func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        if abs(numbers[i] - numbers[i+1]) <= threshold {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        if abs(numbers[i] - numbers[i+1]) <= threshold {
            return true
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        if numbers[i+1] - numbers[i] < threshold {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        if numbers[i+1] - numbers[i] < threshold {
            return true
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        if numbers[i+1] - numbers[i] < threshold {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        if numbers[i+1] - numbers[i] < threshold {
            return true
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        if numbers[i+1] - numbers[i] < threshold {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        if numbers[i+1] - numbers[i] < threshold {
            return true
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        if numbers[i+1] - numbers[i] < threshold {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        if numbers[i+1] - numbers[i] < threshold {
            return true
        }
    }
    return false
}
```
### Inst

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        if numbers[i+1] - numbers[i] < threshold {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        if numbers[i+1] - numbers[i] < threshold {
            return true
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        if abs(numbers[i] - numbers[i+1]) <= threshold {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        if abs(numbers[i] - numbers[i+1]) <= threshold {
            return true
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        if numbers[i+1] - numbers[i] < threshold {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        if numbers[i+1] - numbers[i] < threshold {
            return true
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        if abs(numbers[i] - numbers[i+1]) <= threshold {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        if abs(numbers[i] - numbers[i+1]) <= threshold {
            return true
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        if numbers[i+1] - numbers[i] < threshold {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
### Response:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        if numbers[i+1] - numbers[i] < threshold {
            return true
        }
    }
    return false
}
```

func separateParenGroups(parenString: String) -> [String] {
    var groups: [String] = []
    var currentGroup: String = ""
    var openParens: Int = 0
    for char in parenString {
        if char == "(" {
            openParens += 1
            currentGroup += String(char)
        } else if char == ")" {
            openParens -= 1
            currentGroup += String(char)
            if openParens == 0 {
                groups.append(currentGroup)
                currentGroup = ""
            }
        }
    }
    return groups
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var groups: [String] = []
    var currentGroup: String = ""
    var openParens: Int = 0
    for char in parenString {
        if char == "(" {
            openParens += 1
            currentGroup += String(char)
        } else if char == ")" {
            openParens -= 1
            currentGroup += String(char)
            if openParens == 0 {
                groups.append(currentGroup)
                currentGroup = ""
            }
        }
    }
    return groups
}
```
### Link

func separateParenGroups(parenString: String) -> [String] {
    var groups: [String] = []
    var currentGroup: String = ""
    var isInGroup: Bool = false
    for char in parenString {
        if char == "(" {
            isInGroup = true
            currentGroup.append(char)
        } else if char == ")" {
            isInGroup = false
            currentGroup.append(char)
            groups.append(currentGroup)
            currentGroup = ""
        } else if isInGroup {
            currentGroup.append(char)
        }
    }
    return groups
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var groups: [String] = []
    var currentGroup: String = ""
    var isInGroup: Bool = false
    for char in parenString {
        if char == "(" {
            isInGroup = true
            currentGroup.append(char)
        } else if char == ")" {
            isInGroup = false
            currentGroup.append(char)
            groups.append(currentGroup)
            currentGroup = ""
        } else if isInGroup {
            currentGroup.append(char)
        }
    }
    return groups
}
```

func separateParenGroups(parenString: String) -> [String] {
    var groups = [String]()
    var currentGroup = ""
    var isInGroup = false
    for char in parenString {
        if char == "(" {
            isInGroup = true
            currentGroup += String(char)
        } else if char == ")" {
            isInGroup = false
            currentGroup += String(char)
            groups.append(currentGroup)
            currentGroup = ""
        } else if isInGroup {
            currentGroup += String(char)
        }
    }
    return groups
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var groups = [String]()
    var currentGroup = ""
    var isInGroup = false
    for char in parenString {
        if char == "(" {
            isInGroup = true
            currentGroup += String(char)
        } else if char == ")" {
            isInGroup = false
            currentGroup += String(char)
            groups.append(currentGroup)
            currentGroup = ""
        } else if isInGroup {
            currentGroup += String(char)
        }
    }
    return groups
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var currentGroup = ""
    var isInGroup = false
    for char in parenString {
        if char == "(" {
            if isInGroup {
                currentGroup += String(char)
            } else {
                currentGroup = String(char)
                isInGroup = true
            }
        } else if char == ")" {
            currentGroup += String(char)
            result.append(currentGroup)
            currentGroup = ""
            isInGroup = false
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var currentGroup = ""
    var isInGroup = false
    for char in parenString {
        if char == "(" {
            if isInGroup {
                currentGroup += String(char)
            } else {
                currentGroup = String(char)
                isInGroup = true
            }
        } else if char == ")" {
            currentGroup += String(char)
            result.append(currentGroup)
            currentGroup = ""
            isInGroup = false
        }
    }
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup: String = ""
    var currentChar: Character = " "
    var openParenCount: Int = 0
    var closeParenCount: Int = 0
    for char in parenString {
        if char == "(" {
            openParenCount += 1
        } else if char == ")" {
            closeParenCount += 1
        }
        if openParenCount == closeParenCount {
            result.append(currentGroup)
            currentGroup = ""
            openParenCount = 0
            closeParenCount = 0
        } else {
            currentGroup += String(char)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup: String = ""
    var currentChar: Character = " "
    var openParenCount: Int = 0
    var closeParenCount: Int = 0
    for char in parenString {
        if char == "(" {
            openParenCount += 1
        } else if char == ")" {
            closeParenCount += 1
        }
        if openParenCount == closeParenCount {
            result.append(currentGroup)
            currentGroup = ""
            openParenCount = 0
            closeParenCount = 0
        } else {
            currentGroup += String(char)
        }
    }
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var groups = [String]()
    var currentGroup = ""
    var isInGroup = false
    for char in parenString {
        if char == "(" {
            isInGroup = true
            currentGroup.append(char)
        } else if char == ")" {
            isInGroup = false
            currentGroup.append(char)
            groups.append(currentGroup)
            currentGroup = ""
        } else if isInGroup {
            currentGroup.append(char)
        }
    }
    return groups
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var groups = [String]()
    var currentGroup = ""
    var isInGroup = false
    for char in parenString {
        if char == "(" {
            isInGroup = true
            currentGroup.append(char)
        } else if char == ")" {
            isInGroup = false
            currentGroup.append(char)
            groups.append(currentGroup)
            currentGroup = ""
        } else if isInGroup {
            currentGroup.append(char)
        }
    }
    return groups
}
```

func separateParenGroups(parenString: String) -> [String] {
    var groups = [String]()
    var currentGroup = ""
    var openCount = 0
    for char in parenString {
        if char == "(" {
            openCount += 1
            currentGroup.append(char)
        } else if char == ")" {
            openCount -= 1
            currentGroup.append(char)
            if openCount == 0 {
                groups.append(currentGroup)
                currentGroup = ""
            }
        }
    }
    return groups
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var groups = [String]()
    var currentGroup = ""
    var openCount = 0
    for char in parenString {
        if char == "(" {
            openCount += 1
            currentGroup.append(char)
        } else if char == ")" {
            openCount -= 1
            currentGroup.append(char)
            if openCount == 0 {
                groups.append(currentGroup)
                currentGroup = ""
            }
        }
    }
    return groups
}
```

func separateParenGroups(parenString: String) -> [String] {
    var groups = [String]()
    var group = ""
    var balance = 0
    for char in parenString {
        if char == "(" {
            balance += 1
            group.append(char)
        } else if char == ")" {
            balance -= 1
            group.append(char)
            if balance == 0 {
                groups.append(group)
                group = ""
            }
        }
    }
    return groups
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var groups = [String]()
    var group = ""
    var balance = 0
    for char in parenString {
        if char == "(" {
            balance += 1
            group.append(char)
        } else if char == ")" {
            balance -= 1
            group.append(char)
            if balance == 0 {
                groups.append(group)
                group = ""
            }
        }
    }
    return groups
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup: String = ""
    var currentChar: Character = " "
    var isOpen: Bool = false
    var isClose: Bool = false
    var isBalanced: Bool = true
    for char in parenString {
        if char == "(" {
            isOpen = true
        } else if char == ")" {
            isClose = true
        }
        if isOpen {
            currentGroup.append(char)
            isOpen = false
        } else if isClose {
            currentGroup.append(char)
            isClose = false
        }
        if currentGroup.count > 0 {
            if currentGroup.first == "(" && currentGroup.last == ")" {
                result.append(currentGroup)
                currentGroup = ""
            } else {
                isBalanced = false
            }
        }
    }
    if isBalanced {
        return result
    } else {
        return []
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup: String = ""
    var currentChar: Character = " "
    var isOpen: Bool = false
    var isClose: Bool = false
    var isBalanced: Bool = true
    for char in parenString {
        if char == "(" {
            isOpen = true
        } else if char == ")" {
            isClose = true
        }
        if isOpen {
            currentGroup.append(char)
            isOpen = false
        } else if isClose {
            currentGroup.append(char)
            isClose = false
        }
        if currentGroup.count > 0 {
            if currentGroup.first == "(" && currentGroup.last == ")" {
                result.append(currentGroup)
                currentGroup = ""
            } else {
                isBalanced = false
            }
        }
    }
    if isBalanced {
        return result
    } else {
        return []
    }
}
```

func separateParenGroups(parenString: String) -> [String] {
    var groups = [String]()
    var currentGroup = ""
    var openParens = 0
    for char in parenString {
        if char == "(" {
            openParens += 1
            currentGroup.append(char)
        } else if char == ")" {
            openParens -= 1
            currentGroup.append(char)
            if openParens == 0 {
                groups.append(currentGroup)
                currentGroup = ""
            }
        }
    }
    return groups
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
### Response:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var groups = [String]()
    var currentGroup = ""
    var openParens = 0
    for char in parenString {
        if char == "(" {
            openParens += 1
            currentGroup.append(char)
        } else if char == ")" {
            openParens -= 1
            currentGroup.append(char)
            if openParens == 0 {
                groups.append(currentGroup)
                currentGroup = ""
            }
        }
    }
    return groups
}
```

func truncateNumber(number: Double) -> Double {
    return number.truncatingRemainder(dividingBy: 1)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    return number.truncatingRemainder(dividingBy: 1)
}
```

func truncateNumber(number: Double) -> Double {
    return number.truncatingRemainder(dividingBy: 1)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    return number.truncatingRemainder(dividingBy: 1)
}
```
### Test

func truncateNumber(number: Double) -> Double {
    return number.truncatingRemainder(dividingBy: 1)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    return number.truncatingRemainder(dividingBy: 1)
}
```

func truncateNumber(number: Double) -> Double {
    return number.truncatingRemainder(dividingBy: 1)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    return number.truncatingRemainder(dividingBy: 1)
}
```
### Test

func truncateNumber(number: Double) -> Double {
    return number.truncatingRemainder(dividingBy: 1)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    return number.truncatingRemainder(dividingBy: 1)
}
```

func truncateNumber(number: Double) -> Double {
    return number.truncatingRemainder(dividingBy: 1)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    return number.truncatingRemainder(dividingBy: 1)
}
```
### Test

func truncateNumber(number: Double) -> Double {
    return number.truncatingRemainder(dividingBy: 1)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    return number.truncatingRemainder(dividingBy: 1)
}
```
### Test

func truncateNumber(number: Double) -> Double {
    return number.truncatingRemainder(dividingBy: 1)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    return number.truncatingRemainder(dividingBy: 1)
}
```
### Test

func truncateNumber(number: Double) -> Double {
    return number.truncatingRemainder(dividingBy: 1)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    return number.truncatingRemainder(dividingBy: 1)
}
```

func truncateNumber(number: Double) -> Double {
    return number.truncatingRemainder(dividingBy: 1)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
### Response:
```swift
func truncateNumber(number: Double) -> Double {
    return number.truncatingRemainder(dividingBy: 1)
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```
### Test

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```
### Link

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```
### Test

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```
### Test

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```
### Test

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```
### Link

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```
### Test

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```
### Test

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```
### Link

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
### Response:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```
### Test

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.map { abs($0 - mean) }.reduce(0, +) / Double(numbers.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.map { abs($0 - mean) }.reduce(0, +) / Double(numbers.count)
}
```
### Test

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.map { abs($0 - mean) }.reduce(0, +) / Double(numbers.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.map { abs($0 - mean) }.reduce(0, +) / Double(numbers.count)
}
```
### Test

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    guard numbers.count > 0 else { return 0 }
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let deviations = numbers.map { abs($0 - mean) }
    return deviations.reduce(0, +) / Double(deviations.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    guard numbers.count > 0 else { return 0 }
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let deviations = numbers.map { abs($0 - mean) }
    return deviations.reduce(0, +) / Double(deviations.count)
}
```
### Test

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let deviations = numbers.map { abs($0 - mean) }
    return deviations.reduce(0, +) / Double(deviations.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let deviations = numbers.map { abs($0 - mean) }
    return deviations.reduce(0, +) / Double(deviations.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.map { abs($0 - mean) }.reduce(0, +) / Double(numbers.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.map { abs($0 - mean) }.reduce(0, +) / Double(numbers.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let deviation = numbers.map { abs($0 - mean) }
    return deviation.reduce(0, +) / Double(deviation.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let deviation = numbers.map { abs($0 - mean) }
    return deviation.reduce(0, +) / Double(deviation.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let deviations = numbers.map { abs($0 - mean) }
    return deviations.reduce(0, +) / Double(deviations.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let deviations = numbers.map { abs($0 - mean) }
    return deviations.reduce(0, +) / Double(deviations.count)
}
```
### Inst

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.map { abs($0 - mean) }.reduce(0, +) / Double(numbers.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.map { abs($0 - mean) }.reduce(0, +) / Double(numbers.count)
}
```
### Test

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.map { abs($0 - mean) }.reduce(0, +) / Double(numbers.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    return numbers.map { abs($0 - mean) }.reduce(0, +) / Double(numbers.count)
}
```
### Test

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let deviations = numbers.map { abs($0 - mean) }
    return deviations.reduce(0, +) / Double(deviations.count)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
### Response:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let deviations = numbers.map { abs($0 - mean) }
    return deviations.reduce(0, +) / Double(deviations.count)
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for i in 0..<numbers.count {
        result.append(numbers[i])
        if i < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for i in 0..<numbers.count {
        result.append(numbers[i])
        if i < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for i in 0..<numbers.count {
        if i > 0 {
            result.append(delimeter)
        }
        result.append(numbers[i])
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for i in 0..<numbers.count {
        if i > 0 {
            result.append(delimeter)
        }
        result.append(numbers[i])
    }
    return result
}
```
### Inst

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for i in 0..<numbers.count {
        if i != 0 {
            result.append(delimeter)
        }
        result.append(numbers[i])
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for i in 0..<numbers.count {
        if i != 0 {
            result.append(delimeter)
        }
        result.append(numbers[i])
    }
    return result
}
```
### Inst

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for i in 0..<numbers.count {
        result.append(numbers[i])
        if i < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for i in 0..<numbers.count {
        result.append(numbers[i])
        if i < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for i in 0..<numbers.count {
        result.append(numbers[i])
        if i != numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for i in 0..<numbers.count {
        result.append(numbers[i])
        if i != numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```
### Inst

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for i in 0..<numbers.count {
        if i != 0 {
            result.append(delimeter)
        }
        result.append(numbers[i])
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for i in 0..<numbers.count {
        if i != 0 {
            result.append(delimeter)
        }
        result.append(numbers[i])
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for i in 0..<numbers.count {
        result.append(numbers[i])
        if i < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for i in 0..<numbers.count {
        result.append(numbers[i])
        if i < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for i in 0..<numbers.count {
        result.append(numbers[i])
        if i < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for i in 0..<numbers.count {
        result.append(numbers[i])
        if i < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for i in 0..<numbers.count {
        result.append(numbers[i])
        if i < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
### Response:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for i in 0..<numbers.count {
        result.append(numbers[i])
        if i < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    let parenString = parenString.replacingOccurrences(of: " ", with: "")
    var stack = [Character]()
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            stack.removeLast()
        }
    }
    result.append(stack.count)
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    let parenString = parenString.replacingOccurrences(of: " ", with: "")
    var stack = [Character]()
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            stack.removeLast()
        }
    }
    result.append(stack.count)
    return result
}
```
### Link

func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    for group in parenString.components(separatedBy: " ") {
        var level = 0
        for char in group {
            if char == "(" {
                level += 1
            } else if char == ")" {
                level -= 1
            }
        }
        result.append(level)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    for group in parenString.components(separatedBy: " ") {
        var level = 0
        for char in group {
            if char == "(" {
                level += 1
            } else if char == ")" {
                level -= 1
            }
        }
        result.append(level)
    }
    return result
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var stack = [Int]()
    for char in parenString {
        if char == "(" {
            stack.append(1)
        } else if char == ")" {
            stack.removeLast()
            result.append(stack.count)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var stack = [Int]()
    for char in parenString {
        if char == "(" {
            stack.append(1)
        } else if char == ")" {
            stack.removeLast()
            result.append(stack.count)
        }
    }
    return result
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var stack = [Int]()
    var count = 0
    for char in parenString {
        if char == "(" {
            stack.append(count)
            count += 1
        } else if char == ")" {
            count -= 1
            stack.removeLast()
        }
    }
    result = stack
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    var stack = [Int]()
    var count = 0
    for char in parenString {
        if char == "(" {
            stack.append(count)
            count += 1
        } else if char == ")" {
            count -= 1
            stack.removeLast()
        }
    }
    result = stack
    return result
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    let parenString = parenString.replacingOccurrences(of: " ", with: "")
    var stack = [Character]()
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            stack.removeLast()
        }
    }
    result.append(stack.count)
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    let parenString = parenString.replacingOccurrences(of: " ", with: "")
    var stack = [Character]()
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            stack.removeLast()
        }
    }
    result.append(stack.count)
    return result
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var stack = [Int]()
    var maxDepth = 0
    var currentDepth = 0
    for char in parenString {
        if char == "(" {
            stack.append(currentDepth)
            currentDepth += 1
            maxDepth = max(maxDepth, currentDepth)
        } else if char == ")" {
            currentDepth = stack.removeLast()
        }
    }
    return stack
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var stack = [Int]()
    var maxDepth = 0
    var currentDepth = 0
    for char in parenString {
        if char == "(" {
            stack.append(currentDepth)
            currentDepth += 1
            maxDepth = max(maxDepth, currentDepth)
        } else if char == ")" {
            currentDepth = stack.removeLast()
        }
    }
    return stack
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var result: [Int] = []
    let parenString = parenString.replacingOccurrences(of: " ", with: "")
    var stack: [Character] = []
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            stack.removeLast()
        }
    }
    result.append(stack.count)
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result: [Int] = []
    let parenString = parenString.replacingOccurrences(of: " ", with: "")
    var stack: [Character] = []
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            stack.removeLast()
        }
    }
    result.append(stack.count)
    return result
}
```
### Link

func parseNestedParens(parenString: String) -> [Int] {
    var result: [Int] = []
    let parenString = parenString.replacingOccurrences(of: " ", with: "")
    var stack: [Character] = []
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            stack.removeLast()
        }
    }
    result.append(stack.count)
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result: [Int] = []
    let parenString = parenString.replacingOccurrences(of: " ", with: "")
    var stack: [Character] = []
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            stack.removeLast()
        }
    }
    result.append(stack.count)
    return result
}
```
### Link

func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    for group in parenString.components(separatedBy: " ") {
        var count = 0
        for char in group {
            if char == "(" {
                count += 1
            } else if char == ")" {
                count -= 1
            }
        }
        result.append(count)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    for group in parenString.components(separatedBy: " ") {
        var count = 0
        for char in group {
            if char == "(" {
                count += 1
            } else if char == ")" {
                count -= 1
            }
        }
        result.append(count)
    }
    return result
}
```
### Link

func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    let parenString = parenString.replacingOccurrences(of: " ", with: "")
    var stack = [Character]()
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            stack.removeLast()
        }
    }
    result.append(stack.count)
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
### Response:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var result = [Int]()
    let parenString = parenString.replacingOccurrences(of: " ", with: "")
    var stack = [Character]()
    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            stack.removeLast()
        }
    }
    result.append(stack.count)
    return result
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```
### Inst

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```
### Inst

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
### Response:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```
### Test

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```
### Test

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```
### Test

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
### Response:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = numbers[0]
    for number in numbers {
        max = max > number ? max : number
        result.append(max)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = numbers[0]
    for number in numbers {
        max = max > number ? max : number
        result.append(max)
    }
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var maxValue = numbers[0]
    for number in numbers {
        maxValue = max(maxValue, number)
        result.append(maxValue)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var maxValue = numbers[0]
    for number in numbers {
        maxValue = max(maxValue, number)
        result.append(maxValue)
    }
    return result
}
```
### Link

func rollingMax(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var maxValue = numbers[0]
    for number in numbers {
        maxValue = max(maxValue, number)
        result.append(maxValue)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var maxValue = numbers[0]
    for number in numbers {
        maxValue = max(maxValue, number)
        result.append(maxValue)
    }
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = numbers[0]
    for i in 1..<numbers.count {
        if numbers[i] > max {
            max = numbers[i]
        }
        result.append(max)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = numbers[0]
    for i in 1..<numbers.count {
        if numbers[i] > max {
            max = numbers[i]
        }
        result.append(max)
    }
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = numbers[0]
    for number in numbers {
        max = max > number ? max : number
        result.append(max)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = numbers[0]
    for number in numbers {
        max = max > number ? max : number
        result.append(max)
    }
    return result
}
```
### Inst

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = numbers[0]
    for number in numbers {
        max = max > number ? max : number
        result.append(max)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = numbers[0]
    for number in numbers {
        max = max > number ? max : number
        result.append(max)
    }
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = numbers[0]
    for number in numbers {
        max = max > number ? max : number
        result.append(max)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = numbers[0]
    for number in numbers {
        max = max > number ? max : number
        result.append(max)
    }
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = numbers[0]
    for number in numbers {
        max = max > number ? max : number
        result.append(max)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = numbers[0]
    for number in numbers {
        max = max > number ? max : number
        result.append(max)
    }
    return result
}
```
### Link

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = numbers[0]
    for number in numbers {
        max = max > number ? max : number
        result.append(max)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = numbers[0]
    for number in numbers {
        max = max > number ? max : number
        result.append(max)
    }
    return result
}
```
### Link

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = numbers[0]
    for i in 1..<numbers.count {
        if numbers[i] > max {
            max = numbers[i]
        }
        result.append(max)
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
### Response:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = numbers[0]
    for i in 1..<numbers.count {
        if numbers[i] > max {
            max = numbers[i]
        }
        result.append(max)
    }
    return result
}
```

func makePalindrome(string: String) -> String {
    let postfix = longestPalindromicPostfix(string: string)
    let prefix = string.prefix(string.count - postfix.count)
    let reversePrefix = String(prefix.reversed())
    return prefix + postfix + reversePrefix
}

func longestPalindromicPostfix(string: String) -> String {
    var longest = ""
    for i in 0..<string.count {
        let postfix = string.suffix(string.count - i)
        if isPalindrome(string: postfix) && postfix.count > longest.count {
            longest = postfix
        }
    }
    return longest
}

func isPalindrome(string: String) -> Bool {
    return string == String(string.reversed())
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    let postfix = longestPalindromicPostfix(string: string)
    let prefix = string.prefix(string.count - postfix.count)
    let reversePrefix = String(prefix.reversed())
    return prefix + postfix + reversePrefix
}

func longestPalindromicPostfix(string: String) -> String {
    var longest = ""
    for i in 0..<string.count {
        let postfix = string.suffix(string.count - i)
        if isPalindrome(string: postfix) && postfix.count > longest.count {
            longest = postfix
        }
    }
    return longest
}

func isPalindrome(string: String) -> Bool {
    return string == String(string.reversed())
}
```
### Link

func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    let longestPalindrome = string.longestPalindrome()
    return string + String(reversed.dropFirst(string.count - longestPalindrome.count))
}

extension String {
    func longestPalindrome() -> String {
        var longest = ""
        for i in 0..<count {
            let suffix = self[i...]
            let prefix = self[..<i]
            if suffix.isPalindrome && suffix.count > longest.count {
                longest = suffix
            }
            if prefix.isPalindrome && prefix.count > longest.count {
                longest = prefix
            }
        }
        return longest
    }
    
    var isPalindrome: Bool {
        return self == String(reversed())
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    let longestPalindrome = string.longestPalindrome()
    return string + String(reversed.dropFirst(string.count - longestPalindrome.count))
}

extension String {
    func longestPalindrome() -> String {
        var longest = ""
        for i in 0..<count {
            let suffix = self[i...]
            let prefix = self[..<i]
            if suffix.isPalindrome && suffix.count > longest.count {
                longest = suffix
            }
            if prefix.isPalindrome && prefix.count > longest.count {
                longest = prefix
            }
        }
        return longest
    }
    
    var isPalindrome: Bool {
        return self == String(reversed())
    }
}
```
### Link

func makePalindrome(string: String) -> String {
    let postfix = string.reversed()
    let palindromicSuffix = postfix.commonPrefix(with: string)
    let prefix = String(string.dropLast(string.count - palindromicSuffix.count))
    return prefix + postfix
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    let postfix = string.reversed()
    let palindromicSuffix = postfix.commonPrefix(with: string)
    let prefix = String(string.dropLast(string.count - palindromicSuffix.count))
    return prefix + postfix
}
```
### Link

func makePalindrome(string: String) -> String {
    let reverse = String(string.reversed())
    let longestPalindrome = string.longestPalindromicSuffix
    return string + String(reverse.dropFirst(string.count - longestPalindrome.count))
}

extension String {
    var longestPalindromicSuffix: String {
        var longest = ""
        for i in (0...count).reversed() {
            let suffix = self[i...]
            if suffix.isPalindrome {
                longest = suffix
                break
            }
        }
        return longest
    }
}

extension String {
    var isPalindrome: Bool {
        return self == String(reversed())
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    let reverse = String(string.reversed())
    let longestPalindrome = string.longestPalindromicSuffix
    return string + String(reverse.dropFirst(string.count - longestPalindrome.count))
}

extension String {
    var longestPalindromicSuffix: String {
        var longest = ""
        for i in (0...count).reversed() {
            let suffix = self[i...]
            if suffix.isPalindrome {
                longest = suffix
                break
            }
        }
        return longest
    }
}

extension String {
    var isPalindrome: Bool {
        return self == String(reversed())
    }
}
```

func makePalindrome(string: String) -> String {
    let string = String(string.reversed())
    let postfix = string.longestPalindromicPostfix()
    let prefix = string.prefix(string.count - postfix.count)
    return postfix + prefix.reversed()
}

extension String {
    func longestPalindromicPostfix() -> String {
        var longest = ""
        for i in 0..<count {
            let postfix = suffix(i + 1)
            if postfix == postfix.reversed() {
                longest = postfix
            }
        }
        return longest
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    let string = String(string.reversed())
    let postfix = string.longestPalindromicPostfix()
    let prefix = string.prefix(string.count - postfix.count)
    return postfix + prefix.reversed()
}

extension String {
    func longestPalindromicPostfix() -> String {
        var longest = ""
        for i in 0..<count {
            let postfix = suffix(i + 1)
            if postfix == postfix.reversed() {
                longest = postfix
            }
        }
        return longest
    }
}
```

func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    let longestPalindrome = longestPalindrome(string: string)
    return string + reversed.dropFirst(string.count - longestPalindrome.count)
}

func longestPalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    var longest = ""
    for i in 0..<string.count {
        let prefix = String(string.prefix(i))
        if prefix == reversed.suffix(i) {
            longest = prefix
        }
    }
    return longest
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    let longestPalindrome = longestPalindrome(string: string)
    return string + reversed.dropFirst(string.count - longestPalindrome.count)
}

func longestPalindrome(string: String) -> String {
    let reversed = String(string.reversed())
    var longest = ""
    for i in 0..<string.count {
        let prefix = String(string.prefix(i))
        if prefix == reversed.suffix(i) {
            longest = prefix
        }
    }
    return longest
}
```
### Link

func makePalindrome(string: String) -> String {
    var result = string
    var reversed = String(string.reversed())
    var longestPalindrome = ""
    for i in 0..<string.count {
        let postfix = String(string.suffix(string.count - i))
        if postfix == reversed {
            longestPalindrome = postfix
            break
        }
    }
    result.append(String(reversed.dropFirst(longestPalindrome.count)))
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    var result = string
    var reversed = String(string.reversed())
    var longestPalindrome = ""
    for i in 0..<string.count {
        let postfix = String(string.suffix(string.count - i))
        if postfix == reversed {
            longestPalindrome = postfix
            break
        }
    }
    result.append(String(reversed.dropFirst(longestPalindrome.count)))
    return result
}
```
### Link

func makePalindrome(string: String) -> String {
    let palindromicSuffix = longestPalindromicSuffix(string: string)
    let prefix = string.dropLast(palindromicSuffix.count)
    let suffix = palindromicSuffix.reversed()
    return prefix + String(suffix)
}

func longestPalindromicSuffix(string: String) -> String {
    let reversed = string.reversed()
    var suffix = ""
    for (i, char) in reversed.enumerated() {
        if string.hasSuffix(suffix + String(char)) {
            suffix += String(char)
        } else {
            return String(suffix.reversed())
        }
    }
    return String(suffix.reversed())
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    let palindromicSuffix = longestPalindromicSuffix(string: string)
    let prefix = string.dropLast(palindromicSuffix.count)
    let suffix = palindromicSuffix.reversed()
    return prefix + String(suffix)
}

func longestPalindromicSuffix(string: String) -> String {
    let reversed = string.reversed()
    var suffix = ""
    for (i, char) in reversed.enumerated() {
        if string.hasSuffix(suffix + String(char)) {
            suffix += String(char)
        } else {
            return String(suffix.reversed())
        }
    }
    return String(suffix.reversed())
}
```
### Link

func makePalindrome(string: String) -> String {
    let reverse = String(string.reversed())
    let longestPostfix = longestPalindromicPostfix(string: string)
    return string + String(reverse.dropFirst(string.count - longestPostfix.count))
}

func longestPalindromicPostfix(string: String) -> String {
    let reverse = String(string.reversed())
    var longest = ""
    for i in 0..<string.count {
        let prefix = String(string.suffix(string.count - i))
        if prefix == reverse.prefix(prefix.count) {
            longest = prefix
        }
    }
    return longest
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    let reverse = String(string.reversed())
    let longestPostfix = longestPalindromicPostfix(string: string)
    return string + String(reverse.dropFirst(string.count - longestPostfix.count))
}

func longestPalindromicPostfix(string: String) -> String {
    let reverse = String(string.reversed())
    var longest = ""
    for i in 0..<string.count {
        let prefix = String(string.suffix(string.count - i))
        if prefix == reverse.prefix(prefix.count) {
            longest = prefix
        }
    }
    return longest
}
```
### Link

func makePalindrome(string: String) -> String {
    let palindromicSuffix = longestPalindromicSuffix(string: string)
    let prefix = string.dropLast(palindromicSuffix.count)
    let suffix = String(palindromicSuffix.reversed())
    return prefix + suffix
}

func longestPalindromicSuffix(string: String) -> String {
    let length = string.count
    var longest = 0
    var index = 0
    for i in 0..<length {
        let j = length - i
        if j < longest {
            break
        }
        if string[j..<length] == String(string[..<j].reversed()) {
            longest = j
            index = i
        }
    }
    return String(string[index..<index + longest])
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
### Response:
```swift
func makePalindrome(string: String) -> String {
    let palindromicSuffix = longestPalindromicSuffix(string: string)
    let prefix = string.dropLast(palindromicSuffix.count)
    let suffix = String(palindromicSuffix.reversed())
    return prefix + suffix
}

func longestPalindromicSuffix(string: String) -> String {
    let length = string.count
    var longest = 0
    var index = 0
    for i in 0..<length {
        let j = length - i
        if j < longest {
            break
        }
        if string[j..<length] == String(string[..<j].reversed()) {
            longest = j
            index = i
        }
    }
    return String(string[index..<index + longest])
}
```

func stringXor(a: String, b: String) -> String {
    var result = ""
    for (i, c) in a.enumerated() {
        let d = b[i]
        result.append(c == d ? "0" : "1")
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for (i, c) in a.enumerated() {
        let d = b[i]
        result.append(c == d ? "0" : "1")
    }
    return result
}
```

func stringXor(a: String, b: String) -> String {
    let a = a.map { Int(String($0))! }
    let b = b.map { Int(String($0))! }
    let result = zip(a, b).map { $0 ^ $1 }
    return result.map { String($0) }.joined()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    let a = a.map { Int(String($0))! }
    let b = b.map { Int(String($0))! }
    let result = zip(a, b).map { $0 ^ $1 }
    return result.map { String($0) }.joined()
}
```

func stringXor(a: String, b: String) -> String {
    var result = ""
    for (i, c) in a.enumerated() {
        let d = b[i]
        result.append(String(c == d ? "0" : "1"))
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for (i, c) in a.enumerated() {
        let d = b[i]
        result.append(String(c == d ? "0" : "1"))
    }
    return result
}
```

func stringXor(a: String, b: String) -> String {
    var result = ""
    for i in 0..<a.count {
        let aChar = a[a.index(a.startIndex, offsetBy: i)]
        let bChar = b[b.index(b.startIndex, offsetBy: i)]
        if aChar == bChar {
            result.append("0")
        } else {
            result.append("1")
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for i in 0..<a.count {
        let aChar = a[a.index(a.startIndex, offsetBy: i)]
        let bChar = b[b.index(b.startIndex, offsetBy: i)]
        if aChar == bChar {
            result.append("0")
        } else {
            result.append("1")
        }
    }
    return result
}
```

func stringXor(a: String, b: String) -> String {
    var result = ""
    for i in 0..<a.count {
        let aChar = a[a.index(a.startIndex, offsetBy: i)]
        let bChar = b[b.index(b.startIndex, offsetBy: i)]
        if aChar == bChar {
            result.append("0")
        } else {
            result.append("1")
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for i in 0..<a.count {
        let aChar = a[a.index(a.startIndex, offsetBy: i)]
        let bChar = b[b.index(b.startIndex, offsetBy: i)]
        if aChar == bChar {
            result.append("0")
        } else {
            result.append("1")
        }
    }
    return result
}
```

func stringXor(a: String, b: String) -> String {
    var result = ""
    for (index, element) in a.enumerated() {
        let element = element == "1" ? "0" : "1"
        result += element
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for (index, element) in a.enumerated() {
        let element = element == "1" ? "0" : "1"
        result += element
    }
    return result
}
```

func stringXor(a: String, b: String) -> String {
    var result = ""
    for i in 0..<a.count {
        if a[a.index(a.startIndex, offsetBy: i)] == b[b.index(b.startIndex, offsetBy: i)] {
            result += "0"
        } else {
            result += "1"
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    var result = ""
    for i in 0..<a.count {
        if a[a.index(a.startIndex, offsetBy: i)] == b[b.index(b.startIndex, offsetBy: i)] {
            result += "0"
        } else {
            result += "1"
        }
    }
    return result
}
```

func stringXor(a: String, b: String) -> String {
    return String(zip(a, b).map { $0 == $1 ? "0" : "1" })
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    return String(zip(a, b).map { $0 == $1 ? "0" : "1" })
}
```
### Link

func stringXor(a: String, b: String) -> String {
    let a = a.map { Int(String($0))! }
    let b = b.map { Int(String($0))! }
    let result = zip(a, b).map { $0 ^ $1 }
    return result.map { String($0) }.joined()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    let a = a.map { Int(String($0))! }
    let b = b.map { Int(String($0))! }
    let result = zip(a, b).map { $0 ^ $1 }
    return result.map { String($0) }.joined()
}
```

func stringXor(a: String, b: String) -> String {
    return String(a.map { Int(String($0))! ^ Int(String(b[$0]))! })
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
### Response:
```swift
func stringXor(a: String, b: String) -> String {
    return String(a.map { Int(String($0))! ^ Int(String(b[$0]))! })
}
```
### Link

func longest(strings: [String]) -> String? {
    guard let first = strings.first else { return nil }
    return strings.reduce(first) { $0.count > $1.count ? $0 : $1 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    guard let first = strings.first else { return nil }
    return strings.reduce(first) { $0.count > $1.count ? $0 : $1 }
}
```
### Link

func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    var longest = strings[0]
    for i in 1..<strings.count {
        if strings[i].count > longest.count {
            longest = strings[i]
        }
    }
    return longest
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    var longest = strings[0]
    for i in 1..<strings.count {
        if strings[i].count > longest.count {
            longest = strings[i]
        }
    }
    return longest
}
```

func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    var longest = strings[0]
    for string in strings {
        if string.count > longest.count {
            longest = string
        }
    }
    return longest
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    var longest = strings[0]
    for string in strings {
        if string.count > longest.count {
            longest = string
        }
    }
    return longest
}
```

func longest(strings: [String]) -> String? {
    return strings.max()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    return strings.max()
}
```
### Link

func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    return strings.sorted { $0.count > $1.count }.first
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    return strings.sorted { $0.count > $1.count }.first
}
```
### Link

func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    return strings.reduce(strings[0]) { $0.count > $1.count ? $0 : $1 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    return strings.reduce(strings[0]) { $0.count > $1.count ? $0 : $1 }
}
```
### Link

func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    return strings.sorted { $0.count > $1.count }.first
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    return strings.sorted { $0.count > $1.count }.first
}
```

func longest(strings: [String]) -> String? {
    guard let first = strings.first else { return nil }
    return strings.reduce(first) { $0.count > $1.count ? $0 : $1 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    guard let first = strings.first else { return nil }
    return strings.reduce(first) { $0.count > $1.count ? $0 : $1 }
}
```
### Link

func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    var longest = strings[0]
    for i in 1..<strings.count {
        if strings[i].count > longest.count {
            longest = strings[i]
        }
    }
    return longest
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    var longest = strings[0]
    for i in 1..<strings.count {
        if strings[i].count > longest.count {
            longest = strings[i]
        }
    }
    return longest
}
```

func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    var longest = strings[0]
    for string in strings {
        if string.count > longest.count {
            longest = string
        }
    }
    return longest
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
### Response:
```swift
func longest(strings: [String]) -> String? {
    guard !strings.isEmpty else { return nil }
    var longest = strings[0]
    for string in strings {
        if string.count > longest.count {
            longest = string
        }
    }
    return longest
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}
```
### Inst

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
### Response:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b != 0 {
        let temp = b
        b = a % b
        a = temp
    }
    return a
}
```
### Inst

func allPrefixes(string: String) -> [String] {
    return string.prefix(string.count).reversed()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    return string.prefix(string.count).reversed()
}
```
### Inst

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    return string.prefix(string.count).reversed()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    return string.prefix(string.count).reversed()
}
```
### Inst

func allPrefixes(string: String) -> [String] {
    var result: [String] = []
    for i in 0..<string.count {
        result.append(String(string[..<string.index(string.startIndex, offsetBy: i)]))
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    var result: [String] = []
    for i in 0..<string.count {
        result.append(String(string[..<string.index(string.startIndex, offsetBy: i)]))
    }
    return result
}
```
### Inst

func allPrefixes(string: String) -> [String] {
    var result: [String] = []
    for i in 0..<string.count {
        result.append(String(string.prefix(i + 1)))
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    var result: [String] = []
    for i in 0..<string.count {
        result.append(String(string.prefix(i + 1)))
    }
    return result
}
```
### Inst

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}
```
### Inst

func allPrefixes(string: String) -> [String] {
    var result: [String] = []
    for i in 0..<string.count {
        result.append(String(string.prefix(i + 1)))
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    var result: [String] = []
    for i in 0..<string.count {
        result.append(String(string.prefix(i + 1)))
    }
    return result
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 0..<string.count {
        prefixes.append(String(string[..<string.index(string.startIndex, offsetBy: i)]))
    }
    return prefixes
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 0..<string.count {
        prefixes.append(String(string[..<string.index(string.startIndex, offsetBy: i)]))
    }
    return prefixes
}
```
### Inst

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}
```
### Inst

func allPrefixes(string: String) -> [String] {
    var result: [String] = []
    for i in 0..<string.count {
        result.append(String(string.prefix(i + 1)))
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
### Response:
```swift
func allPrefixes(string: String) -> [String] {
    var result: [String] = []
    for i in 0..<string.count {
        result.append(String(string.prefix(i + 1)))
    }
    return result
}
```
### Inst

func stringSequence(n: Int) -> String {
    return (0...n).map { String($0) }.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    return (0...n).map { String($0) }.joined(separator: " ")
}
```
### Link

func stringSequence(n: Int) -> String {
    return (0...n).map { String($0) }.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    return (0...n).map { String($0) }.joined(separator: " ")
}
```
### Link

func stringSequence(n: Int) -> String {
    return (0...n).map(String.init).joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    return (0...n).map(String.init).joined(separator: " ")
}
```
### Link

func stringSequence(n: Int) -> String {
    return (0...n).map(String.init).joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    return (0...n).map(String.init).joined(separator: " ")
}
```
### Link

func stringSequence(n: Int) -> String {
    return (0...n).map(String.init).joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    return (0...n).map(String.init).joined(separator: " ")
}
```
### Link

func stringSequence(n: Int) -> String {
    return (0...n).map { String($0) }.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    return (0...n).map { String($0) }.joined(separator: " ")
}
```
### Link

func stringSequence(n: Int) -> String {
    return (0...n).map { String($0) }.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    return (0...n).map { String($0) }.joined(separator: " ")
}
```
### Link

func stringSequence(n: Int) -> String {
    return (0...n).map(String.init).joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    return (0...n).map(String.init).joined(separator: " ")
}
```
### Link

func stringSequence(n: Int) -> String {
    return (0...n).map(String.init).joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    return (0...n).map(String.init).joined(separator: " ")
}
```

func stringSequence(n: Int) -> String {
    return (0...n).map { String($0) }.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
### Response:
```swift
func stringSequence(n: Int) -> String {
    return (0...n).map { String($0) }.joined(separator: " ")
}
```
### Link

func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}
```
### Test

func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters: Set<Character> = []
    for character in string {
        distinctCharacters.insert(character)
    }
    return distinctCharacters.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters: Set<Character> = []
    for character in string {
        distinctCharacters.insert(character)
    }
    return distinctCharacters.count
}
```
### Test

func countDistinctCharacters(string: String) -> Int {
    return Set(string).count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    return Set(string).count
}
```
### Test

func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}
```
### Test

func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}
```
### Test

func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}
```
### Test

func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters = Set<Character>()
    for character in string {
        distinctCharacters.insert(character)
    }
    return distinctCharacters.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters = Set<Character>()
    for character in string {
        distinctCharacters.insert(character)
    }
    return distinctCharacters.count
}
```
### Test

func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}
```
### Test

func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    return Set(string.lowercased()).count
}
```
### Test

func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters = Set<Character>()
    for character in string {
        distinctCharacters.insert(character)
    }
    return distinctCharacters.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
### Response:
```swift
func countDistinctCharacters(string: String) -> Int {
    var distinctCharacters = Set<Character>()
    for character in string {
        distinctCharacters.insert(character)
    }
    return distinctCharacters.count
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    for note in musicString.split(separator: " ") {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    for note in musicString.split(separator: " ") {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var result = [Int]()
    let notes = musicString.split(separator: " ")
    for note in notes {
        switch note {
        case "o":
            result.append(4)
        case "o|":
            result.append(2)
        case ".|":
            result.append(1)
        default:
            break
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    var result = [Int]()
    let notes = musicString.split(separator: " ")
    for note in notes {
        switch note {
        case "o":
            result.append(4)
        case "o|":
            result.append(2)
        case ".|":
            result.append(1)
        default:
            break
        }
    }
    return result
}
```

func parseMusic(musicString: String) -> [Int] {
    var result: [Int] = []
    for char in musicString {
        switch char {
        case "o":
            result.append(4)
        case "|":
            result.append(2)
        case ".":
            result.append(1)
        default:
            break
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    var result: [Int] = []
    for char in musicString {
        switch char {
        case "o":
            result.append(4)
        case "|":
            result.append(2)
        case ".":
            result.append(1)
        default:
            break
        }
    }
    return result
}
```

func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats: [Int] = []
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats: [Int] = []
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var result: [Int] = []
    for char in musicString {
        switch char {
        case "o":
            result.append(4)
        case "|":
            result.append(2)
        case ".":
            result.append(1)
        default:
            break
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    var result: [Int] = []
    for char in musicString {
        switch char {
        case "o":
            result.append(4)
        case "|":
            result.append(2)
        case ".":
            result.append(1)
        default:
            break
        }
    }
    return result
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats: [Int] = []
    for note in musicString.split(separator: " ") {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats: [Int] = []
    for note in musicString.split(separator: " ") {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var result: [Int] = []
    let notes = musicString.split(separator: " ")
    for note in notes {
        switch note {
        case "o":
            result.append(4)
        case "o|":
            result.append(2)
        case ".|":
            result.append(1)
        default:
            break
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    var result: [Int] = []
    let notes = musicString.split(separator: " ")
    for note in notes {
        switch note {
        case "o":
            result.append(4)
        case "o|":
            result.append(2)
        case ".|":
            result.append(1)
        default:
            break
        }
    }
    return result
}
```

func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    for char in musicString {
        switch char {
        case "o":
            beats.append(4)
        case "|":
            beats.append(2)
        case ".":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    var beats = [Int]()
    for char in musicString {
        switch char {
        case "o":
            beats.append(4)
        case "|":
            beats.append(2)
        case ".":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    var result: [Int] = []
    for char in musicString {
        switch char {
        case "o":
            result.append(4)
        case "|":
            result.append(2)
        case ".":
            result.append(1)
        default:
            break
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    var result: [Int] = []
    for char in musicString {
        switch char {
        case "o":
            result.append(4)
        case "|":
            result.append(2)
        case ".":
            result.append(1)
        default:
            break
        }
    }
    return result
}
```

func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var result = [Int]()
    for note in notes {
        switch note {
        case "o":
            result.append(4)
        case "o|":
            result.append(2)
        case ".|":
            result.append(1)
        default:
            break
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
### Response:
```swift
func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var result = [Int]()
    for note in notes {
        switch note {
        case "o":
            result.append(4)
        case "o|":
            result.append(2)
        case ".|":
            result.append(1)
        default:
            break
        }
    }
    return result
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    while let range = string[index...].range(of: substring) {
        count += 1
        index = range.upperBound
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    while let range = string[index...].range(of: substring) {
        count += 1
        index = range.upperBound
    }
    return count
}
```
### Link

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var i = 0
    while i < string.count {
        if string[i..<i+substring.count] == substring {
            count += 1
            i += substring.count
        } else {
            i += 1
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var i = 0
    while i < string.count {
        if string[i..<i+substring.count] == substring {
            count += 1
            i += substring.count
        } else {
            i += 1
        }
    }
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    while let range = string[index...].range(of: substring) {
        count += 1
        index = range.upperBound
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    while let range = string[index...].range(of: substring) {
        count += 1
        index = range.upperBound
    }
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    while let range = string[index...].range(of: substring) {
        count += 1
        index = range.upperBound
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    while let range = string[index...].range(of: substring) {
        count += 1
        index = range.upperBound
    }
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    while let range = string[index...].range(of: substring) {
        count += 1
        index = range.upperBound
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    while let range = string[index...].range(of: substring) {
        count += 1
        index = range.upperBound
    }
    return count
}
```
### Link

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    while let range = string[index...].range(of: substring) {
        count += 1
        index = range.upperBound
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    while let range = string[index...].range(of: substring) {
        count += 1
        index = range.upperBound
    }
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    while let range = string[index...].range(of: substring) {
        count += 1
        index = range.upperBound
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    while let range = string[index...].range(of: substring) {
        count += 1
        index = range.upperBound
    }
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var i = 0
    while i < string.count {
        if string[string.index(string.startIndex, offsetBy: i)] == substring[substring.startIndex] {
            var j = 0
            while j < substring.count {
                if string[string.index(string.startIndex, offsetBy: i + j)] != substring[substring.index(substring.startIndex, offsetBy: j)] {
                    break
                }
                j += 1
            }
            if j == substring.count {
                count += 1
            }
        }
        i += 1
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var i = 0
    while i < string.count {
        if string[string.index(string.startIndex, offsetBy: i)] == substring[substring.startIndex] {
            var j = 0
            while j < substring.count {
                if string[string.index(string.startIndex, offsetBy: i + j)] != substring[substring.index(substring.startIndex, offsetBy: j)] {
                    break
                }
                j += 1
            }
            if j == substring.count {
                count += 1
            }
        }
        i += 1
    }
    return count
}
```
### Link

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    while let range = string[index...].range(of: substring) {
        index = string.index(range.lowerBound, offsetBy: substring.count)
        count += 1
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    while let range = string[index...].range(of: substring) {
        index = string.index(range.lowerBound, offsetBy: substring.count)
        count += 1
    }
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    while let range = string[index...].range(of: substring) {
        count += 1
        index = range.upperBound
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
### Response:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    while let range = string[index...].range(of: substring) {
        count += 1
        index = range.upperBound
    }
    return count
}
```

func sortNumbers(numbers: String) -> String {
    let sortedNumbers = numbers.components(separatedBy: " ").sorted()
    return sortedNumbers.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    let sortedNumbers = numbers.components(separatedBy: " ").sorted()
    return sortedNumbers.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let sortedNumbers = numbers.split(separator: " ").sorted()
    return sortedNumbers.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    let sortedNumbers = numbers.split(separator: " ").sorted()
    return sortedNumbers.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numbersArray = numbers.split(separator: " ")
    let sortedArray = numbersArray.sorted()
    return sortedArray.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    let numbersArray = numbers.split(separator: " ")
    let sortedArray = numbersArray.sorted()
    return sortedArray.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let sorted = numbers.split(separator: " ").sorted()
    return sorted.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    let sorted = numbers.split(separator: " ").sorted()
    return sorted.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let sorted = numbers.split(separator: " ").sorted()
    return sorted.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    let sorted = numbers.split(separator: " ").sorted()
    return sorted.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numbers = numbers.split(separator: " ")
    let sortedNumbers = numbers.sorted()
    return sortedNumbers.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    let numbers = numbers.split(separator: " ")
    let sortedNumbers = numbers.sorted()
    return sortedNumbers.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let sorted = numbers.split(separator: " ").sorted()
    return sorted.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    let sorted = numbers.split(separator: " ").sorted()
    return sorted.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numbersArray = numbers.split(separator: " ")
    let sortedArray = numbersArray.sorted()
    let sortedString = sortedArray.joined(separator: " ")
    return sortedString
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    let numbersArray = numbers.split(separator: " ")
    let sortedArray = numbersArray.sorted()
    let sortedString = sortedArray.joined(separator: " ")
    return sortedString
}
```

func sortNumbers(numbers: String) -> String {
    let sortedNumbers = numbers.split(separator: " ").sorted()
    return sortedNumbers.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    let sortedNumbers = numbers.split(separator: " ").sorted()
    return sortedNumbers.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numbersArray = numbers.split(separator: " ")
    let sortedNumbers = numbersArray.sorted()
    return sortedNumbers.joined(separator: " ")
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
### Response:
```swift
func sortNumbers(numbers: String) -> String {
    let numbersArray = numbers.split(separator: " ")
    let sortedNumbers = numbersArray.sorted()
    return sortedNumbers.joined(separator: " ")
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closest = (numbers[0], numbers[1])
    for i in 2..<numbers.count {
        if abs(numbers[i] - closest.0) < abs(closest.1 - closest.0) {
            closest.0 = numbers[i]
        } else if abs(numbers[i] - closest.1) < abs(closest.1 - closest.0) {
            closest.1 = numbers[i]
        }
    }
    return closest
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closest = (numbers[0], numbers[1])
    for i in 2..<numbers.count {
        if abs(numbers[i] - closest.0) < abs(closest.1 - closest.0) {
            closest.0 = numbers[i]
        } else if abs(numbers[i] - closest.1) < abs(closest.1 - closest.0) {
            closest.1 = numbers[i]
        }
    }
    return closest
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closest: (Double, Double) = (numbers[0], numbers[1])
    for i in 2..<numbers.count {
        if abs(numbers[i] - closest.0) < abs(closest.1 - closest.0) {
            closest.0 = numbers[i]
        } else if abs(numbers[i] - closest.1) < abs(closest.1 - closest.0) {
            closest.1 = numbers[i]
        }
    }
    return closest
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closest: (Double, Double) = (numbers[0], numbers[1])
    for i in 2..<numbers.count {
        if abs(numbers[i] - closest.0) < abs(closest.1 - closest.0) {
            closest.0 = numbers[i]
        } else if abs(numbers[i] - closest.1) < abs(closest.1 - closest.0) {
            closest.1 = numbers[i]
        }
    }
    return closest
}
```
### Link

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closest: (Double, Double) = (numbers[0], numbers[1])
    for i in 2..<numbers.count {
        if numbers[i] - closest.0 < closest.1 - numbers[i] {
            closest.0 = numbers[i]
        } else {
            closest.1 = numbers[i]
        }
    }
    return closest
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closest: (Double, Double) = (numbers[0], numbers[1])
    for i in 2..<numbers.count {
        if numbers[i] - closest.0 < closest.1 - numbers[i] {
            closest.0 = numbers[i]
        } else {
            closest.1 = numbers[i]
        }
    }
    return closest
}
```
### Link

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closest = (numbers[0], numbers[1])
    for i in 2..<numbers.count {
        if abs(numbers[i] - closest.0) < abs(closest.1 - closest.0) {
            closest.0 = numbers[i]
        } else if abs(numbers[i] - closest.1) < abs(closest.0 - closest.1) {
            closest.1 = numbers[i]
        }
    }
    return closest
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closest = (numbers[0], numbers[1])
    for i in 2..<numbers.count {
        if abs(numbers[i] - closest.0) < abs(closest.1 - closest.0) {
            closest.0 = numbers[i]
        } else if abs(numbers[i] - closest.1) < abs(closest.0 - closest.1) {
            closest.1 = numbers[i]
        }
    }
    return closest
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closest: (Double, Double) = (numbers[0], numbers[1])
    for i in 2..<numbers.count {
        if abs(closest.0 - closest.1) > abs(numbers[i] - closest.1) {
            closest.0 = closest.1
            closest.1 = numbers[i]
        } else if abs(closest.0 - closest.1) > abs(numbers[i] - closest.0) {
            closest.1 = numbers[i]
        }
    }
    return closest
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closest: (Double, Double) = (numbers[0], numbers[1])
    for i in 2..<numbers.count {
        if abs(closest.0 - closest.1) > abs(numbers[i] - closest.1) {
            closest.0 = closest.1
            closest.1 = numbers[i]
        } else if abs(closest.0 - closest.1) > abs(numbers[i] - closest.0) {
            closest.1 = numbers[i]
        }
    }
    return closest
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closest = (numbers[0], numbers[1])
    for i in 2..<numbers.count {
        if abs(numbers[i] - closest.0) < abs(closest.1 - closest.0) {
            closest.0 = numbers[i]
        } else if abs(numbers[i] - closest.1) < abs(closest.0 - closest.1) {
            closest.1 = numbers[i]
        }
    }
    return closest
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closest = (numbers[0], numbers[1])
    for i in 2..<numbers.count {
        if abs(numbers[i] - closest.0) < abs(closest.1 - closest.0) {
            closest.0 = numbers[i]
        } else if abs(numbers[i] - closest.1) < abs(closest.0 - closest.1) {
            closest.1 = numbers[i]
        }
    }
    return closest
}
```
### Link

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closest = (numbers[0], numbers[1])
    for i in 2..<numbers.count {
        if abs(numbers[i] - closest.0) < abs(closest.1 - closest.0) {
            closest.0 = numbers[i]
        } else if abs(numbers[i] - closest.1) < abs(closest.0 - closest.1) {
            closest.1 = numbers[i]
        }
    }
    return closest
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closest = (numbers[0], numbers[1])
    for i in 2..<numbers.count {
        if abs(numbers[i] - closest.0) < abs(closest.1 - closest.0) {
            closest.0 = numbers[i]
        } else if abs(numbers[i] - closest.1) < abs(closest.0 - closest.1) {
            closest.1 = numbers[i]
        }
    }
    return closest
}
```
### Link

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closest = (numbers[0], numbers[1])
    for i in 2..<numbers.count {
        if abs(closest.0 - closest.1) > abs(numbers[i] - closest.0) {
            closest.0 = closest.1
            closest.1 = numbers[i]
        }
    }
    return closest
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closest = (numbers[0], numbers[1])
    for i in 2..<numbers.count {
        if abs(closest.0 - closest.1) > abs(numbers[i] - closest.0) {
            closest.0 = closest.1
            closest.1 = numbers[i]
        }
    }
    return closest
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closest = (numbers[0], numbers[1])
    for i in 2..<numbers.count {
        if abs(closest.0 - closest.1) > abs(numbers[i] - closest.0) {
            closest.0 = numbers[i]
        } else {
            closest.1 = numbers[i]
        }
    }
    return closest
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closest = (numbers[0], numbers[1])
    for i in 2..<numbers.count {
        if abs(closest.0 - closest.1) > abs(numbers[i] - closest.0) {
            closest.0 = numbers[i]
        } else {
            closest.1 = numbers[i]
        }
    }
    return closest
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closest = (numbers[0], numbers[1])
    for i in 2..<numbers.count {
        if abs(closest.0 - closest.1) > abs(numbers[i] - closest.0) {
            closest = (closest.0, numbers[i])
        } else if abs(closest.0 - closest.1) > abs(numbers[i] - closest.1) {
            closest = (numbers[i], closest.1)
        }
    }
    return closest
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
### Response:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var closest = (numbers[0], numbers[1])
    for i in 2..<numbers.count {
        if abs(closest.0 - closest.1) > abs(numbers[i] - closest.0) {
            closest = (closest.0, numbers[i])
        } else if abs(closest.0 - closest.1) > abs(numbers[i] - closest.1) {
            closest = (numbers[i], closest.1)
        }
    }
    return closest
}
```
### Link

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return numbers.map { ($0 - min) / (max - min) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return numbers.map { ($0 - min) / (max - min) }
}
```
### Test

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return numbers.map { ($0 - min) / (max - min) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return numbers.map { ($0 - min) / (max - min) }
}
```
### Test

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return numbers.map { ($0 - min) / (max - min) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return numbers.map { ($0 - min) / (max - min) }
}
```
### Link

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return numbers.map { (number) -> Double in
        return (number - min) / (max - min)
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return numbers.map { (number) -> Double in
        return (number - min) / (max - min)
    }
}
```
### Test

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return numbers.map { (number) -> Double in
        return (number - min) / (max - min)
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return numbers.map { (number) -> Double in
        return (number - min) / (max - min)
    }
}
```
### Test

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return numbers.map { ($0 - min) / (max - min) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return numbers.map { ($0 - min) / (max - min) }
}
```
### Test

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return numbers.map { ($0 - min) / (max - min) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return numbers.map { ($0 - min) / (max - min) }
}
```
### Link

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return numbers.map { ($0 - min) / (max - min) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return numbers.map { ($0 - min) / (max - min) }
}
```
### Link

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return numbers.map { ($0 - min) / (max - min) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return numbers.map { ($0 - min) / (max - min) }
}
```
### Link

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return numbers.map { (number) -> Double in
        return (number - min) / (max - min)
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
### Response:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return numbers.map { (number) -> Double in
        return (number - min) / (max - min)
    }
}
```
### Link

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```
### Inst

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```
### Inst

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```
### Inst

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```
### Inst

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```
### Inst

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```
### Inst

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
### Response:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func strlen(string: String) -> Int {
    return string.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```
### Inst

func strlen(string: String) -> Int {
    return string.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```
### Inst

func strlen(string: String) -> Int {
    return string.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```
### Inst

func strlen(string: String) -> Int {
    return string.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```
### Inst

func strlen(string: String) -> Int {
    return string.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```
### Inst

func strlen(string: String) -> Int {
    return string.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```
### Inst

func strlen(string: String) -> Int {
    return string.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```
### Inst

func strlen(string: String) -> Int {
    return string.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```
### Inst

func strlen(string: String) -> Int {
    return string.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
### Response:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```
### Inst

func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = 1
    while divisor <= n / 2 {
        if n % divisor == 0 {
            return divisor
        }
        divisor += 1
    }
    return 1
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = 1
    while divisor <= n / 2 {
        if n % divisor == 0 {
            return divisor
        }
        divisor += 1
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return divisor
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return divisor
}
```
### Inst

func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 1 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 0 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 0 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}
```
### Test

func largestDivisor(n: Int) -> Int {
    var i = n - 1
    while i > 0 {
        if n % i == 0 {
            return i
        }
        i -= 1
    }
    return 1
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    var i = n - 1
    while i > 0 {
        if n % i == 0 {
            return i
        }
        i -= 1
    }
    return 1
}
```
### Inst

func largestDivisor(n: Int) -> Int {
    var i = n
    while i > 1 {
        if n % i == 0 {
            return i
        }
        i -= 1
    }
    return 1
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    var i = n
    while i > 1 {
        if n % i == 0 {
            return i
        }
        i -= 1
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 0 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
### Response:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 0 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}
```

func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var current = 2
    while current <= n {
        if n % current == 0 {
            factors.append(current)
            n /= current
        } else {
            current += 1
        }
    }
    return factors
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var current = 2
    while current <= n {
        if n % current == 0 {
            factors.append(current)
            n /= current
        } else {
            current += 1
        }
    }
    return factors
}
```

func factorize(n: Int) -> [Int] {
    var n = n
    var factors: [Int] = []
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            factors.append(i)
            n /= i
        } else {
            i += 1
        }
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var n = n
    var factors: [Int] = []
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            factors.append(i)
            n /= i
        } else {
            i += 1
        }
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}
```
### Link

func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var number = n
    var factor = 2
    while number > 1 {
        if number % factor == 0 {
            factors.append(factor)
            number /= factor
        } else {
            factor += 1
        }
    }
    return factors
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var number = n
    var factor = 2
    while number > 1 {
        if number % factor == 0 {
            factors.append(factor)
            number /= factor
        } else {
            factor += 1
        }
    }
    return factors
}
```
### Link

func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            factors.append(i)
            while n % i == 0 {
                n /= i
            }
        }
        i += 1
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            factors.append(i)
            while n % i == 0 {
                n /= i
            }
        }
        i += 1
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}
```
### Link

func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var n = n
    var i = 2
    while i * i <= n {
        while n % i == 0 {
            factors.append(i)
            n /= i
        }
        i += 1
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var n = n
    var i = 2
    while i * i <= n {
        while n % i == 0 {
            factors.append(i)
            n /= i
        }
        i += 1
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}
```
### Link

func factorize(n: Int) -> [Int] {
    var result: [Int] = []
    var number = n
    var factor = 2
    while factor <= number {
        if number % factor == 0 {
            result.append(factor)
            number /= factor
        } else {
            factor += 1
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var result: [Int] = []
    var number = n
    var factor = 2
    while factor <= number {
        if number % factor == 0 {
            result.append(factor)
            number /= factor
        } else {
            factor += 1
        }
    }
    return result
}
```
### Link

func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var number = n
    var i = 2
    while i * i <= number {
        if number % i == 0 {
            factors.append(i)
            number /= i
        } else {
            i += 1
        }
    }
    if number > 1 {
        factors.append(number)
    }
    return factors
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var number = n
    var i = 2
    while i * i <= number {
        if number % i == 0 {
            factors.append(i)
            number /= i
        } else {
            i += 1
        }
    }
    if number > 1 {
        factors.append(number)
    }
    return factors
}
```

func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var n = n
    for i in 2...Int(sqrt(Double(n))) {
        if n % i == 0 {
            factors.append(i)
            while n % i == 0 {
                n /= i
            }
        }
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var n = n
    for i in 2...Int(sqrt(Double(n))) {
        if n % i == 0 {
            factors.append(i)
            while n % i == 0 {
                n /= i
            }
        }
    }
    if n > 1 {
        factors.append(n)
    }
    return factors
}
```
### Link

func factorize(n: Int) -> [Int] {
    var n = n
    var factors = [Int]()
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            factors.append(i)
            n = n / i
        } else {
            i += 1
        }
    }
    factors.append(n)
    return factors
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var n = n
    var factors = [Int]()
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            factors.append(i)
            n = n / i
        } else {
            i += 1
        }
    }
    factors.append(n)
    return factors
}
```

func factorize(n: Int) -> [Int] {
    var n = n
    var factors: [Int] = []
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            factors.append(i)
            n = n / i
        } else {
            i += 1
        }
    }
    factors.append(n)
    return factors
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
### Response:
```swift
func factorize(n: Int) -> [Int] {
    var n = n
    var factors: [Int] = []
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            factors.append(i)
            n = n / i
        } else {
            i += 1
        }
    }
    factors.append(n)
    return factors
}
```
### Link

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var seen: [Int: Bool] = [:]
    for number in numbers {
        if seen[number] == nil {
            result.append(number)
            seen[number] = true
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var seen: [Int: Bool] = [:]
    for number in numbers {
        if seen[number] == nil {
            result.append(number)
            seen[number] = true
        }
    }
    return result
}
```
### Inst

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var set: Set<Int> = []
    for number in numbers {
        if !set.contains(number) {
            set.insert(number)
            result.append(number)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var set: Set<Int> = []
    for number in numbers {
        if !set.contains(number) {
            set.insert(number)
            result.append(number)
        }
    }
    return result
}
```
### Link

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var seen: [Int: Bool] = [:]
    for number in numbers {
        if seen[number] == nil {
            seen[number] = true
            result.append(number)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var seen: [Int: Bool] = [:]
    for number in numbers {
        if seen[number] == nil {
            seen[number] = true
            result.append(number)
        }
    }
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    for number in numbers {
        if !seen.contains(number) {
            result.append(number)
            seen.insert(number)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    for number in numbers {
        if !seen.contains(number) {
            result.append(number)
            seen.insert(number)
        }
    }
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var set: Set<Int> = []
    for number in numbers {
        if !set.contains(number) {
            set.insert(number)
            result.append(number)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var set: Set<Int> = []
    for number in numbers {
        if !set.contains(number) {
            set.insert(number)
            result.append(number)
        }
    }
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var seen: [Int: Bool] = [:]
    for number in numbers {
        if seen[number] == nil {
            result.append(number)
            seen[number] = true
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var seen: [Int: Bool] = [:]
    for number in numbers {
        if seen[number] == nil {
            result.append(number)
            seen[number] = true
        }
    }
    return result
}
```
### Inst

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    for number in numbers {
        if !seen.contains(number) {
            result.append(number)
            seen.insert(number)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    for number in numbers {
        if !seen.contains(number) {
            result.append(number)
            seen.insert(number)
        }
    }
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var set: Set<Int> = []
    for number in numbers {
        if !set.contains(number) {
            result.append(number)
            set.insert(number)
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var set: Set<Int> = []
    for number in numbers {
        if !set.contains(number) {
            result.append(number)
            set.insert(number)
        }
    }
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var seen: [Int: Bool] = [:]
    for number in numbers {
        if seen[number] == nil {
            result.append(number)
            seen[number] = true
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var seen: [Int: Bool] = [:]
    for number in numbers {
        if seen[number] == nil {
            result.append(number)
            seen[number] = true
        }
    }
    return result
}
```
### Inst

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var seen: [Int: Bool] = [:]
    for number in numbers {
        if seen[number] == nil {
            result.append(number)
            seen[number] = true
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
### Response:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var seen: [Int: Bool] = [:]
    for number in numbers {
        if seen[number] == nil {
            result.append(number)
            seen[number] = true
        }
    }
    return result
}
```
### Inst

func flipCase(string: String) -> String {
    return String(string.map {
        if $0.isLowercase {
            return $0.uppercased()
        } else {
            return $0.lowercased()
        }
    })
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    return String(string.map {
        if $0.isLowercase {
            return $0.uppercased()
        } else {
            return $0.lowercased()
        }
    })
}
```

func flipCase(string: String) -> String {
    return String(string.map {
        $0.isLowercase ? $0.uppercased() : $0.lowercased()
    })
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    return String(string.map {
        $0.isLowercase ? $0.uppercased() : $0.lowercased()
    })
}
```

func flipCase(string: String) -> String {
    return String(string.map {
        $0.isLowercase ? $0.uppercased() : $0.lowercased()
    })
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    return String(string.map {
        $0.isLowercase ? $0.uppercased() : $0.lowercased()
    })
}
```
### Test

func flipCase(string: String) -> String {
    return String(string.map {
        if $0.isLowercase {
            return $0.uppercased()
        } else {
            return $0.lowercased()
        }
    })
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    return String(string.map {
        if $0.isLowercase {
            return $0.uppercased()
        } else {
            return $0.lowercased()
        }
    })
}
```

func flipCase(string: String) -> String {
    return String(string.map {
        if $0.isLowercase {
            return $0.uppercased()
        } else {
            return $0.lowercased()
        }
    })
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    return String(string.map {
        if $0.isLowercase {
            return $0.uppercased()
        } else {
            return $0.lowercased()
        }
    })
}
```
### Test

func flipCase(string: String) -> String {
    return String(string.map {
        $0.isLowercase ? $0.uppercased() : $0.lowercased()
    })
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    return String(string.map {
        $0.isLowercase ? $0.uppercased() : $0.lowercased()
    })
}
```
### Link

func flipCase(string: String) -> String {
    return String(string.map {
        $0.isLowercase ? $0.uppercased() : $0.lowercased()
    })
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    return String(string.map {
        $0.isLowercase ? $0.uppercased() : $0.lowercased()
    })
}
```
### Link

func flipCase(string: String) -> String {
    return String(string.map {
        $0.isLowercase ? $0.uppercased() : $0.lowercased()
    })
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    return String(string.map {
        $0.isLowercase ? $0.uppercased() : $0.lowercased()
    })
}
```
### Test

func flipCase(string: String) -> String {
    return String(string.map {
        if $0.isLowercase {
            return $0.uppercased()
        } else {
            return $0.lowercased()
        }
    })
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    return String(string.map {
        if $0.isLowercase {
            return $0.uppercased()
        } else {
            return $0.lowercased()
        }
    })
}
```
### Test

func flipCase(string: String) -> String {
    return String(string.map {
        $0.isLowercase ? $0.uppercased() : $0.lowercased()
    })
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
### Response:
```swift
func flipCase(string: String) -> String {
    return String(string.map {
        $0.isLowercase ? $0.uppercased() : $0.lowercased()
    })
}
```
### Test

func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
```
### Inst

func concatenate(strings: [String]) -> String {
    return strings.joined()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined()
}
```
### Inst

func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
```
### Inst

func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
```
### Inst

func concatenate(strings: [String]) -> String {
    return strings.joined()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined()
}
```
### Test

func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
```
### Inst

func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
```
### Inst

func concatenate(strings: [String]) -> String {
    return strings.joined()
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined()
}
```
### Inst

func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
```
### Inst

func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
### Response:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
```
### Test

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```
### Inst

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```
### Inst

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```
### Inst

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```
### Inst

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```
### Inst

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```
### Inst

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
### Response:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```
### Inst

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```
### Link

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```
### Inst

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```
### Link

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```
### Inst

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
### Response:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n == 2 {
        return true
    }
    if n % 2 == 0 {
        return false
    }
    for i in 3...Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n == 2 {
        return true
    }
    if n % 2 == 0 {
        return false
    }
    for i in 3...Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2...Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2...Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```
### Test

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    for i in 2...Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    for i in 2...Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2...Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2...Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```
### Test

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    } else if n == 2 {
        return true
    } else if n % 2 == 0 {
        return false
    }
    for i in 3...Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    } else if n == 2 {
        return true
    } else if n % 2 == 0 {
        return false
    }
    for i in 3...Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```
### Test

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    } else if n == 2 {
        return true
    } else if n % 2 == 0 {
        return false
    }

    for i in 3...Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }

    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    } else if n == 2 {
        return true
    } else if n % 2 == 0 {
        return false
    }

    for i in 3...Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }

    return true
}
```

func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2...Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2...Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```
### Test

func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2...Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
### Response:
```swift
func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2...Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```
### Inst

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        l[i] = l[i+2]
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        l[i] = l[i+2]
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        l[i] = l[i...].sorted()[0]
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        l[i] = l[i...].sorted()[0]
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        l[i] = l[i + 1]
        l[i + 1] = l[i + 2]
        l[i + 2] = l[i]
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        l[i] = l[i + 1]
        l[i + 1] = l[i + 2]
        l[i + 2] = l[i]
    }
    return l
}
```
### Test

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        l[i] = l[i..<l.count].sorted()[i]
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        l[i] = l[i..<l.count].sorted()[i]
    }
    return l
}
```
### Test

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        l[i] = l[i+1]
        l[i+1] = l[i+2]
        l[i+2] = l[i]
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        l[i] = l[i+1]
        l[i+1] = l[i+2]
        l[i+2] = l[i]
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        l[i] = l[i+1]
        l[i+1] = l[i+2]
        l[i+2] = l[i]
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        l[i] = l[i+1]
        l[i+1] = l[i+2]
        l[i+2] = l[i]
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 3 == 0 {
            l[i] = l[i..<l.count].sorted()[0]
        }
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 3 == 0 {
            l[i] = l[i..<l.count].sorted()[0]
        }
    }
    return l
}
```
### Test

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        l[i] = l[i + 1]
        l[i + 1] = l[i + 2]
        l[i + 2] = l[i]
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        l[i] = l[i + 1]
        l[i + 1] = l[i + 2]
        l[i + 2] = l[i]
    }
    return l
}
```
### Test

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        l[i] = l[i+1]
        l[i+1] = l[i+2]
        l[i+2] = l[i]
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        l[i] = l[i+1]
        l[i+1] = l[i+2]
        l[i+2] = l[i]
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        l[i] = l[i+1]
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
### Response:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        l[i] = l[i+1]
    }
    return l
}
```
### Test

func unique(l: [Int]) -> [Int] {
    return l.sorted().reduce([], { (result, element) -> [Int] in
        if result.last != element {
            return result + [element]
        } else {
            return result
        }
    })
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    return l.sorted().reduce([], { (result, element) -> [Int] in
        if result.last != element {
            return result + [element]
        } else {
            return result
        }
    })
}
```
### Inst

func unique(l: [Int]) -> [Int] {
    return l.sorted().unique()
}

extension Array where Element: Equatable {
    func unique() -> [Element] {
        var result = [Element]()
        forEach {
            if !result.contains($0) {
                result.append($0)
            }
        }
        return result
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    return l.sorted().unique()
}

extension Array where Element: Equatable {
    func unique() -> [Element] {
        var result = [Element]()
        forEach {
            if !result.contains($0) {
                result.append($0)
            }
        }
        return result
    }
}
```
### Inst

func unique(l: [Int]) -> [Int] {
    return l.sorted().reduce([], { $0.last == $1 ? $0 : $0 + [$1] })
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    return l.sorted().reduce([], { $0.last == $1 ? $0 : $0 + [$1] })
}
```
### Inst

func unique(l: [Int]) -> [Int] {
    return l.sorted().unique()
}

extension Array where Element: Equatable {
    func unique() -> [Element] {
        var result: [Element] = []
        forEach {
            if !result.contains($0) {
                result.append($0)
            }
        }
        return result
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    return l.sorted().unique()
}

extension Array where Element: Equatable {
    func unique() -> [Element] {
        var result: [Element] = []
        forEach {
            if !result.contains($0) {
                result.append($0)
            }
        }
        return result
    }
}
```
### Inst

func unique(l: [Int]) -> [Int] {
    return l.sorted().reduce([Int](), { $0.contains($1) ? $0 : $0 + [$1] })
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    return l.sorted().reduce([Int](), { $0.contains($1) ? $0 : $0 + [$1] })
}
```
### Inst

func unique(l: [Int]) -> [Int] {
    return l.sorted().unique()
}

extension Array where Element: Equatable {
    func unique() -> [Element] {
        var result = [Element]()
        for element in self {
            if !result.contains(element) {
                result.append(element)
            }
        }
        return result
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    return l.sorted().unique()
}

extension Array where Element: Equatable {
    func unique() -> [Element] {
        var result = [Element]()
        for element in self {
            if !result.contains(element) {
                result.append(element)
            }
        }
        return result
    }
}
```
### Inst

func unique(l: [Int]) -> [Int] {
    return l.sorted().reduce([], { $0.last == $1 ? $0 : $0 + [$1] })
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    return l.sorted().reduce([], { $0.last == $1 ? $0 : $0 + [$1] })
}
```
### Inst

func unique(l: [Int]) -> [Int] {
    return l.sorted().unique()
}

extension Array where Element: Equatable {
    func unique() -> [Element] {
        var result = [Element]()
        for element in self {
            if !result.contains(element) {
                result.append(element)
            }
        }
        return result
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    return l.sorted().unique()
}

extension Array where Element: Equatable {
    func unique() -> [Element] {
        var result = [Element]()
        for element in self {
            if !result.contains(element) {
                result.append(element)
            }
        }
        return result
    }
}
```
### Inst

func unique(l: [Int]) -> [Int] {
    return l.sorted().unique()
}

extension Array where Element: Equatable {
    func unique() -> [Element] {
        var result: [Element] = []
        forEach {
            if !result.contains($0) {
                result.append($0)
            }
        }
        return result
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    return l.sorted().unique()
}

extension Array where Element: Equatable {
    func unique() -> [Element] {
        var result: [Element] = []
        forEach {
            if !result.contains($0) {
                result.append($0)
            }
        }
        return result
    }
}
```
### Inst

func unique(l: [Int]) -> [Int] {
    return l.sorted().reduce([], { $0.last == $1 ? $0 : $0 + [$1] })
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
### Response:
```swift
func unique(l: [Int]) -> [Int] {
    return l.sorted().reduce([], { $0.last == $1 ? $0 : $0 + [$1] })
}
```
### Inst

func maxElement(l: [Int]) -> Int {
    return l.max()!
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max()!
}
```
### Inst

func maxElement(l: [Int]) -> Int {
    return l.max()!
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max()!
}
```
### Inst

func maxElement(l: [Int]) -> Int {
    return l.max()!
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max()!
}
```
### Inst

func maxElement(l: [Int]) -> Int {
    return l.max()!
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max()!
}
```
### Inst

func maxElement(l: [Int]) -> Int {
    return l.max()!
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max()!
}
```
### Inst

func maxElement(l: [Int]) -> Int {
    return l.max()!
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max()!
}
```
### Inst

func maxElement(l: [Int]) -> Int {
    return l.max()!
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max()!
}
```
### Inst

func maxElement(l: [Int]) -> Int {
    return l.max()!
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max()!
}
```
### Inst

func maxElement(l: [Int]) -> Int {
    return l.max()!
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max()!
}
```
### Inst

func maxElement(l: [Int]) -> Int {
    return l.max()!
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
### Response:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max()!
}
```
### Inst

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            count += String(i).filter { $0 == "7" }.count
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            count += String(i).filter { $0 == "7" }.count
        }
    }
    return count
}
```
### Test

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            if str.contains("7") {
                count += 1
            }
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            if str.contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            if str.contains("7") {
                count += 1
            }
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            if str.contains("7") {
                count += 1
            }
        }
    }
    return count
}
```
### Test

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            if str.contains("7") {
                count += 1
            }
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            if str.contains("7") {
                count += 1
            }
        }
    }
    return count
}
```
### Test

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            if str.contains("7") {
                count += 1
            }
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            if str.contains("7") {
                count += 1
            }
        }
    }
    return count
}
```
### Test

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            if str.contains("7") {
                count += 1
            }
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            if str.contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            count += String(i).filter { $0 == "7" }.count
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            count += String(i).filter { $0 == "7" }.count
        }
    }
    return count
}
```
### Link

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            if str.contains("7") {
                count += 1
            }
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            if str.contains("7") {
                count += 1
            }
        }
    }
    return count
}
```
### Test

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            if str.contains("7") {
                count += 1
            }
        }
    }
    return count
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
### Response:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let str = String(i)
            if str.contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 2 == 0 {
            l[i] = l[i..<l.count].sorted()[i]
        }
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 2 == 0 {
            l[i] = l[i..<l.count].sorted()[i]
        }
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 2 == 0 {
            l[i] = l.filter({$0 % 2 == 0}).sorted()[i]
        }
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 2 == 0 {
            l[i] = l.filter({$0 % 2 == 0}).sorted()[i]
        }
    }
    return l
}
```
### Inst

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 2 == 0 {
            l[i] = l.filter({ $0 % 2 == 0 }).sorted()[i]
        }
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 2 == 0 {
            l[i] = l.filter({ $0 % 2 == 0 }).sorted()[i]
        }
    }
    return l
}
```
### Inst

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 2 == 0 {
            l[i] = l.filter { $0 % 2 == 0 }.sorted()[i]
        }
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 2 == 0 {
            l[i] = l.filter { $0 % 2 == 0 }.sorted()[i]
        }
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        l[i] = l[i..<l.count].sorted()[i]
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        l[i] = l[i..<l.count].sorted()[i]
    }
    return l
}
```
### Inst

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 2 == 0 {
            l[i] = l.filter({$0 % 2 == 0}).sorted()[i]
        }
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 2 == 0 {
            l[i] = l.filter({$0 % 2 == 0}).sorted()[i]
        }
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 2 == 0 {
            l[i] = l.filter { $0 % 2 == 0 }.sorted()[i]
        }
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 2 == 0 {
            l[i] = l.filter { $0 % 2 == 0 }.sorted()[i]
        }
    }
    return l
}
```
### Test

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 2 == 0 {
            l[i] = l.filter { $0 % 2 == 0 }.sorted()[i]
        }
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 2 == 0 {
            l[i] = l.filter { $0 % 2 == 0 }.sorted()[i]
        }
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 1, to: l.count, by: 2) {
        l[i] = l[i...].sorted()[0]
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 1, to: l.count, by: 2) {
        l[i] = l[i...].sorted()[0]
    }
    return l
}
```
### Test

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 2 == 0 {
            l[i] = l.filter({$0 % 2 == 0}).sorted()[i]
        }
    }
    return l
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
### Response:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in 0..<l.count {
        if i % 2 == 0 {
            l[i] = l.filter({$0 % 2 == 0}).sorted()[i]
        }
    }
    return l
}
```
### Test

func primeFib(n: Int) -> Int {
    var fib = [1, 1]
    var prime = [2]
    var i = 2
    while i < n {
        fib.append(fib[i - 1] + fib[i - 2])
        if isPrime(fib[i]) {
            prime.append(fib[i])
            i += 1
        }
    }
    return prime[n - 1]
}

func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2..<Int(sqrt(Double(n))) + 1 {
        if n % i == 0 {
            return false
        }
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var fib = [1, 1]
    var prime = [2]
    var i = 2
    while i < n {
        fib.append(fib[i - 1] + fib[i - 2])
        if isPrime(fib[i]) {
            prime.append(fib[i])
            i += 1
        }
    }
    return prime[n - 1]
}

func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2..<Int(sqrt(Double(n))) + 1 {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```

func primeFib(n: Int) -> Int {
    var fib = [1, 1]
    var prime = [2, 3]
    var i = 2
    while i < n {
        fib.append(fib[i - 1] + fib[i - 2])
        if isPrime(fib[i]) {
            prime.append(fib[i])
            i += 1
        }
    }
    return prime[n - 1]
}

func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2..<Int(sqrt(Double(n))) + 1 {
        if n % i == 0 {
            return false
        }
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var fib = [1, 1]
    var prime = [2, 3]
    var i = 2
    while i < n {
        fib.append(fib[i - 1] + fib[i - 2])
        if isPrime(fib[i]) {
            prime.append(fib[i])
            i += 1
        }
    }
    return prime[n - 1]
}

func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2..<Int(sqrt(Double(n))) + 1 {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```
### Link

func primeFib(n: Int) -> Int {
    var fib = [1, 1]
    var prime = [2, 3]
    var i = 2
    while i < n {
        fib.append(fib[i - 1] + fib[i - 2])
        if isPrime(fib[i]) {
            prime.append(fib[i])
            i += 1
        }
    }
    return prime[n - 1]
}

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    for i in 2..<Int(sqrt(Double(n))) + 1 {
        if n % i == 0 {
            return false
        }
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var fib = [1, 1]
    var prime = [2, 3]
    var i = 2
    while i < n {
        fib.append(fib[i - 1] + fib[i - 2])
        if isPrime(fib[i]) {
            prime.append(fib[i])
            i += 1
        }
    }
    return prime[n - 1]
}

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    for i in 2..<Int(sqrt(Double(n))) + 1 {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```

func primeFib(n: Int) -> Int {
    var fib = [2, 3]
    var prime = [2, 3]
    var i = 4
    while i <= n {
        let fib_i = fib[i - 1] + fib[i - 2]
        if isPrime(fib_i) {
            fib.append(fib_i)
            prime.append(fib_i)
        }
        i += 1
    }
    return prime[n - 1]
}

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n == 2 {
        return true
    }
    if n % 2 == 0 {
        return false
    }
    for i in 3..<Int(sqrt(Double(n))) + 1 {
        if n % i == 0 {
            return false
        }
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var fib = [2, 3]
    var prime = [2, 3]
    var i = 4
    while i <= n {
        let fib_i = fib[i - 1] + fib[i - 2]
        if isPrime(fib_i) {
            fib.append(fib_i)
            prime.append(fib_i)
        }
        i += 1
    }
    return prime[n - 1]
}

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n == 2 {
        return true
    }
    if n % 2 == 0 {
        return false
    }
    for i in 3..<Int(sqrt(Double(n))) + 1 {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```

func primeFib(n: Int) -> Int {
    var fib = [1, 1]
    var prime = [2, 3]
    var i = 4
    while i <= n {
        fib.append(fib[i - 1] + fib[i - 2])
        if fib[i].isPrime() {
            prime.append(fib[i])
        }
        i += 1
    }
    return prime[n]
}

extension Int {
    func isPrime() -> Bool {
        if self == 1 {
            return false
        }
        if self == 2 {
            return true
        }
        if self % 2 == 0 {
            return false
        }
        for i in 3...Int(sqrt(Double(self))) {
            if self % i == 0 {
                return false
            }
        }
        return true
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var fib = [1, 1]
    var prime = [2, 3]
    var i = 4
    while i <= n {
        fib.append(fib[i - 1] + fib[i - 2])
        if fib[i].isPrime() {
            prime.append(fib[i])
        }
        i += 1
    }
    return prime[n]
}

extension Int {
    func isPrime() -> Bool {
        if self == 1 {
            return false
        }
        if self == 2 {
            return true
        }
        if self % 2 == 0 {
            return false
        }
        for i in 3...Int(sqrt(Double(self))) {
            if self % i == 0 {
                return false
            }
        }
        return true
    }
}
```

func primeFib(n: Int) -> Int {
    var fib = [1, 1]
    var prime = [2, 3]
    var i = 2
    while i < n {
        fib.append(fib[i - 1] + fib[i - 2])
        if fib[i].isPrime {
            prime.append(fib[i])
            i += 1
        }
    }
    return prime[n - 1]
}

extension Int {
    var isPrime: Bool {
        if self < 2 {
            return false
        }
        for i in 2...Int(sqrt(Double(self))) {
            if self % i == 0 {
                return false
            }
        }
        return true
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var fib = [1, 1]
    var prime = [2, 3]
    var i = 2
    while i < n {
        fib.append(fib[i - 1] + fib[i - 2])
        if fib[i].isPrime {
            prime.append(fib[i])
            i += 1
        }
    }
    return prime[n - 1]
}

extension Int {
    var isPrime: Bool {
        if self < 2 {
            return false
        }
        for i in 2...Int(sqrt(Double(self))) {
            if self % i == 0 {
                return false
            }
        }
        return true
    }
}
```

func primeFib(n: Int) -> Int {
    var fib = [1, 1]
    var prime = [2]
    var i = 2
    while fib.count < n {
        let sum = fib[i - 1] + fib[i - 2]
        if sum > 1000000000 {
            return -1
        }
        fib.append(sum)
        if isPrime(sum) {
            prime.append(sum)
        }
        i += 1
    }
    return prime[n - 1]
}

func isPrime(_ n: Int) -> Bool {
    if n < 2 {
        return false
    }
    if n == 2 {
        return true
    }
    if n % 2 == 0 {
        return false
    }
    for i in 3...Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var fib = [1, 1]
    var prime = [2]
    var i = 2
    while fib.count < n {
        let sum = fib[i - 1] + fib[i - 2]
        if sum > 1000000000 {
            return -1
        }
        fib.append(sum)
        if isPrime(sum) {
            prime.append(sum)
        }
        i += 1
    }
    return prime[n - 1]
}

func isPrime(_ n: Int) -> Bool {
    if n < 2 {
        return false
    }
    if n == 2 {
        return true
    }
    if n % 2 == 0 {
        return false
    }
    for i in 3...Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```

func primeFib(n: Int) -> Int {
    var fib = [1, 1]
    var i = 2
    while i < n {
        fib.append(fib[i - 1] + fib[i - 2])
        i += 1
    }
    var prime = fib[n - 1]
    while !isPrime(prime) {
        prime += 1
    }
    return prime
}

func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2...Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var fib = [1, 1]
    var i = 2
    while i < n {
        fib.append(fib[i - 1] + fib[i - 2])
        i += 1
    }
    var prime = fib[n - 1]
    while !isPrime(prime) {
        prime += 1
    }
    return prime
}

func isPrime(n: Int) -> Bool {
    if n < 2 {
        return false
    }
    for i in 2...Int(sqrt(Double(n))) {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```

func primeFib(n: Int) -> Int {
    var fib = [1, 1]
    var prime = [2]
    var i = 2
    while i < n {
        fib.append(fib[i - 1] + fib[i - 2])
        if fib[i].isPrime {
            prime.append(fib[i])
            i += 1
        }
    }
    return prime[n - 1]
}

extension Int {
    var isPrime: Bool {
        if self < 2 {
            return false
        }
        for i in 2..<Int(sqrt(Double(self))) + 1 {
            if self % i == 0 {
                return false
            }
        }
        return true
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var fib = [1, 1]
    var prime = [2]
    var i = 2
    while i < n {
        fib.append(fib[i - 1] + fib[i - 2])
        if fib[i].isPrime {
            prime.append(fib[i])
            i += 1
        }
    }
    return prime[n - 1]
}

extension Int {
    var isPrime: Bool {
        if self < 2 {
            return false
        }
        for i in 2..<Int(sqrt(Double(self))) + 1 {
            if self % i == 0 {
                return false
            }
        }
        return true
    }
}
```

func primeFib(n: Int) -> Int {
    var fib = [1, 1]
    var prime = [2, 3]
    var i = 2
    while i < n {
        fib.append(fib[i - 1] + fib[i - 2])
        if fib[i].isPrime() {
            prime.append(fib[i])
            i += 1
        }
    }
    return prime[n - 1]
}

extension Int {
    func isPrime() -> Bool {
        if self < 2 {
            return false
        }
        for i in 2..<Int(sqrt(Double(self))) {
            if self % i == 0 {
                return false
            }
        }
        return true
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
### Response:
```swift
func primeFib(n: Int) -> Int {
    var fib = [1, 1]
    var prime = [2, 3]
    var i = 2
    while i < n {
        fib.append(fib[i - 1] + fib[i - 2])
        if fib[i].isPrime() {
            prime.append(fib[i])
            i += 1
        }
    }
    return prime[n - 1]
}

extension Int {
    func isPrime() -> Bool {
        if self < 2 {
            return false
        }
        for i in 2..<Int(sqrt(Double(self))) {
            if self % i == 0 {
                return false
            }
        }
        return true
    }
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```
### Test

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```
### Test

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count-2 {
        for j in i+1..<l.count-1 {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count-2 {
        for j in i+1..<l.count-1 {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```
### Test

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```
### Test

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count-2 {
        for j in i+1..<l.count-1 {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count-2 {
        for j in i+1..<l.count-1 {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```
### Test

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
### Response:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if l[i] + l[j] + l[k] == 0 {
                    return true
                }
            }
        }
    }
    return false
}
```
### Test

func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}
```

func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}
```

func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}
```

### Test

func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}
```

### Test

func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}
```

### Test

func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}
```

### Test

func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}
```

### Test

func carRaceCollision(n: Int) -> Int {
    return n * (n + 1) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    return n * (n + 1) / 2
}
```

### Test

func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}
```

### Test

func carRaceCollision(n: Int) -> Int {
    return n * (n + 1) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.

### Response:
```swift
func carRaceCollision(n: Int) -> Int {
    return n * (n + 1) / 2
}
```

### Test

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```
### Inst

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```
### Inst

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```
### Inst

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```
### Test

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```
### Link

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
### Response:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```
### Inst

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```
### Test

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```
### Test

func pairsSumToZero(l: [Int]) -> Bool {
    var result = false
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                result = true
                break
            }
        }
        if result {
            break
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var result = false
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                result = true
                break
            }
        }
        if result {
            break
        }
    }
    return result
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var result = false
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                result = true
                break
            }
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var result = false
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                result = true
                break
            }
        }
    }
    return result
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var result = false
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                result = true
                break
            }
        }
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var result = false
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                result = true
                break
            }
        }
    }
    return result
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```
### Test

func pairsSumToZero(l: [Int]) -> Bool {
    var dict: [Int: Int] = [:]
    for i in l {
        if let j = dict[i] {
            return true
        } else {
            dict[i] = i
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var dict: [Int: Int] = [:]
    for i in l {
        if let j = dict[i] {
            return true
        } else {
            dict[i] = i
        }
    }
    return false
}
```
### Test

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
### Response:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    for i in 0..<l.count {
        for j in i+1..<l.count {
            if l[i] + l[j] == 0 {
                return true
            }
        }
    }
    return false
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var number = x
    repeat {
        result = "\(number % base)" + result
        number /= base
    } while number > 0
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var number = x
    repeat {
        result = "\(number % base)" + result
        number /= base
    } while number > 0
    return result
}
```
### Link

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var number = x
    repeat {
        result = "\(number % base)" + result
        number /= base
    } while number > 0
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var number = x
    repeat {
        result = "\(number % base)" + result
        number /= base
    } while number > 0
    return result
}
```
### Link

func changeBase(x: Int, base: Int) -> String {
    return String(x, radix: base)
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    return String(x, radix: base)
}
```
### Test

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var x = x
    while x > 0 {
        result = String(x % base) + result
        x /= base
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var x = x
    while x > 0 {
        result = String(x % base) + result
        x /= base
    }
    return result
}
```
### Link

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var x = x
    while x > 0 {
        result = String(x % base) + result
        x /= base
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var x = x
    while x > 0 {
        result = String(x % base) + result
        x /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var x = x
    while x > 0 {
        result = String(x % base) + result
        x /= base
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var x = x
    while x > 0 {
        result = String(x % base) + result
        x /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var number = x
    while number > 0 {
        result = String(number % base) + result
        number /= base
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var number = x
    while number > 0 {
        result = String(number % base) + result
        number /= base
    }
    return result
}
```
### Link

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var x = x
    while x > 0 {
        result = String(x % base) + result
        x /= base
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var x = x
    while x > 0 {
        result = String(x % base) + result
        x /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var x = x
    var result = ""
    while x > 0 {
        result = String(x % base) + result
        x /= base
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    var x = x
    var result = ""
    while x > 0 {
        result = String(x % base) + result
        x /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var x = x
    while x > 0 {
        result = String(x % base) + result
        x /= base
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
### Response:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var x = x
    while x > 0 {
        result = String(x % base) + result
        x /= base
    }
    return result
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}
```
### Test

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}
```
### Test

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
### Response:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func fib4(n: Int) -> Int {
    var fib4 = [Int](repeating: 0, count: n + 1)
    fib4[0] = 0
    fib4[1] = 0
    fib4[2] = 2
    fib4[3] = 0
    for i in 4...n {
        fib4[i] = fib4[i - 1] + fib4[i - 2] + fib4[i - 3] + fib4[i - 4]
    }
    return fib4[n]
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var fib4 = [Int](repeating: 0, count: n + 1)
    fib4[0] = 0
    fib4[1] = 0
    fib4[2] = 2
    fib4[3] = 0
    for i in 4...n {
        fib4[i] = fib4[i - 1] + fib4[i - 2] + fib4[i - 3] + fib4[i - 4]
    }
    return fib4[n]
}
```

func fib4(n: Int) -> Int {
    var fib = [Int](repeating: 0, count: n + 1)
    fib[0] = 0
    fib[1] = 0
    fib[2] = 2
    fib[3] = 0
    for i in 4...n {
        fib[i] = fib[i - 1] + fib[i - 2] + fib[i - 3] + fib[i - 4]
    }
    return fib[n]
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var fib = [Int](repeating: 0, count: n + 1)
    fib[0] = 0
    fib[1] = 0
    fib[2] = 2
    fib[3] = 0
    for i in 4...n {
        fib[i] = fib[i - 1] + fib[i - 2] + fib[i - 3] + fib[i - 4]
    }
    return fib[n]
}
```

func fib4(n: Int) -> Int {
    var fib4 = [Int](repeating: 0, count: n)
    fib4[0] = 0
    fib4[1] = 0
    fib4[2] = 2
    fib4[3] = 0
    for i in 4...n {
        fib4[i] = fib4[i-1] + fib4[i-2] + fib4[i-3] + fib4[i-4]
    }
    return fib4[n]
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var fib4 = [Int](repeating: 0, count: n)
    fib4[0] = 0
    fib4[1] = 0
    fib4[2] = 2
    fib4[3] = 0
    for i in 4...n {
        fib4[i] = fib4[i-1] + fib4[i-2] + fib4[i-3] + fib4[i-4]
    }
    return fib4[n]
}
```
### Test

func fib4(n: Int) -> Int {
    var fib4 = [0, 0, 2, 0]
    for i in 4..<n {
        fib4.append(fib4[i-1] + fib4[i-2] + fib4[i-3] + fib4[i-4])
    }
    return fib4[n-1]
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var fib4 = [0, 0, 2, 0]
    for i in 4..<n {
        fib4.append(fib4[i-1] + fib4[i-2] + fib4[i-3] + fib4[i-4])
    }
    return fib4[n-1]
}
```
### Test

func fib4(n: Int) -> Int {
    var fib4 = [Int](repeating: 0, count: n)
    fib4[0] = 0
    fib4[1] = 0
    fib4[2] = 2
    fib4[3] = 0
    for i in 4...n {
        fib4[i] = fib4[i-1] + fib4[i-2] + fib4[i-3] + fib4[i-4]
    }
    return fib4[n]
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var fib4 = [Int](repeating: 0, count: n)
    fib4[0] = 0
    fib4[1] = 0
    fib4[2] = 2
    fib4[3] = 0
    for i in 4...n {
        fib4[i] = fib4[i-1] + fib4[i-2] + fib4[i-3] + fib4[i-4]
    }
    return fib4[n]
}
```

func fib4(n: Int) -> Int {
    var fib4 = [0, 0, 2, 0]
    for i in 4..<n {
        fib4.append(fib4[i-1] + fib4[i-2] + fib4[i-3] + fib4[i-4])
    }
    return fib4[n-1]
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var fib4 = [0, 0, 2, 0]
    for i in 4..<n {
        fib4.append(fib4[i-1] + fib4[i-2] + fib4[i-3] + fib4[i-4])
    }
    return fib4[n-1]
}
```

func fib4(n: Int) -> Int {
    var fib4 = [Int](repeating: 0, count: n + 1)
    fib4[0] = 0
    fib4[1] = 0
    fib4[2] = 2
    fib4[3] = 0
    for i in 4...n {
        fib4[i] = fib4[i - 1] + fib4[i - 2] + fib4[i - 3] + fib4[i - 4]
    }
    return fib4[n]
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var fib4 = [Int](repeating: 0, count: n + 1)
    fib4[0] = 0
    fib4[1] = 0
    fib4[2] = 2
    fib4[3] = 0
    for i in 4...n {
        fib4[i] = fib4[i - 1] + fib4[i - 2] + fib4[i - 3] + fib4[i - 4]
    }
    return fib4[n]
}
```
### Test

func fib4(n: Int) -> Int {
    var fib4 = [0, 0, 2, 0]
    for i in 4..<n {
        fib4.append(fib4[i-1] + fib4[i-2] + fib4[i-3] + fib4[i-4])
    }
    return fib4[n-1]
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var fib4 = [0, 0, 2, 0]
    for i in 4..<n {
        fib4.append(fib4[i-1] + fib4[i-2] + fib4[i-3] + fib4[i-4])
    }
    return fib4[n-1]
}
```

func fib4(n: Int) -> Int {
    var fib4: [Int] = [0, 0, 2, 0]
    for i in 4..<n {
        fib4.append(fib4[i-1] + fib4[i-2] + fib4[i-3] + fib4[i-4])
    }
    return fib4[n-1]
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var fib4: [Int] = [0, 0, 2, 0]
    for i in 4..<n {
        fib4.append(fib4[i-1] + fib4[i-2] + fib4[i-3] + fib4[i-4])
    }
    return fib4[n-1]
}
```
### Test

func fib4(n: Int) -> Int {
    var fib4 = [0, 0, 2, 0]
    for i in 4..<n {
        fib4.append(fib4[i-1] + fib4[i-2] + fib4[i-3] + fib4[i-4])
    }
    return fib4[n-1]
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
### Response:
```swift
func fib4(n: Int) -> Int {
    var fib4 = [0, 0, 2, 0]
    for i in 4..<n {
        fib4.append(fib4[i-1] + fib4[i-2] + fib4[i-3] + fib4[i-4])
    }
    return fib4[n-1]
}
```
### Test

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = sorted.count / 2
    return Double(sorted[middle])
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = sorted.count / 2
    return Double(sorted[middle])
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    if sorted.count % 2 == 0 {
        return Double(sorted[sorted.count / 2] + sorted[sorted.count / 2 - 1]) / 2
    } else {
        return Double(sorted[sorted.count / 2])
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    if sorted.count % 2 == 0 {
        return Double(sorted[sorted.count / 2] + sorted[sorted.count / 2 - 1]) / 2
    } else {
        return Double(sorted[sorted.count / 2])
    }
}
```
### Inst

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[middle - 1] + sorted[middle]) / 2
    } else {
        return Double(sorted[middle])
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[middle - 1] + sorted[middle]) / 2
    } else {
        return Double(sorted[middle])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[middle - 1] + sorted[middle]) / 2
    } else {
        return Double(sorted[middle])
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[middle - 1] + sorted[middle]) / 2
    } else {
        return Double(sorted[middle])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    return Double(sorted[mid])
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    return Double(sorted[mid])
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[middle - 1] + sorted[middle]) / 2
    } else {
        return Double(sorted[middle])
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[middle - 1] + sorted[middle]) / 2
    } else {
        return Double(sorted[middle])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[middle - 1] + sorted[middle]) / 2
    } else {
        return Double(sorted[middle])
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[middle - 1] + sorted[middle]) / 2
    } else {
        return Double(sorted[middle])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[middle - 1] + sorted[middle]) / 2
    } else {
        return Double(sorted[middle])
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[middle - 1] + sorted[middle]) / 2
    } else {
        return Double(sorted[middle])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[middle - 1] + sorted[middle]) / 2
    } else {
        return Double(sorted[middle])
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[middle - 1] + sorted[middle]) / 2
    } else {
        return Double(sorted[middle])
    }
}
```
### Test

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[middle - 1] + sorted[middle]) / 2
    } else {
        return Double(sorted[middle])
    }
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
### Response:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[middle - 1] + sorted[middle]) / 2
    } else {
        return Double(sorted[middle])
    }
}
```
### Inst

func isPalindrome(text: String) -> Bool {
    return text.reversed() == text
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    return text.reversed() == text
}
```

func isPalindrome(text: String) -> Bool {
    let text = text.lowercased()
    let textReversed = String(text.reversed())
    return text == textReversed
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    let text = text.lowercased()
    let textReversed = String(text.reversed())
    return text == textReversed
}
```

func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}
```
### Inst

func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}
```

func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}
```

func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}
```

func isPalindrome(text: String) -> Bool {
    return text.reversed() == text
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    return text.reversed() == text
}
```

func isPalindrome(text: String) -> Bool {
    return text.reversed() == text
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    return text.reversed() == text
}
```

func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}
```

func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
### Response:
```swift
func isPalindrome(text: String) -> Bool {
    return text == String(text.reversed())
}
```
### Inst

func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(2), Double(n))) % p
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
### Response:
```swift
func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(2), Double(n))) % p
}
```
### Inst

func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(2), Double(n))) % p
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
### Response:
```swift
func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(2), Double(n))) % p
}
```
### Inst

func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(2), Double(n))) % p
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
### Response:
```swift
func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(2), Double(n))) % p
}
```
### Inst

func modp(n: Int, p: Int) -> Int {
    var result = 1
    var power = n
    var modulo = p
    while power > 0 {
        if power % 2 == 1 {
            result = (result * modulo) % p
        }
        power /= 2
        modulo = (modulo * modulo) % p
    }
    return result
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
### Response:
```swift
func modp(n: Int, p: Int) -> Int {
    var result = 1
    var power = n
    var modulo = p
    while power > 0 {
        if power % 2 == 1 {
            result = (result * modulo) % p
        }
        power /= 2
        modulo = (modulo * modulo) % p
    }
    return result
}
```
### Test

func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(2), Double(n))) % p
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
### Response:
```swift
func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(2), Double(n))) % p
}
```
### Inst

func modp(n: Int, p: Int) -> Int {
    return (1 << n) % p
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
### Response:
```swift
func modp(n: Int, p: Int) -> Int {
    return (1 << n) % p
}
```

func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(2), Double(n)) % Double(p))
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
### Response:
```swift
func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(2), Double(n)) % Double(p))
}
```

func modp(n: Int, p: Int) -> Int {
    return (1 << n) % p
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
### Response:
```swift
func modp(n: Int, p: Int) -> Int {
    return (1 << n) % p
}
```

func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(2), Double(n))) % p
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
### Response:
```swift
func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(2), Double(n))) % p
}
```
### Inst

func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(2), Double(n))) % p
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
### Response:
```swift
func modp(n: Int, p: Int) -> Int {
    return Int(pow(Double(2), Double(n))) % p
}
```

func removeVowels(text: String) -> String {
    let vowels = ["a", "e", "i", "o", "u"]
    return String(text.filter { !vowels.contains($0) })
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
### Response:
```swift
func removeVowels(text: String) -> String {
    let vowels = ["a", "e", "i", "o", "u"]
    return String(text.filter { !vowels.contains($0) })
}
```

func removeVowels(text: String) -> String {
    let vowels = ["a", "e", "i", "o", "u"]
    return String(text.filter { !vowels.contains($0) })
}

### Instruction:
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
### Response:
```swift
func removeVowels(text: String) -> String {
    let vowels = ["a", "e", "i", "o", "u"]
    return String(text.filter { !vowels.contains($0) })
}
```
### Link

func removeVowels(text: String) -> String {
    let vowels = ["a", "e", "i", "o", "u"]
    return String(text.filter { !vowels.contains($0) })
}