" + binary + "db"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
Answer:
```swift
func decimalToBinary(decimal: Int) -> String {
var binary = ""
var decimalNumber = decimal
while decimalNumber > 0 {
let remainder = decimalNumber % 2
binary = String(remainder) + binary
decimalNumber /= 2
}
return "db" + binary + "db"
}
``` // XCTAssertTrue failedfunc decimalToBinary(decimal: Int) -> String {
var binaryString = "db"
var decimalNumber = decimal
while decimalNumber > 0 {
let remainder = decimalNumber % 2
binaryString.append(remainder == 0? "0" : "1")
decimalNumber /= 2
}
binaryString.append("db")
return binaryString
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
Answer:
```swift
func decimalToBinary(decimal: Int) -> String {
var binaryString = "db"
var decimalNumber = decimal
while decimalNumber > 0 {
let remainder = decimalNumber % 2
binaryString.append(remainder == 0? "0" : "1")
decimalNumber /= 2
}
binaryString.append("db")
return binaryString
}
```binaryString.append(remainder == 0? "0" : "1") // cannot use optional chaining on non-optional value of type 'Int'binaryString.append(remainder == 0? "0" : "1") // expected ',' separatorbinaryString.append(remainder == 0? "0" : "1") // no exact matches in call to instance method 'append'func decimalToBinary(decimal: Int) -> String {
let binary = decimal.description
let binaryString = "db\(binary)db"
return binaryString
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
Answer:
```swift
func decimalToBinary(decimal: Int) -> String {
let binary = decimal.description
let binaryString = "db\(binary)db"
return binaryString
}
``` // XCTAssertTrue failedfunc decimalToBinary(decimal: Int) -> String {
let binaryString = String(format: "%db", decimal)
return binaryString
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
Answer:
```swift
func decimalToBinary(decimal: Int) -> String {
let binaryString = String(format: "%db", decimal)
return binaryString
}
``` // XCTAssertTrue failedfunc isHappy(s: String) -> Bool {
let sorted = s.sorted()
let window = s.count >= 3? Array(sorted[0..<3]) : []
return window.count == Set(window).count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
Answer:
```swift
func isHappy(s: String) -> Bool {
let sorted = s.sorted()
let window = s.count >= 3? Array(sorted[0..<3]) : []
return window.count == Set(window).count
}
```let window = s.count >= 3? Array(sorted[0..<3]) : [] // consecutive statements on a line must be separated by ';'let window = s.count >= 3? Array(sorted[0..<3]) : [] // consecutive statements on a line must be separated by ';'let window = s.count >= 3? Array(sorted[0..<3]) : [] // result of 'Array<Element>' initializer is unusedlet window = s.count >= 3? Array(sorted[0..<3]) : [] // cannot use optional chaining on non-optional value of type 'Int'let window = s.count >= 3? Array(sorted[0..<3]) : [] // expected expressionlet window = s.count >= 3? Array(sorted[0..<3]) : [] // value of optional type 'Int?' must be unwrapped to a value of type 'Int'func isHappy(s: String) -> Bool {
let sorted = s.sorted()
for i in 0..<sorted.count-2 {
if sorted[i] == sorted[i+1] && sorted[i] == sorted[i+2] {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
Answer:
```swift
func isHappy(s: String) -> Bool {
let sorted = s.sorted()
for i in 0..<sorted.count-2 {
if sorted[i] == sorted[i+1] && sorted[i] == sorted[i+2] {
return false
}
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc isHappy(s: String) -> Bool {
let sChars = Array(s)
let sCharsCount = sChars.count
if sCharsCount < 3 {
return false
}
var isHappy = true
var lastChar = sChars[0]
for i in 1..<sCharsCount {
let currentChar = sChars[i]
if currentChar == lastChar {
isHappy = false
break
}
lastChar = currentChar
}
return isHappy
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
Answer:
```swift
func isHappy(s: String) -> Bool {
let sChars = Array(s)
let sCharsCount = sChars.count
if sCharsCount < 3 {
return false
}
var isHappy = true
var lastChar = sChars[0]
for i in 1..<sCharsCount {
let currentChar = sChars[i]
if currentChar == lastChar {
isHappy = false
break
}
lastChar = currentChar
}
return isHappy
}
``` // XCTAssertTrue failedfunc isHappy(s: String) -> Bool {
let sChars = Array(s)
let sCharsCount = sChars.count
let sCharsChars = sChars.map { String($0) }
if sCharsCount < 3 {
return false
}
var lastChar = sCharsChars[0]
var count = 1
for i in 1..<sCharsChars.count {
if sCharsChars[i] == lastChar {
count += 1
} else {
count = 1
lastChar = sCharsChars[i]
}
if count == 3 {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
Answer:
```swift
func isHappy(s: String) -> Bool {
let sChars = Array(s)
let sCharsCount = sChars.count
let sCharsChars = sChars.map { String($0) }
if sCharsCount < 3 {
return false
}
var lastChar = sCharsChars[0]
var count = 1
for i in 1..<sCharsChars.count {
if sCharsChars[i] == lastChar {
count += 1
} else {
count = 1
lastChar = sCharsChars[i]
}
if count == 3 {
return true
}
}
return false
}
``` // XCTAssertTrue failedfunc isHappy(s: String) -> Bool {
let sChars = Array(s)
let sCharsCount = sChars.count
if sCharsCount < 3 {
return false
}
for i in 0..<sCharsCount - 2 {
let first = sChars[i]
let second = sChars[i + 1]
let third = sChars[i + 2]
if first == second || first == third || second == third {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
Answer:
```swift
func isHappy(s: String) -> Bool {
let sChars = Array(s)
let sCharsCount = sChars.count
if sCharsCount < 3 {
return false
}
for i in 0..<sCharsCount - 2 {
let first = sChars[i]
let second = sChars[i + 1]
let third = sChars[i + 2]
if first == second || first == third || second == third {
return false
}
}
return true
}
```func isHappy(s: String) -> Bool {
let sorted = s.sorted()
let distinct = Set(sorted)
return sorted == distinct
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
Answer:
```swift
func isHappy(s: String) -> Bool {
let sorted = s.sorted()
let distinct = Set(sorted)
return sorted == distinct
}
```return sorted == distinct // cannot convert value of type 'Set<String.Element>' (aka 'Set<Character>') to expected argument type '[String.Element]' (aka 'Array<Character>')func isHappy(s: String) -> Bool {
let sChars = Array(s)
let sCharsCount = sChars.count
if sCharsCount < 3 {
return false
}
var firstRun = true
var lastRun = true
while firstRun || lastRun {
firstRun = false
lastRun = false
for i in 0..<sCharsCount-2 {
let first = sChars[i]
let second = sChars[i+1]
let third = sChars[i+2]
if first == second || first == third || second == third {
firstRun = true
}
}
for i in 1..<sCharsCount-1 {
let first = sChars[i-1]
let second = sChars[i]
let third = sChars[i+1]
if first == second || first == third || second == third {
lastRun = true
}
}
}
return!firstRun
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
Answer:
```swift
func isHappy(s: String) -> Bool {
let sChars = Array(s)
let sCharsCount = sChars.count
if sCharsCount < 3 {
return false
}
var firstRun = true
var lastRun = true
while firstRun || lastRun {
firstRun = false
lastRun = false
for i in 0..<sCharsCount-2 {
let first = sChars[i]
let second = sChars[i+1]
let third = sChars[i+2]
if first == second || first == third || second == third {
firstRun = true
}
}
for i in 1..<sCharsCount-1 {
let first = sChars[i-1]
let second = sChars[i]
let third = sChars[i+1]
if first == second || first == third || second == third {
lastRun = true
}
}
}
return!firstRun
}
```return!firstRun // expected expression in 'return' statementfunc isHappy(s: String) -> Bool {
let sChars = Array(s)
let sCharsCount = sChars.count
if sCharsCount < 3 {
return false
}
var lastChar = sChars[0]
var count = 1
var isHappy = true
for i in 1..<sCharsCount {
let currentChar = sChars[i]
if currentChar == lastChar {
count += 1
if count > 1 {
isHappy = false
break
}
} else {
count = 1
lastChar = currentChar
}
}
return isHappy
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
Answer:
```swift
func isHappy(s: String) -> Bool {
let sChars = Array(s)
let sCharsCount = sChars.count
if sCharsCount < 3 {
return false
}
var lastChar = sChars[0]
var count = 1
var isHappy = true
for i in 1..<sCharsCount {
let currentChar = sChars[i]
if currentChar == lastChar {
count += 1
if count > 1 {
isHappy = false
break
}
} else {
count = 1
lastChar = currentChar
}
}
return isHappy
}
``` // XCTAssertTrue failedfunc isHappy(s: String) -> Bool {
let sorted = s.sorted()
let distinct = Set(sorted)
return sorted == distinct.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
Answer:
```swift
func isHappy(s: String) -> Bool {
let sorted = s.sorted()
let distinct = Set(sorted)
return sorted == distinct.sorted()
}
``` // XCTAssertTrue failedfunc isHappy(s: String) -> Bool {
let sortedS = s.sorted()
let distinctS = sortedS.filter { (s[$0], s[$0 + 1], s[$0 + 2])!= (s[$0 + 1], s[$0 + 2], s[$0 + 3]) }
return distinctS.count == s.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
Answer:
```swift
func isHappy(s: String) -> Bool {
let sortedS = s.sorted()
let distinctS = sortedS.filter { (s[$0], s[$0 + 1], s[$0 + 2])!= (s[$0 + 1], s[$0 + 2], s[$0 + 3]) }
return distinctS.count == s.count
}
```let distinctS = sortedS.filter { (s[$0], s[$0 + 1], s[$0 + 2])!= (s[$0 + 1], s[$0 + 2], s[$0 + 3]) } // '=' must have consistent whitespace on both sideslet distinctS = sortedS.filter { (s[$0], s[$0 + 1], s[$0 + 2])!= (s[$0 + 1], s[$0 + 2], s[$0 + 3]) } // the compiler is unable to type-check this expression in reasonable time; try breaking up the expression into distinct sub-expressionsfunc numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades = [String]()
for gpa in grades {
if gpa >= 4.0 {
letterGrades.append("A+")
} else if gpa >= 3.7 {
letterGrades.append("A")
} else if gpa >= 3.3 {
letterGrades.append("A-")
} else if gpa >= 3.0 {
letterGrades.append("B+")
} else if gpa >= 2.7 {
letterGrades.append("B")
} else if gpa >= 2.3 {
letterGrades.append("B-")
} else if gpa >= 2.0 {
letterGrades.append("C+")
} else if gpa >= 1.7 {
letterGrades.append("C")
} else if gpa >= 1.3 {
letterGrades.append("C-")
} else if gpa >= 1.0 {
letterGrades.append("D+")
} else if gpa >= 0.7 {
letterGrades.append("D")
} else {
letterGrades.append("D-")
}
}
return letterGrades
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
Answer:
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades = [String]()
for gpa in grades {
if gpa >= 4.0 {
letterGrades.append("A+")
} else if gpa >= 3.7 {
letterGrades.append("A")
} else if gpa >= 3.3 {
letterGrades.append("A-")
} else if gpa >= 3.0 {
letterGrades.append("B+")
} else if gpa >= 2.7 {
letterGrades.append("B")
} else if gpa >= 2.3 {
letterGrades.append("B-")
} else if gpa >= 2.0 {
letterGrades.append("C+")
} else if gpa >= 1.7 {
letterGrades.append("C")
} else if gpa >= 1.3 {
letterGrades.append("C-")
} else if gpa >= 1.0 {
letterGrades.append("D+")
} else if gpa >= 0.7 {
letterGrades.append("D")
} else {
letterGrades.append("D-")
}
}
return letterGrades
}
``` // XCTAssertTrue failedfunc numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades = [String]()
for gpa in grades {
if gpa >= 4.0 {
letterGrades.append("A+")
} else if gpa >= 3.7 {
letterGrades.append("A")
} else if gpa >= 3.3 {
letterGrades.append("A-")
} else if gpa >= 3.0 {
letterGrades.append("B+")
} else if gpa >= 2.7 {
letterGrades.append("B")
} else if gpa >= 2.3 {
letterGrades.append("B-")
} else if gpa >= 2.0 {
letterGrades.append("C+")
} else if gpa >= 1.7 {
letterGrades.append("C")
} else if gpa >= 1.3 {
letterGrades.append("C-")
} else if gpa >= 1.0 {
letterGrades.append("D+")
} else if gpa >= 0.7 {
letterGrades.append("D")
} else if gpa >= 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
Answer:
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades = [String]()
for gpa in grades {
if gpa >= 4.0 {
letterGrades.append("A+")
} else if gpa >= 3.7 {
letterGrades.append("A")
} else if gpa >= 3.3 {
letterGrades.append("A-")
} else if gpa >= 3.0 {
letterGrades.append("B+")
} else if gpa >= 2.7 {
letterGrades.append("B")
} else if gpa >= 2.3 {
letterGrades.append("B-")
} else if gpa >= 2.0 {
letterGrades.append("C+")
} else if gpa >= 1.7 {
letterGrades.append("C")
} else if gpa >= 1.3 {
letterGrades.append("C-")
} else if gpa >= 1.0 {
letterGrades.append("D+")
} else if gpa >= 0.7 {
letterGrades.append("D")
} else if gpa >= 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}
``` // XCTAssertTrue failedfunc numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades = [String]()
for gpa in grades {
if gpa >= 4.0 {
letterGrades.append("A+")
} else if gpa >= 3.7 {
letterGrades.append("A")
} else if gpa >= 3.3 {
letterGrades.append("A-")
} else if gpa >= 3.0 {
letterGrades.append("B+")
} else if gpa >= 2.7 {
letterGrades.append("B")
} else if gpa >= 2.3 {
letterGrades.append("B-")
} else if gpa >= 2.0 {
letterGrades.append("C+")
} else if gpa >= 1.7 {
letterGrades.append("C")
} else if gpa >= 1.3 {
letterGrades.append("C-")
} else if gpa >= 1.0 {
letterGrades.append("D+")
} else if gpa >= 0.7 {
letterGrades.append("D")
} else if gpa >= 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
Answer:
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades = [String]()
for gpa in grades {
if gpa >= 4.0 {
letterGrades.append("A+")
} else if gpa >= 3.7 {
letterGrades.append("A")
} else if gpa >= 3.3 {
letterGrades.append("A-")
} else if gpa >= 3.0 {
letterGrades.append("B+")
} else if gpa >= 2.7 {
letterGrades.append("B")
} else if gpa >= 2.3 {
letterGrades.append("B-")
} else if gpa >= 2.0 {
letterGrades.append("C+")
} else if gpa >= 1.7 {
letterGrades.append("C")
} else if gpa >= 1.3 {
letterGrades.append("C-")
} else if gpa >= 1.0 {
letterGrades.append("D+")
} else if gpa >= 0.7 {
letterGrades.append("D")
} else if gpa >= 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}
``` // XCTAssertTrue failedfunc numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades = [String]()
for gpa in grades {
if gpa >= 4.0 {
letterGrades.append("A+")
} else if gpa >= 3.7 {
letterGrades.append("A")
} else if gpa >= 3.3 {
letterGrades.append("A-")
} else if gpa >= 3.0 {
letterGrades.append("B+")
} else if gpa >= 2.7 {
letterGrades.append("B")
} else if gpa >= 2.3 {
letterGrades.append("B-")
} else if gpa >= 2.0 {
letterGrades.append("C+")
} else if gpa >= 1.7 {
letterGrades.append("C")
} else if gpa >= 1.3 {
letterGrades.append("C-")
} else if gpa >= 1.0 {
letterGrades.append("D+")
} else if gpa >= 0.7 {
letterGrades.append("D")
} else {
letterGrades.append("D-")
}
}
return letterGrades
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
Answer:
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades = [String]()
for gpa in grades {
if gpa >= 4.0 {
letterGrades.append("A+")
} else if gpa >= 3.7 {
letterGrades.append("A")
} else if gpa >= 3.3 {
letterGrades.append("A-")
} else if gpa >= 3.0 {
letterGrades.append("B+")
} else if gpa >= 2.7 {
letterGrades.append("B")
} else if gpa >= 2.3 {
letterGrades.append("B-")
} else if gpa >= 2.0 {
letterGrades.append("C+")
} else if gpa >= 1.7 {
letterGrades.append("C")
} else if gpa >= 1.3 {
letterGrades.append("C-")
} else if gpa >= 1.0 {
letterGrades.append("D+")
} else if gpa >= 0.7 {
letterGrades.append("D")
} else {
letterGrades.append("D-")
}
}
return letterGrades
}
``` // XCTAssertTrue failedfunc numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades = [String]()
for gpa in grades {
if gpa >= 4.0 {
letterGrades.append("A+")
} else if gpa >= 3.7 {
letterGrades.append("A")
} else if gpa >= 3.3 {
letterGrades.append("A-")
} else if gpa >= 3.0 {
letterGrades.append("B+")
} else if gpa >= 2.7 {
letterGrades.append("B")
} else if gpa >= 2.3 {
letterGrades.append("B-")
} else if gpa >= 2.0 {
letterGrades.append("C+")
} else if gpa >= 1.7 {
letterGrades.append("C")
} else if gpa >= 1.3 {
letterGrades.append("C-")
} else if gpa >= 1.0 {
letterGrades.append("D+")
} else if gpa >= 0.7 {
letterGrades.append("D")
} else {
letterGrades.append("D-")
}
}
return letterGrades
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
Answer:
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades = [String]()
for gpa in grades {
if gpa >= 4.0 {
letterGrades.append("A+")
} else if gpa >= 3.7 {
letterGrades.append("A")
} else if gpa >= 3.3 {
letterGrades.append("A-")
} else if gpa >= 3.0 {
letterGrades.append("B+")
} else if gpa >= 2.7 {
letterGrades.append("B")
} else if gpa >= 2.3 {
letterGrades.append("B-")
} else if gpa >= 2.0 {
letterGrades.append("C+")
} else if gpa >= 1.7 {
letterGrades.append("C")
} else if gpa >= 1.3 {
letterGrades.append("C-")
} else if gpa >= 1.0 {
letterGrades.append("D+")
} else if gpa >= 0.7 {
letterGrades.append("D")
} else {
letterGrades.append("D-")
}
}
return letterGrades
}
``` // XCTAssertTrue failedfunc numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades = [String]()
for gpa in grades {
if gpa >= 4.0 {
letterGrades.append("A+")
} else if gpa >= 3.7 {
letterGrades.append("A")
} else if gpa >= 3.3 {
letterGrades.append("A-")
} else if gpa >= 3.0 {
letterGrades.append("B+")
} else if gpa >= 2.7 {
letterGrades.append("B")
} else if gpa >= 2.3 {
letterGrades.append("B-")
} else if gpa >= 2.0 {
letterGrades.append("C+")
} else if gpa >= 1.7 {
letterGrades.append("C")
} else if gpa >= 1.3 {
letterGrades.append("C-")
} else if gpa >= 1.0 {
letterGrades.append("D+")
} else if gpa >= 0.7 {
letterGrades.append("D")
} else {
letterGrades.append("D-")
}
}
return letterGrades
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
Answer:
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades = [String]()
for gpa in grades {
if gpa >= 4.0 {
letterGrades.append("A+")
} else if gpa >= 3.7 {
letterGrades.append("A")
} else if gpa >= 3.3 {
letterGrades.append("A-")
} else if gpa >= 3.0 {
letterGrades.append("B+")
} else if gpa >= 2.7 {
letterGrades.append("B")
} else if gpa >= 2.3 {
letterGrades.append("B-")
} else if gpa >= 2.0 {
letterGrades.append("C+")
} else if gpa >= 1.7 {
letterGrades.append("C")
} else if gpa >= 1.3 {
letterGrades.append("C-")
} else if gpa >= 1.0 {
letterGrades.append("D+")
} else if gpa >= 0.7 {
letterGrades.append("D")
} else {
letterGrades.append("D-")
}
}
return letterGrades
}
``` // XCTAssertTrue failedfunc numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades = [String]()
for gpa in grades {
if gpa >= 4.0 {
letterGrades.append("A+")
} else if gpa >= 3.7 {
letterGrades.append("A")
} else if gpa >= 3.3 {
letterGrades.append("A-")
} else if gpa >= 3.0 {
letterGrades.append("B+")
} else if gpa >= 2.7 {
letterGrades.append("B")
} else if gpa >= 2.3 {
letterGrades.append("B-")
} else if gpa >= 2.0 {
letterGrades.append("C+")
} else if gpa >= 1.7 {
letterGrades.append("C")
} else if gpa >= 1.3 {
letterGrades.append("C-")
} else if gpa >= 1.0 {
letterGrades.append("D+")
} else if gpa >= 0.7 {
letterGrades.append("D")
} else {
letterGrades.append("D-")
}
}
return letterGrades
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
Answer:
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades = [String]()
for gpa in grades {
if gpa >= 4.0 {
letterGrades.append("A+")
} else if gpa >= 3.7 {
letterGrades.append("A")
} else if gpa >= 3.3 {
letterGrades.append("A-")
} else if gpa >= 3.0 {
letterGrades.append("B+")
} else if gpa >= 2.7 {
letterGrades.append("B")
} else if gpa >= 2.3 {
letterGrades.append("B-")
} else if gpa >= 2.0 {
letterGrades.append("C+")
} else if gpa >= 1.7 {
letterGrades.append("C")
} else if gpa >= 1.3 {
letterGrades.append("C-")
} else if gpa >= 1.0 {
letterGrades.append("D+")
} else if gpa >= 0.7 {
letterGrades.append("D")
} else {
letterGrades.append("D-")
}
}
return letterGrades
}
``` // XCTAssertTrue failedfunc numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades = [String]()
for gpa in grades {
if gpa >= 4.0 {
letterGrades.append("A+")
} else if gpa >= 3.7 {
letterGrades.append("A")
} else if gpa >= 3.3 {
letterGrades.append("A-")
} else if gpa >= 3.0 {
letterGrades.append("B+")
} else if gpa >= 2.7 {
letterGrades.append("B")
} else if gpa >= 2.3 {
letterGrades.append("B-")
} else if gpa >= 2.0 {
letterGrades.append("C+")
} else if gpa >= 1.7 {
letterGrades.append("C")
} else if gpa >= 1.3 {
letterGrades.append("C-")
} else if gpa >= 1.0 {
letterGrades.append("D+")
} else if gpa >= 0.7 {
letterGrades.append("D")
} else {
letterGrades.append("D-")
}
}
return letterGrades
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
Answer:
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades = [String]()
for gpa in grades {
if gpa >= 4.0 {
letterGrades.append("A+")
} else if gpa >= 3.7 {
letterGrades.append("A")
} else if gpa >= 3.3 {
letterGrades.append("A-")
} else if gpa >= 3.0 {
letterGrades.append("B+")
} else if gpa >= 2.7 {
letterGrades.append("B")
} else if gpa >= 2.3 {
letterGrades.append("B-")
} else if gpa >= 2.0 {
letterGrades.append("C+")
} else if gpa >= 1.7 {
letterGrades.append("C")
} else if gpa >= 1.3 {
letterGrades.append("C-")
} else if gpa >= 1.0 {
letterGrades.append("D+")
} else if gpa >= 0.7 {
letterGrades.append("D")
} else {
letterGrades.append("D-")
}
}
return letterGrades
}
``` // XCTAssertTrue failedfunc numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades = [String]()
for gpa in grades {
if gpa >= 4.0 {
letterGrades.append("A+")
} else if gpa >= 3.7 {
letterGrades.append("A")
} else if gpa >= 3.3 {
letterGrades.append("A-")
} else if gpa >= 3.0 {
letterGrades.append("B+")
} else if gpa >= 2.7 {
letterGrades.append("B")
} else if gpa >= 2.3 {
letterGrades.append("B-")
} else if gpa >= 2.0 {
letterGrades.append("C+")
} else if gpa >= 1.7 {
letterGrades.append("C")
} else if gpa >= 1.3 {
letterGrades.append("C-")
} else if gpa >= 1.0 {
letterGrades.append("D+")
} else if gpa >= 0.7 {
letterGrades.append("D")
} else {
letterGrades.append("D-")
}
}
return letterGrades
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
Answer:
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades = [String]()
for gpa in grades {
if gpa >= 4.0 {
letterGrades.append("A+")
} else if gpa >= 3.7 {
letterGrades.append("A")
} else if gpa >= 3.3 {
letterGrades.append("A-")
} else if gpa >= 3.0 {
letterGrades.append("B+")
} else if gpa >= 2.7 {
letterGrades.append("B")
} else if gpa >= 2.3 {
letterGrades.append("B-")
} else if gpa >= 2.0 {
letterGrades.append("C+")
} else if gpa >= 1.7 {
letterGrades.append("C")
} else if gpa >= 1.3 {
letterGrades.append("C-")
} else if gpa >= 1.0 {
letterGrades.append("D+")
} else if gpa >= 0.7 {
letterGrades.append("D")
} else {
letterGrades.append("D-")
}
}
return letterGrades
}
``` // XCTAssertTrue failedfunc numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades = [String]()
for gpa in grades {
if gpa >= 4.0 {
letterGrades.append("A+")
} else if gpa >= 3.7 {
letterGrades.append("A")
} else if gpa >= 3.3 {
letterGrades.append("A-")
} else if gpa >= 3.0 {
letterGrades.append("B+")
} else if gpa >= 2.7 {
letterGrades.append("B")
} else if gpa >= 2.3 {
letterGrades.append("B-")
} else if gpa >= 2.0 {
letterGrades.append("C+")
} else if gpa >= 1.7 {
letterGrades.append("C")
} else if gpa >= 1.3 {
letterGrades.append("C-")
} else if gpa >= 1.0 {
letterGrades.append("D+")
} else if gpa >= 0.7 {
letterGrades.append("D")
} else {
letterGrades.append("D-")
}
}
return letterGrades
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
Answer:
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades = [String]()
for gpa in grades {
if gpa >= 4.0 {
letterGrades.append("A+")
} else if gpa >= 3.7 {
letterGrades.append("A")
} else if gpa >= 3.3 {
letterGrades.append("A-")
} else if gpa >= 3.0 {
letterGrades.append("B+")
} else if gpa >= 2.7 {
letterGrades.append("B")
} else if gpa >= 2.3 {
letterGrades.append("B-")
} else if gpa >= 2.0 {
letterGrades.append("C+")
} else if gpa >= 1.7 {
letterGrades.append("C")
} else if gpa >= 1.3 {
letterGrades.append("C-")
} else if gpa >= 1.0 {
letterGrades.append("D+")
} else if gpa >= 0.7 {
letterGrades.append("D")
} else {
letterGrades.append("D-")
}
}
return letterGrades
}
``` // XCTAssertTrue failedfunc primeLength(string: String) -> Bool {
let length = string.count
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
Answer:
```swift
func primeLength(string: String) -> Bool {
let length = string.count
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc primeLength(string: String) -> Bool {
let length = string.count
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
Answer:
```swift
func primeLength(string: String) -> Bool {
let length = string.count
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc primeLength(string: String) -> Bool {
let length = string.count
if length <= 1 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
Answer:
```swift
func primeLength(string: String) -> Bool {
let length = string.count
if length <= 1 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}
```func primeLength(string: String) -> Bool {
let length = string.count
if length <= 1 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
Answer:
```swift
func primeLength(string: String) -> Bool {
let length = string.count
if length <= 1 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}
```func primeLength(string: String) -> Bool {
let length = string.count
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
Answer:
```swift
func primeLength(string: String) -> Bool {
let length = string.count
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc primeLength(string: String) -> Bool {
let length = string.count
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
Answer:
```swift
func primeLength(string: String) -> Bool {
let length = string.count
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc primeLength(string: String) -> Bool {
let length = string.count
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
Answer:
```swift
func primeLength(string: String) -> Bool {
let length = string.count
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc primeLength(string: String) -> Bool {
let length = string.count
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
Answer:
```swift
func primeLength(string: String) -> Bool {
let length = string.count
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc primeLength(string: String) -> Bool {
let length = string.count
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
Answer:
```swift
func primeLength(string: String) -> Bool {
let length = string.count
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc primeLength(string: String) -> Bool {
let length = string.count
if length < 2 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
Answer:
```swift
func primeLength(string: String) -> Bool {
let length = string.count
if length < 2 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}
```func startsOneEnds(n: Int) -> Int {
let limit = pow(10, Double(n))
var count = 0
for i in 1...limit {
if String(i).hasPrefix("1") || String(i).hasSuffix("1") {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
Answer:
```swift
func startsOneEnds(n: Int) -> Int {
let limit = pow(10, Double(n))
var count = 0
for i in 1...limit {
if String(i).hasPrefix("1") || String(i).hasSuffix("1") {
count += 1
}
}
return count
}
```for i in 1...limit { // referencing instance method 'makeIterator()' on 'ClosedRange' requires that 'Double.Stride' (aka 'Double') conform to 'SignedInteger'for i in 1...limit { // protocol 'Sequence' requires that 'Double.Stride' (aka 'Double') conform to 'SignedInteger'for i in 1...limit { // referencing instance method 'next()' on 'ClosedRange' requires that 'Double.Stride' (aka 'Double') conform to 'SignedInteger'func startsOneEnds(n: Int) -> Int {
guard n > 0 else {
return 0
}
return (10 - 1) * pow(10, Double(n - 1))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
Answer:
```swift
func startsOneEnds(n: Int) -> Int {
guard n > 0 else {
return 0
}
return (10 - 1) * pow(10, Double(n - 1))
}
```return (10 - 1) * pow(10, Double(n - 1)) // cannot convert return expression of type 'Double' to return type 'Int'func startsOneEnds(n: Int) -> Int {
return Int(pow(10, Double(n - 1))) - Int(pow(10, Double(n - 2)))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
Answer:
```swift
func startsOneEnds(n: Int) -> Int {
return Int(pow(10, Double(n - 1))) - Int(pow(10, Double(n - 2)))
}
``` // XCTAssertTrue failedfunc startsOneEnds(n: Int) -> Int {
return Int(pow(10, Double(n)) - pow(10, Double(n - 1)))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
Answer:
```swift
func startsOneEnds(n: Int) -> Int {
return Int(pow(10, Double(n)) - pow(10, Double(n - 1)))
}
``` // XCTAssertTrue failedfunc startsOneEnds(n: Int) -> Int {
return Int(pow(10, Double(n)) - pow(10, Double(n - 1)))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
Answer:
```swift
func startsOneEnds(n: Int) -> Int {
return Int(pow(10, Double(n)) - pow(10, Double(n - 1)))
}
``` // XCTAssertTrue failedfunc startsOneEnds(n: Int) -> Int {
return Int(pow(10, Double(n)) - pow(1, Double(n)))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
Answer:
```swift
func startsOneEnds(n: Int) -> Int {
return Int(pow(10, Double(n)) - pow(1, Double(n)))
}
``` // XCTAssertTrue failedfunc startsOneEnds(n: Int) -> Int {
let count = pow(10, Double(n)) as Int
var result = 0
for i in 1...count {
let s = String(i)
if s.hasPrefix("1") || s.hasSuffix("1") {
result += 1
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
Answer:
```swift
func startsOneEnds(n: Int) -> Int {
let count = pow(10, Double(n)) as Int
var result = 0
for i in 1...count {
let s = String(i)
if s.hasPrefix("1") || s.hasSuffix("1") {
result += 1
}
}
return result
}
```let count = pow(10, Double(n)) as Int // cannot convert value of type 'Double' to type 'Int' in coercionfunc startsOneEnds(n: Int) -> Int {
return Int(pow(10, Double(n)) - pow(1, Double(n)))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
Answer:
```swift
func startsOneEnds(n: Int) -> Int {
return Int(pow(10, Double(n)) - pow(1, Double(n)))
}
``` // XCTAssertTrue failedfunc startsOneEnds(n: Int) -> Int {
var count = 0
let start = Int(pow(10, Double(n - 1)))
let end = Int(pow(10, Double(n)))
for i in start...end {
if i % 10 == 1 || i / 10 % 10 == 1 {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
Answer:
```swift
func startsOneEnds(n: Int) -> Int {
var count = 0
let start = Int(pow(10, Double(n - 1)))
let end = Int(pow(10, Double(n)))
for i in start...end {
if i % 10 == 1 || i / 10 % 10 == 1 {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc startsOneEnds(n: Int) -> Int {
let start = 10^(n - 1)
let end = 10^n - 1
return (end - start) / 10 + 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
Answer:
```swift
func startsOneEnds(n: Int) -> Int {
let start = 10^(n - 1)
let end = 10^n - 1
return (end - start) / 10 + 1
}
``` // XCTAssertTrue failed@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
var result = ""
var n = N
while n > 0 {
result = "\(n % 2)" + result
n /= 2
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
var result = ""
var n = N
while n > 0 {
result = "\(n % 2)" + result
n /= 2
}
return result
}
```@N integer // unknown attribute 'N'@N integer // cannot find type 'integer' in scopeConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scopeConstraints: 0 ≤ N ≤ 10000. // expected expression@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
var result = ""
var number = N
while number > 0 {
result = "\(number % 2)" + result
number /= 2
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
var result = ""
var number = N
while number > 0 {
result = "\(number % 2)" + result
number /= 2
}
return result
}
```@N integer // unknown attribute 'N'@N integer // cannot find type 'integer' in scopeConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scopeConstraints: 0 ≤ N ≤ 10000. // expected expression@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
var result = ""
var n = N
while n > 0 {
result = "\(n % 2)" + result
n /= 2
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
var result = ""
var n = N
while n > 0 {
result = "\(n % 2)" + result
n /= 2
}
return result
}
```@N integer // unknown attribute 'N'@N integer // cannot find type 'integer' in scopeConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scopeConstraints: 0 ≤ N ≤ 10000. // expected expression@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
var result = ""
var number = N
while number > 0 {
result = "\(number % 2)" + result
number /= 2
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
var result = ""
var number = N
while number > 0 {
result = "\(number % 2)" + result
number /= 2
}
return result
}
```@N integer // unknown attribute 'N'@N integer // cannot find type 'integer' in scopeConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scopeConstraints: 0 ≤ N ≤ 10000. // expected expression@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
var result = ""
var n = N
while n > 0 {
result = "\(n % 2)" + result
n /= 2
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
var result = ""
var n = N
while n > 0 {
result = "\(n % 2)" + result
n /= 2
}
return result
}
```@N integer // unknown attribute 'N'@N integer // cannot find type 'integer' in scopeConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scopeConstraints: 0 ≤ N ≤ 10000. // expected expression@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
var binary = ""
while N > 0 {
binary = String(N % 2) + binary
N /= 2
}
return binary
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
var binary = ""
while N > 0 {
binary = String(N % 2) + binary
N /= 2
}
return binary
}
```@N integer // unknown attribute 'N'@N integer // cannot find type 'integer' in scopeConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scopeConstraints: 0 ≤ N ≤ 10000. // expected expressionN /= 2 // left side of mutating operator isn't mutable: 'N' is a 'let' constant@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
var result = ""
var number = N
while number > 0 {
let remainder = number % 2
result = "\(remainder)" + result
number = number / 2
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
var result = ""
var number = N
while number > 0 {
let remainder = number % 2
result = "\(remainder)" + result
number = number / 2
}
return result
}
```@N integer // unknown attribute 'N'@N integer // cannot find type 'integer' in scopeConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scopeConstraints: 0 ≤ N ≤ 10000. // expected expression@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
var result = ""
var number = N
while number > 0 {
result = "\(number % 2)" + result
number /= 2
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
var result = ""
var number = N
while number > 0 {
result = "\(number % 2)" + result
number /= 2
}
return result
}
```@N integer // unknown attribute 'N'@N integer // cannot find type 'integer' in scopeConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scopeConstraints: 0 ≤ N ≤ 10000. // expected expression@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
var result = ""
var number = N
while number > 0 {
result = "\(number % 2)" + result
number /= 2
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
var result = ""
var number = N
while number > 0 {
result = "\(number % 2)" + result
number /= 2
}
return result
}
```@N integer // unknown attribute 'N'@N integer // cannot find type 'integer' in scopeConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scopeConstraints: 0 ≤ N ≤ 10000. // expected expression@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
var binary = ""
while N > 0 {
binary = String(N % 2) + binary
N /= 2
}
return binary
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
var binary = ""
while N > 0 {
binary = String(N % 2) + binary
N /= 2
}
return binary
}
```@N integer // unknown attribute 'N'@N integer // cannot find type 'integer' in scopeConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scopeConstraints: 0 ≤ N ≤ 10000. // expected expressionN /= 2 // left side of mutating operator isn't mutable: 'N' is a 'let' constantfunc add(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2 == 0 {
sum += element
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
Answer:
```swift
func add(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2 == 0 {
sum += element
}
}
return sum
}
```func add(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2 == 0 {
sum += element
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
Answer:
```swift
func add(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2 == 0 {
sum += element
}
}
return sum
}
```func add(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2 == 0 {
sum += element
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
Answer:
```swift
func add(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2 == 0 {
sum += element
}
}
return sum
}
```func add(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2 == 0 {
sum += element
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
Answer:
```swift
func add(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2 == 0 {
sum += element
}
}
return sum
}
```func add(lst: [Int]) -> Int {
var result = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2 == 0 {
result += element
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
Answer:
```swift
func add(lst: [Int]) -> Int {
var result = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2 == 0 {
result += element
}
}
return result
}
```func add(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2 == 0 {
sum += element
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
Answer:
```swift
func add(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2 == 0 {
sum += element
}
}
return sum
}
```func add(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2 == 0 {
sum += element
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
Answer:
```swift
func add(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2 == 0 {
sum += element
}
}
return sum
}
```func add(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2 == 0 {
sum += element
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
Answer:
```swift
func add(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2 == 0 {
sum += element
}
}
return sum
}
```func add(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2 == 0 {
sum += element
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
Answer:
```swift
func add(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2 == 0 {
sum += element
}
}
return sum
}
```func add(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2 == 0 {
sum += element
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
Answer:
```swift
func add(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2 == 0 {
sum += element
}
}
return sum
}
```func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
let sortedWords = words.sorted { $0.asciiValue! < $1.asciiValue! }
return sortedWords.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello!!!Wdlor"
Answer:
```swift
func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
let sortedWords = words.sorted { $0.asciiValue! < $1.asciiValue! }
return sortedWords.joined(separator: " ")
}
```let sortedWords = words.sorted { $0.asciiValue! < $1.asciiValue! } // value of type 'String' has no member 'asciiValue'let sortedWords = words.sorted { $0.asciiValue! < $1.asciiValue! } // value of type 'String' has no member 'asciiValue'func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
let sortedWords = words.sorted { $0.asciiValue! < $1.asciiValue! }
return sortedWords.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello!!!Wdlor"
Answer:
```swift
func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
let sortedWords = words.sorted { $0.asciiValue! < $1.asciiValue! }
return sortedWords.joined(separator: " ")
}
```let sortedWords = words.sorted { $0.asciiValue! < $1.asciiValue! } // value of type 'String' has no member 'asciiValue'let sortedWords = words.sorted { $0.asciiValue! < $1.asciiValue! } // value of type 'String' has no member 'asciiValue'func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
let sortedWords = words.sorted { $0 < $1 }
return sortedWords.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello!!!Wdlor"
Answer:
```swift
func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
let sortedWords = words.sorted { $0 < $1 }
return sortedWords.joined(separator: " ")
}
``` // XCTAssertTrue failedfunc antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
let sortedWords = words.sorted { $0 < $1 }
return sortedWords.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello!!!Wdlor"
Answer:
```swift
func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
let sortedWords = words.sorted { $0 < $1 }
return sortedWords.joined(separator: " ")
}
``` // XCTAssertTrue failedfunc antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
let sortedWords = words.sorted { $0 < $1 }
return sortedWords.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello!!!Wdlor"
Answer:
```swift
func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
let sortedWords = words.sorted { $0 < $1 }
return sortedWords.joined(separator: " ")
}
``` // XCTAssertTrue failedfunc antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
let sortedWords = words.sorted { $0 < $1 }
return sortedWords.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello!!!Wdlor"
Answer:
```swift
func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
let sortedWords = words.sorted { $0 < $1 }
return sortedWords.joined(separator: " ")
}
``` // XCTAssertTrue failedfunc antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
let sortedWords = words.map { String($0.sorted()) }
return sortedWords.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello!!!Wdlor"
Answer:
```swift
func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
let sortedWords = words.map { String($0.sorted()) }
return sortedWords.joined(separator: " ")
}
```func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
let sortedWords = words.map { String($0.sorted()) }
return sortedWords.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello!!!Wdlor"
Answer:
```swift
func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
let sortedWords = words.map { String($0.sorted()) }
return sortedWords.joined(separator: " ")
}
```func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
let sortedWords = words.sorted { $0 < $1 }
return sortedWords.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello!!!Wdlor"
Answer:
```swift
func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
let sortedWords = words.sorted { $0 < $1 }
return sortedWords.joined(separator: " ")
}
``` // XCTAssertTrue failedfunc antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
let sortedWords = words.map { String($0.sorted()) }
return sortedWords.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello!!!Wdlor"
Answer:
```swift
func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
let sortedWords = words.map { String($0.sorted()) }
return sortedWords.joined(separator: " ")
}
```func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
let rows = lst.enumerated()
let sortedRows = rows.sorted { $0.element.count > $1.element.count }
let sortedColumns = sortedRows.flatMap { (row, elements) in
let sortedElements = elements.sorted { $0 > $1 }
return sortedElements.enumerated().map { (index, element) in
(row.offsetBy(1), index)
}
}
return sortedColumns.filter { $0.element == x }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2)...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
Answer:
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
let rows = lst.enumerated()
let sortedRows = rows.sorted { $0.element.count > $1.element.count }
let sortedColumns = sortedRows.flatMap { (row, elements) in
let sortedElements = elements.sorted { $0 > $1 }
return sortedElements.enumerated().map { (index, element) in
(row.offsetBy(1), index)
}
}
return sortedColumns.filter { $0.element == x }
}
```(row.offsetBy(1), index) // value of type 'Int' has no member 'offsetBy'func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
let rows = lst.enumerated()
let sortedRows = rows.sorted { $0.element.count > $1.element.count }
let sortedColumns = sortedRows.map { ($0.element, $0.offset) }
let sortedColumnsByCount = sortedColumns.sorted { $0.0.count > $1.0.count }
return sortedColumnsByCount.filter { $0.0.contains(x) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2)...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
Answer:
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
let rows = lst.enumerated()
let sortedRows = rows.sorted { $0.element.count > $1.element.count }
let sortedColumns = sortedRows.map { ($0.element, $0.offset) }
let sortedColumnsByCount = sortedColumns.sorted { $0.0.count > $1.0.count }
return sortedColumnsByCount.filter { $0.0.contains(x) }
}
```return sortedColumnsByCount.filter { $0.0.contains(x) } // cannot convert return expression of type '[([Int], Int)]' to return type '[(Int, Int)]'func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result = [(Int, Int)]()
for (index, row) in lst.enumerated() {
let column = row.firstIndex(of: x)
if let column = column {
result.append((index, column))
}
}
return result.sorted { $0.0 < $1.0 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2)...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
Answer:
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result = [(Int, Int)]()
for (index, row) in lst.enumerated() {
let column = row.firstIndex(of: x)
if let column = column {
result.append((index, column))
}
}
return result.sorted { $0.0 < $1.0 }
}
``` // XCTAssertTrue failedfunc getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (index, row) in lst.enumerated() {
let column = row.firstIndex(of: x)
if let column = column {
result.append((index, column))
}
}
return result.sorted { $0.0 < $1.0 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2)...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
Answer:
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (index, row) in lst.enumerated() {
let column = row.firstIndex(of: x)
if let column = column {
result.append((index, column))
}
}
return result.sorted { $0.0 < $1.0 }
}
``` // XCTAssertTrue failedfunc getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
let rows = lst.filter { $0.contains(x) }
let sortedRows = rows.sorted { $0.count > $1.count }
let sortedColumns = sortedRows.map { $0.indices.filter { $0 == x }.first! }
let sortedCoordinates = sortedColumns.enumerated().map { ($0, $1) }
return sortedCoordinates
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2)...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
Answer:
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
let rows = lst.filter { $0.contains(x) }
let sortedRows = rows.sorted { $0.count > $1.count }
let sortedColumns = sortedRows.map { $0.indices.filter { $0 == x }.first! }
let sortedCoordinates = sortedColumns.enumerated().map { ($0, $1) }
return sortedCoordinates
}
``` // XCTAssertTrue failedfunc getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (i, row) in lst.enumerated() {
let index = row.firstIndex(of: x)
if let index = index {
result.append((i, index))
}
}
return result.sorted { $0.0 < $1.0 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2)...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
Answer:
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (i, row) in lst.enumerated() {
let index = row.firstIndex(of: x)
if let index = index {
result.append((i, index))
}
}
return result.sorted { $0.0 < $1.0 }
}
``` // XCTAssertTrue failedfunc getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result = [(Int, Int)]()
for (index, row) in lst.enumerated() {
let column = row.firstIndex(of: x)
if let column = column {
result.append((index, column))
}
}
return result.sorted { $0.0 < $1.0 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2)...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
Answer:
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result = [(Int, Int)]()
for (index, row) in lst.enumerated() {
let column = row.firstIndex(of: x)
if let column = column {
result.append((index, column))
}
}
return result.sorted { $0.0 < $1.0 }
}
``` // XCTAssertTrue failedfunc getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (index, row) in lst.enumerated() {
let column = row.firstIndex(of: x)
if let column = column {
result.append((index, column))
}
}
return result.sorted { $0.0 < $1.0 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2)...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
Answer:
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (index, row) in lst.enumerated() {
let column = row.firstIndex(of: x)
if let column = column {
result.append((index, column))
}
}
return result.sorted { $0.0 < $1.0 }
}
``` // XCTAssertTrue failedfunc getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
let rows = lst.filter { $0.contains(x) }
let sortedRows = rows.sorted { $0.count > $1.count }
let sortedColumns = sortedRows.map { $0.indices.filter { $0 == x }.first! }
let sortedCoordinates = sortedColumns.map { ($0, sortedRows.first!.count - 1) }
return sortedCoordinates
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2)...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
Answer:
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
let rows = lst.filter { $0.contains(x) }
let sortedRows = rows.sorted { $0.count > $1.count }
let sortedColumns = sortedRows.map { $0.indices.filter { $0 == x }.first! }
let sortedCoordinates = sortedColumns.map { ($0, sortedRows.first!.count - 1) }
return sortedCoordinates
}
``` // XCTAssertTrue failedfunc getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
let rows = lst.indices.sorted { lst[$0].first! < lst[$1].first! }
var result: [(Int, Int)] = []
for row in rows {
let columns = (0..<lst[row].count).sorted { lst[row][$0] > lst[row][$1] }
for column in columns {
result.append((row, column))
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2)...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
Answer:
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
let rows = lst.indices.sorted { lst[$0].first! < lst[$1].first! }
var result: [(Int, Int)] = []
for row in rows {
let columns = (0..<lst[row].count).sorted { lst[row][$0] > lst[row][$1] }
for column in columns {
result.append((row, column))
}
}
return result
}
``` // XCTAssertTrue failedfunc sortArray(array: [Int]) -> [Int] {
let sum = array.reduce(0, +)
let isOdd = sum % 2 == 1
return isOdd? array.sorted() : array.sorted(by: >)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
Answer:
```swift
func sortArray(array: [Int]) -> [Int] {
let sum = array.reduce(0, +)
let isOdd = sum % 2 == 1
return isOdd? array.sorted() : array.sorted(by: >)
}
```return isOdd? array.sorted() : array.sorted(by: >) // consecutive statements on a line must be separated by ';'return isOdd? array.sorted() : array.sorted(by: >) // cannot use optional chaining on non-optional value of type 'Bool'return isOdd? array.sorted() : array.sorted(by: >) // consecutive statements on a line must be separated by ';'return isOdd? array.sorted() : array.sorted(by: >) // expected expressionreturn isOdd? array.sorted() : array.sorted(by: >) // result of call to 'sorted()' is unusedfunc sortArray(array: [Int]) -> [Int] {
let sum = array.reduce(0, +)
let isOdd = sum % 2 == 1
return array.sorted { isOdd? $0 < $1 : $0 > $1 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
Answer:
```swift
func sortArray(array: [Int]) -> [Int] {
let sum = array.reduce(0, +)
let isOdd = sum % 2 == 1
return array.sorted { isOdd? $0 < $1 : $0 > $1 }
}
```return array.sorted { isOdd? $0 < $1 : $0 > $1 } // consecutive statements on a line must be separated by ';'return array.sorted { isOdd? $0 < $1 : $0 > $1 } // cannot use optional chaining on non-optional value of type 'Bool'return array.sorted { isOdd? $0 < $1 : $0 > $1 } // expected expressionreturn array.sorted { isOdd? $0 < $1 : $0 > $1 } // consecutive statements on a line must be separated by ';'func sortArray(array: [Int]) -> [Int] {
let first = array.first!
let last = array.last!
let sum = first + last
let isOdd = sum % 2 == 1
return isOdd? array.sorted() : array.sorted(by: >)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
Answer:
```swift
func sortArray(array: [Int]) -> [Int] {
let first = array.first!
let last = array.last!
let sum = first + last
let isOdd = sum % 2 == 1
return isOdd? array.sorted() : array.sorted(by: >)
}
```return isOdd? array.sorted() : array.sorted(by: >) // expected expressionreturn isOdd? array.sorted() : array.sorted(by: >) // consecutive statements on a line must be separated by ';'return isOdd? array.sorted() : array.sorted(by: >) // cannot use optional chaining on non-optional value of type 'Bool'return isOdd? array.sorted() : array.sorted(by: >) // result of call to 'sorted()' is unusedreturn isOdd? array.sorted() : array.sorted(by: >) // consecutive statements on a line must be separated by ';'func sortArray(array: [Int]) -> [Int] {
let sum = array.reduce(0, +)
let isOdd = sum % 2 == 1
return isOdd? array.sorted() : array.sorted(by: >)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
Answer:
```swift
func sortArray(array: [Int]) -> [Int] {
let sum = array.reduce(0, +)
let isOdd = sum % 2 == 1
return isOdd? array.sorted() : array.sorted(by: >)
}
```return isOdd? array.sorted() : array.sorted(by: >) // consecutive statements on a line must be separated by ';'return isOdd? array.sorted() : array.sorted(by: >) // cannot use optional chaining on non-optional value of type 'Bool'return isOdd? array.sorted() : array.sorted(by: >) // consecutive statements on a line must be separated by ';'return isOdd? array.sorted() : array.sorted(by: >) // expected expressionreturn isOdd? array.sorted() : array.sorted(by: >) // result of call to 'sorted()' is unusedfunc sortArray(array: [Int]) -> [Int] {
let sum = array.reduce(0, +)
let isSumOdd = sum % 2 == 1
return array.sorted { isSumOdd? $0 < $1 : $0 > $1 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
Answer:
```swift
func sortArray(array: [Int]) -> [Int] {
let sum = array.reduce(0, +)
let isSumOdd = sum % 2 == 1
return array.sorted { isSumOdd? $0 < $1 : $0 > $1 }
}
```return array.sorted { isSumOdd? $0 < $1 : $0 > $1 } // consecutive statements on a line must be separated by ';'return array.sorted { isSumOdd? $0 < $1 : $0 > $1 } // expected expressionreturn array.sorted { isSumOdd? $0 < $1 : $0 > $1 } // cannot use optional chaining on non-optional value of type 'Bool'return array.sorted { isSumOdd? $0 < $1 : $0 > $1 } // consecutive statements on a line must be separated by ';'func sortArray(array: [Int]) -> [Int] {
let sum = array.reduce(0, +)
return sum % 2 == 0? array.sorted() : array.sorted(by: >)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
Answer:
```swift
func sortArray(array: [Int]) -> [Int] {
let sum = array.reduce(0, +)
return sum % 2 == 0? array.sorted() : array.sorted(by: >)
}
```return sum % 2 == 0? array.sorted() : array.sorted(by: >) // consecutive statements on a line must be separated by ';'return sum % 2 == 0? array.sorted() : array.sorted(by: >) // cannot use optional chaining on non-optional value of type 'Int'return sum % 2 == 0? array.sorted() : array.sorted(by: >) // consecutive statements on a line must be separated by ';'return sum % 2 == 0? array.sorted() : array.sorted(by: >) // cannot convert return expression of type 'Bool' to return type '[Int]'return sum % 2 == 0? array.sorted() : array.sorted(by: >) // result of call to 'sorted()' is unusedreturn sum % 2 == 0? array.sorted() : array.sorted(by: >) // expected expressionfunc sortArray(array: [Int]) -> [Int] {
let sum = array.reduce(0, +)
return sum % 2 == 0? array.sorted() : array.sorted(by: >)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
Answer:
```swift
func sortArray(array: [Int]) -> [Int] {
let sum = array.reduce(0, +)
return sum % 2 == 0? array.sorted() : array.sorted(by: >)
}
```return sum % 2 == 0? array.sorted() : array.sorted(by: >) // consecutive statements on a line must be separated by ';'return sum % 2 == 0? array.sorted() : array.sorted(by: >) // cannot use optional chaining on non-optional value of type 'Int'return sum % 2 == 0? array.sorted() : array.sorted(by: >) // consecutive statements on a line must be separated by ';'return sum % 2 == 0? array.sorted() : array.sorted(by: >) // cannot convert return expression of type 'Bool' to return type '[Int]'return sum % 2 == 0? array.sorted() : array.sorted(by: >) // result of call to 'sorted()' is unusedreturn sum % 2 == 0? array.sorted() : array.sorted(by: >) // expected expressionfunc sortArray(array: [Int]) -> [Int] {
let sum = array.reduce(0, +)
return sum % 2 == 0? array.sorted() : array.sorted(by: >)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
Answer:
```swift
func sortArray(array: [Int]) -> [Int] {
let sum = array.reduce(0, +)
return sum % 2 == 0? array.sorted() : array.sorted(by: >)
}
```return sum % 2 == 0? array.sorted() : array.sorted(by: >) // consecutive statements on a line must be separated by ';'return sum % 2 == 0? array.sorted() : array.sorted(by: >) // cannot use optional chaining on non-optional value of type 'Int'return sum % 2 == 0? array.sorted() : array.sorted(by: >) // consecutive statements on a line must be separated by ';'return sum % 2 == 0? array.sorted() : array.sorted(by: >) // cannot convert return expression of type 'Bool' to return type '[Int]'return sum % 2 == 0? array.sorted() : array.sorted(by: >) // result of call to 'sorted()' is unusedreturn sum % 2 == 0? array.sorted() : array.sorted(by: >) // expected expressionfunc sortArray(array: [Int]) -> [Int] {
let sum = array.reduce(0, +)
return sum % 2 == 0? array.sorted() : array.sorted(by: >)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
Answer:
```swift
func sortArray(array: [Int]) -> [Int] {
let sum = array.reduce(0, +)
return sum % 2 == 0? array.sorted() : array.sorted(by: >)
}
```return sum % 2 == 0? array.sorted() : array.sorted(by: >) // consecutive statements on a line must be separated by ';'return sum % 2 == 0? array.sorted() : array.sorted(by: >) // cannot use optional chaining on non-optional value of type 'Int'return sum % 2 == 0? array.sorted() : array.sorted(by: >) // consecutive statements on a line must be separated by ';'return sum % 2 == 0? array.sorted() : array.sorted(by: >) // cannot convert return expression of type 'Bool' to return type '[Int]'return sum % 2 == 0? array.sorted() : array.sorted(by: >) // result of call to 'sorted()' is unusedreturn sum % 2 == 0? array.sorted() : array.sorted(by: >) // expected expressionQuestion:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
Answer:
```swift
func sortArray(array: [Int]) -> [Int] {
let sum = array.reduce(0, +)
let isSumOdd = sum % 2 == 1
let isFirstIndexEven = array[0] % 2 == 0
let isLastIndexEven = array.last! % 2 == 0
let isFirstIndexSmallerThanLastIndex = array[0] < array.last!
let isFirstIndexBiggerThanLastIndex = array[0] > array.last!
let isFirstIndexSmallerThanLastIndexAndIsSumOdd = isFirstIndexSmallerThanLastIndex && isSumOdd
let isFirstIndexBiggerThanLastIndexAndIsSumOdd = isFirstIndexBiggerThanLastIndex && isSumOdd
let isFirstIndexSmallerThanLastIndexAndIsSumEven = isFirstIndexSmallerThanLastIndex && isSumOdd
let isFirstIndexBiggerThanLastIndexAndIsSumEven = isFirstIndexBiggerThanLastIndex && isSumOdd
let isFirstIndexSmallerThanLastIndexAndIsSumOddAndIsFirstIndexEven = isFirstIndexSmallerThanLastIndex && isSumOdd && isFirstIndexEven
let isFirstIndexBiggerThanLastIndexAndIsSumOddAndIsFirstIndexEven = isFirstIndexBiggerThanLastIndex && isSumOdd && isFirstIndexEven
let isFirstIndexSmallerThanLastIndexAndIsSumOddAndIsLastIndexEven = isFirstIndexSmallerThanLastIndex && isSumOdd && isLastIndexEven
let isFirstIndexBiggerThanLastIndexAndIsSumOddAndIsLastIndexEven = isFirstIndexBiggerThanLastIndex && isSumOdd && isLastIndexEven
let isFirstIndexSmallerThanLastIndexAndIsSumOddAndIsFirstIndexOdd = isFirstIndexSmallerThanLastIndex && isSumOdd && isFirstIndexOdd
let isFirstIndexBiggerThanLastIndexAndIsSumOddAndIsFirstIndexOdd = isFirstIndexBiggerThanLastIndex && isSumOdd && isFirstIndexOdd
let isFirstIndexSmallerThanLastIndexAndIsSumOddAndIsLastIndexOdd = isFirstIndexSmallerThanLastIndex && isSumOdd && isLastIndexOdd
let isFirstIndexBiggerThanLastIndexAndIsSumOddAndIsLastIndexOdd = isFirstIndexBiggerThanLastIndex && isSumOdd && isLastIndexOdd
let isFirstIndexSmallerThanLastIndexAndIsSumEvenAndIsFirstIndexEven = isFirstIndexSmallerThanLastIndex && isSumOdd && isFirstIndexEven
let isFirstIndexBiggerThanLastIndexAndIsSumEvenAndIsFirstIndexEven = isFirstIndexBiggerThanLastIndex && isSumOdd && isFirstIndexEven
let isFirstIndexSmallerThanLastIndexAndIsSumEvenAndIsLastIndexEven = isFirstIndexSmallerThanLastIndex && isSumOdd && isLastIndexEven
let isFirstIndexBiggerThanLastIndexAndIsSumEvenAndIsLastIndexEven = isFirstIndexBiggerThanLastIndex && isSumOdd && isLastIndexEven
let isFirstIndexSmallerThanLastIndexAndIsSumEvenAndIsFirstIndexOdd = isFirstIndexSmallerThanLastIndex && isSumOdd && isFirstIndexOdd
let isFirstIndexBiggerThanLastIndexAndIsSumEvenAndIsFirstIndexOdd = isFirstIndexBiggerThanLastIndex && isSumOdd && isFirstIndexOdd
let isFirstIndexSmallerThanLastIndexAndIsSumEvenAndIsLastIndexOdd = isFirstIndexSmallerThanLastIndex && isSumOdd && isLastIndexOdd
let isFirstIndexBiggerThanLastIndexAndIsSumEvenAndIsLastIndexOdd = isFirstIndexBiggerThanLastIndex && isSumOdd && isLastIndexOdd
let isFirstIndexSmallerThanLastIndexAndIsSumOddAndIsFirstIndexEven = isFirstIndexSmallerThanLastIndex && isSumOdd && isFirstIndexEven
let isFirstIndexBiggerThanLastIndexAndIsSumOddAndIsFirstIndexEven = isFirstIndexBiggerThanLastIndex && isSumOdd && isFirstIndexEven
let isFirstIndexSmallerThanLastIndexAndIsSumOddAndIsLastIndexEven = isFirstIndexSmallerThanLastIndex && isSumOdd && isLastIndexEven
let isFirstIndexBiggerThanLastIndexAndIsSumOddAndIsLastIndexEven = isFirstIndexBiggerThanLastIndex && isSumOdd && isLastIndexEven
let isFirstIndexSmallerThanLastIndexAndIsSumOddAndIsFirstIndexOdd = isFirstIndexSmallerThanLastIndex && isSumOdd && isFirstIndexOdd
let isFirstIndexBiggerThanLastIndexAndIsSumOddAndIsFirstIndexOdd = isFirstIndexBiggerThanLastIndex && isSumOdd && isFirstIndexOdd
let isXCTAssertTrue(sortArray(array: [] as [Int]) == [] as [Int]) // cannot find 'sortArray' in scopeXCTAssertTrue(sortArray(array: [5]) == [5]) // cannot find 'sortArray' in scopeXCTAssertTrue(sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]) // cannot find 'sortArray' in scopeXCTAssertTrue(sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]) // cannot find 'sortArray' in scopeXCTAssertTrue(sortArray(array: [2, 1]) == [1, 2]) // cannot find 'sortArray' in scopeXCTAssertTrue(sortArray(array: [15, 42, 87, 32, 11, 0]) == [0, 11, 15, 32, 42, 87]) // cannot find 'sortArray' in scopeXCTAssertTrue(sortArray(array: [21, 14, 23, 11]) == [23, 21, 14, 11]) // cannot find 'sortArray' in scopefunc encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encrypted = ""
for char in s {
let index = alphabet.firstIndex(of: char)!
let encryptedChar = alphabet[index + 2]
encrypted += String(encryptedChar)
}
return encrypted
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
Answer:
```swift
func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encrypted = ""
for char in s {
let index = alphabet.firstIndex(of: char)!
let encryptedChar = alphabet[index + 2]
encrypted += String(encryptedChar)
}
return encrypted
}
```let encryptedChar = alphabet[index + 2] // cannot convert value of type 'String.Index' to expected argument type 'Int'func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encrypted = ""
for char in s {
let index = alphabet.firstIndex(of: char)
let newIndex = index! + 2
let encryptedChar = alphabet[newIndex]
encrypted += String(encryptedChar)
}
return encrypted
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
Answer:
```swift
func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encrypted = ""
for char in s {
let index = alphabet.firstIndex(of: char)
let newIndex = index! + 2
let encryptedChar = alphabet[newIndex]
encrypted += String(encryptedChar)
}
return encrypted
}
```let newIndex = index! + 2 // cannot convert value of type 'String.Index' to expected argument type 'Int'func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encrypted = ""
for char in s {
let index = alphabet.firstIndex(of: char)!
let shiftedIndex = (index + 2) % alphabet.count
encrypted.append(alphabet[shiftedIndex])
}
return encrypted
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
Answer:
```swift
func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encrypted = ""
for char in s {
let index = alphabet.firstIndex(of: char)!
let shiftedIndex = (index + 2) % alphabet.count
encrypted.append(alphabet[shiftedIndex])
}
return encrypted
}
```let shiftedIndex = (index + 2) % alphabet.count // cannot convert value of type 'String.Index' to expected argument type 'Int'func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encrypted = ""
for char in s {
let index = alphabet.firstIndex(of: char)
let newIndex = (index! + 2) % alphabet.count
encrypted.append(alphabet[newIndex])
}
return encrypted
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
Answer:
```swift
func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encrypted = ""
for char in s {
let index = alphabet.firstIndex(of: char)
let newIndex = (index! + 2) % alphabet.count
encrypted.append(alphabet[newIndex])
}
return encrypted
}
```let newIndex = (index! + 2) % alphabet.count // cannot convert value of type 'String.Index' to expected argument type 'Int'func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encrypted = ""
for char in s {
let index = alphabet.firstIndex(of: char)!
let shiftedIndex = index + 2 * 2
let shiftedChar = alphabet[shiftedIndex]
encrypted += String(shiftedChar)
}
return encrypted
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
Answer:
```swift
func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encrypted = ""
for char in s {
let index = alphabet.firstIndex(of: char)!
let shiftedIndex = index + 2 * 2
let shiftedChar = alphabet[shiftedIndex]
encrypted += String(shiftedChar)
}
return encrypted
}
```let shiftedIndex = index + 2 * 2 // cannot convert value of type 'String.Index' to expected argument type 'Int'func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encrypted = ""
for char in s {
let index = alphabet.firstIndex(of: char)
let shiftedIndex = (index! + 2) % alphabet.count
encrypted.append(alphabet[shiftedIndex])
}
return encrypted
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
Answer:
```swift
func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encrypted = ""
for char in s {
let index = alphabet.firstIndex(of: char)
let shiftedIndex = (index! + 2) % alphabet.count
encrypted.append(alphabet[shiftedIndex])
}
return encrypted
}
```let shiftedIndex = (index! + 2) % alphabet.count // cannot convert value of type 'String.Index' to expected argument type 'Int'func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encrypted = ""
for char in s {
let index = alphabet.firstIndex(of: char)
let newIndex = (index! + 2) % alphabet.count
encrypted.append(alphabet[newIndex])
}
return encrypted
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
Answer:
```swift
func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encrypted = ""
for char in s {
let index = alphabet.firstIndex(of: char)
let newIndex = (index! + 2) % alphabet.count
encrypted.append(alphabet[newIndex])
}
return encrypted
}
```let newIndex = (index! + 2) % alphabet.count // cannot convert value of type 'String.Index' to expected argument type 'Int'func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encrypted = ""
for char in s {
let index = alphabet.firstIndex(of: char)!
let encryptedChar = alphabet[index + 2]
encrypted += String(encryptedChar)
}
return encrypted
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
Answer:
```swift
func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encrypted = ""
for char in s {
let index = alphabet.firstIndex(of: char)!
let encryptedChar = alphabet[index + 2]
encrypted += String(encryptedChar)
}
return encrypted
}
```let encryptedChar = alphabet[index + 2] // cannot convert value of type 'String.Index' to expected argument type 'Int'func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encrypted = ""
for char in s {
let index = alphabet.firstIndex(of: char)
let newIndex = (index! + 2) % alphabet.count
encrypted.append(alphabet[newIndex])
}
return encrypted
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
Answer:
```swift
func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encrypted = ""
for char in s {
let index = alphabet.firstIndex(of: char)
let newIndex = (index! + 2) % alphabet.count
encrypted.append(alphabet[newIndex])
}
return encrypted
}
```let newIndex = (index! + 2) % alphabet.count // cannot convert value of type 'String.Index' to expected argument type 'Int'func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encrypted = ""
for char in s {
let index = alphabet.firstIndex(of: char)
let shiftedIndex = index! + 2
let shiftedChar = alphabet[shiftedIndex]
encrypted += String(shiftedChar)
}
return encrypted
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
Answer:
```swift
func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encrypted = ""
for char in s {
let index = alphabet.firstIndex(of: char)
let shiftedIndex = index! + 2
let shiftedChar = alphabet[shiftedIndex]
encrypted += String(shiftedChar)
}
return encrypted
}
```let shiftedIndex = index! + 2 // cannot convert value of type 'String.Index' to expected argument type 'Int'func nextSmallest(lst: [Int]) -> Int? {
guard!lst.isEmpty else {
return nil
}
let min = lst.min()
let max = lst.max()
guard let min = min, let max = max else {
return nil
}
return lst.filter { $0!= min && $0!= max }.min()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
Answer:
```swift
func nextSmallest(lst: [Int]) -> Int? {
guard!lst.isEmpty else {
return nil
}
let min = lst.min()
let max = lst.max()
guard let min = min, let max = max else {
return nil
}
return lst.filter { $0!= min && $0!= max }.min()
}
```guard!lst.isEmpty else { // expected expression, var, let or case in 'guard' conditionreturn lst.filter { $0!= min && $0!= max }.min() // '=' must have consistent whitespace on both sidesreturn lst.filter { $0!= min && $0!= max }.min() // type 'Int' cannot be used as a boolean; test for '!= 0' insteadreturn lst.filter { $0!= min && $0!= max }.min() // trailing closure passed to parameter of type 'Predicate<Int>' that does not accept a closurereturn lst.filter { $0!= min && $0!= max }.min() // '=' must have consistent whitespace on both sidesfunc nextSmallest(lst: [Int]) -> Int? {
guard lst.count > 1 else {
return nil
}
let min = lst.min()
let max = lst.max()
guard let min = min, let max = max else {
return nil
}
return lst.filter { $0!= min && $0!= max }.min()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
Answer:
```swift
func nextSmallest(lst: [Int]) -> Int? {
guard lst.count > 1 else {
return nil
}
let min = lst.min()
let max = lst.max()
guard let min = min, let max = max else {
return nil
}
return lst.filter { $0!= min && $0!= max }.min()
}
```return lst.filter { $0!= min && $0!= max }.min() // type 'Int' cannot be used as a boolean; test for '!= 0' insteadreturn lst.filter { $0!= min && $0!= max }.min() // '=' must have consistent whitespace on both sidesreturn lst.filter { $0!= min && $0!= max }.min() // '=' must have consistent whitespace on both sidesreturn lst.filter { $0!= min && $0!= max }.min() // trailing closure passed to parameter of type 'Predicate<Int>' that does not accept a closurefunc nextSmallest(lst: [Int]) -> Int? {
guard!lst.isEmpty else {
return nil
}
let min = lst.min()
let max = lst.max()
guard let min = min, let max = max else {
return nil
}
return lst.filter { $0!= min && $0!= max }.min()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
Answer:
```swift
func nextSmallest(lst: [Int]) -> Int? {
guard!lst.isEmpty else {
return nil
}
let min = lst.min()
let max = lst.max()
guard let min = min, let max = max else {
return nil
}
return lst.filter { $0!= min && $0!= max }.min()
}
```guard!lst.isEmpty else { // expected expression, var, let or case in 'guard' conditionreturn lst.filter { $0!= min && $0!= max }.min() // '=' must have consistent whitespace on both sidesreturn lst.filter { $0!= min && $0!= max }.min() // type 'Int' cannot be used as a boolean; test for '!= 0' insteadreturn lst.filter { $0!= min && $0!= max }.min() // trailing closure passed to parameter of type 'Predicate<Int>' that does not accept a closurereturn lst.filter { $0!= min && $0!= max }.min() // '=' must have consistent whitespace on both sidesfunc nextSmallest(lst: [Int]) -> Int? {
guard!lst.isEmpty else {
return nil
}
let min = lst.min()
let max = lst.max()
guard let min = min, let max = max else {
return nil
}
return lst.filter { $0!= min && $0!= max }.min()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
Answer:
```swift
func nextSmallest(lst: [Int]) -> Int? {
guard!lst.isEmpty else {
return nil
}
let min = lst.min()
let max = lst.max()
guard let min = min, let max = max else {
return nil
}
return lst.filter { $0!= min && $0!= max }.min()
}
```guard!lst.isEmpty else { // expected expression, var, let or case in 'guard' conditionreturn lst.filter { $0!= min && $0!= max }.min() // '=' must have consistent whitespace on both sidesreturn lst.filter { $0!= min && $0!= max }.min() // type 'Int' cannot be used as a boolean; test for '!= 0' insteadreturn lst.filter { $0!= min && $0!= max }.min() // trailing closure passed to parameter of type 'Predicate<Int>' that does not accept a closurereturn lst.filter { $0!= min && $0!= max }.min() // '=' must have consistent whitespace on both sidesfunc nextSmallest(lst: [Int]) -> Int? {
guard!lst.isEmpty else {
return nil
}
let min = lst.min()
let max = lst.max()
guard let min = min, let max = max else {
return nil
}
return lst.filter { $0!= min && $0!= max }.min()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
Answer:
```swift
func nextSmallest(lst: [Int]) -> Int? {
guard!lst.isEmpty else {
return nil
}
let min = lst.min()
let max = lst.max()
guard let min = min, let max = max else {
return nil
}
return lst.filter { $0!= min && $0!= max }.min()
}
```guard!lst.isEmpty else { // expected expression, var, let or case in 'guard' conditionreturn lst.filter { $0!= min && $0!= max }.min() // '=' must have consistent whitespace on both sidesreturn lst.filter { $0!= min && $0!= max }.min() // type 'Int' cannot be used as a boolean; test for '!= 0' insteadreturn lst.filter { $0!= min && $0!= max }.min() // trailing closure passed to parameter of type 'Predicate<Int>' that does not accept a closurereturn lst.filter { $0!= min && $0!= max }.min() // '=' must have consistent whitespace on both sidesfunc nextSmallest(lst: [Int]) -> Int? {
guard lst.count > 1 else {
return nil
}
let min = lst.min()
let max = lst.max()
guard let min = min, let max = max else {
return nil
}
return lst.filter { $0!= min && $0!= max }.min()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
Answer:
```swift
func nextSmallest(lst: [Int]) -> Int? {
guard lst.count > 1 else {
return nil
}
let min = lst.min()
let max = lst.max()
guard let min = min, let max = max else {
return nil
}
return lst.filter { $0!= min && $0!= max }.min()
}
```return lst.filter { $0!= min && $0!= max }.min() // type 'Int' cannot be used as a boolean; test for '!= 0' insteadreturn lst.filter { $0!= min && $0!= max }.min() // '=' must have consistent whitespace on both sidesreturn lst.filter { $0!= min && $0!= max }.min() // '=' must have consistent whitespace on both sidesreturn lst.filter { $0!= min && $0!= max }.min() // trailing closure passed to parameter of type 'Predicate<Int>' that does not accept a closurefunc nextSmallest(lst: [Int]) -> Int? {
guard lst.count > 1 else {
return nil
}
let min = lst.min()
let max = lst.max()
guard let min = min, let max = max else {
return nil
}
return lst.filter { $0!= min && $0!= max }.min()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
Answer:
```swift
func nextSmallest(lst: [Int]) -> Int? {
guard lst.count > 1 else {
return nil
}
let min = lst.min()
let max = lst.max()
guard let min = min, let max = max else {
return nil
}
return lst.filter { $0!= min && $0!= max }.min()
}
```return lst.filter { $0!= min && $0!= max }.min() // type 'Int' cannot be used as a boolean; test for '!= 0' insteadreturn lst.filter { $0!= min && $0!= max }.min() // '=' must have consistent whitespace on both sidesreturn lst.filter { $0!= min && $0!= max }.min() // '=' must have consistent whitespace on both sidesreturn lst.filter { $0!= min && $0!= max }.min() // trailing closure passed to parameter of type 'Predicate<Int>' that does not accept a closurefunc nextSmallest(lst: [Int]) -> Int? {
guard!lst.isEmpty else {
return nil
}
let min = lst.min()
let max = lst.max()
guard let min = min, let max = max else {
return nil
}
return lst.filter { $0!= min && $0!= max }.min()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
Answer:
```swift
func nextSmallest(lst: [Int]) -> Int? {
guard!lst.isEmpty else {
return nil
}
let min = lst.min()
let max = lst.max()
guard let min = min, let max = max else {
return nil
}
return lst.filter { $0!= min && $0!= max }.min()
}
```guard!lst.isEmpty else { // expected expression, var, let or case in 'guard' conditionreturn lst.filter { $0!= min && $0!= max }.min() // '=' must have consistent whitespace on both sidesreturn lst.filter { $0!= min && $0!= max }.min() // type 'Int' cannot be used as a boolean; test for '!= 0' insteadreturn lst.filter { $0!= min && $0!= max }.min() // trailing closure passed to parameter of type 'Predicate<Int>' that does not accept a closurereturn lst.filter { $0!= min && $0!= max }.min() // '=' must have consistent whitespace on both sidesfunc nextSmallest(lst: [Int]) -> Int? {
guard let first = lst.first, let second = lst.dropFirst().first else {
return nil
}
return lst.contains(first)? second : nil
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
Answer:
```swift
func nextSmallest(lst: [Int]) -> Int? {
guard let first = lst.first, let second = lst.dropFirst().first else {
return nil
}
return lst.contains(first)? second : nil
}
```return lst.contains(first)? second : nil // type of expression is ambiguous without a type annotationreturn lst.contains(first)? second : nil // expression of type 'Int' is unusedreturn lst.contains(first)? second : nil // consecutive statements on a line must be separated by ';'return lst.contains(first)? second : nil // expected expressionreturn lst.contains(first)? second : nil // consecutive statements on a line must be separated by ';'func nextSmallest(lst: [Int]) -> Int? {
guard!lst.isEmpty else {
return nil
}
let min = lst.min()
let max = lst.max()
guard let min = min, let max = max else {
return nil
}
return lst.filter { $0!= min && $0!= max }.min()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
Answer:
```swift
func nextSmallest(lst: [Int]) -> Int? {
guard!lst.isEmpty else {
return nil
}
let min = lst.min()
let max = lst.max()
guard let min = min, let max = max else {
return nil
}
return lst.filter { $0!= min && $0!= max }.min()
}
```guard!lst.isEmpty else { // expected expression, var, let or case in 'guard' conditionreturn lst.filter { $0!= min && $0!= max }.min() // '=' must have consistent whitespace on both sidesreturn lst.filter { $0!= min && $0!= max }.min() // type 'Int' cannot be used as a boolean; test for '!= 0' insteadreturn lst.filter { $0!= min && $0!= max }.min() // trailing closure passed to parameter of type 'Predicate<Int>' that does not accept a closurereturn lst.filter { $0!= min && $0!= max }.min() // '=' must have consistent whitespace on both sidesfunc isBored(S: String) -> Int {
let words = S.components(separatedBy: " ")
var count = 0
for word in words {
if word.hasPrefix("I") {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
Answer:
```swift
func isBored(S: String) -> Int {
let words = S.components(separatedBy: " ")
var count = 0
for word in words {
if word.hasPrefix("I") {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc isBored(S: String) -> Int {
let words = S.components(separatedBy: " ")
var boredoms = 0
for word in words {
if word.hasPrefix("I") {
boredoms += 1
}
}
return boredoms
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
Answer:
```swift
func isBored(S: String) -> Int {
let words = S.components(separatedBy: " ")
var boredoms = 0
for word in words {
if word.hasPrefix("I") {
boredoms += 1
}
}
return boredoms
}
``` // XCTAssertTrue failedfunc isBored(S: String) -> Int {
let words = S.components(separatedBy: " ")
var boredoms = 0
for word in words {
if word.hasPrefix("I") {
boredoms += 1
}
}
return boredoms
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
Answer:
```swift
func isBored(S: String) -> Int {
let words = S.components(separatedBy: " ")
var boredoms = 0
for word in words {
if word.hasPrefix("I") {
boredoms += 1
}
}
return boredoms
}
``` // XCTAssertTrue failedfunc isBored(S: String) -> Int {
let words = S.components(separatedBy: " ")
var count = 0
for word in words {
if word.hasPrefix("I") {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
Answer:
```swift
func isBored(S: String) -> Int {
let words = S.components(separatedBy: " ")
var count = 0
for word in words {
if word.hasPrefix("I") {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc isBored(S: String) -> Int {
let words = S.components(separatedBy: " ")
var count = 0
for word in words {
if word.hasPrefix("I") {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
Answer:
```swift
func isBored(S: String) -> Int {
let words = S.components(separatedBy: " ")
var count = 0
for word in words {
if word.hasPrefix("I") {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc isBored(S: String) -> Int {
let words = S.components(separatedBy: " ")
var count = 0
for word in words {
if word.hasPrefix("I") {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
Answer:
```swift
func isBored(S: String) -> Int {
let words = S.components(separatedBy: " ")
var count = 0
for word in words {
if word.hasPrefix("I") {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc isBored(S: String) -> Int {
let words = S.components(separatedBy: " ")
var count = 0
for word in words {
if word.hasPrefix("I") {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
Answer:
```swift
func isBored(S: String) -> Int {
let words = S.components(separatedBy: " ")
var count = 0
for word in words {
if word.hasPrefix("I") {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc isBored(S: String) -> Int {
let words = S.components(separatedBy: " ")
var boredoms = 0
for word in words {
if word.hasPrefix("I") {
boredoms += 1
}
}
return boredoms
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
Answer:
```swift
func isBored(S: String) -> Int {
let words = S.components(separatedBy: " ")
var boredoms = 0
for word in words {
if word.hasPrefix("I") {
boredoms += 1
}
}
return boredoms
}
``` // XCTAssertTrue failedfunc isBored(S: String) -> Int {
let words = S.components(separatedBy: " ")
var boredoms = 0
for word in words {
if word.hasPrefix("I") {
boredoms += 1
}
}
return boredoms
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
Answer:
```swift
func isBored(S: String) -> Int {
let words = S.components(separatedBy: " ")
var boredoms = 0
for word in words {
if word.hasPrefix("I") {
boredoms += 1
}
}
return boredoms
}
``` // XCTAssertTrue failedfunc isBored(S: String) -> Int {
let words = S.components(separatedBy: " ")
var boredoms = 0
for word in words {
if word.hasPrefix("I") {
boredoms += 1
}
}
return boredoms
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
Answer:
```swift
func isBored(S: String) -> Int {
let words = S.components(separatedBy: " ")
var boredoms = 0
for word in words {
if word.hasPrefix("I") {
boredoms += 1
}
}
return boredoms
}
``` // XCTAssertTrue failedfunc anyInt(x: Double, y: Double, z: Double) -> Bool {
return (x == y + z || y == x + z || z == x + y) && x.isInteger && y.isInteger && z.isInteger
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
Answer:
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
return (x == y + z || y == x + z || z == x + y) && x.isInteger && y.isInteger && z.isInteger
}
```return (x == y + z || y == x + z || z == x + y) && x.isInteger && y.isInteger && z.isInteger // value of type 'Double' has no member 'isInteger'return (x == y + z || y == x + z || z == x + y) && x.isInteger && y.isInteger && z.isInteger // value of type 'Double' has no member 'isInteger'return (x == y + z || y == x + z || z == x + y) && x.isInteger && y.isInteger && z.isInteger // value of type 'Double' has no member 'isInteger'func anyInt(x: Double, y: Double, z: Double) -> Bool {
return (x == y + z || y == x + z || z == x + y) && x.isInteger && y.isInteger && z.isInteger
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
Answer:
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
return (x == y + z || y == x + z || z == x + y) && x.isInteger && y.isInteger && z.isInteger
}
```return (x == y + z || y == x + z || z == x + y) && x.isInteger && y.isInteger && z.isInteger // value of type 'Double' has no member 'isInteger'return (x == y + z || y == x + z || z == x + y) && x.isInteger && y.isInteger && z.isInteger // value of type 'Double' has no member 'isInteger'return (x == y + z || y == x + z || z == x + y) && x.isInteger && y.isInteger && z.isInteger // value of type 'Double' has no member 'isInteger'func anyInt(x: Double, y: Double, z: Double) -> Bool {
return (x == y + z) || (y == x + z) || (z == x + y)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
Answer:
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
return (x == y + z) || (y == x + z) || (z == x + y)
}
``` // XCTAssertTrue failedfunc anyInt(x: Double, y: Double, z: Double) -> Bool {
return (x == y + z || y == x + z || z == x + y) && x.isInteger && y.isInteger && z.isInteger
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
Answer:
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
return (x == y + z || y == x + z || z == x + y) && x.isInteger && y.isInteger && z.isInteger
}
```return (x == y + z || y == x + z || z == x + y) && x.isInteger && y.isInteger && z.isInteger // value of type 'Double' has no member 'isInteger'return (x == y + z || y == x + z || z == x + y) && x.isInteger && y.isInteger && z.isInteger // value of type 'Double' has no member 'isInteger'return (x == y + z || y == x + z || z == x + y) && x.isInteger && y.isInteger && z.isInteger // value of type 'Double' has no member 'isInteger'func anyInt(x: Double, y: Double, z: Double) -> Bool {
return (x == y + z || y == x + z || z == x + y) && x.isInteger && y.isInteger && z.isInteger
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
Answer:
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
return (x == y + z || y == x + z || z == x + y) && x.isInteger && y.isInteger && z.isInteger
}
```return (x == y + z || y == x + z || z == x + y) && x.isInteger && y.isInteger && z.isInteger // value of type 'Double' has no member 'isInteger'return (x == y + z || y == x + z || z == x + y) && x.isInteger && y.isInteger && z.isInteger // value of type 'Double' has no member 'isInteger'return (x == y + z || y == x + z || z == x + y) && x.isInteger && y.isInteger && z.isInteger // value of type 'Double' has no member 'isInteger'func anyInt(x: Double, y: Double, z: Double) -> Bool {
return (x == y + z) || (y == x + z) || (z == x + y)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
Answer:
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
return (x == y + z) || (y == x + z) || (z == x + y)
}
``` // XCTAssertTrue failedfunc anyInt(x: Double, y: Double, z: Double) -> Bool {
return (x == y + z) || (y == x + z) || (z == x + y)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
Answer:
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
return (x == y + z) || (y == x + z) || (z == x + y)
}
``` // XCTAssertTrue failedfunc anyInt(x: Double, y: Double, z: Double) -> Bool {
return (x == y + z) || (y == x + z) || (z == x + y)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
Answer:
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
return (x == y + z) || (y == x + z) || (z == x + y)
}
``` // XCTAssertTrue failedfunc anyInt(x: Double, y: Double, z: Double) -> Bool {
return (x == y + z || y == x + z || z == x + y) && (x.isNaN == false && y.isNaN == false && z.isNaN == false)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
Answer:
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
return (x == y + z || y == x + z || z == x + y) && (x.isNaN == false && y.isNaN == false && z.isNaN == false)
}
``` // XCTAssertTrue failedfunc anyInt(x: Double, y: Double, z: Double) -> Bool {
return (x == y + z || y == x + z || z == x + y) && (x.isNaN == false && y.isNaN == false && z.isNaN == false)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
Answer:
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
return (x == y + z || y == x + z || z == x + y) && (x.isNaN == false && y.isNaN == false && z.isNaN == false)
}
``` // XCTAssertTrue failedfunc encode(message: String) -> String {
let vowels = "aeiouAEIOU"
var encodedMessage = ""
for character in message {
if vowels.contains(character) {
let index = vowels.firstIndex(of: character)!
let newCharacter = vowels[index + 2]
encodedMessage.append(newCharacter)
} else {
encodedMessage.append(character.isUpper? character.lowercased() : character.uppercased())
}
}
return encodedMessage
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
Answer:
```swift
func encode(message: String) -> String {
let vowels = "aeiouAEIOU"
var encodedMessage = ""
for character in message {
if vowels.contains(character) {
let index = vowels.firstIndex(of: character)!
let newCharacter = vowels[index + 2]
encodedMessage.append(newCharacter)
} else {
encodedMessage.append(character.isUpper? character.lowercased() : character.uppercased())
}
}
return encodedMessage
}
```let newCharacter = vowels[index + 2] // cannot convert value of type 'String.Index' to expected argument type 'Int'encodedMessage.append(character.isUpper? character.lowercased() : character.uppercased()) // type of expression is ambiguous without a type annotationencodedMessage.append(character.isUpper? character.lowercased() : character.uppercased()) // expected ',' separatorfunc encode(message: String) -> String {
let vowels = ["a", "e", "i", "o", "u"]
var encodedMessage = ""
for character in message {
if vowels.contains(String(character)) {
let index = vowels.firstIndex(of: String(character))!
let nextVowel = vowels[index + 2]
encodedMessage.append(String(nextVowel))
} else {
encodedMessage.append(String(character).reversed())
}
}
return encodedMessage
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
Answer:
```swift
func encode(message: String) -> String {
let vowels = ["a", "e", "i", "o", "u"]
var encodedMessage = ""
for character in message {
if vowels.contains(String(character)) {
let index = vowels.firstIndex(of: String(character))!
let nextVowel = vowels[index + 2]
encodedMessage.append(String(nextVowel))
} else {
encodedMessage.append(String(character).reversed())
}
}
return encodedMessage
}
```encodedMessage.append(String(character).reversed()) // no exact matches in call to instance method 'append'func encode(message: String) -> String {
let vowels = "aeiou"
var encodedMessage = ""
for character in message {
if vowels.contains(character.lowercased()) {
let index = vowels.firstIndex(of: character.lowercased())!
let newVowel = vowels[index + 2]
encodedMessage.append(newVowel)
} else {
encodedMessage.append(character.isUpper? character.lowercased() : character.uppercased())
}
}
return encodedMessage
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
Answer:
```swift
func encode(message: String) -> String {
let vowels = "aeiou"
var encodedMessage = ""
for character in message {
if vowels.contains(character.lowercased()) {
let index = vowels.firstIndex(of: character.lowercased())!
let newVowel = vowels[index + 2]
encodedMessage.append(newVowel)
} else {
encodedMessage.append(character.isUpper? character.lowercased() : character.uppercased())
}
}
return encodedMessage
}
```let index = vowels.firstIndex(of: character.lowercased())! // cannot convert value of type 'String' to expected argument type 'String.Element' (aka 'Character')encodedMessage.append(character.isUpper? character.lowercased() : character.uppercased()) // expected ',' separatorencodedMessage.append(character.isUpper? character.lowercased() : character.uppercased()) // type of expression is ambiguous without a type annotationfunc encode(message: String) -> String {
let vowels = "aeiouAEIOU"
let alphabet = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
var encodedMessage = ""
for character in message {
if vowels.contains(character) {
let index = vowels.firstIndex(of: character)!
let newCharacter = alphabet[index + 2]
encodedMessage.append(newCharacter)
} else {
encodedMessage.append(character.isUpper? character.lowercased() : character.uppercased())
}
}
return encodedMessage
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
Answer:
```swift
func encode(message: String) -> String {
let vowels = "aeiouAEIOU"
let alphabet = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
var encodedMessage = ""
for character in message {
if vowels.contains(character) {
let index = vowels.firstIndex(of: character)!
let newCharacter = alphabet[index + 2]
encodedMessage.append(newCharacter)
} else {
encodedMessage.append(character.isUpper? character.lowercased() : character.uppercased())
}
}
return encodedMessage
}
```let newCharacter = alphabet[index + 2] // cannot convert value of type 'String.Index' to expected argument type 'Int'encodedMessage.append(character.isUpper? character.lowercased() : character.uppercased()) // expected ',' separatorencodedMessage.append(character.isUpper? character.lowercased() : character.uppercased()) // type of expression is ambiguous without a type annotationfunc encode(message: String) -> String {
let vowels = ["a", "e", "i", "o", "u"]
var encodedMessage = ""
for character in message {
if vowels.contains(String(character)) {
let vowelIndex = vowels.firstIndex(of: String(character))!
let nextVowel = vowels[vowelIndex + 2]
encodedMessage.append(String(nextVowel))
} else {
encodedMessage.append(String(character).reversed())
}
}
return encodedMessage
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
Answer:
```swift
func encode(message: String) -> String {
let vowels = ["a", "e", "i", "o", "u"]
var encodedMessage = ""
for character in message {
if vowels.contains(String(character)) {
let vowelIndex = vowels.firstIndex(of: String(character))!
let nextVowel = vowels[vowelIndex + 2]
encodedMessage.append(String(nextVowel))
} else {
encodedMessage.append(String(character).reversed())
}
}
return encodedMessage
}
```encodedMessage.append(String(character).reversed()) // no exact matches in call to instance method 'append'func encode(message: String) -> String {
let vowels = ["a", "e", "i", "o", "u"]
var encodedMessage = ""
for character in message {
if vowels.contains(character.lowercased()) {
let index = vowels.firstIndex(of: character.lowercased())!
let newVowel = vowels[index + 2]
encodedMessage.append(newVowel)
} else {
encodedMessage.append(character.lowercased().reversed())
}
}
return encodedMessage
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
Answer:
```swift
func encode(message: String) -> String {
let vowels = ["a", "e", "i", "o", "u"]
var encodedMessage = ""
for character in message {
if vowels.contains(character.lowercased()) {
let index = vowels.firstIndex(of: character.lowercased())!
let newVowel = vowels[index + 2]
encodedMessage.append(newVowel)
} else {
encodedMessage.append(character.lowercased().reversed())
}
}
return encodedMessage
}
```encodedMessage.append(character.lowercased().reversed()) // no exact matches in call to instance method 'append'func encode(message: String) -> String {
let vowels = "aeiouAEIOU"
var encodedMessage = ""
for character in message {
if vowels.contains(character) {
let index = vowels.firstIndex(of: character)!
let newCharacter = vowels[index + 2]
encodedMessage.append(newCharacter)
} else {
let newCharacter = character.toggleCase()
encodedMessage.append(newCharacter)
}
}
return encodedMessage
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
Answer:
```swift
func encode(message: String) -> String {
let vowels = "aeiouAEIOU"
var encodedMessage = ""
for character in message {
if vowels.contains(character) {
let index = vowels.firstIndex(of: character)!
let newCharacter = vowels[index + 2]
encodedMessage.append(newCharacter)
} else {
let newCharacter = character.toggleCase()
encodedMessage.append(newCharacter)
}
}
return encodedMessage
}
```let newCharacter = vowels[index + 2] // cannot convert value of type 'String.Index' to expected argument type 'Int'let newCharacter = character.toggleCase() // value of type 'Character' has no member 'toggleCase'func encode(message: String) -> String {
let vowels = "aeiouAEIOU"
var encodedMessage = ""
for character in message {
if vowels.contains(character) {
let index = vowels.firstIndex(of: character)!
let shiftedVowel = vowels[index + 2]
encodedMessage.append(shiftedVowel)
} else {
encodedMessage.append(character.isUpper? character.lowercased() : character.uppercased())
}
}
return encodedMessage
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
Answer:
```swift
func encode(message: String) -> String {
let vowels = "aeiouAEIOU"
var encodedMessage = ""
for character in message {
if vowels.contains(character) {
let index = vowels.firstIndex(of: character)!
let shiftedVowel = vowels[index + 2]
encodedMessage.append(shiftedVowel)
} else {
encodedMessage.append(character.isUpper? character.lowercased() : character.uppercased())
}
}
return encodedMessage
}
```let shiftedVowel = vowels[index + 2] // cannot convert value of type 'String.Index' to expected argument type 'Int'encodedMessage.append(character.isUpper? character.lowercased() : character.uppercased()) // type of expression is ambiguous without a type annotationencodedMessage.append(character.isUpper? character.lowercased() : character.uppercased()) // expected ',' separatorfunc encode(message: String) -> String {
let vowels = ["a", "e", "i", "o", "u"]
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encodedMessage = ""
for character in message {
if vowels.contains(character) {
let vowelIndex = alphabet.firstIndex(of: character)!
let newVowelIndex = vowelIndex + 2
let newVowel = alphabet[newVowelIndex]
encodedMessage.append(newVowel)
} else {
let newCharacter = character.toggleCase()
encodedMessage.append(newCharacter)
}
}
return encodedMessage
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
Answer:
```swift
func encode(message: String) -> String {
let vowels = ["a", "e", "i", "o", "u"]
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encodedMessage = ""
for character in message {
if vowels.contains(character) {
let vowelIndex = alphabet.firstIndex(of: character)!
let newVowelIndex = vowelIndex + 2
let newVowel = alphabet[newVowelIndex]
encodedMessage.append(newVowel)
} else {
let newCharacter = character.toggleCase()
encodedMessage.append(newCharacter)
}
}
return encodedMessage
}
```if vowels.contains(character) { // cannot convert value of type 'Character' to expected argument type 'String'let newVowelIndex = vowelIndex + 2 // cannot convert value of type 'String.Index' to expected argument type 'Int'let newCharacter = character.toggleCase() // value of type 'Character' has no member 'toggleCase'func encode(message: String) -> String {
let vowels = ["a", "e", "i", "o", "u"]
var encodedMessage = ""
for character in message {
if vowels.contains(String(character)) {
let vowelIndex = vowels.firstIndex(of: String(character))!
let nextVowel = vowels[vowelIndex + 2]
encodedMessage.append(String(nextVowel))
} else {
encodedMessage.append(String(character).reversed())
}
}
return encodedMessage
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
Answer:
```swift
func encode(message: String) -> String {
let vowels = ["a", "e", "i", "o", "u"]
var encodedMessage = ""
for character in message {
if vowels.contains(String(character)) {
let vowelIndex = vowels.firstIndex(of: String(character))!
let nextVowel = vowels[vowelIndex + 2]
encodedMessage.append(String(nextVowel))
} else {
encodedMessage.append(String(character).reversed())
}
}
return encodedMessage
}
```encodedMessage.append(String(character).reversed()) // no exact matches in call to instance method 'append'func skjkasdkd(lst: [Int]) -> Int {
var largestPrime = 0
var largestPrimeSum = 0
for num in lst {
if num > largestPrime {
largestPrime = num
largestPrimeSum = 0
for digit in String(num).characters.map { Int(String($0))! } {
largestPrimeSum += digit
}
}
}
return largestPrimeSum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
Answer:
```swift
func skjkasdkd(lst: [Int]) -> Int {
var largestPrime = 0
var largestPrimeSum = 0
for num in lst {
if num > largestPrime {
largestPrime = num
largestPrimeSum = 0
for digit in String(num).characters.map { Int(String($0))! } {
largestPrimeSum += digit
}
}
}
return largestPrimeSum
}
```for digit in String(num).characters.map { Int(String($0))! } { // 'characters' is unavailable: Please use String directlyfor digit in String(num).characters.map { Int(String($0))! } { // trailing closure in this context is confusable with the body of the statement; pass as a parenthesized argument to silence this warningfunc skjkasdkd(lst: [Int]) -> Int {
var largestPrime = 0
for num in lst {
if isPrime(num) {
largestPrime = num
}
}
return sumOfDigits(largestPrime)
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
var sum = 0
while num > 0 {
sum += num % 10
num /= 10
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
Answer:
```swift
func skjkasdkd(lst: [Int]) -> Int {
var largestPrime = 0
for num in lst {
if isPrime(num) {
largestPrime = num
}
}
return sumOfDigits(largestPrime)
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
var sum = 0
while num > 0 {
sum += num % 10
num /= 10
}
return sum
}
```num /= 10 // left side of mutating operator isn't mutable: 'num' is a 'let' constantfunc skjkasdkd(lst: [Int]) -> Int {
var largestPrime = 0
for num in lst {
if isPrime(num) {
largestPrime = num
}
}
return sumOfDigits(largestPrime)
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
var sum = 0
while num > 0 {
sum += num % 10
num /= 10
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
Answer:
```swift
func skjkasdkd(lst: [Int]) -> Int {
var largestPrime = 0
for num in lst {
if isPrime(num) {
largestPrime = num
}
}
return sumOfDigits(largestPrime)
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
var sum = 0
while num > 0 {
sum += num % 10
num /= 10
}
return sum
}
```num /= 10 // left side of mutating operator isn't mutable: 'num' is a 'let' constantfunc skjkasdkd(lst: [Int]) -> Int {
var largestPrime = 0
for num in lst {
if isPrime(num) {
largestPrime = num
}
}
return sumOfDigits(largestPrime)
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
var sum = 0
while num > 0 {
sum += num % 10
num /= 10
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
Answer:
```swift
func skjkasdkd(lst: [Int]) -> Int {
var largestPrime = 0
for num in lst {
if isPrime(num) {
largestPrime = num
}
}
return sumOfDigits(largestPrime)
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
var sum = 0
while num > 0 {
sum += num % 10
num /= 10
}
return sum
}
```num /= 10 // left side of mutating operator isn't mutable: 'num' is a 'let' constantfunc skjkasdkd(lst: [Int]) -> Int {
var largestPrime = 0
for num in lst {
if isPrime(num) {
largestPrime = num
}
}
return sumOfDigits(largestPrime)
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
var sum = 0
while num > 0 {
sum += num % 10
num /= 10
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
Answer:
```swift
func skjkasdkd(lst: [Int]) -> Int {
var largestPrime = 0
for num in lst {
if isPrime(num) {
largestPrime = num
}
}
return sumOfDigits(largestPrime)
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
var sum = 0
while num > 0 {
sum += num % 10
num /= 10
}
return sum
}
```num /= 10 // left side of mutating operator isn't mutable: 'num' is a 'let' constantfunc skjkasdkd(lst: [Int]) -> Int {
var largestPrime = 0
var largestPrimeSum = 0
for num in lst {
if isPrime(num) {
largestPrime = num
largestPrimeSum = sumOfDigits(num)
}
}
return largestPrimeSum
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
var sum = 0
var currentNum = num
while currentNum > 0 {
sum += currentNum % 10
currentNum /= 10
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
Answer:
```swift
func skjkasdkd(lst: [Int]) -> Int {
var largestPrime = 0
var largestPrimeSum = 0
for num in lst {
if isPrime(num) {
largestPrime = num
largestPrimeSum = sumOfDigits(num)
}
}
return largestPrimeSum
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
var sum = 0
var currentNum = num
while currentNum > 0 {
sum += currentNum % 10
currentNum /= 10
}
return sum
}
```var largestPrime = 0 // variable 'largestPrime' was written to, but never read // XCTAssertTrue failedfunc skjkasdkd(lst: [Int]) -> Int {
var largestPrime = 0
var largestPrimeSum = 0
for num in lst {
if isPrime(num) {
largestPrime = num
largestPrimeSum = sumOfDigits(num)
}
}
return largestPrimeSum
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
var sum = 0
var currentNum = num
while currentNum > 0 {
let remainder = currentNum % 10
sum += remainder
currentNum /= 10
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
Answer:
```swift
func skjkasdkd(lst: [Int]) -> Int {
var largestPrime = 0
var largestPrimeSum = 0
for num in lst {
if isPrime(num) {
largestPrime = num
largestPrimeSum = sumOfDigits(num)
}
}
return largestPrimeSum
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
var sum = 0
var currentNum = num
while currentNum > 0 {
let remainder = currentNum % 10
sum += remainder
currentNum /= 10
}
return sum
}
```var largestPrime = 0 // variable 'largestPrime' was written to, but never read // XCTAssertTrue failedfunc skjkasdkd(lst: [Int]) -> Int {
var largestPrime = 0
var largestPrimeSum = 0
for num in lst {
if isPrime(num) {
largestPrime = num
largestPrimeSum = sumOfDigits(num)
}
}
return largestPrimeSum
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
var sum = 0
var currentNum = num
while currentNum > 0 {
sum += currentNum % 10
currentNum /= 10
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
Answer:
```swift
func skjkasdkd(lst: [Int]) -> Int {
var largestPrime = 0
var largestPrimeSum = 0
for num in lst {
if isPrime(num) {
largestPrime = num
largestPrimeSum = sumOfDigits(num)
}
}
return largestPrimeSum
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
var sum = 0
var currentNum = num
while currentNum > 0 {
sum += currentNum % 10
currentNum /= 10
}
return sum
}
```var largestPrime = 0 // variable 'largestPrime' was written to, but never read // XCTAssertTrue failedfunc skjkasdkd(lst: [Int]) -> Int {
var largestPrime = 0
var largestPrimeSum = 0
for num in lst {
if isPrime(num) {
largestPrime = num
largestPrimeSum = sumOfDigits(num)
}
}
return largestPrimeSum
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
var sum = 0
var currentNum = num
while currentNum > 0 {
sum += currentNum % 10
currentNum /= 10
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
Answer:
```swift
func skjkasdkd(lst: [Int]) -> Int {
var largestPrime = 0
var largestPrimeSum = 0
for num in lst {
if isPrime(num) {
largestPrime = num
largestPrimeSum = sumOfDigits(num)
}
}
return largestPrimeSum
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
var sum = 0
var currentNum = num
while currentNum > 0 {
sum += currentNum % 10
currentNum /= 10
}
return sum
}
```var largestPrime = 0 // variable 'largestPrime' was written to, but never read // XCTAssertTrue failedfunc skjkasdkd(lst: [Int]) -> Int {
var largestPrime = 0
var sumOfDigits = 0
for num in lst {
if isPrime(num) {
largestPrime = num
}
sumOfDigits += num.digits.reduce(0, +)
}
return sumOfDigits
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
extension Int {
var digits: [Int] {
return self.description.map { String($0) }.map { Int($0)! }
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
Answer:
```swift
func skjkasdkd(lst: [Int]) -> Int {
var largestPrime = 0
var sumOfDigits = 0
for num in lst {
if isPrime(num) {
largestPrime = num
}
sumOfDigits += num.digits.reduce(0, +)
}
return sumOfDigits
}
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
extension Int {
var digits: [Int] {
return self.description.map { String($0) }.map { Int($0)! }
}
}
```var largestPrime = 0 // variable 'largestPrime' was written to, but never read // XCTAssertTrue failedfunc countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for i in 2...n {
var isPrime = true
for j in 2..<i {
if i % j == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(i)
}
}
return primes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
Answer:
```swift
func countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for i in 2...n {
var isPrime = true
for j in 2..<i {
if i % j == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(i)
}
}
return primes
}
``` // XCTAssertTrue failedfunc countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for i in 2...n {
var isPrime = true
for j in 2..<i {
if i % j == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(i)
}
}
return primes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
Answer:
```swift
func countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for i in 2...n {
var isPrime = true
for j in 2..<i {
if i % j == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(i)
}
}
return primes
}
``` // XCTAssertTrue failedfunc countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for i in 2...n {
var isPrime = true
for j in 2..<i {
if i % j == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(i)
}
}
return primes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
Answer:
```swift
func countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for i in 2...n {
var isPrime = true
for j in 2..<i {
if i % j == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(i)
}
}
return primes
}
``` // XCTAssertTrue failedfunc countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for i in 2...n {
var isPrime = true
for j in 2..<i {
if i % j == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(i)
}
}
return primes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
Answer:
```swift
func countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for i in 2...n {
var isPrime = true
for j in 2..<i {
if i % j == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(i)
}
}
return primes
}
``` // XCTAssertTrue failedfunc countUpTo(n: Int) -> [Int] {
var primes = [Int]()
var i = 2
while primes.count < n {
var isPrime = true
for j in 2..<i {
if i % j == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(i)
}
i += 1
}
return primes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
Answer:
```swift
func countUpTo(n: Int) -> [Int] {
var primes = [Int]()
var i = 2
while primes.count < n {
var isPrime = true
for j in 2..<i {
if i % j == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(i)
}
i += 1
}
return primes
}
``` // XCTAssertTrue failedfunc countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for i in 2...n {
var isPrime = true
for j in 2..<i {
if i % j == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(i)
}
}
return primes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
Answer:
```swift
func countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for i in 2...n {
var isPrime = true
for j in 2..<i {
if i % j == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(i)
}
}
return primes
}
``` // XCTAssertTrue failedfunc countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for i in 2...n {
var isPrime = true
for j in 2..<i {
if i % j == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(i)
}
}
return primes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
Answer:
```swift
func countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for i in 2...n {
var isPrime = true
for j in 2..<i {
if i % j == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(i)
}
}
return primes
}
``` // XCTAssertTrue failedfunc countUpTo(n: Int) -> [Int] {
guard n > 0 else {
return []
}
var primes = [Int]()
var i = 2
while primes.count < n {
if isPrime(i) {
primes.append(i)
}
i += 1
}
return primes
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
Answer:
```swift
func countUpTo(n: Int) -> [Int] {
guard n > 0 else {
return []
}
var primes = [Int]()
var i = 2
while primes.count < n {
if isPrime(i) {
primes.append(i)
}
i += 1
}
return primes
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc countUpTo(n: Int) -> [Int] {
guard n > 0 else {
return []
}
var primes = [Int]()
for i in 2...n {
var isPrime = true
for j in 2..<i {
if i % j == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(i)
}
}
return primes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
Answer:
```swift
func countUpTo(n: Int) -> [Int] {
guard n > 0 else {
return []
}
var primes = [Int]()
for i in 2...n {
var isPrime = true
for j in 2..<i {
if i % j == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(i)
}
}
return primes
}
``` // XCTAssertTrue failedfunc countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for i in 2...n {
var isPrime = true
for j in 2..<i {
if i % j == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(i)
}
}
return primes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
Answer:
```swift
func countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for i in 2...n {
var isPrime = true
for j in 2..<i {
if i % j == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(i)
}
}
return primes
}
``` // XCTAssertTrue failedfunc multiply(a: Int, b: Int) -> Int {
let unitDigitA = a % 10
let unitDigitB = b % 10
return (unitDigitA * unitDigitB) % 10
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
Answer:
```swift
func multiply(a: Int, b: Int) -> Int {
let unitDigitA = a % 10
let unitDigitB = b % 10
return (unitDigitA * unitDigitB) % 10
}
``` // XCTAssertTrue failedfunc multiply(a: Int, b: Int) -> Int {
return (a % 10) * (b % 10)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
Answer:
```swift
func multiply(a: Int, b: Int) -> Int {
return (a % 10) * (b % 10)
}
``` // XCTAssertTrue failedfunc multiply(a: Int, b: Int) -> Int {
return (a % 10) * (b % 10)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
Answer:
```swift
func multiply(a: Int, b: Int) -> Int {
return (a % 10) * (b % 10)
}
``` // XCTAssertTrue failedfunc multiply(a: Int, b: Int) -> Int {
return (a % 10) * (b % 10)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
Answer:
```swift
func multiply(a: Int, b: Int) -> Int {
return (a % 10) * (b % 10)
}
``` // XCTAssertTrue failedfunc multiply(a: Int, b: Int) -> Int {
let unitDigitA = a % 10
let unitDigitB = b % 10
return (unitDigitA * unitDigitB) % 10
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
Answer:
```swift
func multiply(a: Int, b: Int) -> Int {
let unitDigitA = a % 10
let unitDigitB = b % 10
return (unitDigitA * unitDigitB) % 10
}
``` // XCTAssertTrue failedfunc multiply(a: Int, b: Int) -> Int {
let unitA = a % 10
let unitB = b % 10
return (unitA * unitB) % 10
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
Answer:
```swift
func multiply(a: Int, b: Int) -> Int {
let unitA = a % 10
let unitB = b % 10
return (unitA * unitB) % 10
}
``` // XCTAssertTrue failedfunc multiply(a: Int, b: Int) -> Int {
let aUnit = a % 10
let bUnit = b % 10
return aUnit * bUnit
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
Answer:
```swift
func multiply(a: Int, b: Int) -> Int {
let aUnit = a % 10
let bUnit = b % 10
return aUnit * bUnit
}
``` // XCTAssertTrue failedfunc multiply(a: Int, b: Int) -> Int {
return (a % 10) * (b % 10)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
Answer:
```swift
func multiply(a: Int, b: Int) -> Int {
return (a % 10) * (b % 10)
}
``` // XCTAssertTrue failedfunc multiply(a: Int, b: Int) -> Int {
let unitDigitA = a % 10
let unitDigitB = b % 10
return (unitDigitA * unitDigitB) % 10
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
Answer:
```swift
func multiply(a: Int, b: Int) -> Int {
let unitDigitA = a % 10
let unitDigitB = b % 10
return (unitDigitA * unitDigitB) % 10
}
``` // XCTAssertTrue failedfunc multiply(a: Int, b: Int) -> Int {
let unitDigitA = a % 10
let unitDigitB = b % 10
return (unitDigitA * unitDigitB) % 10
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
Answer:
```swift
func multiply(a: Int, b: Int) -> Int {
let unitDigitA = a % 10
let unitDigitB = b % 10
return (unitDigitA * unitDigitB) % 10
}
``` // XCTAssertTrue failedfunc countUpper(s: String) -> Int {
var count = 0
for (index, character) in s.enumerated() {
if index % 2 == 0 && character.isUppercase {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
Answer:
```swift
func countUpper(s: String) -> Int {
var count = 0
for (index, character) in s.enumerated() {
if index % 2 == 0 && character.isUppercase {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc countUpper(s: String) -> Int {
var count = 0
for (index, character) in s.enumerated() where index % 2 == 0 && character.isUpper {
count += 1
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
Answer:
```swift
func countUpper(s: String) -> Int {
var count = 0
for (index, character) in s.enumerated() where index % 2 == 0 && character.isUpper {
count += 1
}
return count
}
```for (index, character) in s.enumerated() where index % 2 == 0 && character.isUpper { // value of type 'String.Element' (aka 'Character') has no member 'isUpper'func countUpper(s: String) -> Int {
var count = 0
for (index, character) in s.enumerated() {
if index % 2 == 0 && character.isUppercase {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
Answer:
```swift
func countUpper(s: String) -> Int {
var count = 0
for (index, character) in s.enumerated() {
if index % 2 == 0 && character.isUppercase {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc countUpper(s: String) -> Int {
var count = 0
for (index, character) in s.enumerated() {
if index % 2 == 0 && character.isUppercase {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
Answer:
```swift
func countUpper(s: String) -> Int {
var count = 0
for (index, character) in s.enumerated() {
if index % 2 == 0 && character.isUppercase {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc countUpper(s: String) -> Int {
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0 && char.isUpper {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
Answer:
```swift
func countUpper(s: String) -> Int {
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0 && char.isUpper {
count += 1
}
}
return count
}
```if index % 2 == 0 && char.isUpper { // value of type 'String.Element' (aka 'Character') has no member 'isUpper'func countUpper(s: String) -> Int {
var count = 0
for (index, character) in s.enumerated() {
if index % 2 == 0 && character.isUppercase {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
Answer:
```swift
func countUpper(s: String) -> Int {
var count = 0
for (index, character) in s.enumerated() {
if index % 2 == 0 && character.isUppercase {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc countUpper(s: String) -> Int {
var count = 0
for (index, character) in s.enumerated() where index % 2 == 0 && character.isUppercase {
count += 1
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
Answer:
```swift
func countUpper(s: String) -> Int {
var count = 0
for (index, character) in s.enumerated() where index % 2 == 0 && character.isUppercase {
count += 1
}
return count
}
``` // XCTAssertTrue failedfunc countUpper(s: String) -> Int {
var count = 0
for (index, character) in s.enumerated() {
if index % 2 == 0 && character.isUppercase {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
Answer:
```swift
func countUpper(s: String) -> Int {
var count = 0
for (index, character) in s.enumerated() {
if index % 2 == 0 && character.isUppercase {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc countUpper(s: String) -> Int {
var count = 0
for (index, character) in s.enumerated() {
if index % 2 == 0 && character.isUppercase {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
Answer:
```swift
func countUpper(s: String) -> Int {
var count = 0
for (index, character) in s.enumerated() {
if index % 2 == 0 && character.isUppercase {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc countUpper(s: String) -> Int {
var count = 0
for (index, character) in s.enumerated() {
if index % 2 == 0 && character.isUppercase {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
Answer:
```swift
func countUpper(s: String) -> Int {
var count = 0
for (index, character) in s.enumerated() {
if index % 2 == 0 && character.isUppercase {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc closestInteger(value: String) -> Int {
let number = Double(value)!
let roundedNumber = round(number)
return Int(roundedNumber)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
Answer:
```swift
func closestInteger(value: String) -> Int {
let number = Double(value)!
let roundedNumber = round(number)
return Int(roundedNumber)
}
```func closestInteger(value: String) -> Int {
let number = Double(value)!
let roundedNumber = round(number)
return Int(roundedNumber)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
Answer:
```swift
func closestInteger(value: String) -> Int {
let number = Double(value)!
let roundedNumber = round(number)
return Int(roundedNumber)
}
```func closestInteger(value: String) -> Int {
let number = Double(value)!
let roundedNumber = round(number)
return Int(roundedNumber)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
Answer:
```swift
func closestInteger(value: String) -> Int {
let number = Double(value)!
let roundedNumber = round(number)
return Int(roundedNumber)
}
```func closestInteger(value: String) -> Int {
let number = Double(value)!
let roundedNumber = round(number)
return Int(roundedNumber)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
Answer:
```swift
func closestInteger(value: String) -> Int {
let number = Double(value)!
let roundedNumber = round(number)
return Int(roundedNumber)
}
```func closestInteger(value: String) -> Int {
let number = Double(value)!
let roundedNumber = round(number)
return Int(roundedNumber)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
Answer:
```swift
func closestInteger(value: String) -> Int {
let number = Double(value)!
let roundedNumber = round(number)
return Int(roundedNumber)
}
```func closestInteger(value: String) -> Int {
let number = Double(value)!
let roundedNumber = round(number)
return Int(roundedNumber)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
Answer:
```swift
func closestInteger(value: String) -> Int {
let number = Double(value)!
let roundedNumber = round(number)
return Int(roundedNumber)
}
```func closestInteger(value: String) -> Int {
let number = Double(value)!
let roundedNumber = round(number)
return Int(roundedNumber)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
Answer:
```swift
func closestInteger(value: String) -> Int {
let number = Double(value)!
let roundedNumber = round(number)
return Int(roundedNumber)
}
```func closestInteger(value: String) -> Int {
let number = Double(value)!
let roundedNumber = round(number)
return Int(roundedNumber)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
Answer:
```swift
func closestInteger(value: String) -> Int {
let number = Double(value)!
let roundedNumber = round(number)
return Int(roundedNumber)
}
```func closestInteger(value: String) -> Int {
let number = Double(value)!
let roundedNumber = round(number)
return Int(roundedNumber)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
Answer:
```swift
func closestInteger(value: String) -> Int {
let number = Double(value)!
let roundedNumber = round(number)
return Int(roundedNumber)
}
```func closestInteger(value: String) -> Int {
let number = Double(value)!
let roundedNumber = round(number)
return Int(roundedNumber)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
Answer:
```swift
func closestInteger(value: String) -> Int {
let number = Double(value)!
let roundedNumber = round(number)
return Int(roundedNumber)
}
```func makeAPile(n: Int) -> [Int] {
var result = [Int]()
var currentLevel = n
while currentLevel > 0 {
result.append(currentLevel)
currentLevel = (currentLevel % 2 == 0)? currentLevel + 2 : currentLevel + 4
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
Answer:
```swift
func makeAPile(n: Int) -> [Int] {
var result = [Int]()
var currentLevel = n
while currentLevel > 0 {
result.append(currentLevel)
currentLevel = (currentLevel % 2 == 0)? currentLevel + 2 : currentLevel + 4
}
return result
}
```currentLevel = (currentLevel % 2 == 0)? currentLevel + 2 : currentLevel + 4 // cannot use optional chaining on non-optional value of type 'Bool'currentLevel = (currentLevel % 2 == 0)? currentLevel + 2 : currentLevel + 4 // consecutive statements on a line must be separated by ';'currentLevel = (currentLevel % 2 == 0)? currentLevel + 2 : currentLevel + 4 // expected expressioncurrentLevel = (currentLevel % 2 == 0)? currentLevel + 2 : currentLevel + 4 // consecutive statements on a line must be separated by ';'currentLevel = (currentLevel % 2 == 0)? currentLevel + 2 : currentLevel + 4 // result of operator '+' is unusedcurrentLevel = (currentLevel % 2 == 0)? currentLevel + 2 : currentLevel + 4 // cannot assign value of type 'Bool?' to type 'Int'func makeAPile(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 0 {
result.append(current)
current = (current + 1) % 2 == 0? current / 2 : (current + 1) / 2
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
Answer:
```swift
func makeAPile(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 0 {
result.append(current)
current = (current + 1) % 2 == 0? current / 2 : (current + 1) / 2
}
return result
}
```current = (current + 1) % 2 == 0? current / 2 : (current + 1) / 2 // cannot assign value of type 'Bool' to type 'Int'current = (current + 1) % 2 == 0? current / 2 : (current + 1) / 2 // cannot use optional chaining on non-optional value of type 'Int'current = (current + 1) % 2 == 0? current / 2 : (current + 1) / 2 // result of operator '/' is unusedcurrent = (current + 1) % 2 == 0? current / 2 : (current + 1) / 2 // consecutive statements on a line must be separated by ';'current = (current + 1) % 2 == 0? current / 2 : (current + 1) / 2 // consecutive statements on a line must be separated by ';'current = (current + 1) % 2 == 0? current / 2 : (current + 1) / 2 // expected expressionfunc makeAPile(n: Int) -> [Int] {
var stones = [Int]()
var current = n
while current > 0 {
stones.append(current)
current = (current + 1) % 2 == 0? current / 2 : (current + 1)
}
return stones
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
Answer:
```swift
func makeAPile(n: Int) -> [Int] {
var stones = [Int]()
var current = n
while current > 0 {
stones.append(current)
current = (current + 1) % 2 == 0? current / 2 : (current + 1)
}
return stones
}
```current = (current + 1) % 2 == 0? current / 2 : (current + 1) // cannot use optional chaining on non-optional value of type 'Int'current = (current + 1) % 2 == 0? current / 2 : (current + 1) // result of operator '/' is unusedcurrent = (current + 1) % 2 == 0? current / 2 : (current + 1) // consecutive statements on a line must be separated by ';'current = (current + 1) % 2 == 0? current / 2 : (current + 1) // cannot assign value of type 'Bool' to type 'Int'current = (current + 1) % 2 == 0? current / 2 : (current + 1) // consecutive statements on a line must be separated by ';'current = (current + 1) % 2 == 0? current / 2 : (current + 1) // expected expressionfunc makeAPile(n: Int) -> [Int] {
var stones = [Int]()
var currentLevel = n
while currentLevel > 0 {
stones.append(currentLevel)
currentLevel = (currentLevel % 2 == 0)? currentLevel + 1 : currentLevel + 2
}
return stones
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
Answer:
```swift
func makeAPile(n: Int) -> [Int] {
var stones = [Int]()
var currentLevel = n
while currentLevel > 0 {
stones.append(currentLevel)
currentLevel = (currentLevel % 2 == 0)? currentLevel + 1 : currentLevel + 2
}
return stones
}
```currentLevel = (currentLevel % 2 == 0)? currentLevel + 1 : currentLevel + 2 // cannot assign value of type 'Bool?' to type 'Int'currentLevel = (currentLevel % 2 == 0)? currentLevel + 1 : currentLevel + 2 // consecutive statements on a line must be separated by ';'currentLevel = (currentLevel % 2 == 0)? currentLevel + 1 : currentLevel + 2 // expected expressioncurrentLevel = (currentLevel % 2 == 0)? currentLevel + 1 : currentLevel + 2 // consecutive statements on a line must be separated by ';'currentLevel = (currentLevel % 2 == 0)? currentLevel + 1 : currentLevel + 2 // cannot use optional chaining on non-optional value of type 'Bool'currentLevel = (currentLevel % 2 == 0)? currentLevel + 1 : currentLevel + 2 // result of operator '+' is unusedfunc makeAPile(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 0 {
result.append(current)
current = (current % 2 == 0)? current + 1 : current + 2
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
Answer:
```swift
func makeAPile(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 0 {
result.append(current)
current = (current % 2 == 0)? current + 1 : current + 2
}
return result
}
```current = (current % 2 == 0)? current + 1 : current + 2 // consecutive statements on a line must be separated by ';'current = (current % 2 == 0)? current + 1 : current + 2 // result of operator '+' is unusedcurrent = (current % 2 == 0)? current + 1 : current + 2 // cannot use optional chaining on non-optional value of type 'Bool'current = (current % 2 == 0)? current + 1 : current + 2 // cannot assign value of type 'Bool?' to type 'Int'current = (current % 2 == 0)? current + 1 : current + 2 // consecutive statements on a line must be separated by ';'current = (current % 2 == 0)? current + 1 : current + 2 // expected expressionfunc makeAPile(n: Int) -> [Int] {
var stones = [Int]()
var currentLevel = n
while currentLevel > 0 {
stones.append(currentLevel)
currentLevel = (currentLevel % 2 == 0)? currentLevel + 1 : currentLevel + 2
}
return stones
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
Answer:
```swift
func makeAPile(n: Int) -> [Int] {
var stones = [Int]()
var currentLevel = n
while currentLevel > 0 {
stones.append(currentLevel)
currentLevel = (currentLevel % 2 == 0)? currentLevel + 1 : currentLevel + 2
}
return stones
}
```currentLevel = (currentLevel % 2 == 0)? currentLevel + 1 : currentLevel + 2 // cannot assign value of type 'Bool?' to type 'Int'currentLevel = (currentLevel % 2 == 0)? currentLevel + 1 : currentLevel + 2 // consecutive statements on a line must be separated by ';'currentLevel = (currentLevel % 2 == 0)? currentLevel + 1 : currentLevel + 2 // expected expressioncurrentLevel = (currentLevel % 2 == 0)? currentLevel + 1 : currentLevel + 2 // consecutive statements on a line must be separated by ';'currentLevel = (currentLevel % 2 == 0)? currentLevel + 1 : currentLevel + 2 // cannot use optional chaining on non-optional value of type 'Bool'currentLevel = (currentLevel % 2 == 0)? currentLevel + 1 : currentLevel + 2 // result of operator '+' is unusedfunc makeAPile(n: Int) -> [Int] {
var stones = [Int]()
var current = n
while current > 0 {
stones.append(current)
current = (current + 1) % 2 == 0? current / 2 : (current + 1) / 2
}
return stones
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
Answer:
```swift
func makeAPile(n: Int) -> [Int] {
var stones = [Int]()
var current = n
while current > 0 {
stones.append(current)
current = (current + 1) % 2 == 0? current / 2 : (current + 1) / 2
}
return stones
}
```current = (current + 1) % 2 == 0? current / 2 : (current + 1) / 2 // cannot assign value of type 'Bool' to type 'Int'current = (current + 1) % 2 == 0? current / 2 : (current + 1) / 2 // cannot use optional chaining on non-optional value of type 'Int'current = (current + 1) % 2 == 0? current / 2 : (current + 1) / 2 // result of operator '/' is unusedcurrent = (current + 1) % 2 == 0? current / 2 : (current + 1) / 2 // consecutive statements on a line must be separated by ';'current = (current + 1) % 2 == 0? current / 2 : (current + 1) / 2 // consecutive statements on a line must be separated by ';'current = (current + 1) % 2 == 0? current / 2 : (current + 1) / 2 // expected expressionfunc makeAPile(n: Int) -> [Int] {
var stones = [Int]()
var currentLevel = n
while currentLevel > 0 {
stones.append(currentLevel)
currentLevel = (currentLevel % 2 == 0)? currentLevel + 1 : currentLevel + 2
}
return stones
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
Answer:
```swift
func makeAPile(n: Int) -> [Int] {
var stones = [Int]()
var currentLevel = n
while currentLevel > 0 {
stones.append(currentLevel)
currentLevel = (currentLevel % 2 == 0)? currentLevel + 1 : currentLevel + 2
}
return stones
}
```currentLevel = (currentLevel % 2 == 0)? currentLevel + 1 : currentLevel + 2 // cannot assign value of type 'Bool?' to type 'Int'currentLevel = (currentLevel % 2 == 0)? currentLevel + 1 : currentLevel + 2 // consecutive statements on a line must be separated by ';'currentLevel = (currentLevel % 2 == 0)? currentLevel + 1 : currentLevel + 2 // expected expressioncurrentLevel = (currentLevel % 2 == 0)? currentLevel + 1 : currentLevel + 2 // consecutive statements on a line must be separated by ';'currentLevel = (currentLevel % 2 == 0)? currentLevel + 1 : currentLevel + 2 // cannot use optional chaining on non-optional value of type 'Bool'currentLevel = (currentLevel % 2 == 0)? currentLevel + 1 : currentLevel + 2 // result of operator '+' is unusedfunc makeAPile(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 0 {
result.append(current)
current = (current + 1) % 2 == 0? current / 2 : (current + 1) / 2
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
Answer:
```swift
func makeAPile(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 0 {
result.append(current)
current = (current + 1) % 2 == 0? current / 2 : (current + 1) / 2
}
return result
}
```current = (current + 1) % 2 == 0? current / 2 : (current + 1) / 2 // cannot assign value of type 'Bool' to type 'Int'current = (current + 1) % 2 == 0? current / 2 : (current + 1) / 2 // cannot use optional chaining on non-optional value of type 'Int'current = (current + 1) % 2 == 0? current / 2 : (current + 1) / 2 // result of operator '/' is unusedcurrent = (current + 1) % 2 == 0? current / 2 : (current + 1) / 2 // consecutive statements on a line must be separated by ';'current = (current + 1) % 2 == 0? current / 2 : (current + 1) / 2 // consecutive statements on a line must be separated by ';'current = (current + 1) % 2 == 0? current / 2 : (current + 1) / 2 // expected expressionfunc makeAPile(n: Int) -> [Int] {
var stones = [Int]()
var current = n
while current > 0 {
stones.append(current)
current = (current + 1) % 2 == 0? current / 2 : (current + 1)
}
return stones
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
Answer:
```swift
func makeAPile(n: Int) -> [Int] {
var stones = [Int]()
var current = n
while current > 0 {
stones.append(current)
current = (current + 1) % 2 == 0? current / 2 : (current + 1)
}
return stones
}
```current = (current + 1) % 2 == 0? current / 2 : (current + 1) // cannot use optional chaining on non-optional value of type 'Int'current = (current + 1) % 2 == 0? current / 2 : (current + 1) // result of operator '/' is unusedcurrent = (current + 1) % 2 == 0? current / 2 : (current + 1) // consecutive statements on a line must be separated by ';'current = (current + 1) % 2 == 0? current / 2 : (current + 1) // cannot assign value of type 'Bool' to type 'Int'current = (current + 1) % 2 == 0? current / 2 : (current + 1) // consecutive statements on a line must be separated by ';'current = (current + 1) % 2 == 0? current / 2 : (current + 1) // expected expressionfunc wordsString(s: String) -> [String] {
let words = s.components(separatedBy: ", ")
return words
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
Answer:
```swift
func wordsString(s: String) -> [String] {
let words = s.components(separatedBy: ", ")
return words
}
``` // XCTAssertTrue failedfunc wordsString(s: String) -> [String] {
let words = s.components(separatedBy: ", ")
return words
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
Answer:
```swift
func wordsString(s: String) -> [String] {
let words = s.components(separatedBy: ", ")
return words
}
``` // XCTAssertTrue failedfunc wordsString(s: String) -> [String] {
let words = s.components(separatedBy: ", ")
return words
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
Answer:
```swift
func wordsString(s: String) -> [String] {
let words = s.components(separatedBy: ", ")
return words
}
``` // XCTAssertTrue failedfunc wordsString(s: String) -> [String] {
return s.components(separatedBy: ", ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
Answer:
```swift
func wordsString(s: String) -> [String] {
return s.components(separatedBy: ", ")
}
``` // XCTAssertTrue failedfunc wordsString(s: String) -> [String] {
let words = s.components(separatedBy: ", ")
return words
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
Answer:
```swift
func wordsString(s: String) -> [String] {
let words = s.components(separatedBy: ", ")
return words
}
``` // XCTAssertTrue failedfunc wordsString(s: String) -> [String] {
return s.components(separatedBy: ", ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
Answer:
```swift
func wordsString(s: String) -> [String] {
return s.components(separatedBy: ", ")
}
``` // XCTAssertTrue failedfunc wordsString(s: String) -> [String] {
return s.components(separatedBy:.whitespacesAndNewlines)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
Answer:
```swift
func wordsString(s: String) -> [String] {
return s.components(separatedBy:.whitespacesAndNewlines)
}
``` // XCTAssertTrue failedfunc wordsString(s: String) -> [String] {
let words = s.components(separatedBy: ", ")
return words
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
Answer:
```swift
func wordsString(s: String) -> [String] {
let words = s.components(separatedBy: ", ")
return words
}
``` // XCTAssertTrue failedfunc wordsString(s: String) -> [String] {
let words = s.components(separatedBy: ", ")
return words
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
Answer:
```swift
func wordsString(s: String) -> [String] {
let words = s.components(separatedBy: ", ")
return words
}
``` // XCTAssertTrue failedfunc wordsString(s: String) -> [String] {
let words = s.components(separatedBy: ", ")
return words
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
Answer:
```swift
func wordsString(s: String) -> [String] {
let words = s.components(separatedBy: ", ")
return words
}
``` // XCTAssertTrue failedfunc chooseNum(x: Int, y: Int) -> Int {
guard x > 0, y > 0 else {
return -1
}
let min = min(x, y)
let max = max(x, y)
for i in min...max {
if i % 2 == 0 {
return i
}
}
return -1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
Answer:
```swift
func chooseNum(x: Int, y: Int) -> Int {
guard x > 0, y > 0 else {
return -1
}
let min = min(x, y)
let max = max(x, y)
for i in min...max {
if i % 2 == 0 {
return i
}
}
return -1
}
``` // XCTAssertTrue failedfunc chooseNum(x: Int, y: Int) -> Int {
guard x > 0 && y > 0 else {
return -1
}
for i in x...y {
if i % 2 == 0 {
return i
}
}
return -1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
Answer:
```swift
func chooseNum(x: Int, y: Int) -> Int {
guard x > 0 && y > 0 else {
return -1
}
for i in x...y {
if i % 2 == 0 {
return i
}
}
return -1
}
``` // XCTAssertTrue failedfunc chooseNum(x: Int, y: Int) -> Int {
guard x > 0, y > 0 else {
return -1
}
for i in x...y {
if i % 2 == 0 {
return i
}
}
return -1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
Answer:
```swift
func chooseNum(x: Int, y: Int) -> Int {
guard x > 0, y > 0 else {
return -1
}
for i in x...y {
if i % 2 == 0 {
return i
}
}
return -1
}
``` // XCTAssertTrue failedfunc chooseNum(x: Int, y: Int) -> Int {
guard x > 0, y > 0 else {
return -1
}
let min = min(x, y)
let max = max(x, y)
for i in min...max {
if i % 2 == 0 {
return i
}
}
return -1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
Answer:
```swift
func chooseNum(x: Int, y: Int) -> Int {
guard x > 0, y > 0 else {
return -1
}
let min = min(x, y)
let max = max(x, y)
for i in min...max {
if i % 2 == 0 {
return i
}
}
return -1
}
``` // XCTAssertTrue failedfunc chooseNum(x: Int, y: Int) -> Int {
guard x > 0, y > 0 else {
return -1
}
for i in x...y {
if i % 2 == 0 {
return i
}
}
return -1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
Answer:
```swift
func chooseNum(x: Int, y: Int) -> Int {
guard x > 0, y > 0 else {
return -1
}
for i in x...y {
if i % 2 == 0 {
return i
}
}
return -1
}
``` // XCTAssertTrue failedfunc chooseNum(x: Int, y: Int) -> Int {
guard x > 0 && y > 0 else {
return -1
}
let min = min(x, y)
let max = max(x, y)
for i in min...max {
if i % 2 == 0 {
return i
}
}
return -1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
Answer:
```swift
func chooseNum(x: Int, y: Int) -> Int {
guard x > 0 && y > 0 else {
return -1
}
let min = min(x, y)
let max = max(x, y)
for i in min...max {
if i % 2 == 0 {
return i
}
}
return -1
}
``` // XCTAssertTrue failedfunc chooseNum(x: Int, y: Int) -> Int {
if x % 2 == 0 && y % 2 == 0 {
return max(x, y)
}
return -1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
Answer:
```swift
func chooseNum(x: Int, y: Int) -> Int {
if x % 2 == 0 && y % 2 == 0 {
return max(x, y)
}
return -1
}
``` // XCTAssertTrue failedfunc chooseNum(x: Int, y: Int) -> Int {
guard x > 0 && y > 0 else {
return -1
}
var result = 0
for i in x...y {
if i % 2 == 0 {
result = i
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
Answer:
```swift
func chooseNum(x: Int, y: Int) -> Int {
guard x > 0 && y > 0 else {
return -1
}
var result = 0
for i in x...y {
if i % 2 == 0 {
result = i
}
}
return result
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc chooseNum(x: Int, y: Int) -> Int {
guard x > 0, y > 0 else {
return -1
}
for i in stride(from: x, to: y, by: 2) {
return i
}
return -1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
Answer:
```swift
func chooseNum(x: Int, y: Int) -> Int {
guard x > 0, y > 0 else {
return -1
}
for i in stride(from: x, to: y, by: 2) {
return i
}
return -1
}
``` // XCTAssertTrue failedfunc chooseNum(x: Int, y: Int) -> Int {
guard x > 0, y > 0 else {
return -1
}
for i in stride(from: x, to: y, by: 2) {
return i
}
return -1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
Answer:
```swift
func chooseNum(x: Int, y: Int) -> Int {
guard x > 0, y > 0 else {
return -1
}
for i in stride(from: x, to: y, by: 2) {
return i
}
return -1
}
``` // XCTAssertTrue failedextension Int: Error {
}
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return.failure(-1)
}
let sum = (n + m) / 2
let binary = String(format: "%08b", sum)
return.success(binary)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) ==.success("0b11")
roundedAvg(n: 7, m: 5) ==.failure(-1)
roundedAvg(n: 10, m: 20) ==.success("0b1111")
roundedAvg(n: 20, m: 33) ==.success("0b11010")
Answer:
```swift
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return.failure(-1)
}
let sum = (n + m) / 2
let binary = String(format: "%08b", sum)
return.success(binary)
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'extension Int: Error {
}
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return.failure(-1)
}
let sum = (n + m) / 2
let roundedSum = round(Double(sum))
let binarySum = String(roundedSum, radix: 2)
return.success(binarySum)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) ==.success("0b11")
roundedAvg(n: 7, m: 5) ==.failure(-1)
roundedAvg(n: 10, m: 20) ==.success("0b1111")
roundedAvg(n: 20, m: 33) ==.success("0b11010")
Answer:
```swift
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return.failure(-1)
}
let sum = (n + m) / 2
let roundedSum = round(Double(sum))
let binarySum = String(roundedSum, radix: 2)
return.success(binarySum)
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'let binarySum = String(roundedSum, radix: 2) // initializer 'init(_:radix:uppercase:)' requires that 'Double' conform to 'BinaryInteger'extension Int: Error {
}
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return.failure(-1)
}
let sum = (n + m) * 0.5
let roundedSum = round(sum)
let binarySum = String(roundedSum, radix: 2)
return.success(binarySum)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) ==.success("0b11")
roundedAvg(n: 7, m: 5) ==.failure(-1)
roundedAvg(n: 10, m: 20) ==.success("0b1111")
roundedAvg(n: 20, m: 33) ==.success("0b11010")
Answer:
```swift
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return.failure(-1)
}
let sum = (n + m) * 0.5
let roundedSum = round(sum)
let binarySum = String(roundedSum, radix: 2)
return.success(binarySum)
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'let sum = (n + m) * 0.5 // binary operator '*' cannot be applied to operands of type 'Int' and 'Double'extension Int: Error {
}
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return.failure(-1)
}
let sum = (n + m) * 0.5
let roundedSum = round(sum)
let binarySum = String(roundedSum, radix: 2)
return.success(binarySum)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) ==.success("0b11")
roundedAvg(n: 7, m: 5) ==.failure(-1)
roundedAvg(n: 10, m: 20) ==.success("0b1111")
roundedAvg(n: 20, m: 33) ==.success("0b11010")
Answer:
```swift
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return.failure(-1)
}
let sum = (n + m) * 0.5
let roundedSum = round(sum)
let binarySum = String(roundedSum, radix: 2)
return.success(binarySum)
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'let sum = (n + m) * 0.5 // binary operator '*' cannot be applied to operands of type 'Int' and 'Double'extension Int: Error {
}
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return.failure(-1)
}
let avg = (n + m) / 2
let binary = String(avg, radix: 2)
return.success(binary)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) ==.success("0b11")
roundedAvg(n: 7, m: 5) ==.failure(-1)
roundedAvg(n: 10, m: 20) ==.success("0b1111")
roundedAvg(n: 20, m: 33) ==.success("0b11010")
Answer:
```swift
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return.failure(-1)
}
let avg = (n + m) / 2
let binary = String(avg, radix: 2)
return.success(binary)
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'extension Int: Error {
}
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return.failure(-1)
}
let sum = (n + m) / 2
let binary = String(format: "%08b", sum)
return.success(binary)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) ==.success("0b11")
roundedAvg(n: 7, m: 5) ==.failure(-1)
roundedAvg(n: 10, m: 20) ==.success("0b1111")
roundedAvg(n: 20, m: 33) ==.success("0b11010")
Answer:
```swift
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return.failure(-1)
}
let sum = (n + m) / 2
let binary = String(format: "%08b", sum)
return.success(binary)
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'extension Int: Error {
}
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return.failure(-1)
}
let avg = (n + m) / 2
let binary = String(avg, radix: 2)
return.success(binary)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) ==.success("0b11")
roundedAvg(n: 7, m: 5) ==.failure(-1)
roundedAvg(n: 10, m: 20) ==.success("0b1111")
roundedAvg(n: 20, m: 33) ==.success("0b11010")
Answer:
```swift
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return.failure(-1)
}
let avg = (n + m) / 2
let binary = String(avg, radix: 2)
return.success(binary)
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'extension Int: Error {
}
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return.failure(-1)
}
let sum = (n + m) * 0.5
let roundedSum = round(sum)
let binarySum = String(roundedSum, radix: 2)
return.success(binarySum)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) ==.success("0b11")
roundedAvg(n: 7, m: 5) ==.failure(-1)
roundedAvg(n: 10, m: 20) ==.success("0b1111")
roundedAvg(n: 20, m: 33) ==.success("0b11010")
Answer:
```swift
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return.failure(-1)
}
let sum = (n + m) * 0.5
let roundedSum = round(sum)
let binarySum = String(roundedSum, radix: 2)
return.success(binarySum)
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'let sum = (n + m) * 0.5 // binary operator '*' cannot be applied to operands of type 'Int' and 'Double'extension Int: Error {
}
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return.failure(-1)
}
let avg = (n + m) / 2
let binary = String(avg, radix: 2)
return.success(binary)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) ==.success("0b11")
roundedAvg(n: 7, m: 5) ==.failure(-1)
roundedAvg(n: 10, m: 20) ==.success("0b1111")
roundedAvg(n: 20, m: 33) ==.success("0b11010")
Answer:
```swift
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return.failure(-1)
}
let avg = (n + m) / 2
let binary = String(avg, radix: 2)
return.success(binary)
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'extension Int: Error {
}
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return.failure(-1)
}
let sum = (n + m) * 0.5
let roundedSum = round(sum)
let binarySum = String(roundedSum, radix: 2)
return.success(binarySum)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) ==.success("0b11")
roundedAvg(n: 7, m: 5) ==.failure(-1)
roundedAvg(n: 10, m: 20) ==.success("0b1111")
roundedAvg(n: 20, m: 33) ==.success("0b11010")
Answer:
```swift
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return.failure(-1)
}
let sum = (n + m) * 0.5
let roundedSum = round(sum)
let binarySum = String(roundedSum, radix: 2)
return.success(binarySum)
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'let sum = (n + m) * 0.5 // binary operator '*' cannot be applied to operands of type 'Int' and 'Double'func uniqueDigits(x: [Int]) -> [Int] {
var result = [Int]()
for num in x {
let numString = String(num)
let hasEvenDigit = numString.contains { $0.description.contains("2") || $0.description.contains("4") || $0.description.contains("6") || $0.description.contains("8") }
if!hasEvenDigit {
result.append(num)
}
}
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
Answer:
```swift
func uniqueDigits(x: [Int]) -> [Int] {
var result = [Int]()
for num in x {
let numString = String(num)
let hasEvenDigit = numString.contains { $0.description.contains("2") || $0.description.contains("4") || $0.description.contains("6") || $0.description.contains("8") }
if!hasEvenDigit {
result.append(num)
}
}
return result.sorted()
}
```if!hasEvenDigit { // expected expression, var, or let in 'if' conditionfunc uniqueDigits(x: [Int]) -> [Int] {
var result = [Int]()
for num in x {
let numString = String(num)
let hasEvenDigit = numString.contains { $0.description.contains("2") || $0.description.contains("4") || $0.description.contains("6") || $0.description.contains("8") }
if!hasEvenDigit {
result.append(num)
}
}
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
Answer:
```swift
func uniqueDigits(x: [Int]) -> [Int] {
var result = [Int]()
for num in x {
let numString = String(num)
let hasEvenDigit = numString.contains { $0.description.contains("2") || $0.description.contains("4") || $0.description.contains("6") || $0.description.contains("8") }
if!hasEvenDigit {
result.append(num)
}
}
return result.sorted()
}
```if!hasEvenDigit { // expected expression, var, or let in 'if' conditionfunc uniqueDigits(x: [Int]) -> [Int] {
var result = [Int]()
for num in x {
let numString = String(num)
let hasEvenDigit = numString.contains { $0.description.contains("2") || $0.description.contains("4") || $0.description.contains("6") || $0.description.contains("8") }
if!hasEvenDigit {
result.append(num)
}
}
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
Answer:
```swift
func uniqueDigits(x: [Int]) -> [Int] {
var result = [Int]()
for num in x {
let numString = String(num)
let hasEvenDigit = numString.contains { $0.description.contains("2") || $0.description.contains("4") || $0.description.contains("6") || $0.description.contains("8") }
if!hasEvenDigit {
result.append(num)
}
}
return result.sorted()
}
```if!hasEvenDigit { // expected expression, var, or let in 'if' conditionfunc uniqueDigits(x: [Int]) -> [Int] {
var result = [Int]()
for num in x {
let numString = String(num)
let hasEvenDigit = numString.contains { String($0).contains("2") || String($0).contains("4") || String($0).contains("6") || String($0).contains("8") }
if!hasEvenDigit {
result.append(num)
}
}
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
Answer:
```swift
func uniqueDigits(x: [Int]) -> [Int] {
var result = [Int]()
for num in x {
let numString = String(num)
let hasEvenDigit = numString.contains { String($0).contains("2") || String($0).contains("4") || String($0).contains("6") || String($0).contains("8") }
if!hasEvenDigit {
result.append(num)
}
}
return result.sorted()
}
```if!hasEvenDigit { // expected expression, var, or let in 'if' conditionfunc uniqueDigits(x: [Int]) -> [Int] {
var result = [Int]()
for num in x {
let numString = String(num)
let hasEvenDigit = numString.contains { $0.description.contains("2") || $0.description.contains("4") || $0.description.contains("6") || $0.description.contains("8") }
if!hasEvenDigit {
result.append(num)
}
}
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
Answer:
```swift
func uniqueDigits(x: [Int]) -> [Int] {
var result = [Int]()
for num in x {
let numString = String(num)
let hasEvenDigit = numString.contains { $0.description.contains("2") || $0.description.contains("4") || $0.description.contains("6") || $0.description.contains("8") }
if!hasEvenDigit {
result.append(num)
}
}
return result.sorted()
}
```if!hasEvenDigit { // expected expression, var, or let in 'if' conditionfunc uniqueDigits(x: [Int]) -> [Int] {
var result = [Int]()
let xString = String(x.reduce(0, +))
let xChars = Array(xString)
for char in xChars {
if let int = Int(String(char)) {
if int % 2!= 0 {
result.append(int)
}
}
}
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
Answer:
```swift
func uniqueDigits(x: [Int]) -> [Int] {
var result = [Int]()
let xString = String(x.reduce(0, +))
let xChars = Array(xString)
for char in xChars {
if let int = Int(String(char)) {
if int % 2!= 0 {
result.append(int)
}
}
}
return result.sorted()
}
```if int % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'if int % 2!= 0 { // '=' must have consistent whitespace on both sidesif int % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if int % 2!= 0 { // expression is not assignable: binary operator returns immutable valuefunc uniqueDigits(x: [Int]) -> [Int] {
var result = [Int]()
let numbers = x.sorted()
for number in numbers {
let numberString = String(number)
let hasEvenDigit = numberString.contains { $0.description.contains("2") || $0.description.contains("4") || $0.description.contains("6") || $0.description.contains("8") }
if!hasEvenDigit {
result.append(number)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
Answer:
```swift
func uniqueDigits(x: [Int]) -> [Int] {
var result = [Int]()
let numbers = x.sorted()
for number in numbers {
let numberString = String(number)
let hasEvenDigit = numberString.contains { $0.description.contains("2") || $0.description.contains("4") || $0.description.contains("6") || $0.description.contains("8") }
if!hasEvenDigit {
result.append(number)
}
}
return result
}
```if!hasEvenDigit { // expected expression, var, or let in 'if' conditionfunc uniqueDigits(x: [Int]) -> [Int] {
var result = [Int]()
for num in x {
let numString = String(num)
let hasEvenDigit = numString.contains { $0.description.contains("2") || $0.description.contains("4") || $0.description.contains("6") || $0.description.contains("8") }
if!hasEvenDigit {
result.append(num)
}
}
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
Answer:
```swift
func uniqueDigits(x: [Int]) -> [Int] {
var result = [Int]()
for num in x {
let numString = String(num)
let hasEvenDigit = numString.contains { $0.description.contains("2") || $0.description.contains("4") || $0.description.contains("6") || $0.description.contains("8") }
if!hasEvenDigit {
result.append(num)
}
}
return result.sorted()
}
```if!hasEvenDigit { // expected expression, var, or let in 'if' conditionfunc uniqueDigits(x: [Int]) -> [Int] {
var result = [Int]()
let string = String(x.reduce(0) { $0 + $1 })
let array = Array(string.characters)
for digit in array {
if digit.description.contains("2") || digit.description.contains("4") || digit.description.contains("6") || digit.description.contains("8") {
continue
}
result.append(digit)
}
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
Answer:
```swift
func uniqueDigits(x: [Int]) -> [Int] {
var result = [Int]()
let string = String(x.reduce(0) { $0 + $1 })
let array = Array(string.characters)
for digit in array {
if digit.description.contains("2") || digit.description.contains("4") || digit.description.contains("6") || digit.description.contains("8") {
continue
}
result.append(digit)
}
return result.sorted()
}
```let array = Array(string.characters) // 'characters' is unavailable: Please use String directlyresult.append(digit) // cannot convert value of type 'String.Element' (aka 'Character') to expected argument type 'Int'func uniqueDigits(x: [Int]) -> [Int] {
var result = [Int]()
for num in x {
let numString = String(num)
let hasEvenDigit = numString.contains { $0.description.contains("2") || $0.description.contains("4") || $0.description.contains("6") || $0.description.contains("8") }
if!hasEvenDigit {
result.append(num)
}
}
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
Answer:
```swift
func uniqueDigits(x: [Int]) -> [Int] {
var result = [Int]()
for num in x {
let numString = String(num)
let hasEvenDigit = numString.contains { $0.description.contains("2") || $0.description.contains("4") || $0.description.contains("6") || $0.description.contains("8") }
if!hasEvenDigit {
result.append(num)
}
}
return result.sorted()
}
```if!hasEvenDigit { // expected expression, var, or let in 'if' conditionfunc byLength(arr: [Int]) -> [String] {
let numbers = arr.filter { $0 in 1...9 }
let sortedNumbers = numbers.sorted()
let reversedNumbers = sortedNumbers.reversed()
let names = reversedNumbers.map {
switch $0 {
case 1: return "One"
case 2: return "Two"
case 3: return "Three"
case 4: return "Four"
case 5: return "Five"
case 6: return "Six"
case 7: return "Seven"
case 8: return "Eight"
case 9: return "Nine"
default: return ""
}
}
return names
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
Answer:
```swift
func byLength(arr: [Int]) -> [String] {
let numbers = arr.filter { $0 in 1...9 }
let sortedNumbers = numbers.sorted()
let reversedNumbers = sortedNumbers.reversed()
let names = reversedNumbers.map {
switch $0 {
case 1: return "One"
case 2: return "Two"
case 3: return "Three"
case 4: return "Four"
case 5: return "Five"
case 6: return "Six"
case 7: return "Seven"
case 8: return "Eight"
case 9: return "Nine"
default: return ""
}
}
return names
}
```let numbers = arr.filter { $0 in 1...9 } // consecutive statements on a line must be separated by ';'let numbers = arr.filter { $0 in 1...9 } // cannot convert value of type 'Int' to closure result type 'Bool'let numbers = arr.filter { $0 in 1...9 } // expected expressionfunc byLength(arr: [Int]) -> [String] {
let numbers = arr.filter { $0 in 1...9 }
let sortedNumbers = numbers.sorted()
let reversedNumbers = sortedNumbers.reversed()
let names = reversedNumbers.map {
switch $0 {
case 1: return "One"
case 2: return "Two"
case 3: return "Three"
case 4: return "Four"
case 5: return "Five"
case 6: return "Six"
case 7: return "Seven"
case 8: return "Eight"
case 9: return "Nine"
default: return ""
}
}
return names
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
Answer:
```swift
func byLength(arr: [Int]) -> [String] {
let numbers = arr.filter { $0 in 1...9 }
let sortedNumbers = numbers.sorted()
let reversedNumbers = sortedNumbers.reversed()
let names = reversedNumbers.map {
switch $0 {
case 1: return "One"
case 2: return "Two"
case 3: return "Three"
case 4: return "Four"
case 5: return "Five"
case 6: return "Six"
case 7: return "Seven"
case 8: return "Eight"
case 9: return "Nine"
default: return ""
}
}
return names
}
```let numbers = arr.filter { $0 in 1...9 } // consecutive statements on a line must be separated by ';'let numbers = arr.filter { $0 in 1...9 } // cannot convert value of type 'Int' to closure result type 'Bool'let numbers = arr.filter { $0 in 1...9 } // expected expressionfunc byLength(arr: [Int]) -> [String] {
let numbers = arr.filter { $0 in 1...9 }
let sortedNumbers = numbers.sorted()
let reversedNumbers = sortedNumbers.reversed()
let names = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
return reversedNumbers.map { names[$0 - 1] }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
Answer:
```swift
func byLength(arr: [Int]) -> [String] {
let numbers = arr.filter { $0 in 1...9 }
let sortedNumbers = numbers.sorted()
let reversedNumbers = sortedNumbers.reversed()
let names = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
return reversedNumbers.map { names[$0 - 1] }
}
```let numbers = arr.filter { $0 in 1...9 } // consecutive statements on a line must be separated by ';'let numbers = arr.filter { $0 in 1...9 } // cannot convert value of type 'Int' to closure result type 'Bool'let numbers = arr.filter { $0 in 1...9 } // expected expressionfunc byLength(arr: [Int]) -> [String] {
let numbers = arr.filter { $0 in 1...9 }
let sortedNumbers = numbers.sorted()
let reversedNumbers = sortedNumbers.reversed()
let names = reversedNumbers.map {
switch $0 {
case 1:
return "One"
case 2:
return "Two"
case 3:
return "Three"
case 4:
return "Four"
case 5:
return "Five"
case 6:
return "Six"
case 7:
return "Seven"
case 8:
return "Eight"
case 9:
return "Nine"
default:
return ""
}
}
return names
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
Answer:
```swift
func byLength(arr: [Int]) -> [String] {
let numbers = arr.filter { $0 in 1...9 }
let sortedNumbers = numbers.sorted()
let reversedNumbers = sortedNumbers.reversed()
let names = reversedNumbers.map {
switch $0 {
case 1:
return "One"
case 2:
return "Two"
case 3:
return "Three"
case 4:
return "Four"
case 5:
return "Five"
case 6:
return "Six"
case 7:
return "Seven"
case 8:
return "Eight"
case 9:
return "Nine"
default:
return ""
}
}
return names
}
```let numbers = arr.filter { $0 in 1...9 } // consecutive statements on a line must be separated by ';'let numbers = arr.filter { $0 in 1...9 } // cannot convert value of type 'Int' to closure result type 'Bool'let numbers = arr.filter { $0 in 1...9 } // expected expressionfunc byLength(arr: [Int]) -> [String] {
let numbers = arr.filter { $0 in 1...9 }
let sortedNumbers = numbers.sorted()
let reversedNumbers = sortedNumbers.reversed()
let names = reversedNumbers.map {
switch $0 {
case 1:
return "One"
case 2:
return "Two"
case 3:
return "Three"
case 4:
return "Four"
case 5:
return "Five"
case 6:
return "Six"
case 7:
return "Seven"
case 8:
return "Eight"
case 9:
return "Nine"
default:
return ""
}
}
return names
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
Answer:
```swift
func byLength(arr: [Int]) -> [String] {
let numbers = arr.filter { $0 in 1...9 }
let sortedNumbers = numbers.sorted()
let reversedNumbers = sortedNumbers.reversed()
let names = reversedNumbers.map {
switch $0 {
case 1:
return "One"
case 2:
return "Two"
case 3:
return "Three"
case 4:
return "Four"
case 5:
return "Five"
case 6:
return "Six"
case 7:
return "Seven"
case 8:
return "Eight"
case 9:
return "Nine"
default:
return ""
}
}
return names
}
```let numbers = arr.filter { $0 in 1...9 } // consecutive statements on a line must be separated by ';'let numbers = arr.filter { $0 in 1...9 } // cannot convert value of type 'Int' to closure result type 'Bool'let numbers = arr.filter { $0 in 1...9 } // expected expressionfunc byLength(arr: [Int]) -> [String] {
let numbers = arr.filter { $0 in 1...9 }
let sortedNumbers = numbers.sorted()
let reversedNumbers = sortedNumbers.reversed()
let names = reversedNumbers.map { number in
switch number {
case 1: return "One"
case 2: return "Two"
case 3: return "Three"
case 4: return "Four"
case 5: return "Five"
case 6: return "Six"
case 7: return "Seven"
case 8: return "Eight"
case 9: return "Nine"
default: return ""
}
}
return names
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
Answer:
```swift
func byLength(arr: [Int]) -> [String] {
let numbers = arr.filter { $0 in 1...9 }
let sortedNumbers = numbers.sorted()
let reversedNumbers = sortedNumbers.reversed()
let names = reversedNumbers.map { number in
switch number {
case 1: return "One"
case 2: return "Two"
case 3: return "Three"
case 4: return "Four"
case 5: return "Five"
case 6: return "Six"
case 7: return "Seven"
case 8: return "Eight"
case 9: return "Nine"
default: return ""
}
}
return names
}
```let numbers = arr.filter { $0 in 1...9 } // consecutive statements on a line must be separated by ';'let numbers = arr.filter { $0 in 1...9 } // cannot convert value of type 'Int' to closure result type 'Bool'let numbers = arr.filter { $0 in 1...9 } // expected expressionfunc byLength(arr: [Int]) -> [String] {
let numbers = arr.filter { $0 in 1...9 }
let sortedNumbers = numbers.sorted()
let reversedNumbers = sortedNumbers.reversed()
let names = reversedNumbers.map {
switch $0 {
case 1:
return "One"
case 2:
return "Two"
case 3:
return "Three"
case 4:
return "Four"
case 5:
return "Five"
case 6:
return "Six"
case 7:
return "Seven"
case 8:
return "Eight"
case 9:
return "Nine"
default:
return ""
}
}
return names
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
Answer:
```swift
func byLength(arr: [Int]) -> [String] {
let numbers = arr.filter { $0 in 1...9 }
let sortedNumbers = numbers.sorted()
let reversedNumbers = sortedNumbers.reversed()
let names = reversedNumbers.map {
switch $0 {
case 1:
return "One"
case 2:
return "Two"
case 3:
return "Three"
case 4:
return "Four"
case 5:
return "Five"
case 6:
return "Six"
case 7:
return "Seven"
case 8:
return "Eight"
case 9:
return "Nine"
default:
return ""
}
}
return names
}
```let numbers = arr.filter { $0 in 1...9 } // consecutive statements on a line must be separated by ';'let numbers = arr.filter { $0 in 1...9 } // cannot convert value of type 'Int' to closure result type 'Bool'let numbers = arr.filter { $0 in 1...9 } // expected expressionfunc byLength(arr: [Int]) -> [String] {
let numbers = arr.filter { $0 in 1...9 }
let sortedNumbers = numbers.sorted()
let reversedNumbers = sortedNumbers.reversed()
let names = reversedNumbers.map { number in
switch number {
case 1:
return "One"
case 2:
return "Two"
case 3:
return "Three"
case 4:
return "Four"
case 5:
return "Five"
case 6:
return "Six"
case 7:
return "Seven"
case 8:
return "Eight"
case 9:
return "Nine"
default:
return ""
}
}
return names
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
Answer:
```swift
func byLength(arr: [Int]) -> [String] {
let numbers = arr.filter { $0 in 1...9 }
let sortedNumbers = numbers.sorted()
let reversedNumbers = sortedNumbers.reversed()
let names = reversedNumbers.map { number in
switch number {
case 1:
return "One"
case 2:
return "Two"
case 3:
return "Three"
case 4:
return "Four"
case 5:
return "Five"
case 6:
return "Six"
case 7:
return "Seven"
case 8:
return "Eight"
case 9:
return "Nine"
default:
return ""
}
}
return names
}
```let numbers = arr.filter { $0 in 1...9 } // consecutive statements on a line must be separated by ';'let numbers = arr.filter { $0 in 1...9 } // cannot convert value of type 'Int' to closure result type 'Bool'let numbers = arr.filter { $0 in 1...9 } // expected expressionfunc byLength(arr: [Int]) -> [String] {
let numbers = arr.filter { $0 in 1...9 }
let sortedNumbers = numbers.sorted()
let reversedNumbers = sortedNumbers.reversed()
let names = reversedNumbers.map { number in
switch number {
case 1: return "One"
case 2: return "Two"
case 3: return "Three"
case 4: return "Four"
case 5: return "Five"
case 6: return "Six"
case 7: return "Seven"
case 8: return "Eight"
case 9: return "Nine"
default: return ""
}
}
return names
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
Answer:
```swift
func byLength(arr: [Int]) -> [String] {
let numbers = arr.filter { $0 in 1...9 }
let sortedNumbers = numbers.sorted()
let reversedNumbers = sortedNumbers.reversed()
let names = reversedNumbers.map { number in
switch number {
case 1: return "One"
case 2: return "Two"
case 3: return "Three"
case 4: return "Four"
case 5: return "Five"
case 6: return "Six"
case 7: return "Seven"
case 8: return "Eight"
case 9: return "Nine"
default: return ""
}
}
return names
}
```let numbers = arr.filter { $0 in 1...9 } // consecutive statements on a line must be separated by ';'let numbers = arr.filter { $0 in 1...9 } // cannot convert value of type 'Int' to closure result type 'Bool'let numbers = arr.filter { $0 in 1...9 } // expected expressionfunc byLength(arr: [Int]) -> [String] {
let numbers = arr.filter { $0 in 1...9 }
let sortedNumbers = numbers.sorted()
let reversedNumbers = sortedNumbers.reversed()
let names = reversedNumbers.map { number in
switch number {
case 1:
return "One"
case 2:
return "Two"
case 3:
return "Three"
case 4:
return "Four"
case 5:
return "Five"
case 6:
return "Six"
case 7:
return "Seven"
case 8:
return "Eight"
case 9:
return "Nine"
default:
return ""
}
}
return names
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
Answer:
```swift
func byLength(arr: [Int]) -> [String] {
let numbers = arr.filter { $0 in 1...9 }
let sortedNumbers = numbers.sorted()
let reversedNumbers = sortedNumbers.reversed()
let names = reversedNumbers.map { number in
switch number {
case 1:
return "One"
case 2:
return "Two"
case 3:
return "Three"
case 4:
return "Four"
case 5:
return "Five"
case 6:
return "Six"
case 7:
return "Seven"
case 8:
return "Eight"
case 9:
return "Nine"
default:
return ""
}
}
return names
}
```let numbers = arr.filter { $0 in 1...9 } // consecutive statements on a line must be separated by ';'let numbers = arr.filter { $0 in 1...9 } // cannot convert value of type 'Int' to closure result type 'Bool'let numbers = arr.filter { $0 in 1...9 } // expected expressionfunc f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 0..<n {
if i % 2 == 0 {
result[i] = Int(factorial(Double(i)))
} else {
result[i] = 1..<i+1).reduce(0, +)
}
}
return result
}
func factorial(_ n: Double) -> Double {
var result = 1.0
for i in 1...Int(n) {
result *= Double(i)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 *... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
Answer:
```swift
func f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 0..<n {
if i % 2 == 0 {
result[i] = Int(factorial(Double(i)))
} else {
result[i] = 1..<i+1).reduce(0, +)
}
}
return result
}
func factorial(_ n: Double) -> Double {
var result = 1.0
for i in 1...Int(n) {
result *= Double(i)
}
return result
}
```result[i] = 1..<i+1).reduce(0, +) // cannot assign value of type 'Range<Int>' to subscript of type 'Int'result[i] = 1..<i+1).reduce(0, +) // consecutive statements on a line must be separated by ';'result[i] = 1..<i+1).reduce(0, +) // expected expressionfunc f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 0..<n {
if i % 2 == 0 {
result[i] = Int(factorial(Double(i)))
} else {
result[i] = Int(i * (i + 1) / 2)
}
}
return result
}
func factorial(_ n: Double) -> Double {
var result = 1.0
for i in 1...Int(n) {
result *= Double(i)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 *... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
Answer:
```swift
func f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 0..<n {
if i % 2 == 0 {
result[i] = Int(factorial(Double(i)))
} else {
result[i] = Int(i * (i + 1) / 2)
}
}
return result
}
func factorial(_ n: Double) -> Double {
var result = 1.0
for i in 1...Int(n) {
result *= Double(i)
}
return result
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 0..<n {
if i % 2 == 0 {
result[i] = Int(factorial(Double(i)))
} else {
result[i] = Int(sum(from: 1, to: i))
}
}
return result
}
func factorial(_ n: Double) -> Double {
var result = 1.0
for i in 1...n {
result *= Double(i)
}
return result
}
func sum(from start: Int, to end: Int) -> Int {
var result = 0
for i in start...end {
result += i
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 *... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
Answer:
```swift
func f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 0..<n {
if i % 2 == 0 {
result[i] = Int(factorial(Double(i)))
} else {
result[i] = Int(sum(from: 1, to: i))
}
}
return result
}
func factorial(_ n: Double) -> Double {
var result = 1.0
for i in 1...n {
result *= Double(i)
}
return result
}
func sum(from start: Int, to end: Int) -> Int {
var result = 0
for i in start...end {
result += i
}
return result
}
```for i in 1...n { // protocol 'Sequence' requires that 'Double.Stride' (aka 'Double') conform to 'SignedInteger'for i in 1...n { // referencing instance method 'next()' on 'ClosedRange' requires that 'Double.Stride' (aka 'Double') conform to 'SignedInteger'for i in 1...n { // referencing instance method 'makeIterator()' on 'ClosedRange' requires that 'Double.Stride' (aka 'Double') conform to 'SignedInteger'func f(n: Int) -> [Int] {
var result: [Int] = []
for i in 1...n {
if i % 2 == 0 {
result.append(Int(factorial(of: i)))
} else {
result.append(Int(sumOfNumbers(upTo: i)))
}
}
return result
}
func factorial(of n: Int) -> Int {
var result = 1
for i in 1...n {
result *= i
}
return result
}
func sumOfNumbers(upTo n: Int) -> Int {
return (n * (n + 1)) / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 *... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
Answer:
```swift
func f(n: Int) -> [Int] {
var result: [Int] = []
for i in 1...n {
if i % 2 == 0 {
result.append(Int(factorial(of: i)))
} else {
result.append(Int(sumOfNumbers(upTo: i)))
}
}
return result
}
func factorial(of n: Int) -> Int {
var result = 1
for i in 1...n {
result *= i
}
return result
}
func sumOfNumbers(upTo n: Int) -> Int {
return (n * (n + 1)) / 2
}
```func f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 0..<n {
if i % 2 == 0 {
result[i] = Int(factorial(Double(i)))
} else {
result[i] = 1..<i+1 |> reduce(0, +)
}
}
return result
}
func factorial(_ n: Double) -> Double {
var result = 1.0
for i in 1..<Int(n) {
result *= Double(i)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 *... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
Answer:
```swift
func f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 0..<n {
if i % 2 == 0 {
result[i] = Int(factorial(Double(i)))
} else {
result[i] = 1..<i+1 |> reduce(0, +)
}
}
return result
}
func factorial(_ n: Double) -> Double {
var result = 1.0
for i in 1..<Int(n) {
result *= Double(i)
}
return result
}
```result[i] = 1..<i+1 |> reduce(0, +) // cannot find 'reduce' in scoperesult[i] = 1..<i+1 |> reduce(0, +) // cannot find operator '|>' in scoperesult[i] = 1..<i+1 |> reduce(0, +) // cannot assign value of type 'Range<Int>' to subscript of type 'Int'func f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 0..<n {
if i % 2 == 0 {
result[i] = Int(factorial(Double(i)))
} else {
result[i] = 1..<i+1 |> reduce(0, +)
}
}
return result
}
func factorial(_ n: Double) -> Double {
return Double(1...Int(n)).reduce(1, *)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 *... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
Answer:
```swift
func f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 0..<n {
if i % 2 == 0 {
result[i] = Int(factorial(Double(i)))
} else {
result[i] = 1..<i+1 |> reduce(0, +)
}
}
return result
}
func factorial(_ n: Double) -> Double {
return Double(1...Int(n)).reduce(1, *)
}
```result[i] = 1..<i+1 |> reduce(0, +) // cannot find operator '|>' in scoperesult[i] = 1..<i+1 |> reduce(0, +) // cannot find 'reduce' in scoperesult[i] = 1..<i+1 |> reduce(0, +) // cannot assign value of type 'Range<Int>' to subscript of type 'Int'return Double(1...Int(n)).reduce(1, *) // no exact matches in call to initializerreturn Double(1...Int(n)).reduce(1, *) // reference to member 'reduce' cannot be resolved without a contextual typefunc f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 1...n {
if i % 2 == 0 {
result[i-1] = Int(factorial(Double(i)))
} else {
result[i-1] = Int(sum(from: 1, to: i))
}
}
return result
}
func factorial(_ n: Double) -> Double {
var result = 1.0
for i in 1...Int(n) {
result *= Double(i)
}
return result
}
func sum(from start: Int, to end: Int) -> Int {
var result = 0
for i in start...end {
result += i
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 *... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
Answer:
```swift
func f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 1...n {
if i % 2 == 0 {
result[i-1] = Int(factorial(Double(i)))
} else {
result[i-1] = Int(sum(from: 1, to: i))
}
}
return result
}
func factorial(_ n: Double) -> Double {
var result = 1.0
for i in 1...Int(n) {
result *= Double(i)
}
return result
}
func sum(from start: Int, to end: Int) -> Int {
var result = 0
for i in start...end {
result += i
}
return result
}
```func f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 0..<n {
if i % 2 == 0 {
result[i] = Int(factorial(Double(i)))
} else {
result[i] = Int(i * (i + 1) / 2)
}
}
return result
}
func factorial(_ n: Double) -> Double {
var result = 1.0
for i in 1...Int(n) {
result *= Double(i)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 *... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
Answer:
```swift
func f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 0..<n {
if i % 2 == 0 {
result[i] = Int(factorial(Double(i)))
} else {
result[i] = Int(i * (i + 1) / 2)
}
}
return result
}
func factorial(_ n: Double) -> Double {
var result = 1.0
for i in 1...Int(n) {
result *= Double(i)
}
return result
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 0..<n {
if i % 2 == 0 {
result[i] = Int(factorial(Double(i)))
} else {
result[i] = Int(i * (i + 1) / 2)
}
}
return result
}
func factorial(_ n: Double) -> Double {
var result = 1.0
for i in 1...Int(n) {
result *= Double(i)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 *... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
Answer:
```swift
func f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 0..<n {
if i % 2 == 0 {
result[i] = Int(factorial(Double(i)))
} else {
result[i] = Int(i * (i + 1) / 2)
}
}
return result
}
func factorial(_ n: Double) -> Double {
var result = 1.0
for i in 1...Int(n) {
result *= Double(i)
}
return result
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 0..<n {
if i % 2 == 0 {
result[i] = Int(factorial(Double(i)))
} else {
result[i] = Int(i * (i + 1) / 2)
}
}
return result
}
func factorial(_ n: Double) -> Double {
var result = 1.0
for i in 1...Int(n) {
result *= Double(i)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 *... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
Answer:
```swift
func f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 0..<n {
if i % 2 == 0 {
result[i] = Int(factorial(Double(i)))
} else {
result[i] = Int(i * (i + 1) / 2)
}
}
return result
}
func factorial(_ n: Double) -> Double {
var result = 1.0
for i in 1...Int(n) {
result *= Double(i)
}
return result
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc evenOddPalindrome(n: Int) -> (Int, Int) {
var countEven = 0
var countOdd = 0
for i in 1...n {
let num = i
let reversedNum = String(num).reversed()
let reversedNumInt = Int(reversedNum)!
if num == reversedNumInt {
if num % 2 == 0 {
countEven += 1
} else {
countOdd += 1
}
}
}
return (countEven, countOdd)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
Answer:
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var countEven = 0
var countOdd = 0
for i in 1...n {
let num = i
let reversedNum = String(num).reversed()
let reversedNumInt = Int(reversedNum)!
if num == reversedNumInt {
if num % 2 == 0 {
countEven += 1
} else {
countOdd += 1
}
}
}
return (countEven, countOdd)
}
```let reversedNumInt = Int(reversedNum)! // cannot convert value of type 'ReversedCollection<String>' to expected argument type 'String'func evenOddPalindrome(n: Int) -> (Int, Int) {
var even = 0
var odd = 0
for i in 1...n {
let num = i
let reverse = String(num).reversed()
let reversedNum = Int(reverse)!
if num == reversedNum {
if num % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
Answer:
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var even = 0
var odd = 0
for i in 1...n {
let num = i
let reverse = String(num).reversed()
let reversedNum = Int(reverse)!
if num == reversedNum {
if num % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}
```let reversedNum = Int(reverse)! // cannot convert value of type 'ReversedCollection<String>' to expected argument type 'String'func evenOddPalindrome(n: Int) -> (Int, Int) {
var even = 0
var odd = 0
for i in 1...n {
let num = i
let reversedNum = Int(String(num).reversed())!
if num == reversedNum {
if num % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
Answer:
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var even = 0
var odd = 0
for i in 1...n {
let num = i
let reversedNum = Int(String(num).reversed())!
if num == reversedNum {
if num % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}
```let reversedNum = Int(String(num).reversed())! // cannot convert value of type 'ReversedCollection<String>' to expected argument type 'String'func evenOddPalindrome(n: Int) -> (Int, Int) {
var even = 0
var odd = 0
for i in 1...n {
let num = i
let reverse = String(num).reversed()
let reversedNum = Int(reverse)!
if num == reversedNum {
if num % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
Answer:
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var even = 0
var odd = 0
for i in 1...n {
let num = i
let reverse = String(num).reversed()
let reversedNum = Int(reverse)!
if num == reversedNum {
if num % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}
```let reversedNum = Int(reverse)! // cannot convert value of type 'ReversedCollection<String>' to expected argument type 'String'func evenOddPalindrome(n: Int) -> (Int, Int) {
var evens = 0
var odds = 0
for i in 1...n {
let num = i
let reversedNum = String(num).reversed()
let reversedNumInt = Int(reversedNum)!
if num == reversedNumInt {
if num % 2 == 0 {
evens += 1
} else {
odds += 1
}
}
}
return (evens, odds)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
Answer:
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var evens = 0
var odds = 0
for i in 1...n {
let num = i
let reversedNum = String(num).reversed()
let reversedNumInt = Int(reversedNum)!
if num == reversedNumInt {
if num % 2 == 0 {
evens += 1
} else {
odds += 1
}
}
}
return (evens, odds)
}
```let reversedNumInt = Int(reversedNum)! // cannot convert value of type 'ReversedCollection<String>' to expected argument type 'String'func evenOddPalindrome(n: Int) -> (Int, Int) {
var even = 0
var odd = 0
for i in 1...n {
let num = i
let reversedNum = String(num).reversed()
let reversedNumInt = Int(reversedNum)!
if num == reversedNumInt {
if num % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
Answer:
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var even = 0
var odd = 0
for i in 1...n {
let num = i
let reversedNum = String(num).reversed()
let reversedNumInt = Int(reversedNum)!
if num == reversedNumInt {
if num % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}
```let reversedNumInt = Int(reversedNum)! // cannot convert value of type 'ReversedCollection<String>' to expected argument type 'String'func evenOddPalindrome(n: Int) -> (Int, Int) {
var even = 0
var odd = 0
for i in 1...n {
let num = i
let reversedNum = String(num).reversed()
let reversedNumInt = Int(reversedNum)!
if num == reversedNumInt {
if num % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
Answer:
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var even = 0
var odd = 0
for i in 1...n {
let num = i
let reversedNum = String(num).reversed()
let reversedNumInt = Int(reversedNum)!
if num == reversedNumInt {
if num % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}
```let reversedNumInt = Int(reversedNum)! // cannot convert value of type 'ReversedCollection<String>' to expected argument type 'String'func evenOddPalindrome(n: Int) -> (Int, Int) {
var count = 0
var even = 0
var odd = 0
for i in 1...n {
let num = i
let reversedNum = String(num).reversed()
let reversedNumInt = Int(reversedNum)!
if num == reversedNumInt {
count += 1
if num % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
Answer:
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var count = 0
var even = 0
var odd = 0
for i in 1...n {
let num = i
let reversedNum = String(num).reversed()
let reversedNumInt = Int(reversedNum)!
if num == reversedNumInt {
count += 1
if num % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}
```let reversedNumInt = Int(reversedNum)! // cannot convert value of type 'ReversedCollection<String>' to expected argument type 'String'func evenOddPalindrome(n: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for i in 1...n {
let number = i.description
let reverseNumber = String(number.reversed())
if number == reverseNumber {
if i % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
}
return (evenCount, oddCount)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
Answer:
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for i in 1...n {
let number = i.description
let reverseNumber = String(number.reversed())
if number == reverseNumber {
if i % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
}
return (evenCount, oddCount)
}
```func evenOddPalindrome(n: Int) -> (Int, Int) {
var even = 0
var odd = 0
for i in 1...n {
let num = i.description
if num == String(num.reversed()) {
if i % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
Answer:
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var even = 0
var odd = 0
for i in 1...n {
let num = i.description
if num == String(num.reversed()) {
if i % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}
```func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let sum = num.description.reduce(0) { $0 + Int($1) }
if sum > 0 {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
Answer:
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let sum = num.description.reduce(0) { $0 + Int($1) }
if sum > 0 {
count += 1
}
}
return count
}
```let sum = num.description.reduce(0) { $0 + Int($1) } // no exact matches in call to initializerfunc countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let sumOfDigits = num.description.reduce(0, { $0 + Int($1) })
if sumOfDigits > 0 {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
Answer:
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let sumOfDigits = num.description.reduce(0, { $0 + Int($1) })
if sumOfDigits > 0 {
count += 1
}
}
return count
}
```let sumOfDigits = num.description.reduce(0, { $0 + Int($1) }) // no exact matches in call to initializerfunc countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let sum = num.description.reduce(0) { $0 + Int($1) }
if sum > 0 {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
Answer:
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let sum = num.description.reduce(0) { $0 + Int($1) }
if sum > 0 {
count += 1
}
}
return count
}
```let sum = num.description.reduce(0) { $0 + Int($1) } // no exact matches in call to initializerfunc countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let sum = num.digits.reduce(0, +)
if sum > 0 {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
Answer:
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let sum = num.digits.reduce(0, +)
if sum > 0 {
count += 1
}
}
return count
}
```let sum = num.digits.reduce(0, +) // value of type 'Int' has no member 'digits'func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let sum = num.description.reduce(0) { $0 + Int($1) }
if sum > 0 {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
Answer:
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let sum = num.description.reduce(0) { $0 + Int($1) }
if sum > 0 {
count += 1
}
}
return count
}
```let sum = num.description.reduce(0) { $0 + Int($1) } // no exact matches in call to initializerfunc countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
if num > 0 {
let sum = num.digits.reduce(0, +)
if sum > 0 {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
Answer:
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
if num > 0 {
let sum = num.digits.reduce(0, +)
if sum > 0 {
count += 1
}
}
}
return count
}
```let sum = num.digits.reduce(0, +) // value of type 'Int' has no member 'digits'func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
if num < 0 {
let signedDigits = String(num).components(separatedBy: "-").map { Int($0)! }
let sumOfDigits = signedDigits.reduce(0, +)
if sumOfDigits > 0 {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
Answer:
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
if num < 0 {
let signedDigits = String(num).components(separatedBy: "-").map { Int($0)! }
let sumOfDigits = signedDigits.reduce(0, +)
if sumOfDigits > 0 {
count += 1
}
}
}
return count
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let sum = num.description.reduce(0) { $0 + Int($1) }
if sum > 0 {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
Answer:
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let sum = num.description.reduce(0) { $0 + Int($1) }
if sum > 0 {
count += 1
}
}
return count
}
```let sum = num.description.reduce(0) { $0 + Int($1) } // no exact matches in call to initializerfunc countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
if num > 0 {
let sum = num.description.reduce(0, { $0 + Int($1) })
if sum > 0 {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
Answer:
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
if num > 0 {
let sum = num.description.reduce(0, { $0 + Int($1) })
if sum > 0 {
count += 1
}
}
}
return count
}
```let sum = num.description.reduce(0, { $0 + Int($1) }) // no exact matches in call to initializerfunc countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
if num < 0 {
let signedDigits = String(num).components(separatedBy: "-").map { Int($0)! }
let sumOfDigits = signedDigits.reduce(0, +)
if sumOfDigits > 0 {
count += 1
}
} else {
let sumOfDigits = String(num).components(separatedBy: "").map { Int($0)! }.reduce(0, +)
if sumOfDigits > 0 {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
Answer:
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
if num < 0 {
let signedDigits = String(num).components(separatedBy: "-").map { Int($0)! }
let sumOfDigits = signedDigits.reduce(0, +)
if sumOfDigits > 0 {
count += 1
}
} else {
let sumOfDigits = String(num).components(separatedBy: "").map { Int($0)! }.reduce(0, +)
if sumOfDigits > 0 {
count += 1
}
}
}
return count
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else {
return true
}
let first = arr[0]
var hasChanged = false
for i in 0..<arr.count {
if arr[i] < first {
hasChanged = true
arr.swapAt(i, 0)
break
}
}
return!hasChanged
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2],..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
Answer:
```swift
func moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else {
return true
}
let first = arr[0]
var hasChanged = false
for i in 0..<arr.count {
if arr[i] < first {
hasChanged = true
arr.swapAt(i, 0)
break
}
}
return!hasChanged
}
```arr.swapAt(i, 0) // cannot use mutating member on immutable value: 'arr' is a 'let' constantreturn!hasChanged // expected expression in 'return' statementfunc moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else {
return true
}
let first = arr[0]
for i in 0..<arr.count {
if arr[i]!= first {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2],..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
Answer:
```swift
func moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else {
return true
}
let first = arr[0]
for i in 0..<arr.count {
if arr[i]!= first {
return false
}
}
return true
}
```if arr[i]!= first { // cannot force unwrap value of non-optional type 'Int'if arr[i]!= first { // '=' must have consistent whitespace on both sidesif arr[i]!= first { // use of '=' in a boolean context, did you mean '=='?func moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else {
return true
}
var first = 0
var last = arr.count - 1
while first < last {
if arr[first] == 0 {
first += 1
} else if arr[last] == 0 {
last -= 1
} else {
arr[first], arr[last] = arr[last], arr[first]
first += 1
last -= 1
}
}
return arr == [0]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2],..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
Answer:
```swift
func moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else {
return true
}
var first = 0
var last = arr.count - 1
while first < last {
if arr[first] == 0 {
first += 1
} else if arr[last] == 0 {
last -= 1
} else {
arr[first], arr[last] = arr[last], arr[first]
first += 1
last -= 1
}
}
return arr == [0]
}
```arr[first], arr[last] = arr[last], arr[first] // expression of type 'Int' is unusedarr[first], arr[last] = arr[last], arr[first] // consecutive statements on a line must be separated by ';'arr[first], arr[last] = arr[last], arr[first] // expected expressionfunc moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 1 else {
return true
}
var left = 0
var right = arr.count - 1
while left < right {
while arr[left] == arr[left + 1] {
left += 1
}
while arr[right] == arr[right - 1] {
right -= 1
}
if arr[left] > arr[right] {
return false
}
left += 1
right -= 1
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2],..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
Answer:
```swift
func moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 1 else {
return true
}
var left = 0
var right = arr.count - 1
while left < right {
while arr[left] == arr[left + 1] {
left += 1
}
while arr[right] == arr[right - 1] {
right -= 1
}
if arr[left] > arr[right] {
return false
}
left += 1
right -= 1
}
return true
}
``` // XCTAssertTrue failedfunc moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else {
return true
}
let first = arr.first!
let last = arr.last!
var left = 0
var right = arr.count - 1
while left < right {
while left < right && arr[left] == first {
left += 1
}
while left < right && arr[right] == last {
right -= 1
}
if left < right {
arr.swapAt(left, right)
left += 1
right -= 1
}
}
return arr == arr.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2],..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
Answer:
```swift
func moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else {
return true
}
let first = arr.first!
let last = arr.last!
var left = 0
var right = arr.count - 1
while left < right {
while left < right && arr[left] == first {
left += 1
}
while left < right && arr[right] == last {
right -= 1
}
if left < right {
arr.swapAt(left, right)
left += 1
right -= 1
}
}
return arr == arr.sorted()
}
```arr.swapAt(left, right) // cannot use mutating member on immutable value: 'arr' is a 'let' constantfunc moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else {
return true
}
let first = arr[0]
var left = 0
var right = arr.count - 1
while left < right {
while left < right && arr[right] >= first {
right -= 1
}
while left < right && arr[left] <= first {
left += 1
}
if left < right {
arr.swapAt(left, right)
left += 1
right -= 1
}
}
return arr == arr.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2],..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
Answer:
```swift
func moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else {
return true
}
let first = arr[0]
var left = 0
var right = arr.count - 1
while left < right {
while left < right && arr[right] >= first {
right -= 1
}
while left < right && arr[left] <= first {
left += 1
}
if left < right {
arr.swapAt(left, right)
left += 1
right -= 1
}
}
return arr == arr.sorted()
}
```arr.swapAt(left, right) // cannot use mutating member on immutable value: 'arr' is a 'let' constantfunc moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else {
return true
}
let first = arr[0]
var left = 0
var right = arr.count - 1
while left < right {
while left < right && arr[right] >= first {
right -= 1
}
while left < right && arr[left] <= first {
left += 1
}
if left < right {
arr.swapAt(left, right)
left += 1
right -= 1
}
}
return arr == arr.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2],..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
Answer:
```swift
func moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else {
return true
}
let first = arr[0]
var left = 0
var right = arr.count - 1
while left < right {
while left < right && arr[right] >= first {
right -= 1
}
while left < right && arr[left] <= first {
left += 1
}
if left < right {
arr.swapAt(left, right)
left += 1
right -= 1
}
}
return arr == arr.sorted()
}
```arr.swapAt(left, right) // cannot use mutating member on immutable value: 'arr' is a 'let' constantfunc moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else {
return true
}
var left = 0
var right = arr.count - 1
while left < right {
while arr[left] == arr[left + 1] {
left += 1
}
while arr[right] == arr[right - 1] {
right -= 1
}
if arr[left] > arr[right] {
return false
}
left += 1
right -= 1
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2],..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
Answer:
```swift
func moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else {
return true
}
var left = 0
var right = arr.count - 1
while left < right {
while arr[left] == arr[left + 1] {
left += 1
}
while arr[right] == arr[right - 1] {
right -= 1
}
if arr[left] > arr[right] {
return false
}
left += 1
right -= 1
}
return true
}
``` // XCTAssertTrue failedfunc moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 1 else {
return true
}
var left = 0
var right = arr.count - 1
while left < right {
while arr[left] == arr[left + 1] {
left += 1
}
while arr[right] == arr[right - 1] {
right -= 1
}
if arr[left] > arr[right] {
return false
}
left += 1
right -= 1
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2],..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
Answer:
```swift
func moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 1 else {
return true
}
var left = 0
var right = arr.count - 1
while left < right {
while arr[left] == arr[left + 1] {
left += 1
}
while arr[right] == arr[right - 1] {
right -= 1
}
if arr[left] > arr[right] {
return false
}
left += 1
right -= 1
}
return true
}
``` // XCTAssertTrue failedfunc moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else {
return true
}
let first = arr[0]
for i in 1..<arr.count {
if arr[i] < first {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2],..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
Answer:
```swift
func moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else {
return true
}
let first = arr[0]
for i in 1..<arr.count {
if arr[i] < first {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc exchange(lst1: [Int], lst2: [Int]) -> String {
guard!lst1.isEmpty &&!lst2.isEmpty else {
return "NO"
}
var lst1 = lst1
var lst2 = lst2
for i in 0..<lst1.count {
if lst1[i] % 2 == 0 {
lst1.remove(at: i)
}
}
for i in 0..<lst2.count {
if lst2[i] % 2 == 0 {
lst2.remove(at: i)
}
}
return lst1 == lst2? "YES" : "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
Answer:
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
guard!lst1.isEmpty &&!lst2.isEmpty else {
return "NO"
}
var lst1 = lst1
var lst2 = lst2
for i in 0..<lst1.count {
if lst1[i] % 2 == 0 {
lst1.remove(at: i)
}
}
for i in 0..<lst2.count {
if lst2[i] % 2 == 0 {
lst2.remove(at: i)
}
}
return lst1 == lst2? "YES" : "NO"
}
```guard!lst1.isEmpty &&!lst2.isEmpty else { // expected expression, var, let or case in 'guard' conditionreturn lst1 == lst2? "YES" : "NO" // expected expressionreturn lst1 == lst2? "YES" : "NO" // string literal is unusedreturn lst1 == lst2? "YES" : "NO" // consecutive statements on a line must be separated by ';'return lst1 == lst2? "YES" : "NO" // cannot use optional chaining on non-optional value of type '[Int]'return lst1 == lst2? "YES" : "NO" // cannot convert return expression of type 'Bool' to return type 'String'return lst1 == lst2? "YES" : "NO" // consecutive statements on a line must be separated by ';'func exchange(lst1: [Int], lst2: [Int]) -> String {
guard!lst1.isEmpty &&!lst2.isEmpty else {
return "NO"
}
var lst1 = lst1
var lst2 = lst2
for i in 0..<lst1.count {
if lst1[i] % 2 == 0 {
lst1.remove(at: i)
}
}
for i in 0..<lst2.count {
if lst2[i] % 2 == 0 {
lst2.remove(at: i)
}
}
return lst1.count == 0 && lst2.count == 0? "YES" : "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
Answer:
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
guard!lst1.isEmpty &&!lst2.isEmpty else {
return "NO"
}
var lst1 = lst1
var lst2 = lst2
for i in 0..<lst1.count {
if lst1[i] % 2 == 0 {
lst1.remove(at: i)
}
}
for i in 0..<lst2.count {
if lst2[i] % 2 == 0 {
lst2.remove(at: i)
}
}
return lst1.count == 0 && lst2.count == 0? "YES" : "NO"
}
```guard!lst1.isEmpty &&!lst2.isEmpty else { // expected expression, var, let or case in 'guard' conditionreturn lst1.count == 0 && lst2.count == 0? "YES" : "NO" // expected expressionreturn lst1.count == 0 && lst2.count == 0? "YES" : "NO" // consecutive statements on a line must be separated by ';'return lst1.count == 0 && lst2.count == 0? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Int'return lst1.count == 0 && lst2.count == 0? "YES" : "NO" // cannot convert return expression of type 'Bool' to return type 'String'return lst1.count == 0 && lst2.count == 0? "YES" : "NO" // string literal is unusedreturn lst1.count == 0 && lst2.count == 0? "YES" : "NO" // consecutive statements on a line must be separated by ';'func exchange(lst1: [Int], lst2: [Int]) -> String {
var lst1 = lst1
var lst2 = lst2
var evenCount = 0
for num in lst1 {
if num % 2 == 0 {
evenCount += 1
}
}
if evenCount == lst1.count {
return "YES"
}
for num in lst2 {
if num % 2 == 0 {
evenCount += 1
}
}
if evenCount == lst2.count {
return "YES"
}
return "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
Answer:
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
var lst1 = lst1
var lst2 = lst2
var evenCount = 0
for num in lst1 {
if num % 2 == 0 {
evenCount += 1
}
}
if evenCount == lst1.count {
return "YES"
}
for num in lst2 {
if num % 2 == 0 {
evenCount += 1
}
}
if evenCount == lst2.count {
return "YES"
}
return "NO"
}
```var lst1 = lst1 // variable 'lst1' was never mutated; consider changing to 'let' constantvar lst2 = lst2 // variable 'lst2' was never mutated; consider changing to 'let' constantfunc exchange(lst1: [Int], lst2: [Int]) -> String {
var lst1 = lst1
var lst2 = lst2
var evenCount = 0
for num in lst1 {
if num % 2 == 0 {
evenCount += 1
}
}
if evenCount == lst1.count {
return "YES"
}
for num in lst2 {
if num % 2 == 0 {
evenCount += 1
}
}
if evenCount == lst2.count {
return "YES"
}
for i in 0..<lst1.count {
for j in 0..<lst2.count {
if lst1[i] % 2 == 0 {
lst1[i] = lst2[j]
lst2[j] = lst1[i]
break
}
}
}
for num in lst1 {
if num % 2 == 0 {
evenCount += 1
}
}
if evenCount == lst1.count {
return "YES"
}
return "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
Answer:
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
var lst1 = lst1
var lst2 = lst2
var evenCount = 0
for num in lst1 {
if num % 2 == 0 {
evenCount += 1
}
}
if evenCount == lst1.count {
return "YES"
}
for num in lst2 {
if num % 2 == 0 {
evenCount += 1
}
}
if evenCount == lst2.count {
return "YES"
}
for i in 0..<lst1.count {
for j in 0..<lst2.count {
if lst1[i] % 2 == 0 {
lst1[i] = lst2[j]
lst2[j] = lst1[i]
break
}
}
}
for num in lst1 {
if num % 2 == 0 {
evenCount += 1
}
}
if evenCount == lst1.count {
return "YES"
}
return "NO"
}
```func exchange(lst1: [Int], lst2: [Int]) -> String {
var lst1 = lst1
var lst2 = lst2
var evenCount = 0
for num in lst1 {
if num % 2 == 0 {
evenCount += 1
}
}
if evenCount == lst1.count {
return "YES"
}
for num in lst2 {
if num % 2 == 0 {
evenCount += 1
lst1.append(num)
}
}
if evenCount == lst1.count {
return "YES"
}
return "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
Answer:
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
var lst1 = lst1
var lst2 = lst2
var evenCount = 0
for num in lst1 {
if num % 2 == 0 {
evenCount += 1
}
}
if evenCount == lst1.count {
return "YES"
}
for num in lst2 {
if num % 2 == 0 {
evenCount += 1
lst1.append(num)
}
}
if evenCount == lst1.count {
return "YES"
}
return "NO"
}
```var lst2 = lst2 // variable 'lst2' was never mutated; consider changing to 'let' constant // XCTAssertTrue failedfunc exchange(lst1: [Int], lst2: [Int]) -> String {
var evenCount = 0
for num in lst1 {
if num % 2 == 0 {
evenCount += 1
}
}
if evenCount == lst1.count {
return "YES"
} else {
return "NO"
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
Answer:
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
var evenCount = 0
for num in lst1 {
if num % 2 == 0 {
evenCount += 1
}
}
if evenCount == lst1.count {
return "YES"
} else {
return "NO"
}
}
``` // XCTAssertTrue failedfunc exchange(lst1: [Int], lst2: [Int]) -> String {
var lst1 = lst1
var lst2 = lst2
var evenCount = 0
for num in lst1 {
if num % 2 == 0 {
evenCount += 1
}
}
if evenCount == lst1.count {
return "YES"
}
var i = 0
while i < lst1.count {
if lst1[i] % 2 == 0 {
lst1.remove(at: i)
lst2.append(lst1.remove(at: 0))
evenCount += 1
}
i += 1
}
if evenCount == lst1.count {
return "YES"
}
return "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
Answer:
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
var lst1 = lst1
var lst2 = lst2
var evenCount = 0
for num in lst1 {
if num % 2 == 0 {
evenCount += 1
}
}
if evenCount == lst1.count {
return "YES"
}
var i = 0
while i < lst1.count {
if lst1[i] % 2 == 0 {
lst1.remove(at: i)
lst2.append(lst1.remove(at: 0))
evenCount += 1
}
i += 1
}
if evenCount == lst1.count {
return "YES"
}
return "NO"
}
``` // XCTAssertTrue failedfunc exchange(lst1: [Int], lst2: [Int]) -> String {
var lst1 = lst1
var lst2 = lst2
var evenCount = 0
for num in lst1 {
if num % 2 == 0 {
evenCount += 1
}
}
for num in lst2 {
if num % 2 == 0 {
evenCount += 1
}
}
if evenCount == lst1.count {
return "YES"
} else {
return "NO"
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
Answer:
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
var lst1 = lst1
var lst2 = lst2
var evenCount = 0
for num in lst1 {
if num % 2 == 0 {
evenCount += 1
}
}
for num in lst2 {
if num % 2 == 0 {
evenCount += 1
}
}
if evenCount == lst1.count {
return "YES"
} else {
return "NO"
}
}
```var lst1 = lst1 // variable 'lst1' was never mutated; consider changing to 'let' constantvar lst2 = lst2 // variable 'lst2' was never mutated; consider changing to 'let' constant // XCTAssertTrue failedfunc exchange(lst1: [Int], lst2: [Int]) -> String {
var lst1 = lst1
var lst2 = lst2
var evenCount = 0
for num in lst1 {
if num % 2 == 0 {
evenCount += 1
}
}
for num in lst2 {
if num % 2 == 0 {
evenCount += 1
}
}
if evenCount == lst1.count {
return "YES"
} else {
return "NO"
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
Answer:
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
var lst1 = lst1
var lst2 = lst2
var evenCount = 0
for num in lst1 {
if num % 2 == 0 {
evenCount += 1
}
}
for num in lst2 {
if num % 2 == 0 {
evenCount += 1
}
}
if evenCount == lst1.count {
return "YES"
} else {
return "NO"
}
}
```var lst1 = lst1 // variable 'lst1' was never mutated; consider changing to 'let' constantvar lst2 = lst2 // variable 'lst2' was never mutated; consider changing to 'let' constant // XCTAssertTrue failedfunc exchange(lst1: [Int], lst2: [Int]) -> String {
var lst1 = lst1
var lst2 = lst2
var evenCount = 0
for num in lst1 {
if num % 2 == 0 {
evenCount += 1
}
}
if evenCount == lst1.count {
return "YES"
}
while lst1.count > 0 && lst2.count > 0 {
let firstNum = lst1.removeFirst()
let secondNum = lst2.removeFirst()
lst1.append(secondNum)
lst2.append(firstNum)
}
evenCount = 0
for num in lst1 {
if num % 2 == 0 {
evenCount += 1
}
}
if evenCount == lst1.count {
return "YES"
}
return "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
Answer:
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
var lst1 = lst1
var lst2 = lst2
var evenCount = 0
for num in lst1 {
if num % 2 == 0 {
evenCount += 1
}
}
if evenCount == lst1.count {
return "YES"
}
while lst1.count > 0 && lst2.count > 0 {
let firstNum = lst1.removeFirst()
let secondNum = lst2.removeFirst()
lst1.append(secondNum)
lst2.append(firstNum)
}
evenCount = 0
for num in lst1 {
if num % 2 == 0 {
evenCount += 1
}
}
if evenCount == lst1.count {
return "YES"
}
return "NO"
}
```func histogram(test: String) -> [String : Int] {
let letters = test.lowercased().filter { $0.isLetter }
var result = [String : Int]()
for letter in letters {
if let count = result[letter] {
result[letter] = count + 1
} else {
result[letter] = 1
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
Answer:
```swift
func histogram(test: String) -> [String : Int] {
let letters = test.lowercased().filter { $0.isLetter }
var result = [String : Int]()
for letter in letters {
if let count = result[letter] {
result[letter] = count + 1
} else {
result[letter] = 1
}
}
return result
}
```if let count = result[letter] { // cannot convert value of type 'Character' to expected argument type 'String'result[letter] = count + 1 // cannot convert value of type 'Character' to expected argument type 'String'result[letter] = 1 // cannot convert value of type 'Character' to expected argument type 'String'func histogram(test: String) -> [String : Int] {
let letters = test.lowercased().filter { $0.isLetter }
let counts = Dictionary(uniqueKeysWithValues: letters.map { ($0, 1) })
return counts
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
Answer:
```swift
func histogram(test: String) -> [String : Int] {
let letters = test.lowercased().filter { $0.isLetter }
let counts = Dictionary(uniqueKeysWithValues: letters.map { ($0, 1) })
return counts
}
```return counts // cannot convert return expression of type '[String.Element : Int]' (aka 'Dictionary<Character, Int>') to return type '[String : Int]'func histogram(test: String) -> [String : Int] {
var result = [String : Int]()
let letters = test.lowercased().split(separator: " ")
for letter in letters {
if let count = result[letter] {
result[letter] = count + 1
} else {
result[letter] = 1
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
Answer:
```swift
func histogram(test: String) -> [String : Int] {
var result = [String : Int]()
let letters = test.lowercased().split(separator: " ")
for letter in letters {
if let count = result[letter] {
result[letter] = count + 1
} else {
result[letter] = 1
}
}
return result
}
```if let count = result[letter] { // cannot convert value of type 'String.SubSequence' (aka 'Substring') to expected argument type 'String'result[letter] = count + 1 // cannot convert value of type 'String.SubSequence' (aka 'Substring') to expected argument type 'String'result[letter] = 1 // cannot convert value of type 'String.SubSequence' (aka 'Substring') to expected argument type 'String'func histogram(test: String) -> [String : Int] {
var result = [String : Int]()
let letters = test.lowercased().filter { $0.isLetter }
for letter in letters {
if let count = result[letter] {
result[letter] = count + 1
} else {
result[letter] = 1
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
Answer:
```swift
func histogram(test: String) -> [String : Int] {
var result = [String : Int]()
let letters = test.lowercased().filter { $0.isLetter }
for letter in letters {
if let count = result[letter] {
result[letter] = count + 1
} else {
result[letter] = 1
}
}
return result
}
```if let count = result[letter] { // cannot convert value of type 'Character' to expected argument type 'String'result[letter] = count + 1 // cannot convert value of type 'Character' to expected argument type 'String'result[letter] = 1 // cannot convert value of type 'Character' to expected argument type 'String'func histogram(test: String) -> [String : Int] {
var result = [String : Int]()
let letters = test.lowercased().split(separator: " ")
for letter in letters {
if let count = result[letter] {
result[letter] = count + 1
} else {
result[letter] = 1
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
Answer:
```swift
func histogram(test: String) -> [String : Int] {
var result = [String : Int]()
let letters = test.lowercased().split(separator: " ")
for letter in letters {
if let count = result[letter] {
result[letter] = count + 1
} else {
result[letter] = 1
}
}
return result
}
```if let count = result[letter] { // cannot convert value of type 'String.SubSequence' (aka 'Substring') to expected argument type 'String'result[letter] = count + 1 // cannot convert value of type 'String.SubSequence' (aka 'Substring') to expected argument type 'String'result[letter] = 1 // cannot convert value of type 'String.SubSequence' (aka 'Substring') to expected argument type 'String'func histogram(test: String) -> [String : Int] {
let letters = test.lowercased().split(separator: " ")
var result = [String : Int]()
for letter in letters {
if let count = result[letter] {
result[letter] = count + 1
} else {
result[letter] = 1
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
Answer:
```swift
func histogram(test: String) -> [String : Int] {
let letters = test.lowercased().split(separator: " ")
var result = [String : Int]()
for letter in letters {
if let count = result[letter] {
result[letter] = count + 1
} else {
result[letter] = 1
}
}
return result
}
```if let count = result[letter] { // cannot convert value of type 'String.SubSequence' (aka 'Substring') to expected argument type 'String'result[letter] = count + 1 // cannot convert value of type 'String.SubSequence' (aka 'Substring') to expected argument type 'String'result[letter] = 1 // cannot convert value of type 'String.SubSequence' (aka 'Substring') to expected argument type 'String'func histogram(test: String) -> [String : Int] {
var result = [String : Int]()
let letters = test.lowercased().split(separator: " ")
for letter in letters {
if let count = result[letter] {
result[letter] = count + 1
} else {
result[letter] = 1
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
Answer:
```swift
func histogram(test: String) -> [String : Int] {
var result = [String : Int]()
let letters = test.lowercased().split(separator: " ")
for letter in letters {
if let count = result[letter] {
result[letter] = count + 1
} else {
result[letter] = 1
}
}
return result
}
```if let count = result[letter] { // cannot convert value of type 'String.SubSequence' (aka 'Substring') to expected argument type 'String'result[letter] = count + 1 // cannot convert value of type 'String.SubSequence' (aka 'Substring') to expected argument type 'String'result[letter] = 1 // cannot convert value of type 'String.SubSequence' (aka 'Substring') to expected argument type 'String'func histogram(test: String) -> [String : Int] {
var result = [String : Int]()
let letters = test.lowercased().split(separator: " ")
for letter in letters {
if let count = result[letter] {
result[letter] = count + 1
} else {
result[letter] = 1
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
Answer:
```swift
func histogram(test: String) -> [String : Int] {
var result = [String : Int]()
let letters = test.lowercased().split(separator: " ")
for letter in letters {
if let count = result[letter] {
result[letter] = count + 1
} else {
result[letter] = 1
}
}
return result
}
```if let count = result[letter] { // cannot convert value of type 'String.SubSequence' (aka 'Substring') to expected argument type 'String'result[letter] = count + 1 // cannot convert value of type 'String.SubSequence' (aka 'Substring') to expected argument type 'String'result[letter] = 1 // cannot convert value of type 'String.SubSequence' (aka 'Substring') to expected argument type 'String'func histogram(test: String) -> [String : Int] {
var result = [String : Int]()
let letters = test.lowercased().split(separator: " ")
for letter in letters {
if let count = result[letter] {
result[letter] = count + 1
} else {
result[letter] = 1
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
Answer:
```swift
func histogram(test: String) -> [String : Int] {
var result = [String : Int]()
let letters = test.lowercased().split(separator: " ")
for letter in letters {
if let count = result[letter] {
result[letter] = count + 1
} else {
result[letter] = 1
}
}
return result
}
```if let count = result[letter] { // cannot convert value of type 'String.SubSequence' (aka 'Substring') to expected argument type 'String'result[letter] = count + 1 // cannot convert value of type 'String.SubSequence' (aka 'Substring') to expected argument type 'String'result[letter] = 1 // cannot convert value of type 'String.SubSequence' (aka 'Substring') to expected argument type 'String'func histogram(test: String) -> [String : Int] {
let letters = test.lowercased().filter { $0.isLetter }
let counts = Dictionary(uniqueKeysWithValues: letters.map { ($0, 1) })
return counts
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
Answer:
```swift
func histogram(test: String) -> [String : Int] {
let letters = test.lowercased().filter { $0.isLetter }
let counts = Dictionary(uniqueKeysWithValues: letters.map { ($0, 1) })
return counts
}
```return counts // cannot convert return expression of type '[String.Element : Int]' (aka 'Dictionary<Character, Int>') to return type '[String : Int]'func reverseDelete(s: String, c: String) -> (String, Bool) {
let sChars = Array(s)
let cChars = Array(c)
var result = ""
var isPalindrome = true
for i in 0..<sChars.count {
if!cChars.contains(sChars[i]) {
result.append(sChars[i])
}
}
for i in 0..<result.count {
if result[i]!= result[result.count - 1 - i] {
isPalindrome = false
break
}
}
return (result, isPalindrome)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
Answer:
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
let sChars = Array(s)
let cChars = Array(c)
var result = ""
var isPalindrome = true
for i in 0..<sChars.count {
if!cChars.contains(sChars[i]) {
result.append(sChars[i])
}
}
for i in 0..<result.count {
if result[i]!= result[result.count - 1 - i] {
isPalindrome = false
break
}
}
return (result, isPalindrome)
}
```if!cChars.contains(sChars[i]) { // expected expression, var, or let in 'if' conditionif result[i]!= result[result.count - 1 - i] { // cannot force unwrap value of non-optional type 'Character'if result[i]!= result[result.count - 1 - i] { // '=' must have consistent whitespace on both sidesif result[i]!= result[result.count - 1 - i] { // use of '=' in a boolean context, did you mean '=='?func reverseDelete(s: String, c: String) -> (String, Bool) {
let sChars = Array(s)
let cChars = Array(c)
for i in 0..<sChars.count {
if cChars.contains(sChars[i]) {
sChars.remove(at: i)
i -= 1
}
}
let result = String(sChars)
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
Answer:
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
let sChars = Array(s)
let cChars = Array(c)
for i in 0..<sChars.count {
if cChars.contains(sChars[i]) {
sChars.remove(at: i)
i -= 1
}
}
let result = String(sChars)
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}
```sChars.remove(at: i) // cannot use mutating member on immutable value: 'sChars' is a 'let' constanti -= 1 // left side of mutating operator isn't mutable: 'i' is a 'let' constantfunc reverseDelete(s: String, c: String) -> (String, Bool) {
let sChars = Array(s)
let cChars = Array(c)
var resultChars = sChars
for c in cChars {
resultChars = resultChars.filter { $0!= c }
}
let resultString = String(resultChars)
let isPalindrome = resultString == String(resultChars.reversed())
return (resultString, isPalindrome)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
Answer:
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
let sChars = Array(s)
let cChars = Array(c)
var resultChars = sChars
for c in cChars {
resultChars = resultChars.filter { $0!= c }
}
let resultString = String(resultChars)
let isPalindrome = resultString == String(resultChars.reversed())
return (resultString, isPalindrome)
}
```resultChars = resultChars.filter { $0!= c } // cannot force unwrap value of non-optional type 'String.Element' (aka 'Character')resultChars = resultChars.filter { $0!= c } // '=' must have consistent whitespace on both sidesfunc reverseDelete(s: String, c: String) -> (String, Bool) {
let sChars = Array(s)
let cChars = Array(c)
var result = ""
var isPalindrome = true
for (i, char) in sChars.enumerated() {
if!cChars.contains(char) {
result.append(char)
} else {
isPalindrome = false
}
}
return (result, isPalindrome)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
Answer:
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
let sChars = Array(s)
let cChars = Array(c)
var result = ""
var isPalindrome = true
for (i, char) in sChars.enumerated() {
if!cChars.contains(char) {
result.append(char)
} else {
isPalindrome = false
}
}
return (result, isPalindrome)
}
```if!cChars.contains(char) { // expected expression, var, or let in 'if' conditionfunc reverseDelete(s: String, c: String) -> (String, Bool) {
let sChars = Array(s)
let cChars = Array(c)
var resultChars = sChars
for cChar in cChars {
let index = resultChars.firstIndex(of: cChar)
if let index = index {
resultChars.remove(at: index)
}
}
let resultString = String(resultChars)
let isPalindrome = resultString == String(resultChars.reversed())
return (resultString, isPalindrome)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
Answer:
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
let sChars = Array(s)
let cChars = Array(c)
var resultChars = sChars
for cChar in cChars {
let index = resultChars.firstIndex(of: cChar)
if let index = index {
resultChars.remove(at: index)
}
}
let resultString = String(resultChars)
let isPalindrome = resultString == String(resultChars.reversed())
return (resultString, isPalindrome)
}
``` // XCTAssertTrue failedfunc reverseDelete(s: String, c: String) -> (String, Bool) {
var result = ""
var isPalindrome = true
for char in s {
if!c.contains(char) {
result.append(char)
}
}
for i in 0..<result.count/2 {
if result[i]!= result[result.count - 1 - i] {
isPalindrome = false
break
}
}
return (result, isPalindrome)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
Answer:
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
var result = ""
var isPalindrome = true
for char in s {
if!c.contains(char) {
result.append(char)
}
}
for i in 0..<result.count/2 {
if result[i]!= result[result.count - 1 - i] {
isPalindrome = false
break
}
}
return (result, isPalindrome)
}
```if!c.contains(char) { // expected expression, var, or let in 'if' conditionif result[i]!= result[result.count - 1 - i] { // use of '=' in a boolean context, did you mean '=='?if result[i]!= result[result.count - 1 - i] { // '=' must have consistent whitespace on both sidesif result[i]!= result[result.count - 1 - i] { // cannot force unwrap value of non-optional type 'Character'func reverseDelete(s: String, c: String) -> (String, Bool) {
let sChars = Array(s)
let cChars = Array(c)
for char in cChars {
if let index = sChars.firstIndex(of: char) {
sChars.remove(at: index)
}
}
let result = String(sChars)
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
Answer:
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
let sChars = Array(s)
let cChars = Array(c)
for char in cChars {
if let index = sChars.firstIndex(of: char) {
sChars.remove(at: index)
}
}
let result = String(sChars)
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}
```sChars.remove(at: index) // cannot use mutating member on immutable value: 'sChars' is a 'let' constantfunc reverseDelete(s: String, c: String) -> (String, Bool) {
let sChars = Array(s)
let cChars = Array(c)
var resultChars = sChars
for char in cChars {
resultChars = resultChars.filter { $0!= char }
}
let resultString = String(resultChars)
let isPalindrome = resultString == String(resultChars.reversed())
return (resultString, isPalindrome)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
Answer:
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
let sChars = Array(s)
let cChars = Array(c)
var resultChars = sChars
for char in cChars {
resultChars = resultChars.filter { $0!= char }
}
let resultString = String(resultChars)
let isPalindrome = resultString == String(resultChars.reversed())
return (resultString, isPalindrome)
}
```resultChars = resultChars.filter { $0!= char } // '=' must have consistent whitespace on both sidesresultChars = resultChars.filter { $0!= char } // cannot force unwrap value of non-optional type 'String.Element' (aka 'Character')func reverseDelete(s: String, c: String) -> (String, Bool) {
let sChars = Array(s)
let cChars = Array(c)
for i in 0..<sChars.count {
if cChars.contains(sChars[i]) {
sChars.remove(at: i)
i -= 1
}
}
let result = String(sChars)
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
Answer:
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
let sChars = Array(s)
let cChars = Array(c)
for i in 0..<sChars.count {
if cChars.contains(sChars[i]) {
sChars.remove(at: i)
i -= 1
}
}
let result = String(sChars)
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}
```sChars.remove(at: i) // cannot use mutating member on immutable value: 'sChars' is a 'let' constanti -= 1 // left side of mutating operator isn't mutable: 'i' is a 'let' constantfunc reverseDelete(s: String, c: String) -> (String, Bool) {
let sChars = Array(s)
let cChars = Array(c)
var resultChars = sChars
for char in cChars {
resultChars.removeAll(where: { $0 == char })
}
let resultString = String(resultChars)
let isPalindrome = resultString == String(resultChars.reversed())
return (resultString, isPalindrome)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
Answer:
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
let sChars = Array(s)
let cChars = Array(c)
var resultChars = sChars
for char in cChars {
resultChars.removeAll(where: { $0 == char })
}
let resultString = String(resultChars)
let isPalindrome = resultString == String(resultChars.reversed())
return (resultString, isPalindrome)
}
```func oddCount(lst: [String]) -> [String] {
var result = [String]()
for i in 0..<lst.count {
let count = lst[i].filter { $0.characters.contains("1") }.count
result.append("the number of odd elements \(count)n the str\(i+1)ng \(i+1) of the \(i+1)nput.")
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
Answer:
```swift
func oddCount(lst: [String]) -> [String] {
var result = [String]()
for i in 0..<lst.count {
let count = lst[i].filter { $0.characters.contains("1") }.count
result.append("the number of odd elements \(count)n the str\(i+1)ng \(i+1) of the \(i+1)nput.")
}
return result
}
```let count = lst[i].filter { $0.characters.contains("1") }.count // no exact matches in call to subscriptfunc oddCount(lst: [String]) -> [String] {
var result = [String]()
for i in 0..<lst.count {
var count = 0
for char in lst[i] {
if char.isOddDigit {
count += 1
}
}
result.append("the number of odd elements \(count)n the str\(i+1)ng \(i+1) of the \(i+1)nput.")
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
Answer:
```swift
func oddCount(lst: [String]) -> [String] {
var result = [String]()
for i in 0..<lst.count {
var count = 0
for char in lst[i] {
if char.isOddDigit {
count += 1
}
}
result.append("the number of odd elements \(count)n the str\(i+1)ng \(i+1) of the \(i+1)nput.")
}
return result
}
```if char.isOddDigit { // value of type 'Character' has no member 'isOddDigit'func oddCount(lst: [String]) -> [String] {
var result = [String]()
for i in 0..<lst.count {
var count = 0
for j in 0..<lst[i].count {
if lst[i][j] == "1" || lst[i][j] == "3" || lst[i][j] == "5" || lst[i][j] == "7" || lst[i][j] == "9" {
count += 1
}
}
result.append("the number of odd elements \(count)n the str\(i+1)ng \(i+1) of the \(i+1)nput.")
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
Answer:
```swift
func oddCount(lst: [String]) -> [String] {
var result = [String]()
for i in 0..<lst.count {
var count = 0
for j in 0..<lst[i].count {
if lst[i][j] == "1" || lst[i][j] == "3" || lst[i][j] == "5" || lst[i][j] == "7" || lst[i][j] == "9" {
count += 1
}
}
result.append("the number of odd elements \(count)n the str\(i+1)ng \(i+1) of the \(i+1)nput.")
}
return result
}
```if lst[i][j] == "1" || lst[i][j] == "3" || lst[i][j] == "5" || lst[i][j] == "7" || lst[i][j] == "9" { // 'subscript(_:)' is unavailable: cannot subscript String with an Int, use a String.Index instead.if lst[i][j] == "1" || lst[i][j] == "3" || lst[i][j] == "5" || lst[i][j] == "7" || lst[i][j] == "9" { // 'subscript(_:)' is unavailable: cannot subscript String with an Int, use a String.Index instead.if lst[i][j] == "1" || lst[i][j] == "3" || lst[i][j] == "5" || lst[i][j] == "7" || lst[i][j] == "9" { // 'subscript(_:)' is unavailable: cannot subscript String with an Int, use a String.Index instead.if lst[i][j] == "1" || lst[i][j] == "3" || lst[i][j] == "5" || lst[i][j] == "7" || lst[i][j] == "9" { // 'subscript(_:)' is unavailable: cannot subscript String with an Int, use a String.Index instead.if lst[i][j] == "1" || lst[i][j] == "3" || lst[i][j] == "5" || lst[i][j] == "7" || lst[i][j] == "9" { // 'subscript(_:)' is unavailable: cannot subscript String with an Int, use a String.Index instead.func oddCount(lst: [String]) -> [String] {
var result = [String]()
for i in 0..<lst.count {
var count = 0
for c in lst[i] {
if c.isdigit && Int(String(c)) % 2!= 0 {
count += 1
}
}
result.append("the number of odd elements \(count)n the str\(i+1)ng \(i+1) of the \(i+1)nput.")
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
Answer:
```swift
func oddCount(lst: [String]) -> [String] {
var result = [String]()
for i in 0..<lst.count {
var count = 0
for c in lst[i] {
if c.isdigit && Int(String(c)) % 2!= 0 {
count += 1
}
}
result.append("the number of odd elements \(count)n the str\(i+1)ng \(i+1) of the \(i+1)nput.")
}
return result
}
```if c.isdigit && Int(String(c)) % 2!= 0 { // value of optional type 'Int?' must be unwrapped to a value of type 'Int'if c.isdigit && Int(String(c)) % 2!= 0 { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadif c.isdigit && Int(String(c)) % 2!= 0 { // '=' must have consistent whitespace on both sidesif c.isdigit && Int(String(c)) % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if c.isdigit && Int(String(c)) % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'if c.isdigit && Int(String(c)) % 2!= 0 { // value of type 'Character' has no member 'isdigit'func oddCount(lst: [String]) -> [String] {
var result = [String]()
for i in 0..<lst.count {
var count = 0
for char in lst[i] {
if Int(String(char))! % 2!= 0 {
count += 1
}
}
result.append("the number of odd elements \(count)n the str\(i+1)ng \(i+1) of the \(i+1)nput.")
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
Answer:
```swift
func oddCount(lst: [String]) -> [String] {
var result = [String]()
for i in 0..<lst.count {
var count = 0
for char in lst[i] {
if Int(String(char))! % 2!= 0 {
count += 1
}
}
result.append("the number of odd elements \(count)n the str\(i+1)ng \(i+1) of the \(i+1)nput.")
}
return result
}
```if Int(String(char))! % 2!= 0 { // expression is not assignable: binary operator returns immutable valueif Int(String(char))! % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'if Int(String(char))! % 2!= 0 { // '=' must have consistent whitespace on both sidesif Int(String(char))! % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?func oddCount(lst: [String]) -> [String] {
var result = [String]()
for i in 0..<lst.count {
var count = 0
for c in lst[i] {
if c.isdigit && Int(String(c)) % 2!= 0 {
count += 1
}
}
result.append("the number of odd elements \(count)n the str\(i+1)ng \(i+1) of the \(i+1)nput.")
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
Answer:
```swift
func oddCount(lst: [String]) -> [String] {
var result = [String]()
for i in 0..<lst.count {
var count = 0
for c in lst[i] {
if c.isdigit && Int(String(c)) % 2!= 0 {
count += 1
}
}
result.append("the number of odd elements \(count)n the str\(i+1)ng \(i+1) of the \(i+1)nput.")
}
return result
}
```if c.isdigit && Int(String(c)) % 2!= 0 { // value of optional type 'Int?' must be unwrapped to a value of type 'Int'if c.isdigit && Int(String(c)) % 2!= 0 { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadif c.isdigit && Int(String(c)) % 2!= 0 { // '=' must have consistent whitespace on both sidesif c.isdigit && Int(String(c)) % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if c.isdigit && Int(String(c)) % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'if c.isdigit && Int(String(c)) % 2!= 0 { // value of type 'Character' has no member 'isdigit'func oddCount(lst: [String]) -> [String] {
var result = [String]()
for i in 0..<lst.count {
let count = lst[i].filter { $0 == "1" || $0 == "3" || $0 == "5" || $0 == "7" || $0 == "9" }.count
result.append("the number of odd elements \(count)n the str\(i+1)ng \(i+1) of the \(i+1)nput.")
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
Answer:
```swift
func oddCount(lst: [String]) -> [String] {
var result = [String]()
for i in 0..<lst.count {
let count = lst[i].filter { $0 == "1" || $0 == "3" || $0 == "5" || $0 == "7" || $0 == "9" }.count
result.append("the number of odd elements \(count)n the str\(i+1)ng \(i+1) of the \(i+1)nput.")
}
return result
}
``` // XCTAssertTrue failedfunc oddCount(lst: [String]) -> [String] {
return lst.map { str in
let count = str.filter { $0.isdigit && Int($0)! % 2 == 1 }.count
return "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
Answer:
```swift
func oddCount(lst: [String]) -> [String] {
return lst.map { str in
let count = str.filter { $0.isdigit && Int($0)! % 2 == 1 }.count
return "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
}
}
```let count = str.filter { $0.isdigit && Int($0)! % 2 == 1 }.count // trailing closure passed to parameter of type 'Predicate<String.Element>' (aka 'Predicate<Character>') that does not accept a closurefunc oddCount(lst: [String]) -> [String] {
return lst.map { str in
let count = str.filter { $0.isdigit && Int($0)! % 2 == 1 }.count
return "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
Answer:
```swift
func oddCount(lst: [String]) -> [String] {
return lst.map { str in
let count = str.filter { $0.isdigit && Int($0)! % 2 == 1 }.count
return "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
}
}
```let count = str.filter { $0.isdigit && Int($0)! % 2 == 1 }.count // trailing closure passed to parameter of type 'Predicate<String.Element>' (aka 'Predicate<Character>') that does not accept a closurefunc oddCount(lst: [String]) -> [String] {
var result = [String]()
for (index, string) in lst.enumerated() {
let count = string.filter { $0.isOdd }.count
let formattedString = "the number of odd elements \(count)n the str\(index+1)ng \(index+1) of the \(index+1)nput."
result.append(formattedString)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
Answer:
```swift
func oddCount(lst: [String]) -> [String] {
var result = [String]()
for (index, string) in lst.enumerated() {
let count = string.filter { $0.isOdd }.count
let formattedString = "the number of odd elements \(count)n the str\(index+1)ng \(index+1) of the \(index+1)nput."
result.append(formattedString)
}
return result
}
```let count = string.filter { $0.isOdd }.count // value of type 'String.Element' (aka 'Character') has no member 'isOdd'func minSubArraySum(nums: [Int]) -> Int {
var minSum = Int.max
var currentSum = 0
for num in nums {
currentSum += num
minSum = min(minSum, currentSum)
currentSum = max(currentSum, 0)
}
return minSum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
Answer:
```swift
func minSubArraySum(nums: [Int]) -> Int {
var minSum = Int.max
var currentSum = 0
for num in nums {
currentSum += num
minSum = min(minSum, currentSum)
currentSum = max(currentSum, 0)
}
return minSum
}
``` // XCTAssertTrue failedfunc minSubArraySum(nums: [Int]) -> Int {
var minSum = Int.max
var currentSum = 0
for num in nums {
currentSum += num
minSum = min(minSum, currentSum)
currentSum = max(currentSum, 0)
}
return minSum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
Answer:
```swift
func minSubArraySum(nums: [Int]) -> Int {
var minSum = Int.max
var currentSum = 0
for num in nums {
currentSum += num
minSum = min(minSum, currentSum)
currentSum = max(currentSum, 0)
}
return minSum
}
``` // XCTAssertTrue failedfunc minSubArraySum(nums: [Int]) -> Int {
var minSum = Int.max
var currentSum = 0
var currentMin = 0
for num in nums {
currentSum += num
currentMin = min(currentMin, currentSum)
minSum = min(minSum, currentSum - currentMin)
}
return minSum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
Answer:
```swift
func minSubArraySum(nums: [Int]) -> Int {
var minSum = Int.max
var currentSum = 0
var currentMin = 0
for num in nums {
currentSum += num
currentMin = min(currentMin, currentSum)
minSum = min(minSum, currentSum - currentMin)
}
return minSum
}
``` // XCTAssertTrue failedfunc minSubArraySum(nums: [Int]) -> Int {
var minSum = Int.max
var currentSum = 0
for num in nums {
currentSum += num
minSum = min(minSum, currentSum)
currentSum = max(currentSum, 0)
}
return minSum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
Answer:
```swift
func minSubArraySum(nums: [Int]) -> Int {
var minSum = Int.max
var currentSum = 0
for num in nums {
currentSum += num
minSum = min(minSum, currentSum)
currentSum = max(currentSum, 0)
}
return minSum
}
``` // XCTAssertTrue failedfunc minSubArraySum(nums: [Int]) -> Int {
var minSum = Int.max
var currentSum = 0
var start = 0
var end = 0
while end < nums.count {
currentSum += nums[end]
end += 1
while currentSum < 0 {
currentSum -= nums[start]
start += 1
}
minSum = min(minSum, currentSum)
}
return minSum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
Answer:
```swift
func minSubArraySum(nums: [Int]) -> Int {
var minSum = Int.max
var currentSum = 0
var start = 0
var end = 0
while end < nums.count {
currentSum += nums[end]
end += 1
while currentSum < 0 {
currentSum -= nums[start]
start += 1
}
minSum = min(minSum, currentSum)
}
return minSum
}
``` // XCTAssertTrue failedfunc minSubArraySum(nums: [Int]) -> Int {
var minSum = Int.max
var currentSum = 0
var windowStart = 0
var windowEnd = 0
while windowEnd < nums.count {
currentSum += nums[windowEnd]
windowEnd += 1
while currentSum < 0 {
currentSum -= nums[windowStart]
windowStart += 1
}
minSum = min(minSum, currentSum)
}
return minSum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
Answer:
```swift
func minSubArraySum(nums: [Int]) -> Int {
var minSum = Int.max
var currentSum = 0
var windowStart = 0
var windowEnd = 0
while windowEnd < nums.count {
currentSum += nums[windowEnd]
windowEnd += 1
while currentSum < 0 {
currentSum -= nums[windowStart]
windowStart += 1
}
minSum = min(minSum, currentSum)
}
return minSum
}
``` // XCTAssertTrue failedfunc minSubArraySum(nums: [Int]) -> Int {
var minSum = Int.max
var currentSum = 0
for num in nums {
currentSum += num
minSum = min(minSum, currentSum)
currentSum = max(currentSum, 0)
}
return minSum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
Answer:
```swift
func minSubArraySum(nums: [Int]) -> Int {
var minSum = Int.max
var currentSum = 0
for num in nums {
currentSum += num
minSum = min(minSum, currentSum)
currentSum = max(currentSum, 0)
}
return minSum
}
``` // XCTAssertTrue failedfunc minSubArraySum(nums: [Int]) -> Int {
var minSum = Int.max
var currentSum = 0
var currentStart = 0
var currentEnd = 0
for i in 0..<nums.count {
currentSum += nums[i]
if currentSum < minSum {
minSum = currentSum
currentStart = currentEnd
currentEnd = i
}
if currentSum > 0 {
currentSum = 0
currentEnd = i
}
}
return nums.prefix(currentStart).reduce(0, +) + minSum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
Answer:
```swift
func minSubArraySum(nums: [Int]) -> Int {
var minSum = Int.max
var currentSum = 0
var currentStart = 0
var currentEnd = 0
for i in 0..<nums.count {
currentSum += nums[i]
if currentSum < minSum {
minSum = currentSum
currentStart = currentEnd
currentEnd = i
}
if currentSum > 0 {
currentSum = 0
currentEnd = i
}
}
return nums.prefix(currentStart).reduce(0, +) + minSum
}
``` // XCTAssertTrue failedfunc minSubArraySum(nums: [Int]) -> Int {
var minSum = Int.max
var currentSum = 0
var currentMin = 0
for num in nums {
currentSum += num
currentMin = min(currentMin, currentSum)
minSum = min(minSum, currentSum - currentMin)
}
return minSum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
Answer:
```swift
func minSubArraySum(nums: [Int]) -> Int {
var minSum = Int.max
var currentSum = 0
var currentMin = 0
for num in nums {
currentSum += num
currentMin = min(currentMin, currentSum)
minSum = min(minSum, currentSum - currentMin)
}
return minSum
}
``` // XCTAssertTrue failedfunc minSubArraySum(nums: [Int]) -> Int {
var minSum = Int.max
var currentSum = 0
var currentStart = 0
var currentEnd = 0
for i in 0..<nums.count {
currentSum += nums[i]
if currentSum < minSum {
minSum = currentSum
currentStart = currentEnd
currentEnd = i
}
if currentSum > 0 {
currentSum = 0
currentEnd = i
}
}
return nums[currentStart..<currentEnd].reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
Answer:
```swift
func minSubArraySum(nums: [Int]) -> Int {
var minSum = Int.max
var currentSum = 0
var currentStart = 0
var currentEnd = 0
for i in 0..<nums.count {
currentSum += nums[i]
if currentSum < minSum {
minSum = currentSum
currentStart = currentEnd
currentEnd = i
}
if currentSum > 0 {
currentSum = 0
currentEnd = i
}
}
return nums[currentStart..<currentEnd].reduce(0, +)
}
``` // XCTAssertTrue failedfunc maxFill(grid: [[Int]], capacity: Int) -> Int {
var result = 0
var row = 0
var col = 0
var total = 0
while row < grid.count, col < grid[row].count {
let well = grid[row][col]
if well == 1 {
total += 1
}
if total > capacity {
result += 1
total -= 1
}
col += 1
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
Answer:
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
var result = 0
var row = 0
var col = 0
var total = 0
while row < grid.count, col < grid[row].count {
let well = grid[row][col]
if well == 1 {
total += 1
}
if total > capacity {
result += 1
total -= 1
}
col += 1
}
return result
}
```var row = 0 // variable 'row' was never mutated; consider changing to 'let' constant // XCTAssertTrue failedfunc maxFill(grid: [[Int]], capacity: Int) -> Int {
var result = 0
var row = 0
var col = 0
var total = 0
while row < grid.count, col < grid[row].count {
let water = min(capacity, grid[row][col])
total += water
grid[row][col] -= water
if grid[row][col] == 0 {
col += 1
}
result += water
row += 1
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
Answer:
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
var result = 0
var row = 0
var col = 0
var total = 0
while row < grid.count, col < grid[row].count {
let water = min(capacity, grid[row][col])
total += water
grid[row][col] -= water
if grid[row][col] == 0 {
col += 1
}
result += water
row += 1
}
return result
}
```grid[row][col] -= water // left side of mutating operator isn't mutable: 'grid' is a 'let' constantfunc maxFill(grid: [[Int]], capacity: Int) -> Int {
var result = 0
var row = 0
var col = 0
var total = 0
while row < grid.count {
while col < grid[row].count {
if grid[row][col] == 1 {
total += 1
if total > capacity {
result += 1
total -= 1
}
}
col += 1
}
total = 0
row += 1
col = 0
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
Answer:
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
var result = 0
var row = 0
var col = 0
var total = 0
while row < grid.count {
while col < grid[row].count {
if grid[row][col] == 1 {
total += 1
if total > capacity {
result += 1
total -= 1
}
}
col += 1
}
total = 0
row += 1
col = 0
}
return result
}
``` // XCTAssertTrue failedfunc maxFill(grid: [[Int]], capacity: Int) -> Int {
guard!grid.isEmpty else {
return 0
}
var result = 0
var queue = [grid.count - 1]
while!queue.isEmpty {
let row = queue.removeFirst()
for col in 0..<grid[row].count {
if grid[row][col] == 1 {
let newRow = row - 1
let newCol = col - 1
if newRow >= 0 && newCol >= 0 {
grid[newRow][newCol] += 1
queue.append(newRow)
}
if newRow >= 0 && newCol < grid[row].count - 1 {
grid[newRow][newCol + 1] += 1
queue.append(newRow)
}
if newRow < grid.count - 1 && newCol >= 0 {
grid[newRow + 1][newCol] += 1
queue.append(newRow + 1)
}
if newRow < grid.count - 1 && newCol < grid[row].count - 1 {
grid[newRow + 1][newCol + 1] += 1
queue.append(newRow + 1)
}
}
}
result += 1
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
Answer:
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
guard!grid.isEmpty else {
return 0
}
var result = 0
var queue = [grid.count - 1]
while!queue.isEmpty {
let row = queue.removeFirst()
for col in 0..<grid[row].count {
if grid[row][col] == 1 {
let newRow = row - 1
let newCol = col - 1
if newRow >= 0 && newCol >= 0 {
grid[newRow][newCol] += 1
queue.append(newRow)
}
if newRow >= 0 && newCol < grid[row].count - 1 {
grid[newRow][newCol + 1] += 1
queue.append(newRow)
}
if newRow < grid.count - 1 && newCol >= 0 {
grid[newRow + 1][newCol] += 1
queue.append(newRow + 1)
}
if newRow < grid.count - 1 && newCol < grid[row].count - 1 {
grid[newRow + 1][newCol + 1] += 1
queue.append(newRow + 1)
}
}
}
result += 1
}
return result
}
```guard!grid.isEmpty else { // expected expression, var, let or case in 'guard' conditionwhile!queue.isEmpty { // expected expression, var, or let in 'while' conditionfunc maxFill(grid: [[Int]], capacity: Int) -> Int {
var result = 0
var row = 0
var col = 0
var water = 0
while row < grid.count, col < grid[row].count {
if grid[row][col] == 1 {
water += 1
}
if water > capacity {
result += 1
water -= capacity
}
col += 1
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
Answer:
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
var result = 0
var row = 0
var col = 0
var water = 0
while row < grid.count, col < grid[row].count {
if grid[row][col] == 1 {
water += 1
}
if water > capacity {
result += 1
water -= capacity
}
col += 1
}
return result
}
```var row = 0 // variable 'row' was never mutated; consider changing to 'let' constant // XCTAssertTrue failedfunc maxFill(grid: [[Int]], capacity: Int) -> Int {
var result = 0
var row = 0
var col = 0
var total = 0
while row < grid.count, col < grid[row].count {
if grid[row][col] == 1 {
total += 1
}
if total > capacity {
total -= 1
row += 1
} else {
col += 1
}
result += 1
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
Answer:
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
var result = 0
var row = 0
var col = 0
var total = 0
while row < grid.count, col < grid[row].count {
if grid[row][col] == 1 {
total += 1
}
if total > capacity {
total -= 1
row += 1
} else {
col += 1
}
result += 1
}
return result
}
``` // XCTAssertTrue failedfunc maxFill(grid: [[Int]], capacity: Int) -> Int {
var result = 0
var row = 0
var col = 0
var total = 0
while row < grid.count, col < grid[0].count {
if total + grid[row][col] <= capacity {
total += grid[row][col]
col += 1
} else {
result += 1
total = grid[row][col]
col = 0
row += 1
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
Answer:
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
var result = 0
var row = 0
var col = 0
var total = 0
while row < grid.count, col < grid[0].count {
if total + grid[row][col] <= capacity {
total += grid[row][col]
col += 1
} else {
result += 1
total = grid[row][col]
col = 0
row += 1
}
}
return result
}
``` // XCTAssertTrue failedfunc maxFill(grid: [[Int]], capacity: Int) -> Int {
var result = 0
var row = 0
var col = 0
var total = 0
while row < grid.count, col < grid[0].count {
let well = grid[row][col]
if well == 1 {
total += 1
if total > capacity {
result += 1
total = 0
}
}
col += 1
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
Answer:
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
var result = 0
var row = 0
var col = 0
var total = 0
while row < grid.count, col < grid[0].count {
let well = grid[row][col]
if well == 1 {
total += 1
if total > capacity {
result += 1
total = 0
}
}
col += 1
}
return result
}
```var row = 0 // variable 'row' was never mutated; consider changing to 'let' constant // XCTAssertTrue failedfunc maxFill(grid: [[Int]], capacity: Int) -> Int {
var result = 0
var row = 0
var col = 0
var water = 0
while row < grid.count, col < grid[0].count {
let well = grid[row][col]
if well == 1 {
water += 1
}
if water > capacity {
result += 1
water -= 1
}
col += 1
if col == grid[0].count {
col = 0
row += 1
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
Answer:
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
var result = 0
var row = 0
var col = 0
var water = 0
while row < grid.count, col < grid[0].count {
let well = grid[row][col]
if well == 1 {
water += 1
}
if water > capacity {
result += 1
water -= 1
}
col += 1
if col == grid[0].count {
col = 0
row += 1
}
}
return result
}
``` // XCTAssertTrue failedfunc maxFill(grid: [[Int]], capacity: Int) -> Int {
var result = 0
var row = 0
var col = 0
var water = 0
while row < grid.count, col < grid[0].count {
let well = grid[row][col]
if well == 1 {
water += 1
}
if water > capacity {
result += 1
water -= capacity
}
col += 1
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
Answer:
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
var result = 0
var row = 0
var col = 0
var water = 0
while row < grid.count, col < grid[0].count {
let well = grid[row][col]
if well == 1 {
water += 1
}
if water > capacity {
result += 1
water -= capacity
}
col += 1
}
return result
}
```var row = 0 // variable 'row' was never mutated; consider changing to 'let' constant // XCTAssertTrue failedfunc sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (lhs, rhs) -> Bool in
let l = countOnes(in: lhs)
let r = countOnes(in: rhs)
return l < r || (l == r && lhs < rhs)
}
return sorted
}
func countOnes(in number: Int) -> Int {
var count = 0
while number > 0 {
if number & 1 == 1 {
count += 1
}
number >>= 1
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
Answer:
```swift
func sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (lhs, rhs) -> Bool in
let l = countOnes(in: lhs)
let r = countOnes(in: rhs)
return l < r || (l == r && lhs < rhs)
}
return sorted
}
func countOnes(in number: Int) -> Int {
var count = 0
while number > 0 {
if number & 1 == 1 {
count += 1
}
number >>= 1
}
return count
}
```number >>= 1 // left side of mutating operator isn't mutable: 'number' is a 'let' constantfunc sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (lhs, rhs) -> Bool in
let l = countOnes(in: lhs)
let r = countOnes(in: rhs)
return l < r || (l == r && lhs < rhs)
}
return sorted
}
func countOnes(in number: Int) -> Int {
var count = 0
while number > 0 {
if number % 2 == 1 {
count += 1
}
number /= 2
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
Answer:
```swift
func sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (lhs, rhs) -> Bool in
let l = countOnes(in: lhs)
let r = countOnes(in: rhs)
return l < r || (l == r && lhs < rhs)
}
return sorted
}
func countOnes(in number: Int) -> Int {
var count = 0
while number > 0 {
if number % 2 == 1 {
count += 1
}
number /= 2
}
return count
}
```number /= 2 // left side of mutating operator isn't mutable: 'number' is a 'let' constantfunc sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (lhs, rhs) -> Bool in
let l = countOnes(in: lhs)
let r = countOnes(in: rhs)
return l < r || (l == r && lhs < rhs)
}
return sorted
}
func countOnes(in n: Int) -> Int {
var count = 0
while n > 0 {
n &= n - 1
count += 1
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
Answer:
```swift
func sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (lhs, rhs) -> Bool in
let l = countOnes(in: lhs)
let r = countOnes(in: rhs)
return l < r || (l == r && lhs < rhs)
}
return sorted
}
func countOnes(in n: Int) -> Int {
var count = 0
while n > 0 {
n &= n - 1
count += 1
}
return count
}
```n &= n - 1 // left side of mutating operator isn't mutable: 'n' is a 'let' constantfunc sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { a, b in
let aCount = countOnes(a)
let bCount = countOnes(b)
return aCount < bCount || (aCount == bCount && a < b)
}
return sorted
}
func countOnes(num: Int) -> Int {
var count = 0
var n = num
while n > 0 {
count += n & 1
n >>= 1
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
Answer:
```swift
func sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { a, b in
let aCount = countOnes(a)
let bCount = countOnes(b)
return aCount < bCount || (aCount == bCount && a < b)
}
return sorted
}
func countOnes(num: Int) -> Int {
var count = 0
var n = num
while n > 0 {
count += n & 1
n >>= 1
}
return count
}
```let aCount = countOnes(a) // missing argument label 'num:' in callfunc sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (lhs, rhs) -> Bool in
let l = countOnes(in: lhs)
let r = countOnes(in: rhs)
return l < r || (l == r && lhs < rhs)
}
return sorted
}
func countOnes(in n: Int) -> Int {
var count = 0
while n > 0 {
if n % 2 == 1 {
count += 1
}
n /= 2
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
Answer:
```swift
func sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (lhs, rhs) -> Bool in
let l = countOnes(in: lhs)
let r = countOnes(in: rhs)
return l < r || (l == r && lhs < rhs)
}
return sorted
}
func countOnes(in n: Int) -> Int {
var count = 0
while n > 0 {
if n % 2 == 1 {
count += 1
}
n /= 2
}
return count
}
```n /= 2 // left side of mutating operator isn't mutable: 'n' is a 'let' constantfunc sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (lhs, rhs) -> Bool in
let l = countOnes(in: lhs)
let r = countOnes(in: rhs)
return l < r || (l == r && lhs < rhs)
}
return sorted
}
func countOnes(in n: Int) -> Int {
var count = 0
while n > 0 {
n &= (n - 1)
count += 1
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
Answer:
```swift
func sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (lhs, rhs) -> Bool in
let l = countOnes(in: lhs)
let r = countOnes(in: rhs)
return l < r || (l == r && lhs < rhs)
}
return sorted
}
func countOnes(in n: Int) -> Int {
var count = 0
while n > 0 {
n &= (n - 1)
count += 1
}
return count
}
```n &= (n - 1) // left side of mutating operator isn't mutable: 'n' is a 'let' constantfunc sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted {
let a = $0.description.count
let b = $1.description.count
if a!= b {
return a < b
}
return $0 < $1
}
return sorted
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
Answer:
```swift
func sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted {
let a = $0.description.count
let b = $1.description.count
if a!= b {
return a < b
}
return $0 < $1
}
return sorted
}
```if a!= b { // cannot force unwrap value of non-optional type 'Int'if a!= b { // use of '=' in a boolean context, did you mean '=='?if a!= b { // '=' must have consistent whitespace on both sidesfunc sortArray(arr: [Int]) -> [Int] {
let onesCount = arr.map { Int($0).description.count(where: ==("1")) }
let sortedIndices = onesCount.indices.sorted { arr[indices[0]] < arr[indices[1]] }
return sortedIndices.map { arr[$0] }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
Answer:
```swift
func sortArray(arr: [Int]) -> [Int] {
let onesCount = arr.map { Int($0).description.count(where: ==("1")) }
let sortedIndices = onesCount.indices.sorted { arr[indices[0]] < arr[indices[1]] }
return sortedIndices.map { arr[$0] }
}
```let onesCount = arr.map { Int($0).description.count(where: ==("1")) } // '==' is not a prefix unary operatorlet onesCount = arr.map { Int($0).description.count(where: ==("1")) } // cannot call value of non-function type 'Int'let sortedIndices = onesCount.indices.sorted { arr[indices[0]] < arr[indices[1]] } // cannot find 'indices' in scopelet sortedIndices = onesCount.indices.sorted { arr[indices[0]] < arr[indices[1]] } // cannot find 'indices' in scopefunc sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (lhs, rhs) -> Bool in
let l = countOnes(in: lhs)
let r = countOnes(in: rhs)
return l < r || (l == r && lhs < rhs)
}
return sorted
}
func countOnes(in n: Int) -> Int {
var count = 0
while n > 0 {
n &= (n - 1)
count += 1
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
Answer:
```swift
func sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (lhs, rhs) -> Bool in
let l = countOnes(in: lhs)
let r = countOnes(in: rhs)
return l < r || (l == r && lhs < rhs)
}
return sorted
}
func countOnes(in n: Int) -> Int {
var count = 0
while n > 0 {
n &= (n - 1)
count += 1
}
return count
}
```n &= (n - 1) // left side of mutating operator isn't mutable: 'n' is a 'let' constantfunc sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { a, b in
let aCount = countOnes(in: a)
let bCount = countOnes(in: b)
return aCount < bCount || (aCount == bCount && a < b)
}
return sorted
}
func countOnes(in number: Int) -> Int {
var count = 0
var n = number
while n > 0 {
if n % 2 == 1 {
count += 1
}
n /= 2
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
Answer:
```swift
func sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { a, b in
let aCount = countOnes(in: a)
let bCount = countOnes(in: b)
return aCount < bCount || (aCount == bCount && a < b)
}
return sorted
}
func countOnes(in number: Int) -> Int {
var count = 0
var n = number
while n > 0 {
if n % 2 == 1 {
count += 1
}
n /= 2
}
return count
}
``` // XCTAssertTrue failedfunc selectWords(s: String, n: Int) -> [String] {
let consonants = "bcdfghjklmnpqrstvwxyz".filter { s.contains($0) }
var result = [String]()
var currentWord = ""
for char in s {
if consonants.contains(char) {
currentWord.append(char)
} else {
if currentWord.count == n {
result.append(currentWord)
}
currentWord = ""
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
Answer:
```swift
func selectWords(s: String, n: Int) -> [String] {
let consonants = "bcdfghjklmnpqrstvwxyz".filter { s.contains($0) }
var result = [String]()
var currentWord = ""
for char in s {
if consonants.contains(char) {
currentWord.append(char)
} else {
if currentWord.count == n {
result.append(currentWord)
}
currentWord = ""
}
}
return result
}
``` // XCTAssertTrue failedfunc selectWords(s: String, n: Int) -> [String] {
let consonants = "bcdfghjklmnpqrstvwxyz".filter { s.contains($0) }
var result = [String]()
for word in s.components(separatedBy: " ") {
let consonantsCount = word.filter { consonants.contains($0) }.count
if consonantsCount == n {
result.append(word)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
Answer:
```swift
func selectWords(s: String, n: Int) -> [String] {
let consonants = "bcdfghjklmnpqrstvwxyz".filter { s.contains($0) }
var result = [String]()
for word in s.components(separatedBy: " ") {
let consonantsCount = word.filter { consonants.contains($0) }.count
if consonantsCount == n {
result.append(word)
}
}
return result
}
``` // XCTAssertTrue failedfunc selectWords(s: String, n: Int) -> [String] {
let consonants = "bcdfghjklmnpqrstvwxyz".filter { s.contains($0) }
var result = [String]()
for word in s.components(separatedBy: " ") {
let consonantCount = word.filter { consonants.contains($0) }.count
if consonantCount == n {
result.append(word)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
Answer:
```swift
func selectWords(s: String, n: Int) -> [String] {
let consonants = "bcdfghjklmnpqrstvwxyz".filter { s.contains($0) }
var result = [String]()
for word in s.components(separatedBy: " ") {
let consonantCount = word.filter { consonants.contains($0) }.count
if consonantCount == n {
result.append(word)
}
}
return result
}
``` // XCTAssertTrue failedfunc selectWords(s: String, n: Int) -> [String] {
let consonants = "bcdfghjklmnpqrstvwxyz".filter { s.contains($0) }
var result = [String]()
var currentWord = ""
for char in s {
if consonants.contains(char) {
currentWord.append(char)
} else {
if currentWord.count == n {
result.append(currentWord)
}
currentWord = ""
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
Answer:
```swift
func selectWords(s: String, n: Int) -> [String] {
let consonants = "bcdfghjklmnpqrstvwxyz".filter { s.contains($0) }
var result = [String]()
var currentWord = ""
for char in s {
if consonants.contains(char) {
currentWord.append(char)
} else {
if currentWord.count == n {
result.append(currentWord)
}
currentWord = ""
}
}
return result
}
``` // XCTAssertTrue failedfunc selectWords(s: String, n: Int) -> [String] {
let consonants = "bcdfghjklmnpqrstvwxyz"
var result = [String]()
var currentWord = ""
var currentCount = 0
for character in s {
if consonants.contains(character) {
currentWord.append(character)
currentCount += 1
} else {
if currentCount == n {
result.append(currentWord)
}
currentWord = ""
currentCount = 0
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
Answer:
```swift
func selectWords(s: String, n: Int) -> [String] {
let consonants = "bcdfghjklmnpqrstvwxyz"
var result = [String]()
var currentWord = ""
var currentCount = 0
for character in s {
if consonants.contains(character) {
currentWord.append(character)
currentCount += 1
} else {
if currentCount == n {
result.append(currentWord)
}
currentWord = ""
currentCount = 0
}
}
return result
}
``` // XCTAssertTrue failedfunc selectWords(s: String, n: Int) -> [String] {
let consonants = "bcdfghjklmnpqrstvwxyz".filter { s.contains($0) }
var result = [String]()
var currentWord = ""
for char in s {
if consonants.contains(char) {
currentWord.append(char)
if currentWord.count == n {
result.append(currentWord)
currentWord = ""
}
} else {
currentWord = ""
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
Answer:
```swift
func selectWords(s: String, n: Int) -> [String] {
let consonants = "bcdfghjklmnpqrstvwxyz".filter { s.contains($0) }
var result = [String]()
var currentWord = ""
for char in s {
if consonants.contains(char) {
currentWord.append(char)
if currentWord.count == n {
result.append(currentWord)
currentWord = ""
}
} else {
currentWord = ""
}
}
return result
}
``` // XCTAssertTrue failedfunc selectWords(s: String, n: Int) -> [String] {
let consonants = "bcdfghjklmnpqrstvwxyz"
var words = [String]()
var currentWord = ""
var currentConsonants = 0
for character in s {
if character.isLetter {
currentWord.append(character)
if consonants.contains(character.lowercased()) {
currentConsonants += 1
}
} else {
if currentConsonants == n {
words.append(currentWord)
}
currentWord = ""
currentConsonants = 0
}
}
return words
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
Answer:
```swift
func selectWords(s: String, n: Int) -> [String] {
let consonants = "bcdfghjklmnpqrstvwxyz"
var words = [String]()
var currentWord = ""
var currentConsonants = 0
for character in s {
if character.isLetter {
currentWord.append(character)
if consonants.contains(character.lowercased()) {
currentConsonants += 1
}
} else {
if currentConsonants == n {
words.append(currentWord)
}
currentWord = ""
currentConsonants = 0
}
}
return words
}
``` // XCTAssertTrue failedfunc selectWords(s: String, n: Int) -> [String] {
let consonants = ["b", "c", "d", "f", "g", "h", "j", "k", "l", "m", "n", "p", "q", "r", "s", "t", "v", "w", "x", "y", "z"]
var result = [String]()
let words = s.components(separatedBy: " ")
for word in words {
var count = 0
for char in word {
if consonants.contains(String(char).lowercased()) {
count += 1
}
}
if count == n {
result.append(word)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
Answer:
```swift
func selectWords(s: String, n: Int) -> [String] {
let consonants = ["b", "c", "d", "f", "g", "h", "j", "k", "l", "m", "n", "p", "q", "r", "s", "t", "v", "w", "x", "y", "z"]
var result = [String]()
let words = s.components(separatedBy: " ")
for word in words {
var count = 0
for char in word {
if consonants.contains(String(char).lowercased()) {
count += 1
}
}
if count == n {
result.append(word)
}
}
return result
}
```func selectWords(s: String, n: Int) -> [String] {
let consonants = "bcdfghjklmnpqrstvwxyz"
var result = [String]()
var currentWord = ""
var currentCount = 0
for char in s {
if consonants.contains(char) {
currentCount += 1
} else {
if currentCount == n {
result.append(currentWord)
}
currentWord = ""
currentCount = 0
}
currentWord.append(char)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
Answer:
```swift
func selectWords(s: String, n: Int) -> [String] {
let consonants = "bcdfghjklmnpqrstvwxyz"
var result = [String]()
var currentWord = ""
var currentCount = 0
for char in s {
if consonants.contains(char) {
currentCount += 1
} else {
if currentCount == n {
result.append(currentWord)
}
currentWord = ""
currentCount = 0
}
currentWord.append(char)
}
return result
}
``` // XCTAssertTrue failedfunc selectWords(s: String, n: Int) -> [String] {
let consonants = "bcdfghjklmnpqrstvwxyz".filter { s.contains($0) }
var result = [String]()
var currentWord = ""
for char in s {
if consonants.contains(char) {
currentWord.append(char)
} else {
if currentWord.count == n {
result.append(currentWord)
}
currentWord = ""
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
Answer:
```swift
func selectWords(s: String, n: Int) -> [String] {
let consonants = "bcdfghjklmnpqrstvwxyz".filter { s.contains($0) }
var result = [String]()
var currentWord = ""
for char in s {
if consonants.contains(char) {
currentWord.append(char)
} else {
if currentWord.count == n {
result.append(currentWord)
}
currentWord = ""
}
}
return result
}
``` // XCTAssertTrue failedfunc getClosestVowel(word: String) -> String {
let consonants = ["b", "c", "d", "f", "g", "h", "j", "k", "l", "m", "n", "p", "q", "r", "s", "t", "v", "w", "x", "y", "z"]
var result = ""
var index = 0
while index < word.count {
if consonants.contains(String(word[index])) {
index += 1
continue
}
let vowels = ["a", "e", "i", "o", "u"]
for vowel in vowels {
let vowelIndex = word.index(word.startIndex, offsetBy: index, limitedBy: word.endIndex)!
if String(word[vowelIndex]) == vowel {
result = vowel
break
}
}
break
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
Answer:
```swift
func getClosestVowel(word: String) -> String {
let consonants = ["b", "c", "d", "f", "g", "h", "j", "k", "l", "m", "n", "p", "q", "r", "s", "t", "v", "w", "x", "y", "z"]
var result = ""
var index = 0
while index < word.count {
if consonants.contains(String(word[index])) {
index += 1
continue
}
let vowels = ["a", "e", "i", "o", "u"]
for vowel in vowels {
let vowelIndex = word.index(word.startIndex, offsetBy: index, limitedBy: word.endIndex)!
if String(word[vowelIndex]) == vowel {
result = vowel
break
}
}
break
}
return result
}
```if consonants.contains(String(word[index])) { // 'subscript(_:)' is unavailable: cannot subscript String with an Int, use a String.Index instead.func getClosestVowel(word: String) -> String {
guard word.count > 1 else {
return ""
}
let consonants = word.filter {!$0.isVowel }
let consonantsCount = consonants.count
guard consonantsCount > 0 else {
return ""
}
let lastConsonant = consonants[consonantsCount - 1]
let lastConsonantIndex = word.firstIndex(of: lastConsonant)!
let vowels = word.filter { $0.isVowel }
let vowelsCount = vowels.count
guard vowelsCount > 0 else {
return ""
}
let firstVowel = vowels[0]
let firstVowelIndex = word.firstIndex(of: firstVowel)!
let firstVowelDistance = lastConsonantIndex - firstVowelIndex
let lastVowelDistance = word.count - lastConsonantIndex - 1
let closestVowelDistance = min(firstVowelDistance, lastVowelDistance)
let closestVowel = vowels[closestVowelDistance]
return closestVowel
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
Answer:
```swift
func getClosestVowel(word: String) -> String {
guard word.count > 1 else {
return ""
}
let consonants = word.filter {!$0.isVowel }
let consonantsCount = consonants.count
guard consonantsCount > 0 else {
return ""
}
let lastConsonant = consonants[consonantsCount - 1]
let lastConsonantIndex = word.firstIndex(of: lastConsonant)!
let vowels = word.filter { $0.isVowel }
let vowelsCount = vowels.count
guard vowelsCount > 0 else {
return ""
}
let firstVowel = vowels[0]
let firstVowelIndex = word.firstIndex(of: firstVowel)!
let firstVowelDistance = lastConsonantIndex - firstVowelIndex
let lastVowelDistance = word.count - lastConsonantIndex - 1
let closestVowelDistance = min(firstVowelDistance, lastVowelDistance)
let closestVowel = vowels[closestVowelDistance]
return closestVowel
}
```let consonants = word.filter {!$0.isVowel } // trailing closure passed to parameter of type 'Predicate<String.Element>' (aka 'Predicate<Character>') that does not accept a closurelet vowels = word.filter { $0.isVowel } // value of type 'String.Element' (aka 'Character') has no member 'isVowel'func getClosestVowel(word: String) -> String {
let consonants = ["b", "c", "d", "f", "g", "h", "j", "k", "l", "m", "n", "p", "q", "r", "s", "t", "v", "w", "x", "y", "z"]
var closestVowel = ""
var currentVowel = ""
var isVowel = false
var isConsonant = false
var isFirstVowel = true
var isFirstConsonant = true
for letter in word {
if consonants.contains(letter) {
isConsonant = true
isFirstConsonant = false
} else if isConsonant {
isVowel = true
isFirstVowel = false
let index = consonants.firstIndex(of: letter)
if index!= nil {
let vowel = consonants[index! - 1]
let distance = abs(vowel.distance(to: letter))
if closestVowel == "" || distance < closestVowel.distance(to: letter) {
closestVowel = vowel
}
}
}
}
return closestVowel
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
Answer:
```swift
func getClosestVowel(word: String) -> String {
let consonants = ["b", "c", "d", "f", "g", "h", "j", "k", "l", "m", "n", "p", "q", "r", "s", "t", "v", "w", "x", "y", "z"]
var closestVowel = ""
var currentVowel = ""
var isVowel = false
var isConsonant = false
var isFirstVowel = true
var isFirstConsonant = true
for letter in word {
if consonants.contains(letter) {
isConsonant = true
isFirstConsonant = false
} else if isConsonant {
isVowel = true
isFirstVowel = false
let index = consonants.firstIndex(of: letter)
if index!= nil {
let vowel = consonants[index! - 1]
let distance = abs(vowel.distance(to: letter))
if closestVowel == "" || distance < closestVowel.distance(to: letter) {
closestVowel = vowel
}
}
}
}
return closestVowel
}
```if consonants.contains(letter) { // cannot convert value of type 'Character' to expected argument type 'String'let index = consonants.firstIndex(of: letter) // cannot convert value of type 'Character' to expected argument type 'String'if index!= nil { // '=' must have consistent whitespace on both sidesif index!= nil { // use of '=' in a boolean context, did you mean '=='?if closestVowel == "" || distance < closestVowel.distance(to: letter) { // cannot convert value of type 'Character' to expected argument type 'String.Index'if closestVowel == "" || distance < closestVowel.distance(to: letter) { // missing argument for parameter 'from' in callfunc getClosestVowel(word: String) -> String {
let consonants = ["b", "c", "d", "f", "g", "h", "j", "k", "l", "m", "n", "p", "q", "r", "s", "t", "v", "w", "x", "y", "z"]
var closestVowel = ""
var closestDistance = 100
var currentDistance = 0
var currentVowel = ""
for i in 0..<word.count {
let currentLetter = word[word.count - 1 - i]
if consonants.contains(currentLetter) {
currentDistance = 0
} else {
currentDistance += 1
}
if currentDistance < closestDistance {
closestDistance = currentDistance
closestVowel = currentLetter
}
}
return closestVowel
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
Answer:
```swift
func getClosestVowel(word: String) -> String {
let consonants = ["b", "c", "d", "f", "g", "h", "j", "k", "l", "m", "n", "p", "q", "r", "s", "t", "v", "w", "x", "y", "z"]
var closestVowel = ""
var closestDistance = 100
var currentDistance = 0
var currentVowel = ""
for i in 0..<word.count {
let currentLetter = word[word.count - 1 - i]
if consonants.contains(currentLetter) {
currentDistance = 0
} else {
currentDistance += 1
}
if currentDistance < closestDistance {
closestDistance = currentDistance
closestVowel = currentLetter
}
}
return closestVowel
}
```let currentLetter = word[word.count - 1 - i] // 'subscript(_:)' is unavailable: cannot subscript String with an Int, use a String.Index instead.if consonants.contains(currentLetter) { // cannot convert value of type 'Character' to expected argument type 'String'closestVowel = currentLetter // cannot assign value of type 'Character' to type 'String'func getClosestVowel(word: String) -> String {
let consonants = ["b", "c", "d", "f", "g", "h", "j", "k", "l", "m", "n", "p", "q", "r", "s", "t", "v", "w", "x", "y", "z"]
var result = ""
var index = 0
var isVowel = false
while index < word.count {
let currentChar = word[word.index(word.startIndex, offsetBy: index)]
if consonants.contains(currentChar) {
isVowel = false
} else {
isVowel = true
}
if isVowel {
let previousChar = word[word.index(word.startIndex, offsetBy: index - 1)]
let nextChar = word[word.index(word.startIndex, offsetBy: index + 1)]
if consonants.contains(previousChar) && consonants.contains(nextChar) {
result = currentChar
break
}
}
index += 1
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
Answer:
```swift
func getClosestVowel(word: String) -> String {
let consonants = ["b", "c", "d", "f", "g", "h", "j", "k", "l", "m", "n", "p", "q", "r", "s", "t", "v", "w", "x", "y", "z"]
var result = ""
var index = 0
var isVowel = false
while index < word.count {
let currentChar = word[word.index(word.startIndex, offsetBy: index)]
if consonants.contains(currentChar) {
isVowel = false
} else {
isVowel = true
}
if isVowel {
let previousChar = word[word.index(word.startIndex, offsetBy: index - 1)]
let nextChar = word[word.index(word.startIndex, offsetBy: index + 1)]
if consonants.contains(previousChar) && consonants.contains(nextChar) {
result = currentChar
break
}
}
index += 1
}
return result
}
```if consonants.contains(currentChar) { // cannot convert value of type 'Character' to expected argument type 'String'if consonants.contains(previousChar) && consonants.contains(nextChar) { // cannot convert value of type 'Character' to expected argument type 'String'if consonants.contains(previousChar) && consonants.contains(nextChar) { // cannot convert value of type 'Character' to expected argument type 'String'result = currentChar // cannot assign value of type 'Character' to type 'String'func getClosestVowel(word: String) -> String {
let consonants = ["b", "c", "d", "f", "g", "h", "j", "k", "l", "m", "n", "p", "q", "r", "s", "t", "v", "w", "x", "y", "z"]
var closestVowel = ""
var closestDistance = 0
for (index, character) in word.reversed().enumerated() {
if consonants.contains(character.lowercased()) {
let distance = index - closestDistance
if distance > 0 {
closestVowel = word[index]
closestDistance = index
}
}
}
return closestVowel
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
Answer:
```swift
func getClosestVowel(word: String) -> String {
let consonants = ["b", "c", "d", "f", "g", "h", "j", "k", "l", "m", "n", "p", "q", "r", "s", "t", "v", "w", "x", "y", "z"]
var closestVowel = ""
var closestDistance = 0
for (index, character) in word.reversed().enumerated() {
if consonants.contains(character.lowercased()) {
let distance = index - closestDistance
if distance > 0 {
closestVowel = word[index]
closestDistance = index
}
}
}
return closestVowel
}
```closestVowel = word[index] // cannot assign value of type 'Character' to type 'String'func getClosestVowel(word: String) -> String {
let consonants = ["b", "c", "d", "f", "g", "h", "j", "k", "l", "m", "n", "p", "q", "r", "s", "t", "v", "w", "x", "y", "z"]
var result = ""
var isVowel = false
var isConsonant = false
var isFirstVowel = true
var isLastVowel = false
var lastVowel = ""
for char in word {
if consonants.contains(String(char)) {
isConsonant = true
} else {
isConsonant = false
}
if isConsonant &&!isVowel {
isVowel = true
isFirstVowel = false
} else if isVowel &&!isConsonant {
isVowel = false
isLastVowel = true
}
if isVowel &&!isFirstVowel {
result = String(char)
break
}
}
if isLastVowel {
return result
} else {
return ""
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
Answer:
```swift
func getClosestVowel(word: String) -> String {
let consonants = ["b", "c", "d", "f", "g", "h", "j", "k", "l", "m", "n", "p", "q", "r", "s", "t", "v", "w", "x", "y", "z"]
var result = ""
var isVowel = false
var isConsonant = false
var isFirstVowel = true
var isLastVowel = false
var lastVowel = ""
for char in word {
if consonants.contains(String(char)) {
isConsonant = true
} else {
isConsonant = false
}
if isConsonant &&!isVowel {
isVowel = true
isFirstVowel = false
} else if isVowel &&!isConsonant {
isVowel = false
isLastVowel = true
}
if isVowel &&!isFirstVowel {
result = String(char)
break
}
}
if isLastVowel {
return result
} else {
return ""
}
}
```var isFirstVowel = true // variable 'isFirstVowel' was written to, but never readvar lastVowel = "" // initialization of variable 'lastVowel' was never used; consider replacing with assignment to '_' or removing itif isConsonant &&!isVowel { // expected '{' after 'if' condition} else if isVowel &&!isConsonant { // expected '{' after 'if' conditionif isVowel &&!isFirstVowel { // expected '{' after 'if' conditionfunc getClosestVowel(word: String) -> String {
let consonants = ["b", "c", "d", "f", "g", "h", "j", "k", "l", "m", "n", "p", "q", "r", "s", "t", "v", "w", "x", "y", "z"]
var result = ""
var index = 0
while index < word.count {
if consonants.contains(word[index]) {
index += 1
continue
}
if let vowel = vowels.first(where: { $0 == word[index] }) {
result = vowel
break
}
index += 1
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
Answer:
```swift
func getClosestVowel(word: String) -> String {
let consonants = ["b", "c", "d", "f", "g", "h", "j", "k", "l", "m", "n", "p", "q", "r", "s", "t", "v", "w", "x", "y", "z"]
var result = ""
var index = 0
while index < word.count {
if consonants.contains(word[index]) {
index += 1
continue
}
if let vowel = vowels.first(where: { $0 == word[index] }) {
result = vowel
break
}
index += 1
}
return result
}
```if consonants.contains(word[index]) { // cannot convert value of type 'Character' to expected argument type 'String'if let vowel = vowels.first(where: { $0 == word[index] }) { // cannot find 'vowels' in scopefunc getClosestVowel(word: String) -> String {
let consonants = ["b", "c", "d", "f", "g", "h", "j", "k", "l", "m", "n", "p", "q", "r", "s", "t", "v", "w", "x", "y", "z"]
var closestVowel = ""
var closestDistance = 0
for i in 0..<word.count {
let currentChar = word[word.count - 1 - i]
if consonants.contains(currentChar.lowercased()) {
let currentDistance = i
if currentDistance > closestDistance {
closestVowel = ""
closestDistance = currentDistance
}
} else if currentChar.lowercased() == "a" || currentChar.lowercased() == "e" || currentChar.lowercased() == "i" || currentChar.lowercased() == "o" || currentChar.lowercased() == "u" {
let currentDistance = i
if currentDistance > closestDistance {
closestVowel = String(currentChar)
closestDistance = currentDistance
}
}
}
return closestVowel
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
Answer:
```swift
func getClosestVowel(word: String) -> String {
let consonants = ["b", "c", "d", "f", "g", "h", "j", "k", "l", "m", "n", "p", "q", "r", "s", "t", "v", "w", "x", "y", "z"]
var closestVowel = ""
var closestDistance = 0
for i in 0..<word.count {
let currentChar = word[word.count - 1 - i]
if consonants.contains(currentChar.lowercased()) {
let currentDistance = i
if currentDistance > closestDistance {
closestVowel = ""
closestDistance = currentDistance
}
} else if currentChar.lowercased() == "a" || currentChar.lowercased() == "e" || currentChar.lowercased() == "i" || currentChar.lowercased() == "o" || currentChar.lowercased() == "u" {
let currentDistance = i
if currentDistance > closestDistance {
closestVowel = String(currentChar)
closestDistance = currentDistance
}
}
}
return closestVowel
}
```let currentChar = word[word.count - 1 - i] // 'subscript(_:)' is unavailable: cannot subscript String with an Int, use a String.Index instead.func getClosestVowel(word: String) -> String {
guard let first = word.first, let last = word.last else {
return ""
}
let consonants = word.filter {!$0.isVowel }
let consonantsCount = consonants.count
guard consonantsCount > 1 else {
return ""
}
let lastConsonantIndex = consonants.firstIndex(of: last)!
let firstConsonantIndex = consonants.firstIndex(of: first)!
let firstConsonantDistance = lastConsonantIndex - firstConsonantIndex
let lastConsonantDistance = word.count - firstConsonantIndex - 1
let firstConsonantVowelIndex = consonants.firstIndex(of: word[firstConsonantIndex])
let lastConsonantVowelIndex = consonants.firstIndex(of: word[lastConsonantIndex])
let firstConsonantVowel = firstConsonantVowelIndex.flatMap { consonants[$0] }
let lastConsonantVowel = lastConsonantVowelIndex.flatMap { consonants[$0] }
let firstConsonantVowelDistance = firstConsonantVowelIndex.flatMap { abs($0 - firstConsonantIndex) }
let lastConsonantVowelDistance = lastConsonantVowelIndex.flatMap { abs($0 - lastConsonantIndex) }
let closestVowel = firstConsonantVowel?? lastConsonantVowel
guard let closestVowelDistance = closestVowel.flatMap { abs($0 - firstConsonantIndex) } else {
return ""
}
return closestVowelDistance < firstConsonantDistance? firstConsonantVowel : lastConsonantVowel
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
Answer:
```swift
func getClosestVowel(word: String) -> String {
guard let first = word.first, let last = word.last else {
return ""
}
let consonants = word.filter {!$0.isVowel }
let consonantsCount = consonants.count
guard consonantsCount > 1 else {
return ""
}
let lastConsonantIndex = consonants.firstIndex(of: last)!
let firstConsonantIndex = consonants.firstIndex(of: first)!
let firstConsonantDistance = lastConsonantIndex - firstConsonantIndex
let lastConsonantDistance = word.count - firstConsonantIndex - 1
let firstConsonantVowelIndex = consonants.firstIndex(of: word[firstConsonantIndex])
let lastConsonantVowelIndex = consonants.firstIndex(of: word[lastConsonantIndex])
let firstConsonantVowel = firstConsonantVowelIndex.flatMap { consonants[$0] }
let lastConsonantVowel = lastConsonantVowelIndex.flatMap { consonants[$0] }
let firstConsonantVowelDistance = firstConsonantVowelIndex.flatMap { abs($0 - firstConsonantIndex) }
let lastConsonantVowelDistance = lastConsonantVowelIndex.flatMap { abs($0 - lastConsonantIndex) }
let closestVowel = firstConsonantVowel?? lastConsonantVowel
guard let closestVowelDistance = closestVowel.flatMap { abs($0 - firstConsonantIndex) } else {
return ""
}
return closestVowelDistance < firstConsonantDistance? firstConsonantVowel : lastConsonantVowel
}
```let consonants = word.filter {!$0.isVowel } // trailing closure passed to parameter of type 'Predicate<String.Element>' (aka 'Predicate<Character>') that does not accept a closurelet closestVowel = firstConsonantVowel?? lastConsonantVowel // consecutive statements on a line must be separated by ';'guard let closestVowelDistance = closestVowel.flatMap { abs($0 - firstConsonantIndex) } else { // expected 'else' after 'guard' conditionguard let closestVowelDistance = closestVowel.flatMap { abs($0 - firstConsonantIndex) } else { // consecutive statements on a line must be separated by ';'guard let closestVowelDistance = closestVowel.flatMap { abs($0 - firstConsonantIndex) } else { // cannot convert value of type 'Duration' to expected argument type 'Int32'guard let closestVowelDistance = closestVowel.flatMap { abs($0 - firstConsonantIndex) } else { // expected expressionguard let closestVowelDistance = closestVowel.flatMap { abs($0 - firstConsonantIndex) } else { // anonymous closure argument not contained in a closurereturn closestVowelDistance < firstConsonantDistance? firstConsonantVowel : lastConsonantVowel // consecutive statements on a line must be separated by ';'return closestVowelDistance < firstConsonantDistance? firstConsonantVowel : lastConsonantVowel // value of optional type 'Optional<_>' must be unwrapped to a value of type '_'return closestVowelDistance < firstConsonantDistance? firstConsonantVowel : lastConsonantVowel // consecutive statements on a line must be separated by ';'return closestVowelDistance < firstConsonantDistance? firstConsonantVowel : lastConsonantVowel // expected expressionreturn closestVowelDistance < firstConsonantDistance? firstConsonantVowel : lastConsonantVowel // cannot convert return expression of type 'Bool' to return type 'String'func matchParens(lst: [String]) -> String {
var stack = [Character]()
for str in lst {
for char in str {
if char == "(" {
stack.append(char)
} else {
if stack.isEmpty {
return "No"
}
stack.removeLast()
}
}
}
return stack.isEmpty? "Yes" : "No"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
Answer:
```swift
func matchParens(lst: [String]) -> String {
var stack = [Character]()
for str in lst {
for char in str {
if char == "(" {
stack.append(char)
} else {
if stack.isEmpty {
return "No"
}
stack.removeLast()
}
}
}
return stack.isEmpty? "Yes" : "No"
}
```return stack.isEmpty? "Yes" : "No" // expected expressionreturn stack.isEmpty? "Yes" : "No" // string literal is unusedreturn stack.isEmpty? "Yes" : "No" // cannot use optional chaining on non-optional value of type 'Bool'return stack.isEmpty? "Yes" : "No" // consecutive statements on a line must be separated by ';'return stack.isEmpty? "Yes" : "No" // consecutive statements on a line must be separated by ';'func matchParens(lst: [String]) -> String {
let stack = [Character]()
for str in lst {
for char in str {
switch char {
case "(":
stack.append(char)
case ")":
if stack.isEmpty || stack.last!= "(" {
return "No"
}
stack.removeLast()
default:
return "No"
}
}
}
return stack.isEmpty? "Yes" : "No"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
Answer:
```swift
func matchParens(lst: [String]) -> String {
let stack = [Character]()
for str in lst {
for char in str {
switch char {
case "(":
stack.append(char)
case ")":
if stack.isEmpty || stack.last!= "(" {
return "No"
}
stack.removeLast()
default:
return "No"
}
}
}
return stack.isEmpty? "Yes" : "No"
}
```stack.append(char) // cannot use mutating member on immutable value: 'stack' is a 'let' constantif stack.isEmpty || stack.last!= "(" { // expression is not assignable: '||' returns immutable valueif stack.isEmpty || stack.last!= "(" { // cannot convert value of type 'Character' to expected argument type 'Bool'if stack.isEmpty || stack.last!= "(" { // '=' must have consistent whitespace on both sidesif stack.isEmpty || stack.last!= "(" { // use of '=' in a boolean context, did you mean '=='?stack.removeLast() // cannot use mutating member on immutable value: 'stack' is a 'let' constantreturn stack.isEmpty? "Yes" : "No" // consecutive statements on a line must be separated by ';'return stack.isEmpty? "Yes" : "No" // cannot use optional chaining on non-optional value of type 'Bool'return stack.isEmpty? "Yes" : "No" // consecutive statements on a line must be separated by ';'return stack.isEmpty? "Yes" : "No" // expected expressionreturn stack.isEmpty? "Yes" : "No" // string literal is unusedfunc matchParens(lst: [String]) -> String {
var stack = [Character]()
for str in lst {
for char in str {
if char == "(" {
stack.append(char)
} else {
if stack.isEmpty || stack.last!= "(" {
return "No"
}
stack.removeLast()
}
}
}
return stack.isEmpty? "Yes" : "No"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
Answer:
```swift
func matchParens(lst: [String]) -> String {
var stack = [Character]()
for str in lst {
for char in str {
if char == "(" {
stack.append(char)
} else {
if stack.isEmpty || stack.last!= "(" {
return "No"
}
stack.removeLast()
}
}
}
return stack.isEmpty? "Yes" : "No"
}
```if stack.isEmpty || stack.last!= "(" { // cannot convert value of type 'Character' to expected argument type 'Bool'if stack.isEmpty || stack.last!= "(" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.last!= "(" { // expression is not assignable: '||' returns immutable valueif stack.isEmpty || stack.last!= "(" { // '=' must have consistent whitespace on both sidesreturn stack.isEmpty? "Yes" : "No" // expected expressionreturn stack.isEmpty? "Yes" : "No" // string literal is unusedreturn stack.isEmpty? "Yes" : "No" // cannot use optional chaining on non-optional value of type 'Bool'return stack.isEmpty? "Yes" : "No" // consecutive statements on a line must be separated by ';'return stack.isEmpty? "Yes" : "No" // consecutive statements on a line must be separated by ';'func matchParens(lst: [String]) -> String {
let stack = [Character]()
for str in lst {
for char in str {
if char == "(" {
stack.append(char)
} else {
if stack.isEmpty || stack.last!= "(" {
return "No"
}
stack.removeLast()
}
}
}
return stack.isEmpty? "Yes" : "No"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
Answer:
```swift
func matchParens(lst: [String]) -> String {
let stack = [Character]()
for str in lst {
for char in str {
if char == "(" {
stack.append(char)
} else {
if stack.isEmpty || stack.last!= "(" {
return "No"
}
stack.removeLast()
}
}
}
return stack.isEmpty? "Yes" : "No"
}
```stack.append(char) // cannot use mutating member on immutable value: 'stack' is a 'let' constantif stack.isEmpty || stack.last!= "(" { // cannot convert value of type 'Character' to expected argument type 'Bool'if stack.isEmpty || stack.last!= "(" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.last!= "(" { // expression is not assignable: '||' returns immutable valueif stack.isEmpty || stack.last!= "(" { // '=' must have consistent whitespace on both sidesstack.removeLast() // cannot use mutating member on immutable value: 'stack' is a 'let' constantreturn stack.isEmpty? "Yes" : "No" // expected expressionreturn stack.isEmpty? "Yes" : "No" // string literal is unusedreturn stack.isEmpty? "Yes" : "No" // cannot use optional chaining on non-optional value of type 'Bool'return stack.isEmpty? "Yes" : "No" // consecutive statements on a line must be separated by ';'return stack.isEmpty? "Yes" : "No" // consecutive statements on a line must be separated by ';'func matchParens(lst: [String]) -> String {
let stack = [Character]()
for str in lst {
for char in str {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.isEmpty || stack.last!= "(" {
return "No"
}
stack.removeLast()
}
}
}
return stack.isEmpty? "Yes" : "No"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
Answer:
```swift
func matchParens(lst: [String]) -> String {
let stack = [Character]()
for str in lst {
for char in str {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.isEmpty || stack.last!= "(" {
return "No"
}
stack.removeLast()
}
}
}
return stack.isEmpty? "Yes" : "No"
}
```stack.append(char) // cannot use mutating member on immutable value: 'stack' is a 'let' constantif stack.isEmpty || stack.last!= "(" { // cannot convert value of type 'Character' to expected argument type 'Bool'if stack.isEmpty || stack.last!= "(" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.last!= "(" { // expression is not assignable: '||' returns immutable valueif stack.isEmpty || stack.last!= "(" { // '=' must have consistent whitespace on both sidesstack.removeLast() // cannot use mutating member on immutable value: 'stack' is a 'let' constantreturn stack.isEmpty? "Yes" : "No" // expected expressionreturn stack.isEmpty? "Yes" : "No" // string literal is unusedreturn stack.isEmpty? "Yes" : "No" // cannot use optional chaining on non-optional value of type 'Bool'return stack.isEmpty? "Yes" : "No" // consecutive statements on a line must be separated by ';'return stack.isEmpty? "Yes" : "No" // consecutive statements on a line must be separated by ';'func matchParens(lst: [String]) -> String {
let stack = [Character]()
for str in lst {
for char in str {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.isEmpty || stack.last!= "(" {
return "No"
}
stack.removeLast()
}
}
}
return stack.isEmpty? "Yes" : "No"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
Answer:
```swift
func matchParens(lst: [String]) -> String {
let stack = [Character]()
for str in lst {
for char in str {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.isEmpty || stack.last!= "(" {
return "No"
}
stack.removeLast()
}
}
}
return stack.isEmpty? "Yes" : "No"
}
```stack.append(char) // cannot use mutating member on immutable value: 'stack' is a 'let' constantif stack.isEmpty || stack.last!= "(" { // cannot convert value of type 'Character' to expected argument type 'Bool'if stack.isEmpty || stack.last!= "(" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.last!= "(" { // expression is not assignable: '||' returns immutable valueif stack.isEmpty || stack.last!= "(" { // '=' must have consistent whitespace on both sidesstack.removeLast() // cannot use mutating member on immutable value: 'stack' is a 'let' constantreturn stack.isEmpty? "Yes" : "No" // expected expressionreturn stack.isEmpty? "Yes" : "No" // string literal is unusedreturn stack.isEmpty? "Yes" : "No" // cannot use optional chaining on non-optional value of type 'Bool'return stack.isEmpty? "Yes" : "No" // consecutive statements on a line must be separated by ';'return stack.isEmpty? "Yes" : "No" // consecutive statements on a line must be separated by ';'func matchParens(lst: [String]) -> String {
var stack = [Character]()
for str in lst {
for c in str {
if c == "(" {
stack.append(c)
} else if c == ")" {
if stack.isEmpty || stack.last!= "(" {
return "No"
}
stack.removeLast()
}
}
}
return stack.isEmpty? "Yes" : "No"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
Answer:
```swift
func matchParens(lst: [String]) -> String {
var stack = [Character]()
for str in lst {
for c in str {
if c == "(" {
stack.append(c)
} else if c == ")" {
if stack.isEmpty || stack.last!= "(" {
return "No"
}
stack.removeLast()
}
}
}
return stack.isEmpty? "Yes" : "No"
}
```if stack.isEmpty || stack.last!= "(" { // cannot convert value of type 'Character' to expected argument type 'Bool'if stack.isEmpty || stack.last!= "(" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.last!= "(" { // expression is not assignable: '||' returns immutable valueif stack.isEmpty || stack.last!= "(" { // '=' must have consistent whitespace on both sidesreturn stack.isEmpty? "Yes" : "No" // expected expressionreturn stack.isEmpty? "Yes" : "No" // string literal is unusedreturn stack.isEmpty? "Yes" : "No" // cannot use optional chaining on non-optional value of type 'Bool'return stack.isEmpty? "Yes" : "No" // consecutive statements on a line must be separated by ';'return stack.isEmpty? "Yes" : "No" // consecutive statements on a line must be separated by ';'func matchParens(lst: [String]) -> String {
let stack = [Character]()
for str in lst {
for char in str {
if char == "(" {
stack.append(char)
} else {
if stack.isEmpty || stack.last!= "(" {
return "No"
}
stack.removeLast()
}
}
}
return stack.isEmpty? "Yes" : "No"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
Answer:
```swift
func matchParens(lst: [String]) -> String {
let stack = [Character]()
for str in lst {
for char in str {
if char == "(" {
stack.append(char)
} else {
if stack.isEmpty || stack.last!= "(" {
return "No"
}
stack.removeLast()
}
}
}
return stack.isEmpty? "Yes" : "No"
}
```stack.append(char) // cannot use mutating member on immutable value: 'stack' is a 'let' constantif stack.isEmpty || stack.last!= "(" { // cannot convert value of type 'Character' to expected argument type 'Bool'if stack.isEmpty || stack.last!= "(" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.last!= "(" { // expression is not assignable: '||' returns immutable valueif stack.isEmpty || stack.last!= "(" { // '=' must have consistent whitespace on both sidesstack.removeLast() // cannot use mutating member on immutable value: 'stack' is a 'let' constantreturn stack.isEmpty? "Yes" : "No" // expected expressionreturn stack.isEmpty? "Yes" : "No" // string literal is unusedreturn stack.isEmpty? "Yes" : "No" // cannot use optional chaining on non-optional value of type 'Bool'return stack.isEmpty? "Yes" : "No" // consecutive statements on a line must be separated by ';'return stack.isEmpty? "Yes" : "No" // consecutive statements on a line must be separated by ';'func matchParens(lst: [String]) -> String {
let stack = [Character]()
for str in lst {
for char in str {
switch char {
case "(":
stack.append(char)
case ")":
if stack.isEmpty || stack.last!= "(" {
return "No"
}
stack.removeLast()
default:
return "No"
}
}
}
return stack.isEmpty? "Yes" : "No"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
Answer:
```swift
func matchParens(lst: [String]) -> String {
let stack = [Character]()
for str in lst {
for char in str {
switch char {
case "(":
stack.append(char)
case ")":
if stack.isEmpty || stack.last!= "(" {
return "No"
}
stack.removeLast()
default:
return "No"
}
}
}
return stack.isEmpty? "Yes" : "No"
}
```stack.append(char) // cannot use mutating member on immutable value: 'stack' is a 'let' constantif stack.isEmpty || stack.last!= "(" { // expression is not assignable: '||' returns immutable valueif stack.isEmpty || stack.last!= "(" { // cannot convert value of type 'Character' to expected argument type 'Bool'if stack.isEmpty || stack.last!= "(" { // '=' must have consistent whitespace on both sidesif stack.isEmpty || stack.last!= "(" { // use of '=' in a boolean context, did you mean '=='?stack.removeLast() // cannot use mutating member on immutable value: 'stack' is a 'let' constantreturn stack.isEmpty? "Yes" : "No" // consecutive statements on a line must be separated by ';'return stack.isEmpty? "Yes" : "No" // cannot use optional chaining on non-optional value of type 'Bool'return stack.isEmpty? "Yes" : "No" // consecutive statements on a line must be separated by ';'return stack.isEmpty? "Yes" : "No" // expected expressionreturn stack.isEmpty? "Yes" : "No" // string literal is unusedfunc matchParens(lst: [String]) -> String {
var stack = [Character]()
for str in lst {
for char in str {
if char == "(" {
stack.append(char)
} else {
if stack.isEmpty || stack.last!= "(" {
return "No"
}
stack.removeLast()
}
}
}
return stack.isEmpty? "Yes" : "No"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
Answer:
```swift
func matchParens(lst: [String]) -> String {
var stack = [Character]()
for str in lst {
for char in str {
if char == "(" {
stack.append(char)
} else {
if stack.isEmpty || stack.last!= "(" {
return "No"
}
stack.removeLast()
}
}
}
return stack.isEmpty? "Yes" : "No"
}
```if stack.isEmpty || stack.last!= "(" { // cannot convert value of type 'Character' to expected argument type 'Bool'if stack.isEmpty || stack.last!= "(" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.last!= "(" { // expression is not assignable: '||' returns immutable valueif stack.isEmpty || stack.last!= "(" { // '=' must have consistent whitespace on both sidesreturn stack.isEmpty? "Yes" : "No" // expected expressionreturn stack.isEmpty? "Yes" : "No" // string literal is unusedreturn stack.isEmpty? "Yes" : "No" // cannot use optional chaining on non-optional value of type 'Bool'return stack.isEmpty? "Yes" : "No" // consecutive statements on a line must be separated by ';'return stack.isEmpty? "Yes" : "No" // consecutive statements on a line must be separated by ';'func maximum(arr: [Int], k: Int) -> [Int] {
var heap = [Int]()
var result = [Int]()
for num in arr {
if heap.count < k {
heap.append(num)
} else {
let index = heap.binarySearch(num)
heap[index] = num
}
if heap.count > k {
heap.removeFirst()
}
}
return heap
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
Answer:
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
var heap = [Int]()
var result = [Int]()
for num in arr {
if heap.count < k {
heap.append(num)
} else {
let index = heap.binarySearch(num)
heap[index] = num
}
if heap.count > k {
heap.removeFirst()
}
}
return heap
}
```let index = heap.binarySearch(num) // value of type '[Int]' has no member 'binarySearch'func maximum(arr: [Int], k: Int) -> [Int] {
guard arr.count > 0 else {
return []
}
let sortedArr = arr.sorted()
var result = [Int]()
for i in 0..<k {
result.append(sortedArr[sortedArr.count - 1 - i])
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
Answer:
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
guard arr.count > 0 else {
return []
}
let sortedArr = arr.sorted()
var result = [Int]()
for i in 0..<k {
result.append(sortedArr[sortedArr.count - 1 - i])
}
return result
}
``` // XCTAssertTrue failedfunc maximum(arr: [Int], k: Int) -> [Int] {
guard arr.count > 0 else {
return []
}
guard k > 0 else {
return []
}
guard k <= arr.count else {
return arr
}
let sortedArr = arr.sorted()
let result = sortedArr.prefix(k)
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
Answer:
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
guard arr.count > 0 else {
return []
}
guard k > 0 else {
return []
}
guard k <= arr.count else {
return arr
}
let sortedArr = arr.sorted()
let result = sortedArr.prefix(k)
return result
}
```return result // cannot convert return expression of type 'Array<Int>.SubSequence' (aka 'ArraySlice<Int>') to return type '[Int]'func maximum(arr: [Int], k: Int) -> [Int] {
guard arr.count > 0 else {
return []
}
let sortedArr = arr.sorted()
let end = min(k, sortedArr.count)
return Array(sortedArr[sortedArr.count - end...])
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
Answer:
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
guard arr.count > 0 else {
return []
}
let sortedArr = arr.sorted()
let end = min(k, sortedArr.count)
return Array(sortedArr[sortedArr.count - end...])
}
```return Array(sortedArr[sortedArr.count - end...]) // cannot convert value of type 'PartialRangeFrom<Int>' to expected argument type 'Int'return Array(sortedArr[sortedArr.count - end...]) // missing argument label 'arrayLiteral:' in callfunc maximum(arr: [Int], k: Int) -> [Int] {
var heap = [Int]()
var result = [Int]()
for num in arr {
if heap.count < k {
heap.append(num)
} else {
let maxIndex = heap.firstIndex(of: heap.first!)!
if num > heap[maxIndex] {
heap[maxIndex] = num
heapify(heap: &heap, index: maxIndex)
}
}
}
while!heap.isEmpty {
result.append(heap.removeFirst())
}
return result
}
func heapify(heap: inout [Int], index: Int) {
let left = index * 2 + 1
let right = index * 2 + 2
var largest = index
if left < heap.count && heap[left] > heap[largest] {
largest = left
}
if right < heap.count && heap[right] > heap[largest] {
largest = right
}
if largest!= index {
let temp = heap[index]
heap[index] = heap[largest]
heap[largest] = temp
heapify(heap: &heap, index: largest)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
Answer:
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
var heap = [Int]()
var result = [Int]()
for num in arr {
if heap.count < k {
heap.append(num)
} else {
let maxIndex = heap.firstIndex(of: heap.first!)!
if num > heap[maxIndex] {
heap[maxIndex] = num
heapify(heap: &heap, index: maxIndex)
}
}
}
while!heap.isEmpty {
result.append(heap.removeFirst())
}
return result
}
func heapify(heap: inout [Int], index: Int) {
let left = index * 2 + 1
let right = index * 2 + 2
var largest = index
if left < heap.count && heap[left] > heap[largest] {
largest = left
}
if right < heap.count && heap[right] > heap[largest] {
largest = right
}
if largest!= index {
let temp = heap[index]
heap[index] = heap[largest]
heap[largest] = temp
heapify(heap: &heap, index: largest)
}
}
```while!heap.isEmpty { // expected expression, var, or let in 'while' conditionif largest!= index { // '=' must have consistent whitespace on both sidesif largest!= index { // use of '=' in a boolean context, did you mean '=='?if largest!= index { // cannot force unwrap value of non-optional type 'Int'func maximum(arr: [Int], k: Int) -> [Int] {
guard arr.count > 0 else {
return []
}
var result = [Int]()
var heap = [Int]()
for num in arr {
if heap.count < k {
heap.append(num)
} else {
if num > heap[0] {
heap[0] = num
heap = heap.sorted()
}
}
}
return heap
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
Answer:
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
guard arr.count > 0 else {
return []
}
var result = [Int]()
var heap = [Int]()
for num in arr {
if heap.count < k {
heap.append(num)
} else {
if num > heap[0] {
heap[0] = num
heap = heap.sorted()
}
}
}
return heap
}
```var result = [Int]() // initialization of variable 'result' was never used; consider replacing with assignment to '_' or removing it // XCTAssertTrue failedfunc maximum(arr: [Int], k: Int) -> [Int] {
guard arr.count > 0 else {
return []
}
guard k > 0 else {
return []
}
guard k <= arr.count else {
return arr
}
let sortedArr = arr.sorted()
let maxK = sortedArr.prefix(k)
return maxK
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
Answer:
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
guard arr.count > 0 else {
return []
}
guard k > 0 else {
return []
}
guard k <= arr.count else {
return arr
}
let sortedArr = arr.sorted()
let maxK = sortedArr.prefix(k)
return maxK
}
```return maxK // cannot convert return expression of type 'Array<Int>.SubSequence' (aka 'ArraySlice<Int>') to return type '[Int]'func maximum(arr: [Int], k: Int) -> [Int] {
var heap = [Int]()
var result = [Int]()
for num in arr {
if heap.count < k {
heap.append(num)
} else {
let index = heap.binarySearch { $0 > num }
heap[index] = num
}
if heap.count == k {
result.append(heap[0])
heap.removeFirst()
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
Answer:
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
var heap = [Int]()
var result = [Int]()
for num in arr {
if heap.count < k {
heap.append(num)
} else {
let index = heap.binarySearch { $0 > num }
heap[index] = num
}
if heap.count == k {
result.append(heap[0])
heap.removeFirst()
}
}
return result
}
```let index = heap.binarySearch { $0 > num } // value of type '[Int]' has no member 'binarySearch'func maximum(arr: [Int], k: Int) -> [Int] {
guard arr.count > 0 else {
return []
}
let sortedArr = arr.sorted()
let maxK = sortedArr.prefix(k)
return maxK
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
Answer:
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
guard arr.count > 0 else {
return []
}
let sortedArr = arr.sorted()
let maxK = sortedArr.prefix(k)
return maxK
}
```return maxK // cannot convert return expression of type 'Array<Int>.SubSequence' (aka 'ArraySlice<Int>') to return type '[Int]'func maximum(arr: [Int], k: Int) -> [Int] {
guard arr.count > 0, k > 0 else {
return []
}
let sortedArr = arr.sorted()
var result = [Int]()
for i in 0..<k {
result.append(sortedArr[sortedArr.count - 1 - i])
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
Answer:
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
guard arr.count > 0, k > 0 else {
return []
}
let sortedArr = arr.sorted()
var result = [Int]()
for i in 0..<k {
result.append(sortedArr[sortedArr.count - 1 - i])
}
return result
}
``` // XCTAssertTrue failedfunc solution(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2!= 0 {
sum += element
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
Answer:
```swift
func solution(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2!= 0 {
sum += element
}
}
return sum
}
```if index % 2 == 1 && element % 2!= 0 { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadif index % 2 == 1 && element % 2!= 0 { // '=' must have consistent whitespace on both sidesif index % 2 == 1 && element % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'if index % 2 == 1 && element % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if index % 2 == 1 && element % 2!= 0 { // expression is not assignable: '&&' returns immutable valuefunc solution(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 0 && element % 2!= 0 {
sum += element
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
Answer:
```swift
func solution(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 0 && element % 2!= 0 {
sum += element
}
}
return sum
}
```if index % 2 == 0 && element % 2!= 0 { // '=' must have consistent whitespace on both sidesif index % 2 == 0 && element % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if index % 2 == 0 && element % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'if index % 2 == 0 && element % 2!= 0 { // expression is not assignable: '&&' returns immutable valueif index % 2 == 0 && element % 2!= 0 { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadfunc solution(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 0 && element % 2!= 0 {
sum += element
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
Answer:
```swift
func solution(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 0 && element % 2!= 0 {
sum += element
}
}
return sum
}
```if index % 2 == 0 && element % 2!= 0 { // '=' must have consistent whitespace on both sidesif index % 2 == 0 && element % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if index % 2 == 0 && element % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'if index % 2 == 0 && element % 2!= 0 { // expression is not assignable: '&&' returns immutable valueif index % 2 == 0 && element % 2!= 0 { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadfunc solution(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 0 && element % 2!= 0 {
sum += element
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
Answer:
```swift
func solution(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 0 && element % 2!= 0 {
sum += element
}
}
return sum
}
```if index % 2 == 0 && element % 2!= 0 { // '=' must have consistent whitespace on both sidesif index % 2 == 0 && element % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if index % 2 == 0 && element % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'if index % 2 == 0 && element % 2!= 0 { // expression is not assignable: '&&' returns immutable valueif index % 2 == 0 && element % 2!= 0 { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadfunc solution(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2 == 1 {
sum += element
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
Answer:
```swift
func solution(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2 == 1 {
sum += element
}
}
return sum
}
``` // XCTAssertTrue failedfunc solution(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2!= 0 {
sum += element
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
Answer:
```swift
func solution(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2!= 0 {
sum += element
}
}
return sum
}
```if index % 2 == 1 && element % 2!= 0 { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadif index % 2 == 1 && element % 2!= 0 { // '=' must have consistent whitespace on both sidesif index % 2 == 1 && element % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'if index % 2 == 1 && element % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if index % 2 == 1 && element % 2!= 0 { // expression is not assignable: '&&' returns immutable valuefunc solution(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2 == 1 {
sum += element
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
Answer:
```swift
func solution(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2 == 1 {
sum += element
}
}
return sum
}
``` // XCTAssertTrue failedfunc solution(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2 == 1 {
sum += element
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
Answer:
```swift
func solution(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2 == 1 {
sum += element
}
}
return sum
}
``` // XCTAssertTrue failedfunc solution(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2!= 0 {
sum += element
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
Answer:
```swift
func solution(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2!= 0 {
sum += element
}
}
return sum
}
```if index % 2 == 1 && element % 2!= 0 { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadif index % 2 == 1 && element % 2!= 0 { // '=' must have consistent whitespace on both sidesif index % 2 == 1 && element % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'if index % 2 == 1 && element % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if index % 2 == 1 && element % 2!= 0 { // expression is not assignable: '&&' returns immutable valuefunc solution(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2 == 1 {
sum += element
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
Answer:
```swift
func solution(lst: [Int]) -> Int {
var sum = 0
for (index, element) in lst.enumerated() {
if index % 2 == 1 && element % 2 == 1 {
sum += element
}
}
return sum
}
``` // XCTAssertTrue failedfunc addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
let element = arr[i]
if element < 10 {
sum += element
} else if element < 100 {
sum += element / 10
sum += element % 10
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
Answer:
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
let element = arr[i]
if element < 10 {
sum += element
} else if element < 100 {
sum += element / 10
sum += element % 10
}
}
return sum
}
``` // XCTAssertTrue failedfunc addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] < 10 {
sum += arr[i]
} else if arr[i] < 100 {
sum += arr[i] / 10
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
Answer:
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] < 10 {
sum += arr[i]
} else if arr[i] < 100 {
sum += arr[i] / 10
}
}
return sum
}
``` // XCTAssertTrue failedfunc addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
let element = arr[i]
if element < 10 {
sum += element
} else if element < 100 {
sum += element / 10 + element % 10
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
Answer:
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
let element = arr[i]
if element < 10 {
sum += element
} else if element < 100 {
sum += element / 10 + element % 10
}
}
return sum
}
``` // XCTAssertTrue failedfunc addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] < 100 {
sum += arr[i]
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
Answer:
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] < 100 {
sum += arr[i]
}
}
return sum
}
```func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
let element = arr[i]
if element < 10 {
sum += element
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
Answer:
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
let element = arr[i]
if element < 10 {
sum += element
}
}
return sum
}
``` // XCTAssertTrue failedfunc addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] < 10 {
sum += arr[i]
} else if arr[i] < 100 {
sum += arr[i] / 10
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
Answer:
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] < 10 {
sum += arr[i]
} else if arr[i] < 100 {
sum += arr[i] / 10
}
}
return sum
}
``` // XCTAssertTrue failedfunc addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] < 10 {
sum += arr[i]
} else if arr[i] < 100 {
sum += arr[i] / 10
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
Answer:
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] < 10 {
sum += arr[i]
} else if arr[i] < 100 {
sum += arr[i] / 10
}
}
return sum
}
``` // XCTAssertTrue failedfunc addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
let element = arr[i]
if element < 10 {
sum += element
} else if element < 100 {
sum += element / 10
sum += element % 10
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
Answer:
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
let element = arr[i]
if element < 10 {
sum += element
} else if element < 100 {
sum += element / 10
sum += element % 10
}
}
return sum
}
``` // XCTAssertTrue failedfunc addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
let element = arr[i]
if element < 10 {
sum += element
} else if element < 100 {
sum += element / 10
sum += element % 10
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
Answer:
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
let element = arr[i]
if element < 10 {
sum += element
} else if element < 100 {
sum += element / 10
sum += element % 10
}
}
return sum
}
``` // XCTAssertTrue failedfunc addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] < 100 {
sum += arr[i]
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
Answer:
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] < 100 {
sum += arr[i]
}
}
return sum
}
```func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var currentNumber = n
while currentNumber!= 1 {
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = currentNumber * 3 + 1
}
if currentNumber % 2!= 0 {
result.append(currentNumber)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var currentNumber = n
while currentNumber!= 1 {
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = currentNumber * 3 + 1
}
if currentNumber % 2!= 0 {
result.append(currentNumber)
}
}
return result
}
```while currentNumber!= 1 { // cannot force unwrap value of non-optional type 'Int'while currentNumber!= 1 { // use of '=' in a boolean context, did you mean '=='?while currentNumber!= 1 { // '=' must have consistent whitespace on both sidesif currentNumber % 2!= 0 { // '=' must have consistent whitespace on both sidesif currentNumber % 2!= 0 { // expression is not assignable: binary operator returns immutable valueif currentNumber % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if currentNumber % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var currentNumber = n
while currentNumber!= 1 {
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = currentNumber * 3 + 1
}
if currentNumber % 2!= 0 {
result.append(currentNumber)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var currentNumber = n
while currentNumber!= 1 {
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = currentNumber * 3 + 1
}
if currentNumber % 2!= 0 {
result.append(currentNumber)
}
}
return result
}
```while currentNumber!= 1 { // cannot force unwrap value of non-optional type 'Int'while currentNumber!= 1 { // use of '=' in a boolean context, did you mean '=='?while currentNumber!= 1 { // '=' must have consistent whitespace on both sidesif currentNumber % 2!= 0 { // '=' must have consistent whitespace on both sidesif currentNumber % 2!= 0 { // expression is not assignable: binary operator returns immutable valueif currentNumber % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if currentNumber % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
result.append(current)
current = current % 2 == 0? current / 2 : 3 * current + 1
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
result.append(current)
current = current % 2 == 0? current / 2 : 3 * current + 1
}
return result
}
```current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot assign value of type 'Bool' to type 'Int'current = current % 2 == 0? current / 2 : 3 * current + 1 // expected expressioncurrent = current % 2 == 0? current / 2 : 3 * current + 1 // cannot use optional chaining on non-optional value of type 'Int'current = current % 2 == 0? current / 2 : 3 * current + 1 // result of operator '/' is unusedfunc getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
result.append(current)
current = current % 2 == 0? current / 2 : 3 * current + 1
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
result.append(current)
current = current % 2 == 0? current / 2 : 3 * current + 1
}
return result
}
```current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot assign value of type 'Bool' to type 'Int'current = current % 2 == 0? current / 2 : 3 * current + 1 // expected expressioncurrent = current % 2 == 0? current / 2 : 3 * current + 1 // cannot use optional chaining on non-optional value of type 'Int'current = current % 2 == 0? current / 2 : 3 * current + 1 // result of operator '/' is unusedfunc getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var currentNumber = n
while currentNumber!= 1 {
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = currentNumber * 3 + 1
}
if currentNumber % 2 == 1 {
result.append(currentNumber)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var currentNumber = n
while currentNumber!= 1 {
if currentNumber % 2 == 0 {
currentNumber = currentNumber / 2
} else {
currentNumber = currentNumber * 3 + 1
}
if currentNumber % 2 == 1 {
result.append(currentNumber)
}
}
return result
}
```while currentNumber!= 1 { // cannot force unwrap value of non-optional type 'Int'while currentNumber!= 1 { // '=' must have consistent whitespace on both sideswhile currentNumber!= 1 { // use of '=' in a boolean context, did you mean '=='?func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = (current * 3) + 1
}
if current % 2!= 0 {
result.append(current)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current /= 2
} else {
current = (current * 3) + 1
}
if current % 2!= 0 {
result.append(current)
}
}
return result
}
```while current!= 1 { // use of '=' in a boolean context, did you mean '=='?while current!= 1 { // cannot force unwrap value of non-optional type 'Int'while current!= 1 { // '=' must have consistent whitespace on both sidesif current % 2!= 0 { // expression is not assignable: binary operator returns immutable valueif current % 2!= 0 { // '=' must have consistent whitespace on both sidesif current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = (current * 3) + 1
}
result.append(current)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = (current * 3) + 1
}
result.append(current)
}
return result
}
```while current!= 1 { // use of '=' in a boolean context, did you mean '=='?while current!= 1 { // cannot force unwrap value of non-optional type 'Int'while current!= 1 { // '=' must have consistent whitespace on both sidesfunc getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
result.append(current)
current = current % 2 == 0? current / 2 : 3 * current + 1
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current > 1 {
result.append(current)
current = current % 2 == 0? current / 2 : 3 * current + 1
}
return result
}
```current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'current = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot assign value of type 'Bool' to type 'Int'current = current % 2 == 0? current / 2 : 3 * current + 1 // expected expressioncurrent = current % 2 == 0? current / 2 : 3 * current + 1 // cannot use optional chaining on non-optional value of type 'Int'current = current % 2 == 0? current / 2 : 3 * current + 1 // result of operator '/' is unusedfunc getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = 3 * current + 1
}
if current % 2!= 0 {
result.append(current)
}
}
return result
}
```while current!= 1 { // use of '=' in a boolean context, did you mean '=='?while current!= 1 { // cannot force unwrap value of non-optional type 'Int'while current!= 1 { // '=' must have consistent whitespace on both sidesif current % 2!= 0 { // expression is not assignable: binary operator returns immutable valueif current % 2!= 0 { // '=' must have consistent whitespace on both sidesif current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = (current * 3) + 1
}
if current % 2!= 0 {
result.append(current)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 0 {
current = current / 2
} else {
current = (current * 3) + 1
}
if current % 2!= 0 {
result.append(current)
}
}
return result
}
```while current!= 1 { // use of '=' in a boolean context, did you mean '=='?while current!= 1 { // cannot force unwrap value of non-optional type 'Int'while current!= 1 { // '=' must have consistent whitespace on both sidesif current % 2!= 0 { // expression is not assignable: binary operator returns immutable valueif current % 2!= 0 { // '=' must have consistent whitespace on both sidesif current % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'if current % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?func validDate(date: String) -> Bool {
let dateComponents = DateFormatter.components(.year,.month,.day, from: date)
let year = dateComponents.year
let month = dateComponents.month
let day = dateComponents.day
if date.contains("/") {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM/dd/yyyy"
if let date = dateFormatter.date(from: date) {
let calendar = Calendar.current
let components = calendar.dateComponents([.year,.month,.day], from: date)
year = components.year
month = components.month
day = components.day
}
}
if year == nil || month == nil || day == nil {
return false
}
let isLeapYear = Calendar.current.isDateInLeapYear(year!)
let daysInMonth = isLeapYear? 366 : 365
if month! < 1 || month! > 12 {
return false
}
if day! < 1 || day! > daysInMonth {
return false
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
Answer:
```swift
func validDate(date: String) -> Bool {
let dateComponents = DateFormatter.components(.year,.month,.day, from: date)
let year = dateComponents.year
let month = dateComponents.month
let day = dateComponents.day
if date.contains("/") {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM/dd/yyyy"
if let date = dateFormatter.date(from: date) {
let calendar = Calendar.current
let components = calendar.dateComponents([.year,.month,.day], from: date)
year = components.year
month = components.month
day = components.day
}
}
if year == nil || month == nil || day == nil {
return false
}
let isLeapYear = Calendar.current.isDateInLeapYear(year!)
let daysInMonth = isLeapYear? 366 : 365
if month! < 1 || month! > 12 {
return false
}
if day! < 1 || day! > daysInMonth {
return false
}
return true
}
```let dateComponents = DateFormatter.components(.year,.month,.day, from: date) // cannot infer contextual base in reference to member 'month'let dateComponents = DateFormatter.components(.year,.month,.day, from: date) // cannot infer contextual base in reference to member 'year'let dateComponents = DateFormatter.components(.year,.month,.day, from: date) // type 'DateFormatter' has no member 'components'let dateComponents = DateFormatter.components(.year,.month,.day, from: date) // cannot infer contextual base in reference to member 'day'let isLeapYear = Calendar.current.isDateInLeapYear(year!) // value of type 'Calendar' has no member 'isDateInLeapYear'let daysInMonth = isLeapYear? 366 : 365 // integer literal is unusedlet daysInMonth = isLeapYear? 366 : 365 // consecutive statements on a line must be separated by ';'let daysInMonth = isLeapYear? 366 : 365 // consecutive statements on a line must be separated by ';'let daysInMonth = isLeapYear? 366 : 365 // expected expressionfunc validDate(date: String) -> Bool {
let dateComponents = DateFormatter.dateComponents([.day,.month,.year], from: date)
let day = dateComponents.day
let month = dateComponents.month
let year = dateComponents.year
guard let day = day, let month = month, let year = year else {
return false
}
switch month {
case 1, 3, 5, 7, 8, 10, 12:
if day < 1 || day > 31 {
return false
}
case 4, 6, 9, 11:
if day < 1 || day > 30 {
return false
}
case 2:
if day < 1 || day > 29 {
return false
}
default:
return false
}
if month < 1 || month > 12 {
return false
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
Answer:
```swift
func validDate(date: String) -> Bool {
let dateComponents = DateFormatter.dateComponents([.day,.month,.year], from: date)
let day = dateComponents.day
let month = dateComponents.month
let year = dateComponents.year
guard let day = day, let month = month, let year = year else {
return false
}
switch month {
case 1, 3, 5, 7, 8, 10, 12:
if day < 1 || day > 31 {
return false
}
case 4, 6, 9, 11:
if day < 1 || day > 30 {
return false
}
case 2:
if day < 1 || day > 29 {
return false
}
default:
return false
}
if month < 1 || month > 12 {
return false
}
return true
}
```let dateComponents = DateFormatter.dateComponents([.day,.month,.year], from: date) // type 'DateFormatter' has no member 'dateComponents'let dateComponents = DateFormatter.dateComponents([.day,.month,.year], from: date) // reference to member 'day' cannot be resolved without a contextual typelet dateComponents = DateFormatter.dateComponents([.day,.month,.year], from: date) // reference to member 'year' cannot be resolved without a contextual typelet dateComponents = DateFormatter.dateComponents([.day,.month,.year], from: date) // reference to member 'month' cannot be resolved without a contextual typefunc validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
let date = dateFormatter.date(from: date)
return date!= nil
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
Answer:
```swift
func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
let date = dateFormatter.date(from: date)
return date!= nil
}
```return date!= nil // use of '=' in a boolean context, did you mean '=='?return date!= nil // cannot assign through '!': 'date' is a 'let' constantreturn date!= nil // 'nil' cannot be assigned to type 'Date'return date!= nil // '=' must have consistent whitespace on both sidesfunc validDate(date: String) -> Bool {
let dateComponents = DateFormatter.dateComponents([.day,.month,.year], from: date)
let day = dateComponents.day
let month = dateComponents.month
let year = dateComponents.year
if date.count == 0 {
return false
}
if month == 2 {
if day! < 1 || day! > 29 {
return false
}
} else if month == 4 || month == 6 || month == 9 || month == 11 {
if day! < 1 || day! > 30 {
return false
}
} else {
if day! < 1 || day! > 31 {
return false
}
}
if month < 1 || month > 12 {
return false
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
Answer:
```swift
func validDate(date: String) -> Bool {
let dateComponents = DateFormatter.dateComponents([.day,.month,.year], from: date)
let day = dateComponents.day
let month = dateComponents.month
let year = dateComponents.year
if date.count == 0 {
return false
}
if month == 2 {
if day! < 1 || day! > 29 {
return false
}
} else if month == 4 || month == 6 || month == 9 || month == 11 {
if day! < 1 || day! > 30 {
return false
}
} else {
if day! < 1 || day! > 31 {
return false
}
}
if month < 1 || month > 12 {
return false
}
return true
}
```let dateComponents = DateFormatter.dateComponents([.day,.month,.year], from: date) // type 'DateFormatter' has no member 'dateComponents'let dateComponents = DateFormatter.dateComponents([.day,.month,.year], from: date) // reference to member 'day' cannot be resolved without a contextual typelet dateComponents = DateFormatter.dateComponents([.day,.month,.year], from: date) // reference to member 'year' cannot be resolved without a contextual typelet dateComponents = DateFormatter.dateComponents([.day,.month,.year], from: date) // reference to member 'month' cannot be resolved without a contextual typefunc validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
let date = dateFormatter.date(from: date)
return date!= nil
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
Answer:
```swift
func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
let date = dateFormatter.date(from: date)
return date!= nil
}
```return date!= nil // use of '=' in a boolean context, did you mean '=='?return date!= nil // cannot assign through '!': 'date' is a 'let' constantreturn date!= nil // 'nil' cannot be assigned to type 'Date'return date!= nil // '=' must have consistent whitespace on both sidesfunc validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
guard let date = dateFormatter.date(from: date) else {
return false
}
let calendar = Calendar.current
let components = calendar.dateComponents([.year,.month,.day], from: date)
if components.year == nil || components.month == nil || components.day == nil {
return false
}
let month = components.month!
let day = components.day!
let year = components.year!
if month < 1 || month > 12 {
return false
}
if month == 2 {
if day < 1 || day > 29 {
return false
}
} else {
if day < 1 || day > 31 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
Answer:
```swift
func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
guard let date = dateFormatter.date(from: date) else {
return false
}
let calendar = Calendar.current
let components = calendar.dateComponents([.year,.month,.day], from: date)
if components.year == nil || components.month == nil || components.day == nil {
return false
}
let month = components.month!
let day = components.day!
let year = components.year!
if month < 1 || month > 12 {
return false
}
if month == 2 {
if day < 1 || day > 29 {
return false
}
} else {
if day < 1 || day > 31 {
return false
}
}
return true
}
```let year = components.year! // initialization of immutable value 'year' was never used; consider replacing with assignment to '_' or removing itfunc validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
let date = dateFormatter.date(from: date)
return date!= nil
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
Answer:
```swift
func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
let date = dateFormatter.date(from: date)
return date!= nil
}
```return date!= nil // use of '=' in a boolean context, did you mean '=='?return date!= nil // cannot assign through '!': 'date' is a 'let' constantreturn date!= nil // 'nil' cannot be assigned to type 'Date'return date!= nil // '=' must have consistent whitespace on both sidesfunc validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
guard let date = dateFormatter.date(from: date) else {
return false
}
let calendar = Calendar.current
let components = calendar.dateComponents([.day,.month,.year], from: date)
let day = components.day
let month = components.month
let year = components.year
let isLeapYear = calendar.isDateInLeapYear(date)
let daysInMonth = isLeapYear? 29 : (month == 2? 28 : (month == 4 || month == 6 || month == 9 || month == 11? 30 : 31))
return day!= nil && day! > 0 && day! <= daysInMonth && month!= nil && month! > 0 && month! <= 12 && year!= nil && year! > 0
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
Answer:
```swift
func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
guard let date = dateFormatter.date(from: date) else {
return false
}
let calendar = Calendar.current
let components = calendar.dateComponents([.day,.month,.year], from: date)
let day = components.day
let month = components.month
let year = components.year
let isLeapYear = calendar.isDateInLeapYear(date)
let daysInMonth = isLeapYear? 29 : (month == 2? 28 : (month == 4 || month == 6 || month == 9 || month == 11? 30 : 31))
return day!= nil && day! > 0 && day! <= daysInMonth && month!= nil && month! > 0 && month! <= 12 && year!= nil && year! > 0
}
```let isLeapYear = calendar.isDateInLeapYear(date) // value of type 'Calendar' has no member 'isDateInLeapYear'let daysInMonth = isLeapYear? 29 : (month == 2? 28 : (month == 4 || month == 6 || month == 9 || month == 11? 30 : 31)) // integer literal is unusedlet daysInMonth = isLeapYear? 29 : (month == 2? 28 : (month == 4 || month == 6 || month == 9 || month == 11? 30 : 31)) // consecutive statements on a line must be separated by ';'let daysInMonth = isLeapYear? 29 : (month == 2? 28 : (month == 4 || month == 6 || month == 9 || month == 11? 30 : 31)) // expected expressionlet daysInMonth = isLeapYear? 29 : (month == 2? 28 : (month == 4 || month == 6 || month == 9 || month == 11? 30 : 31)) // consecutive statements on a line must be separated by ';'return day!= nil && day! > 0 && day! <= daysInMonth && month!= nil && month! > 0 && month! <= 12 && year!= nil && year! > 0 // type 'Int' cannot be used as a boolean; test for '!= 0' insteadreturn day!= nil && day! > 0 && day! <= daysInMonth && month!= nil && month! > 0 && month! <= 12 && year!= nil && year! > 0 // '=' must have consistent whitespace on both sidesreturn day!= nil && day! > 0 && day! <= daysInMonth && month!= nil && month! > 0 && month! <= 12 && year!= nil && year! > 0 // type 'Int' cannot be used as a boolean; test for '!= 0' insteadreturn day!= nil && day! > 0 && day! <= daysInMonth && month!= nil && month! > 0 && month! <= 12 && year!= nil && year! > 0 // use of '=' in a boolean context, did you mean '=='?return day!= nil && day! > 0 && day! <= daysInMonth && month!= nil && month! > 0 && month! <= 12 && year!= nil && year! > 0 // cannot assign through '!': 'day' is a 'let' constantreturn day!= nil && day! > 0 && day! <= daysInMonth && month!= nil && month! > 0 && month! <= 12 && year!= nil && year! > 0 // 'nil' is not compatible with expected argument type 'Bool'return day!= nil && day! > 0 && day! <= daysInMonth && month!= nil && month! > 0 && month! <= 12 && year!= nil && year! > 0 // 'nil' is not compatible with expected argument type 'Bool'return day!= nil && day! > 0 && day! <= daysInMonth && month!= nil && month! > 0 && month! <= 12 && year!= nil && year! > 0 // 'nil' is not compatible with expected argument type 'Bool'return day!= nil && day! > 0 && day! <= daysInMonth && month!= nil && month! > 0 && month! <= 12 && year!= nil && year! > 0 // '=' must have consistent whitespace on both sidesreturn day!= nil && day! > 0 && day! <= daysInMonth && month!= nil && month! > 0 && month! <= 12 && year!= nil && year! > 0 // cannot assign value of type '()' to type 'Int'return day!= nil && day! > 0 && day! <= daysInMonth && month!= nil && month! > 0 && month! <= 12 && year!= nil && year! > 0 // '=' must have consistent whitespace on both sidesfunc validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
let date = dateFormatter.date(from: date)
return date!= nil
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
Answer:
```swift
func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
let date = dateFormatter.date(from: date)
return date!= nil
}
```return date!= nil // use of '=' in a boolean context, did you mean '=='?return date!= nil // cannot assign through '!': 'date' is a 'let' constantreturn date!= nil // 'nil' cannot be assigned to type 'Date'return date!= nil // '=' must have consistent whitespace on both sidesfunc validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
let date = dateFormatter.date(from: date)
return date!= nil
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
Answer:
```swift
func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
let date = dateFormatter.date(from: date)
return date!= nil
}
```return date!= nil // use of '=' in a boolean context, did you mean '=='?return date!= nil // cannot assign through '!': 'date' is a 'let' constantreturn date!= nil // 'nil' cannot be assigned to type 'Date'return date!= nil // '=' must have consistent whitespace on both sidesextension Int: Error {
}
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.components(separatedBy: " ")
let letters = txt.lowercased().characters.map { String($0) }
let oddLetters = letters.filter { $0.distance(from: "a") % 2 == 1 }
return words.isEmpty?.success(oddLetters) :.success(words)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1,... ord('z') = 25
Examples
splitWords(txt: "Hello world!") ==.success(["Hello", "world!"])
splitWords(txt: "Hello,world!") ==.success(["Hello", "world!"])
splitWords(txt: "abcdef") ==.failure(3)
Answer:
```swift
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.components(separatedBy: " ")
let letters = txt.lowercased().characters.map { String($0) }
let oddLetters = letters.filter { $0.distance(from: "a") % 2 == 1 }
return words.isEmpty?.success(oddLetters) :.success(words)
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'let letters = txt.lowercased().characters.map { String($0) } // 'characters' is unavailable: Please use String directlylet oddLetters = letters.filter { $0.distance(from: "a") % 2 == 1 } // missing argument for parameter 'to' in calllet oddLetters = letters.filter { $0.distance(from: "a") % 2 == 1 } // cannot convert value of type 'String' to expected argument type 'String.Index'return words.isEmpty?.success(oddLetters) :.success(words) // cannot convert return expression of type 'Optional<_>' to return type 'Result<[String], Int>'return words.isEmpty?.success(oddLetters) :.success(words) // expected expressionreturn words.isEmpty?.success(oddLetters) :.success(words) // consecutive statements on a line must be separated by ';'return words.isEmpty?.success(oddLetters) :.success(words) // value of type 'Bool' has no member 'success'return words.isEmpty?.success(oddLetters) :.success(words) // cannot use optional chaining on non-optional value of type 'Bool'extension Int: Error {
}
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.components(separatedBy: " ")
if words.count > 0 {
return.success(words)
} else {
let letters = txt.lowercased().map { String($0) }
let oddLetters = letters.filter { Int(String($0).first!)! % 2!= 0 }
return.success(oddLetters)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1,... ord('z') = 25
Examples
splitWords(txt: "Hello world!") ==.success(["Hello", "world!"])
splitWords(txt: "Hello,world!") ==.success(["Hello", "world!"])
splitWords(txt: "abcdef") ==.failure(3)
Answer:
```swift
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.components(separatedBy: " ")
if words.count > 0 {
return.success(words)
} else {
let letters = txt.lowercased().map { String($0) }
let oddLetters = letters.filter { Int(String($0).first!)! % 2!= 0 }
return.success(oddLetters)
}
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'let oddLetters = letters.filter { Int(String($0).first!)! % 2!= 0 } // cannot convert value of type '()' to closure result type 'Bool'let oddLetters = letters.filter { Int(String($0).first!)! % 2!= 0 } // expression is not assignable: binary operator returns immutable valuelet oddLetters = letters.filter { Int(String($0).first!)! % 2!= 0 } // '=' must have consistent whitespace on both sideslet oddLetters = letters.filter { Int(String($0).first!)! % 2!= 0 } // cannot force unwrap value of non-optional type 'Int'let oddLetters = letters.filter { Int(String($0).first!)! % 2!= 0 } // cannot convert value of type 'String.Element' (aka 'Character') to expected argument type 'String'extension Int: Error {
}
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.components(separatedBy: " ")
let letters = txt.lowercased().map { String($0) }
let oddLetters = letters.filter { Int($0.description) % 2 == 1 }
return words.count > 0?.success(words) :.success(oddLetters)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1,... ord('z') = 25
Examples
splitWords(txt: "Hello world!") ==.success(["Hello", "world!"])
splitWords(txt: "Hello,world!") ==.success(["Hello", "world!"])
splitWords(txt: "abcdef") ==.failure(3)
Answer:
```swift
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.components(separatedBy: " ")
let letters = txt.lowercased().map { String($0) }
let oddLetters = letters.filter { Int($0.description) % 2 == 1 }
return words.count > 0?.success(words) :.success(oddLetters)
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'let oddLetters = letters.filter { Int($0.description) % 2 == 1 } // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return words.count > 0?.success(words) :.success(oddLetters) // cannot use optional chaining on non-optional value of type 'Int'return words.count > 0?.success(words) :.success(oddLetters) // cannot convert return expression of type 'Bool' to return type 'Result<[String], Int>'return words.count > 0?.success(words) :.success(oddLetters) // consecutive statements on a line must be separated by ';'return words.count > 0?.success(words) :.success(oddLetters) // value of type 'Int' has no member 'success'return words.count > 0?.success(words) :.success(oddLetters) // expected expressionreturn words.count > 0?.success(words) :.success(oddLetters) // value of optional type 'Int?' must be unwrapped to a value of type 'Int'extension Int: Error {
}
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.components(separatedBy: " ")
if words.count > 0 {
return.success(words)
} else {
let letters = txt.lowercased().characters.map { String($0) }
let oddLetters = letters.filter { $0.characters.count % 2 == 1 }
return.success(oddLetters)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1,... ord('z') = 25
Examples
splitWords(txt: "Hello world!") ==.success(["Hello", "world!"])
splitWords(txt: "Hello,world!") ==.success(["Hello", "world!"])
splitWords(txt: "abcdef") ==.failure(3)
Answer:
```swift
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.components(separatedBy: " ")
if words.count > 0 {
return.success(words)
} else {
let letters = txt.lowercased().characters.map { String($0) }
let oddLetters = letters.filter { $0.characters.count % 2 == 1 }
return.success(oddLetters)
}
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'let letters = txt.lowercased().characters.map { String($0) } // 'characters' is unavailable: Please use String directlylet oddLetters = letters.filter { $0.characters.count % 2 == 1 } // 'characters' is unavailable: Please use String directlyextension Int: Error {
}
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.components(separatedBy: " ")
let commas = txt.components(separatedBy: ",")
if words.count > 0 {
return.success(words)
} else if commas.count > 0 {
return.success(commas)
} else {
let letters = txt.lowercased().map { String($0) }
var count = 0
for (index, letter) in letters.enumerated() {
if index % 2!= 0 {
count += 1
}
}
return.failure(count)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1,... ord('z') = 25
Examples
splitWords(txt: "Hello world!") ==.success(["Hello", "world!"])
splitWords(txt: "Hello,world!") ==.success(["Hello", "world!"])
splitWords(txt: "abcdef") ==.failure(3)
Answer:
```swift
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.components(separatedBy: " ")
let commas = txt.components(separatedBy: ",")
if words.count > 0 {
return.success(words)
} else if commas.count > 0 {
return.success(commas)
} else {
let letters = txt.lowercased().map { String($0) }
var count = 0
for (index, letter) in letters.enumerated() {
if index % 2!= 0 {
count += 1
}
}
return.failure(count)
}
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'if index % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if index % 2!= 0 { // expression is not assignable: binary operator returns immutable valueif index % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'if index % 2!= 0 { // '=' must have consistent whitespace on both sidesextension Int: Error {
}
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.components(separatedBy: " ")
let letters = txt.lowercased().filter { $0.isLetter }
let oddLetters = letters.filter { Int($0.asciiValue?? 0) % 2!= 0 }
return words.count > 0?.success(words) : oddLetters.count > 0?.success(oddLetters) :.failure(3)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1,... ord('z') = 25
Examples
splitWords(txt: "Hello world!") ==.success(["Hello", "world!"])
splitWords(txt: "Hello,world!") ==.success(["Hello", "world!"])
splitWords(txt: "abcdef") ==.failure(3)
Answer:
```swift
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.components(separatedBy: " ")
let letters = txt.lowercased().filter { $0.isLetter }
let oddLetters = letters.filter { Int($0.asciiValue?? 0) % 2!= 0 }
return words.count > 0?.success(words) : oddLetters.count > 0?.success(oddLetters) :.failure(3)
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'let oddLetters = letters.filter { Int($0.asciiValue?? 0) % 2!= 0 } // cannot convert value of type '()' to closure result type 'Bool'let oddLetters = letters.filter { Int($0.asciiValue?? 0) % 2!= 0 } // missing argument label 'strategy:' in calllet oddLetters = letters.filter { Int($0.asciiValue?? 0) % 2!= 0 } // expected ',' separatorlet oddLetters = letters.filter { Int($0.asciiValue?? 0) % 2!= 0 } // initializer 'init(_:strategy:)' requires that 'Int' conform to 'ParseStrategy'let oddLetters = letters.filter { Int($0.asciiValue?? 0) % 2!= 0 } // cannot force unwrap value of non-optional type 'Int'let oddLetters = letters.filter { Int($0.asciiValue?? 0) % 2!= 0 } // cannot use optional chaining on non-optional value of type 'UInt8'let oddLetters = letters.filter { Int($0.asciiValue?? 0) % 2!= 0 } // '=' must have consistent whitespace on both sidesreturn words.count > 0?.success(words) : oddLetters.count > 0?.success(oddLetters) :.failure(3) // consecutive statements on a line must be separated by ';'return words.count > 0?.success(words) : oddLetters.count > 0?.success(oddLetters) :.failure(3) // value of type 'Int' has no member 'success'return words.count > 0?.success(words) : oddLetters.count > 0?.success(oddLetters) :.failure(3) // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return words.count > 0?.success(words) : oddLetters.count > 0?.success(oddLetters) :.failure(3) // cannot convert return expression of type 'Bool' to return type 'Result<[String], Int>'return words.count > 0?.success(words) : oddLetters.count > 0?.success(oddLetters) :.failure(3) // cannot use optional chaining on non-optional value of type 'Int'return words.count > 0?.success(words) : oddLetters.count > 0?.success(oddLetters) :.failure(3) // expected expressionextension Int: Error {
}
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.components(separatedBy: " ")
if words.count > 0 {
return.success(words)
} else {
let letters = txt.lowercased().filter { $0.isLetter }
let oddLetters = letters.enumerated().filter { $0.offset % 2 == 1 }.map { String(UnicodeScalar($0.element)!) }
return.success(oddLetters)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1,... ord('z') = 25
Examples
splitWords(txt: "Hello world!") ==.success(["Hello", "world!"])
splitWords(txt: "Hello,world!") ==.success(["Hello", "world!"])
splitWords(txt: "abcdef") ==.failure(3)
Answer:
```swift
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.components(separatedBy: " ")
if words.count > 0 {
return.success(words)
} else {
let letters = txt.lowercased().filter { $0.isLetter }
let oddLetters = letters.enumerated().filter { $0.offset % 2 == 1 }.map { String(UnicodeScalar($0.element)!) }
return.success(oddLetters)
}
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'let oddLetters = letters.enumerated().filter { $0.offset % 2 == 1 }.map { String(UnicodeScalar($0.element)!) } // no exact matches in call to initializerextension Int: Error {
}
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.components(separatedBy: " ")
let letters = txt.lowercased().map { String($0) }
let oddLetters = letters.filter { Int(String($0).first?? "")?? 0 % 2 == 1 }
return words.count > 0?.success(words) :.success(oddLetters)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1,... ord('z') = 25
Examples
splitWords(txt: "Hello world!") ==.success(["Hello", "world!"])
splitWords(txt: "Hello,world!") ==.success(["Hello", "world!"])
splitWords(txt: "abcdef") ==.failure(3)
Answer:
```swift
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.components(separatedBy: " ")
let letters = txt.lowercased().map { String($0) }
let oddLetters = letters.filter { Int(String($0).first?? "")?? 0 % 2 == 1 }
return words.count > 0?.success(words) :.success(oddLetters)
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'let oddLetters = letters.filter { Int(String($0).first?? "")?? 0 % 2 == 1 } // missing argument label 'strategy:' in calllet oddLetters = letters.filter { Int(String($0).first?? "")?? 0 % 2 == 1 } // cannot use optional chaining on non-optional value of type 'Int'let oddLetters = letters.filter { Int(String($0).first?? "")?? 0 % 2 == 1 } // cannot use optional chaining on non-optional value of type 'Int'let oddLetters = letters.filter { Int(String($0).first?? "")?? 0 % 2 == 1 } // cannot use optional chaining on non-optional value of type 'String.Element' (aka 'Character')let oddLetters = letters.filter { Int(String($0).first?? "")?? 0 % 2 == 1 } // consecutive statements on a line must be separated by ';'let oddLetters = letters.filter { Int(String($0).first?? "")?? 0 % 2 == 1 } // initializer 'init(_:strategy:)' requires that 'String' conform to 'ParseStrategy'let oddLetters = letters.filter { Int(String($0).first?? "")?? 0 % 2 == 1 } // expected ',' separatorreturn words.count > 0?.success(words) :.success(oddLetters) // cannot use optional chaining on non-optional value of type 'Int'return words.count > 0?.success(words) :.success(oddLetters) // cannot convert return expression of type 'Bool' to return type 'Result<[String], Int>'return words.count > 0?.success(words) :.success(oddLetters) // value of type 'Int' has no member 'success'return words.count > 0?.success(words) :.success(oddLetters) // consecutive statements on a line must be separated by ';'return words.count > 0?.success(words) :.success(oddLetters) // expected expressionreturn words.count > 0?.success(words) :.success(oddLetters) // value of optional type 'Int?' must be unwrapped to a value of type 'Int'extension Int: Error {
}
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.split(separator: " ")
let letters = txt.lowercased().map { String($0) }
let oddLetters = letters.filter { Int($0.description, radix: 10) % 2 == 1 }
let count = oddLetters.count
return count > 0?.failure(count) :.success(words)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1,... ord('z') = 25
Examples
splitWords(txt: "Hello world!") ==.success(["Hello", "world!"])
splitWords(txt: "Hello,world!") ==.success(["Hello", "world!"])
splitWords(txt: "abcdef") ==.failure(3)
Answer:
```swift
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.split(separator: " ")
let letters = txt.lowercased().map { String($0) }
let oddLetters = letters.filter { Int($0.description, radix: 10) % 2 == 1 }
let count = oddLetters.count
return count > 0?.failure(count) :.success(words)
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'let oddLetters = letters.filter { Int($0.description, radix: 10) % 2 == 1 } // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return count > 0?.failure(count) :.success(words) // consecutive statements on a line must be separated by ';'return count > 0?.failure(count) :.success(words) // cannot convert return expression of type 'Bool' to return type 'Result<[String], Int>'return count > 0?.failure(count) :.success(words) // expected expressionreturn count > 0?.failure(count) :.success(words) // value of type 'Int' has no member 'failure'return count > 0?.failure(count) :.success(words) // value of optional type 'Optional<_>' must be unwrapped to a value of type '_'return count > 0?.failure(count) :.success(words) // cannot use optional chaining on non-optional value of type 'Int'extension Int: Error {
}
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.components(separatedBy: " ")
let letters = txt.lowercased().characters.map { String($0) }
let oddLetters = letters.filter { $0.characters.count % 2 == 1 }
return words.count > 0?.success(words) :.success(oddLetters)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1,... ord('z') = 25
Examples
splitWords(txt: "Hello world!") ==.success(["Hello", "world!"])
splitWords(txt: "Hello,world!") ==.success(["Hello", "world!"])
splitWords(txt: "abcdef") ==.failure(3)
Answer:
```swift
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.components(separatedBy: " ")
let letters = txt.lowercased().characters.map { String($0) }
let oddLetters = letters.filter { $0.characters.count % 2 == 1 }
return words.count > 0?.success(words) :.success(oddLetters)
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'let letters = txt.lowercased().characters.map { String($0) } // 'characters' is unavailable: Please use String directlylet oddLetters = letters.filter { $0.characters.count % 2 == 1 } // 'characters' is unavailable: Please use String directlyreturn words.count > 0?.success(words) :.success(oddLetters) // cannot use optional chaining on non-optional value of type 'Int'return words.count > 0?.success(words) :.success(oddLetters) // cannot convert return expression of type 'Bool' to return type 'Result<[String], Int>'return words.count > 0?.success(words) :.success(oddLetters) // value of type 'Int' has no member 'success'return words.count > 0?.success(words) :.success(oddLetters) // consecutive statements on a line must be separated by ';'return words.count > 0?.success(words) :.success(oddLetters) // expected expressionreturn words.count > 0?.success(words) :.success(oddLetters) // value of optional type 'Int?' must be unwrapped to a value of type 'Int'func isSorted(lst: [Int]) -> Bool {
guard lst.count > 1 else {
return true
}
for i in 0..<lst.count - 1 {
if lst[i] > lst[i + 1] {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
Answer:
```swift
func isSorted(lst: [Int]) -> Bool {
guard lst.count > 1 else {
return true
}
for i in 0..<lst.count - 1 {
if lst[i] > lst[i + 1] {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc isSorted(lst: [Int]) -> Bool {
guard lst.count > 1 else {
return true
}
for i in 0..<lst.count-1 {
if lst[i] > lst[i+1] {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
Answer:
```swift
func isSorted(lst: [Int]) -> Bool {
guard lst.count > 1 else {
return true
}
for i in 0..<lst.count-1 {
if lst[i] > lst[i+1] {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc isSorted(lst: [Int]) -> Bool {
for i in 0..<lst.count - 1 {
if lst[i] > lst[i + 1] {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
Answer:
```swift
func isSorted(lst: [Int]) -> Bool {
for i in 0..<lst.count - 1 {
if lst[i] > lst[i + 1] {
return false
}
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc isSorted(lst: [Int]) -> Bool {
guard lst.count > 1 else {
return true
}
for i in 0..<lst.count - 1 {
if lst[i] > lst[i + 1] {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
Answer:
```swift
func isSorted(lst: [Int]) -> Bool {
guard lst.count > 1 else {
return true
}
for i in 0..<lst.count - 1 {
if lst[i] > lst[i + 1] {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc isSorted(lst: [Int]) -> Bool {
guard lst.count > 1 else {
return true
}
for i in 0..<lst.count - 1 {
if lst[i] > lst[i + 1] {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
Answer:
```swift
func isSorted(lst: [Int]) -> Bool {
guard lst.count > 1 else {
return true
}
for i in 0..<lst.count - 1 {
if lst[i] > lst[i + 1] {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc isSorted(lst: [Int]) -> Bool {
guard lst.count > 1 else {
return true
}
var isSorted = true
for i in 0..<lst.count - 1 {
if lst[i] > lst[i + 1] {
isSorted = false
break
}
}
return isSorted
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
Answer:
```swift
func isSorted(lst: [Int]) -> Bool {
guard lst.count > 1 else {
return true
}
var isSorted = true
for i in 0..<lst.count - 1 {
if lst[i] > lst[i + 1] {
isSorted = false
break
}
}
return isSorted
}
``` // XCTAssertTrue failedfunc isSorted(lst: [Int]) -> Bool {
guard lst.count > 1 else {
return true
}
for i in 0..<lst.count - 1 {
if lst[i] > lst[i + 1] {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
Answer:
```swift
func isSorted(lst: [Int]) -> Bool {
guard lst.count > 1 else {
return true
}
for i in 0..<lst.count - 1 {
if lst[i] > lst[i + 1] {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc isSorted(lst: [Int]) -> Bool {
guard lst.count > 1 else {
return true
}
for i in 0..<lst.count - 1 {
if lst[i] > lst[i + 1] {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
Answer:
```swift
func isSorted(lst: [Int]) -> Bool {
guard lst.count > 1 else {
return true
}
for i in 0..<lst.count - 1 {
if lst[i] > lst[i + 1] {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc isSorted(lst: [Int]) -> Bool {
guard lst.count > 1 else {
return true
}
for i in 0..<lst.count-1 {
if lst[i] > lst[i+1] {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
Answer:
```swift
func isSorted(lst: [Int]) -> Bool {
guard lst.count > 1 else {
return true
}
for i in 0..<lst.count-1 {
if lst[i] > lst[i+1] {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc isSorted(lst: [Int]) -> Bool {
guard lst.count > 1 else {
return true
}
for i in 0..<lst.count-1 {
if lst[i] > lst[i+1] {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
Answer:
```swift
func isSorted(lst: [Int]) -> Bool {
guard lst.count > 1 else {
return true
}
for i in 0..<lst.count-1 {
if lst[i] > lst[i+1] {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else { return false }
if number == 2 { return true }
if number % 2 == 0 { return false }
let sqrt = Int(sqrt(Double(number)))
for i in 3...sqrt {
if number % i == 0 { return false }
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
return isPrime(length)? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else { return false }
if number == 2 { return true }
if number % 2 == 0 { return false }
let sqrt = Int(sqrt(Double(number)))
for i in 3...sqrt {
if number % i == 0 { return false }
}
return true
}
```return isPrime(length)? "YES" : "NO" // string literal is unusedreturn isPrime(length)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime(length)? "YES" : "NO" // expected expressionfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
return length.isPrime? "YES" : "NO"
}
extension Int {
var isPrime: Bool {
return (2..<self).none { self % $0 == 0 }
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
return length.isPrime? "YES" : "NO"
}
extension Int {
var isPrime: Bool {
return (2..<self).none { self % $0 == 0 }
}
}
```return length.isPrime? "YES" : "NO" // string literal is unusedreturn length.isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return length.isPrime? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return length.isPrime? "YES" : "NO" // expected expressionreturn length.isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return (2..<self).none { self % $0 == 0 } // value of type 'Range<Int>' has no member 'none'func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
return length > 1 && length % 2!= 0? "YES" : "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
return length > 1 && length % 2!= 0? "YES" : "NO"
}
```return length > 1 && length % 2!= 0? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Int'return length > 1 && length % 2!= 0? "YES" : "NO" // cannot convert return expression of type '()' to return type 'String'return length > 1 && length % 2!= 0? "YES" : "NO" // cannot force unwrap value of non-optional type 'Int'return length > 1 && length % 2!= 0? "YES" : "NO" // expected expressionreturn length > 1 && length % 2!= 0? "YES" : "NO" // consecutive statements on a line must be separated by ';'return length > 1 && length % 2!= 0? "YES" : "NO" // string literal is unusedreturn length > 1 && length % 2!= 0? "YES" : "NO" // expression is not assignable: '&&' returns immutable valuereturn length > 1 && length % 2!= 0? "YES" : "NO" // '=' must have consistent whitespace on both sidesreturn length > 1 && length % 2!= 0? "YES" : "NO" // consecutive statements on a line must be separated by ';'return length > 1 && length % 2!= 0? "YES" : "NO" // type 'Int' cannot be used as a boolean; test for '!= 0' insteadfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
guard interval1.0 <= interval2.0 else {
return "NO"
}
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
let isPrime = length > 1 && (length % 2 == 1 || length % 3 == 0)
return isPrime? "YES" : "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
guard interval1.0 <= interval2.0 else {
return "NO"
}
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
let isPrime = length > 1 && (length % 2 == 1 || length % 3 == 0)
return isPrime? "YES" : "NO"
}
```return isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // expected expressionreturn isPrime? "YES" : "NO" // string literal is unusedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime? "YES" : "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
var isPrime = true
for i in 2..<length {
if length % i == 0 {
isPrime = false
break
}
}
return isPrime? "YES" : "NO"
}
```return isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // expected expressionreturn isPrime? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'return isPrime? "YES" : "NO" // consecutive statements on a line must be separated by ';'return isPrime? "YES" : "NO" // string literal is unusedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start1 = interval1.0
let end1 = interval1.1
let start2 = interval2.0
let end2 = interval2.1
if start1 > end2 || start2 > end1 {
return "NO"
}
let start = max(start1, start2)
let end = min(end1, end2)
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
return length > 1 && isPrime(length)? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
let length = end - start + 1
return length > 1 && isPrime(length)? "YES" : "NO"
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```return length > 1 && isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return length > 1 && isPrime(length)? "YES" : "NO" // expected expressionreturn length > 1 && isPrime(length)? "YES" : "NO" // consecutive statements on a line must be separated by ';'return length > 1 && isPrime(length)? "YES" : "NO" // string literal is unusedreturn length > 1 && isPrime(length)? "YES" : "NO" // cannot convert return expression of type 'Bool' to return type 'String'return length > 1 && isPrime(length)? "YES" : "NO" // optional type 'Bool?' cannot be used as a boolean; test for '!= nil' insteadreturn length > 1 && isPrime(length)? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Bool'func prodSigns(arr: [Int]) -> Int? {
guard arr.count > 0 else {
return nil
}
let positiveCount = arr.filter({ $0 > 0 }).count
let negativeCount = arr.filter({ $0 < 0 }).count
let zeroCount = arr.filter({ $0 == 0 }).count
let totalMagnitude = arr.reduce(0, { $0 + abs($1) })
let totalSign = positiveCount % 2 == 0? 1 : -1
return totalMagnitude * totalSign
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
Answer:
```swift
func prodSigns(arr: [Int]) -> Int? {
guard arr.count > 0 else {
return nil
}
let positiveCount = arr.filter({ $0 > 0 }).count
let negativeCount = arr.filter({ $0 < 0 }).count
let zeroCount = arr.filter({ $0 == 0 }).count
let totalMagnitude = arr.reduce(0, { $0 + abs($1) })
let totalSign = positiveCount % 2 == 0? 1 : -1
return totalMagnitude * totalSign
}
```let totalSign = positiveCount % 2 == 0? 1 : -1 // cannot use optional chaining on non-optional value of type 'Int'let totalSign = positiveCount % 2 == 0? 1 : -1 // consecutive statements on a line must be separated by ';'let totalSign = positiveCount % 2 == 0? 1 : -1 // expected expressionlet totalSign = positiveCount % 2 == 0? 1 : -1 // integer literal is unusedlet totalSign = positiveCount % 2 == 0? 1 : -1 // consecutive statements on a line must be separated by ';'func prodSigns(arr: [Int]) -> Int? {
guard arr.count > 0 else {
return nil
}
var sum = 0
var sign = 1
for num in arr {
sum += abs(num)
sign *= num > 0? 1 : num < 0? -1 : 0
}
return sum * sign
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
Answer:
```swift
func prodSigns(arr: [Int]) -> Int? {
guard arr.count > 0 else {
return nil
}
var sum = 0
var sign = 1
for num in arr {
sum += abs(num)
sign *= num > 0? 1 : num < 0? -1 : 0
}
return sum * sign
}
```sign *= num > 0? 1 : num < 0? -1 : 0 // cannot use optional chaining on non-optional value of type 'Int'sign *= num > 0? 1 : num < 0? -1 : 0 // consecutive statements on a line must be separated by ';'sign *= num > 0? 1 : num < 0? -1 : 0 // integer literal is unusedsign *= num > 0? 1 : num < 0? -1 : 0 // consecutive statements on a line must be separated by ';'sign *= num > 0? 1 : num < 0? -1 : 0 // expected expressionsign *= num > 0? 1 : num < 0? -1 : 0 // value of optional type 'Int?' must be unwrapped to a value of type 'Int'sign *= num > 0? 1 : num < 0? -1 : 0 // cannot convert value of type 'Bool' to expected argument type 'Int'func prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else {
return nil
}
let positiveCount = arr.filter { $0 > 0 }.count
let negativeCount = arr.filter { $0 < 0 }.count
let zeroCount = arr.filter { $0 == 0 }.count
return positiveCount * negativeCount * zeroCount
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
Answer:
```swift
func prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else {
return nil
}
let positiveCount = arr.filter { $0 > 0 }.count
let negativeCount = arr.filter { $0 < 0 }.count
let zeroCount = arr.filter { $0 == 0 }.count
return positiveCount * negativeCount * zeroCount
}
```guard!arr.isEmpty else { // expected expression, var, let or case in 'guard' conditionfunc prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else {
return nil
}
let positiveCount = arr.filter { $0 > 0 }.count
let negativeCount = arr.filter { $0 < 0 }.count
let zeroCount = arr.filter { $0 == 0 }.count
return positiveCount * negativeCount * zeroCount
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
Answer:
```swift
func prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else {
return nil
}
let positiveCount = arr.filter { $0 > 0 }.count
let negativeCount = arr.filter { $0 < 0 }.count
let zeroCount = arr.filter { $0 == 0 }.count
return positiveCount * negativeCount * zeroCount
}
```guard!arr.isEmpty else { // expected expression, var, let or case in 'guard' conditionfunc prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else {
return nil
}
let positiveCount = arr.filter { $0 > 0 }.count
let negativeCount = arr.filter { $0 < 0 }.count
let zeroCount = arr.filter { $0 == 0 }.count
return positiveCount * negativeCount * zeroCount
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
Answer:
```swift
func prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else {
return nil
}
let positiveCount = arr.filter { $0 > 0 }.count
let negativeCount = arr.filter { $0 < 0 }.count
let zeroCount = arr.filter { $0 == 0 }.count
return positiveCount * negativeCount * zeroCount
}
```guard!arr.isEmpty else { // expected expression, var, let or case in 'guard' conditionfunc prodSigns(arr: [Int]) -> Int? {
guard arr.count > 0 else {
return nil
}
let positiveCount = arr.filter({ $0 > 0 }).count
let negativeCount = arr.filter({ $0 < 0 }).count
let zeroCount = arr.filter({ $0 == 0 }).count
return positiveCount * negativeCount * zeroCount
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
Answer:
```swift
func prodSigns(arr: [Int]) -> Int? {
guard arr.count > 0 else {
return nil
}
let positiveCount = arr.filter({ $0 > 0 }).count
let negativeCount = arr.filter({ $0 < 0 }).count
let zeroCount = arr.filter({ $0 == 0 }).count
return positiveCount * negativeCount * zeroCount
}
``` // XCTAssertTrue failedfunc prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else {
return nil
}
var sum = 0
var sign = 1
for num in arr {
sum += abs(num)
sign *= num > 0? 1 : num < 0? -1 : 0
}
return sum * sign
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
Answer:
```swift
func prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else {
return nil
}
var sum = 0
var sign = 1
for num in arr {
sum += abs(num)
sign *= num > 0? 1 : num < 0? -1 : 0
}
return sum * sign
}
```guard!arr.isEmpty else { // expected expression, var, let or case in 'guard' conditionsign *= num > 0? 1 : num < 0? -1 : 0 // cannot use optional chaining on non-optional value of type 'Int'sign *= num > 0? 1 : num < 0? -1 : 0 // consecutive statements on a line must be separated by ';'sign *= num > 0? 1 : num < 0? -1 : 0 // integer literal is unusedsign *= num > 0? 1 : num < 0? -1 : 0 // consecutive statements on a line must be separated by ';'sign *= num > 0? 1 : num < 0? -1 : 0 // expected expressionsign *= num > 0? 1 : num < 0? -1 : 0 // value of optional type 'Int?' must be unwrapped to a value of type 'Int'sign *= num > 0? 1 : num < 0? -1 : 0 // cannot convert value of type 'Bool' to expected argument type 'Int'func prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else {
return nil
}
let positiveCount = arr.filter { $0 > 0 }.count
let negativeCount = arr.filter { $0 < 0 }.count
let zeroCount = arr.filter { $0 == 0 }.count
return positiveCount * negativeCount * zeroCount
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
Answer:
```swift
func prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else {
return nil
}
let positiveCount = arr.filter { $0 > 0 }.count
let negativeCount = arr.filter { $0 < 0 }.count
let zeroCount = arr.filter { $0 == 0 }.count
return positiveCount * negativeCount * zeroCount
}
```guard!arr.isEmpty else { // expected expression, var, let or case in 'guard' conditionfunc prodSigns(arr: [Int]) -> Int? {
guard arr.count > 0 else {
return nil
}
let positiveCount = arr.filter { $0 > 0 }.count
let negativeCount = arr.filter { $0 < 0 }.count
return positiveCount * negativeCount * arr.reduce(0, { $0 + abs($1) })
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
Answer:
```swift
func prodSigns(arr: [Int]) -> Int? {
guard arr.count > 0 else {
return nil
}
let positiveCount = arr.filter { $0 > 0 }.count
let negativeCount = arr.filter { $0 < 0 }.count
return positiveCount * negativeCount * arr.reduce(0, { $0 + abs($1) })
}
``` // XCTAssertTrue failedfunc prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else {
return nil
}
let positiveCount = arr.filter { $0 > 0 }.count
let negativeCount = arr.filter { $0 < 0 }.count
let zeroCount = arr.filter { $0 == 0 }.count
let totalCount = positiveCount + negativeCount + zeroCount
let totalSum = arr.reduce(0, +)
let totalProduct = positiveCount % 2 == 0? 1 : -1
return totalSum * totalProduct
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
Answer:
```swift
func prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else {
return nil
}
let positiveCount = arr.filter { $0 > 0 }.count
let negativeCount = arr.filter { $0 < 0 }.count
let zeroCount = arr.filter { $0 == 0 }.count
let totalCount = positiveCount + negativeCount + zeroCount
let totalSum = arr.reduce(0, +)
let totalProduct = positiveCount % 2 == 0? 1 : -1
return totalSum * totalProduct
}
```guard!arr.isEmpty else { // expected expression, var, let or case in 'guard' conditionlet totalProduct = positiveCount % 2 == 0? 1 : -1 // consecutive statements on a line must be separated by ';'let totalProduct = positiveCount % 2 == 0? 1 : -1 // integer literal is unusedlet totalProduct = positiveCount % 2 == 0? 1 : -1 // consecutive statements on a line must be separated by ';'let totalProduct = positiveCount % 2 == 0? 1 : -1 // cannot use optional chaining on non-optional value of type 'Int'let totalProduct = positiveCount % 2 == 0? 1 : -1 // expected expressionfunc minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
let m = grid[0].count
let dp = Array(repeating: Array(repeating: 0, count: k + 1), count: n)
let dirs = [(x: Int, y: Int), (x: Int, y: Int)] {
return [(x: $0 - 1, y: $1), (x: $0 + 1, y: $1), (x: $0, y: $1 - 1), (x: $0, y: $1 + 1)]
}
let rec = { (x: Int, y: Int, k: Int) -> Int in
if k == 0 {
return 0
}
if x < 0 || y < 0 || x >= n || y >= m {
return Int.max
}
if dp[x][y]!= 0 {
return dp[x][y]
}
let res = grid[x][y] + rec(x: x + dirs[0].x, y: y + dirs[0].y, k: k - 1)
let res2 = grid[x][y] + rec(x: x + dirs[1].x, y: y + dirs[1].y, k: k - 1)
let res3 = grid[x][y] + rec(x: x + dirs[2].x, y: y + dirs[2].y, k: k - 1)
let res4 = grid[x][y] + rec(x: x + dirs[3].x, y: y + dirs[3].y, k: k - 1)
dp[x][y] = min(res, res2, res3, res4)
return dp[x][y]
}
return rec(x: 0, y: 0, k: k)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
Answer:
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
let m = grid[0].count
let dp = Array(repeating: Array(repeating: 0, count: k + 1), count: n)
let dirs = [(x: Int, y: Int), (x: Int, y: Int)] {
return [(x: $0 - 1, y: $1), (x: $0 + 1, y: $1), (x: $0, y: $1 - 1), (x: $0, y: $1 + 1)]
}
let rec = { (x: Int, y: Int, k: Int) -> Int in
if k == 0 {
return 0
}
if x < 0 || y < 0 || x >= n || y >= m {
return Int.max
}
if dp[x][y]!= 0 {
return dp[x][y]
}
let res = grid[x][y] + rec(x: x + dirs[0].x, y: y + dirs[0].y, k: k - 1)
let res2 = grid[x][y] + rec(x: x + dirs[1].x, y: y + dirs[1].y, k: k - 1)
let res3 = grid[x][y] + rec(x: x + dirs[2].x, y: y + dirs[2].y, k: k - 1)
let res4 = grid[x][y] + rec(x: x + dirs[3].x, y: y + dirs[3].y, k: k - 1)
dp[x][y] = min(res, res2, res3, res4)
return dp[x][y]
}
return rec(x: 0, y: 0, k: k)
}
```let dirs = [(x: Int, y: Int), (x: Int, y: Int)] { // expected member name or constructor call after type namelet dirs = [(x: Int, y: Int), (x: Int, y: Int)] { // computed property must have an explicit typelet dirs = [(x: Int, y: Int), (x: Int, y: Int)] { // expected member name or constructor call after type namelet dirs = [(x: Int, y: Int), (x: Int, y: Int)] { // variable with getter/setter cannot have an initial valuelet dirs = [(x: Int, y: Int), (x: Int, y: Int)] { // 'let' declarations cannot be computed propertiesreturn [(x: $0 - 1, y: $1), (x: $0 + 1, y: $1), (x: $0, y: $1 - 1), (x: $0, y: $1 + 1)] // anonymous closure argument not contained in a closurereturn [(x: $0 - 1, y: $1), (x: $0 + 1, y: $1), (x: $0, y: $1 - 1), (x: $0, y: $1 + 1)] // cannot convert value of type '(x: _, y: Int)' to expected element type '(x: Int, y: Int).Type'return [(x: $0 - 1, y: $1), (x: $0 + 1, y: $1), (x: $0, y: $1 - 1), (x: $0, y: $1 + 1)] // anonymous closure argument not contained in a closurereturn [(x: $0 - 1, y: $1), (x: $0 + 1, y: $1), (x: $0, y: $1 - 1), (x: $0, y: $1 + 1)] // anonymous closure argument not contained in a closurereturn [(x: $0 - 1, y: $1), (x: $0 + 1, y: $1), (x: $0, y: $1 - 1), (x: $0, y: $1 + 1)] // anonymous closure argument not contained in a closurereturn [(x: $0 - 1, y: $1), (x: $0 + 1, y: $1), (x: $0, y: $1 - 1), (x: $0, y: $1 + 1)] // anonymous closure argument not contained in a closurereturn [(x: $0 - 1, y: $1), (x: $0 + 1, y: $1), (x: $0, y: $1 - 1), (x: $0, y: $1 + 1)] // anonymous closure argument not contained in a closurereturn [(x: $0 - 1, y: $1), (x: $0 + 1, y: $1), (x: $0, y: $1 - 1), (x: $0, y: $1 + 1)] // cannot convert value of type '(x: _, y: Int)' to expected element type '(x: Int, y: Int).Type'return [(x: $0 - 1, y: $1), (x: $0 + 1, y: $1), (x: $0, y: $1 - 1), (x: $0, y: $1 + 1)] // cannot convert value of type '(x: Int, y: _)' to expected element type '(x: Int, y: Int).Type'return [(x: $0 - 1, y: $1), (x: $0 + 1, y: $1), (x: $0, y: $1 - 1), (x: $0, y: $1 + 1)] // cannot convert value of type '(x: Int, y: _)' to expected element type '(x: Int, y: Int).Type'return [(x: $0 - 1, y: $1), (x: $0 + 1, y: $1), (x: $0, y: $1 - 1), (x: $0, y: $1 + 1)] // anonymous closure argument not contained in a closurereturn [(x: $0 - 1, y: $1), (x: $0 + 1, y: $1), (x: $0, y: $1 - 1), (x: $0, y: $1 + 1)] // anonymous closure argument not contained in a closureif dp[x][y]!= 0 { // '=' must have consistent whitespace on both sidesif dp[x][y]!= 0 { // cannot force unwrap value of non-optional type 'Int'if dp[x][y]!= 0 { // use of '=' in a boolean context, did you mean '=='?func minPath(grid: [[Int]], k: Int) -> [Int] {
let m = grid.count
let n = grid[0].count
let dp = Array(repeating: Array(repeating: 0, count: k + 1), count: m)
for i in 0..<m {
for j in 0..<n {
dp[i][1] = grid[i][j]
}
}
for l in 2..<k + 1 {
for i in 0..<m {
for j in 0..<n {
dp[i][l] = Int.max
for di in -1...1 {
for dj in -1...1 {
if di == 0 && dj == 0 { continue }
let ni = i + di
let nj = j + dj
if ni >= 0 && ni < m && nj >= 0 && nj < n {
dp[i][l] = min(dp[i][l], dp[ni][l - 1] + grid[i][j])
}
}
}
}
}
}
var result = [Int]()
var i = 0, j = k
while i < m && j > 0 {
result.append(dp[i][j])
let di = i + 1 == m? 0 : (i + 1 < m && dp[i + 1][j] < dp[i][j]? 1 : -1)
let dj = j + 1 == k? 0 : (j + 1 < k && dp[i][j + 1] < dp[i][j]? 1 : -1)
i += di
j += dj
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
Answer:
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
let m = grid.count
let n = grid[0].count
let dp = Array(repeating: Array(repeating: 0, count: k + 1), count: m)
for i in 0..<m {
for j in 0..<n {
dp[i][1] = grid[i][j]
}
}
for l in 2..<k + 1 {
for i in 0..<m {
for j in 0..<n {
dp[i][l] = Int.max
for di in -1...1 {
for dj in -1...1 {
if di == 0 && dj == 0 { continue }
let ni = i + di
let nj = j + dj
if ni >= 0 && ni < m && nj >= 0 && nj < n {
dp[i][l] = min(dp[i][l], dp[ni][l - 1] + grid[i][j])
}
}
}
}
}
}
var result = [Int]()
var i = 0, j = k
while i < m && j > 0 {
result.append(dp[i][j])
let di = i + 1 == m? 0 : (i + 1 < m && dp[i + 1][j] < dp[i][j]? 1 : -1)
let dj = j + 1 == k? 0 : (j + 1 < k && dp[i][j + 1] < dp[i][j]? 1 : -1)
i += di
j += dj
}
return result
}
```dp[i][1] = grid[i][j] // cannot assign through subscript: 'dp' is a 'let' constantdp[i][l] = Int.max // cannot assign through subscript: 'dp' is a 'let' constantdp[i][l] = min(dp[i][l], dp[ni][l - 1] + grid[i][j]) // cannot assign through subscript: 'dp' is a 'let' constantlet di = i + 1 == m? 0 : (i + 1 < m && dp[i + 1][j] < dp[i][j]? 1 : -1) // integer literal is unusedlet di = i + 1 == m? 0 : (i + 1 < m && dp[i + 1][j] < dp[i][j]? 1 : -1) // consecutive statements on a line must be separated by ';'let di = i + 1 == m? 0 : (i + 1 < m && dp[i + 1][j] < dp[i][j]? 1 : -1) // consecutive statements on a line must be separated by ';'let di = i + 1 == m? 0 : (i + 1 < m && dp[i + 1][j] < dp[i][j]? 1 : -1) // cannot use optional chaining on non-optional value of type 'Int'let di = i + 1 == m? 0 : (i + 1 < m && dp[i + 1][j] < dp[i][j]? 1 : -1) // expected expressionlet dj = j + 1 == k? 0 : (j + 1 < k && dp[i][j + 1] < dp[i][j]? 1 : -1) // integer literal is unusedlet dj = j + 1 == k? 0 : (j + 1 < k && dp[i][j + 1] < dp[i][j]? 1 : -1) // consecutive statements on a line must be separated by ';'let dj = j + 1 == k? 0 : (j + 1 < k && dp[i][j + 1] < dp[i][j]? 1 : -1) // consecutive statements on a line must be separated by ';'let dj = j + 1 == k? 0 : (j + 1 < k && dp[i][j + 1] < dp[i][j]? 1 : -1) // cannot use optional chaining on non-optional value of type 'Int'let dj = j + 1 == k? 0 : (j + 1 < k && dp[i][j + 1] < dp[i][j]? 1 : -1) // expected expressionfunc minPath(grid: [[Int]], k: Int) -> [Int] {
let m = grid.count
let n = grid[0].count
let dp = Array(repeating: Array(repeating: 0, count: k + 1), count: m)
let dirs = [(0, 1), (0, -1), (1, 0), (-1, 0)]
for i in 0..<m {
for j in 0..<n {
dp[i][1] = grid[i][j]
}
}
for i in 1..<k + 1 {
for j in 0..<m {
for dir in dirs {
let x = j + dir.0
let y = i + dir.1
if x >= 0 && x < n && y >= 0 && y < m {
dp[y][i + 1] = min(dp[y][i + 1], dp[j][i] + grid[y][x])
}
}
}
}
var result = [Int]()
var i = 0
var j = k
while i < m && j >= 0 {
result.append(dp[i][j])
let dir = dirs.first { (x, y) in
i + x >= 0 && i + x < m && j + y >= 0 && j + y < k
}!
i += dir.0
j -= dir.1
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
Answer:
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
let m = grid.count
let n = grid[0].count
let dp = Array(repeating: Array(repeating: 0, count: k + 1), count: m)
let dirs = [(0, 1), (0, -1), (1, 0), (-1, 0)]
for i in 0..<m {
for j in 0..<n {
dp[i][1] = grid[i][j]
}
}
for i in 1..<k + 1 {
for j in 0..<m {
for dir in dirs {
let x = j + dir.0
let y = i + dir.1
if x >= 0 && x < n && y >= 0 && y < m {
dp[y][i + 1] = min(dp[y][i + 1], dp[j][i] + grid[y][x])
}
}
}
}
var result = [Int]()
var i = 0
var j = k
while i < m && j >= 0 {
result.append(dp[i][j])
let dir = dirs.first { (x, y) in
i + x >= 0 && i + x < m && j + y >= 0 && j + y < k
}!
i += dir.0
j -= dir.1
}
return result
}
```dp[i][1] = grid[i][j] // cannot assign through subscript: 'dp' is a 'let' constantdp[y][i + 1] = min(dp[y][i + 1], dp[j][i] + grid[y][x]) // cannot assign through subscript: 'dp' is a 'let' constantfunc minPath(grid: [[Int]], k: Int) -> [Int] {
let m = grid.count
let n = grid[0].count
let dp = Array(repeating: Array(repeating: 0, count: k + 1), count: m)
for i in 0..<m {
for j in 0..<n {
dp[i][1] = grid[i][j]
}
}
for l in 2..<k + 1 {
for i in 0..<m {
for j in 0..<n {
dp[i][l] = Int.max
for di in -1...1 {
for dj in -1...1 {
if di == 0 && dj == 0 {
continue
}
let ni = i + di
let nj = j + dj
if 0 <= ni && ni < m && 0 <= nj && nj < n {
dp[i][l] = min(dp[i][l], dp[ni][l - 1] + grid[i][j])
}
}
}
}
}
}
var result = [Int]()
var i = 0, j = k
while i < m && j > 0 {
result.append(dp[i][j])
let di = i + 1 == m? 0 : (i + 1 == m - 1? 1 : 2)
let dj = j - 1 == 0? 0 : (j - 1 == 1? 1 : 2)
i += di
j -= dj
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
Answer:
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
let m = grid.count
let n = grid[0].count
let dp = Array(repeating: Array(repeating: 0, count: k + 1), count: m)
for i in 0..<m {
for j in 0..<n {
dp[i][1] = grid[i][j]
}
}
for l in 2..<k + 1 {
for i in 0..<m {
for j in 0..<n {
dp[i][l] = Int.max
for di in -1...1 {
for dj in -1...1 {
if di == 0 && dj == 0 {
continue
}
let ni = i + di
let nj = j + dj
if 0 <= ni && ni < m && 0 <= nj && nj < n {
dp[i][l] = min(dp[i][l], dp[ni][l - 1] + grid[i][j])
}
}
}
}
}
}
var result = [Int]()
var i = 0, j = k
while i < m && j > 0 {
result.append(dp[i][j])
let di = i + 1 == m? 0 : (i + 1 == m - 1? 1 : 2)
let dj = j - 1 == 0? 0 : (j - 1 == 1? 1 : 2)
i += di
j -= dj
}
return result
}
```dp[i][1] = grid[i][j] // cannot assign through subscript: 'dp' is a 'let' constantdp[i][l] = Int.max // cannot assign through subscript: 'dp' is a 'let' constantdp[i][l] = min(dp[i][l], dp[ni][l - 1] + grid[i][j]) // cannot assign through subscript: 'dp' is a 'let' constantlet di = i + 1 == m? 0 : (i + 1 == m - 1? 1 : 2) // consecutive statements on a line must be separated by ';'let di = i + 1 == m? 0 : (i + 1 == m - 1? 1 : 2) // consecutive statements on a line must be separated by ';'let di = i + 1 == m? 0 : (i + 1 == m - 1? 1 : 2) // cannot use optional chaining on non-optional value of type 'Int'let di = i + 1 == m? 0 : (i + 1 == m - 1? 1 : 2) // expected expressionlet di = i + 1 == m? 0 : (i + 1 == m - 1? 1 : 2) // integer literal is unusedlet dj = j - 1 == 0? 0 : (j - 1 == 1? 1 : 2) // cannot use optional chaining on non-optional value of type 'Int'let dj = j - 1 == 0? 0 : (j - 1 == 1? 1 : 2) // consecutive statements on a line must be separated by ';'let dj = j - 1 == 0? 0 : (j - 1 == 1? 1 : 2) // integer literal is unusedlet dj = j - 1 == 0? 0 : (j - 1 == 1? 1 : 2) // expected expressionlet dj = j - 1 == 0? 0 : (j - 1 == 1? 1 : 2) // consecutive statements on a line must be separated by ';'func minPath(grid: [[Int]], k: Int) -> [Int] {
let m = grid.count
let n = grid[0].count
let dp = Array(repeating: Array(repeating: 0, count: k + 1), count: m)
for i in 0..<m {
for j in 0..<n {
dp[i][1] = grid[i][j]
}
}
for l in 2..<k + 1 {
for i in 0..<m {
for j in 0..<n {
let minValue = dp[i][l - 1]
let top = i > 0? dp[i - 1][l] : Int.max
let left = j > 0? dp[i][l - 1] : Int.max
dp[i][l] = min(minValue, top, left) + grid[i][j]
}
}
}
var result = [Int]()
var i = m - 1
var j = n - 1
while k > 0 {
result.append(dp[i][k])
let top = i > 0? dp[i - 1][k] : Int.max
let left = j > 0? dp[i][k - 1] : Int.max
if dp[i][k] == top + grid[i][j] {
j -= 1
} else {
i -= 1
}
k -= 1
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
Answer:
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
let m = grid.count
let n = grid[0].count
let dp = Array(repeating: Array(repeating: 0, count: k + 1), count: m)
for i in 0..<m {
for j in 0..<n {
dp[i][1] = grid[i][j]
}
}
for l in 2..<k + 1 {
for i in 0..<m {
for j in 0..<n {
let minValue = dp[i][l - 1]
let top = i > 0? dp[i - 1][l] : Int.max
let left = j > 0? dp[i][l - 1] : Int.max
dp[i][l] = min(minValue, top, left) + grid[i][j]
}
}
}
var result = [Int]()
var i = m - 1
var j = n - 1
while k > 0 {
result.append(dp[i][k])
let top = i > 0? dp[i - 1][k] : Int.max
let left = j > 0? dp[i][k - 1] : Int.max
if dp[i][k] == top + grid[i][j] {
j -= 1
} else {
i -= 1
}
k -= 1
}
return result
}
```dp[i][1] = grid[i][j] // cannot assign through subscript: 'dp' is a 'let' constantlet top = i > 0? dp[i - 1][l] : Int.max // consecutive statements on a line must be separated by ';'let top = i > 0? dp[i - 1][l] : Int.max // value of optional type 'Int?' must be unwrapped to a value of type 'Int'let top = i > 0? dp[i - 1][l] : Int.max // expected expressionlet top = i > 0? dp[i - 1][l] : Int.max // consecutive statements on a line must be separated by ';'let top = i > 0? dp[i - 1][l] : Int.max // expression of type 'Int' is unusedlet top = i > 0? dp[i - 1][l] : Int.max // cannot use optional chaining on non-optional value of type 'Int'let left = j > 0? dp[i][l - 1] : Int.max // consecutive statements on a line must be separated by ';'let left = j > 0? dp[i][l - 1] : Int.max // cannot use optional chaining on non-optional value of type 'Int'let left = j > 0? dp[i][l - 1] : Int.max // value of optional type 'Int?' must be unwrapped to a value of type 'Int'let left = j > 0? dp[i][l - 1] : Int.max // expression of type 'Int' is unusedlet left = j > 0? dp[i][l - 1] : Int.max // expected expressionlet left = j > 0? dp[i][l - 1] : Int.max // consecutive statements on a line must be separated by ';'let top = i > 0? dp[i - 1][k] : Int.max // expected expressionlet top = i > 0? dp[i - 1][k] : Int.max // consecutive statements on a line must be separated by ';'let top = i > 0? dp[i - 1][k] : Int.max // consecutive statements on a line must be separated by ';'let top = i > 0? dp[i - 1][k] : Int.max // value of optional type 'Int?' must be unwrapped to a value of type 'Int'let top = i > 0? dp[i - 1][k] : Int.max // cannot use optional chaining on non-optional value of type 'Int'let top = i > 0? dp[i - 1][k] : Int.max // expression of type 'Int' is unusedlet left = j > 0? dp[i][k - 1] : Int.max // consecutive statements on a line must be separated by ';'let left = j > 0? dp[i][k - 1] : Int.max // cannot use optional chaining on non-optional value of type 'Int'let left = j > 0? dp[i][k - 1] : Int.max // value of optional type 'Int?' must be unwrapped to a value of type 'Int'let left = j > 0? dp[i][k - 1] : Int.max // expression of type 'Int' is unusedlet left = j > 0? dp[i][k - 1] : Int.max // expected expressionlet left = j > 0? dp[i][k - 1] : Int.max // consecutive statements on a line must be separated by ';'k -= 1 // left side of mutating operator isn't mutable: 'k' is a 'let' constantfunc minPath(grid: [[Int]], k: Int) -> [Int] {
guard k > 0 else {
return []
}
let m = grid.count
let n = grid[0].count
let dp = Array(repeating: Array(repeating: 0, count: k + 1), count: m)
let dirs = [(x: Int, y: Int)] {
return [(-1, 0), (1, 0), (0, -1), (0, 1)]
}
let rec = { (x: Int, y: Int, k: Int) -> Int in
guard k > 0 else {
return 0
}
if x < 0 || y < 0 || x >= m || y >= n {
return Int.max
}
if dp[x][y]!= 0 {
return dp[x][y]
}
let res = grid[x][y] + rec(x + dirs[0].x, y + dirs[0].y, k - 1)
dp[x][y] = res
return res
}
let startX = 0
let startY = 0
return rec(startX, startY, k) == 0? [] : rec(startX, startY, k).path
}
extension Int {
var path: [Int] {
var path = [self]
var x = self
while x > 0 {
x /= 10
path.append(x % 10)
}
return path.reversed()
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
Answer:
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
guard k > 0 else {
return []
}
let m = grid.count
let n = grid[0].count
let dp = Array(repeating: Array(repeating: 0, count: k + 1), count: m)
let dirs = [(x: Int, y: Int)] {
return [(-1, 0), (1, 0), (0, -1), (0, 1)]
}
let rec = { (x: Int, y: Int, k: Int) -> Int in
guard k > 0 else {
return 0
}
if x < 0 || y < 0 || x >= m || y >= n {
return Int.max
}
if dp[x][y]!= 0 {
return dp[x][y]
}
let res = grid[x][y] + rec(x + dirs[0].x, y + dirs[0].y, k - 1)
dp[x][y] = res
return res
}
let startX = 0
let startY = 0
return rec(startX, startY, k) == 0? [] : rec(startX, startY, k).path
}
extension Int {
var path: [Int] {
var path = [self]
var x = self
while x > 0 {
x /= 10
path.append(x % 10)
}
return path.reversed()
}
}
```let dirs = [(x: Int, y: Int)] { // expected member name or constructor call after type namelet dirs = [(x: Int, y: Int)] { // variable with getter/setter cannot have an initial valuelet dirs = [(x: Int, y: Int)] { // 'let' declarations cannot be computed propertieslet dirs = [(x: Int, y: Int)] { // computed property must have an explicit typereturn [(-1, 0), (1, 0), (0, -1), (0, 1)] // cannot convert return expression of type '[(Int, Int)]' to return type '[(x: Int, y: Int)].Type'if dp[x][y]!= 0 { // use of '=' in a boolean context, did you mean '=='?if dp[x][y]!= 0 { // cannot force unwrap value of non-optional type 'Int'if dp[x][y]!= 0 { // '=' must have consistent whitespace on both sidesreturn rec(startX, startY, k) == 0? [] : rec(startX, startY, k).path // expected expressionreturn rec(startX, startY, k) == 0? [] : rec(startX, startY, k).path // consecutive statements on a line must be separated by ';'return rec(startX, startY, k) == 0? [] : rec(startX, startY, k).path // value of type 'Int' has no subscriptsreturn rec(startX, startY, k) == 0? [] : rec(startX, startY, k).path // cannot use optional chaining on non-optional value of type 'Int'return rec(startX, startY, k) == 0? [] : rec(startX, startY, k).path // cannot convert return expression of type 'Bool' to return type '[Int]'func minPath(grid: [[Int]], k: Int) -> [Int] {
guard k > 0 else {
return []
}
let m = grid.count
let n = grid[0].count
let dp = Array(repeating: Array(repeating: 0, count: k + 1), count: m)
for i in 0..<m {
for j in 0..<n {
dp[i][1] = grid[i][j]
}
}
for l in 2..<k + 1 {
for i in 0..<m {
for j in 0..<n {
dp[i][l] = Int.max
for di in -1...1 {
for dj in -1...1 {
if di == 0 && dj == 0 {
continue
}
let ni = i + di
let nj = j + dj
if ni >= 0 && ni < m && nj >= 0 && nj < n {
dp[i][l] = min(dp[i][l], dp[ni][l - 1] + grid[i][j])
}
}
}
}
}
}
var result = [Int]()
var i = 0, j = k
while i < m && j > 0 {
result.append(dp[i][j])
let di = i + 1 == m? 0 : (grid[i + 1][j] > grid[i][j]? 1 : -1)
let dj = j + 1 == k? 0 : (grid[i][j + 1] > grid[i][j]? 1 : -1)
i += di
j += dj
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
Answer:
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
guard k > 0 else {
return []
}
let m = grid.count
let n = grid[0].count
let dp = Array(repeating: Array(repeating: 0, count: k + 1), count: m)
for i in 0..<m {
for j in 0..<n {
dp[i][1] = grid[i][j]
}
}
for l in 2..<k + 1 {
for i in 0..<m {
for j in 0..<n {
dp[i][l] = Int.max
for di in -1...1 {
for dj in -1...1 {
if di == 0 && dj == 0 {
continue
}
let ni = i + di
let nj = j + dj
if ni >= 0 && ni < m && nj >= 0 && nj < n {
dp[i][l] = min(dp[i][l], dp[ni][l - 1] + grid[i][j])
}
}
}
}
}
}
var result = [Int]()
var i = 0, j = k
while i < m && j > 0 {
result.append(dp[i][j])
let di = i + 1 == m? 0 : (grid[i + 1][j] > grid[i][j]? 1 : -1)
let dj = j + 1 == k? 0 : (grid[i][j + 1] > grid[i][j]? 1 : -1)
i += di
j += dj
}
return result
}
```dp[i][1] = grid[i][j] // cannot assign through subscript: 'dp' is a 'let' constantdp[i][l] = Int.max // cannot assign through subscript: 'dp' is a 'let' constantdp[i][l] = min(dp[i][l], dp[ni][l - 1] + grid[i][j]) // cannot assign through subscript: 'dp' is a 'let' constantlet di = i + 1 == m? 0 : (grid[i + 1][j] > grid[i][j]? 1 : -1) // consecutive statements on a line must be separated by ';'let di = i + 1 == m? 0 : (grid[i + 1][j] > grid[i][j]? 1 : -1) // consecutive statements on a line must be separated by ';'let di = i + 1 == m? 0 : (grid[i + 1][j] > grid[i][j]? 1 : -1) // integer literal is unusedlet di = i + 1 == m? 0 : (grid[i + 1][j] > grid[i][j]? 1 : -1) // expected expressionlet di = i + 1 == m? 0 : (grid[i + 1][j] > grid[i][j]? 1 : -1) // cannot use optional chaining on non-optional value of type 'Int'let dj = j + 1 == k? 0 : (grid[i][j + 1] > grid[i][j]? 1 : -1) // integer literal is unusedlet dj = j + 1 == k? 0 : (grid[i][j + 1] > grid[i][j]? 1 : -1) // consecutive statements on a line must be separated by ';'let dj = j + 1 == k? 0 : (grid[i][j + 1] > grid[i][j]? 1 : -1) // consecutive statements on a line must be separated by ';'let dj = j + 1 == k? 0 : (grid[i][j + 1] > grid[i][j]? 1 : -1) // cannot use optional chaining on non-optional value of type 'Int'let dj = j + 1 == k? 0 : (grid[i][j + 1] > grid[i][j]? 1 : -1) // expected expressionfunc minPath(grid: [[Int]], k: Int) -> [Int] {
let m = grid.count
let n = grid[0].count
let dp = Array(repeating: Array(repeating: 0, count: k + 1), count: m)
for i in 0..<m {
for j in 0..<n {
dp[i][1] = grid[i][j]
}
}
for l in 2..<k + 1 {
for i in 0..<m {
for j in 0..<n {
dp[i][l] = Int.max
for x in 0..<m {
for y in 0..<n {
if i == x || j == y {
dp[i][l] = min(dp[i][l], dp[x][l - 1])
}
}
}
}
}
}
var result = [Int]()
var i = 0, j = k
while i < m && j > 0 {
result.append(dp[i][j])
if j == 1 {
i += 1
} else {
j -= 1
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
Answer:
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
let m = grid.count
let n = grid[0].count
let dp = Array(repeating: Array(repeating: 0, count: k + 1), count: m)
for i in 0..<m {
for j in 0..<n {
dp[i][1] = grid[i][j]
}
}
for l in 2..<k + 1 {
for i in 0..<m {
for j in 0..<n {
dp[i][l] = Int.max
for x in 0..<m {
for y in 0..<n {
if i == x || j == y {
dp[i][l] = min(dp[i][l], dp[x][l - 1])
}
}
}
}
}
}
var result = [Int]()
var i = 0, j = k
while i < m && j > 0 {
result.append(dp[i][j])
if j == 1 {
i += 1
} else {
j -= 1
}
}
return result
}
```dp[i][1] = grid[i][j] // cannot assign through subscript: 'dp' is a 'let' constantdp[i][l] = Int.max // cannot assign through subscript: 'dp' is a 'let' constantdp[i][l] = min(dp[i][l], dp[x][l - 1]) // cannot assign through subscript: 'dp' is a 'let' constantfunc minPath(grid: [[Int]], k: Int) -> [Int] {
let m = grid.count
let n = grid[0].count
let dp = Array(repeating: Array(repeating: 0, count: k + 1), count: m)
for i in 0..<m {
for j in 0..<n {
dp[i][0] = grid[i][j]
}
}
for i in 0..<m {
for j in 0..<n {
for k in 1..<k + 1 {
dp[i][k] = min(dp[i - 1][k - 1], dp[i][k - 1], dp[i][k - 2]) + grid[i][j]
}
}
}
var result = [Int]()
var i = m - 1
var j = k
while i >= 0 && j >= 0 {
result.append(dp[i][j])
if j > 0 && dp[i - 1][j - 1] == dp[i][j - 1] {
i -= 1
} else if dp[i][j - 1] < dp[i - 1][j] {
j -= 1
} else {
i -= 1
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
Answer:
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
let m = grid.count
let n = grid[0].count
let dp = Array(repeating: Array(repeating: 0, count: k + 1), count: m)
for i in 0..<m {
for j in 0..<n {
dp[i][0] = grid[i][j]
}
}
for i in 0..<m {
for j in 0..<n {
for k in 1..<k + 1 {
dp[i][k] = min(dp[i - 1][k - 1], dp[i][k - 1], dp[i][k - 2]) + grid[i][j]
}
}
}
var result = [Int]()
var i = m - 1
var j = k
while i >= 0 && j >= 0 {
result.append(dp[i][j])
if j > 0 && dp[i - 1][j - 1] == dp[i][j - 1] {
i -= 1
} else if dp[i][j - 1] < dp[i - 1][j] {
j -= 1
} else {
i -= 1
}
}
return result
}
```dp[i][0] = grid[i][j] // cannot assign through subscript: 'dp' is a 'let' constantdp[i][k] = min(dp[i - 1][k - 1], dp[i][k - 1], dp[i][k - 2]) + grid[i][j] // cannot assign through subscript: 'dp' is a 'let' constantQuestion:
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
Answer:
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
let m = grid.count
let n = grid[0].count
let dp = Array(repeating: Array(repeating: 0, count: k + 1), count: m)
let dirs = [(x: Int, y: Int), (x: Int, y: Int)] {
($0.x == 0)? (0, 1) : ($0.x == m - 1)? (0, -1) : ($0.y == 0)? (1, 0) : (-1, 0)
}
let dirs = dirs.map { (x: Int, y: Int) in
(x: x + grid[0].count, y: y + grid.count)
}
let dirs = dirs.filter { $0.x >= 0 && $0.y >= 0 && $0.x < m * n && $0.y < m * n }
let dirs = dirs.sorted { $0.x * m + $0.y < $1.x * m + $1.y }
let dirs = dirs.prefix(k)
let dirs = dirs.map { (x: Int, y: Int) in
(x: x / m, y: x % m)
}
let dirs = dirs.map { (x: Int, y: Int) in
(x: x - grid[0].count, y: y - grid.count)
}
let dirs = dirs.sorted { $0.x * m + $0.y < $1.x * m + $1.y }
let dirs = dirs.prefix(k)
let dirs = dirs.map { (x: Int, y: Int) in
(x: x / m, y: x % m)
}
let dirs = dirs.map { (x: Int, y: Int) in
(x: x - grid[0].count, y: y - grid.count)
}
let dirs = dirs.sorted { $0.x * m + $0.y < $1.x * m + $1.y }
let dirs = dirs.prefix(k)
let dirs = dirs.map { (x: Int, y: Int) in
(x: x / m, y: x % m)
}
let dirs = dirs.map { (x: Int, y: Int) in
(x: x - grid[0].count, y: y - grid.count)
}
let dirs = dirs.sorted { $0.x * m + $0.y < $1.x * m + $1.y }
let dirs = dirs.prefix(k)
let dirs = dirs.map { (x: Int, y: Int) in
(x: x / m, y: x % m)
}
let dirs = dirs.map { (x: Int, y: Int) in
(x: x - grid[0].count, y: y - grid.count)
}
let dirs = dirs.sorted { $0.x * m + $0.y < $1.x * m + $1.y }
let dirs = dirs.prefix(k)
let dirs = dirs.map { (x: Int, y: Int) in
(x: x / m, y: x % m)
}
let dirs = dirs.map { (x: Int, y: Int) in
(x: x - grid[0].count, y: y - grid.count)
}
let dirs = dirs.sorted { $0.x * m + $0.y < $1.x * m + $1.y }
let dirs = dirs.prefix(k)
let dirs = dirs.map { (x: Int, y: Int) in
(x: x / m, y: x % m)
}
let dirs = dirs.map { (x: Int, y: Int) in
(x: x - grid[0].count, y: y - grid.count)
}
let dirs = dirs.sorted { $0.x * m + $0.y < $1.x * m + $1.y }
let dirs = dirs.prefix(k)
let dirs = dirs.map { (x: Int, y: Int) in
(x: x / m, y: x % m)
}
let dirs = dirs.map { (x: Int, y: Int) in
(x: x - grid[0].count, y: y - grid.count)
}
let dirs =func tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[0] = 1
result[1] = 3
for i in 2..<n+1 {
if i % 2 == 0 {
result[i] = 1 + i / 2
} else {
result[i] = result[i - 1] + result[i - 2] + result[i + 1]
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
Answer:
```swift
func tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[0] = 1
result[1] = 3
for i in 2..<n+1 {
if i % 2 == 0 {
result[i] = 1 + i / 2
} else {
result[i] = result[i - 1] + result[i - 2] + result[i + 1]
}
}
return result
}
``` // Fatal error: Index out of rangefunc tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[0] = 1
result[1] = 3
result[2] = 2
for i in 3...n {
if i % 2 == 0 {
result[i] = 1 + i / 2
} else {
result[i] = result[i - 1] + result[i - 2] + result[i + 1]
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
Answer:
```swift
func tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[0] = 1
result[1] = 3
result[2] = 2
for i in 3...n {
if i % 2 == 0 {
result[i] = 1 + i / 2
} else {
result[i] = result[i - 1] + result[i - 2] + result[i + 1]
}
}
return result
}
``` // Fatal error: Index out of rangefunc tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[1] = 3
result[2] = 3
for i in 3...n {
if i % 2 == 0 {
result[i] = i / 2
} else {
result[i] = result[i - 1] + result[i - 2] + result[i + 1]
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
Answer:
```swift
func tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[1] = 3
result[2] = 3
for i in 3...n {
if i % 2 == 0 {
result[i] = i / 2
} else {
result[i] = result[i - 1] + result[i - 2] + result[i + 1]
}
}
return result
}
``` // Fatal error: Index out of rangefunc tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[0] = 1
result[1] = 3
for i in 2..<n + 1 {
if i % 2 == 0 {
result[i] = i / 2
} else {
result[i] = result[i - 1] + result[i - 2] + result[i + 1]
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
Answer:
```swift
func tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[0] = 1
result[1] = 3
for i in 2..<n + 1 {
if i % 2 == 0 {
result[i] = i / 2
} else {
result[i] = result[i - 1] + result[i - 2] + result[i + 1]
}
}
return result
}
``` // Fatal error: Index out of rangefunc tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[0] = 1
result[1] = 3
result[2] = 2
for i in 3...n {
if i % 2 == 0 {
result[i] = 1 + i / 2
} else {
result[i] = result[i - 1] + result[i - 2] + result[i + 1]
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
Answer:
```swift
func tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[0] = 1
result[1] = 3
result[2] = 2
for i in 3...n {
if i % 2 == 0 {
result[i] = 1 + i / 2
} else {
result[i] = result[i - 1] + result[i - 2] + result[i + 1]
}
}
return result
}
``` // Fatal error: Index out of rangefunc tri(n: Int) -> [Int] {
var result: [Int] = [1]
var last = 1
var current = 3
for _ in 1...n {
let next = last + current + result[result.count - 1]
result.append(next)
last = current
current = next
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
Answer:
```swift
func tri(n: Int) -> [Int] {
var result: [Int] = [1]
var last = 1
var current = 3
for _ in 1...n {
let next = last + current + result[result.count - 1]
result.append(next)
last = current
current = next
}
return result
}
``` // XCTAssertTrue failedfunc tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[0] = 1
result[1] = 3
for i in 2..<n + 1 {
if i % 2 == 0 {
result[i] = i / 2
} else {
result[i] = result[i - 1] + result[i - 2] + result[i + 1]
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
Answer:
```swift
func tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[0] = 1
result[1] = 3
for i in 2..<n + 1 {
if i % 2 == 0 {
result[i] = i / 2
} else {
result[i] = result[i - 1] + result[i - 2] + result[i + 1]
}
}
return result
}
``` // Fatal error: Index out of rangefunc tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[1] = 3
result[2] = 3
result[3] = 8
for i in 4...n {
result[i] = result[i - 1] + result[i - 2] + result[i - 3]
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
Answer:
```swift
func tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[1] = 3
result[2] = 3
result[3] = 8
for i in 4...n {
result[i] = result[i - 1] + result[i - 2] + result[i - 3]
}
return result
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc tri(n: Int) -> [Int] {
var result: [Int] = []
result.append(1)
result.append(3)
if n > 1 {
result.append(1)
}
if n > 2 {
result.append(3)
}
for i in 3..<n {
result.append(result[i - 1] + result[i - 2] + result[i - 3])
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
Answer:
```swift
func tri(n: Int) -> [Int] {
var result: [Int] = []
result.append(1)
result.append(3)
if n > 1 {
result.append(1)
}
if n > 2 {
result.append(3)
}
for i in 3..<n {
result.append(result[i - 1] + result[i - 2] + result[i - 3])
}
return result
}
``` // XCTAssertTrue failedfunc tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[1] = 3
result[2] = 1
result[3] = 2
for i in 4...n {
result[i] = result[i - 1] + result[i - 2] + result[i - 3]
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
Answer:
```swift
func tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[1] = 3
result[2] = 1
result[3] = 2
for i in 4...n {
result[i] = result[i - 1] + result[i - 2] + result[i - 3]
}
return result
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc digits(n: Int) -> Int {
var result = 1
var number = n
while number > 0 {
let digit = number % 10
if digit % 2 == 1 {
result *= digit
}
number /= 10
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
Answer:
```swift
func digits(n: Int) -> Int {
var result = 1
var number = n
while number > 0 {
let digit = number % 10
if digit % 2 == 1 {
result *= digit
}
number /= 10
}
return result
}
``` // XCTAssertTrue failedfunc digits(n: Int) -> Int {
var result = 1
var n = n
while n > 0 {
let digit = n % 10
if digit % 2 == 1 {
result *= digit
}
n /= 10
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
Answer:
```swift
func digits(n: Int) -> Int {
var result = 1
var n = n
while n > 0 {
let digit = n % 10
if digit % 2 == 1 {
result *= digit
}
n /= 10
}
return result
}
``` // XCTAssertTrue failedfunc digits(n: Int) -> Int {
var result = 1
var number = n
while number > 0 {
let digit = number % 10
if digit % 2 == 1 {
result *= digit
}
number /= 10
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
Answer:
```swift
func digits(n: Int) -> Int {
var result = 1
var number = n
while number > 0 {
let digit = number % 10
if digit % 2 == 1 {
result *= digit
}
number /= 10
}
return result
}
``` // XCTAssertTrue failedfunc digits(n: Int) -> Int {
var result = 1
var n = n
while n > 0 {
let digit = n % 10
if digit % 2 == 1 {
result *= digit
}
n /= 10
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
Answer:
```swift
func digits(n: Int) -> Int {
var result = 1
var n = n
while n > 0 {
let digit = n % 10
if digit % 2 == 1 {
result *= digit
}
n /= 10
}
return result
}
``` // XCTAssertTrue failedfunc digits(n: Int) -> Int {
var result = 1
var number = n
while number > 0 {
let digit = number % 10
if digit % 2!= 0 {
result *= digit
}
number /= 10
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
Answer:
```swift
func digits(n: Int) -> Int {
var result = 1
var number = n
while number > 0 {
let digit = number % 10
if digit % 2!= 0 {
result *= digit
}
number /= 10
}
return result
}
```if digit % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'if digit % 2!= 0 { // '=' must have consistent whitespace on both sidesif digit % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if digit % 2!= 0 { // expression is not assignable: binary operator returns immutable valuefunc digits(n: Int) -> Int {
var result = 1
var n = n
while n > 0 {
let digit = n % 10
if digit % 2 == 1 {
result *= digit
}
n /= 10
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
Answer:
```swift
func digits(n: Int) -> Int {
var result = 1
var n = n
while n > 0 {
let digit = n % 10
if digit % 2 == 1 {
result *= digit
}
n /= 10
}
return result
}
``` // XCTAssertTrue failedfunc digits(n: Int) -> Int {
var product = 1
var number = n
while number > 0 {
let digit = number % 10
if digit % 2 == 1 {
product *= digit
}
number /= 10
}
return product
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
Answer:
```swift
func digits(n: Int) -> Int {
var product = 1
var number = n
while number > 0 {
let digit = number % 10
if digit % 2 == 1 {
product *= digit
}
number /= 10
}
return product
}
``` // XCTAssertTrue failedfunc digits(n: Int) -> Int {
var result = 1
var n = n
while n > 0 {
let digit = n % 10
if digit % 2 == 1 {
result *= digit
}
n /= 10
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
Answer:
```swift
func digits(n: Int) -> Int {
var result = 1
var n = n
while n > 0 {
let digit = n % 10
if digit % 2 == 1 {
result *= digit
}
n /= 10
}
return result
}
``` // XCTAssertTrue failedfunc digits(n: Int) -> Int {
var result = 1
var n = n
while n > 0 {
let digit = n % 10
if digit % 2 == 1 {
result *= digit
}
n /= 10
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
Answer:
```swift
func digits(n: Int) -> Int {
var result = 1
var n = n
while n > 0 {
let digit = n % 10
if digit % 2 == 1 {
result *= digit
}
n /= 10
}
return result
}
``` // XCTAssertTrue failedfunc digits(n: Int) -> Int {
var result = 1
var n = n
while n > 0 {
let digit = n % 10
if digit % 2 == 1 {
result *= digit
}
n /= 10
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
Answer:
```swift
func digits(n: Int) -> Int {
var result = 1
var n = n
while n > 0 {
let digit = n % 10
if digit % 2 == 1 {
result *= digit
}
n /= 10
}
return result
}
``` // XCTAssertTrue failedfunc isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last!= "[" {
return false
} else {
stack.removeLast()
}
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
Answer:
```swift
func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last!= "[" {
return false
} else {
stack.removeLast()
}
}
}
return stack.isEmpty
}
```if stack.isEmpty || stack.last!= "[" { // '=' must have consistent whitespace on both sidesif stack.isEmpty || stack.last!= "[" { // expression is not assignable: '||' returns immutable valueif stack.isEmpty || stack.last!= "[" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.last!= "[" { // cannot convert value of type 'Character' to expected argument type 'Bool'func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last!= "[" {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
Answer:
```swift
func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last!= "[" {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}
```if stack.isEmpty || stack.last!= "[" { // '=' must have consistent whitespace on both sidesif stack.isEmpty || stack.last!= "[" { // expression is not assignable: '||' returns immutable valueif stack.isEmpty || stack.last!= "[" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.last!= "[" { // cannot convert value of type 'Character' to expected argument type 'Bool'func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last!= "[" {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
Answer:
```swift
func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last!= "[" {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}
```if stack.isEmpty || stack.last!= "[" { // expression is not assignable: '||' returns immutable valueif stack.isEmpty || stack.last!= "[" { // cannot convert value of type 'Character' to expected argument type 'Bool'if stack.isEmpty || stack.last!= "[" { // '=' must have consistent whitespace on both sidesif stack.isEmpty || stack.last!= "[" { // use of '=' in a boolean context, did you mean '=='?func isNested(string: String) -> Bool {
let stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last!= "[" {
return false
} else {
stack.removeLast()
}
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
Answer:
```swift
func isNested(string: String) -> Bool {
let stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last!= "[" {
return false
} else {
stack.removeLast()
}
}
}
return stack.isEmpty
}
```stack.append(char) // cannot use mutating member on immutable value: 'stack' is a 'let' constantif stack.isEmpty || stack.last!= "[" { // '=' must have consistent whitespace on both sidesif stack.isEmpty || stack.last!= "[" { // cannot convert value of type 'Character' to expected argument type 'Bool'if stack.isEmpty || stack.last!= "[" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.last!= "[" { // expression is not assignable: '||' returns immutable valuestack.removeLast() // cannot use mutating member on immutable value: 'stack' is a 'let' constantfunc isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last!= "[" {
return false
} else {
stack.removeLast()
}
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
Answer:
```swift
func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last!= "[" {
return false
} else {
stack.removeLast()
}
}
}
return stack.isEmpty
}
```if stack.isEmpty || stack.last!= "[" { // '=' must have consistent whitespace on both sidesif stack.isEmpty || stack.last!= "[" { // expression is not assignable: '||' returns immutable valueif stack.isEmpty || stack.last!= "[" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.last!= "[" { // cannot convert value of type 'Character' to expected argument type 'Bool'func isNested(string: String) -> Bool {
let stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last!= "[" {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
Answer:
```swift
func isNested(string: String) -> Bool {
let stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last!= "[" {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}
```stack.append(char) // cannot use mutating member on immutable value: 'stack' is a 'let' constantif stack.isEmpty || stack.last!= "[" { // cannot convert value of type 'Character' to expected argument type 'Bool'if stack.isEmpty || stack.last!= "[" { // '=' must have consistent whitespace on both sidesif stack.isEmpty || stack.last!= "[" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.last!= "[" { // expression is not assignable: '||' returns immutable valuestack.removeLast() // cannot use mutating member on immutable value: 'stack' is a 'let' constantfunc isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last!= "[" {
return false
} else {
stack.removeLast()
}
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
Answer:
```swift
func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last!= "[" {
return false
} else {
stack.removeLast()
}
}
}
return stack.isEmpty
}
```if stack.isEmpty || stack.last!= "[" { // expression is not assignable: '||' returns immutable valueif stack.isEmpty || stack.last!= "[" { // cannot convert value of type 'Character' to expected argument type 'Bool'if stack.isEmpty || stack.last!= "[" { // '=' must have consistent whitespace on both sidesif stack.isEmpty || stack.last!= "[" { // use of '=' in a boolean context, did you mean '=='?func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last!= "[" {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
Answer:
```swift
func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last!= "[" {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}
```if stack.isEmpty || stack.last!= "[" { // '=' must have consistent whitespace on both sidesif stack.isEmpty || stack.last!= "[" { // expression is not assignable: '||' returns immutable valueif stack.isEmpty || stack.last!= "[" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.last!= "[" { // cannot convert value of type 'Character' to expected argument type 'Bool'func isNested(string: String) -> Bool {
let stack = [Character]()
for character in string {
if character == "[" {
stack.append(character)
} else if character == "]" {
if stack.isEmpty || stack.last!= "[" {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
Answer:
```swift
func isNested(string: String) -> Bool {
let stack = [Character]()
for character in string {
if character == "[" {
stack.append(character)
} else if character == "]" {
if stack.isEmpty || stack.last!= "[" {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}
```stack.append(character) // cannot use mutating member on immutable value: 'stack' is a 'let' constantif stack.isEmpty || stack.last!= "[" { // cannot convert value of type 'Character' to expected argument type 'Bool'if stack.isEmpty || stack.last!= "[" { // '=' must have consistent whitespace on both sidesif stack.isEmpty || stack.last!= "[" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.last!= "[" { // expression is not assignable: '||' returns immutable valuestack.removeLast() // cannot use mutating member on immutable value: 'stack' is a 'let' constantfunc isNested(string: String) -> Bool {
let stack = [Character]()
for character in string {
switch character {
case "[":
stack.append(character)
case "]":
if stack.isEmpty || stack.last!= "[" {
return false
}
stack.removeLast()
default:
return false
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
Answer:
```swift
func isNested(string: String) -> Bool {
let stack = [Character]()
for character in string {
switch character {
case "[":
stack.append(character)
case "]":
if stack.isEmpty || stack.last!= "[" {
return false
}
stack.removeLast()
default:
return false
}
}
return stack.isEmpty
}
```stack.append(character) // cannot use mutating member on immutable value: 'stack' is a 'let' constantif stack.isEmpty || stack.last!= "[" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.last!= "[" { // cannot convert value of type 'Character' to expected argument type 'Bool'if stack.isEmpty || stack.last!= "[" { // '=' must have consistent whitespace on both sidesif stack.isEmpty || stack.last!= "[" { // expression is not assignable: '||' returns immutable valuestack.removeLast() // cannot use mutating member on immutable value: 'stack' is a 'let' constantfunc sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
Answer:
```swift
func sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, +)
}
``` // XCTAssertTrue failedfunc sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
Answer:
```swift
func sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, +)
}
``` // XCTAssertTrue failedfunc sumSquares(lst: [Double]) -> Int {
let rounded = lst.map { Int(ceil($0)) }
return rounded.reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
Answer:
```swift
func sumSquares(lst: [Double]) -> Int {
let rounded = lst.map { Int(ceil($0)) }
return rounded.reduce(0, +)
}
``` // XCTAssertTrue failedfunc sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
Answer:
```swift
func sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, +)
}
``` // XCTAssertTrue failedfunc sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
Answer:
```swift
func sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, +)
}
``` // XCTAssertTrue failedfunc sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
Answer:
```swift
func sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, +)
}
``` // XCTAssertTrue failedfunc sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
Answer:
```swift
func sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, +)
}
``` // XCTAssertTrue failedfunc sumSquares(lst: [Double]) -> Int {
var sum = 0
for num in lst {
let roundedNum = Int(ceil(num))
sum += roundedNum * roundedNum
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
Answer:
```swift
func sumSquares(lst: [Double]) -> Int {
var sum = 0
for num in lst {
let roundedNum = Int(ceil(num))
sum += roundedNum * roundedNum
}
return sum
}
```func sumSquares(lst: [Double]) -> Int {
let rounded = lst.map { Int(ceil($0)) }
return rounded.reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
Answer:
```swift
func sumSquares(lst: [Double]) -> Int {
let rounded = lst.map { Int(ceil($0)) }
return rounded.reduce(0, +)
}
``` // XCTAssertTrue failedfunc sumSquares(lst: [Double]) -> Int {
let rounded = lst.map { Int(ceil($0)) }
let squares = rounded.map { $0 * $0 }
return squares.reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
Answer:
```swift
func sumSquares(lst: [Double]) -> Int {
let rounded = lst.map { Int(ceil($0)) }
let squares = rounded.map { $0 * $0 }
return squares.reduce(0, +)
}
```func checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = txt.last
let isLastCharALetter = lastChar!= nil && lastChar!.isLetter
let isLastCharNotPartOfWord = txt.components(separatedBy: " ").last!= lastChar
return isLastCharALetter && isLastCharNotPartOfWord
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
Answer:
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = txt.last
let isLastCharALetter = lastChar!= nil && lastChar!.isLetter
let isLastCharNotPartOfWord = txt.components(separatedBy: " ").last!= lastChar
return isLastCharALetter && isLastCharNotPartOfWord
}
```let isLastCharALetter = lastChar!= nil && lastChar!.isLetter // '=' must have consistent whitespace on both sideslet isLastCharALetter = lastChar!= nil && lastChar!.isLetter // cannot assign value of type 'Bool' to type 'String.Element' (aka 'Character')let isLastCharALetter = lastChar!= nil && lastChar!.isLetter // 'nil' is not compatible with expected argument type 'Bool'let isLastCharALetter = lastChar!= nil && lastChar!.isLetter // cannot assign through '!': 'lastChar' is a 'let' constantlet isLastCharNotPartOfWord = txt.components(separatedBy: " ").last!= lastChar // cannot assign value of type 'String.Element?' (aka 'Optional<Character>') to type 'String'let isLastCharNotPartOfWord = txt.components(separatedBy: " ").last!= lastChar // '=' must have consistent whitespace on both sideslet isLastCharNotPartOfWord = txt.components(separatedBy: " ").last!= lastChar // cannot assign through '!': 'last' is a get-only propertyfunc checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = String(txt.reversed().prefix(1))
let isLetter = lastChar.contains(where: { $0.isLetter })
let isNotPartOfWord =!txt.contains(where: { $0.isLetter })
return isLetter && isNotPartOfWord
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
Answer:
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = String(txt.reversed().prefix(1))
let isLetter = lastChar.contains(where: { $0.isLetter })
let isNotPartOfWord =!txt.contains(where: { $0.isLetter })
return isLetter && isNotPartOfWord
}
```let isNotPartOfWord =!txt.contains(where: { $0.isLetter }) // consecutive statements on a line must be separated by ';'let isNotPartOfWord =!txt.contains(where: { $0.isLetter }) // type annotation missing in patternlet isNotPartOfWord =!txt.contains(where: { $0.isLetter }) // cannot find operator '=!' in scopefunc checkIfLastCharIsALetter(txt: String) -> Bool {
let words = txt.components(separatedBy: " ")
let lastWord = words.last
let lastChar = lastWord?.last
return lastChar!= nil && lastChar!.isLetter
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
Answer:
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
let words = txt.components(separatedBy: " ")
let lastWord = words.last
let lastChar = lastWord?.last
return lastChar!= nil && lastChar!.isLetter
}
```return lastChar!= nil && lastChar!.isLetter // '=' must have consistent whitespace on both sidesreturn lastChar!= nil && lastChar!.isLetter // use of '=' in a boolean context, did you mean '=='?return lastChar!= nil && lastChar!.isLetter // cannot assign value of type 'Bool' to type 'String.Element' (aka 'Character')return lastChar!= nil && lastChar!.isLetter // 'nil' is not compatible with expected argument type 'Bool'return lastChar!= nil && lastChar!.isLetter // cannot assign through '!': 'lastChar' is a 'let' constantfunc checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = String(txt.reversed().prefix(1))
let isLetter = lastChar.rangeOfCharacter(from:.letters)!= nil
let isNotWord =!txt.contains(" ")
return isLetter && isNotWord
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
Answer:
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = String(txt.reversed().prefix(1))
let isLetter = lastChar.rangeOfCharacter(from:.letters)!= nil
let isNotWord =!txt.contains(" ")
return isLetter && isNotWord
}
```let isLetter = lastChar.rangeOfCharacter(from:.letters)!= nil // 'nil' cannot be assigned to type 'Range<String.Index>'let isLetter = lastChar.rangeOfCharacter(from:.letters)!= nil // cannot assign through '!': function call returns immutable valuelet isLetter = lastChar.rangeOfCharacter(from:.letters)!= nil // '=' must have consistent whitespace on both sideslet isNotWord =!txt.contains(" ") // consecutive statements on a line must be separated by ';'let isNotWord =!txt.contains(" ") // type annotation missing in patternlet isNotWord =!txt.contains(" ") // cannot find operator '=!' in scopefunc checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = String(txt.reversed().prefix(1))
let isLetter = lastChar.contains(where: { $0.isLetter })
let isNotPartOfWord =!txt.contains(" ")
return isLetter &&!isNotPartOfWord
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
Answer:
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = String(txt.reversed().prefix(1))
let isLetter = lastChar.contains(where: { $0.isLetter })
let isNotPartOfWord =!txt.contains(" ")
return isLetter &&!isNotPartOfWord
}
```let isNotPartOfWord =!txt.contains(" ") // type annotation missing in patternlet isNotPartOfWord =!txt.contains(" ") // consecutive statements on a line must be separated by ';'let isNotPartOfWord =!txt.contains(" ") // cannot find operator '=!' in scopereturn isLetter &&!isNotPartOfWord // consecutive statements on a line must be separated by ';'return isLetter &&!isNotPartOfWord // cannot find operator '&&!' in scopefunc checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = String(txt.characters.reversed().first!)
let isLetter = lastChar.isLetter
let isNotPartOfWord =!txt.contains(" ")
return isLetter && isNotPartOfWord
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
Answer:
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = String(txt.characters.reversed().first!)
let isLetter = lastChar.isLetter
let isNotPartOfWord =!txt.contains(" ")
return isLetter && isNotPartOfWord
}
```let lastChar = String(txt.characters.reversed().first!) // 'characters' is unavailable: Please use String directlylet isLetter = lastChar.isLetter // value of type 'String' has no member 'isLetter'let isNotPartOfWord =!txt.contains(" ") // type annotation missing in patternlet isNotPartOfWord =!txt.contains(" ") // consecutive statements on a line must be separated by ';'let isNotPartOfWord =!txt.contains(" ") // cannot find operator '=!' in scopefunc checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = String(txt.characters.reversed().first?? "")
let isLetter = lastChar.isLetter
let isNotPartOfWord =!txt.contains(" ")
return isLetter && isNotPartOfWord
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
Answer:
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = String(txt.characters.reversed().first?? "")
let isLetter = lastChar.isLetter
let isNotPartOfWord =!txt.contains(" ")
return isLetter && isNotPartOfWord
}
```let lastChar = String(txt.characters.reversed().first?? "") // cannot use optional chaining on non-optional value of type 'ReversedCollection<String>.Element' (aka 'Character')let lastChar = String(txt.characters.reversed().first?? "") // expected ',' separatorlet lastChar = String(txt.characters.reversed().first?? "") // initializer 'init(bytes:encoding:)' requires that 'ReversedCollection<String>.Element?' (aka 'Optional<Character>') conform to 'Sequence'let lastChar = String(txt.characters.reversed().first?? "") // missing argument labels 'bytes:encoding:' in calllet lastChar = String(txt.characters.reversed().first?? "") // cannot convert value of type 'String' to expected argument type 'String.Encoding'let isNotPartOfWord =!txt.contains(" ") // type annotation missing in patternlet isNotPartOfWord =!txt.contains(" ") // consecutive statements on a line must be separated by ';'let isNotPartOfWord =!txt.contains(" ") // cannot find operator '=!' in scopefunc checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = String(txt.reversed().prefix(1))
let isLetter = lastChar.contains(where: { $0.isLetter })
let isNotPartOfWord =!txt.contains(where: { $0.isLetter })
return isLetter && isNotPartOfWord
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
Answer:
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = String(txt.reversed().prefix(1))
let isLetter = lastChar.contains(where: { $0.isLetter })
let isNotPartOfWord =!txt.contains(where: { $0.isLetter })
return isLetter && isNotPartOfWord
}
```let isNotPartOfWord =!txt.contains(where: { $0.isLetter }) // consecutive statements on a line must be separated by ';'let isNotPartOfWord =!txt.contains(where: { $0.isLetter }) // type annotation missing in patternlet isNotPartOfWord =!txt.contains(where: { $0.isLetter }) // cannot find operator '=!' in scopefunc checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = String(txt.reversed().prefix(1))
let isLetter = lastChar.contains(where: { $0.isLetter })
let isNotPartOfWord =!txt.contains(" ")
return isLetter && isNotPartOfWord
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
Answer:
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = String(txt.reversed().prefix(1))
let isLetter = lastChar.contains(where: { $0.isLetter })
let isNotPartOfWord =!txt.contains(" ")
return isLetter && isNotPartOfWord
}
```let isNotPartOfWord =!txt.contains(" ") // consecutive statements on a line must be separated by ';'let isNotPartOfWord =!txt.contains(" ") // cannot find operator '=!' in scopelet isNotPartOfWord =!txt.contains(" ") // type annotation missing in patternfunc checkIfLastCharIsALetter(txt: String) -> Bool {
let words = txt.components(separatedBy: " ")
let lastWord = words.last
let lastChar = lastWord?.last
return lastChar.flatMap { CharacterSet.alphanumerics.contains($0) } == nil
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
Answer:
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
let words = txt.components(separatedBy: " ")
let lastWord = words.last
let lastChar = lastWord?.last
return lastChar.flatMap { CharacterSet.alphanumerics.contains($0) } == nil
}
```return lastChar.flatMap { CharacterSet.alphanumerics.contains($0) } == nil // cannot convert value of type 'String.Element' (aka 'Character') to expected argument type 'Unicode.Scalar'func canArrange(arr: [Int]) -> Int {
guard arr.count > 1 else {
return -1
}
var largestIndex = 0
var largestValue = arr[0]
for (index, value) in arr.enumerated() {
if value > largestValue {
largestIndex = index
largestValue = value
}
}
return largestIndex
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
Answer:
```swift
func canArrange(arr: [Int]) -> Int {
guard arr.count > 1 else {
return -1
}
var largestIndex = 0
var largestValue = arr[0]
for (index, value) in arr.enumerated() {
if value > largestValue {
largestIndex = index
largestValue = value
}
}
return largestIndex
}
``` // XCTAssertTrue failedfunc canArrange(arr: [Int]) -> Int {
guard arr.count > 1 else {
return -1
}
var largestIndex = 0
var largestValue = arr[0]
for i in 1..<arr.count {
if arr[i] > largestValue {
largestIndex = i
largestValue = arr[i]
}
}
return largestIndex
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
Answer:
```swift
func canArrange(arr: [Int]) -> Int {
guard arr.count > 1 else {
return -1
}
var largestIndex = 0
var largestValue = arr[0]
for i in 1..<arr.count {
if arr[i] > largestValue {
largestIndex = i
largestValue = arr[i]
}
}
return largestIndex
}
``` // XCTAssertTrue failedfunc canArrange(arr: [Int]) -> Int {
guard arr.count > 1 else {
return -1
}
var largestIndex = 0
var largestValue = arr[0]
for i in 1..<arr.count {
if arr[i] > largestValue {
largestIndex = i
largestValue = arr[i]
}
}
return largestIndex
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
Answer:
```swift
func canArrange(arr: [Int]) -> Int {
guard arr.count > 1 else {
return -1
}
var largestIndex = 0
var largestValue = arr[0]
for i in 1..<arr.count {
if arr[i] > largestValue {
largestIndex = i
largestValue = arr[i]
}
}
return largestIndex
}
``` // XCTAssertTrue failedfunc canArrange(arr: [Int]) -> Int {
guard arr.count > 1 else {
return -1
}
var largestIndex = 0
var largestValue = arr[0]
for (index, value) in arr.enumerated() {
if value > largestValue {
largestIndex = index
largestValue = value
}
}
return largestIndex
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
Answer:
```swift
func canArrange(arr: [Int]) -> Int {
guard arr.count > 1 else {
return -1
}
var largestIndex = 0
var largestValue = arr[0]
for (index, value) in arr.enumerated() {
if value > largestValue {
largestIndex = index
largestValue = value
}
}
return largestIndex
}
``` // XCTAssertTrue failedfunc canArrange(arr: [Int]) -> Int {
guard arr.count > 1 else {
return -1
}
var largestIndex = 0
var largestValue = arr[0]
for (index, value) in arr.enumerated() {
if value > largestValue {
largestIndex = index
largestValue = value
}
}
return largestIndex
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
Answer:
```swift
func canArrange(arr: [Int]) -> Int {
guard arr.count > 1 else {
return -1
}
var largestIndex = 0
var largestValue = arr[0]
for (index, value) in arr.enumerated() {
if value > largestValue {
largestIndex = index
largestValue = value
}
}
return largestIndex
}
``` // XCTAssertTrue failedfunc canArrange(arr: [Int]) -> Int {
guard arr.count > 1 else {
return -1
}
var largestIndex = 0
for (index, value) in arr.enumerated() {
if value > arr[index - 1] {
largestIndex = index
}
}
return largestIndex
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
Answer:
```swift
func canArrange(arr: [Int]) -> Int {
guard arr.count > 1 else {
return -1
}
var largestIndex = 0
for (index, value) in arr.enumerated() {
if value > arr[index - 1] {
largestIndex = index
}
}
return largestIndex
}
``` // Fatal error: Index out of rangefunc canArrange(arr: [Int]) -> Int {
guard arr.count > 1 else {
return -1
}
var maxIndex = 0
var maxElement = arr[0]
for i in 1..<arr.count {
if arr[i] > maxElement {
maxIndex = i
maxElement = arr[i]
}
}
return maxIndex
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
Answer:
```swift
func canArrange(arr: [Int]) -> Int {
guard arr.count > 1 else {
return -1
}
var maxIndex = 0
var maxElement = arr[0]
for i in 1..<arr.count {
if arr[i] > maxElement {
maxIndex = i
maxElement = arr[i]
}
}
return maxIndex
}
``` // XCTAssertTrue failedfunc canArrange(arr: [Int]) -> Int {
guard arr.count > 1 else {
return -1
}
var largestIndex = 0
var largestValue = arr[0]
for i in 1..<arr.count {
if arr[i] > largestValue {
largestValue = arr[i]
largestIndex = i
}
}
return largestIndex
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
Answer:
```swift
func canArrange(arr: [Int]) -> Int {
guard arr.count > 1 else {
return -1
}
var largestIndex = 0
var largestValue = arr[0]
for i in 1..<arr.count {
if arr[i] > largestValue {
largestValue = arr[i]
largestIndex = i
}
}
return largestIndex
}
``` // XCTAssertTrue failedfunc canArrange(arr: [Int]) -> Int {
var largestIndex = -1
for (index, value) in arr.enumerated() {
if value > arr[index - 1] {
largestIndex = index
}
}
return largestIndex
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
Answer:
```swift
func canArrange(arr: [Int]) -> Int {
var largestIndex = -1
for (index, value) in arr.enumerated() {
if value > arr[index - 1] {
largestIndex = index
}
}
return largestIndex
}
``` // Fatal error: Index out of rangefunc canArrange(arr: [Int]) -> Int {
guard arr.count > 1 else {
return -1
}
var maxIndex = 0
var maxVal = arr[0]
for (index, value) in arr.enumerated() {
if value > maxVal {
maxIndex = index
maxVal = value
}
}
return maxIndex
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
Answer:
```swift
func canArrange(arr: [Int]) -> Int {
guard arr.count > 1 else {
return -1
}
var maxIndex = 0
var maxVal = arr[0]
for (index, value) in arr.enumerated() {
if value > maxVal {
maxIndex = index
maxVal = value
}
}
return maxIndex
}
``` // XCTAssertTrue failedfunc largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var negative = Int?()
var positive = Int?()
for num in lst {
if num < 0 {
negative = num
} else if num > 0 {
positive = num
}
}
return (negative, positive)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
Answer:
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var negative = Int?()
var positive = Int?()
for num in lst {
if num < 0 {
negative = num
} else if num > 0 {
positive = num
}
}
return (negative, positive)
}
```var negative = Int?() // missing argument for parameter #1 in callvar positive = Int?() // missing argument for parameter #1 in callfunc largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largest: Int?
var smallest: Int?
for num in lst {
if num < 0 {
if largest == nil || num > largest! {
largest = num
}
} else if num > 0 {
if smallest == nil || num < smallest! {
smallest = num
}
}
}
return (largest, smallest)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
Answer:
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largest: Int?
var smallest: Int?
for num in lst {
if num < 0 {
if largest == nil || num > largest! {
largest = num
}
} else if num > 0 {
if smallest == nil || num < smallest! {
smallest = num
}
}
}
return (largest, smallest)
}
```func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
guard!lst.isEmpty else {
return (nil, nil)
}
let negative = lst.filter { $0 < 0 }
let positive = lst.filter { $0 > 0 }
let largestNegative = negative.max()
let smallestPositive = positive.min()
return (largestNegative, smallestPositive)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
Answer:
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
guard!lst.isEmpty else {
return (nil, nil)
}
let negative = lst.filter { $0 < 0 }
let positive = lst.filter { $0 > 0 }
let largestNegative = negative.max()
let smallestPositive = positive.min()
return (largestNegative, smallestPositive)
}
```guard!lst.isEmpty else { // expected expression, var, let or case in 'guard' conditionfunc largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var negative = Int.min
var positive = Int.max
for num in lst {
if num < 0 {
negative = num
} else if num > 0 {
positive = num
}
}
return (negative, positive)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
Answer:
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var negative = Int.min
var positive = Int.max
for num in lst {
if num < 0 {
negative = num
} else if num > 0 {
positive = num
}
}
return (negative, positive)
}
``` // XCTAssertTrue failedfunc largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largest: Int?
var smallest: Int?
for num in lst {
if num < 0 {
if largest == nil || num > largest! {
largest = num
}
} else if num > 0 {
if smallest == nil || num < smallest! {
smallest = num
}
}
}
return (largest, smallest)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
Answer:
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largest: Int?
var smallest: Int?
for num in lst {
if num < 0 {
if largest == nil || num > largest! {
largest = num
}
} else if num > 0 {
if smallest == nil || num < smallest! {
smallest = num
}
}
}
return (largest, smallest)
}
```func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var negative = Int.min
var positive = Int.max
for num in lst {
if num < 0 {
negative = num
} else if num > 0 {
positive = num
}
}
return (negative, positive)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
Answer:
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var negative = Int.min
var positive = Int.max
for num in lst {
if num < 0 {
negative = num
} else if num > 0 {
positive = num
}
}
return (negative, positive)
}
``` // XCTAssertTrue failedfunc largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var negative = Int.min
var positive = Int.max
for num in lst {
if num < 0 {
negative = num
} else if num > 0 {
positive = num
}
}
return (negative, positive)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
Answer:
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var negative = Int.min
var positive = Int.max
for num in lst {
if num < 0 {
negative = num
} else if num > 0 {
positive = num
}
}
return (negative, positive)
}
``` // XCTAssertTrue failedfunc largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var negative = Int.min
var positive = Int.max
for num in lst {
if num < 0 {
negative = num
} else if num > 0 {
positive = num
}
}
return (negative, positive)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
Answer:
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var negative = Int.min
var positive = Int.max
for num in lst {
if num < 0 {
negative = num
} else if num > 0 {
positive = num
}
}
return (negative, positive)
}
``` // XCTAssertTrue failedfunc largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var negative = Int.min
var positive = Int.max
for num in lst {
if num < 0 {
negative = num
} else if num > 0 {
positive = num
}
}
return (negative, positive)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
Answer:
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var negative = Int.min
var positive = Int.max
for num in lst {
if num < 0 {
negative = num
} else if num > 0 {
positive = num
}
}
return (negative, positive)
}
``` // XCTAssertTrue failedfunc largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var negative = Int.min
var positive = Int.max
for num in lst {
if num < 0 {
negative = num
} else if num > 0 {
positive = num
}
}
return (negative, positive)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
Answer:
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var negative = Int.min
var positive = Int.max
for num in lst {
if num < 0 {
negative = num
} else if num > 0 {
positive = num
}
}
return (negative, positive)
}
``` // XCTAssertTrue failedenum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let a),.intValue(let b)):
return a > b?.intValue(a) : nil
case (.intValue(let a),.doubleValue(let b)):
return a > b?.doubleValue(a) : nil
case (.intValue(let a),.stringValue(let b)):
return a > Int(b)?.intValue(a) : nil
case (.doubleValue(let a),.intValue(let b)):
return a > Double(b)?.doubleValue(a) : nil
case (.doubleValue(let a),.doubleValue(let b)):
return a > b?.doubleValue(a) : nil
case (.doubleValue(let a),.stringValue(let b)):
return a > Double(b)?.doubleValue(a) : nil
case (.stringValue(let a),.intValue(let b)):
return a > String(b)?.stringValue(a) : nil
case (.stringValue(let a),.doubleValue(let b)):
return a > String(b)?.stringValue(a) : nil
case (.stringValue(let a),.stringValue(let b)):
return a > b?.stringValue(a) : nil
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be. or,
compareOne(a:.intValue(1), b:.doubleValue(2.5)) ==.doubleValue(2.5)
compareOne(a:.intValue(1), b:.stringValue("2,3")) ==.stringValue("2,3")
compareOne(a:.stringValue("5,1"), b:.stringValue("6")) ==.stringValue("6")
compareOne(a:.stringValue("1"), b:.intValue(1)) == nil
Answer:
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let a),.intValue(let b)):
return a > b?.intValue(a) : nil
case (.intValue(let a),.doubleValue(let b)):
return a > b?.doubleValue(a) : nil
case (.intValue(let a),.stringValue(let b)):
return a > Int(b)?.intValue(a) : nil
case (.doubleValue(let a),.intValue(let b)):
return a > Double(b)?.doubleValue(a) : nil
case (.doubleValue(let a),.doubleValue(let b)):
return a > b?.doubleValue(a) : nil
case (.doubleValue(let a),.stringValue(let b)):
return a > Double(b)?.doubleValue(a) : nil
case (.stringValue(let a),.intValue(let b)):
return a > String(b)?.stringValue(a) : nil
case (.stringValue(let a),.doubleValue(let b)):
return a > String(b)?.stringValue(a) : nil
case (.stringValue(let a),.stringValue(let b)):
return a > b?.stringValue(a) : nil
}
}
```return a > b?.intValue(a) : nil // expected expressionreturn a > b?.intValue(a) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return a > b?.intValue(a) : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return a > b?.intValue(a) : nil // consecutive statements on a line must be separated by ';'return a > b?.intValue(a) : nil // value of type 'Int' has no member 'intValue'return a > b?.intValue(a) : nil // cannot use optional chaining on non-optional value of type 'Int'return a > b?.doubleValue(a) : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return a > b?.doubleValue(a) : nil // value of type 'Double' has no member 'doubleValue'return a > b?.doubleValue(a) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return a > b?.doubleValue(a) : nil // expected expressionreturn a > b?.doubleValue(a) : nil // consecutive statements on a line must be separated by ';'return a > b?.doubleValue(a) : nil // cannot use optional chaining on non-optional value of type 'Double'return a > Int(b)?.intValue(a) : nil // consecutive statements on a line must be separated by ';'return a > Int(b)?.intValue(a) : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return a > Int(b)?.intValue(a) : nil // value of type 'Int' has no member 'intValue'return a > Int(b)?.intValue(a) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return a > Int(b)?.intValue(a) : nil // expected expressionreturn a > Double(b)?.doubleValue(a) : nil // expected expressionreturn a > Double(b)?.doubleValue(a) : nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return a > Double(b)?.doubleValue(a) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return a > Double(b)?.doubleValue(a) : nil // value of type 'Double' has no member 'doubleValue'return a > Double(b)?.doubleValue(a) : nil // consecutive statements on a line must be separated by ';'return a > Double(b)?.doubleValue(a) : nil // no exact matches in call to initializerreturn a > b?.doubleValue(a) : nil // consecutive statements on a line must be separated by ';'return a > b?.doubleValue(a) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return a > b?.doubleValue(a) : nil // cannot use optional chaining on non-optional value of type 'Double'return a > b?.doubleValue(a) : nil // value of type 'Double' has no member 'doubleValue'return a > b?.doubleValue(a) : nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return a > b?.doubleValue(a) : nil // expected expressionreturn a > Double(b)?.doubleValue(a) : nil // value of type 'Double' has no member 'doubleValue'return a > Double(b)?.doubleValue(a) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return a > Double(b)?.doubleValue(a) : nil // consecutive statements on a line must be separated by ';'return a > Double(b)?.doubleValue(a) : nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return a > Double(b)?.doubleValue(a) : nil // expected expressionreturn a > String(b)?.stringValue(a) : nil // expected expressionreturn a > String(b)?.stringValue(a) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return a > String(b)?.stringValue(a) : nil // value of optional type 'String?' must be unwrapped to a value of type 'String'return a > String(b)?.stringValue(a) : nil // value of type 'String' has no member 'stringValue'return a > String(b)?.stringValue(a) : nil // consecutive statements on a line must be separated by ';'return a > String(b)?.stringValue(a) : nil // cannot use optional chaining on non-optional value of type 'String'return a > String(b)?.stringValue(a) : nil // value of type 'String' has no member 'stringValue'return a > String(b)?.stringValue(a) : nil // value of optional type 'String?' must be unwrapped to a value of type 'String'return a > String(b)?.stringValue(a) : nil // consecutive statements on a line must be separated by ';'return a > String(b)?.stringValue(a) : nil // cannot use optional chaining on non-optional value of type 'String'return a > String(b)?.stringValue(a) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return a > String(b)?.stringValue(a) : nil // expected expressionreturn a > b?.stringValue(a) : nil // expected expressionreturn a > b?.stringValue(a) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return a > b?.stringValue(a) : nil // consecutive statements on a line must be separated by ';'return a > b?.stringValue(a) : nil // cannot use optional chaining on non-optional value of type 'String'return a > b?.stringValue(a) : nil // value of optional type 'String?' must be unwrapped to a value of type 'String'return a > b?.stringValue(a) : nil // value of type 'String' has no member 'stringValue'enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt),.intValue(let bInt)):
return aInt > bInt?.intValue(aInt) : nil
case (.intValue(let aInt),.doubleValue(let bDouble)):
return aInt > bDouble.rounded()?.intValue(aInt) : nil
case (.intValue(let aInt),.stringValue(let bString)):
return aInt > Int(bString.replacingOccurrences(of: ",", with: ""))?.intValue(aInt) : nil
case (.doubleValue(let aDouble),.intValue(let bInt)):
return aDouble.rounded() > bInt?.intValue(bInt) : nil
case (.doubleValue(let aDouble),.doubleValue(let bDouble)):
return aDouble > bDouble?.doubleValue(aDouble) : nil
case (.doubleValue(let aDouble),.stringValue(let bString)):
return aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil
case (.stringValue(let aString),.intValue(let bInt)):
return Int(aString.replacingOccurrences(of: ",", with: "")) > bInt?.intValue(bInt) : nil
case (.stringValue(let aString),.doubleValue(let bDouble)):
return Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil
case (.stringValue(let aString),.stringValue(let bString)):
return aString.replacingOccurrences(of: ",", with: "") > bString.replacingOccurrences(of: ",", with: "")?.intValue(bInt) : nil
default:
return nil
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be. or,
compareOne(a:.intValue(1), b:.doubleValue(2.5)) ==.doubleValue(2.5)
compareOne(a:.intValue(1), b:.stringValue("2,3")) ==.stringValue("2,3")
compareOne(a:.stringValue("5,1"), b:.stringValue("6")) ==.stringValue("6")
compareOne(a:.stringValue("1"), b:.intValue(1)) == nil
Answer:
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt),.intValue(let bInt)):
return aInt > bInt?.intValue(aInt) : nil
case (.intValue(let aInt),.doubleValue(let bDouble)):
return aInt > bDouble.rounded()?.intValue(aInt) : nil
case (.intValue(let aInt),.stringValue(let bString)):
return aInt > Int(bString.replacingOccurrences(of: ",", with: ""))?.intValue(aInt) : nil
case (.doubleValue(let aDouble),.intValue(let bInt)):
return aDouble.rounded() > bInt?.intValue(bInt) : nil
case (.doubleValue(let aDouble),.doubleValue(let bDouble)):
return aDouble > bDouble?.doubleValue(aDouble) : nil
case (.doubleValue(let aDouble),.stringValue(let bString)):
return aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil
case (.stringValue(let aString),.intValue(let bInt)):
return Int(aString.replacingOccurrences(of: ",", with: "")) > bInt?.intValue(bInt) : nil
case (.stringValue(let aString),.doubleValue(let bDouble)):
return Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil
case (.stringValue(let aString),.stringValue(let bString)):
return aString.replacingOccurrences(of: ",", with: "") > bString.replacingOccurrences(of: ",", with: "")?.intValue(bInt) : nil
default:
return nil
}
}
```return aInt > bInt?.intValue(aInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aInt > bInt?.intValue(aInt) : nil // consecutive statements on a line must be separated by ';'return aInt > bInt?.intValue(aInt) : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return aInt > bInt?.intValue(aInt) : nil // value of type 'Int' has no member 'intValue'return aInt > bInt?.intValue(aInt) : nil // expected expressionreturn aInt > bInt?.intValue(aInt) : nil // cannot use optional chaining on non-optional value of type 'Int'return aInt > bDouble.rounded()?.intValue(aInt) : nil // consecutive statements on a line must be separated by ';'return aInt > bDouble.rounded()?.intValue(aInt) : nil // expected expressionreturn aInt > bDouble.rounded()?.intValue(aInt) : nil // value of type 'Double' has no member 'intValue'return aInt > bDouble.rounded()?.intValue(aInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aInt > bDouble.rounded()?.intValue(aInt) : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return aInt > bDouble.rounded()?.intValue(aInt) : nil // cannot use optional chaining on non-optional value of type 'Double'return aInt > Int(bString.replacingOccurrences(of: ",", with: ""))?.intValue(aInt) : nil // value of type 'Int' has no member 'intValue'return aInt > Int(bString.replacingOccurrences(of: ",", with: ""))?.intValue(aInt) : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return aInt > Int(bString.replacingOccurrences(of: ",", with: ""))?.intValue(aInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aInt > Int(bString.replacingOccurrences(of: ",", with: ""))?.intValue(aInt) : nil // consecutive statements on a line must be separated by ';'return aInt > Int(bString.replacingOccurrences(of: ",", with: ""))?.intValue(aInt) : nil // expected expressionreturn aDouble.rounded() > bInt?.intValue(bInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aDouble.rounded() > bInt?.intValue(bInt) : nil // value of type 'Int' has no member 'intValue'return aDouble.rounded() > bInt?.intValue(bInt) : nil // expected expressionreturn aDouble.rounded() > bInt?.intValue(bInt) : nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return aDouble.rounded() > bInt?.intValue(bInt) : nil // consecutive statements on a line must be separated by ';'return aDouble.rounded() > bInt?.intValue(bInt) : nil // cannot use optional chaining on non-optional value of type 'Int'return aDouble > bDouble?.doubleValue(aDouble) : nil // value of type 'Double' has no member 'doubleValue'return aDouble > bDouble?.doubleValue(aDouble) : nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return aDouble > bDouble?.doubleValue(aDouble) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aDouble > bDouble?.doubleValue(aDouble) : nil // consecutive statements on a line must be separated by ';'return aDouble > bDouble?.doubleValue(aDouble) : nil // expected expressionreturn aDouble > bDouble?.doubleValue(aDouble) : nil // cannot use optional chaining on non-optional value of type 'Double'return aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil // consecutive statements on a line must be separated by ';'return aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil // cannot find 'bInt' in scopereturn aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil // value of type 'Double' has no member 'intValue'return aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil // expected expressionreturn Int(aString.replacingOccurrences(of: ",", with: "")) > bInt?.intValue(bInt) : nil // value of optional type 'Optional<_>' must be unwrapped to a value of type '_'return Int(aString.replacingOccurrences(of: ",", with: "")) > bInt?.intValue(bInt) : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return Int(aString.replacingOccurrences(of: ",", with: "")) > bInt?.intValue(bInt) : nil // value of type 'Int' has no member 'intValue'return Int(aString.replacingOccurrences(of: ",", with: "")) > bInt?.intValue(bInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return Int(aString.replacingOccurrences(of: ",", with: "")) > bInt?.intValue(bInt) : nil // expected expressionreturn Int(aString.replacingOccurrences(of: ",", with: "")) > bInt?.intValue(bInt) : nil // cannot use optional chaining on non-optional value of type 'Int'return Int(aString.replacingOccurrences(of: ",", with: "")) > bInt?.intValue(bInt) : nil // consecutive statements on a line must be separated by ';'return Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil // cannot use optional chaining on non-optional value of type 'Double'return Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil // expected expressionreturn Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil // cannot find 'bInt' in scopereturn Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil // value of type 'Double' has no member 'intValue'return Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil // no exact matches in call to initializerreturn Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil // consecutive statements on a line must be separated by ';'return Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aString.replacingOccurrences(of: ",", with: "") > bString.replacingOccurrences(of: ",", with: "")?.intValue(bInt) : nil // expected expressionreturn aString.replacingOccurrences(of: ",", with: "") > bString.replacingOccurrences(of: ",", with: "")?.intValue(bInt) : nil // value of type 'String' has no member 'intValue'return aString.replacingOccurrences(of: ",", with: "") > bString.replacingOccurrences(of: ",", with: "")?.intValue(bInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aString.replacingOccurrences(of: ",", with: "") > bString.replacingOccurrences(of: ",", with: "")?.intValue(bInt) : nil // value of optional type 'String?' must be unwrapped to a value of type 'String'return aString.replacingOccurrences(of: ",", with: "") > bString.replacingOccurrences(of: ",", with: "")?.intValue(bInt) : nil // cannot find 'bInt' in scopereturn aString.replacingOccurrences(of: ",", with: "") > bString.replacingOccurrences(of: ",", with: "")?.intValue(bInt) : nil // consecutive statements on a line must be separated by ';'return aString.replacingOccurrences(of: ",", with: "") > bString.replacingOccurrences(of: ",", with: "")?.intValue(bInt) : nil // cannot use optional chaining on non-optional value of type 'String'enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt),.intValue(let bInt)):
return aInt > bInt?.intValue(aInt) : nil
case (.intValue(let aInt),.doubleValue(let bDouble)):
return aInt > bDouble?.intValue(aInt) : nil
case (.intValue(let aInt),.stringValue(let bString)):
return aInt > Int(bString)?.intValue(aInt) : nil
case (.doubleValue(let aDouble),.intValue(let bInt)):
return aDouble > Double(bInt)?.doubleValue(aDouble) : nil
case (.doubleValue(let aDouble),.doubleValue(let bDouble)):
return aDouble > bDouble?.doubleValue(aDouble) : nil
case (.doubleValue(let aDouble),.stringValue(let bString)):
return aDouble > Double(bString)?.doubleValue(aDouble) : nil
case (.stringValue(let aString),.intValue(let bInt)):
return aString > String(bInt)?.stringValue(aString) : nil
case (.stringValue(let aString),.doubleValue(let bDouble)):
return aString > String(bDouble)?.stringValue(aString) : nil
case (.stringValue(let aString),.stringValue(let bString)):
return aString > bString?.stringValue(aString) : nil
default:
return nil
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be. or,
compareOne(a:.intValue(1), b:.doubleValue(2.5)) ==.doubleValue(2.5)
compareOne(a:.intValue(1), b:.stringValue("2,3")) ==.stringValue("2,3")
compareOne(a:.stringValue("5,1"), b:.stringValue("6")) ==.stringValue("6")
compareOne(a:.stringValue("1"), b:.intValue(1)) == nil
Answer:
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt),.intValue(let bInt)):
return aInt > bInt?.intValue(aInt) : nil
case (.intValue(let aInt),.doubleValue(let bDouble)):
return aInt > bDouble?.intValue(aInt) : nil
case (.intValue(let aInt),.stringValue(let bString)):
return aInt > Int(bString)?.intValue(aInt) : nil
case (.doubleValue(let aDouble),.intValue(let bInt)):
return aDouble > Double(bInt)?.doubleValue(aDouble) : nil
case (.doubleValue(let aDouble),.doubleValue(let bDouble)):
return aDouble > bDouble?.doubleValue(aDouble) : nil
case (.doubleValue(let aDouble),.stringValue(let bString)):
return aDouble > Double(bString)?.doubleValue(aDouble) : nil
case (.stringValue(let aString),.intValue(let bInt)):
return aString > String(bInt)?.stringValue(aString) : nil
case (.stringValue(let aString),.doubleValue(let bDouble)):
return aString > String(bDouble)?.stringValue(aString) : nil
case (.stringValue(let aString),.stringValue(let bString)):
return aString > bString?.stringValue(aString) : nil
default:
return nil
}
}
```return aInt > bInt?.intValue(aInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aInt > bInt?.intValue(aInt) : nil // consecutive statements on a line must be separated by ';'return aInt > bInt?.intValue(aInt) : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return aInt > bInt?.intValue(aInt) : nil // value of type 'Int' has no member 'intValue'return aInt > bInt?.intValue(aInt) : nil // expected expressionreturn aInt > bInt?.intValue(aInt) : nil // cannot use optional chaining on non-optional value of type 'Int'return aInt > bDouble?.intValue(aInt) : nil // consecutive statements on a line must be separated by ';'return aInt > bDouble?.intValue(aInt) : nil // value of type 'Double' has no member 'intValue'return aInt > bDouble?.intValue(aInt) : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return aInt > bDouble?.intValue(aInt) : nil // cannot use optional chaining on non-optional value of type 'Double'return aInt > bDouble?.intValue(aInt) : nil // expected expressionreturn aInt > bDouble?.intValue(aInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aInt > Int(bString)?.intValue(aInt) : nil // consecutive statements on a line must be separated by ';'return aInt > Int(bString)?.intValue(aInt) : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return aInt > Int(bString)?.intValue(aInt) : nil // value of type 'Int' has no member 'intValue'return aInt > Int(bString)?.intValue(aInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aInt > Int(bString)?.intValue(aInt) : nil // expected expressionreturn aDouble > Double(bInt)?.doubleValue(aDouble) : nil // no exact matches in call to initializerreturn aDouble > Double(bInt)?.doubleValue(aDouble) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aDouble > Double(bInt)?.doubleValue(aDouble) : nil // value of type 'Double' has no member 'doubleValue'return aDouble > Double(bInt)?.doubleValue(aDouble) : nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return aDouble > Double(bInt)?.doubleValue(aDouble) : nil // consecutive statements on a line must be separated by ';'return aDouble > Double(bInt)?.doubleValue(aDouble) : nil // expected expressionreturn aDouble > bDouble?.doubleValue(aDouble) : nil // value of type 'Double' has no member 'doubleValue'return aDouble > bDouble?.doubleValue(aDouble) : nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return aDouble > bDouble?.doubleValue(aDouble) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aDouble > bDouble?.doubleValue(aDouble) : nil // consecutive statements on a line must be separated by ';'return aDouble > bDouble?.doubleValue(aDouble) : nil // expected expressionreturn aDouble > bDouble?.doubleValue(aDouble) : nil // cannot use optional chaining on non-optional value of type 'Double'return aDouble > Double(bString)?.doubleValue(aDouble) : nil // expected expressionreturn aDouble > Double(bString)?.doubleValue(aDouble) : nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return aDouble > Double(bString)?.doubleValue(aDouble) : nil // value of type 'Double' has no member 'doubleValue'return aDouble > Double(bString)?.doubleValue(aDouble) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aDouble > Double(bString)?.doubleValue(aDouble) : nil // consecutive statements on a line must be separated by ';'return aString > String(bInt)?.stringValue(aString) : nil // expected expressionreturn aString > String(bInt)?.stringValue(aString) : nil // consecutive statements on a line must be separated by ';'return aString > String(bInt)?.stringValue(aString) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aString > String(bInt)?.stringValue(aString) : nil // value of type 'String' has no member 'stringValue'return aString > String(bInt)?.stringValue(aString) : nil // value of optional type 'String?' must be unwrapped to a value of type 'String'return aString > String(bInt)?.stringValue(aString) : nil // cannot use optional chaining on non-optional value of type 'String'return aString > String(bDouble)?.stringValue(aString) : nil // value of optional type 'String?' must be unwrapped to a value of type 'String'return aString > String(bDouble)?.stringValue(aString) : nil // value of type 'String' has no member 'stringValue'return aString > String(bDouble)?.stringValue(aString) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aString > String(bDouble)?.stringValue(aString) : nil // consecutive statements on a line must be separated by ';'return aString > String(bDouble)?.stringValue(aString) : nil // expected expressionreturn aString > String(bDouble)?.stringValue(aString) : nil // cannot use optional chaining on non-optional value of type 'String'return aString > bString?.stringValue(aString) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aString > bString?.stringValue(aString) : nil // value of type 'String' has no member 'stringValue'return aString > bString?.stringValue(aString) : nil // value of optional type 'String?' must be unwrapped to a value of type 'String'return aString > bString?.stringValue(aString) : nil // cannot use optional chaining on non-optional value of type 'String'return aString > bString?.stringValue(aString) : nil // consecutive statements on a line must be separated by ';'return aString > bString?.stringValue(aString) : nil // expected expressionenum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aValue),.intValue(let bValue)):
return aValue > bValue?.intValue(aValue) : nil
case (.intValue(let aValue),.doubleValue(let bValue)):
return aValue > bValue?.doubleValue(aValue) : nil
case (.intValue(let aValue),.stringValue(let bValue)):
return aValue > Int(bValue)?.intValue(aValue) : nil
case (.doubleValue(let aValue),.intValue(let bValue)):
return aValue > Double(bValue)?.doubleValue(aValue) : nil
case (.doubleValue(let aValue),.doubleValue(let bValue)):
return aValue > bValue?.doubleValue(aValue) : nil
case (.doubleValue(let aValue),.stringValue(let bValue)):
return aValue > Double(bValue)?.doubleValue(aValue) : nil
case (.stringValue(let aValue),.intValue(let bValue)):
return aValue > String(bValue)?.stringValue(aValue) : nil
case (.stringValue(let aValue),.doubleValue(let bValue)):
return aValue > String(bValue)?.stringValue(aValue) : nil
case (.stringValue(let aValue),.stringValue(let bValue)):
return aValue > bValue?.stringValue(aValue) : nil
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be. or,
compareOne(a:.intValue(1), b:.doubleValue(2.5)) ==.doubleValue(2.5)
compareOne(a:.intValue(1), b:.stringValue("2,3")) ==.stringValue("2,3")
compareOne(a:.stringValue("5,1"), b:.stringValue("6")) ==.stringValue("6")
compareOne(a:.stringValue("1"), b:.intValue(1)) == nil
Answer:
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aValue),.intValue(let bValue)):
return aValue > bValue?.intValue(aValue) : nil
case (.intValue(let aValue),.doubleValue(let bValue)):
return aValue > bValue?.doubleValue(aValue) : nil
case (.intValue(let aValue),.stringValue(let bValue)):
return aValue > Int(bValue)?.intValue(aValue) : nil
case (.doubleValue(let aValue),.intValue(let bValue)):
return aValue > Double(bValue)?.doubleValue(aValue) : nil
case (.doubleValue(let aValue),.doubleValue(let bValue)):
return aValue > bValue?.doubleValue(aValue) : nil
case (.doubleValue(let aValue),.stringValue(let bValue)):
return aValue > Double(bValue)?.doubleValue(aValue) : nil
case (.stringValue(let aValue),.intValue(let bValue)):
return aValue > String(bValue)?.stringValue(aValue) : nil
case (.stringValue(let aValue),.doubleValue(let bValue)):
return aValue > String(bValue)?.stringValue(aValue) : nil
case (.stringValue(let aValue),.stringValue(let bValue)):
return aValue > bValue?.stringValue(aValue) : nil
}
}
```return aValue > bValue?.intValue(aValue) : nil // expected expressionreturn aValue > bValue?.intValue(aValue) : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return aValue > bValue?.intValue(aValue) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aValue > bValue?.intValue(aValue) : nil // value of type 'Int' has no member 'intValue'return aValue > bValue?.intValue(aValue) : nil // cannot use optional chaining on non-optional value of type 'Int'return aValue > bValue?.intValue(aValue) : nil // consecutive statements on a line must be separated by ';'return aValue > bValue?.doubleValue(aValue) : nil // consecutive statements on a line must be separated by ';'return aValue > bValue?.doubleValue(aValue) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aValue > bValue?.doubleValue(aValue) : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return aValue > bValue?.doubleValue(aValue) : nil // value of type 'Double' has no member 'doubleValue'return aValue > bValue?.doubleValue(aValue) : nil // cannot use optional chaining on non-optional value of type 'Double'return aValue > bValue?.doubleValue(aValue) : nil // expected expressionreturn aValue > Int(bValue)?.intValue(aValue) : nil // consecutive statements on a line must be separated by ';'return aValue > Int(bValue)?.intValue(aValue) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aValue > Int(bValue)?.intValue(aValue) : nil // value of type 'Int' has no member 'intValue'return aValue > Int(bValue)?.intValue(aValue) : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return aValue > Int(bValue)?.intValue(aValue) : nil // expected expressionreturn aValue > Double(bValue)?.doubleValue(aValue) : nil // no exact matches in call to initializerreturn aValue > Double(bValue)?.doubleValue(aValue) : nil // value of type 'Double' has no member 'doubleValue'return aValue > Double(bValue)?.doubleValue(aValue) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aValue > Double(bValue)?.doubleValue(aValue) : nil // expected expressionreturn aValue > Double(bValue)?.doubleValue(aValue) : nil // consecutive statements on a line must be separated by ';'return aValue > Double(bValue)?.doubleValue(aValue) : nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return aValue > bValue?.doubleValue(aValue) : nil // value of type 'Double' has no member 'doubleValue'return aValue > bValue?.doubleValue(aValue) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aValue > bValue?.doubleValue(aValue) : nil // consecutive statements on a line must be separated by ';'return aValue > bValue?.doubleValue(aValue) : nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return aValue > bValue?.doubleValue(aValue) : nil // cannot use optional chaining on non-optional value of type 'Double'return aValue > bValue?.doubleValue(aValue) : nil // expected expressionreturn aValue > Double(bValue)?.doubleValue(aValue) : nil // value of type 'Double' has no member 'doubleValue'return aValue > Double(bValue)?.doubleValue(aValue) : nil // consecutive statements on a line must be separated by ';'return aValue > Double(bValue)?.doubleValue(aValue) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aValue > Double(bValue)?.doubleValue(aValue) : nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return aValue > Double(bValue)?.doubleValue(aValue) : nil // expected expressionreturn aValue > String(bValue)?.stringValue(aValue) : nil // value of type 'String' has no member 'stringValue'return aValue > String(bValue)?.stringValue(aValue) : nil // value of optional type 'String?' must be unwrapped to a value of type 'String'return aValue > String(bValue)?.stringValue(aValue) : nil // consecutive statements on a line must be separated by ';'return aValue > String(bValue)?.stringValue(aValue) : nil // cannot use optional chaining on non-optional value of type 'String'return aValue > String(bValue)?.stringValue(aValue) : nil // expected expressionreturn aValue > String(bValue)?.stringValue(aValue) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aValue > String(bValue)?.stringValue(aValue) : nil // expected expressionreturn aValue > String(bValue)?.stringValue(aValue) : nil // value of optional type 'String?' must be unwrapped to a value of type 'String'return aValue > String(bValue)?.stringValue(aValue) : nil // cannot use optional chaining on non-optional value of type 'String'return aValue > String(bValue)?.stringValue(aValue) : nil // consecutive statements on a line must be separated by ';'return aValue > String(bValue)?.stringValue(aValue) : nil // value of type 'String' has no member 'stringValue'return aValue > String(bValue)?.stringValue(aValue) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aValue > bValue?.stringValue(aValue) : nil // cannot use optional chaining on non-optional value of type 'String'return aValue > bValue?.stringValue(aValue) : nil // value of type 'String' has no member 'stringValue'return aValue > bValue?.stringValue(aValue) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aValue > bValue?.stringValue(aValue) : nil // value of optional type 'String?' must be unwrapped to a value of type 'String'return aValue > bValue?.stringValue(aValue) : nil // consecutive statements on a line must be separated by ';'return aValue > bValue?.stringValue(aValue) : nil // expected expressionenum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt),.intValue(let bInt)):
return aInt > bInt?.intValue(aInt) :.intValue(bInt)
case (.intValue(let aInt),.doubleValue(let bDouble)):
return aInt > bDouble?.intValue(aInt) :.intValue(Int(bDouble))
case (.intValue(let aInt),.stringValue(let bString)):
return aInt > Int(bString)?.intValue(aInt) :.intValue(Int(bString)!)
case (.doubleValue(let aDouble),.intValue(let bInt)):
return aDouble > Double(bInt)?.doubleValue(aDouble) :.intValue(bInt)
case (.doubleValue(let aDouble),.doubleValue(let bDouble)):
return aDouble > bDouble?.doubleValue(aDouble) :.doubleValue(bDouble)
case (.doubleValue(let aDouble),.stringValue(let bString)):
return aDouble > Double(bString)?.doubleValue(aDouble) :.intValue(Int(bString)!)
case (.stringValue(let aString),.intValue(let bInt)):
return aString > String(bInt)?.stringValue(aString) :.intValue(bInt)
case (.stringValue(let aString),.doubleValue(let bDouble)):
return aString > String(Int(bDouble))?.stringValue(aString) :.intValue(Int(bDouble)!)
case (.stringValue(let aString),.stringValue(let bString)):
return aString > bString?.stringValue(aString) :.stringValue(bString)
default:
return nil
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be. or,
compareOne(a:.intValue(1), b:.doubleValue(2.5)) ==.doubleValue(2.5)
compareOne(a:.intValue(1), b:.stringValue("2,3")) ==.stringValue("2,3")
compareOne(a:.stringValue("5,1"), b:.stringValue("6")) ==.stringValue("6")
compareOne(a:.stringValue("1"), b:.intValue(1)) == nil
Answer:
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt),.intValue(let bInt)):
return aInt > bInt?.intValue(aInt) :.intValue(bInt)
case (.intValue(let aInt),.doubleValue(let bDouble)):
return aInt > bDouble?.intValue(aInt) :.intValue(Int(bDouble))
case (.intValue(let aInt),.stringValue(let bString)):
return aInt > Int(bString)?.intValue(aInt) :.intValue(Int(bString)!)
case (.doubleValue(let aDouble),.intValue(let bInt)):
return aDouble > Double(bInt)?.doubleValue(aDouble) :.intValue(bInt)
case (.doubleValue(let aDouble),.doubleValue(let bDouble)):
return aDouble > bDouble?.doubleValue(aDouble) :.doubleValue(bDouble)
case (.doubleValue(let aDouble),.stringValue(let bString)):
return aDouble > Double(bString)?.doubleValue(aDouble) :.intValue(Int(bString)!)
case (.stringValue(let aString),.intValue(let bInt)):
return aString > String(bInt)?.stringValue(aString) :.intValue(bInt)
case (.stringValue(let aString),.doubleValue(let bDouble)):
return aString > String(Int(bDouble))?.stringValue(aString) :.intValue(Int(bDouble)!)
case (.stringValue(let aString),.stringValue(let bString)):
return aString > bString?.stringValue(aString) :.stringValue(bString)
default:
return nil
}
}
```return aInt > bInt?.intValue(aInt) :.intValue(bInt) // expected expressionreturn aInt > bInt?.intValue(aInt) :.intValue(bInt) // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return aInt > bInt?.intValue(aInt) :.intValue(bInt) // value of type 'Int' has no member 'intValue'return aInt > bInt?.intValue(aInt) :.intValue(bInt) // consecutive statements on a line must be separated by ';'return aInt > bInt?.intValue(aInt) :.intValue(bInt) // cannot convert return expression of type 'Bool' to return type 'Value?'return aInt > bInt?.intValue(aInt) :.intValue(bInt) // cannot use optional chaining on non-optional value of type 'Int'return aInt > bDouble?.intValue(aInt) :.intValue(Int(bDouble)) // cannot convert return expression of type 'Bool' to return type 'Value?'return aInt > bDouble?.intValue(aInt) :.intValue(Int(bDouble)) // expected expressionreturn aInt > bDouble?.intValue(aInt) :.intValue(Int(bDouble)) // cannot use optional chaining on non-optional value of type 'Double'return aInt > bDouble?.intValue(aInt) :.intValue(Int(bDouble)) // value of type 'Double' has no member 'intValue'return aInt > bDouble?.intValue(aInt) :.intValue(Int(bDouble)) // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return aInt > bDouble?.intValue(aInt) :.intValue(Int(bDouble)) // consecutive statements on a line must be separated by ';'return aInt > Int(bString)?.intValue(aInt) :.intValue(Int(bString)!) // value of type 'Int' has no member 'intValue'return aInt > Int(bString)?.intValue(aInt) :.intValue(Int(bString)!) // expected expressionreturn aInt > Int(bString)?.intValue(aInt) :.intValue(Int(bString)!) // cannot convert return expression of type 'Bool' to return type 'Value?'return aInt > Int(bString)?.intValue(aInt) :.intValue(Int(bString)!) // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return aInt > Int(bString)?.intValue(aInt) :.intValue(Int(bString)!) // consecutive statements on a line must be separated by ';'return aDouble > Double(bInt)?.doubleValue(aDouble) :.intValue(bInt) // value of type 'Double' has no member 'doubleValue'return aDouble > Double(bInt)?.doubleValue(aDouble) :.intValue(bInt) // cannot convert return expression of type 'Bool' to return type 'Value?'return aDouble > Double(bInt)?.doubleValue(aDouble) :.intValue(bInt) // consecutive statements on a line must be separated by ';'return aDouble > Double(bInt)?.doubleValue(aDouble) :.intValue(bInt) // no exact matches in call to initializerreturn aDouble > Double(bInt)?.doubleValue(aDouble) :.intValue(bInt) // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return aDouble > Double(bInt)?.doubleValue(aDouble) :.intValue(bInt) // expected expressionreturn aDouble > bDouble?.doubleValue(aDouble) :.doubleValue(bDouble) // cannot use optional chaining on non-optional value of type 'Double'return aDouble > bDouble?.doubleValue(aDouble) :.doubleValue(bDouble) // cannot convert return expression of type 'Bool' to return type 'Value?'return aDouble > bDouble?.doubleValue(aDouble) :.doubleValue(bDouble) // value of type 'Double' has no member 'doubleValue'return aDouble > bDouble?.doubleValue(aDouble) :.doubleValue(bDouble) // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return aDouble > bDouble?.doubleValue(aDouble) :.doubleValue(bDouble) // expected expressionreturn aDouble > bDouble?.doubleValue(aDouble) :.doubleValue(bDouble) // consecutive statements on a line must be separated by ';'return aDouble > Double(bString)?.doubleValue(aDouble) :.intValue(Int(bString)!) // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return aDouble > Double(bString)?.doubleValue(aDouble) :.intValue(Int(bString)!) // value of type 'Double' has no member 'doubleValue'return aDouble > Double(bString)?.doubleValue(aDouble) :.intValue(Int(bString)!) // cannot convert return expression of type 'Bool' to return type 'Value?'return aDouble > Double(bString)?.doubleValue(aDouble) :.intValue(Int(bString)!) // expected expressionreturn aDouble > Double(bString)?.doubleValue(aDouble) :.intValue(Int(bString)!) // consecutive statements on a line must be separated by ';'return aString > String(bInt)?.stringValue(aString) :.intValue(bInt) // cannot convert return expression of type 'Bool' to return type 'Value?'return aString > String(bInt)?.stringValue(aString) :.intValue(bInt) // value of type 'String' has no member 'stringValue'return aString > String(bInt)?.stringValue(aString) :.intValue(bInt) // value of optional type 'String?' must be unwrapped to a value of type 'String'return aString > String(bInt)?.stringValue(aString) :.intValue(bInt) // consecutive statements on a line must be separated by ';'return aString > String(bInt)?.stringValue(aString) :.intValue(bInt) // cannot use optional chaining on non-optional value of type 'String'return aString > String(bInt)?.stringValue(aString) :.intValue(bInt) // expected expressionreturn aString > String(Int(bDouble))?.stringValue(aString) :.intValue(Int(bDouble)!) // cannot use optional chaining on non-optional value of type 'String'return aString > String(Int(bDouble))?.stringValue(aString) :.intValue(Int(bDouble)!) // cannot convert return expression of type 'Bool' to return type 'Value?'return aString > String(Int(bDouble))?.stringValue(aString) :.intValue(Int(bDouble)!) // value of optional type 'String?' must be unwrapped to a value of type 'String'return aString > String(Int(bDouble))?.stringValue(aString) :.intValue(Int(bDouble)!) // value of type 'String' has no member 'stringValue'return aString > String(Int(bDouble))?.stringValue(aString) :.intValue(Int(bDouble)!) // consecutive statements on a line must be separated by ';'return aString > String(Int(bDouble))?.stringValue(aString) :.intValue(Int(bDouble)!) // expected expressionreturn aString > bString?.stringValue(aString) :.stringValue(bString) // cannot convert return expression of type 'Bool' to return type 'Value?'return aString > bString?.stringValue(aString) :.stringValue(bString) // value of optional type 'String?' must be unwrapped to a value of type 'String'return aString > bString?.stringValue(aString) :.stringValue(bString) // value of type 'String' has no member 'stringValue'return aString > bString?.stringValue(aString) :.stringValue(bString) // consecutive statements on a line must be separated by ';'return aString > bString?.stringValue(aString) :.stringValue(bString) // cannot use optional chaining on non-optional value of type 'String'return aString > bString?.stringValue(aString) :.stringValue(bString) // expected expressionenum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt),.intValue(let bInt)):
return aInt > bInt?.intValue(aInt) : nil
case (.intValue(let aInt),.doubleValue(let bDouble)):
return aInt > bDouble.rounded()?.intValue(aInt) : nil
case (.intValue(let aInt),.stringValue(let bString)):
return aInt > Int(bString.replacingOccurrences(of: ",", with: ""))?.intValue(aInt) : nil
case (.doubleValue(let aDouble),.intValue(let bInt)):
return aDouble.rounded() > bInt?.intValue(bInt) : nil
case (.doubleValue(let aDouble),.doubleValue(let bDouble)):
return aDouble > bDouble?.doubleValue(aDouble) : nil
case (.doubleValue(let aDouble),.stringValue(let bString)):
return aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil
case (.stringValue(let aString),.intValue(let bInt)):
return Int(aString.replacingOccurrences(of: ",", with: "")) > bInt?.intValue(bInt) : nil
case (.stringValue(let aString),.doubleValue(let bDouble)):
return Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil
case (.stringValue(let aString),.stringValue(let bString)):
return aString > bString?.intValue(bInt) : nil
default:
return nil
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be. or,
compareOne(a:.intValue(1), b:.doubleValue(2.5)) ==.doubleValue(2.5)
compareOne(a:.intValue(1), b:.stringValue("2,3")) ==.stringValue("2,3")
compareOne(a:.stringValue("5,1"), b:.stringValue("6")) ==.stringValue("6")
compareOne(a:.stringValue("1"), b:.intValue(1)) == nil
Answer:
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt),.intValue(let bInt)):
return aInt > bInt?.intValue(aInt) : nil
case (.intValue(let aInt),.doubleValue(let bDouble)):
return aInt > bDouble.rounded()?.intValue(aInt) : nil
case (.intValue(let aInt),.stringValue(let bString)):
return aInt > Int(bString.replacingOccurrences(of: ",", with: ""))?.intValue(aInt) : nil
case (.doubleValue(let aDouble),.intValue(let bInt)):
return aDouble.rounded() > bInt?.intValue(bInt) : nil
case (.doubleValue(let aDouble),.doubleValue(let bDouble)):
return aDouble > bDouble?.doubleValue(aDouble) : nil
case (.doubleValue(let aDouble),.stringValue(let bString)):
return aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil
case (.stringValue(let aString),.intValue(let bInt)):
return Int(aString.replacingOccurrences(of: ",", with: "")) > bInt?.intValue(bInt) : nil
case (.stringValue(let aString),.doubleValue(let bDouble)):
return Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil
case (.stringValue(let aString),.stringValue(let bString)):
return aString > bString?.intValue(bInt) : nil
default:
return nil
}
}
```return aInt > bInt?.intValue(aInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aInt > bInt?.intValue(aInt) : nil // consecutive statements on a line must be separated by ';'return aInt > bInt?.intValue(aInt) : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return aInt > bInt?.intValue(aInt) : nil // value of type 'Int' has no member 'intValue'return aInt > bInt?.intValue(aInt) : nil // expected expressionreturn aInt > bInt?.intValue(aInt) : nil // cannot use optional chaining on non-optional value of type 'Int'return aInt > bDouble.rounded()?.intValue(aInt) : nil // consecutive statements on a line must be separated by ';'return aInt > bDouble.rounded()?.intValue(aInt) : nil // expected expressionreturn aInt > bDouble.rounded()?.intValue(aInt) : nil // value of type 'Double' has no member 'intValue'return aInt > bDouble.rounded()?.intValue(aInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aInt > bDouble.rounded()?.intValue(aInt) : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return aInt > bDouble.rounded()?.intValue(aInt) : nil // cannot use optional chaining on non-optional value of type 'Double'return aInt > Int(bString.replacingOccurrences(of: ",", with: ""))?.intValue(aInt) : nil // value of type 'Int' has no member 'intValue'return aInt > Int(bString.replacingOccurrences(of: ",", with: ""))?.intValue(aInt) : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return aInt > Int(bString.replacingOccurrences(of: ",", with: ""))?.intValue(aInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aInt > Int(bString.replacingOccurrences(of: ",", with: ""))?.intValue(aInt) : nil // consecutive statements on a line must be separated by ';'return aInt > Int(bString.replacingOccurrences(of: ",", with: ""))?.intValue(aInt) : nil // expected expressionreturn aDouble.rounded() > bInt?.intValue(bInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aDouble.rounded() > bInt?.intValue(bInt) : nil // value of type 'Int' has no member 'intValue'return aDouble.rounded() > bInt?.intValue(bInt) : nil // expected expressionreturn aDouble.rounded() > bInt?.intValue(bInt) : nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return aDouble.rounded() > bInt?.intValue(bInt) : nil // consecutive statements on a line must be separated by ';'return aDouble.rounded() > bInt?.intValue(bInt) : nil // cannot use optional chaining on non-optional value of type 'Int'return aDouble > bDouble?.doubleValue(aDouble) : nil // value of type 'Double' has no member 'doubleValue'return aDouble > bDouble?.doubleValue(aDouble) : nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return aDouble > bDouble?.doubleValue(aDouble) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aDouble > bDouble?.doubleValue(aDouble) : nil // consecutive statements on a line must be separated by ';'return aDouble > bDouble?.doubleValue(aDouble) : nil // expected expressionreturn aDouble > bDouble?.doubleValue(aDouble) : nil // cannot use optional chaining on non-optional value of type 'Double'return aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil // consecutive statements on a line must be separated by ';'return aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil // cannot find 'bInt' in scopereturn aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil // value of type 'Double' has no member 'intValue'return aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil // expected expressionreturn Int(aString.replacingOccurrences(of: ",", with: "")) > bInt?.intValue(bInt) : nil // value of optional type 'Optional<_>' must be unwrapped to a value of type '_'return Int(aString.replacingOccurrences(of: ",", with: "")) > bInt?.intValue(bInt) : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return Int(aString.replacingOccurrences(of: ",", with: "")) > bInt?.intValue(bInt) : nil // value of type 'Int' has no member 'intValue'return Int(aString.replacingOccurrences(of: ",", with: "")) > bInt?.intValue(bInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return Int(aString.replacingOccurrences(of: ",", with: "")) > bInt?.intValue(bInt) : nil // expected expressionreturn Int(aString.replacingOccurrences(of: ",", with: "")) > bInt?.intValue(bInt) : nil // cannot use optional chaining on non-optional value of type 'Int'return Int(aString.replacingOccurrences(of: ",", with: "")) > bInt?.intValue(bInt) : nil // consecutive statements on a line must be separated by ';'return Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil // cannot use optional chaining on non-optional value of type 'Double'return Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil // expected expressionreturn Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil // cannot find 'bInt' in scopereturn Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil // value of type 'Double' has no member 'intValue'return Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil // no exact matches in call to initializerreturn Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil // consecutive statements on a line must be separated by ';'return Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aString > bString?.intValue(bInt) : nil // consecutive statements on a line must be separated by ';'return aString > bString?.intValue(bInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aString > bString?.intValue(bInt) : nil // expected expressionreturn aString > bString?.intValue(bInt) : nil // cannot use optional chaining on non-optional value of type 'String'return aString > bString?.intValue(bInt) : nil // value of optional type 'String?' must be unwrapped to a value of type 'String'return aString > bString?.intValue(bInt) : nil // value of type 'String' has no member 'intValue'return aString > bString?.intValue(bInt) : nil // cannot find 'bInt' in scopeenum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt),.intValue(let bInt)):
return aInt > bInt?.intValue(aInt) : nil
case (.intValue(let aInt),.doubleValue(let bDouble)):
return aInt > bDouble.rounded()?.intValue(aInt) : nil
case (.intValue(let aInt),.stringValue(let bString)):
return aInt > Int(bString.replacingOccurrences(of: ",", with: ""))?.intValue(aInt) : nil
case (.doubleValue(let aDouble),.intValue(let bInt)):
return aDouble.rounded() > bInt?.intValue(bInt) : nil
case (.doubleValue(let aDouble),.doubleValue(let bDouble)):
return aDouble > bDouble?.doubleValue(aDouble) : nil
case (.doubleValue(let aDouble),.stringValue(let bString)):
return aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil
case (.stringValue(let aString),.intValue(let bInt)):
return Int(aString.replacingOccurrences(of: ",", with: ""))! > bInt?.intValue(bInt) : nil
case (.stringValue(let aString),.doubleValue(let bDouble)):
return Double(aString.replacingOccurrences(of: ",", with: ""))! > bDouble.rounded()?.intValue(bInt) : nil
case (.stringValue(let aString),.stringValue(let bString)):
return aString > bString?.intValue(bInt) : nil
default:
return nil
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be. or,
compareOne(a:.intValue(1), b:.doubleValue(2.5)) ==.doubleValue(2.5)
compareOne(a:.intValue(1), b:.stringValue("2,3")) ==.stringValue("2,3")
compareOne(a:.stringValue("5,1"), b:.stringValue("6")) ==.stringValue("6")
compareOne(a:.stringValue("1"), b:.intValue(1)) == nil
Answer:
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt),.intValue(let bInt)):
return aInt > bInt?.intValue(aInt) : nil
case (.intValue(let aInt),.doubleValue(let bDouble)):
return aInt > bDouble.rounded()?.intValue(aInt) : nil
case (.intValue(let aInt),.stringValue(let bString)):
return aInt > Int(bString.replacingOccurrences(of: ",", with: ""))?.intValue(aInt) : nil
case (.doubleValue(let aDouble),.intValue(let bInt)):
return aDouble.rounded() > bInt?.intValue(bInt) : nil
case (.doubleValue(let aDouble),.doubleValue(let bDouble)):
return aDouble > bDouble?.doubleValue(aDouble) : nil
case (.doubleValue(let aDouble),.stringValue(let bString)):
return aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil
case (.stringValue(let aString),.intValue(let bInt)):
return Int(aString.replacingOccurrences(of: ",", with: ""))! > bInt?.intValue(bInt) : nil
case (.stringValue(let aString),.doubleValue(let bDouble)):
return Double(aString.replacingOccurrences(of: ",", with: ""))! > bDouble.rounded()?.intValue(bInt) : nil
case (.stringValue(let aString),.stringValue(let bString)):
return aString > bString?.intValue(bInt) : nil
default:
return nil
}
}
```return aInt > bInt?.intValue(aInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aInt > bInt?.intValue(aInt) : nil // consecutive statements on a line must be separated by ';'return aInt > bInt?.intValue(aInt) : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return aInt > bInt?.intValue(aInt) : nil // value of type 'Int' has no member 'intValue'return aInt > bInt?.intValue(aInt) : nil // expected expressionreturn aInt > bInt?.intValue(aInt) : nil // cannot use optional chaining on non-optional value of type 'Int'return aInt > bDouble.rounded()?.intValue(aInt) : nil // consecutive statements on a line must be separated by ';'return aInt > bDouble.rounded()?.intValue(aInt) : nil // expected expressionreturn aInt > bDouble.rounded()?.intValue(aInt) : nil // value of type 'Double' has no member 'intValue'return aInt > bDouble.rounded()?.intValue(aInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aInt > bDouble.rounded()?.intValue(aInt) : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return aInt > bDouble.rounded()?.intValue(aInt) : nil // cannot use optional chaining on non-optional value of type 'Double'return aInt > Int(bString.replacingOccurrences(of: ",", with: ""))?.intValue(aInt) : nil // value of type 'Int' has no member 'intValue'return aInt > Int(bString.replacingOccurrences(of: ",", with: ""))?.intValue(aInt) : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return aInt > Int(bString.replacingOccurrences(of: ",", with: ""))?.intValue(aInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aInt > Int(bString.replacingOccurrences(of: ",", with: ""))?.intValue(aInt) : nil // consecutive statements on a line must be separated by ';'return aInt > Int(bString.replacingOccurrences(of: ",", with: ""))?.intValue(aInt) : nil // expected expressionreturn aDouble.rounded() > bInt?.intValue(bInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aDouble.rounded() > bInt?.intValue(bInt) : nil // value of type 'Int' has no member 'intValue'return aDouble.rounded() > bInt?.intValue(bInt) : nil // expected expressionreturn aDouble.rounded() > bInt?.intValue(bInt) : nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return aDouble.rounded() > bInt?.intValue(bInt) : nil // consecutive statements on a line must be separated by ';'return aDouble.rounded() > bInt?.intValue(bInt) : nil // cannot use optional chaining on non-optional value of type 'Int'return aDouble > bDouble?.doubleValue(aDouble) : nil // value of type 'Double' has no member 'doubleValue'return aDouble > bDouble?.doubleValue(aDouble) : nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return aDouble > bDouble?.doubleValue(aDouble) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aDouble > bDouble?.doubleValue(aDouble) : nil // consecutive statements on a line must be separated by ';'return aDouble > bDouble?.doubleValue(aDouble) : nil // expected expressionreturn aDouble > bDouble?.doubleValue(aDouble) : nil // cannot use optional chaining on non-optional value of type 'Double'return aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil // consecutive statements on a line must be separated by ';'return aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil // cannot find 'bInt' in scopereturn aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil // value of type 'Double' has no member 'intValue'return aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil // expected expressionreturn Int(aString.replacingOccurrences(of: ",", with: ""))! > bInt?.intValue(bInt) : nil // cannot use optional chaining on non-optional value of type 'Int'return Int(aString.replacingOccurrences(of: ",", with: ""))! > bInt?.intValue(bInt) : nil // value of type 'Int' has no member 'intValue'return Int(aString.replacingOccurrences(of: ",", with: ""))! > bInt?.intValue(bInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return Int(aString.replacingOccurrences(of: ",", with: ""))! > bInt?.intValue(bInt) : nil // consecutive statements on a line must be separated by ';'return Int(aString.replacingOccurrences(of: ",", with: ""))! > bInt?.intValue(bInt) : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return Int(aString.replacingOccurrences(of: ",", with: ""))! > bInt?.intValue(bInt) : nil // expected expressionreturn Double(aString.replacingOccurrences(of: ",", with: ""))! > bDouble.rounded()?.intValue(bInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(aString.replacingOccurrences(of: ",", with: ""))! > bDouble.rounded()?.intValue(bInt) : nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(aString.replacingOccurrences(of: ",", with: ""))! > bDouble.rounded()?.intValue(bInt) : nil // value of type 'Double' has no member 'intValue'return Double(aString.replacingOccurrences(of: ",", with: ""))! > bDouble.rounded()?.intValue(bInt) : nil // consecutive statements on a line must be separated by ';'return Double(aString.replacingOccurrences(of: ",", with: ""))! > bDouble.rounded()?.intValue(bInt) : nil // expected expressionreturn Double(aString.replacingOccurrences(of: ",", with: ""))! > bDouble.rounded()?.intValue(bInt) : nil // cannot find 'bInt' in scopereturn Double(aString.replacingOccurrences(of: ",", with: ""))! > bDouble.rounded()?.intValue(bInt) : nil // cannot use optional chaining on non-optional value of type 'Double'return aString > bString?.intValue(bInt) : nil // consecutive statements on a line must be separated by ';'return aString > bString?.intValue(bInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aString > bString?.intValue(bInt) : nil // expected expressionreturn aString > bString?.intValue(bInt) : nil // cannot use optional chaining on non-optional value of type 'String'return aString > bString?.intValue(bInt) : nil // value of optional type 'String?' must be unwrapped to a value of type 'String'return aString > bString?.intValue(bInt) : nil // value of type 'String' has no member 'intValue'return aString > bString?.intValue(bInt) : nil // cannot find 'bInt' in scopeenum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt),.intValue(let bInt)):
return aInt > bInt?.intValue(aInt) : nil
case (.intValue(let aInt),.doubleValue(let bDouble)):
return aInt > bDouble.rounded()?.intValue(aInt) : nil
case (.intValue(let aInt),.stringValue(let bString)):
return aInt > Int(bString.replacingOccurrences(of: ",", with: ""))?.intValue(aInt) : nil
case (.doubleValue(let aDouble),.intValue(let bInt)):
return aDouble.rounded() > bInt?.intValue(bInt) : nil
case (.doubleValue(let aDouble),.doubleValue(let bDouble)):
return aDouble > bDouble?.doubleValue(aDouble) : nil
case (.doubleValue(let aDouble),.stringValue(let bString)):
return aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil
case (.stringValue(let aString),.intValue(let bInt)):
return Int(aString.replacingOccurrences(of: ",", with: "")) > bInt?.intValue(bInt) : nil
case (.stringValue(let aString),.doubleValue(let bDouble)):
return Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil
case (.stringValue(let aString),.stringValue(let bString)):
return aString.replacingOccurrences(of: ",", with: "") > bString.replacingOccurrences(of: ",", with: "")?.intValue(bInt) : nil
default:
return nil
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be. or,
compareOne(a:.intValue(1), b:.doubleValue(2.5)) ==.doubleValue(2.5)
compareOne(a:.intValue(1), b:.stringValue("2,3")) ==.stringValue("2,3")
compareOne(a:.stringValue("5,1"), b:.stringValue("6")) ==.stringValue("6")
compareOne(a:.stringValue("1"), b:.intValue(1)) == nil
Answer:
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt),.intValue(let bInt)):
return aInt > bInt?.intValue(aInt) : nil
case (.intValue(let aInt),.doubleValue(let bDouble)):
return aInt > bDouble.rounded()?.intValue(aInt) : nil
case (.intValue(let aInt),.stringValue(let bString)):
return aInt > Int(bString.replacingOccurrences(of: ",", with: ""))?.intValue(aInt) : nil
case (.doubleValue(let aDouble),.intValue(let bInt)):
return aDouble.rounded() > bInt?.intValue(bInt) : nil
case (.doubleValue(let aDouble),.doubleValue(let bDouble)):
return aDouble > bDouble?.doubleValue(aDouble) : nil
case (.doubleValue(let aDouble),.stringValue(let bString)):
return aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil
case (.stringValue(let aString),.intValue(let bInt)):
return Int(aString.replacingOccurrences(of: ",", with: "")) > bInt?.intValue(bInt) : nil
case (.stringValue(let aString),.doubleValue(let bDouble)):
return Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil
case (.stringValue(let aString),.stringValue(let bString)):
return aString.replacingOccurrences(of: ",", with: "") > bString.replacingOccurrences(of: ",", with: "")?.intValue(bInt) : nil
default:
return nil
}
}
```return aInt > bInt?.intValue(aInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aInt > bInt?.intValue(aInt) : nil // consecutive statements on a line must be separated by ';'return aInt > bInt?.intValue(aInt) : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return aInt > bInt?.intValue(aInt) : nil // value of type 'Int' has no member 'intValue'return aInt > bInt?.intValue(aInt) : nil // expected expressionreturn aInt > bInt?.intValue(aInt) : nil // cannot use optional chaining on non-optional value of type 'Int'return aInt > bDouble.rounded()?.intValue(aInt) : nil // consecutive statements on a line must be separated by ';'return aInt > bDouble.rounded()?.intValue(aInt) : nil // expected expressionreturn aInt > bDouble.rounded()?.intValue(aInt) : nil // value of type 'Double' has no member 'intValue'return aInt > bDouble.rounded()?.intValue(aInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aInt > bDouble.rounded()?.intValue(aInt) : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return aInt > bDouble.rounded()?.intValue(aInt) : nil // cannot use optional chaining on non-optional value of type 'Double'return aInt > Int(bString.replacingOccurrences(of: ",", with: ""))?.intValue(aInt) : nil // value of type 'Int' has no member 'intValue'return aInt > Int(bString.replacingOccurrences(of: ",", with: ""))?.intValue(aInt) : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return aInt > Int(bString.replacingOccurrences(of: ",", with: ""))?.intValue(aInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aInt > Int(bString.replacingOccurrences(of: ",", with: ""))?.intValue(aInt) : nil // consecutive statements on a line must be separated by ';'return aInt > Int(bString.replacingOccurrences(of: ",", with: ""))?.intValue(aInt) : nil // expected expressionreturn aDouble.rounded() > bInt?.intValue(bInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aDouble.rounded() > bInt?.intValue(bInt) : nil // value of type 'Int' has no member 'intValue'return aDouble.rounded() > bInt?.intValue(bInt) : nil // expected expressionreturn aDouble.rounded() > bInt?.intValue(bInt) : nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return aDouble.rounded() > bInt?.intValue(bInt) : nil // consecutive statements on a line must be separated by ';'return aDouble.rounded() > bInt?.intValue(bInt) : nil // cannot use optional chaining on non-optional value of type 'Int'return aDouble > bDouble?.doubleValue(aDouble) : nil // value of type 'Double' has no member 'doubleValue'return aDouble > bDouble?.doubleValue(aDouble) : nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return aDouble > bDouble?.doubleValue(aDouble) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aDouble > bDouble?.doubleValue(aDouble) : nil // consecutive statements on a line must be separated by ';'return aDouble > bDouble?.doubleValue(aDouble) : nil // expected expressionreturn aDouble > bDouble?.doubleValue(aDouble) : nil // cannot use optional chaining on non-optional value of type 'Double'return aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil // consecutive statements on a line must be separated by ';'return aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil // cannot find 'bInt' in scopereturn aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil // value of type 'Double' has no member 'intValue'return aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return aDouble > Double(bString.replacingOccurrences(of: ",", with: ""))?.intValue(bInt) : nil // expected expressionreturn Int(aString.replacingOccurrences(of: ",", with: "")) > bInt?.intValue(bInt) : nil // value of optional type 'Optional<_>' must be unwrapped to a value of type '_'return Int(aString.replacingOccurrences(of: ",", with: "")) > bInt?.intValue(bInt) : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return Int(aString.replacingOccurrences(of: ",", with: "")) > bInt?.intValue(bInt) : nil // value of type 'Int' has no member 'intValue'return Int(aString.replacingOccurrences(of: ",", with: "")) > bInt?.intValue(bInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return Int(aString.replacingOccurrences(of: ",", with: "")) > bInt?.intValue(bInt) : nil // expected expressionreturn Int(aString.replacingOccurrences(of: ",", with: "")) > bInt?.intValue(bInt) : nil // cannot use optional chaining on non-optional value of type 'Int'return Int(aString.replacingOccurrences(of: ",", with: "")) > bInt?.intValue(bInt) : nil // consecutive statements on a line must be separated by ';'return Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil // cannot use optional chaining on non-optional value of type 'Double'return Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil // expected expressionreturn Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil // cannot find 'bInt' in scopereturn Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil // value of type 'Double' has no member 'intValue'return Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil // no exact matches in call to initializerreturn Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil // consecutive statements on a line must be separated by ';'return Double(aString.replacingOccurrences(of: ",", with: "")) > bDouble.rounded()?.intValue(bInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aString.replacingOccurrences(of: ",", with: "") > bString.replacingOccurrences(of: ",", with: "")?.intValue(bInt) : nil // expected expressionreturn aString.replacingOccurrences(of: ",", with: "") > bString.replacingOccurrences(of: ",", with: "")?.intValue(bInt) : nil // value of type 'String' has no member 'intValue'return aString.replacingOccurrences(of: ",", with: "") > bString.replacingOccurrences(of: ",", with: "")?.intValue(bInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aString.replacingOccurrences(of: ",", with: "") > bString.replacingOccurrences(of: ",", with: "")?.intValue(bInt) : nil // value of optional type 'String?' must be unwrapped to a value of type 'String'return aString.replacingOccurrences(of: ",", with: "") > bString.replacingOccurrences(of: ",", with: "")?.intValue(bInt) : nil // cannot find 'bInt' in scopereturn aString.replacingOccurrences(of: ",", with: "") > bString.replacingOccurrences(of: ",", with: "")?.intValue(bInt) : nil // consecutive statements on a line must be separated by ';'return aString.replacingOccurrences(of: ",", with: "") > bString.replacingOccurrences(of: ",", with: "")?.intValue(bInt) : nil // cannot use optional chaining on non-optional value of type 'String'enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt),.intValue(let bInt)):
return aInt > bInt?.intValue(aInt) : nil
case (.doubleValue(let aDouble),.doubleValue(let bDouble)):
return aDouble > bDouble?.doubleValue(aDouble) : nil
case (.stringValue(let aString),.stringValue(let bString)):
let aDouble = Double(aString.replacingOccurrences(of: ",", with: "."))
let bDouble = Double(bString.replacingOccurrences(of: ",", with: "."))
return aDouble > bDouble?.doubleValue(aDouble) : nil
default:
return nil
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be. or,
compareOne(a:.intValue(1), b:.doubleValue(2.5)) ==.doubleValue(2.5)
compareOne(a:.intValue(1), b:.stringValue("2,3")) ==.stringValue("2,3")
compareOne(a:.stringValue("5,1"), b:.stringValue("6")) ==.stringValue("6")
compareOne(a:.stringValue("1"), b:.intValue(1)) == nil
Answer:
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt),.intValue(let bInt)):
return aInt > bInt?.intValue(aInt) : nil
case (.doubleValue(let aDouble),.doubleValue(let bDouble)):
return aDouble > bDouble?.doubleValue(aDouble) : nil
case (.stringValue(let aString),.stringValue(let bString)):
let aDouble = Double(aString.replacingOccurrences(of: ",", with: "."))
let bDouble = Double(bString.replacingOccurrences(of: ",", with: "."))
return aDouble > bDouble?.doubleValue(aDouble) : nil
default:
return nil
}
}
```return aInt > bInt?.intValue(aInt) : nil // consecutive statements on a line must be separated by ';'return aInt > bInt?.intValue(aInt) : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return aInt > bInt?.intValue(aInt) : nil // expected expressionreturn aInt > bInt?.intValue(aInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aInt > bInt?.intValue(aInt) : nil // value of type 'Int' has no member 'intValue'return aInt > bInt?.intValue(aInt) : nil // cannot use optional chaining on non-optional value of type 'Int'return aDouble > bDouble?.doubleValue(aDouble) : nil // expected expressionreturn aDouble > bDouble?.doubleValue(aDouble) : nil // consecutive statements on a line must be separated by ';'return aDouble > bDouble?.doubleValue(aDouble) : nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return aDouble > bDouble?.doubleValue(aDouble) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aDouble > bDouble?.doubleValue(aDouble) : nil // value of type 'Double' has no member 'doubleValue'return aDouble > bDouble?.doubleValue(aDouble) : nil // cannot use optional chaining on non-optional value of type 'Double'return aDouble > bDouble?.doubleValue(aDouble) : nil // binary operator '>' cannot be applied to operands of type 'Double?' and 'Optional<_>'return aDouble > bDouble?.doubleValue(aDouble) : nil // value of type 'Double' has no member 'doubleValue'return aDouble > bDouble?.doubleValue(aDouble) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aDouble > bDouble?.doubleValue(aDouble) : nil // expected expressionreturn aDouble > bDouble?.doubleValue(aDouble) : nil // consecutive statements on a line must be separated by ';'enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt),.intValue(let bInt)):
return aInt > bInt?.intValue(aInt) : nil
case (.intValue(let aInt),.doubleValue(let bDouble)):
return aInt > bDouble.rounded()?.intValue(aInt) : nil
case (.intValue(let aInt),.stringValue(let bString)):
return aInt > Int(bString)?? nil
case (.doubleValue(let aDouble),.intValue(let bInt)):
return aDouble.rounded() > bInt?.intValue(bInt) : nil
case (.doubleValue(let aDouble),.doubleValue(let bDouble)):
return aDouble > bDouble?.doubleValue(aDouble) : nil
case (.doubleValue(let aDouble),.stringValue(let bString)):
return aDouble > Double(bString)?? nil
case (.stringValue(let aString),.intValue(let bInt)):
return Int(aString) > bInt?.intValue(bInt) : nil
case (.stringValue(let aString),.doubleValue(let bDouble)):
return Double(aString) > bDouble?.intValue(bInt) : nil
case (.stringValue(let aString),.stringValue(let bString)):
return aString > bString?.intValue(bInt) : nil
default:
return nil
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be. or,
compareOne(a:.intValue(1), b:.doubleValue(2.5)) ==.doubleValue(2.5)
compareOne(a:.intValue(1), b:.stringValue("2,3")) ==.stringValue("2,3")
compareOne(a:.stringValue("5,1"), b:.stringValue("6")) ==.stringValue("6")
compareOne(a:.stringValue("1"), b:.intValue(1)) == nil
Answer:
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt),.intValue(let bInt)):
return aInt > bInt?.intValue(aInt) : nil
case (.intValue(let aInt),.doubleValue(let bDouble)):
return aInt > bDouble.rounded()?.intValue(aInt) : nil
case (.intValue(let aInt),.stringValue(let bString)):
return aInt > Int(bString)?? nil
case (.doubleValue(let aDouble),.intValue(let bInt)):
return aDouble.rounded() > bInt?.intValue(bInt) : nil
case (.doubleValue(let aDouble),.doubleValue(let bDouble)):
return aDouble > bDouble?.doubleValue(aDouble) : nil
case (.doubleValue(let aDouble),.stringValue(let bString)):
return aDouble > Double(bString)?? nil
case (.stringValue(let aString),.intValue(let bInt)):
return Int(aString) > bInt?.intValue(bInt) : nil
case (.stringValue(let aString),.doubleValue(let bDouble)):
return Double(aString) > bDouble?.intValue(bInt) : nil
case (.stringValue(let aString),.stringValue(let bString)):
return aString > bString?.intValue(bInt) : nil
default:
return nil
}
}
```return aInt > bInt?.intValue(aInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aInt > bInt?.intValue(aInt) : nil // cannot use optional chaining on non-optional value of type 'Int'return aInt > bInt?.intValue(aInt) : nil // consecutive statements on a line must be separated by ';'return aInt > bInt?.intValue(aInt) : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return aInt > bInt?.intValue(aInt) : nil // value of type 'Int' has no member 'intValue'return aInt > bInt?.intValue(aInt) : nil // expected expressionreturn aInt > bDouble.rounded()?.intValue(aInt) : nil // consecutive statements on a line must be separated by ';'return aInt > bDouble.rounded()?.intValue(aInt) : nil // expected expressionreturn aInt > bDouble.rounded()?.intValue(aInt) : nil // value of type 'Double' has no member 'intValue'return aInt > bDouble.rounded()?.intValue(aInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aInt > bDouble.rounded()?.intValue(aInt) : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return aInt > bDouble.rounded()?.intValue(aInt) : nil // cannot use optional chaining on non-optional value of type 'Double'return aInt > Int(bString)?? nil // consecutive statements on a line must be separated by ';'return aInt > Int(bString)?? nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return aInt > Int(bString)?? nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aInt > Int(bString)?? nil // cannot use optional chaining on non-optional value of type 'Int'return aInt > Int(bString)?? nil // 'nil' requires a contextual typereturn aDouble.rounded() > bInt?.intValue(bInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aDouble.rounded() > bInt?.intValue(bInt) : nil // value of type 'Int' has no member 'intValue'return aDouble.rounded() > bInt?.intValue(bInt) : nil // expected expressionreturn aDouble.rounded() > bInt?.intValue(bInt) : nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return aDouble.rounded() > bInt?.intValue(bInt) : nil // consecutive statements on a line must be separated by ';'return aDouble.rounded() > bInt?.intValue(bInt) : nil // cannot use optional chaining on non-optional value of type 'Int'return aDouble > bDouble?.doubleValue(aDouble) : nil // value of type 'Double' has no member 'doubleValue'return aDouble > bDouble?.doubleValue(aDouble) : nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return aDouble > bDouble?.doubleValue(aDouble) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aDouble > bDouble?.doubleValue(aDouble) : nil // consecutive statements on a line must be separated by ';'return aDouble > bDouble?.doubleValue(aDouble) : nil // expected expressionreturn aDouble > bDouble?.doubleValue(aDouble) : nil // cannot use optional chaining on non-optional value of type 'Double'return aDouble > Double(bString)?? nil // cannot use optional chaining on non-optional value of type 'Double'return aDouble > Double(bString)?? nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aDouble > Double(bString)?? nil // 'nil' requires a contextual typereturn aDouble > Double(bString)?? nil // consecutive statements on a line must be separated by ';'return aDouble > Double(bString)?? nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Int(aString) > bInt?.intValue(bInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return Int(aString) > bInt?.intValue(bInt) : nil // cannot use optional chaining on non-optional value of type 'Int'return Int(aString) > bInt?.intValue(bInt) : nil // value of type 'Int' has no member 'intValue'return Int(aString) > bInt?.intValue(bInt) : nil // consecutive statements on a line must be separated by ';'return Int(aString) > bInt?.intValue(bInt) : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return Int(aString) > bInt?.intValue(bInt) : nil // expected expressionreturn Double(aString) > bDouble?.intValue(bInt) : nil // no exact matches in call to initializerreturn Double(aString) > bDouble?.intValue(bInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(aString) > bDouble?.intValue(bInt) : nil // consecutive statements on a line must be separated by ';'return Double(aString) > bDouble?.intValue(bInt) : nil // cannot use optional chaining on non-optional value of type 'Double'return Double(aString) > bDouble?.intValue(bInt) : nil // expected expressionreturn Double(aString) > bDouble?.intValue(bInt) : nil // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(aString) > bDouble?.intValue(bInt) : nil // value of type 'Double' has no member 'intValue'return Double(aString) > bDouble?.intValue(bInt) : nil // cannot find 'bInt' in scopereturn aString > bString?.intValue(bInt) : nil // consecutive statements on a line must be separated by ';'return aString > bString?.intValue(bInt) : nil // cannot convert return expression of type 'Bool' to return type 'Value?'return aString > bString?.intValue(bInt) : nil // expected expressionreturn aString > bString?.intValue(bInt) : nil // cannot use optional chaining on non-optional value of type 'String'return aString > bString?.intValue(bInt) : nil // value of optional type 'String?' must be unwrapped to a value of type 'String'return aString > bString?.intValue(bInt) : nil // value of type 'String' has no member 'intValue'return aString > bString?.intValue(bInt) : nil // cannot find 'bInt' in scopefunc isEqualToSumEven(n: Int) -> Bool {
let numbers = [2, 4, 6, 8]
var sum = 0
for number in numbers {
if n - number >= 0 {
sum += number
}
}
return sum == n
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
Answer:
```swift
func isEqualToSumEven(n: Int) -> Bool {
let numbers = [2, 4, 6, 8]
var sum = 0
for number in numbers {
if n - number >= 0 {
sum += number
}
}
return sum == n
}
``` // XCTAssertTrue failedfunc isEqualToSumEven(n: Int) -> Bool {
var sum = 0
for i in 2...n, i % 2 == 0 {
sum += i
}
return sum == n
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
Answer:
```swift
func isEqualToSumEven(n: Int) -> Bool {
var sum = 0
for i in 2...n, i % 2 == 0 {
sum += i
}
return sum == n
}
```for i in 2...n, i % 2 == 0 { // expected '{' to start the body of for-each loopfunc isEqualToSumEven(n: Int) -> Bool {
let numbers = [2, 4, 6, 8]
var sum = 0
for number in numbers {
if n - number >= 0 {
sum += number
}
}
return sum == n
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
Answer:
```swift
func isEqualToSumEven(n: Int) -> Bool {
let numbers = [2, 4, 6, 8]
var sum = 0
for number in numbers {
if n - number >= 0 {
sum += number
}
}
return sum == n
}
``` // XCTAssertTrue failedfunc isEqualToSumEven(n: Int) -> Bool {
let numbers = [2, 4, 6, 8]
var sum = 0
for number in numbers {
if n - number >= 0 {
sum += number
if sum == n {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
Answer:
```swift
func isEqualToSumEven(n: Int) -> Bool {
let numbers = [2, 4, 6, 8]
var sum = 0
for number in numbers {
if n - number >= 0 {
sum += number
if sum == n {
return true
}
}
}
return false
}
``` // XCTAssertTrue failedfunc isEqualToSumEven(n: Int) -> Bool {
let numbers = [2, 4, 6, 8]
var sum = 0
for number in numbers {
if n - number >= 0 {
sum += number
}
}
return sum == n
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
Answer:
```swift
func isEqualToSumEven(n: Int) -> Bool {
let numbers = [2, 4, 6, 8]
var sum = 0
for number in numbers {
if n - number >= 0 {
sum += number
}
}
return sum == n
}
``` // XCTAssertTrue failedfunc isEqualToSumEven(n: Int) -> Bool {
var sum = 0
var count = 0
for i in 2...n {
if i % 2 == 0 {
sum += i
count += 1
}
if count == 4 {
break
}
}
return sum == n
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
Answer:
```swift
func isEqualToSumEven(n: Int) -> Bool {
var sum = 0
var count = 0
for i in 2...n {
if i % 2 == 0 {
sum += i
count += 1
}
if count == 4 {
break
}
}
return sum == n
}
``` // XCTAssertTrue failedfunc isEqualToSumEven(n: Int) -> Bool {
let numbers = [2, 4, 6, 8]
var sum = 0
for number in numbers {
if n - number >= 0 {
sum += number
}
}
return sum == n
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
Answer:
```swift
func isEqualToSumEven(n: Int) -> Bool {
let numbers = [2, 4, 6, 8]
var sum = 0
for number in numbers {
if n - number >= 0 {
sum += number
}
}
return sum == n
}
``` // XCTAssertTrue failedfunc isEqualToSumEven(n: Int) -> Bool {
let numbers = [2, 4, 6, 8]
var sum = 0
for number in numbers {
if n - number >= 0 {
sum += number
}
}
return sum == n
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
Answer:
```swift
func isEqualToSumEven(n: Int) -> Bool {
let numbers = [2, 4, 6, 8]
var sum = 0
for number in numbers {
if n - number >= 0 {
sum += number
}
}
return sum == n
}
``` // XCTAssertTrue failedfunc isEqualToSumEven(n: Int) -> Bool {
let numbers = [2, 4, 6, 8]
var sum = 0
for number in numbers {
if n - number >= 0 {
sum += number
}
}
return sum == n
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
Answer:
```swift
func isEqualToSumEven(n: Int) -> Bool {
let numbers = [2, 4, 6, 8]
var sum = 0
for number in numbers {
if n - number >= 0 {
sum += number
}
}
return sum == n
}
``` // XCTAssertTrue failedfunc isEqualToSumEven(n: Int) -> Bool {
let numbers = [2, 4, 6, 8]
var sum = 0
for number in numbers {
if n - number >= 0 {
sum += number
}
}
return sum == n
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
Answer:
```swift
func isEqualToSumEven(n: Int) -> Bool {
let numbers = [2, 4, 6, 8]
var sum = 0
for number in numbers {
if n - number >= 0 {
sum += number
}
}
return sum == n
}
``` // XCTAssertTrue failedfunc specialFactorial(n: Int) -> Int {
if n <= 1 {
return 1
}
var result = 1
for i in 1...n {
result *= i
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! *... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
Answer:
```swift
func specialFactorial(n: Int) -> Int {
if n <= 1 {
return 1
}
var result = 1
for i in 1...n {
result *= i
}
return result
}
``` // XCTAssertTrue failedfunc specialFactorial(n: Int) -> Int {
var result = 1
for i in 1...n {
result *= i
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! *... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
Answer:
```swift
func specialFactorial(n: Int) -> Int {
var result = 1
for i in 1...n {
result *= i
}
return result
}
``` // XCTAssertTrue failedfunc specialFactorial(n: Int) -> Int {
var result = 1
for i in 1...n {
result *= i
}
return result
}
func brazilianFactorial(n: Int) -> Int {
var result = 1
for i in 1...n {
result *= i
}
return result * specialFactorial(n: n - 1)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! *... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
Answer:
```swift
func specialFactorial(n: Int) -> Int {
var result = 1
for i in 1...n {
result *= i
}
return result
}
func brazilianFactorial(n: Int) -> Int {
var result = 1
for i in 1...n {
result *= i
}
return result * specialFactorial(n: n - 1)
}
``` // XCTAssertTrue failedfunc specialFactorial(n: Int) -> Int {
var result = 1
for i in 1...n {
result *= i
}
return result
}
func brazilianFactorial(n: Int) -> Int {
var result = 1
for i in 1...n {
result *= i
}
return result * specialFactorial(n: n - 1)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! *... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
Answer:
```swift
func specialFactorial(n: Int) -> Int {
var result = 1
for i in 1...n {
result *= i
}
return result
}
func brazilianFactorial(n: Int) -> Int {
var result = 1
for i in 1...n {
result *= i
}
return result * specialFactorial(n: n - 1)
}
``` // XCTAssertTrue failedfunc specialFactorial(n: Int) -> Int {
var result = 1
for i in 1...n {
result *= i
}
return result
}
func brazilianFactorial(n: Int) -> Int {
var result = 1
for i in 1...n {
result *= i
}
return result * specialFactorial(n: n - 1)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! *... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
Answer:
```swift
func specialFactorial(n: Int) -> Int {
var result = 1
for i in 1...n {
result *= i
}
return result
}
func brazilianFactorial(n: Int) -> Int {
var result = 1
for i in 1...n {
result *= i
}
return result * specialFactorial(n: n - 1)
}
``` // XCTAssertTrue failedfunc specialFactorial(n: Int) -> Int {
var result = 1
for i in 1...n {
result *= i
}
return result
}
func brazilianFactorial(n: Int) -> Int {
var result = 1
for i in 1...n {
result *= i
}
return result * specialFactorial(n: n - 1)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! *... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
Answer:
```swift
func specialFactorial(n: Int) -> Int {
var result = 1
for i in 1...n {
result *= i
}
return result
}
func brazilianFactorial(n: Int) -> Int {
var result = 1
for i in 1...n {
result *= i
}
return result * specialFactorial(n: n - 1)
}
``` // XCTAssertTrue failedfunc specialFactorial(n: Int) -> Int {
var result = 1
for i in 1...n {
result *= i
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! *... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
Answer:
```swift
func specialFactorial(n: Int) -> Int {
var result = 1
for i in 1...n {
result *= i
}
return result
}
``` // XCTAssertTrue failedfunc specialFactorial(n: Int) -> Int {
var result = 1
for i in 1...n {
result *= i
}
return result
}
func brazilianFactorial(n: Int) -> Int {
var result = 1
for i in 1...n {
result *= i
}
return result * specialFactorial(n: n-1)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! *... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
Answer:
```swift
func specialFactorial(n: Int) -> Int {
var result = 1
for i in 1...n {
result *= i
}
return result
}
func brazilianFactorial(n: Int) -> Int {
var result = 1
for i in 1...n {
result *= i
}
return result * specialFactorial(n: n-1)
}
``` // XCTAssertTrue failedfunc specialFactorial(n: Int) -> Int {
var result = 1
for i in 1...n {
result *= i
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! *... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
Answer:
```swift
func specialFactorial(n: Int) -> Int {
var result = 1
for i in 1...n {
result *= i
}
return result
}
``` // XCTAssertTrue failedfunc specialFactorial(n: Int) -> Int {
if n == 0 {
return 1
}
return n * specialFactorial(n: n - 1)
}
func brazilianFactorial(n: Int) -> Int {
if n == 0 {
return 1
}
return n * brazilianFactorial(n: n - 1)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! *... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
Answer:
```swift
func specialFactorial(n: Int) -> Int {
if n == 0 {
return 1
}
return n * specialFactorial(n: n - 1)
}
func brazilianFactorial(n: Int) -> Int {
if n == 0 {
return 1
}
return n * brazilianFactorial(n: n - 1)
}
``` // XCTAssertTrue failedfunc fixSpaces(text: String) -> String {
let components = text.components(separatedBy: " ")
var result = ""
for (index, component) in components.enumerated() {
if index == 0 {
result += component
} else {
result += "_" + component
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
Answer:
```swift
func fixSpaces(text: String) -> String {
let components = text.components(separatedBy: " ")
var result = ""
for (index, component) in components.enumerated() {
if index == 0 {
result += component
} else {
result += "_" + component
}
}
return result
}
``` // XCTAssertTrue failedfunc fixSpaces(text: String) -> String {
let regex = try! NSRegularExpression(pattern: "\\s{2,}")
let string = regex.stringByReplacingMatches(in: text, options: [], range: NSRange(text.startIndex..., in: text), withTemplate: "_")
let string = regex.stringByReplacingMatches(in: string, options: [], range: NSRange(string.startIndex..., in: string), withTemplate: "-")
return string
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
Answer:
```swift
func fixSpaces(text: String) -> String {
let regex = try! NSRegularExpression(pattern: "\\s{2,}")
let string = regex.stringByReplacingMatches(in: text, options: [], range: NSRange(text.startIndex..., in: text), withTemplate: "_")
let string = regex.stringByReplacingMatches(in: string, options: [], range: NSRange(string.startIndex..., in: string), withTemplate: "-")
return string
}
```let string = regex.stringByReplacingMatches(in: string, options: [], range: NSRange(string.startIndex..., in: string), withTemplate: "-") // invalid redeclaration of 'string'func fixSpaces(text: String) -> String {
let regex = try! NSRegularExpression(pattern: "\\s{2,}", options: [])
let result = regex.stringByReplacingMatches(in: text, options: [], range: NSRange(text.startIndex..., in: text), withTemplate: "_")
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
Answer:
```swift
func fixSpaces(text: String) -> String {
let regex = try! NSRegularExpression(pattern: "\\s{2,}", options: [])
let result = regex.stringByReplacingMatches(in: text, options: [], range: NSRange(text.startIndex..., in: text), withTemplate: "_")
return result
}
``` // XCTAssertTrue failedfunc fixSpaces(text: String) -> String {
let regex = try! NSRegularExpression(pattern: "\\s{2,}")
let string = regex.stringByReplacingMatches(in: text, options: [], range: NSRange(text.startIndex..., in: text), withTemplate: "_")
let regex2 = try! NSRegularExpression(pattern: "\\s")
let string2 = regex2.stringByReplacingMatches(in: string, options: [], range: NSRange(string.startIndex..., in: string), withTemplate: "-")
return string2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
Answer:
```swift
func fixSpaces(text: String) -> String {
let regex = try! NSRegularExpression(pattern: "\\s{2,}")
let string = regex.stringByReplacingMatches(in: text, options: [], range: NSRange(text.startIndex..., in: text), withTemplate: "_")
let regex2 = try! NSRegularExpression(pattern: "\\s")
let string2 = regex2.stringByReplacingMatches(in: string, options: [], range: NSRange(string.startIndex..., in: string), withTemplate: "-")
return string2
}
``` // XCTAssertTrue failedfunc fixSpaces(text: String) -> String {
let components = text.components(separatedBy: " ")
var result = ""
for (index, component) in components.enumerated() {
if component.isEmpty {
result += "_"
} else {
result += component.replacingOccurrences(of: " ", with: "_")
}
if index < components.count - 1 {
result += "_"
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
Answer:
```swift
func fixSpaces(text: String) -> String {
let components = text.components(separatedBy: " ")
var result = ""
for (index, component) in components.enumerated() {
if component.isEmpty {
result += "_"
} else {
result += component.replacingOccurrences(of: " ", with: "_")
}
if index < components.count - 1 {
result += "_"
}
}
return result
}
``` // XCTAssertTrue failedfunc fixSpaces(text: String) -> String {
let regex = try! NSRegularExpression(pattern: "\\s{2,}")
return regex.stringByReplacingMatches(in: text, options:.anchored, range: NSRange(text.startIndex..., in: text), withTemplate: "_")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
Answer:
```swift
func fixSpaces(text: String) -> String {
let regex = try! NSRegularExpression(pattern: "\\s{2,}")
return regex.stringByReplacingMatches(in: text, options:.anchored, range: NSRange(text.startIndex..., in: text), withTemplate: "_")
}
``` // XCTAssertTrue failedfunc fixSpaces(text: String) -> String {
let components = text.components(separatedBy: " ")
var result = ""
for (index, component) in components.enumerated() {
if component.isEmpty {
result += "_"
} else {
result += component
if index < components.count - 1 {
result += "_"
}
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
Answer:
```swift
func fixSpaces(text: String) -> String {
let components = text.components(separatedBy: " ")
var result = ""
for (index, component) in components.enumerated() {
if component.isEmpty {
result += "_"
} else {
result += component
if index < components.count - 1 {
result += "_"
}
}
}
return result
}
``` // XCTAssertTrue failedfunc fixSpaces(text: String) -> String {
let components = text.components(separatedBy: " ")
var result = ""
for (index, component) in components.enumerated() {
if index == 0 {
result += component
} else {
result += component.replacingOccurrences(of: " ", with: "_")
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
Answer:
```swift
func fixSpaces(text: String) -> String {
let components = text.components(separatedBy: " ")
var result = ""
for (index, component) in components.enumerated() {
if index == 0 {
result += component
} else {
result += component.replacingOccurrences(of: " ", with: "_")
}
}
return result
}
``` // XCTAssertTrue failedfunc fixSpaces(text: String) -> String {
let components = text.components(separatedBy: " ")
var result = ""
for (index, component) in components.enumerated() {
if index == 0 {
result += component
} else {
result += component.replacingOccurrences(of: " ", with: "_")
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
Answer:
```swift
func fixSpaces(text: String) -> String {
let components = text.components(separatedBy: " ")
var result = ""
for (index, component) in components.enumerated() {
if index == 0 {
result += component
} else {
result += component.replacingOccurrences(of: " ", with: "_")
}
}
return result
}
``` // XCTAssertTrue failedfunc fixSpaces(text: String) -> String {
let components = text.components(separatedBy: " ")
var result = ""
for (index, component) in components.enumerated() {
if index == 0 {
result += component
} else {
result += component.replacingOccurrences(of: " ", with: "_")
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
Answer:
```swift
func fixSpaces(text: String) -> String {
let components = text.components(separatedBy: " ")
var result = ""
for (index, component) in components.enumerated() {
if index == 0 {
result += component
} else {
result += component.replacingOccurrences(of: " ", with: "_")
}
}
return result
}
``` // XCTAssertTrue failedfunc fileNameCheck(fileName: String) -> String {
let regex = try! NSRegularExpression(pattern: "^[a-zA-Z][a-zA-Z0-9]{0,3}\\.[tT][xX][tT]$")
return regex.firstMatch(in: fileName, options: [], range: NSRange(location: 0, length: fileName.utf16.count))!= nil? "Yes" : "No"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
Answer:
```swift
func fileNameCheck(fileName: String) -> String {
let regex = try! NSRegularExpression(pattern: "^[a-zA-Z][a-zA-Z0-9]{0,3}\\.[tT][xX][tT]$")
return regex.firstMatch(in: fileName, options: [], range: NSRange(location: 0, length: fileName.utf16.count))!= nil? "Yes" : "No"
}
```return regex.firstMatch(in: fileName, options: [], range: NSRange(location: 0, length: fileName.utf16.count))!= nil? "Yes" : "No" // consecutive statements on a line must be separated by ';'return regex.firstMatch(in: fileName, options: [], range: NSRange(location: 0, length: fileName.utf16.count))!= nil? "Yes" : "No" // 'nil' requires a contextual typereturn regex.firstMatch(in: fileName, options: [], range: NSRange(location: 0, length: fileName.utf16.count))!= nil? "Yes" : "No" // consecutive statements on a line must be separated by ';'return regex.firstMatch(in: fileName, options: [], range: NSRange(location: 0, length: fileName.utf16.count))!= nil? "Yes" : "No" // cannot convert return expression of type '()' to return type 'String'return regex.firstMatch(in: fileName, options: [], range: NSRange(location: 0, length: fileName.utf16.count))!= nil? "Yes" : "No" // expected expressionreturn regex.firstMatch(in: fileName, options: [], range: NSRange(location: 0, length: fileName.utf16.count))!= nil? "Yes" : "No" // string literal is unusedreturn regex.firstMatch(in: fileName, options: [], range: NSRange(location: 0, length: fileName.utf16.count))!= nil? "Yes" : "No" // cannot assign value of type 'Optional<_>' to type 'NSTextCheckingResult'return regex.firstMatch(in: fileName, options: [], range: NSRange(location: 0, length: fileName.utf16.count))!= nil? "Yes" : "No" // '=' must have consistent whitespace on both sidesreturn regex.firstMatch(in: fileName, options: [], range: NSRange(location: 0, length: fileName.utf16.count))!= nil? "Yes" : "No" // cannot assign through '!': function call returns immutable valuefunc fileNameCheck(fileName: String) -> String {
let regex = try! NSRegularExpression(pattern: "^[a-zA-Z][a-zA-Z0-9]{0,3}\\.(txt|exe|dll)$")
return regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName))!= nil? "Yes" : "No"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
Answer:
```swift
func fileNameCheck(fileName: String) -> String {
let regex = try! NSRegularExpression(pattern: "^[a-zA-Z][a-zA-Z0-9]{0,3}\\.(txt|exe|dll)$")
return regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName))!= nil? "Yes" : "No"
}
```return regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName))!= nil? "Yes" : "No" // cannot assign through '!': function call returns immutable valuereturn regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName))!= nil? "Yes" : "No" // cannot convert return expression of type '()' to return type 'String'return regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName))!= nil? "Yes" : "No" // expected expressionreturn regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName))!= nil? "Yes" : "No" // consecutive statements on a line must be separated by ';'return regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName))!= nil? "Yes" : "No" // '=' must have consistent whitespace on both sidesreturn regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName))!= nil? "Yes" : "No" // cannot assign value of type 'Optional<_>' to type 'NSTextCheckingResult'return regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName))!= nil? "Yes" : "No" // string literal is unusedreturn regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName))!= nil? "Yes" : "No" // consecutive statements on a line must be separated by ';'return regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName))!= nil? "Yes" : "No" // 'nil' requires a contextual typefunc fileNameCheck(fileName: String) -> String {
let regex = try! NSRegularExpression(pattern: "^[a-zA-Z][a-zA-Z0-9]{0,3}\\.[tT][xX][tT]$")
let isMatch = regex.firstMatch(in: fileName, options: [], range: NSRange(location: 0, length: fileName.utf16.count))!= nil
return isMatch? "Yes" : "No"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
Answer:
```swift
func fileNameCheck(fileName: String) -> String {
let regex = try! NSRegularExpression(pattern: "^[a-zA-Z][a-zA-Z0-9]{0,3}\\.[tT][xX][tT]$")
let isMatch = regex.firstMatch(in: fileName, options: [], range: NSRange(location: 0, length: fileName.utf16.count))!= nil
return isMatch? "Yes" : "No"
}
```let isMatch = regex.firstMatch(in: fileName, options: [], range: NSRange(location: 0, length: fileName.utf16.count))!= nil // cannot assign through '!': function call returns immutable valuelet isMatch = regex.firstMatch(in: fileName, options: [], range: NSRange(location: 0, length: fileName.utf16.count))!= nil // '=' must have consistent whitespace on both sideslet isMatch = regex.firstMatch(in: fileName, options: [], range: NSRange(location: 0, length: fileName.utf16.count))!= nil // 'nil' cannot be assigned to type 'NSTextCheckingResult'return isMatch? "Yes" : "No" // consecutive statements on a line must be separated by ';'return isMatch? "Yes" : "No" // consecutive statements on a line must be separated by ';'return isMatch? "Yes" : "No" // cannot convert return expression of type 'Optional<_>' to return type 'String'return isMatch? "Yes" : "No" // expected expressionreturn isMatch? "Yes" : "No" // string literal is unusedfunc fileNameCheck(fileName: String) -> String {
let regex = try! NSRegularExpression(pattern: "^[a-zA-Z][a-zA-Z0-9]{0,3}\\.[tT][xX][tT]$")
return regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName)).map { _ in "Yes" }?? "No"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
Answer:
```swift
func fileNameCheck(fileName: String) -> String {
let regex = try! NSRegularExpression(pattern: "^[a-zA-Z][a-zA-Z0-9]{0,3}\\.[tT][xX][tT]$")
return regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName)).map { _ in "Yes" }?? "No"
}
```return regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName)).map { _ in "Yes" }?? "No" // string literal is unusedreturn regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName)).map { _ in "Yes" }?? "No" // consecutive statements on a line must be separated by ';'return regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName)).map { _ in "Yes" }?? "No" // value of optional type 'String?' must be unwrapped to a value of type 'String'func fileNameCheck(fileName: String) -> String {
let nameComponents = fileName.components(separatedBy: ".")
let name = nameComponents.first?? ""
let extension = nameComponents.last?? ""
if name.count > 3 {
return "No"
}
if name.count == 0 ||!name.first!.isLetter {
return "No"
}
if!["txt", "exe", "dll"].contains(extension) {
return "No"
}
return "Yes"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
Answer:
```swift
func fileNameCheck(fileName: String) -> String {
let nameComponents = fileName.components(separatedBy: ".")
let name = nameComponents.first?? ""
let extension = nameComponents.last?? ""
if name.count > 3 {
return "No"
}
if name.count == 0 ||!name.first!.isLetter {
return "No"
}
if!["txt", "exe", "dll"].contains(extension) {
return "No"
}
return "Yes"
}
```let name = nameComponents.first?? "" // string literal is unusedlet name = nameComponents.first?? "" // cannot use optional chaining on non-optional value of type 'String'let name = nameComponents.first?? "" // consecutive statements on a line must be separated by ';'let extension = nameComponents.last?? "" // consecutive statements on a line must be separated by ';'let extension = nameComponents.last?? "" // string literal is unusedlet extension = nameComponents.last?? "" // keyword 'extension' cannot be used as an identifier herelet extension = nameComponents.last?? "" // cannot use optional chaining on non-optional value of type 'String'if name.count == 0 ||!name.first!.isLetter { // expected '{' after 'if' conditionif!["txt", "exe", "dll"].contains(extension) { // expected expression, var, or let in 'if' conditionfunc fileNameCheck(fileName: String) -> String {
let nameComponents = fileName.components(separatedBy: ".")
let nameWithoutExtension = nameComponents.first?? ""
let extension = nameComponents.last?? ""
if nameWithoutExtension.count > 3 {
return "No"
}
if nameWithoutExtension.first == nil ||!nameWithoutExtension.first!.isLetter {
return "No"
}
if!["txt", "exe", "dll"].contains(extension) {
return "No"
}
return "Yes"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
Answer:
```swift
func fileNameCheck(fileName: String) -> String {
let nameComponents = fileName.components(separatedBy: ".")
let nameWithoutExtension = nameComponents.first?? ""
let extension = nameComponents.last?? ""
if nameWithoutExtension.count > 3 {
return "No"
}
if nameWithoutExtension.first == nil ||!nameWithoutExtension.first!.isLetter {
return "No"
}
if!["txt", "exe", "dll"].contains(extension) {
return "No"
}
return "Yes"
}
```let nameWithoutExtension = nameComponents.first?? "" // cannot use optional chaining on non-optional value of type 'String'let nameWithoutExtension = nameComponents.first?? "" // consecutive statements on a line must be separated by ';'let nameWithoutExtension = nameComponents.first?? "" // string literal is unusedlet extension = nameComponents.last?? "" // consecutive statements on a line must be separated by ';'let extension = nameComponents.last?? "" // string literal is unusedlet extension = nameComponents.last?? "" // keyword 'extension' cannot be used as an identifier herelet extension = nameComponents.last?? "" // cannot use optional chaining on non-optional value of type 'String'if nameWithoutExtension.first == nil ||!nameWithoutExtension.first!.isLetter { // expected '{' after 'if' conditionif!["txt", "exe", "dll"].contains(extension) { // expected expression, var, or let in 'if' conditionfunc fileNameCheck(fileName: String) -> String {
let nameComponents = fileName.components(separatedBy: ".")
if nameComponents.count!= 2 {
return "No"
}
let extension = nameComponents.last!
let name = nameComponents.first!
if name.count > 3 || name.first! ~= name.first!.uppercased() {
return "No"
}
if extension!= "txt" && extension!= "exe" && extension!= "dll" {
return "No"
}
return "Yes"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
Answer:
```swift
func fileNameCheck(fileName: String) -> String {
let nameComponents = fileName.components(separatedBy: ".")
if nameComponents.count!= 2 {
return "No"
}
let extension = nameComponents.last!
let name = nameComponents.first!
if name.count > 3 || name.first! ~= name.first!.uppercased() {
return "No"
}
if extension!= "txt" && extension!= "exe" && extension!= "dll" {
return "No"
}
return "Yes"
}
```if nameComponents.count!= 2 { // use of '=' in a boolean context, did you mean '=='?if nameComponents.count!= 2 { // cannot force unwrap value of non-optional type 'Int'if nameComponents.count!= 2 { // '=' must have consistent whitespace on both sideslet extension = nameComponents.last! // keyword 'extension' cannot be used as an identifier hereif name.count > 3 || name.first! ~= name.first!.uppercased() { // cannot convert value of type 'String.Element' (aka 'Character') to expected argument type 'Substring'if extension!= "txt" && extension!= "exe" && extension!= "dll" { // expected expression, var, or let in 'if' conditionif extension!= "txt" && extension!= "exe" && extension!= "dll" { // expected type name in extension declarationif extension!= "txt" && extension!= "exe" && extension!= "dll" { // expected '{' in extensionif extension!= "txt" && extension!= "exe" && extension!= "dll" { // '=' must have consistent whitespace on both sidesif extension!= "txt" && extension!= "exe" && extension!= "dll" { // declaration is only valid at file scopeif extension!= "txt" && extension!= "exe" && extension!= "dll" { // declaration is only valid at file scopeif extension!= "txt" && extension!= "exe" && extension!= "dll" { // expected type name in extension declarationif extension!= "txt" && extension!= "exe" && extension!= "dll" { // expected '{' in extensionif extension!= "txt" && extension!= "exe" && extension!= "dll" { // '=' must have consistent whitespace on both sidesif extension!= "txt" && extension!= "exe" && extension!= "dll" { // '=' must have consistent whitespace on both sidesif extension!= "txt" && extension!= "exe" && extension!= "dll" { // expected type name in extension declarationif extension!= "txt" && extension!= "exe" && extension!= "dll" { // expected '{' in extensionif extension!= "txt" && extension!= "exe" && extension!= "dll" { // declaration is only valid at file scopefunc fileNameCheck(fileName: String) -> String {
let regex = try! NSRegularExpression(pattern: "^[a-zA-Z][a-zA-Z0-9]{0,3}\\.(txt|exe|dll)$")
return regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName))!= nil? "Yes" : "No"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
Answer:
```swift
func fileNameCheck(fileName: String) -> String {
let regex = try! NSRegularExpression(pattern: "^[a-zA-Z][a-zA-Z0-9]{0,3}\\.(txt|exe|dll)$")
return regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName))!= nil? "Yes" : "No"
}
```return regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName))!= nil? "Yes" : "No" // cannot assign through '!': function call returns immutable valuereturn regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName))!= nil? "Yes" : "No" // cannot convert return expression of type '()' to return type 'String'return regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName))!= nil? "Yes" : "No" // expected expressionreturn regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName))!= nil? "Yes" : "No" // consecutive statements on a line must be separated by ';'return regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName))!= nil? "Yes" : "No" // '=' must have consistent whitespace on both sidesreturn regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName))!= nil? "Yes" : "No" // cannot assign value of type 'Optional<_>' to type 'NSTextCheckingResult'return regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName))!= nil? "Yes" : "No" // string literal is unusedreturn regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName))!= nil? "Yes" : "No" // consecutive statements on a line must be separated by ';'return regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName))!= nil? "Yes" : "No" // 'nil' requires a contextual typefunc fileNameCheck(fileName: String) -> String {
let regex = try! NSRegularExpression(pattern: "^[a-zA-Z][a-zA-Z0-9]{0,3}\\.[tT][xX][tT]$")
return regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName)) == nil? "No" : "Yes"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
Answer:
```swift
func fileNameCheck(fileName: String) -> String {
let regex = try! NSRegularExpression(pattern: "^[a-zA-Z][a-zA-Z0-9]{0,3}\\.[tT][xX][tT]$")
return regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName)) == nil? "No" : "Yes"
}
```return regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName)) == nil? "No" : "Yes" // cannot convert return expression of type 'Bool' to return type 'String'return regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName)) == nil? "No" : "Yes" // string literal is unusedreturn regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName)) == nil? "No" : "Yes" // expected expressionreturn regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName)) == nil? "No" : "Yes" // consecutive statements on a line must be separated by ';'return regex.firstMatch(in: fileName, options: [], range: NSRange(fileName.startIndex..., in: fileName)) == nil? "No" : "Yes" // consecutive statements on a line must be separated by ';'func fileNameCheck(fileName: String) -> String {
let nameComponents = fileName.components(separatedBy: ".")
let extension = nameComponents.last
let nameWithoutExtension = nameComponents.prefix(nameComponents.count - 1).joined(separator: ".")
if nameWithoutExtension.count > 3 {
return "No"
}
if nameWithoutExtension.first == nil ||!CharacterSet.letters.contains(nameWithoutExtension.first!) {
return "No"
}
if!["txt", "exe", "dll"].contains(extension) {
return "No"
}
return "Yes"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
Answer:
```swift
func fileNameCheck(fileName: String) -> String {
let nameComponents = fileName.components(separatedBy: ".")
let extension = nameComponents.last
let nameWithoutExtension = nameComponents.prefix(nameComponents.count - 1).joined(separator: ".")
if nameWithoutExtension.count > 3 {
return "No"
}
if nameWithoutExtension.first == nil ||!CharacterSet.letters.contains(nameWithoutExtension.first!) {
return "No"
}
if!["txt", "exe", "dll"].contains(extension) {
return "No"
}
return "Yes"
}
```let extension = nameComponents.last // keyword 'extension' cannot be used as an identifier hereif nameWithoutExtension.first == nil ||!CharacterSet.letters.contains(nameWithoutExtension.first!) { // expected '{' after 'if' conditionif!["txt", "exe", "dll"].contains(extension) { // expected expression, var, or let in 'if' conditionfunc wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var result = ""
for word in words {
if isPrime(word.count) {
result += word + " "
}
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
Answer:
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var result = ""
for word in words {
if isPrime(word.count) {
result += word + " "
}
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var result = ""
for word in words {
if isPrime(word.count) {
result += word + " "
}
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
Answer:
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var result = ""
for word in words {
if isPrime(word.count) {
result += word + " "
}
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var result = ""
for word in words {
if isPrime(word.count) {
result += word + " "
}
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
Answer:
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var result = ""
for word in words {
if isPrime(word.count) {
result += word + " "
}
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var result = ""
for word in words {
if isPrime(word.count) {
result += word + " "
}
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
Answer:
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var result = ""
for word in words {
if isPrime(word.count) {
result += word + " "
}
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var result = ""
for word in words {
if isPrime(word.count) {
result += word + " "
}
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
Answer:
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var result = ""
for word in words {
if isPrime(word.count) {
result += word + " "
}
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var result = ""
for word in words {
let length = word.count
if isPrime(number: length) {
result += word + " "
}
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
Answer:
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var result = ""
for word in words {
let length = word.count
if isPrime(number: length) {
result += word + " "
}
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
func isPrime(number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var result = ""
for word in words {
if isPrime(word.count) {
result += word + " "
}
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
Answer:
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var result = ""
for word in words {
if isPrime(word.count) {
result += word + " "
}
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var result = ""
for word in words {
if isPrime(word.count) {
result += word + " "
}
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
Answer:
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var result = ""
for word in words {
if isPrime(word.count) {
result += word + " "
}
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var result = ""
for word in words {
if isPrime(word.count) {
result += word + " "
}
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
Answer:
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var result = ""
for word in words {
if isPrime(word.count) {
result += word + " "
}
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var result = ""
for word in words {
if isPrime(word.count) {
result += word + " "
}
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
Answer:
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var result = ""
for word in words {
if isPrime(word.count) {
result += word + " "
}
}
return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```func simplify(x: String, n: String) -> Bool {
let xNumerator = Int(x.components(separatedBy: "/")[0])!
let xDenominator = Int(x.components(separatedBy: "/")[1])!
let nNumerator = Int(n.components(separatedBy: "/")[0])!
let nDenominator = Int(n.components(separatedBy: "/")[1])!
let product = xNumerator * nNumerator
let gcd = gcd(xNumerator, xDenominator) * gcd(nNumerator, nDenominator)
return product % gcd == 0
}
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
}
return gcd(b, a % b)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
Answer:
```swift
func simplify(x: String, n: String) -> Bool {
let xNumerator = Int(x.components(separatedBy: "/")[0])!
let xDenominator = Int(x.components(separatedBy: "/")[1])!
let nNumerator = Int(n.components(separatedBy: "/")[0])!
let nDenominator = Int(n.components(separatedBy: "/")[1])!
let product = xNumerator * nNumerator
let gcd = gcd(xNumerator, xDenominator) * gcd(nNumerator, nDenominator)
return product % gcd == 0
}
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
}
return gcd(b, a % b)
}
``` // XCTAssertTrue failedfunc simplify(x: String, n: String) -> Bool {
let xComponents = x.components(separatedBy: "/")
let nComponents = n.components(separatedBy: "/")
let xNumerator = Int(xComponents[0])!
let xDenominator = Int(xComponents[1])!
let nNumerator = Int(nComponents[0])!
let nDenominator = Int(nComponents[1])!
let gcd = gcd(xNumerator, xDenominator)
let simplifiedXNumerator = xNumerator / gcd
let simplifiedXNominator = xDenominator / gcd
let gcd2 = gcd(nNumerator, nDenominator)
let simplifiedNNumerator = nNumerator / gcd2
let simplifiedNDenominator = nDenominator / gcd2
return (simplifiedXNumerator * simplifiedNDenominator) == (simplifiedNNumerator * simplifiedXNominator)
}
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
}
return gcd(b, a % b)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
Answer:
```swift
func simplify(x: String, n: String) -> Bool {
let xComponents = x.components(separatedBy: "/")
let nComponents = n.components(separatedBy: "/")
let xNumerator = Int(xComponents[0])!
let xDenominator = Int(xComponents[1])!
let nNumerator = Int(nComponents[0])!
let nDenominator = Int(nComponents[1])!
let gcd = gcd(xNumerator, xDenominator)
let simplifiedXNumerator = xNumerator / gcd
let simplifiedXNominator = xDenominator / gcd
let gcd2 = gcd(nNumerator, nDenominator)
let simplifiedNNumerator = nNumerator / gcd2
let simplifiedNDenominator = nDenominator / gcd2
return (simplifiedXNumerator * simplifiedNDenominator) == (simplifiedNNumerator * simplifiedXNominator)
}
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
}
return gcd(b, a % b)
}
```let gcd2 = gcd(nNumerator, nDenominator) // cannot call value of non-function type 'Int'func simplify(x: String, n: String) -> Bool {
let xNumerator = Int(x.components(separatedBy: "/")[0])!
let xDenominator = Int(x.components(separatedBy: "/")[1])!
let nNumerator = Int(n.components(separatedBy: "/")[0])!
let nDenominator = Int(n.components(separatedBy: "/")[1])!
let product = xNumerator * nNumerator
let gcd = gcd(xNumerator, xDenominator) * gcd(nNumerator, nDenominator)
return product % gcd == 0
}
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
}
return gcd(b, a % b)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
Answer:
```swift
func simplify(x: String, n: String) -> Bool {
let xNumerator = Int(x.components(separatedBy: "/")[0])!
let xDenominator = Int(x.components(separatedBy: "/")[1])!
let nNumerator = Int(n.components(separatedBy: "/")[0])!
let nDenominator = Int(n.components(separatedBy: "/")[1])!
let product = xNumerator * nNumerator
let gcd = gcd(xNumerator, xDenominator) * gcd(nNumerator, nDenominator)
return product % gcd == 0
}
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
}
return gcd(b, a % b)
}
``` // XCTAssertTrue failedfunc simplify(x: String, n: String) -> Bool {
let xNumerator = Int(x.components(separatedBy: "/")[0])!
let xDenominator = Int(x.components(separatedBy: "/")[1])!
let nNumerator = Int(n.components(separatedBy: "/")[0])!
let nDenominator = Int(n.components(separatedBy: "/")[1])!
return (xNumerator * nDenominator) % (xDenominator * nNumerator) == 0
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
Answer:
```swift
func simplify(x: String, n: String) -> Bool {
let xNumerator = Int(x.components(separatedBy: "/")[0])!
let xDenominator = Int(x.components(separatedBy: "/")[1])!
let nNumerator = Int(n.components(separatedBy: "/")[0])!
let nDenominator = Int(n.components(separatedBy: "/")[1])!
return (xNumerator * nDenominator) % (xDenominator * nNumerator) == 0
}
``` // XCTAssertTrue failedfunc simplify(x: String, n: String) -> Bool {
let xNumerator = Int(x.components(separatedBy: "/")[0])!
let xDenominator = Int(x.components(separatedBy: "/")[1])!
let nNumerator = Int(n.components(separatedBy: "/")[0])!
let nDenominator = Int(n.components(separatedBy: "/")[1])!
let product = xNumerator * nNumerator
let gcd = gcd(xNumerator, nNumerator)
return product / gcd == xDenominator * nDenominator
}
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
}
return gcd(b, a % b)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
Answer:
```swift
func simplify(x: String, n: String) -> Bool {
let xNumerator = Int(x.components(separatedBy: "/")[0])!
let xDenominator = Int(x.components(separatedBy: "/")[1])!
let nNumerator = Int(n.components(separatedBy: "/")[0])!
let nDenominator = Int(n.components(separatedBy: "/")[1])!
let product = xNumerator * nNumerator
let gcd = gcd(xNumerator, nNumerator)
return product / gcd == xDenominator * nDenominator
}
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
}
return gcd(b, a % b)
}
``` // XCTAssertTrue failedfunc simplify(x: String, n: String) -> Bool {
let xNumerator = Int(x.components(separatedBy: "/")[0])?? 0
let xDenominator = Int(x.components(separatedBy: "/")[1])?? 0
let nNumerator = Int(n.components(separatedBy: "/")[0])?? 0
let nDenominator = Int(n.components(separatedBy: "/")[1])?? 0
let gcd = gcd(xNumerator, xDenominator)
let simplifiedXNumerator = xNumerator / gcd
let simplifiedXNominator = xDenominator / gcd
let gcd2 = gcd(simplifiedXNumerator, nNumerator)
let simplifiedXNumerator2 = simplifiedXNumerator / gcd2
let simplifiedXNominator2 = nNumerator / gcd2
return simplifiedXNumerator2 * simplifiedXNominator2 == nNumerator * nDenominator
}
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
}
return gcd(b, a % b)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
Answer:
```swift
func simplify(x: String, n: String) -> Bool {
let xNumerator = Int(x.components(separatedBy: "/")[0])?? 0
let xDenominator = Int(x.components(separatedBy: "/")[1])?? 0
let nNumerator = Int(n.components(separatedBy: "/")[0])?? 0
let nDenominator = Int(n.components(separatedBy: "/")[1])?? 0
let gcd = gcd(xNumerator, xDenominator)
let simplifiedXNumerator = xNumerator / gcd
let simplifiedXNominator = xDenominator / gcd
let gcd2 = gcd(simplifiedXNumerator, nNumerator)
let simplifiedXNumerator2 = simplifiedXNumerator / gcd2
let simplifiedXNominator2 = nNumerator / gcd2
return simplifiedXNumerator2 * simplifiedXNominator2 == nNumerator * nDenominator
}
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
}
return gcd(b, a % b)
}
```let xNumerator = Int(x.components(separatedBy: "/")[0])?? 0 // cannot use optional chaining on non-optional value of type 'Int'let xNumerator = Int(x.components(separatedBy: "/")[0])?? 0 // consecutive statements on a line must be separated by ';'let xNumerator = Int(x.components(separatedBy: "/")[0])?? 0 // integer literal is unusedlet xDenominator = Int(x.components(separatedBy: "/")[1])?? 0 // consecutive statements on a line must be separated by ';'let xDenominator = Int(x.components(separatedBy: "/")[1])?? 0 // cannot use optional chaining on non-optional value of type 'Int'let xDenominator = Int(x.components(separatedBy: "/")[1])?? 0 // integer literal is unusedlet nNumerator = Int(n.components(separatedBy: "/")[0])?? 0 // consecutive statements on a line must be separated by ';'let nNumerator = Int(n.components(separatedBy: "/")[0])?? 0 // integer literal is unusedlet nNumerator = Int(n.components(separatedBy: "/")[0])?? 0 // cannot use optional chaining on non-optional value of type 'Int'let nDenominator = Int(n.components(separatedBy: "/")[1])?? 0 // integer literal is unusedlet nDenominator = Int(n.components(separatedBy: "/")[1])?? 0 // cannot use optional chaining on non-optional value of type 'Int'let nDenominator = Int(n.components(separatedBy: "/")[1])?? 0 // consecutive statements on a line must be separated by ';'func simplify(x: String, n: String) -> Bool {
let xComponents = x.components(separatedBy: "/")
let nComponents = n.components(separatedBy: "/")
let xNumerator = Int(xComponents[0])!
let xDenominator = Int(xComponents[1])!
let nNumerator = Int(nComponents[0])!
let nDenominator = Int(nComponents[1])!
let gcd = gcd(xNumerator, xDenominator)
let simplifiedXNumerator = xNumerator / gcd
let simplifiedXNominator = xDenominator / gcd
let gcd2 = gcd(simplifiedXNumerator, nNumerator)
let simplifiedXNumerator2 = simplifiedXNumerator / gcd2
let simplifiedXNominator2 = nNumerator / gcd2
return (simplifiedXNumerator2 * nDenominator) == (simplifiedXNominator2 * nNumerator)
}
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
}
return gcd(b, a % b)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
Answer:
```swift
func simplify(x: String, n: String) -> Bool {
let xComponents = x.components(separatedBy: "/")
let nComponents = n.components(separatedBy: "/")
let xNumerator = Int(xComponents[0])!
let xDenominator = Int(xComponents[1])!
let nNumerator = Int(nComponents[0])!
let nDenominator = Int(nComponents[1])!
let gcd = gcd(xNumerator, xDenominator)
let simplifiedXNumerator = xNumerator / gcd
let simplifiedXNominator = xDenominator / gcd
let gcd2 = gcd(simplifiedXNumerator, nNumerator)
let simplifiedXNumerator2 = simplifiedXNumerator / gcd2
let simplifiedXNominator2 = nNumerator / gcd2
return (simplifiedXNumerator2 * nDenominator) == (simplifiedXNominator2 * nNumerator)
}
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
}
return gcd(b, a % b)
}
```let gcd2 = gcd(simplifiedXNumerator, nNumerator) // cannot call value of non-function type 'Int'func simplify(x: String, n: String) -> Bool {
let xComponents = x.components(separatedBy: "/")
let nComponents = n.components(separatedBy: "/")
let xNumerator = Int(xComponents[0])!
let xDenominator = Int(xComponents[1])!
let nNumerator = Int(nComponents[0])!
let nDenominator = Int(nComponents[1])!
let product = xNumerator * nNumerator
let gcd = gcd(xNumerator, nNumerator)
return product / gcd == nNumerator / gcd
}
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
}
return gcd(b, a % b)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
Answer:
```swift
func simplify(x: String, n: String) -> Bool {
let xComponents = x.components(separatedBy: "/")
let nComponents = n.components(separatedBy: "/")
let xNumerator = Int(xComponents[0])!
let xDenominator = Int(xComponents[1])!
let nNumerator = Int(nComponents[0])!
let nDenominator = Int(nComponents[1])!
let product = xNumerator * nNumerator
let gcd = gcd(xNumerator, nNumerator)
return product / gcd == nNumerator / gcd
}
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
}
return gcd(b, a % b)
}
```let xDenominator = Int(xComponents[1])! // initialization of immutable value 'xDenominator' was never used; consider replacing with assignment to '_' or removing itlet nDenominator = Int(nComponents[1])! // initialization of immutable value 'nDenominator' was never used; consider replacing with assignment to '_' or removing it // XCTAssertTrue failedfunc simplify(x: String, n: String) -> Bool {
let xNumerator = Int(x.components(separatedBy: "/")[0])!
let xDenominator = Int(x.components(separatedBy: "/")[1])!
let nNumerator = Int(n.components(separatedBy: "/")[0])!
let nDenominator = Int(n.components(separatedBy: "/")[1])!
let product = xNumerator * nNumerator
let gcd = gcd(xNumerator, nNumerator)
let simplifiedNumerator = product / gcd
let simplifiedDenominator = xDenominator * nDenominator
let gcd2 = gcd(simplifiedNumerator, simplifiedDenominator)
let simplifiedNumerator2 = simplifiedNumerator / gcd2
let simplifiedDenominator2 = simplifiedDenominator / gcd2
return simplifiedNumerator2 % simplifiedDenominator2 == 0
}
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
}
return gcd(b, a % b)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
Answer:
```swift
func simplify(x: String, n: String) -> Bool {
let xNumerator = Int(x.components(separatedBy: "/")[0])!
let xDenominator = Int(x.components(separatedBy: "/")[1])!
let nNumerator = Int(n.components(separatedBy: "/")[0])!
let nDenominator = Int(n.components(separatedBy: "/")[1])!
let product = xNumerator * nNumerator
let gcd = gcd(xNumerator, nNumerator)
let simplifiedNumerator = product / gcd
let simplifiedDenominator = xDenominator * nDenominator
let gcd2 = gcd(simplifiedNumerator, simplifiedDenominator)
let simplifiedNumerator2 = simplifiedNumerator / gcd2
let simplifiedDenominator2 = simplifiedDenominator / gcd2
return simplifiedNumerator2 % simplifiedDenominator2 == 0
}
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
}
return gcd(b, a % b)
}
```let gcd2 = gcd(simplifiedNumerator, simplifiedDenominator) // cannot call value of non-function type 'Int'func simplify(x: String, n: String) -> Bool {
let xComponents = x.components(separatedBy: "/")
let nComponents = n.components(separatedBy: "/")
let xNumerator = Int(xComponents[0])!
let xDenominator = Int(xComponents[1])!
let nNumerator = Int(nComponents[0])!
let nDenominator = Int(nComponents[1])!
let gcd = gcd(xNumerator, xDenominator)
let simplifiedXNumerator = xNumerator / gcd
let simplifiedXNominator = xDenominator / gcd
let gcd2 = gcd(nNumerator, nDenominator)
let simplifiedNNumerator = nNumerator / gcd2
let simplifiedNDenominator = nDenominator / gcd2
return (simplifiedXNumerator * simplifiedNDenominator) == (simplifiedNNumerator * simplifiedXNominator)
}
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
}
return gcd(b, a % b)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
Answer:
```swift
func simplify(x: String, n: String) -> Bool {
let xComponents = x.components(separatedBy: "/")
let nComponents = n.components(separatedBy: "/")
let xNumerator = Int(xComponents[0])!
let xDenominator = Int(xComponents[1])!
let nNumerator = Int(nComponents[0])!
let nDenominator = Int(nComponents[1])!
let gcd = gcd(xNumerator, xDenominator)
let simplifiedXNumerator = xNumerator / gcd
let simplifiedXNominator = xDenominator / gcd
let gcd2 = gcd(nNumerator, nDenominator)
let simplifiedNNumerator = nNumerator / gcd2
let simplifiedNDenominator = nDenominator / gcd2
return (simplifiedXNumerator * simplifiedNDenominator) == (simplifiedNNumerator * simplifiedXNominator)
}
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
}
return gcd(b, a % b)
}
```let gcd2 = gcd(nNumerator, nDenominator) // cannot call value of non-function type 'Int'func orderByPoints(nums: [Int]) -> [Int] {
let sorted = nums.sorted { $0.digitsSum() < $1.digitsSum() }
return sorted
}
extension Int {
func digitsSum() -> Int {
return reduce(0, { $0 * 10 + String($1).digitsSum() })
}
}
extension String {
func digitsSum() -> Int {
return reduce(0, { $0 * 10 + String($1).digitsSum() })
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
Answer:
```swift
func orderByPoints(nums: [Int]) -> [Int] {
let sorted = nums.sorted { $0.digitsSum() < $1.digitsSum() }
return sorted
}
extension Int {
func digitsSum() -> Int {
return reduce(0, { $0 * 10 + String($1).digitsSum() })
}
}
extension String {
func digitsSum() -> Int {
return reduce(0, { $0 * 10 + String($1).digitsSum() })
}
}
```return reduce(0, { $0 * 10 + String($1).digitsSum() }) // cannot find 'reduce' in scopefunc orderByPoints(nums: [Int]) -> [Int] {
let sorted = nums.sorted { $0.digitsSum() < $1.digitsSum() }
let result = sorted.enumerated().sorted { $0.element.digitsSum() < $1.element.digitsSum() }
return result.map { $0.element }
}
extension Int {
func digitsSum() -> Int {
return String(self).reduce(0, { $0 + Int($1) })
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
Answer:
```swift
func orderByPoints(nums: [Int]) -> [Int] {
let sorted = nums.sorted { $0.digitsSum() < $1.digitsSum() }
let result = sorted.enumerated().sorted { $0.element.digitsSum() < $1.element.digitsSum() }
return result.map { $0.element }
}
extension Int {
func digitsSum() -> Int {
return String(self).reduce(0, { $0 + Int($1) })
}
}
```return String(self).reduce(0, { $0 + Int($1) }) // no exact matches in call to initializerfunc orderByPoints(nums: [Int]) -> [Int] {
let sorted = nums.sorted { $0.digitsSum() < $1.digitsSum() }
let result = sorted.enumerated().map { $0.element }
return result
}
extension Int {
func digitsSum() -> Int {
return String(self).reduce(0, { $0 + Int($1) })
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
Answer:
```swift
func orderByPoints(nums: [Int]) -> [Int] {
let sorted = nums.sorted { $0.digitsSum() < $1.digitsSum() }
let result = sorted.enumerated().map { $0.element }
return result
}
extension Int {
func digitsSum() -> Int {
return String(self).reduce(0, { $0 + Int($1) })
}
}
```return String(self).reduce(0, { $0 + Int($1) }) // no exact matches in call to initializerfunc orderByPoints(nums: [Int]) -> [Int] {
let sorted = nums.sorted { $0.digitsSum() < $1.digitsSum() }
return sorted
}
extension Int {
func digitsSum() -> Int {
return self.description.reduce(0) { $0 + Int($1) }
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
Answer:
```swift
func orderByPoints(nums: [Int]) -> [Int] {
let sorted = nums.sorted { $0.digitsSum() < $1.digitsSum() }
return sorted
}
extension Int {
func digitsSum() -> Int {
return self.description.reduce(0) { $0 + Int($1) }
}
}
```return self.description.reduce(0) { $0 + Int($1) } // no exact matches in call to initializerfunc orderByPoints(nums: [Int]) -> [Int] {
let sorted = nums.sorted { $0.digitsSum() < $1.digitsSum() }
let result = sorted.enumerated().map { nums[$0.offset] }
return result
}
extension Int {
func digitsSum() -> Int {
return String(self).reduce(0, { $0 + Int($1) })
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
Answer:
```swift
func orderByPoints(nums: [Int]) -> [Int] {
let sorted = nums.sorted { $0.digitsSum() < $1.digitsSum() }
let result = sorted.enumerated().map { nums[$0.offset] }
return result
}
extension Int {
func digitsSum() -> Int {
return String(self).reduce(0, { $0 + Int($1) })
}
}
```return String(self).reduce(0, { $0 + Int($1) }) // no exact matches in call to initializerfunc orderByPoints(nums: [Int]) -> [Int] {
let sorted = nums.sorted { $0.digitsSum() < $1.digitsSum() }
let result = sorted.enumerated().map { nums[$0.offset] }
return result
}
extension Int {
func digitsSum() -> Int {
return String(self).reduce(0, { $0 + Int($1) })
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
Answer:
```swift
func orderByPoints(nums: [Int]) -> [Int] {
let sorted = nums.sorted { $0.digitsSum() < $1.digitsSum() }
let result = sorted.enumerated().map { nums[$0.offset] }
return result
}
extension Int {
func digitsSum() -> Int {
return String(self).reduce(0, { $0 + Int($1) })
}
}
```return String(self).reduce(0, { $0 + Int($1) }) // no exact matches in call to initializerfunc orderByPoints(nums: [Int]) -> [Int] {
let sorted = nums.sorted { $0.digitsSum() < $1.digitsSum() }
let result = sorted.enumerated().map { $0.element }
return result
}
extension Int {
func digitsSum() -> Int {
return String(self).reduce(0, { $0 + Int($1) })
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
Answer:
```swift
func orderByPoints(nums: [Int]) -> [Int] {
let sorted = nums.sorted { $0.digitsSum() < $1.digitsSum() }
let result = sorted.enumerated().map { $0.element }
return result
}
extension Int {
func digitsSum() -> Int {
return String(self).reduce(0, { $0 + Int($1) })
}
}
```return String(self).reduce(0, { $0 + Int($1) }) // no exact matches in call to initializerfunc orderByPoints(nums: [Int]) -> [Int] {
let sorted = nums.sorted { $0.digitsSum() < $1.digitsSum() }
let result = sorted.enumerated().map { $0.element }
return result
}
extension Int {
func digitsSum() -> Int {
return self.description.reduce(0) { $0 + Int($1) }
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
Answer:
```swift
func orderByPoints(nums: [Int]) -> [Int] {
let sorted = nums.sorted { $0.digitsSum() < $1.digitsSum() }
let result = sorted.enumerated().map { $0.element }
return result
}
extension Int {
func digitsSum() -> Int {
return self.description.reduce(0) { $0 + Int($1) }
}
}
```return self.description.reduce(0) { $0 + Int($1) } // no exact matches in call to initializerfunc orderByPoints(nums: [Int]) -> [Int] {
let sorted = nums.sorted { $0.digitsSum() < $1.digitsSum() }
let result = sorted.enumerated().map { nums[$0.offset] }
return result
}
extension Int {
func digitsSum() -> Int {
return reduce(0, { $0 + String($1).digitsSum() })
}
}
extension String {
func digitsSum() -> Int {
return reduce(0, { $0 + Int($1.description)! })
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
Answer:
```swift
func orderByPoints(nums: [Int]) -> [Int] {
let sorted = nums.sorted { $0.digitsSum() < $1.digitsSum() }
let result = sorted.enumerated().map { nums[$0.offset] }
return result
}
extension Int {
func digitsSum() -> Int {
return reduce(0, { $0 + String($1).digitsSum() })
}
}
extension String {
func digitsSum() -> Int {
return reduce(0, { $0 + Int($1.description)! })
}
}
```return reduce(0, { $0 + String($1).digitsSum() }) // cannot find 'reduce' in scopefunc orderByPoints(nums: [Int]) -> [Int] {
let sorted = nums.sorted { $0.digitsSum() < $1.digitsSum() }
let result = sorted.enumerated().map { $0.element }
return result
}
extension Int {
func digitsSum() -> Int {
return String(self).reduce(0) { $0 + Int($1) }
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
Answer:
```swift
func orderByPoints(nums: [Int]) -> [Int] {
let sorted = nums.sorted { $0.digitsSum() < $1.digitsSum() }
let result = sorted.enumerated().map { $0.element }
return result
}
extension Int {
func digitsSum() -> Int {
return String(self).reduce(0) { $0 + Int($1) }
}
}
```return String(self).reduce(0) { $0 + Int($1) } // no exact matches in call to initializerfunc specialFilter(nums: [Int]) -> Int {
var count = 0
for num in nums {
if num > 10 && (num % 2 == 1) {
let firstDigit = num / 10
let lastDigit = num % 10
if firstDigit % 2 == 1 && lastDigit % 2 == 1 {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
Answer:
```swift
func specialFilter(nums: [Int]) -> Int {
var count = 0
for num in nums {
if num > 10 && (num % 2 == 1) {
let firstDigit = num / 10
let lastDigit = num % 10
if firstDigit % 2 == 1 && lastDigit % 2 == 1 {
count += 1
}
}
}
return count
}
``` // XCTAssertTrue failedfunc specialFilter(nums: [Int]) -> Int {
var count = 0
for num in nums {
if num > 10 && (num % 2!= 0) {
let firstDigit = num / 10
let lastDigit = num % 10
if firstDigit % 2!= 0 && lastDigit % 2!= 0 {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
Answer:
```swift
func specialFilter(nums: [Int]) -> Int {
var count = 0
for num in nums {
if num > 10 && (num % 2!= 0) {
let firstDigit = num / 10
let lastDigit = num % 10
if firstDigit % 2!= 0 && lastDigit % 2!= 0 {
count += 1
}
}
}
return count
}
```if num > 10 && (num % 2!= 0) { // use of '=' in a boolean context, did you mean '=='?if num > 10 && (num % 2!= 0) { // '=' must have consistent whitespace on both sidesif num > 10 && (num % 2!= 0) { // expression is not assignable: binary operator returns immutable valueif num > 10 && (num % 2!= 0) { // cannot force unwrap value of non-optional type 'Int'if firstDigit % 2!= 0 && lastDigit % 2!= 0 { // expression is not assignable: binary operator returns immutable valueif firstDigit % 2!= 0 && lastDigit % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if firstDigit % 2!= 0 && lastDigit % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'if firstDigit % 2!= 0 && lastDigit % 2!= 0 { // integer literal value '0' cannot be used as a boolean; did you mean 'false'?if firstDigit % 2!= 0 && lastDigit % 2!= 0 { // '=' must have consistent whitespace on both sidesif firstDigit % 2!= 0 && lastDigit % 2!= 0 { // expression is not assignable: '&&' returns immutable valueif firstDigit % 2!= 0 && lastDigit % 2!= 0 { // '=' must have consistent whitespace on both sidesif firstDigit % 2!= 0 && lastDigit % 2!= 0 { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadif firstDigit % 2!= 0 && lastDigit % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'func specialFilter(nums: [Int]) -> Int {
var count = 0
for num in nums {
if num > 10 && (num % 2!= 0) && (num % 10!= 0) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
Answer:
```swift
func specialFilter(nums: [Int]) -> Int {
var count = 0
for num in nums {
if num > 10 && (num % 2!= 0) && (num % 10!= 0) {
count += 1
}
}
return count
}
```if num > 10 && (num % 2!= 0) && (num % 10!= 0) { // expression is not assignable: binary operator returns immutable valueif num > 10 && (num % 2!= 0) && (num % 10!= 0) { // '=' must have consistent whitespace on both sidesif num > 10 && (num % 2!= 0) && (num % 10!= 0) { // expression is not assignable: binary operator returns immutable valueif num > 10 && (num % 2!= 0) && (num % 10!= 0) { // cannot force unwrap value of non-optional type 'Int'if num > 10 && (num % 2!= 0) && (num % 10!= 0) { // cannot force unwrap value of non-optional type 'Int'if num > 10 && (num % 2!= 0) && (num % 10!= 0) { // use of '=' in a boolean context, did you mean '=='?if num > 10 && (num % 2!= 0) && (num % 10!= 0) { // '=' must have consistent whitespace on both sidesif num > 10 && (num % 2!= 0) && (num % 10!= 0) { // use of '=' in a boolean context, did you mean '=='?func specialFilter(nums: [Int]) -> Int {
var count = 0
for num in nums {
if num > 10 && (num % 2 == 1 || (num % 10) % 2 == 1) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
Answer:
```swift
func specialFilter(nums: [Int]) -> Int {
var count = 0
for num in nums {
if num > 10 && (num % 2 == 1 || (num % 10) % 2 == 1) {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc specialFilter(nums: [Int]) -> Int {
var count = 0
for num in nums {
if num > 10 && (num % 2!= 0) {
let firstDigit = num / 10
let lastDigit = num % 10
if firstDigit % 2!= 0 && lastDigit % 2!= 0 {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
Answer:
```swift
func specialFilter(nums: [Int]) -> Int {
var count = 0
for num in nums {
if num > 10 && (num % 2!= 0) {
let firstDigit = num / 10
let lastDigit = num % 10
if firstDigit % 2!= 0 && lastDigit % 2!= 0 {
count += 1
}
}
}
return count
}
```if num > 10 && (num % 2!= 0) { // use of '=' in a boolean context, did you mean '=='?if num > 10 && (num % 2!= 0) { // '=' must have consistent whitespace on both sidesif num > 10 && (num % 2!= 0) { // expression is not assignable: binary operator returns immutable valueif num > 10 && (num % 2!= 0) { // cannot force unwrap value of non-optional type 'Int'if firstDigit % 2!= 0 && lastDigit % 2!= 0 { // expression is not assignable: binary operator returns immutable valueif firstDigit % 2!= 0 && lastDigit % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if firstDigit % 2!= 0 && lastDigit % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'if firstDigit % 2!= 0 && lastDigit % 2!= 0 { // integer literal value '0' cannot be used as a boolean; did you mean 'false'?if firstDigit % 2!= 0 && lastDigit % 2!= 0 { // '=' must have consistent whitespace on both sidesif firstDigit % 2!= 0 && lastDigit % 2!= 0 { // expression is not assignable: '&&' returns immutable valueif firstDigit % 2!= 0 && lastDigit % 2!= 0 { // '=' must have consistent whitespace on both sidesif firstDigit % 2!= 0 && lastDigit % 2!= 0 { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadif firstDigit % 2!= 0 && lastDigit % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'func specialFilter(nums: [Int]) -> Int {
var count = 0
for num in nums {
if num > 10 && (num % 2!= 0) {
let firstDigit = num % 10
let lastDigit = num / 10 % 10
if firstDigit % 2!= 0 && lastDigit % 2!= 0 {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
Answer:
```swift
func specialFilter(nums: [Int]) -> Int {
var count = 0
for num in nums {
if num > 10 && (num % 2!= 0) {
let firstDigit = num % 10
let lastDigit = num / 10 % 10
if firstDigit % 2!= 0 && lastDigit % 2!= 0 {
count += 1
}
}
}
return count
}
```if num > 10 && (num % 2!= 0) { // use of '=' in a boolean context, did you mean '=='?if num > 10 && (num % 2!= 0) { // '=' must have consistent whitespace on both sidesif num > 10 && (num % 2!= 0) { // expression is not assignable: binary operator returns immutable valueif num > 10 && (num % 2!= 0) { // cannot force unwrap value of non-optional type 'Int'if firstDigit % 2!= 0 && lastDigit % 2!= 0 { // expression is not assignable: binary operator returns immutable valueif firstDigit % 2!= 0 && lastDigit % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if firstDigit % 2!= 0 && lastDigit % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'if firstDigit % 2!= 0 && lastDigit % 2!= 0 { // integer literal value '0' cannot be used as a boolean; did you mean 'false'?if firstDigit % 2!= 0 && lastDigit % 2!= 0 { // '=' must have consistent whitespace on both sidesif firstDigit % 2!= 0 && lastDigit % 2!= 0 { // expression is not assignable: '&&' returns immutable valueif firstDigit % 2!= 0 && lastDigit % 2!= 0 { // '=' must have consistent whitespace on both sidesif firstDigit % 2!= 0 && lastDigit % 2!= 0 { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadif firstDigit % 2!= 0 && lastDigit % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'func specialFilter(nums: [Int]) -> Int {
var count = 0
for num in nums {
if num > 10 && (num % 2!= 0) {
let firstDigit = num / 10
let lastDigit = num % 10
if firstDigit % 2!= 0 && lastDigit % 2!= 0 {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
Answer:
```swift
func specialFilter(nums: [Int]) -> Int {
var count = 0
for num in nums {
if num > 10 && (num % 2!= 0) {
let firstDigit = num / 10
let lastDigit = num % 10
if firstDigit % 2!= 0 && lastDigit % 2!= 0 {
count += 1
}
}
}
return count
}
```if num > 10 && (num % 2!= 0) { // use of '=' in a boolean context, did you mean '=='?if num > 10 && (num % 2!= 0) { // '=' must have consistent whitespace on both sidesif num > 10 && (num % 2!= 0) { // expression is not assignable: binary operator returns immutable valueif num > 10 && (num % 2!= 0) { // cannot force unwrap value of non-optional type 'Int'if firstDigit % 2!= 0 && lastDigit % 2!= 0 { // expression is not assignable: binary operator returns immutable valueif firstDigit % 2!= 0 && lastDigit % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if firstDigit % 2!= 0 && lastDigit % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'if firstDigit % 2!= 0 && lastDigit % 2!= 0 { // integer literal value '0' cannot be used as a boolean; did you mean 'false'?if firstDigit % 2!= 0 && lastDigit % 2!= 0 { // '=' must have consistent whitespace on both sidesif firstDigit % 2!= 0 && lastDigit % 2!= 0 { // expression is not assignable: '&&' returns immutable valueif firstDigit % 2!= 0 && lastDigit % 2!= 0 { // '=' must have consistent whitespace on both sidesif firstDigit % 2!= 0 && lastDigit % 2!= 0 { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadif firstDigit % 2!= 0 && lastDigit % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'func specialFilter(nums: [Int]) -> Int {
var count = 0
for num in nums {
if num > 10 && (num % 2 == 1) && (num % 10 == 1 || num % 10 == 3 || num % 10 == 5 || num % 10 == 7 || num % 10 == 9) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
Answer:
```swift
func specialFilter(nums: [Int]) -> Int {
var count = 0
for num in nums {
if num > 10 && (num % 2 == 1) && (num % 10 == 1 || num % 10 == 3 || num % 10 == 5 || num % 10 == 7 || num % 10 == 9) {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc specialFilter(nums: [Int]) -> Int {
var count = 0
for num in nums {
if num > 10 && (num % 2 == 1 || num % 10 == 1 || num % 100 == 1) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
Answer:
```swift
func specialFilter(nums: [Int]) -> Int {
var count = 0
for num in nums {
if num > 10 && (num % 2 == 1 || num % 10 == 1 || num % 100 == 1) {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc specialFilter(nums: [Int]) -> Int {
var count = 0
for num in nums {
if num > 10 && (num % 2!= 0) {
let firstDigit = num / 10
let lastDigit = num % 10
if firstDigit % 2!= 0 && lastDigit % 2!= 0 {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
Answer:
```swift
func specialFilter(nums: [Int]) -> Int {
var count = 0
for num in nums {
if num > 10 && (num % 2!= 0) {
let firstDigit = num / 10
let lastDigit = num % 10
if firstDigit % 2!= 0 && lastDigit % 2!= 0 {
count += 1
}
}
}
return count
}
```if num > 10 && (num % 2!= 0) { // use of '=' in a boolean context, did you mean '=='?if num > 10 && (num % 2!= 0) { // '=' must have consistent whitespace on both sidesif num > 10 && (num % 2!= 0) { // expression is not assignable: binary operator returns immutable valueif num > 10 && (num % 2!= 0) { // cannot force unwrap value of non-optional type 'Int'if firstDigit % 2!= 0 && lastDigit % 2!= 0 { // expression is not assignable: binary operator returns immutable valueif firstDigit % 2!= 0 && lastDigit % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if firstDigit % 2!= 0 && lastDigit % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'if firstDigit % 2!= 0 && lastDigit % 2!= 0 { // integer literal value '0' cannot be used as a boolean; did you mean 'false'?if firstDigit % 2!= 0 && lastDigit % 2!= 0 { // '=' must have consistent whitespace on both sidesif firstDigit % 2!= 0 && lastDigit % 2!= 0 { // expression is not assignable: '&&' returns immutable valueif firstDigit % 2!= 0 && lastDigit % 2!= 0 { // '=' must have consistent whitespace on both sidesif firstDigit % 2!= 0 && lastDigit % 2!= 0 { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadif firstDigit % 2!= 0 && lastDigit % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'func getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 0..<n {
a[i] = i * i - i + 1
}
for i in 0..<n {
for j in (i + 1)..<n {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
Answer:
```swift
func getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 0..<n {
a[i] = i * i - i + 1
}
for i in 0..<n {
for j in (i + 1)..<n {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
``` // XCTAssertTrue failedfunc getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i-1] = i * i - i + 1
}
for i in 0..<n-2 {
for j in (i+1)..<n-1 {
for k in (j+1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
Answer:
```swift
func getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i-1] = i * i - i + 1
}
for i in 0..<n-2 {
for j in (i+1)..<n-1 {
for k in (j+1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
```func getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 0..<n {
a[i] = i * i - i + 1
}
for i in 0..<n {
for j in i+1..<n {
for k in j+1..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
Answer:
```swift
func getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 0..<n {
a[i] = i * i - i + 1
}
for i in 0..<n {
for j in i+1..<n {
for k in j+1..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
``` // XCTAssertTrue failedfunc getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 0..<n {
a[i] = i * i - i + 1
}
for i in 0..<n {
for j in (i + 1)..<n {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
Answer:
```swift
func getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 0..<n {
a[i] = i * i - i + 1
}
for i in 0..<n {
for j in (i + 1)..<n {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
``` // XCTAssertTrue failedfunc getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 0..<n {
a[i] = i * i - i + 1
}
for i in 0..<n {
for j in i+1..<n {
for k in j+1..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
Answer:
```swift
func getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 0..<n {
a[i] = i * i - i + 1
}
for i in 0..<n {
for j in i+1..<n {
for k in j+1..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
``` // XCTAssertTrue failedfunc getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i-1] = i * i - i + 1
}
for i in 0..<n {
for j in (i+1)..<n {
for k in (j+1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
Answer:
```swift
func getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i-1] = i * i - i + 1
}
for i in 0..<n {
for j in (i+1)..<n {
for k in (j+1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
```func getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i-1] = i * i - i + 1
}
for i in 0..<n {
for j in (i + 1)..<n {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
Answer:
```swift
func getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i-1] = i * i - i + 1
}
for i in 0..<n {
for j in (i + 1)..<n {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
```func getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 0..<n {
a[i] = i * i - i + 1
}
for i in 0..<n {
for j in (i + 1)..<n {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
Answer:
```swift
func getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 0..<n {
a[i] = i * i - i + 1
}
for i in 0..<n {
for j in (i + 1)..<n {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
``` // XCTAssertTrue failedfunc getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 0..<n {
a[i] = i * i - i + 1
}
for i in 0..<n {
for j in i+1..<n {
for k in j+1..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
Answer:
```swift
func getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 0..<n {
a[i] = i * i - i + 1
}
for i in 0..<n {
for j in i+1..<n {
for k in j+1..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
``` // XCTAssertTrue failedfunc getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i-1] = i * i - i + 1
}
for i in 0..<n {
for j in (i+1)..<n {
for k in (j+1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
Answer:
```swift
func getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i-1] = i * i - i + 1
}
for i in 0..<n {
for j in (i+1)..<n {
for k in (j+1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
```func sortedListSum(lst: [String]) -> [String] {
let sortedList = lst.sorted { $0.count < $1.count }
return sortedList
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
Answer:
```swift
func sortedListSum(lst: [String]) -> [String] {
let sortedList = lst.sorted { $0.count < $1.count }
return sortedList
}
``` // XCTAssertTrue failedfunc sortedListSum(lst: [String]) -> [String] {
let sortedList = lst.sorted { $0.count < $1.count }
return sortedList
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
Answer:
```swift
func sortedListSum(lst: [String]) -> [String] {
let sortedList = lst.sorted { $0.count < $1.count }
return sortedList
}
``` // XCTAssertTrue failedfunc sortedListSum(lst: [String]) -> [String] {
let sortedList = lst.sorted { $0.count < $1.count }
return sortedList
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
Answer:
```swift
func sortedListSum(lst: [String]) -> [String] {
let sortedList = lst.sorted { $0.count < $1.count }
return sortedList
}
``` // XCTAssertTrue failedfunc sortedListSum(lst: [String]) -> [String] {
let sortedList = lst.sorted { $0.count < $1.count }
return sortedList
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
Answer:
```swift
func sortedListSum(lst: [String]) -> [String] {
let sortedList = lst.sorted { $0.count < $1.count }
return sortedList
}
``` // XCTAssertTrue failedfunc sortedListSum(lst: [String]) -> [String] {
let sorted = lst.sorted { $0.count < $1.count }
return sorted
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
Answer:
```swift
func sortedListSum(lst: [String]) -> [String] {
let sorted = lst.sorted { $0.count < $1.count }
return sorted
}
``` // XCTAssertTrue failedfunc sortedListSum(lst: [String]) -> [String] {
let sortedList = lst.sorted { $0.count < $1.count }
return sortedList
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
Answer:
```swift
func sortedListSum(lst: [String]) -> [String] {
let sortedList = lst.sorted { $0.count < $1.count }
return sortedList
}
``` // XCTAssertTrue failedfunc sortedListSum(lst: [String]) -> [String] {
let sorted = lst.sorted { $0.count < $1.count }
return sorted
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
Answer:
```swift
func sortedListSum(lst: [String]) -> [String] {
let sorted = lst.sorted { $0.count < $1.count }
return sorted
}
``` // XCTAssertTrue failedfunc sortedListSum(lst: [String]) -> [String] {
let sortedList = lst.sorted { $0.count < $1.count }
return sortedList
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
Answer:
```swift
func sortedListSum(lst: [String]) -> [String] {
let sortedList = lst.sorted { $0.count < $1.count }
return sortedList
}
``` // XCTAssertTrue failedfunc sortedListSum(lst: [String]) -> [String] {
let sortedList = lst.sorted { $0.count < $1.count }
return sortedList
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
Answer:
```swift
func sortedListSum(lst: [String]) -> [String] {
let sortedList = lst.sorted { $0.count < $1.count }
return sortedList
}
``` // XCTAssertTrue failedfunc sortedListSum(lst: [String]) -> [String] {
let sortedList = lst.sorted { $0.count < $1.count }
return sortedList
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
Answer:
```swift
func sortedListSum(lst: [String]) -> [String] {
let sortedList = lst.sorted { $0.count < $1.count }
return sortedList
}
``` // XCTAssertTrue failedfunc xOrY(n: Int, x: Int, y: Int) -> Int {
if isPrime(n: n) {
return x
} else {
return y
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
Answer:
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
if isPrime(n: n) {
return x
} else {
return y
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
```func xOrY(n: Int, x: Int, y: Int) -> Int {
if isPrime(n: n) {
return x
} else {
return y
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
Answer:
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
if isPrime(n: n) {
return x
} else {
return y
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
```func xOrY(n: Int, x: Int, y: Int) -> Int {
if isPrime(n: n) {
return x
} else {
return y
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
Answer:
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
if isPrime(n: n) {
return x
} else {
return y
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
```func xOrY(n: Int, x: Int, y: Int) -> Int {
if isPrime(n: n) {
return x
} else {
return y
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
Answer:
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
if isPrime(n: n) {
return x
} else {
return y
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
```func xOrY(n: Int, x: Int, y: Int) -> Int {
if isPrime(n: n) {
return x
} else {
return y
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
Answer:
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
if isPrime(n: n) {
return x
} else {
return y
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
```func xOrY(n: Int, x: Int, y: Int) -> Int {
if isPrime(n: n) {
return x
} else {
return y
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
Answer:
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
if isPrime(n: n) {
return x
} else {
return y
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
```func xOrY(n: Int, x: Int, y: Int) -> Int {
if isPrime(n: n) {
return x
} else {
return y
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
Answer:
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
if isPrime(n: n) {
return x
} else {
return y
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
```func xOrY(n: Int, x: Int, y: Int) -> Int {
if isPrime(n: n) {
return x
} else {
return y
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
Answer:
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
if isPrime(n: n) {
return x
} else {
return y
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
```func xOrY(n: Int, x: Int, y: Int) -> Int {
if isPrime(n: n) {
return x
} else {
return y
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
Answer:
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
if isPrime(n: n) {
return x
} else {
return y
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
```func xOrY(n: Int, x: Int, y: Int) -> Int {
if isPrime(n: n) {
return x
} else {
return y
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
Answer:
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
if isPrime(n: n) {
return x
} else {
return y
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
```func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if let intNum = num as? Int, intNum % 2 == 1, intNum > 0 {
sum += intNum * intNum
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
Answer:
```swift
func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if let intNum = num as? Int, intNum % 2 == 1, intNum > 0 {
sum += intNum * intNum
}
}
return sum
}
```if let intNum = num as? Int, intNum % 2 == 1, intNum > 0 { // cast from 'Double' to unrelated type 'Int' always fails // XCTAssertTrue failedfunc doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if let num = num as? Double, num.isOdd, num > 0 {
sum += num * num
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
Answer:
```swift
func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if let num = num as? Double, num.isOdd, num > 0 {
sum += num * num
}
}
return sum
}
```if let num = num as? Double, num.isOdd, num > 0 { // value of type 'Double' has no member 'isOdd'if let num = num as? Double, num.isOdd, num > 0 { // conditional cast from 'Double' to 'Double' always succeedssum += num * num // cannot convert value of type 'Double' to expected argument type 'Int'func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if let intNum = num as? Int, intNum % 2!= 0, intNum > 0 {
sum += intNum * intNum
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
Answer:
```swift
func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if let intNum = num as? Int, intNum % 2!= 0, intNum > 0 {
sum += intNum * intNum
}
}
return sum
}
```if let intNum = num as? Int, intNum % 2!= 0, intNum > 0 { // expression is not assignable: binary operator returns immutable valueif let intNum = num as? Int, intNum % 2!= 0, intNum > 0 { // cannot force unwrap value of non-optional type 'Int'if let intNum = num as? Int, intNum % 2!= 0, intNum > 0 { // use of '=' in a boolean context, did you mean '=='?if let intNum = num as? Int, intNum % 2!= 0, intNum > 0 { // cast from 'Double' to unrelated type 'Int' always failsif let intNum = num as? Int, intNum % 2!= 0, intNum > 0 { // '=' must have consistent whitespace on both sidesfunc doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if num > 0 && num.isInteger {
sum += num * num
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
Answer:
```swift
func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if num > 0 && num.isInteger {
sum += num * num
}
}
return sum
}
```if num > 0 && num.isInteger { // value of type 'Double' has no member 'isInteger'sum += num * num // cannot convert value of type 'Double' to expected argument type 'Int'func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if let num = num as? Double, num.isOdd, num > 0 {
sum += num * num
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
Answer:
```swift
func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if let num = num as? Double, num.isOdd, num > 0 {
sum += num * num
}
}
return sum
}
```if let num = num as? Double, num.isOdd, num > 0 { // value of type 'Double' has no member 'isOdd'if let num = num as? Double, num.isOdd, num > 0 { // conditional cast from 'Double' to 'Double' always succeedssum += num * num // cannot convert value of type 'Double' to expected argument type 'Int'func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if let num = num as? Double, num.isOdd, num > 0 {
sum += num * num
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
Answer:
```swift
func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if let num = num as? Double, num.isOdd, num > 0 {
sum += num * num
}
}
return sum
}
```if let num = num as? Double, num.isOdd, num > 0 { // value of type 'Double' has no member 'isOdd'if let num = num as? Double, num.isOdd, num > 0 { // conditional cast from 'Double' to 'Double' always succeedssum += num * num // cannot convert value of type 'Double' to expected argument type 'Int'func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if let num = num as? Double, num.isOdd, num >= 0 {
sum += num * num
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
Answer:
```swift
func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if let num = num as? Double, num.isOdd, num >= 0 {
sum += num * num
}
}
return sum
}
```if let num = num as? Double, num.isOdd, num >= 0 { // value of type 'Double' has no member 'isOdd'if let num = num as? Double, num.isOdd, num >= 0 { // conditional cast from 'Double' to 'Double' always succeedssum += num * num // cannot convert value of type 'Double' to expected argument type 'Int'func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if let num = num as? Double, num > 0, num.isOdd {
sum += num * num
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
Answer:
```swift
func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if let num = num as? Double, num > 0, num.isOdd {
sum += num * num
}
}
return sum
}
```if let num = num as? Double, num > 0, num.isOdd { // value of type 'Double' has no member 'isOdd'if let num = num as? Double, num > 0, num.isOdd { // conditional cast from 'Double' to 'Double' always succeedssum += num * num // cannot convert value of type 'Double' to expected argument type 'Int'func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if let num = num as? Double, num.isOdd, num >= 0 {
sum += num * num
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
Answer:
```swift
func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if let num = num as? Double, num.isOdd, num >= 0 {
sum += num * num
}
}
return sum
}
```if let num = num as? Double, num.isOdd, num >= 0 { // value of type 'Double' has no member 'isOdd'if let num = num as? Double, num.isOdd, num >= 0 { // conditional cast from 'Double' to 'Double' always succeedssum += num * num // cannot convert value of type 'Double' to expected argument type 'Int'func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if let num = num as? Double, num.isOdd, num > 0 {
sum += num * num
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
Answer:
```swift
func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if let num = num as? Double, num.isOdd, num > 0 {
sum += num * num
}
}
return sum
}
```if let num = num as? Double, num.isOdd, num > 0 { // value of type 'Double' has no member 'isOdd'if let num = num as? Double, num.isOdd, num > 0 { // conditional cast from 'Double' to 'Double' always succeedssum += num * num // cannot convert value of type 'Double' to expected argument type 'Int'func compare(game: [Int], guess: [Int]) -> [Int] {
var result = [Int]()
for i in 0..<game.count {
let diff = abs(game[i] - guess[i])
result.append(diff)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
Answer:
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
var result = [Int]()
for i in 0..<game.count {
let diff = abs(game[i] - guess[i])
result.append(diff)
}
return result
}
```func compare(game: [Int], guess: [Int]) -> [Int] {
var result = [Int]()
for i in 0..<game.count {
result.append(abs(game[i] - guess[i]))
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
Answer:
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
var result = [Int]()
for i in 0..<game.count {
result.append(abs(game[i] - guess[i]))
}
return result
}
```func compare(game: [Int], guess: [Int]) -> [Int] {
var result = [Int]()
for i in 0..<game.count {
let diff = abs(game[i] - guess[i])
result.append(diff)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
Answer:
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
var result = [Int]()
for i in 0..<game.count {
let diff = abs(game[i] - guess[i])
result.append(diff)
}
return result
}
```func compare(game: [Int], guess: [Int]) -> [Int] {
var result = [Int]()
for i in 0..<game.count {
let diff = abs(game[i] - guess[i])
result.append(diff)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
Answer:
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
var result = [Int]()
for i in 0..<game.count {
let diff = abs(game[i] - guess[i])
result.append(diff)
}
return result
}
```func compare(game: [Int], guess: [Int]) -> [Int] {
var result = [Int]()
for (index, score) in game.enumerated() {
let difference = abs(score - guess[index])
result.append(difference)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
Answer:
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
var result = [Int]()
for (index, score) in game.enumerated() {
let difference = abs(score - guess[index])
result.append(difference)
}
return result
}
```func compare(game: [Int], guess: [Int]) -> [Int] {
var result = [Int]()
for i in 0..<game.count {
result.append(abs(game[i] - guess[i]))
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
Answer:
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
var result = [Int]()
for i in 0..<game.count {
result.append(abs(game[i] - guess[i]))
}
return result
}
```func compare(game: [Int], guess: [Int]) -> [Int] {
var result: [Int] = []
for i in 0..<game.count {
let diff = abs(game[i] - guess[i])
result.append(diff)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
Answer:
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
var result: [Int] = []
for i in 0..<game.count {
let diff = abs(game[i] - guess[i])
result.append(diff)
}
return result
}
```func compare(game: [Int], guess: [Int]) -> [Int] {
var result = [Int]()
for i in 0..<game.count {
let diff = abs(game[i] - guess[i])
result.append(diff)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
Answer:
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
var result = [Int]()
for i in 0..<game.count {
let diff = abs(game[i] - guess[i])
result.append(diff)
}
return result
}
```func compare(game: [Int], guess: [Int]) -> [Int] {
var result = [Int]()
for i in 0..<game.count {
let diff = abs(game[i] - guess[i])
result.append(diff)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
Answer:
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
var result = [Int]()
for i in 0..<game.count {
let diff = abs(game[i] - guess[i])
result.append(diff)
}
return result
}
```func compare(game: [Int], guess: [Int]) -> [Int] {
var result = [Int]()
for i in 0..<game.count {
let diff = abs(game[i] - guess[i])
result.append(diff)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
Answer:
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
var result = [Int]()
for i in 0..<game.count {
let diff = abs(game[i] - guess[i])
result.append(diff)
}
return result
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension: String = ""
var maxStrength: Double = 0
for extension in extensions {
let extensionName = extension.replacingOccurrences(of: " ", with: "_")
let extensionStrength = Double(extensionName.count - extensionName.countOf(where: { $0.isUppercase }))
if extensionStrength > maxStrength {
maxStrength = extensionStrength
strongestExtension = extension
}
}
return "\(className.replacingOccurrences(of: " ", with: "_")).\(strongestExtension)"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension: String = ""
var maxStrength: Double = 0
for extension in extensions {
let extensionName = extension.replacingOccurrences(of: " ", with: "_")
let extensionStrength = Double(extensionName.count - extensionName.countOf(where: { $0.isUppercase }))
if extensionStrength > maxStrength {
maxStrength = extensionStrength
strongestExtension = extension
}
}
return "\(className.replacingOccurrences(of: " ", with: "_")).\(strongestExtension)"
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scope(its strength is -1). // expected '{' in extension(its strength is -1). // expected ',' separator(its strength is -1). // expected type(its strength is -1). // expected type(its strength is -1). // expected member name following '.'(its strength is -1). // expected ':' following argument label and parameter namefor extension in extensions { // expected '{' to start the body of for-each loopfor extension in extensions { // expected patternfor extension in extensions { // expected Sequence expression for for-each looplet extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected type name in extension declarationlet extensionName = extension.replacingOccurrences(of: " ", with: "_") // declaration is only valid at file scopelet extensionName = extension.replacingOccurrences(of: " ", with: "_") // consecutive statements on a line must be separated by ';'let extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected '{' in extensionlet extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected initial value after '='strongestExtension = extension // expected expression in assignmentstrongestExtension = extension // expected '{' in extensionstrongestExtension = extension // declaration is only valid at file scope} // expected type name in extension declarationextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var strongestStrength = 0
for extension in extensions {
let extensionName = extension.replacingOccurrences(of: " ", with: "_")
let extensionStrength = extensionName.count - extensionName.lowercased().count
if extensionStrength > strongestStrength {
strongestExtension = extension
strongestStrength = extensionStrength
}
}
return className + "." + strongestExtension
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var strongestStrength = 0
for extension in extensions {
let extensionName = extension.replacingOccurrences(of: " ", with: "_")
let extensionStrength = extensionName.count - extensionName.lowercased().count
if extensionStrength > strongestStrength {
strongestExtension = extension
strongestStrength = extensionStrength
}
}
return className + "." + strongestExtension
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scope(its strength is -1). // expected '{' in extension(its strength is -1). // expected ',' separator(its strength is -1). // expected type(its strength is -1). // expected type(its strength is -1). // expected member name following '.'(its strength is -1). // expected ':' following argument label and parameter namefor extension in extensions { // expected '{' to start the body of for-each loopfor extension in extensions { // expected patternfor extension in extensions { // expected Sequence expression for for-each looplet extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected type name in extension declarationlet extensionName = extension.replacingOccurrences(of: " ", with: "_") // declaration is only valid at file scopelet extensionName = extension.replacingOccurrences(of: " ", with: "_") // consecutive statements on a line must be separated by ';'let extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected '{' in extensionlet extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected initial value after '='strongestExtension = extension // expected expression in assignmentstrongestExtension = extension // declaration is only valid at file scopestrongestStrength = extensionStrength // cannot find type 'strongestStrength' in scopestrongestStrength = extensionStrength // expected '{' in extensionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var maxStrength = 0
for extension in extensions {
let extensionName = extension.replacingOccurrences(of: " ", with: "_")
let extensionStrength = extensionName.uppercased().count - extensionName.lowercased().count
if extensionStrength > maxStrength {
strongestExtension = extension
maxStrength = extensionStrength
}
}
return "\(className).\(strongestExtension)"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var maxStrength = 0
for extension in extensions {
let extensionName = extension.replacingOccurrences(of: " ", with: "_")
let extensionStrength = extensionName.uppercased().count - extensionName.lowercased().count
if extensionStrength > maxStrength {
strongestExtension = extension
maxStrength = extensionStrength
}
}
return "\(className).\(strongestExtension)"
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scope(its strength is -1). // expected '{' in extension(its strength is -1). // expected ',' separator(its strength is -1). // expected type(its strength is -1). // expected type(its strength is -1). // expected member name following '.'(its strength is -1). // expected ':' following argument label and parameter namefor extension in extensions { // expected '{' to start the body of for-each loopfor extension in extensions { // expected patternfor extension in extensions { // expected Sequence expression for for-each looplet extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected type name in extension declarationlet extensionName = extension.replacingOccurrences(of: " ", with: "_") // declaration is only valid at file scopelet extensionName = extension.replacingOccurrences(of: " ", with: "_") // consecutive statements on a line must be separated by ';'let extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected '{' in extensionlet extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected initial value after '='strongestExtension = extension // declaration is only valid at file scopestrongestExtension = extension // expected expression in assignmentmaxStrength = extensionStrength // expected '{' in extensionmaxStrength = extensionStrength // cannot find type 'maxStrength' in scopeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var strongestStrength = 0
for extension in extensions {
let extensionName = extension.replacingOccurrences(of: " ", with: "_")
let extensionStrength = extensionName.count - extensionName.lowercased().count
if extensionStrength > strongestStrength {
strongestExtension = extension
strongestStrength = extensionStrength
}
}
return "\(className)_\(strongestExtension)"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var strongestStrength = 0
for extension in extensions {
let extensionName = extension.replacingOccurrences(of: " ", with: "_")
let extensionStrength = extensionName.count - extensionName.lowercased().count
if extensionStrength > strongestStrength {
strongestExtension = extension
strongestStrength = extensionStrength
}
}
return "\(className)_\(strongestExtension)"
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scope(its strength is -1). // expected '{' in extension(its strength is -1). // expected ',' separator(its strength is -1). // expected type(its strength is -1). // expected type(its strength is -1). // expected member name following '.'(its strength is -1). // expected ':' following argument label and parameter namefor extension in extensions { // expected Sequence expression for for-each loopfor extension in extensions { // expected patternfor extension in extensions { // expected '{' to start the body of for-each looplet extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected initial value after '='let extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected type name in extension declarationlet extensionName = extension.replacingOccurrences(of: " ", with: "_") // consecutive statements on a line must be separated by ';'let extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected '{' in extensionlet extensionName = extension.replacingOccurrences(of: " ", with: "_") // declaration is only valid at file scopestrongestExtension = extension // expected expression in assignmentstrongestExtension = extension // declaration is only valid at file scopestrongestStrength = extensionStrength // cannot find type 'strongestStrength' in scopestrongestStrength = extensionStrength // expected '{' in extensionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var maxStrength = 0
for extension in extensions {
let extensionName = extension.replacingOccurrences(of: " ", with: "_")
let extensionStrength = extensionName.count - extensionName.lowercased().count
if extensionStrength > maxStrength {
strongestExtension = extension
maxStrength = extensionStrength
}
}
return "\(className).\(strongestExtension)"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var maxStrength = 0
for extension in extensions {
let extensionName = extension.replacingOccurrences(of: " ", with: "_")
let extensionStrength = extensionName.count - extensionName.lowercased().count
if extensionStrength > maxStrength {
strongestExtension = extension
maxStrength = extensionStrength
}
}
return "\(className).\(strongestExtension)"
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scope(its strength is -1). // expected '{' in extension(its strength is -1). // expected ',' separator(its strength is -1). // expected type(its strength is -1). // expected type(its strength is -1). // expected member name following '.'(its strength is -1). // expected ':' following argument label and parameter namefor extension in extensions { // expected '{' to start the body of for-each loopfor extension in extensions { // expected patternfor extension in extensions { // expected Sequence expression for for-each looplet extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected type name in extension declarationlet extensionName = extension.replacingOccurrences(of: " ", with: "_") // declaration is only valid at file scopelet extensionName = extension.replacingOccurrences(of: " ", with: "_") // consecutive statements on a line must be separated by ';'let extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected '{' in extensionlet extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected initial value after '='strongestExtension = extension // declaration is only valid at file scopestrongestExtension = extension // expected expression in assignmentmaxStrength = extensionStrength // expected '{' in extensionmaxStrength = extensionStrength // cannot find type 'maxStrength' in scopeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var maxStrength = 0
for extension in extensions {
let extensionName = extension.replacingOccurrences(of: " ", with: "_")
let extensionStrength = extensionName.count - extensionName.lowercased().count
if extensionStrength > maxStrength {
maxStrength = extensionStrength
strongestExtension = extension
}
}
return "\(className).\(strongestExtension)"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var maxStrength = 0
for extension in extensions {
let extensionName = extension.replacingOccurrences(of: " ", with: "_")
let extensionStrength = extensionName.count - extensionName.lowercased().count
if extensionStrength > maxStrength {
maxStrength = extensionStrength
strongestExtension = extension
}
}
return "\(className).\(strongestExtension)"
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scope(its strength is -1). // expected '{' in extension(its strength is -1). // expected ',' separator(its strength is -1). // expected type(its strength is -1). // expected type(its strength is -1). // expected member name following '.'(its strength is -1). // expected ':' following argument label and parameter namefor extension in extensions { // expected '{' to start the body of for-each loopfor extension in extensions { // expected patternfor extension in extensions { // expected Sequence expression for for-each looplet extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected type name in extension declarationlet extensionName = extension.replacingOccurrences(of: " ", with: "_") // declaration is only valid at file scopelet extensionName = extension.replacingOccurrences(of: " ", with: "_") // consecutive statements on a line must be separated by ';'let extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected '{' in extensionlet extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected initial value after '='strongestExtension = extension // expected '{' in extensionstrongestExtension = extension // expected expression in assignmentstrongestExtension = extension // declaration is only valid at file scope} // expected type name in extension declarationextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var maxStrength = 0
for extension in extensions {
let extensionName = extension.replacingOccurrences(of: " ", with: "_")
let extensionStrength = extensionName.count - extensionName.lowercased().count
if extensionStrength > maxStrength {
maxStrength = extensionStrength
strongestExtension = extension
}
}
return "\(className)_\(strongestExtension)"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var maxStrength = 0
for extension in extensions {
let extensionName = extension.replacingOccurrences(of: " ", with: "_")
let extensionStrength = extensionName.count - extensionName.lowercased().count
if extensionStrength > maxStrength {
maxStrength = extensionStrength
strongestExtension = extension
}
}
return "\(className)_\(strongestExtension)"
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scope(its strength is -1). // expected '{' in extension(its strength is -1). // expected ',' separator(its strength is -1). // expected type(its strength is -1). // expected type(its strength is -1). // expected member name following '.'(its strength is -1). // expected ':' following argument label and parameter namefor extension in extensions { // expected Sequence expression for for-each loopfor extension in extensions { // expected patternfor extension in extensions { // expected '{' to start the body of for-each looplet extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected initial value after '='let extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected type name in extension declarationlet extensionName = extension.replacingOccurrences(of: " ", with: "_") // consecutive statements on a line must be separated by ';'let extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected '{' in extensionlet extensionName = extension.replacingOccurrences(of: " ", with: "_") // declaration is only valid at file scopestrongestExtension = extension // expected '{' in extensionstrongestExtension = extension // declaration is only valid at file scopestrongestExtension = extension // expected expression in assignment} // expected type name in extension declarationextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var strongestStrength = 0
for extension in extensions {
let extensionName = extension.replacingOccurrences(of: " ", with: "_")
let extensionStrength = extensionName.count - extensionName.lowercased().count
if extensionStrength > strongestStrength {
strongestExtension = extension
strongestStrength = extensionStrength
}
}
return className + "." + strongestExtension
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var strongestStrength = 0
for extension in extensions {
let extensionName = extension.replacingOccurrences(of: " ", with: "_")
let extensionStrength = extensionName.count - extensionName.lowercased().count
if extensionStrength > strongestStrength {
strongestExtension = extension
strongestStrength = extensionStrength
}
}
return className + "." + strongestExtension
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scope(its strength is -1). // expected '{' in extension(its strength is -1). // expected ',' separator(its strength is -1). // expected type(its strength is -1). // expected type(its strength is -1). // expected member name following '.'(its strength is -1). // expected ':' following argument label and parameter namefor extension in extensions { // expected '{' to start the body of for-each loopfor extension in extensions { // expected patternfor extension in extensions { // expected Sequence expression for for-each looplet extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected type name in extension declarationlet extensionName = extension.replacingOccurrences(of: " ", with: "_") // declaration is only valid at file scopelet extensionName = extension.replacingOccurrences(of: " ", with: "_") // consecutive statements on a line must be separated by ';'let extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected '{' in extensionlet extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected initial value after '='strongestExtension = extension // expected expression in assignmentstrongestExtension = extension // declaration is only valid at file scopestrongestStrength = extensionStrength // cannot find type 'strongestStrength' in scopestrongestStrength = extensionStrength // expected '{' in extensionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var strongestStrength = 0
for extension in extensions {
let extensionName = extension.replacingOccurrences(of: " ", with: "_")
let extensionStrength = extensionName.count - extensionName.lowercased().count
if extensionStrength > strongestStrength {
strongestExtension = extension
strongestStrength = extensionStrength
}
}
return "\(className)_\(strongestExtension)"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var strongestStrength = 0
for extension in extensions {
let extensionName = extension.replacingOccurrences(of: " ", with: "_")
let extensionStrength = extensionName.count - extensionName.lowercased().count
if extensionStrength > strongestStrength {
strongestExtension = extension
strongestStrength = extensionStrength
}
}
return "\(className)_\(strongestExtension)"
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scope(its strength is -1). // expected '{' in extension(its strength is -1). // expected ',' separator(its strength is -1). // expected type(its strength is -1). // expected type(its strength is -1). // expected member name following '.'(its strength is -1). // expected ':' following argument label and parameter namefor extension in extensions { // expected '{' to start the body of for-each loopfor extension in extensions { // expected patternfor extension in extensions { // expected Sequence expression for for-each looplet extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected type name in extension declarationlet extensionName = extension.replacingOccurrences(of: " ", with: "_") // declaration is only valid at file scopelet extensionName = extension.replacingOccurrences(of: " ", with: "_") // consecutive statements on a line must be separated by ';'let extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected '{' in extensionlet extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected initial value after '='strongestExtension = extension // declaration is only valid at file scopestrongestExtension = extension // expected expression in assignmentstrongestStrength = extensionStrength // cannot find type 'strongestStrength' in scopestrongestStrength = extensionStrength // expected '{' in extensionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var strongestStrength = 0
for extension in extensions {
let extensionName = extension.replacingOccurrences(of: " ", with: "_")
let extensionStrength = extensionName.count - extensionName.lowercased().count
if extensionStrength > strongestStrength {
strongestExtension = extension
strongestStrength = extensionStrength
}
}
return "\(className)_\(strongestExtension)"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var strongestStrength = 0
for extension in extensions {
let extensionName = extension.replacingOccurrences(of: " ", with: "_")
let extensionStrength = extensionName.count - extensionName.lowercased().count
if extensionStrength > strongestStrength {
strongestExtension = extension
strongestStrength = extensionStrength
}
}
return "\(className)_\(strongestExtension)"
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scope(its strength is -1). // expected '{' in extension(its strength is -1). // expected ',' separator(its strength is -1). // expected type(its strength is -1). // expected type(its strength is -1). // expected member name following '.'(its strength is -1). // expected ':' following argument label and parameter namefor extension in extensions { // expected '{' to start the body of for-each loopfor extension in extensions { // expected patternfor extension in extensions { // expected Sequence expression for for-each looplet extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected type name in extension declarationlet extensionName = extension.replacingOccurrences(of: " ", with: "_") // declaration is only valid at file scopelet extensionName = extension.replacingOccurrences(of: " ", with: "_") // consecutive statements on a line must be separated by ';'let extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected '{' in extensionlet extensionName = extension.replacingOccurrences(of: " ", with: "_") // expected initial value after '='strongestExtension = extension // declaration is only valid at file scopestrongestExtension = extension // expected expression in assignmentstrongestStrength = extensionStrength // cannot find type 'strongestStrength' in scopestrongestStrength = extensionStrength // expected '{' in extensionfunc cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a.characters)
let bChars = Array(b.characters)
let bCharsRotated = bChars.rotated()
return aChars.contains(bChars) || aChars.contains(bCharsRotated)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
Answer:
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a.characters)
let bChars = Array(b.characters)
let bCharsRotated = bChars.rotated()
return aChars.contains(bChars) || aChars.contains(bCharsRotated)
}
```let aChars = Array(a.characters) // 'characters' is unavailable: Please use String directlylet bChars = Array(b.characters) // 'characters' is unavailable: Please use String directlylet bCharsRotated = bChars.rotated() // value of type '[String.Element]' (aka 'Array<Character>') has no member 'rotated'func cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a)
let bChars = Array(b)
let aCharsCount = aChars.count
let bCharsCount = bChars.count
if aCharsCount < bCharsCount {
return false
}
for i in 0..<aCharsCount {
let aCharsSubarray = aChars[i..<i+bCharsCount]
let bCharsSubarray = bChars.reversed()
if aCharsSubarray == bCharsSubarray {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
Answer:
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a)
let bChars = Array(b)
let aCharsCount = aChars.count
let bCharsCount = bChars.count
if aCharsCount < bCharsCount {
return false
}
for i in 0..<aCharsCount {
let aCharsSubarray = aChars[i..<i+bCharsCount]
let bCharsSubarray = bChars.reversed()
if aCharsSubarray == bCharsSubarray {
return true
}
}
return false
}
```if aCharsSubarray == bCharsSubarray { // cannot convert value of type 'ReversedCollection<[String.Element]>' (aka 'ReversedCollection<Array<Character>>') to expected argument type 'ArraySlice<String.Element>' (aka 'ArraySlice<Character>')Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
Answer:
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
let aChars = a.characters.map { String($0) }
let bChars = b.characters.map { String($0) }
let aCharsCount = aChars.count
let bCharsCount = bChars.count
let aCharsCycle = aChars.cycle
let bCharsCycle = bChars.cycle
let aCharsCycleCount = aCharsCycle.count
let bCharsCycleCount = bCharsCycle.count
let aCharsCycleIndex = aCharsCycle.firstIndex(of: bCharsCycle.first)!
let bCharsCycleIndex = bCharsCycle.firstIndex(of: aCharsCycle.first)!
let aCharsCycleIndexCount = aCharsCycle.count
let bCharsCycleIndexCount = bCharsCycle.count
let aCharsCycleIndexOffset = aCharsCycleIndexCount - bCharsCycleIndexCount
let aCharsCycleIndexOffsetCycle = aCharsCycleIndexOffset % aCharsCycleIndexCount
let aCharsCycleIndexOffsetCycleIndex = aCharsCycleIndexOffsetCycle % aCharsCycleIndexCount
let aCharsCycleIndexOffsetCycleIndexCount = aCharsCycleIndexOffsetCycleIndex % aCharsCycleIndexCount
let aCharsCycleIndexOffsetCycleIndexCountCycle = aCharsCycleIndexOffsetCycleIndexCount % aCharsCycleIndexCount
let aCharsCycleIndexOffsetCycleIndexCountCycleIndex = aCharsCycleIndexOffsetCycleIndexCountCycle % aCharsCycleIndexCount
let aCharsCycleIndexOffsetCycleIndexCountCycleIndexCount = aCharsCycleIndexOffsetCycleIndexCountCycleIndex % aCharsCycleIndexCount
let aCharsCycleIndexOffsetCycleIndexCountCycleIndexCountCycle = aCharsCycleIndexOffsetCycleIndexCountCycleIndexCount % aCharsCycleIndexCount
let aCharsCycleIndexOffsetCycleIndexCountCycleIndexCountCycleIndex = aCharsCycleIndexOffsetCycleIndexCountCycleIndexCountCycle % aCharsCycleIndexCount
let aCharsCycleIndexOffsetCycleIndexCountCycleIndexCountCycleIndex = aCharsCycleIndexOffsetCycleIndexCountCycleIndexCountCycleIndex % aCharsCycleIndexCount
let aCharsCycleIndexOffsetCycleIndexCountCycleIndexCountCycleIndexCount = aCharsCycleIndexOffsetCycleIndexCountCycleIndexCountCycleIndexCountCycle % aCharsCycleIndexCount
let aCharsCycleIndexOffsetCycleIndexCountCycleIndexCountCycleIndexCount = aCharsCycleIndexOffsetCycleIndexCountCycleIndexCountCycleIndexCountCycle % aCharsCycleIndexCount
let aCharsCycleIndexOffsetCycleIndexCountCycleIndexCountCycleIndexCountCount = aCharsCycleIndexOffsetCycleIndexCountCycleIndexCountCycleIndexCountCycleIndexCount % aCharsCycleIndexCount
let aCharsCycleIndexOffsetCycleIndexCountCycleIndexCountCycleIndexCountCountCount = aCharsCycleIndexOffsetCycleIndexCountCycleIndexCountCycleIndexCountCycleIndexCountCount % aCharsCycleIndexCount
let aCharsCycleIndexOffsetCycleIndexCountCycleIndexCountCycleIndexCountCountCount = aCharsCycleIndexOffsetCycleIndexCountCycleIndexCountCycleIndexCountCycleIndexCountCountCount % aCharsCycleIndexCount
let aCharsCycleIndexOffsetCycleIndexCountCycleIndexCountCycleIndexCountCountCountCount = aCharsCycleIndexOffsetCycleIndexCountCycleIndexCountCycleIndexCountCycleIndexCountCountCountCount % aCharsCycleIndexCount
let aCharsCycleIndexOffsetCycleIndexCountCycleIndexCountCycleIndexCountCountCountCountCount = aCharsCycleIndexOffsetCycleIndexCountCycleIndexCountCycleIndexCountCycleIndexCountCountCountCountCount % aCharsCycleIndexCount
let aCharsCycleIndexOffsetCycleIndexCountCycleIndexCountCycleIndexCountCountCountCountCountCount = aCharsCycleIndexOffsetCycleIndexCountCycleIndexCountCycleIndexCountCycleIndexCountCountCountCountCountCount % aCharsCycleIndexCount
let aCharsCycleIndexOffsetCycleIndexCountCycleIndexCountCycleIndexCountCountCountCountCountCountCountCount = aCharsCycleIndexOffsetCycleIndexCountCycleIndexCountCycleIndexCountCycleIndexCountCountCountCountCountCountCountCount % aCharsCycleIndexCount
let aCharsCycleIndexOffsetCycleIndexCountCycleIndexCountCycleIndexCountCountCountCountCountCountCountCountCount = aCharsCycleIndexOffsetCycleIndexCountCycleIndexCountCycleIndexCountCycleIndexCountCountCountCountCountCountCountCountCount % aCharsCycleIndexCount
let aCharsCycleIndexOffsetCycleIndexCountCycleIndexCountCycleIndexCountCountCountCountCountCountCountCountCountCount = aCharsCycleIndexOffsetCycleIndexCountCycleIndexCountCycleIndexCountCycleIndexCountCountCountCountCountCountCountCountCountCount % aCharsCycleIndexCount
let aCharsCycleIndexOffsetCycleIndexCountCycleIndexCountCycleIndexCountCountCountCountCountCountCountCountCountCountCount = aCharsCycleIndexOffsetCycleIndexCountCycleIndexCountCycleIndexCountCycleIndexCountCountCountCountCountCountCountCountCountCountCount % aCharsCycleIndexCount
let aCharsCycleIndexOffsetCycleIndexCountCycleIndexXCTAssertTrue(cycpatternCheck(a: "xyzw", b: "xyw") == false) // cannot find 'cycpatternCheck' in scopeXCTAssertTrue(cycpatternCheck(a: "yello", b: "ell") == true) // cannot find 'cycpatternCheck' in scopeXCTAssertTrue(cycpatternCheck(a: "whattup", b: "ptut") == false) // cannot find 'cycpatternCheck' in scopeXCTAssertTrue(cycpatternCheck(a: "efef", b: "fee") == true) // cannot find 'cycpatternCheck' in scopeXCTAssertTrue(cycpatternCheck(a: "abab", b: "aabb") == false) // cannot find 'cycpatternCheck' in scopeXCTAssertTrue(cycpatternCheck(a: "winemtt", b: "tinem") == true) // cannot find 'cycpatternCheck' in scopefunc cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a.lowercased())
let bChars = Array(b.lowercased())
for i in 0..<bChars.count {
let bCharsRotated = bChars.suffix(from: i) + bChars.prefix(from: 0)
if aChars.contains(bCharsRotated) {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
Answer:
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a.lowercased())
let bChars = Array(b.lowercased())
for i in 0..<bChars.count {
let bCharsRotated = bChars.suffix(from: i) + bChars.prefix(from: 0)
if aChars.contains(bCharsRotated) {
return true
}
}
return false
}
```let bCharsRotated = bChars.suffix(from: i) + bChars.prefix(from: 0) // no exact matches in call to instance method 'prefix'func cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a.lowercased())
let bChars = Array(b.lowercased())
for i in 0..<bChars.count {
let bCharsRotated = Array(bChars.suffix(from: i)) + Array(bChars.prefix(from: i))
if aChars.contains(bCharsRotated) {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
Answer:
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a.lowercased())
let bChars = Array(b.lowercased())
for i in 0..<bChars.count {
let bCharsRotated = Array(bChars.suffix(from: i)) + Array(bChars.prefix(from: i))
if aChars.contains(bCharsRotated) {
return true
}
}
return false
}
```let bCharsRotated = Array(bChars.suffix(from: i)) + Array(bChars.prefix(from: i)) // no exact matches in call to instance method 'prefix'func cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a.lowercased())
let bChars = Array(b.lowercased())
let bCharsRotated = bChars.rotated(by: bChars.count / 2)
return aChars.contains(bChars) || aChars.contains(bCharsRotated)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
Answer:
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a.lowercased())
let bChars = Array(b.lowercased())
let bCharsRotated = bChars.rotated(by: bChars.count / 2)
return aChars.contains(bChars) || aChars.contains(bCharsRotated)
}
```let bCharsRotated = bChars.rotated(by: bChars.count / 2) // value of type '[String.Element]' (aka 'Array<Character>') has no member 'rotated'func cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a.characters)
let bChars = Array(b.characters)
let bCharsRotated = bChars.rotated()
return aChars.contains(bChars) || aChars.contains(bCharsRotated)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
Answer:
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a.characters)
let bChars = Array(b.characters)
let bCharsRotated = bChars.rotated()
return aChars.contains(bChars) || aChars.contains(bCharsRotated)
}
```let aChars = Array(a.characters) // 'characters' is unavailable: Please use String directlylet bChars = Array(b.characters) // 'characters' is unavailable: Please use String directlylet bCharsRotated = bChars.rotated() // value of type '[String.Element]' (aka 'Array<Character>') has no member 'rotated'func cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a.characters)
let bChars = Array(b.characters)
let aCharsCount = aChars.count
let bCharsCount = bChars.count
let bCharsRotated = bChars.rotated()
let bCharsRotatedCount = bCharsRotated.count
let bCharsConcat = bChars + bCharsRotated
let bCharsConcatCount = bCharsConcat.count
let aCharsConcat = aChars + aChars
let aCharsConcatCount = aCharsConcat.count
let aCharsConcatRotated = aCharsConcat.rotated()
let aCharsConcatRotatedCount = aCharsConcatRotated.count
let aCharsConcatRotatedFirst = aCharsConcatRotated.prefix(bCharsConcatCount)
let aCharsConcatRotatedLast = aCharsConcatRotated.suffix(bCharsConcatCount)
let aCharsConcatRotatedFirstChars = Array(aCharsConcatRotatedFirst.characters)
let aCharsConcatRotatedLastChars = Array(aCharsConcatRotatedLast.characters)
let aCharsConcatRotatedFirstCharsCount = aCharsConcatRotatedFirstChars.count
let aCharsConcatRotatedLastCharsCount = aCharsConcatRotatedLastChars.count
let aCharsConcatRotatedFirstCharsLastChars = aCharsConcatRotatedFirstChars + aCharsConcatRotatedLastChars
let aCharsConcatRotatedFirstCharsLastCharsCount = aCharsConcatRotatedFirstCharsLastChars.count
let aCharsConcatRotatedFirstCharsLastCharsFirstChars = aCharsConcatRotatedFirstCharsLastChars.prefix(bCharsConcatCount)
let aCharsConcatRotatedFirstCharsLastCharsFirstCharsCount = aCharsConcatRotatedFirstCharsLastCharsFirstChars.count
let aCharsConcatRotatedFirstCharsLastCharsFirstCharsLastChars = aCharsConcatRotatedFirstCharsLastCharsFirstChars + aCharsConcatRotatedFirstCharsLastChars
let aCharsConcatRotatedFirstCharsLastCharsFirstCharsLastCharsCount = aCharsConcatRotatedFirstCharsLastCharsFirstCharsLastChars.count
let aCharsConcatRotatedFirstCharsLastCharsFirstCharsLastCharsFirstChars = aCharsConcatRotatedFirstCharsLastCharsFirstCharsLastChars.prefix(bCharsConcatCount)
let aCharsConcatRotatedFirstCharsLastCharsFirstCharsLastCharsFirstCharsCount = aCharsConcatRotatedFirstCharsLastCharsFirstCharsLastCharsFirstChars.count
return aCharsConcatRotatedFirstCharsLastCharsFirstCharsLastCharsFirstCharsCount == bCharsConcatCount
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
Answer:
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a.characters)
let bChars = Array(b.characters)
let aCharsCount = aChars.count
let bCharsCount = bChars.count
let bCharsRotated = bChars.rotated()
let bCharsRotatedCount = bCharsRotated.count
let bCharsConcat = bChars + bCharsRotated
let bCharsConcatCount = bCharsConcat.count
let aCharsConcat = aChars + aChars
let aCharsConcatCount = aCharsConcat.count
let aCharsConcatRotated = aCharsConcat.rotated()
let aCharsConcatRotatedCount = aCharsConcatRotated.count
let aCharsConcatRotatedFirst = aCharsConcatRotated.prefix(bCharsConcatCount)
let aCharsConcatRotatedLast = aCharsConcatRotated.suffix(bCharsConcatCount)
let aCharsConcatRotatedFirstChars = Array(aCharsConcatRotatedFirst.characters)
let aCharsConcatRotatedLastChars = Array(aCharsConcatRotatedLast.characters)
let aCharsConcatRotatedFirstCharsCount = aCharsConcatRotatedFirstChars.count
let aCharsConcatRotatedLastCharsCount = aCharsConcatRotatedLastChars.count
let aCharsConcatRotatedFirstCharsLastChars = aCharsConcatRotatedFirstChars + aCharsConcatRotatedLastChars
let aCharsConcatRotatedFirstCharsLastCharsCount = aCharsConcatRotatedFirstCharsLastChars.count
let aCharsConcatRotatedFirstCharsLastCharsFirstChars = aCharsConcatRotatedFirstCharsLastChars.prefix(bCharsConcatCount)
let aCharsConcatRotatedFirstCharsLastCharsFirstCharsCount = aCharsConcatRotatedFirstCharsLastCharsFirstChars.count
let aCharsConcatRotatedFirstCharsLastCharsFirstCharsLastChars = aCharsConcatRotatedFirstCharsLastCharsFirstChars + aCharsConcatRotatedFirstCharsLastChars
let aCharsConcatRotatedFirstCharsLastCharsFirstCharsLastCharsCount = aCharsConcatRotatedFirstCharsLastCharsFirstCharsLastChars.count
let aCharsConcatRotatedFirstCharsLastCharsFirstCharsLastCharsFirstChars = aCharsConcatRotatedFirstCharsLastCharsFirstCharsLastChars.prefix(bCharsConcatCount)
let aCharsConcatRotatedFirstCharsLastCharsFirstCharsLastCharsFirstCharsCount = aCharsConcatRotatedFirstCharsLastCharsFirstCharsLastCharsFirstChars.count
return aCharsConcatRotatedFirstCharsLastCharsFirstCharsLastCharsFirstCharsCount == bCharsConcatCount
}
```let aChars = Array(a.characters) // 'characters' is unavailable: Please use String directlylet bChars = Array(b.characters) // 'characters' is unavailable: Please use String directlylet bCharsRotated = bChars.rotated() // value of type '[String.Element]' (aka 'Array<Character>') has no member 'rotated'let aCharsConcatRotated = aCharsConcat.rotated() // value of type '[String.Element]' (aka 'Array<Character>') has no member 'rotated'func cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a)
let bChars = Array(b)
let aCharsCount = aChars.count
let bCharsCount = bChars.count
if aCharsCount < bCharsCount {
return false
}
for i in 0..<aCharsCount {
let aCharsSubarray = aChars[i..<i+bCharsCount]
let bCharsSubarray = bChars.reversed()
if aCharsSubarray == bCharsSubarray {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
Answer:
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a)
let bChars = Array(b)
let aCharsCount = aChars.count
let bCharsCount = bChars.count
if aCharsCount < bCharsCount {
return false
}
for i in 0..<aCharsCount {
let aCharsSubarray = aChars[i..<i+bCharsCount]
let bCharsSubarray = bChars.reversed()
if aCharsSubarray == bCharsSubarray {
return true
}
}
return false
}
```if aCharsSubarray == bCharsSubarray { // cannot convert value of type 'ReversedCollection<[String.Element]>' (aka 'ReversedCollection<Array<Character>>') to expected argument type 'ArraySlice<String.Element>' (aka 'ArraySlice<Character>')func cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a.characters)
let bChars = Array(b.characters)
let aCharsCount = aChars.count
let bCharsCount = bChars.count
let bCharsRotated = bChars.rotated()
let bCharsRotatedCount = bCharsRotated.count
let isBCharsSubString = aChars.contains(bChars) || aChars.contains(bCharsRotated)
return isBCharsSubString
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
Answer:
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a.characters)
let bChars = Array(b.characters)
let aCharsCount = aChars.count
let bCharsCount = bChars.count
let bCharsRotated = bChars.rotated()
let bCharsRotatedCount = bCharsRotated.count
let isBCharsSubString = aChars.contains(bChars) || aChars.contains(bCharsRotated)
return isBCharsSubString
}
```let aChars = Array(a.characters) // 'characters' is unavailable: Please use String directlylet bChars = Array(b.characters) // 'characters' is unavailable: Please use String directlylet bCharsRotated = bChars.rotated() // value of type '[String.Element]' (aka 'Array<Character>') has no member 'rotated'func evenOddCount(num: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for digit in String(num).characters.map { Int(String($0))! } {
if digit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
Answer:
```swift
func evenOddCount(num: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for digit in String(num).characters.map { Int(String($0))! } {
if digit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}
```for digit in String(num).characters.map { Int(String($0))! } { // 'characters' is unavailable: Please use String directlyfor digit in String(num).characters.map { Int(String($0))! } { // trailing closure in this context is confusable with the body of the statement; pass as a parenthesized argument to silence this warningfunc evenOddCount(num: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
var number = num
while number!= 0 {
let digit = number % 10
if digit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
number /= 10
}
return (evenCount, oddCount)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
Answer:
```swift
func evenOddCount(num: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
var number = num
while number!= 0 {
let digit = number % 10
if digit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
number /= 10
}
return (evenCount, oddCount)
}
```while number!= 0 { // cannot force unwrap value of non-optional type 'Int'while number!= 0 { // '=' must have consistent whitespace on both sideswhile number!= 0 { // use of '=' in a boolean context, did you mean '=='?func evenOddCount(num: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for digit in String(num).characters.map { Int(String($0))! } {
if digit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
Answer:
```swift
func evenOddCount(num: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for digit in String(num).characters.map { Int(String($0))! } {
if digit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}
```for digit in String(num).characters.map { Int(String($0))! } { // 'characters' is unavailable: Please use String directlyfor digit in String(num).characters.map { Int(String($0))! } { // trailing closure in this context is confusable with the body of the statement; pass as a parenthesized argument to silence this warningfunc evenOddCount(num: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
let string = String(num)
for digit in string {
let intDigit = Int(String(digit))?? 0
if intDigit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
Answer:
```swift
func evenOddCount(num: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
let string = String(num)
for digit in string {
let intDigit = Int(String(digit))?? 0
if intDigit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}
```let intDigit = Int(String(digit))?? 0 // consecutive statements on a line must be separated by ';'let intDigit = Int(String(digit))?? 0 // integer literal is unusedlet intDigit = Int(String(digit))?? 0 // cannot use optional chaining on non-optional value of type 'Int'func evenOddCount(num: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for digit in String(num).characters {
if Int(String(digit))! % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
Answer:
```swift
func evenOddCount(num: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for digit in String(num).characters {
if Int(String(digit))! % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}
```for digit in String(num).characters { // 'characters' is unavailable: Please use String directlyfunc evenOddCount(num: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
var currentNumber = num
while currentNumber!= 0 {
let lastDigit = currentNumber % 10
if lastDigit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
currentNumber /= 10
}
return (evenCount, oddCount)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
Answer:
```swift
func evenOddCount(num: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
var currentNumber = num
while currentNumber!= 0 {
let lastDigit = currentNumber % 10
if lastDigit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
currentNumber /= 10
}
return (evenCount, oddCount)
}
```while currentNumber!= 0 { // cannot force unwrap value of non-optional type 'Int'while currentNumber!= 0 { // use of '=' in a boolean context, did you mean '=='?while currentNumber!= 0 { // '=' must have consistent whitespace on both sidesfunc evenOddCount(num: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for digit in String(num).characters.map { Int(String($0))! } {
if digit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
Answer:
```swift
func evenOddCount(num: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for digit in String(num).characters.map { Int(String($0))! } {
if digit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}
```for digit in String(num).characters.map { Int(String($0))! } { // 'characters' is unavailable: Please use String directlyfor digit in String(num).characters.map { Int(String($0))! } { // trailing closure in this context is confusable with the body of the statement; pass as a parenthesized argument to silence this warningfunc evenOddCount(num: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for digit in String(num).characters {
if let intValue = Int(String(digit)), intValue % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
Answer:
```swift
func evenOddCount(num: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for digit in String(num).characters {
if let intValue = Int(String(digit)), intValue % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}
```for digit in String(num).characters { // 'characters' is unavailable: Please use String directlyfunc evenOddCount(num: Int) -> (Int, Int) {
var even = 0
var odd = 0
var absNum = abs(num)
while absNum > 0 {
let digit = absNum % 10
if digit % 2 == 0 {
even += 1
} else {
odd += 1
}
absNum /= 10
}
return (even, odd)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
Answer:
```swift
func evenOddCount(num: Int) -> (Int, Int) {
var even = 0
var odd = 0
var absNum = abs(num)
while absNum > 0 {
let digit = absNum % 10
if digit % 2 == 0 {
even += 1
} else {
odd += 1
}
absNum /= 10
}
return (even, odd)
}
``` // XCTAssertTrue failedfunc evenOddCount(num: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for digit in String(num).characters {
let intValue = Int(String(digit))?? 0
if intValue % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
Answer:
```swift
func evenOddCount(num: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for digit in String(num).characters {
let intValue = Int(String(digit))?? 0
if intValue % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}
```for digit in String(num).characters { // 'characters' is unavailable: Please use String directlylet intValue = Int(String(digit))?? 0 // consecutive statements on a line must be separated by ';'let intValue = Int(String(digit))?? 0 // cannot use optional chaining on non-optional value of type 'Int'let intValue = Int(String(digit))?? 0 // integer literal is unusedfunc intToMiniRoman(number: Int) -> String {
let romanNumerals = ["M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"]
var result = ""
var num = number
for (index, value) in romanNumerals.enumerated() {
while num >= value {
num -= value
result += String(romanNumerals[index])
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
Answer:
```swift
func intToMiniRoman(number: Int) -> String {
let romanNumerals = ["M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"]
var result = ""
var num = number
for (index, value) in romanNumerals.enumerated() {
while num >= value {
num -= value
result += String(romanNumerals[index])
}
}
return result
}
```while num >= value { // binary operator '>=' cannot be applied to operands of type 'Int' and 'String'num -= value // cannot convert value of type 'String' to expected argument type 'Int'func intToMiniRoman(number: Int) -> String {
let romanNumerals = ["M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"]
var result = ""
var num = number
for (index, value) in romanNumerals.enumerated() {
while num >= value {
num -= value
result.append(romanNumerals[index])
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
Answer:
```swift
func intToMiniRoman(number: Int) -> String {
let romanNumerals = ["M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"]
var result = ""
var num = number
for (index, value) in romanNumerals.enumerated() {
while num >= value {
num -= value
result.append(romanNumerals[index])
}
}
return result
}
```while num >= value { // binary operator '>=' cannot be applied to operands of type 'Int' and 'String'num -= value // cannot convert value of type 'String' to expected argument type 'Int'func intToMiniRoman(number: Int) -> String {
let romanNumerals = ["M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"]
var result = ""
var num = number
for (index, value) in romanNumerals.enumerated() {
while num >= value {
result.append(romanNumerals[index])
num -= value
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
Answer:
```swift
func intToMiniRoman(number: Int) -> String {
let romanNumerals = ["M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"]
var result = ""
var num = number
for (index, value) in romanNumerals.enumerated() {
while num >= value {
result.append(romanNumerals[index])
num -= value
}
}
return result
}
```while num >= value { // binary operator '>=' cannot be applied to operands of type 'Int' and 'String'num -= value // cannot convert value of type 'String' to expected argument type 'Int'func intToMiniRoman(number: Int) -> String {
let romanNumerals = ["M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"]
var result = ""
var num = number
for (index, value) in romanNumerals.enumerated() {
while num >= value {
result.append(value)
num -= value
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
Answer:
```swift
func intToMiniRoman(number: Int) -> String {
let romanNumerals = ["M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"]
var result = ""
var num = number
for (index, value) in romanNumerals.enumerated() {
while num >= value {
result.append(value)
num -= value
}
}
return result
}
```while num >= value { // binary operator '>=' cannot be applied to operands of type 'Int' and 'String'num -= value // cannot convert value of type 'String' to expected argument type 'Int'func intToMiniRoman(number: Int) -> String {
let romanNumerals = ["M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"]
var result = ""
var num = number
for (index, value) in romanNumerals.enumerated() {
while num >= value {
num -= value
result += String(romanNumerals[index])
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
Answer:
```swift
func intToMiniRoman(number: Int) -> String {
let romanNumerals = ["M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"]
var result = ""
var num = number
for (index, value) in romanNumerals.enumerated() {
while num >= value {
num -= value
result += String(romanNumerals[index])
}
}
return result
}
```while num >= value { // binary operator '>=' cannot be applied to operands of type 'Int' and 'String'num -= value // cannot convert value of type 'String' to expected argument type 'Int'func intToMiniRoman(number: Int) -> String {
let romanNumerals = ["M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"]
var result = ""
var num = number
for (i, value) in romanNumerals.enumerated() {
while num >= value {
result.append(romanNumerals[i])
num -= value
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
Answer:
```swift
func intToMiniRoman(number: Int) -> String {
let romanNumerals = ["M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"]
var result = ""
var num = number
for (i, value) in romanNumerals.enumerated() {
while num >= value {
result.append(romanNumerals[i])
num -= value
}
}
return result
}
```while num >= value { // binary operator '>=' cannot be applied to operands of type 'Int' and 'String'num -= value // cannot convert value of type 'String' to expected argument type 'Int'func intToMiniRoman(number: Int) -> String {
let romanNumerals = ["M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"]
var result = ""
var num = number
for (index, value) in romanNumerals.enumerated() {
while num >= value {
result.append(value)
num -= value
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
Answer:
```swift
func intToMiniRoman(number: Int) -> String {
let romanNumerals = ["M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"]
var result = ""
var num = number
for (index, value) in romanNumerals.enumerated() {
while num >= value {
result.append(value)
num -= value
}
}
return result
}
```while num >= value { // binary operator '>=' cannot be applied to operands of type 'Int' and 'String'num -= value // cannot convert value of type 'String' to expected argument type 'Int'func intToMiniRoman(number: Int) -> String {
let romanNumerals = [
(1000, "m"),
(900, "cm"),
(500, "d"),
(400, "cd"),
(100, "c"),
(90, "xc"),
(50, "l"),
(40, "xl"),
(10, "x"),
(9, "ix"),
(5, "v"),
(4, "iv"),
(1, "i")
]
var result = ""
for (value, romanNumeral) in romanNumerals {
while number >= value {
result += romanNumeral
number -= value
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
Answer:
```swift
func intToMiniRoman(number: Int) -> String {
let romanNumerals = [
(1000, "m"),
(900, "cm"),
(500, "d"),
(400, "cd"),
(100, "c"),
(90, "xc"),
(50, "l"),
(40, "xl"),
(10, "x"),
(9, "ix"),
(5, "v"),
(4, "iv"),
(1, "i")
]
var result = ""
for (value, romanNumeral) in romanNumerals {
while number >= value {
result += romanNumeral
number -= value
}
}
return result
}
```number -= value // left side of mutating operator isn't mutable: 'number' is a 'let' constantfunc intToMiniRoman(number: Int) -> String {
let romanNumerals = ["M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"]
var result = ""
var num = number
for (index, value) in romanNumerals.enumerated() {
while num >= value {
result.append(value)
num -= value
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
Answer:
```swift
func intToMiniRoman(number: Int) -> String {
let romanNumerals = ["M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"]
var result = ""
var num = number
for (index, value) in romanNumerals.enumerated() {
while num >= value {
result.append(value)
num -= value
}
}
return result
}
```while num >= value { // binary operator '>=' cannot be applied to operands of type 'Int' and 'String'num -= value // cannot convert value of type 'String' to expected argument type 'Int'func intToMiniRoman(number: Int) -> String {
let romanNumerals = ["M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"]
var result = ""
var index = 0
var num = number
while num > 0 {
let remainder = num % 10
let value = romanNumerals[index]
if remainder == 9 {
result += value + value
} else if remainder == 4 {
result += value + value + value
} else if remainder == 5 {
result += value + value
} else if remainder == 1 {
result += value
}
num /= 10
index += 1
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
Answer:
```swift
func intToMiniRoman(number: Int) -> String {
let romanNumerals = ["M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"]
var result = ""
var index = 0
var num = number
while num > 0 {
let remainder = num % 10
let value = romanNumerals[index]
if remainder == 9 {
result += value + value
} else if remainder == 4 {
result += value + value + value
} else if remainder == 5 {
result += value + value
} else if remainder == 1 {
result += value
}
num /= 10
index += 1
}
return result
}
``` // XCTAssertTrue failedfunc rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let s = (a + b + c) / 2
return (s > a && s > b && s > c) && (a * a + b * b == c * c)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
Answer:
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let s = (a + b + c) / 2
return (s > a && s > b && s > c) && (a * a + b * b == c * c)
}
``` // XCTAssertTrue failedfunc rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let sum = a + b + c
return sum == 10
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
Answer:
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let sum = a + b + c
return sum == 10
}
``` // XCTAssertTrue failedfunc rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let s = (a + b + c) / 2
return (s > a && s > b && s > c) && (s * (s - a) * (s - b) * (s - c) == 0)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
Answer:
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let s = (a + b + c) / 2
return (s > a && s > b && s > c) && (s * (s - a) * (s - b) * (s - c) == 0)
}
``` // XCTAssertTrue failedfunc rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let sum = a + b + c
return sum == 10
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
Answer:
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let sum = a + b + c
return sum == 10
}
``` // XCTAssertTrue failedfunc rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let s = (a + b + c) / 2
return s * (s - a) * (s - b) * (s - c) == 0
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
Answer:
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let s = (a + b + c) / 2
return s * (s - a) * (s - b) * (s - c) == 0
}
``` // XCTAssertTrue failedfunc rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let sum = a + b + c
return sum == 10
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
Answer:
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let sum = a + b + c
return sum == 10
}
``` // XCTAssertTrue failedfunc rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let s = (a + b + c) / 2
return (s > a && s > b && s > c) && (s * s == (a * a) + (b * b) + (c * c))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
Answer:
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let s = (a + b + c) / 2
return (s > a && s > b && s > c) && (s * s == (a * a) + (b * b) + (c * c))
}
``` // XCTAssertTrue failedfunc rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let sum = a + b + c
let isRightAngle = a * a + b * b == c * c
return isRightAngle
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
Answer:
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let sum = a + b + c
let isRightAngle = a * a + b * b == c * c
return isRightAngle
}
```let sum = a + b + c // initialization of immutable value 'sum' was never used; consider replacing with assignment to '_' or removing it // XCTAssertTrue failedfunc rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let s = (a + b + c) / 2
return (s > a && s > b && s > c) && (s * s == (a * a) + (b * b) + (c * c))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
Answer:
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let s = (a + b + c) / 2
return (s > a && s > b && s > c) && (s * s == (a * a) + (b * b) + (c * c))
}
``` // XCTAssertTrue failedfunc rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let s = (a + b + c) / 2
return s * (s - a) * (s - b) * (s - c) == 0
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
Answer:
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let s = (a + b + c) / 2
return s * (s - a) * (s - b) * (s - c) == 0
}
``` // XCTAssertTrue failedfunc findMax(words: [String]) -> String {
var maxWord = ""
var maxCount = 0
for word in words {
let uniqueChars = Set(word)
if uniqueChars.count > maxCount {
maxCount = uniqueChars.count
maxWord = word
}
}
return maxWord
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
Answer:
```swift
func findMax(words: [String]) -> String {
var maxWord = ""
var maxCount = 0
for word in words {
let uniqueChars = Set(word)
if uniqueChars.count > maxCount {
maxCount = uniqueChars.count
maxWord = word
}
}
return maxWord
}
``` // XCTAssertTrue failedfunc findMax(words: [String]) -> String {
var maxWord = ""
var maxCount = 0
for word in words {
let uniqueChars = Set(word)
let count = uniqueChars.count
if count > maxCount {
maxCount = count
maxWord = word
}
}
return maxWord
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
Answer:
```swift
func findMax(words: [String]) -> String {
var maxWord = ""
var maxCount = 0
for word in words {
let uniqueChars = Set(word)
let count = uniqueChars.count
if count > maxCount {
maxCount = count
maxWord = word
}
}
return maxWord
}
``` // XCTAssertTrue failedfunc findMax(words: [String]) -> String {
var maxWord = ""
var maxCount = 0
for word in words {
let count = Set(word).count
if count > maxCount {
maxCount = count
maxWord = word
}
}
return maxWord
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
Answer:
```swift
func findMax(words: [String]) -> String {
var maxWord = ""
var maxCount = 0
for word in words {
let count = Set(word).count
if count > maxCount {
maxCount = count
maxWord = word
}
}
return maxWord
}
``` // XCTAssertTrue failedfunc findMax(words: [String]) -> String {
var maxCount = 0
var result = ""
for word in words {
let count = Set(word).count
if count > maxCount {
maxCount = count
result = word
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
Answer:
```swift
func findMax(words: [String]) -> String {
var maxCount = 0
var result = ""
for word in words {
let count = Set(word).count
if count > maxCount {
maxCount = count
result = word
}
}
return result
}
``` // XCTAssertTrue failedfunc findMax(words: [String]) -> String {
var maxWord = ""
var maxCount = 0
for word in words {
let uniqueChars = Set(word)
let count = uniqueChars.count
if count > maxCount {
maxCount = count
maxWord = word
}
}
return maxWord
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
Answer:
```swift
func findMax(words: [String]) -> String {
var maxWord = ""
var maxCount = 0
for word in words {
let uniqueChars = Set(word)
let count = uniqueChars.count
if count > maxCount {
maxCount = count
maxWord = word
}
}
return maxWord
}
``` // XCTAssertTrue failedfunc findMax(words: [String]) -> String {
var maxCount = 0
var maxWord = ""
for word in words {
let uniqueChars = Set(word)
let count = uniqueChars.count
if count > maxCount {
maxCount = count
maxWord = word
}
}
return maxWord
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
Answer:
```swift
func findMax(words: [String]) -> String {
var maxCount = 0
var maxWord = ""
for word in words {
let uniqueChars = Set(word)
let count = uniqueChars.count
if count > maxCount {
maxCount = count
maxWord = word
}
}
return maxWord
}
``` // XCTAssertTrue failedfunc findMax(words: [String]) -> String {
var maxWord = ""
var maxCount = 0
for word in words {
let uniqueChars = Set(word)
let count = uniqueChars.count
if count > maxCount {
maxCount = count
maxWord = word
}
}
return maxWord
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
Answer:
```swift
func findMax(words: [String]) -> String {
var maxWord = ""
var maxCount = 0
for word in words {
let uniqueChars = Set(word)
let count = uniqueChars.count
if count > maxCount {
maxCount = count
maxWord = word
}
}
return maxWord
}
``` // XCTAssertTrue failedfunc findMax(words: [String]) -> String {
var maxWord = ""
var maxCount = 0
for word in words {
let uniqueChars = Set(word)
let count = uniqueChars.count
if count > maxCount {
maxCount = count
maxWord = word
}
}
return maxWord
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
Answer:
```swift
func findMax(words: [String]) -> String {
var maxWord = ""
var maxCount = 0
for word in words {
let uniqueChars = Set(word)
let count = uniqueChars.count
if count > maxCount {
maxCount = count
maxWord = word
}
}
return maxWord
}
``` // XCTAssertTrue failedfunc findMax(words: [String]) -> String {
var maxWord = ""
var maxCount = 0
for word in words {
let count = Set(word).count
if count > maxCount {
maxCount = count
maxWord = word
}
}
return maxWord
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
Answer:
```swift
func findMax(words: [String]) -> String {
var maxWord = ""
var maxCount = 0
for word in words {
let count = Set(word).count
if count > maxCount {
maxCount = count
maxWord = word
}
}
return maxWord
}
``` // XCTAssertTrue failedfunc findMax(words: [String]) -> String {
var maxWord = ""
var maxCount = 0
for word in words {
let uniqueChars = Set(word)
let count = uniqueChars.count
if count > maxCount {
maxCount = count
maxWord = word
}
}
return maxWord
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
Answer:
```swift
func findMax(words: [String]) -> String {
var maxWord = ""
var maxCount = 0
for word in words {
let uniqueChars = Set(word)
let count = uniqueChars.count
if count > maxCount {
maxCount = count
maxWord = word
}
}
return maxWord
}
``` // XCTAssertTrue failed@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let total = number + need
let left = total > remaining? remaining : total
return [total, left]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let total = number + need
let left = total > remaining? remaining : total
return [total, left]
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'let left = total > remaining? remaining : total // value of optional type 'Int?' must be unwrapped to a value of type 'Int'let left = total > remaining? remaining : total // cannot use optional chaining on non-optional value of type 'Int'let left = total > remaining? remaining : total // consecutive statements on a line must be separated by ';'let left = total > remaining? remaining : total // expression of type 'Int' is unusedlet left = total > remaining? remaining : total // consecutive statements on a line must be separated by ';'let left = total > remaining? remaining : total // expected expression@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let total = number + need
let left = total > remaining? remaining : total
return [total, left]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let total = number + need
let left = total > remaining? remaining : total
return [total, left]
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'let left = total > remaining? remaining : total // value of optional type 'Int?' must be unwrapped to a value of type 'Int'let left = total > remaining? remaining : total // cannot use optional chaining on non-optional value of type 'Int'let left = total > remaining? remaining : total // consecutive statements on a line must be separated by ';'let left = total > remaining? remaining : total // expression of type 'Int' is unusedlet left = total > remaining? remaining : total // consecutive statements on a line must be separated by ';'let left = total > remaining? remaining : total // expected expression@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let total = number + need
let left = total > remaining? remaining : total
return [total, left]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let total = number + need
let left = total > remaining? remaining : total
return [total, left]
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'let left = total > remaining? remaining : total // value of optional type 'Int?' must be unwrapped to a value of type 'Int'let left = total > remaining? remaining : total // cannot use optional chaining on non-optional value of type 'Int'let left = total > remaining? remaining : total // consecutive statements on a line must be separated by ';'let left = total > remaining? remaining : total // expression of type 'Int' is unusedlet left = total > remaining? remaining : total // consecutive statements on a line must be separated by ';'let left = total > remaining? remaining : total // expected expression@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
var result = number
if need > remaining {
result += remaining
return [result, 0]
} else {
result += need
return [result, remaining - need]
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
var result = number
if need > remaining {
result += remaining
return [result, 0]
} else {
result += need
return [result, remaining - need]
}
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let total = number + need
let left = total > remaining? remaining : total
return [total, left]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let total = number + need
let left = total > remaining? remaining : total
return [total, left]
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'let left = total > remaining? remaining : total // value of optional type 'Int?' must be unwrapped to a value of type 'Int'let left = total > remaining? remaining : total // cannot use optional chaining on non-optional value of type 'Int'let left = total > remaining? remaining : total // consecutive statements on a line must be separated by ';'let left = total > remaining? remaining : total // expression of type 'Int' is unusedlet left = total > remaining? remaining : total // consecutive statements on a line must be separated by ';'let left = total > remaining? remaining : total // expected expression@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
var eaten = number
var left = remaining
while eaten < need {
eaten += 1
left -= 1
}
return [eaten, left]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
var eaten = number
var left = remaining
while eaten < need {
eaten += 1
left -= 1
}
return [eaten, left]
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
var result = number
if result + need > remaining {
result = remaining
}
return [result, remaining - result]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
var result = number
if result + need > remaining {
result = remaining
}
return [result, remaining - result]
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let total = number + need
let left = total > remaining? remaining : total
return [total, left]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let total = number + need
let left = total > remaining? remaining : total
return [total, left]
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'let left = total > remaining? remaining : total // value of optional type 'Int?' must be unwrapped to a value of type 'Int'let left = total > remaining? remaining : total // cannot use optional chaining on non-optional value of type 'Int'let left = total > remaining? remaining : total // consecutive statements on a line must be separated by ';'let left = total > remaining? remaining : total // expression of type 'Int' is unusedlet left = total > remaining? remaining : total // consecutive statements on a line must be separated by ';'let left = total > remaining? remaining : total // expected expression@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
var eaten = number
var left = remaining
if eaten + need > left {
eaten = left
} else {
eaten += need
}
return [eaten, left - eaten]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
var eaten = number
var left = remaining
if eaten + need > left {
eaten = left
} else {
eaten += need
}
return [eaten, left - eaten]
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'var left = remaining // variable 'left' was never mutated; consider changing to 'let' constant@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let total = number + need
let left = total > remaining? remaining : total
return [total, left]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let total = number + need
let left = total > remaining? remaining : total
return [total, left]
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'let left = total > remaining? remaining : total // value of optional type 'Int?' must be unwrapped to a value of type 'Int'let left = total > remaining? remaining : total // cannot use optional chaining on non-optional value of type 'Int'let left = total > remaining? remaining : total // consecutive statements on a line must be separated by ';'let left = total > remaining? remaining : total // expression of type 'Int' is unusedlet left = total > remaining? remaining : total // consecutive statements on a line must be separated by ';'let left = total > remaining? remaining : total // expected expressionfunc doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 1..<operators.count {
let operator = operators[i]
let operand = operands[i]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "/":
result /= operand
case "**":
result = Int(pow(Double(result), Double(operand)))
default:
break
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
Answer:
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 1..<operators.count {
let operator = operators[i]
let operand = operands[i]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "/":
result /= operand
case "**":
result = Int(pow(Double(result), Double(operand)))
default:
break
}
}
return result
}
```let operator = operators[i] // keyword 'operator' cannot be used as an identifier hereswitch operator { // expected operator name in operator declarationswitch operator { // expected expression in 'switch' statementfunc doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 1..<operators.count {
let operator = operators[i]
let operand = operands[i]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "/":
result /= operand
case "**":
result = pow(result, Double(operand))
default:
break
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
Answer:
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 1..<operators.count {
let operator = operators[i]
let operand = operands[i]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "/":
result /= operand
case "**":
result = pow(result, Double(operand))
default:
break
}
}
return result
}
```let operator = operators[i] // keyword 'operator' cannot be used as an identifier hereswitch operator { // expected operator name in operator declarationswitch operator { // expected expression in 'switch' statementfunc doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 1..<operators.count {
let operator = operators[i]
let operand = operands[i]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "/":
result /= operand
case "**":
result = pow(result, Double(operand))
default:
break
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
Answer:
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 1..<operators.count {
let operator = operators[i]
let operand = operands[i]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "/":
result /= operand
case "**":
result = pow(result, Double(operand))
default:
break
}
}
return result
}
```let operator = operators[i] // keyword 'operator' cannot be used as an identifier hereswitch operator { // expected operator name in operator declarationswitch operator { // expected expression in 'switch' statementfunc doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 1..<operators.count {
let operator = operators[i]
let operand = operands[i]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "/":
result /= operand
case "**":
result = Int(pow(Double(result), Double(operand)))
default:
break
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
Answer:
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 1..<operators.count {
let operator = operators[i]
let operand = operands[i]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "/":
result /= operand
case "**":
result = Int(pow(Double(result), Double(operand)))
default:
break
}
}
return result
}
```let operator = operators[i] // keyword 'operator' cannot be used as an identifier hereswitch operator { // expected operator name in operator declarationswitch operator { // expected expression in 'switch' statementfunc doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 1..<operators.count {
let operator = operators[i]
let operand = operands[i]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "/":
result /= operand
case "**":
result = pow(result, Double(operand))
default:
break
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
Answer:
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 1..<operators.count {
let operator = operators[i]
let operand = operands[i]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "/":
result /= operand
case "**":
result = pow(result, Double(operand))
default:
break
}
}
return result
}
```let operator = operators[i] // keyword 'operator' cannot be used as an identifier hereswitch operator { // expected operator name in operator declarationswitch operator { // expected expression in 'switch' statementfunc doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 1..<operators.count {
let operator = operators[i]
let operand = operands[i]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "/":
result /= operand
case "**":
result = pow(result, Double(operand))
default:
break
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
Answer:
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 1..<operators.count {
let operator = operators[i]
let operand = operands[i]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "/":
result /= operand
case "**":
result = pow(result, Double(operand))
default:
break
}
}
return result
}
```let operator = operators[i] // keyword 'operator' cannot be used as an identifier hereswitch operator { // expected operator name in operator declarationswitch operator { // expected expression in 'switch' statementfunc doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 1..<operators.count {
let operator = operators[i]
let operand = operands[i]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "/":
result /= operand
case "**":
result = pow(result, Double(operand))
default:
break
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
Answer:
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 1..<operators.count {
let operator = operators[i]
let operand = operands[i]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "/":
result /= operand
case "**":
result = pow(result, Double(operand))
default:
break
}
}
return result
}
```let operator = operators[i] // keyword 'operator' cannot be used as an identifier hereswitch operator { // expected operator name in operator declarationswitch operator { // expected expression in 'switch' statementfunc doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 1..<operators.count {
let operator = operators[i]
let operand = operands[i]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "/":
result /= operand
case "**":
result = Int(pow(Double(result), Double(operand)))
default:
break
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
Answer:
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 1..<operators.count {
let operator = operators[i]
let operand = operands[i]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "/":
result /= operand
case "**":
result = Int(pow(Double(result), Double(operand)))
default:
break
}
}
return result
}
```let operator = operators[i] // keyword 'operator' cannot be used as an identifier hereswitch operator { // expected operator name in operator declarationswitch operator { // expected expression in 'switch' statementfunc doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 1..<operators.count {
let operator = operators[i]
let operand = operands[i]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "/":
result /= operand
case "**":
result = Int(pow(Double(result), Double(operand)))
default:
break
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
Answer:
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 1..<operators.count {
let operator = operators[i]
let operand = operands[i]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "/":
result /= operand
case "**":
result = Int(pow(Double(result), Double(operand)))
default:
break
}
}
return result
}
```let operator = operators[i] // keyword 'operator' cannot be used as an identifier hereswitch operator { // expected operator name in operator declarationswitch operator { // expected expression in 'switch' statementfunc doAlgebra(operators: [String], operands: [Int]) -> Int {
var stack = [Int]()
for (index, operator) in operators.enumerated() {
let right = operands[index + 1]
let left = stack.popLast()!
switch operator {
case "+":
stack.append(left + right)
case "-":
stack.append(left - right)
case "*":
stack.append(left * right)
case "/":
stack.append(left / right)
case "**":
stack.append(Int(pow(Double(left), Double(right))))
default:
break
}
}
return stack.first!
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
Answer:
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var stack = [Int]()
for (index, operator) in operators.enumerated() {
let right = operands[index + 1]
let left = stack.popLast()!
switch operator {
case "+":
stack.append(left + right)
case "-":
stack.append(left - right)
case "*":
stack.append(left * right)
case "/":
stack.append(left / right)
case "**":
stack.append(Int(pow(Double(left), Double(right))))
default:
break
}
}
return stack.first!
}
```for (index, operator) in operators.enumerated() { // expected '{' to start the body of for-each loopfor (index, operator) in operators.enumerated() { // expected 'in' after for-each patternfor (index, operator) in operators.enumerated() { // expected Sequence expression for for-each loopfor (index, operator) in operators.enumerated() { // expected patternswitch operator { // expected operator name in operator declarationswitch operator { // expected expression in 'switch' statementfunc solve(s: String) -> String {
let letters = s.filter { $0.isLetter }
let reversed = letters.reversed()
let result = letters.prefix(letters.count - reversed.count) + reversed
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
Answer:
```swift
func solve(s: String) -> String {
let letters = s.filter { $0.isLetter }
let reversed = letters.reversed()
let result = letters.prefix(letters.count - reversed.count) + reversed
return result
}
```return result // cannot convert return expression of type 'String.SubSequence' (aka 'Substring') to return type 'String'func solve(s: String) -> String {
var result = ""
for c in s {
if c.isLetter {
result.append(c.isUpper? c.lowercased() : c.uppercased())
} else {
result.append(c)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
Answer:
```swift
func solve(s: String) -> String {
var result = ""
for c in s {
if c.isLetter {
result.append(c.isUpper? c.lowercased() : c.uppercased())
} else {
result.append(c)
}
}
return result
}
```result.append(c.isUpper? c.lowercased() : c.uppercased()) // type of expression is ambiguous without a type annotationresult.append(c.isUpper? c.lowercased() : c.uppercased()) // expected ',' separatorfunc solve(s: String) -> String {
var result = ""
for character in s {
if character.isLetter {
result.append(character.isUpper? character.lowercased() : character.uppercased())
} else {
result.append(character)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
Answer:
```swift
func solve(s: String) -> String {
var result = ""
for character in s {
if character.isLetter {
result.append(character.isUpper? character.lowercased() : character.uppercased())
} else {
result.append(character)
}
}
return result
}
```result.append(character.isUpper? character.lowercased() : character.uppercased()) // expected ',' separatorresult.append(character.isUpper? character.lowercased() : character.uppercased()) // type of expression is ambiguous without a type annotationfunc solve(s: String) -> String {
let letters = s.filter { $0.isLetter }
let reversed = letters.reversed()
let result = letters.count > 0? String(reversed) : s.reversed()
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
Answer:
```swift
func solve(s: String) -> String {
let letters = s.filter { $0.isLetter }
let reversed = letters.reversed()
let result = letters.count > 0? String(reversed) : s.reversed()
return result
}
```let result = letters.count > 0? String(reversed) : s.reversed() // value of optional type 'Int?' must be unwrapped to a value of type 'Int'let result = letters.count > 0? String(reversed) : s.reversed() // expected expressionlet result = letters.count > 0? String(reversed) : s.reversed() // consecutive statements on a line must be separated by ';'let result = letters.count > 0? String(reversed) : s.reversed() // result of 'String' initializer is unusedlet result = letters.count > 0? String(reversed) : s.reversed() // consecutive statements on a line must be separated by ';'let result = letters.count > 0? String(reversed) : s.reversed() // cannot use optional chaining on non-optional value of type 'Int'func solve(s: String) -> String {
var result = ""
for char in s {
if char.isLetter {
result.append(char.isUpper? char.lowercased() : char.uppercased())
} else {
result.append(char)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
Answer:
```swift
func solve(s: String) -> String {
var result = ""
for char in s {
if char.isLetter {
result.append(char.isUpper? char.lowercased() : char.uppercased())
} else {
result.append(char)
}
}
return result
}
```result.append(char.isUpper? char.lowercased() : char.uppercased()) // type of expression is ambiguous without a type annotationresult.append(char.isUpper? char.lowercased() : char.uppercased()) // expected ',' separatorfunc solve(s: String) -> String {
var result = ""
for char in s {
if let char = String(char).unicodeScalars.first {
if char.isLetter {
result.append(char.isUpper? String(char).lowercased() : String(char).uppercased())
} else {
result.append(char)
}
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
Answer:
```swift
func solve(s: String) -> String {
var result = ""
for char in s {
if let char = String(char).unicodeScalars.first {
if char.isLetter {
result.append(char.isUpper? String(char).lowercased() : String(char).uppercased())
} else {
result.append(char)
}
}
}
return result
}
```if char.isLetter { // value of type 'String.UnicodeScalarView.Element' (aka 'Unicode.Scalar') has no member 'isLetter'result.append(char.isUpper? String(char).lowercased() : String(char).uppercased()) // type of expression is ambiguous without a type annotationresult.append(char.isUpper? String(char).lowercased() : String(char).uppercased()) // expected ',' separatorresult.append(char) // no exact matches in call to instance method 'append'func solve(s: String) -> String {
var result = ""
for char in s {
if let char = String(char).unicodeScalars.first {
if char.isLetter {
result.append(char.isUpper? String(char).lowercased() : String(char).uppercased())
} else {
result.append(char)
}
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
Answer:
```swift
func solve(s: String) -> String {
var result = ""
for char in s {
if let char = String(char).unicodeScalars.first {
if char.isLetter {
result.append(char.isUpper? String(char).lowercased() : String(char).uppercased())
} else {
result.append(char)
}
}
}
return result
}
```if char.isLetter { // value of type 'String.UnicodeScalarView.Element' (aka 'Unicode.Scalar') has no member 'isLetter'result.append(char.isUpper? String(char).lowercased() : String(char).uppercased()) // type of expression is ambiguous without a type annotationresult.append(char.isUpper? String(char).lowercased() : String(char).uppercased()) // expected ',' separatorresult.append(char) // no exact matches in call to instance method 'append'func solve(s: String) -> String {
var result = ""
for c in s {
if c.isLetter {
result.append(c.isUpper? c.lowercased() : c.uppercased())
} else {
result.append(c)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
Answer:
```swift
func solve(s: String) -> String {
var result = ""
for c in s {
if c.isLetter {
result.append(c.isUpper? c.lowercased() : c.uppercased())
} else {
result.append(c)
}
}
return result
}
```result.append(c.isUpper? c.lowercased() : c.uppercased()) // type of expression is ambiguous without a type annotationresult.append(c.isUpper? c.lowercased() : c.uppercased()) // expected ',' separatorfunc solve(s: String) -> String {
var result = ""
for character in s {
if character.isLetter {
result.append(character.isUpper? character.lowercased() : character.uppercased())
} else {
result.append(character)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
Answer:
```swift
func solve(s: String) -> String {
var result = ""
for character in s {
if character.isLetter {
result.append(character.isUpper? character.lowercased() : character.uppercased())
} else {
result.append(character)
}
}
return result
}
```result.append(character.isUpper? character.lowercased() : character.uppercased()) // expected ',' separatorresult.append(character.isUpper? character.lowercased() : character.uppercased()) // type of expression is ambiguous without a type annotationfunc solve(s: String) -> String {
var result = ""
for character in s {
if character.isLetter {
result.append(character.isUpper? character.lowercased() : character.uppercased())
} else {
result.append(character)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
Answer:
```swift
func solve(s: String) -> String {
var result = ""
for character in s {
if character.isLetter {
result.append(character.isUpper? character.lowercased() : character.uppercased())
} else {
result.append(character)
}
}
return result
}
```result.append(character.isUpper? character.lowercased() : character.uppercased()) // expected ',' separatorresult.append(character.isUpper? character.lowercased() : character.uppercased()) // type of expression is ambiguous without a type annotationimport CommonCrypto
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else {
return nil
}
let data = text.data(using:.utf8)!
let md5 = data.md5()
let hexString = md5.map { String(format: "%02.2hhx", arguments: [$0]) }.joined()
return hexString
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
Answer:
```swift
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else {
return nil
}
let data = text.data(using:.utf8)!
let md5 = data.md5()
let hexString = md5.map { String(format: "%02.2hhx", arguments: [$0]) }.joined()
return hexString
}
```guard!text.isEmpty else { // expected expression, var, let or case in 'guard' conditionlet md5 = data.md5() // value of type 'Data' has no member 'md5'import CommonCrypto
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else {
return nil
}
let data = text.data(using:.utf8)!
let md5 = data.md5()
return md5.description
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
Answer:
```swift
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else {
return nil
}
let data = text.data(using:.utf8)!
let md5 = data.md5()
return md5.description
}
```guard!text.isEmpty else { // expected expression, var, let or case in 'guard' conditionlet md5 = data.md5() // value of type 'Data' has no member 'md5'import CommonCrypto
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else {
return nil
}
let data = text.data(using:.utf8)!
let md5 = data.md5()
return md5.hexString
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
Answer:
```swift
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else {
return nil
}
let data = text.data(using:.utf8)!
let md5 = data.md5()
return md5.hexString
}
```guard!text.isEmpty else { // expected expression, var, let or case in 'guard' conditionlet md5 = data.md5() // value of type 'Data' has no member 'md5'import CommonCrypto
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else {
return nil
}
let data = text.data(using:.utf8)!
let hash = data.md5()
return hash.description
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
Answer:
```swift
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else {
return nil
}
let data = text.data(using:.utf8)!
let hash = data.md5()
return hash.description
}
```guard!text.isEmpty else { // expected expression, var, let or case in 'guard' conditionlet hash = data.md5() // value of type 'Data' has no member 'md5'import CommonCrypto
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else {
return nil
}
let data = text.data(using:.utf8)!
let md5 = data.md5()
let hexString = md5.map { String(format: "%02.2hhx", arguments: [$0]) }.joined()
return hexString
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
Answer:
```swift
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else {
return nil
}
let data = text.data(using:.utf8)!
let md5 = data.md5()
let hexString = md5.map { String(format: "%02.2hhx", arguments: [$0]) }.joined()
return hexString
}
```guard!text.isEmpty else { // expected expression, var, let or case in 'guard' conditionlet md5 = data.md5() // value of type 'Data' has no member 'md5'import CommonCrypto
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else {
return nil
}
let data = text.data(using:.utf8)!
let md5 = data.md5()
let hexString = md5.map { String(format: "%02.2hhx", arguments: [$0]) }.joined()
return hexString
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
Answer:
```swift
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else {
return nil
}
let data = text.data(using:.utf8)!
let md5 = data.md5()
let hexString = md5.map { String(format: "%02.2hhx", arguments: [$0]) }.joined()
return hexString
}
```guard!text.isEmpty else { // expected expression, var, let or case in 'guard' conditionlet md5 = data.md5() // value of type 'Data' has no member 'md5'import CommonCrypto
func stringToMd5(text: String) -> String? {
guard let data = text.data(using:.utf8) else {
return nil
}
let md5 = data.md5()
return md5.description
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
Answer:
```swift
func stringToMd5(text: String) -> String? {
guard let data = text.data(using:.utf8) else {
return nil
}
let md5 = data.md5()
return md5.description
}
```let md5 = data.md5() // value of type 'Data' has no member 'md5'import CommonCrypto
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else {
return nil
}
let data = text.data(using:.utf8)!
let hash = data.md5()
let hexString = hash.description
return hexString
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
Answer:
```swift
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else {
return nil
}
let data = text.data(using:.utf8)!
let hash = data.md5()
let hexString = hash.description
return hexString
}
```guard!text.isEmpty else { // expected expression, var, let or case in 'guard' conditionlet hash = data.md5() // value of type 'Data' has no member 'md5'import CommonCrypto
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else {
return nil
}
let data = text.data(using:.utf8)!
let md5 = data.md5()
let hexString = md5.map { String(format: "%02.2hhx", arguments: [$0]) }.joined()
return hexString
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
Answer:
```swift
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else {
return nil
}
let data = text.data(using:.utf8)!
let md5 = data.md5()
let hexString = md5.map { String(format: "%02.2hhx", arguments: [$0]) }.joined()
return hexString
}
```guard!text.isEmpty else { // expected expression, var, let or case in 'guard' conditionlet md5 = data.md5() // value of type 'Data' has no member 'md5'import CommonCrypto
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else {
return nil
}
let data = text.data(using:.utf8)!
let md5 = data.md5()
let hexString = md5.map { String(format: "%02.2hhx", arguments: [$0]) }.joined()
return hexString
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
Answer:
```swift
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else {
return nil
}
let data = text.data(using:.utf8)!
let md5 = data.md5()
let hexString = md5.map { String(format: "%02.2hhx", arguments: [$0]) }.joined()
return hexString
}
```guard!text.isEmpty else { // expected expression, var, let or case in 'guard' conditionlet md5 = data.md5() // value of type 'Data' has no member 'md5'func generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
for i in a...b {
let string = String(i)
let evenDigits = string.filter { $0.isDigit && Int($0) % 2 == 0 }
let intValue = Int(evenDigits.description)
if let intValue = intValue {
result.append(intValue)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
Answer:
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
for i in a...b {
let string = String(i)
let evenDigits = string.filter { $0.isDigit && Int($0) % 2 == 0 }
let intValue = Int(evenDigits.description)
if let intValue = intValue {
result.append(intValue)
}
}
return result
}
```let evenDigits = string.filter { $0.isDigit && Int($0) % 2 == 0 } // trailing closure passed to parameter of type 'Predicate<String.Element>' (aka 'Predicate<Character>') that does not accept a closurefunc generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
for i in a...b {
let string = String(i)
let evenDigits = string.filter { $0.isDigit && Int($0) % 2 == 0 }
let evenDigitsInt = evenDigits.map { Int($0)! }
result.append(contentsOf: evenDigitsInt)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
Answer:
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
for i in a...b {
let string = String(i)
let evenDigits = string.filter { $0.isDigit && Int($0) % 2 == 0 }
let evenDigitsInt = evenDigits.map { Int($0)! }
result.append(contentsOf: evenDigitsInt)
}
return result
}
```let evenDigits = string.filter { $0.isDigit && Int($0) % 2 == 0 } // trailing closure passed to parameter of type 'Predicate<String.Element>' (aka 'Predicate<Character>') that does not accept a closurefunc generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
for i in a...b {
let string = String(i)
let evenDigits = string.filter { $0.isDigit && Int($0) % 2 == 0 }
let intValue = Int(evenDigits)
if let intValue = intValue {
result.append(intValue)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
Answer:
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
for i in a...b {
let string = String(i)
let evenDigits = string.filter { $0.isDigit && Int($0) % 2 == 0 }
let intValue = Int(evenDigits)
if let intValue = intValue {
result.append(intValue)
}
}
return result
}
```let evenDigits = string.filter { $0.isDigit && Int($0) % 2 == 0 } // trailing closure passed to parameter of type 'Predicate<String.Element>' (aka 'Predicate<Character>') that does not accept a closurefunc generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
for i in a...b {
let string = String(i)
let evenDigits = string.filter { $0.isDigit && Int($0) % 2 == 0 }
let intValue = Int(evenDigits.description)
if let intValue = intValue {
result.append(intValue)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
Answer:
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
for i in a...b {
let string = String(i)
let evenDigits = string.filter { $0.isDigit && Int($0) % 2 == 0 }
let intValue = Int(evenDigits.description)
if let intValue = intValue {
result.append(intValue)
}
}
return result
}
```let evenDigits = string.filter { $0.isDigit && Int($0) % 2 == 0 } // trailing closure passed to parameter of type 'Predicate<String.Element>' (aka 'Predicate<Character>') that does not accept a closurefunc generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
for i in a...b {
let string = String(i)
let evenDigits = string.filter { $0.isDigit && Int($0) % 2 == 0 }
let evenDigitsInt = evenDigits.map { Int($0)! }
result.append(contentsOf: evenDigitsInt)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
Answer:
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
for i in a...b {
let string = String(i)
let evenDigits = string.filter { $0.isDigit && Int($0) % 2 == 0 }
let evenDigitsInt = evenDigits.map { Int($0)! }
result.append(contentsOf: evenDigitsInt)
}
return result
}
```let evenDigits = string.filter { $0.isDigit && Int($0) % 2 == 0 } // trailing closure passed to parameter of type 'Predicate<String.Element>' (aka 'Predicate<Character>') that does not accept a closurefunc generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
for i in a...b {
let string = String(i)
let evenDigits = string.filter { $0.isDigit && Int($0) % 2 == 0 }
let intValue = Int(evenDigits)
if let intValue = intValue {
result.append(intValue)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
Answer:
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
for i in a...b {
let string = String(i)
let evenDigits = string.filter { $0.isDigit && Int($0) % 2 == 0 }
let intValue = Int(evenDigits)
if let intValue = intValue {
result.append(intValue)
}
}
return result
}
```let evenDigits = string.filter { $0.isDigit && Int($0) % 2 == 0 } // trailing closure passed to parameter of type 'Predicate<String.Element>' (aka 'Predicate<Character>') that does not accept a closurefunc generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
for i in a...b {
if i % 2 == 0 {
result.append(i)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
Answer:
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
for i in a...b {
if i % 2 == 0 {
result.append(i)
}
}
return result
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
for i in a...b {
let string = String(i)
let evenDigits = string.filter { $0.isDigit && Int($0) % 2 == 0 }
let evenDigitsInt = evenDigits.map { Int($0)! }
result.append(contentsOf: evenDigitsInt)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
Answer:
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
for i in a...b {
let string = String(i)
let evenDigits = string.filter { $0.isDigit && Int($0) % 2 == 0 }
let evenDigitsInt = evenDigits.map { Int($0)! }
result.append(contentsOf: evenDigitsInt)
}
return result
}
```let evenDigits = string.filter { $0.isDigit && Int($0) % 2 == 0 } // trailing closure passed to parameter of type 'Predicate<String.Element>' (aka 'Predicate<Character>') that does not accept a closurefunc generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
for i in a...b {
let string = String(i)
let evenDigits = string.filter { $0.isDigit && Int($0) % 2 == 0 }
let intValue = Int(evenDigits.description)
if let value = intValue {
result.append(value)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
Answer:
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
for i in a...b {
let string = String(i)
let evenDigits = string.filter { $0.isDigit && Int($0) % 2 == 0 }
let intValue = Int(evenDigits.description)
if let value = intValue {
result.append(value)
}
}
return result
}
```let evenDigits = string.filter { $0.isDigit && Int($0) % 2 == 0 } // trailing closure passed to parameter of type 'Predicate<String.Element>' (aka 'Predicate<Character>') that does not accept a closurefunc generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
for i in a...b {
if i % 2 == 0 {
result.append(i)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
Answer:
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
for i in a...b {
if i % 2 == 0 {
result.append(i)
}
}
return result
}
``` // Fatal error: Range requires lowerBound <= upperBound