func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i+1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i+1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i+1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i+1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i+1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i+1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup = ""
    var openBraces = 0

    for char in parenString {
        if char == "(" {
            openBraces += 1
            currentGroup += char
        } else if char == ")" {
            openBraces -= 1
            currentGroup += char

            if openBraces == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }

    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup = ""
    var openBraces = 0

    for char in parenString {
        if char == "(" {
            openBraces += 1
            currentGroup += char
        } else if char == ")" {
            openBraces -= 1
            currentGroup += char

            if openBraces == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }

    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup = ""
    var stack: [Character] = []

    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            if stack.isEmpty || stack.last!= "(" {
                return []
            }
            stack.removeLast()
        } else {
            continue
        }

        if stack.isEmpty {
            result.append(currentGroup)
            currentGroup = ""
        }
    }

    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup = ""
    var stack: [Character] = []

    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            if stack.isEmpty || stack.last!= "(" {
                return []
            }
            stack.removeLast()
        } else {
            continue
        }

        if stack.isEmpty {
            result.append(currentGroup)
            currentGroup = ""
        }
    }

    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup = ""
    var stack: [Character] = []

    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            if stack.isEmpty || stack.last!= "(" {
                return []
            }
            stack.removeLast()
        } else {
            continue
        }

        if stack.isEmpty {
            result.append(currentGroup)
            currentGroup = ""
        }
    }

    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup = ""
    var stack: [Character] = []

    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            if stack.isEmpty || stack.last!= "(" {
                return []
            }
            stack.removeLast()
        } else {
            continue
        }

        if stack.isEmpty {
            result.append(currentGroup)
            currentGroup = ""
        }
    }

    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup = ""
    var openBraces = 0

    for char in parenString {
        if char == "(" {
            openBraces += 1
            currentGroup += char
        } else if char == ")" {
            openBraces -= 1
            currentGroup += char

            if openBraces == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }

    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup = ""
    var openBraces = 0

    for char in parenString {
        if char == "(" {
            openBraces += 1
            currentGroup += char
        } else if char == ")" {
            openBraces -= 1
            currentGroup += char

            if openBraces == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }

    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup = ""
    var openParenCount = 0

    for char in parenString {
        if char == "(" {
            openParenCount += 1
            currentGroup += char
        } else if char == ")" {
            openParenCount -= 1
            currentGroup += char

            if openParenCount == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }

    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup = ""
    var openParenCount = 0

    for char in parenString {
        if char == "(" {
            openParenCount += 1
            currentGroup += char
        } else if char == ")" {
            openParenCount -= 1
            currentGroup += char

            if openParenCount == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }

    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup = ""
    var openBraces = 0

    for char in parenString {
        if char == "(" {
            openBraces += 1
            currentGroup += char
        } else if char == ")" {
            openBraces -= 1
            currentGroup += char

            if openBraces == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }

    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup = ""
    var openBraces = 0

    for char in parenString {
        if char == "(" {
            openBraces += 1
            currentGroup += char
        } else if char == ")" {
            openBraces -= 1
            currentGroup += char

            if openBraces == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }

    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup = ""
    var openBraces = 0

    for char in parenString {
        if char == "(" {
            openBraces += 1
            currentGroup += char
        } else if char == ")" {
            openBraces -= 1
            currentGroup += char

            if openBraces == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }

    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup = ""
    var openBraces = 0

    for char in parenString {
        if char == "(" {
            openBraces += 1
            currentGroup += char
        } else if char == ")" {
            openBraces -= 1
            currentGroup += char

            if openBraces == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }

    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup: String = ""
    var openBraces = 0

    for char in parenString {
        if char == "(" {
            openBraces += 1
            currentGroup += char
        } else if char == ")" {
            openBraces -= 1
            currentGroup += char

            if openBraces == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }

    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup: String = ""
    var openBraces = 0

    for char in parenString {
        if char == "(" {
            openBraces += 1
            currentGroup += char
        } else if char == ")" {
            openBraces -= 1
            currentGroup += char

            if openBraces == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }

    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup = ""
    var stack: [Character] = []

    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            stack.popLast()
        }

        currentGroup.append(char)

        if stack.isEmpty {
            result.append(currentGroup)
            currentGroup = ""
        }
    }

    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup = ""
    var stack: [Character] = []

    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            stack.popLast()
        }

        currentGroup.append(char)

        if stack.isEmpty {
            result.append(currentGroup)
            currentGroup = ""
        }
    }

    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup = ""
    var stack: [Character] = []

    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            stack.removeLast()
        }

        currentGroup.append(char)

        if stack.isEmpty {
            result.append(currentGroup)
            currentGroup = ""
        }
    }

    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup = ""
    var stack: [Character] = []

    for char in parenString {
        if char == "(" {
            stack.append(char)
        } else if char == ")" {
            stack.removeLast()
        }

        currentGroup.append(char)

        if stack.isEmpty {
            result.append(currentGroup)
            currentGroup = ""
        }
    }

    return result
}
```

func truncateNumber(number: Double) -> Double {
    return number - Int(number)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    return number - Int(number)
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let intPart = Int(number)
    let decimalPart = number - Double(intPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let intPart = Int(number)
    let decimalPart = number - Double(intPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let intPart = Int(number)
    let decimalPart = number - Double(intPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let intPart = Int(number)
    let decimalPart = number - Double(intPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let differences = numbers.map { abs($0 - mean) }
    return differences.reduce(0, +) / Double(differences.count)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let differences = numbers.map { abs($0 - mean) }
    return differences.reduce(0, +) / Double(differences.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let differences = numbers.map { abs($0 - mean) }
    return differences.reduce(0, +) / Double(differences.count)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let differences = numbers.map { abs($0 - mean) }
    return differences.reduce(0, +) / Double(differences.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let differences = numbers.map { abs($0 - mean) }
    return differences.reduce(0, +) / Double(differences.count)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let differences = numbers.map { abs($0 - mean) }
    return differences.reduce(0, +) / Double(differences.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let differences = numbers.map { abs($0 - mean) }
    return differences.reduce(0, +) / Double(differences.count)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let differences = numbers.map { abs($0 - mean) }
    return differences.reduce(0, +) / Double(differences.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let differences = numbers.map { abs($0 - mean) }
    return differences.reduce(0, +) / Double(differences.count)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let differences = numbers.map { abs($0 - mean) }
    return differences.reduce(0, +) / Double(differences.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0.0, +) / Double(numbers.count)
    let differences = numbers.map { abs($0 - mean) }
    return differences.reduce(0.0, +) / Double(differences.count)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0.0, +) / Double(numbers.count)
    let differences = numbers.map { abs($0 - mean) }
    return differences.reduce(0.0, +) / Double(differences.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let differences = numbers.map { abs($0 - mean) }
    return differences.reduce(0, +) / Double(differences.count)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let differences = numbers.map { abs($0 - mean) }
    return differences.reduce(0, +) / Double(differences.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let differences = numbers.map { abs($0 - mean) }
    return differences.reduce(0, +) / Double(differences.count)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let differences = numbers.map { abs($0 - mean) }
    return differences.reduce(0, +) / Double(differences.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0.0, +) / Double(numbers.count)
    let differences = numbers.map { abs($0 - mean) }
    return differences.reduce(0.0, +) / Double(differences.count)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0.0, +) / Double(numbers.count)
    let differences = numbers.map { abs($0 - mean) }
    return differences.reduce(0.0, +) / Double(differences.count)
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let differences = numbers.map { abs($0 - mean) }
    return differences.reduce(0, +) / Double(differences.count)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let differences = numbers.map { abs($0 - mean) }
    return differences.reduce(0, +) / Double(differences.count)
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result: [Int] = []
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func parseNestedParens(parenString: String) -> [Int] {
    let parenGroups = parenString.components(separatedBy: " ")
    var maxDepths = [Int]()
    
    for group in parenGroups {
        var depth = 0
        var maxDepth = 0
        
        for char in group {
            if char == "(" {
                depth += 1
                maxDepth = max(maxDepth, depth)
            } else if char == ")" {
                depth -= 1
            }
        }
        
        maxDepths.append(maxDepth)
    }
    
    return maxDepths
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    let parenGroups = parenString.components(separatedBy: " ")
    var maxDepths = [Int]()
    
    for group in parenGroups {
        var depth = 0
        var maxDepth = 0
        
        for char in group {
            if char == "(" {
                depth += 1
                maxDepth = max(maxDepth, depth)
            } else if char == ")" {
                depth -= 1
            }
        }
        
        maxDepths.append(maxDepth)
    }
    
    return maxDepths
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var maxNesting = [Int]()
    var currentNesting = 0

    for char in parenString {
        if char == "(" {
            currentNesting += 1
        } else if char == ")" {
            currentNesting -= 1
        }

        maxNesting.append(currentNesting)
    }

    return maxNesting
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var maxNesting = [Int]()
    var currentNesting = 0

    for char in parenString {
        if char == "(" {
            currentNesting += 1
        } else if char == ")" {
            currentNesting -= 1
        }

        maxNesting.append(currentNesting)
    }

    return maxNesting
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var maxDepths = [Int]()
    var currentDepth = 0
    var maxDepth = 0

    for char in parenString {
        if char == "(" {
            currentDepth += 1
            maxDepth = max(maxDepth, currentDepth)
        } else if char == ")" {
            currentDepth -= 1
        }
        maxDepths.append(maxDepth)
    }

    return maxDepths
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var maxDepths = [Int]()
    var currentDepth = 0
    var maxDepth = 0

    for char in parenString {
        if char == "(" {
            currentDepth += 1
            maxDepth = max(maxDepth, currentDepth)
        } else if char == ")" {
            currentDepth -= 1
        }
        maxDepths.append(maxDepth)
    }

    return maxDepths
}
```

func parseNestedParens(parenString: String) -> [Int] {
    let parenGroups = parenString.components(separatedBy: " ")
    var maxDepths = [Int]()
    
    for group in parenGroups {
        var depth = 0
        var maxDepth = 0
        
        for char in group {
            if char == "(" {
                depth += 1
                maxDepth = max(maxDepth, depth)
            } else if char == ")" {
                depth -= 1
            }
        }
        
        maxDepths.append(maxDepth)
    }
    
    return maxDepths
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    let parenGroups = parenString.components(separatedBy: " ")
    var maxDepths = [Int]()
    
    for group in parenGroups {
        var depth = 0
        var maxDepth = 0
        
        for char in group {
            if char == "(" {
                depth += 1
                maxDepth = max(maxDepth, depth)
            } else if char == ")" {
                depth -= 1
            }
        }
        
        maxDepths.append(maxDepth)
    }
    
    return maxDepths
}
```

func parseNestedParens(parenString: String) -> [Int] {
    let groups = parenString.split(separator: " ")
    var maxNestingLevels: [Int] = []
    
    for group in groups {
        var currentLevel = 0
        var maxLevel = 0
        
        for char in group {
            if char == "(" {
                currentLevel += 1
                maxLevel = max(maxLevel, currentLevel)
            } else if char == ")" {
                currentLevel -= 1
            }
        }
        
        maxNestingLevels.append(maxLevel)
    }
    
    return maxNestingLevels
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    let groups = parenString.split(separator: " ")
    var maxNestingLevels: [Int] = []
    
    for group in groups {
        var currentLevel = 0
        var maxLevel = 0
        
        for char in group {
            if char == "(" {
                currentLevel += 1
                maxLevel = max(maxLevel, currentLevel)
            } else if char == ")" {
                currentLevel -= 1
            }
        }
        
        maxNestingLevels.append(maxLevel)
    }
    
    return maxNestingLevels
}
```

func parseNestedParens(parenString: String) -> [Int] {
    let groups = parenString.components(separatedBy: " ")
    var maxDepths = [Int]()
    
    for group in groups {
        var depth = 0
        var maxDepth = 0
        
        for char in group {
            if char == "(" {
                depth += 1
                maxDepth = max(maxDepth, depth)
            } else if char == ")" {
                depth -= 1
            }
        }
        
        maxDepths.append(maxDepth)
    }
    
    return maxDepths
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    let groups = parenString.components(separatedBy: " ")
    var maxDepths = [Int]()
    
    for group in groups {
        var depth = 0
        var maxDepth = 0
        
        for char in group {
            if char == "(" {
                depth += 1
                maxDepth = max(maxDepth, depth)
            } else if char == ")" {
                depth -= 1
            }
        }
        
        maxDepths.append(maxDepth)
    }
    
    return maxDepths
}
```

func parseNestedParens(parenString: String) -> [Int] {
    let groups = parenString.components(separatedBy: " ")
    var maxDepths = [Int]()
    
    for group in groups {
        var depth = 0
        var maxDepth = 0
        
        for char in group {
            if char == "(" {
                depth += 1
                maxDepth = max(maxDepth, depth)
            } else if char == ")" {
                depth -= 1
            }
        }
        
        maxDepths.append(maxDepth)
    }
    
    return maxDepths
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    let groups = parenString.components(separatedBy: " ")
    var maxDepths = [Int]()
    
    for group in groups {
        var depth = 0
        var maxDepth = 0
        
        for char in group {
            if char == "(" {
                depth += 1
                maxDepth = max(maxDepth, depth)
            } else if char == ")" {
                depth -= 1
            }
        }
        
        maxDepths.append(maxDepth)
    }
    
    return maxDepths
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var maxNesting = [Int]()
    var currentNesting = 0
    var currentMax = 0

    for char in parenString {
        if char == "(" {
            currentNesting += 1
            currentMax = max(currentMax, currentNesting)
        } else if char == ")" {
            currentNesting -= 1
        }
        maxNesting.append(currentMax)
    }

    return maxNesting
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var maxNesting = [Int]()
    var currentNesting = 0
    var currentMax = 0

    for char in parenString {
        if char == "(" {
            currentNesting += 1
            currentMax = max(currentMax, currentNesting)
        } else if char == ")" {
            currentNesting -= 1
        }
        maxNesting.append(currentMax)
    }

    return maxNesting
}
```

func parseNestedParens(parenString: String) -> [Int] {
    let parenGroups = parenString.components(separatedBy: " ")
    var maxDepths = [Int]()
    
    for group in parenGroups {
        var depth = 0
        var maxDepth = 0
        
        for char in group {
            if char == "(" {
                depth += 1
                maxDepth = max(maxDepth, depth)
            } else if char == ")" {
                depth -= 1
            }
        }
        
        maxDepths.append(maxDepth)
    }
    
    return maxDepths
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    let parenGroups = parenString.components(separatedBy: " ")
    var maxDepths = [Int]()
    
    for group in parenGroups {
        var depth = 0
        var maxDepth = 0
        
        for char in group {
            if char == "(" {
                depth += 1
                maxDepth = max(maxDepth, depth)
            } else if char == ")" {
                depth -= 1
            }
        }
        
        maxDepths.append(maxDepth)
    }
    
    return maxDepths
}
```

func parseNestedParens(parenString: String) -> [Int] {
    let parenGroups = parenString.components(separatedBy: " ")
    var maxDepths = [Int]()
    
    for parenGroup in parenGroups {
        var depth = 0
        var maxDepth = 0
        
        for char in parenGroup {
            if char == "(" {
                depth += 1
                maxDepth = max(maxDepth, depth)
            } else if char == ")" {
                depth -= 1
            }
        }
        
        maxDepths.append(maxDepth)
    }
    
    return maxDepths
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    let parenGroups = parenString.components(separatedBy: " ")
    var maxDepths = [Int]()
    
    for parenGroup in parenGroups {
        var depth = 0
        var maxDepth = 0
        
        for char in parenGroup {
            if char == "(" {
                depth += 1
                maxDepth = max(maxDepth, depth)
            } else if char == ")" {
                depth -= 1
            }
        }
        
        maxDepths.append(maxDepth)
    }
    
    return maxDepths
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    
    for number in numbers {
        sum += number
        product *= number
    }
    
    return (sum, product)
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var max = numbers[0]
    var result = [max]
    
    for number in numbers {
        max = max > number? max : number
        result.append(max)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var max = numbers[0]
    var result = [max]
    
    for number in numbers {
        max = max > number? max : number
        result.append(max)
    }
    
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var max = numbers[0]
    var result = [max]
    
    for number in numbers {
        max = max > number? max : number
        result.append(max)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var max = numbers[0]
    var result = [max]
    
    for number in numbers {
        max = max > number? max : number
        result.append(max)
    }
    
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var max = 0
    var result = [Int]()
    
    for number in numbers {
        max = max > number? max : number
        result.append(max)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var max = 0
    var result = [Int]()
    
    for number in numbers {
        max = max > number? max : number
        result.append(max)
    }
    
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var max = numbers[0]
    var result = [max]
    
    for number in numbers {
        if number > max {
            max = number
        }
        result.append(max)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var max = numbers[0]
    var result = [max]
    
    for number in numbers {
        if number > max {
            max = number
        }
        result.append(max)
    }
    
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var max = numbers[0]
    var result = [max]
    
    for number in numbers {
        max = max > number? max : number
        result.append(max)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var max = numbers[0]
    var result = [max]
    
    for number in numbers {
        max = max > number? max : number
        result.append(max)
    }
    
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var max = 0
    var result = [Int]()
    
    for number in numbers {
        if number > max {
            max = number
        }
        result.append(max)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var max = 0
    var result = [Int]()
    
    for number in numbers {
        if number > max {
            max = number
        }
        result.append(max)
    }
    
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var max = 0
    var result = [Int]()
    
    for number in numbers {
        if number > max {
            max = number
        }
        result.append(max)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var max = 0
    var result = [Int]()
    
    for number in numbers {
        if number > max {
            max = number
        }
        result.append(max)
    }
    
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var maxElement = numbers[0]
    var result = [maxElement]
    
    for number in numbers {
        maxElement = max(maxElement, number)
        result.append(maxElement)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var maxElement = numbers[0]
    var result = [maxElement]
    
    for number in numbers {
        maxElement = max(maxElement, number)
        result.append(maxElement)
    }
    
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var maxElement = numbers[0]
    var rollingMax = [maxElement]
    
    for number in numbers {
        maxElement = max(maxElement, number)
        rollingMax.append(maxElement)
    }
    
    return rollingMax
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var maxElement = numbers[0]
    var rollingMax = [maxElement]
    
    for number in numbers {
        maxElement = max(maxElement, number)
        rollingMax.append(maxElement)
    }
    
    return rollingMax
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var maxElement = numbers[0]
    var result = [maxElement]
    
    for number in numbers {
        maxElement = max(maxElement, number)
        result.append(maxElement)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var maxElement = numbers[0]
    var result = [maxElement]
    
    for number in numbers {
        maxElement = max(maxElement, number)
        result.append(maxElement)
    }
    
    return result
}
```

func makePalindrome(string: String) -> String {
    let length = string.count
    if length == 0 {
        return string
    }
    var left = 0
    var right = length - 1
    while left < right {
        if string[left] == string[right] {
            left += 1
            right -= 1
        } else {
            break
        }
    }
    let prefix = String(string.prefix(left))
    let suffix = String(string.suffix(from: right + 1))
    return prefix + String(suffix.reversed()) + prefix
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let length = string.count
    if length == 0 {
        return string
    }
    var left = 0
    var right = length - 1
    while left < right {
        if string[left] == string[right] {
            left += 1
            right -= 1
        } else {
            break
        }
    }
    let prefix = String(string.prefix(left))
    let suffix = String(string.suffix(from: right + 1))
    return prefix + String(suffix.reversed()) + prefix
}
```

func makePalindrome(string: String) -> String {
    let length = string.count
    if length == 0 {
        return string
    }
    let mid = length / 2
    let prefix = String(string.prefix(mid))
    let suffix = String(string.suffix(from: mid))
    if prefix == String(prefix.reversed()) {
        return string + String(suffix.reversed())
    } else {
        let reversedPrefix = String(prefix.reversed())
        let palindrome = makePalindrome(string: reversedPrefix)
        return palindrome + string
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let length = string.count
    if length == 0 {
        return string
    }
    let mid = length / 2
    let prefix = String(string.prefix(mid))
    let suffix = String(string.suffix(from: mid))
    if prefix == String(prefix.reversed()) {
        return string + String(suffix.reversed())
    } else {
        let reversedPrefix = String(prefix.reversed())
        let palindrome = makePalindrome(string: reversedPrefix)
        return palindrome + string
    }
}
```

func makePalindrome(string: String) -> String {
    let length = string.count
    if length == 0 {
        return string
    }
    let mid = length / 2
    let prefix = String(string.prefix(mid))
    let suffix = String(string.suffix(from: mid))
    if prefix == String(prefix.reversed()) {
        return string + String(suffix.reversed())
    } else {
        let midIndex = string.index(string.startIndex, offsetBy: mid)
        let leftPalindrome = makePalindrome(string: String(string.prefix(upTo: midIndex)))
        let rightPalindrome = makePalindrome(string: String(string.suffix(from: midIndex)))
        return leftPalindrome + rightPalindrome
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let length = string.count
    if length == 0 {
        return string
    }
    let mid = length / 2
    let prefix = String(string.prefix(mid))
    let suffix = String(string.suffix(from: mid))
    if prefix == String(prefix.reversed()) {
        return string + String(suffix.reversed())
    } else {
        let midIndex = string.index(string.startIndex, offsetBy: mid)
        let leftPalindrome = makePalindrome(string: String(string.prefix(upTo: midIndex)))
        let rightPalindrome = makePalindrome(string: String(string.suffix(from: midIndex)))
        return leftPalindrome + rightPalindrome
    }
}
```

func makePalindrome(string: String) -> String {
    let length = string.count
    let mid = length / 2
    let prefix = String(string.prefix(mid))
    let suffix = String(string.suffix(from: length - mid))
    let reversedPrefix = String(prefix.reversed())
    return "\(prefix)\(reversedPrefix)\(suffix)"
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let length = string.count
    let mid = length / 2
    let prefix = String(string.prefix(mid))
    let suffix = String(string.suffix(from: length - mid))
    let reversedPrefix = String(prefix.reversed())
    return "\(prefix)\(reversedPrefix)\(suffix)"
}
```

func makePalindrome(string: String) -> String {
    let length = string.count
    if length <= 1 {
        return string
    }
    let prefix = String(string.prefix(length - 1))
    let suffix = String(string.suffix(length - 1))
    if prefix == String(prefix.reversed()) {
        return string + String(suffix.reversed())
    } else {
        return makePalindrome(string: prefix) + string
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let length = string.count
    if length <= 1 {
        return string
    }
    let prefix = String(string.prefix(length - 1))
    let suffix = String(string.suffix(length - 1))
    if prefix == String(prefix.reversed()) {
        return string + String(suffix.reversed())
    } else {
        return makePalindrome(string: prefix) + string
    }
}
```

func makePalindrome(string: String) -> String {
    let length = string.count
    if length < 2 {
        return string
    }

    let prefix = String(string.prefix(length - 1))
    let suffix = String(string.suffix(length - 1))

    if prefix == String(prefix.reversed()) {
        return string + String(suffix.reversed())
    } else {
        return makePalindrome(string: prefix) + string
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let length = string.count
    if length < 2 {
        return string
    }

    let prefix = String(string.prefix(length - 1))
    let suffix = String(string.suffix(length - 1))

    if prefix == String(prefix.reversed()) {
        return string + String(suffix.reversed())
    } else {
        return makePalindrome(string: prefix) + string
    }
}
```

func makePalindrome(string: String) -> String {
    let length = string.count
    if length == 0 {
        return string
    }

    let prefix = String(string.prefix(length / 2))
    let suffix = String(string.suffix(length / 2))

    if prefix == String(prefix.reversed()) {
        return string + String(suffix.reversed())
    } else {
        let mid = length / 2
        let left = String(string.prefix(mid))
        let right = String(string.suffix(mid))
        let reversedLeft = String(left.reversed())
        return reversedLeft + string + reversedLeft
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let length = string.count
    if length == 0 {
        return string
    }

    let prefix = String(string.prefix(length / 2))
    let suffix = String(string.suffix(length / 2))

    if prefix == String(prefix.reversed()) {
        return string + String(suffix.reversed())
    } else {
        let mid = length / 2
        let left = String(string.prefix(mid))
        let right = String(string.suffix(mid))
        let reversedLeft = String(left.reversed())
        return reversedLeft + string + reversedLeft
    }
}
```

func makePalindrome(string: String) -> String {
    let length = string.count
    if length < 2 {
        return string
    }

    let prefix = String(string.prefix(length - 1))
    let suffix = String(string.suffix(length - 1))

    if prefix == String(prefix.reversed()) {
        return string + suffix
    } else {
        return makePalindrome(string: prefix) + suffix
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let length = string.count
    if length < 2 {
        return string
    }

    let prefix = String(string.prefix(length - 1))
    let suffix = String(string.suffix(length - 1))

    if prefix == String(prefix.reversed()) {
        return string + suffix
    } else {
        return makePalindrome(string: prefix) + suffix
    }
}
```

func makePalindrome(string: String) -> String {
    let length = string.count
    if length == 0 {
        return string
    }
    let prefix = String(string.prefix(length / 2))
    let suffix = String(string.suffix(length / 2))
    if prefix == suffix {
        return string
    }
    let reversedPrefix = String(prefix.reversed())
    return "\(string)\(reversedPrefix)"
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let length = string.count
    if length == 0 {
        return string
    }
    let prefix = String(string.prefix(length / 2))
    let suffix = String(string.suffix(length / 2))
    if prefix == suffix {
        return string
    }
    let reversedPrefix = String(prefix.reversed())
    return "\(string)\(reversedPrefix)"
}
```

func makePalindrome(string: String) -> String {
    let length = string.count
    if length <= 1 {
        return string
    }

    let prefix = String(string.prefix(length - 1))
    let suffix = String(string.suffix(length - 1))

    if prefix == reverse(suffix) {
        return string
    }

    let middle = makePalindrome(string: suffix)
    return prefix + middle + reverse(prefix)
}

func reverse(_ string: String) -> String {
    return String(string.reversed())
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let length = string.count
    if length <= 1 {
        return string
    }

    let prefix = String(string.prefix(length - 1))
    let suffix = String(string.suffix(length - 1))

    if prefix == reverse(suffix) {
        return string
    }

    let middle = makePalindrome(string: suffix)
    return prefix + middle + reverse(prefix)
}

func reverse(_ string: String) -> String {
    return String(string.reversed())
}
```

func stringXor(a: String, b: String) -> String {
    let aArray = Array(a)
    let bArray = Array(b)
    var result = [Character]()
    
    for i in 0..<aArray.count {
        let aInt = Int(String(aArray[i]))?? 0
        let bInt = Int(String(bArray[i]))?? 0
        let xorInt = aInt ^ bInt
        let xorChar = Character(UnicodeScalar(xorInt)!)
        result.append(xorChar)
    }
    
    return String(result)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aArray = Array(a)
    let bArray = Array(b)
    var result = [Character]()
    
    for i in 0..<aArray.count {
        let aInt = Int(String(aArray[i]))?? 0
        let bInt = Int(String(bArray[i]))?? 0
        let xorInt = aInt ^ bInt
        let xorChar = Character(UnicodeScalar(xorInt)!)
        result.append(xorChar)
    }
    
    return String(result)
}
```

func stringXor(a: String, b: String) -> String {
    let aArray = Array(a)
    let bArray = Array(b)
    var result = [Character]()
    
    for i in 0..<aArray.count {
        let aInt = Int(String(aArray[i]))?? 0
        let bInt = Int(String(bArray[i]))?? 0
        let xorInt = aInt ^ bInt
        let xorStr = String(xorInt)
        result.append(Character(xorStr))
    }
    
    return String(result)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aArray = Array(a)
    let bArray = Array(b)
    var result = [Character]()
    
    for i in 0..<aArray.count {
        let aInt = Int(String(aArray[i]))?? 0
        let bInt = Int(String(bArray[i]))?? 0
        let xorInt = aInt ^ bInt
        let xorStr = String(xorInt)
        result.append(Character(xorStr))
    }
    
    return String(result)
}
```

func stringXor(a: String, b: String) -> String {
    let aArray = Array(a)
    let bArray = Array(b)
    var result = [Character]()
    
    for i in 0..<aArray.count {
        let aInt = Int(String(aArray[i]))?? 0
        let bInt = Int(String(bArray[i]))?? 0
        let xorInt = aInt ^ bInt
        let xorChar = Character(UnicodeScalar(xorInt)!)
        result.append(xorChar)
    }
    
    return String(result)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aArray = Array(a)
    let bArray = Array(b)
    var result = [Character]()
    
    for i in 0..<aArray.count {
        let aInt = Int(String(aArray[i]))?? 0
        let bInt = Int(String(bArray[i]))?? 0
        let xorInt = aInt ^ bInt
        let xorChar = Character(UnicodeScalar(xorInt)!)
        result.append(xorChar)
    }
    
    return String(result)
}
```

func stringXor(a: String, b: String) -> String {
    let aArray = Array(a)
    let bArray = Array(b)
    var result = [Character]()

    for (index, _) in aArray.enumerated() {
        let aBit = aArray[index] == "1"? 1 : 0
        let bBit = bArray[index] == "1"? 1 : 0
        let xorBit = aBit ^ bBit
        let xorChar = xorBit == 1? "1" : "0"
        result.append(Character(xorChar))
    }

    return String(result)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aArray = Array(a)
    let bArray = Array(b)
    var result = [Character]()

    for (index, _) in aArray.enumerated() {
        let aBit = aArray[index] == "1"? 1 : 0
        let bBit = bArray[index] == "1"? 1 : 0
        let xorBit = aBit ^ bBit
        let xorChar = xorBit == 1? "1" : "0"
        result.append(Character(xorChar))
    }

    return String(result)
}
```

func stringXor(a: String, b: String) -> String {
    let aArray = Array(a)
    let bArray = Array(b)
    var result = [Character]()
    
    for i in 0..<aArray.count {
        let aInt = Int(String(aArray[i]))!
        let bInt = Int(String(bArray[i]))!
        let xorInt = aInt ^ bInt
        let xorChar = Character(UnicodeScalar(xorInt)!)
        result.append(xorChar)
    }
    
    return String(result)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aArray = Array(a)
    let bArray = Array(b)
    var result = [Character]()
    
    for i in 0..<aArray.count {
        let aInt = Int(String(aArray[i]))!
        let bInt = Int(String(bArray[i]))!
        let xorInt = aInt ^ bInt
        let xorChar = Character(UnicodeScalar(xorInt)!)
        result.append(xorChar)
    }
    
    return String(result)
}
```

func stringXor(a: String, b: String) -> String {
    let aArray = Array(a)
    let bArray = Array(b)
    var resultArray = [Character]()
    
    for i in 0..<aArray.count {
        let aInt = Int(String(aArray[i]))!
        let bInt = Int(String(bArray[i]))!
        let xorInt = aInt ^ bInt
        let xorChar = Character(UnicodeScalar(xorInt)!)
        resultArray.append(xorChar)
    }
    
    return String(resultArray)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aArray = Array(a)
    let bArray = Array(b)
    var resultArray = [Character]()
    
    for i in 0..<aArray.count {
        let aInt = Int(String(aArray[i]))!
        let bInt = Int(String(bArray[i]))!
        let xorInt = aInt ^ bInt
        let xorChar = Character(UnicodeScalar(xorInt)!)
        resultArray.append(xorChar)
    }
    
    return String(resultArray)
}
```

func stringXor(a: String, b: String) -> String {
    let aArray = Array(a)
    let bArray = Array(b)
    var result = [Character]()
    
    for i in 0..<aArray.count {
        let aInt = Int(String(aArray[i]))!
        let bInt = Int(String(bArray[i]))!
        let xorResult = aInt ^ bInt
        result.append(Character(UnicodeScalar(xorResult)!))
    }
    
    return String(result)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aArray = Array(a)
    let bArray = Array(b)
    var result = [Character]()
    
    for i in 0..<aArray.count {
        let aInt = Int(String(aArray[i]))!
        let bInt = Int(String(bArray[i]))!
        let xorResult = aInt ^ bInt
        result.append(Character(UnicodeScalar(xorResult)!))
    }
    
    return String(result)
}
```

func stringXor(a: String, b: String) -> String {
    let aArray = Array(a)
    let bArray = Array(b)
    var result = [Character]()
    
    for i in 0..<aArray.count {
        let aInt = Int(String(aArray[i]))!
        let bInt = Int(String(bArray[i]))!
        let xorInt = aInt ^ bInt
        let xorChar = Character(UnicodeScalar(xorInt)!)
        result.append(xorChar)
    }
    
    return String(result)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aArray = Array(a)
    let bArray = Array(b)
    var result = [Character]()
    
    for i in 0..<aArray.count {
        let aInt = Int(String(aArray[i]))!
        let bInt = Int(String(bArray[i]))!
        let xorInt = aInt ^ bInt
        let xorChar = Character(UnicodeScalar(xorInt)!)
        result.append(xorChar)
    }
    
    return String(result)
}
```

func stringXor(a: String, b: String) -> String {
    let aArray = Array(a)
    let bArray = Array(b)
    var result = [Character]()
    
    for (i, char) in aArray.enumerated() {
        let aInt = Int(String(char))!
        let bInt = Int(String(bArray[i]))!
        let xorInt = aInt ^ bInt
        let xorChar = Character(UnicodeScalar(xorInt)!)
        result.append(xorChar)
    }
    
    return String(result)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aArray = Array(a)
    let bArray = Array(b)
    var result = [Character]()
    
    for (i, char) in aArray.enumerated() {
        let aInt = Int(String(char))!
        let bInt = Int(String(bArray[i]))!
        let xorInt = aInt ^ bInt
        let xorChar = Character(UnicodeScalar(xorInt)!)
        result.append(xorChar)
    }
    
    return String(result)
}
```

func stringXor(a: String, b: String) -> String {
    let aArray = Array(a)
    let bArray = Array(b)
    var result = [Character]()
    
    for i in 0..<aArray.count {
        let aInt = Int(String(aArray[i]))!
        let bInt = Int(String(bArray[i]))!
        let xorInt = aInt ^ bInt
        let xorChar = Character(UnicodeScalar(xorInt)!)
        result.append(xorChar)
    }
    
    return String(result)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aArray = Array(a)
    let bArray = Array(b)
    var result = [Character]()
    
    for i in 0..<aArray.count {
        let aInt = Int(String(aArray[i]))!
        let bInt = Int(String(bArray[i]))!
        let xorInt = aInt ^ bInt
        let xorChar = Character(UnicodeScalar(xorInt)!)
        result.append(xorChar)
    }
    
    return String(result)
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.sorted { $0.count > $1.count }.first
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.sorted { $0.count > $1.count }.first
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.sorted { $0.count > $1.count }.first
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.sorted { $0.count > $1.count }.first
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.sorted { $0.count > $1.count }.first
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.sorted { $0.count > $1.count }.first
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.sorted { $0.count > $1.count }.first
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.sorted { $0.count > $1.count }.first
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.sorted { $0.count > $1.count }.first
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.sorted { $0.count > $1.count }.first
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.sorted { $0.count > $1.count }.first
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.sorted { $0.count > $1.count }.first
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.sorted { $0.count > $1.count }.first
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.sorted { $0.count > $1.count }.first
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.sorted { $0.count > $1.count }.first
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.sorted { $0.count > $1.count }.first
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.sorted { $0.count > $1.count }.first
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.sorted { $0.count > $1.count }.first
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.sorted { $0.count > $1.count }.first
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.sorted { $0.count > $1.count }.first
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    }
    return greatestCommonDivisor(b, a % b)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    }
    return greatestCommonDivisor(b, a % b)
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    }
    return greatestCommonDivisor(b, a % b)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    }
    return greatestCommonDivisor(b, a % b)
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    }
    return greatestCommonDivisor(b, a % b)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    }
    return greatestCommonDivisor(b, a % b)
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    }
    return greatestCommonDivisor(b, a % b)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    }
    return greatestCommonDivisor(b, a % b)
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    }
    return greatestCommonDivisor(b, a % b)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    }
    return greatestCommonDivisor(b, a % b)
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var x = a
    var y = b

    while y!= 0 {
        let temp = y
        y = x % y
        x = temp
    }

    return x
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var x = a
    var y = b

    while y!= 0 {
        let temp = y
        y = x % y
        x = temp
    }

    return x
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    }
    return greatestCommonDivisor(b, a % b)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    }
    return greatestCommonDivisor(b, a % b)
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    }
    return greatestCommonDivisor(b, a % b)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    }
    return greatestCommonDivisor(b, a % b)
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    }
    return greatestCommonDivisor(b, a % b)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    if b == 0 {
        return a
    }
    return greatestCommonDivisor(b, a % b)
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var x = a
    var y = b
    
    while y!= 0 {
        let temp = y
        y = x % y
        x = temp
    }
    
    return x
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var x = a
    var y = b
    
    while y!= 0 {
        let temp = y
        y = x % y
        x = temp
    }
    
    return x
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 1...string.count {
        let prefix = String(string.prefix(i))
        prefixes.append(prefix)
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 1...string.count {
        let prefix = String(string.prefix(i))
        prefixes.append(prefix)
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 1...string.count {
        let prefix = String(string.prefix(i))
        prefixes.append(prefix)
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 1...string.count {
        let prefix = String(string.prefix(i))
        prefixes.append(prefix)
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 1...string.count {
        prefixes.append(String(string.prefix(i)))
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 1...string.count {
        prefixes.append(String(string.prefix(i)))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes = [String]()
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}
```

func stringSequence(n: Int) -> String {
    var sequence = [String]()
    for i in 0...n {
        sequence.append(String(i))
    }
    return sequence.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var sequence = [String]()
    for i in 0...n {
        sequence.append(String(i))
    }
    return sequence.joined(separator: " ")
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
```

func stringSequence(n: Int) -> String {
    var sequence = [String]()
    for i in 0...n {
        sequence.append(String(i))
    }
    return sequence.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var sequence = [String]()
    for i in 0...n {
        sequence.append(String(i))
    }
    return sequence.joined(separator: " ")
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
```

func stringSequence(n: Int) -> String {
    var sequence = [String]()
    for i in 0...n {
        sequence.append(String(i))
    }
    return sequence.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var sequence = [String]()
    for i in 0...n {
        sequence.append(String(i))
    }
    return sequence.joined(separator: " ")
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
```

func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    var result = ""
    for i in 0...n {
        result += "\(i) "
    }
    return result.trimmingCharacters(in:.whitespacesAndNewlines)
}
```

func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    let distinctCharacters = Set(lowercaseString)
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    let distinctCharacters = Set(lowercaseString)
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    let distinctCharacters = Set(lowercaseString)
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    let distinctCharacters = Set(lowercaseString)
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    let distinctCharacters = Set(lowercaseString)
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    let distinctCharacters = Set(lowercaseString)
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    let distinctCharacters = Set(lowercaseString)
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    let distinctCharacters = Set(lowercaseString)
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    let distinctCharacters = Set(lowercaseString)
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    let distinctCharacters = Set(lowercaseString)
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    let distinctCharacters = Set(lowercaseString)
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    let distinctCharacters = Set(lowercaseString)
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    let distinctCharacters = Set(lowercaseString)
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    let distinctCharacters = Set(lowercaseString)
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    let distinctCharacters = Set(lowercaseString)
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    let distinctCharacters = Set(lowercaseString)
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    let distinctCharacters = Set(lowercaseString)
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    let distinctCharacters = Set(lowercaseString)
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    let distinctCharacters = Set(lowercaseString)
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    let distinctCharacters = Set(lowercaseString)
    return distinctCharacters.count
}
```

func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats: [Int] = []
    
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats: [Int] = []
    
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats: [Int] = []
    
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats: [Int] = []
    
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats: [Int] = []
    
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats: [Int] = []
    
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats: [Int] = []
    
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats: [Int] = []
    
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats = [Int]()
    
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats = [Int]()
    
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats: [Int] = []
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats: [Int] = []
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats = [Int]()
    
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats = [Int]()
    
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats: [Int] = []
    
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats: [Int] = []
    
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats = [Int]()
    
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats = [Int]()
    
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats: [Int] = []
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats: [Int] = []
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}
```

func howManyTimes(string: String, substring: String) -> Int {
    guard!substring.isEmpty else {
        return 0
    }

    var count = 0
    var index = string.startIndex

    while let range = string.range(of: substring, options:.caseInsensitive, range: index..<string.endIndex) {
        count += 1
        index = range.upperBound
    }

    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    guard!substring.isEmpty else {
        return 0
    }

    var count = 0
    var index = string.startIndex

    while let range = string.range(of: substring, options:.caseInsensitive, range: index..<string.endIndex) {
        count += 1
        index = range.upperBound
    }

    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    guard!substring.isEmpty else {
        return 0
    }
    
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.anchored, range: index..<string.endIndex) {
        count += 1
        index = range.upperBound
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    guard!substring.isEmpty else {
        return 0
    }
    
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.anchored, range: index..<string.endIndex) {
        count += 1
        index = range.upperBound
    }
    
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    guard!substring.isEmpty else {
        return 0
    }
    
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.caseInsensitive, range: index..<string.endIndex) {
        count += 1
        index = range.upperBound
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    guard!substring.isEmpty else {
        return 0
    }
    
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.caseInsensitive, range: index..<string.endIndex) {
        count += 1
        index = range.upperBound
    }
    
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    guard!substring.isEmpty else {
        return 0
    }

    var count = 0
    var index = string.startIndex

    while let range = string.range(of: substring, options:.anchored, range: index..<string.endIndex) {
        count += 1
        index = range.upperBound
    }

    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    guard!substring.isEmpty else {
        return 0
    }

    var count = 0
    var index = string.startIndex

    while let range = string.range(of: substring, options:.anchored, range: index..<string.endIndex) {
        count += 1
        index = range.upperBound
    }

    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    guard!substring.isEmpty else {
        return 0
    }

    var count = 0
    var index = string.startIndex

    while let range = string.range(of: substring, options:.caseInsensitive, range: index..<string.endIndex) {
        count += 1
        index = range.upperBound
    }

    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    guard!substring.isEmpty else {
        return 0
    }

    var count = 0
    var index = string.startIndex

    while let range = string.range(of: substring, options:.caseInsensitive, range: index..<string.endIndex) {
        count += 1
        index = range.upperBound
    }

    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    guard!substring.isEmpty else {
        return 0
    }
    
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.anchored, range: index..<string.endIndex) {
        count += 1
        index = range.upperBound
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    guard!substring.isEmpty else {
        return 0
    }
    
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.anchored, range: index..<string.endIndex) {
        count += 1
        index = range.upperBound
    }
    
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    guard!substring.isEmpty else {
        return 0
    }
    
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.caseInsensitive, range: index..<string.endIndex) {
        count += 1
        index = range.upperBound
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    guard!substring.isEmpty else {
        return 0
    }
    
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.caseInsensitive, range: index..<string.endIndex) {
        count += 1
        index = range.upperBound
    }
    
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    guard!substring.isEmpty else {
        return 0
    }

    var count = 0
    var index = string.startIndex

    while let range = string.range(of: substring, options:.anchored, range: index..<string.endIndex) {
        count += 1
        index = string.index(after: range.upperBound)
    }

    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    guard!substring.isEmpty else {
        return 0
    }

    var count = 0
    var index = string.startIndex

    while let range = string.range(of: substring, options:.anchored, range: index..<string.endIndex) {
        count += 1
        index = string.index(after: range.upperBound)
    }

    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    guard!substring.isEmpty else {
        return 0
    }
    
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.anchored, range: index..<string.endIndex) {
        count += 1
        index = range.upperBound
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    guard!substring.isEmpty else {
        return 0
    }
    
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.anchored, range: index..<string.endIndex) {
        count += 1
        index = range.upperBound
    }
    
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.anchored, range: index..<string.endIndex) {
        count += 1
        index = string.index(after: range.upperBound)
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var index = string.startIndex
    
    while let range = string.range(of: substring, options:.anchored, range: index..<string.endIndex) {
        count += 1
        index = string.index(after: range.upperBound)
    }
    
    return count
}
```

func sortNumbers(numbers: String) -> String {
    let words = numbers.components(separatedBy: " ")
    let numbers = words.map { number in
        switch number {
        case "zero": return 0
        case "one": return 1
        case "two": return 2
        case "three": return 3
        case "four": return 4
        case "five": return 5
        case "six": return 6
        case "seven": return 7
        case "eight": return 8
        case "nine": return 9
        default: return 0
        }
    }
    let sortedNumbers = numbers.sorted()
    let sortedWords = sortedNumbers.map { number in
        switch number {
        case 0: return "zero"
        case 1: return "one"
        case 2: return "two"
        case 3: return "three"
        case 4: return "four"
        case 5: return "five"
        case 6: return "six"
        case 7: return "seven"
        case 8: return "eight"
        case 9: return "nine"
        default: return ""
        }
    }
    return sortedWords.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let words = numbers.components(separatedBy: " ")
    let numbers = words.map { number in
        switch number {
        case "zero": return 0
        case "one": return 1
        case "two": return 2
        case "three": return 3
        case "four": return 4
        case "five": return 5
        case "six": return 6
        case "seven": return 7
        case "eight": return 8
        case "nine": return 9
        default: return 0
        }
    }
    let sortedNumbers = numbers.sorted()
    let sortedWords = sortedNumbers.map { number in
        switch number {
        case 0: return "zero"
        case 1: return "one"
        case 2: return "two"
        case 3: return "three"
        case 4: return "four"
        case 5: return "five"
        case 6: return "six"
        case 7: return "seven"
        case 8: return "eight"
        case 9: return "nine"
        default: return ""
        }
    }
    return sortedWords.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numberWords = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
    let numberValues = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
    let numberMap = Dictionary(zip(numberWords, numberValues))
    
    let sortedNumbers = numbers.components(separatedBy: " ").sorted { numberMap[$0]! < numberMap[$1]! }
    return sortedNumbers.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberWords = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
    let numberValues = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
    let numberMap = Dictionary(zip(numberWords, numberValues))
    
    let sortedNumbers = numbers.components(separatedBy: " ").sorted { numberMap[$0]! < numberMap[$1]! }
    return sortedNumbers.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numberMap = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
    let numbersArray = numbers.components(separatedBy: " ")
    let sortedNumbersArray = numbersArray.sorted { numberMap[$0]! < numberMap[$1]! }
    return sortedNumbersArray.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberMap = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
    let numbersArray = numbers.components(separatedBy: " ")
    let sortedNumbersArray = numbersArray.sorted { numberMap[$0]! < numberMap[$1]! }
    return sortedNumbersArray.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let words = numbers.components(separatedBy: " ")
    let numbers = words.map { numberWords[$0]! }
    let sortedNumbers = numbers.sorted()
    let sortedWords = sortedNumbers.map { numberMap[$0]! }
    return sortedWords.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let words = numbers.components(separatedBy: " ")
    let numbers = words.map { numberWords[$0]! }
    let sortedNumbers = numbers.sorted()
    let sortedWords = sortedNumbers.map { numberMap[$0]! }
    return sortedWords.joined(separator: " ")
}

let numberWords = [
    "zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9
]

let numberMap = [
    0: "zero", 1: "one", 2: "two", 3: "three", 4: "four", 5: "five", 6: "six", 7: "seven", 8: "eight", 9: "nine"
]
```

func sortNumbers(numbers: String) -> String {
    let words = numbers.components(separatedBy: " ")
    let numbers = words.map { number in
        switch number {
        case "zero": return 0
        case "one": return 1
        case "two": return 2
        case "three": return 3
        case "four": return 4
        case "five": return 5
        case "six": return 6
        case "seven": return 7
        case "eight": return 8
        case "nine": return 9
        default: return -1
        }
    }
    let sortedNumbers = numbers.sorted()
    let sortedWords = sortedNumbers.map { number in
        switch number {
        case 0: return "zero"
        case 1: return "one"
        case 2: return "two"
        case 3: return "three"
        case 4: return "four"
        case 5: return "five"
        case 6: return "six"
        case 7: return "seven"
        case 8: return "eight"
        case 9: return "nine"
        default: return ""
        }
    }
    return sortedWords.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let words = numbers.components(separatedBy: " ")
    let numbers = words.map { number in
        switch number {
        case "zero": return 0
        case "one": return 1
        case "two": return 2
        case "three": return 3
        case "four": return 4
        case "five": return 5
        case "six": return 6
        case "seven": return 7
        case "eight": return 8
        case "nine": return 9
        default: return -1
        }
    }
    let sortedNumbers = numbers.sorted()
    let sortedWords = sortedNumbers.map { number in
        switch number {
        case 0: return "zero"
        case 1: return "one"
        case 2: return "two"
        case 3: return "three"
        case 4: return "four"
        case 5: return "five"
        case 6: return "six"
        case 7: return "seven"
        case 8: return "eight"
        case 9: return "nine"
        default: return ""
        }
    }
    return sortedWords.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let words = numbers.components(separatedBy: " ")
    let numbers = words.map { numberWords[$0]! }
    let sortedNumbers = numbers.sorted()
    let sortedWords = sortedNumbers.map { numberMap[$0]! }
    return sortedWords.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let words = numbers.components(separatedBy: " ")
    let numbers = words.map { numberWords[$0]! }
    let sortedNumbers = numbers.sorted()
    let sortedWords = sortedNumbers.map { numberMap[$0]! }
    return sortedWords.joined(separator: " ")
}

let numberWords = [
    "zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9
]

let numberMap = [
    0: "zero", 1: "one", 2: "two", 3: "three", 4: "four", 5: "five", 6: "six", 7: "seven", 8: "eight", 9: "nine"
]
```

func sortNumbers(numbers: String) -> String {
    let words = numbers.split(separator: " ")
    let numbers = words.map { number in
        switch number {
        case "zero": return 0
        case "one": return 1
        case "two": return 2
        case "three": return 3
        case "four": return 4
        case "five": return 5
        case "six": return 6
        case "seven": return 7
        case "eight": return 8
        case "nine": return 9
        default: return 0
        }
    }
    let sortedNumbers = numbers.sorted()
    let sortedWords = sortedNumbers.map { number in
        switch number {
        case 0: return "zero"
        case 1: return "one"
        case 2: return "two"
        case 3: return "three"
        case 4: return "four"
        case 5: return "five"
        case 6: return "six"
        case 7: return "seven"
        case 8: return "eight"
        case 9: return "nine"
        default: return ""
        }
    }
    return sortedWords.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let words = numbers.split(separator: " ")
    let numbers = words.map { number in
        switch number {
        case "zero": return 0
        case "one": return 1
        case "two": return 2
        case "three": return 3
        case "four": return 4
        case "five": return 5
        case "six": return 6
        case "seven": return 7
        case "eight": return 8
        case "nine": return 9
        default: return 0
        }
    }
    let sortedNumbers = numbers.sorted()
    let sortedWords = sortedNumbers.map { number in
        switch number {
        case 0: return "zero"
        case 1: return "one"
        case 2: return "two"
        case 3: return "three"
        case 4: return "four"
        case 5: return "five"
        case 6: return "six"
        case 7: return "seven"
        case 8: return "eight"
        case 9: return "nine"
        default: return ""
        }
    }
    return sortedWords.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let words = numbers.components(separatedBy: " ")
    let numbers = words.map { number in
        switch number {
        case "zero": return 0
        case "one": return 1
        case "two": return 2
        case "three": return 3
        case "four": return 4
        case "five": return 5
        case "six": return 6
        case "seven": return 7
        case "eight": return 8
        case "nine": return 9
        default: return 0
        }
    }
    let sortedNumbers = numbers.sorted()
    let sortedWords = sortedNumbers.map { number in
        switch number {
        case 0: return "zero"
        case 1: return "one"
        case 2: return "two"
        case 3: return "three"
        case 4: return "four"
        case 5: return "five"
        case 6: return "six"
        case 7: return "seven"
        case 8: return "eight"
        case 9: return "nine"
        default: return ""
        }
    }
    return sortedWords.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let words = numbers.components(separatedBy: " ")
    let numbers = words.map { number in
        switch number {
        case "zero": return 0
        case "one": return 1
        case "two": return 2
        case "three": return 3
        case "four": return 4
        case "five": return 5
        case "six": return 6
        case "seven": return 7
        case "eight": return 8
        case "nine": return 9
        default: return 0
        }
    }
    let sortedNumbers = numbers.sorted()
    let sortedWords = sortedNumbers.map { number in
        switch number {
        case 0: return "zero"
        case 1: return "one"
        case 2: return "two"
        case 3: return "three"
        case 4: return "four"
        case 5: return "five"
        case 6: return "six"
        case 7: return "seven"
        case 8: return "eight"
        case 9: return "nine"
        default: return ""
        }
    }
    return sortedWords.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let words = numbers.components(separatedBy: " ")
    let numbers = words.map { number in
        switch number {
        case "zero":
            return 0
        case "one":
            return 1
        case "two":
            return 2
        case "three":
            return 3
        case "four":
            return 4
        case "five":
            return 5
        case "six":
            return 6
        case "seven":
            return 7
        case "eight":
            return 8
        case "nine":
            return 9
        default:
            return 0
        }
    }
    let sortedNumbers = numbers.sorted()
    let sortedWords = sortedNumbers.map { number in
        switch number {
        case 0:
            return "zero"
        case 1:
            return "one"
        case 2:
            return "two"
        case 3:
            return "three"
        case 4:
            return "four"
        case 5:
            return "five"
        case 6:
            return "six"
        case 7:
            return "seven"
        case 8:
            return "eight"
        case 9:
            return "nine"
        default:
            return ""
        }
    }
    return sortedWords.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let words = numbers.components(separatedBy: " ")
    let numbers = words.map { number in
        switch number {
        case "zero":
            return 0
        case "one":
            return 1
        case "two":
            return 2
        case "three":
            return 3
        case "four":
            return 4
        case "five":
            return 5
        case "six":
            return 6
        case "seven":
            return 7
        case "eight":
            return 8
        case "nine":
            return 9
        default:
            return 0
        }
    }
    let sortedNumbers = numbers.sorted()
    let sortedWords = sortedNumbers.map { number in
        switch number {
        case 0:
            return "zero"
        case 1:
            return "one"
        case 2:
            return "two"
        case 3:
            return "three"
        case 4:
            return "four"
        case 5:
            return "five"
        case 6:
            return "six"
        case 7:
            return "seven"
        case 8:
            return "eight"
        case 9:
            return "nine"
        default:
            return ""
        }
    }
    return sortedWords.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let words = numbers.split(separator: " ")
    let numbers = words.map { number in
        switch number {
        case "zero":
            return 0
        case "one":
            return 1
        case "two":
            return 2
        case "three":
            return 3
        case "four":
            return 4
        case "five":
            return 5
        case "six":
            return 6
        case "seven":
            return 7
        case "eight":
            return 8
        case "nine":
            return 9
        default:
            return 0
        }
    }
    let sortedNumbers = numbers.sorted()
    let sortedWords = sortedNumbers.map { number in
        switch number {
        case 0:
            return "zero"
        case 1:
            return "one"
        case 2:
            return "two"
        case 3:
            return "three"
        case 4:
            return "four"
        case 5:
            return "five"
        case 6:
            return "six"
        case 7:
            return "seven"
        case 8:
            return "eight"
        case 9:
            return "nine"
        default:
            return ""
        }
    }
    return sortedWords.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let words = numbers.split(separator: " ")
    let numbers = words.map { number in
        switch number {
        case "zero":
            return 0
        case "one":
            return 1
        case "two":
            return 2
        case "three":
            return 3
        case "four":
            return 4
        case "five":
            return 5
        case "six":
            return 6
        case "seven":
            return 7
        case "eight":
            return 8
        case "nine":
            return 9
        default:
            return 0
        }
    }
    let sortedNumbers = numbers.sorted()
    let sortedWords = sortedNumbers.map { number in
        switch number {
        case 0:
            return "zero"
        case 1:
            return "one"
        case 2:
            return "two"
        case 3:
            return "three"
        case 4:
            return "four"
        case 5:
            return "five"
        case 6:
            return "six"
        case 7:
            return "seven"
        case 8:
            return "eight"
        case 9:
            return "nine"
        default:
            return ""
        }
    }
    return sortedWords.joined(separator: " ")
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must have at least two elements")
    }

    var minDiff = Double.infinity
    var closestPair: (Double, Double)?

    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            let diff = abs(numbers[i] - numbers[j])
            if diff < minDiff {
                minDiff = diff
                closestPair = (numbers[i], numbers[j])
            }
        }
    }

    guard let pair = closestPair else {
        fatalError("No closest pair found")
    }

    return pair
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must have at least two elements")
    }

    var minDiff = Double.infinity
    var closestPair: (Double, Double)?

    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            let diff = abs(numbers[i] - numbers[j])
            if diff < minDiff {
                minDiff = diff
                closestPair = (numbers[i], numbers[j])
            }
        }
    }

    guard let pair = closestPair else {
        fatalError("No closest pair found")
    }

    return pair
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must have at least two elements")
    }

    var minDiff = Double.infinity
    var closestPair = (numbers[0], numbers[1])

    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            let diff = abs(numbers[i] - numbers[j])
            if diff < minDiff {
                minDiff = diff
                closestPair = (numbers[i], numbers[j])
            }
        }
    }

    return closestPair
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must have at least two elements")
    }

    var minDiff = Double.infinity
    var closestPair = (numbers[0], numbers[1])

    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            let diff = abs(numbers[i] - numbers[j])
            if diff < minDiff {
                minDiff = diff
                closestPair = (numbers[i], numbers[j])
            }
        }
    }

    return closestPair
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must have at least two elements")
    }

    var minDiff = Double.infinity
    var closestPair = (0.0, 0.0)

    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            let diff = abs(numbers[i] - numbers[j])
            if diff < minDiff {
                minDiff = diff
                closestPair = (numbers[i], numbers[j])
            }
        }
    }

    return closestPair
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must have at least two elements")
    }

    var minDiff = Double.infinity
    var closestPair = (0.0, 0.0)

    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            let diff = abs(numbers[i] - numbers[j])
            if diff < minDiff {
                minDiff = diff
                closestPair = (numbers[i], numbers[j])
            }
        }
    }

    return closestPair
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must have at least two elements")
    }
    
    var minDiff = Double.infinity
    var closestPair: (Double, Double)?
    
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            let diff = abs(numbers[i] - numbers[j])
            if diff < minDiff {
                minDiff = diff
                closestPair = (numbers[i], numbers[j])
            }
        }
    }
    
    guard let pair = closestPair else {
        fatalError("No closest pair found")
    }
    
    return pair
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must have at least two elements")
    }
    
    var minDiff = Double.infinity
    var closestPair: (Double, Double)?
    
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            let diff = abs(numbers[i] - numbers[j])
            if diff < minDiff {
                minDiff = diff
                closestPair = (numbers[i], numbers[j])
            }
        }
    }
    
    guard let pair = closestPair else {
        fatalError("No closest pair found")
    }
    
    return pair
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must have at least two elements")
    }
    
    var minDiff = Double.infinity
    var closestElements: (Double, Double)? = nil
    
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            let diff = abs(numbers[i] - numbers[j])
            if diff < minDiff {
                minDiff = diff
                closestElements = (numbers[i], numbers[j])
            }
        }
    }
    
    guard let elements = closestElements else {
        fatalError("No closest elements found")
    }
    
    return elements
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must have at least two elements")
    }
    
    var minDiff = Double.infinity
    var closestElements: (Double, Double)? = nil
    
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            let diff = abs(numbers[i] - numbers[j])
            if diff < minDiff {
                minDiff = diff
                closestElements = (numbers[i], numbers[j])
            }
        }
    }
    
    guard let elements = closestElements else {
        fatalError("No closest elements found")
    }
    
    return elements
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        return (0.0, 0.0)
    }
    
    var minDiff = Double.infinity
    var closestPair: (Double, Double) = (0.0, 0.0)
    
    for i in 0..<numbers.count {
        for j in i+1..<numbers.count {
            let diff = abs(numbers[i] - numbers[j])
            if diff < minDiff {
                minDiff = diff
                closestPair = (numbers[i], numbers[j])
            }
        }
    }
    
    return closestPair
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        return (0.0, 0.0)
    }
    
    var minDiff = Double.infinity
    var closestPair: (Double, Double) = (0.0, 0.0)
    
    for i in 0..<numbers.count {
        for j in i+1..<numbers.count {
            let diff = abs(numbers[i] - numbers[j])
            if diff < minDiff {
                minDiff = diff
                closestPair = (numbers[i], numbers[j])
            }
        }
    }
    
    return closestPair
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must have at least two elements")
    }

    var minDiff = Double.infinity
    var closestPair = (numbers[0], numbers[1])

    for i in 0..<numbers.count - 1 {
        for j in (i + 1)..<numbers.count {
            let diff = abs(numbers[i] - numbers[j])
            if diff < minDiff {
                minDiff = diff
                closestPair = (numbers[i], numbers[j])
            }
        }
    }

    return closestPair
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must have at least two elements")
    }

    var minDiff = Double.infinity
    var closestPair = (numbers[0], numbers[1])

    for i in 0..<numbers.count - 1 {
        for j in (i + 1)..<numbers.count {
            let diff = abs(numbers[i] - numbers[j])
            if diff < minDiff {
                minDiff = diff
                closestPair = (numbers[i], numbers[j])
            }
        }
    }

    return closestPair
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must have at least two elements")
    }
    
    var minDiff = Double.infinity
    var result: (Double, Double)? = nil
    
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            let diff = abs(numbers[i] - numbers[j])
            if diff < minDiff {
                minDiff = diff
                result = (numbers[i], numbers[j])
            }
        }
    }
    
    guard let r = result else {
        fatalError("No result found")
    }
    
    return r
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must have at least two elements")
    }
    
    var minDiff = Double.infinity
    var result: (Double, Double)? = nil
    
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            let diff = abs(numbers[i] - numbers[j])
            if diff < minDiff {
                minDiff = diff
                result = (numbers[i], numbers[j])
            }
        }
    }
    
    guard let r = result else {
        fatalError("No result found")
    }
    
    return r
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        return (0.0, 0.0)
    }
    
    var minDiff = Double.infinity
    var result: (Double, Double) = (0.0, 0.0)
    
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            let diff = abs(numbers[i] - numbers[j])
            if diff < minDiff {
                minDiff = diff
                result = (numbers[i], numbers[j])
            }
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        return (0.0, 0.0)
    }
    
    var minDiff = Double.infinity
    var result: (Double, Double) = (0.0, 0.0)
    
    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            let diff = abs(numbers[i] - numbers[j])
            if diff < minDiff {
                minDiff = diff
                result = (numbers[i], numbers[j])
            }
        }
    }
    
    return result
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must have at least two elements")
    }

    var minDiff = Double.infinity
    var closestPair: (Double, Double)?

    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            let diff = abs(numbers[i] - numbers[j])
            if diff < minDiff {
                minDiff = diff
                closestPair = (numbers[i], numbers[j])
            }
        }
    }

    guard let pair = closestPair else {
        fatalError("No closest pair found")
    }

    return pair
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    guard numbers.count >= 2 else {
        fatalError("Array must have at least two elements")
    }

    var minDiff = Double.infinity
    var closestPair: (Double, Double)?

    for i in 0..<numbers.count {
        for j in (i + 1)..<numbers.count {
            let diff = abs(numbers[i] - numbers[j])
            if diff < minDiff {
                minDiff = diff
                closestPair = (numbers[i], numbers[j])
            }
        }
    }

    guard let pair = closestPair else {
        fatalError("No closest pair found")
    }

    return pair
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return numbers.map { ($0 - min) / (max - min) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return numbers.map { ($0 - min) / (max - min) }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    guard numbers.count >= 2 else {
        return []
    }
    
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    
    return numbers.map { ($0 - min) / range }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    guard numbers.count >= 2 else {
        return []
    }
    
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    
    return numbers.map { ($0 - min) / range }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return numbers.map { ($0 - min) / (max - min) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return numbers.map { ($0 - min) / (max - min) }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return numbers.map { ($0 - min) / (max - min) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    return numbers.map { ($0 - min) / (max - min) }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    guard numbers.count >= 2 else {
        return []
    }
    
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    
    return numbers.map { ($0 - min) / range }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    guard numbers.count >= 2 else {
        return []
    }
    
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    
    return numbers.map { ($0 - min) / range }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    guard numbers.count >= 2 else {
        return []
    }
    
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    
    return numbers.map { ($0 - min) / range }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    guard numbers.count >= 2 else {
        return []
    }
    
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    
    return numbers.map { ($0 - min) / range }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { $0 as? Int }
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.utf16.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.utf16.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.utf16.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.utf16.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.utf16.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.utf16.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = n / 2
    while divisor > 0 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n / 2
    while divisor > 0 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = n / 2
    while divisor > 0 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n / 2
    while divisor > 0 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = n / 2
    while divisor > 0 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n / 2
    while divisor > 0 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = n / 2
    while divisor > 0 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n / 2
    while divisor > 0 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = n / 2
    while divisor > 0 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n / 2
    while divisor > 0 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = n / 2
    while divisor > 0 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n / 2
    while divisor > 0 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = n / 2
    while divisor > 0 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n / 2
    while divisor > 0 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = n / 2
    while divisor > 0 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n / 2
    while divisor > 0 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 0 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n
    while divisor > 0 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    var divisor = n / 2
    while divisor > 0 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    var divisor = n / 2
    while divisor > 0 {
        if n % divisor == 0 {
            return divisor
        }
        divisor -= 1
    }
    return 1
}
```

func factorize(n: Int) -> [Int] {
    var number = n
    var factors = [Int]()

    for i in 2...number {
        while number % i == 0 {
            factors.append(i)
            number /= i
        }
    }

    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var number = n
    var factors = [Int]()

    for i in 2...number {
        while number % i == 0 {
            factors.append(i)
            number /= i
        }
    }

    return factors
}
```

func factorize(n: Int) -> [Int] {
    var number = n
    var factors: [Int] = []
    
    for i in 2...number {
        while number % i == 0 {
            factors.append(i)
            number /= i
        }
    }
    
    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var number = n
    var factors: [Int] = []
    
    for i in 2...number {
        while number % i == 0 {
            factors.append(i)
            number /= i
        }
    }
    
    return factors
}
```

func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var number = n
    
    for i in 2...number {
        while number % i == 0 {
            factors.append(i)
            number /= i
        }
    }
    
    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var number = n
    
    for i in 2...number {
        while number % i == 0 {
            factors.append(i)
            number /= i
        }
    }
    
    return factors
}
```

func factorize(n: Int) -> [Int] {
    var result: [Int] = []
    var number = n
    
    for i in 2...number {
        while number % i == 0 {
            result.append(i)
            number /= i
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var result: [Int] = []
    var number = n
    
    for i in 2...number {
        while number % i == 0 {
            result.append(i)
            number /= i
        }
    }
    
    return result
}
```

func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var number = n
    
    for i in 2...number {
        while number % i == 0 {
            factors.append(i)
            number /= i
        }
    }
    
    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var factors = [Int]()
    var number = n
    
    for i in 2...number {
        while number % i == 0 {
            factors.append(i)
            number /= i
        }
    }
    
    return factors
}
```

func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var number = n
    
    for i in 2...number {
        while number % i == 0 {
            factors.append(i)
            number /= i
        }
    }
    
    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var number = n
    
    for i in 2...number {
        while number % i == 0 {
            factors.append(i)
            number /= i
        }
    }
    
    return factors
}
```

func factorize(n: Int) -> [Int] {
    var number = n
    var factors: [Int] = []
    
    for i in 2...number {
        while number % i == 0 {
            factors.append(i)
            number /= i
        }
    }
    
    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var number = n
    var factors: [Int] = []
    
    for i in 2...number {
        while number % i == 0 {
            factors.append(i)
            number /= i
        }
    }
    
    return factors
}
```

func factorize(n: Int) -> [Int] {
    var number = n
    var factors: [Int] = []

    for i in 2...number {
        while number % i == 0 {
            factors.append(i)
            number /= i
        }
    }

    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var number = n
    var factors: [Int] = []

    for i in 2...number {
        while number % i == 0 {
            factors.append(i)
            number /= i
        }
    }

    return factors
}
```

func factorize(n: Int) -> [Int] {
    var number = n
    var factors: [Int] = []
    
    for i in 2...number {
        while number % i == 0 {
            factors.append(i)
            number /= i
        }
    }
    
    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var number = n
    var factors: [Int] = []
    
    for i in 2...number {
        while number % i == 0 {
            factors.append(i)
            number /= i
        }
    }
    
    return factors
}
```

func factorize(n: Int) -> [Int] {
    var number = n
    var factors: [Int] = []
    
    for i in 2...number {
        while number % i == 0 {
            factors.append(i)
            number /= i
        }
    }
    
    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var number = n
    var factors: [Int] = []
    
    for i in 2...number {
        while number % i == 0 {
            factors.append(i)
            number /= i
        }
    }
    
    return factors
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()

    for number in numbers {
        if!seen.contains(number) {
            result.append(number)
            seen.insert(number)
        }
    }

    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()

    for number in numbers {
        if!seen.contains(number) {
            result.append(number)
            seen.insert(number)
        }
    }

    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            result.append(number)
            seen.insert(number)
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            result.append(number)
            seen.insert(number)
        }
    }
    
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()

    for number in numbers {
        if!seen.contains(number) {
            result.append(number)
            seen.insert(number)
        }
    }

    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()

    for number in numbers {
        if!seen.contains(number) {
            result.append(number)
            seen.insert(number)
        }
    }

    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()

    for number in numbers {
        if!seen.contains(number) {
            result.append(number)
            seen.insert(number)
        }
    }

    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()

    for number in numbers {
        if!seen.contains(number) {
            result.append(number)
            seen.insert(number)
        }
    }

    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            result.append(number)
            seen.insert(number)
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            result.append(number)
            seen.insert(number)
        }
    }
    
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var uniqueNumbers = [Int]()
    var seen = Set<Int>()

    for number in numbers {
        if!seen.contains(number) {
            uniqueNumbers.append(number)
            seen.insert(number)
        }
    }

    return uniqueNumbers
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var uniqueNumbers = [Int]()
    var seen = Set<Int>()

    for number in numbers {
        if!seen.contains(number) {
            uniqueNumbers.append(number)
            seen.insert(number)
        }
    }

    return uniqueNumbers
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            result.append(number)
            seen.insert(number)
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            result.append(number)
            seen.insert(number)
        }
    }
    
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var uniqueNumbers = [Int]()
    var seen = Set<Int>()

    for number in numbers {
        if!seen.contains(number) {
            uniqueNumbers.append(number)
            seen.insert(number)
        }
    }

    return uniqueNumbers
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var uniqueNumbers = [Int]()
    var seen = Set<Int>()

    for number in numbers {
        if!seen.contains(number) {
            uniqueNumbers.append(number)
            seen.insert(number)
        }
    }

    return uniqueNumbers
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var uniqueNumbers = [Int]()
    var seen = Set<Int>()

    for number in numbers {
        if!seen.contains(number) {
            uniqueNumbers.append(number)
            seen.insert(number)
        }
    }

    return uniqueNumbers
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var uniqueNumbers = [Int]()
    var seen = Set<Int>()

    for number in numbers {
        if!seen.contains(number) {
            uniqueNumbers.append(number)
            seen.insert(number)
        }
    }

    return uniqueNumbers
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            result.append(number)
            seen.insert(number)
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            result.append(number)
            seen.insert(number)
        }
    }
    
    return result
}
```

func flipCase(string: String) -> String {
    var result = ""
    for char in string {
        if let upperCase = char.unicodeScalars.first?.upperCase {
            result.append(Character(upperCase))
        } else if let lowerCase = char.unicodeScalars.first?.lowerCase {
            result.append(Character(lowerCase))
        } else {
            result.append(char)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    var result = ""
    for char in string {
        if let upperCase = char.unicodeScalars.first?.upperCase {
            result.append(Character(upperCase))
        } else if let lowerCase = char.unicodeScalars.first?.lowerCase {
            result.append(Character(lowerCase))
        } else {
            result.append(char)
        }
    }
    return result
}
```

func flipCase(string: String) -> String {
    return string.unicodeScalars.map { $0.isLowercase? $0.uppercase() : $0.lowercase() }.reduce("", +)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    return string.unicodeScalars.map { $0.isLowercase? $0.uppercase() : $0.lowercase() }.reduce("", +)
}
```

func flipCase(string: String) -> String {
    var result = ""
    for char in string {
        if let upperCase = char.ascii uppercase {
            result.append(Character(UnicodeScalar(upperCase)!))
        } else if let lowerCase = char.ascii lowercase {
            result.append(Character(UnicodeScalar(lowerCase)!))
        } else {
            result.append(char)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    var result = ""
    for char in string {
        if let upperCase = char.ascii uppercase {
            result.append(Character(UnicodeScalar(upperCase)!))
        } else if let lowerCase = char.ascii lowercase {
            result.append(Character(UnicodeScalar(lowerCase)!))
        } else {
            result.append(char)
        }
    }
    return result
}
```

func flipCase(string: String) -> String {
    return string.unicodeScalars.map { $0.isUppercase? $0.lowercased() : $0.uppercased() }.reduce("", +)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    return string.unicodeScalars.map { $0.isUppercase? $0.lowercased() : $0.uppercased() }.reduce("", +)
}
```

func flipCase(string: String) -> String {
    return string.unicodeScalars.map { $0.isLowercase? $0.uppercasesd() : $0.lowercased() }.reduce("", +)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    return string.unicodeScalars.map { $0.isLowercase? $0.uppercasesd() : $0.lowercased() }.reduce("", +)
}
```

func flipCase(string: String) -> String {
    var flippedString = ""
    for character in string {
        if let uppercase = character.unicodeScalars.first?.upperCase {
            flippedString.append(String(uppercase))
        } else if let lowercase = character.unicodeScalars.first?.lowerCase {
            flippedString.append(String(lowercase))
        } else {
            flippedString.append(character)
        }
    }
    return flippedString
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    var flippedString = ""
    for character in string {
        if let uppercase = character.unicodeScalars.first?.upperCase {
            flippedString.append(String(uppercase))
        } else if let lowercase = character.unicodeScalars.first?.lowerCase {
            flippedString.append(String(lowercase))
        } else {
            flippedString.append(character)
        }
    }
    return flippedString
}
```

func flipCase(string: String) -> String {
    return string.unicodeScalars.map { $0.isLowercase? $0.uppercasesd() : $0.lowercased() }.reduce("", +)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    return string.unicodeScalars.map { $0.isLowercase? $0.uppercasesd() : $0.lowercased() }.reduce("", +)
}
```

func flipCase(string: String) -> String {
    var result = ""
    for char in string {
        if let upperCase = char.unicodeScalars.first?.upperCase {
            result.append(Character(upperCase))
        } else if let lowerCase = char.unicodeScalars.first?.lowerCase {
            result.append(Character(lowerCase))
        } else {
            result.append(char)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    var result = ""
    for char in string {
        if let upperCase = char.unicodeScalars.first?.upperCase {
            result.append(Character(upperCase))
        } else if let lowerCase = char.unicodeScalars.first?.lowerCase {
            result.append(Character(lowerCase))
        } else {
            result.append(char)
        }
    }
    return result
}
```

func flipCase(string: String) -> String {
    return string.unicodeScalars.map { $0.isUppercase? String($0.lowercased()) : String($0.uppercased()) }.joined()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    return string.unicodeScalars.map { $0.isUppercase? String($0.lowercased()) : String($0.uppercased()) }.joined()
}
```

func flipCase(string: String) -> String {
    return string.unicodeScalars.map { $0.isLowercase? $0.uppercasesFirst : $0.lowercased() }.reduce("") { $0 + String($1) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    return string.unicodeScalars.map { $0.isLowercase? $0.uppercasesFirst : $0.lowercased() }.reduce("") { $0 + String($1) }
}
```

func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}
```

func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}
```

func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}
```

func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}
```

func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}
```

func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}
```

func concatenate(strings: [String]) -> String {
    return strings.joined()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined()
}
```

func concatenate(strings: [String]) -> String {
    return strings.joined()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined()
}
```

func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined(separator: "")
}
```

func concatenate(strings: [String]) -> String {
    return strings.joined()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined()
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func isPrime(n: Int) -> Bool {
    guard n > 1 else {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    guard n > 1 else {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}
```

func isPrime(n: Int) -> Bool {
    guard n > 1 else {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    guard n > 1 else {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}
```

func isPrime(n: Int) -> Bool {
    guard n > 1 else {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    guard n > 1 else {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}
```

func isPrime(n: Int) -> Bool {
    guard n > 1 else {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    guard n > 1 else {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}
```

func isPrime(n: Int) -> Bool {
    guard n > 1 else { return false }
    if n == 2 { return true }
    if n % 2 == 0 { return false }
    for i in 3...Int(sqrt(Double(n))) {
        if n % i == 0 { return false }
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    guard n > 1 else { return false }
    if n == 2 { return true }
    if n % 2 == 0 { return false }
    for i in 3...Int(sqrt(Double(n))) {
        if n % i == 0 { return false }
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    guard n > 1 else {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    guard n > 1 else {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}
```

func isPrime(n: Int) -> Bool {
    guard n > 1 else {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    guard n > 1 else {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}
```

func isPrime(n: Int) -> Bool {
    guard n > 1 else {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    guard n > 1 else {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}
```

func isPrime(n: Int) -> Bool {
    guard n > 1 else {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    guard n > 1 else {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    for i in 5...Int(sqrt(Double(n))) {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    for i in 5...Int(sqrt(Double(n))) {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
    }
    return true
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        l.remove(at: i)
        let sorted = l[i-2..<i].sorted()
        l.insert(contentsOf: sorted, at: i)
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        l.remove(at: i)
        let sorted = l[i-2..<i].sorted()
        l.insert(contentsOf: sorted, at: i)
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        l.swapAt(i, l.index(before: l.index(i)))
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        l.swapAt(i, l.index(before: l.index(i)))
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        if i + 2 < l.count {
            let subArray = Array(l[i..<i+3])
            let sortedSubArray = subArray.sorted()
            l[i..<i+3] = sortedSubArray
        }
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        if i + 2 < l.count {
            let subArray = Array(l[i..<i+3])
            let sortedSubArray = subArray.sorted()
            l[i..<i+3] = sortedSubArray
        }
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        l.remove(at: i)
        let sorted = l[i-2..<i].sorted()
        l.insert(contentsOf: sorted, at: i)
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        l.remove(at: i)
        let sorted = l[i-2..<i].sorted()
        l.insert(contentsOf: sorted, at: i)
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        if i + 2 < l.count {
            let subArray = Array(l[i..<i+3])
            let sortedArray = subArray.sorted()
            l[i..<i+3] = sortedArray
        }
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        if i + 2 < l.count {
            let subArray = Array(l[i..<i+3])
            let sortedArray = subArray.sorted()
            l[i..<i+3] = sortedArray
        }
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        if i + 2 < l.count {
            let subArray = Array(l[i..<i+3])
            let sortedArray = subArray.sorted()
            l[i..<i+3] = sortedArray
        }
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 3) {
        if i + 2 < l.count {
            let subArray = Array(l[i..<i+3])
            let sortedArray = subArray.sorted()
            l[i..<i+3] = sortedArray
        }
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        l.remove(at: i)
        let sorted = l[i-2..<i].sorted()
        l.insert(contentsOf: sorted, at: i)
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        l.remove(at: i)
        let sorted = l[i-2..<i].sorted()
        l.insert(contentsOf: sorted, at: i)
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        l.remove(at: i)
        let sorted = l[i-2..<i].sorted()
        l.insert(contentsOf: sorted, at: i)
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        l.remove(at: i)
        let sorted = l[i-2..<i].sorted()
        l.insert(contentsOf: sorted, at: i)
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        l.swapAt(i, i - 2)
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        l.swapAt(i, i - 2)
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        l.remove(at: i)
        let sorted = l[i-2..<i].sorted()
        l.insert(contentsOf: sorted, at: i)
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 2, to: l.count, by: 3) {
        l.remove(at: i)
        let sorted = l[i-2..<i].sorted()
        l.insert(contentsOf: sorted, at: i)
    }
    return l
}
```

func unique(l: [Int]) -> [Int] {
    var uniqueElements = [Int]()
    var seen = Set<Int>()
    
    for element in l {
        if!seen.contains(element) {
            uniqueElements.append(element)
            seen.insert(element)
        }
    }
    
    return uniqueElements.sorted()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var uniqueElements = [Int]()
    var seen = Set<Int>()
    
    for element in l {
        if!seen.contains(element) {
            uniqueElements.append(element)
            seen.insert(element)
        }
    }
    
    return uniqueElements.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var uniqueElements = [Int]()
    var seen = Set<Int>()

    for element in l {
        if!seen.contains(element) {
            uniqueElements.append(element)
            seen.insert(element)
        }
    }

    return uniqueElements.sorted()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var uniqueElements = [Int]()
    var seen = Set<Int>()

    for element in l {
        if!seen.contains(element) {
            uniqueElements.append(element)
            seen.insert(element)
        }
    }

    return uniqueElements.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var uniqueElements = [Int]()
    var seen = Set<Int>()
    
    for element in l {
        if!seen.contains(element) {
            uniqueElements.append(element)
            seen.insert(element)
        }
    }
    
    return uniqueElements.sorted()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var uniqueElements = [Int]()
    var seen = Set<Int>()
    
    for element in l {
        if!seen.contains(element) {
            uniqueElements.append(element)
            seen.insert(element)
        }
    }
    
    return uniqueElements.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var uniqueElements = [Int]()
    var seen = Set<Int>()

    for element in l {
        if!seen.contains(element) {
            uniqueElements.append(element)
            seen.insert(element)
        }
    }

    return uniqueElements.sorted()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var uniqueElements = [Int]()
    var seen = Set<Int>()

    for element in l {
        if!seen.contains(element) {
            uniqueElements.append(element)
            seen.insert(element)
        }
    }

    return uniqueElements.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var uniqueSet = Set<Int>()
    for element in l {
        uniqueSet.insert(element)
    }
    return Array(uniqueSet)
}

func sortedUnique(l: [Int]) -> [Int] {
    var uniqueSet = Set<Int>()
    for element in l {
        uniqueSet.insert(element)
    }
    var sortedUnique = Array(uniqueSet)
    sortedUnique.sort()
    return sortedUnique
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var uniqueSet = Set<Int>()
    for element in l {
        uniqueSet.insert(element)
    }
    return Array(uniqueSet)
}

func sortedUnique(l: [Int]) -> [Int] {
    var uniqueSet = Set<Int>()
    for element in l {
        uniqueSet.insert(element)
    }
    var sortedUnique = Array(uniqueSet)
    sortedUnique.sort()
    return sortedUnique
}
```

func unique(l: [Int]) -> [Int] {
    var uniqueElements = [Int]()
    var seenElements = Set<Int>()

    for element in l {
        if!seenElements.contains(element) {
            uniqueElements.append(element)
            seenElements.insert(element)
        }
    }

    return uniqueElements.sorted()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var uniqueElements = [Int]()
    var seenElements = Set<Int>()

    for element in l {
        if!seenElements.contains(element) {
            uniqueElements.append(element)
            seenElements.insert(element)
        }
    }

    return uniqueElements.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var uniqueElements = [Int]()
    var seenElements = Set<Int>()

    for element in l {
        if!seenElements.contains(element) {
            uniqueElements.append(element)
            seenElements.insert(element)
        }
    }

    return uniqueElements.sorted()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var uniqueElements = [Int]()
    var seenElements = Set<Int>()

    for element in l {
        if!seenElements.contains(element) {
            uniqueElements.append(element)
            seenElements.insert(element)
        }
    }

    return uniqueElements.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var uniqueElements = [Int]()
    var seen = Set<Int>()

    for element in l {
        if!seen.contains(element) {
            uniqueElements.append(element)
            seen.insert(element)
        }
    }

    return uniqueElements.sorted()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var uniqueElements = [Int]()
    var seen = Set<Int>()

    for element in l {
        if!seen.contains(element) {
            uniqueElements.append(element)
            seen.insert(element)
        }
    }

    return uniqueElements.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var set = Set<Int>()
    for num in l {
        set.insert(num)
    }
    return Array(set)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var set = Set<Int>()
    for num in l {
        set.insert(num)
    }
    return Array(set)
}
```

func unique(l: [Int]) -> [Int] {
    var set = Set<Int>()
    for num in l {
        set.insert(num)
    }
    return Array(set)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var set = Set<Int>()
    for num in l {
        set.insert(num)
    }
    return Array(set)
}
```

func maxElement(l: [Int]) -> Int {
    return l.max()!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max()!
}
```

func maxElement(l: [Int]) -> Int {
    return l.max()!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max()!
}
```

func maxElement(l: [Int]) -> Int {
    return l.max()!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max()!
}
```

func maxElement(l: [Int]) -> Int {
    return l.max()!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max()!
}
```

func maxElement(l: [Int]) -> Int {
    return l.max()!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max()!
}
```

func maxElement(l: [Int]) -> Int {
    return l.max()!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max()!
}
```

func maxElement(l: [Int]) -> Int {
    return l.max()!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max()!
}
```

func maxElement(l: [Int]) -> Int {
    return l.max()!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max()!
}
```

func maxElement(l: [Int]) -> Int {
    return l.max()!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max()!
}
```

func maxElement(l: [Int]) -> Int {
    return l.max()!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    return l.max()!
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n-1 {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n-1 {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n-1 {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n-1 {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n-1 {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n-1 {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n-1 {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n-1 {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n-1 {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n-1 {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1..<n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n-1 {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n-1 {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenValues = l[i..<min(i + 2, l.count)]
        let sortedValues = evenValues.sorted()
        l[i..<min(i + 2, l.count)] = sortedValues
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenValues = l[i..<min(i + 2, l.count)]
        let sortedValues = evenValues.sorted()
        l[i..<min(i + 2, l.count)] = sortedValues
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenValues = l[i..<min(i + 2, l.count)]
        let sortedEvenValues = evenValues.sorted()
        l[i..<min(i + 2, l.count)] = sortedEvenValues
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenValues = l[i..<min(i + 2, l.count)]
        let sortedEvenValues = evenValues.sorted()
        l[i..<min(i + 2, l.count)] = sortedEvenValues
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var result = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenValues = l[i..<min(i + 2, l.count)]
        let sortedValues = evenValues.sorted()
        result[i..<min(i + 2, l.count)] = sortedValues
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var result = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenValues = l[i..<min(i + 2, l.count)]
        let sortedValues = evenValues.sorted()
        result[i..<min(i + 2, l.count)] = sortedValues
    }
    return result
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 1, to: l.count, by: 2) {
        let evenValues = l[i..<min(i+2, l.count)].sorted()
        l[i..<min(i+2, l.count)] = evenValues
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 1, to: l.count, by: 2) {
        let evenValues = l[i..<min(i+2, l.count)].sorted()
        l[i..<min(i+2, l.count)] = evenValues
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenValues = l[i..<min(i + 2, l.count)]
        let sortedValues = evenValues.sorted()
        l[i..<min(i + 2, l.count)] = sortedValues
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenValues = l[i..<min(i + 2, l.count)]
        let sortedValues = evenValues.sorted()
        l[i..<min(i + 2, l.count)] = sortedValues
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 1, to: l.count, by: 2) {
        l[i] = l[i].sorted()
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 1, to: l.count, by: 2) {
        l[i] = l[i].sorted()
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenValues = l[i..<min(i + 2, l.count)]
        let sortedValues = evenValues.sorted()
        l[i..<min(i + 2, l.count)] = sortedValues
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        let evenValues = l[i..<min(i + 2, l.count)]
        let sortedValues = evenValues.sorted()
        l[i..<min(i + 2, l.count)] = sortedValues
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        l[i] = l[i].sorted()
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 0, to: l.count, by: 2) {
        l[i] = l[i].sorted()
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 1, to: l.count, by: 2) {
        l.swapAt(i, l.sorted(by: <)[i])
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 1, to: l.count, by: 2) {
        l.swapAt(i, l.sorted(by: <)[i])
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 1, to: l.count, by: 2) {
        let evenValues = l[i...].sorted()
        l.replaceSubrange(i...i+evenValues.count-1, with: evenValues)
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    for i in stride(from: 1, to: l.count, by: 2) {
        let evenValues = l[i...].sorted()
        l.replaceSubrange(i...i+evenValues.count-1, with: evenValues)
    }
    return l
}
```

func primeFib(n: Int) -> Int {
    var count = 0
    var a = 1
    var b = 1
    while count < n {
        let c = a + b
        if isPrime(c) {
            count += 1
        }
        a = b
        b = c
    }
    return b
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var count = 0
    var a = 1
    var b = 1
    while count < n {
        let c = a + b
        if isPrime(c) {
            count += 1
        }
        a = b
        b = c
    }
    return b
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func primeFib(n: Int) -> Int {
    var count = 0
    var a = 1
    var b = 1
    while count < n {
        let c = a + b
        if isPrime(c) {
            count += 1
        }
        a = b
        b = c
    }
    return b
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var count = 0
    var a = 1
    var b = 1
    while count < n {
        let c = a + b
        if isPrime(c) {
            count += 1
        }
        a = b
        b = c
    }
    return b
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```

func primeFib(n: Int) -> Int {
    var count = 0
    var a = 0
    var b = 1
    var result = 0
    
    while count < n {
        result = a + b
        if isPrime(result) {
            count += 1
        }
        a = b
        b = result
    }
    
    return result
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var count = 0
    var a = 0
    var b = 1
    var result = 0
    
    while count < n {
        result = a + b
        if isPrime(result) {
            count += 1
        }
        a = b
        b = result
    }
    
    return result
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}
```

func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var count = 0
    var result = 0

    while count < n {
        let temp = a + b
        a = b
        b = temp

        if isPrime(temp) {
            result = temp
            count += 1
        }
    }

    return result
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }

    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }

    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var count = 0
    var result = 0

    while count < n {
        let temp = a + b
        a = b
        b = temp

        if isPrime(temp) {
            result = temp
            count += 1
        }
    }

    return result
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }

    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }

    return true
}
```

func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var count = 0
    var result = 0
    
    while count < n {
        let temp = a + b
        a = b
        b = temp
        
        if isPrime(temp) {
            result = temp
            count += 1
        }
    }
    
    return result
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var count = 0
    var result = 0
    
    while count < n {
        let temp = a + b
        a = b
        b = temp
        
        if isPrime(temp) {
            result = temp
            count += 1
        }
    }
    
    return result
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}
```

func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var count = 0
    var result = 0

    while count < n {
        let temp = a + b
        a = b
        b = temp

        if isPrime(temp) {
            result = temp
            count += 1
        }
    }

    return result
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }

    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }

    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var count = 0
    var result = 0

    while count < n {
        let temp = a + b
        a = b
        b = temp

        if isPrime(temp) {
            result = temp
            count += 1
        }
    }

    return result
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }

    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }

    return true
}
```

func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var count = 0
    var result = 0
    
    while count < n {
        let temp = a + b
        a = b
        b = temp
        
        if isPrime(temp) {
            result = temp
            count += 1
        }
    }
    
    return result
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var count = 0
    var result = 0
    
    while count < n {
        let temp = a + b
        a = b
        b = temp
        
        if isPrime(temp) {
            result = temp
            count += 1
        }
    }
    
    return result
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}
```

func primeFib(n: Int) -> Int {
    var fib1 = 0
    var fib2 = 1
    var count = 0
    var result = 0
    
    while count < n {
        let fibNext = fib1 + fib2
        if isPrime(fibNext) {
            result = fibNext
            count += 1
        }
        fib1 = fib2
        fib2 = fibNext
    }
    
    return result
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var fib1 = 0
    var fib2 = 1
    var count = 0
    var result = 0
    
    while count < n {
        let fibNext = fib1 + fib2
        if isPrime(fibNext) {
            result = fibNext
            count += 1
        }
        fib1 = fib2
        fib2 = fibNext
    }
    
    return result
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}
```

func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var count = 0
    var result = 0
    
    while count < n {
        let temp = a + b
        a = b
        b = temp
        
        if isPrime(temp) {
            result = temp
            count += 1
        }
    }
    
    return result
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var a = 0
    var b = 1
    var count = 0
    var result = 0
    
    while count < n {
        let temp = a + b
        a = b
        b = temp
        
        if isPrime(temp) {
            result = temp
            count += 1
        }
    }
    
    return result
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}
```

func primeFib(n: Int) -> Int {
    var fib1 = 0
    var fib2 = 1
    var count = 0
    var result = 0
    
    while count < n {
        let fibNext = fib1 + fib2
        if isPrime(fibNext) {
            result = fibNext
            count += 1
        }
        fib1 = fib2
        fib2 = fibNext
    }
    
    return result
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var fib1 = 0
    var fib2 = 1
    var count = 0
    var result = 0
    
    while count < n {
        let fibNext = fib1 + fib2
        if isPrime(fibNext) {
            result = fibNext
            count += 1
        }
        fib1 = fib2
        fib2 = fibNext
    }
    
    return result
}

func isPrime(_ n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    
    return true
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    var set = Set(l)
    for i in 0..<l.count {
        for j in (i + 1)..<l.count {
            let k = -l[i] - l[j]
            if set.contains(k) {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    var set = Set(l)
    for i in 0..<l.count {
        for j in (i + 1)..<l.count {
            let k = -l[i] - l[j]
            if set.contains(k) {
                return true
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    var set = Set(l)
    for i in 0..<l.count {
        for j in (i + 1)..<l.count {
            let k = -l[i] - l[j]
            if set.contains(k) {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    var set = Set(l)
    for i in 0..<l.count {
        for j in (i + 1)..<l.count {
            let k = -l[i] - l[j]
            if set.contains(k) {
                return true
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    let set = Set(l)
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if set.contains(-l[i] - l[j] - l[k]) {
                    return true
                }
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    let set = Set(l)
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if set.contains(-l[i] - l[j] - l[k]) {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    let set = Set(l)
    for i in 0..<l.count {
        for j in (i + 1)..<l.count {
            for k in (j + 1)..<l.count {
                if set.contains(-l[i] - l[j] - l[k]) {
                    return true
                }
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    let set = Set(l)
    for i in 0..<l.count {
        for j in (i + 1)..<l.count {
            for k in (j + 1)..<l.count {
                if set.contains(-l[i] - l[j] - l[k]) {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    let set = Set(l)
    for i in 0..<l.count {
        for j in (i + 1)..<l.count {
            for k in (j + 1)..<l.count {
                if set.contains(-l[i] - l[j] - l[k]) {
                    return true
                }
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    let set = Set(l)
    for i in 0..<l.count {
        for j in (i + 1)..<l.count {
            for k in (j + 1)..<l.count {
                if set.contains(-l[i] - l[j] - l[k]) {
                    return true
                }
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    let set = Set(l)
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if set.contains(-l[i] - l[j] - l[k]) {
                    return true
                }
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    let set = Set(l)
    for i in 0..<l.count {
        for j in i+1..<l.count {
            for k in j+1..<l.count {
                if set.contains(-l[i] - l[j] - l[k]) {
                    return true
                }
            }
        }
    }
    return false
}
```

func carRaceCollision(n: Int) -> Int {
    var leftCars = [Int]()
    var rightCars = [Int]()
    var collisions = 0
    
    for i in 1...n {
        leftCars.append(i)
        rightCars.append(n - i + 1)
    }
    
    while!leftCars.isEmpty &&!rightCars.isEmpty {
        let leftCar = leftCars.removeFirst()
        let rightCar = rightCars.removeLast()
        
        if leftCar < rightCar {
            leftCars.append(leftCar)
        } else if leftCar > rightCar {
            rightCars.append(rightCar)
        } else {
            collisions += 1
        }
    }
    
    return collisions
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var leftCars = [Int]()
    var rightCars = [Int]()
    var collisions = 0
    
    for i in 1...n {
        leftCars.append(i)
        rightCars.append(n - i + 1)
    }
    
    while!leftCars.isEmpty &&!rightCars.isEmpty {
        let leftCar = leftCars.removeFirst()
        let rightCar = rightCars.removeLast()
        
        if leftCar < rightCar {
            leftCars.append(leftCar)
        } else if leftCar > rightCar {
            rightCars.append(rightCar)
        } else {
            collisions += 1
        }
    }
    
    return collisions
}
```

func carRaceCollision(n: Int) -> Int {
    var leftCars = [Int]()
    var rightCars = [Int]()
    var collisions = 0

    for i in 0..<n {
        leftCars.append(i)
        rightCars.append(n - 1 - i)
    }

    while!leftCars.isEmpty &&!rightCars.isEmpty {
        let leftCar = leftCars.removeFirst()
        let rightCar = rightCars.removeLast()

        if leftCar < rightCar {
            leftCars.append(leftCar + n)
        } else {
            rightCars.insert(rightCar - n, at: 0)
            collisions += 1
        }
    }

    return collisions
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var leftCars = [Int]()
    var rightCars = [Int]()
    var collisions = 0

    for i in 0..<n {
        leftCars.append(i)
        rightCars.append(n - 1 - i)
    }

    while!leftCars.isEmpty &&!rightCars.isEmpty {
        let leftCar = leftCars.removeFirst()
        let rightCar = rightCars.removeLast()

        if leftCar < rightCar {
            leftCars.append(leftCar + n)
        } else {
            rightCars.insert(rightCar - n, at: 0)
            collisions += 1
        }
    }

    return collisions
}
```

func carRaceCollision(n: Int) -> Int {
    var leftCars = [Int]()
    var rightCars = [Int]()
    var collisions = 0

    for i in 0..<n {
        leftCars.append(i)
        rightCars.append(n - 1 - i)
    }

    while!leftCars.isEmpty &&!rightCars.isEmpty {
        let leftCar = leftCars.removeFirst()
        let rightCar = rightCars.removeLast()

        if leftCar < rightCar {
            leftCars.append(leftCar + n)
        } else {
            rightCars.insert(rightCar - n, at: 0)
            collisions += 1
        }
    }

    return collisions
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var leftCars = [Int]()
    var rightCars = [Int]()
    var collisions = 0

    for i in 0..<n {
        leftCars.append(i)
        rightCars.append(n - 1 - i)
    }

    while!leftCars.isEmpty &&!rightCars.isEmpty {
        let leftCar = leftCars.removeFirst()
        let rightCar = rightCars.removeLast()

        if leftCar < rightCar {
            leftCars.append(leftCar + n)
        } else {
            rightCars.insert(rightCar - n, at: 0)
            collisions += 1
        }
    }

    return collisions
}
```

func carRaceCollision(n: Int) -> Int {
    var leftCars = [Int]()
    var rightCars = [Int]()
    var collisions = 0

    for i in 0..<n {
        leftCars.append(i)
        rightCars.append(i)
    }

    while!leftCars.isEmpty &&!rightCars.isEmpty {
        let leftCar = leftCars.removeFirst()
        let rightCar = rightCars.removeLast()

        if leftCar < rightCar {
            leftCars.append(leftCar + n)
            collisions += 1
        } else if leftCar > rightCar {
            rightCars.insert(rightCar + n, at: 0)
            collisions += 1
        }
    }

    return collisions
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var leftCars = [Int]()
    var rightCars = [Int]()
    var collisions = 0

    for i in 0..<n {
        leftCars.append(i)
        rightCars.append(i)
    }

    while!leftCars.isEmpty &&!rightCars.isEmpty {
        let leftCar = leftCars.removeFirst()
        let rightCar = rightCars.removeLast()

        if leftCar < rightCar {
            leftCars.append(leftCar + n)
            collisions += 1
        } else if leftCar > rightCar {
            rightCars.insert(rightCar + n, at: 0)
            collisions += 1
        }
    }

    return collisions
}
```

func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    return n * (n - 1) / 2
}
```

func carRaceCollision(n: Int) -> Int {
    var leftCars = [Int]()
    var rightCars = [Int]()
    
    for i in 1...n {
        leftCars.append(i)
        rightCars.append(n - i + 1)
    }
    
    var collisions = 0
    
    while!leftCars.isEmpty &&!rightCars.isEmpty {
        let leftCar = leftCars.removeFirst()
        let rightCar = rightCars.removeLast()
        
        if leftCar == rightCar {
            collisions += 1
        } else if leftCar < rightCar {
            leftCars.append(leftCar)
        } else {
            rightCars.append(rightCar)
        }
    }
    
    return collisions
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var leftCars = [Int]()
    var rightCars = [Int]()
    
    for i in 1...n {
        leftCars.append(i)
        rightCars.append(n - i + 1)
    }
    
    var collisions = 0
    
    while!leftCars.isEmpty &&!rightCars.isEmpty {
        let leftCar = leftCars.removeFirst()
        let rightCar = rightCars.removeLast()
        
        if leftCar == rightCar {
            collisions += 1
        } else if leftCar < rightCar {
            leftCars.append(leftCar)
        } else {
            rightCars.append(rightCar)
        }
    }
    
    return collisions
}
```

func carRaceCollision(n: Int) -> Int {
    var leftCars = [Int]()
    var rightCars = [Int]()
    var collisions = 0

    for i in 0..<n {
        leftCars.append(i)
        rightCars.append(i)
    }

    while!leftCars.isEmpty &&!rightCars.isEmpty {
        let leftCar = leftCars.removeFirst()
        let rightCar = rightCars.removeLast()

        if leftCar == rightCar {
            collisions += 1
        } else {
            leftCars.append(leftCar)
            rightCars.insert(rightCar, at: 0)
        }
    }

    return collisions
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var leftCars = [Int]()
    var rightCars = [Int]()
    var collisions = 0

    for i in 0..<n {
        leftCars.append(i)
        rightCars.append(i)
    }

    while!leftCars.isEmpty &&!rightCars.isEmpty {
        let leftCar = leftCars.removeFirst()
        let rightCar = rightCars.removeLast()

        if leftCar == rightCar {
            collisions += 1
        } else {
            leftCars.append(leftCar)
            rightCars.insert(rightCar, at: 0)
        }
    }

    return collisions
}
```

func carRaceCollision(n: Int) -> Int {
    var leftCars = [Int]()
    var rightCars = [Int]()
    var collisions = 0

    for i in 0..<n {
        leftCars.append(i)
        rightCars.append(n - 1 - i)
    }

    while!leftCars.isEmpty &&!rightCars.isEmpty {
        let leftCar = leftCars.removeFirst()
        let rightCar = rightCars.removeLast()

        if leftCar < rightCar {
            leftCars.append(leftCar + n)
            collisions += 1
        } else if leftCar > rightCar {
            rightCars.insert(rightCar + n, at: 0)
            collisions += 1
        }
    }

    return collisions
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var leftCars = [Int]()
    var rightCars = [Int]()
    var collisions = 0

    for i in 0..<n {
        leftCars.append(i)
        rightCars.append(n - 1 - i)
    }

    while!leftCars.isEmpty &&!rightCars.isEmpty {
        let leftCar = leftCars.removeFirst()
        let rightCar = rightCars.removeLast()

        if leftCar < rightCar {
            leftCars.append(leftCar + n)
            collisions += 1
        } else if leftCar > rightCar {
            rightCars.insert(rightCar + n, at: 0)
            collisions += 1
        }
    }

    return collisions
}
```

func carRaceCollision(n: Int) -> Int {
    var leftCars = [Int]()
    var rightCars = [Int]()
    var collisions = 0

    for i in 0..<n {
        leftCars.append(i)
        rightCars.append(n - 1 - i)
    }

    while!leftCars.isEmpty &&!rightCars.isEmpty {
        let leftCar = leftCars.removeFirst()
        let rightCar = rightCars.removeLast()

        if leftCar < rightCar {
            leftCars.append(leftCar + n)
        } else {
            rightCars.insert(rightCar - n, at: 0)
            collisions += 1
        }
    }

    return collisions
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var leftCars = [Int]()
    var rightCars = [Int]()
    var collisions = 0

    for i in 0..<n {
        leftCars.append(i)
        rightCars.append(n - 1 - i)
    }

    while!leftCars.isEmpty &&!rightCars.isEmpty {
        let leftCar = leftCars.removeFirst()
        let rightCar = rightCars.removeLast()

        if leftCar < rightCar {
            leftCars.append(leftCar + n)
        } else {
            rightCars.insert(rightCar - n, at: 0)
            collisions += 1
        }
    }

    return collisions
}
```

func carRaceCollision(n: Int) -> Int {
    var leftCars = [Int]()
    var rightCars = [Int]()
    
    for i in 0..<n {
        leftCars.append(i)
        rightCars.append(n - 1 - i)
    }
    
    var collisions = 0
    var leftIndex = 0
    var rightIndex = 0
    
    while leftIndex < n && rightIndex < n {
        if leftCars[leftIndex] < rightCars[rightIndex] {
            leftIndex += 1
        } else if leftCars[leftIndex] > rightCars[rightIndex] {
            rightIndex += 1
        } else {
            collisions += 1
            leftIndex += 1
            rightIndex += 1
        }
    }
    
    return collisions
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var leftCars = [Int]()
    var rightCars = [Int]()
    
    for i in 0..<n {
        leftCars.append(i)
        rightCars.append(n - 1 - i)
    }
    
    var collisions = 0
    var leftIndex = 0
    var rightIndex = 0
    
    while leftIndex < n && rightIndex < n {
        if leftCars[leftIndex] < rightCars[rightIndex] {
            leftIndex += 1
        } else if leftCars[leftIndex] > rightCars[rightIndex] {
            rightIndex += 1
        } else {
            collisions += 1
            leftIndex += 1
            rightIndex += 1
        }
    }
    
    return collisions
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    var result = [Int]()
    for num in l {
        result.append(num + 1)
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    var result = [Int]()
    for num in l {
        result.append(num + 1)
    }
    return result
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    var result = [Int]()
    for num in l {
        result.append(num + 1)
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    var result = [Int]()
    for num in l {
        result.append(num + 1)
    }
    return result
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    var result = [Int]()
    for num in l {
        result.append(num + 1)
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    var result = [Int]()
    for num in l {
        result.append(num + 1)
    }
    return result
}
```

func incrList(l: [Int]) -> [Int] {
    var result = [Int]()
    for num in l {
        result.append(num + 1)
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    var result = [Int]()
    for num in l {
        result.append(num + 1)
    }
    return result
}
```

func incrList(l: [Int]) -> [Int] {
    var result = [Int]()
    for num in l {
        result.append(num + 1)
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    var result = [Int]()
    for num in l {
        result.append(num + 1)
    }
    return result
}
```

func incrList(l: [Int]) -> [Int] {
    var result = [Int]()
    for num in l {
        result.append(num + 1)
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    var result = [Int]()
    for num in l {
        result.append(num + 1)
    }
    return result
}
```

func incrList(l: [Int]) -> [Int] {
    var result = [Int]()
    for i in l {
        result.append(i + 1)
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    var result = [Int]()
    for i in l {
        result.append(i + 1)
    }
    return result
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var seen = Set<Int>()
    
    for num in l {
        if seen.contains(-num) {
            return true
        }
        seen.insert(num)
    }
    
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var seen = Set<Int>()
    
    for num in l {
        if seen.contains(-num) {
            return true
        }
        seen.insert(num)
    }
    
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var seen = Set<Int>()
    
    for num in l {
        if seen.contains(-num) {
            return true
        }
        seen.insert(num)
    }
    
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var seen = Set<Int>()
    
    for num in l {
        if seen.contains(-num) {
            return true
        }
        seen.insert(num)
    }
    
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var seen = Set<Int>()
    for num in l {
        if seen.contains(-num) {
            return true
        }
        seen.insert(num)
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var seen = Set<Int>()
    for num in l {
        if seen.contains(-num) {
            return true
        }
        seen.insert(num)
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    
    for num in l {
        if set.contains(-num) {
            return true
        } else {
            set.insert(num)
        }
    }
    
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    
    for num in l {
        if set.contains(-num) {
            return true
        } else {
            set.insert(num)
        }
    }
    
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var seen = Set<Int>()
    for num in l {
        if seen.contains(-num) {
            return true
        }
        seen.insert(num)
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var seen = Set<Int>()
    for num in l {
        if seen.contains(-num) {
            return true
        }
        seen.insert(num)
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var seen = Set<Int>()
    for num in l {
        if seen.contains(-num) {
            return true
        }
        seen.insert(num)
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var seen = Set<Int>()
    for num in l {
        if seen.contains(-num) {
            return true
        }
        seen.insert(num)
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var seen = Set<Int>()
    for num in l {
        if seen.contains(-num) {
            return true
        }
        seen.insert(num)
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var seen = Set<Int>()
    for num in l {
        if seen.contains(-num) {
            return true
        }
        seen.insert(num)
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    let set = Set(l)
    for i in 0..<l.count {
        if set.contains(-l[i]) {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    let set = Set(l)
    for i in 0..<l.count {
        if set.contains(-l[i]) {
            return true
        }
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var seen = Set<Int>()
    
    for num in l {
        if seen.contains(-num) {
            return true
        }
        seen.insert(num)
    }
    
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var seen = Set<Int>()
    
    for num in l {
        if seen.contains(-num) {
            return true
        }
        seen.insert(num)
    }
    
    return false
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var number = x
    while number > 0 {
        let remainder = number % base
        result = String(remainder) + result
        number /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var number = x
    while number > 0 {
        let remainder = number % base
        result = String(remainder) + result
        number /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var number = x
    while number > 0 {
        let remainder = number % base
        result = String(remainder) + result
        number /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var number = x
    while number > 0 {
        let remainder = number % base
        result = String(remainder) + result
        number /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var number = x
    while number > 0 {
        let remainder = number % base
        result = String(remainder) + result
        number /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var number = x
    while number > 0 {
        let remainder = number % base
        result = String(remainder) + result
        number /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var number = x
    while number > 0 {
        let remainder = number % base
        result = String(remainder) + result
        number /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var number = x
    while number > 0 {
        let remainder = number % base
        result = String(remainder) + result
        number /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var number = x
    while number > 0 {
        let remainder = number % base
        result = String(remainder) + result
        number /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var number = x
    while number > 0 {
        let remainder = number % base
        result = String(remainder) + result
        number /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var number = x
    while number > 0 {
        let remainder = number % base
        result = String(remainder) + result
        number /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var number = x
    while number > 0 {
        let remainder = number % base
        result = String(remainder) + result
        number /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var number = x
    while number > 0 {
        let remainder = number % base
        result = String(remainder) + result
        number /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var number = x
    while number > 0 {
        let remainder = number % base
        result = String(remainder) + result
        number /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var number = x
    while number > 0 {
        let remainder = number % base
        result = String(remainder) + result
        number /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var number = x
    while number > 0 {
        let remainder = number % base
        result = String(remainder) + result
        number /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var remainder = x
    while remainder > 0 {
        let digit = remainder % base
        result = String(digit) + result
        remainder /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var remainder = x
    while remainder > 0 {
        let digit = remainder % base
        result = String(digit) + result
        remainder /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var number = x
    while number > 0 {
        let remainder = number % base
        result = String(remainder) + result
        number /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var result = ""
    var number = x
    while number > 0 {
        let remainder = number % base
        result = String(remainder) + result
        number /= base
    }
    return result
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    let area = Double(a) * Double(h) / 2
    return area
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    let area = Double(a) * Double(h) / 2
    return area
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    let area = Double(a) * Double(h) / 2
    return area
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    let area = Double(a) * Double(h) / 2
    return area
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a) * Double(h) / 2
}
```

func fib4(n: Int) -> Int {
    guard n > 0 else {
        return 0
    }
    
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    
    for i in 1...n {
        let sum = a + b + c + d
        a = b
        b = c
        c = d
        d = sum
    }
    
    return d
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    guard n > 0 else {
        return 0
    }
    
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    
    for i in 1...n {
        let sum = a + b + c + d
        a = b
        b = c
        c = d
        d = sum
    }
    
    return d
}
```

func fib4(n: Int) -> Int {
    guard n > 0 else { return 0 }
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    for _ in 1...n {
        let e = a + b + c + d
        a = b
        b = c
        c = d
        d = e
    }
    return d
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    guard n > 0 else { return 0 }
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    for _ in 1...n {
        let e = a + b + c + d
        a = b
        b = c
        c = d
        d = e
    }
    return d
}
```

func fib4(n: Int) -> Int {
    guard n > 0 else { return 0 }
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    for _ in 1...n {
        let e = a + b + c + d
        a = b
        b = c
        c = d
        d = e
    }
    return d
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    guard n > 0 else { return 0 }
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    for _ in 1...n {
        let e = a + b + c + d
        a = b
        b = c
        c = d
        d = e
    }
    return d
}
```

func fib4(n: Int) -> Int {
    guard n > 0 else {
        return 0
    }
    
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    
    for i in 1...n {
        let temp = c
        c = d + b
        d = a + b
        a = b
        b = temp
    }
    
    return d
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    guard n > 0 else {
        return 0
    }
    
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    
    for i in 1...n {
        let temp = c
        c = d + b
        d = a + b
        a = b
        b = temp
    }
    
    return d
}
```

func fib4(n: Int) -> Int {
    guard n > 0 else { return 0 }
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    for _ in 1...n {
        let sum = a + b + c + d
        a = b
        b = c
        c = d
        d = sum
    }
    return d
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    guard n > 0 else { return 0 }
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    for _ in 1...n {
        let sum = a + b + c + d
        a = b
        b = c
        c = d
        d = sum
    }
    return d
}
```

func fib4(n: Int) -> Int {
    guard n > 0 else { return 0 }
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    for _ in 1...n {
        let temp = d
        d = c + b
        c = b
        b = a
        a = temp
    }
    return d
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    guard n > 0 else { return 0 }
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    for _ in 1...n {
        let temp = d
        d = c + b
        c = b
        b = a
        a = temp
    }
    return d
}
```

func fib4(n: Int) -> Int {
    guard n > 0 else { return 0 }
    
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    
    for i in 1...n {
        let temp = d
        d = c + b
        c = b
        b = a
        a = temp
    }
    
    return d
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    guard n > 0 else { return 0 }
    
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    
    for i in 1...n {
        let temp = d
        d = c + b
        c = b
        b = a
        a = temp
    }
    
    return d
}
```

func fib4(n: Int) -> Int {
    guard n > 0 else { return 0 }
    var prev3 = 0
    var prev2 = 0
    var prev1 = 2
    var current = 0
    
    for i in 1...n {
        current = prev3 + prev2 + prev1
        prev3 = prev2
        prev2 = prev1
        prev1 = current
    }
    
    return current
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    guard n > 0 else { return 0 }
    var prev3 = 0
    var prev2 = 0
    var prev1 = 2
    var current = 0
    
    for i in 1...n {
        current = prev3 + prev2 + prev1
        prev3 = prev2
        prev2 = prev1
        prev1 = current
    }
    
    return current
}
```

func fib4(n: Int) -> Int {
    if n <= 0 {
        return 0
    } else if n == 1 {
        return 0
    } else if n == 2 {
        return 2
    } else if n == 3 {
        return 0
    }
    
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    
    for i in 4..<n {
        let e = a + b + c + d
        a = b
        b = c
        c = d
        d = e
    }
    
    return d
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    if n <= 0 {
        return 0
    } else if n == 1 {
        return 0
    } else if n == 2 {
        return 2
    } else if n == 3 {
        return 0
    }
    
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    
    for i in 4..<n {
        let e = a + b + c + d
        a = b
        b = c
        c = d
        d = e
    }
    
    return d
}
```

func fib4(n: Int) -> Int {
    guard n > 0 else {
        return 0
    }
    
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    
    for i in 1...n {
        let temp = d
        d = c + b
        c = b + a
        b = a
        a = temp
    }
    
    return d
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    guard n > 0 else {
        return 0
    }
    
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    
    for i in 1...n {
        let temp = d
        d = c + b
        c = b + a
        b = a
        a = temp
    }
    
    return d
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid] + sorted[mid - 1]) / 2
    } else {
        return Double(sorted[mid])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid] + sorted[mid - 1]) / 2
    } else {
        return Double(sorted[mid])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid] + sorted[mid - 1]) / 2
    } else {
        return Double(sorted[mid])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid] + sorted[mid - 1]) / 2
    } else {
        return Double(sorted[mid])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid] + sorted[mid - 1]) / 2
    } else {
        return Double(sorted[mid])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid] + sorted[mid - 1]) / 2
    } else {
        return Double(sorted[mid])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid - 1] + sorted[mid]) / 2
    } else {
        return Double(sorted[mid])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid - 1] + sorted[mid]) / 2
    } else {
        return Double(sorted[mid])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid - 1] + sorted[mid]) / 2
    } else {
        return Double(sorted[mid])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid - 1] + sorted[mid]) / 2
    } else {
        return Double(sorted[mid])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid - 1] + sorted[mid]) / 2
    } else {
        return Double(sorted[mid])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid - 1] + sorted[mid]) / 2
    } else {
        return Double(sorted[mid])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid] + sorted[mid - 1]) / 2
    } else {
        return Double(sorted[mid])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid] + sorted[mid - 1]) / 2
    } else {
        return Double(sorted[mid])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid - 1] + sorted[mid]) / 2
    } else {
        return Double(sorted[mid])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid - 1] + sorted[mid]) / 2
    } else {
        return Double(sorted[mid])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid] + sorted[mid - 1]) / 2
    } else {
        return Double(sorted[mid])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid] + sorted[mid - 1]) / 2
    } else {
        return Double(sorted[mid])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid] + sorted[mid - 1]) / 2
    } else {
        return Double(sorted[mid])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid] + sorted[mid - 1]) / 2
    } else {
        return Double(sorted[mid])
    }
}
```

func isPalindrome(text: String) -> Bool {
    let cleanText = text.lowercased().replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
    let reversedText = String(cleanText.reversed())
    return cleanText == reversedText
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false

Answer:
```swift
func isPalindrome(text: String) -> Bool {
    let cleanText = text.lowercased().replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
    let reversedText = String(cleanText.reversed())
    return cleanText == reversedText
}
```

func isPalindrome(text: String) -> Bool {
    let lowercasedText = text.lowercased()
    let reversedText = String(lowercasedText.reversed())
    return lowercasedText == reversedText
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false

Answer:
```swift
func isPalindrome(text: String) -> Bool {
    let lowercasedText = text.lowercased()
    let reversedText = String(lowercasedText.reversed())
    return lowercasedText == reversedText
}
```

func isPalindrome(text: String) -> Bool {
    let cleanText = text.lowercased().replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
    let reversedText = String(cleanText.reversed())
    return cleanText == reversedText
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false

Answer:
```swift
func isPalindrome(text: String) -> Bool {
    let cleanText = text.lowercased().replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
    let reversedText = String(cleanText.reversed())
    return cleanText == reversedText
}
```

func isPalindrome(text: String) -> Bool {
    let lowercasedText = text.lowercased()
    let reversedText = String(lowercasedText.reversed())
    return lowercasedText == reversedText
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false

Answer:
```swift
func isPalindrome(text: String) -> Bool {
    let lowercasedText = text.lowercased()
    let reversedText = String(lowercasedText.reversed())
    return lowercasedText == reversedText
}
```

func isPalindrome(text: String) -> Bool {
    let cleanText = text.lowercased().replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
    let reversedText = String(cleanText.reversed())
    return cleanText == reversedText
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false

Answer:
```swift
func isPalindrome(text: String) -> Bool {
    let cleanText = text.lowercased().replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
    let reversedText = String(cleanText.reversed())
    return cleanText == reversedText
}
```

func isPalindrome(text: String) -> Bool {
    let lowercasedText = text.lowercased()
    let reversedText = String(lowercasedText.reversed())
    return lowercasedText == reversedText
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false

Answer:
```swift
func isPalindrome(text: String) -> Bool {
    let lowercasedText = text.lowercased()
    let reversedText = String(lowercasedText.reversed())
    return lowercasedText == reversedText
}
```

func isPalindrome(text: String) -> Bool {
    let cleanText = text.lowercased().replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
    let reversedText = String(cleanText.reversed())
    return cleanText == reversedText
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false

Answer:
```swift
func isPalindrome(text: String) -> Bool {
    let cleanText = text.lowercased().replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
    let reversedText = String(cleanText.reversed())
    return cleanText == reversedText
}
```

func isPalindrome(text: String) -> Bool {
    let cleanText = text.lowercased().replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
    let reversedText = String(cleanText.reversed())
    return cleanText == reversedText
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false

Answer:
```swift
func isPalindrome(text: String) -> Bool {
    let cleanText = text.lowercased().replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
    let reversedText = String(cleanText.reversed())
    return cleanText == reversedText
}
```

func isPalindrome(text: String) -> Bool {
    let lowercasedText = text.lowercased()
    let reversedText = String(lowercasedText.reversed())
    return lowercasedText == reversedText
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false

Answer:
```swift
func isPalindrome(text: String) -> Bool {
    let lowercasedText = text.lowercased()
    let reversedText = String(lowercasedText.reversed())
    return lowercasedText == reversedText
}
```

func isPalindrome(text: String) -> Bool {
    let lowercasedText = text.lowercased()
    let cleanText = lowercasedText.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
    let reversedText = String(cleanText.reversed())
    
    return cleanText == reversedText
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false

Answer:
```swift
func isPalindrome(text: String) -> Bool {
    let lowercasedText = text.lowercased()
    let cleanText = lowercasedText.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
    let reversedText = String(cleanText.reversed())
    
    return cleanText == reversedText
}
```

func modp(n: Int, p: Int) -> Int {
    return pow(2, n) % p
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1

Answer:
```swift
func modp(n: Int, p: Int) -> Int {
    return pow(2, n) % p
}
```

func modp(n: Int, p: Int) -> Int {
    return pow(2, n) % p
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1

Answer:
```swift
func modp(n: Int, p: Int) -> Int {
    return pow(2, n) % p
}
```

func modp(n: Int, p: Int) -> Int {
    return pow(2, n) % p
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1

Answer:
```swift
func modp(n: Int, p: Int) -> Int {
    return pow(2, n) % p
}
```

func modp(n: Int, p: Int) -> Int {
    return pow(2, n) % p
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1

Answer:
```swift
func modp(n: Int, p: Int) -> Int {
    return pow(2, n) % p
}
```